message: chore(observeOn): fix skipped test
  Closes
diff: @@ -83,7 +83,7 @@ describe('observeOn operator', () => {
  expectSubscriptions(e1.subscriptions).toBe(sub);
  });
  - xit('should clean up subscriptions created by async scheduling (prevent memory leaks #2244)', (done) => {
  + it('should clean up subscriptions created by async scheduling (prevent memory leaks #2244)', (done) => {
  //HACK: Deep introspection to make sure we're cleaning up notifications in scheduling.
  // as the architecture changes, this test may become brittle.
  const results: number[] = [];
  @@ -104,7 +104,7 @@ describe('observeOn operator', () => {
  .subscribe(
  x => {
  const observeOnSubscriber = subscription._subscriptions[0];
  - expect(observeOnSubscriber._subscriptions.length).to.equal(2); // 1 for the consumer, and one for the notification
  + expect(observeOnSubscriber._subscriptions.length).to.equal(2); // one for the consumer, and one for the notification
  expect(observeOnSubscriber._subscriptions[1].state.notification.kind)
  .to.equal('N');
  expect(observeOnSubscriber._subscriptions[1].state.notification.value)
  @@ -114,10 +114,11 @@ describe('observeOn operator', () => {
  err => done(err),
  () => {
  // now that the last nexted value is done, there should only be a complete notification scheduled
  + // the consumer will have been unsubscribed via Subscriber#_parentSubscription
  const observeOnSubscriber = subscription._subscriptions[0];
  - expect(observeOnSubscriber._subscriptions.length).to.equal(2); // 1 for the consumer, one for the complete notification
  + expect(observeOnSubscriber._subscriptions.length).to.equal(1); // one for the complete notification
  // only this completion notification should remain.
  - expect(observeOnSubscriber._subscriptions[1].state.notification.kind)
  + expect(observeOnSubscriber._subscriptions[0].state.notification.kind)
  .to.equal('C');
  // After completion, the entire _subscriptions list is nulled out anyhow, so we can't test much further than this.
  expect(results).to.deep.equal([1, 2, 3]);
  