message: Update Problem Statement
diff: Palindrome Permutation: Given a string, write a function to check if it is a permutation of a palindrome. A palindrome is a word or phrase that is the same forwards and backwards. A permutation is a rearrangement of letters. The palindrome does not need to be limited to just dictionary words.
  -EXAMPLE
  +###EXAMPLE
  Input: Tact Coa
  Output: True (permutations: "taco cat", "atco eta", etc.)
  +
  +
  +##Solution(in python)
  +
  +'''
  +Basic requirement for the number to be palindrome is that it must contain letters in multiple of 2
  +and only '0' or '1' odd chracters
  +'''
  +from collections import Counter
  +def pali(str):
  + temp = []
  + sum = 0
  + for i in str:
  + if(i.isalpha()):
  + temp.append(i.lower())
  + counts = Counter(temp) #Returns a dictionary containing the count of each character
  + print(counts)
  + for y in counts.values(): #checks the number of odd numbered characters
  + if y%2!=0: #if its greater than 2 than the number cannot be palindrome
  + sum+=1
  + if sum < 2:
  + return True
  + else:
  + return False
  +
  +mystring = 'ara'
  +print(pali(mystring))
  +
  