def METHOD_NAME(text: str) -> str:
    """
    Remove all punctuation symbols (e.g., ., !, ?) from the text of the column 'column_name'
    """
    if pd.isnull(text):
        return text
    split_urls_from_text = gruber.split(text)
    # The non-URLs are always even-numbered entries in the list and the URLs are odd-numbered.
    for i in range(0, len(split_urls_from_text), 2):
        split_urls_from_text[i] = split_urls_from_text[i].translate(str.maketrans("", "", string.punctuation))
    stripped_text = "".join(split_urls_from_text)
    return stripped_text