Compiled x.shape throws Tuple out-of-range error
Related: https://github.com/tensorflow/tensorflow/issues/61856 @sachinprasadhs,
I was able to reproduce the issue on tensorflow v2.12, v2.13 and tf-nightly. Kindly find the gist of it [here](https://colab.research.google.com/gist/tilakrayal/133237432d8d43f4aeb8c31899c321e7/untitled1366.ipynb).
### Issue type

Bug

### Have you reproduced the bug with TensorFlow Nightly?

Yes

### Source

source

### TensorFlow version

tf2.13, 2.15.0-dev20230913

### Custom code

Yes

### OS platform and distribution

_No response_

### Mobile device

_No response_

### Python version

_No response_

### Bazel version

_No response_

### GCC/compiler version

_No response_

### CUDA/cuDNN version

_No response_

### GPU model and memory

_No response_

### Current behavior?

When a tensor has shape `(2,)`, `x.shape` returns `2`, and throws an error when I try to get `x.shape[0]`. Without `@tf.function(jit_compile=True)` it works well.

### Standalone code to reproduce the issue

```shell
class Model(tf.keras.Model):

  def __init__(self):
    super(Model, self).__init__()

  @tf.function(jit_compile=True)
  def call(self, x1):
    def select_2_or_one(x):
      print(x.shape)
      if int(x.shape[0]) == 2:
        return x
      else:
        return tf.stack([x,x])
    return tf.cond(tf.less(x1[0], x1[1]),
        lambda: select_2_or_one(x1),
        lambda: select_2_or_one(x1[0]))

m = Model()

input_shape = [2,]
x1 = tf.constant([2.,3.], shape=input_shape)

y = m(x1)
print(y)
```


### Relevant log output

```shell
if int(x.shape[0]) == 2:

    IndexError: tuple index out of range


Call arguments received by layer 'model_1' (type Model):
  • x1=tf.Tensor(shape=(2,), dtype=float32)
```
