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https://journalofinequalitiesandapplications.springeropen.com/articles/10.1186/s13660-017-1297-z
[ "# Optimal partial regularity of very weak solutions to nonhomogeneous A-harmonic systems\n\n## Abstract\n\nWe study partial regularity of very weak solutions to some nonhomogeneous A-harmonic systems. To obtain the reverse Hölder inequality of the gradient of a very weak solution, we construct a suitable test function by Hodge decomposition. With the aid of Gehring’s lemma, we prove that these very weak solutions are weak solutions. Further, we show that these solutions are in fact optimal Hölder continuity based on A-harmonic approximation technique.\n\n## Introduction\n\nWe consider optimal partial regularity of very weak solutions to nonhomogeneous A-harmonic systems of the following type:\n\n$$-\\operatorname{div} A(x,u,Du)=f(x),$$\n(1.1)\n\nwhere $$u:\\Omega \\rightarrow R^{N}$$ is a vector-valued function on a bounded domain $$\\Omega \\subset R^{n}$$ ($$n\\geqslant 2$$), and $$Du=\\{D_{ \\alpha} u^{i}\\}$$ ($$1\\leqslant \\alpha \\leqslant n,1\\leqslant i\\leqslant N$$) stands for the gradient matrix of u, $$A(x,u,\\xi ):\\Omega \\times R ^{N} \\times {R^{nN}\\rightarrow R^{nN}}$$ is a measurable function, and $$A_{i}^{\\alpha} (x,u,\\xi)$$ ($$1\\leqslant \\alpha \\leqslant n,1\\leqslant i\\leqslant N$$) are of class $$C^{1}$$ in ξ. To define the very weak solutions to systems (1.1) and obtain the optimal partial regularity results, we need to impose certain structural and regularity conditions on A and to restrict u and f to a particular class of functions as follows: for some $$p\\geqslant 2$$,\n\n1. (H1)\n\nA is a bounded operator, that is, there exists a constant $$\\beta >0$$ such that\n\n\\begin{aligned} \\bigl\\vert A(x,u,\\xi ) \\bigr\\vert \\leqslant \\beta \\bigl(1+\\vert \\xi \\vert ^{2} \\bigr)^{\\frac{p-1}{ 2} } \\quad \\mbox{for all } (x,u,\\xi )\\in \\Omega \\times R^{N} \\times R ^{nN}; \\end{aligned}\n2. (H2)\n\nA is differentiable with respect to $$\\xi \\in R^{nN}$$, that is, there exists a constant $$\\alpha >0$$ such that\n\n\\begin{aligned} D_{\\xi} A(x,u,\\xi )\\zeta \\cdot \\zeta \\geqslant \\alpha \\bigl(1+\\vert \\xi \\vert ^{2} \\bigr)^{ \\frac{{p-2}}{2 }}\\vert \\zeta \\vert ^{2} \\end{aligned}\n\nfor all $$x\\in \\Omega ,u\\in R^{N}$$, and $$\\xi ,\\zeta \\in R^{nN}$$;\n\n3. (H3)\n\nthere exist a constant $$\\gamma \\in (0,1)$$ and a nondecreasing function $$K: [0,\\infty )\\rightarrow [0,\\infty )$$ such that\n\n\\begin{aligned} \\bigl\\vert A(x,u,\\xi )-A(\\tilde{x},\\tilde{u},\\xi ) \\bigr\\vert \\leqslant K \\bigl(\\vert u \\vert \\bigr) \\bigl(\\vert x-\\tilde{x}\\vert ^{p}+ \\vert u-\\tilde{u}\\vert ^{p} \\bigr)^{\\frac{\\gamma }{p}} \\bigl(1+ \\vert \\xi \\vert \\bigr)^{\\frac{p}{2}} \\end{aligned}\n\nfor all $$x,\\tilde{x} \\in \\Omega ,u,\\tilde{u}\\in R^{N}$$ and $$\\xi \\in R^{nN}$$; without loss of generality, we take $$K \\geq 1$$;\n\n4. (H4)\n\nf is a given vector field in $$R^{N}$$ of class $$L_{\\mathrm{loc}}^{\\frac{nq}{n(p-1)+q}}(\\Omega )$$, $$q>p$$.\n\nUnder these assumptions, we can now define very weak solutions to (1.1).\n\n### Definition 1\n\nA mapping $$u\\in W_{\\mathrm{loc}}^{1,r}(\\Omega ),p-1\\leqslant r< p$$, is called a very weak solution to (1.1) if\n\n$$\\int_{\\Omega} A(x,u,Du)\\cdot D\\phi \\,dx= \\int_{\\Omega} f(x) \\phi \\,dx$$\n(1.2)\n\nfor all $$\\phi \\in W_{0}^{1,\\frac{r}{r-p+1}}(\\Omega )$$.\n\nIn order to improve the integrability of a very weak solution to (1.1), we need to prove a suitable reverse Hölder inequality. In 1973, Gehring discovered the crucial self-improving property of the reverse Hölder inequality and applied it to establish higher integrability of n-dimensional k-quasiconformal mapping. Subsequently, Meyers and Elcrat generalized this inequality based on Caccioppoli’s inequality. They improved the integrability of weak solutions to nonlinear elliptic systems with the help of Gehring’s lemma. Especially, they pointed out that regularity properties remained valid in a somewhat slightly larger Sobolev space to linear elliptic systems depending on the duality. In fact, this regularity result about very weak solutions was first showed by Meyers in 1963. Unfortunately, neither the method used in for proving the reverse Hölder inequality nor the duality employed in [2, 3] can be applied to deal with very weak solutions to nonlinear elliptic systems. To overcome these difficulties, Lewis used the technique of harmonic analysis and successfully proved that very weak solutions to nonlinear elliptic systems are indeed weak solutions. Later Iwaniec and Sbordone achieved a similar result via the methods of Hodge decomposition and prior estimation.\n\nSince then, studies on properties of very weak solutions to partial differential equations, especially for regularity of very weak solutions to A-harmonic systems, have attracted considerable attention. Following the method of Iwaniec and Sbordone , Giachetti, Leonetti, and Schiachi obtained the partial regularity result of A-harmonic systems $$\\operatorname{div} A (x,u,Du)=0$$. Tong, Gu, and Xu extended their result to nonhomogeneous A-harmonic systems $$\\operatorname{div} A(x,Du)=f(x)$$ and improved the integrability of very weak solutions. Greco, Iwaniec, and Sbordone even applied this method to the p-harmonic equation $$\\operatorname{div} \\vert Du \\vert ^{p-2}Du=\\operatorname{div} f$$.\n\nMotivated by these works, we mainly consider the optimal partial regularity to nonhomogeneous A-harmonic systems in the form of (1.1) under assumptions (H1)-(H4).\n\nFor the sake of desired results, we first need to improve the exponent of integrability for the gradient of a very weak solution to an even slightly better one than the natural exponent p. The crucial difficulty is to construct an appropriate test function below the natural exponent. In this article, we follow the spirit of Iwaniec and Sbordone using the Hodge decomposition to construct it. Combining the Sobolev imbedding theorem, Young’s inequality, Poincaré’s inequality, and so on, we improve the exponents of integrability of very weak solutions to (1.1). In other words, we successfully prove that very weak solutions to (1.1) are in fact weak solutions. More precisely, we obtain the following result.\n\n### Theorem 1\n\nLet u be a very weak solution to systems (1.1). Assume that the structure conditions (H1), (H2), and (H4) hold. Then there exist exponents $$p-1< r_{1}=r_{1}(n,N,p,\\alpha ,\\beta )< p< r_{2}=r_{2}(n,N,p, \\alpha ,\\beta )<\\infty$$ such that $$u\\in W_{\\mathrm{loc}}^{1,r_{1}}(\\Omega )$$ belongs to $$W_{\\mathrm{loc}}^{1,r_{2}}(\\Omega )$$.\n\nA direct consequence of this result follows immediately.\n\n### Corollary 1\n\nUnder the assumptions of Theorem  1, there exists $$r_{1}=r_{1}(n,N,p, \\alpha ,\\beta )< p$$ such that every very weak solution $$u\\in W_{\\mathrm{loc}} ^{1,r}(\\Omega )$$ with $$r_{1}< r< p$$ belongs to $$W_{\\mathrm{loc}}^{1,p}(\\Omega )$$.\n\nFurther, we establish the optimal partial regularity result of very weak solutions to (1.1). Generally speaking, we cannot expect that weak solutions to (1.1) will be $$C^{2}$$-solutions even under reasonable assumptions on operator A and f. This is initially pointed out by De Giorgi [9, 10] and Giusti and Miranda . Thus, our aim is to obtain the optimal Hölder continuity of very weak solutions to (1.1). Fortunately, we achieve it by means of A-harmonic approximation technique and obtain the optimal Hölder continuity $$C^{1,\\gamma }$$ in the regular set of the following:\n\n### Theorem 2\n\nLet $$u\\in W_{\\mathrm{loc}}^{1,r}(\\Omega )$$, $$r_{1}< r< p$$, be a very weak solution to (1.1). Consider $$r_{1}$$ as in Corollary  1. Suppose that assumptions (H1)-(H4) hold. Then there exists an open set $$\\Omega_{0}\\subset \\Omega$$ such that $$u\\in C^{1,\\gamma }(\\Omega_{0})$$ for γ is defined in (H3). We have\n\n\\begin{aligned} \\Omega -\\Omega_{0}=\\Sigma_{1}\\cup \\Sigma_{2}, \\end{aligned}\n\nwhere\n\n\\begin{aligned} \\Sigma_{1}= \\biggl\\{ x_{0} \\in \\Omega : \\hskip4pt \\liminf _{R \\to 0^{+}} \\fint_{B_{R}(x _{0})} \\bigl\\vert Du-(D u)_{x_{0},R} \\bigr\\vert ^{p} \\,dx >0 \\biggr\\} \\end{aligned}\n\nand\n\n\\begin{aligned} \\Sigma_{2}= \\Bigl\\{ x_{0} \\in \\Omega : \\hskip4pt \\limsup _{R \\to 0^{+}} \\bigl(\\vert u_{x_{0},R} \\vert + \\bigl\\vert (D u)_{x_{0},R} \\bigr\\vert \\bigr)= \\infty \\Bigr\\} . \\end{aligned}\n\nMoreover, we have $$\\vert \\Omega -\\Omega_{0} \\vert =0$$.\n\nTo close this section, we briefly summarize the notation used in this paper. As noted before, we consider a bounded domain $$\\Omega \\subset R ^{n}(n\\geqslant 2)$$ and mappings from Ω to $$R^{N}$$. We write $$B_{r}(x_{0})=\\{x\\in \\Omega : \\vert x-x_{0} \\vert < r\\},x_{0}\\in \\Omega$$. For a given set X, we denote by $$\\vert X \\vert$$ its n-dimensional Lebesgue measure. If $$\\vert X \\vert >0$$, then the average of a given $$g\\in L^{1}(X)$$ over X is denoted by $$\\fint_{X} g \\,dx$$, that is, $$\\fint_{X} g \\,dx=\\frac{1}{\\vert X \\vert }\\int_{X}g \\,dx$$. In particular, we write $$g_{x_{0},r}=\\fint_{B_{r}(x_{0})}g\\,dx$$. Let $$\\alpha_{n}$$ denote the volume of the unit ball in $$R^{n}$$, that is, $$\\alpha_{n}=\\vert B_{1}(0) \\vert$$, then $$\\vert B_{r}(x_{0}) \\vert =\\alpha_{n} r^{n}$$.\n\nThe rest of this paper is arranged as follows. In Section 2, we provide some necessary preliminary lemmas. In Section 3, we prove the main results.\n\n## Preliminary lemmas\n\nBefore proving the results, we state a few useful lemmas.\n\nThe first one is a stability result of the Hodge decomposition, from which we could construct a suitable test-function concerning estimates below the natural exponent for (1.1).\n\n### Lemma 1\n\n\n\nLet $$\\Omega \\subset R^{n}$$ be a regular domain, and $$w\\in W_{0} ^{1,r}(\\Omega ,R^{N}),r>1$$, and let $$-1<\\epsilon <r-1$$. Then there exist $$\\phi \\in W_{0}^{1, \\frac{r}{1+\\epsilon }}(\\Omega ,R^{N})$$ and a divergence-free matrix field $$H\\in L^{\\frac{r}{1+\\epsilon }}(\\Omega ,R ^{nN})$$ such that\n\n$$\\vert D w \\vert ^{\\epsilon} D w=D\\phi +H.$$\n(2.1)\n\nMoreover,\n\n$$\\Vert H \\Vert _{\\frac{r}{1+\\epsilon }}\\leqslant C_{r}( \\Omega , N)\\vert \\epsilon \\vert \\Vert D w \\Vert _{r}^{1+\\epsilon }.$$\n(2.2)\n\nThe most useful case for us in Lemma 1 is where ϵ is negative. For $$u\\in W_{\\mathrm{loc}}^{1,r}(\\Omega )$$ with $$p-1< r< p$$ that is a very weak solution to (1.1), we can set $$\\epsilon =r-p$$ $$(-1<\\epsilon <0)$$. Then there exists $$\\phi \\in W_{0}^{1,\\frac{r}{1+r-p}}(\\Omega )$$; thus, ϕ can be illustrated as a test-function in (1.2). In view of (2.1) and (2.2), we also can get an estimate of , which is similar to (2.2).\n\nApplying Lemma 2, we can decompose the left term of the Hodge decomposition into two terms that could be controlled more easily in the proof of Theorem 1.\n\n### Lemma 2\n\n\n\nFor every $$X, Y \\in R^{n}$$, $$X\\neq 0, Y\\neq 0$$, and $$0\\leqslant \\epsilon <1$$, we have the inequality\n\n\\begin{aligned} \\bigl\\vert \\vert X \\vert ^{-\\epsilon }X- \\bigr\\vert Y \\bigl\\vert ^{-\\epsilon }Y \\bigr\\vert \\leq 2^{\\epsilon} \\frac{1+ \\epsilon }{1-\\epsilon }\\vert X-Y \\vert ^{1-\\epsilon }. \\end{aligned}\n\nIn the end of this section, we shall introduce a form of Gehring’s lemma, which plays an important role in the proof of Theorem 1. It implies in particular that from it higher integrability of $$g(x)$$ follows.\n\n### Lemma 3\n\n[2, 13]\n\nLet $$0< R< R_{0}\\leqslant \\operatorname{dist} (x_{0},\\partial \\Omega ),x _{0}\\in \\Omega$$. Suppose that $$g(x)\\in L^{p} (B_{R}(x_{0}) )$$, $$f(x) \\in L^{t} (B_{R}(x_{0}) ),t>p,1< p<\\infty$$, satisfy the reverse Hölder inequality\n\n\\begin{aligned} \\fint_{B_{R/2}(x_{0})} \\bigl\\vert g(x) \\bigr\\vert ^{p}\\,dx \\leqslant \\theta \\fint_{B_{R}(x_{0})} \\bigl\\vert g(x) \\bigr\\vert ^{p}\\,dx +C^{*} \\biggl[ \\fint_{B_{R}(x_{0})} \\bigl\\vert g(x) \\bigr\\vert ^{s}\\,dx \\biggr]^{p/s} + \\fint_{B_{R}(x_{0})} \\bigl\\vert f(x) \\bigr\\vert ^{p}\\,dx \\end{aligned}\n\nfor some $$1\\leqslant s< p,0\\leqslant \\theta <1$$. Then $$g\\in L_{\\mathrm{loc}} ^{p'}(\\Omega )$$ for some $$p'=p'(\\theta ,p,n,C^{*})$$ $$(t\\geqslant p' >p)$$, and\n\n\\begin{aligned} \\biggl[ \\fint_{B_{R/2}(x_{0})} \\bigl\\vert g(x) \\bigr\\vert ^{p'}\\,dx \\biggr]^{1/{p'}} \\leqslant C_{*} \\biggl[ \\fint_{B_{R}(x_{0})} \\bigl\\vert g(x) \\bigr\\vert ^{p}\\,dx \\biggr]^{1/p} +C_{*} \\biggl[ \\fint_{B_{R}(x_{0})} \\bigl\\vert f(x) \\bigr\\vert ^{p'}\\,dx \\biggr]^{1/{p'}}, \\end{aligned}\n\nwhere $$C_{*}=C_{*}(n,C^{*},p,\\theta ,R_{0})$$.\n\n## Proof of the main theorems\n\nIn this section, we give a proof of partial regularity results. Consider u solving (1.1) on $$B_{R}(x_{0})\\Subset \\Omega$$, where we restrict $$0< R< R_{0}<\\min\\{1, \\operatorname{dist}(x_{0},\\partial \\Omega )\\}$$.\n\n### Proof\n\nFix a cut-off function $$\\eta \\in C_{0}^{\\infty }(B_{R}(x _{0}))$$ satisfying $$0\\leqslant \\eta \\leqslant 1$$, $$\\vert D \\eta \\vert \\leqslant C/R$$, and $$\\eta \\equiv 1$$ on $$B_{R/2}(x_{0})$$. Let $$u\\in W_{\\mathrm{loc}}^{1,r}(B _{R}(x_{0}))$$ with $$p-1< r< p$$ be a very weak solution to (1.1). Denote $$u-u_{x_{0},R}-p_{0}(x-x_{0})$$ by v, where $$p_{0}\\in R^{nN}$$. We find that v has calculus mean-value 0 on $$B_{R}(x_{0})$$, that is, $$v_{x_{0},R}=0$$. Notice that $$\\eta v \\in W_{0}^{1,r}(B_{R}(x_{0}))$$ and $$-1< r-p<0$$. Then there exist $$\\phi \\in W_{0}^{1,\\frac{r}{1+r-p}}(B _{R}(x_{0}))$$ and $$h\\in L^{\\frac{r }{{1+r-p}}}(B_{R}(x_{0}))$$ such that $$\\vert D(\\eta v) \\vert ^{r-p}D(\\eta v)=D \\phi +h$$ according to the Hodge decomposition. Thus, ϕ is admissible as a test-function in the definition of very weak solutions. Set $$-\\varepsilon =r-p$$ ($$-1<-\\varepsilon <0$$) for convenience. Then $$r=p-\\varepsilon$$, and we have\n\n$$\\bigl\\vert D(\\eta v) \\bigr\\vert ^{-\\varepsilon }D(\\eta v)=D \\phi +h,$$\n(3.1)\n\nwhere h satisfies\n\n$$\\Vert h \\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }}\\leqslant C_{r}( \\Omega ,N) \\varepsilon \\bigl\\Vert D (\\eta v) \\bigr\\Vert _{p-\\varepsilon }^{1-\\varepsilon }.$$\n(3.2)\n\nFurther, applying Poincaré’s inequality with constant $$C_{P}$$ and noting that $$v_{x_{0},R}=0$$, we get\n\n\\begin{aligned} \\bigl\\Vert D(\\eta v) \\bigr\\Vert _{p-\\varepsilon }^{1-\\varepsilon }& \\leqslant \\bigl(\\Vert vD\\eta \\Vert _{p-\\varepsilon }+\\Vert \\eta Dv \\Vert _{p-\\varepsilon } \\bigr)^{1-\\varepsilon } \\\\ &\\leqslant \\biggl(\\frac{C}{R}\\Vert v \\Vert _{p-\\varepsilon }+\\Vert Dv \\Vert _{p-\\varepsilon } \\biggr)^{1-\\varepsilon } \\\\ &\\leqslant \\bigl(CC_{P}^{\\frac{1}{p-\\varepsilon }}\\Vert Dv \\Vert _{p-\\varepsilon }+ \\Vert Dv \\Vert _{p-\\varepsilon } \\bigr)^{1-\\varepsilon } \\\\ &< \\bigl(1+C C_{P}^{\\frac{1}{p-\\varepsilon }} \\bigr)\\Vert Dv \\Vert _{p-\\varepsilon }^{1- \\varepsilon }. \\end{aligned}\n(3.3)\n\nIn view of (3.2) and (3.3), we have\n\n$$\\Vert h \\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }}\\leqslant C_{1} \\varepsilon \\Vert Dv \\Vert _{p-\\varepsilon }^{1-\\varepsilon },$$\n(3.4)\n\nwhere $$C_{1}=C_{r}(\\Omega ,N)(1+C C_{P}^{\\frac{1}{p-\\varepsilon }})$$.\n\nIn particular, combining (3.1) and (3.2), we find\n\n\\begin{aligned} \\Vert D\\phi \\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }} &= \\bigl\\Vert \\bigl\\vert D(\\eta v) \\bigr\\vert ^{-\\varepsilon }D(\\eta v)-h \\bigr\\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }} \\\\ &\\leqslant \\bigl\\Vert \\bigl\\vert D(\\eta v) \\bigr\\vert ^{-\\varepsilon }D( \\eta v) \\bigr\\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }}+ \\Vert h \\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }} \\\\ &\\leqslant \\bigl\\Vert D (\\eta v) \\bigr\\Vert _{p-\\varepsilon }^{1-\\varepsilon }+C_{r}( \\Omega ,N)\\varepsilon \\bigl\\Vert D (\\eta v) \\bigr\\Vert _{p-\\varepsilon }^{1-\\varepsilon } \\\\ &\\leqslant \\bigl(1+C_{r}(\\Omega ,N)\\varepsilon \\bigr) \\bigl\\Vert D (\\eta v) \\bigr\\Vert _{p-\\varepsilon }^{1-\\varepsilon }. \\end{aligned}\n\nSubstituting (3.3) into this estimate, we have\n\n$$\\Vert D\\phi \\Vert _{\\frac{p-\\varepsilon }{1-\\varepsilon }} \\leqslant C_{2}\\Vert Dv \\Vert _{p-\\varepsilon }^{1-\\varepsilon },$$\n(3.5)\n\nwhere $$C_{2}=(1+C_{r}(\\Omega ,N)\\varepsilon )(1+C C_{P}^{\\frac{1}{p- \\varepsilon }})$$.\n\nSince it is hard to estimate $$\\vert D(\\eta v) \\vert ^{-\\varepsilon }D(\\eta v)$$ directly, we set\n\n$$E(\\eta ,v)= \\bigl\\vert D(\\eta v) \\bigr\\vert ^{-\\varepsilon }D( \\eta v)-\\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta Dv,$$\n\nwhich by Lemma 2 yields\n\n$$\\bigl\\vert E(\\eta ,v) \\bigr\\vert \\leqslant 2^{\\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon }\\vert vD \\eta \\vert ^{1-\\varepsilon }.$$\n\nJoining $$E(\\eta ,v)$$ with (3.1), we arrive at\n\n\\begin{aligned} D\\phi =E(\\eta ,v)+\\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta Dv-h. \\end{aligned}\n\nInserting into equality (1.2), we get\n\n\\begin{aligned} & \\int_{B_{R}(x_{0})} A(x, u,Du)\\cdot \\vert \\eta Dv \\vert ^{-\\varepsilon } \\eta Dv \\,dx \\\\ &\\quad = \\int_{B_{R}(x_{0})} A(x, u,Du)\\cdot h\\,dx- \\int_{B_{R}(x_{0})} A(x, u,Du) \\cdot E(\\eta ,v)\\,dx+ \\int_{B_{R}(x_{0})} f(x) \\phi \\,dx. \\end{aligned}\n(3.6)\n\nIn order to use (H2), we need to transform the left-hand side of (3.6) as follows:\n\n\\begin{aligned} & \\int_{B_{R}(x_{0})} A(x, u,Du)\\cdot \\vert \\eta Dv \\vert ^{-\\varepsilon } \\eta Dv \\,dx \\\\ &\\quad = \\int_{B_{R}(x_{0})} \\bigl(A(x, u,Du)-A(x,u,p_{0})+A(x,u,p_{0}) \\bigr)\\cdot \\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta Dv\\,dx \\\\ &\\quad = \\int_{B_{R}(x_{0})} \\bigl(A(x, u,Du)-A(x,u, p_{0}) \\bigr) \\cdot \\vert \\eta Dv \\vert ^{- \\varepsilon }\\eta Dv\\,dx \\\\ &\\quad \\quad {}+ \\int_{B_{R}(x_{0})} A(x, u,p_{0})\\cdot \\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta Dv\\,dx. \\end{aligned}\n\nCombining this equality with (3.6), we find\n\n\\begin{aligned} & \\int_{B_{R}(x_{0})} \\bigl(A(x, u,Du)-A(x,u, p_{0}) \\bigr) \\cdot \\vert \\eta Dv \\vert ^{- \\varepsilon }\\eta Dv\\,dx \\\\ &\\quad =- \\int_{B_{R}(x_{0})} A(x, u,p_{0}) \\cdot \\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta Dv\\,dx+ \\int_{B_{R}(x_{0})}A(x,u,Du)\\cdot h\\,dx \\\\ &\\quad \\quad {}- \\int_{B_{R}(x_{0})} A(x, u,Du)\\cdot E(\\eta ,v)\\,dx + \\int_{B_{R}(x_{0})} f(x)\\phi \\,dx \\\\ &\\quad \\leqslant I_{1}+I_{2}+I_{3}+I_{4}, \\end{aligned}\n(3.7)\n\nwhere\n\n\\begin{aligned} &I_{1}= \\biggl\\vert -\\int_{B_{R}(x_{0})} A(x, u,p_{0})\\cdot \\vert \\eta Dv\\vert ^{-\\varepsilon}\\eta Dv\\,dx \\biggr\\vert ; \\\\ &I_{2}= \\biggl\\vert \\int_{B_{R}(x_{0})}A(x,u,Du)\\cdot h\\,dx \\biggr\\vert ; \\\\ &I_{3}= \\biggl\\vert - \\int_{B_{R}(x_{0})} A(x, u,Du)\\cdot E(\\eta ,v)\\,dx \\biggr\\vert ; \\\\ &I_{4}= \\biggl\\vert \\int_{B_{R}(x_{0})} f(x)\\phi \\,dx \\biggr\\vert . \\end{aligned}\n\nConsequently, we shall derive estimate for each term of (3.7) so as to establish a reverse Hölder inequality for $$\\vert Du-p_{0} \\vert ^{p-\\varepsilon }$$.\n\nIn the case of the term on the left-hand side of (3.7), we want to derive an estimate from below in terms of $$\\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon }\\,dx$$. For this purpose, we need the inequality\n\n$$\\bigl(A(x,u,\\zeta )-A(x,u,\\xi ) \\bigr)\\cdot (\\zeta -\\xi )\\geqslant \\alpha \\bigl(1+\\vert \\zeta \\vert ^{2}+\\vert \\xi \\vert ^{2} \\bigr)^{\\frac{p-2}{2}}\\vert \\zeta -\\xi \\vert ^{2},$$\n\nwhich can be deduced from (H2) immediately.\n\nThen we infer that\n\n\\begin{aligned} & \\int_{B_{R}(x_{0})} \\bigl(A(x, u,Du)-A(x,u, p_{0}) \\bigr) \\cdot \\vert \\eta Dv \\vert ^{- \\varepsilon }\\eta Dv\\,dx \\\\ &\\quad = \\int_{B_{R}(x_{0})} \\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta \\bigl(A(x, u,Du)-A(x,u, p_{0}) \\bigr)\\cdot (Du-p_{0})\\,dx \\\\ &\\quad \\geqslant \\alpha \\int_{B_{R}(x_{0})}\\vert \\eta Dv \\vert ^{-\\varepsilon }\\eta \\bigl(1+ \\vert Du \\vert ^{2}+\\vert p _{0} \\vert ^{2} \\bigr)^{\\frac{p-2}{2}} \\vert Du-p_{0}\\vert ^{2}\\,dx \\\\ &\\quad \\geqslant \\alpha \\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{2-\\varepsilon } \\biggl(1+\\frac{\\vert Du-p_{0} \\vert ^{2}}{2} \\biggr)^{\\frac{p-2}{2}}\\,dx \\\\ &\\quad \\geqslant 2^{\\frac{2-p}{2}}\\alpha \\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p- \\varepsilon } \\,dx. \\end{aligned}\n(3.8)\n\nUsing (H1) and Young’s inequality with exponents $$\\frac{p-\\varepsilon }{1-\\varepsilon }$$ and $$\\frac{p-\\varepsilon }{p-1}$$, we find that, for $$\\varepsilon_{1}>0$$,\n\n\\begin{aligned} I_{1}&\\leqslant \\int_{B_{R}(x_{0})} \\bigl\\vert A(x, u,p_{0}) \\bigr\\vert \\vert Dv \\vert ^{1-\\varepsilon }\\,dx \\\\ & \\leqslant \\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{1-\\varepsilon } \\,dx \\\\ & \\leqslant \\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\int_{B_{R}(x_{0})} \\bigl( \\varepsilon_{1}\\vert Du-p_{0} \\vert ^{p-\\varepsilon }+\\varepsilon_{1}^{-\\frac{1- \\varepsilon }{p-1}}1^{\\frac{p-\\varepsilon }{p-1}} \\bigr)\\,dx \\\\ & \\leqslant \\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{1} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad {}+\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{1}^{-\\frac{1- \\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx. \\end{aligned}\n(3.9)\n\nBy (H1) we have\n\n\\begin{aligned} I_{2} & \\leqslant \\int_{B_{R}(x_{0})} \\bigl\\vert A(x,u,Du) \\bigr\\vert \\vert h \\vert \\,dx \\\\ &\\leqslant \\beta \\int_{B_{R}(x_{0})} \\bigl(1+\\vert Du \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\vert h \\vert \\,dx \\\\ &\\leqslant \\beta \\int_{B_{R}(x_{0})} \\bigl(2+\\vert Du-p_{0}+p_{0} \\vert ^{2} \\bigr)^{ \\frac{p-1}{2}}\\vert h \\vert \\,dx \\\\ &\\leqslant \\beta \\int_{B_{R}(x_{0})} \\bigl(2 \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)+2\\vert Du-p_{0} \\vert ^{2} \\bigr)^{ \\frac{p-1}{2}}\\vert h \\vert \\,dx \\\\ &\\leqslant 2^{p-1}\\beta \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-1} \\vert h \\vert \\,dx+2^{p-1} \\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\int_{B_{R}(x_{0})}\\vert h \\vert \\,dx. \\end{aligned}\n\nApplying both Hölder’s inequality and Young’s inequality with exponents $$\\frac{p-\\varepsilon }{p-1}$$ and $$\\frac{p-\\varepsilon }{1- \\varepsilon }$$, by (3.4) we further have that, for $$\\varepsilon_{2}>0$$,\n\n\\begin{aligned} I_{2}&\\leqslant 2^{p-1}\\beta \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\biggr)^{\\frac{p-1}{p-\\varepsilon }} \\biggl( \\int_{B_{R}(x_{0})}\\vert h \\vert ^{\\frac{p- \\varepsilon }{1-\\varepsilon }}\\,dx \\biggr)^{\\frac{1-\\varepsilon }{p-\\varepsilon }} \\\\ &\\quad +2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\biggl( \\int_{B_{R}(x _{0})}1^{p-\\varepsilon }\\,dx \\biggr)^{\\frac{p-1}{p-\\varepsilon }} \\biggl( \\int_{B_{R}(x_{0})}\\vert h \\vert ^{\\frac{p-\\varepsilon }{1-\\varepsilon }}\\,dx \\biggr)^{\\frac{1- \\varepsilon }{p-\\varepsilon }} \\\\ &\\leqslant 2^{p-1}\\beta C_{1}\\varepsilon \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p _{0} \\vert ^{p-\\varepsilon } \\,dx \\biggr)^{\\frac{p-1}{p-\\varepsilon }} \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\biggr)^{\\frac{1-\\varepsilon }{p-\\varepsilon }} \\\\ &\\quad +2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}C_{1}\\varepsilon \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon }\\,dx \\biggr)^{\\frac{1-\\varepsilon }{p-\\varepsilon }} \\biggl(\\int_{B_{R}(x_{0})}\\,dx \\biggr)^{\\frac{p-1}{p-\\varepsilon }} \\\\ &\\leqslant 2^{p-1}\\beta C_{1}\\varepsilon \\int_{B_{R}(x_{0})}\\vert Du-p _{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad +2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}C_{1}\\varepsilon \\biggl( \\varepsilon_{2} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx+ \\varepsilon_{2}^{-\\frac{1-\\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx \\biggr) \\\\ &\\leqslant 2^{p-1}\\beta C_{1}\\varepsilon \\int_{B_{R}(x_{0})}\\vert Du-p _{0} \\vert ^{p-\\varepsilon }\\,dx+2^{p-1}\\beta \\bigl(1+ \\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}C _{1}\\varepsilon\\varepsilon_{2}^{-\\frac{1-\\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx \\\\ &\\quad +2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}C_{1}\\varepsilon \\varepsilon_{2} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx. \\end{aligned}\n(3.10)\n\nCombining (H1) and the estimate of $$E(\\eta ,v)$$, we find that\n\n\\begin{aligned} I_{3}&\\leqslant \\int_{B_{R}(x_{0})} \\bigl\\vert A(x, u,Du) \\bigr\\vert \\bigl\\vert E( \\eta ,v) \\bigr\\vert \\,dx \\\\ &\\leqslant \\int_{B_{R}(x_{0})} \\beta \\bigl(1+\\vert Du \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}2^{ \\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon }\\vert vD \\eta \\vert ^{1- \\varepsilon }\\,dx \\\\ &\\leqslant \\beta 2^{\\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon } \\biggl(\\frac{C}{R} \\biggr)^{1-\\varepsilon } \\int_{B_{R}(x_{0})} \\bigl(1+\\vert Du \\vert ^{2} \\bigr)^{ \\frac{p-1}{2}}\\vert v \\vert ^{1-\\varepsilon }\\,dx. \\\\ &\\leqslant \\beta 2^{\\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon } \\biggl(\\frac{C}{R}\\biggr)^{1-\\varepsilon } \\int_{B_{R}(x_{0})} \\bigl(2 \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)+2\\vert Du-p _{0}\\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\vert v \\vert ^{1-\\varepsilon } \\,dx \\\\ &\\leqslant \\beta 2^{\\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon } \\biggl(\\frac{C}{R} \\biggr)^{1-\\varepsilon }2^{p-1} \\int_{B_{R}(x_{0})} \\bigl( \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{ \\frac{p-1}{2}}+\\vert Du-p_{0} \\vert ^{p-1} \\bigr)\\vert v \\vert ^{1-\\varepsilon }\\,dx. \\end{aligned}\n\nDenoting $$\\beta 2^{\\varepsilon} \\frac{1+\\varepsilon }{1-\\varepsilon }( \\frac{C}{R})^{1-\\varepsilon }2^{p-1}$$ by $$C_{3}$$, we have\n\n$$I_{3} \\leqslant C_{3} \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}K_{1}+C_{3}K _{2},$$\n(3.11)\n\nwhere $$K_{1}=\\int_{B_{R}(x_{0})} \\vert v \\vert ^{1-\\varepsilon }\\,dx$$ and $$K_{2}=\\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-1}\\vert v \\vert ^{1-\\varepsilon }\\,dx$$. Let us estimate $$K_{1}$$ and $$K_{2}$$. Using Young’s inequality with exponents $$\\frac{p-\\varepsilon }{1-\\varepsilon }$$ and $$\\frac{p-\\varepsilon }{p-1}$$ and Poincaré’s inequality with constant $$C_{P}$$, we find that, for $$\\varepsilon_{3}>0$$,\n\n\\begin{aligned} K_{1} &\\leqslant \\int_{B_{R}(x_{0})} \\bigl(\\varepsilon_{3}\\vert v \\vert ^{p-\\varepsilon }+\\varepsilon_{3}^{-\\frac{1-\\varepsilon }{p-1}}1^{\\frac{p-\\varepsilon }{p-1}} \\bigr) \\,dx \\\\ &\\leqslant \\varepsilon_{3} \\int_{B_{R}(x_{0})}\\vert v \\vert ^{p-\\varepsilon }\\,dx+ \\varepsilon_{3}^{-\\frac{1-\\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx \\\\ &\\leqslant \\varepsilon_{3}C_{P} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p- \\varepsilon } \\,dx+\\varepsilon_{3}^{-\\frac{1-\\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx. \\end{aligned}\n(3.12)\n\nLetting $$p'=\\frac{n(p-\\varepsilon )}{(n+1-\\varepsilon )(p-1)}$$ and $$q'=\\frac{n(p-\\varepsilon )}{(n-p+1)(1-\\varepsilon )}$$, we see that $$1< p'<\\infty$$, $$1< q'<\\infty$$, and $$\\frac{1}{p'}+\\frac{1}{q'}=1$$. With the aid of Hölder’s inequality, we can estimate\n\n\\begin{aligned} K_{2} &\\leqslant \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{(p-1)p'} \\,dx \\biggr)^{ \\frac{1}{p'}} \\biggl( \\int_{B_{R}(x_{0})}\\vert v \\vert ^{(1-\\varepsilon )q'}\\,dx \\biggr)^{ \\frac{1}{q'}} \\\\ &\\leqslant \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p-\\varepsilon )}{n+1- \\varepsilon }} \\,dx \\biggr)^{\\frac{(n+1-\\varepsilon )(p-1)}{n(p-\\varepsilon )}} \\biggl( \\int_{B_{R}(x_{0})}\\vert v \\vert ^{\\frac{n(p-\\varepsilon )}{n-p+1}}\\,dx \\biggr)^{\\frac{(n-p+1)(1- \\varepsilon )}{n(p-\\varepsilon )}}. \\end{aligned}\n\nNow we set $$p''=\\frac{n(p-\\varepsilon )}{n+1-\\varepsilon }$$. Then $$\\frac{np''}{n-p''}=\\frac{n(p-\\varepsilon )}{n-p+1}$$. Using the Sobolev-Poincaré inequality with constant $$C_{s}$$, we get\n\n\\begin{aligned} K_{2} &\\leqslant C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p- \\varepsilon )}{n+1-\\varepsilon }} \\,dx \\biggr)^{\\frac{(n+1-\\varepsilon )(p-1)}{n(p- \\varepsilon )}} \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p-\\varepsilon )}{n+1- \\varepsilon }} \\,dx \\biggr)^{\\frac{(n+1-\\varepsilon )(1-\\varepsilon )}{n(p- \\varepsilon )}} \\\\ &\\leqslant C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p- \\varepsilon )}{n+1-\\varepsilon }} \\,dx \\biggr)^{\\frac{n+1-\\varepsilon }{n}}. \\end{aligned}\n(3.13)\n\nCombining (3.11) with (3.12) and (3.13), we obtain the estimate for $$I_{3}$$:\n\n\\begin{aligned} I_{3} &\\leqslant C_{3} \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}} \\varepsilon_{3}C _{P} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad {}+C_{3} \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{3}^{-\\frac{1- \\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx \\\\ &\\quad {}+C_{3} C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p- \\varepsilon )}{n+1-\\varepsilon }} \\,dx \\biggr)^{\\frac{n+1-\\varepsilon }{n}}. \\end{aligned}\n(3.14)\n\nFinally, we estimate $$I_{4}$$. Using Hölder’s inequality with exponents $$\\frac{n(p-\\varepsilon )}{n(p-1)+p-\\varepsilon }$$ and $$\\frac{n(p-\\varepsilon )}{n(1-\\varepsilon )-p+\\varepsilon }$$, we have\n\n\\begin{aligned} I_{4} & \\leqslant \\int_{B_{R}(x_{0})} \\bigl\\vert f(x) \\bigr\\vert \\vert \\phi \\vert \\,dx \\\\ & \\leqslant \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p- \\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-\\varepsilon )}} \\biggl( \\int_{B_{R}(x_{0})}\\vert \\phi \\vert ^{\\frac{n(p-\\varepsilon )}{n(1-\\varepsilon )-p+\\varepsilon }}\\,dx \\biggr)^{\\frac{n(1-\\varepsilon )-p+\\varepsilon }{n(p- \\varepsilon )}}. \\end{aligned}\n\nSetting $$p'''=\\frac{p-\\varepsilon }{1-\\varepsilon }$$, we have $$\\frac{np'''}{n-p'''}=\\frac{n(p-\\varepsilon )}{n(1-\\varepsilon )-p+ \\varepsilon }$$. Notice that $$\\phi \\in W_{0}^{1,\\frac{p-\\varepsilon }{1- \\varepsilon }}(B_{R}(x_{0}))$$. Therefore, we can apply the Sobolev-Poincaré inequality to get\n\n\\begin{aligned} I_{4}\\leqslant C_{s} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p- \\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-\\varepsilon )}} \\biggl( \\int_{B_{R}(x_{0})}\\vert D\\phi \\vert ^{\\frac{p-\\varepsilon }{1-\\varepsilon }}\\,dx \\biggr)^{\\frac{1- \\varepsilon }{p-\\varepsilon }}. \\end{aligned}\n\nCombining this with (3.5), with the aid of Young’s inequality, we obtain, for $$\\varepsilon_{4}>0$$,\n\n\\begin{aligned} I_{4}&\\leqslant C_{s} C_{2} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p- \\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-\\varepsilon )}} \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\biggr)^{\\frac{1- \\varepsilon }{p-\\varepsilon }} \\\\ &\\leqslant C_{s} C_{2} \\biggl(\\varepsilon_{4} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p- \\varepsilon } \\,dx+\\varepsilon_{4}^{-\\frac{1-\\varepsilon }{p-1}} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-1)}} \\biggr). \\end{aligned}\n(3.15)\n\nSubstituting (3.8), (3.9), (3.10), (3.14), and (3.15) into (3.7), we finally have\n\n\\begin{aligned} & 2^{\\frac{2-p}{2}}\\alpha \\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad \\leqslant \\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{1} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx+2^{p-1}\\beta C_{1} \\varepsilon \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad\\quad {}+2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}C_{1}\\varepsilon \\varepsilon_{2} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad \\quad {}+C_{3} \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{3}C_{P} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx +C_{s} C_{2} \\varepsilon_{4} \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad \\quad {}+C_{3} C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\frac{n(p- \\varepsilon )}{n+1-\\varepsilon }} \\,dx \\biggr)^{\\frac{n+1-\\varepsilon }{n}} \\\\ &\\quad \\quad {} +C _{s} C_{2} \\varepsilon_{4}^{-\\frac{1-\\varepsilon }{p-1}} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-1)}} \\\\ &\\quad\\quad {} +\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{1}^{-\\frac{1- \\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx+2^{p-1}\\beta \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{ \\frac{p-1}{2}}C_{1} \\varepsilon \\varepsilon_{2}^{-\\frac{1-\\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx \\\\ &\\quad \\quad {}+C_{3} \\bigl(1+\\vert p_{0} \\vert ^{2} \\bigr)^{\\frac{p-1}{2}}\\varepsilon_{3}^{-\\frac{1- \\varepsilon }{p-1}} \\int_{B_{R}(x_{0})}\\,dx. \\end{aligned}\n\nRearranging this inequality, we have\n\n\\begin{aligned} & \\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad \\leqslant \\theta \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx +\\frac{1}{ \\alpha }2^{\\frac{p-2}{2}}C_{3} C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x _{0})}\\vert Du-p_{0} \\vert ^{\\tau } \\,dx \\biggr)^{\\frac{p-\\varepsilon }{\\tau }} \\\\ &\\quad \\quad {}+\\frac{1}{\\alpha }2^{\\frac{p-2}{2}}C_{s} C_{2} \\varepsilon _{4}^{-\\frac{1-\\varepsilon }{p-1}} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p- \\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx \\biggr)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-1)}} +C_{4} \\int_{B_{R}(x_{0})}\\,dx, \\end{aligned}\n\nwhere $$\\theta =\\frac{1}{\\alpha }2^{\\frac{p-2}{2}}(\\beta (1+\\vert p_{0} \\vert ^{2})^{ \\frac{p-1}{2}}\\varepsilon_{1}+2^{p-1}\\beta C_{1}\\varepsilon +2^{p-1} \\beta (1+\\vert p_{0} \\vert ^{2})^{\\frac{p-1}{2}}C_{1}\\varepsilon \\varepsilon_{2}+C _{3} (1+\\vert p_{0} \\vert ^{2})^{\\frac{p-1}{2}} \\varepsilon_{3}C_{P}+C_{s} C_{2} \\varepsilon_{4})$$, $$\\tau =\\frac{n(p-\\varepsilon )}{n+1-\\varepsilon }$$, and $$C_{4}=\\frac{1}{\\alpha }2^{\\frac{p-2}{2}}(\\beta (1+\\vert p_{0} \\vert ^{2})^{ \\frac{p-1}{2}}\\varepsilon_{1}^{-\\frac{1-\\varepsilon }{p-1}}+2^{p-1} \\beta (1+\\vert p_{0} \\vert ^{2})^{\\frac{p-1}{2}}C_{1}\\varepsilon \\varepsilon_{2} ^{-\\frac{1-\\varepsilon }{p-1}}+C_{3}(1+\\vert p_{0} \\vert ^{2})^{\\frac{p-1}{2}} \\varepsilon_{3}^{-\\frac{1-\\varepsilon }{p-1}})$$.\n\nBy (H4) we get $$\\frac{n(p-\\varepsilon )}{n(p-1)+p-\\varepsilon }< \\frac{nq}{n(p-1)+q}$$ and $$\\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx< M$$.\n\nMoreover, we have $$(\\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p-\\varepsilon )}{n(p-1)+p- \\varepsilon }}\\,dx)^{\\frac{n(p-1)+p-\\varepsilon }{n(p-1)}}\\leqslant M ^{\\frac{p-\\varepsilon }{n(p-1)}}\\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n(p- \\varepsilon )}{n(p-1)+p-\\varepsilon }}\\,dx$$.\n\nSetting $$C_{5}=\\max \\{\\frac{1}{\\alpha }2^{\\frac{p-2}{2}}C_{s} C_{2} \\varepsilon_{4}^{-\\frac{1-\\varepsilon }{p-1}}M^{ \\frac{p-\\varepsilon }{n(p-1)}},C_{4}\\}$$, we have\n\n\\begin{aligned} & \\int_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\ &\\quad \\leqslant \\theta \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx +\\frac{1}{ \\alpha }2^{\\frac{p-2}{2}}C_{3} C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x _{0})}\\vert Du-p_{0} \\vert ^{\\tau } \\,dx \\biggr)^{\\frac{p-\\varepsilon }{\\tau }} \\\\ &\\quad\\quad {} +C_{5} \\biggl( \\int_{B_{R}(x_{0})}\\vert f \\vert ^{\\frac{n}{n(p-1)+p-\\varepsilon }(p-\\varepsilon )}\\,dx + \\int_{B_{R}(x_{0})}\\,dx \\biggr) \\\\ &\\quad \\leqslant \\theta \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx +\\frac{1}{ \\alpha }2^{\\frac{p-2}{2}}C_{3} C_{s}^{1-\\varepsilon } \\biggl( \\int_{B_{R}(x _{0})}\\vert Du-p_{0} \\vert ^{\\tau } \\,dx \\biggr)^{\\frac{p-\\varepsilon }{\\tau }} \\\\ &\\quad \\quad {}+C_{5} \\int_{B_{R}(x_{0})} \\bigl(\\vert f \\vert ^{\\frac{n}{n(p-1)+p-\\varepsilon }}+1 \\bigr)^{p-\\varepsilon }\\,dx. \\end{aligned}\n\nDividing both sides by $$\\vert B_{R}(x_{0}) \\vert =\\alpha_{n} R^{n}$$ yields\n\n\\begin{aligned}& \\fint_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx \\\\& \\quad \\leqslant 2^{n}\\theta - \\int_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{p-\\varepsilon } \\,dx +C_{6} \\biggl( \\fint_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\tau } \\,dx \\biggr)^{\\frac{p-\\varepsilon }{ \\tau }} \\\\& \\quad \\quad {}+2^{n}C_{5} \\fint_{B_{R}(x_{0})} \\bigl(\\vert f \\vert ^{\\frac{n}{n(p-1)+p-\\varepsilon }}+1 \\bigr)^{p- \\varepsilon }\\,dx, \\end{aligned}\n(3.16)\n\nwhere $$C_{6}=\\frac{2^{n}}{\\alpha }2^{\\frac{p-2}{2}}C_{3} C_{s}^{1- \\varepsilon }(\\alpha_{n}R^{n})^{\\frac{p-\\tau -\\varepsilon }{\\tau }}$$.\n\nTaking $$\\varepsilon ,\\varepsilon_{1},\\varepsilon_{2},\\varepsilon_{3}, \\varepsilon_{4}$$ sufficiently small such that $$2^{n}\\theta <1$$ and $$\\tau >1$$, we obtain the reverse Hölder inequality for $$\\vert Du-p_{0} \\vert ^{p- \\varepsilon }$$. Accordingly, by Lemma 2 we can derive that u belongs to $$W^{1,r'}_{\\mathrm{loc}}(\\Omega )$$ with $$r'>r$$. Since $$f\\in L_{\\mathrm{loc}}^{ \\frac{nq}{n(p-1)+q}}(\\Omega )$$, $$q>p$$, reasoning as before, we get a new estimate analogous to (3.16) with exponents $$r'$$ and $$\\tau '$$ in place of r, that is, $$p-\\varepsilon$$ and τ, respectively:\n\n\\begin{aligned}& \\fint_{B_{R/2}(x_{0})}\\vert Du-p_{0} \\vert ^{r'}\\,dx \\\\& \\quad \\leqslant 2^{n}\\theta ' \\fint_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{r'}\\,dx +C_{6}' \\biggl( \\fint_{B_{R}(x_{0})}\\vert Du-p_{0} \\vert ^{\\tau '}\\,dx \\biggr)^{\\frac{r'}{\\tau '}} \\\\& \\quad\\quad {} +2^{n}C_{5}' \\fint_{B_{R}(x_{0})} \\bigl(\\vert f \\vert ^{\\frac{n}{n(p-1)+r'}}+1 \\bigr)^{r'}\\,dx. \\end{aligned}\n\nTherefore, we get $$u\\in W^{1,r''}_{\\mathrm{loc}}(\\Omega )$$ with $$r''>r'$$. Repeating this process, we can improve the degree of integrability of Du again and again. Thus, it is clear that $$u\\in W^{1,t}_{\\mathrm{loc}}( \\Omega )$$ with any $$t\\in (r_{1},r_{2})$$.\n\nThis completes the proof of Theorem 1. □\n\n### Proof\n\nThe aim of Theorem 2 is to prove that very weak solutions to systems (1.1) are not only weak solutions to (1.1) but also the optimal Hölder continuity. In fact, under the assumptions of Theorem 1, we get that $$u\\in W_{\\mathrm{loc}}^{1,r}(\\Omega )$$ with $$r_{1}< r< p$$ are weak solutions $$u\\in W_{\\mathrm{loc}}^{1,p}(\\Omega )$$ to systems (1.1) by Corollary 1. Then we can safely infer $$u\\in C^{1,\\gamma }(\\Omega_{0})$$ based on A-harmonic approximation technique. The proving method is standard, so we omit the process of derivation in this paper. For more details, we refer the reader to Theorem 1.1 of and the related literature. So the proof of Theorem 2 is complete. □\n\n## References\n\n1. Gehring, FW: The $$L^{p}$$-integrability of the partial derivatives of a quasiconformal mapping. Acta Math. 130, 265-277 (1973)\n\n2. Meyers, N, Elcrat, A: Some results on regularity for solutions of non-linear elliptic systems and quasi-regular functions. Duke Math. J. 42(1), 121-136 (1975)\n\n3. Meyers, N: An $$L^{p}$$-estimate for the gradient of solutions of second order elliptic divergence equations. Ann. Sc. Norm. Super. Pisa, Cl. Sci. 17, 189-206 (1963)\n\n4. Lewis, JL: On the very weak solutions of certain elliptic systems. Commun. Partial Differ. Equ. 18, 1515-1537 (1993)\n\n5. Iwaniec, T, Sbordone, C: Weak minima of variational integrals. J. Reine Angew. Math. 454, 143-161 (1994)\n\n6. Giachetti, D, Leonetti, F, Schiachi, R: On the regularity of very weak minimal. Proc. R. Soc. Edinb. A 126, 287-296 (1996)\n\n7. Tong, YX, Gu, JT, Xu, XJ: Regularity for very weak solutions to A-harmonic equation. Appl. Math. J. Chin. Univ. Ser. A 24(3), 319-323 (2009)\n\n8. Greco, L, Iwaniec, T, Sbordone, C: Inverting the p-harmonic operator. Manuscr. Math. 92, 249-258 (1997)\n\n9. De Giorgi, E: Frontiere orientate di misura minima. Seminaro Mat. Scuola Norm. Sup. Pisa. Editrice Tecnico Scientifica, Pisa (1961)\n\n10. De Giorgi, E: Un esempio di estremali discontinue per un problema variazionale di tipo ellitico. Boll. Unione Mat. Ital. 4, 135-137 (1968)\n\n11. Giusti, E, Miranda, M: Sulla regolarità delle soluzioni deboli di una classe di sistemi ellittici quasi-lineari. Arch. Ration. Mech. Anal. 31, 173-184 (1968)\n\n12. Iwaniec, T, Migliaccio, L, Nania, L, Sbordone, C: Integrability and removability results for quasiregular mappings in high dimensions. Math. Scand. 75(2), 263-279 (1994)\n\n13. Giaquinta, M: Multiple Integrals in the Calculus of Variations and Nonlinear Elliptic Systems. Princeton University Press, Princeton (1983)\n\n14. Chen, SH, Tan, Z: Optimal interior partial regularity for nonlinear elliptic systems under the natural growth condition: the method of A-harmonic approximation. Acta Math. Sci. 27B(3), 491-508 (2007)\n\n## Acknowledgements\n\nThe authors would like to thank the anonymous referee for careful reading the manuscript and valuable comments. This work was supported by the National Natural Science foundation of China under Grant No. 11571159.\n\n## Author information\n\nAuthors\n\n### Corresponding author\n\nCorrespondence to Qing Zhao.\n\n### Competing interests\n\nThe authors declare that they have no competing interests.\n\n### Authors’ contributions\n\nBoth authors contributed equally to writing of this paper. Both authors read and approved the final manuscript.\n\n## Rights and permissions", null, "" ]
[ null, "https://journalofinequalitiesandapplications.springeropen.com/track/article/10.1186/s13660-017-1297-z", null ]
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http://archive.numdam.org/book-part/AST_1992__207__35_0/
[ "Spectral theory of elliptic operators on non-compact manifolds\nMéthodes semi-classiques Volume 1 - École d'Été (Nantes, juin 1991), Astérisque no. 207  (1992), p. 35-108\n@incollection{AST_1992__207__35_0,\nauthor = {Shubin, M. A.},\ntitle = {Spectral theory of elliptic operators on non-compact manifolds},\nbooktitle = {M\\'ethodes semi-classiques Volume 1 - \\'Ecole d'\\'Et\\'e (Nantes, juin 1991)},\nauthor = {Collectif},\nseries = {Ast\\'erisque},\npublisher = {Soci\\'et\\'e math\\'ematique de France},\nnumber = {207},\nyear = {1992},\npages = {35-108},\nlanguage = {en},\nurl = {http://www.numdam.org/item/AST_1992__207__35_0}\n}\n\nShubin, M. A. Spectral theory of elliptic operators on non-compact manifolds, in Méthodes semi-classiques Volume 1 - École d'Été (Nantes, juin 1991), Astérisque, no. 207 (1992), pp. 35-108. http://www.numdam.org/item/AST_1992__207__35_0/\n\n S. Agmon, On the eigenfunctions and on the eigenvalues of general elliptic boundary value problems, C.P.A.M. 15 (1) (1962), 119-147.\n\n M. S. Agranovich, M. I. Vishik, Elliptic problems with a parameter and parabolic problems of general type. Russian Math. Surveys 19 (1964), no. 3, 53-157.\n\n M. Atiyah, R. Bott, A Lefschetz fixed point formula for elliptic complexes I., Ann. of Math. 86 (1967), 374-407.\n\n Yu M. Berezanski, Expansions in Eigenfunctions of Selfadjoint Operators. AMS Translation of Math. Monographs, Providence, Rhode Island, 1968.\n\n F. A. Berezin, M. A. Shubin, The Schrödinger Equation. Kluwer, Dordrecht, 1991.\n\n R. Brooks, The fundamental group and the spectrum of the Laplacian. Comment. Math. Helv., 56 (1981), 581-598.\n\n F. E. Browder, On the spectral theory of elliptic differential operators. I, Math. Ann. 142 (1) (1960-61), 22-130.\n\n J. Cheeger, M. Gromov, M. Taylor, Finite propagation speed, kernel estimates for functions of the Laplace operator and the geometry of complete Riemannian manifolds. J. Diff. Geom. 17 (1982), 15-53.\n\n P. Chernoff, Essential self-adjointness of powers of generators of hyperbolic equations. J. Funct. Anal. 12 (1973), 401-414.\n\n H. O. Cordes, Self-adjointness of powers of elliptic operators on non-compact manifolds. Math. Ann., 195 (1972), 257-272.\n\n H. L. Cycon, R. G. Froese, W. Kirsch, B. Simon, Schrödinger operators. Springer, Berlin e.a., 1987.\n\n E. B. Davies, ${L}^{1}$-properties of second order elliptic operators, Bull. London Math. Soc. 17 (5) (1985), 417-436.\n\n K. O. Friedrichs, Symmetric hyperbolic linear differential equations. Comm. Pure Appl. Math. 7 (1954), 345-392.\n\n M. P. Gaffney, The harmonic operator for exterior differential forms. Proc. Nat. Acad. Sci. USA, 37 (1951), 48-50.\n\n M. P. Gaffney, A special Stokes's theorem for complete Riemannian manifolds. Ann. of Math. 60 (1954), 140-145.\n\n M. P. Gaffney, Hilbert space methods in the theory of harmonic integrals. Transactions Amer. Math. Soc., 78 (1955), 587-665.\n\n I. M. Gelfand, A. G. Kostyuchenko, Expansion in eigenfunctions of differential and other operators. Dokl. Akad. Nauk SSSR, 103 (1955), 349-352.\n\n I. M. Glazman, Direct Methods of Qualitative Spectral Analysis of Singular Differential Operators. Israel Program for Scientific Translation, Jerusalem 1965.\n\n M. Gromov, Curvature, diameter and Betti numbers. Comment Math. Helvetici 56 (1981), 179-195.\n\n M. Gromov, Structures métriques pour les variétés Riemanniennes, CEDIC/Fernand Nathan (1981).\n\n M. Gromov, H. B. Lawson, Positive scalar curvature and the Dirac operator on complete Riemannian manifolds. Publications Mathématiques, 58 (1983), 83-196.\n\n L. Hörmander. The analysis of linear partial differential operators. Berlin e.a., Springer-Verlag, vol. 1, 2 (1983)\n\nL. Hörmander. The analysis of linear partial differential operators. Berlin e.a., Springer-Verlag, vol. 3, 4 (1985).\n\n T. Ikebe, T. Kato, Uniqueness of the self-adjoint extension of singular elliptic differential operators. Arch. Rath. Mech. Anal. 9 (1962), 77-92.\n\n T. Kato, A remark to the preceding paper by Chernoff. J. Funct. Anal., 12 (1973), 415-417.\n\n T. Kato, ${L}^{p}$-theory of Schrödinger operators with a singular potential, In: Aspects of positivity in functional analysis-Proc. of a Conference in Tubingen, North Holland, Math. Studies 122 (1986), 63-78.\n\n T. Kobayashi, K. Ono, T. Sunada. Periodic Schrödinger operators on a manifold. Forum Math. 1 (1989), 69-79.\n\n Yu. A. Kordyukov. ${L}^{p}$-theory of elliptic differential operators with bounded coefficients. Vestnik Moskovskogo Universiteta, Ser. I Math. Mech. 1988, N° 4, 98-100 (in Russian).\n\n Yu. A. Kordyukov. Elliptic operators on manifolds of bounded geometry. Thesis, Moscow State University, 1987 (in Russian).\n\n G. A. Meladze, M. A. Shubin. Properly supported uniform pseudo-differential operators on unimodular Lie groups. Trudy Sem. Petrovskogo 11 (1986), 74-97\n\nG. A. Meladze, M. A. Shubin. Functional calculus of pseudo-differential operators on unimodular Lie groups. Trudy Sem. Petrovskogo 12 (1987), 164-200 (in Russian).\n\n I. M. Oleinik. On the essential self-adjointness of the Schrodinger operator on complete Riemannian manifolds. Preprint, 1991 (in Russian).\n\n A. Ja. Povzner. On the expansion of arbitrary functions in characteristic functions of the operator $-\\Delta u+cu$, Mat. Sb. 32 (74) (1953), 109-156; English transl.: AMS Transl. (2) 60 (1966), 1-49.\n\n M. Reed, B. Simon. Methods of Modern Mathematical Physis. I: Functional Analysis. Academic Press, New York e.a., 1980.\n\nM. Reed, B. Simon. Methods of Modern Mathematical Physis. II: Fourier Analysis, Self-Adjointness. Academic Press, New York e.a., 1975.\n\n J. Roe. An index theorem on open manifolds. I. II. J. Diff. Geom. 27 (1988), 87-113, 115-136.\n\n W. Roelcke. Über den Laplace-Operator auf Riemannschen Mannigfaltigkeiten mit diskontinuerlichen Gruppen. Math. Nachr., 21 (1960), 132-149.\n\n F. S. Rofe-Beketov. Deficiency indices and properties of spectum of some classes of differential operators. In: Spectral Theory and Differential Equations (Proc. Sympos., Dundee, 1974, dedicated to Konrad Jörgens). Lect. Notes Math., 448 (1975), 273-293.\n\n F. S. Rofe-Beketov. Square-integrable solutions, self-adjoint extensions and spectrum of differential systems. In: Differ. Equations (Proc. Intern. Conf., Uppsala, 1977)\n\nF. S. Rofe-Beketov. Square-integrable solutions, self-adjoint extensions and spectrum of differential systems. In: Sympos. Univ. Upsaliensis Ann. Quingentesimum Celebrantis, No. 7, Almquist & Wiksell, Stockholm, 1977, 169-178.\n\n F. S. Rofe-Beketov, A. M. Hol'Kin. Conditions for the self-adjointness of second order elliptic operators of general form. Teor. Funkcii i Funkcional. Anal. i Priložen. 17 (1973), 41-51.\n\n E. Schnol. On the behaviour of the Schrödinger equation. Mat. Sbornik 42 (1957), 273-286 (in Russian).\n\n D. B. Sears. Note on the uniqueness of Green's functions associated with certain differential equations. Canadian J. Math. 2 (1950), 314-325.\n\n R. Seeley, Complex powers of elliptic operators, Proc. Symp. Pure Math. 10 (1967), 288-307.\n\n M. A. Shubin. Pseudodifferential Operators and Spectral Theory. Springer-Verlag, Berlin e.a., 1987.\n\n M. A. Shubin. Theorems on the coincidence of the spectra of a pseudo-differential almost periodic operator in the spaces ${L}^{2}\\left({ℝ}^{n}\\right)$ and ${B}^{2}\\left({ℝ}^{n}\\right)$. Sibirsk. Mat. Zh. 17 (1976), no. 1, 200-215.\n\n M. A. Shubin. Pseudodifference operators and their Green's functions. Math. USSR Izvestiya 26 (1986), no. 3, 605-622.\n\n M. A. Shubin. Weak Bloch property and weight estimates for elliptic operators. Séminaire Equations aux derivées partielles, 1989-1990, École Polytechnique, Exposé n. V.\n\n M. A. Shubin, J. Sjöstrand, On the equality between weak and strong extensions. Séminaire Equations aux derivées partielles, 1989-1990, École Polytechnique, Appendix a l'Exposé n. V.\n\n H. B. Stewart, Generation of analytic semigroups by strongly elliptic operators, Trans. A.M.S., 199 (1) (1974), 141-162.\n\n R. S. Strichartz, ${L}^{p}$-contractive projections and the heat semigroup for differential forms, J. Funct. Anal., 65 (3) (1986), 348-357.\n\n E. C. Titchmarsh. Eigenfunction expansions associated with second-order differential equations. Part II. Oxford, 1958.\n\n E. Wienholtz. Halbbeschränkte partielle Differentialoperatoren zweiter Ordnung vom elliptischen Typus. Math. Ann. 135 (1958), 50-80." ]
[ null ]
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https://simpliengineering.com/t/steel-pipe-maximum-bending-moment/2437
[ "", null, "# Steel Pipe Maximum Bending Moment\n\nQUESTION\nI am sorry for asking such a fundamental question. I have forgotten Strength of Material Basics that I studied in 1st Yr. I just want to know what is the formula for maximum bending moment for a steel pipe?\n\nI am not too sure exactly about the conditions. It is a 6\" subsea pipeline between Well Head Platform and Production Platform with risers installed at both ends. I would like to know bending moment for subsea pipeline as well as the riser. I don’t know in which category this would come. Is it possible to determine or some more information is necessary?\n\nI have read in a technical document, that for initial calculation Max Bending Moment can be estimated as 0.85 times SMYS. So my question is how can i get Bending Moment if I know SMYS because SMYS is a stress with units in MPa and Bending Moment units is in Kilo Newton Metre.\n\nI am doing wall thickness calculation based on DNV-OS-F-101. In the spreadsheet, for load interaction, I need to put the value of ME (Maximum Bending Moment due to Environmental load). I know I can get the exact value once I do Dynamic Pipeline Analysis, but initially I must assume certain value to put in the spreadsheet, as based on that spreadhsheet, will give the result whether the assumed thickness is ok or not. From yielding stress, how can I get limiting moment capacity (even though it may not be too useful). In the reference document that I am mentioning, they have arrived at the value of Max Bending bending of arnd 50kNm for 6\" pipeline (Grade X-52;SMYS=359Mpa) by taking it 0.85 X Yield Stress.\n\nREPLIES\n\npatswfc\nMoment capacity of pipe = yield stress x elastic section modulus of pipe.\n\nelastic section modulus of pipe = I/y\n\nI = pi(d4 - (d - 2t)4) / 64 , the two 4’s are to the power of 4\n\ny = d/2\n\nSOURCE" ]
[ null, "https://simpliengineering.com/uploads/default/original/1X/464e1a7fc53c30c8b37f1750c02df1ea62a1611b.svg", null ]
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https://discuss.pytorch.org/t/error-for-converting-numpy-images-to-tensor/112883
[ "# Error for converting numpy images to tensor\n\nI use the Opencv to read images, and then convert them to tensor to feed DNN for inference. The reason is that I need to use Opencv to handle the images and then DNN inference. However, when I use transforms to preprocess the images. It gives the error: “ValueError: pic should be 2/3 dimensional. Got 4 dimensions.”\nThe code is\n\n``````for index in range(len(datasets)):\nimg = datasets[index]\nframe = frame * (1/255)\nframe = cv2.resize(frame , (224, 224))\nframe = np.transpose(frame , (2, 0, 1))\nif index == 0:\nframes = frame\ncontinue\nframes = np.stack((frames , frame))\n\ntransform = transforms.Compose([\ntransforms.ToTensor(),\ntransforms.Normalize(mean=[0.485, 0.456, 0.406], std=[0.229, 0.224, 0.225])\n])\n\nframes = transform(frames ).to('cuda')\n``````\n\nThen it has the error “ValueError: pic should be 2/3 dimensional. Got 4 dimensions.” The shape of frames is (2, 3, 224, 224). 2 is the number of batches.\n\nI don’t know how to deal with this error. Thank you for any help.\n\nThe `ToTensor` tfm is expecting a channel last image, this works:\n\n``````transform(np.random.random((224,244, 3)))\n``````\n\nit is also not expecting a batch. From the dos:\n\nConvert a `PIL Image` or `numpy.ndarray` to tensor.\n\nIt expects one PIL image.\n\nLet me show some examples\n\nexample 1: use OpenCV and do transforms for each image\n\n``````transform = transforms.Compose([\ntransforms.ToTensor(),\ntransforms.Normalize(mean=[0.485, 0.456, 0.406], std=[0.229, 0.224, 0.225])\n])\nframes = []\nfor index in range(2):\nframe = (np.random.rand(256, 256, 3) * 255).astype(np.uint8)\n\n# resize image\nframe = frame * (1/255)\nframe = cv2.resize(frame, (224, 224))\nframe = transform(frame)\nif index == 0:\nframes = [frame]\ncontinue\nframes.append(frame)\n\nframes = torch.stack(frames)\n``````\n\nexample 2: use OpenCV and do transform after collecting all images\n\n``````frames = []\nfor index in range(2):\nframe = (np.random.rand(256, 256, 3) * 255).astype(np.uint8)\n\n# resize image\nframe = frame * (1/255)\nframe = cv2.resize(frame, (224, 224))\nframe = np.transpose(frame, (2, 0, 1))\nif index == 0:\nframes = [frame]\ncontinue\nframes.append(frame)\n\nframes = np.stack(frame, axis=0)\n# transform\nmean, std = torch.tensor([0.485, 0.456, 0.406]), torch.tensor([0.229, 0.224, 0.225])\nframes = (torch.from_numpy(frames) - mean[None, :, None, None]) / std[None, :, None, None]\n``````" ]
[ null ]
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http://consulask.it/pos91y77o27ozyj63l.php
[ "", null, "## Lavoro intellettuale o manuale\n\n(We then say the number is an even number. lavkro For example, in the number 236, the last. Digit is 6. Since 6 is divisible by 2 (6 247; 2 3), 236 is divisible by. A number is divisible by 3 if the sum of all the. Digits is divisible Let us take a number that does not end with zeros, for example, 916. This number can be pdf for sample fresno employment test county like the sum 900 16. Because both the addends are divisible by 4, their sum. 916 is also divisible by 4. On the contrary, 918 is not divisible by 4 because 918 900 18 and one of. The addends (18) is not divisible …Textbook solution for A Transition to Advanced Mathematics 8th Edition Douglas Smith Chapter 1. 7 Problem 3E. We have step-by-step solutions for your textbooks written by Bartleby inte,lettuale. 24, 2010Feb 01, 2020The sum inside the first brackets is divisible by 9 because all the addends see more divisible by 9. If the sum in the second brackets (3 2 4) is also divisible by 9, then the whole sum, 324. Is divisible by 9. Since the sum 3 2 4 is divisible by 9, we conclude that 324 is also divisible. By 9." ]
[ null, "http://consulask.it/img/blog/main-blog/m-blog-1.jp", null ]
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https://www.geeksforgeeks.org/count-numbers-divisible-m-given-range/?ref=rp
[ "# Count the numbers divisible by ‘M’ in a given range\n\n• Difficulty Level : Medium\n• Last Updated : 26 Oct, 2021\n\nA and B are two numbers which define a range, where A <= B. Find the total numbers in the given range [A … B] divisible by ‘M’\nExamples:\n\n```Input : A = 25, B = 100, M = 30\nOutput : 3\nExplanation : In the given range [25 - 100],\n30, 60 and 90 are divisible by 30\n\nInput : A = 6, B = 15, M = 3\nOutput : 4\nExplanation : In the given range [6 - 15],\n6, 9, 12 and 15 are divisible by 3```\n\nAttention reader! Don’t stop learning now. Get hold of all the important mathematical concepts for competitive programming with the Essential Maths for CP Course at a student-friendly price. To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.\n\nMethod 1 : [Brute-force]\nRun a loop from A to B. If a number divisible by ‘M’ is found, increment counter.\nBelow is the implementation of above method:\n\n## C++\n\n `// Program to count the numbers divisible by``// M in a given range``#include ``using` `namespace` `std;` `int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``{``    ``// Variable to store the counter``    ``int` `counter = 0;` `    ``// Running a loop from A to B and check``    ``// if a number is divisible by M.``    ``for` `(``int` `i = A; i <= B; i++)``        ``if` `(i % M == 0)``            ``counter++;` `    ``return` `counter;``}` `// Driver code``int` `main()``{``    ``// A and B define the range, M is the dividend``    ``int` `A = 30, B = 100, M = 30;` `    ``// Printing the result``    ``cout << countDivisibles(A, B, M) << endl;` `    ``return` `0;``}`\n\n## Java\n\n `// Java program to count the numbers divisible by``// M in a given range``import` `java.io.*;` `class` `GFG {``    ``// Function to count the numbers divisible by``    ``// M in a given range``    ``static` `int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``    ``{``        ``// Variable to store the counter``        ``int` `counter = ``0``;` `        ``// Running a loop from A to B and check``        ``// if a number is divisible by M.``        ``for` `(``int` `i = A; i <= B; i++)``            ``if` `(i % M == ``0``)``                ``counter++;` `        ``return` `counter;``    ``}` `    ``// driver program``    ``public` `static` `void` `main(String[] args)``    ``{``        ``// A and B define the range, M is the dividend``        ``int` `A = ``30``, B = ``100``, M = ``30``;` `        ``// Printing the result``        ``System.out.println(countDivisibles(A, B, M));``    ``}``}` `// Contributed by Pramod Kumar`\n\n## Python3\n\n `# Program to count the numbers``# divisible by M in a given range` `def` `countDivisibles(A, B, M):``    ` `    ``# Variable to store the counter``    ``counter ``=` `0``;` `    ``# Running a loop from A to B``    ``# and check if a number is``    ``# divisible by M.``    ``for` `i ``in` `range``(A, B):``        ``if` `(i ``%` `M ``=``=` `0``):``            ``counter ``=` `counter ``+` `1` `    ``return` `counter` `# Driver code``# A and B define the range,``# M is the dividend``A ``=` `30``B ``=` `100``M ``=` `30` `# Printing the result``print``(countDivisibles(A, B, M))` `# This code is contributed by Sam007.`\n\n## C#\n\n `// C# program to count the numbers``// divisible by M in a given range``using` `System;` `public` `class` `GFG {` `    ``// Function to count the numbers divisible by``    ``// M in a given range``    ``static` `int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``    ``{``        ``// Variable to store the counter``        ``int` `counter = 0;` `        ``// Running a loop from A to B and check``        ``// if a number is divisible by M.``        ``for` `(``int` `i = A; i <= B; i++)``            ``if` `(i % M == 0)``                ``counter++;` `        ``return` `counter;``    ``}` `    ``// driver program``    ``public` `static` `void` `Main()``    ``{``        ``// A and B define the range, M is the dividend``        ``int` `A = 30, B = 100, M = 30;` `        ``// Printing the result``        ``Console.WriteLine(countDivisibles(A, B, M));``    ``}``}` `// This code is contributed by Sam007`\n\n## PHP\n\n ``\n\n## Javascript\n\n ``\n\nOutput:\n\n`3`\n\nMethod 2 : [Better]\nThe loop can be modified by incrementing the iterator ‘M’ times after the first divisible is found. Also, if ‘A’ is less than ‘M’, it can be changed to ‘M’, because a number less than ‘M’ can not be divided by it.\nMethod 3 : [Efficient]\n\n```Let B = b * M and\nA = a * M\nThe count of numbers divisible by\n'M' between A and B will be equal\nto b - a.\n\nExample:\nA = 25, B = 70, M = 10.\nNow, a = 2, b = 7.\nCount = 7 - 2 = 5.```\n\nIt can be observed that, if A is divisible by M, ‘b – a’ will exclude the count for A, so the count will be less by 1. Thus, in this case we add 1 explicitly.\nExample when A is divisible by M:\n\n```A = 30, B = 70, M = 10.\nNow, a = 3, b = 7.\nCount = 7 - 3 = 4.\nBut, Count should be 5. Thus, we will\n\nBelow is the implementation of the above method :\n\n## C++\n\n `// C++ program to count the numbers divisible by``// M in a given range``#include ``using` `namespace` `std;` `// Function to count the numbers divisible by``// M in a given range``int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``{``  ` `    ``// Add 1 explicitly as A is divisible by M``    ``if` `(A % M == 0)``        ``return` `(B / M) - (A / M) + 1;` `    ``// A is not divisible by M``    ``return` `(B / M) - (A / M);``}` `// driver program``int` `main()``{``  ` `    ``// A and B define the range, M is the dividend``    ``int` `A = 30, B = 100, M = 30;` `    ``// Printing the result``    ``cout << (countDivisibles(A, B, M));``}` `// This code is contributed by subham348.`\n\n## Java\n\n `// Java program to count the numbers divisible by``// M in a given range``import` `java.io.*;` `class` `GFG {``    ``// Function to count the numbers divisible by``    ``// M in a given range``    ``static` `int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``    ``{``        ``// Add 1 explicitly as A is divisible by M``        ``if` `(A % M == ``0``)``            ``return` `(B / M) - (A / M) + ``1``;` `        ``// A is not divisible by M``        ``return` `(B / M) - (A / M);``    ``}` `    ``// driver program``    ``public` `static` `void` `main(String[] args)``    ``{``        ``// A and B define the range, M is the dividend``        ``int` `A = ``30``, B = ``100``, M = ``30``;` `        ``// Printing the result``        ``System.out.println(countDivisibles(A, B, M));``    ``}``}` `// Contributed by Pramod Kumar`\n\n## Python3\n\n `# Program to count the numbers divisible``# by M in a given range` `# Returns count of numbers in [A B] that``# are divisible by M.``def` `countDivisibles(A, B, M):``    ` `    ``# Add 1 explicitly as A is divisible by M``    ``if` `(A ``%` `M ``=``=` `0``):``        ``return` `((B ``/` `M) ``-` `(A ``/` `M)) ``+` `1` `    ``# A is not divisible by M``    ``return` `((B ``/` `M) ``-` `(A ``/` `M))` `# Driver Code``# A and B define the range, M``# is the divident``A ``=` `30``B ``=` `70``M ``=` `10` `# Printing the result``print``(countDivisibles(A, B, M))` `# This code is contributed by Sam007`\n\n## C#\n\n `// C# program to count the numbers``// divisible by M in a given range``using` `System;` `public` `class` `GFG {` `    ``// Function to count the numbers divisible by``    ``// M in a given range``    ``static` `int` `countDivisibles(``int` `A, ``int` `B, ``int` `M)``    ``{``        ``// Add 1 explicitly as A is divisible by M``        ``if` `(A % M == 0)``            ``return` `(B / M) - (A / M) + 1;` `        ``// A is not divisible by M``        ``return` `(B / M) - (A / M);``    ``}` `    ``// driver program``    ``public` `static` `void` `Main()``    ``{``        ``// A and B define the range, M is the dividend``        ``int` `A = 30, B = 100, M = 30;` `        ``// Printing the result``        ``Console.WriteLine(countDivisibles(A, B, M));``    ``}``}` `// This code is contributed by Sam007`\n\n## PHP\n\n ``\n\n## Javascript\n\n `// Javascript Program to count the numbers``// divisible by M in a given range` `// Returns count of numbers in``// [A B] that are divisible by M.``function` `countDivisibles(A, B, M)``{``    ` `    ``// Add 1 explicitly as A``    ``// is divisible by M``    ``if` `(A % M == 0)``        ``return` `(B / M) -``            ``(A / M) + 1;` `    ``// A is not divisible by M``    ``return` `(B / M) -``        ``(A / M);``}` `    ``// Driver Code``    ``// A and B define the range,``    ``// M is the divident``    ``let A = 30;``    ``let B = 70;``    ``let M = 10;` `    ``// Printing the result``    ``document.write(countDivisibles(A, B, M));` `// This code is contributed by gfgking`\nOutput\n`3`\n\nThis article is contributed by Rohit Thapliyal. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to [email protected]. See your article appearing on the GeeksforGeeks main page and help other Geeks." ]
[ null ]
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https://www.colorhexa.com/01488e
[ "# #01488e Color Information\n\nIn a RGB color space, hex #01488e is composed of 0.4% red, 28.2% green and 55.7% blue. Whereas in a CMYK color space, it is composed of 99.3% cyan, 49.3% magenta, 0% yellow and 44.3% black. It has a hue angle of 209.8 degrees, a saturation of 98.6% and a lightness of 28%. #01488e color hex could be obtained by blending #0290ff with #00001d. Closest websafe color is: #003399.\n\n• R 0\n• G 28\n• B 56\nRGB color chart\n• C 99\n• M 49\n• Y 0\n• K 44\nCMYK color chart\n\n#01488e color description : Dark blue.\n\n# #01488e Color Conversion\n\nThe hexadecimal color #01488e has RGB values of R:1, G:72, B:142 and CMYK values of C:0.99, M:0.49, Y:0, K:0.44. Its decimal value is 84110.\n\nHex triplet RGB Decimal 01488e `#01488e` 1, 72, 142 `rgb(1,72,142)` 0.4, 28.2, 55.7 `rgb(0.4%,28.2%,55.7%)` 99, 49, 0, 44 209.8°, 98.6, 28 `hsl(209.8,98.6%,28%)` 209.8°, 99.3, 55.7 003399 `#003399`\nCIE-LAB 30.863, 9.675, -44.044 7.211, 6.594, 26.482 0.179, 0.164, 6.594 30.863, 45.094, 282.389 30.863, -17.009, -59.597 25.678, 5.193, -43.173 00000001, 01001000, 10001110\n\n# Color Schemes with #01488e\n\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #8e4701\n``#8e4701` `rgb(142,71,1)``\nComplementary Color\n• #018e8e\n``#018e8e` `rgb(1,142,142)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #01018e\n``#01018e` `rgb(1,1,142)``\nAnalogous Color\n• #8e8e01\n``#8e8e01` `rgb(142,142,1)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #8e0101\n``#8e0101` `rgb(142,1,1)``\nSplit Complementary Color\n• #488e01\n``#488e01` `rgb(72,142,1)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #8e0148\n``#8e0148` `rgb(142,1,72)``\n• #018e47\n``#018e47` `rgb(1,142,71)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #8e0148\n``#8e0148` `rgb(142,1,72)``\n• #8e4701\n``#8e4701` `rgb(142,71,1)``\n• #002142\n``#002142` `rgb(0,33,66)``\n• #012e5b\n``#012e5b` `rgb(1,46,91)``\n• #013b75\n``#013b75` `rgb(1,59,117)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #0155a7\n``#0155a7` `rgb(1,85,167)``\n• #0162c1\n``#0162c1` `rgb(1,98,193)``\n• #026fda\n``#026fda` `rgb(2,111,218)``\nMonochromatic Color\n\n# Alternatives to #01488e\n\nBelow, you can see some colors close to #01488e. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #016b8e\n``#016b8e` `rgb(1,107,142)``\n• #01608e\n``#01608e` `rgb(1,96,142)``\n• #01548e\n``#01548e` `rgb(1,84,142)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #013c8e\n``#013c8e` `rgb(1,60,142)``\n• #01318e\n``#01318e` `rgb(1,49,142)``\n• #01258e\n``#01258e` `rgb(1,37,142)``\nSimilar Colors\n\n# #01488e Preview\n\nThis text has a font color of #01488e.\n\n``<span style=\"color:#01488e;\">Text here</span>``\n#01488e background color\n\nThis paragraph has a background color of #01488e.\n\n``<p style=\"background-color:#01488e;\">Content here</p>``\n#01488e border color\n\nThis element has a border color of #01488e.\n\n``<div style=\"border:1px solid #01488e;\">Content here</div>``\nCSS codes\n``.text {color:#01488e;}``\n``.background {background-color:#01488e;}``\n``.border {border:1px solid #01488e;}``\n\n# Shades and Tints of #01488e\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #000306 is the darkest color, while #f1f8ff is the lightest one.\n\n• #000306\n``#000306` `rgb(0,3,6)``\n• #000d19\n``#000d19` `rgb(0,13,25)``\n• #00172d\n``#00172d` `rgb(0,23,45)``\n• #002040\n``#002040` `rgb(0,32,64)``\n• #012a54\n``#012a54` `rgb(1,42,84)``\n• #013467\n``#013467` `rgb(1,52,103)``\n• #013e7b\n``#013e7b` `rgb(1,62,123)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\n• #0152a1\n``#0152a1` `rgb(1,82,161)``\n• #015cb5\n``#015cb5` `rgb(1,92,181)``\n• #0166c8\n``#0166c8` `rgb(1,102,200)``\n• #0270dc\n``#0270dc` `rgb(2,112,220)``\n• #0279ef\n``#0279ef` `rgb(2,121,239)``\n• #0783fd\n``#0783fd` `rgb(7,131,253)``\n• #1b8dfd\n``#1b8dfd` `rgb(27,141,253)``\n• #2e97fe\n``#2e97fe` `rgb(46,151,254)``\n• #42a0fe\n``#42a0fe` `rgb(66,160,254)``\n• #55aafe\n``#55aafe` `rgb(85,170,254)``\n• #69b4fe\n``#69b4fe` `rgb(105,180,254)``\n• #7cbefe\n``#7cbefe` `rgb(124,190,254)``\n• #90c7fe\n``#90c7fe` `rgb(144,199,254)``\n• #a3d1fe\n``#a3d1fe` `rgb(163,209,254)``\n• #b7dbfe\n``#b7dbfe` `rgb(183,219,254)``\n• #cae5ff\n``#cae5ff` `rgb(202,229,255)``\n• #deeeff\n``#deeeff` `rgb(222,238,255)``\n• #f1f8ff\n``#f1f8ff` `rgb(241,248,255)``\nTint Color Variation\n\n# Tones of #01488e\n\nA tone is produced by adding gray to any pure hue. In this case, #43484c is the less saturated color, while #01488e is the most saturated one.\n\n• #43484c\n``#43484c` `rgb(67,72,76)``\n• #3e4852\n``#3e4852` `rgb(62,72,82)``\n• #384857\n``#384857` `rgb(56,72,87)``\n• #33485d\n``#33485d` `rgb(51,72,93)``\n• #2d4862\n``#2d4862` `rgb(45,72,98)``\n• #284868\n``#284868` `rgb(40,72,104)``\n• #22486d\n``#22486d` `rgb(34,72,109)``\n• #1d4873\n``#1d4873` `rgb(29,72,115)``\n• #174878\n``#174878` `rgb(23,72,120)``\n• #12487e\n``#12487e` `rgb(18,72,126)``\n• #0c4883\n``#0c4883` `rgb(12,72,131)``\n• #074889\n``#074889` `rgb(7,72,137)``\n• #01488e\n``#01488e` `rgb(1,72,142)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #01488e is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
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https://arxiv.org/abs/1809.00781?context=math
[ "math\n\n# Title:Matrix Infinitely Divisible Series: Tail Inequalities and Applications in Optimization\n\nAbstract: In this paper, we study tail inequalities of the largest eigenvalue of a matrix infinitely divisible (i.d.) series, which is a finite sum of fixed matrices weighted by i.d. random variables. We obtain several types of tail inequalities, including Bennett-type and Bernstein-type inequalities. This allows us to further bound the expectation of the spectral norm of a matrix i.d. series. Moreover, by developing a new lower-bound function for $Q(s)=(s+1)\\log(s+1)-s$ that appears in the Bennett-type inequality, we derive a tighter tail inequality of the largest eigenvalue of the matrix i.d. series than the Bernstein-type inequality when the matrix dimension is high. The resulting lower-bound function is of independent interest and can improve any Bennett-type concentration inequality that involves the function $Q(s)$. The class of i.d. probability distributions is large and includes Gaussian and Poisson distributions, among many others. Therefore, our results encompass the existing work \\cite{tropp2012user} on matrix Gaussian series as a special case. Lastly, we show that the tail inequalities of a matrix i.d. series have applications in several optimization problems including the chance constrained optimization problem and the quadratic optimization problem with orthogonality constraints.\n Comments: Comments Welcome! Subjects: Information Theory (cs.IT); Optimization and Control (math.OC) Cite as: arXiv:1809.00781 [cs.IT] (or arXiv:1809.00781v1 [cs.IT] for this version)\n\n## Submission history\n\nFrom: Min-Hsiu Hsieh [view email]\n[v1] Tue, 4 Sep 2018 03:11:44 UTC (211 KB)" ]
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https://pro.arcgis.com/en/pro-app/latest/arcpy/spatial-analyst/savi.htm
[ "# SAVI\n\n## Summary\n\nCalculates the Soil Adjusted Vegetation Index (SAVI) from a multiband raster object and returns a raster object with the index values.\n\n## Discussion\n\nThe Soil-Adjusted Vegetation Index (SAVI) method is a vegetation index that attempts to minimize soil brightness influences using a soil-brightness correction factor. This is often used in arid regions where vegetative cover is low, and it outputs values between -1.0 and 1.0.\n\n``SAVI = ((NIR - Red)/(NIR + Red + L)) * (1 + L)``\n\n• L—The amount of green vegetation cover. For example, 0.5.\n\nFor information about other multiband raster indexes, see the Band Arithmetic raster function.\n\nThe referenced raster dataset for the raster object is temporary. To make it permanent, you can call the raster object's save method.\n\n## Syntax\n\n`SAVI (raster, {nir_band_id}, {red_band_id}, {l})`\n Parameter Explanation Data Type raster The input raster. Raster nir_band_id The band ID of the near-infrared band. The ID index uses one-based indexing.(The default value is 7) Integer red_band_id The band ID of the red-edge band. The band ID index uses one-based indexing.(The default value is 6) Integer l The amount of green vegetative cover.(The default value is 0.33) Double\nReturn Value\n Data Type Explanation Raster The output raster with SAVI index values.\n\n## Code sample\n\nSAVI example\n\nCalculates the Soil Adjusted Vegetation Index for a Landsat 8 image.\n\n``````import arcpy\n\nSAVI_raster = arcpy.sa.SAVI(\"Landsat8.tif\",5,4,0.5)``````\n\n#### Related topics\n\n##### Related topics\n1. An overview of the Spatial Analyst functions" ]
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https://gitlab.mpi-sws.org/iris/actris/-/commit/4193e2e16d8f086d58aea8b1e73c1704e3371663
[ "### More things:\n\n```- Revise telescope setup.\n- Add append function on protocols.\n- Add a crappy normalizer for protocols that handles append and dual.\n- Prove non-expansiveness of tons of operators.```\nparent 83692823\nThis diff is collapsed.\n ... ... @@ -41,6 +41,25 @@ Definition proto_message {V} `{!Cofe PROPn, !Cofe PROP} (a : action) (pc : V → (laterO (proto V PROPn PROP) -n> PROPn) -n> PROP) : proto V PROPn PROP := proto_fold (Some (a, pc)). Instance proto_message_ne {V} `{!Cofe PROPn, !Cofe PROP} a n : Proper (pointwise_relation V (dist n) ==> dist n) (proto_message (PROPn:=PROPn) (PROP:=PROP) a). Proof. intros c1 c2 Hc. rewrite /proto_message. f_equiv. by repeat constructor. Qed. Instance proto_message_proper {V} `{!Cofe PROPn, !Cofe PROP} a : Proper (pointwise_relation V (≡) ==> (≡)) (proto_message (PROPn:=PROPn) (PROP:=PROP) a). Proof. intros c1 c2 Hc. rewrite /proto_message. f_equiv. by repeat constructor. Qed. Lemma proto_case {V} `{!Cofe PROPn, !Cofe PROP} (p : proto V PROPn PROP) : p ≡ proto_end ∨ ∃ a pc, p ≡ proto_message a pc. Proof. destruct (proto_unfold p) as [[a pc]|] eqn:E; simpl in *; last first. - left. by rewrite -(proto_fold_unfold p) E. - right. exists a, pc. by rewrite -(proto_fold_unfold p) E. Qed. Instance proto_inhabited {V} `{!Cofe PROPn, !Cofe PROP} : Inhabited (proto V PROPn PROP) := populate proto_end. Lemma proto_message_equivI {SPROP : sbi} {V} `{!Cofe PROPn, !Cofe PROP} a1 a2 pc1 pc2 : proto_message (V:=V) (PROPn:=PROPn) (PROP:=PROP) a1 pc1 ≡ proto_message a2 pc2 ⊣⊢@{SPROP} ⌜ a1 = a2 ⌝ ∧ (∀ v, pc1 v ≡ pc2 v). ... ... @@ -54,31 +73,106 @@ Proof. by rewrite bi.discrete_fun_equivI bi.discrete_eq. Qed. Lemma proto_case {V} `{!Cofe PROPn, !Cofe PROP} (p : proto V PROPn PROP) : p ≡ proto_end ∨ ∃ a pc, p ≡ proto_message a pc. Proof. destruct (proto_unfold p) as [[a pc]|] eqn:E; simpl in *; last first. - left. by rewrite -(proto_fold_unfold p) E. - right. exists a, pc. by rewrite -(proto_fold_unfold p) E. Qed. Instance proto_inhabited {V} `{!Cofe PROPn, !Cofe PROP} : Inhabited (proto V PROPn PROP) := populate proto_end. Instance proto_message_ne {V} `{!Cofe PROPn, !Cofe PROP} a n : Proper (pointwise_relation V (dist n) ==> dist n) (proto_message (PROPn:=PROPn) (PROP:=PROP) a). Proof. intros c1 c2 Hc. rewrite /proto_message. f_equiv. by repeat constructor. Qed. Instance proto_message_proper {V} `{!Cofe PROPn, !Cofe PROP} a : Proper (pointwise_relation V (≡) ==> (≡)) (proto_message (PROPn:=PROPn) (PROP:=PROP) a). Proof. intros c1 c2 Hc. rewrite /proto_message. f_equiv. by repeat constructor. Qed. Definition proto_cont_map `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, Cofe PROP', !Cofe A, !Cofe B} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP', !Cofe A, !Cofe B} (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') (h : A -n> B) : ((laterO A -n> PROPn) -n> PROP) -n> (laterO B -n> PROPn') -n> PROP' := ofe_morO_map (ofe_morO_map (laterO_map h) gn) g. (** Append *) Program Definition proto_app_flipped_aux {V} `{!Cofe PROPn, !Cofe PROP} (p2 : proto V PROPn PROP) (rec : proto V PROPn PROP -n> proto V PROPn PROP) : proto V PROPn PROP -n> proto V PROPn PROP := λne p1, match proto_unfold p1 return _ with | None => p2 | Some (a, c) => proto_message a (proto_cont_map cid cid rec ∘ c) end. Next Obligation. intros V PROPn ? PROP ? rec n p2 p1 p1' Hp. apply (ofe_mor_ne _ _ proto_unfold) in Hp. destruct Hp as [[??][??] [-> ?]|]; simplify_eq/=; last done. f_equiv=> v /=. by f_equiv. Qed. Instance proto_app_flipped_aux_contractive {V} `{!Cofe PROPn, !Cofe PROP} (p2 : proto V PROPn PROP) : Contractive (proto_app_flipped_aux p2). Proof. intros n rec1 rec2 Hrec p1. simpl. destruct (proto_unfold p1) as [[a c]|]; last done. f_equiv=> v /=. do 2 f_equiv. intros=> p'. apply Next_contractive. destruct n as [|n]=> //=. Qed. Definition proto_app_flipped {V} `{!Cofe PROPn, !Cofe PROP} (p2 : proto V PROPn PROP) : proto V PROPn PROP -n> proto V PROPn PROP := fixpoint (proto_app_flipped_aux p2). Definition proto_app {V} `{!Cofe PROPn, !Cofe PROP} (p1 p2 : proto V PROPn PROP) : proto V PROPn PROP := proto_app_flipped p2 p1. Instance: Params (@proto_app) 5. Lemma proto_app_flipped_unfold {V} `{!Cofe PROPn, !Cofe PROP} (p1 p2 : proto V PROPn PROP): proto_app_flipped p2 p1 ≡ proto_app_flipped_aux p2 (proto_app_flipped p2) p1. Proof. apply (fixpoint_unfold (proto_app_flipped_aux p2)). Qed. Lemma proto_app_unfold {V} `{!Cofe PROPn, !Cofe PROP} (p1 p2 : proto V PROPn PROP): proto_app (V:=V) p1 p2 ≡ proto_app_flipped_aux p2 (proto_app_flipped p2) p1. Proof. apply (fixpoint_unfold (proto_app_flipped_aux p2)). Qed. Lemma proto_app_end_l {V} `{!Cofe PROPn, !Cofe PROP} (p2 : proto V PROPn PROP) : proto_app proto_end p2 ≡ p2. Proof. rewrite proto_app_unfold /proto_end /=. pose proof (proto_unfold_fold (V:=V) (PROPn:=PROPn) (PROP:=PROP) None) as Hfold. by destruct (proto_unfold (proto_fold None)) as [[??]|] eqn:E; rewrite E; inversion Hfold. Qed. Lemma proto_app_message {V} `{!Cofe PROPn, !Cofe PROP} a c (p2 : proto V PROPn PROP) : proto_app (proto_message a c) p2 ≡ proto_message a (proto_cont_map cid cid (proto_app_flipped p2) ∘ c). Proof. rewrite proto_app_unfold /proto_message /=. pose proof (proto_unfold_fold (V:=V) (PROPn:=PROPn) (PROP:=PROP) (Some (a, c))) as Hfold. destruct (proto_unfold (proto_fold (Some (a, c)))) as [[??]|] eqn:E; inversion Hfold as [?? [Ha Hc]|]; simplify_eq/=. rewrite /proto_message. do 3 f_equiv. intros v=> /=. apply equiv_dist=> n. f_equiv. by apply equiv_dist. Qed. Instance proto_app_ne {V} `{!Cofe PROPn, !Cofe PROP} : NonExpansive2 (proto_app (V:=V) (PROPn:=PROPn) (PROP:=PROP)). Proof. intros n p1 p1' Hp1 p2 p2' Hp2. rewrite /proto_app -Hp1 {p1' Hp1}. revert p1. induction (lt_wf n) as [n _ IH]=> p1 /=. rewrite !proto_app_flipped_unfold /proto_app_flipped_aux /=. destruct (proto_unfold p1) as [[a c]|]; last done. f_equiv=> v f /=. do 2 f_equiv. intros p. apply Next_contractive. destruct n as [|n]=> //=. apply IH; first lia; auto using dist_S. Qed. Instance proto_app_proper {V} `{!Cofe PROPn, !Cofe PROP} : Proper ((≡) ==> (≡) ==> (≡)) (proto_app (V:=V) (PROPn:=PROPn) (PROP:=PROP)). Proof. apply (ne_proper_2 _). Qed. Lemma proto_app_end_r {V} `{!Cofe PROPn, !Cofe PROP} (p1 : proto V PROPn PROP) : proto_app p1 proto_end ≡ p1. Proof. apply equiv_dist=> n. revert p1. induction (lt_wf n) as [n _ IH]=> p1 /=. destruct (proto_case p1) as [->|(a & c & ->)]. - by rewrite !proto_app_end_l. - rewrite !proto_app_message /=. f_equiv=> v c' /=. f_equiv=> p' /=. f_equiv. apply Next_contractive. destruct n as [|n]=> //=. apply IH; first lia; auto using dist_S. Qed. Lemma proto_app_assoc {V} `{!Cofe PROPn, !Cofe PROP} (p1 p2 p3 : proto V PROPn PROP) : proto_app p1 (proto_app p2 p3) ≡ proto_app (proto_app p1 p2) p3. Proof. apply equiv_dist=> n. revert p1. induction (lt_wf n) as [n _ IH]=> p1 /=. destruct (proto_case p1) as [->|(a & c & ->)]. - by rewrite !proto_app_end_l. - rewrite !proto_app_message /=. f_equiv=> v c' /=. f_equiv=> p' /=. f_equiv. apply Next_contractive. destruct n as [|n]=> //=. apply IH; first lia; auto using dist_S. Qed. (** Functor *) Program Definition proto_map_aux {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') ... ... @@ -94,7 +188,6 @@ Next Obligation. destruct Hp as [[??][??] [-> ?]|]; simplify_eq/=; last done. f_equiv=> v /=. by f_equiv. Qed. Instance proto_map_aux_contractive {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') : ... ... @@ -105,7 +198,6 @@ Proof. f_equiv=> v /=. do 2 f_equiv. intros=> p'. apply Next_contractive. destruct n as [|n]=> //=. Qed. Definition proto_map {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') : ... ... @@ -116,7 +208,7 @@ Lemma proto_map_unfold {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') p : proto_map (V:=V) f gn g p ≡ proto_map_aux f gn g (proto_map f gn g) p. Proof. apply (fixpoint_unfold (proto_map_aux f gn g)). Qed. Lemma proto_map_end {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, Cofe PROP'} Lemma proto_map_end {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') : proto_map (V:=V) f gn g proto_end ≡ proto_end. Proof. ... ... @@ -182,6 +274,20 @@ Proof. apply IH; first lia; auto using dist_S. Qed. Lemma proto_map_app {V} `{!Cofe PROPn, !Cofe PROPn', !Cofe PROP, !Cofe PROP'} (f : action → action) (gn : PROPn' -n> PROPn) (g : PROP -n> PROP') p1 p2 : proto_map (V:=V) f gn g (proto_app p1 p2) ≡ proto_app (proto_map (V:=V) f gn g p1) (proto_map (V:=V) f gn g p2). Proof. apply equiv_dist=> n. revert p1 p2. induction (lt_wf n) as [n _ IH]=> p1 p2 /=. destruct (proto_case p1) as [->|(a & c & ->)]. - by rewrite proto_map_end !proto_app_end_l. - rewrite proto_map_message !proto_app_message proto_map_message /=. f_equiv=> v c' /=. do 2 f_equiv. move=> p' /=. do 2 f_equiv. apply Next_contractive. destruct n as [|n]=> //=. apply IH; first lia; auto using dist_S. Qed. Program Definition protoOF (V : Type) (Fn F : oFunctor) `{!∀ A B `{!Cofe A, !Cofe B}, Cofe (oFunctor_car Fn A B)} `{!∀ A B `{!Cofe A, !Cofe B}, Cofe (oFunctor_car F A B)} : oFunctor := {| ... ...\n From stdpp Require Import sorting. From osiris.channel Require Import proto_channel. From iris.heap_lang Require Import proofmode notation. From osiris.utils Require Import list. From osiris.channel Require Import proto_channel. Definition lmerge : val := rec: \"go\" \"cmp\" \"hys\" \"hzs\" := ... ... @@ -28,14 +28,14 @@ Definition list_sort_service : val := let: \"ys_zs\" := lsplit !\"xs\" in let: \"ys\" := ref (Fst \"ys_zs\") in let: \"zs\" := ref (Snd \"ys_zs\") in let: \"cy\" := new_chan #() in Fork(\"go\" (Fst \"cy\"));; let: \"cz\" := new_chan #() in Fork(\"go\" (Fst \"cz\"));; send (Snd \"cy\") \"cmp\";; send (Snd \"cy\") \"ys\";; send (Snd \"cz\") \"cmp\";; send (Snd \"cz\") \"zs\";; recv (Snd \"cy\");; recv (Snd \"cz\");; let: \"cy\" := new_chan #() in Fork(\"go\" (Snd \"cy\"));; let: \"cz\" := new_chan #() in Fork(\"go\" (Snd \"cz\"));; send (Fst \"cy\") \"cmp\";; send (Fst \"cy\") \"ys\";; send (Fst \"cz\") \"cmp\";; send (Fst \"cz\") \"zs\";; recv (Fst \"cy\");; recv (Fst \"cz\");; \"xs\" <- lmerge \"cmp\" !\"ys\" !\"zs\";; send \"c\" #(). ... ... @@ -50,15 +50,15 @@ Section list_sort. {{{ RET #(bool_decide (R x x')); I x v ∗ I x' v' }}})%I. Definition sort_protocol : iProto Σ := ( ∃ A (I : A → val → iProp Σ) (R : A → A → Prop) ( A (I : A → val → iProp Σ) (R : A → A → Prop) `{!RelDecision R, !TotalOrder R} (cmp : val), MSG cmp {{ cmp_spec I R cmp }}; ∃ (xs : list A) (l : loc) (vs : list val), (xs : list A) (l : loc) (vs : list val), MSG #l {{ l ↦ val_encode vs ∗ [∗ list] x;v ∈ xs;vs, I x v }}; ∃ (xs' : list A) (vs' : list val), (xs' : list A) (vs' : list val), MSG #() {{ ⌜ Sorted R xs' ⌝ ∗ ⌜ xs' ≡ₚ xs ⌝ ∗ l ↦ val_encode vs' ∗ [∗ list] x;v ∈ xs';vs', I x v }}; iProto_end)%proto. END)%proto. Lemma lmerge_spec {A} (I : A → val → iProp Σ) (R : A → A → Prop) `{!RelDecision R, !TotalOrder R} (cmp : val) xs1 xs2 vs1 vs2 : ... ... @@ -93,12 +93,12 @@ Section list_sort. iApply \"HΨ\". iFrame. Qed. Lemma list_sort_service_spec c : {{{ c ↣ sort_protocol @ N }}} Lemma list_sort_service_spec p c : {{{ c ↣ iProto_dual sort_protocol <++> p @ N }}} list_sort_service c {{{ RET #(); c ↣ iProto_end @ N }}}. {{{ RET #(); c ↣ p @ N }}}. Proof. iIntros (Ψ) \"Hc HΨ\". iLöb as \"IH\" forall (c Ψ). iIntros (Ψ) \"Hc HΨ\". iLöb as \"IH\" forall (p c Ψ). wp_lam. wp_apply (recv_proto_spec with \"Hc\"); simpl. iIntros (A I R ?? cmp) \"/= Hc #Hcmp\". ... ... @@ -116,23 +116,25 @@ Section list_sort. iDestruct (big_sepL2_app_inv_r with \"HI\") as (xs1 xs2 ->) \"[HI1 HI2]\". wp_apply (new_chan_proto_spec N sort_protocol)=> //. iIntros (cy1 cy2) \"[Hcy1 Hcy2]\". wp_apply (wp_fork with \"[Hcy1]\"). { iNext. wp_apply (\"IH\" with \"Hcy1\"); auto. } wp_apply (wp_fork with \"[Hcy2]\"). { iNext. rewrite -{2}(right_id END%proto _ (iProto_dual _)). wp_apply (\"IH\" with \"Hcy2\"); auto. } wp_apply (new_chan_proto_spec N sort_protocol)=> //. iIntros (cz1 cz2) \"[Hcz1 Hcz2]\". wp_apply (wp_fork with \"[Hcz1]\"). { iNext. wp_apply (\"IH\" with \"Hcz1\"); auto. } wp_apply (send_proto_spec with \"Hcy2\"); simpl. iExists _, I, R, _, _, cmp. iSplit; first done. iIntros \"{\\$Hcmp} !> Hcy2\". wp_apply (send_proto_spec with \"Hcy2\"); simpl. iExists xs1, l1, vs1. iSplit; first done. iIntros \"{\\$Hl1 \\$HI1} !> Hcy2\". wp_apply (send_proto_spec with \"Hcz2\"); simpl. iExists _, I, R, _, _, cmp. iSplit; first done. iIntros \"{\\$Hcmp} !> Hcz2\". wp_apply (send_proto_spec with \"Hcz2\"); simpl. iExists xs2, l2, vs2. iSplit; first done. iIntros \"{\\$Hl2 \\$HI2} !> Hcz2\". wp_apply (recv_proto_spec with \"Hcy2\"); simpl. wp_apply (wp_fork with \"[Hcz2]\"). { iNext. rewrite -{2}(right_id END%proto _ (iProto_dual _)). wp_apply (\"IH\" with \"Hcz2\"); auto. } wp_apply (send_proto_spec with \"Hcy1\"); simpl. iExists _, I, R, _, _, cmp. iSplit; first done. iIntros \"{\\$Hcmp} !> Hcy1\". wp_apply (send_proto_spec with \"Hcy1\"); simpl. iExists xs1, l1, vs1. iSplit; first done. iIntros \"{\\$Hl1 \\$HI1} !> Hcy1\". wp_apply (send_proto_spec with \"Hcz1\"); simpl. iExists _, I, R, _, _, cmp. iSplit; first done. iIntros \"{\\$Hcmp} !> Hcz1\". wp_apply (send_proto_spec with \"Hcz1\"); simpl. iExists xs2, l2, vs2. iSplit; first done. iIntros \"{\\$Hl2 \\$HI2} !> Hcz1\". wp_apply (recv_proto_spec with \"Hcy1\"); simpl. iIntros (ys1 ws1) \"_\". iDestruct 1 as (??) \"[Hl1 HI1]\". wp_apply (recv_proto_spec with \"Hcz2\"); simpl. wp_apply (recv_proto_spec with \"Hcz1\"); simpl. iIntros (ys2 ws2) \"_\". iDestruct 1 as (??) \"[Hl2 HI2]\". do 2 wp_load. wp_apply (lmerge_spec with \"Hcmp [\\$HI1 \\$HI2]\"); iIntros (ws) \"HI\". ... ...\nMarkdown is supported\n0% or\nYou are about to add 0 people to the discussion. Proceed with caution.\nFinish editing this message first!" ]
[ null ]
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http://pantheonresources.com/about-pantheon/operations/glossary/54-monte-carlo
[ "# Monte Carlo\n\nTerm Definition\nMonte Carlo\n\nA methodology for estimating a given quantity based on the statistical distribution of input values on which the quantity depends. Typically, the output quantity is calculated several thousand times (each calculation is called a trial), for each trial using input parameter values extracted randomly according to their statistical distributions. The result is a statistical distribution of output values." ]
[ null ]
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https://optimization-online.org/tag/polynomial-algorithm/
[ "## A polynomial-time descent method for separable convex optimization problems with linear constraints\n\nWe propose a polynomial algorithm for a separable convex optimization problem with linear constraints. We do not make any additional assumptions about the structure of the objective function except for polynomial computability. That is, the objective function can be non-differentiable. The running time of our algorithm is polynomial in the the size of the input … Read more\n\n## A polynomial algorithm for linear optimization which is strongly polynomial under certain conditions on optimal solutions\n\nThis paper proposes a polynomial algorithm for linear programming which is strongly polynomial for linear optimization problems $\\min\\{c^Tx : Ax = b, x\\ge {\\bf 0}\\}$ having optimal solutions where each non-zero component $x_j$ belongs to an interval of the form $[\\alpha_j, \\alpha_j\\cdot 2^{p(n)}],$ where $\\alpha_j$ is some positive value and $p(n)$ is a polynomial of … Read more\n\n## A polynomial relaxation-type algorithm for linear programming\n\nThe paper proposes a polynomial algorithm for solving systems of linear inequalities. The algorithm uses a polynomial relaxation-type procedure which either finds a solution for Ax = b, 0\n\n## A Polynomial Arc-Search Interior-Point Algorithm for Linear Programming\n\nIn this paper, ellipse is used to approximate the central path of the linear programming. An interior-point algorithm is devised to search the optimizers along the ellipse. The algorithm is proved to be polynomial with the complexity bound $O(n^{\\frac{1}{2}}\\log(1/\\epsilon))$. Numerical test is conducted for problems in Netlib. For most tested Netlib problems, the result shows … Read more\n\n## A Polynomial Arc-Search Interior-Point Algorithm for Convex Quadratic Programming\n\nArc-search is developed for linear programming in \\cite{yang09, yang10}. The algorithms search for optimizers along an ellipse that are approximations of the central path. In this paper, the arc-search method is applied to primal-dual path-following interior-point method for convex quadratic programming. A simple algorithm with iteration complexity $O(\\sqrt{n}\\log(1/\\epsilon))$ is devised. Several improvements on the simple … Read more" ]
[ null ]
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https://www.linuxtopia.org/online_books/programming_books/python_programming/python_ch08s07.html
[ "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "On-line Guides", null, "All Guides", null, "eBook Store", null, "iOS / Android", null, "Linux for Beginners", null, "Office Productivity", null, "Linux Installation", null, "Linux Security", null, "Linux Utilities", null, "Linux Virtualization", null, "Linux Kernel", null, "System/Network Admin", null, "Programming", null, "Scripting Languages", null, "Development Tools", null, "Web Development", null, "GUI Toolkits/Desktop", null, "Databases", null, "Mail Systems", null, "openSolaris", null, "Eclipse Documentation", null, "Techotopia.com", null, "Virtuatopia.com", null, "How To Guides", null, "Virtualization", null, "General System Admin", null, "Linux Security", null, "Linux Filesystems", null, "Web Servers", null, "Graphics & Desktop", null, "PC Hardware", null, "Windows", null, "Problem Solutions", null, "Privacy Policy", null, "", null, "## A Digression\n\nFor those new to programming, here's a short digression, adapted from chapter 8 of Edsger Dijkstra's book, A Discipline of Programming [Dijkstra76].\n\nLet's say we need to set a variable, `m`, to the larger of two input values, `a` and `b`. We start with a state we could call “ `m` undefined”. Then we want to execute a statement after which we are in a state of “(`m`==`a` or `m`==`b`) and `m``a` and `m``b` ”.\n\nClearly, we need to choose correctly between two different assignment statements. We need to do either m=a or m=b . How do we make this choice? With a little logic, we can derive the condition by taking each of these statement's effects out of the desired end-state.\n\nFor the statement m=a to be the right statement to use, we show the effect of the statement by replacing `m` with the value `a`, and examining the end state: (`a`==`a` or `a`==`b`) and `a``a` and `a``b`. Removing the parts that are obviously true, we're left with `a``b`. Therefore, the assignment m=a is only useful when `a``b`.\n\nFor the statement m=b to be the right statement to establish the necessary condition, we do a similar replacement of `b` for `m` and examine the end state: (`b`==`a` or `b`==`b`) and `b``a` and `b``b`. Again, we remove the parts that are obviously true and we're left with `b``a`. Therefore, the assignment m=b is only useful when `b``a`.\n\nEach assignment statement can be “guarded” by an appropriate condition.\n\n```if a>=b: m=a\nelif b>=a: m=b\n```\n\nIs the correct statement to set `m` to the larger of `a` or `b`.\n\nNote that the hard part is establishing the post condition. Once we have that stated correctly, it's relatively easy to figure the basic kind of statement that might make some or all of the post condition true. Then we do a little algebra to fill in any guards or loop conditions to make sure that only the correct statement is executed.\n\nSuccessful Loop Design. There are several considerations when using the while statement. This list is taken from David Gries', The Science of Programming [Gries81].\n\n1. The body condition must be initialized properly.\n2. At the end of the suite, the body condition is just as true as it was after initialization. This is called the invariant, because it is always true during the loop.\n3. When this body condition is true and the while condition is false, the loop will have completed properly.\n4. When the while condition is true, there are more iterations left to do. If we wanted to, we could define a mathematical function based on the current state that computes how many iterations are left to do; this function must have a value greater than zero when the while condition is true.\n5. Each time through the loop we change the state of our variables so that we are getting closer to making the while condition false; we reduce the number of iterations left to do.\n\nWhile these conditions seem overly complex for something so simple as a loop, many programming problems arise from missing one of them.\n\nGries recommends putting comments around a loop showing the conditions before and after the loop. Since Python provides the assert statement; this formalizes these comments into actual tests to be sure the program is correct.\n\nDesigning a Loop. Let's put a particular loop under the microscope. This is a small example, but shows all of the steps to loop construction. We want to find the least power of 2 greater than or equal to some number greater than 1, call it `x`. This power of 2 will tell us how many bits are required to represent `x`, for example.\n\nWe can state this mathematically as looking for some number, `n`, such that 2 n -1 < `x` ≤ 2 n . This says that if `x` is a power of 2, for example 64, we'd find 26. If `x` is another number, for example 66, we'd find 26 < 66 ≤ 27, or 64 < 66 ≤ 128.\n\nWe can start to sketch our loop already.\n\n```assert x > 1\n\n... initialize ...\n\n... some loop ...\n\nassert 2**(n-1) < x <= 2**n\n```\n\nWe work out the initialization to make sure that the invariant condition of the loop is initially true. Since `x` must be greater than or equal to 1, we can set `n` to 1. 21-1=20=1 < `x`. This will set things up to satisfy rule 1 and 2.\n\n```assert x > 1\nn= 1\n\n... some loop ...\n\nassert 2**(n-1) < x <= 2**n\n```\n\nIn loops, there must be a condition on the body that is invariant, and a terminating condition that changes. The terminating condition is written in the while clause. In this case, it is invariant (always true) that 2**(`n`-1) < `x`. That means that the other part of our final condition is the part that changes.\n\n```assert x > 1\nn= 1\nwhile not ( x <= 2**n ):\nn= n + 1\nassert 2**(n-1) < x\nassert 2**(n-1) < x <= 2**n\n```\n\nThe next to last step is to show that when the while condition is true, there are more than zero trips through the loop possible. We know that `x` is finite and some power of 2 will satisfy this condition. There's some `n` such that `n`-1 < ```log2 ```( `x` ) < = `n` that limits the trips through the loop.\n\nThe final step is to show that each cycle through the loop reduces the trip count. We can argue that increasing `n` gets us closer to the upper bound of ```log2 ```( `x` ).\n\nWe should add this information on successful termination as comments in our loop.", null, "Published under the terms of the Open Publication License Design by Interspire" ]
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https://math.stackexchange.com/questions/1935614/homeomorphism-between-union-of-intervals-and-reals
[ "# homeomorphism between union of intervals and reals\n\nQuestion:\n\nShow that $$\\left ( 0,1 \\right )$$ and $$\\mathbb{R}$$ are homeomorphic.\n\nProposition:If $$a,b,c,d \\in \\mathbb{R}$$, $$a and $$c then $$\\left ( a,b \\right )$$ is homeomorphic to $$\\left ( c,d \\right )$$.\n\nFor any point $$x \\in \\mathbb{R}$$, we have that $$x \\in \\left ( c,d \\right )$$ where $$c\n\nHence, $$\\left ( 0,1 \\right )$$ is homeomorphic to $$\\mathbb{R}$$\n\nNow,\n\nQuestion: Show that $$\\left ( 0,1 \\right ) \\cup \\left ( 2,3 \\right )$$ is not homeomorphic to $$\\mathbb{R}$$.\n\n$$\\textbf{Hint}$$: any two points in $$\\mathbb{R}$$ are joined by a continuous curve.\n\nI'll like a hint as to the second question.\n\nAny help is appreciated.\n\n• For $x\\in (0,1)$ let $f(x)=\\tan \\pi (x-1/2).$ Then $f:(0,1)\\to \\mathbb R$ is a homeomorphism. This is because $f$ is a continuous, strictly monotonic bijection. – DanielWainfleet Sep 22 '16 at 1:14\n\nSuppose you have a homeomorphism $\\phi: (0,1) \\cup (2,3) \\to \\mathbb{R}$. Take the points $x=\\phi(0.5)$ and $y=\\phi(2,3)$. Now have a continuous curve from $x$ to $y$, lets call it $\\gamma: [0,1] \\to \\mathbb{R}$ (I think you can construct such a curve easily).\n\nHint: The pullback of the curve $\\gamma'=\\phi^{-1}(\\gamma)$ is hence also a continuous curve in $(0,1) \\cup (2,3)$ with certain endpoints. Does such a curve exist?\n\nAnother possibility/hint without curves: Make yourself clear that in $(0,1) \\cup (2,3)$ the interval $(0,1)$ is open (as open interval) and closed (as complement of the open interval $(2,3)$). Assume you have a homeomorphism $\\phi: (0,1) \\cup (2,3) \\to \\mathbb{R}$, then $\\phi( (0,1)) \\subseteq \\mathbb{R}$ is (since $\\phi$ is a homeomorphism) a closed and open subset of $\\mathbb{R}$. You might know all the subsets of $\\mathbb{R}$ which are closed and open (hint: there are 2 such subsets). Take it from here (remember that images of non-empty sets are non-empty and a homeomorphism is also injective)!\n\n• So essentially what I do need to do is find an inverse function such that for some value in the codomain, the inverse function maps that value to a value not in the domain? – Mathematicing Sep 21 '16 at 13:52\n• @Mathematicing Nope. I suppose you follow the first hint: You get that inverse function (since you have an homeomorphism). What you should focus on is the path $\\gamma '$. This is a continuous path from $\\phi^{-1}(x)=0.5$ to $\\phi^{-1}(y)=1.5$ in your union of intervals. You now have to show, that such a path is not possible (if you didn't see that yet). Hint: Look at the point, where you \"jump\" from one intervall to the next one in the domain of your path. (actually I prefer the way without curves but maybe the first way is easier to see for a start) – ctst Sep 21 '16 at 13:58\n• I prefer the hint without curves. I assume the function is a homeomorphism. So we have that the function f is bijective with f and f^{-1} being continuous. We know that open intervals are open sets. The union of open sets are open sets. By this, we have that f and f^{-1} maps open sets to open sets. Have I got this correct? – Mathematicing Sep 21 '16 at 14:06\n• @Mathematicing Yes absolutly (you don't need that the union of open sets are open sets for this, but only that $f$ and $f^{-1}$ are continuous)! And by taking complements you also know $f$ maps closed sets to closed sets. – ctst Sep 21 '16 at 14:08\n• Would you mind expounding on the part where you mention f maps closed sets to closed sets? I think there's a subtlety that I'm not realising it fully. – Mathematicing Sep 21 '16 at 14:17\n\nLet's go back to your first problem:\n\nFor any point $$x \\in \\mathbb{R}$$, we have that $$x \\in \\left ( c,d \\right )$$ where $$c\n\nHence, $$\\left ( 0,1 \\right )$$ is homeomorphic to $$\\mathbb{R}$$\n\nOne point that's confusing for a reader is that you say \"hence\" as if the second sentence follows from the first. But the two don't seem to have much to do with each other.\n\nThe first statement looks like you've jumbled up the quantifiers. You're asked to prove that for all $$a$$, $$b$$, $$c$$, and $$d$$ with $$a and $$c, that $$(a,b)$$ is homeomorphic to $$(c,d)$$. You assert that for all $$x \\in \\mathbb{R}$$, that there exist $$c$$ and $$d$$ such that $$c. This is true, but it's not relevant to the problem.\n\nFirst, try to show that $$(0,1)$$ is homeomorphic to $$\\mathbb{R}$$. Then, generalize your proof to show that $$(a,b)$$ is homeomorphic to $$\\mathbb{R}$$, for any $$a. This shows that $$(a,b)$$ is homeomorphic to $$(c,d)$$, by transitivity.\n\nTo look for a continuous, invertible map that sends $$(0,1)$$ to $$(-\\infty,\\infty)$$, think of rational functions. Can you construct a function $$f(x)$$ which is monotone increasing on $$(0,1)$$, has $$\\lim_{x\\to 0^+} f(x) =-\\infty$$, and $$\\lim_{x\\to 1^-}f(x) = +\\infty$$?\n\nI am not exactly sure what you did to prove the first part... But regarding your second question, $\\mathbb{R}$ is connected, whereas $(0,1) \\cup (2,3)$ is not, and homeomorphisms preserve connectedness.\n\n• In the first part, all I note was that any value on the real line is between two open intervals. Then, using the proposition that the open intervals is an interval between c and d with c <d. – Mathematicing Sep 21 '16 at 12:58" ]
[ null ]
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https://forum.knime.com/t/calculation-with-previous-rows/9059
[ "# Calculation with previous rows\n\nHello all,\n\nI have a problem which is simple (I guess) but I don't know how to solve it :(\n\nI have the following (current) Data:\n\n current goal result 750 750 750 -700 -700 50 -375 -50 0 125 125 125 -250 -125 0 750 750 750 -750 -750 0\n\nI need KNIME to calculate from the \"current\" data the goal and the result column. The result column can be easily calculated from the goal column. It is important, that the values in the result column never reach below 0, therefore I need to have a adjusted goal column. The calculation in the result column is just an addition of the previos row in the result column with the current row in the goal column.\n\nAny solution for that?\n\nThanks  :)\n\nRalph\n\nHi Ralph,\n\nI think the result colum is a sum of all previous rows of the goal?\n\nIn this case you can use the moving aggregation node with cumulative computation and sum.\n\nIf you need the previous row, you can get is using the lag column node. It will \"shift\" some of the values in a new column.\n\nIf you need full control of the previous values, you need to use a Java Snippet.\n\nHope this helps,\n\nBest, Iris\n\n2 Likes\n\nIris' suggestions will work only if the input contains both the current and goal values.\n\nSince the calculation for a row depends on the calculation in the previous row, a recursive loop will do the trick.\nIn the attached workflow, the upper branch calculates the goal and result values for each row.  The result of each row is fed back for use in the next iteration, along with the unaltered remaining rows of the input table.\n\nThere are other ways to do this, but this workflow gives the desired output using only the current values as input.  Hope this helps.\n\nTim\n\n2 Likes" ]
[ null ]
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https://demo.formulasearchengine.com/wiki/BRST_quantization
[ "# BRST quantization\n\nIn theoretical physics, BRST quantization (where the BRST refers to Becchi, Rouet, Stora and Tyutin) is a relatively rigorous mathematical approach to quantizing a field theory with a gauge symmetry. Quantization rules in earlier QFT frameworks resembled \"prescriptions\" or \"heuristics\" more than proofs, especially in non-abelian QFT, where the use of \"ghost fields\" with superficially bizarre properties is almost unavoidable for technical reasons related to renormalization and anomaly cancellation. The BRST supersymmetry was introduced in the mid-1970s and was quickly understood to justify the introduction of these Faddeev–Popov ghosts and their exclusion from \"physical\" asymptotic states when performing QFT calculations. Work by other authors a few years later related the BRST operator to the existence of a rigorous alternative to path integrals when quantizing a gauge theory.\n\nOnly in the late 1980s, when QFT was reformulated in fiber bundle language for application to problems in the topology of low-dimensional manifolds, did it become apparent that the BRST \"transformation\" is fundamentally geometrical in character. In this light, \"BRST quantization\" becomes more than an alternate way to arrive at anomaly-cancelling ghosts. It is a different perspective on what the ghost fields represent, why the Faddeev–Popov method works, and how it is related to the use of Hamiltonian mechanics to construct a perturbative framework. The relationship between gauge invariance and \"BRST invariance\" forces the choice of a Hamiltonian system whose states are composed of \"particles\" according to the rules familiar from the canonical quantization formalism. This esoteric consistency condition therefore comes quite close to explaining how quanta and fermions arise in physics to begin with.\n\nIn certain cases, notably gravity and supergravity, BRST must be superseded by a more general formalism, the Batalin–Vilkovisky formalism.\n\n## Technical summary\n\nBRST quantization (or the BRST formalism) is a differential geometric approach to performing consistent, anomaly-free perturbative calculations in a non-abelian gauge theory. The analytical form of the BRST \"transformation\" and its relevance to renormalization and anomaly cancellation were described by Carlo Maria Becchi, Alain Rouet, and Raymond Stora in a series of papers culminating in the 1976 \"Renormalization of gauge theories\". The equivalent transformation and many of its properties were independently discovered by Igor Viktorovich Tyutin. Its significance for rigorous canonical quantization of a Yang–Mills theory and its correct application to the Fock space of instantaneous field configurations were elucidated by Kugo Taichiro and Ojima Izumi. Later work by many authors, notably Thomas Schücker and Edward Witten, has clarified the geometric significance of the BRST operator and related fields and emphasized its importance to topological quantum field theory and string theory.\n\nIn the BRST approach, one selects a perturbation-friendly gauge fixing procedure for the action principle of a gauge theory using the differential geometry of the gauge bundle on which the field theory lives. One then quantizes the theory to obtain a Hamiltonian system in the interaction picture in such a way that the \"unphysical\" fields introduced by the gauge fixing procedure resolve gauge anomalies without appearing in the asymptotic states of the theory. The result is a set of Feynman rules for use in a Dyson series perturbative expansion of the S-matrix which guarantee that it is unitary and renormalizable at each loop order—in short, a coherent approximation technique for making physical predictions about the results of scattering experiments.\n\n### Classical BRST\n\nThis is related to a supersymplectic manifold where pure operators are graded by integral ghost numbers and we have a BRST cohomology.\n\n## Gauge transformations in QFT\n\nFrom a practical perspective, a quantum field theory consists of an action principle and a set of procedures for performing perturbative calculations. There are other kinds of \"sanity checks\" that can be performed on a quantum field theory to determine whether it fits qualitative phenomena such as quark confinement and asymptotic freedom. However, most of the predictive successes of quantum field theory, from quantum electrodynamics to the present day, have been quantified by matching S-matrix calculations against the results of scattering experiments.\n\nIn the early days of QFT, one would have to have said that the quantization and renormalization prescriptions were as much part of the model as the Lagrangian density, especially when they relied on the powerful but mathematically ill-defined path integral formalism. It quickly became clear that QED was almost \"magical\" in its relative tractability, and that most of the ways that one might imagine extending it would not produce rational calculations. However, one class of field theories remained promising: gauge theories, in which the objects in the theory represent equivalence classes of physically indistinguishable field configurations, any two of which are related by a gauge transformation. This generalizes the QED idea of a local change of phase to a more complicated Lie group.\n\nQED itself is a gauge theory, as is general relativity, although the latter has proven resistant to quantization so far, for reasons related to renormalization. Another class of gauge theories with a non-Abelian gauge group, beginning with Yang–Mills theory, became amenable to quantization in the late 1960s and early 1970s, largely due to the work of Ludwig D. Faddeev, Victor Popov, Bryce DeWitt, and Gerardus 't Hooft. However, they remained very difficult to work with until the introduction of the BRST method. The BRST method provided the calculation techniques and renormalizability proofs needed to extract accurate results from both \"unbroken\" Yang–Mills theories and those in which the Higgs mechanism leads to spontaneous symmetry breaking. Representatives of these two types of Yang–Mills systems—quantum chromodynamics and electroweak theory—appear in the Standard Model of particle physics.\n\nIt has proven rather more difficult to prove the existence of non-Abelian quantum field theory in a rigorous sense than to obtain accurate predictions using semi-heuristic calculation schemes. This is because analyzing a quantum field theory requires two mathematically interlocked perspectives: a Lagrangian system based on the action functional, composed of fields with distinct values at each point in spacetime and local operators which act on them, and a Hamiltonian system in the Dirac picture, composed of states which characterize the entire system at a given time and field operators which act on them. What makes this so difficult in a gauge theory is that the objects of the theory are not really local fields on spacetime; they are right-invariant local fields on the principal gauge bundle, and different local sections through a portion of the gauge bundle, related by passive transformations, produce different Dirac pictures.\n\nWhat is more, a description of the system as a whole in terms of a set of fields contains many redundant degrees of freedom; the distinct configurations of the theory are equivalence classes of field configurations, so that two descriptions which are related to one another by an active gauge transformation are also really the same physical configuration. The \"solutions\" of a quantized gauge theory exist not in a straightforward space of fields with values at every point in spacetime but in a quotient space (or cohomology) whose elements are equivalence classes of field configurations. Hiding in the BRST formalism is a system for parameterizing the variations associated with all possible active gauge transformations and correctly accounting for their physical irrelevance during the conversion of a Lagrangian system to a Hamiltonian system.\n\n### Gauge fixing and perturbation theory\n\nThe principle of gauge invariance is essential to constructing a workable quantum field theory. But it is generally not feasible to perform a perturbative calculation in a gauge theory without first \"fixing the gauge\"—adding terms to the Lagrangian density of the action principle which \"break the gauge symmetry\" to suppress these \"unphysical\" degrees of freedom. The idea of gauge fixing goes back to the Lorenz gauge approach to electromagnetism, which suppresses most of the excess degrees of freedom in the four-potential while retaining manifest Lorentz invariance. The Lorenz gauge is a great simplification relative to Maxwell's field-strength approach to classical electrodynamics, and illustrates why it is useful to deal with excess degrees of freedom in the representation of the objects in a theory at the Lagrangian stage, before passing over to Hamiltonian mechanics via the Legendre transform.\n\nThe Hamiltonian density is related to the Lie derivative of the Lagrangian density with respect to a unit timelike horizontal vector field on the gauge bundle. In a quantum mechanical context it is conventionally rescaled by a factor $i\\hbar$", null, ". Integrating it by parts over a spacelike cross section recovers the form of the integrand familiar from canonical quantization. Because the definition of the Hamiltonian involves a unit time vector field on the base space, a horizontal lift to the bundle space, and a spacelike surface \"normal\" (in the Minkowski metric) to the unit time vector field at each point on the base manifold, it is dependent both on the connection and the choice of Lorentz frame, and is far from being globally defined. But it is an essential ingredient in the perturbative framework of quantum field theory, into which the quantized Hamiltonian enters via the Dyson series.\n\nFor perturbative purposes, we gather the configuration of all the fields of our theory on an entire three-dimensional horizontal spacelike cross section of P into one object (a Fock state), and then describe the \"evolution\" of this state over time using the interaction picture. The Fock space is spanned by the multi-particle eigenstates of the \"unperturbed\" or \"non-interaction\" portion ${\\mathcal {H}}_{0}$", null, "of the Hamiltonian ${\\mathcal {H}}$", null, ". Hence the instantaneous description of any Fock state is a complex-amplitude-weighted sum of eigenstates of ${\\mathcal {H}}_{0}$", null, ". In the interaction picture, we relate Fock states at different times by prescribing that each eigenstate of the unperturbed Hamiltonian experiences a constant rate of phase rotation proportional to its energy (the corresponding eigenvalue of the unperturbed Hamiltonian).\n\nHence, in the zero-order approximation, the set of weights characterizing a Fock state does not change over time, but the corresponding field configuration does. In higher approximations, the weights also change; collider experiments in high-energy physics amount to measurements of the rate of change in these weights (or rather integrals of them over distributions representing uncertainty in the initial and final conditions of a scattering event). The Dyson series captures the effect of the discrepancy between ${\\mathcal {H}}_{0}$", null, "and the true Hamiltonian ${\\mathcal {H}}$", null, ", in the form of a power series in the coupling constant g; it is the principal tool for making quantitative predictions from a quantum field theory.\n\nTo use the Dyson series to calculate anything, one needs more than a gauge-invariant Lagrangian density; one also needs the quantization and gauge fixing prescriptions that enter into the Feynman rules of the theory. The Dyson series produces infinite integrals of various kinds when applied to the Hamiltonian of a particular QFT. This is partly because all usable quantum field theories to date must be considered effective field theories, describing only interactions on a certain range of energy scales that we can experimentally probe and therefore vulnerable to ultraviolet divergences. These are tolerable as long as they can be handled via standard techniques of renormalization; they are not so tolerable when they result in an infinite series of infinite renormalizations or, worse, in an obviously unphysical prediction such as an uncancelled gauge anomaly. There is a deep relationship between renormalizability and gauge invariance, which is easily lost in the course of attempts to obtain tractable Feynman rules by fixing the gauge.\n\n### Pre-BRST approaches to gauge fixing\n\nThe traditional gauge fixing prescriptions of continuum electrodynamics select a unique representative from each gauge-transformation-related equivalence class using a constraint equation such as the Lorenz gauge $\\partial ^{\\mu }A_{\\mu }=0$", null, ". This sort of prescription can be applied to an Abelian gauge theory such as QED, although it results in some difficulty in explaining why the Ward identities of the classical theory carry over to the quantum theory—in other words, why Feynman diagrams containing internal longitudinally polarized virtual photons do not contribute to S-matrix calculations. This approach also does not generalize well to non-Abelian gauge groups such as the SU(2) of Yang–Mills and electroweak theory and the SU(3) of quantum chromodynamics. It suffers from Gribov ambiguities and from the difficulty of defining a gauge fixing constraint that is in some sense \"orthogonal\" to physically significant changes in the field configuration.\n\nMore sophisticated approaches do not attempt to apply a delta function constraint to the gauge transformation degrees of freedom. Instead of \"fixing\" the gauge to a particular \"constraint surface\" in configuration space, one can break the gauge freedom with an additional, non-gauge-invariant term added to the Lagrangian density. In order to reproduce the successes of gauge fixing, this term is chosen to be minimal for the choice of gauge that corresponds to the desired constraint and to depend quadratically on the deviation of the gauge from the constraint surface. By the stationary phase approximation on which the Feynman path integral is based, the dominant contribution to perturbative calculations will come from field configurations in the neighborhood of the constraint surface.\n\nThe perturbative expansion associated with this Lagrangian, using the method of functional quantization, is generally referred to as the Rξ gauge. It reduces in the case of an Abelian U(1) gauge to the same set of Feynman rules that one obtains in the method of canonical quantization. But there is an important difference: the broken gauge freedom appears in the functional integral as an additional factor in the overall normalization. This factor can only be pulled out of the perturbative expansion (and ignored) when the contribution to the Lagrangian of a perturbation along the gauge degrees of freedom is independent of the particular \"physical\" field configuration. This is the condition that fails to hold for non-Abelian gauge groups. If one ignores the problem and attempts to use the Feynman rules obtained from \"naive\" functional quantization, one finds that one's calculations contain unremovable anomalies.\n\nThe problem of perturbative calculations in QCD was solved by introducing additional fields known as Faddeev–Popov ghosts, whose contribution to the gauge-fixed Lagrangian offsets the anomaly introduced by the coupling of \"physical\" and \"unphysical\" perturbations of the non-Abelian gauge field. From the functional quantization perspective, the \"unphysical\" perturbations of the field configuration (the gauge transformations) form a subspace of the space of all (infinitesimal) perturbations; in the non-Abelian case, the embedding of this subspace in the larger space depends on the configuration around which the perturbation takes place. The ghost term in the Lagrangian represents the functional determinant of the Jacobian of this embedding, and the properties of the ghost field are dictated by the exponent desired on the determinant in order to correct the functional measure on the remaining \"physical\" perturbation axes.\n\n## Mathematical approach to BRST\n\nFirst, using the regular sequence of functions defining M0 inside M, construct a Koszul complex\n\n$\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M).$", null, "The differential, δ, on this complex is an odd C(M)-linear derivation of the graded C(M)-algebra $\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M)$", null, ". This odd derivation is defined by extending the Lie algebra homomorphim ${\\mathfrak {g}}\\to C^{\\infty }(M)$", null, "of the hamiltonian action. The resulting Koszul complex is the Koszul complex of the $S({\\mathfrak {g}})$", null, "-module C(M), where $S({\\mathfrak {g}})$", null, "is the symmetric algebra of ${\\mathfrak {g}}$", null, ", and the module structure comes from a ring homomorphism $S({\\mathfrak {g}})\\to C^{\\infty }(M)$", null, "induced by the hamiltonian action ${\\mathfrak {g}}\\to C^{\\infty }(M)$", null, ".\n\n$H^{j}(\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M),\\delta )={\\begin{cases}C^{\\infty }(M_{0})&j=0\\\\0&j\\neq 0\\end{cases}}$", null, "Then, consider the Chevalley-Eilenberg cochain complex for the Koszul complex $\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M)$", null, "considered as a dg module over the Lie algebra ${\\mathfrak {g}}$", null, ":\n\n$K^{\\cdot ,\\cdot }=C^{\\cdot }\\left({\\mathfrak {g}},\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M)\\right)=\\Lambda ^{\\cdot }{\\mathfrak {g}}^{*}\\otimes \\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M).$", null, "The \"horizontal\" differential $d:K^{i,\\cdot }\\to K^{i+1,\\cdot }$", null, "is defined on the coefficients\n\n$\\Lambda ^{\\cdot }{\\mathfrak {g}}\\otimes C^{\\infty }(M)$", null, "Let Tot(K) be a complex such that\n\n$\\operatorname {Tot} (K)^{n}=\\bigoplus \\nolimits _{i-j=n}K^{i,j}$", null, "with a differential D = d + δ. The cohomology groups of (Tot(K), D) are computed using a spectral sequence associated to the double complex $(K^{\\cdot ,\\cdot },d,\\delta )$", null, ".\n\nThe first term of the spectral sequence computes the cohomology of the \"vertical\" differential δ:\n\n$E_{1}^{i,j}=H^{j}(K^{i,\\cdot },\\delta )=\\Lambda ^{i}{\\mathfrak {g}}^{*}\\otimes C^{\\infty }(M_{0})$", null, ", if j = 0 and zero otherwise.\n\nThe first term of the spectral sequence may be interpreted as the complex of vertical differential forms\n\n$(\\Omega _{\\operatorname {vert} }^{\\cdot }(M_{0}),d_{\\operatorname {vert} })$", null, "The second term of the spectral sequence computes the cohomology of the \"horizontal\" differential d on $E_{1}^{\\cdot ,\\cdot }$", null, ":\n\n$E_{2}^{i,j}\\cong H^{i}(E_{1}^{\\cdot ,j},d)=C^{\\infty }(M_{0})^{g}=C^{\\infty }({\\widetilde {M}})$", null, ", if $i=j=0$", null, "and zero otherwise.\n\nThe spectral sequence collapses at the second term, so that $E_{\\infty }^{i,j}=E_{2}^{i,j}$", null, ", which is concentrated in degree zero.\n\nTherefore,\n\n$H^{p}(\\operatorname {Tot} (K),D)=C^{\\infty }(M_{0})^{g}=C^{\\infty }({\\widetilde {M}})$", null, ", if p = 0 and 0 otherwise.\n\n## The BRST operator and asymptotic Fock space\n\nTwo important remarks about the BRST operator are due. First, instead of working with the gauge group G one can use only the action of the gauge algebra ${\\mathfrak {g}}$", null, "on the fields (functions on the phase space).\n\nSecond, the variation of any \"BRST exact form\" sBX with respect to a local gauge transformation dλ is\n\n$\\left[i_{\\delta \\lambda },s_{B}\\right]s_{B}X=i_{\\delta \\lambda }(s_{B}s_{B}X)+s_{B}\\left(i_{\\delta \\lambda }(s_{B}X)\\right)=s_{B}\\left(i_{\\delta \\lambda }(s_{B}X)\\right),$", null, "which is itself an exact form.\n\nMore importantly for the Hamiltonian perturbative formalism (which is carried out not on the fiber bundle but on a local section), adding a BRST exact term to a gauge invariant Lagrangian density preserves the relation sBX = 0. As we shall see, this implies that there is a related operator QB on the state space for which $[Q_{B},{\\mathcal {H}}]=0$", null, "—i. e., the BRST operator on Fock states is a conserved charge of the Hamiltonian system. This implies that the time evolution operator in a Dyson series calculation will not evolve a field configuration obeying $Q_{B}|\\Psi _{i}\\rangle =0$", null, "into a later configuration with $Q_{B}|\\Psi _{f}\\rangle \\neq 0$", null, "(or vice versa).\n\nAnother way of looking at the nilpotence of the BRST operator is to say that its image (the space of BRST exact forms) lies entirely within its kernel (the space of BRST closed forms). (The \"true\" Lagrangian, presumed to be invariant under local gauge transformations, is in the kernel of the BRST operator but not in its image.) The preceding argument says that we can limit our universe of initial and final conditions to asymptotic \"states\"—field configurations at timelike infinity, where the interaction Lagrangian is \"turned off\"—that lie in the kernel of QB and still obtain a unitary scattering matrix. (BRST closed and exact states are defined similarly to BRST closed and exact fields; closed states are annihilated by QB, while exact states are those obtainable by applying QB to some arbitrary field configuration.)\n\nWe can also suppress states that lie inside the image of QB when defining the asymptotic states of our theory—but the reasoning is a bit subtler. Since we have postulated that the \"true\" Lagrangian of our theory is gauge invariant, the true \"states\" of our Hamiltonian system are equivalence classes under local gauge transformation; in other words, two initial or final states in the Hamiltonian picture that differ only by a BRST exact state are physically equivalent. However, the use of a BRST exact gauge breaking prescription does not guarantee that the interaction Hamiltonian will preserve any particular subspace of closed field configurations that we can call \"orthogonal\" to the space of exact configurations. (This is a crucial point, often mishandled in QFT textbooks. There is no a priori inner product on field configurations built into the action principle; we construct such an inner product as part of our Hamiltonian perturbative apparatus.)\n\nWe therefore focus on the vector space of BRST closed configurations at a particular time with the intention of converting it into a Fock space of intermediate states suitable for Hamiltonian perturbation. To this end, we shall endow it with ladder operators for the energy-momentum eigenconfigurations (particles) of each field, complete with appropriate (anti-)commutation rules, as well as a positive semi-definite inner product. We require that the inner product be singular exclusively along directions that correspond to BRST exact eigenstates of the unperturbed Hamiltonian. This ensures that one can freely choose, from within the two equivalence classes of asymptotic field configurations corresponding to particular initial and final eigenstates of the (unbroken) free-field Hamiltonian, any pair of BRST closed Fock states that we like.\n\nThe desired quantization prescriptions will also provide a quotient Fock space isomorphic to the BRST cohomology, in which each BRST closed equivalence class of intermediate states (differing only by an exact state) is represented by exactly one state that contains no quanta of the BRST exact fields. This is the Fock space we want for asymptotic states of the theory; even though we will not generally succeed in choosing the particular final field configuration to which the gauge-fixed Lagrangian dynamics would have evolved that initial configuration, the singularity of the inner product along BRST exact degrees of freedom ensures that we will get the right entries for the physical scattering matrix.\n\n(Actually, we should probably be constructing a Krein space for the BRST-closed intermediate Fock states, with the time reversal operator playing the role of the \"fundamental symmetry\" relating the Lorentz-invariant and positive semi-definite inner products. The asymptotic state space is presumably the Hilbert space obtained by quotienting BRST exact states out of this Krein space.)\n\nIn sum, no field introduced as part of a BRST gauge fixing procedure will appear in asymptotic states of the gauge-fixed theory. However, this does not imply that we can do without these \"unphysical\" fields in the intermediate states of a perturbative calculation! This is because perturbative calculations are done in the interaction picture. They implicitly involve initial and final states of the non-interaction Hamiltonian ${\\mathcal {H}}_{0}$", null, ", gradually transformed into states of the full Hamiltonian in accordance with the adiabatic theorem by \"turning on\" the interaction Hamiltonian (the gauge coupling). The expansion of the Dyson series in terms of Feynman diagrams will include vertices that couple \"physical\" particles (those that can appear in asymptotic states of the free Hamiltonian) to \"unphysical\" particles (states of fields that live outside the kernel of sB or inside the image of sB) and vertices that couple \"unphysical\" particles to one another.\n\n### The Kugo–Ojima answer to unitarity questions\n\nT. Kugo and I. Ojima are commonly credited with the discovery of the principal QCD color confinement criterion. Their role in obtaining a correct version of the BRST formalism in the Lagrangian framework seems to be less widely appreciated. It is enlightening to inspect their variant of the BRST transformation, which emphasizes the hermitian properties of the newly introduced fields, before proceeding from an entirely geometrical angle. The gauge fixed Lagrangian density is below; the two terms in parentheses form the coupling between the gauge and ghost sectors, and the final term becomes a Gaussian weighting for the functional measure on the auxiliary field B.\n\n${\\mathcal {L}}={\\mathcal {L}}_{\\textrm {matter}}(\\psi ,\\,A_{\\mu }^{a})-{\\tfrac {1}{4}}F_{\\mu \\nu }^{a}F^{a,\\,\\mu \\nu }-(i(\\partial ^{\\mu }{\\bar {c}}^{a})D_{\\mu }^{ab}c^{b}+(\\partial ^{\\mu }B^{a})A_{\\mu }^{a})+{\\tfrac {1}{2}}\\alpha _{0}B^{a}B^{a}$", null, "The Faddeev–Popov ghost field c is unique among the new fields of our gauge-fixed theory in having a geometrical meaning beyond the formal requirements of the BRST procedure. It is a version of the Maurer–Cartan form on $V{\\mathfrak {E}}$", null, ", which relates each right-invariant vertical vector field $\\delta \\lambda \\in V{\\mathfrak {E}}$", null, "to its representation (up to a phase) as a ${\\mathfrak {g}}$", null, "-valued field. This field must enter into the formulas for infinitesimal gauge transformations on objects (such as fermions ψ, gauge bosons Aμ, and the ghost c itself) which carry a non-trivial representation of the gauge group. The BRST transformation with respect to δλ is therefore:\n\n{\\begin{aligned}\\delta \\psi _{i}&=\\delta \\lambda D_{i}c\\\\\\delta A_{\\mu }&=\\delta \\lambda D_{\\mu }c\\\\\\delta c&=-\\delta \\lambda {\\tfrac {g}{2}}[c,c]\\\\\\delta {\\bar {c}}&=i\\delta \\lambda B\\\\\\delta B&=0\\end{aligned}}", null, "Here we have omitted the details of the matter sector ψ and left the form of the Ward operator on it unspecified; these are unimportant so long as the representation of the gauge algebra on the matter fields is consistent with their coupling to δAμ. The properties of the other fields we have added are fundamentally analytical rather than geometric. The bias we have introduced towards connections with $\\partial ^{\\mu }A_{\\mu }=0$", null, "is gauge-dependent and has no particular geometrical significance. The anti-ghost ${\\bar {c}}$", null, "is nothing but a Lagrange multiplier for the gauge fixing term, and the properties of the scalar field B are entirely dictated by the relationship $\\delta {\\bar {c}}=i\\delta \\lambda B$", null, ". (The new fields are all Hermitian in Kugo–Ojima conventions, but the parameter δλ is an anti-Hermitian \"anti-commuting c-number\". This results in some unnecessary awkwardness with regard to phases and passing infinitesimal parameters through operators; this will be resolved with a change of conventions in the geometric treatment below.)\n\nWe already know, from the relation of the BRST operator to the exterior derivative and the Faddeev–Popov ghost to the Maurer–Cartan form, that the ghost c corresponds (up to a phase) to a ${\\mathfrak {g}}$", null, "-valued 1-form on $V{\\mathfrak {E}}$", null, ". In order for integration of a term like $-i(\\partial ^{\\mu }{\\bar {c}})D_{\\mu }c$", null, "to be meaningful, the anti-ghost ${\\bar {c}}$", null, "must carry representations of these two Lie algebras—the vertical ideal $V{\\mathfrak {E}}$", null, "and the gauge algebra ${\\mathfrak {g}}$", null, "—dual to those carried by the ghost. In geometric terms, ${\\bar {c}}$", null, "must be fiberwise dual to ${\\mathfrak {g}}$", null, "and one rank short of being a top form on $V{\\mathfrak {E}}$", null, ". Likewise, the auxiliary field B must carry the same representation of ${\\mathfrak {g}}$", null, "(up to a phase) as ${\\bar {c}}$", null, ", as well as the representation of $V{\\mathfrak {E}}$", null, "dual to its trivial representation on Aμ—i. e., B is a fiberwise ${\\mathfrak {g}}$", null, "-dual top form on $V{\\mathfrak {E}}$", null, ".\n\nLet us focus briefly on the one-particle states of the theory, in the adiabatically decoupled limit g → 0. There are two kinds of quanta in the Fock space of the gauge-fixed Hamiltonian that we expect to lie entirely outside the kernel of the BRST operator: those of the Faddeev–Popov anti-ghost ${\\bar {c}}$", null, "and the forward polarized gauge boson. This is because no combination of fields containing ${\\bar {c}}$", null, "is annihilated by sB and we have added to the Lagrangian a gauge breaking term that is equal up to a divergence to\n\n$s_{B}\\left({\\bar {c}}\\left(i\\partial ^{\\mu }A_{\\mu }-{\\tfrac {1}{2}}\\alpha _{0}s_{B}{\\bar {c}}\\right)\\right).$", null, "Likewise, there are two kinds of quanta that will lie entirely in the image of the BRST operator: those of the Faddeev–Popov ghost c and the scalar field B, which is \"eaten\" by completing the square in the functional integral to become the backward polarized gauge boson. These are the four types of \"unphysical\" quanta which will not appear in the asymptotic states of a perturbative calculation—if we get our quantization rules right.\n\nThe anti-ghost is taken to be a Lorentz scalar for the sake of Poincaré invariance in $-i(\\partial ^{\\mu }{\\bar {c}})D_{\\mu }c$", null, ". However, its (anti-)commutation law relative to c—i. e., its quantization prescription, which ignores the spin-statistics theorem by giving Fermi–Dirac statistics to a spin-0 particle—will be given by the requirement that the inner product on our Fock space of asymptotic states be singular along directions corresponding to the raising and lowering operators of some combination of non-BRST-closed and BRST-exact fields. This last statement is the key to \"BRST quantization\", as opposed to mere \"BRST symmetry\" or \"BRST transformation\".\n\n(Needs to be completed in the language of BRST cohomology, with reference to the Kugo–Ojima treatment of asymptotic Fock space.)\n\n## Gauge bundles and the vertical ideal\n\nIn order to do the BRST method justice, we must switch from the \"algebra-valued fields on Minkowski space\" picture typical of quantum field theory texts (and of the above exposition) to the language of fiber bundles, in which there are two quite different ways to look at a gauge transformation: as a change of local section (also known in general relativity as a passive transformation) or as the pullback of the field configuration along a vertical diffeomorphism of the principal bundle. It is the latter sort of gauge transformation that enters into the BRST method. Unlike a passive transformation, it is well-defined globally on a principal bundle with any structure group over an arbitrary manifold. (However, for concreteness and relevance to conventional QFT, this article will stick to the case of a principal gauge bundle with compact fiber over 4-dimensional Minkowski space.)\n\nA principal gauge bundle P over a 4-manifold M is locally isomorphic to U × F, where U ⊂ R4 and the fiber F is isomorphic to a Lie group G, the gauge group of the field theory (this is an isomorphism of manifold structures, not of group structures; there is no special surface in P corresponding to 1 in G, so it is more proper to say that the fiber F is a G-torsor). Thus, the (physical) principal gauge bundle is related to the (mathematical) principal G-bundle but has more structure. Its most basic property as a fiber bundle is the \"projection to the base space\" π : P → M, which defines the \"vertical\" directions on P (those lying within the fiber π−1(p) over each point p in M). As a gauge bundle it has a left action of G on P which respects the fiber structure, and as a principal bundle it also has a right action of G on P which also respects the fiber structure and commutes with the left action.\n\nThe left action of the structure group G on P corresponds to a mere change of coordinate system on an individual fiber. The (global) right action Rg : P → P for a fixed g in G corresponds to an actual automorphism of each fiber and hence to a map of P to itself. In order for P to qualify as a principal G-bundle, the global right action of each g in G must be an automorphism with respect to the manifold structure of P with a smooth dependence on g—i. e., a diffeomorphism P × G → P.\n\nThe existence of the global right action of the structure group picks out a special class of right invariant geometric objects on P—those which do not change when they are pulled back along Rg for all values of g in G. The most important right invariant objects on a principal bundle are the right invariant vector fields, which form an ideal ${\\mathfrak {E}}$", null, "of the Lie algebra of infinitesimal diffeomorphisms on P. Those vector fields on P which are both right invariant and vertical form an ideal $V{\\mathfrak {E}}$", null, "of ${\\mathfrak {E}}$", null, ", which has a relationship to the entire bundle P analogous to that of the Lie algebra ${\\mathfrak {g}}$", null, "of the gauge group G to the individual G-torsor fiber F.\n\nThe \"field theory\" of interest is defined in terms of a set of \"fields\" (smooth maps into various vector spaces) defined on a principal gauge bundle P. Different fields carry different representations of the gauge group G, and perhaps of other symmetry groups of the manifold such as the Poincaré group. One may define the space Pl of local polynomials in these fields and their derivatives. The fundamental Lagrangian density of one's theory is presumed to lie in the subspace Pl0 of polynomials which are real-valued and invariant under any unbroken non-gauge symmetry groups. It is also presumed to be invariant not only under the left action (passive coordinate transformations) and the global right action of the gauge group but also under local gauge transformationspullback along the infinitesimal diffeomorphism associated with an arbitrary choice of right invariant vertical vector field $\\epsilon \\in V{\\mathfrak {E}}$", null, ".\n\nIdentifying local gauge transformations with a particular subspace of vector fields on the manifold P equips us with a better framework for dealing with infinite-dimensional infinitesimals: differential geometry and the exterior calculus. The change in a scalar field under pullback along an infinitesimal automorphism is captured in the Lie derivative, and the notion of retaining only the term linear in the scale of the vector field is implemented by separating it into the inner derivative and the exterior derivative. (In this context, \"forms\" and the exterior calculus refer exclusively to degrees of freedom which are dual to vector fields on the gauge bundle, not to degrees of freedom expressed in (Greek) tensor indices on the base manifold or (Roman) matrix indices on the gauge algebra.)\n\nThe Lie derivative on a manifold is a globally well-defined operation in a way that the partial derivative is not. The proper generalization of Clairaut's theorem to the non-trivial manifold structure of P is given by the Lie bracket of vector fields and the nilpotence of the exterior derivative. And we obtain an essential tool for computation: the generalized Stokes theorem, which allows us to integrate by parts and drop the surface term as long as the integrand drops off rapidly enough in directions where there is an open boundary. (This is not a trivial assumption, but can be dealt with by renormalization techniques such as dimensional regularization as long as the surface term can be made gauge invariant.)\n\n## BRST formalism\n\nIn theoretical physics, the BRST formalism is a method of implementing first class constraints. The letters BRST stand for Becchi, Rouet, Stora, and (independently) Tyutin who discovered this formalism. It is a sophisticated method to deal with quantum physical theories with gauge invariance. For example, the BRST methods are often applied to gauge theory and quantized general relativity.\n\n### Quantum version\n\nThe space of states is not a Hilbert space (see below). This vector space is both Z2-graded and R-graded. If you wish, you may think of it as a Z2 × R-graded vector space. The former grading is the parity, which can either be even or odd. The latter grading is the ghost number. Note that it is R and not Z because unlike the classical case, we can have nonintegral ghost numbers. Operators acting upon this space are also Z2 × R-graded in the obvious manner. In particular, Q is odd and has a ghost number of 1.\n\nLet Hn be the subspace of all states with ghost number n. Then, Q restricted to Hn maps Hn to Hn+1. Since Q2 = 0, we have a cochain complex describing a cohomology.\n\nThe physical states are identified as elements of cohomology of the operator Q, i.e. as vectors in Ker(Qn+1)/Im(Qn). The BRST theory is in fact linked to the standard resolution in Lie algebra cohomology.\n\nRecall that the space of states is Z2-graded. If A is a pure graded operator, then the BRST transformation maps A to [QA) where [ , ) is the supercommutator. BRST-invariant operators are operators for which [QA) = 0. Since the operators are also graded by ghost numbers, this BRST transformation also forms a cohomology for the operators since [Q, [QA)) = 0.\n\nAlthough the BRST formalism is more general than the Faddeev-Popov gauge fixing, in the special case where it is derived from it, the BRST operator is also useful to obtain the right Jacobian associated with constraints that gauge-fix the symmetry.\n\nThe BRST is a supersymmetry. It generates the Lie superalgebra with a zero-dimensional even part and a one-dimensional odd part spanned by Q. [QQ) = {QQ} = 0 where [ , ) is the Lie superbracket (i.e. Q2 = 0). This means Q acts as an antiderivation.\n\nBecause Q is Hermitian and its square is zero but Q itself is nonzero, this means the vector space of all states prior to the cohomological reduction has an indefinite norm! This means it is not a Hilbert space.\n\nFor more general flows which can't be described by first class constraints, see Batalin–Vilkovisky formalism.\n\n### Example\n\nFor the special case of gauge theories (of the usual kind described by sections of a principal G-bundle) with a quantum connection form A, a BRST charge (sometimes also a BRS charge) is an operator usually denoted Q.\n\nLet the ${\\mathfrak {g}}$", null, "-valued gauge fixing conditions be $G=\\xi \\partial ^{\\mu }A_{\\mu }$", null, "where ξ is a positive number determining the gauge. There are many other possible gauge fixings, but they will not be covered here. The fields are the ${\\mathfrak {g}}$", null, "-valued connection form A, ${\\mathfrak {g}}$", null, "-valued scalar field with fermionic statistics, b and c and a ${\\mathfrak {g}}$", null, "-valued scalar field with bosonic statistics B. c deals with the gauge transformations wheareas b and B deal with the gauge fixings. There actually are some subtleties associated with the gauge fixing due to Gribov ambiguities but they will not be covered here.\n\n$QA=Dc$", null, "where D is the covariant derivative.\n\n$Qc={\\tfrac {i}{2}}[c,c]_{L}$", null, "where [ , ]L is the Lie bracket, NOT the commutator.\n\n$QB=0$", null, "$Qb=B$", null, "Q is an antiderivation.\n\nThe BRST Lagrangian density\n\n${\\mathcal {L}}=-{\\frac {1}{4g^{2}}}\\operatorname {Tr} [F^{\\mu \\nu }F_{\\mu \\nu }]+{1 \\over 2g^{2}}\\operatorname {Tr} [BB]-{1 \\over g^{2}}\\operatorname {Tr} [BG]-{\\xi \\over g^{2}}\\operatorname {Tr} [\\partial ^{\\mu }bD_{\\mu }c]$", null, "While the Lagrangian density isn't BRST invariant, its integral over all of spacetime, the action is.\n\nThe operator Q is defined as\n\n$Q=c^{i}\\left(L_{i}-{\\frac {1}{2}}{{f_{i}}^{j}}_{k}b_{j}c^{k}\\right)$", null, "" ]
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https://www.gradesaver.com/textbooks/math/calculus/university-calculus-early-transcendentals-3rd-edition/chapter-3-section-3-11-linearization-and-differentials-exercises-page-198/13
[ "## University Calculus: Early Transcendentals (3rd Edition)\n\n$L(x)=-x+1$\n$f(x)=e^{-x}$, $L(x)=f(a)+f'(a)(x-a)$ $f'(x)=-e^{-x}$ $x_{0}=0$ $f(0)={e^0}=1$ $f'(0)=-e^{-0}=-1$ then $L(x)=1-1(x-0)=-x+1$ $L(x)=-x+1$ Thus, the final answer is: $L(x)=-x+1$" ]
[ null ]
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https://calculat.io/en/number/decimal-as-a-fraction/3.825
[ "# Decimal 3.825 as a fraction\n\n## What is 3.825 as a fraction in simplest form?\n\nAnswer: Decimal 3.825 as a fraction is 3 33/40\n3.825=\n153\n/\n40\n=3\n33\n/\n40\n\nThe fractional equivalent of 3.825 is 3 33/40\n\n## Explanation of 3.825 Decimal to Fraction Conversion\n\nIn order to find the simplest fraction form of 3.825 first we need to write out decimal number 3.825 as fraction. Any number can be written as a fraction quite simply - just divide it by 1:\n\n3.825 =\n3.825\n/\n1\n\nNext we need to get rid of the decimal part in our numerator so that the numerator in our fraction becomes a whole number. To do so we need to multiply both numerator and denominator by 1000 (because there are 3 digits after the decimal point in the number 3.825):\n\n3.825 × 1000\n/\n1 × 1000\n=\n3825\n/\n1000\n\nNow we need to simplify our fraction to its simplest form. To do so we have to find the Greatest Common Factor (GCF) of 3825 and 1000. To find the GCF of 2 numbers you can use our GCF Calculator . GCF of 1000 and 3825 is 25. So in order to simplify our fraction we need to divide both numerator and denominator by 25:\n\n3825 ÷ 25\n/\n1000 ÷ 25\n=\n153\n/\n40\n=3\n33\n/\n40\n\nThat's it! 3.825 as a fraction in it's simplest form is equal to 3 33/40.\n\n## About \"Decimal to Fraction Converter\" Calculator\n\nThis online Decimal to Fraction converter is a tool that can help you convert any decimal number into its fractional form quickly and easily. For example, it can help you find out what is 3.825 as a fraction in simplest form? (The answer is: 3 33/40). It is especially useful for those who need to work with fractions in their daily lives or in academic or professional settings.\n\nTo use this converter, all you need to do is enter the decimal number you want to convert into the designated field, for example, '3.825'. Once you have entered the decimal, hit the 'Convert' button to start the conversion process.\n\nThe converter will then show you the fractional equivalent of the decimal number you entered, as well as provide a step-by-step explanation of the conversion process. Additionally, the final fraction will be simplified to its simplest form using the greatest common factor (GCF).\n\nFor example, if you enter '3.825' into the converter, it will show you that this decimal is equivalent to the fraction '3 33/40'. It will also explain how it arrived at this answer, showing you the steps involved in the conversion process.\n\nOverall, the online Decimal to Fraction converter is an essential tool for anyone who needs to work with fractions, whether in everyday life or in an academic or professional context. It is fast, easy to use, and provides accurate results, making it a valuable resource for anyone who needs to convert decimals to fractions.\n\n## FAQ\n\n### What is 3.825 as a fraction in simplest form?\n\nDecimal 3.825 as a fraction is 3 33/40" ]
[ null ]
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http://perplexus.info/show.php?pid=10987&cid=58651
[ "", null, "All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars", null, "", null, "perplexus dot info", null, "", null, "Square Egyptians (Posted on 2017-06-28)", null, "Express 1/2 as the sum of Square Egyptian Numbers with distinct denominators under 362.\n\nI.e. reciprocals of perfect squares.\n\n No Solution Yet Submitted by Jer No Rating", null, "Comments: ( Back to comment list | You must be logged in to post comments.)", null, "computer solution Comment 1 of 1\n1/2 = 1/4 + 1/9 + 1/16 + 1/25 + 1/49 + 1/144 + 1/225 + 1/400 + 1/784 + 1/1225\n\nThe denominators are the squares of:\n\n2 3 4 5 7 12 15 20 28 35\n\nas found by the below VB program and verified by using exact rational fractions in UBASIC.\n\nThe program  produces a total that prints out as exactly .5 but did not register as equal to .5 within the program, due to rounding, and thus necessitated the difference to be below the small threshhold of absolute value difference shown in the program, rather than testing if = 0.5.\n\nThe first portion of the program determined how far back from 1/36^2 would be necessary and found that the first term must be 1/2^2, otherwise the total would be impossible. It was only after this was run that the rest of the program was added, to find the actual result.\n\nDefDbl A-Z\nDim crlf\\$, h(36), tot\n\nForm1.Visible = True\n\nText1.Text = \"\"\ncrlf = Chr\\$(13) + Chr\\$(10)\n\nFor rt = 36 To 1 Step -1\nptot = tot\ntot = tot + 1 / (rt * rt)\nIf tot >= 0.5 Then Text1.Text = Text1.Text & rt & Str(tot) & Str(ptot) & crlf & crlf: Exit For\nNext\n\nh(1) = 4: tot = 1 / 4\n\nText1.Text = Text1.Text & crlf & \" done\"\n\nEnd Sub\n\nDoEvents\nst = Int(Sqr(h(wh - 1)) + 0.5) + 1\nFor i = st To 36\nh(wh) = i * i\nsavetot = tot\ntot = tot + 1 / (i * i)\nIf Abs(tot - 0.5) < 0.000000000001 Then\nText1.Text = Text1.Text & tot & crlf & \"   \"\nFor j = 1 To wh\nText1.Text = Text1.Text & \" + 1/\" & h(j)\nNext\nText1.Text = Text1.Text & crlf\nFor j = 1 To wh\nText1.Text = Text1.Text & Str(Sqr(h(j)))\nNext\nText1.Text = Text1.Text & crlf\n\nEnd If\nIf i < 36 And tot < 0.5001 Then\nEnd If\ntot = savetot\nNext\nEnd Sub\n\n2 .617538519845469 .367538519845469\n\n0.5\n+ 1/4 + 1/9 + 1/16 + 1/25 + 1/49 + 1/144 + 1/225 + 1/400 + 1/784 + 1/1225\n2 3 4 5 7 12 15 20 28 35\n\n Posted by Charlie on 2017-06-28 13:59:04", null, "Please log in:\n\n Search: Search body:\nForums (4)" ]
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https://carloscaballero.es/refactoring-a-real-case/
[ "Angular\nJavaScript\nNestJS\nNodeJS\nTypeScript\nUI-UX\nZExtra\n\n# Refactoring a real-case\n\n6 min read\n\nAs a result of publishing the series of post of the clock-in/out system, I had the need to write a function to import the data from a large XLS file to a Postgres database using the ORM (TypeORM).\n\nThis function was written quickly as a script without thinking too much about the quality of the code, but simply \"work\". However, once the system is working and a test suite is available, it is a good idea to go through a constant refactoring to improve the code.\n\nNext I will show different refactoring steps that I have applied to this function to improve the quality of the code. Therefore, the function that we are going to improve is shown first.\n\n``````\nconst xls = require('node-xlsx').parse(__dirname + '/schedule.xls');\n\nexport function XSLToJson() {\nconst schedulers = [];\nconst users = [];\n\nxls.data.slice(2).forEach(teacher => {\nlet schedule = {};\nlet user = {};\n\nlet name = teacher.split(',');\nif (name.length > 1) {\nname = name + ', ' + name.trim() + '.';\n}\nuser = {\nuid: name,\nname,\n};\nusers.push(user);\nconst monday = [...teacher.slice(1, 7), ...teacher.slice(8, 14)];\nconst tuesday = [...teacher.slice(14, 20), ...teacher.slice(21, 27)];\nconst wednesday = [...teacher.slice(27, 33), ...teacher.slice(34, 40)];\nconst thursday = [...teacher.slice(40, 46), ...teacher.slice(47, 53)];\nconst friday = [...teacher.slice(53, 59), ...teacher.slice(60, 66)];\n\n[monday, tuesday, wednesday, thursday, friday].forEach((day, numberOfDay) =>\nday.forEach((room, hour) => {\nif (room) {\nschedule = {\nuser: {\nuid: name,\n},\nroom: room.replace(/\\n/g, ' - '),\nday: numberOfDay,\nhour,\n};\nschedulers.push(schedule);\n}\n}),\n);\n});\nreturn [schedulers, users];\n}\n\n``````\n\nFirstly, we can observe that there are different concepts in the same function, this gives us the warning that we need to extract functions. The following functions can be identified in the code:\n\n• normalizedUID: this function is used to generate the name/uid (string) of each teacher.\n• getDaysByTeacher: Returns an array in which each position represents each user's day. Each of the days is also represented by an array. Hence, this function returns an array of arrays in which we will have organized the weekly working hours of each user (fixed schedules).\n• factorySchedule: Create a schedule object from another object composed of the room, hour and number of day.\n\nimport.ts\n\n``````\nfunction normalizeUID(teacher): string {\nlet name = teacher.split(',');\nif (name.length > 1) {\nname = name + ', ' + name.trim() + '.';\n}\nreturn name;\n}\nfunction getDaysByTeacher(teacher): [any[], any[], any[], any[], any[]] {\nreturn [\n[...teacher.slice(1, 7), ...teacher.slice(8, 14)],\n[...teacher.slice(14, 20), ...teacher.slice(21, 27)],\n[...teacher.slice(27, 33), ...teacher.slice(34, 40)],\n[...teacher.slice(40, 46), ...teacher.slice(47, 53)],\n[...teacher.slice(53, 59), ...teacher.slice(60, 66)],\n];\n}\nfunction factorySchedule({ name, room, hour, numberOfDay }) {\nreturn {\nuser: {\nuid: name,\n},\nroom: room.replace(/\\n/g, ' - '),\nday: numberOfDay,\nhour,\n};\n}\n``````\n\nThe main code would be as follows after the extraction of functions:\n\n``````\nexport function XSLToJson() {\nconst schedulers = [];\nconst users = [];\n\nxls.data.slice(2).forEach(teacher => {\nlet schedule = {};\nlet user = {};\nconst name = normalizeUID(teacher);\nuser = {\nuid: name,\nname,\n};\nusers.push(user);\nconst days = getDaysByTeacher(teacher);\n\ndays.forEach((day, numberOfDay) =>\nday.forEach((room, hour) => {\nif (room) {\nconst schedule = factorySchedule({ name, room, hour, numberOfDay });\nschedulers.push(schedule);\n}\n}),\n);\n});\nreturn [schedulers, users];\n}\n\n``````\n\nBefore going on to address the next phase of refactoring, we will eliminate the variables that are understood using the domain of the problem, also the temporary variables will be removed.\n\n``````\nexport function XSLToJson() {\nconst schedulers = [];\nconst users = [];\n\nxls.data.slice(2).forEach(teacher => {\nconst name = normalizeUID(teacher);\nconst user = {\nuid: name,\nname,\n};\nusers.push(user);\nconst days = getDaysByTeacher(teacher);\n\ndays.forEach((day, numberOfDay) =>\nday.forEach((room, hour) => {\nif (room) {\nconst schedule = factorySchedule({ name, room, hour, numberOfDay });\nschedulers.push(schedule);\n}\n}),\n);\n});\nreturn [schedulers, users];\n}\n``````\n\nIn this moment, we see that we are making use of one of the most powerful features of JavaScript, functions as a parameter in the forEachmethods. But really, the forEach methods are only acting as syntactic sugar against the classical for of the imperative programming. Therefore, we will be modifying each forEach method by the most appropriate one according to the task that they perform.\n\nThe first forEach loop that we are going to address is the following:\n\n``````\ndays.forEach((day, numberOfDay) =>\nday.forEach((room, hour) => {\nif (room) {\nconst schedule = factorySchedule({ name, room, hour, numberOfDay });\nschedulers.push(schedule);\n}\n}),\n);\n``````\n\nThis loop can be transformed into the method reduce because of what we want to get a single value (an array) after iterating through each of the days. In addition, the schedule variable can be omitted and the factorSchedule method can be invoked directly since the creation of this variable does not add semantic value in the code.\n\n``````\ndays.forEach((day, numberOfDay) => {\nschedulers = day.reduce((acc, room, hour) => {\nif (room) {\nacc.push(factorySchedule({ name, room, hour, numberOfDay }));\n}\nreturn acc;\n}, []);\n});\n``````\n\nIf we observe the function performed in the body of the method reduce, it is an if-else which can be transformed into a ternary operation that we can combine with the potential of immutability (another characteristic of functional programming) leaving the code as follows:\n\n``````\ndays.forEach((day, numberOfDay) => {\nschedulers = day.reduce((acc, room, hour) => {\nreturn room\n? [...acc, factorySchedule({ name, room, hour, numberOfDay })]\n: acc;\n}, []);\n});\n``````\n\nAnother small step in the refactoring would be to omit the explicit invocation of return when using fat-arrow (lambda functions) of JavaScript, leaving the code as follows:\n\n``````\ndays.forEach((day, numberOfDay) => {\nschedulers = day.reduce(\n(acc, room, hour) =>\nroom ? [...acc, factorySchedule({ name, room, hour, numberOfDay })] : acc,\n[],\n);\n});\n``````\n\nIf we look at the code, the next natural step will be to replace the forEach method that includes the reduce by another method reduce. It may seem complicated the code that will generate since we are using  the features of fat-arrow and spread operator (...) which if you never are used before can seem abstract (we will solve it by creating functions that allow you to decompose the task).\n\n``````\nschedulers1 = days.reduce(\n(acc, day, numberOfDay) => [\n...acc,\nday.reduce(\n(schedulers, room, hour) =>\ngenerateScheduler({ room, schedulers, hour, numberOfDay, name }),\n[],\n),\n],\n[],\n);\n``````\n\nTherefore, the next step is to build small functions that perform the task that is done within each of the reduce. But we have a small problem, we need to pass extra parameters to each of the callbacks of the reduce methods. This problem is easily solved in JavaScript with different techniques such as overwriting the scope (this), using variables from a larger scope, or your own such as the bind, apply or call methods.\n\nIn our case, we are going to create several small functions that combined with the bind method will solve the problem of passing parameters in the callbacks. In this way, the resulting code until this moment would be the following:\n\n``````\nexport function XSLToJson() {\nconst users = [];\nlet schedulers = [];\nxls.data.slice(2).forEach(teacher => {\nconst name = normalizeUID(teacher);\nconst user = {\nuid: name,\nname,\n};\nusers.push(user);\nconst days = getDaysByTeacher(teacher);\n\nschedulers = days.reduce(generateSchedulers.bind(null, name), []);\n});\nreturn [schedulers, users];\n}\nfunction generateSchedulers(name, schedulers, day, numberOfDay) {\nreturn [\n...schedulers,\nday.reduce(generateScheduler.bind(null, numberOfDay, name), []),\n];\n}\n\nfunction generateScheduler(numberOfDay, name, schedulers, room, hour) {\nreturn room\n? [...schedulers, factorySchedule({ name, room, hour, numberOfDay })]\n: schedulers;\n}\n\n``````\n\nThe next step is to address the forEach method that encompasses the entire main method. The elimination of this method will allow us to eliminate the two variables that act as accumulators (users and schedulers). In such a way, that the method reduce will receive as an accumulator an array that contains two arrays (schedulers and users), which will be unstructured to be able to be concatenated easily in the method reduced.\n\nAfter refactoring the code we find the following version:\n\n``````\nexport function XSLToJson() {\nreturn xls.data.slice(2).reduce(\n([schedulers, users], teacher) => {\nconst name = normalizeUID(teacher);\nconst user = {\nuid: name,\nname,\n};\nconst days = getDaysByTeacher(teacher);\nconst scheduler = days.reduce(generateSchedulers.bind(null, name), []);\nreturn [[...schedulers, scheduler], [...users, user]];\n},\n[[], []],\n);\n}\n\n``````\n\nIn the same way as we did in the previous case, the method reduce receives a callback that is the one that performs the conversion to JSON, and finally we rename the content of the file to a variable called xls. So the partial result is the following:\n\n``````\n\nexport function XSLToJson() {\nreturn xls.reduce(convertToJson, [[], []]);\n}\nfunction convertToJson([schedulers, users], teacher) {\nconst name = normalizeUID(teacher);\nconst user = {\nuid: name,\nname,\n};\nconst days = getDaysByTeacher(teacher);\nconst scheduler = days.reduce(generateSchedulers.bind(null, name), []);\nreturn [[...schedulers, scheduler], [...users, user]];\n}\n``````\n\nFinally the result of the script after making these changes is shown below:\n\n``````\nconst xls = require('node-xlsx')\n.parse(__dirname + '/schedule.xls')\n.data.slice(2);\n\nexport function XSLToJson() {\nreturn xls.reduce(convertToJson, [[], []]);\n}\nfunction convertToJson([schedulers, users], teacher) {\nconst name = normalizeUID(teacher);\nconst user = {\nuid: name,\nname,\n};\nconst days = getDaysByTeacher(teacher);\nconst scheduler = days.reduce(generateSchedulers.bind(null, name), []);\nreturn [[...schedulers, scheduler], [...users, user]];\n}\nfunction normalizeUID(teacher): string {\nlet name = teacher.split(',');\nif (name.length > 1) {\nname = name + ', ' + name.trim() + '.';\n}\nreturn name;\n}\nfunction getDaysByTeacher(teacher): [any[], any[], any[], any[], any[]] {\nreturn [\n[...teacher.slice(1, 7), ...teacher.slice(8, 14)],\n[...teacher.slice(14, 20), ...teacher.slice(21, 27)],\n[...teacher.slice(27, 33), ...teacher.slice(34, 40)],\n[...teacher.slice(40, 46), ...teacher.slice(47, 53)],\n[...teacher.slice(53, 59), ...teacher.slice(60, 66)],\n];\n}\nfunction factorySchedule({ name, room, hour, numberOfDay }) {\nreturn {\nuser: {\nuid: name,\n},\nroom: room.replace(/\\n/g, ' - '),\nday: numberOfDay,\nhour,\n};\n}\n\nfunction generateSchedulers(name, schedulers, day, numberOfDay) {\nreturn [\n...schedulers,\nday.reduce(generateScheduler.bind(null, numberOfDay, name), []),\n];\n}\n\nfunction generateScheduler(numberOfDay, name, schedulers, room, hour) {\nreturn room\n? [...schedulers, factorySchedule({ name, room, hour, numberOfDay })]\n: schedulers;\n}\n``````\n\nSummary\n\n1. Extract functions.\n2. Name the functions and variables must be an identification value.\n3. Use the built-in language methods for your use (forEach against of reduce).\n4. Abstract complexity and details of the code to auxiliary functions of lower level." ]
[ null ]
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https://chem.libretexts.org/Bookshelves/Ancillary_Materials/Worksheets/Worksheets%3A_General_Chemistry/Worksheets%3A_General_Chemistry_(Traditional)/Point_Groups_2_(Worksheet)
[ "# Point Groups 2 (Worksheet)\n\nName: ______________________________\n\nSection: _____________________________\n\nStudent ID#:__________________________\n\nWork in groups on these problems. You should try to answer the questions without referring to your textbook. If you get stuck, try asking another group for help.\n\nDetermine the point group assignment for the following:", null, "", null, "", null, "", null, "", null, "", null, "", null, "acetylene", null, "", null, "", null, "", null, "", null, "", null, "$$PtCl_2I_2^{2-}$$ (cis and trans) $$XeOF_4$$ $$AsF_5$$ $$PF_3$$ $$SCl_4$$ benzene $$BrF_3$$ $$S_8$$ (crown) Staggered ethane $$I_3^-$$", null, "", null, "$$Mo(CO)_6$$ A black cat at its highest symmetry $$CS_2$$ A three-legged stool $$PFCl_2$$ A rectangular brick" ]
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https://epub.ub.uni-muenchen.de/5140/
[ "", null, "", null, "Gabriel, Wilfried; Taylor, B. E.; Kirsch-Prokosch, Susanne (1987): Cladoceran birth and death rates estimates. Experimental comparisons of egg-ratio methods. In: Freshwater Biology, Vol. 18, No. 2: pp. 361-372", null, "", null, "Preview\n3MB\n\n### Abstract\n\nI. Birth and death rates of natural cladoceran populations cannot be measured directly. Estimates of these population parameters must be calculated using methods that make assumptions about the form of population growth. These methods generally assume that the population has a stable age distribution. 2. To assess the effect of variable age distributions, we tested six egg ratio methods for estimating birth and death rates with data from thirty-seven laboratory populations of Daphnia pulicaria. The populations were grown under constant conditions, but the initial age distributions and egg ratios of the populations varied. Actual death rates were virtually zero, so the difference between the estimated and actual death rates measured the error in both birth and death rate estimates. 3. The results demonstrate that unstable population structures may produce large errors in the birth and death rates estimated by any of these methods. Among the methods tested, Taylor and Slatkin's formula and Paloheimo's formula were most reliable for the experimental data. 4. Further analyses of three of the methods were made using computer simulations of growth of age-structured populations with initially unstable age distributions. These analyses show that the time interval between sampling strongly influences the reliability of birth and death rate estimates. At a sampling interval of 2.5 days (equal to the duration of the egg stage), Paloheimo's formula was most accurate. At longer intervals (7.5–10 days), Taylor and Slatkin's formula which includes information on population structure was most accurate.", null, "", null, "" ]
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https://www.wias-berlin.de/publications/wias-publ/run.jsp?template=abstract&type=Preprint&year=&number=2591
[ "WIAS Preprint No. 2591, (2019)\n\n# A class of second-order geometric quasilinear hyperbolic PDEs and their application in imaging science\n\nAuthors\n\n• Dong, Guozhi\nORCID: 0000-0002-9674-6143\n• Hintermüller, Michael\nORCID: 0000-0001-9471-2479\n• Zhang, Ye\n\n2010 Mathematics Subject Classification\n\n• 35L10 35L70 35L72\n\nKeywords\n\n• Quasilinear hyperbolic equation, geometric PDEs, total variation flow, mean curvature flow, level set, second-order dynamics, non-smooth and non-convex variational methods, image denoising, displacement error correction\n\nDOI\n\n10.20347/WIAS.PREPRINT.2591\n\nAbstract\n\nIn this paper, we study damped second-order dynamics, which are quasilinear hyperbolic partial differential equations (PDEs). This is inspired by the recent development of second-order damping systems for accelerating energy decay of gradient flows. We concentrate on two equations: one is a damped second-order total variation flow, which is primarily motivated by the application of image denoising; the other is a damped second-order mean curvature flow for level sets of scalar functions, which is related to a non-convex variational model capable of correcting displacement errors in image data (e.g. dejittering). For the former equation, we prove the existence and uniqueness of the solution. For the latter, we draw a connection between the equation and some second-order geometric PDEs evolving the hypersurfaces which are described by level sets of scalar functions, and show the existence and uniqueness of the solution for a regularized version of the equation. The latter is used in our algorithmic development. A general algorithm for numerical discretization of the two nonlinear PDEs is proposed and analyzed. Its efficiency is demonstrated by various numerical examples, where simulations on the behavior of solutions of the new equations and comparisons with first-order flows are also documented.\n\nAppeared in" ]
[ null ]
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https://mathcoachblog.com/2014/11/07/class-opener-day-44-statistics-clue-boxes/
[ "# Class Opener – Day 44 – Statistics Clue Boxes\n\nA problem I gave as review for our statistics test today became not only a source of conversation regarding vocabulary, but provided me some insight into the problem solving approaches of my students.\n\nHere’s the problem. A list of numbers is given, listed in order, with some numbers removed:", null, "The list has the following characteristics:\n\n• A mean of 76\n• A range of 32\n• An inter-quartile range of 21\n\nMany students quickly understood the last blank must be 92, due to the range, but then became stuck.  As we’ve never explicity seen a problem like this before, the reactions from students was fascinating.  Some pockets of students had no fear in drawing circles and arrows to break down the data set. Others preferred to talk ideas out, but without putting pen to paper this doesn’t lead to solutions right away. I was thrilled to see a few students step up and take the lead, and explain their ideas to others, which then led to breakthroughs.  Identifying the positions of median and quartiles here lets us fill in one of the missing numbers:", null, "But a subset of my class was content to watch from afar, waiting for hints which they assumed would come. Or worse, tuning out until I presented an explanation to the class….which never came.\n\nAnd that last blank caused more trouble than I would have expected, as some students had trouble making the connection between the mean of a data set and the sum of its elements.  To help with this, I asked struggling students to provide me with any 4 numbers which had a mean of 10 (making them different numbers).  I asked students what I should be looking for to check accuracy besides computing the mean….and then, the light bulb!  All lists need to add up to 40!  So without explictly doing the empty blank problem in front of us, I sent students back to the board to think about this fact.  And the results were satisfying, as many of my fringe students could now complete the task and explain their procedure to their peers.\n\nStudents need to understand math ideas in many forms, and the concept of mean here demonstrates this need.  If you ask a student how to compute a mean, they most likely have little difficulty, and have had much practice:\n\nMean = sum of “scores” / count of “scores”\n\nBut in the missing numbers puzzle, the concept “felt” different and thus “new” to many students.  For me, this is where many students struggle in math classrooms.  Are we showing students how ideas and problems connect to big ideas?  Or does each combination of an existing problem become treated like a new experience?  It’s hard to break the pattern of students wanting specific rules for each type of math problem, when this is often the math conditioning they receive. But it’s worth the hard-fought battle.\n\nAnd if you had fun with the challenge at the start of this post, try the similar problem I give later as an assessment:", null, "" ]
[ null, "https://mathcoachblog.files.wordpress.com/2014/11/pic2.jpg", null, "https://mathcoachblog.files.wordpress.com/2014/11/pic1.jpg", null, "https://mathcoachblog.files.wordpress.com/2014/11/boxes.png", null ]
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https://apcz.umk.pl/czasopisma/index.php/TMNA/article/view/TMNA.2004.006
[ "### Differential inclusions on closed sets in Banach spaces with application to sweeping process\n\nHoucine Benabdellah\n\nDOI: http://dx.doi.org/10.12775/TMNA.2004.006\n\n#### Abstract\n\nThis paper deals with the existence of absolutely continuous solutions of a\ndifferential inclusion with state constraint in a separable Banach space%\n$$x( 0) =x_{0}, \\quad x( t) \\in C( t) ,\\quad \\dot{x}( t) \\in F( t,x( t) )$$\nwhere $C\\colon [ 0,a] \\rightarrow X$ is a multifunction with closed graph\n$G$ and $F\\colon G\\rightarrow X$ is a convex compact valued multifunction\nwhich is\nseparately measurable in $t\\in[ 0,a]$ and separately upper\nsemicontinuous in $x\\in X$. Application to a non convex sweeping process is\nalso considered.\n\n#### Keywords\n\nDifferential inclusions; Bouligand cone; Scorza-Dragoni theorem\n\nFULL TEXT\n\n### Refbacks\n\n• There are currently no refbacks." ]
[ null ]
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https://ace-writers.com/help-with-homework-online-class-work-and-assignments-17350/
[ "# Need help with QNT295 statistics\n\nHow would you explain the difference between a confounding variable and a lurking variable?\n\nWhat are the components of a time series? What external factors might affect each of the different component?\n\nSuccessful forecasting? (Example)\n\nWhat are the conditions we must check when summarizing the association between two variables with a line and why is this important?\n\nJoint and Marginal Probability (example)\n\nDifferences between independents and dependent event", null, "" ]
[ null, "https://writerbay.net/wp-content/uploads/2020/08/paper.png", null ]
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https://vsbattles.fandom.com/wiki/User_blog:Morning_Star_TM/RWBY_-_Weiss_creates_an_ice_construct_that_knock_off_a_mecha
[ "# VS Battles Wiki\n\nWe have moved to a new external forum hosted at https://vsbattles.com\n\nWe have a new automated signup system for our wiki members, with a procedure that must be exactly followed in order to register.\n\n## Introduction\n\nPage that holds feat in question: Scan.\n\nBasically, Weiss creates an ice construct that knocks off this giant robot. I will calculate the amount of ice that she created.\n\n## Calculation\n\nSince the whole ice construct is not definite in shape, i will try to measure each icicle 1 by 1.\n\n1st, let's bring forth the height of each icicle. ( I swear this job is going to kill me with shortened age).\n\nRuby (The small black dot in front of the ice) = 10 px = 1.62 m.\n\nPixel scaling = 1.62/10 = 0.162 m/px.\n\n### Icicles' Heights\n\nHeight of 1st icicle = 43 px = 6.966 meters.\n\nHeight of 2nd icicle = Height of 1st icicle = 6.966 meters.\n\nHeight of 3rd icicle = 56 px = 9.072 meters.\n\nHeight of 4th icicle = 70 px = 11.34 meters.\n\nHeight of 5th icicle = 77 px = 12.474 meters.\n\nHeight of 6th icicle = 82 px = 13.284 meters.\n\nHeight of 7th icicle = 82 px = 13.284 meters.\n\nHeight of 8th icicle = 99 px = 16.038 meters.\n\nHeight of 9th icicle = 117 px = 18.954 meters.\n\nHeight of 10th icicle = 202 px = 32.724 meters.\n\nHeight of 11th icicle = 223 px = 36.126 meters.\n\nWith that out of the way, let's determine the radius of each icicle. (I really want to die right now)\n\nDiameter of 1st icicle = 6 px = 0.972 meters.\n\nRadius of 1st icicle = 0.486 meters.\n\nDiameter of 2nd icicle = 8 px = 1.296 meters.\n\nRadius of 2nd icicle = 0.648 meters.\n\nDiameter of 3rd icicle = 5 px = 0.81 meters.\n\nRadius of 3rd icicle = 0.405 meters.\n\nDiameter of 4th icicle = 6 px = 0.972 meters.\n\nRadius of 4th icicle = 0.486 meters.\n\nDiameter of 5th icicle = 16 px = 2.592 meters.\n\nRadius of 5th icicle = 1.296 meters.\n\nDiameter of 6th icicle = 37 px = 5.994 meters.\n\nRadius of 6th icicle = 2.997 meters.\n\nDiameter of 7th icicle = 7 px = 1.134 meters.\n\nRadius of 7th icicle = 0.567 meters.\n\nDiameter of 8th icicle = 10 px = 1.62 meters.\n\nRadius of 8th icicle = 0.81 meters.\n\nDiameter of 9th icicle = 18 px = 2.916 meters.\n\nRadius of 9th icicle = 1.458 meters.\n\nDiameter of 10th icicle = 75 px = 12.15 meters.\n\nRadius of 10th icicle = 6.075 meters.\n\nDiameter of 11th icicle = 38 px = 6.156 meters.\n\nRadius of 11th icicle = 3.078 meters.\n\nOkay. With that out of the way, each and every single 1 of those icicles resemble a cylinder to me, so i will gather each and every single 1 of them and apply the volume of a cylinder to each icicle.\n\n### Icicles' Volumes\n\nVolume of 1st icicle = 5.1689922538252 m^3.\n\nVolume of 2nd icicle = 9.1893195623559 m^3.\n\nVolume of 3rd icicle = 4.674799195966 m^3.\n\nVolume of 4th icicle = 8.4146385527387 m^3.\n\nVolume of 5th icicle = 65.821172679201 m^3.\n\nVolume of 6th icicle = 374.84543438625 m^3.\n\nVolume of 7th icicle = 13.416673692422 m^3.\n\nVolume of 8th icicle = 33.057508600045 m^3.\n\nVolume of 9th icicle = 126.58020565763 m^3.\n\nVolume of 10th icicle = 3794.1004188688 m^3.\n\nVolume of 11th icicle = 1075.2438847796 m^3.\n\nAnyways, with that out of the way, taking into account that the density of water is 1000 kg/m^3, let's determine the mass of each icicle.\n\n### Icicles' Masses\n\nMass of 1st icicle = 5.1689922538252 * 1000 = 5169 kg.\n\nMass of 2nd icicle = 9.1893195623559 * 1000 = 9189.32 kg.\n\nMass of 3rd icicle = 4.674799195966 * 1000 = 4674.8 kg.\n\nMass of 4th icicle = 8.4146385527387 * 1000 = 8414.64 kg.\n\nMass of 5th icicle = 65.821172679201 * 1000 = 65821.2 kg.\n\nMass of 6th icicle = 374.84543438625 * 1000 = 374845.4344 kg.\n\nMass of 7th icicle = 13.416673692422 * 1000 = 13416.7 kg.\n\nMass of 8th icicle = 33.057508600045 * 1000 = 33057.51 kg.\n\nMass of 9th icicle = 126.58020565763 * 1000 = 126580.206 kg.\n\nMass of 10th icicle = 3794.1004188688 * 1000 = 3794100.42 kg.\n\nMass of 11th icicle = 1075.2438847796 * 1000 = 1075244 kg.\n\nLastly, we find the E of all of this.\n\n### Icicles' (E)\n\nI am using the ocean water method due to the fact that Weiss created the ice on the surface of what looks like an ocean. This doesn't look like a lake at all.\n\nSpecific Heat Capacity of water = 4181 J/kg.\n\nTemperature = 15 C. (Let's go with 15 degrees for temperature difference. 20 degrees would have meant that the water would be almost room temperature anyways).\n\nNow, to find the E:\n\n#### (E) through Total Mass\n\nTotal Mass of all icicles = 5510513.2304 kg.\n\nQ1 = MC(Delta T) = (5510513.2304)(4181)(15) = 345591837244.5 Joules.\n\nQ2 = (5510513.2304)(334000) = 1.840511418954e12 Joules.\n\nE = Q1 + Q2 = 2.186103256199e12 Joules = 522.5 Tons of TNT (Multi-City Block level).\n\n#### Revised Calculation by Mr. TheRustyOne\n\nQuoting from said Mister:\n\n “ This is amazing but those aren't cylinders, cylinders don't have a point at the top. I think using a cone would be more accurate. „ ~ TheRustyOne\n\nVolume 1 = 1.7229974179417 m^3\n\nVolume 2 = 3.0631065207853 m^3\n\nVolume 3 = 1.5582663986553 m^3\n\nVolume 4 = 2.8048795175796 m^3\n\nVolume 5 = 21.940390893067 m^3\n\nVolume 6 = 124.94847812875 m^3\n\nVolume 7 = 4.4722245641408 m^3\n\nVolume 8 = 11.019169533348 m^3\n\nVolume 9 = 42.193401885876 m^3\n\nVolume 10 = 1264.7001396229 m^3\n\nVolume 11 = 358.41462825985 m^3\n\nTotal Volume = 1836.83768274 m^3\n\nTotal Mass of all icicles = 1836.83768274 x 1000 = 1836837.68274 kg.\n\nQ1 = MC(Delta T) = (1836837.68274)(4181)(15) = 115197275273 Joules.\n\nQ2 = (1836837.68274)(334000) = 613503786035.2 Joules.\n\nE = Q1 + Q2 = 728701061308.2 Joules = 174.2 Tons of TNT (Multi-City Block level).\n\n## Final Conclusion\n\nWeiss creates an ice construct that knock off a mecha (Total Mass Method) = 522.5 Tons of TNT (Multi-City Block level).\n\nWeiss creates an ice construct that knock off a mecha (Mr. TheRustyOne Method) = 174.2 Tons of TNT (Multi-City Block level).\n\nCredits to Mr. TheRustyOne for giving me the more accurate scan and helping me with the calculation, and for Mr. Dargoo Faust for giving me the accurate idea of how to calculate this." ]
[ null ]
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https://www.colorhexa.com/14ff7f
[ "# #14ff7f Color Information\n\nIn a RGB color space, hex #14ff7f is composed of 7.8% red, 100% green and 49.8% blue. Whereas in a CMYK color space, it is composed of 92.2% cyan, 0% magenta, 50.2% yellow and 0% black. It has a hue angle of 147.3 degrees, a saturation of 100% and a lightness of 53.9%. #14ff7f color hex could be obtained by blending #28fffe with #00ff00. Closest websafe color is: #00ff66.\n\n• R 8\n• G 100\n• B 50\nRGB color chart\n• C 92\n• M 0\n• Y 50\n• K 0\nCMYK color chart\n\n#14ff7f color description : Vivid cyan - lime green.\n\n# #14ff7f Color Conversion\n\nThe hexadecimal color #14ff7f has RGB values of R:20, G:255, B:127 and CMYK values of C:0.92, M:0, Y:0.5, K:0. Its decimal value is 1376127.\n\nHex triplet RGB Decimal 14ff7f `#14ff7f` 20, 255, 127 `rgb(20,255,127)` 7.8, 100, 49.8 `rgb(7.8%,100%,49.8%)` 92, 0, 50, 0 147.3°, 100, 53.9 `hsl(147.3,100%,53.9%)` 147.3°, 92.2, 100 00ff66 `#00ff66`\nCIE-LAB 88.541, -76.301, 47.128 39.876, 73.197, 32.104 0.275, 0.504, 73.197 88.541, 89.682, 148.298 88.541, -78.956, 75.339 85.555, -66.524, 37.64 00010100, 11111111, 01111111\n\n# Color Schemes with #14ff7f\n\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #ff1494\n``#ff1494` `rgb(255,20,148)``\nComplementary Color\n• #1fff14\n``#1fff14` `rgb(31,255,20)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #14fff5\n``#14fff5` `rgb(20,255,245)``\nAnalogous Color\n• #ff141f\n``#ff141f` `rgb(255,20,31)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #f514ff\n``#f514ff` `rgb(245,20,255)``\nSplit Complementary Color\n• #ff7f14\n``#ff7f14` `rgb(255,127,20)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #7f14ff\n``#7f14ff` `rgb(127,20,255)``\n• #94ff14\n``#94ff14` `rgb(148,255,20)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #7f14ff\n``#7f14ff` `rgb(127,20,255)``\n• #ff1494\n``#ff1494` `rgb(255,20,148)``\n• #00c75a\n``#00c75a` `rgb(0,199,90)``\n• #00e066\n``#00e066` `rgb(0,224,102)``\n• #00fa72\n``#00fa72` `rgb(0,250,114)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #2eff8d\n``#2eff8d` `rgb(46,255,141)``\n• #47ff9b\n``#47ff9b` `rgb(71,255,155)``\n• #61ffa9\n``#61ffa9` `rgb(97,255,169)``\nMonochromatic Color\n\n# Alternatives to #14ff7f\n\nBelow, you can see some colors close to #14ff7f. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #14ff44\n``#14ff44` `rgb(20,255,68)``\n• #14ff58\n``#14ff58` `rgb(20,255,88)``\n• #14ff6b\n``#14ff6b` `rgb(20,255,107)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #14ff93\n``#14ff93` `rgb(20,255,147)``\n• #14ffa6\n``#14ffa6` `rgb(20,255,166)``\n• #14ffba\n``#14ffba` `rgb(20,255,186)``\nSimilar Colors\n\n# #14ff7f Preview\n\nThis text has a font color of #14ff7f.\n\n``<span style=\"color:#14ff7f;\">Text here</span>``\n#14ff7f background color\n\nThis paragraph has a background color of #14ff7f.\n\n``<p style=\"background-color:#14ff7f;\">Content here</p>``\n#14ff7f border color\n\nThis element has a border color of #14ff7f.\n\n``<div style=\"border:1px solid #14ff7f;\">Content here</div>``\nCSS codes\n``.text {color:#14ff7f;}``\n``.background {background-color:#14ff7f;}``\n``.border {border:1px solid #14ff7f;}``\n\n# Shades and Tints of #14ff7f\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #000000 is the darkest color, while #ecfff5 is the lightest one.\n\n• #000000\n``#000000` `rgb(0,0,0)``\n• #001409\n``#001409` `rgb(0,20,9)``\n• #002812\n``#002812` `rgb(0,40,18)``\n• #003b1b\n``#003b1b` `rgb(0,59,27)``\n• #004f24\n``#004f24` `rgb(0,79,36)``\n• #00622d\n``#00622d` `rgb(0,98,45)``\n• #007636\n``#007636` `rgb(0,118,54)``\n• #008a3f\n``#008a3f` `rgb(0,138,63)``\n• #009d48\n``#009d48` `rgb(0,157,72)``\n• #00b151\n``#00b151` `rgb(0,177,81)``\n• #00c559\n``#00c559` `rgb(0,197,89)``\n• #00d862\n``#00d862` `rgb(0,216,98)``\n• #00ec6b\n``#00ec6b` `rgb(0,236,107)``\n• #00ff74\n``#00ff74` `rgb(0,255,116)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\n• #28ff8a\n``#28ff8a` `rgb(40,255,138)``\n• #3bff94\n``#3bff94` `rgb(59,255,148)``\n• #4fff9f\n``#4fff9f` `rgb(79,255,159)``\n• #62ffaa\n``#62ffaa` `rgb(98,255,170)``\n• #76ffb4\n``#76ffb4` `rgb(118,255,180)``\n• #8affbf\n``#8affbf` `rgb(138,255,191)``\n• #9dffca\n``#9dffca` `rgb(157,255,202)``\n• #b1ffd4\n``#b1ffd4` `rgb(177,255,212)``\n• #c5ffdf\n``#c5ffdf` `rgb(197,255,223)``\n• #d8ffea\n``#d8ffea` `rgb(216,255,234)``\n• #ecfff5\n``#ecfff5` `rgb(236,255,245)``\nTint Color Variation\n\n# Tones of #14ff7f\n\nA tone is produced by adding gray to any pure hue. In this case, #809389 is the less saturated color, while #14ff7f is the most saturated one.\n\n• #809389\n``#809389` `rgb(128,147,137)``\n• #779c88\n``#779c88` `rgb(119,156,136)``\n• #6ea587\n``#6ea587` `rgb(110,165,135)``\n• #65ae86\n``#65ae86` `rgb(101,174,134)``\n• #5cb785\n``#5cb785` `rgb(92,183,133)``\n• #53c085\n``#53c085` `rgb(83,192,133)``\n• #4ac984\n``#4ac984` `rgb(74,201,132)``\n• #41d283\n``#41d283` `rgb(65,210,131)``\n• #38db82\n``#38db82` `rgb(56,219,130)``\n• #2fe481\n``#2fe481` `rgb(47,228,129)``\n• #26ed81\n``#26ed81` `rgb(38,237,129)``\n• #1df680\n``#1df680` `rgb(29,246,128)``\n• #14ff7f\n``#14ff7f` `rgb(20,255,127)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #14ff7f is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
[ null ]
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https://googology.fandom.com/wiki/Subcubic_graph_number
[ "# Googology Wiki\n\nThis wiki's URL has been migrated to the primary fandom.com domain.Read more here\n\nThe subcubic graph numbers are the outputs of a fast-growing combinatorial function. They were devised by Harvey Friedman, who showed that it eventually dominates every recursive function provably total in the theory of $$\\Pi^1_1$$-$$\\text{CA}_0$$, and is itself provably total in the theory of $$\\Pi_1^1-\\textrm{CA}+\\textrm{BI}$$[citation needed].\n\nOne output of the sequence, SCG(13), is a subject of extensive research. It is known to surpass TREE(3), a number that arises from a related sequence.\n\n## Definition\n\nA subcubic graph is a finite graph in which each vertex has a valence of at most three, i.e. no vertex is connected to more than three edges. (For the sake of this article, subcubic graphs are allowed to be multigraphs, and are not required to be connected.) We also define the graph minor relation as follows: A is said to be a graph minor of B if we can derive A from the following process: start with B, remove vertices and edges, and contract edges. An example of a graph minor derivation is shown in the infobox of this article.\n\nGiven an integer k, suppose we have a sequence of subcubic graphs G1, G2, ... such that each graph Gi has at most i + k vertices and for no i < j is Gi homeomorphically embeddable into Gj (i.e. is a graph minor).\n\nThe Robertson-Seymour theorem proves that subcubic graphs are well-quasi-ordered by homeomorphic embeddability, implying such a sequence cannot be infinite. So, for each value of k, there is a sequence with maximal length. We denote this maximal length using SCG(k).\n\n## Specific values\n\nIt is possible to show that SCG(0) = 6. The first graph is one vertex with a loop,\n\nthe second is two vertices connected by a single edge, and the next four graphs consist of 3, 2, 1, and 0 unconnected vertices. All maximal sequences will peak and decline this way.\n\nThe following bounds have been claimed by Googology Wiki user Hyp cos.\n\n• $$\\text{SCG}(1) > f_{\\varepsilon_22}(f_{\\varepsilon_02}(f_{\\varepsilon_0+1}(f_{\\varepsilon_0}(f_{\\omega^\\omega+1}(f_{\\omega^5+\\omega^2+\\omega}(\\\\f_{\\omega^23+1}(f_{\\omega^22+1}(f_{\\omega^2+\\omega3+1}(f_{\\omega^2+1}(f_{\\omega^2}(3\\times2^{3\\times2^{95}})))))))))))$$.\n\n• $$\\text{SCG}(2) > f_{\\vartheta(\\Omega^\\omega)}(f_{\\varepsilon_22}(f_{\\varepsilon_02}(f_{\\varepsilon_0+1}(f_{\\varepsilon_0}(f_{\\omega^\\omega+1}(\\\\f_{\\omega^5+\\omega^2+\\omega}(f_{\\omega^23+1}(f_{\\omega^22+1}(f_{\\omega^2+\\omega3+1}(f_{\\omega^2+1}(f_{\\omega^2}(3\\times2^{3\\times2^{95}}))))))))))))$$\n\nThese bounds use a non-standard choice of fundamental sequences for ordinals — by using a particular, highly complex bijection between ordinals and small graphs, which we will denote here by $$f$$, we define $$\\alpha[n]=\\max\\{\\beta: \\beta<\\alpha\\text{ and } f(\\beta)\\text{ is a graph with }\\leq n\\text{ vertices}\\}$$.\n\nSince the graph indices start at one, it is also valid to say that SCG(-1) = 1, consisting only of the empty graph.\n\nFriedman stated that SCG(13) is greater than the halting time of any Turing machine such that it can be proven to halt in at most 22,000 symbols in $$\\Pi^1_1$$-$$\\text{CA}_0$$. It is therefore far larger than TREE(3).\n\nSCG(n) is computable,therefore it is naturally surpassed by $$\\Sigma(n)$$ for some n.\n\n## Matrix interpretation\n\nAn alternate way of describing the SCG function is as follows. Define an incidence matrix as a matrix with entries in {0, 1, 2} where each column sums to exactly 2 and each row sums to at most 3. Given a nonnegative integer k, we construct a sequence of n incidence matrices M1, M2, ..., Mn such that each matrix Mi has at most i + k rows, and no matrix can be changed into an earlier one by repeated applications of any of the following processes:\n\n• Reordering rows or columns.\n• Deleting columns.\n• Deleting rows, then deleting all columns that do not sum to 2.\n• Take two rows A and B such that A + B contains a 2 in position i for some i. Remove A and B, append A + B to the matrix, and finally remove column i.\n\nSCG(k), then, is the largest possible value of n.\n\n## Simple subcubic graph numbers\n\nIf we require the subcubic graphs to be simple (i.e. no loops or multiple edges), we get the simple subcubic graph numbers, denoted SSCG. Although this community believed that Adam P. Goucher has shown that SSCG(2) << TREE(3) << SSCG(3) in his article, it just contains a rough estimation without a proof. Moreover, the community believed that he has shown that even TREEn(3) for even very large n (for example n=TREE(3)) does not compete at all with SSCG(3). Later, he proved that TREE(3) < SSCG(3) in a different blog post.\n\nGoucher claimed that he had proved that $$\\text{SSCG}(4n+3) \\geq \\text{SCG}(n)$$ in his comment and hence SCG(n) and SSCG(n) have comparable growth rates. He later proved it in a later blog post.\n\nSimilar to the fact that there are many wrong informations on \"the actual results on TREE with proofs\", there are many statements on SCG which are said to be proved but do not have actual proofs. See also issues on analysis of TREE.\n\n### Values and bounds\n\n• SSCG(0) = 2\n• SSCG(1) = 5\n• SSCG(2) $$\\geq 3 \\cdot 2^{3 \\cdot 2^{95}}-8 \\approx 10^{3.5775 \\cdot 10^{28}}$$ (it is possible, that sequence of subcubic graphs that Adam P. Goucher has shown is really optimal, but it remains unproven.)\n\n## Sources\n\n1. Harvey Friedman, FOM 279:Subcubic Graph Numbers/restated\n2. Technically a topological minor, but topological minors and graph minors are equivalent for subcubic graphs.\n3. User blog:Hyp cos/SCG(n) and some related" ]
[ null ]
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https://www.studyadda.com/notes/10th-class/mathematics/triangles/triangles/15131
[ "10th Class Mathematics Triangles\n\nTriangles\n\nCategory : 10th Class\n\nTRIANGLES\n\nFUNDAMENTALS\n\nSimilar figures:", null, "• Figures having the same shape (not necessarily the same size) are called similar figures. Same shapes ensure that the corresponding angles are equal and their corresponding sides are proportional.\n\nCongruent figures:", null, "• Figures having the same shape and the same size are called congruent figures. Here, apart from angles, corresponding sides are also equal\n\nSimilar Triangles:\n\n• Two triangles are said to be similar, if their corresponding angles are equal and corresponding sides are proportional.", null, "e.g., If in $\\Delta \\,ABC$and $\\Delta \\,PQR$\n\n$\\angle A=\\angle P,\\angle B=\\angle Q,\\angle C=\\angle R$\n\nand       $\\frac{AB}{PQ}=\\frac{BC}{QR}=\\frac{AC}{PR},$       then, $\\Delta \\text{ }ABC\\sim \\Delta \\,PQR;$ where symbol $\\sim$ is read as ‘is similar to’.\n\n• When two triangles ($\\Delta \\text{ }ABC$and $\\Delta \\text{ }DEF$as below) are similar, then all above results about angles and ratio of sides hold good. However, in questions, when you are asked to prove similarly, you can either prove:", null, "(i) $\\angle A=\\angle D,\\angle B=\\angle E$ (called AA similarly)\n\nOr\n\n(ii) $\\frac{AB}{DE}=\\frac{BC}{EF}=\\frac{AC}{DF}$ (called SSS similarity)\n\nOr\n\n(iii) $\\frac{AB}{PQ}=\\frac{BC}{QR}$ and $\\angle B=\\angle Q$ (called SAS similarity)\n\nAny one of the above three, would be sufficient for proving similarity.\n\nConversely: If $\\Delta \\text{ }ABC$is similar to$\\Delta \\text{ }PQR$, then\n\n$\\angle A=\\angle D;\\angle B=\\angle E;\\angle C=\\angle Q$ and $\\frac{AB}{DE}=\\frac{BC}{EF}=\\frac{AC}{DF}$\n\n• When two triangles are congruent (notation for congruent is $\\cong$)\n\nThen, $\\angle A=\\angle D;\\text{ }\\angle B=\\angle E;\\text{ }\\angle C=\\angle F$\n\nand, $AB=DE,BC=EF$ and $CA=FD$\n\nHowever, to prove congruency, we need to prove any one of the following only:\n\n(i) $\\text{ }AB=DE,\\text{ }BC=EF\\And CA=FD$(SSS congruency)\n\nor\n\n(ii) $AB=DE;\\text{ }BC=EF\\And \\angle B=\\angle E$ (SAS congruency)\n\nor\n\n(iii) $\\angle A=\\angle D;\\angle B=\\angle E$ and $AB=DE$(ASA congruency)\n\nHow to look for similarity and congruency of angles\n\nWhile looking for similarity and congruency, you should not only see external appearance but also which of the corresponding angles are equal (or, which of corresponding sides are in the same ratio).", null, "", null, "In the above figure, $\\angle B=\\angle F;\\text{ }\\angle C=\\angle E$and $\\angle A\\cong \\angle D;$ thus $\\Delta \\,ACB\\cong \\Delta \\,DEF$(and not$\\Delta \\,ABC\\cong \\Delta \\,DEF$)", null, "Mathematical statement of the theorem$\\frac{AD}{DB}=\\frac{AE}{EC}$ (where$DE\\parallel ~BC$)\n\ni.e., if in $\\Delta \\text{ }ABC$as shown above, $DE\\parallel BC\\Rightarrow \\frac{AD}{DB}=\\frac{AE}{EC}$\n\nConverse of Basic Proportionality Theorem:", null, "Mathematical statement of the theorem if in $\\Delta \\,ABC$(as shown above),\n\n$\\frac{AD}{DB}=\\frac{AE}{EC}\\Rightarrow DE\\parallel BC)$\n\nOther Topics\n\nNotes - Triangles\n\nYou need to login to perform this action.\nYou will be redirected in 3 sec", null, "" ]
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https://mathlesstraveled.com/2015/11/13/mablowrimo-12-groups-and-order/?shared=email&msg=fail
[ "## MaBloWriMo 12: Groups and Order\n\nContinuing our discussion of groups (see here and here), today I want to discuss the concept of order, which is defined both for groups themselves and for the elements of a group.\n\nThe order of a group simply means the size of the set", null, "$G$. So instead of “a group with 8 elements” you will often hear “a group of order 8” instead.\n\nElements of a group also have an order. Recall the example", null, "$\\mathbb{Z}_8$, the group with elements", null, "$\\{0, 1, \\dots, 7\\}$, and with binary operation addition", null, "$\\pmod 8$. Consider what happens if we start with", null, "$1$ and keep combining it with itself according to the group operation.", null, "$1 +_8 1 = 2$, then", null, "$1 +_8 1 +_8 1 = 3$, and so on, until we get to adding eight copies of", null, "$1$, giving", null, "$1 +_8 \\dots +_8 1 = 0$. If we add up copies of", null, "$2$, on the other hand, it takes only", null, "$4$ copies to reach", null, "$0$. What about", null, "$3$? Well,", null, "$3 +_8 3 = 6$; three copies yield", null, "$1$; four copies yield", null, "$4$; and so on. As you can verify, we actually need eight copies of", null, "$3$ before we get to", null, "$0$.\n\nIn general, if", null, "$G$ is a group and", null, "$g \\in G$ is some element of the group, the order of", null, "$g$ is defined as the smallest number of copies of", null, "$g$ which combine to yield the identity element. So in", null, "$\\mathbb{Z}_8$,", null, "$1$ has order eight,", null, "$2$ has order four,", null, "$3$ also has order eight, and so on.", null, "$0$ itself has order 1, because one copy of", null, "$0$ is already", null, "$0$.\n\nA few questions immediately suggest themselves:\n\n1. Does every group element have a well-defined order?\n2. How does the order of group elements relate to the order of the group?\n\nTo answer the first question, recall that the integers form a group under addition, and obviously if you start with some nonzero integer", null, "$n$, you can add", null, "$n$ to itself as many times as you like but you will never get zero! In such cases we say that the order is infinite.\n\nOK, but the group", null, "$\\mathbb{Z}$ itself has infinitely many elements. Let’s refine our question a bit:\n\n1. (revised) Does every element of a finite group have a well-defined, finite order?\n\nEven in a finite group, you could imagine having some element", null, "$g \\in G$ such that no matter how much you combine it with itself, you will never get the identity element. Can this happen? (Also, as a tangential challenge, can you come up with an example of an infinite group where some elements other than the identity do have a finite order?)\n\nFor now, I’ll let you think about these questions! Tomorrow, we’ll answer question 1; the next day, we’ll talk about a simple answer to question 2 which will be sufficient for our purposes (there is also a more nuanced answer which is harder to prove).\n\nAs an aside, remember that we’re trying to prove the Lucas-Lehmer test, and currently we’re trying to understand the related number", null, "$\\omega = 2 + \\sqrt{3}$. The point of all this stuff about groups is that (1) we’re going to construct a group containing", null, "$\\omega$ as an element, and then (2) we’re going to figure out something about the order of", null, "$\\omega$ in that group. We’ll see that if the Lucas-Lehmer test didn’t work, then the order of", null, "$\\omega$ would be in contradiction to the answer to question 2.", null, "" ]
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https://e-zaitaku.info/essay-beowulf/5-1-homework-system-of-equations-76233.php
[ "# 5. 1 homework system of equations\n\n61%\n545 1 month ago\nA system of linear equations is a set of linear equations that have common variables. Common systems consist of two variables, x and y, and two linear equations. The solution to the system is the value of x and y that satisfy both equations. There are two ways to solve systems: substitution and elimination. Step 1: Solve one equation in terms of one of the variables whichever is easier. Step 2: Substitute one equation into the other in terms of the variable found in step one.", null, "", null, "## Unit 5: Linear Systems of Equations", null, "", null, "", null, "", null, "## Homework: Systems of Equations Word Problems Quiz - Quizizz\n\nTeachers Pay Teachers is an online marketplace where teachers buy and sell original educational materials. Are you getting the free resources, updates, and special offers we send out every week in our teacher newsletter? Grade Level. Resource Type. Log In Join Us. View Wish List View Cart. You Selected: Keyword systems of equations graphing worksheet.", null, "", null, "", null, "### 5.1: Solve Systems of Equations by Graphing\n\nIf you missed this problem, review Example 1. If you missed this problem, review Example 2. We have solved systems of linear equations by graphing and by substitution. Graphing works well when the variable coefficients are small and the solution has integer values.", null, "", null, "", null, "", null, "", null, "There are two methods that will be used in this lesson to solve a system of linear equations algebraically. They are 1 substitution , and 2 elimination. They are both aimed at eliminating one variable so that normal algebraic means can be used to solve for the other variable. Once one variable is solved, then substitution will be used in both above methods to find the second variable. Special Circumstances.", null, "Category: essay beowulf\nReport this post:\nCause:\n\n### Your comments\n\nRicky S. 23.04.2021\nIm not good at making calculations so I decided to turn to professionals with my excel exercises." ]
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http://oalevelsolutions.com/past-papers-solutions/cambridge-international-examinations/as-a-level-mathematics-9709/pure-mathematics-p2-9709-02/year-2003-october-november-p2-9709-02/cie_03_on_9709_02_q_7/
[ "# Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 2 (P2-9709/02) | Year 2003 | Oct-Nov | (P2-9709/02) | Q#7\n\nHits: 210\n\nQuestion\n\ni.       By differentiating", null, ", show that if y = cot x then", null, "ii.       Hence, show that", null, "By using appropriate trigonometrical identities, find the exact value of\n\niii.", null, "iv.", null, "Solution\n\ni.\n\nWe are given;", null, "Gradient (slope) of the curve is the derivative of equation of the curve. Hence gradient of curve", null, "with respect to", null, "is:", null, "", null, "If", null, "and", null, "are functions of", null, ", and if", null, ", then;", null, "Let", null, "and", null, ", then;", null, "", null, "Rule for differentiation of", null, "is;", null, "Rule for differentiation of", null, "is;", null, "", null, "", null, "", null, "We have the trigonometric identity;", null, "", null, "", null, "provided that", null, "", null, "Therefore, if;", null, "", null, "provided that", null, "Hence;", null, "For;", null, "As demonstrated above;", null, "Hence;", null, "ii.", null, "As we have demonstrated in (i) that;", null, "Therefore, the inverse of differentiate ie integral must be as;", null, "Hence;", null, "", null, "", null, "", null, "provided that", null, "", null, "", null, "", null, "iii.", null, "Utilizing the identity;", null, "", null, "We can write;", null, "Rule for integration of", null, "is:", null, "", null, "As demonstrated in (ii);", null, "Hence;", null, "Rule for integration of", null, "is:", null, "", null, "", null, "", null, "", null, "iv.", null, "", null, "", null, "", null, "We have the trigonometric identity;", null, "", null, "", null, "", null, "", null, "Rule for integration of", null, "is:", null, "", null, "", null, "provided that", null, "", null, "We have shown in (ii) that;", null, "Therefore;", null, "" ]
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https://ambrevar.xyz/homogeneous/index.html
[ "# Homogeneous Coordinates\n\nA Concrete Explanation\n\nComputer graphics programs usually work with homogeneous coordinates, whose main purpose is to allow for some operations like translation to be linear and thus vectorizable. Vectorized operations can be heavily parallelized on the processing unit which results in a tremendous performance boost. Video games make heavy use of this technique.\n\nHomogeneous coordinates are often introduced as a trick. I think this is a misconception and it paves the way for a lot of misunderstandings and errors when working with computer graphics.\n\nIn the following article I will detail a more natural approach to the concept.\n\n## Notations\n\nIn the following we will consider canonical Euclidean planes and spaces. $$x$$, $$y$$ and $$z$$ are the canonical Euclidean dimensions or the vector components depending on the context.\n\nThe initial space is called the projective space.\n\nAll the transformations are supposed to be endomorphisms.\n\n## Usual transformations\n\nLinear transformations in a Euclidean space can be written as a matrix $$M$$ so that the transformed point $$P'$$ of $$P$$ is:\n\n$P' = M \\cdot P$\n\nIn 2D, the matrix is of size $$(2,2)$$. A few examples follow:\n\n• 2D scaling $$(x,y) \\to (sx, sy)$$:\n\\begin{pmatrix} s & 0 \\\\ 0 & s \\\\ \\end{pmatrix}\n• Rotation of angle $$\\theta$$:\n\nIn 2D:\n\n\\begin{pmatrix} \\cos(\\theta) & -\\sin(\\theta) \\\\ \\sin(\\theta) & \\cos(\\theta) \\\\ \\end{pmatrix}\n\nIn 3D, around the $$z$$-axis:\n\n\\begin{pmatrix} \\cos(\\theta) & -\\sin(\\theta) & 0 \\\\ \\sin(\\theta) & \\cos(\\theta) & 0 \\\\ 0 & 0 & 1 \\\\ \\end{pmatrix}\n\nOther linear transformations include shearing and mirroring.\n\n## Non-linear operations\n\nIn the following section we will consider the projective space to be a 2D plane. This is only to make the explanation more visual, since this can be easily generalized to any dimension.\n\nSome operations are not linear in the projective plane. But what if we consider the projective plane as being a plane in a 3D space? Then we can apply any 3D transformation on the points of this plane.\n\nWe say that we promote the plane to the next dimension.\n\nThe fundamental principle here is that the higher dimension allows for more complex transformations, e.g. some specific shearing operations in 3D can be seen as a translation on the plane.\n\nAfter the desired transformations have been applied, we project the resulting points back to the plane.\n\nThere are some parameters we need to specify:\n\n• How do we promote the points? I.e. where does the projective plane lie in 3D?\n• How do we project the transformation result back to the plane?\n\nIn order to answer this we need to analyze how some non-linear operations behave.\n\n### Translation operation\n\n#### Promotion\n\nTranslations are not linear in the 2D-Euclidean space. Now if we promote the input points to a 3D space, they will all lie in a plane. It is obviously simpler to keep the $$x$$ and $$y$$ vectors identical. Then the only parameter for defining the plane is $$z$$.\n\nLet’s have a look at the following shearing of some point $$P=(i,j,k)$$ by the scalars $$a$$ and $$b$$:\n\n$\\begin{pmatrix} 1 & 0 & a \\\\ 0 & 1 & b \\\\ 0 & 0 & 1 \\\\ \\end{pmatrix} \\cdot (i, j, k) = (i+ka, j+kb, k)$\n\nIf $$k=1$$, then the transformed point is $$(i+a, j+b, 1)$$, which is a translation on the plane $$z=1$$.\n\nConsidering the projective plane at $$z=1$$ makes it easy to write a translation matrix.\n\nConclusion: the points from a projective space of any dimension can be promoted to the next dimension by adding a coordinate with the scalar value 1.\n\n#### Projection\n\nIf the transformed points lie in the plane, the projection back to the projective space is trivial: we simply cut off the last dimension.\n\nHowever, the transformed points might end up somewhere outside the plane. In that case we need some way to map the 3D points to the 2D points. There are several ways of doing this.\n\n• One would be to simply cut off the last dimension.\n• Another solution would be to divide all dimensions by the last one when it is non-zero. The last dimension would then always be 1, which matches the position of the plane $$z=1$$ as we defined it previously.\n\nFirst let’s consider some point $$P=(i,j,k)$$ and let’s see what happens if we apply the same transformation as before:\n\n$\\begin{pmatrix} 1 & 0 & a \\\\ 0 & 1 & b \\\\ 0 & 0 & 1 \\\\ \\end{pmatrix} \\cdot (i,j,k) = (i+ka, j+ka, k) = P'$\n\n• If we project by cutting off the last coordinate, the projection of $$P$$ is $$(i, j)$$, the projection of $$P'$$ is $$(i+ka, j+kb)$$. The transformation is generally not the translation by $$(a, b)$$.\n• Using the division by the last coordinate, the projection of $$P$$ is $$(i/k, j/k)$$, the projection of $$P'$$ is $$(i/k+a, j/k+b)$$. This time the transformation is the translation by $$(a, b)$$.\n\nConclusion: the projection back to the projective space is done by dividing all dimensions by the last one when non-zero. This allows for translations in the projective space.\n\n### Perspective operation\n\nWe have seen one example that covers it all. But what if the above analysis was good enough for translations only? Let us have a look at a very common operation in computer graphics: perspective correction.\n\nIn this section we consider a 3D projective space. The higher dimension is 4D and the 4th coordinates we be written $$w$$.\n\nWhen the camera and the screen are centered on the $$z$$-axis, perspective projection results from simple triangular relations, i.e. by dividing $$x$$ and $$y$$ by $$\\alpha+\\beta\\cdot z$$, where $$\\alpha$$ and $$\\beta$$ are scalars depending on the distance from the camera and the screen to the origin.\n\nIn the previous scheme, $$i' = i\\frac{z_s-z_c}{k-z_c}$$ and $$j' = j\\frac{z_s-z_c}{k-z_c}$$.\n\nIn the simplest case the camera is at the origin and the screen is at $$z=1$$, as above. We get the simple transformation where $$\\alpha=1$$ and $$\\beta=1$$, that is, in our example, $$i' = i/k$$ and $$j' = j/k$$.\n\nBut there is no way a matrix multiplication can induce a division by one of the dimension. After all, matrices are a notation for linear transformations.\n\nThere is one way out though: a division by one dimension is performed during the projection back to the projective space. As such, our lead is to “inject” $$z$$ into $$w$$:\n\n$\\begin{pmatrix} 1 & 0 & 0 & 0 \\\\ 0 & 1 & 0 & 0 \\\\ 0 & 0 & 1 & 0 \\\\ 0 & 0 & \\beta & \\alpha \\\\ \\end{pmatrix} \\cdot (i, j, k, 1) = (i, j, k, \\alpha+\\beta k)$\n\nIf we project the result back to the projective space, we get the 3D point $$(\\frac{i}{\\alpha+\\beta k}, \\frac{j}{\\alpha+\\beta k}, \\frac{k}{\\alpha+\\beta k})$$. If we project the result on the plane $$z=z_s$$, we obtain the perspective projection of $$(i, j, k)$$.\n\nConclusion: one more time, the division by the last coordinate is a projection technique that allows for operations in the next dimension to be properly mapped to the projective space.\n\n## Homogeneous coordinates\n\nThe above analysis issued a relation between points in the projective space and points in the next dimension.\n\nMaking use of the above reasoning, homogeneous coordinates offer an alternative notation to cartesian coordinates. We insist on the word ’notation’ as there are no new points nor new spaces. It means that $$(i,j,k)$$ and $$(i,j,k,1)_h$$ specify the same point in 3D.\n\nWe use the $$_h$$ index to avoid confusion between homogeneous coordinates and cartesian coordinates in a higher dimension.\n\nThe mapping between the two coordinate systems is central: the cartesian coordinates are obtained by dividing all dimensions by the homogeneous component if not null, and discarding this last component. This has several consequences:\n\n• Infinity can be represented using finite coordinates, e.g. $$(x, y, 0)_h$$ in 2D.\n• The $$0_h$$ vector is ignored.\n• The origin is the vector where all components are 0 but the last one is 1, e.g. $$(0,0,1)_h$$ in 2D.\n• All points on a line going through $$0_h$$ represent the same point. A non-null scalar multiplication over homogeneous coordinates does not change the point. For instance $$(i, j) = (i, j, 1)_h = (2i, 2j, 2)_h = (\\alpha i, \\alpha j, \\alpha)_h$$ for all scalars $$\\alpha$$.\n\n## Examples\n\n### Rendering pipeline\n\nIn computer graphics, homogeneous coordinates play an important role as they allow for perspective transformations in 3D.\n\nThe 3D rendering pipeline can be summarized as follows (C stands for cartesian, H stands for homogeneous):\n\nVertex data (3D C) → Object data (3D H) → Eye coordinates (3D H) → Clip coordinates (3D H) → Normalized device coordinates (3D C) → Window coordinates (2D C)\n\n• Vertex data are 3D vectors. The graphic pipeline uses homogeneous coordinates for object data, with the homogeneous component being 1, for the reason detailed above.\n• Object data is then translated and rotated as needed via $$(4,4)_h$$-matrices. This yields the homogeneous eye coordinates.\n• A $$(4,4)_h$$-perspective matrix is applied on the eye coordinates, which leads to the homogeneous clip coordinates.\n• The homogeneous clip coordinates are converted to cartesian coordinates, a.k.a. normalized device coordinates (NDC), by dividing every coordinate by the last one, as usual.\n• The NDC are converted to the 2D window coordinates by removing the third dimension and applying some scaling.\n\n### 2D perspective correction\n\nLet us consider the following problem: we want to rectify the perspective of a picture, e.g. we want a tilted building facade picture to appear as if it had been taken orthogonally.\n\nWe proceed with control points: we select pixels in the input picture and tell the program where we would like it to be on the transformed picture.\n\nA $$(2,2)$$-matrix will not do the trick as it is not able to handle translations for instance.\n\nUsing homogeneous coordinates, we can transform the entire plane to the orthogonal picture we would like. In 3D, this can be seen as tilting the plane to make it match the screen.\n\nThis transformation can be embodied within a $$(3,3)_h$$-matrix $$M$$. The answer to our problem is $$M$$.\n\nLet us consider a set of known point pairs $$\\langle \\text{ control point } (i,j), \\text{ target point } (I,J)\\rangle$$, so that\n\n$\\begin{pmatrix} m_{11} & m_{12} & m_{13} \\\\ m_{21} & m_{22} & m_{23} \\\\ m_{31} & m_{32} & m_{33} \\\\ \\end{pmatrix} \\cdot (i, j, 1)_h = (\\alpha I, \\alpha J, \\alpha)_h$\n\nWe could be tempted to think we only need the first 2 rows of the matrix: this is wrong! The result of the matrix multiplication yields the homogeneous coordinates of a point, which still needs to be projected to the 2D plane to be significant. Therefore we need to compute the homogeneous component of every point.\n\nThe previous matrix operation yields the following equations:\n\n$\\left\\{ \\begin{array}{l l} m_{11}i + m_{12}j + m_{13} &= \\alpha I \\\\ m_{21}i + m_{22}j + m_{23} &= \\alpha J \\\\ m_{31}i + m_{32}j + m_{33} &= \\alpha \\\\ \\end{array} \\right.$\n\nor, cancelling the scale factor:\n\n$\\left\\{\\begin{array}{l l} \\frac{m_{11}i + m_{12}j + m_{13}}{m_{31}i + m_{32}j + m_{33}} &= I \\\\ \\frac{m_{21}i + m_{22}j + m_{23}}{m_{31}i + m_{32}j + m_{33}} &= J \\\\ \\end{array} \\right.$\n\nThe matrix has 9 unknown coefficients, but since it is homogeneous, it is defined up to a scale factor. For instance, we have $$M=M/m_{11}$$ if $$m_{11}≠0$$. As such, only 8 coefficient determines a homogeneous matrix uniquely.\n\nWe can solve the system of 8 linearly independent equations constructed as above from 4 well chosen points. The above equation pair yields\n\n$\\left\\{\\begin{array}{l l} m_{11}i + m_{12}j + m_{13} - m_{31}iI - m_{32}jI - m_{33}I &= 0 \\\\ m_{21}i + m_{22}j + m_{23} - m_{31}iJ - m_{32}jJ - m_{33}J &= 0 \\\\ \\end{array} \\right.$\n\nwhich can be written as a multiplication\n\n$\\left\\{\\begin{array}{l l} (i, j, 1, 0, 0, 0, -iI, -jI, -I) \\cdot m^T &= 0 \\\\ (0, 0, 0, i, j, 1, -iJ, -jJ, -J) \\cdot m^T &= 0 \\\\ \\end{array} \\right.$\n\nwith $$m=(m_{11}, m_{12}, m_{13}, m_{21}, m_{22}, m_{23}, m_{31}, m_{32}, m_{33})$$.\n\nWe can build the following matrix from 4 point sets:\n\n$S = \\begin{pmatrix} i_1 & j_1 & 1 & 0 & 0 & 0 & -i_1I_1 & -j_1I_1 & -I_1 \\\\ 0 & 0 & 0 & i_1 & j_1 & 1 & -i_1J_1 & -j_1J_1 & -J_1 \\\\ ... \\\\ i_4 & j_4 & 1 & 0 & 0 & 0 & -i_4I_4 & -j_4I_4 & -I_4 \\\\ 0 & 0 & 0 & i_4 & j_4 & 1 & -i_4J_4 & -j_4J_4 & -J_4 \\\\ \\end{pmatrix}$\n\nIf $$det(S) ≠ 0$$, then the result can be found by solving\n\n$S\\cdot m = 0$\n\nwhich is equivalent to finding the eigenvalues of $$S$$. A singular-value decomposition will numerically find $$m$$.\n\n## Final note\n\nThe present article does not claim to provide any new results when it comes to homogeneous coordinates. It only aims at explaining the theory more visually, and thus making it easier to understand and remember. It all makes perfect sense, it is not just a trick. Mathematically speaking, the key argument that I introduced above is to consider the projective space as an affine hyperplane in the next dimension. Then everything falls into place:\n\n• the link between cartesian and homogeneous coordinates;\n• why this actually works;\n• when we should manipulate homogeneous coordinates, when we should project back to the projective space.\n\nThe central idea can be seen as a hook in the process: we momentarily promote our data to the next dimension, manipulate it in there, then project the result back to the original dimension. It generally does not make sense to exploit a result in homogeneous coordinates." ]
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https://curriculum.illustrativemathematics.org/k5/teachers/grade-4/unit-4/lesson-8/preparation.html
[ "# Lesson 8\n\nBeyond 100,000\n\n### Lesson Purpose\n\nThe purpose of this lesson is to read, write, and represent numbers within 1,000,000 using base-ten blocks, diagrams, and expanded form.\n\n### Lesson Narrative\n\nIn previous grades, students used base-ten blocks, diagrams, and expanded form, a specific way of writing a number as a sum of hundreds, tens, and ones, to represent numbers within 1,000. In this lesson, they extend their understanding of place value to write and represent numbers within 1,000,000.\n\nThroughout the lesson, students determine the value represented by given sets of blocks and consider how to use blocks to represent given numbers. The reasoning students use helps to develop conceptual understanding of expanded form, allows them to practice reading and writing large numbers, and prompts them to think about the relative value of each place. In the next lesson, students generalize observations in terms of the relationship between any two adjacent digits in a multi-digit number.\n\nThe emphasis in this lesson and subsequent ones is not on how to write a number in expanded form. However, this notation may be helpful for students to notice a relationship between the same digits in adjacent places in large numbers. For example, when students expand 23,450 as $$20,\\!000 +3,\\!000+400+50$$ and 2,345 as $$2,\\!000+300+40+5$$, they see that the digit 2 in 23,450 has ten times the value of the 2 in 2,345.\n\nWhen students use strategies that are based on place value and our number system, they are looking for and making use of structure (MP7).\n\n• Representation\n\n### Learning Goals\n\nTeacher Facing\n\n• Represent, read, and write multi-digit whole numbers within 1,000,000, including in expanded form.\n\n### Student Facing\n\n• Let’s read, write, and represent numbers beyond 100,000.\n\n### Required Materials\n\nMaterials to Gather\n\n### Lesson Timeline\n\n Warm-up 10 min Activity 1 15 min Activity 2 10 min Activity 3 10 min Lesson Synthesis 10 min Cool-down 5 min\n\n### Teacher Reflection Questions\n\nReflect on your experience with “How Many Do You See?” in the curriculum. What moves or questions have improved the learning for each of your students during this routine? What improvements would you make next time?\n\n### Suggested Centers\n\n• Greatest of Them All (1–5), Stage 2: Three-digit Numbers (Supporting)\n• Mystery Number (1–4), Stage 4: Fractions with Denominators 5, 8, 10, 12, 100 (Supporting)\n\n### Print Formatted Materials\n\nFor access, consult one of our IM Certified Partners." ]
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http://ixtrieve.fh-koeln.de/birds/litie/document/31516
[ "# Document (#31516)\n\nAuthor\nHudson, J.\nTitle\nOn-the-job training for cataloging and classification\nSource\nCataloging and classification quarterly. 7(1987) no.4, S.69-78\nYear\n1987\nAbstract\nTraining for cataloging and classification within the Cataloging Department is discussed for two levels of staff, copy catalogers and original catalogers. A general pattern which moves from learning to catalog straightforward materials which require minimal editing to processing materials which are progressively more complex is described for copy catalogers. A survey of heads of cataloging departments reveals that there is a general feeling that cataloging and classification are being shortchanged in library school training and recommendations for such training are made. Training programs for original catalogers also follow a pattern, from working with LC copy to preparing original cataloging records. Some variations to the training patterns for each group are noted. The article concludes with a discussion of continuing education for both groups.\nFootnote\nSimultaneously published as Education and Training for Catalogers and Classifiers\nTheme\nAusbildung\nFormalerschließung\nLocation\nUSA\n\n## Similar documents (content)\n\n1. Gomez, J.; LaGrange, J.: ¬A Chinese challenge : utilizing students for special cataloging projects (1990) 0.31\n```0.3051187 = sum of:\n0.3051187 = product of:\n0.953496 = sum of:\n0.06604984 = weight(abstract_txt:department in 1625) [ClassicSimilarity], result of:\n0.06604984 = score(doc=1625,freq=2.0), product of:\n0.09656785 = queryWeight, product of:\n6.19062 = idf(docFreq=237, maxDocs=42740)\n0.015599059 = queryNorm\n0.6839734 = fieldWeight in 1625, product of:\n1.4142135 = tf(freq=2.0), with freq of:\n2.0 = termFreq=2.0\n6.19062 = idf(docFreq=237, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.014908394 = weight(abstract_txt:which in 1625) [ClassicSimilarity], result of:\n0.014908394 = score(doc=1625,freq=1.0), product of:\n0.06505126 = queryWeight, product of:\n1.4215829 = boost\n2.9334934 = idf(docFreq=6181, maxDocs=42740)\n0.015599059 = queryNorm\n0.22917917 = fieldWeight in 1625, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n2.9334934 = idf(docFreq=6181, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.046423588 = weight(abstract_txt:materials in 1625) [ClassicSimilarity], result of:\n0.046423588 = score(doc=1625,freq=1.0), product of:\n0.121179886 = queryWeight, product of:\n1.5842146 = boost\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.015599059 = queryNorm\n0.3830965 = fieldWeight in 1625, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.037795503 = weight(abstract_txt:classification in 1625) [ClassicSimilarity], result of:\n0.037795503 = score(doc=1625,freq=1.0), product of:\n0.12094704 = queryWeight, product of:\n1.9383937 = boost\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.015599059 = queryNorm\n0.3124963 = fieldWeight in 1625, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.16240333 = weight(abstract_txt:original in 1625) [ClassicSimilarity], result of:\n0.16240333 = score(doc=1625,freq=3.0), product of:\n0.22164503 = queryWeight, product of:\n2.6240575 = boost\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.015599059 = queryNorm\n0.7327181 = fieldWeight in 1625, product of:\n1.7320508 = tf(freq=3.0), with freq of:\n3.0 = termFreq=3.0\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.1919416 = weight(abstract_txt:copy in 1625) [ClassicSimilarity], result of:\n0.1919416 = score(doc=1625,freq=1.0), product of:\n0.35733968 = queryWeight, product of:\n3.3318465 = boost\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.015599059 = queryNorm\n0.5371405 = fieldWeight in 1625, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.2884648 = weight(abstract_txt:catalogers in 1625) [ClassicSimilarity], result of:\n0.2884648 = score(doc=1625,freq=2.0), product of:\n0.40957487 = queryWeight, product of:\n4.1188917 = boost\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.015599059 = queryNorm\n0.704303 = fieldWeight in 1625, product of:\n1.4142135 = tf(freq=2.0), with freq of:\n2.0 = termFreq=2.0\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.1455089 = weight(abstract_txt:cataloging in 1625) [ClassicSimilarity], result of:\n0.1455089 = score(doc=1625,freq=1.0), product of:\n0.37431583 = queryWeight, product of:\n4.822569 = boost\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.015599059 = queryNorm\n0.38873297 = fieldWeight in 1625, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.078125 = fieldNorm(doc=1625)\n0.32 = coord(8/25)\n```\n2. Kao, M.L.: Cataloging and classification for library technicians (2001) 0.25\n```0.24878125 = sum of:\n0.24878125 = product of:\n1.2439063 = sum of:\n0.092847176 = weight(abstract_txt:materials in 6364) [ClassicSimilarity], result of:\n0.092847176 = score(doc=6364,freq=1.0), product of:\n0.121179886 = queryWeight, product of:\n1.5842146 = boost\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.015599059 = queryNorm\n0.766193 = fieldWeight in 6364, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.15625 = fieldNorm(doc=6364)\n0.075591005 = weight(abstract_txt:classification in 6364) [ClassicSimilarity], result of:\n0.075591005 = score(doc=6364,freq=1.0), product of:\n0.12094704 = queryWeight, product of:\n1.9383937 = boost\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.015599059 = queryNorm\n0.6249926 = fieldWeight in 6364, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.15625 = fieldNorm(doc=6364)\n0.18752721 = weight(abstract_txt:original in 6364) [ClassicSimilarity], result of:\n0.18752721 = score(doc=6364,freq=1.0), product of:\n0.22164503 = queryWeight, product of:\n2.6240575 = boost\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.015599059 = queryNorm\n0.84607 = fieldWeight in 6364, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.15625 = fieldNorm(doc=6364)\n0.3838832 = weight(abstract_txt:copy in 6364) [ClassicSimilarity], result of:\n0.3838832 = score(doc=6364,freq=1.0), product of:\n0.35733968 = queryWeight, product of:\n3.3318465 = boost\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.015599059 = queryNorm\n1.074281 = fieldWeight in 6364, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.15625 = fieldNorm(doc=6364)\n0.50405765 = weight(abstract_txt:cataloging in 6364) [ClassicSimilarity], result of:\n0.50405765 = score(doc=6364,freq=3.0), product of:\n0.37431583 = queryWeight, product of:\n4.822569 = boost\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.015599059 = queryNorm\n1.3466105 = fieldWeight in 6364, product of:\n1.7320508 = tf(freq=3.0), with freq of:\n3.0 = termFreq=3.0\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.15625 = fieldNorm(doc=6364)\n0.2 = coord(5/25)\n```\n3. Kao, M.L.: Cataloging and classification for library technicians (1995) 0.25\n```0.24878125 = sum of:\n0.24878125 = product of:\n1.2439063 = sum of:\n0.092847176 = weight(abstract_txt:materials in 2180) [ClassicSimilarity], result of:\n0.092847176 = score(doc=2180,freq=1.0), product of:\n0.121179886 = queryWeight, product of:\n1.5842146 = boost\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.015599059 = queryNorm\n0.766193 = fieldWeight in 2180, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.903635 = idf(docFreq=861, maxDocs=42740)\n0.15625 = fieldNorm(doc=2180)\n0.075591005 = weight(abstract_txt:classification in 2180) [ClassicSimilarity], result of:\n0.075591005 = score(doc=2180,freq=1.0), product of:\n0.12094704 = queryWeight, product of:\n1.9383937 = boost\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.015599059 = queryNorm\n0.6249926 = fieldWeight in 2180, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.15625 = fieldNorm(doc=2180)\n0.18752721 = weight(abstract_txt:original in 2180) [ClassicSimilarity], result of:\n0.18752721 = score(doc=2180,freq=1.0), product of:\n0.22164503 = queryWeight, product of:\n2.6240575 = boost\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.015599059 = queryNorm\n0.84607 = fieldWeight in 2180, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.15625 = fieldNorm(doc=2180)\n0.3838832 = weight(abstract_txt:copy in 2180) [ClassicSimilarity], result of:\n0.3838832 = score(doc=2180,freq=1.0), product of:\n0.35733968 = queryWeight, product of:\n3.3318465 = boost\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.015599059 = queryNorm\n1.074281 = fieldWeight in 2180, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.15625 = fieldNorm(doc=2180)\n0.50405765 = weight(abstract_txt:cataloging in 2180) [ClassicSimilarity], result of:\n0.50405765 = score(doc=2180,freq=3.0), product of:\n0.37431583 = queryWeight, product of:\n4.822569 = boost\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.015599059 = queryNorm\n1.3466105 = fieldWeight in 2180, product of:\n1.7320508 = tf(freq=3.0), with freq of:\n3.0 = termFreq=3.0\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.15625 = fieldNorm(doc=2180)\n0.2 = coord(5/25)\n```\n4. Howarth, L.C.: (Re)making the serials cataloger : the SCCTP within an educational framework (2000) 0.24\n```0.24051598 = sum of:\n0.24051598 = product of:\n1.0021499 = sum of:\n0.058125988 = weight(abstract_txt:continuing in 370) [ClassicSimilarity], result of:\n0.058125988 = score(doc=370,freq=1.0), product of:\n0.11173133 = queryWeight, product of:\n1.0756506 = boost\n6.658944 = idf(docFreq=148, maxDocs=42740)\n0.015599059 = queryNorm\n0.52023 = fieldWeight in 370, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.658944 = idf(docFreq=148, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.093763605 = weight(abstract_txt:original in 370) [ClassicSimilarity], result of:\n0.093763605 = score(doc=370,freq=1.0), product of:\n0.22164503 = queryWeight, product of:\n2.6240575 = boost\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.015599059 = queryNorm\n0.423035 = fieldWeight in 370, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.1919416 = weight(abstract_txt:copy in 370) [ClassicSimilarity], result of:\n0.1919416 = score(doc=370,freq=1.0), product of:\n0.35733968 = queryWeight, product of:\n3.3318465 = boost\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.015599059 = queryNorm\n0.5371405 = fieldWeight in 370, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.3532958 = weight(abstract_txt:catalogers in 370) [ClassicSimilarity], result of:\n0.3532958 = score(doc=370,freq=3.0), product of:\n0.40957487 = queryWeight, product of:\n4.1188917 = boost\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.015599059 = queryNorm\n0.8625915 = fieldWeight in 370, product of:\n1.7320508 = tf(freq=3.0), with freq of:\n3.0 = termFreq=3.0\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.1455089 = weight(abstract_txt:cataloging in 370) [ClassicSimilarity], result of:\n0.1455089 = score(doc=370,freq=1.0), product of:\n0.37431583 = queryWeight, product of:\n4.822569 = boost\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.015599059 = queryNorm\n0.38873297 = fieldWeight in 370, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.15951402 = weight(abstract_txt:training in 370) [ClassicSimilarity], result of:\n0.15951402 = score(doc=370,freq=1.0), product of:\n0.39796457 = queryWeight, product of:\n4.9725776 = boost\n5.130556 = idf(docFreq=686, maxDocs=42740)\n0.015599059 = queryNorm\n0.4008247 = fieldWeight in 370, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n5.130556 = idf(docFreq=686, maxDocs=42740)\n0.078125 = fieldNorm(doc=370)\n0.24 = coord(6/25)\n```\n5. Ferris, A.M.: Results of an expanded survey on the use of Classification Web : they will use it, if you buy it! (2009) 0.23\n```0.23041469 = sum of:\n0.23041469 = product of:\n0.96006125 = sum of:\n0.017890071 = weight(abstract_txt:which in 4992) [ClassicSimilarity], result of:\n0.017890071 = score(doc=4992,freq=1.0), product of:\n0.06505126 = queryWeight, product of:\n1.4215829 = boost\n2.9334934 = idf(docFreq=6181, maxDocs=42740)\n0.015599059 = queryNorm\n0.275015 = fieldWeight in 4992, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n2.9334934 = idf(docFreq=6181, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.07855648 = weight(abstract_txt:classification in 4992) [ClassicSimilarity], result of:\n0.07855648 = score(doc=4992,freq=3.0), product of:\n0.12094704 = queryWeight, product of:\n1.9383937 = boost\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.015599059 = queryNorm\n0.6495114 = fieldWeight in 4992, product of:\n1.7320508 = tf(freq=3.0), with freq of:\n3.0 = termFreq=3.0\n3.9999528 = idf(docFreq=2127, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.11251632 = weight(abstract_txt:original in 4992) [ClassicSimilarity], result of:\n0.11251632 = score(doc=4992,freq=1.0), product of:\n0.22164503 = queryWeight, product of:\n2.6240575 = boost\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.015599059 = queryNorm\n0.507642 = fieldWeight in 4992, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n5.414848 = idf(docFreq=516, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.23032995 = weight(abstract_txt:copy in 4992) [ClassicSimilarity], result of:\n0.23032995 = score(doc=4992,freq=1.0), product of:\n0.35733968 = queryWeight, product of:\n3.3318465 = boost\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.015599059 = queryNorm\n0.6445686 = fieldWeight in 4992, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n6.8753986 = idf(docFreq=119, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.34615776 = weight(abstract_txt:catalogers in 4992) [ClassicSimilarity], result of:\n0.34615776 = score(doc=4992,freq=2.0), product of:\n0.40957487 = queryWeight, product of:\n4.1188917 = boost\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.015599059 = queryNorm\n0.8451636 = fieldWeight in 4992, product of:\n1.4142135 = tf(freq=2.0), with freq of:\n2.0 = termFreq=2.0\n6.3746233 = idf(docFreq=197, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.17461067 = weight(abstract_txt:cataloging in 4992) [ClassicSimilarity], result of:\n0.17461067 = score(doc=4992,freq=1.0), product of:\n0.37431583 = queryWeight, product of:\n4.822569 = boost\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.015599059 = queryNorm\n0.46647954 = fieldWeight in 4992, product of:\n1.0 = tf(freq=1.0), with freq of:\n1.0 = termFreq=1.0\n4.975782 = idf(docFreq=801, maxDocs=42740)\n0.09375 = fieldNorm(doc=4992)\n0.24 = coord(6/25)\n```" ]
[ null ]
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https://mathematica.stackexchange.com/questions/278807/how-to-plot-a-point-with-two-colors
[ "# How to plot a point with two colors?\n\nHow can I use this type of marker for this?", null, "Plot[{x + 3, x^2 + 1}, {x, -5, 5}, PlotStyle -> Thickness[0.01],\nEpilog -> {Red, PointSize[0.03], Point[{2, 5}]}]\n\n\nI would be nice if the colors are added automatically from the two curves.", null, "f1[x_] := x + 3\nf2[x_] := 1 + x^2\n\nmeshStyle = (# /. Point[x_] :>\nMap[Inset[PieChart[{1, 1}, SectorOrigin -> Bottom],\n#, Center, Scaled[.1]] &, x] &);\n\nPlot[{f1[x], f2[x]}, {x, -5, 5},\nPlotStyle -> Thickness[0.01],\nMeshFunctions -> {f1[#] - f2[#] &},\nMesh -> {{0}},\nMeshStyle -> meshStyle]", null, "• We can define PlotMarkers by any Graphics object and using ListPlot to add such markers of points.\n\n• We using MeshFunctions to get the intersection points of two curves.\n\n• The AspectRatio can be any ratio,here we set AspectRatio -> 1/2.\n\nClear[f, g, hemipoint, plot, indexes, meshs];\nhemipoint =\nGraphics[{{ColorData,\nDisk[{0, 0}, 1, {π/2, 2 π - π/2}]}, {ColorData[\n2], Disk[{0, 0}, 1, {-π/2, π/2}]}}, ImageSize -> 20];\nf[x_] = x + 3;\ng[x_] = x^2 + 1;\nplot = Plot[{f[x], g[x]}, {x, -5, 5}, PlotStyle -> Thickness[0.01],\nMesh -> {{0}}, MeshFunctions -> {f[#] - g[#] &}, MeshStyle -> None];\npts = Cases[plot,\nGraphicsComplex[pts_, rest__] :> pts, ∞][];\nindexes = Cases[plot, Point[index_] :> index, ∞];\nmeshs = pts[[#]] & /@ indexes;\nShow[plot, ListPlot[{meshs[[1, 2]]}, PlotMarkers -> hemipoint],\nAspectRatio -> 1/2]", null, "• Define two types of PlotMarkers.\nClear[hemipoint1,hemipoint2,plot,indexes,meshs];\nhemipoint1 =\nGraphics[{{ColorData,\nDisk[{0, 0}, 1, {π/2, 2 π - π/2}]}, {ColorData[\n2], Disk[{0, 0}, 1, {-π/2, π/2}]}}, ImageSize -> 20];\nhemipoint2 =\nGraphics[{{ColorData,\nDisk[{0, 0}, 1, {π/2, 2 π - π/2}]}, {ColorData[\n1], Disk[{0, 0}, 1, {-π/2, π/2}]}}, ImageSize -> 20];\nf[x_] = x + 3;\ng[x_] = x^2 + 1;\nplot = Plot[{f[x], g[x]}, {x, -5, 5}, PlotStyle -> Thickness[0.01],\nMesh -> {{0}}, MeshFunctions -> {f[#] - g[#] &}, MeshStyle -> None];\npts = Cases[plot,\nGraphicsComplex[pts_, rest__] :> pts, ∞][];\nindexes = Cases[plot, Point[index_] :> index, ∞];\nmeshs = pts[[#]] & /@ indexes;\nShow[plot,\nListPlot[{{meshs[[1, 2]]}, {meshs[[1, 1]]}},\nPlotMarkers -> {hemipoint1, hemipoint2}], AspectRatio -> 1/2]", null, "It's not so easy to do this automatically, and you have to account for the aspect ratio of your plot, without which you end up with a squashed marker. Here's my attempt for manual points and colour selection:\n\nmarker[pos_, radius_, col1_, col2_] :=\nWith[{d = Disk[pos, radius, {-Pi/2, Pi/2}]},\n{EdgeForm[Black], col1, d, col2, Rotate[d, Pi, pos]}]\n\nxrange = {-5, 5};\nyrange = {-5, 30};\naspect = Subtract @@ yrange/Subtract @@ xrange;\nPlot[{x + 3, x^2 + 1}, {x, xrange[], xrange[]},\nPlotRange -> {xrange, yrange}, PlotStyle -> Thickness[0.01],\nEpilog -> {\nRGBColor[0.368417, 0.506779, 0.709798],\nRGBColor[0.880722, 0.611041, 0.142051]]}, AspectRatio -> 1]", null, "• Thanks, it is much more complex than I though even without automatically adding colors. It works great but does not work when I use it like this Show[plot1, plot_with_marker]. How can I fix this?" ]
[ null, "https://i.stack.imgur.com/oSCzT.png", null, "https://i.stack.imgur.com/ley0O.png", null, "https://i.stack.imgur.com/2Cpjg.png", null, "https://i.stack.imgur.com/wCNZ6.png", null, "https://i.stack.imgur.com/GppCC.png", null, "https://i.stack.imgur.com/4aj4r.png", null ]
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https://metacpan.org/release/Statistics-ROC/source/lib/Statistics/ROC.pm
[ "#LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL\n#\n# ROC.pm - A Perl module implementing receiver-operator-characteristic (ROC)\n# curves with nonparametric confidence bounds\n#\n# This program is free software; you may redistribute it and/or\n# modify it under the same terms as Perl itself.\n#\n# This code implements a method for constructing nonparametric confidence\n# for ROC curves described in\n# R.A. Hilgers, Distribution-Free Confidence Bounds for ROC Curves,\n# Meth Inform Med 1991; 30:96-101\n# Additionally some auxilliary functions were ported (and corrected) from\n# Fortran (Applied Statistics, ACM).\n#\n# Written in Perl by Hans A. Kestler.\n# Hans A. Kestler <[email protected]>\n# <[email protected]>\n#\n#\n#LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL\n\npackage Statistics::ROC;\nrequire 5;\nuse Carp;\nuse strict;\nuse vars qw($VERSION @ISA @EXPORT @EXPORT_OK); require Exporter; @ISA = ('Exporter'); @EXPORT = qw( roc rank loggamma betain Betain xinbta Xinbta );$VERSION = '0.01';\n\n# Algorithm 291, Logarithm of the gamma function.\n# in Collected Algorithms of the ACM, Vol II, 1980\n# M.C. Pike and I.D. Hill with remark by M.R. Hoare\n# see also Pike, M.C. and Hill, I.D. (1966). Algorithm 291. Logarithm of the\n# gamma function. Commun. Ass. Comput. Mach., 9,684.\n\nsub loggamma($){ # This procedure evaluates the natural logarithm of gamma(x) for all # x>0, accurate to 10 decimal places. Stirlings formula is used for the # central polynomial part of the procedure my$x= shift; # default arg is @_\nmy ($f,$z);\n\nif($x==0){return 743.746924740801} # this is: loggamma(9.9999999999E-324) if($x < 7)\n{\nfor($z=$x,$f=1;$z<7;$z++) {$x=$z;$f*=$z; }$x++;\n$f= -log($f); # log returns the natural logarithm\n}\nelse{ $f=0;}$z=1/($x*$x);\nreturn $f+($x-.5)*log($x)-$x+.918938533204673+\n(((-.000595238095238*$z+.000793650793651)*$z-\n.002777777777778)*$z+.083333333333333)/$x;\n}\n\n# Algorithm AS 63 with remark AS R19,\n# Computes incomplete beta function ratio\n# K.L. Majumder and G.P. Bhattacharjee (1973). The Incomplete Beta Integral,\n# Appl. Statist.,22:409:411 and\n# G.W. Cran, K.J. Martin and G.E. Thomas (1977).Remark AS R19 and\n# Algorithm AS109, A Remark on Algorithms AS 63: The Incomplete Beta Integral\n# AS 64: Inverse of the Incomplete Beta Function Ratio,\n# Appl. Statist., 26:111-114.\n#\n# Remarks:\n# Complete beta function: B(p,q)=gamma(p)*gamma(q)/gamma(p+q)\n# log(B(p,q))=ln(gamma(p))+ln(gamma(q))-ln(gamma(p+q))\n#\n# Incomplete beta function ratio:\n# I_x(p,q)=1/B(p,q) * \\int_0^x t^{p-1}*(1-t)^{q-1} dt\n#\n# --> log(B(p,q)) has to be supplied to calculate I_x(p,q)\n# log denotes the natural logarithm\n# $beta = log(B(p,q)) #$x = x\n# $p = p #$q = q\n# The subroutine returns I_x(p,q). If an error occurs a negative value\n# {-1,-2} is returned.\n\nsub betain(){\n# Computes incomplete beta function ratio for arguments\n# $x between zero and one,$p and $q positive. # Log of complete beta function,$beta, is assumed to be known.\n\nmy ($x,$p, $q,$beta) = @_;\nmy ($xx,$psq, $cx,$pp, $qq,$index, $betain,$ns, $term,$ai, $rx,$temp);\nmy $ACU=1.0E-14; # accuracy # tests for admissibility of arguments if($p<=0 || $q<=0){ return -1;} if($x<0 || $x>1) { return -2;} # change tail if necessary and determine s$psq=$p+$q; $cx=1-$x;\nif($p<$psq*$x){$xx=$cx;$cx=$x;$pp=$q;$qq=$p;$index=1;}\nelse{ $xx=$x; $pp=$p; $qq=$q; $index=0;}$term=1; $ai=1;$betain=1;\n$ns=$qq+$cx*$psq;\n\n# use Soper's reduction formulae\n$rx=$xx/$cx; do{ if($ns>=0){$temp=$qq-$ai; if($ns==0){$rx=$xx;}}\nelse{ $temp=$psq; $psq++;}$term *= $temp*$rx/($pp+$ai);\n$betain+=$term;\n$temp=abs($term); $ai++;$ns--;}\nuntil($temp<=$ACU && $temp<=$ACU*$betain); # calculate result$betain *= exp($pp*log($xx)+($qq-1)*log($cx)-$beta)/$pp;\nif($index){ return 1-$betain;}\nelse{ return $betain;} } sub Betain($$){ # Computes the incomplete beta function # by calling loggamma() and betain() my (x, p, q) = @_; if(x==1){return 1;} elsif(x==0){return 0;} else{ return betain(x, p, q,loggamma(p)+loggamma(q)-loggamma(p+q));} } sub max($$){ # computes the maximum of two numbers my ($a, $b) = @_; if($a>$b){ return$a;}\nelse{ return $b;} } # Algorithm AS 109, # Computes inverse of incomplete beta function ratio # G.W. Cran, K.J. Martin and G.E. Thomas (1977).Remark AS R19 and # Algorithm AS109, A Remark on Algorithms AS 63: The Incomplete Beta Integral # AS 64: Inverse of the Incomplete Beta Function Ratio, # Appl. Statist., 26:111-114. # # Remark AS R83 and the correction in vol40(1) of Appl. Statist.(1991), p.236 # have been incorporated in this version. # K.J. Berry, P.W. Mielke, Jr and G.W. Cran (1990) Algorithm AS R83, A Remark # on Algorithm AS 109: Inverse of the Incomplete Beta Function Ratio, # Appl. Statist., 39:309-310. # # Remarks: # # Complete beta function: B(p,q)=gamma(p)*gamma(q)/gamma(p+q) # log(B(p,q))=ln(gamma(p))+ln(gamma(q))-ln(gamma(p+q)) # # Incomplete beta function ratio: # alpha = I_x(p,q) = 1/B(p,q) * \\int_0^x t^{p-1}*(1-t)^{q-1} dt # # --> log(B(p,q)) has to be supplied to calculate I_x(p,q) # log denotes the natural logarithm #$beta = log(B(p,q))\n# $alpha= I_x(p,q) #$p = p\n# $q = q # The subroutine returns x. If an error occurs a negative value {-1,-2,-3} # is returned. sub xinbta(){ # Computes inverse of incomplete beta function ratio # for given positive values of the arguments$p and $q, #$alpha between zero and one.\n# Log of complete beta function, $beta is assumed to be known. # # copyright by H.A. Kestler, 1998 my ($p, $q,$beta, $alpha) = @_; my ($a, $y,$pp, $qq,$index, $r,$h, $t,$w, $xinbta,$yprev, $prev,$s, $sq,$tx, $adj,$g);\nmy $SAE=-37; my$FPU=10**$SAE; my$ACU;\n\n# test for admissibility of parameters\nif($p<=0 ||$q<=0){ return -1;}\nif($alpha<0 ||$alpha>1) { return -2;}\nif($alpha==0 ||$alpha==1){ return $alpha;} # change tail if necessary if($alpha>.5){ $a=1-$alpha; $pp=$q; $qq=$p; $index=1;} else{$a=$alpha;$pp=$p;$qq=$q;$index=0;}\n\n# calculate the initial approximation\n$r=sqrt(-log($a*$a));$y=$r-(2.30753+.27061*$r)/(1+(.99229+.04481*$r)*$r);\nif($pp>1 &&$qq > 1)\n{\n$r=($y*$y-3)/6;$s=1/($pp+$pp-1); $t=1/($qq+$qq-1);$h=2/($s+$t);\n$w=$y*sqrt($h+$r)/$h-($t-$s)*($r+5/6-2/(3*$h));$xinbta=$pp/($pp+$qq*exp($w+$w)); } else {$r=$qq+$qq; $t=1/(9*$qq);\n$t=$r*(1-$t+$y*sqrt($t))**3; if($t<=0){\n$xinbta=1-exp((log((1-$a)*$qq)+$beta)/$qq); } else{$t=(4*$pp+$r-2)/$t; if($t<=1){ $xinbta=exp((log($a*$pp)+$beta)/$pp);} else{$xinbta=1-2/($t+1);} } } # solve for$x by a modified newton-raphson method\n# using subroutine betain()\n$r=1-$pp; $t=1-$qq; $yprev=0;$sq=1; $prev=1; if($xinbta<.0001){ $xinbta=.0001;} if($xinbta>.9999){ $xinbta=.9999;}$ACU=10**(max(-5/$pp**2-1/$a**.2-13,$SAE)); do{$y=betain($xinbta,$pp,$qq,$beta);\nif($y==-1 ||$y==-2){ return -3;} # betain returns an exception\n$y=($y-$a)*exp($beta+$r*log($xinbta)+$t*log(1-$xinbta));\nif($y*$y<=0){ $prev=max($sq,$FPU);}$g=1;\nLabel10: do{\ndo{ $adj=$g*$y;$sq=$adj*$adj; $g/=3;} while($sq>=$prev);$tx=$xinbta-$adj;}\nuntil($tx>=0 &&$tx<=1);\nif($prev<=$ACU || $y*$y<=$ACU){ goto Label12;} if($tx==0 || $tx==1){ goto Label10;}$xinbta=$tx;$yprev=$y;} until($adj==0);\n\nLabel12:\nif($index){ return 1-$xinbta;}\nelse{ return $xinbta;} } sub Xinbta($$){ # Computes the inverse of the incomplete beta function # by calling loggamma() and xinbta() # # copyright by H.A. Kestler, 1998 my (p, q, alpha) = @_; if(alpha==1){return 1;} elsif(alpha==0){return 0;} else{ return xinbta(p, q,loggamma(p)+loggamma(q)-loggamma(p+q), alpha);} } sub rank(\\@){ # Computes the ranks of the values specified as the second # argument (an array). Returns a vector of ranks # corresponding to the input vector. # Different types of ranking are possible ('high', 'low', 'mean'), # and are specified as first argument. # These differ in the way ties of the input vector, i.e. identical # values, are treated: # 'high' --> replace ranks of identical values with their # highest rank # 'low' --> replace ranks of identical values with their # lowest rank # 'mean' --> replace ranks of identical values with the mean # of their rank # # copyright by H.A. Kestler, 1998 my (type, r) = @_; # type: type of ranking 'high', 'low' or 'mean' # r: reference to array of values to be ranked my (@s, s, i, @e, @rk, rk_m); # calculate initial rank's @s=sort{$$r[$a]<=>$$r[b]} 0..#{r}; # sort idx num. by values of @r for(i=0,@rk=@s;i<@rk;i++){ rk[s[i]]=i+1;} # set rank's # treat ties for(i=1,@e=(); i<@s; i++){ if($$r[$s[$i]]==$$r[s[i-1]]){ # test if there are ties push @e,i-1;} # save index numbers of tied values (minus 1) elsif(@e){ # ties have occured and are now being treated if(type eq'mean'){ # calculate mean value of tied ranks rk_m=0; for(@e,e[-1]+1){ rk_m+=rk[s[_]];} rk_m/=@e+1; } for(@e,e[-1]+1){ if(type eq 'high'){ rk[s[_]]=rk[s[e[-1]+1]];} elsif(type eq 'low' ){ rk[s[_]]=rk[s[e]];} elsif(type eq 'mean'){ rk[s[_]]=rk_m;} else{ croak \"Wrong type of ranking (high|low|mean).\\n\";} } @e=(); # reinitialize @e } } return @rk; } sub locate(\\@){ # Routine to find the index for table lookup which is below # the value to be interpolated. # Given a reference to an array xx and a value x a value j # is returned such that x is between xx[j] and xx[j+1]. # xx must be monotonic, either increasing or decreasing. # # This routine is adapted from \"Numerical Recipes in C\", # second edition, by Press, Teukolsky, Vetterling and Flannery, # Cambridge University Press, 1992. # It uses bisection to find the right place, which has a # comutational complexity of O(log_2(n)). # # copyright by H.A. Kestler, 1998 my (xx,x)=@_; my (jl,ju)=(0,#{xx}); # initialize lower and upper limits my (jm,ascend); ascend=$$xx[$ju] > $$xx; # test if x is inside of the array if((x>$$xx[$ju] || $x<$$xx[jl]) && ascend) { croak \"Value out of range for table lookup (1): x.\\n\";} if((x<$$xx[$ju] || $x>$$xx[jl]) && !ascend) { croak \"Value out of range for table lookup (2): x.\\n\";} while((ju-jl)>1) { # If we are not yet done jm=int((ju+jl)/2); # compute a midpoint, if(x > xx->[jm] == ascend) { jl=jm;} # and replace either the lower limit else { ju=jm;} # or the upper limit, as appropriate. } return jl; } sub linlocate(\\@$$){ # Routine to find the index for table lookup which is below # the value to be interpolated. # Given a reference to an array$xx and a value $x a value$j\n# is returned such that $x is between$xx[$j] and$xx[$j+1]. #$xx must be monotonic, either increasing or decreasing.\n#\n# Starts searching linearly from an initial index value\n# provided as the third argument.\n# If no index value can be found a negative value is\n# returned, i.e. -1.\n#\n# copyright by H.A. Kestler, 1998\n\nmy ($xx,$x,$index)=@_; my ($jl,$ju)=(0,$#{$xx}); # initialize lower and upper limits my$ascend;\n\n$ascend=$$xx[ju] >$$xx; # test if$x is inside of the array\nif(($x>$$xx[ju] || x<$$xx[$jl]) && $ascend) { croak \"Value out of range for table lookup.\\n\";} if(($x<$$xx[ju] || x>$$xx[$jl]) && !$ascend)\n{ croak \"Value out of range for table lookup.\\n\";}\n\n# step through the table sequentially\nif($ascend &&$xx->[$index]<$x){ # ascending\nwhile($x>$xx->[$index] and$index<=$ju) {$index++;}}\nelsif(!$ascend &&$xx->[$index]>$x){ # descending\nwhile($x<$xx->[$index] and$index<=$ju) {$index++;}}\nelse{ return -1;} # starting index is too high\n\nreturn $index-1; } sub interp(\\@\\@\\@){ # Interpolates (table lookup) piecewise linearly an # array (third argument). Returns # The table is represented by the first two arguments, i.e. @xx and @yy. # Assumes the @xx values to be monotonically increasing. # # copyright by H.A. Kestler, 1998 use vars ('@xx', '@yy', '@x'); local (*xx, *yy, *x)=@_; my ($i, $index, @y); # make checks if(@xx != @yy) {croak \"Sizes of xx and yy arrays are not equal.\\n\";} for($i=0; $i<@x;$i++)\n{\n$index=locate(@xx,$x[$i]);$y[$i]=($yy[$index+1]-$yy[$index])/($xx[$index+1]-$xx[$index])* ($x[$i]-$xx[$index]) +$yy[$index]; } return @y; } sub roc($$\\@){ # ROC (receiver operator characteristic) curves with confidence bounds # # Determines the ROC curve and its nonparametric confidence bounds. # The ROC curve shows the relationship of \"probability of false # alarm\" (x-axis) to \"probability of detection\" (y-axis) for a # certain test. # Or in medical terms: the \"probability of a positive test, given no # disease\" to the \"probability of a positive test, given disease\". # The ROC curve may be used to determine an \"optimal\" cutoff # point for the test. # # The routine takes three arguments: # (1) type of model: 'decrease' or 'increase', this states the assumption # that a higher ('increase') value of the data tends to be an # indicator of a positive test result or for the model 'decrease' # a lower value. # (2) two-sided confidence interval (usually 0.95 is chosen). # (3) the data stored as a list-of-lists: # each entry in this list consits of an \"value / true group\" pair, # i.e. value / disease present. Group values are from {0,1}. # 0 stands for disease (or signal) not present (prior knowledge) and # 1 for disease (or signal) present (prior knowledge). # Example: @s=([2, 0], [12.5, 1], [3, 0], [10, 1], [9.5, 0], [9, 1]); # Notice the small overlap of the groups. The # optimal cutoff point to separate the two groups would be between # 9 and 9.5 if the criterion of optimality is to maximize the # probability of detection and simultaneously minimize the # probability of false alarm. # # Returns a list-of-lists with the three curves: # @ROC=([@lower_b], [@roc], [@upper_b]) each of the curves is # again a list-of-lists with each entry consisting of one (x,y) pair. # The routine impelements the method described in: # R.A. Hilgers, Distribution-Free Confidence Bounds for ROC Curves, # Meth Inform Med 1991; 30:96-101 # # copyright by H.A. Kestler, 1998 my$model_type = shift; # assign\nmy $conf = shift; use vars '@val_grp'; local (*val_grp)=@_; my ($cu, $cl,$elem, $n1,$n0, $i,$j);\nmy @grp1=();my @grp0=();\nmy (@f_l_1,@f_m_1,@f_h_1,@f_l_0,@f_m_0,@f_h_0,@mat,@xx,@yy,@x,@y,@index);\nmy (@lower_b ,@roc ,@upper_b, @ROC);\n\n# make checks\nif($conf>=1 ||$conf<=0){ croak\n\"The nominal 2-sided confidence limit must be a number of [0,1].\\n\";}\nif($model_type ne 'increase' &&$model_type ne 'decrease'){ croak\n\"Wrong model type specified!\\n\";}\n\n$cu=(sqrt($conf)+1)/2; # calculate the one-sided upper\n$cl=1-$cu; # and lower confidence limits\n\n# extract values\nfor($i=0;$i<@val_grp;$i++){ if($val_grp[$i]==1) { push @grp1,$val_grp[$i];} else { push @grp0,$val_grp[$i];} } # compute ranks and values of inverse incomplete beta function @f_l_1=rank('low' ,@grp1); @f_m_1=rank('mean',@grp1); @f_h_1=rank('high',@grp1); @f_l_0=rank('low' ,@grp0); @f_m_0=rank('mean',@grp0); @f_h_0=rank('high',@grp0);$n1=@grp1; $n0=@grp0; # number of elements in both arrays for$elem (@f_l_1){ $elem=Xinbta($elem,$n1+1-$elem,$cl);} for$elem (@f_m_1){ $elem=Xinbta($elem,$n1+1-$elem,0.5);}\nfor $elem (@f_h_1){$elem=Xinbta($elem,$n1+1-$elem,$cu);}\nfor $elem (@f_l_0){$elem=Xinbta($elem,$n0+1-$elem,$cl);}\nfor $elem (@f_m_0){$elem=Xinbta($elem,$n0+1-$elem,0.5);} for$elem (@f_h_0){ $elem=Xinbta($elem,$n0+1-$elem,$cu);} # merge and sort @mat=(); for($i=0;$i<$n1;$i++){ push @mat, [($grp1[$i], -1, -1, -1,$f_l_1[$i],$f_m_1[$i],$f_h_1[$i])];} for($i=0;$i<$n0;$i++){ push @mat, [($grp0[$i],$f_l_0[$i],$f_m_0[$i],$f_h_0[$i], -1, -1, -1)];} # sort numerically according to value in first column @mat=@mat[sort{$mat[$a] <=>$mat[$b]} 0..$#mat];\n\n# for practical purposes augment @mat and fill missing data (-1)\n# at the beginning and end of the matrix\nunshift @mat,[-1, 0, 0, Xinbta(1,$n0,$cu), 0, 0, Xinbta(1,$n1,$cu)];\npush @mat,[-1, Xinbta($n0,1,$cl), 1, 1, Xinbta($n1,1,$cl), 1, 1];\nfor($i=1;$mat[$i]==-1;$i++){\n$mat[$i]=0; $mat[$i]=0; $mat[$i]=$mat;} for($i=1;$mat[$i]==-1; $i++){$mat[$i]=0;$mat[$i]=0;$mat[$i]=$mat;}\nfor($i=$#mat-1;$mat[$i]==-1; $i--){$mat[$i]=$mat[$#mat];$mat[$i]=1;$mat[$i]=1;} for($i=$#mat-1;$mat[$i]==-1;$i--){\n$mat[$i]=$mat[$#mat]; $mat[$i]=1; $mat[$i]=1;}\n\n# replace missing data (-1) with a piecewise linear interpolation\nfor($j=1;$j<7;$j++) # iterate thru columns { for($i=1,@xx=(),@yy=(),@x=(),@index=();$i<$#mat;$i++){ push @xx,$mat[$i] if$mat[$i][$j] !=-1;\npush @yy, $mat[$i][$j] if$mat[$i][$j] !=-1;\npush @x, $mat[$i] if $mat[$i][$j] ==-1; push @index,$i if $mat[$i][$j] ==-1; } @y=interp(@xx,@yy,@x); for($i=0;$i<@index;$i++){ $mat[$index[$i]][$j]=$y[$i];}\n}\n\n# calculate (x,y) pairs of ROC curve and its limit curves\n# (lower, ROC, upper) according to specified model\nfor($i=0,@lower_b=(),@roc=(),@upper_b=(),;$i<@mat;$i++){ if($model_type eq 'decrease'){\npush @lower_b, [($mat[$i], $mat[$i])];\npush @roc, [($mat[$i], $mat[$i])];\npush @upper_b, [($mat[$i], $mat[$i])];\n}\nelse{\npush @lower_b, [(1-$mat[$i], 1-$mat[$i])];\npush @roc, [(1-$mat[$i], 1-$mat[$i])];\npush @upper_b, [(1-$mat[$i], 1-$mat[$i])];\n}\n}\n\n@ROC=([@lower_b], [@roc], [@upper_b]);\nreturn @ROC;\n}\n\n# Autoload methods go after =cut, and are processed by the autosplit program.\n\n1;\n__END__\n\nStatistics::ROC - receiver-operator-characteristic (ROC) curves with nonparametric confidence bounds\n\nuse Statistics::ROC;\n\nmy ($y) = loggamma($x);\nmy ($y) = betain($x, $p,$q, $beta); my ($y) = Betain($x,$p, $q); my ($y) = xinbta($p,$q, $beta,$alpha);\nmy ($y) = Xinbta($p, $q,$alpha);\nmy (@rk) = rank($type, \\@r); my (@ROC) = roc($model_type,$conf,\\@val_grp); =head1 DESCRIPTION This program determines the ROC curve and its nonparametric confidence bounds for data categorized into two groups. A ROC curve shows the relationship of B<probability of false alarm> (x-axis) to B<probability of detection> (y-axis) for a certain test. Expressed in medical terms: the B<probability of a positive test, given no disease> to the B<probability of a positive test, given disease>. The ROC curve may be used to determine an I<optimal> cutoff point for the test. The main function is B<roc()>. The other exported functions are used by B<roc()>, but might be useful for other nonparametric statistical procedures. =over 4 =item B<loggamma> This procedure evaluates the natural logarithm of gamma(x) for all x>0, accurate to 10 decimal places. Stirlings formula is used for the central polynomial part of the procedure. For C<x=0> a value of 743.746924740801 will be returned: this is loggamma(9.9999999999E-324). =item B<betain> Computes incomplete beta function ratio Remarks: Complete beta function: B(p,q)=gamma(p)*gamma(q)/gamma(p+q) log(B(p,q))=ln(gamma(p))+ln(gamma(q))-ln(gamma(p+q)) Incomplete beta function ratio: I_x(p,q)=1/B(p,q) * \\int_0^x t^{p-1}*(1-t)^{q-1} dt --> log(B(p,q)) has to be supplied to calculate I_x(p,q) log denotes the natural logarithm$beta = log(B(p,q))\n$x = x$p = p\n$q = q The subroutine returns I_x(p,q). If an error occurs a negative value {-1,-2} is returned. =item B<Betain> Computes the incomplete beta function by calling B<loggamma()> and B<betain()>. =item B<xinbta> Computes inverse of incomplete beta function ratio Remarks: Complete beta function: B(p,q)=gamma(p)*gamma(q)/gamma(p+q) log(B(p,q))=ln(gamma(p))+ln(gamma(q))-ln(gamma(p+q)) Incomplete beta function ratio: alpha = I_x(p,q) = 1/B(p,q) * \\int_0^x t^{p-1}*(1-t)^{q-1} dt --> log(B(p,q)) has to be supplied to calculate I_x(p,q) log denotes the natural logarithm$beta = log(B(p,q))\n$alpha= I_x(p,q)$p = p\n$q = q The subroutine returns x. If an error occurs a negative value {-1,-2,-3} is returned. =item B<Xinbta> Computes the inverse of the incomplete beta function by calling B<loggamma()> and B<xinbta()>. =item B<rank> Computes the ranks of the values specified as the second argument (an array). Returns a vector of ranks corresponding to the input vector. Different types of ranking are possible ('high', 'low', 'mean'), and are specified as first argument. These differ in the way ties of the input vector, i.e. identical values, are treated: =over 10 =item * B<high>: replace ranks of identical values with their highest rank =item * B<low>: replace ranks of identical values with their lowest rank =item * B<mean>: replace ranks of identical values with the mean of their ranks =back =item B<roc> Determines the ROC curve and its nonparametric confidence bounds. The ROC curve shows the relationship of \"probability of false alarm\" (x-axis) to \"probability of detection\" (y-axis) for a certain test. Or in medical terms: the \"probability of a positive test, given no disease\" to the \"probability of a positive test, given disease\". The ROC curve may be used to determine an \"optimal\" cutoff point for the test. The routine takes three arguments: (1) type of model: 'decrease' or 'increase', this states the assumption that a higher ('increase') value of the data tends to be an indicator of a positive test result or for the model 'decrease' a lower value. (2) two-sided confidence interval (usually 0.95 is chosen). (3) the data stored as a list-of-lists: each entry in this list consits of an \"value / true group\" pair, i.e. value / disease present. Group values are from {0,1}. 0 stands for disease (or signal) not present (prior knowledge) and 1 for disease (or signal) present (prior knowledge). Example: @s=([2, 0], [12.5, 1], [3, 0], [10, 1], [9.5, 0], [9, 1]); Notice the small overlap of the groups. The optimal cutoff point to separate the two groups would be between 9 and 9.5 if the criterion of optimality is to maximize the probability of detection and simultaneously minimize the probability of false alarm. Returns a list-of-lists with the three curves: @ROC=([@lower_b], [@roc], [@upper_b]) each of the curves is again a list-of-lists with each entry consisting of one (x,y) pair. =back =over 4 =head2 Examples$,=\" \";\nprint loggamma(10), \"\\n\";\nprint Xinbta(3,4,Betain(.6,3,4)),\"\\n\";\n\n@e=(0.7, 0.7, 0.9, 0.6, 1.0, 1.1, 1,.7,.6);\nprint rank('low',@e),\"\\n\";\nprint rank('high',@e),\"\\n\";\nprint rank('mean',@e),\"\\n\";\n\n@var_grp=([1.5,0],[1.4,0],[1.4,0],[1.3,0],[1.2,0],[1,0],[0.8,0],\n[1.1,1],[1,1],[1,1],[0.9,1],[0.7,1],[0.7,1],[0.6,1]);\n@curves=roc('decrease',0.95,@var_grp);\nprint \"$curves$curves \\n\";\n\nHans A. Kestler, I<[email protected]> B<or>\nI<[email protected]>\n\nPerl/Tk userinterface for drawing ROC curves (requires installed Tk and X11 on MacOS X).\n\nR.A. Hilgers, Distribution-Free Confidence Bounds for ROC Curves (1991),\nI<Meth Inform Med>, 30:96-101\n\nAlgorithm 291, Logarithm of the gamma function.\nI<Collected Algorithms of the ACM>, Vol II, 1980\n\nI<Numerical Recipes in C>, second edition, by Press, Teukolsky, Vetterling and Flannery,\nCambridge University Press, 1992.\n\nG.W. Cran, K.J. Martin and G.E. Thomas (1977).Remark AS R19 and\nAlgorithm AS109, A Remark on Algorithms AS 63: The Incomplete Beta Integral\nAS 64: Inverse of the Incomplete Beta Function Ratio,\nI<Appl Statist>, 26:111-114.\n\nK.J. Berry, P.W. Mielke, Jr and G.W. Cran (1990) Algorithm AS R83, A Remark\non Algorithm AS 109: Inverse of the Incomplete Beta Function Ratio,\nI<Appl Statist>, 39:309-310.\n\n=cut" ]
[ null ]
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https://www.emworks.com/application/inductance-capacitance-and-resistance-of-a-pcb-structure
[ "HOME / Applications / Inductance Capacitance and Resistance of a PCB structure\n\n# Inductance Capacitance and Resistance of a PCB structure\n\nUsed Tools:", null, "", null, "## Parasitic parameters of a PCB\n\nEMI, or electromagnetic interference, is an undesirable electromagnetic noise from a device or a system that interferes with the normal operation of neighboring devices or systems.\nThe basic process of EMI modeling and prediction requires the extraction of parasitic parameters of a PCB and circuit components to build high frequency circuit models.\n\n## Parasitic capacitance, parasitic resistance, and parasitic inductance\n\nIn electronic design automation (EDA), parasitic extraction is the calculation of the parasitic effects in both the designed devices and the required wiring interconnects of an electronic circuit: parasitic capacitance, parasitic resistance, and parasitic inductance. In this article, we illustrate the use of EMS to calculate these circuit parameters and compare the results to published data .\n\n## Soildworks PCB model\n\nA PCB structure shown in Figure 1, contains two copper traces on a 4-oz FR4 PCB square board and a 5 mils thickness copper Ground. Some parameters used in simulation are given below where all dimensions are in mils.\nConductivity of Copper = 5.8 107S/m\nRelative Permittivity of FR4 = 4.4", null, "Figure 1 -  A PCB structure used for simulation where all dimensions are in mils\n\n## Capacitance calculation\n\nTo compute the parasitic capacitance of the PCB structure, shown in Figure 1, the Electrostatic module is invoked. Figure 2 shows the model and the mesh for the PCB structure.", null, "Figure 2 - Model and mesh of the PCB structure\n\n## Three floating conductors\n\nTo account for the capacitance of a given conductor, it is assigned a floating boundary condition, including the ground plane, in EMS.  As a result, this PCB structure has three floating conductors, i.e. the left and right traces as well as the ground plane.\nThe EMS capacitance results and that of the Reference are shown in Figure 3 and Table 1.", null, "Figure 3 - Parasitic capacitance computed by EMS\n\n Reference EMS The capacitance between the left trace and the ground plane -4.3047 pF -4.3563 pF The capacitance between the right trace and the ground plane -4.3046 pF -4.3552 pF The capacitance between the two copper traces -0.1673 pF -0.1825 pF\nTable 1 - Capacitance results of EMS compared to Reference \n\n## DC Inductance & DC Resistance calculation\n\nTo compute the DC resistance and inductance of the PCB structure, shown in Figure 1, the EMS Magnetostatic module is invoked.  To compute the DC inductance and DC resistance of the copper traces, they are modeled as coils. The DC inductance and DC resistance results obtained by EMS and compared to Reference , are shown below:", null, "Figure 4 - DC Resistance computed by EMS", null, "Figure 5 - DC Inductance computed by EMS\n\nDC loop Inductance is obtained by the following formula:\nL Loop = L11+L22- 2*M12 ; where L11, L22: self inductances; M12: mutual inductance\n\n Reference EMS DC resistance 5.4304 m Ohm 5.4304 m Ohm DC Loop inductance 50.742 n Henry 54.775 n Henry\nTable 2 - DC resistance and DC inductance results produced by EMS and compared to Reference \n\n## AC Inductance & AC Resistance calculation\n\nIn addition to DC inductance and resistance calculation, EMS is equipped with AC Magnetic and eddy current capabilities which are used to compute the AC resistance and AC loop inductance for the PCB structure at hand at the frequencies: 1Khz, 2Khz, 5Khz, 10 KHz, 20 KHz, 50 KHz, 100 KHz, 200 KHz, 500 KHz, 1 Mhz.\n\n### Reduced model\n\nDue to the small size of the skin depth of the field for the conducting regions, i.e. order of 1e-005 to 1e-004 mm, important computer resources, both in terms of CPU and RAM, are needed.  Therefore, only 1/20 of the model is simulated as shown in Figure 6.  In turn, the obtained inductance and resistance by the reduced model are multiplied by 20 to recover the full model results.", null, "Figure 6 - 1/20 of the structure is modeled for AC Magnetic analysis\n\nSimilar to the above Magnetostatic analysis, the two traces are modeled as coils.  In order to account for the skin depth in the AC resistance calculation, the coils are modeled as solids, i.e. wound coils do not support eddy current.  Figure 7 shows the AC resistance for frequencies from 1 KHz to 1 MHz computed by EMS and compared to Reference .   Whereas Figure 8 shows the AC inductance results and comparison for the same frequency range.", null, "Figure 7 - AC resistance computed by EMS and compared to Reference", null, "Figure 8 - AC inductance computed by EMS and compared to Reference \n\n## Conclusion\n\nClearly, EMS compares well with the capacitance, AC and DC inductance and resistance published results for PCB structures.  Hence EMS can readily be used to easily and quickly extract parasitic parameters for PCB and electronic structures which, in turn, can be used to build high frequency circuit models.\n\n## References\n\n Jingen Qian, “RF Models for Active IPEMs”, MS Thesis in Electrical Engineering,  Virginia Polytechnic Institute and State University, January 31, 2003." ]
[ null, "https://www.emworks.com/media/images/product/large/EMS-logo.png", null, "https://www.emworks.com/assets/img/cad/solidworks-icon.png", null, "https://www.emworks.com/ckfinder/userfiles/images/PCB-structure-used-for-simulation.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/model-and-mesh-of-the-PCB-structure.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/Parasitic-capacitance-computed-by-EMS.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/DC-Resistance-computed-by-EMS.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/DC-Inductance-computed-by-EMS.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/simulate-a-portion-of-the-model.jpg", null, "https://www.emworks.com/ckfinder/userfiles/images/AC-resistance-comparison.png", null, "https://www.emworks.com/ckfinder/userfiles/images/AC-inductance-comparison.png", null ]
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http://neuralensemble.blogspot.com/2015/04/elephant-010-released.html
[ "## Wednesday, April 8, 2015\n\n### Elephant 0.1.0 released\n\nWe are pleased to announce the first release of the Elephant toolbox for the analysis of neurophysiology data.\n\nElephant builds on the Python scientific stack (NumPy, SciPy) to provide a set of well-tested analysis functions for spike train data and time series recordings from electrodes, such as spike train statistics, power spectrum analysis, filtering, cross-correlation and spike-triggered averaging. The toolbox also provides tools to generate artificial spike trains, either from stochastic processes or by controlled perturbations of real spike trains. Elephant is built on the Neo data model, and takes advantage of the broad file-format support provided by the Neo library. A bridge to the Pandas data analysis library is also provided.\n\nElephant is a community-based effort, aimed at providing a common platform to test and distribute code from different laboratories, with the goal of improving the reproducibility of modern neuroscience research. If you are a neuroscience researcher or student using Python for data analysis, please consider joining us, either to contribute your own code or to help with code review and testing.\n\nElephant is the direct successor to NeuroTools and maintains ties to complementary projects such as OpenElectrophy and SpykeViewer. It is also the default tool for electrophysiology data analysis in the Human Brain Project.\n\nAs a simple example, let's generate some artificial spike train data using a homogeneous Poisson process:\n\nfrom elephant.spike_train_generation import homogeneous_poisson_process\nfrom quantities import Hz, s, ms\nspiketrains = [\nhomogeneous_poisson_process(rate=10.0*Hz, t_start=0.0*s, t_stop=100.0*s)\nfor i in range(100)]\n\nand visualize it in Matplotlib:\n\nimport matplotlib.pyplot as plt\nimport numpy as np\nfor i, spiketrain in enumerate(spiketrains):\nt = spiketrain.rescale(ms)\nplt.plot(t, i * np.ones_like(t), 'k.', markersize=2)\nplt.axis('tight')\nplt.xlim(0, 1000)\nplt.xlabel('Time (ms)', fontsize=16)\nplt.ylabel('Spike Train Index', fontsize=16)\nplt.gca().tick_params(axis='both', which='major', labelsize=14)\nplt.show()", null, "Now we calculate the coefficient of variation of the inter-spike interval for each of the 100 spike trains.\n\nfrom elephant.statistics import isi, cv\ncv_list = [cv(isi(spiketrain)) for spiketrain in spiketrains]\n\nAs expected for a Poisson process, the values cluster around 1:\n\nplt.hist(cv_list)\nplt.xlabel('CV', fontsize=16)\nplt.ylabel('count', fontsize=16)\nplt.gca().tick_params(axis='both', which='major', labelsize=14)\nplt.show()", null, "" ]
[ null, "http://elephant.readthedocs.org/en/latest/_images/tutorial_1_figure_1.png", null, "http://elephant.readthedocs.org/en/latest/_images/tutorial_1_figure_2.png", null ]
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https://whatisconvert.com/141-acres-in-square-inches
[ "# What is 141 Acres in Square Inches?\n\n## Convert 141 Acres to Square Inches\n\nTo calculate 141 Acres to the corresponding value in Square Inches, multiply the quantity in Acres by 6272640 (conversion factor). In this case we should multiply 141 Acres by 6272640 to get the equivalent result in Square Inches:\n\n141 Acres x 6272640 = 884442240 Square Inches\n\n141 Acres is equivalent to 884442240 Square Inches.\n\n## How to convert from Acres to Square Inches\n\nThe conversion factor from Acres to Square Inches is 6272640. To find out how many Acres in Square Inches, multiply by the conversion factor or use the Area converter above. One hundred forty-one Acres is equivalent to eight hundred eighty-four million four hundred forty-two thousand two hundred forty Square Inches.", null, "## Definition of Acre\n\nThe acre (symbol: ac) is a unit of land area used in the imperial and US customary systems. It is defined as the area of 1 chain by 1 furlong (66 by 660 feet), which is exactly equal to  1⁄640 of a square mile, 43,560 square feet, approximately 4,047 m2, or about 40% of a hectare. The most commonly used acre today is the international acre. In the United States both the international acre and the US survey acre are in use, but differ by only two parts per million, see below. The most common use of the acre is to measure tracts of land. One international acre is defined as exactly 4,046.8564224 square metres.\n\n## Definition of Square Inch\n\nA square inch (plural: square inches) is a unit of area, equal to the area of a square with sides of one inch. The following symbols are used to denote square inches: square in, sq inches, sq inch, sq in inches/-2, inch/-2, in/-2, inches^2, inch^2, in^2, inches2, inch2, in2. The square inch is a common unit of measurement in the United States and the United Kingdom.\n\n### Using the Acres to Square Inches converter you can get answers to questions like the following:\n\n• How many Square Inches are in 141 Acres?\n• 141 Acres is equal to how many Square Inches?\n• How to convert 141 Acres to Square Inches?\n• How many is 141 Acres in Square Inches?\n• What is 141 Acres in Square Inches?\n• How much is 141 Acres in Square Inches?\n• How many in2 are in 141 ac?\n• 141 ac is equal to how many in2?\n• How to convert 141 ac to in2?\n• How many is 141 ac in in2?\n• What is 141 ac in in2?\n• How much is 141 ac in in2?" ]
[ null, "https://whatisconvert.com/images/141-acres-in-square-inches", null ]
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https://www.nag.com/numeric/cl/nagdoc_latest/html/f01/f01efc.html
[ "# NAG C Library Function Document\n\n## 1Purpose\n\nnag_matop_real_symm_matrix_fun (f01efc) computes the matrix function, $f\\left(A\\right)$, of a real symmetric $n$ by $n$ matrix $A$. $f\\left(A\\right)$ must also be a real symmetric matrix.\n\n## 2Specification\n\n #include #include\nvoid  nag_matop_real_symm_matrix_fun (Nag_OrderType order, Nag_UploType uplo, Integer n, double a[], Integer pda,\n void (*f)(Integer *flag, Integer n, const double x[], double fx[], Nag_Comm *comm),\nNag_Comm *comm, Integer *flag, NagError *fail)\n\n## 3Description\n\n$f\\left(A\\right)$ is computed using a spectral factorization of $A$\n $A = Q D QT ,$\nwhere $D$ is the diagonal matrix whose diagonal elements, ${d}_{i}$, are the eigenvalues of $A$, and $Q$ is an orthogonal matrix whose columns are the eigenvectors of $A$. $f\\left(A\\right)$ is then given by\n $fA = Q fD QT ,$\nwhere $f\\left(D\\right)$ is the diagonal matrix whose $i$th diagonal element is $f\\left({d}_{i}\\right)$. See for example Section 4.5 of Higham (2008). $f\\left({d}_{i}\\right)$ is assumed to be real.\nHigham N J (2008) Functions of Matrices: Theory and Computation SIAM, Philadelphia, PA, USA\n\n## 5Arguments\n\n1:    $\\mathbf{order}$Nag_OrderTypeInput\nOn entry: the order argument specifies the two-dimensional storage scheme being used, i.e., row-major ordering or column-major ordering. C language defined storage is specified by ${\\mathbf{order}}=\\mathrm{Nag_RowMajor}$. See Section 3.3.1.3 in How to Use the NAG Library and its Documentation for a more detailed explanation of the use of this argument.\nConstraint: ${\\mathbf{order}}=\\mathrm{Nag_RowMajor}$ or $\\mathrm{Nag_ColMajor}$.\n2:    $\\mathbf{uplo}$Nag_UploTypeInput\nOn entry: if ${\\mathbf{uplo}}=\\mathrm{Nag_Upper}$, the upper triangle of the matrix $A$ is stored.\nIf ${\\mathbf{uplo}}=\\mathrm{Nag_Lower}$, the lower triangle of the matrix $A$ is stored.\nConstraint: ${\\mathbf{uplo}}=\\mathrm{Nag_Upper}$ or $\\mathrm{Nag_Lower}$.\n3:    $\\mathbf{n}$IntegerInput\nOn entry: $n$, the order of the matrix $A$.\nConstraint: ${\\mathbf{n}}\\ge 0$.\n4:    $\\mathbf{a}\\left[\\mathit{dim}\\right]$doubleInput/Output\nNote: the dimension, dim, of the array a must be at least ${\\mathbf{pda}}×{\\mathbf{n}}$.\nOn entry: the $n$ by $n$ symmetric matrix $A$.\nIf ${\\mathbf{order}}=\\mathrm{Nag_ColMajor}$, ${A}_{ij}$ is stored in ${\\mathbf{a}}\\left[\\left(j-1\\right)×{\\mathbf{pda}}+i-1\\right]$.\nIf ${\\mathbf{order}}=\\mathrm{Nag_RowMajor}$, ${A}_{ij}$ is stored in ${\\mathbf{a}}\\left[\\left(i-1\\right)×{\\mathbf{pda}}+j-1\\right]$.\nIf ${\\mathbf{uplo}}=\\mathrm{Nag_Upper}$, the upper triangular part of $A$ must be stored and the elements of the array below the diagonal are not referenced.\nIf ${\\mathbf{uplo}}=\\mathrm{Nag_Lower}$, the lower triangular part of $A$ must be stored and the elements of the array above the diagonal are not referenced.\nOn exit: if ${\\mathbf{fail}}\\mathbf{.}\\mathbf{code}=$ NE_NOERROR, the upper or lower triangular part of the $n$ by $n$ matrix function, $f\\left(A\\right)$.\n5:    $\\mathbf{pda}$IntegerInput\nOn entry: the stride separating row or column elements (depending on the value of order) of the matrix $A$ in the array a.\nConstraint: ${\\mathbf{pda}}\\ge \\mathrm{max}\\phantom{\\rule{0.125em}{0ex}}\\left(1,{\\mathbf{n}}\\right)$.\n6:    $\\mathbf{f}$function, supplied by the userExternal Function\nThe function f evaluates $f\\left({z}_{i}\\right)$ at a number of points ${z}_{i}$.\nThe specification of f is:\n void f (Integer *flag, Integer n, const double x[], double fx[], Nag_Comm *comm)\n1:    $\\mathbf{flag}$Integer *Input/Output\nOn entry: flag will be zero.\nOn exit: flag should either be unchanged from its entry value of zero, or may be set nonzero to indicate that there is a problem in evaluating the function $f\\left(x\\right)$; for instance $f\\left(x\\right)$ may not be defined, or may be complex. If flag is returned as nonzero then nag_matop_real_symm_matrix_fun (f01efc) will terminate the computation, with ${\\mathbf{fail}}\\mathbf{.}\\mathbf{code}=$ NE_USER_STOP.\n2:    $\\mathbf{n}$IntegerInput\nOn entry: $n$, the number of function values required.\n3:    $\\mathbf{x}\\left[{\\mathbf{n}}\\right]$const doubleInput\nOn entry: the $n$ points ${x}_{1},{x}_{2},\\dots ,{x}_{n}$ at which the function $f$ is to be evaluated.\n4:    $\\mathbf{fx}\\left[{\\mathbf{n}}\\right]$doubleOutput\nOn exit: the $n$ function values. ${\\mathbf{fx}}\\left[\\mathit{i}-1\\right]$ should return the value $f\\left({x}_{\\mathit{i}}\\right)$, for $\\mathit{i}=1,2,\\dots ,n$.\n5:    $\\mathbf{comm}$Nag_Comm *\nPointer to structure of type Nag_Comm; the following members are relevant to f.\nuserdouble *\niuserInteger *\npPointer\nThe type Pointer will be void *. Before calling nag_matop_real_symm_matrix_fun (f01efc) you may allocate memory and initialize these pointers with various quantities for use by f when called from nag_matop_real_symm_matrix_fun (f01efc) (see Section 3.3.1.1 in How to Use the NAG Library and its Documentation).\nNote: f should not return floating-point NaN (Not a Number) or infinity values, since these are not handled by nag_matop_real_symm_matrix_fun (f01efc). If your code inadvertently does return any NaNs or infinities, nag_matop_real_symm_matrix_fun (f01efc) is likely to produce unexpected results.\n7:    $\\mathbf{comm}$Nag_Comm *\nThe NAG communication argument (see Section 3.3.1.1 in How to Use the NAG Library and its Documentation).\n8:    $\\mathbf{flag}$Integer *Output\nOn exit: ${\\mathbf{flag}}=0$, unless you have set flag nonzero inside f, in which case flag will be the value you set and fail will be set to ${\\mathbf{fail}}\\mathbf{.}\\mathbf{code}=$ NE_USER_STOP.\n9:    $\\mathbf{fail}$NagError *Input/Output\nThe NAG error argument (see Section 3.7 in How to Use the NAG Library and its Documentation).\n\n## 6Error Indicators and Warnings\n\nIf ${\\mathbf{fail}}\\mathbf{.}\\mathbf{code}=i$, the algorithm to compute the spectral factorization failed to converge; $i$ off-diagonal elements of an intermediate tridiagonal form did not converge to zero (see nag_dsyev (f08fac)).\nNE_ALLOC_FAIL\nDynamic memory allocation failed.\nSee Section 2.3.1.2 in How to Use the NAG Library and its Documentation for further information.\nOn entry, argument $〈\\mathit{\\text{value}}〉$ had an illegal value.\nNE_CONVERGENCE\nThe computation of the spectral factorization failed to converge.\nNE_INT\nOn entry, ${\\mathbf{n}}=〈\\mathit{\\text{value}}〉$.\nConstraint: ${\\mathbf{n}}\\ge 0$.\nNE_INT_2\nOn entry, ${\\mathbf{pda}}=〈\\mathit{\\text{value}}〉$ and ${\\mathbf{n}}=〈\\mathit{\\text{value}}〉$.\nConstraint: ${\\mathbf{pda}}\\ge {\\mathbf{n}}$.\nNE_INTERNAL_ERROR\nAn internal error has occurred in this function. Check the function call and any array sizes. If the call is correct then please contact NAG for assistance.\nSee Section 2.7.6 in How to Use the NAG Library and its Documentation for further information.\nNE_NO_LICENCE\nYour licence key may have expired or may not have been installed correctly.\nSee Section 2.7.5 in How to Use the NAG Library and its Documentation for further information.\nNE_USER_STOP\nflag was set to a nonzero value in f.\n\n## 7Accuracy\n\nProvided that $f\\left(D\\right)$ can be computed accurately then the computed matrix function will be close to the exact matrix function. See Section 10.2 of Higham (2008) for details and further discussion.\n\n## 8Parallelism and Performance\n\nnag_matop_real_symm_matrix_fun (f01efc) is threaded by NAG for parallel execution in multithreaded implementations of the NAG Library.\nnag_matop_real_symm_matrix_fun (f01efc) makes calls to BLAS and/or LAPACK routines, which may be threaded within the vendor library used by this implementation. Consult the documentation for the vendor library for further information.\nPlease consult the x06 Chapter Introduction for information on how to control and interrogate the OpenMP environment used within this function. Please also consult the Users' Note for your implementation for any additional implementation-specific information.\n\nThe Integer allocatable memory required is n, and the double allocatable memory required is approximately $\\left({\\mathbf{n}}+\\mathit{nb}+4\\right)×{\\mathbf{n}}$, where nb is the block size required by nag_dsyev (f08fac).\nThe cost of the algorithm is $O\\left({n}^{3}\\right)$ plus the cost of evaluating $f\\left(D\\right)$. If ${\\stackrel{^}{\\lambda }}_{i}$ is the $i$th computed eigenvalue of $A$, then the user-supplied function f will be asked to evaluate the function $f$ at $f\\left({\\stackrel{^}{\\lambda }}_{i}\\right)$, $i=1,2,\\dots ,n$.\nFor further information on matrix functions, see Higham (2008).\nnag_matop_complex_herm_matrix_fun (f01ffc) can be used to find the matrix function $f\\left(A\\right)$ for a complex Hermitian matrix $A$.\n\n## 10Example\n\nThis example finds the matrix cosine, $\\mathrm{cos}\\left(A\\right)$, of the symmetric matrix\n $A= 1 2 3 4 2 1 2 3 3 2 1 2 4 3 2 1 .$\n\n### 10.1Program Text\n\nProgram Text (f01efce.c)\n\n### 10.2Program Data\n\nProgram Data (f01efce.d)\n\n### 10.3Program Results\n\nProgram Results (f01efce.r)" ]
[ null ]
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https://www.rapidtables.com/math/algebra/logarithm/Logarithm_of_Infinity.html
[ "# Logarithm of Infinity\n\nWhat is the logarithm of infinity?\n\nlog10(∞) = ?\n\nSince infinity is not a number, we should use limits:\n\n### x approaches infinity\n\nThe limit of the logarithm of x when x approaches infinity is infinity:\n\nlim log10(x) = ∞\n\nx→∞\n\n### x approaches minus infinity\n\nThe opposite case, the logarithm of minus infinity (-∞) is undefined for real numbers, since the logarithmic function is undefined for negative numbers:\n\nlim log10(x) is undefined\n\nx → -∞\n\nLogarithm of negative number ►" ]
[ null ]
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https://webusers.imj-prg.fr/~jean.michel/gap3/htm/chap010.htm
[ "10 Integers\n\nOne of the most fundamental datatypes in every programming language is the integer type. GAP3 is no exception.\n\nGAP3 integers are entered as a sequence of digits optionally preceded by a `+` sign for positive integers or a `-` sign for negative integers. The size of integers in GAP3 is only limited by the amount of available memory, so you can compute with integers having thousands of digits.\n\n``` gap> -1234;\n-1234\ngap> 123456789012345678901234567890123456789012345678901234567890;\n123456789012345678901234567890123456789012345678901234567890 ```\n\nThe first sections in this chapter describe the operations applicable to integers (see Comparisons of Integers, Operations for Integers, QuoInt and RemInt).\n\nThe next sections describe the functions that test whether an object is an integer (see IsInt) and convert objects of various types to integers (see Int).\n\nThe next sections describe functions related to the ordering of integers (see AbsInt, SignInt).\n\nThe next section describes the function that computes a Chinese remainder (see ChineseRem).\n\nThe next sections describe the functions related to the ordering of integers, logarithms, and roots (LogInt, RootInt, SmallestRootInt).\n\nThe GAP3 object `Integers` is the ring domain of all integers. So all set theoretic functions are also applicable to this domain (see chapter Domains and Set Functions for Integers). The only serious use of this however seems to be the generation of random integers.\n\nSince the integers form a Euclidean ring all the ring functions are applicable to integers (see chapter Rings, Ring Functions for Integers, Primes, IsPrimeInt, IsPrimePowerInt, NextPrimeInt, PrevPrimeInt, FactorsInt, DivisorsInt, Sigma, Tau, and MoebiusMu).\n\nSince the integers are naturally embedded in the field of rationals all the field functions are applicable to integers (see chapter Fields and Field Functions for Rationals).\n\nMany more functions that are mainly related to the prime residue group of integers modulo an integer are described in chapter Number Theory.\n\nThe external functions are in the file `LIBNAME/\"integer.g\"`.\n\n10.1 Comparisons of Integers\n\n`n1 = n2`\n`n1 <> n2`\n\nThe equality operator `=` evaluates to `true` if the integer n1 is equal to the integer n2 and `false` otherwise. The inequality operator `<>` evaluates to `true` if n1 is not equal to n2 and `false` otherwise.\n\nIntegers can also be compared to objects of other types; of course, they are never equal.\n\n``` gap> 1 = 1;\ntrue\ngap> 1 <> 0;\ntrue\ngap> 1 = (1,2); # `(1,2)` is a permutation\nfalse ```\n\n`n1 < n2`\n`n1 <= n2`\n`n1 > n2`\n`n1 >= n2`\n\nThe operators `<`, `<=`, `>`, and `=>` evaluate to `true` if the integer n1 is less than, less than or equal to, greater than, or greater than or equal to the integer n2, respectively.\n\nIntegers can also be compared to objects of other types, they are considered smaller than any other object, except rationals, where the ordering reflects the ordering of the rationals (see Comparisons of Rationals).\n\n``` gap> 1 < 2;\ntrue\ngap> 1 < -1;\nfalse\ngap> 1 < 3/2;\ntrue\ngap> 1 < false;\ntrue ```\n\n10.2 Operations for Integers\n\n`n1 + n2`\n\nThe operator `+` evaluates to the sum of the two integers n1 and n2.\n\n`n1 - n2`\n\nThe operator `-` evaluates to the difference of the two integers n1 and n2.\n\n`n1 * n2`\n\nThe operator `*` evaluates to the product of the two integers n1 and n2.\n\n`n1 / n2`\n\nThe operator `/` evaluates to the quotient of the two integers n1 and n2. If the divisor does not divide the dividend the quotient is a rational (see Rationals). If the divisor is 0 an error is signalled. The integer part of the quotient can be computed with `QuoInt` (see QuoInt).\n\n`n1 mod n2`\n\nThe operator `mod` evaluates to the smallest positive representative of the residue class of the left operand modulo the right, i.e., ```i mod k``` is the unique m in the range `[0 .. AbsInt(k)-1]` such that k divides `i - m`. If the right operand is 0 an error is signalled. The remainder of the division can be computed with `RemInt` (see RemInt).\n\n`n1 ^ n2`\n\nThe operator `^` evaluates to the n2-th power of the integer n1. If n2 is a positive integer then `n1^n2` is `n1* n1* ..* n1` (n2 factors). If n2 is a negative integer `n1^n2` is defined as 1 / n1-n2. If 0 is raised to a negative power an error is signalled. Any integer, even 0, raised to the zeroth power yields 1.\n\nSince integers embed naturally into the field of rationals all the rational operations are available for integers too (see Operations for Rationals).\n\nFor the precedence of the operators see Operations.\n\n``` gap> 2 * 3 + 1;\n7 ```\n\n10.3 QuoInt\n\n`QuoInt( n1, n2 )`\n\n`QuoInt` returns the integer part of the quotient of its integer operands.\n\nIf n1 and n2 are positive `QuoInt( n1, n2 )` is the largest positive integer q such that `q*n2 <= n1`. If n1 or n2 or both are negative the absolute value of the integer part of the quotient is the quotient of the absolute values of n1 and n2, and the sign of it is the product of the signs of n1 and n2.\n\n`RemInt` (see RemInt) can be used to compute the remainder.\n\n``` gap> QuoInt(5,2); QuoInt(-5,2); QuoInt(5,-2); QuoInt(-5,-2);\n2\n-2\n-2\n2 ```\n\n10.4 RemInt\n\n`RemInt( n1, n2 )`\n\n`RemInt` returns the remainder of its two integer operands.\n\nIf n2 is not equal to zero ```RemInt( n1, n2 ) = n1 - n2* QuoInt( n1, n2 )```. Note that the rules given for `QuoInt` (see QuoInt) imply that `RemInt( n1, n2 )` has the same sign as n1 and its absolute value is strictly less than the absolute value of n2. Dividing by 0 signals an error.\n\n``` gap> RemInt(5,2); RemInt(-5,2); RemInt(5,-2); RemInt(-5,-2);\n1\n-1\n1\n-1 ```\n\n10.5 IsInt\n\n`IsInt( obj )`\n\n`IsInt` returns `true` if obj, which can be an arbitrary object, is an integer and `false` otherwise. `IsInt` will signal an error if obj is an unbound variable.\n\n``` gap> IsInt( 1 );\ntrue\ngap> IsInt( IsInt );\nfalse # `IsInt` is a function, not an integer ```\n\n10.6 Int\n\n`Int( obj )`\n\n`Int` converts an object obj to an integer. If obj is an integer `Int` will simply return obj.\n\nIf obj is a rational number (see Rationals) `Int` returns the unique integer that has the same sign as obj and the largest absolute value not larger than the absolute value of obj.\n\nIf obj is an element of the prime field of a finite field F, `Int` returns the least positive integer n such that `n* F.one = obj` (see IntFFE).\n\nIf obj is not of one of the above types an error is signalled.\n\n``` gap> Int( 17 );\n17\ngap> Int( 17 / 3 );\n5\ngap> Int( Z(5^3)^62 );\n4 # Z(53)62=(Z(53)124/4)2=Z(5)2=PrimitiveRoot(5)2=22 ```\n\n10.7 AbsInt\n\n`AbsInt( n )`\n\n`AbsInt` returns the absolute value of the integer n, i.e., n if n is positive, -n if n is negative and 0 if n is 0 (see SignInt).\n\n``` gap> AbsInt( 33 );\n33\ngap> AbsInt( -214378 );\n214378\ngap> AbsInt( 0 );\n0 ```\n\n10.8 SignInt\n\n`SignInt( obj )`\n\n`SignInt` returns the sign of the integer obj, i.e., 1 if obj is positive, -1 if obj is negative and 0 if obj is 0 (see AbsInt).\n\n``` gap> SignInt( 33 );\n1\ngap> SignInt( -214378 );\n-1\ngap> SignInt( 0 );\n0 ```\n\n10.9 IsOddInt\n\n`IsOddInt( i )`\n\nDetermines whether i is odd.\n\n``` gap> IsOddInt(3);IsOddInt(4);\ntrue\nfalse```\n\n10.10 IsEvenInt\n\n`IsEvenInt( i )`\n\nDetermines whether i is even.\n\n``` gap> IsEvenInt(3);IsEvenInt(4);\nfalse\ntrue```\n\n10.11 ChineseRem\n\n`ChineseRem( moduli, residues )`\n\n`ChineseRem` returns the combination of the residues modulo the moduli, i.e., the unique integer c from `[0..Lcm(moduli)-1]` such that `c = residues[i]` modulo `moduli[i]` for all i, if it exists. If no such combination exists `ChineseRem` signals an error.\n\nSuch a combination does exist if and only if\n`residues[i]=residues[k]` mod `Gcd(moduli[i],moduli[k])` for every pair i, k. Note that this implies that such a combination exists if the moduli are pairwise relatively prime. This is called the Chinese remainder theorem.\n\n``` gap> ChineseRem( [ 2, 3, 5, 7 ], [ 1, 2, 3, 4 ] );\n53\ngap> ChineseRem( [ 6, 10, 14 ], [ 1, 3, 5 ] );\n103\ngap> ChineseRem( [ 6, 10, 14 ], [ 1, 2, 3 ] );\nError, the residues must be equal modulo 2 ```\n\n`LogInt( n, base )`\n\n`LogInt` returns the integer part of the logarithm of the positive integer n with respect to the positive integer base, i.e., the largest positive integer exp such that baseexp <= n. `LogInt` will signal an error if either n or base is not positive.\n\n``` gap> LogInt( 1030, 2 );\n10 # 210 = 1024\n0 ```\n\n10.13 RootInt\n\n`RootInt( n )`\n`RootInt( n, k )`\n\n`RootInt` returns the integer part of the kth root of the integer n. If the optional integer argument k is not given it defaults to 2, i.e., `RootInt` returns the integer part of the square root in this case.\n\nIf n is positive `RootInt` returns the largest positive integer r such that rk <= n. If n is negative and k is odd `RootInt` returns `-RootInt( -n, k )`. If n is negative and k is even `RootInt` will cause an error. `RootInt` will also cause an error if k is 0 or negative.\n\n``` gap> RootInt( 361 );\n19\ngap> RootInt( 2 * 10^12 );\n1414213\ngap> RootInt( 17000, 5 );\n7 # 75 = 16807 ```\n\n10.14 SmallestRootInt\n\n`SmallestRootInt( n )`\n\n`SmallestRootInt` returns the smallest root of the integer n.\n\nThe smallest root of an integer n is the integer r of smallest absolute value for which a positive integer k exists such that n = rk.\n\n``` gap> SmallestRootInt( 2^30 );\n2\ngap> SmallestRootInt( -(2^30) );\n-4 # note that (-2)30 = +(230)\ngap> SmallestRootInt( 279936 );\n6\n7\ngap> SmallestRootInt( 1001 );\n1001 ```\n\n`SmallestRootInt` can be used to identify and decompose powers of primes as is demonstrated in the following example (see IsPrimePowerInt)\n\n``` p := SmallestRootInt( q ); n := LogInt( q, p );\nif not IsPrimeInt(p) then Error(\"GF: <q> must be a primepower\"); fi;```\n\n10.15 Set Functions for Integers\n\nAs already mentioned in the first section of this chapter, `Integers` is the domain of all integers. Thus in principle all set theoretic functions, for example `Intersection`, `Size`, and so on can be applied to this domain. This seems generally of little use.\n\n``` gap> Intersection( Integers, [ 0, 1/2, 1, 3/2 ] );\n[ 0, 1 ]\ngap> Size( Integers );\n\"infinity\" ```\n\n`Random( Integers )`\n\nThis seems to be the only useful domain function that can be applied to the domain `Integers`. It returns pseudo random integers between -10 and 10 distributed according to a binomial distribution.\n\n``` gap> Random( Integers );\n1\ngap> Random( Integers );\n-4 ```\n\nTo generate uniformly distributed integers from a range, use the construct `Random( [ low .. high ] )`.\n\n10.16 Ring Functions for Integers\n\nAs was already noted in the introduction to this chapter the integers form a Euclidean ring, so all ring functions (see chapter Rings) are applicable to the integers. This section comments on the implementation of those functions for the integers and tells you how you can call the corresponding functions directly, for example to save time.\n\n`IsPrime( Integers, n )`\n\nThis is implemented by `IsPrimeInt`, which you can call directly to save a little bit of time (see IsPrimeInt).\n\n`Factors( Integers, n )`\n\nThis is implemented as by `FactorsInt`, which you can call directly to save a little bit of time (see FactorsInt).\n\n`EuclideanDegree( Integers, n )`\n\nThe Euclidean degree of an integer is of course simply the absolute value of the integer. Calling `AbsInt` directly will be a little bit faster.\n\n`EuclideanRemainder( Integers, n, m )`\n\nThis is implemented as `RemInt( n, m )`, which you can use directly to save a lot of time.\n\n`EuclideanQuotient( Integers, n, m )`\n\nThis is implemented as `QuoInt( n, m )`, which you can use directly to save a lot of time.\n\n`QuotientRemainder( Integers, n, m )`\n\nThis is implemented as `[ QuoInt(n,m), RemInt(n,m) ]`, which you can use directly to save a lot of time.\n\n`QuotientMod( Integers, n1, n2, m )`\n\nThis is implemented as `(n1 / n2) mod m`, which you can use directly to save a lot of time.\n\n`PowerMod( Integers, n, e, m )`\n\nThis is implemented by `PowerModInt`, which you can call directly to save a little bit of time. Note that using `n ^ e mod m` will generally be slower, because it can not reduce intermediate results like `PowerMod`.\n\n`Gcd( Integers, n1, n2.. )`\n\nThis is implemented by `GcdInt`, which you can call directly to save a lot of time. Note that `GcdInt` takes only two arguments, not several as `Gcd` does.\n\n`Gcdex( n1, n2 )`\n\n`Gcdex` returns a record. The component `gcd` is the gcd of n1 and n2.\n\nThe components `coeff1` and `coeff2` are integer cofactors such that\n`g.gcd = g.coeff1*n1 + g.coeff2*n2`.\nIf n1 and n2 both are nonzero, `AbsInt( g.coeff1 )` is less than or equal to `AbsInt(n2) / (2*g.gcd)` and `AbsInt( g.coeff2 )` is less than or equal to `AbsInt(n1) / (2*g.gcd)`.\n\nThe components `coeff3` and `coeff4` are integer cofactors such that\n`0 = g.coeff3*n1 + g.coeff4*n2`.\nIf n1 or n2 or are both nonzero `coeff3` is `-n2 / g.gcd` and `coeff4` is `n1 / g.gcd`.\n\nThe coefficients always form a unimodular matrix, i.e., the determinant\n`g.coeff1*g.coeff4 - g.coeff3*g.coeff2`\nis 1 or -1.\n\n``` gap> Gcdex( 123, 66 );\nrec(\ngcd := 3,\ncoeff1 := 7,\ncoeff2 := -13,\ncoeff3 := -22,\ncoeff4 := 41 )\n# 3 = 7*123 - 13*66, 0 = -22*123 + 41*66\ngap> Gcdex( 0, -3 );\nrec(\ngcd := 3,\ncoeff1 := 0,\ncoeff2 := -1,\ncoeff3 := 1,\ncoeff4 := 0 )\ngap> Gcdex( 0, 0 );\nrec(\ngcd := 0,\ncoeff1 := 1,\ncoeff2 := 0,\ncoeff3 := 0,\ncoeff4 := 1 ) ```\n\n`Lcm( Integers, n1, n2.. )`\n\nThis is implemented as `LcmInt`, which you can call directly to save a little bit of time. Note that `LcmInt` takes only two arguments, not several as `Lcm` does.\n\n10.17 Primes\n\n`Primes[ n ]`\n\n`Primes` is a set, i.e., a sorted list, of the 168 primes less than 1000.\n\n`Primes` is used in `IsPrimeInt` (see IsPrimeInt) and `FactorsInt` (see FactorsInt) to cast out small prime divisors quickly.\n\n``` gap> Primes;\n2\ngap> Primes;\n541 ```\n\n10.18 IsPrimeInt\n\n`IsPrimeInt( n )`\n\n`IsPrimeInt` returns `false` if it can prove that n is composite and `true` otherwise. By convention `IsPrimeInt(0) = IsPrimeInt(1) = false` and we define `IsPrimeInt( -n ) = IsPrimeInt( n )`.\n\n`IsPrimeInt` will return `true` for all prime n. `IsPrimeInt` will return `false` for all composite n < 1013 and for all composite n that have a factor p < 1000. So for integers n < 1013, `IsPrimeInt` is a proper primality test. It is conceivable that `IsPrimeInt` may return `true` for some composite n > 1013, but no such n is currently known. So for integers n > 1013, `IsPrimeInt` is a probable-primality test. If composites that fool `IsPrimeInt` do exist, they would be extremly rare, and finding one by pure chance is less likely than finding a bug in GAP3.\n\n`IsPrimeInt` is a deterministic algorithm, i.e., the computations involve no random numbers, and repeated calls will always return the same result. `IsPrimeInt` first does trial divisions by the primes less than 1000. Then it tests that n is a strong pseudoprime w.r.t. the base 2. Finally it tests whether n is a Lucas pseudoprime w.r.t. the smallest quadratic nonresidue of n. A better description can be found in the comment in the library file `integer.g`.\n\nThe time taken by `IsPrimeInt` is approximately proportional to the third power of the number of digits of n. Testing numbers with several hundreds digits is quite feasible.\n\n``` gap> IsPrimeInt( 2^31 - 1 );\ntrue\ngap> IsPrimeInt( 10^42 + 1 );\nfalse ```\n\n10.19 IsPrimePowerInt\n\n`IsPrimePowerInt( n )`\n\n`IsPrimePowerInt` returns `true` if the integer n is a prime power and `false` otherwise.\n\nn is a prime power if there exists a prime p and a positive integer i such that pi = n. If n is negative the condition is that there must exist a negative prime p and an odd positive integer i such that pi = n. 1 and -1 are not prime powers.\n\nNote that `IsPrimePowerInt` uses `SmallestRootInt` (see SmallestRootInt) and a probable-primality test (see IsPrimeInt).\n\n``` gap> IsPrimePowerInt( 31^5 );\ntrue\ngap> IsPrimePowerInt( 2^31-1 );\ntrue # 231-1 is actually a prime\ngap> IsPrimePowerInt( 2^63-1 );\nfalse\ngap> Filtered( [-10..10], IsPrimePowerInt );\n[ -8, -7, -5, -3, -2, 2, 3, 4, 5, 7, 8, 9 ] ```\n\n10.20 NextPrimeInt\n\n`NextPrimeInt( n )`\n\n`NextPrimeInt` returns the smallest prime which is strictly larger than the integer n.\n\nNote that `NextPrimeInt` uses a probable-primality test (see IsPrimeInt).\n\n``` gap> NextPrimeInt( 541 );\n547\ngap> NextPrimeInt( -1 );\n2 ```\n\n10.21 PrevPrimeInt\n\n`PrevPrimeInt( n )`\n\n`PrevPrimeInt` returns the largest prime which is strictly smaller than the integer n.\n\nNote that `PrevPrimeInt` uses a probable-primality test (see IsPrimeInt).\n\n``` gap> PrevPrimeInt( 541 );\n523\ngap> PrevPrimeInt( 1 );\n-2 ```\n\n10.22 FactorsInt\n\n`FactorsInt( n )`\n\n`FactorsInt` returns a list of the prime factors of the integer n. If the ith power of a prime divides n this prime appears i times. The list is sorted, that is the smallest prime factors come first. The first element has the same sign as n, the others are positive. For any integer n it holds that `Product( FactorsInt( n ) ) = n`.\n\nNote that `FactorsInt` uses a probable-primality test (see IsPrimeInt). Thus `FactorsInt` might return a list which contains composite integers.\n\nThe time taken by `FactorsInt` is approximately proportional to the square root of the second largest prime factor of n, which is the last one that `FactorsInt` has to find, since the largest factor is simply what remains when all others have been removed. Thus the time is roughly bounded by the fourth root of n. `FactorsInt` is guaranteed to find all factors less than 106 and will find most factors less than 1010. If n contains multiple factors larger than that `FactorsInt` may not be able to factor n and will then signal an error.\n\n``` gap> FactorsInt( -Factorial(6) );\n[ -2, 2, 2, 2, 3, 3, 5 ]\ngap> Set( FactorsInt( Factorial(13)/11 ) );\n[ 2, 3, 5, 7, 13 ]\ngap> FactorsInt( 2^63 - 1 );\n[ 7, 7, 73, 127, 337, 92737, 649657 ]\ngap> FactorsInt( 10^42 + 1 );\n[ 29, 101, 281, 9901, 226549, 121499449, 4458192223320340849 ] ```\n\n10.23 DivisorsInt\n\n`DivisorsInt( n )`\n\n`DivisorsInt` returns a list of all positive divisors of the integer n. The list is sorted, so it starts with 1 and ends with n. We define `DivisorsInt( -n ) = DivisorsInt( n )`. Since the set of divisors of 0 is infinite calling `DivisorsInt( 0 )` causes an error.\n\n`DivisorsInt` calls `FactorsInt` (see FactorsInt) to obtain the prime factors. `Sigma` (see Sigma) computes the sum, `Tau` (see Tau) the number of positive divisors.\n\n``` gap> DivisorsInt( 1 );\n[ 1 ]\ngap> DivisorsInt( 20 );\n[ 1, 2, 4, 5, 10, 20 ]\ngap> DivisorsInt( 541 );\n[ 1, 541 ] ```\n\n10.24 Sigma\n\n`Sigma( n )`\n\n`Sigma` returns the sum of the positive divisors (see DivisorsInt) of the integer n.\n\n`Sigma` is a multiplicative arithmetic function, i.e., if n and m are relatively prime we have σ(n m) = σ(n) σ(m). Together with the formula σ(pe) = (pe+1-1) / (p-1) this allows you to compute σ(n).\n\nIntegers n for which σ(n)=2 n are called perfect. Even perfect integers are exactly of the form 2n-1(2n-1) where 2n-1 is prime. Primes of the form 2n-1 are called Mersenne primes, the known ones are obtained for n = 2, 3, 5, 7, 13, 17, 19, 31, 61, 89, 107, 127, 521, 607, 1279, 2203, 2281, 3217, 4253, 4423, 9689, 9941, 11213, 19937, 21701, 23209, 44497, 86243, 110503, 132049, 216091, 756839, and 859433. It is not known whether odd perfect integers exist, however BC89 show that any such integer must have at least 300 decimal digits.\n\n`Sigma` usually spends most of its time factoring n (see FactorsInt).\n\n``` gap> Sigma( 0 );\nError, Sigma: <n> must not be 0\ngap> Sigma( 1 );\n1\ngap> Sigma( 1009 );\n1010 # thus 1009 is a prime\ngap> Sigma( 8128 ) = 2*8128;\ntrue # thus 8128 is a perfect number ```\n\n10.25 Tau\n\n`Tau( n )`\n\n`Tau` returns the number of the positive divisors (see DivisorsInt) of the integer n.\n\n`Tau` is a multiplicative arithmetic function, i.e., if n and m are relatively prime we have τ(n m) = τ(n) τ(m). Together with the formula τ(pe) = e+1 this allows us to compute τ(n).\n\n`Tau` usually spends most of its time factoring n (see FactorsInt).\n\n``` gap> Tau( 0 );\nError, Tau: <n> must not be 0\ngap> Tau( 1 );\n1\ngap> Tau( 1013 );\n2 # thus 1013 is a prime\ngap> Tau( 8128 );\n14\ngap> Tau( 36 );\n9 # τ(n) is odd if and only if n is a perfect square ```\n\n10.26 MoebiusMu\n\n`MoebiusMu( n )`\n\n`MoebiusMu` computes the value of the Moebius function for the integer n. This is 0 for integers which are not squarefree, i.e., which are divisible by a square r2. Otherwise it is 1 if n has an even number and -1 if n has an odd number of prime factors.\n\nThe importance of μ stems from the so called inversion formula. Suppose f(n) is a function defined on the positive integers and let g(n)=∑d | nf(d). Then f(n)=∑d | nμ(d) g(n/d). As a special case we have φ(n) = ∑d | nμ(d) n/d since n = ∑d | nφ(d) (see Phi).\n\n`MoebiusMu` usually spends all of its time factoring n (see FactorsInt).\n\n``` gap> MoebiusMu( 60 );\n0\ngap> MoebiusMu( 61 );\n-1\ngap> MoebiusMu( 62 );\n1 ```\n\ngap3-jm\n11 Mar 2019" ]
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https://www.colorhexa.com/157e7a
[ "# #157e7a Color Information\n\nIn a RGB color space, hex #157e7a is composed of 8.2% red, 49.4% green and 47.8% blue. Whereas in a CMYK color space, it is composed of 83.3% cyan, 0% magenta, 3.2% yellow and 50.6% black. It has a hue angle of 177.7 degrees, a saturation of 71.4% and a lightness of 28.8%. #157e7a color hex could be obtained by blending #2afcf4 with #000000. Closest websafe color is: #006666.\n\n• R 8\n• G 49\n• B 48\nRGB color chart\n• C 83\n• M 0\n• Y 3\n• K 51\nCMYK color chart\n\n#157e7a color description : Dark cyan.\n\n# #157e7a Color Conversion\n\nThe hexadecimal color #157e7a has RGB values of R:21, G:126, B:122 and CMYK values of C:0.83, M:0, Y:0.03, K:0.51. Its decimal value is 1408634.\n\nHex triplet RGB Decimal 157e7a `#157e7a` 21, 126, 122 `rgb(21,126,122)` 8.2, 49.4, 47.8 `rgb(8.2%,49.4%,47.8%)` 83, 0, 3, 51 177.7°, 71.4, 28.8 `hsl(177.7,71.4%,28.8%)` 177.7°, 83.3, 49.4 006666 `#006666`\nCIE-LAB 47.605, -28.432, -5.888 11.282, 16.485, 20.999 0.231, 0.338, 16.485 47.605, 29.036, 191.699 47.605, -35.584, -4.291 40.602, -21.455, -2.242 00010101, 01111110, 01111010\n\n# Color Schemes with #157e7a\n\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #7e1519\n``#7e1519` `rgb(126,21,25)``\nComplementary Color\n• #157e46\n``#157e46` `rgb(21,126,70)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #154e7e\n``#154e7e` `rgb(21,78,126)``\nAnalogous Color\n• #7e4615\n``#7e4615` `rgb(126,70,21)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #7e154e\n``#7e154e` `rgb(126,21,78)``\nSplit Complementary Color\n• #7e7a15\n``#7e7a15` `rgb(126,122,21)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #7a157e\n``#7a157e` `rgb(122,21,126)``\n• #197e15\n``#197e15` `rgb(25,126,21)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #7a157e\n``#7a157e` `rgb(122,21,126)``\n• #7e1519\n``#7e1519` `rgb(126,21,25)``\n• #0a3c3b\n``#0a3c3b` `rgb(10,60,59)``\n• #0e5250\n``#0e5250` `rgb(14,82,80)``\n• #116865\n``#116865` `rgb(17,104,101)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #19948f\n``#19948f` `rgb(25,148,143)``\n• #1caaa4\n``#1caaa4` `rgb(28,170,164)``\n• #20c0b9\n``#20c0b9` `rgb(32,192,185)``\nMonochromatic Color\n\n# Alternatives to #157e7a\n\nBelow, you can see some colors close to #157e7a. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #157e60\n``#157e60` `rgb(21,126,96)``\n• #157e69\n``#157e69` `rgb(21,126,105)``\n• #157e71\n``#157e71` `rgb(21,126,113)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #15797e\n``#15797e` `rgb(21,121,126)``\n• #15717e\n``#15717e` `rgb(21,113,126)``\n• #15687e\n``#15687e` `rgb(21,104,126)``\nSimilar Colors\n\n# #157e7a Preview\n\nThis text has a font color of #157e7a.\n\n``<span style=\"color:#157e7a;\">Text here</span>``\n#157e7a background color\n\nThis paragraph has a background color of #157e7a.\n\n``<p style=\"background-color:#157e7a;\">Content here</p>``\n#157e7a border color\n\nThis element has a border color of #157e7a.\n\n``<div style=\"border:1px solid #157e7a;\">Content here</div>``\nCSS codes\n``.text {color:#157e7a;}``\n``.background {background-color:#157e7a;}``\n``.border {border:1px solid #157e7a;}``\n\n# Shades and Tints of #157e7a\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #010808 is the darkest color, while #f6fefd is the lightest one.\n\n• #010808\n``#010808` `rgb(1,8,8)``\n• #041918\n``#041918` `rgb(4,25,24)``\n• #072a29\n``#072a29` `rgb(7,42,41)``\n• #0a3b39\n``#0a3b39` `rgb(10,59,57)``\n• #0d4c49\n``#0d4c49` `rgb(13,76,73)``\n• #0f5c59\n``#0f5c59` `rgb(15,92,89)``\n• #126d6a\n``#126d6a` `rgb(18,109,106)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #188f8a\n``#188f8a` `rgb(24,143,138)``\n• #1ba09b\n``#1ba09b` `rgb(27,160,155)``\n• #1db0ab\n``#1db0ab` `rgb(29,176,171)``\n• #20c1bb\n``#20c1bb` `rgb(32,193,187)``\n• #23d2cb\n``#23d2cb` `rgb(35,210,203)``\n• #2ddcd5\n``#2ddcd5` `rgb(45,220,213)``\n• #3edfd9\n``#3edfd9` `rgb(62,223,217)``\n• #4ee2dc\n``#4ee2dc` `rgb(78,226,220)``\n• #5fe4df\n``#5fe4df` `rgb(95,228,223)``\n• #70e7e3\n``#70e7e3` `rgb(112,231,227)``\n• #81eae6\n``#81eae6` `rgb(129,234,230)``\n• #92ede9\n``#92ede9` `rgb(146,237,233)``\n• #a2f0ed\n``#a2f0ed` `rgb(162,240,237)``\n• #b3f2f0\n``#b3f2f0` `rgb(179,242,240)``\n• #c4f5f3\n``#c4f5f3` `rgb(196,245,243)``\n• #d5f8f7\n``#d5f8f7` `rgb(213,248,247)``\n• #e6fbfa\n``#e6fbfa` `rgb(230,251,250)``\n• #f6fefd\n``#f6fefd` `rgb(246,254,253)``\nTint Color Variation\n\n# Tones of #157e7a\n\nA tone is produced by adding gray to any pure hue. In this case, #484b4b is the less saturated color, while #048f8a is the most saturated one.\n\n• #484b4b\n``#484b4b` `rgb(72,75,75)``\n• #425150\n``#425150` `rgb(66,81,80)``\n• #3d5655\n``#3d5655` `rgb(61,86,85)``\n• #375c5b\n``#375c5b` `rgb(55,92,91)``\n• #316260\n``#316260` `rgb(49,98,96)``\n• #2c6765\n``#2c6765` `rgb(44,103,101)``\n• #266d6a\n``#266d6a` `rgb(38,109,106)``\n• #207370\n``#207370` `rgb(32,115,112)``\n• #1b7875\n``#1b7875` `rgb(27,120,117)``\n• #157e7a\n``#157e7a` `rgb(21,126,122)``\n• #0f847f\n``#0f847f` `rgb(15,132,127)``\n• #0a8984\n``#0a8984` `rgb(10,137,132)``\n• #048f8a\n``#048f8a` `rgb(4,143,138)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #157e7a is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
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https://m.scirp.org/papers/47456
[ "Kinematics of a 2D Asymmetric Nonlinear Oscillator\nAuthor(s) Haiduke Sarafian*\nABSTRACT\n\nMotion of a point-like massive particle under the influence of two nonidentical linear springs conducive to an irregular planar oscillation is analyzed. For a two dimensional oscillations the equation of motion is a coupled highly nonlinear differential equation. The set of equations cannot be solved analytically. Utilizing a Computer Algebra System (CAS) such as Mathematica we solve the equations numerically. Kinematics of the particle is presented. For a comprehensive visual understanding the oscillations are simulated. We also include an extended atlas of useful two-dimensional time-folded diagrams.\n\nCite this paper\nSarafian, H. (2014) Kinematics of a 2D Asymmetric Nonlinear Oscillator. World Journal of Mechanics, 4, 197-201. doi: 10.4236/wjm.2014.46020.\nReferences\n   (2012) Mathematica, V9.0, a Computational Software Program to Do Scientific Computation. Wolfram Research.\n\n   Sarafian, H. (2013) Linear, Cubic and Quintic Coordinate-Dependent Forces and Kinematic Characteristics of a Spring-Mass System. World Journal of Mechanics, 3, 265-269.\nhttp://dx.doi.org/10.4236/wjm.2013.36027\n\n   Sarafian, H. (2011) Nonlinear Oscillations of a Magneto Static Spring-Mass. Journal of Electromagnetic Analysis and Applications, 3, 133-139.\nhttp://dx.doi.org/10.4236/jemaa.2011.35022\n\nTop" ]
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https://www.sciforums.com/threads/luminiferous-aether-exists.114230/
[ "# Luminiferous Aether Exists!\n\nDiscussion in 'Pseudoscience Archive' started by Mazulu, Jun 19, 2012.\n\n1. The luminiferous aether is a medium that propagates light (through a vacuum). The carrier for electromagnetism is the virtual photon. A virtual photon is a photon that only exists for a short time because it doesn't have enough energy. If you add energy, then virtual photons become real photons.\n\nThe scientific community claims that the aether does not exist. Can someone explain to me why virtual photons, which fill the vacuum of space everywhere in the universe, are not the luminiferous aether?\n\n3. The luminiferous aether was an 18th century construct, which was fixed in space. It did not interact with matter and did not move, though matter moved through it.\n\nThe virtual particles of QM are dynamic. They move and do interact with matter. It is difficult to characterize them as the medium for the propagation of light. They are a form of EM radiation, jus as light itself is.\n\nThe Dynamical Casimir Effect is a case where virtual photons become \"real\" photons. However, I am unsure that this has been conclusively experimentally demonstrated. I have not followed the peer review of the one case I have read about.\n\nThere are some aspects of both GR and QM that seem to be similar to an ether, but they are nothing like the luminiferous aerther... And there is so much misinformation and so many fringe ideas involving the ether, that the word itself has come to be a problem. It remains so closely defined by the past and characteristics that are inconsistent with modern experience, that it is of little real use in a serious discussion.\n\nPart of the continuing problem is that where lay oriented discussions are concerned, there is no good alternative and the mathematics and technical descriptions are of little use in lay discussions.\n\nAnyway, the luminiferous aether, as commonly defined is not consistent with experience. It is therefor of no use in discussions and descriptions of the world as we have come to understand it.\n\n5. I didn't expect to find such a well articulated rebuttal. Finally, this allows us to get down to the heart of the issue.\n\nIf the words luminiferous aether are too charged with magical connotations and misinformation, then let's chuck it. But we still need a medium for light propagation plus other things. I've already raised a concern that cosmologists observe a very finely tuned universe. That doesn't happen by accident. Time and distance have to be calibrated, and I have an idea how nature does that.\n\nThen, there is the issue of permitivity and permeability of free space. Anywhere and everywhere in the universe, $c^2\\epsilon_0\\mu_0 = 1$. Even when there aren't any photons around, permitivity and permeability are exactly related to the speed of light.\n\nNext, there is the invariance of the speed of light. Einstein set down two postulates for SR. The second one is,\n\nBut nobody can explain how nature accomplishes this. They only say that they observe it, it's an Einstein postulate, and nobody questions it.\n\nGotta go, be back later.\n\n7. I've been telling you that nature needs a medium to calibrate distance and time. Nature constructs her own inertial and accelerating reference frames out of waves: fully energized waves, virtual photon waves, and non energized waves. Along the x-direction, from x = x_a = 0 m to x = x_b = 300meters, nature uses the full frequency bandwidth of electromagnetic radiation of waves going in the -x and the +x directions; this results in an infinite number of standing waves. Let me illustrate with $c = \\lambda*f$.\n\n1KHz has a cycle wavelength of 300 Km. There is one thousanth of a cycle or 0.36 degrees of a 1KHz standing wave.\n\n1MHz has a cycle wavelength of 300 meters. There is one cycle, 360 degrees of a 1 MHz standing wave.\n\n1GHz has a wavelength of 0.3 meters. There are 100 1GHz cycles, 36000 degrees of 1GHz standing waves in a 300 meter distance.\n\n1THz has wavelengths of 300 microns. There are 10^5 1THz cycles, 36,000,000 degrees of 1THz standing waves in a 300 meter distance.\n\nThese four waves are binded together to become one line of vacuum, 300 meters long in one of nature's inertial reference frames. Virtual photons can form temporarily at any of these frequencies by using available background energy. Or, if you emit radiation at one of these frequencies, it will transmit along the x-axis at the speed of light.\n\nYou should be complaining that I am using waves with no energy in them. But I need those empty energy waveforms to calibrate distance. I only described four frequencies, but there are an infinite set, from 0.1Hz to 10^27Hz, that calibrate distance using their cycles/degrees.\n\n8. If a line 300 meters long is made up of the full electromagnetic bandwidth, measured out by the radians/cycles/degrees of one frequency, then the next, then next, then you get an idea of how nature constructs a line of vacuum. But inertial reference frame should be in three dimensions. Calculating how nature constructs a 3D vacuum box using waves from every frequency in the spectrum is beyond me. But at every point in this inertial frame, there is a full range of frequencies, emitting outwards sphereically and going inwards spherically.\n\nReference frames are really meant for particles with mass. So what happens if we put a single electron in this 300x300x300 box of empty space? It gets difficult; the electron, at whatever position it is in the box, it should be treated as if it has a spectral signature. The electron is considered to have established relationships with each frequency in the frequency spectrum of that inertial reference frame. When the electron is somehow transitioned to another reference frame, there is a frequency shift of the electrons signature.\n\nSomehow, velocity information is part of the electrons frequency spectrum, but I haven't figured how to convert velocity (kinetic energy) information of the electron into spectral information.\n\n9. ### Crunchy CatF-in' *meow* baby!!!Valued Senior Member\n\nMessages:\n8,423\nDo you have evidence that it exists, let alone propagates photons?\n\nCorrect.\n\nInaccurate. A virtual photon pair is literally a temporary fluctuation in an EM field. The energy sum of the pair is zero and they simply come together and cancel (i.e. the fluctuation is over).\n\nCorrect.\n\nIt's more than a claim. Reality disagrees with the assertion \"aether exists\".\n\nBeause they are EM field fluctuations? That's a rather silly question.\n\n10. Above, I explained how nature calibrates distances through space by binding together the wavelengths of the full electromagnetic spectrum. This is how nature creates an inertial reference frame.\n\nNow I will describe how nature creates an accelerating frame, in the x-direction. For a time dilation, from point A x_a = 0m to point B at x=x_b = 300 meters, there are an infinite set of frequencies, from 0.1Hz to 10^27Hz, each of which measures that distance using cycles of its wavelength. When there is a time dilation of $t_a/t_b = 2$, then every frequency in the spectrum will frequency shifts $\\frac{f_b}{f_a}=2$.\n\nHo hum, you expected that anyway. Time dilation causes frequency shift. Except for how I defined how nature creates inertial and accelerating frames of reference. Nature uses every frequency in the spectrum, whether it has energy or not. Of course all frequencies have noise. But in this model, time dilation is the effect, not the cause.\n\n11. ### AlexGLike nailing Jello to a treeValued Senior Member\n\nMessages:\n4,304\nDid God tell you that, or was it the aliens? Because I find it difficult to impossible to accept your 'telling us' as any kind of valid statement.\n\n12. ### Gerhard KemmererBannedBanned\n\nMessages:\n649\nThe answer is the nature or definition of the aether. Most concepts of it are a variation or reflection of known physics/mechanics, which concepts I do not agree with.\nBut it would have the capability to carry any type of virtual particles, including those elements that live on the edge, so to speak, appearing and disappearing from detection.\n\n13. ### Gerhard KemmererBannedBanned\n\nMessages:\n649\nThis concept is interesting.\n\n14. Look at the second postulate of special relativity.\nWhy is the speed of light the same for all observers? If any physicists or physics student dares to try to answer this question, they usually point to the physics model of relativity, and mumble something about about how we observe this to be true. But nobody seems to understand how nature accomplishes such a clever trick. Why is the speed of light the same for all inertial observers?\n\nHere is the answer. There really is a medium. This medium is made out of waves. These waves are moving at the speed of light. These waves measure all distances with their wavelengths. There is one wavelength for each frequency in the frequency spectrum: $v = \\lambda f.$ Distance is measured with wavelengths from each of 10^27 separate frequencies from within the electromagnetic frequency band. Each inertial reference frame is made out of standing waves. There are more than 10^27 frequencies, each with its own wavelength, that measures distance in the inertial frame. Likewise, there are 10^27 clocks that measure time within each inertial frame. These waves are often mistaken for some kind of electromagnetic field that will go away if there is no energy at a given frequency. But these waves don't go away, even when there is no energy at any frequency. These waves calibrate distances from one end of the universe to the other, or as small as the quantum scale. These waves uphold the properties of the space-time continuum model. These waves also provide the vacuum values of permittivity and permeability of free space. When these waves are energized, we see see photons of light travel away at the speed of light. Remember: for any particular reference frame, all 10^27 waves are binded together in such a way that all waves move as a group.\n\nInertial reference frames are tethered together with accelerated frames. Scientists have the mistaken belief that time dilation causes frequency shift. But the reverse is actually true. Accelerated frames have 10^27 waves, each of which frequency shifts by the same amount; e.g. f to 2f, for each frequency. The net effect looks like time dilation and length contraction in the accelerated frame.\n\nThe existence of a medium made of waves traveling at the speed of light is the only way to ensure that the speed of light is invariant for all reference frames. It is these waves that perform all of nature's length and time measurements.\n\n15. First inertia is related to objects having mass. Not so much to EM radiation including light. Though there is some connection.\n\nThe constancy of the speed of light, in vacuum, is a locally observed fact.\n\nAccepting the obseverved constancy of the speed of light, there have been attempts to explain inertia. There are many papers out there. Following is just the first one handy for reference, Inertia as reaction of the vacuum to accelerated motion.\n\nApproaches along the lines described in the above paper may lead to an explanation of why massive objects and particles have inertia. They don't, at least, directly explain anything about why photons are limited to $c$. That remains for now a matter of experimental and observational fact.\n\nBTW The whole concept of an ether replaces the idea of space. They become indistinguishable. Massive particles, objects, photons and virtual particles all exist within or in space. They are not theirselves space as we currently understand it. Inertia seems to be emergent from an interaction between things that exist in space, not a characteristic of space itself.\n\nAs I mentioned earlier, there are some similarities between aspects of both GR and QM and a relativistic ether, but there does not at present seem to be any proof that those similarities represent a description of space, rather than some characteristic of something, that exists in space.\n\n16. So every inertial frame has its own unique set of wave frequencies. This set of wave frequencies is the frame's foundation, the medium available for\nvirtual photons so that Maxwell's equations phenomena can work; for virtual particles so that others force carriers can exist; and for energized photons so that electromagnetic radiation can exist.\n\nThe invariance of the speed of light c, for all inertial reference frames, is what opens the door to the question: does light perform all of nature's distance and time measurements?\n\nThe answer is: no, not light, but something that looks like light. Something with wavelength that can be used to measure length over huge distances. It has to look like the space-time continuum model for gravity. When it is energized, we see photons of light traveling through it. The only conclusion that really fits is some kind of medium made of waves.\n\nEinstein's second postulate of SR refers to inertial reference frames. So it made sense to describe space as being organized into inertial reference frames. Since time dilation is such a precisely predictable phenomena, then the medium has to interconnect these inertial frames in such a way that the connection upholds the invariance of the speed of light, as well.\n\nTo move from one inertial frame to another, you have to accelerate. You have to pass through an accelerated reference frame that upholds the invariance of c. Nature constructs the inertial reference frame medium from the electromagnetic frequency bandwidth. Time dilation and length contraction are predicted and observed phenomena between inertial frames. It makes sense that an accelerated reference frame is created by the frequency shift of every frequency across the length of the accelerated frame.\n\nIf inertial frames are made of constant frequencies, and accelerated frames are made of frequency shifts, then what will happen if we try to generate a frequency shift? Nobody has modulated a sawtooth wave with an FM transmitter, and broadcasted it into the LIGO Laser Interferometer Gravitational-Wave Observatory. So there is no data to support, or dispute the idea that transmitted frequency shift can generate a gravity field. If the scientific community was willing to pursue the question (does generating a frequency shift produce an acceleration field?), then we might be able to stumble upon a new form of propulsion.\n\n17. By incorporating a medium made of waves, I am in effect describing a ZPE quantum vacuum. Yes, I agree with the article that massive particles interact with the ZPE inertially. The best way I can describe it right now is that every quark and lepton has a frequency signature. When the particle is moved to another inertial frame, the particle's frequency signature has to frequency shift to it's new and proper frequency signature in the new frame.\n\nThe exact nature of how a particle is connected to the vacuum is being researched. But I just want to emphasize that inertial frames are made of waves, and that the quarks and leptons in those frames are, in some way, excitations of the inertial frames waves. The quantum vacuum of space, for a given inertial frame, is made of waves; particles are an excitation of these waves.\n\nLast edited: Jun 20, 2012\n18. The speed of light is invariant for all reference frames. How does nature do that without a medium? No, it's not magic.\nDo you believe that the laws of nature are sacred? That we should not try to figure out how nature implements them?\n\nBy the way, Crunchy Cat is a cool name.\n\n19. ### AlexGLike nailing Jello to a treeValued Senior Member\n\nMessages:\n4,304\nLight does not need a medium to propagate.\n\nBut then, you've been told that dozens of times, but it makes no difference.:wallbang:\n\n20. ### Crunchy CatF-in' *meow* baby!!!Valued Senior Member\n\nMessages:\n8,423\nI can't answer the question because I don't think the speed of light is invariant for all reference frames. If you take a photon and send it through a rotating fiber ring, it will take longer for the photon to travel through the whole ring in the direction of the rotation than in the opposite direction. Weird huh?\n\nThis seems like an unrelated question. The answer is \"no\". The concept of sacred is subjective and not valuable to me.\n\n*should*, *should not*, this is all subjective and not very relevant.\n\n:3\n\n21. Does gravity need a medium to propagate?\n\n22. OK, I'm trying to give you guys a reasonable explanation for how the laws of physics are implemented. I'm trying to create a medium out of waves. But you don't want to play along, so fine.\n\nThe laws of physics were spoken into existence by the Creator, by God. The laws of physics are implemented by magic. Are you happy now?\n\n23. Not only does nature employ a medium, but it uses that medium to measure distance and time. Nature measures distance and time by using the full electromagnetic frequency bandwidth. Every frequency has a corresponding wavelength. The speed of light, $c=\\lambda f$ is invariant for all reference frames. Nature does this by measuring every distance and every segment of time using the speed of light. The medium is a built in support system for light. If this were not true, if there was no metric measuring medium, then why would Keppler's Laws be true?\n\nIf there is no medium, then there is only one alternative explanation: God did it!" ]
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http://num.bubble.ro/d/18007/
[ "# Division table for N = 18007 / 0÷1\n\n18007 / 0 = inf [+]\n18007 / 0.01 = 1800700 [+]\n18007 / 0.02 = 900350 [+]\n18007 / 0.03 = 600233.3333 [+]\n18007 / 0.04 = 450175 [+]\n18007 / 0.05 = 360140 [+]\n18007 / 0.06 = 300116.6667 [+]\n18007 / 0.07 = 257242.8571 [+]\n18007 / 0.08 = 225087.5 [+]\n18007 / 0.09 = 200077.7778 [+]\n18007 / 0.1 = 180070 [+]\n18007 / 0.11 = 163700 [+]\n18007 / 0.12 = 150058.3333 [+]\n18007 / 0.13 = 138515.3846 [+]\n18007 / 0.14 = 128621.4286 [+]\n18007 / 0.15 = 120046.6667 [+]\n18007 / 0.16 = 112543.75 [+]\n18007 / 0.17 = 105923.5294 [+]\n18007 / 0.18 = 100038.8889 [+]\n18007 / 0.19 = 94773.6842 [+]\n18007 / 0.2 = 90035 [+]\n18007 / 0.21 = 85747.619 [+]\n18007 / 0.22 = 81850 [+]\n18007 / 0.23 = 78291.3043 [+]\n18007 / 0.24 = 75029.1667 [+]\n18007 / 0.25 = 72028 [+]\n18007 / 0.26 = 69257.6923 [+]\n18007 / 0.27 = 66692.5926 [+]\n18007 / 0.28 = 64310.7143 [+]\n18007 / 0.29 = 62093.1034 [+]\n18007 / 0.3 = 60023.3333 [+]\n18007 / 0.31 = 58087.0968 [+]\n18007 / 0.32 = 56271.875 [+]\n18007 / 0.33 = 54566.6667 [+]\n18007 / 0.34 = 52961.7647 [+]\n18007 / 0.35 = 51448.5714 [+]\n18007 / 0.36 = 50019.4444 [+]\n18007 / 0.37 = 48667.5676 [+]\n18007 / 0.38 = 47386.8421 [+]\n18007 / 0.39 = 46171.7949 [+]\n18007 / 0.4 = 45017.5 [+]\n18007 / 0.41 = 43919.5122 [+]\n18007 / 0.42 = 42873.8095 [+]\n18007 / 0.43 = 41876.7442 [+]\n18007 / 0.44 = 40925 [+]\n18007 / 0.45 = 40015.5556 [+]\n18007 / 0.46 = 39145.6522 [+]\n18007 / 0.47 = 38312.766 [+]\n18007 / 0.48 = 37514.5833 [+]\n18007 / 0.49 = 36748.9796 [+]\n18007 / 0.5 = 36014 [+]\n18007 / 0.51 = 35307.8431 [+]\n18007 / 0.52 = 34628.8462 [+]\n18007 / 0.53 = 33975.4717 [+]\n18007 / 0.54 = 33346.2963 [+]\n18007 / 0.55 = 32740 [+]\n18007 / 0.56 = 32155.3571 [+]\n18007 / 0.57 = 31591.2281 [+]\n18007 / 0.58 = 31046.5517 [+]\n18007 / 0.59 = 30520.339 [+]\n18007 / 0.6 = 30011.6667 [+]\n18007 / 0.61 = 29519.6721 [+]\n18007 / 0.62 = 29043.5484 [+]\n18007 / 0.63 = 28582.5397 [+]\n18007 / 0.64 = 28135.9375 [+]\n18007 / 0.65 = 27703.0769 [+]\n18007 / 0.66 = 27283.3333 [+]\n18007 / 0.67 = 26876.1194 [+]\n18007 / 0.68 = 26480.8824 [+]\n18007 / 0.69 = 26097.1014 [+]\n18007 / 0.7 = 25724.2857 [+]\n18007 / 0.71 = 25361.9718 [+]\n18007 / 0.72 = 25009.7222 [+]\n18007 / 0.73 = 24667.1233 [+]\n18007 / 0.74 = 24333.7838 [+]\n18007 / 0.75 = 24009.3333 [+]\n18007 / 0.76 = 23693.4211 [+]\n18007 / 0.77 = 23385.7143 [+]\n18007 / 0.78 = 23085.8974 [+]\n18007 / 0.79 = 22793.6709 [+]\n18007 / 0.8 = 22508.75 [+]\n18007 / 0.81 = 22230.8642 [+]\n18007 / 0.82 = 21959.7561 [+]\n18007 / 0.83 = 21695.1807 [+]\n18007 / 0.84 = 21436.9048 [+]\n18007 / 0.85 = 21184.7059 [+]\n18007 / 0.86 = 20938.3721 [+]\n18007 / 0.87 = 20697.7011 [+]\n18007 / 0.88 = 20462.5 [+]\n18007 / 0.89 = 20232.5843 [+]\n18007 / 0.9 = 20007.7778 [+]\n18007 / 0.91 = 19787.9121 [+]\n18007 / 0.92 = 19572.8261 [+]\n18007 / 0.93 = 19362.3656 [+]\n18007 / 0.94 = 19156.383 [+]\n18007 / 0.95 = 18954.7368 [+]\n18007 / 0.96 = 18757.2917 [+]\n18007 / 0.97 = 18563.9175 [+]\n18007 / 0.98 = 18374.4898 [+]\nNavigation: Home | Addition | Substraction | Multiplication | Division       Tables for 18007: Addition | Substraction | Multiplication | Division\n\nOperand: 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 200 300 400 500 600 700 800 900 1000 2000 3000 4000 5000 6000 7000 8000 9000\n\nDivision for: 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 200 300 400 500 600 700 800 900 1000 2000 3000 4000 5000 6000 7000 8000 9000 18001 18002 18003 18004 18005 18006 18007 18008 18009 19000 20000 21000 22000 23000 24000 25000 26000 27000 28000" ]
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https://www.analystforum.com/t/calculating-portfolio-variance/13081
[ "", null, "# Calculating Portfolio Variance\n\nWhen you are calculating the variance of an equally weighted portfolio of n stocks, you take the variance of the portfolio, and you multiply it by (1- variance/covariance) / 1, and then multiply it by the variance/covariance to get your number. If variance/covariance is beta, why do they use a different symbol in the books? Why isn’t this annotated like beta? Thanks.\n\ncovariance/variance is beta only when covariance is cov with market and variance is market variance\n\nOK, I get it, so when you are calculating portfolio variance, you are looking at each stocks’ variance with the portfolio of stocks, not the market, thus you use a different symbol. Thanks.\n\nyes and calculate average cov and variance can’t remember the formula right now\n\ni totally don’t get what you are describing… only thing i know is: Var_p = 1/n * var_mean + (n - 1) / n * cov_mean.\n\nwhat page number are you seeing this ? is it schweser or cfa? i am working on portfolio management and cannot remember what you are referring. thanks\n\nlxwqh Wrote: ------------------------------------------------------- > i totally don’t get what you are describing… > > only thing i know is: > > Var_p = 1/n * var_mean + (n - 1) / n * cov_mean. Yeah, I believe this is it for an equally weighted portfolio." ]
[ null, "https://analystforum-uploads.s3.dualstack.us-east-1.amazonaws.com/original/2X/8/8e7be8e6512cde25d070f18d332292fb5a3804d9.png", null ]
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https://www.colorhexa.com/381313
[ "# #381313 Color Information\n\nIn a RGB color space, hex #381313 is composed of 22% red, 7.5% green and 7.5% blue. Whereas in a CMYK color space, it is composed of 0% cyan, 66.1% magenta, 66.1% yellow and 78% black. It has a hue angle of 0 degrees, a saturation of 49.3% and a lightness of 14.7%. #381313 color hex could be obtained by blending #702626 with #000000. Closest websafe color is: #330000.\n\n• R 22\n• G 7\n• B 7\nRGB color chart\n• C 0\n• M 66\n• Y 66\n• K 78\nCMYK color chart\n\n#381313 color description : Very dark red.\n\n# #381313 Color Conversion\n\nThe hexadecimal color #381313 has RGB values of R:56, G:19, B:19 and CMYK values of C:0, M:0.66, Y:0.66, K:0.78. Its decimal value is 3674899.\n\nHex triplet RGB Decimal 381313 `#381313` 56, 19, 19 `rgb(56,19,19)` 22, 7.5, 7.5 `rgb(22%,7.5%,7.5%)` 0, 66, 66, 78 0°, 49.3, 14.7 `hsl(0,49.3%,14.7%)` 0°, 66.1, 22 330000 `#330000`\nCIE-LAB 11.646, 18.445, 9.023 1.981, 1.354, 0.773 0.482, 0.33, 1.354 11.646, 20.533, 26.067 11.646, 18.812, 4.058 11.635, 10.037, 4.205 00111000, 00010011, 00010011\n\n# Color Schemes with #381313\n\n• #381313\n``#381313` `rgb(56,19,19)``\n• #133838\n``#133838` `rgb(19,56,56)``\nComplementary Color\n• #381326\n``#381326` `rgb(56,19,38)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #382613\n``#382613` `rgb(56,38,19)``\nAnalogous Color\n• #132638\n``#132638` `rgb(19,38,56)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #133826\n``#133826` `rgb(19,56,38)``\nSplit Complementary Color\n• #131338\n``#131338` `rgb(19,19,56)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #133813\n``#133813` `rgb(19,56,19)``\n• #381338\n``#381338` `rgb(56,19,56)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #133813\n``#133813` `rgb(19,56,19)``\n• #133838\n``#133838` `rgb(19,56,56)``\n• #000000\n``#000000` `rgb(0,0,0)``\n• #120606\n``#120606` `rgb(18,6,6)``\n• #250d0d\n``#250d0d` `rgb(37,13,13)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #4b1919\n``#4b1919` `rgb(75,25,25)``\n• #5e2020\n``#5e2020` `rgb(94,32,32)``\n• #712626\n``#712626` `rgb(113,38,38)``\nMonochromatic Color\n\n# Alternatives to #381313\n\nBelow, you can see some colors close to #381313. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #38131c\n``#38131c` `rgb(56,19,28)``\n• #381319\n``#381319` `rgb(56,19,25)``\n• #381316\n``#381316` `rgb(56,19,22)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #381613\n``#381613` `rgb(56,22,19)``\n• #381913\n``#381913` `rgb(56,25,19)``\n• #381c13\n``#381c13` `rgb(56,28,19)``\nSimilar Colors\n\n# #381313 Preview\n\nThis text has a font color of #381313.\n\n``<span style=\"color:#381313;\">Text here</span>``\n#381313 background color\n\nThis paragraph has a background color of #381313.\n\n``<p style=\"background-color:#381313;\">Content here</p>``\n#381313 border color\n\nThis element has a border color of #381313.\n\n``<div style=\"border:1px solid #381313;\">Content here</div>``\nCSS codes\n``.text {color:#381313;}``\n``.background {background-color:#381313;}``\n``.border {border:1px solid #381313;}``\n\n# Shades and Tints of #381313\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #0c0404 is the darkest color, while #fefcfc is the lightest one.\n\n• #0c0404\n``#0c0404` `rgb(12,4,4)``\n• #1b0909\n``#1b0909` `rgb(27,9,9)``\n• #290e0e\n``#290e0e` `rgb(41,14,14)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #471818\n``#471818` `rgb(71,24,24)``\n• #551d1d\n``#551d1d` `rgb(85,29,29)``\n• #642222\n``#642222` `rgb(100,34,34)``\n• #732727\n``#732727` `rgb(115,39,39)``\n• #812c2c\n``#812c2c` `rgb(129,44,44)``\n• #903131\n``#903131` `rgb(144,49,49)``\n• #9f3636\n``#9f3636` `rgb(159,54,54)``\n``#ad3b3b` `rgb(173,59,59)``\n• #bc4040\n``#bc4040` `rgb(188,64,64)``\n• #c24d4d\n``#c24d4d` `rgb(194,77,77)``\n• #c75b5b\n``#c75b5b` `rgb(199,91,91)``\n• #cc6a6a\n``#cc6a6a` `rgb(204,106,106)``\n• #d17979\n``#d17979` `rgb(209,121,121)``\n• #d68787\n``#d68787` `rgb(214,135,135)``\n• #db9696\n``#db9696` `rgb(219,150,150)``\n• #e0a5a5\n``#e0a5a5` `rgb(224,165,165)``\n• #e5b3b3\n``#e5b3b3` `rgb(229,179,179)``\n• #eac2c2\n``#eac2c2` `rgb(234,194,194)``\n• #efd0d0\n``#efd0d0` `rgb(239,208,208)``\n• #f4dfdf\n``#f4dfdf` `rgb(244,223,223)``\n• #f9eeee\n``#f9eeee` `rgb(249,238,238)``\n• #fefcfc\n``#fefcfc` `rgb(254,252,252)``\nTint Color Variation\n\n# Tones of #381313\n\nA tone is produced by adding gray to any pure hue. In this case, #272424 is the less saturated color, while #490202 is the most saturated one.\n\n• #272424\n``#272424` `rgb(39,36,36)``\n• #2a2121\n``#2a2121` `rgb(42,33,33)``\n• #2c1f1f\n``#2c1f1f` `rgb(44,31,31)``\n• #2f1c1c\n``#2f1c1c` `rgb(47,28,28)``\n• #321919\n``#321919` `rgb(50,25,25)``\n• #351616\n``#351616` `rgb(53,22,22)``\n• #381313\n``#381313` `rgb(56,19,19)``\n• #3b1010\n``#3b1010` `rgb(59,16,16)``\n• #3e0d0d\n``#3e0d0d` `rgb(62,13,13)``\n• #410a0a\n``#410a0a` `rgb(65,10,10)``\n• #440707\n``#440707` `rgb(68,7,7)``\n• #460505\n``#460505` `rgb(70,5,5)``\n• #490202\n``#490202` `rgb(73,2,2)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #381313 is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
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https://cs.stackexchange.com/questions/71434/numbering-of-computable-functions/71484
[ "Numbering of computable functions\n\nIs there a numbering (not Gödel numbering) of all computable functions $U(p, x)$, such that the set of numbers of functions defined in zero is exactly the set of even numbers. More formally: $I = \\{p,\\ |\\ U(p, 0)\\ \\mathrm{defined}\\} = 2\\mathbb{N}$.\n\nMy guess that it's true. But I'm not sure how to prove it.\n\nIdeas:\n\nWe can construct a numbering of all computable functions, defined in zero using the function $F(p, x, t)$ which is equal to $0$ if $U(p, x)$ hasn't finished work in $t$ steps and $1$ in other case. We can do it because set of pairs $(p, t)$ is enumerable.\n\nThen, having this function $V(p, x)$ and some other numbering $U(p, x)$ we can construct numbering\n\n$$U'(p, x) = \\begin{cases} V(\\frac{p}{2}, x)\\ \\ if\\ p \\vdots 2\\\\ U(\\frac{p + 1}{2}, x)\\ \\ if\\ p \\not\\vdots 2 \\end{cases}$$\n\n• Try first constructing such a numbering in which $I = \\mathbb{N}$, and use this numbering to solve your question. Give it a few hours. – Yuval Filmus Mar 12 '17 at 16:14\n• What do you mean by \"not Gödel numbering\"? Any bijection between computable functions and the natural numbers is a Gödel numbering: that's what the term means. – David Richerby Mar 12 '17 at 16:27\n• I meant that this numbering is not the main numbering. (By main numbering i mean such a numbering $U(k, x)$ that for any computable function $V(p, x)$ there exist function $s(p)$ such that $U(s(p), x) = V(p, x)$) – puhsu Mar 12 '17 at 16:35\n• Welcome to Computer Science! You can show such a claim by giving the numbering. What have you tried? Where did you get stuck? We do not want to just hand you the solution; we want you to gain understanding. However, as it is we do not know what your underlying problem is, so we can not begin to help. See here for tips on asking questions about exercise problems. If you are uncertain how to improve your question, why not ask around in Computer Science Chat? – Raphael Mar 12 '17 at 17:52\n• @DavidRicherby Some sources use \"Gödel numbering\" to mean \"admissible numbering\". – Raphael Mar 12 '17 at 17:54" ]
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https://www.clutchprep.com/physics/practice-problems/148545/a-0-160-h-inductor-is-connected-in-series-with-a-85-0-resistor-and-ac-source-the
[ "# Problem: A 0.160 H inductor is connected in series with a 85.0 Ω resistor and ac source. The voltage across the inductor isvL = -(11.0V)sin[473 rad/s)t].Part A. Derive an expression for the voltage vR across the resistorExpress your answer in terms of variables L, R, VL (amplitude of the voltage across the inductor), ω, and t.Part B. What is vR at 2.04 ms?Express your answer with the appropriate units\n\n###### FREE Expert Solution\n\nInductive reactance is expressed as:\n\n$\\overline{){{\\mathbf{X}}}_{{\\mathbf{L}}}{\\mathbf{=}}{\\mathbf{\\omega }}{\\mathbf{L}}}$\n\nCurrent passing through the resistor is:\n\n$\\mathbit{i}\\mathbf{=}\\frac{\\mathbf{V}}{{\\mathbf{X}}_{\\mathbf{L}}}$\n\nBut from the boxed equation, XL = ωL\n\nTherefore,\n\n$\\overline{){\\mathbf{i}}{\\mathbf{=}}\\frac{\\mathbf{V}}{\\mathbf{\\omega }\\mathbf{L}}}$\n\n95% (424 ratings)", null, "###### Problem Details\n\nA 0.160 H inductor is connected in series with a 85.0 Ω resistor and ac source. The voltage across the inductor is\n\nvL = -(11.0V)sin[473 rad/s)t].\n\nPart A. Derive an expression for the voltage vR across the resistor\nExpress your answer in terms of variables L, R, VL (amplitude of the voltage across the inductor), ω, and t.\n\nPart B. What is vR at 2.04 ms?\nExpress your answer with the appropriate units\n\nFrequently Asked Questions\n\nWhat scientific concept do you need to know in order to solve this problem?\n\nOur tutors have indicated that to solve this problem you will need to apply the Inductors in AC Circuits concept. You can view video lessons to learn Inductors in AC Circuits. Or if you need more Inductors in AC Circuits practice, you can also practice Inductors in AC Circuits practice problems." ]
[ null, "https://cdn.clutchprep.com/assets/button-view-text-solution.png", null ]
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https://codereview.stackexchange.com/questions/159565/a-simple-maze-generator-written-in-rust
[ "# A simple maze generator written in Rust\n\nI have been interested in trying Rust in a long time, and I finally got around to sit down and start reading \"The Book\". I have not finished yet, so there are probably a few features that I could have used, but I didn't know about.\n\nAnyway, the purpose of this program is to generate a maze (using the simplest \"Randomized DFS\" algorithm).\n\nSince the main goal for me was to practice the language, I tried to make the program as \"idiomatic\" as possible. The main thing that still bothers me is all those type conversions between the signed and unsigned types. Since this is my first Rust program, I am mainly just looking for feedback on anything that could be considered \"bad code\", or parts that could be improved in any way.\n\nextern crate rand;\nextern crate image;\nuse std::io::Write;\nuse rand::Rng;\n\n#[derive(Clone, PartialEq)]\nenum Cell {\nBlocked,\nFree,\n}\n\nfn make_odd(mut t: (usize, usize)) -> (usize, usize) {\nlet o = |v: &mut usize| if *v%2==0{*v+=1};\no(&mut t.0); o(&mut t.1); t\n}\n\nfn gen(s: (usize, usize)) -> Vec<Vec<Cell>> {\nlet mut t = vec![vec![Cell::Blocked; s.1]; s.0];\nlet mut stack = Vec::<(isize, isize)>::new();\n\nlet c = make_odd((s.0/2, s.1/2));\nstack.push((c.0 as isize, c.1 as isize));\nt[c.0][c.1] = Cell::Free;\n\nlet mut dirs: [(isize, isize); 4] = [(2, 0), (-2, 0), (0, 2), (0, -2)];\n'o: while let Some(&(x, y)) = stack.last() {\nrng.shuffle(&mut dirs);\nfor i in 0..4 {\nlet (dx, dy) = dirs[i];\nlet (nx, ny) = (x+dx, y+dy);\nif nx < 0 || ny < 0 || nx >= (s.0 as isize) || ny >= (s.1 as isize) { continue; }\nif t[nx as usize][ny as usize] != Cell::Free {\nstack.push((nx, ny));\nt[nx as usize][ny as usize] = Cell::Free;\nt[(x+dx/2) as usize][(y+dy/2) as usize] = Cell::Free;\ncontinue 'o;\n}\n}\nstack.pop();\n}\n\nt = Cell::Free;\nt[s.0-1][s.1-2] = Cell::Free;\nt\n}\n\nfn print_usage() -> ! {\nlet _ = writeln!(std::io::stderr(), \"Usage: maze-gen width height [output.png]\");\nstd::process::exit(1);\n}\n\nfn main() {\nlet args: Vec<_> = std::env::args().collect();\nif args.len() < 3 { print_usage(); }\nlet mut nums = [0; 2];\nfor i in 0..2 {\nmatch args[i+1].parse::<usize>() {\nErr(_) => { print_usage(); },\nOk(v) => nums[i] = v,\n}\n}\nlet s0 = (nums, nums);\nlet mut s = make_odd(s0);\nif s.0 < 3 { s.0 = 3; }\nif s.1 < 3 { s.1 = 3; }\nif s != s0 {\nlet _ = writeln!(std::io::stderr(),\n\"Warning: Adjusting sizes to {} and {}!\", s.0, s.1);\n}\nlet m = gen(s);\nlet mut buf = image::ImageBuffer::new(s.0 as u32, s.1 as u32);\nfor (x,y,px) in buf.enumerate_pixels_mut() {\n*px = image::Luma([\nmatch m[x as usize][y as usize] {\nCell::Free => 255,\nCell::Blocked => 0,\n}\n]);\n}\nlet filename = if args.len() >= 4 { args.as_str() } else { \"out.png\" };\nlet ref mut file = std::fs::File::create(&std::path::Path::new(filename)).unwrap();\nimage::ImageLuma8(buf).save(file, image::PNG).unwrap();\n}\n\n\nSample output: (It's quite tiny, you might have to download it and zoom in to see it properly.)", null, "(Sorry for any bad grammar, English is not my native language.)\n\n1. Learn to love rustfmt.\n\n1. Spaces go around operators and after commas\n\n- let c = make_odd((s.0/2, s.1/2));\n+ let c = make_odd((s.0 / 2, s.1 / 2));\n\n- for (x,y,px) in buf.enumerate_pixels_mut() {\n+ for (x, y, px) in buf.enumerate_pixels_mut() {\n\n2. Don't put multiple statements on one line\n\n- o(&mut t.0); o(&mut t.1); t\n+ o(&mut t.0);\n+ o(&mut t.1);\n+ t\n\n2. Make a type for whatever (usize, usize) is. At the very least, create a type alias.\n\n3. Actually, there are three places that want to apply a change to both components of the tuple. Promote the tuple to a type and add a map method.\n\n4. If you have to give your closure arguments types anyway, and there's nothing captured by the closure, just make an inline function.\n\n5. There's no real reason to take mutable reference to increment an integral value.\n\n6. You define stack then immediately push a value on. instead, just use the vec! macro to create it all at once..\n\n7. There's no need to specify the type of dirs\n\n8. Instead of re-coding the number of elements in dir and having to potentially do bounds-checking again, just iterate over dirs directly\n\n9. Characters are free. Use some longer variable names.\n\n10. If you don't need the program name, skip it to avoid remembering it's there and then adding numbers here and there to compensate.\n\n11. There's no need for the turbofish when parsing the maze size.\n\n12. Use unwrap_or_else to handle a failure to parse.\n\n13. Use enumerate to avoid indexing the args slice again.\n\n14. Use std::cmp::max to provide a lower value for the sizes.\n\n15. Don't ignore errors. If writing to stderr is important, use expect.\n\n16. Use Vec::get instead of checking the size and then using the index operator (which checks the size again)\n\n17. You don't need to contruct a Path, just pass in the &str\n\n18. Prefer expect to unwrap.\n\n19. You can use ImageBuffer::from_fn. Note that this removes the need to make your variable mutable.\n\n20. Dont' use ref in let bindings. Using & on the right hand side is more idiomatic. In this case, &mut at call is more idiomatic.\n\n21. To deal with the unsigned / signed transformations, remember that a + (-2) is the same as a - (+2). Add an enum to define the directions, a method to apply those directions to a point, use checked_add / checked_sub in that method to deal with under/overflow, then add your own \"overflow\" check for the size of the maze.\n\nextern crate rand;\nextern crate image;\n\nuse rand::Rng;\nuse std::cmp::max;\nuse std::io::Write;\n\n#[derive(Clone, PartialEq)]\nenum Cell {\nBlocked,\nFree,\n}\n\n#[derive(Debug, Copy, Clone)]\nenum Direction {\nUp,\nDown,\nLeft,\nRight,\n}\n\n#[derive(Debug, Copy, Clone, PartialEq)]\nstruct Point(usize, usize);\n\nimpl Point {\nfn map<F>(self, mut f: F) -> Self\nwhere F: FnMut(usize) -> usize\n{\nPoint(f(self.0), f(self.1))\n}\n\nfn move_by(self, amount: usize, dir: Direction) -> Option<Self> {\nuse Direction::*;\nmatch dir {\nLeft => self.0.checked_sub(amount).map(|x| Point(x, self.1)),\nUp => self.1.checked_sub(amount).map(|y| Point(self.0, y)),\n}\n}\n}\n\nfn next_odd_number(n: usize) -> usize {\nn + if n % 2 == 0 { 1 } else { 0 }\n}\n\nfn generate_maze(size: Point) -> Vec<Vec<Cell>> {\nuse Direction::*;\n\nlet center = size.map(|v| v / 2).map(next_odd_number);\nlet mut stack = vec![Point(center.0, center.1)];\n\nlet mut maze = vec![vec![Cell::Blocked; size.1]; size.0];\nmaze[center.0][center.1] = Cell::Free;\n\nlet mut dirs = [Left, Right, Up, Down];\n\nlet ensure_in_bounds = |z: Point| {\nif z.0 >= size.0 || z.1 >= size.1 {\nNone\n} else {\nSome(z)\n}\n};\n\n'next_odd_number: while let Some(&point) = stack.last() {\nrng.shuffle(&mut dirs);\n\nfor &dir in &dirs {\nlet new_point = match point.move_by(2, dir).and_then(&ensure_in_bounds) {\nSome(new_point) => new_point,\nNone => continue,\n};\n\nif maze[new_point.0][new_point.1] != Cell::Free {\nstack.push(new_point);\nmaze[new_point.0][new_point.1] = Cell::Free;\nlet middle_point = point.move_by(1, dir)\n.expect(\"Middle point cannot be out-of-bounds\");\nmaze[middle_point.0][middle_point.1] = Cell::Free;\ncontinue 'next_odd_number;\n}\n}\nstack.pop();\n}\n\nmaze = Cell::Free;\nmaze[size.0 - 1][size.1 - 2] = Cell::Free;\nmaze\n}\n\nfn print_usage() -> ! {\nwriteln!(std::io::stderr(), \"Usage: maze-gen width height [output.png]\")\n.expect(\"Unable to write to stderr\");\nstd::process::exit(1);\n}\n\nfn main() {\nlet args: Vec<_> = std::env::args().skip(1).collect();\nif args.len() < 2 {\nprint_usage();\n}\n\nlet mut dimensions = [0; 2];\nfor (i, arg) in args.iter().enumerate() {\ndimensions[i] = arg.parse().unwrap_or_else(|_| print_usage());\n}\nlet requested_size = Point(dimensions, dimensions);\nlet valid_size = requested_size.map(next_odd_number).map(|v| max(v, 3));\n\nif valid_size != requested_size {\nwriteln!(std::io::stderr(),\n\"Warning: Adjusting sizes to {} and {}!\",\nvalid_size.0,\nvalid_size.1)\n.expect(\"Unable to write to stderr\");\n}\n\nlet maze = generate_maze(valid_size);\n\nlet buf = image::ImageBuffer::from_fn(valid_size.0 as u32, valid_size.1 as u32, |x, y| {\nlet luma = match maze[x as usize][y as usize] {\nCell::Free => 255,\nCell::Blocked => 0,\n};\nimage::Luma([luma])\n});\nlet filename = args.get(2).map(String::as_str).unwrap_or(\"out.png\");\n\nlet mut file = std::fs::File::create(filename).expect(\"Couldn't open the file\");\nimage::ImageLuma8(buf).save(&mut file, image::PNG).expect(\"Coulding write the file\");\n}\n\n\nI might next look into implementing a flat storage for the maze, one that can be directly indexed by a Point. That would allow this change:\n\n-maze[middle_point.0][middle_point.1] = Cell::Free;\n+maze[middle_point] = Cell::Free;\n\n\nI'll be honest and say that I strongly dislike the usage of the labelled loop. I don't think I've ever needed them, and they are one of the rarest constructs in Rust, based on my experience. I'd probably spend a lot of time (more than I already did...) trying to rewrite that in a different manner." ]
[ null, "https://i.stack.imgur.com/1bGZI.png", null ]
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https://www.thequizlet.com/2021/06/25/calculate-dividend-yield/
[ "# Calculate Dividend Yield\n\n1. Calculate P1 for the common stock of Microsoft Corporation Use the Dividend Growth Model (DGM) Assume Microsoft’s last annual dividend was D0 = \\$129 per share and the company expects the dividend to have a constant growth rate of 122 percent If investors require a return of 15 percent on this stock, determine the future intrinsic value of the company’s stock in one year or P1\n\nA \\$5168\n\nB \\$5413\n\nC \\$5800\n\nD \\$6496\n\nE \\$7850\n\n2 Calculate Dividend Yield for Alpha Beta Corporation The last annual dividend was D0 = \\$124, but is projected to continue growing every year by g = 55% and investors in this stock expect a return of Ri = 900 percent What is the next annual dividend or D1? Also, if the stock’s price right now is P0 = \\$3784 then what is the expected dividend yield for the next year?\n\nA1308; 35%\n\nB1308; 39%\n\nC1380; 43%\n\nD1380; 48%\n\nE1380; 55%\n\n3Calculate Dividend Yield for Alpha Beta Corporation The last annual dividend was D0 = \\$124, but is projected to continue growing every year by g = 55% and investors in this stock expect a return of Ri = 900 percent What is the next annual dividend or D1? Also, if the stock’s price right now is P0 = \\$3784 then what is the expected dividend yield for the next year?\n\nA1308; 35%\n\nB1308; 39%\n\nC1380; 43%\n\nD1380; 48%\n\nE1380; 55%\n\n4Calculate Capital Gains from Price Appreciation If the last dividend of Alpha Beta Corporation was D0 = \\$124, but is projected to continue growing every year by g = 55 percent, and the stock’s price right now is P0 = \\$3784, then what is the stock’s expected price appreciation for the coming year? (HINT: the theory behind the Dividend Discount Model states that this question can be answered without any calculations)\n\nA 47%\n\nB 55%\n\nC 65%\n\nD 70%\n\nE 81%\n\n5Understanding CAPM language, part 1 Assume the common stock of PacWest Bank has a beta of 20; the risk-free return is Rf = 55 percent, and the market return is Rm = 120 percent According to CAPM and the formula for its Security Market Line (SML), the stock is correctly priced for its unique level of risk at an Expected Return of E(Ri)=:\n\nA 195%\n\nB 179%\n\nC 185%\n\nD 75%\n\n## Looking for help with your homework? Grab a 30% Discount and Get your paper done!", null, "30% OFF", null, "Turnitin Report", null, "Formatting", null, "Title Page", null, "Citation\nPlace an Order" ]
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https://www.colorhexa.com/00e603
[ "# #00e603 Color Information\n\nIn a RGB color space, hex #00e603 is composed of 0% red, 90.2% green and 1.2% blue. Whereas in a CMYK color space, it is composed of 100% cyan, 0% magenta, 98.7% yellow and 9.8% black. It has a hue angle of 120.8 degrees, a saturation of 100% and a lightness of 45.1%. #00e603 color hex could be obtained by blending #00ff06 with #00cd00. Closest websafe color is: #00ff00.\n\n• R 0\n• G 90\n• B 1\nRGB color chart\n• C 100\n• M 0\n• Y 99\n• K 10\nCMYK color chart\n\n#00e603 color description : Pure (or mostly pure) lime green.\n\n# #00e603 Color Conversion\n\nThe hexadecimal color #00e603 has RGB values of R:0, G:230, B:3 and CMYK values of C:1, M:0, Y:0.99, K:0.1. Its decimal value is 58883.\n\nHex triplet RGB Decimal 00e603 `#00e603` 0, 230, 3 `rgb(0,230,3)` 0, 90.2, 1.2 `rgb(0%,90.2%,1.2%)` 100, 0, 99, 10 120.8°, 100, 45.1 `hsl(120.8,100%,45.1%)` 120.8°, 100, 90.2 00ff00 `#00ff00`\nCIE-LAB 79.952, -79.665, 76.673 28.312, 56.597, 9.518 0.3, 0.599, 56.597 79.952, 110.568, 136.097 79.952, -75.687, 97.698 75.231, -64.479, 45.16 00000000, 11100110, 00000011\n\n# Color Schemes with #00e603\n\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #e600e3\n``#e600e3` `rgb(230,0,227)``\nComplementary Color\n• #70e600\n``#70e600` `rgb(112,230,0)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #00e676\n``#00e676` `rgb(0,230,118)``\nAnalogous Color\n• #e60070\n``#e60070` `rgb(230,0,112)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #7600e6\n``#7600e6` `rgb(118,0,230)``\nSplit Complementary Color\n• #e60300\n``#e60300` `rgb(230,3,0)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #0300e6\n``#0300e6` `rgb(3,0,230)``\nTriadic Color\n• #e3e600\n``#e3e600` `rgb(227,230,0)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #0300e6\n``#0300e6` `rgb(3,0,230)``\n• #e600e3\n``#e600e3` `rgb(230,0,227)``\nTetradic Color\n• #009a02\n``#009a02` `rgb(0,154,2)``\n• #00b302\n``#00b302` `rgb(0,179,2)``\n• #00cd03\n``#00cd03` `rgb(0,205,3)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #00ff04\n``#00ff04` `rgb(0,255,4)``\n• #1aff1d\n``#1aff1d` `rgb(26,255,29)``\n• #34ff36\n``#34ff36` `rgb(52,255,54)``\nMonochromatic Color\n\n# Alternatives to #00e603\n\nBelow, you can see some colors close to #00e603. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #36e600\n``#36e600` `rgb(54,230,0)``\n• #23e600\n``#23e600` `rgb(35,230,0)``\n• #10e600\n``#10e600` `rgb(16,230,0)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #00e616\n``#00e616` `rgb(0,230,22)``\n• #00e629\n``#00e629` `rgb(0,230,41)``\n• #00e63d\n``#00e63d` `rgb(0,230,61)``\nSimilar Colors\n\n# #00e603 Preview\n\nText with hexadecimal color #00e603\n\nThis text has a font color of #00e603.\n\n``<span style=\"color:#00e603;\">Text here</span>``\n#00e603 background color\n\nThis paragraph has a background color of #00e603.\n\n``<p style=\"background-color:#00e603;\">Content here</p>``\n#00e603 border color\n\nThis element has a border color of #00e603.\n\n``<div style=\"border:1px solid #00e603;\">Content here</div>``\nCSS codes\n``.text {color:#00e603;}``\n``.background {background-color:#00e603;}``\n``.border {border:1px solid #00e603;}``\n\n# Shades and Tints of #00e603\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #000e00 is the darkest color, while #fafffa is the lightest one.\n\n• #000e00\n``#000e00` `rgb(0,14,0)``\n• #002200\n``#002200` `rgb(0,34,0)``\n• #003501\n``#003501` `rgb(0,53,1)``\n• #004901\n``#004901` `rgb(0,73,1)``\n• #005d01\n``#005d01` `rgb(0,93,1)``\n• #007001\n``#007001` `rgb(0,112,1)``\n• #008402\n``#008402` `rgb(0,132,2)``\n• #009802\n``#009802` `rgb(0,152,2)``\n• #00ab02\n``#00ab02` `rgb(0,171,2)``\n• #00bf02\n``#00bf02` `rgb(0,191,2)``\n• #00d203\n``#00d203` `rgb(0,210,3)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\n• #00fa03\n``#00fa03` `rgb(0,250,3)``\nShade Color Variation\n• #0eff11\n``#0eff11` `rgb(14,255,17)``\n• #22ff25\n``#22ff25` `rgb(34,255,37)``\n• #35ff38\n``#35ff38` `rgb(53,255,56)``\n• #49ff4b\n``#49ff4b` `rgb(73,255,75)``\n• #5dff5f\n``#5dff5f` `rgb(93,255,95)``\n• #70ff72\n``#70ff72` `rgb(112,255,114)``\n• #84ff86\n``#84ff86` `rgb(132,255,134)``\n• #98ff99\n``#98ff99` `rgb(152,255,153)``\n• #abffac\n``#abffac` `rgb(171,255,172)``\n• #bfffc0\n``#bfffc0` `rgb(191,255,192)``\n• #d2ffd3\n``#d2ffd3` `rgb(210,255,211)``\n• #e6ffe6\n``#e6ffe6` `rgb(230,255,230)``\n• #fafffa\n``#fafffa` `rgb(250,255,250)``\nTint Color Variation\n\n# Tones of #00e603\n\nA tone is produced by adding gray to any pure hue. In this case, #6a7c6a is the less saturated color, while #00e603 is the most saturated one.\n\n• #6a7c6a\n``#6a7c6a` `rgb(106,124,106)``\n• #618562\n``#618562` `rgb(97,133,98)``\n• #588e59\n``#588e59` `rgb(88,142,89)``\n• #509651\n``#509651` `rgb(80,150,81)``\n• #479f48\n``#479f48` `rgb(71,159,72)``\n• #3ea83f\n``#3ea83f` `rgb(62,168,63)``\n• #35b137\n``#35b137` `rgb(53,177,55)``\n• #2cba2e\n``#2cba2e` `rgb(44,186,46)``\n• #23c325\n``#23c325` `rgb(35,195,37)``\n• #1bcb1d\n``#1bcb1d` `rgb(27,203,29)``\n• #12d414\n``#12d414` `rgb(18,212,20)``\n• #09dd0c\n``#09dd0c` `rgb(9,221,12)``\n• #00e603\n``#00e603` `rgb(0,230,3)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #00e603 is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
[ null ]
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http://placement.freshersworld.com/cdac-question-papers/technical-other/33135370
[ "Centre for Development of Advanced Computing Technical-Other Contributed by Murali Krisnan updated on May 2019\n|   17812\n\nC DAC PAPER ON 15th APRIL AT CHENNAI\n\nHi i have attended CDAC exam of 15th april 2007 and the test comprises of\n1. Aptitude\n2. c/c++\n3. Java\n\naptitude is nothing it will be very easy, jus from R.S Agarvall example\n1.time and work problem\n2.train problem\n3.chain rule problem\n4.ratios\n\nAnd in technical side it will be from c and c++? and im hosting some of the c and c++ question which i know\n1.Find which one of the following is correct?\na) !(p||q) !p || !q\nb) !!!p = !p\nc) p && q  || r  p && ( q || r )\nd)nothing\n\n2. find the output of the following program?\nmain()\n{\nstatic i = 3;\npringf(\"%d\",i--)\nreturn i >0 ? main():0;\n}\nans:\na)333\nb)321\nc)111\nd)error in the code\n\n3.find the output of the following program?\nmain()\n{\ncharp[] = \"%d\\n\";\np = 'c'c;\nprintf(p,65);\n}\nans:\na) 0\nb) a\nc) A\nd) error in the code\n\n4.which will return integer?\na) int*s (  )\nb) ( int* ) s(  )\nb) int ( *s ) (  )\n\n5.find the output of the following program?\nchar*myfunc(char*ptr)\n{\nptr +=3;\nreturn (ptr);\n}\nint main()\n{\nchar*x,*y;\nx=\"HELLO\";\ny=myfunc(x);\nprintf(\"y = %s\\n\",y);\nreturn 0;\n}\nans:\na) HELLO\nb) LLO\nc) LO\nd) L\n\n6.find the output of the following program?\nmain()\n{\nint i = _1_abc(10);\nprintf(\"%d\\n\",--i);\n}\n{\nint_1_abc(int i)\n{\nreturn(++i);\n}\nans:\na)10\nb)11\nc)9\nd)error\n\n7.In order  to force derived class A to redefine a function a fun, void foo( )\nhow should A declare foo( )?\ninline foo()\nvirtual voidfoo( ) = 0\n\n8. which operator cant be overloaded?\nans:\na) &;\nb) [ ] ;\nc) :: ;\nd) all the above;\n\n8.If u allocate it as,\nint *ptr = new int [ 25];\nHow will u deallocate it ?\nans:\na)   delete *pint;\nb)   delete [ ] pint;\nc)   delete pint ;\nd)   all ;\n\n9. which virtual ?\na) constant;\nb) static function;\nc) return;\nd) none;\n\n10. How many times \"hello world\" will be printed?\nvoid fun(int n)\n{\nint i;\nfor (i = 0; i < = n; i ++)\n{\nfun(n-i);\nprintf(\"hello world\");\n}\n}\nans:\na) infinite\nb)zero\nc)one\nd)n times\n\nBEST OF LUCK\n\nBy,\nMurali Krisnan" ]
[ null ]
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https://talesfromafork.com/sightseer/question-what-is-force-of-attraction-in-chemistry.html
[ "# Question: What is force of attraction in chemistry?\n\nContents\n\n## What are the forces of attraction?\n\nThe force of attraction is a force that draws the body close to it due to an attraction. … These are the electric force, magnetic force, electrostatic force, gravitational force, and electromagnetic force. Gravitational force is a well-recognized force that attracts the body towards it despite the distance.\n\n## What is the force of attraction between atoms?\n\nA chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.\n\n## What is the name of attraction force?\n\nGravitational force:\n\nThe gravitational force (F) is a force that attracts any two objects with a mass within a universe. Every object, including you, is pulling on every other object in the entire universe. This is called Newton’s Universal Law of Gravitation. Example of Gravitational force (F):\n\n## What are the types of intermolecular forces of attraction?\n\nThere are three types of intermolecular forces: London dispersion forces (LDF), dipole- dipole interactions, and hydrogen bonding.\n\n## Which has more intermolecular force of attraction?\n\nAnd the involatility of the water molecule, in which hydrogen bonding is MOST effective, is a clear consequence of this. And so I maintain that the strongest intermolecular force of attraction is intermolecular hydrogen bonding .\n\nIT IS INTERESTING:  What has been the role of foreign direct investments in the economic development of developing countries?\n\n## What is the definition of attractive force?\n\nDefinitions of attractive force. the force by which one object attracts another. synonyms: attraction. Antonyms: repulsion, repulsive force. the force by which bodies repel one another.\n\n## Is the force of attraction between two objects?\n\nGravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.\n\n## What’s another word for attractive force?\n\nmagnetism magnetic force magnetic attr… gravity gravitational… gravitational… gravitation attraction attractive…" ]
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http://www.stockinvestingzone.com/albert-einstein-electrons
[ "## Albert Einstein Electrons\n\nThursday, 13. June 2019\n\nDiagram Bohr model Bohr model. Bohr’s model or Bohr-Rutherford is a quantized model of the atom that Bohr proposed in 1913 to explain how electrons can have stable orbits around the nucleus. This planetary model is a functional model that represents the atom (physical object) itself but explains how it works by means of equations. Niels Bohr was based on the hydrogen atom for the model that bears his name. Bohr tried to make an atomic model can explain the stability of matter and the emission and absorption spectra observed in discrete gases. He described the hydrogen atom with one proton in its nucleus, and revolving around an electron. The model was based conceptually Bohr Rutherford model and the emerging ideas that had emerged quantization few years earlier with the investigations of Max Planck and Albert Einstein.Because of its simplicity, the Bohr model is still frequently used as a simplification of the structure of matter. In this model, electrons revolve in circular orbits around the nucleus, occupying the lowest possible energy orbit, or orbit as close as possible to the nucleus. The classical electromagnetism predicted that a charged particle moving in a circular energy emitted as the electrons would collapse into the nucleus in a moment of time. To overcome this problem Bohr assumed that electrons could only move in specific orbits, each of which characterized by its energy level.\n\nEach orbit can then be identified by an integer n that takes values from 1 onward. This number “n” is called the principal quantum number. He assumed further that the angular momentum of each electron was quantized, and only fractions could vary entire Planck’s constant.According to principal quantum number calculated the distance at which each core was one of the allowed orbits in the hydrogen atom. These levels were initially classified by letters, starting at the “K” and ended at the “Q”. Subsequently the electron levels are ordered by numbers. Each orbit has electrons with different energy levels from which later has to release and that is why the electron will jump from one orbit to another until you reach a space that has the appropriate level, depending on the energy it holds and to free no problem and again return to its original orbit. But did not explain the fine structure spectrum could be explained some years later thanks to Sommerfeld atomic model. Historically the development of the Bohr model with wave-particle duality allow Erwin Schr dinger discovered the fundamental equation of quantum mechanics." ]
[ null ]
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https://www.infoq.cn/article/msfu3mv8XPisYRywy9fK
[ "# 算法(4th ed)(150):基础——算法分析 6.2.3", null, "(观察:实验数据的分析)\n\nDoublingTest 是Stopwatch 的一个更加复杂的用例,并能够为 ThreeSum 产生实验数据。它会生成一系列随机输入数组,在每一步中将数组长度加倍,并打印出ThreeSum.count() 处理每种输入规模所需的运行时间。这些实验显然是可重现的——你也可以在自己的计算机上运行它们,多少次都行。在运行 DoublingTest 时,你会发现自己进入了一个“预测—验证”的循环:它会快速打印出几行数据,但随即慢了下来。每当它打印出一行结果时,你都会开始琢磨它还需要多久才能打出下一行。当然,因为大家使用的计算机不同,你得到的实际运行时间很可能和我们的计算机得到的不一样。事实上,如果你的计算机比我们的快一倍,你所得到的运行时间应该大致是我们所得到的一半。由此我们马上可以得出一条有说服力的猜想:程序在不同的计算机上的运行时间之比通常是一个常数。尽管如此,你还是会提出更详细的问题:作为问题规模的一个函数,我的程序的运行时间是多久?为了帮助你回答这个问题,我们来将数据绘制成图表。图 1.4.2 就是产生结果,使用的分别是标准比例尺和对数比例尺。其中 $x$ 轴表示 $N$$y$ 轴表示程序的运行时间 $T(N)$。由对数的图像我们立即可以得到一个关于运行时间的猜想——因为数据和斜率为 3 的直线完全吻合。该直线的公式为(其中 a 为常数):\n\n$\\lg(T(N))=3\\lg N+\\lg a$\n\n$T(N)=aN^3$\n\n$T(N)=9.98\\times10^{-11}N^3$\n\npublic class DoublingTest{ public static double timeTrial(int N) { // 为处理 N 个随机的六位整数的 ThreeSum.count() 计时 int MAX = 1000000; int[] a = new int[N]; for (int i = 0; i < N; i++) a[i] = StdRandom.uniform(-MAX, MAX); Stopwatch timer = new Stopwatch(); int cnt = ThreeSum.count(a); return timer.elapsedTime(); } public static void main(String[] args) { // 打印运行时间的表格 for (int N = 250; true; N += N) { // 打印问题规模为 N 时程序的用时 double time = timeTrial(N); StdOut.printf(\"%7d %5.1f\\n\", N, time); } }}", null, "", null, "" ]
[ null, "https://static001.infoq.cn/resource/image/c5/0f/c533eaef72054100191631b81bc1e30f.png", null, "https://static001.infoq.cn/resource/image/57/8b/57e7539acb8e2aa530a44bb3ebd6ac8b.png", null, "https://static001.infoq.cn/resource/image/ac/4a/ac4bb8c38b62f139f67bc0597b99814a.png", null ]
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https://mathoverflow.net/questions/262568/is-there-an-upper-bound-on-dimension-of-kernel-of-elliptic-operator-for-a-fixed
[ "# Is there an upper bound on dimension of kernel of elliptic operator for a fixed closed manifold M\n\nAssume that $M$ is a smooth closed manifold and $E,F$ are fixed smooth vector bundles over $M.$\n\nIs there a number $C,$ such that for any elliptic operator $\\mathcal{D}:\\Gamma(E)\\to\\Gamma(F)$ $$\\dim\\ker\\mathcal{D}\\leqslant C.$$\n\nFor simplicity, we may assume that $\\Gamma(E)=\\Gamma(F)=C^\\infty(M).$\n\n• I think $\\prod_{k=1}^n, (d^2+k^2)$ on $S^1$ is another counter example. But do you have an example of such manifold? What about if we assume some restriction on the principal simple and requre the bounded ness of index? – Ali Taghavi Jun 13 '17 at 20:34\n\nThere are, at least, many examples where this is false. For instance, Hitchin showed (I think this was his thesis) that there is a sequence of metrics $\\{g_k\\}_{k=1}^{\\infty}$ on the three sphere such that the kernel of the Dirac operator associated to $g_{k}$ has dimension at least $k.$ It is stated as a conjecture in these notes http://www.mathematik.uni-regensburg.de/ammann/talks/11BerlinSFB.pdf that this is a generic phenomena for spin manifolds of dimension at least three.\n\nIn the case where $E=F=M\\times \\mathbb{R},$ I don't have any examples in mind off the top of my head, but I could imagine one could construct a family of metrics $\\{g_{k}\\}$ and a family of functions $f_{k}:M\\rightarrow \\mathbb{R}$ such that the sequence of elliptic operators \\begin{align} D_{k}=\\Delta_{g_{k}} + f_{k} \\end{align} has arbitrarily large kernel.\n\nWith this in mind, it's hard to imagine a circumstance where what you are asking is true. A better question might be: for some sensible elliptic operator that depends on a parameter, like the Dirac operator on a spin manifold depending on a Riemannian metric, can you find sensible geometric bounds on the Riemannian metric under which this kernel has a uniform bound.\n\n• I purpously posted this question in such naive way, because I was unable to came up with any exaples. Thank you for this neat answer. – Fallen Apart Feb 18 '17 at 21:59\n\nHere is another simple counterexample: every holomorphic vector bundle over a Riemann surface gives rise to an elliptic operator (the $\\bar\\partial$-operator) whose kernel is the space of holomorphic sections. Two vector bundles over the same compact surface are isomorphic as smooth complex vector bundles if and only if the have the same rank and the same degree. Now take the Riemann sphere $P^1$ and a line bundle $L\\to P^1$ of degree $d\\geq 1$ and the rank $2$ vector bundle $$E=L\\oplus L^*\\to P^1.$$ $E$ has degree $0$ for every $d$ but the dimension of holomorphic sections, i.e. the dimension of the kernel is $d+1$.\n\nOn the other hand, there is a class of elliptic operators for which such an estimate exists: every linear elliptic differential operator $$D\\colon\\Gamma(M,L)\\to\\Gamma(M,\\tilde L)$$ of order 1 between complex line bundles $L,\\tilde L$ over a surface $M$ is given as the $\\bar\\partial$-operator of some holomorphic line bundle (with respect to an appropriate Riemann surface structure). The dimension of the kernel is then restricted by $$\\dim\\ker D\\leq \\mathrm{deg}(L)+1$$ because we can always produce a $(k-1)$th order zero at a point for some section in a $k$-dimensional space of holomorphic sections of a line bundle.\n\n• Excuse me Sebastian, but I am afraid that I cannot understand the phrase starting with \"On the other hand\", could you please edit it? – Paul-Benjamin Feb 20 '17 at 10:22\n• Sorry for the late reply: What I mean is that in general, there is no such estimate, but in special situations (like line bundles over compact Riemann surfaces and elliptic operators of order 1), there can be such an estimate. – Sebastian Jun 14 '17 at 6:33" ]
[ null ]
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https://thecomputing.zone/Python/9-Conditionals/9-4-Nested-IF-Statement/
[ "", null, "", null, "Once you are feeling comfortable with the if, elif, and else statements, you can move on to nested conditional statements. We can use nested if statements for situations where we want to check for a secondary condition if the first condition executes as true. For this, we can have an if-else statement inside of another if-else statement. Let’s look at the syntax of a nested if statement:\n\n```if statement1: #outer if statement\nprint(\"true\")\n\nif nested_statement: #nested if statement\nprint(\"yes\")\n\nelse #nested else statement\nprint(\"no\")\n\nelse: #outer else statement\nprint(\"false\")```\n\nA few possible outputs can result from running this code:\n\n• If statement1 evaluates to true, the program will then evaluate whether the nested_statement also evaluates to true. If both cases are true, the output will be:\n\n```true\nyes```\n\nIf, however, statement1 evaluates to true, but nested_statement evaluates to false, then the output will be:\n\n```yes\nfalse```\n\nAnd if statement1 evaluates to false, the nested if-else statement will not run, so the else statement will run alone, and the output will be:\n\n`false`\n\nWe can also have multiple if statements nested throughout our code:\n\n```if statement1: #outer if\nprint(\"hello world\")\n\nif nested_statement1: #first nested if\nprint(\"yes\")\n\nelif nested_statement2: #first nested elif\nprint(\"maybe\")\n\nelse #first nested else\nprint(\"no\")\n\nelif statement2: #outer elif\nprint(\"hello galaxy\")\n\nif nested_statement3: #second nested if\nprint(\"yes\")\n\nelif nested_statement4: #second nested elif\nprint(\"maybe\")\n\nelse #second nested else\nprint(\"no\")\n\nelse: #outer else\nstatement(\"hello universe\")```\n\nIn the above code, there is a nested if statement inside each if statement in addition to the elif statement. This will allow for more options within each condition.\n\nLet’s look at an example of nested if statements with our grade program. We can check for whether a grade is passing first (greater than or equal to 65%), then evaluate which letter grade the numerical grade should be equivalent to. If the grade is not passing, though, we do not need to run through the letter grades, and instead can have the program report that the grade is failing. Our modified code with the nested if statement will look like this:\n\n```grade = 60\n\nprint(\"A\")\n\nprint(\"B\")\n\nprint(\"C\")\n\nprint(\"D\")\n\nelse:\n\nIf we run the code with the variable grade set to the integer value 92, the first condition is met, and the program will print out Passing grade of:. Next, it will check to see if the grade is greater than or equal to 90, and since this condition is also met, it will print out A.\n\nIf we run the code with the grade variable set to 60, then the first condition is not met, so the program will skip the nested if statements and move down to the else statement, with the program printing out Failing grade.\n\nWe can of course add even more options to this, and use a second layer of nested if statements. Perhaps we will want to evaluate for grades of A+, A and A- separately. We can do so by first checking if the grade is passing, then checkingto see if the grade is 90 or above, then checkingto see if the grade is over 96 for an A+ for instance:\n\n```grade = 60\n\nprint(\"A+\")\n\nprint(\"A\")\n\nprint(\"A-\")```\n\nIn the code above, for a grade variable set to 96, the program will run the following:\n\n1. Check if the grade is greater than or equal to 65 (true)\n2. Print out Passing grade of:\n3. Check if the grade is greater than or equal to 90 (true)\n4. Check if the grade is greater than 96 (false)\n5. Check if the grade is greater than 93 and also less than or equal to 96 (true)\n6. Print A\n7. Leave these nested conditional statements and continue with remaining code\nThe output of the program for a grade of 96 therefore looks like this:\n\n```Passing grade of:\nA```\n\nNested if statements can provide the opportunity to add several specific levels of conditions to your code.", null, "Introduction\n\nWrite a program that uses a one level nested IF.\n\nWrite a program that uses a two level nested IF.\n\nWrite a program that uses a three level nested IF.", null, "", null, "If you need to get in touch with Mr McG then this is the way….\n\nThank you [name], that's great.\n\nCan I ask where you are from?\nHey [name], can I ask where you are from?\nHey [name], which class are you in?\nOK [name], thanks for that.\n\nThanks [name], nearly there." ]
[ null, "https://thecomputing.zone/resources/Logos/Logo-Full-White.svg", null, "https://thecomputing.zone/resources/Titles/Python/9-3-Nested-If-Statements-B.svg", null, "https://thecomputing.zone/Python/9-Conditionals/9-4-Nested-IF-Statement/files/item_image_icon_2063.png", null, "https://thecomputing.zone/Python/9-Conditionals/9-4-Nested-IF-Statement/files/item_image_icon_2168.png", null, "https://thecomputing.zone/Python/9-Conditionals/9-4-Nested-IF-Statement/files/item_image_icon_2179.png", null ]
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http://mathopenref.com/equation.html
[ "# Equation\n\nAn equation is a mathematical statement that two things are equal. It consists of two expressions, one on each side of an 'equals' sign. For example: This equation states that 12 is equal to the sum of 7 and 5, which is obviously true. In an equation, the left side is always equal to the right side.\n\n## Using variables\n\nThe most common equations contain one or more variables. If we let x stand for an unknown number, and write the equation We know the left side and right side are equal, so we can see that x must be 12+5 or 17. This is the only value that x can have that makes the equation a true statement. We say that x=17 'satisfies' the equation.\n\nThis process of finding the value of the unknowns is called \"solving the equation\". We often say that we \"solve for x\" - meaning solve the equation to find the value of the unknown number x.\n\n## A common mistake\n\nYou will often see things that are called equations when they are not. For example you may see something like this referred to as an equation: It does not have an equals sign in it, and so is not an equation. It is called an 'expression'.\n\n## Algebra\n\nThe study of algebra is in large part about learning ways to solve various kinds equations. For example, there are ways to solve quadratic equations such as" ]
[ null ]
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https://confluence.hdfgroup.org/exportword?pageId=50071874
[ "Message-ID: <583000033.301.1606335772651.JavaMail.confluence@kumara.ad.hdfgroup.org> Subject: Exported From Confluence MIME-Version: 1.0 Content-Type: multipart/related; boundary=\"----=_Part_300_1857047672.1606335772649\" ------=_Part_300_1857047672.1606335772649 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable Content-Location: file:///C:/exported.html H5P_GET_LINK_CREATION_ORDER\n\n=20\n= =20\n=20\n\n=20\n=20 Collapse all=20\n=20 Expand all  = ;=20 Collapse all=20\n=20\n=20\n=20\n=20\n=20\n=20\n=20 =20 = =20 =20 =20 =20 =20 =20 =20 = =20 =20 =20 =20 =20\n=20 =20\n=20\n=20\n=20\n\n=20\n=20\n=20 =20\n= =20\n=20\n\n=20\n=20\n=20 =20 =20 =20\n\n• Switch language ...\n\n=20\n=20 =20 =20\n=20\n=20 =20 =20 =20\n=20\n\n=20 =20\n\n=20\n=20\n=20\n\n=20\n\n=20 =20\n=20\n=20\n\n=20\n\n=20\n=20\n\n=20\n\nQueries whether link creation order is tra= cked and/or indexed in a group\n\n=20\n\n=20\n=20\n\n``````herr_t H5Pget_link_creation_order(\nhid_t gcpl_id,\nunsigned *crt_order_flags\n)\n``````\n=20\n=20\n\n hid_t `gcpl_id` IN: Group or file creation property list identif= ier unsigned *```crt_order_flags&nb= sp;   ``` OUT: Creation order flag(s)\n=20\n\nH5P_GET_LINK_CREATION_ORDER queries the group or file creation property = list, `gcpl_id`, and returns a flag indicating whether link crea= tion order is tracked and/or indexed in a group.\n\nSee H5P_SET_LINK_CREATION_ORDER for a list of vali= d creation order flags, as passed in `crt_order_flags`, and thei= r meanings.\n\n=20\n\nReturns a non-negative value if successful; otherwise returns a negative= value.\n\n=20\n\nComing Soon!\n\n=20\n\nRelease    = Change\n1.8.0 Function introduced in this release.\n=20\n=20" ]
[ null ]
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http://www.hoppeninjamath.com/uncategorized/hwk-33/
[ "Hwk 3/3\nThursday March 03rd 2011, 12:17 pm\nFiled under: Algebra,Algebra 1A,Homework,Pre-Algebra,Uncategorized\n\nALGEBRA\n1. District Test wrong questions! – do the problems you got wrong\n2. Accelerated Math (11 objectives by 3/4/11)\nToday we took a test.  Tomorrow we will learn more about multiplying binomials and work on Accelerated Math tests.\n\nPRE-ALGEBRA B\n1. Accelerated Math (13 objectives by 3/4/11)\nToday we took a test.  Tomorrow we will learn more about integer exponents and work on Accelerated Math tests.\n\nALGEBRA 1A\n1. ST Math\nToday we took a test.  Tomorrow we will learn more about negative rates and do ST Math on the computers." ]
[ null ]
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https://community.tableau.com/thread/176722
[ "2 Replies Latest reply on Jun 25, 2015 7:43 PM by dennis.garlick\n\n# How to reference a column's value in a calculated field?\n\nHi,\n\nSay if you have 2 date fields, OrderDate and FulfillmentDate, and you want to do a line graph showing the number of open orders on a day-to-day basis. In other words, a record will only be counted if the OrderDate is less than or equal to the current date being plotted, and the FulfillmentDate is greater than or equal to the current date being plotted or is null.\n\nWhen I reference fields in calculated fields, the values of the individual record are being referenced, not a variable value that changes as a value changes in a line graph. I presume that there is an easy way to reference a value from the axes of a line graph??\n\n• ###### 1. Re: How to reference a column's value in a calculated field?\n\nToady() is equal to Current Date ---- (Today is 25 -Jun-2015 IST)\n\n1) Create a calculation like below.\n\nIf datediff( 'day', [Order_Date], today())<=0 and datediff( 'day', [Order_Fullfillment_Date], today())>=0  then [Show required Measure] end\n\n2)  Drag the Order ID or Referencing of Order ID Column into Columns Shelf.\n\n3) Drag the Above calculated field, select the marks Type \"Line\"\n\nBest Regards\n\nLaxman Kumar\n\n• ###### 2. Re: How to reference a column's value in a calculated field?\n\nThanks for the suggestions so far. I tried the Today statement, but that didn't work as it only references the current date - not the differing dates that are being plotted in the figure. Kettan's response might work, but is less than ideal from a performance standpoint. Thinking about it some more, an alternative approach would be to have a Date range on the x-axis, then do a count of the number of records where [Order_Date]<Date, and do a count of the number of records where [Fulfillment_Date]<Date. This will give us two lines. If we can then calculate a third line that represents the difference between lines 1 and 2, it should be want is required. Is it possible to reference the value of one line in determining the value of another line?" ]
[ null ]
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https://uk.mathworks.com/matlabcentral/cody/problems/716-arrange-vector-in-ascending-order/solutions/1986082
[ "Cody\n\n# Problem 716. Arrange vector in ascending order\n\nSolution 1986082\n\nSubmitted on 22 Oct 2019 by Adobe Fl\nThis solution is locked. To view this solution, you need to provide a solution of the same size or smaller.\n\n### Test Suite\n\nTest Status Code Input and Output\n1   Pass\nx = [4 5 1 2 9]; y_correct = [1 2 4 5 9]; assert(isequal(ascending_order(x),y_correct))\n\n2   Pass\nx = [10 8 -4 3 1 -1 0]; y_correct = [-4 -1 0 1 3 8 10]; assert(isequal(ascending_order(x),y_correct))\n\n3   Pass\nx = 0; y_correct = 0; assert(isequal(ascending_order(x),y_correct))" ]
[ null ]
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https://ofstack.com/python/22055/golang-and-python-thread-details-and-simple-examples.html
[ "# Golang and python thread details and simple examples\n\n• 2020-05-30 20:32:13\n• OfStack\n\nGolang and python threads details and simple examples\n\nIn GO, 15 threads are started and each thread iterates the global variable 100,000 times, so the predicted result is 15* 100,000 = 1,500,000.\n\n``````\nvar sum int\nvar cccc int\nvar m *sync.Mutex\n\nfunc Count1(i int, ch chan int) {\nfor j := 0; j < 100000; j++ {\ncccc = cccc + 1\n}\nch <- cccc\n}\nfunc main() {\nm = new(sync.Mutex)\nch := make(chan int, 15)\nfor i := 0; i < 15; i++ {\ngo Count1(i, ch)\n}\nfor i := 0; i < 15; i++ {\nselect {\ncase msg := <-ch:\nfmt.Println(msg)\n}\n}\n}\n\n``````\n\nBut the end result, 406,527\n\nIt says it needs to be locked.\n\n``````\nfunc Count1(i int, ch chan int) {\nm.Lock()\nfor j := 0; j < 100000; j++ {\ncccc = cccc + 1\n}\nch <- cccc\nm.Unlock()\n}\n``````\n\nFinal output: 1500000\n\npython: same way, no.\n\n``````\ncount = 0\ndef sumCount(temp):\nglobal count\nfor i in range(temp):\ncount = count + 1\nli = []\nfor i in range(15):\nth.start()\nli.append(th)\nfor i in li:\ni.join()\nprint(count)\n``````\n\nOutput result: 3004737\n\nNote also need to be locked:\n\n``````\ncount = 0\ndef sumCount(temp):\nglobal count\nmutex.acquire()\nfor i in range(temp):\ncount = count + 1\nmutex.release()\nli = []\nfor i in range(15):\nth.start()\nli.append(th)\nfor i in li:\ni.join()\nprint(count)\n``````\n\nThe output of 1500000\n\nOK, small column with locks." ]
[ null ]
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http://www.sourcecodeonline.com/list?q=fractal_dimension
[ "Search\nCode Directory", null, "ASP", null, "ASP.NET", null, "C/C++", null, "CFML", null, "CGI/PERL", null, "Delphi", null, "Development", null, "Flash", null, "HTML", null, "Java", null, "JavaScript", null, "Pascal", null, "PHP", null, "Python", null, "SQL", null, "Tools", null, "Visual Basic & VB.NET", null, "XML\nNew Code", null, "Rapid PHP 2018 15.5", null, "IBDAC 6.4", null, "Online Course Booking Script 1.3.3", null, "Database Workbench Pro 5.6.4", null, "Job Portal Script 1.3.2", null, "The C# PDF Library 5.2", null, "PostgreSQL Data Access Components 6.0", null, "Virtual Data Access Components 11.0", null, "HTMLPad 2018 15.5", null, "WeBuilder 2018 15.5", null, "SentiMask SDK Trial 2.0.0", null, "Track Order For Magento 2 1.0.0", null, "Calendar 365 For Dynamics CRM 4.0", null, "Scimbo 1.2", null, "Odoo Furnito Theme 1.0\nTop Code", null, "VisualNEO Web 2018.12.15", null, "Azizi search engine script PHP 4.1.10", null, "Paste phpSoftPro 1.4.1", null, "Extreme Injector 3.7", null, "Deals and Discounts Website Script 1.0.2", null, "ADO.NET Provider for ExactTarget 1.0", null, "Solid File System OS edition 5.1", null, "Classified Ad Lister 1.0", null, "Aglowsoft SQL Query Tools 8.2", null, "Invoice Manager by PHPJabbers 3.0", null, "ICPennyBid Penny Auction Script 4.0", null, "PHP Review Script 1.0", null, "ATN Resume Finder 2.0", null, "ATN Site Builder 3.0", null, "Availability Booking Calendar PHP 1.0\nTop Search", null, "Code To Add Url", null, "Dirty Word", null, "Guestbooks Aspnetindex", null, "Animated Counter", null, "Photo Add Comment Php", null, "Gallery Comment", null, "German Guestbook", null, "Gallery Comments", null, "Video Free", null, "Html Guestbook Codes", null, "Taxi Fare Calculator", null, "Twitter Update Script Php", null, "Mini Project On Cloud Computing", null, "Article Directory Script For Wordpress", null, "Jforum Source Code\nRelated Search", null, "Fractal Dimension", null, "Fractal Dimension Index", null, "Fractal Dimension Indicator", null, "Fractal Image Compression", null, "L-System Fractal", null, "Browser Sniffer Dimension", null, "Time Dimension", null, "Delphi Fractal", null, "Fractal Compression Source Code In C", null, "Region Based Fractal Image Compression", null, "Double Dimension Bubblesort", null, "Multi Dimension Array Search", null, "Array One Dimension", null, "Fractal Compression", null, "Generate A Date Dimension Table\nFractal Dimension\n\nCode 1-20 of 60   Pages: Go to  1  2  3  Next >>  page\n\n### Calculation of fractal dimension of... - Jianbo ZhangTools / Development Tools\n\nFDSURFFT computes fractal dimension (slope) of surface image im and draw rose plots of slope and intercept.\n\n### Finding the Fractal Dimension using... - AnoopTools / Development Tools\n\nIts based on the traditional box-counting method for finding the fractal dimension of an image. The code is just for beginners for getting an idea of how the box-counting is done.\n\n### IFS fractal dimension calculation... - FB36Python / Miscellaneous\n\nIFS fractal dimension calculation using box-counting method.\n\n### Hausdorff (Box-Counting) Fractal... - Alceu CostaTools / Development Tools\n\nReturns the Haussdorf fractal dimension D of an object represented by the binary image I. Nonzero pixels belong to an object and 0 pixels constitute the background.\n\nAlgorithm:\n\n1 - Pad the image with background pixels so that...\n\n### Calculation of fractal dimension of a... - Jianbo ZhangTools / Development Tools\n\nThis matlab scprit calculates fractal dimension and intercept of a 3D volume along each redial line using Fourier analytical technique. Directionally averaged fractal dimension, intercept and Hedgehog plots of fractal dimension and intercept of...\n\n### FRACTAL DIMENSION USING SEMIVARIANCE... - Karunanithi RajamanickamTools / Development Tools\n\nTHIS ALGORITHM COMPUTES FRACTAL DIMENSION USING SEMI-VARIANCE TECHNIQUE. IT HELPS TO ASSESS THE DIRECTIONALITY OF THE TEXTURE PATTERN IN AN IMAGE. SEMI-VARIANCE ALONG HORIZONTAL DIRECTION IS DEFINED AS THE SUMMATION OVER ALL PIXELS N, OF THE...\n\n### Fractal Volatility of Financial Time... - HanTools / Development Tools\n\n[DIMENSION STANDARD_DEV] = fractalvol(DATA) calculates the fractal dimension of the 1 dimensional random walk, DATA. DATA is assumed to be a function of its indices.\nFinds fractal volatility by embedding in the unit square and box\n...\n\n### IFS fractal dimension calculation  - FB36Python / Miscellaneous\n\nI found this equation in Wikipedia page for \"List of fractals by Hausdorff dimension\".\nThe problem is how to calculate the scaling coefficients for any given IFS fractal.\nYou can see the heuristic I used in the code.\nIt...\n\n### Fractal Volatility through Variation... - HanTools / Development Tools\n\n[VINDX FRACDIM V_SIGMA COVERSIZE] = varIndx(LOW,HIGH)\n\nLOW is a column vector of the lowest price in the bar (second, minute,\netc).\nHIGH is a column vector of the highest price in the bar.\n\nVINDX is the variation...\n\n### boxcount 1.0 - Frederic MoisyTools / Development Tools\n\nBOXCOUNT Box-Counting of a D-dimensional array (with D=1,2,3).\n\nThe Box-counting method is useful to determine fractal properties of a\n1D segment, a 2D image or a 3D array. If C is a fractal set, with fractal dimension DF < D,...\n\n### Calculation of fractal dimension... - Izard EdouardTools / Development Tools\n\nA file ReadMe explains everything in the folder.\n\n### Simple Higuchi Fractal Dimension... - SUMANTHTools / Development Tools\n\nCalculate HFD method1 uses HFDCALC() which in turn uses split() method2 uses HFD_LCALC()\nPlease read readme and HDF_sumanth.pdf files in the present zip file.\n\n### Sliding Window Gen and usage with... - SUMANTHTools / Development Tools\n\nSWG() is a multipurpose, segment generation tool based on input, window size, overlap size\nSWG() along with FFT() can be used to implement STFT\n\nIn the present implementation,\nusing SWG(), window based HFD is done on a sample data\n\n### Generalized Apollonian Gasket Fractal  - FB36Python / Miscellaneous\n\nIt draws Apollonian Gasket Fractal for any n using Descartes theorem.\n\nThis is not the standard way though. It simply randomly finds 3 tangent circles at each iteration and tries to add new circles. The good thing is it can start w/ any...\n\n### Apollonian Gasket Fractal using IFS  - FB36Python / Miscellaneous\n\nIt draws the central region of Apollonian Gasket fractal using IFS description.\n\n### Dragon IFS Fractal  - FB36Python / Miscellaneous\n\nDragon IFS Fractal\n\n### Tetration Fractal  - FB36Python / Miscellaneous\n\nTetration Fractal.\n\n### Fuzzy Logic Fractal  - FB36Python / Miscellaneous\n\nThis fractal created by converting logic statements into equations using fuzzy logic operators:\n\nX: X is as true as Y is true\n\nY: Y is as true as X is false\n\nSee: Scientific American Magazine, February 1993, \"A...\n\n### Random fractal curve  - FB36Python / Miscellaneous\n\nRandom fractal curve (non-deterministic)." ]
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https://www.hindawi.com/journals/bmri/2014/618404/
[ "#### Abstract\n\nAn analysis of the model underpinning the description of the spread of HIV infection of CD4+T cells is examined in detail in this work. Investigations of the disease free and endemic equilibrium are done using the method of Jacobian matrix. An iteration technique, namely, the homotopy decomposition method (HDM), is implemented to give an approximate solution of nonlinear ordinary differential equation systems. The technique is described and illustrated with numerical examples. The approximated solution obtained via HDM is compared with those obtained via other methods to prove the trustworthiness of HDM. Moreover, the lessening and simplicity in calculations furnish HDM with a broader applicability.\n\n#### 1. Introduction\n\nThe cause of the progressive depletion of CD4+T cells in HIV-infected people is one of the most fundamental and controversial issues in AIDS research. HIV infects and kills CD4+T cells. The infection results in high T-cell activation and turnover. An immediately intuitive assumption is that HIV-mediated destruction of CD4+ cells directly reduces the number of these cells and that the high turnover rates of T cells and the slow progression to AIDS reflect a long but eventually lost struggle of the immune system to replace killed cells in its effort to maintain T-cell homeostasis . However, HIV mainly infects activated CD4+ cells, and activated cells normally follow different dynamics than cells that belong to resting populations whose numbers are controlled by homeostatic mechanisms.\n\nIn this study, we consider that the HIV infection model of CD4+T cells is examined in . This model is given by the components of the basic three-component model which are the concentration of susceptible CD4+T cells, CD4+T cells infected by the HIV viruses, and free HIV virus particles in the blood. CD4+T cells are also called leukocytes or T helper cells. These with order cells in human immunity systems fight against diseases. HIV use cells in order to propagate. In a healthy person, the number of CD4+T cells is 800/1200 mm3. This model is characterized by a system of the nonlinear differential equations: subject to the initial conditions Here, is any positive constant, , , and show the concentration of susceptible CD4+T cells, CD4+T cells infected by the HIV viruses, and free HIV virus particles in the blood, respectively, , , and stand for natural turnover rates of uninfected Tells, infected T cells, and virus particles, respectively, describes the logistic growth of the healthy CD4+T cells, and proliferation of infected CD4+T cells is neglected. For is the infection rate, the term describes the incidence of HIV infection of healthy CD4+T cells. Each infected CD4+T cell is assumed to produce l virus particles during its lifetime, including any of its daughter cells. The body is believed to produce CD4+T cells from precursors in the bone marrow and thymus at a constant rate . T cells multiply through mitosis with a rate when T cells are stimulated by antigen or mitogen. denotes the maximum CD4+T cell concentration in the body .\n\nAs Andrianov and Manevitch wrote in the foreword of a popular science book Asymtotology: Ideas, Methods, and Applications, asymptotic methods belong to the, perhaps, most romantic area of modern mathematics . Though computer science is growing very fast and numerical simulation is applied everywhere, nonnumerical issues will still play a large role . There exist some alternative analytical asymptotic approaches, such as the nonperturbative method, modified Lindstedt-Poincaré method , variational iteration method , Adomian decomposition method , homotopy perturbation method [16, 17], and book-keeping artificial parameter perturbation method .\n\nThe purpose of this paper is to derive analytical solutions of model for HIV infection of CD4+T cells (1) via the relatively new analytical solution homotopy decomposition method (HDM). The HDM was recently used to solve one- and two-dimensional fractional heat-like problem, Burgers equation, the Klein-Gordon equation, a coupled Burgers equation, 2D and 3D Poisson equations and biharmonic equations, the groundwater flow equation , the Hamilton-Jacobi-Bellman equation, high even-order differential equation, parabolic equations and coupled Van der Pol’s nonlinear partial differential equation, and coupled attractor one-dimensional Keller-Segel equations. This method displays some advantages over the existing methods.\n\n#### 2. Stability Analysis\n\nThe aim of this section is to present a stability analysis of the system equation (1) that will be achieved via the use the eigenvalues obtained via the Jacobian matrix. We will start by providing the equilibrium point and also the desease free equilibrium. To obtain the equilibrium points, we assume that the system does not depend on the parameter ; this will further imply that After the first manipulations, we obtain that From the above equation, we can obtain However, replacing (5) into the first equation of system (3) and rearranging it, we obtain the following: Therefore, the equilibrium points are given as The above equilibrium points are valid if the following conditions are satisfied: The disease free equilibrium is obtained by solving the following equation: which has the following solution: Therefore, the diseases free equilibrium is given as\n\nWith the above information on hand, we will now find the eigenvalues associated with this problem, which will allow us to give stability of the system. The Jacobian matrix associated with this problem is given by Now, using the equilibrium free point, we obtain the following: In order to find the eigenvalues associate, we will solve the following equation: Using the standard method, we obtain the following solution: With the Eigen values in hand, we conclude that there is stability if and only if the following conditions are observed:\n\n#### 3. Some Useful Information regarding the Methodology of (HDM)\n\nTo illustrate the basic idea of this method, we consider a general nonlinear nonhomogeneous differential equation with initial conditions of the following form (see also in [16, 19]): Subjected to the initial condition, is the order of the derivative.\n\nis a known function, is the general nonlinear differential operator, represents a linear differential operator, and is the order of the derivative. The method’s first step here is to apply the inverse operator on both sides of (17) to obtain The multi-integral in (17) can be transformed to so that (19) can be reformulated as Using the homotopy scheme, the solution of the above integral equation is given in series form as follows: and the nonlinear term can be decomposed as where is an embedding parameter. is the He’s polynomials that can be generated by The homotopy decomposition method is obtained by the graceful coupling of decomposition method with He’s polynomials and is given by with Comparing the terms of the same powers of , we obtain solutions of various orders. The initial guess of the approximation is ; this is actually the Taylor series of the exact solution of order . Note that this initial guess insures the uniqueness of the series decompositions.\n\n#### 4. Applications\n\nIn this section, we applied the HDM to solve the system of the nonlinear differential equations (1). To be consistent in comparison with the existing methods, we chose the following initial condition and parameters as in [20, 21]: Following carefully the steps of the HDM, we obtain the following equations: Comparing the terms of the same power of , we obtain the following integral equations that are much easier to solve. Note that, with the homotopy perturbation method (HPM), one will obtain a set of ordinary differential equations, after comparing the terms of the same power of , which something is very heavy to compute in the case of high order ODE. Consider We will give the general algorithm in order to accommodate scholars using computers program; the algorithm will then be used to derive special solution of the system of equation for a given set of theoretical parameters.\n\nAlgorithm 1. (i)input: , and as initial guest;(ii)-number terms in the rough calculation;(iii)output: the approximate solutions.\nStep 1. Put , , , .\nStep 2. From to , do Steps 3 and Step 4.\nStep 3. Compute\nStep 4. Compute , , and     .\nStop.\n\nWe will now make use of the above algorithm to derive the special solution. We therefore obtain the following series solutions: Using the package Mathematica, in the same manner, one can obtain the rest of the components. But, in this case, 9 terms were computed and the asymptotic solution is given by\n\n##### 4.1. Numerical Applications\n\nTo test the effectiveness and the accuracy of the HDM for solving this type of problem, we compare the approximated solutions obtained via other methods and HDM, and the results are shown in Tables 1, 2, and 3.\n\nNumerical comparison shows that the approximated solutions obtained via LADM-Padé are in good agreement with the results obtained via HDM. More precisely, the approximated solutions are exactly the same. However, in the technique used in , one needs first to apply the Laplace transform on the system, following by the ADM, and finally take the inverse Laplace transform to obtain the approximated solutions, which is much time consuming and sometimes can lead to a very difficult situation, for example, if the inverse Laplace transform cannot be obtained.\n\n#### 5. Conclusions\n\nIn this paper, homotopy decomposition method has been developed for finding approximate solutions of HIV infection model of CD4+T which is a class of nonlinear ordinary differential equation systems. We have demonstrated the accuracy and efficiency of the present technique with an example and comparison of the approximate solution obtained via the technique with those obtained with other methods. Comparing the methodology HDM to homotopy perturbation method (HPM), Adomian decomposition method (ADM), variational iteration method (VIM), and homotopy analysis method (HAM) has advantages. Disparate the ADM, the HDM is free from the need of Adomian polynomials. In this method, we do not need the Lagrange multiplier, correction functional, stationary conditions, or calculation of heavy integrals; the solution obtained is noise free, which eliminate the complications that exist in the VIM . In contract to HPM, we do not need to continuously deform a difficult problem to another that is easier to solve. In contrast to LADM, the technique does not need any change of space, which sometime can be very difficult situation to handle, for example, in case the inverse Laplace transform cannot be found. We can easily conclude that the homotopy decomposition method is an efficient tool to solve approximate solution of nonlinear system partial differential equations.\n\n#### Conflict of Interests\n\nThe authors declare that there is no conflict of interests regarding the publication of this paper." ]
[ null ]
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https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/08%3A_Work_and_Energy/8.03%3A_Kinetic_Energy
[ "# 8.3: Kinetic Energy\n\n•", null, "• OpenStax\n• OpenStax\n$$\\newcommand{\\vecs}{\\overset { \\rightharpoonup} {\\mathbf{#1}} }$$ $$\\newcommand{\\vecd}{\\overset{-\\!-\\!\\rightharpoonup}{\\vphantom{a}\\smash {#1}}}$$$$\\newcommand{\\id}{\\mathrm{id}}$$ $$\\newcommand{\\Span}{\\mathrm{span}}$$ $$\\newcommand{\\kernel}{\\mathrm{null}\\,}$$ $$\\newcommand{\\range}{\\mathrm{range}\\,}$$ $$\\newcommand{\\RealPart}{\\mathrm{Re}}$$ $$\\newcommand{\\ImaginaryPart}{\\mathrm{Im}}$$ $$\\newcommand{\\Argument}{\\mathrm{Arg}}$$ $$\\newcommand{\\norm}{\\| #1 \\|}$$ $$\\newcommand{\\inner}{\\langle #1, #2 \\rangle}$$ $$\\newcommand{\\Span}{\\mathrm{span}}$$ $$\\newcommand{\\id}{\\mathrm{id}}$$ $$\\newcommand{\\Span}{\\mathrm{span}}$$ $$\\newcommand{\\kernel}{\\mathrm{null}\\,}$$ $$\\newcommand{\\range}{\\mathrm{range}\\,}$$ $$\\newcommand{\\RealPart}{\\mathrm{Re}}$$ $$\\newcommand{\\ImaginaryPart}{\\mathrm{Im}}$$ $$\\newcommand{\\Argument}{\\mathrm{Arg}}$$ $$\\newcommand{\\norm}{\\| #1 \\|}$$ $$\\newcommand{\\inner}{\\langle #1, #2 \\rangle}$$ $$\\newcommand{\\Span}{\\mathrm{span}}$$$$\\newcommand{\\AA}{\\unicode[.8,0]{x212B}}$$\n\n## Learning Objectives\n\n• Calculate the kinetic energy of a particle given its mass and its velocity or momentum\n• Evaluate the kinetic energy of a body, relative to different frames of reference\n\nIt’s plausible to suppose that the greater the velocity of a body, the greater effect it could have on other bodies. This does not depend on the direction of the velocity, only its magnitude. At the end of the seventeenth century, a quantity was introduced into mechanics to explain collisions between two perfectly elastic bodies, in which one body makes a head-on collision with an identical body at rest. The first body stops, and the second body moves off with the initial velocity of the first body. (If you have ever played billiards or croquet, or seen a model of Newton’s Cradle, you have observed this type of collision.) The idea behind this quantity was related to the forces acting on a body and was referred to as “the energy of motion.” Later on, during the eighteenth century, the name kinetic energy was given to energy of motion.", null, "Newton's cradle in motion. One ball is set in motion and soon collides with the rest, conveying the energy through the rest of the balls and eventually to the last ball, which in turn is set in motion. (CC SA-BY 3.0; Dominique Toussaint).\n\nWith this history in mind, we can now state the classical definition of kinetic energy. Note that when we say “classical,” we mean non-relativistic, that is, at speeds much less that the speed of light. At speeds comparable to the speed of light, the special theory of relativity requires a different expression for the kinetic energy of a particle, as discussed in Relativity. Since objects (or systems) of interest vary in complexity, we first define the kinetic energy of a particle with mass m.\n\n## Kinetic Energy\n\nThe kinetic energy of a particle is one-half the product of the particle’s mass m and the square of its speed $$v$$:\n\n$K = \\frac{1}{2} mv^{2} \\ldotp \\label{7.6}$\n\nWe then extend this definition to any system of particles by adding up the kinetic energies of all the constituent particles:\n\n$K =\\sum \\frac{1}{2} mv^{2} \\ldotp \\label{7.7}$\n\nNote that just as we can express Newton’s second law in terms of either the rate of change of momentum or mass times the rate of change of velocity, so the kinetic energy of a particle can be expressed in terms of its mass and momentum ($$\\vec{p}$$ = m $$\\vec{v}$$), instead of its mass and velocity. Since v = $$\\frac{p}{m}$$, we see that\n\n$K = \\frac{1}{2} m \\left(\\dfrac{p}{m}\\right)^{2} = \\frac{p^{2}}{2m}$\n\nalso expresses the kinetic energy of a single particle. Sometimes, this expression is more convenient to use than Equation $$\\ref{7.6}$$. The units of kinetic energy are mass times the square of speed, or kg • m2/s2. But the units of force are mass times acceleration, kg • m/s2, so the units of kinetic energy are also the units of force times distance, which are the units of work, or joules. You will see in the next section that work and kinetic energy have the same units, because they are different forms of the same, more general, physical property.\n\n## Example $$\\PageIndex{1}$$: Kinetic Energy of an Object\n\n1. What is the kinetic energy of an 80-kg athlete, running at 10 m/s?\n2. The Chicxulub crater in Yucatan, one of the largest existing impact craters on Earth, is thought to have been created by an asteroid, traveling at 22 km/s and releasing 4.2 x 1023 J of kinetic energy upon impact. What was its mass?\n3. In nuclear reactors, thermal neutrons, traveling at about 2.2 km/s, play an important role. What is the kinetic energy of such a particle?\n\nStrategy\n\nTo answer these questions, you can use the definition of kinetic energy in Equation $$\\ref{7.6}$$. You also have to look up the mass of a neutron.\n\n###### Solution\n\nDo not forget to convert km into m to do these calculations, although, to save space, we omitted showing these conversions.\n\n1. $$K = \\frac{1}{2} (80\\; kg)(10\\; m/s)^{2} = 4.0\\; kJ \\ldotp \\nonumber$$\n2. $$m = \\frac{2K}{v^{2}} = \\frac{2(4.2 \\times 10^{23}\\; J)}{22\\; km/s)^{2}} = 1.7 \\times 10^{15}\\; kg \\ldotp \\nonumber$$\n3. $$K = \\frac{1}{2} (1.68 \\times 110^{-27}\\; kg) (2.2\\; km/s)^{2} = 4.1 \\times 10^{-21}\\; J \\ldotp \\nonumber$$\n\nSignificance\n\nIn this example, we used the way mass and speed are related to kinetic energy, and we encountered a very wide range of values for the kinetic energies. Different units are commonly used for such very large and very small values. The energy of the impactor in part (b) can be compared to the explosive yield of TNT and nuclear explosions, 1 megaton = 4.18 x 1015 J. The Chicxulub asteroid’s kinetic energy was about a hundred million megatons. At the other extreme, the energy of subatomic particle is expressed in electron-volts, 1 eV = 1.6 x 10−19 J. The thermal neutron in part (c) has a kinetic energy of about one fortieth of an electronvolt.\n\n## Exercise $$\\PageIndex{1}$$\n\n1. A car and a truck are each moving with the same kinetic energy. Assume that the truck has more mass than the car. Which has the greater speed?\n2. A car and a truck are each moving with the same speed. Which has the greater kinetic energy?\n\nBecause velocity is a relative quantity, you can see that the value of kinetic energy must depend on your frame of reference. You can generally choose a frame of reference that is suited to the purpose of your analysis and that simplifies your calculations. One such frame of reference is the one in which the observations of the system are made (likely an external frame). Another choice is a frame that is attached to, or moves with, the system (likely an internal frame). The equations for relative motion, discussed in Motion in Two and Three Dimensions, provide a link to calculating the kinetic energy of an object with respect to different frames of reference.\n\n## Example $$\\PageIndex{2}$$: Kinetic Energy Relative to Different Frames\n\nA 75.0-kg person walks down the central aisle of a subway car at a speed of 1.50 m/s relative to the car, whereas the train is moving at 15.0 m/s relative to the tracks.\n\n1. What is the person’s kinetic energy relative to the car?\n2. What is the person’s kinetic energy relative to the tracks?\n3. What is the person’s kinetic energy relative to a frame moving with the person?\n\nStrategy\n\nSince speeds are given, we can use $$\\frac{1}{2}$$mv2 to calculate the person’s kinetic energy. However, in part (a), the person’s speed is relative to the subway car (as given); in part (b), it is relative to the tracks; and in part (c), it is zero. If we denote the car frame by C, the track frame by T, and the person by P, the relative velocities in part (b) are related by $$\\vec{v}_{PT}$$ = $$\\vec{v}_{PC}$$ + $$\\vec{v}_{CT}$$. We can assume that the central aisle and the tracks lie along the same line, but the direction the person is walking relative to the car isn’t specified, so we will give an answer for each possibility, vPT = vCT ± vPC, as shown in Figure $$\\PageIndex{1}$$.", null, "Figure $$\\PageIndex{1}$$: The possible motions of a person walking in a train are (a) toward the front of the car and (b) toward the back of the car.\n###### Solution\n1. $$K = \\dfrac{1}{2} (75.0\\; kg)(11.50\\; m/s)^{2} = 84.4\\; J \\ldotp \\nonumber$$\n2. $$v_{PT} = (15.0 \\pm 1.50)7; m/s \\ldotp \\nonumber$$ Therefore, the two possible values for kinetic energy relative to the car are $$K = \\dfrac{1}{2} (75.0\\; kg)(13.5\\; m/s)^{2} = 6.83\\; kJ \\nonumber$$ and $$K = \\frac{1}{2} (75.0\\; kg)(16.5\\; m/s)^{2} = 10.2\\; kJ \\ldotp \\nonumber$$\n3. In a frame where vP = 0, K = 0 as well.\n\nSignificance\n\nYou can see that the kinetic energy of an object can have very different values, depending on the frame of reference. However, the kinetic energy of an object can never be negative, since it is the product of the mass and the square of the speed, both of which are always positive or zero.\n\n## Exercise $$\\PageIndex{2}$$\n\nYou are rowing a boat parallel to the banks of a river. Your kinetic energy relative to the banks is less than your kinetic energy relative to the water. Are you rowing with or against the current?\n\nThe kinetic energy of a particle is a single quantity, but the kinetic energy of a system of particles can sometimes be divided into various types, depending on the system and its motion. For example:\n\n• If all the particles in a system have the same velocity, the system is undergoing translational motion and has translational kinetic energy.\n• If an object is rotating, it could have rotational kinetic energy.\n• If it is vibrating, it could have vibrational kinetic energy.\n\nThe kinetic energy of a system, relative to an internal frame of reference, may be called internal kinetic energy. The kinetic energy associated with random molecular motion may be called thermal energy. These names will be used in later chapters of the book, when appropriate. Regardless of the name, every kind of kinetic energy is the same physical quantity, representing energy associated with motion.\n\n## Example $$\\PageIndex{3}$$: Special Names for Kinetic Energy\n\n1. A player lobs a mid-court pass with a 624-g basketball, which covers 15 m in 2 s. What is the basketball’s horizontal translational kinetic energy while in flight?\n2. An average molecule of air, in the basketball in part (a), has a mass of 29 u, and an average speed of 500 m/s, relative to the basketball. There are about 3 x 1023 molecules inside it, moving in random directions, when the ball is properly inflated. What is the average translational kinetic energy of the random motion of all the molecules inside, relative to the basketball?\n3. How fast would the basketball have to travel relative to the court, as in part (a), so as to have a kinetic energy equal to the amount in part (b)?\n\nStrategy\n\nIn part (a), first find the horizontal speed of the basketball and then use the definition of kinetic energy in terms of mass and speed, K = $$\\frac{1}{2} mv^{2}$$. Then in part (b), convert unified units to kilograms and then use K = $$\\frac{1}{2} mv^{2}$$ to get the average translational kinetic energy of one molecule, relative to the basketball. Then multiply by the number of molecules to get the total result. Finally, in part (c), we can substitute the amount of kinetic energy in part (b), and the mass of the basketball in part (a), into the definition K = $$\\frac{1}{2} mv^{2}$$, and solve for v.\n\n###### Solution\n1. The horizontal speed is $$\\frac{(15\\; m)}{(2\\; s)}$$, so the horizontal kinetic energy of the basketball is $$\\frac{1}{2} (0.624\\; kg)(7.5\\; m/s)^{2} = 17.6\\; J \\ldotp \\nonumber$$\n2. The average translational kinetic energy of a molecule is $$\\frac{1}{2} (29\\; u) (1.66 \\times 10^{-27}\\; kg/u) (500\\; m/s)^{2} = 6.02 \\times 10^{-21}\\; J, \\nonumber$$ and the total kinetic energy of all the molecules is $$(3 \\times 10^{23})(6.02 \\times 10^{-21}\\; J) = 1.80\\; kJ \\ldotp \\nonumber$$\n3. $$v = \\sqrt{\\frac{2(1.8\\; kJ)}{(0.624\\; kg)}} = 76.0\\; m/s \\ldotp \\nonumber$$\n\nSignificance\n\nIn part (a), this kind of kinetic energy can be called the horizontal kinetic energy of an object (the basketball), relative to its surroundings (the court). If the basketball were spinning, all parts of it would have not just the average speed, but it would also have rotational kinetic energy. Part (b) reminds us that this kind of kinetic energy can be called internal or thermal kinetic energy. Notice that this energy is about a hundred times the energy in part (a). How to make use of thermal energy will be the subject of the chapters on thermodynamics. In part (c), since the energy in part (b) is about 100 times that in part (a), the speed should be about 10 times as big, which it is (76 compared to 7.5 m/s).\n\nThis page titled 8.3: Kinetic Energy is shared under a CC BY license and was authored, remixed, and/or curated by OpenStax." ]
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http://forums.wolfram.com/mathgroup/archive/2009/Feb/msg00738.html
[ "", null, "", null, "", null, "", null, "", null, "", null, "", null, "please is it possible with mathematica, thank you!\n\n• To: mathgroup at smc.vnet.net\n• Subject: [mg96715] please is it possible with mathematica, thank you!\n• From: olfa <olfa.mraihi at yahoo.fr>\n• Date: Sun, 22 Feb 2009 00:34:20 -0500 (EST)\n\n```Hi mathematica community!\nI have this input: Not[(y > 0)] and Exists[{x}, (x > 0) && y == x -\n1]\nI want mathematica to give me y==0 as output.\nIs it possible and if it is what predefined function should I use?In\nthis function I want to make this assumption:\nx and y are integers.\nthank you very much.\n\n```\n\n• Prev by Date: DiscretePlot\n• Next by Date: FullGraphics of Graphics3D\n• Previous by thread: Re: DiscretePlot\n• Next by thread: Re: please is it possible with mathematica, thank you!" ]
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https://en.khanacademy.org/math/algebra-home/alg-system-of-equations/alg-solving-equations-by-graphing/a/solving-advanced-equations-by-graphing
[ "If you're seeing this message, it means we're having trouble loading external resources on our website.\n\nIf you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.\n\n## Algebra (all content)\n\n### Course: Algebra (all content)>Unit 5\n\nLesson 8: Solving equations by graphing (Algebra 2 level)\n\n# Solving equations graphically\n\nLearn a clever method for approximating the solution of any equation.\n\n## Introduction\n\nCan you solve the equation ${\\mathrm{log}}_{2}\\left(x+4\\right)=3-x$?\nWould any of the algebraic techniques you've learned so far work for this equation?\nTry as you may, you will find that solving ${\\mathrm{log}}_{2}\\left(x+4\\right)=3-x$ algebraically is a difficult task!\nThis article explores a simple graphing method that can be used to approximate solutions to equations that cannot be solved directly.\n\n## Let's make a system\n\nThinking about the equation as a system of equations gives us insight into how we can solve the equation graphically.\nSo, let's turn the original equation into a system of equations. We can define a variable $y$ and set it equal to the left and then the right side of the original equation. This will give us the following system of equations.\n$y={\\mathrm{log}}_{2}\\left(x+4\\right)$\n$y=3-x$\nNow let's graph the equations.\nWhich of these best approximates the solution to the above system?\n\nIt follows then, that an approximate solution to ${\\mathrm{log}}_{2}\\left(x+4\\right)=3-x$ is $x\\approx 0.75$.\n\n### Reflection question\n\nWhy does it follow that $0.75$ is a solution to the equation ${\\mathrm{log}}_{2}\\left(x+4\\right)=3-x$?\n\nWe can verify our solution by substituting $x=0.75$ into the given equation.\n\n## We did it!\n\nUsing the graphing method, we were able to solve the advanced equation ${\\mathrm{log}}_{2}\\left(x+4\\right)=3-x$.\nWe can use the graphing method to solve any equation; however, the method is particularly useful if the equation cannot be solved algebraically.\n\n## A general method for solving equations by graphing\n\nLet's generalize what we did above.\nHere is a general method for solving equations by graphing.\nStep $1$: Let $y$ be equal to the expressions on both sides of the equal sign.\nStep $2$: Graph the two functions that were created.\nStep $3$: Approximate the point(s) at which the graphs of the functions intersect.\nThe $x$ coordinate of the point(s) where the graphs of the functions intersect will be the solution(s) to the equation.\n\n## Try it yourself\n\nNow let's put it all together. The graphs of $y={2}^{x}-3$ and $y=\\left(x-6{\\right)}^{2}-4$ are shown below.\nWhat is the solution of ${2}^{x}-3=\\left(x-6{\\right)}^{2}-4$?\n$x=$" ]
[ null ]
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https://au.mathworks.com/matlabcentral/answers/1572903-how-to-identify-and-read-positive-and-negative-data-from-excel
[ "# how to identify and read positive and negative data from excel?\n\n17 views (last 30 days)\nVishnuvardhan Naidu Tanga on 27 Oct 2021\nAnswered: Mathieu NOE on 27 Oct 2021\nHello all,\nI am trying to read excel data which has positive and negative. Is there any way to identify the data. I am currently using the following code to identify it. But is theree any other simple way because i need to analyse other data where the number of cells change. Thanks in advance.\nMy code:\nV = 40.020;\nA1 = pi*(X1).^2;\nInt1 = trapz(A1, Y1);\nA2 = pi*(X2).^2;\nInt2 = trapz(A2, Y2);\n\nChetan Bhavsar on 27 Oct 2021\nEdited: Chetan Bhavsar on 27 Oct 2021\n% get data in two columns\ncol_1 = num(:,1);\ncol_2 = num(:,2);\n% get negative index by col_1<0\nNeg_X = col_1(col_1<0);\nNeg_Y = col_2(col_1<0);\n% get positive index by col_1>=0\nPOS_X = col_1(col_1>=0);\nPOS_Y = col_2(col_1>=0);\nA1 = pi*(Neg_X).^2;\nInt1 = trapz(A1, Neg_Y)\nInt1 = 0.5773\nA2 = pi*(POS_X).^2;\nInt2 = trapz(A2, POS_Y)\nInt2 = 0.5789\nVishnuvardhan Naidu Tanga on 27 Oct 2021\nThats fine. I am considering the zero as a positive integer. Thanks once again\n\nMathieu NOE on 27 Oct 2021\nHello\ntry this - it also only need one call to readxls\nX = data(:,1);\nY = data(:,2);\nX1 = X(X<0);\nX2 = X(X>=0);\nY1 = Y(X<0);\nY2 = Y(X>=0);\nV = 40.020;\nA1 = pi*(X1).^2;\nInt1 = trapz(A1, Y1)\nA2 = pi*(X2).^2;\nInt2 = trapz(A2, Y2)" ]
[ null ]
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https://www.encyclopedia.com/social-sciences/applied-and-social-sciences-magazines/time-trends
[ "views updated\n\n# Time Trends\n\nBIBLIOGRAPHY\n\nA time trend, or time index, is the ordered set of natural numbers, for example, t = (1, 2, 3, 4 ), that measures the time span between observations. The slope of a time-trend line represents the growth of a variable. For example, a time-trend line may be used to illustrate growth in production or industry earnings. To predict or explain economic variables, regression equations often use time trends. There are three main reasons for introducing time trends in regression equations that use time-series data. One reason is that a time trend captures the trajectory of the variable over time, providing forecasts of an economic variable. A second reason is that a time trend captures the effect of relevant variables in the regression equation that change over time and are not directly measurable. For example, in the estimation of production functions, Thomas Cooley and Edward Prescott (1973) use a trend variable as a proxy for technological change. A third advantage is that the time trend may capture specification error in regression equations that stem from functional form choice or variable aggregation.\n\nBoth linear and nonlinear time trends may be used in regression equations. The assumption in the linear-trend model is that changes will continue into the future at the same or similar rate. This assumption is particularly restrictive when only more recent observations contribute to explaining the future. A more flexible form is a linear trend under a spline-functional form (nonlinear time trend). The spline function jointly determines the trajectory and the memory of the series by allowing the slope of the time trend to vary across time. For example, the rate of change in the price of gasoline may vary across time. In this case, a time trend in a spline function allows the forecasting model to switch the slope parameters with the current economic regime. Both linear and nonlinear time-trend functions may be used in forecasting economic series such as prices, inventories, productivity, and consumption.\n\nIn addition to its uses in forecasting, a time trend serves as a proxy for nonmeasurable variables when explaining economic relationships, and it is commonly used in consumption models as well as in models that explain production, employment, and other factors of production. For example, food consumption is often specified as a function of personal disposable income, the price of food, the price of other goods, and a time trend. The time trend captures changes in consumer preferences.\n\nA time trend also captures omitted information from specification error that stems from functional form choice or variable aggregation in the regression equation. The effectiveness of a time trend as a proxy for the omitted information from specification error depends on its correlation to included and excluded information in the regression equation, as well as the choice of functional form for the time trend in the equation. In a simulation study, Camilo Sarmiento and Richard Just (2005) provide evidence that a time trend is able to capture variation of the aggregation error (a special form of specification error) in aggregate consumption functions more effectively than methods based on conceptually accurate, time-specific approximations.\n\nClive Granger (2001) indicates the potential and unexplored uses of varying coefficients to approximate functional form in applications that use time series data. A time trend as an interaction variable in the model can be used to introduce time-varying coefficients and, thus, approximate unobserved functional structure in economic models, while reducing dimensionality issues in the specification of the functional form from the m -dimensional space (number of explanatory variables in the model) to the simpler one-dimensional space. The functional form for the time trend as an interactive variable in the regression equation could be linear or nonlinear. Significant empirical work and simulation analysis is needed in this area.\n\nThe popularity of a time trend in many economic models stems from its simplicity and intuitive interpretation. Statistical tests may be used to evaluate the effectiveness of time trends in forecasting and regression equations. Effectiveness depends largely on the application. The choice of time trend as a tool in model building involves not only whether to include a time trend and its functional form (spline function), but also whether to include it as an interactive variable.\n\n## BIBLIOGRAPHY\n\nCooley, Thomas F., and Edward C. Prescott. 1973. Systematic (Non-random) Varying Parameter Regression: A Theory and Some Applications. Annals of Economic and Social Measurement 16: 463474.\n\nGranger, Clive W. J. 2001. Macroeconomics: Past and Future. Journal of Econometrics 100: 1719.\n\nSarmiento, Camilo, and Richard E. Just. 2005. Empirical Modelling of the Aggregation Error in the Representative Consumer Model. Applied Economics 37: 11631175.\n\nCamilo Sarmiento" ]
[ null ]
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https://acsolutions.lu/monte-carlo-simulation-in-scrum/
[ "", null, "Monte Carlo simulation could help to “estimate” the probable range of a sprint.\n\nIn order to demonstrate this, I have prepared a small Excel sheet which could be downloaded and I will explain how it works.\n\nThe idea is to use a set of story points and simulate several scenarios in order to have a kind of tendency.", null, "The column Sprint [A] provides a history of 20 sprints.\nThe columns available story point comes from the initial estimations.\nColumn [C] contains the actual Story points completed over the sprints.\nI will not describe now the columns [D,E,F,G], I will discuss this in another subject (maybe).\n\nWhat is important here is to define a mean to resample a set of these sprints, I have done that over the column [J] & [K].\nThe formula I have used is\n\n[J2]<=====>[K2]\n=J2+1<==>=INDEX(B\\$2:B\\$21,RANDBETWEEN(1,ROWS(B\\$2:B\\$21)),1)\nThe K column provide a means to provide a random value from the column [B] which contains “effective” story point.\nEach time you press F9 you will have another set of values.\n\nSo it’s a bit like having twenty balls in a basket and you pick them off and you are able to repeat this several times.\n\nColumns [N] and [O] are a representation of these Sprints repeated several times, in this case 201.\nSo [N] is the Sprint number and the column [O] formula is SUM(\\$K\\$2:\\$K\\$21) which is the number of Story points after 20 Sprints.\n\nA quick way to set this data over is to use the condition What If (not the TV series 😉 but the Excel function).", null, "Now, you can press F9 to obtain another set of data, and let’s say that you are willing to check the probability that the team could achieve 530 story points over 20 Sprints.\n\nThis what you might be looking for.", null, "" ]
[ null, "https://secure.late6year.com/201110.png", null, "https://acsolutions.lu/wp-content/uploads/2019/09/Monte-Carlo.jpg", null, "https://acsolutions.lu/wp-content/uploads/2019/09/MonteCarlo-test.jpg", null, "https://acsolutions.lu/wp-content/uploads/2019/09/MonteCarlo-test2.jpg", null ]
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https://ijnaa.semnan.ac.ir/article_252.html
[ "### Polarization constant $\\mathcal{K}(n,X)=1$ for entire functions of exponential type\n\nDocument Type : Research Paper\n\nAuthors\n\n1 Civil Engineering Department, School of Technological Applications, Piraeus University of Applied Sciences (Technological Education Institute of Piraeus), GR 11244, Egaleo, Athens, Greece\n\n2 adepartment of electronics engineering, school of technological applications, technological educational institution (tei) of piraeus, gr 11244, egaleo, athens, Greece.\n\n3 Department of Electronics Engineering, School of Technological Applications, Piraeus University of Applied Sciences (Technological Education Institute of Piraeus), GR 11244, Egaleo, Athens, Greece\n\nAbstract\n\nIn this paper we will prove that if $L$ is a continuous symmetric n-linear form on a Hilbert space and $\\widehat{L}$ is the associated continuous n-homogeneous polynomial, then $||L||=||\\widehat{L}||$. For the proof we are using a classical generalized  inequality due to S. Bernstein for entire functions of exponential type. Furthermore we study the case that if X is a Banach space then we have that\n$$|L|=|\\widehat{L}|, \\forall L \\in{\\mathcal{L}}^{s}(^{n}X).$$\nIf the previous relation holds for every $L \\in {\\mathcal{L}}^{s}\\left(^{n}X\\right)$, then spaces ${\\mathcal{P}}\\left(^{n}X\\right)$ and  $L \\in {\\mathcal{L}}^{s}(^{n}X)$ are isometric. We can also study the same problem using Fr$\\acute{e}$chet derivative.\n\nKeywords" ]
[ null ]
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https://e-baketabam.ir/shop/psychology/P1463-heads-up-psychology-marcus-weeks-dk-series.html
[ "", null, "۰\nسبد خرید", null, "هر روز با کتاب‌های بیشتر", null, "# Heads Up Psychology - Marcus Weeks | DK Series\n\nکد محصول: eSHB-1391\n۱۰,۷۹۰ تومان", null, "افزودن به سبد خرید\n• درباره کتاب\n• بخشی از کتاب\n• نظرات\n•", null, "• ## تخفیف ویژه | اولین سفارش\n\n<% if (product.thumbnail) { %>", null, "<% } %>\n<% if (product.price_label) { %>\n<%- (product.price_label.toString()) %>\n<% } else { %>\n\n### <%- product.title %>\n\n<% if (Array.isArray(product.attributes)) { %>\n<% _.forEach(product.attributes, function(attribute, index) { %>\n• <%- attribute.name %>: <%- attribute.value %>\n• <% }); %>\n<% } %>\n<% if (product.in_stock == 1) { %>\n<% if (product.sale_price) { %><%- (product.price.toString().formatNumber().convertToLocalNumber() + currency_sign) %><%- (product.sale_price.toString().formatNumber().convertToLocalNumber() + currency_sign) %><% } else { %><%- (product.price.toString().formatNumber().convertToLocalNumber() + currency_sign) %><% } %>\n<% } else { %>\nاتمام موجودی\n<% } %><% } %>\n<% if (product.ribbon) { %>\n<%- product.ribbon %>\n<% } %><% if (product.sale_amount) { %><% if (product.in_stock==1) { %>\n<% if (product.sale_type==2) { %> <%- ((product.sale_amount).toString().formatNumber().convertToLocalNumber() + currency_sign) %><% } else { %> <%- (product.sale_amount.toString().formatNumber().convertToLocalNumber()) %> درصد <% } %>\n<% } %><% } %>", null, "رمز عبورتان را فراموش کرده‌اید؟\n\nثبت کلمه عبور خود را فراموش کرده‌اید؟ لطفا شماره همراه یا آدرس ایمیل خودتان را وارد کنید. شما به زودی یک ایمیل یا اس ام اس برای ایجاد کلمه عبور جدید، دریافت خواهید کرد.\n\nبازگشت به بخش ورود\n\nکد دریافتی را وارد نمایید.\n\nبازگشت به بخش ورود\n\n### مشاهده سفارش\n\n<%- order.customer_name.toString() %>\n<%- order.id.toString().convertToLocalNumber() %>\n<%- order.customer_province.toString() %>-<%- order.customer_city.toString() %>-<%- order.customer_address.toString() %>\n<%- order.customer_mobile.toString().convertToLocalNumber() %>\n<%- order.shipping_name.toString() %>\n<%- (Number(order.total_shipping).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<%- order.payment_method_name.toString() %>\n<%- (Number(order.total).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<% if(order.tracking_number) { %>\n<%- order.tracking_number.toString() %>\n<% } %>\nنام محصول\nتعداد\nقیمت واحد\nقیمت کل\nتخفیف\nقیمت نهایی\n<% \\$.each(products, function(index,product) { %>", null, "<%- product.name %>\n<%- product.quantity %>\n<%- (Number(product.original_price).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<%- (Number(product.original_price*product.quantity).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<%- (Number(product.discount).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<%- (Number(product.total).toString().formatNumber().convertToLocalNumber() + currency_sign) %>\n<% }); %>\n<% if(!orders.length) { %>\n\nشما هنوز هیچ سفارشی ثبت نکرده‌اید.\n\n<% } else { %>\n• شماره سفارش\nتاریخ سفارش\nپرداخت\nوضعیت\nجمع نهایی\n• <% \\$.each(orders, function(index,order) { %>\n• <%- order.id.toString().convertToLocalNumber() %>" ]
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https://www.scienceforums.net/profile/34382-kumarevo/
[ "", null, "", null, "# kumarevo\n\nMembers\n\n11\n\n## kumarevo's Achievements", null, "-1\n\n### Reputation\n\n1. $\\frac{Z}{{{{10}^n}}}= {\\rm ?}$ 1.Z÷(10^n)=? a={0,1,2,3,4,5,6,7,8,9} , b={1,2,3,4,5,6,7,8,9} n=1 , Z÷10={...,(-2÷10),(-1÷10),(0÷10),(1÷10),(2÷10),...}={...,-0.2,-0.1,0,0.1,0.2,...}={Z,Z.b} n=2 , Z÷100={Z,Z.b,Z.ab} n=3 , Z÷1000={Z,Z.b,Zab,Zaab} n=4 , Z÷10000={Z,Z.b,Z.ab,Zaab,Zaaab} ...\n2. Presupposition-numbers have opposite points Process: P1 0=(s.0) P2 1={(s.0),(s.1)} P3 2={(s.0),(s.1),(s.2)} P4 3={(s.0),(s.1),(s.2),(s.3)} P5 4={(s.0),(s.1),(s.2),(s.3),(s.4)} ... ... [s7]-number opposite points CM-[s7]does not know ______________ Presupposition-numbers are comparable with each other Process: P1-two numbers (a, b ) are comparable with each other - a> b, a =b, a <b, ).(=(>,=,<) P2-three numbers (a, b, c) are comparable with each other P3-four numbers (a, b, c, d) are comparable with each other ... [s8]-comparability numbers CM-[s8]known two of comparability, comparability of three numbers(a number comparable with the numbers b and c), comparability of the other knows.\n3. I initially gave you three questions, first can be solved by the present knowledge of mathematics (so please solve it, you'll get an interesting result, which calls into question some sets of numbers), the second task will not be resolved because it knows that the current math functions can be final and only the set of natural numbers, the third task will not be resolved because the math does not know the current gap number and several forms of calculation subtraction. what I've realized that the whole thing in math geometry, and that everything is a ratio of two (more) geometrical object in a line, plane, n-volume, I am totally rejected the historical legacy that has a current math, I started from the first geometry object (along natural) and the concept of point and a basic rule to connect the two (more) along the natural area this is the first axiom and it does not prove,each new object (concept, calculation, ...) occurs along the natural object or arising out along natural ...\n4. NATURAL MATHEMATICS Presupposition-natural long merge points in the direction of the first natural along AB Process: P1-AB..CD..ABC(AC) to read- natural along AB to point B, is connected to the natural long CD to point C, shall be P2-ABC(AC)..DE..ABCD(AD) read- along the ABC(AC) to point C , connecting with the natural long DE to point D is done renaming of points , we get along ABCD(AD) P3-ABCD(AD)..EF..ABCDE(AE) ... [s3]-along (natural basis) Definition[along]-the first and last point and the distance between points CM-[s3]-does not know _________________________________________________________________________________ Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0,1 ),..., (0,1,2,3,4,5,6,7,8,9 ),... Process: P1-N (0) = {0,00,000,0000,...} P2-N (0,1) = {0,1,10,11,100,...} ... P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...} ... [s4]-number along [s5]-set of natural numbers N We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12,...} Definition[number along]- a starting point (0), the last point at infinity [number N]-The number 0 is the point 0 -Other numbers are longer, the first item is 0, the last point is the point of the name (number) CM-[s4].does not know , [s5]-axiom _______________________ Presupposition-Numbers have their points Process: P1 0=(.0) P2 1={(.0),(.1)} P3 2={(.0),(.1),(.2)} P4 3={(.0),(.1),(.2),(.3)} P5 4={(.0),(.1),(.2),(.3),(.4)}... [s6]-number points CM-[s6]does not know\n5. questions 1.Z÷(10^n)=?,Z-integers 2.write in abbreviated form (if the function can be final and natural) 2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40, 2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 , 2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94 3.how to solve this current knowledge of mathematics: along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c (image) Can mathematics explain the only two axiom that the rest are just evidence (experiments), if you think so join me show you Srdanova math, see you __________________________________________________ ______________ I figure this way, from education school has 12 years, I was always the subject of mathematics and physics had the best grades, math deal amateur, studying mathematics I came to know that mathematics can be simplified and be connected (to be explained only with two axiom) and extend the mathematics that can solve math problems that present no solution. Marjanovic Srdan M.Biljanica natural axiom What is \" nature along \"? -nature along in figure 1 What is \"point\"? -start (end) natural long in figure 2 What is the \" basic rule \"? -basic rule is determined that the two ( more) longer only have to connect the points [sn]-mathematical facts [s1]-nature along [s2]-point (natural meaning of) Definition[natural along]-two points , distance between two points CM (current mathematics)-[s1]-does not know , [s2]-point is not defined , so anything and everything\n6. Are you saying that a point do not exist? because a point has a length? I (MS.0) showed evidence that the length (area, volume) does not consist of points.Point there (I have defined MS.0). __________________________________________________________________________________________________________ MS.5. Copying from the basic set of numbers into another set of skup.Re-set. From the basic set of numbers are copied ((;)with repetition without repetition, finally, endless, combined) in the second set. Re-set (; is the release of a set of number brackets (code sets, = sign) to another form of description set.Re-set together with a number, just remove the brackets (code set, character =). MS.6. Re-set set- frequency. Sign connecting _ (minimum 2) re-set sets. Same set of numbers (minimum 2) to re-set in frequency. Form: a (number) f (mark frequency), b (as there are same number), b (end frequency). Simple form. To understand my math read all articles marked MS. (of evidence). kumarevo.ms @ gmail.com MS.7.Re-set set-srcko. Set of numbers (minimum 2) where the distance to the furthest point to the same re-set in srcko. Form:a (initial number), b (distance), c (final number, if there is srcko final, unless there is srcko is infinite). Simple form. MS.8.Re-set set-frequency + pendant. Re-set meeting (frequency) joined the other numbers (minimum 1) that are not in re-set frequency. Form (number) f (mark frequency), b (as there are same number), b (end frequency), c (pendant-number). Simple form.\n7. MS.3. Cycle connection (2.1) the direction AB. Along. The cycle of connection (2.1 (final, infinite)) in the direction AB. Along the required form of natural line (series connection (2.1) the direction of AB), can be finite or infinite To understand my math read all articles marked MS. (of evidence). kumarevo.ms @ gmail.com MS.4. Cycle signs. The main set of numbers-natural numbers. Numerical along. The first point (A), connecting the points (B, C, D,...) in a cycle of (2.1 (the direction AB,infinite (along numeric)))replace the cycle of signs: (0,1), (0,1,2), (0,1,2,3), (0,1,2,3,4), (0,1,2,3, 4.5),(0,1,2,3,4,5,6), (0,1,2,3,4,5,6,7) (0,1,2,3,4,5,6,7,, (0,1,2,3,4,5,6 , 7,8,9), (0,1,2,3,4,5,6,7,8,9, A), (0,1,2,3,4,5,6,7,8,9, A, B ),.... , cycle signs we'll call numbers. In today's applied mathematics series characters: (0.1), (0,1,2,3,4,5,6,7),(0,1,2,3,4,5,6,7,8 , 9), (0,1,2,3,4,5,6,7,8,9, A, B, C, D, E, F). We will apply (0,1,2,3,4,5, 6,7,8,9) because he isa mass use. Set the current math axiom, mine is a basic set of numbers (N = {0,1,2,3,4,5,...}. To understand my math read all articles marked MS. (of evidence). kumarevo.ms @ gmail.com\n8. MS.2. Fit natural cycles along. Naturally along the lines. Uniform (finite, infinite) cycle, the forms (2.1) (3.1) (4.1 ),.. The combined (final, infinite) cycle, combinations of natural connection longer. example (small image) All these cycles are natural along the line.\n9. MS.1. Connecting natural longer. Natural longer connecting points. Types of mergers: (2.1) (3.1) (4.1 )..... To understand my math read all articles marked MS. (of evidence). kumarevo.ms @ gmail.com\n10. Mathematics as we know is limited, there are mistakes. The first error of mathematics: length (area, volume) consists of the points. Look at the evidence which shows that the length includes the length, size of area,volume by volume. Then you wonder what is the point. (larger image) I am a mathematician, inventor. My basis for an axiom (definition point, along a natural). Everything else is proved in the space, get to know my math, expand their knowledge. MS.0. The basic axiom. Definition point. Natural along. Beginning (end) is longer than the natural point. Natural along with two points, the lengthbetween points. (small image) To understand my math read all articles marked MS. (of evidence). kumarevo.ms @ gmail.com\n×" ]
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https://en.wikipedia.org/wiki/Ideal_point
[ "# Ideal point\n\nIn hyperbolic geometry, an ideal point, omega point or point at infinity is a well-defined point outside the hyperbolic plane or space. Given a line l and a point P not on l, right- and left-limiting parallels to l through P converge to l at ideal points.\n\nUnlike the projective case, ideal points form a boundary, not a submanifold. So, these lines do not intersect at an ideal point and such points, although well-defined, do not belong to the hyperbolic space itself.\n\nThe ideal points together form the Cayley absolute or boundary of a hyperbolic geometry. For instance, the unit circle forms the Cayley absolute of the Poincaré disk model and the Klein disk model. While the real line forms the Cayley absolute of the Poincaré half-plane model .\n\nPasch's axiom and the exterior angle theorem still hold for an omega triangle, defined by two points in hyperbolic space and an omega point.\n\n## Properties\n\n• The hyperbolic distance between an ideal point and any other point or ideal point is infinite.\n• The centres of horocycles and horoballs are ideal points; two horocycles are concentric when they have the same centre.\n\n## Polygons with ideal vertices\n\n### Ideal triangles\n\nif all vertices of a triangle are ideal points the triangle is an ideal triangle.\n\nSome properties of ideal triangles include:\n\n• All ideal triangles are congruent.\n• The interior angles of an ideal triangle are all zero.\n• Any ideal triangle has an infinite perimeter.\n• Any ideal triangle has area $\\pi /-K$", null, "where K is the (negative) curvature of the plane.\n\nWhile all ideal triangles are congruent, not all quadrilaterals are; the diagonals can make different angles with each other resulting in noncongruent quadrilaterals. Having said this:[clarification needed]\n\n• The interior angles of an ideal quadrilateral are all zero.\n• Any ideal quadrilateral has an infinite perimeter.\n• Any ideal (convex non intersecting) quadrilateral has area $2\\pi /-K$", null, "where K is the (negative) curvature of the plane.\n\n### Ideal square\n\nThe ideal quadrilateral where the two diagonals are perpendicular to each other form an ideal square.\n\nIt was used by Ferdinand Karl Schweikart in his memorandum on what he called \"astral geometry\", one of the first publications acknowledging the possibility of hyperbolic geometry.\n\n### Ideal n-gons\n\nAn ideal n-gon can be subdivided into (n − 2) ideal triangles, with area (n − 2) times the area of an ideal triangle.\n\n## Representations in models of hyperbolic geometry\n\nIn the Klein disk model and the Poincaré disk model of the hyperbolic plane the ideal points are on the unit circle (hyperbolic plane) or unit sphere (higher dimensions) which is the unreachable boundary of the hyperbolic plane.\n\nWhen projecting the same hyperbolic line to the Klein disk model and the Poincaré disk model both lines go through the same two ideal points (the ideal points in both models are on the same spot).\n\n### Klein disk model\n\nGiven two distinct points p and q in the open unit disk the unique straight line connecting them intersects the unit circle in two ideal points, a and b, labeled so that the points are, in order, a, p, q, b so that |aq| > |ap| and |pb| > |qb|. Then the hyperbolic distance between p and q is expressed as\n\n$d(p,q)={\\frac {1}{2}}\\log {\\frac {\\left|qa\\right|\\left|bp\\right|}{\\left|pa\\right|\\left|bq\\right|}},$", null, "### Poincaré disk model\n\nGiven two distinct points p and q in the open unit disk then the unique circle arc orthogonal to the boundary connecting them intersects the unit circle in two ideal points, a and b, labeled so that the points are, in order, a, p, q, b so that |aq| > |ap| and |pb| > |qb|. Then the hyperbolic distance between p and q is expressed as\n\n$d(p,q)=\\log {\\frac {\\left|qa\\right|\\left|bp\\right|}{\\left|pa\\right|\\left|bq\\right|}},$", null, "Where the distances are measured along the (straight line) segments aq, ap, pb and qb.\n\n### Poincaré half-plane model\n\nIn the Poincaré half-plane model the ideal points are the points on the boundary axis. There is also another ideal point that is not represented in the half-plane model (but rays parallel to the positive y-axis approach it).\n\n### Hyperboloid model\n\nIn the hyperboloid model there are no ideal points." ]
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https://cbp.tnw.utwente.nl/PolymeerDictaat/node32.html
[ "", null, "", null, "", null, "", null, "", null, "Next: Appendix A Up: Stochastic processes Previous: The Smoluchowski time scale\n\n# The Smoluchowski equation\n\nWe shall now derive the equivalent of the Fokker-Planck equation, but this time applicable at the Smoluchowski timescale.\n\nSuppose we are given a distribution", null, "of particles which were at position", null, "at time t=0. We assume that the particles are at every instant of time in thermal equilibrium with respect to their velocities. A flux will exist, given by", null, "(4.29)\n\nwhere D is the diffusion constant , occurring in", null, ", and", null, "is the friction coefficient  on the Smoluchowski timescale. At equilibrium, the flux must be zero and the distribution be equal to", null, "(4.30)\n\nUsing this in Eq. (4.29) while setting", null, ", leads to the Einstein equation (4.13).\n\nIntroducing Eq. (4.29) into the equation of particle conservation", null, "(4.31)\n\nwe get the Smoluchowski equation", null, "=", null, "(4.32)", null, "=", null, "(4.33)\n\nIn the remaining part of this section we shall substantiate the above derivation. First we define the particle distribution on the Smoluchowski timescale by", null, "=", null, "(4.34)", null, "=", null, "(4.35)\n\nAveraging the Fokker-Planck equation  over the initial velocities and integrating over", null, ", we find the continuity equation Eq. (4.31), with", null, "=", null, "=", null, "(4.36)\n\nwhere the second step serves to define the velocity", null, "at time t at position", null, ", given that the particle was originally at", null, ".\n\nWe next derive an equation describing the time development of the velocity", null, ". To this end we multiply the Fokker-Planck equation by", null, ", average over the initial velocities, and integrate over", null, ", obtaining", null, "(4.37)\n\nUsing the continuity equation  and rearranging we find", null, "(4.38)\n\nIn a strongly damped system the integral on the right hand side yields the velocity fluctuation at position", null, ", multiplied by the probability to find the particle at position", null, ", which is GkT1/m. On the left hand side we recognize the acceleration of the particle at", null, "(see section 5.1). Eq. (4.38) may then be written as", null, "(4.39)\n\nIn a strongly damped system the average particle velocity is almost constant. We therefore put the left hand side of Eq. (4.39) equal to zero and solve for", null, ". Introducing the result into Eq. (4.36) we find the flux Eq. (4.29) and next the Smoluchowski equation. In Eq. (4.39)", null, "is called the Brownian force.\n\nIn appendix B we shall present an alternative derivation of the Smoluchowski equation. In appendix C we will demonstrate that the Langevin equations (4.27), (4.28) are equivalent to the Smoluchowski equation.", null, "", null, "", null, "", null, "", null, "Next: Appendix A Up: Stochastic processes Previous: The Smoluchowski time scale\nW.J. Briels" ]
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https://csmbrannon.net/2011/09/11/convergence-of-nonlinear-solvers/
[ "# Tutorial: assessing convergence of nonlinear solvers\n\nGiven software that finds a value of x that makes", null, "$f(x)=0$, how do you infer the rate of convergence of the algorithm embedded in the software?  The answer is to do some tests for which you know the answer.  Shown below are convergence plots of the error", null, "$\\left(e_i = |x_i-x^\\text{exact}|\\right)$ for three solver methods applied to find a zero of the function", null, "$f(x)=(x-1.5)(x-2.3)$. In all cases, the first guess is taken so that the root", null, "$x=1.5$ is found by the solvers. The errors at each iteration are used to generate points on a convergence plot as indicated.  The slope of the plot is the rate of convergence. The zip file, 5newtonIterationErrorConvergenceAnalysis.zip, contains the Mathematica commands (.pdf and .nb) used to conduct this study.\n\n(a) Classical Newton-Raphson", null, "Classical Newton-Raphson iteration, here applied to find the zero of the function (x-1.5)(x-2.3) using a starting guess of x=0, has approximately second-order convergence (slope of the line).\n\n(b) Modified Newton-Raphson:", null, "The modified Newton-Raphson method, which uses the function slope at the first iteration for all subsequent iterations, has approximately first-order convergence and thus requires more iterations (more red dots).\n\n(c) Secant solver:", null, "Convergence for a secant solver, in which the function slope is approximated by the secant connecting two first guesses (x=0 and x=0.5), showing a convergence rate (slope of this line) somewhere between 1st-order and 2nd-order\n\nThe zip file, 5newtonIterationErrorConvergenceAnalysis.zip, contains the Mathematica commands (.pdf and .nb) used to conduct this study." ]
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https://binews.org/what-is-pulse-amplitude-modulation/
[ "Tuesday, February 25, 2020\nEducation\n\n# What is Pulse Amplitude Modulation", null, "Pulse Amplitude Modulation is the basic form of pulse modulation in which the signal is sampled at regular intervals such that each amplitude and sample are proportional. Let’s study the basics of modulation.\n\nWhat is modulation?\n\nModulation is defined as the process of changing the characteristics of a carrier signal. Frequency, amplitude, and width are the characteristics of the signals.\n\nModulation types\n\nFollowing are the types of modulation:\n\n1. Continuous-wave modulation\n\n• Amplitude modulation\n• Angle modulation\n• Frequency modulation\n• Phase modulation\n\n2. Pulse modulation\n\n• Analog modulation\n• PAM (Pulse Amplitude Modulation)\n• Single polarity PAM\n• Double Polarity PAM\n• PWM (Pulse Width Modulation)\n• PPM (Pulse Position Modulation)\n• Digital modulation\n• Pulse code modulation\n• Delta modulation\n\nContinuous-wave Modulation\n\nIn continuous wave modulation, the carrier signal is modulated depending on the three parameters namely: frequency, amplitude and phase. Therefore, continuous-wave modulation is classified as:\n\n1. Amplitude modulation\n2. Frequency modulation\n3. Phase modulation\n\nPulse Modulation\n\nIn pulse modulation, the information is carried by the signals in pulses. Pulse modulation is divided into analog pulse modulation and digital pulse modulation.\n\nAnalog pulse modulation is further classified as PPM, PWM and PAM.\n\nPulse Amplitude Modulation\n\nPulse amplitude modulation is a technique in which the amplitude of each pulse is controlled such that they are proportional to the instantaneous amplitude of the message signal. Pulse amplitude modulation (PAM) is obtained from the pure sine wave. Following are the types of sampling techniques for transmitting the signal using PAM.\n\n• Flat top PAM: At the time of pulse occurrence, the amplitude of each pulse is proportional to the amplitude of the modulating signal such that the peaks of the amplitude remain flat.\n• Natural PAM: At the time of pulse occurrence, the amplitude of each pulse is proportional to the amplitude of the modulating signal such that the amplitude of the pulse follows the half cycle for the rest of the process.\n\nTypes of PAM\n\nFollowing are the types of PAM:\n\n1. Single Polarity PAM\n2. Double Polarity PAM\n\nApplications of PAM\n\nFollowing are the application of PAM:\n\n1. Photobiology uses of PAM\n2. PAM is used for LED lighting in an electronic driver\n3. PAM is used in micro-controllers for generating controlled signals" ]
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https://algebra-net.com/homework-tutorials/elementry-algebra-formulas.html
[ "Try the Free Math Solver or Scroll down to Resources!\n\n Depdendent Variable\n\n Number of equations to solve: 23456789\n Equ. #1:\n Equ. #2:\n\n Equ. #3:\n\n Equ. #4:\n\n Equ. #5:\n\n Equ. #6:\n\n Equ. #7:\n\n Equ. #8:\n\n Equ. #9:\n\n Solve for:\n\n Dependent Variable\n\n Number of inequalities to solve: 23456789\n Ineq. #1:\n Ineq. #2:\n\n Ineq. #3:\n\n Ineq. #4:\n\n Ineq. #5:\n\n Ineq. #6:\n\n Ineq. #7:\n\n Ineq. #8:\n\n Ineq. #9:\n\n Solve for:\n\n Please use this form if you would like to have this math solver on your website, free of charge. Name: Email: Your Website: Msg:", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "OUR USERS", null, "", null, "", null, "Thanks for making my life a whole lot easier!\nDana Boggs, VT\n\nAlgebra Professor really makes algebra easy to use.\nMay Sung, OK\n\nI have two children that are average students. They do fine in most subjects but math has always stumped them. They found your algebra software to be like an in-home tutor. Im happy to say their marks are finally going up.\nLaura Keller, MD\n\nIf you are having trouble with complicated algebra equations I have two words for you: the Algebra Professor! Try it, I guarantee you will see results in your mathematical performance. It helped me and my friends pass our tough freshman math class.\nMichael Tanskley, CA\n\nStudents struggling with all kinds of algebra problems find out that our software is a life-saver. Here are the search phrases that today's searchers used to find our site. Can you find yours among them?\n\nSearch phrases used on 2010-03-18:\n\n• converting stereo coordinates to lat/long\n• online calculator fractions to decimals\n• Simplifying rational expressions worksheet\n• How to sove 3 simultaneous equations in Algebra\n• graphing calculator 1st and 2nd derivative\n• solve the system of eaquations by graphing on TI 89\n• simplify radical expressions by factoring\n• teach me to do algebra 2\n• lesson plan on dividing integers\n• transforming formulas pre algebra\n• maths problems on ratios circles grade 9\n• online variable calculator\n• ti-89 leaves numbers in fraction form when dividing\n• ti rom code\n• Simplify Calculator Square Root Support\n• online graphing calculator with table\n• Rational Expression Solver\n• general maths mcqs\n• texas instruments ti-83 plus cubed squared\n• math tutor first year college\n• Printable Practice SOLs\n• south carolina's 9th honors english eoc test\n• ti-84+ differential equation\n• online calculator rational expression\n• lesson plan on polynomials\n• subtracting negative and positive fractions\n• algebra exponents solve\n• maths find a rule worksheets\n• java reducing a mathamatical formula\n• who invented perpendicular symbol\n• javascript percentage symbol\n• math questions for yr 8\n• graphing parabolic equations\n• maths quiz questions ks3\n• lesson plan on factoring\n• Solve simultaneous equations on calculator\n• word problems fractions ks3\n• TI-83 exponential graphing equation\n• prentice hall mathematics book\n• factoring expressions\n• polar formula\n• free fourth grade fraction simplifying practice problems\n• maths formula questions\n• +\"practice problems\" +sequences +\"changing difference\"\n• RADICAL AND RATIONAL EXPONENTS CALCULATOR\n• free trial \"my mathematical life\"\n• ks4 algebra\n• online fraction calculator\n• who discovered the formula forPi\n• simplify algebra math problems\n• South Carolina Mathematics Standards for Algebra 1 Mcdougal Littell practice test 1 answers\n• elementary algebra practice probems with angles\n• solving binomial\n• ti84.rom\n• LEVEL F MATHS TEST PRACTICE SHEETS\n• boolean algebra examples with solutions\n• coreplus worksheets\n• \"intermediate accounting\" cd \"answer key\"\n• Free Online Math Tutor\n• algebra worksheet excecise\n• math test papers grade 6\n• maths pratice papers for 8 year old\n• algebra ks2 intro\n• math standard notation\n• factoring cubed variables\n• practice 6th grade eog questions\n• prentice hall mathematics", null, "", null, "" ]
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https://fincad.com/resources/resource-library/article/next-generation-variance-derivatives
[ "## Resources\n\nFINCAD offers the most transparent solutions in the industry, providing extensive documentation with every product. This is complemented by an extensive library of white papers, articles and case studies.\n\nNext Generation Variance Derivatives\n\nFINCAD F3 is an enterprise portfolio and risk analytics solution that provides industry standard modeling and analytics with broad asset class coverage and flexibility to model virtually any instrument including complex derivatives such as Corridor Variance Swaps.\n\nFINCAD Analytics Suite includes coverage of variance and volatility derivatives by adding functions for the valuation of next generation variance derivatives, such as conditional variance swaps and options on future realized variance.\n\n## Overview\n\nA variance swap is a forward contract on future realized price variance. It allows investors to take views on future variance (or volatility) without sensitivity to the level of the underlying asset price. Variance swaps can be used to protect against falling markets, since usually volatility (and therefore variance, which is the square of volatility) rises when markets fall.\n\nThe corridor variance swap and the conditional variance swap are more exotic versions of the vanilla variance swap. In short these next generation variance derivatives accumulate variance only if the price of the underlying asset is within a certain range (the corridor). These instruments provide more flexibility to the investor, as the instrument can be targeted at specific market conditions by selecting the corridor appropriately. A popular instrument is the conditional down variance swap which only accumulates variance if the underlying asset price falls below a pre-determined barrier. This instrument can be very effective in protecting against falling markets. It provides income when the underlying price falls and realized variance rises above the strike but remains at zero value if the asset price stays above the barrier.\n\nOptions on future realized variance provide another means for investors to take views on variance. These are options that pay out on the realized variance during the life of an underlying variance swap whose fixed rate equals the strike of the option.\n\nFINCAD Analytics Suite 2009 provides functions to value conditional and corridor variance swaps and options on realized variance in the Heston model of stochastic volatility.\n\nA conditional variance swap only accumulates realized variance in the floating leg and the fixed variance (\"strike\") in the fixed leg, if the underlying price is within a pre-determined range. The payoff of a swap with principal P (in units of $per volatility point squared) and variance strike KVar is therefore", null, "Up and down variance swaps are the two principal types in the market. Up variance swaps only accrue realized variance when the underlying stays above a pre-specified barrier U (i.e. Si > U), whereas down variance swaps only accrue realized variance when the underlying is below the barrier D (i.e., Si ≤ D). Conditional down-variance swaps are particularly useful to protect against falling markets. The swap remains worthless as long as the underlying price stays above the barrier D, but it accrues variance as markets fall and the investor gains if the variance is larger than the strike. The biggest risk for the buyer of conditional variance is that the underlying price falls below the price barrier, but variance remains small. FINCAD Analytics Suite 2009 provides functions to value these swaps in the Heston model: aaCondVarianceSwap_Heston_p calculates the price and risk statistics of a conditional variance swap. aaCondVarianceSwap_Heston_iv calculates the fair strike and risk statistics of a conditional variance swap. ## Corridor Variance Swaps Corridor variance swaps are very similar to conditional variance swaps; they only accrue realized variance if the underlying price is within a certain range. However, the fixed leg always accrues. Using the notation above, we can write the payoff as", null, "Similar to the conditional down variance swap, a corridor down variance swap can be useful to protect against falling markets, when volatility is large. The biggest risk for the buyer of a corridor variance swap is that the underlying price never enters the range specified in the contract. FINCAD Analytics Suite 2009 provides functions to value these swaps in the Heston model: aaCorrVarianceSwap_Heston_p calculates the price and risk statistics of a corridor variance swap. aaCorrVarianceSwap_Heston_iv calculates the fair strike and risk statistics of a corridor variance swap. ## Options on Realized Variance An option on realized variance gives the holder the right to enter into a variance swap at its expiry. The underlying of this option is therefore the variance that accumulated during the term of the option. The payoff for a call option is", null, "The buyer of a call option gains when realized variance rises above the expected level determined by the strike, but is protected from smaller than expected realized variance. Conversely, the holder of a put option gains when realized variance is below the expected level as determined by the strike, and is protected from large realized variance. FINCAD Analytics Suite 2009 provides functions to value options on variance in the Heston model: aaVarianceOption_Heston_p calculates the price and risk statistics of an option on realized variance. aaVarianceOption_Heston_iv calculates the implied volatility smile for options on realized variance. ## Valuation in the Heston Model of stochastic volatility Vanilla variance and volatility swaps can be replicated with a portfolio of European options. The valuation of the next-generation variance derivatives described above cannot be done without a model for the volatility process, because conditional and corridor variance swaps depend on the price path of the underlying asset and because of the optionality in the option on variance. In the Heston model both the price S with drift and the variance V follow a stochastic process ,", null, "Pricing variance derivatives in the Heston model comes down to computing the expected conditional variance (or optionality in the case of the variance option). The FINCAD functions implement the quasi-closed form solutions for pricing these derivatives given in [2, 3]. The algorithms require several numerical integration which renders the FINCAD functions quite complicated. ## Example: Pricing a Conditional Down Variance Swap In this example, we calculate the fair strike for a conditional down variance swap at its inception. We intend to enter into a conditional down variance with this fair strike for a three month term on a traded equity. At inception, the equity price is$500 and we set the barrier of the swap at $400. For the valuation in the Heston model we calibrated the model parameters using European options on the equity. We use the FINCAD workbook \"Corridor or Conditional Variance Swap (Heston Model)\" for our calculations. Figure 1 shows the inputs for this example on the worksheet \"Main\". Given the inputs in Figure 1, we find a fair variance of 0:179 which was calculated with the function aaCondVarianceSwap_Heston_iv. Evaluating the fair value using the function aaCondVarianceSwap_Heston_p on the effective date, we indeed find that - up to rounding errors in the fair variance - the fair value of the swap is zero. On December 22, 2008, we use aaCondVarianceSwap_p to compute the present value of the conditional variance swap we bought. We enter the price path of the asset for the past 19 market days on the worksheet \"Realized Var\". Given the particular path, we find that the asset was below the barrier on eight out of the 19 days and that the realized conditional variance is 0:221. These values are linked to the worksheet \"Main\" and we proceed to compute the fair value on December 22, 2008 by only changing the value date on the worksheet. The function returns the fair value in the section \"Results - Fair Value\" to be about$493,000.", null, "Figure 1: Screen shot of the inputs to aaCondVarianceSwap_Heston_iv for the calculation of the fair variance.\n\n## Summary\n\nFINCAD Analytics Suite 2009 provides functions to compute fair strikes, prices and all risk statistics for vanilla variance and volatility swaps as well as second and third generation variance derivatives, such as conditional variance swaps and options on realized variance. As the valuation of these more recent instruments cannot be done without a model for the volatility process, the new FINCAD functions use the Heston model of stochastic volatility to value these instruments.\n\n## References\n\n Heston, S. (1993), A closed-form solution for options with stochastic volatility, Review of Financial Studies, 6: pp. 327-343.\n\n Sepp, Artur (2007), Pricing options on realized volatility in heston model with volatility jumps, Journal of Computational Finance.\n\n Sepp, Artur (March 2007), Variance swaps under no conditions, Risk, pp. 82-87." ]
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http://math-it.com/Mathematik/OR/Container.html
[ "The Posten container problem", null, "A forwarding agent shall supply various articles by container to a supermarket. The container has given capacities of weigt and of volume, whereas the articles have fixed weight, volume, and value per item. How many items of each article should the forwarding agent pack into a container such that the container contents has maximum value under the constraint that given minimum quantities per article are to be supplied?\n\nLet for instance the articles A, B, C as well as the capacity limits of the container be given according to the following table.\n\narticle\n volume (m3/item)\n weight (kg/item)\ndemand\n price (k€/item)\nA 6 3 1 10\nB 3 2 1 8\nC 1 1 1 2\ncapacity 15 8 - -\n\nArticle A thus has a volume of 6 m3 and a weight of 3 kg per item, and must be supplied at least once; its value is 10 000 €.\n\nWith Dynamic Programming, a method of Operations Research, the problem is solved as a multistage decision problem. However, you may solve this small example above by simple enumeration:\n\n1 - 2 - 1     (read: 1x A, 2x B, 1x C),\n\nwith a value of 28 k€. Please press the start button to solve an arbitrary Posten problem (You can determine the number of articles, but at present the number of columns cannot be changed):\n\n===================\n © de Vries 2002", null, "", null, "" ]
[ null, "http://math-it.com/grafik/german.gif", null, "http://math-it.com/grafik/federstrichKlein.gif", null, "http://math-it.com/grafik/home.gif", null ]
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https://www.pk-anexcelexpert.com/vba/worksheets/
[ "# Worksheets\n\nIn this chapter you will learn about the worksheets properties and events.\n\n### How to add a new worksheet?\n\n```Sub Add_New_Worksheet()\n\nDim sh As Worksheet\n\nEnd Sub```\n\n### How to rename new worksheet or existing worksheet?\n\nTo rename the new worksheet below is the code. We are renaming the worksheet as “Data”.\n\n```Sub Rename_New_Worksheet()\n\nDim sh As Worksheet\n\nsh.Name = \"Data\"\n\nEnd Sub```\n\nTo Rename an existing worksheet below are the code. Here are renaming Sheet1 with Data.\n\n```Sub Rename_Existing_Worksheet()\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Name = \"Data\"\n\nEnd Sub```\n\n### How delete a worksheet?\n\nTo delete a worksheet below is the code. It will ask a confirmation before deleting the worksheet. If you don’t want to see that alert then you need use “Application.DisplayAlerts = False\n\n```Sub Delete_Worksheet()\n\n'This is being used disbable the sheet delete confirmation.\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Delete\n\nEnd Sub```\n\n### How to hide/unhide a worksheet?\n\nThere are two types of worksheet hidden in excel vba.\n\n1. xlSheetHidden  is used to normal hide and worksheet can be un-hidden from excel by using sheet unhide(Alt O+H+U).\n2. xlSheetVeryHidden  is used to very hidden and worksheet can not be un-hidden from excel by using sheet unhide. To unhide such worksheet we have to use VBA or Sheet properties window.\n\nBelow is the xlSheetHidden example:\n\n```Sub Hidden_Worksheet()\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Visible = xlSheetHidden\n\nEnd Sub```\n\nBelow is the  xlSheetVeryHidden example:\n\n```Sub Very_Hidden_Worksheet()\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Visible = xlSheetVeryHidden\n\nEnd Sub```\n\nBelow is code to unhide a worksheet:\n\n```Sub Unhide_Worksheet()\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Visible = xlSheetVisible\n\nEnd Sub```\n\n### How to activate a worksheet?\n\nWe can active any worksheet. For example, we have 3 sheets “Sheet1”, “Sheet2” and “Sheet3” in our workbook and currently sheet3 is active. If we want to active “Sheet1” the below is the code.\n\n```Sub Activate_Worksheet()\n\nDim sh As Worksheet\n\nSet sh = ThisWorkbook.Sheets(\"Sheet1\")\n\nsh.Activate\n\nEnd Sub```\n\n### What is ActiveSheet? How to get the name of ActiveSheet?\n\nActiveSheet is the sheet which is currently active in the workbook. To get the Activesheet Name below is the code.\n\n```Sub Get_ActiveSheet_Name()\n\nDim sh As Worksheet\n\nSet sh = ActiveSheet\n\nMsgBox sh.Name\n\nEnd Sub```\n\n### How to get the sheets count in our workbook?\n\nWe can get the total sheets count of our workbook even they are hidden.\n\nBelow is the code:\n\n```Sub Get_Sheets_Count()\n\nDim sheet_count As Integer\n\nsheet_count = ThisWorkbook.Sheets.Count\n\nMsgBox sheet_count\n\nEnd Sub```\n\n## Worksheet Events:\n\nWe can run a certain code on the worksheet event like: SelectionChange, Activate, Deactivate, Calculate etc.\n\nTo use the Worksheet Events go to the Visual Basic Editor and double click on that particular sheet. Select the Worksheet in left drop-down box in place of General. In the right drop-down box you can select the event as given in below image.\n\n```Private Sub Worksheet_SelectionChange(ByVal Target As Range)" ]
[ null ]
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https://kanoki.org/2019/09/04/pandas-groupby-tutorial/
[ "# Pandas Groupby Tutorial\n\nPosted on Sep 04, 2019 · 9 mins read\n\nHope if you are reading this post then you know what is groupby in SQL and how it is being used to aggregate the data of the rows with the same value in one or more column. I was recently working on the Pandas Groupby and found there are lot of useful features which can be used to explore the data and this triggered me to write this post so that anyone with a SQL groupby knowledge can learn the Pandas group by within no time. In this blog I am going to take a dataset and show how we can perform groupby on this data and explore the data further.\n\nWe are going to use the seaborn exercise data for this tutorial. The data represents the type of diet and its corresponding pulse rate measured for the time in mins. You can load this data with a simple searborn command and then after some cleanup the data is ready to be used\n\n``````import seaborn as sns\nimport pandas as pd\n\nexercise.drop('Unnamed: 0',inplace=True,axis='columns')\nexercise['time']=exercise['time'].str.replace(' min','')\nexercise['time']= pd.to_numeric(exercise['time'])\nexercise.rename(columns={'time':'time_mins'},inplace=True)\n``````", null, "## Pandas Groupby Count\n\nAs a first step everyone would be interested to group the data on single or multiple column and count the number of rows within each group. So you can get the count using size or count function. if you are using the count() function then it will return a dataframe. Here we are interested to group on the id and Kind(resting,walking,sleeping etc.) when the pulse rate is measured. You can see for the id: 1 and kind resting the data has 3 rows in it and for walking and running there are no rows available in the data.\n\n``````grouped=exercise.groupby(['id','kind'],axis=0)\ngrouped.count()\n``````", null, "## Basic Aggreggation\n\nNow lets look at the simple aggregations functions that can be applied on the columns for this data. So if you have seen this data then the first thing you would be interested to know is what is the mean or average pulse rate across each of the diet under each id. Here we will first group by id and diet and then use the mean function to get a multi-index dataframe of the groups with the mean values for the column pulse and time_mins. We can easily find it out from this data that diet with low fat gives less pulse rate than the diet with no fat. Wow so we cleared the misconception with this data that eating fat rich food is not good for health.\n\n``````exercise.groupby(['diet']).mean()\n``````", null, "I hope at this point of time you would also be interested to see what is the average pulse for each of the kind. so lets find it out. Looks like resting has lowest mean pulse rate and running has the highest which was expected.\n\n``````exercise.groupby(['kind']).mean()\n``````", null, "There are other aggregating functions like sum, min, max, std,var etc. We will look into some of these functions later in the post. You can check these other functions\n\n### Aggregating functions", null, "The result of the aggregation will have the group names as the new index along the grouped axis. In the case of multiple keys, the result is a Multi-Index by default, though this can be changed by using the as_index option. You can set the as_index parameter as False\n\n``````exercise.groupby(['id','diet'],as_index=False).agg(sum).head()\n``````\n\nor\n\nYou can also do a reset_index\n\n``````exercise.groupby(['id','diet']).sum().head().reset_index()\n``````", null, "### Describe\n\nif you want to generate a descriptive statistics that summarize the count, mean, std deviation, percentile and max values of a datasets distribution then simply use the describe function on the groupby object\n\n``````grouped=exercise.groupby(['id','diet'])\n``````", null, "## Pandas Groupby Multiple Functions\n\nWith a grouped series or a column of the group you can also use a list of aggregate function or a dict of functions to do aggregation with and the result would be a hierarchical index dataframe\n\n``````exercise.groupby(['id','diet'])['pulse'].agg(['max','mean','min']).head()\n``````", null, "Similarly on a groupby object you can pass list of functions and it will give the aggregated results for all the columns in the group\n\n``````exercise.groupby(['id','diet']).agg(['max','mean','min']).head()\n``````", null, "## Lambda function for Aggreggation\n\nYou can also use a lambda function for aggregation with the groupby object. So here I am looking for a lambda function on the groupby which will give me the diff of max and min value in each group for both the columns pulse and time. The output will be a multi-index dataframe object and also renaming the column to diff\n\n``````grouped = exercise.groupby(['id','diet']).agg([lambda x: x.max() - x.min()]).rename(columns={'<lambda>': 'diff'})\n``````", null, "## Pandas groupby aggregate multiple columns using Named Aggregation\n\nAs per the Pandas Documentation,To support column-specific aggregation with control over the output column names, pandas accepts the special syntax in GroupBy.agg(), known as “named aggregation”, where\n\n1. The keywords are the output column names\n2. The values are tuples whose first element is the column to select and the second element is the aggregation to apply to that column. Pandas provides the pandas.NamedAgg namedtuple with the fields [‘column’, ‘aggfunc’] to make it clearer what the arguments are. As usual, the aggregation can be a callable or a string alias.\n\nSo we can specify for each column what is the aggregation function we want to apply and give a customize name to it.\n\n``````import numpy as np\nexercise.groupby(['id','diet']).agg(min_pulse=pd.NamedAgg(column='pulse', aggfunc='min'),\nmax_time=pd.NamedAgg(column='time_mins', aggfunc='max'),\n``````", null, "## Column Indexing\n\nThe groupby object can be indexed by a column and the result will be a Series groupby object. Let’s use series groupby object time_mins and calculate its mean. So we get the total time for each of the kind.\n\n``````exercise.groupby('kind')['time_mins'].mean()\n``````", null, "``````exercise.groupby('kind')['pulse'].mean()\n``````", null, "## Pandas groupby get_group\n\nAnother useful method to select a group from the groupby object so from the groupby object we want to get kind - walking and it gives a dataframe with all rows of walking group. Basically it gets you all the rows of the group you are seeking for\n\n``````grouped=exercise.groupby('kind')\n``````", null, "for an object grouped on multiple columns:\n\n``````grouped=exercise.groupby(['kind','diet'])\n``````", null, "## Iterating groupby\n\nif you want to iterate through each group for some manual operation then you can use something like this and it will return either a series or dataframe\n\n``````for name, group in grouped:\nprint(name)\nprint(group)\n``````", null, "## Pandas SQL groupby Having\n\nyou can query the multi-index dataframe using query function or use filter. Read this blog on how to use filters on groupby object\n\n``````grouped=exercise.groupby(['id','diet']).agg('count').head()\n# Same as SQL having\ngrouped.query('pulse > 2')\n``````", null, "## Groupby Cumulative Sum\n\nSo you want to do a cumulative sum of all the pulse and time_mins for each group, which means to add up those column values for each group\n\n``````exercise.groupby(['id','diet']).agg(sum).groupby('diet').cumsum()\n``````", null, "## Filtering Multi-index Columns\n\nThere is a small work around for filtering the multi-index grouped dataframe. Suppose you want to get all the rows where pulse max,min difference is greater than 10 and time_mins max value is greater than or equal to 30\n\n``````grouped[(grouped[('pulse','diff')]>10) & (grouped[('time_mins','max')]>=30)]\n``````", null, "## Transform and Filter\n\nUsing transform you can create a new column with the aggregated data and get your original dataframe back. Whereas filter can be used like having in SQL. I have a detailed blog which talks about how to use Transform and Filter with groupby. Please check this link.\n\n## Groupby Apply Function\n\nWe can also use apply and pass a function to each group in the groupby object. Say you want to half the pulse-rate in each group, so we can group it by id first and then use apply and pass our customized function so that it will return a dataframe with all the rows of the group and their halved pulse rate.\n\n``````def divide_by_half(x):\n# x is a DataFrame of group values\nx['pulse']=x['pulse']/2\nreturn x\n\nexercise.groupby('id').apply(norm_by_data2)\n``````", null, "## Pandas groupby aggregate to list\n\nMany a times we have seen instead of applying aggregation function we want the values of each group to be bind in a list. So if you want to list of all the time_mins in each group by id and diet then here is how you can do it\n\n``````exercise.groupby(['id','diet'])['time_mins'].apply(list)\n``````", null, "## Conditional Group by count\n\nThis is an interesting one. Suppose you want to group the data on id and diet and want to count all the pulse which is equal to 85\n\n``````exercise.groupby(['id','diet'])['pulse'].apply(lambda x: x[x == 85].count())\n``````", null, "This post was a very detailed introduction to pandas group by and all the features and functions that can be used along with it. As a next step you can run these codes and play around with other aggregation functions and get into the details of the code and can get many more interesting results. It’s not possible to cover all the scenarios and use cases around the groupby in one blog post. I will try to cover other features and use cases in my upcoming blogs. Let me know if you find this blog useful or do you have any suggestions in the comments sections below." ]
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http://ademar.name/blog/2009/07/lsystems-and-the-fibonacci-wor.html
[ "09 July 2009\n\nCheck out this article for a lot of interesting properties of this fractal and its relation to the Fibonacci sequence. F# code follows after the image.", null, "Fibonacci word fractal\n\n``````open System\nopen System.Drawing\nopen System.Drawing.Imaging\n\nlet right = Math.PI / 2.0\nlet left = 3.0 * Math.PI / 2.0\n\ntype Alphabet =\n|K of float\n|Q of float\n|R of float\n|L of float\n|T of float\n\nlet fibonacci_word = function\n|L(x) -> [T(left) ; R(x); T(right); L(x); K(x); L(x); T(right); R(x); T(left) ]\n|R(x) -> [T(right); L(x); T(left) ; R(x); Q(x); R(x); T(left) ; L(x); T(right)]\n|K(x) -> [L(x)]\n|Q(x) -> [R(x)]\n|T(x) -> [T(x)]\n\nlet rec internal applyN f n x =\nif n = 0 then x else f (applyN f (n-1) x)\n\ntype ITurtle =\nabstract draw_forward : float -> unit\nabstract move_forward : float -> unit\nabstract turn : float -> unit\n\nlet interpreter (turtle: ITurtle) = function\n|L(x) -> turtle.draw_forward(x)\n|R(x) -> turtle.draw_forward(x)\n|K(x) -> turtle.move_forward(x)\n|Q(x) -> turtle.move_forward(x)\n|T(x) -> turtle.turn(x)\n\nlet rotate (x,y) theta =\nlet x' = x * cos theta - y * sin theta\nlet y' = x * sin theta + y * cos theta\n(x',y')\n\nlet Turtle(screen:Graphics) =\nlet x = ref 1.0\nlet y = ref 500.0\nlet dx = ref 1.0\nlet dy = ref 0.0\n{ new ITurtle with\nmember t.draw_forward(scale) = screen.DrawLine( new Pen(Color.Red),\nPointF(float32 !x,float32 !y),\nPointF(float32(!x + (!dx*scale)),\nfloat32( !y + (!dy*scale))))\nt.move_forward(scale)\nmember t.move_forward(scale) = x := !x + (!dx*scale)\ny := !y + (!dy*scale)\nmember t.turn(theta) = let dx',dy' = rotate (!dx,!dy) (theta)\ndx := dx'\ndy := dy'\n\n};;\n\nlet bitmap = new Bitmap(1000,1000)\n\nlet turtle = Turtle(Graphics.FromImage(bitmap))\n\nList.iter (interpreter turtle) (applyN (List.collect fibonacci_word) 8 [L(0.5)])\n\nbitmap.Save(\"fibonacci_word.bmp\")\n\n``````" ]
[ null, "http://ademar.name/blog/fibonacci_word.GIF", null ]
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https://ezapata.medium.com/a-brief-introduction-to-active-learning-f292eddec86e?source=post_internal_links---------7----------------------------
[ "# Introduction\n\nWe are currently immersed in a large quantity of data and information which we can use to create efficient models of machine learning. The biggest drawback we found when we are working with supervised models is that we don’t have enough tagged data. Data tagging involves a great effort in time and cost.\n\n## How to use this technique?\n\nLet’s start with an example, if we only had the capacity in time and effort to tag only 500 data in order to improve our models, this strategy will allow us to take those 500 data to optimize our model with a lower cost, the following graphic shows the process described before.", null, "Pipeline Active Learning\n\n# Pool-Based Sampling\n\nIn this stage we assume that we have already some tagged data, (a subset L), and another set of unlabeled data U. In each iteration, a subsample, which belongs to U, is selected to be tagged for a human annotator.\n\n• Variance Reduction: This strategy selects a subset of unlabeled data in order to reduce the variance of the final model. This way we are indirectly minimising the error of generalization of the trained model. However, this strategy could be very computational expensive.\n• Expected Error Reduction: Selecting a subset of data to posteriori decrease generalization error of the model, that would reduce the false positive rate.\n• Query-By-Committee (QBC): This strategy trains a set of models with the data tagged. These trained model will predict new unlabeled data. At the end the data that differ the most in the prediction will be sent to tag.\n\n# Pipeline\n\nIn this dummy example, I will go to use iris dataset to do validation of how Active Learning helps to improve models. I will use a library called modAL to do an example, using uncertainty sampling strategy and later I will train another model with random sampling strategy.\n\n`import pandas as pdimport numpy as npimport matplotlib.pyplot as pltfrom sklearn.datasets import load_iris# load datasetiris = load_iris()X_raw = iris['data']y_raw = iris['target']`\n`# split datasetn_labeled_examples = X_raw.shapetraining_indices = np.random.randint(low=0, high=n_labeled_examples + 1, size=5)X_train = X_raw[training_indices]y_train = y_raw[training_indices]# Isolate the non-training examples we'll be querying.X_pool = np.delete(X_raw, training_indices, axis=0)y_pool = np.delete(y_raw, training_indices, axis=0)`\n`learner = ActiveLearner(estimator=RandomForestClassifier(), query_strategy=uncertainty_sampling, X_training=X_train, y_training=y_train)unqueried_score = learner.score(X_raw, y_raw)`\n`clf, list_history = loop(learner, X_pool, y_pool, performance_history=[unqueried_score])`\n`def random_sampling(classifier, X_pool): query_idx = np.random.choice(range(X_pool.shape)) return query_idx, X_pool[query_idx]# create a random learner object with the strategies created before.learner_random = ActiveLearner(estimator=RandomForestClassifier(), query_strategy=random_sampling, X_training=X_train, y_training=y_train)clf, list_history_random = loop(learner_random, X_pool, y_pool, performance_history=[unqueried_score])`", null, "Active Learning VS Random Sample.\n\n# Conclusions\n\nAs can be seen, using a strategy to label data more intelligently helps improve the model’s metrics with much less data.\n\n# References\n\nData Scientist at Mercado Libre\n\n## More from Elbio Zapata\n\nData Scientist at Mercado Libre" ]
[ null, "https://miro.medium.com/max/60/1*7YxXKNmQVfOC3V60Hpu1Dw.png", null, "https://miro.medium.com/max/60/1*VoAiTQWcppgkSskvC3HZnw.png", null ]
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https://www.instasolv.com/question/1-84-g-mixture-of-caco-and-mgcoz-was-heated-to-a-constant-weight-till-0-9-4dggks
[ "1.84 g mixture of Caco, and MgCoz w...\nQuestion", null, "", null, "# 1.84 g mixture of Caco, and MgCoz was heated to a constant weight till 0.96 g residue formed. % (by mass) of MgCoz in sample was (1) 45.66% (2) 54.34% (3) 30% (4) 70%\n\nJEE/Engineering Exams\nChemistry\nSolution", null, "60", null, "4.0 (1 ratings)", null, "", null, "Let man of ( a a c_{3}=x g ) Man of ( m g(0,3)=(1.84-x) ) ( x ) gram of ( operatorname{cacos} ) will give ( quad operatorname{cat}=56 x ) 100 ( | log _{2}(1.84-x) ) g will gine ( m g 0=frac{40(1.84-x)}{84} ) Total man ( =0.96 ) ( 0 cdot 56 x+frac{40(1-84-x)}{84}=0.96 ) ( x=1 ) ( % ) of ( operatorname{cac} 0,3=frac{1}{1.84}=54 cdot 35 ) \" of ( m g cos =100-54.35=45.65 )", null, "Quick and Stepwise Solutions Just click and Send", null, "OVER 20 LAKH QUESTIONS ANSWERED Download App for Free" ]
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https://devsolus.com/2022/09/23/inconsistent-non-exhaustive-pattern-matching-with-if-statements/
[ "# inconsistent non-exhaustive pattern matching with if statements\n\nI’ve wrote two equivalent functions in Rust, one compiles the other doesn’t.\n\nProgram 1:\n\n``````pub fn majority_element<T: Eq>(nums: &[T]) -> Option<&T> {\nnums.iter().fold(None, |acc, curr| {\nmatch acc {\nNone => Some((1, curr)),\nSome((0, prev)) if prev != curr => Some((1, curr)),\nSome((count, prev)) => Some((count + if prev == curr { 1 } else { -1 }, prev)),\n}\n}).map(|(_, val)| val)\n}\n``````\n\nprogram 2 (doesn’t compile)\n\n``````pub fn majority_element<T: Eq>(nums: &[T]) -> Option<&T> {\nnums.iter().fold(None, |acc, curr| {\nmatch acc {\nNone => Some((1, curr)),\nSome((0, prev)) if prev != curr => Some((1, curr)),\nSome((count, prev)) if prev == curr => Some((count + 1, prev)),\nSome((count, prev)) if prev != curr => Some((count - 1, prev)),\n}\n}).map(|(_, val)| val)\n}\n``````\n``````error[E0004]: non-exhaustive patterns: `Some(_)` not covered\n--> src/lib.rs:3:15\n|\n3 | match acc {\n| ^^^ pattern `Some(_)` not covered\n|\n``````\n\nI prefer the second one because it expresses more clearly my intent.\n\nIs this a compiler quirk or my pattern is actually not exhaustive? (and if so what am I missing?)\nThe type of acc is: `Option<(usize, &T)>`\n\n### >Solution :\n\nThe compiler doesn’t understand that either `x == y` or `x != y`, but for generic types this also can be false. I can create a type that returns `false` for both `a == b` and `a != b` fairly easily:\n\n``````struct Evil;\n\nimpl PartialEq for Evil {\nfn eq(&self, _other: &Self) -> bool { false }\nfn ne(&self, _other: &Self) -> bool { false }\n}\n\nimpl Eq for Evil {}\n\n#[test]\nfn test() {\nassert!(!(Evil == Evil));\nassert!(!(Evil != Evil));\n}\n``````\n\nSuch implementation violates the contract of `PartialEq`, as it requires that:\n\n`a != b` if and only if `!(a == b)`.\n\nBut it is still possible to write without unsafe code. That means that we can for example panic if this contract is violated, but we cannot cause undefined behavior. Unfortunately, non-exhaustive match can cause UB, and such is your case: if none of the arms matches you don’t return any value from the function.\n\nSo the compiler not only does not, but also cannot rely on that. If you prefer, you can rewrite the code in the following way:\n\n``````pub fn majority_element2<T: Eq>(nums: &[T]) -> Option<&T> {\nnums.iter()\n.fold(None, |acc, curr| match acc {\nNone => Some((1, curr)),\nSome((0, prev)) if prev != curr => Some((1, curr)),\nSome((count, prev)) => match prev == curr {\ntrue => Some((count + 1, prev)),\nfalse => Some((count - 1, prev)),\n},\n})\n.map(|(_, val)| val)\n}\n``````" ]
[ null ]
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https://www.varsitytutors.com/mcat_physical-help/distillation
[ "# MCAT Physical : Distillation\n\n## Example Questions\n\n### Example Question #1 : Purification Techniques\n\nConsider the following solutions.\n\nSolution A: 1M sodium chloride solution\n\nSolution B: 1M calcium nitrate solution\n\nSolution C: 1M sucrose solution\n\nEqual volumes of the solutions are combined and the mixture is added to a distillation column. Which of the following solutions will separate first?\n\nSolution A\n\nThese solutions cannot be separated via distillation\n\nSolution C\n\nSolution B\n\nSolution C\n\nExplanation:\n\nDistillation is a process of separating a liquid from solutes or other liquids. It utilizes the boiling point differences to separate substances. A substance with a low boiling point will evaporate first in a distillation column and will be isolated first. The question is asking which solution will be isolated first; therefore, we need to figure out which solution has the lowest boiling point. Recall that the boiling point of a solution is elevated when there are more solutes present in the solution. Sodium chloride (", null, ") contributes two solutes (sodium ions and chloride ions). Calcium nitrate (", null, ") contributes three solutes (one calcium ion and two nitrate ions). Sucrose does not dissociate into ions in solution; therefore, it only contributes one solute. This means that the sucrose solution will have the lowest amount of molecules in solution, the lowest boiling point, and will be separated first.\n\n### Example Question #2 : Purification Techniques\n\nSmall differences in boiling point require the use of __________ distillation and large differences in boiling point require the use of __________ distillation.\n\nfractional . . . simple\n\nsimple . . . fractional\n\nsimple . . . simple\n\nfractional . . . fractional\n\nfractional . . . simple\n\nExplanation:\n\nThere are two types of distillation. Simple distillation is used to separate molecules that have very different boiling points. Fractional distillation is used to separate molecules with small differences in boiling points. Fractional distillation is often used if the difference between boiling points is less than", null, ". In simple distillation, the vapor is immediately collected in a condenser. On the other hand, fractional distillation allows vapor to condense and revaporize several times. These repeated cycles allow fractional distillation to purify the vapor better than simple distillation.\n\n### Example Question #3 : Purification Techniques\n\nWhich of the following mixtures can be separated using fractional distillation (boiling points of each substance given in", null, ")?\n\nI. Chloroform (62.2) and", null, "(76.7)\n\nII. Iodine (184.3) and mercury (356.9)\n\nIII. Nitric acid (120) and sulfuric acid (310)\n\nII and III\n\nII only\n\nI, II, and III\n\nI only\n\nI, II, and III\n\nExplanation:\n\nDistillation is used to separate molecules with different boiling points. Simple distillation is used to separate molecules with vastly different boiling points. Fractional distillation, on the other hand, is a refined form of simple distillation that can be used to separate molecules with similar boiling points. Note that fractional distillation can separate molecules with either different or similar boiling points; therefore, fractional distillation can be used to separate any of the given mixtures.\n\n### Example Question #4 : Purification Techniques\n\nWhich of the following conditions will result in the greatest increase in the rate of distillation of a substance?\n\nDecreasing the vapor pressure\n\nDecreasing the mole fraction of the substance\n\nDecreasing the atmospheric pressure\n\nDecreasing the temperature", null, "" ]
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https://www.mathrecreation.com/2009/01/humble-multiplication-table-1.html
[ "## Friday, January 16, 2009\n\n### The Humble Multiplication Table, 1", null, "A surprising relationship found in the multiplication table is that the sum of the entries in the main upwards diagonal and the diagonal above it is equal to the sum of the entries in the main downwards diagonal. What is also surprising is that this is but one among several observations about the multiplication table that can be expressed in terms of polygonal numbers.\n\nThis relationship involves three-dimensional triangular numbers (triangle-based pyramidal numbers, or tetrahedral numbers), and three-dimensional square numbers (square-based pyramidal numbers). Some values for these, and a few other polygonals, are shown below.", null, "To see why this relationship holds, first note that the sum of the entries in the nth upward diagonal in the multiplication table is equal to the nth three-dimensional triangular number.", null, "Second, observe that he entries in the main down diagonal are square numbers (two-dimensional), so the sum of the main down diagonal is the nth three-dimensional square number.\n\nFinally, we use the fact that a square number (of any dimension) can be split into two triangular numbers (of the same dimension), which gives us the surprising result above." ]
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https://www.aanda.org/articles/aa/full_html/2015/12/aa26456-15/aa26456-15.html
[ "Subscriber Authentication Point\nFree Access\n Issue A&A Volume 584, December 2015 A23 6 Planets and planetary systems https://doi.org/10.1051/0004-6361/201526456 13 November 2015\n\n## 1. Introduction\n\nThe ellipsoidal figure is justified for a small solar system object on both physical and mathematical grounds. For a rotating fluid object, a reasonable model for a small body composed of particles of varying size, the figure of hydrostatic equilibrium tends toward an ellipsoidal shape. When parameterizing a nonspherical shape, the ellipsoid provides a mathematical model with only two parameters, i.e., the axial ratios.\n\nIndeed, the ellipsoidal shape model is popular in studies of asteroids. Magnusson et al. (1989) applied the ellipsoid in retrieving asteroid pole orientations from the photometric lightcurves. Drummond et al. (2010) gave the ellipsoid axial ratios for (21) Lutetia, one of the asteroid fly-by targets of the Rosetta mission. Torppa et al. (2008) characterized large numbers of irregular asteroids by the axial ratios of the best-fit ellipsoids. Cellino et al. (2009) introduced the ellipsoid as the asteroid shape model to be utilized in the interpretation of the sparse photometric data by the Gaia mission.\n\nWe calculate analytically the disk-integrated brightness and photocenter of a triaxial ellipsoidal asteroid with a Lommel-Seeliger surface reflection coefficient (LS reflection coefficient). The LS coefficient originates from the radiative-transfer equation (Chandrasekhar 1960; Lumme & Bowell 1981). For a small single-scattering albedo and a semi-infinite, plane-parallel medium of particles, diffuse reflection of incident unidirectional radiation can be described by the first-order multiple-scattering approximation, that is, the Lommel-Seeliger approximation. Strictly, the LS reflection coefficient is valid for media of sparsely distributed particles in each other’s far-field scattering regimes. However, close-packed particulate media that are weakly multiply scattering, such as the surfaces of C-class asteroids and many other solar system objects, scatter light in accordance with the Lommel-Seeliger approximation. There are indications that the applicability can further extend toward brighter asteroids, such as the S-class and M-class asteroids. The LS reflection coefficient can be analytically integrated over a spherical asteroid (LS sphere) and the photocenter of the LS sphere is also readily available in a closed form (see Kaasalainen & Tanga 2004 and below).\n\nThe Lommel-Seeliger ellipsoid (LS ellipsoid) is an appealing model for dark, nonspherical asteroids. In conventional lightcurve inversion for asteroid rotation periods, pole orientations, and scattering properties, the ellipsoidal shape offers a tool for the initial scanning of the rotation period (cf. Kaasalainen et al. 2001). In the inversion of sparse photometry, as is the case for the Gaia mission, the ellipsoid has been selected as the primary shape model (cf. Cellino et al. 2009; Carbognani et al. 2012). The present work facilitates an efficient initial scanning of rotation periods and pole orientations. It allows for a full-scale initial statistical inversion of sparse photometry for the rotation, shape, and scattering parameters.\n\nIn Sect. 2, we describe the Lommel-Seeliger reflection coefficient and give the analytical disk-integrated brightness and photocenter offset for the LS ellipsoid. In Sect. 3, we utilize the disk-integrated brightness and photocenter in the computation of example lightcurves and photocenter variations in differing illumination and observation geometries. In Sect. 4, we close the article with conclusions and future prospects.\n\n## 2. Photometry\n\n### 2.1. Reflection coefficient\n\nThe reflection coefficient R of a surface element on a solar system object relates the incident flux density πF0 and the emergent intensity I as", null, "(1)where ι and ϵ are the angles of incidence and emergence as measured from the outward normal vector of the surface element, and φ0 and φ are the azimuthal angles. It is customary to measure the azimuth angle φ so that the backscattering (or light source) direction is at φ = 0°. For the common assumption of an isotropic surface, φ0 is unnecessary and presently omitted. The reflection coefficient obeys the reciprocity relation", null, "(2)The Lommel-Seeliger reflection coefficient (subscript LS) is", null, "(3)where", null, "is the single-scattering albedo, P is the single-scattering phase function, and α is the phase angle, the Sun-object-observer angle.\n\nThe Lommel-Seeliger reflection coefficient, which is the first-order, multiple-scattering approximation from the radiative transfer theory (Chandrasekhar 1960; Lumme & Bowell 1981), is applicable to dark, weakly scattering media of particles; the intensity terms", null, ", k ≥ 2 are assumed negligible. The single-scattering albedo", null, "is the fraction of the incident flux scattered by the single scatterer in the random particulate medium exhibited by the asteroid surfaces. The single scatterers can be single particles or volume elements within the medium. In scalar radiative transfer omitting polarization, the scattering phase function P provides the angular distribution of scattered light in an individual interaction. It is normalized so that", null, "(4)It is well known that although the radiative-transfer theory is, in principle, only applicable to sparse media of particles in their far-field scattering regimes, the theory can satisfactorily describe the diffuse reflection from close-packed, particulate media, such as the surfaces of atmosphereless solar system objects.\n\n### 2.2. Disk-integrated brightness\n\nThe disk-integrated brightness L equals the surface integral", null, "(5)where A+ stands for the part of the surface that is both illuminated by the light source and visible to the observer. For a nonspherical asteroid, L can depend strongly on the orientation of the asteroid with respect to the scattering plane, where L is measured.\n\nFor a spherical asteroid (subscript “s” ) with diameter D,", null, "(6)where Ω+ stands for the part of the unit sphere both illuminated and observable. The computation of Ls can be carried out in a coordinate system, where, for example, the Sun is in the direction of the x-axis and the observer is on the xy-plane. For the Lommel-Seeliger surface reflection coefficient, we obtain", null, "(7)We consider next an ellipsoidal asteroid with the semiaxes a, b, and c, and denote", null, "(8)Let e and e be the unit vectors in the directions of the Sun and the observer, respectively, in the principal axes reference frame of the ellipsoid.\n\nThe disk-integrated brightness of an LS ellipsoid (subscript “e” ) can be computed with the help of the coordinate system", null, "(9)and is given by", null, "(10)where we utilize a number of auxiliary quantities. First, the solar phase angle α follows from the directions of the light source e and observer e,", null, "(11)Second, the scalars S and S are", null, "(12)For their relation to the projected area of the ellipsoid, see Eq. (16) below. Third, the angle α is defined by", null, "(13)Finally, the amplitude S and angle λ are given by", null, "(14)We can verify that, in the limit of a = b = c, the disk-integrated brightness of the triaxial ellipsoid reduces to that of the sphere. For the sphere, the auxiliary quantities above are", null, "(15)Inserting these auxiliary quantities into Eq. (10) gives the expression in Eq. (7). Furthermore, for the illumination and observation geometry e = e corresponding to the astronomical opposition, that is, α = 0°, the disk-integrated brightness becomes proportional to the projected area A of the ellipsoid,", null, "(16)", null, "Fig. 1Lightcurves (Eq. (10)) computed for two Lommel-Seeliger ellipsoids (left and right) illuminated and observed in the ecliptic plane with a phase angle of α = 0° (bottom), 45° (middle), and 90° (top). The ellipsoid axial ratios are b/a = 0.86, c/a = 0.82 (left) and b/a = 0.88, c/a = 0.63 (right). The pole longitudes and latitudes are (λ,β) = (0°,90°) (solid line), (0°,30°) (dashed line), and (45°,30°) (dotted line). Open with DEXTER", null, "Fig. 2Photocenter variations (Eq. (25)) computed for two Lommel-Seeliger ellipsoids illuminated and observed in the ecliptic plane with a phase angle of α = 45° (bottom three curves) and 90° (top three curves), with the constant photocenter offsets for the Lommel-Seeliger sphere (dash-dotted lines). The ellipsoid axial ratios are b/a = 0.86, c/a = 0.82 (left) and b/a = 0.88, c/a = 0.63 (right). The pole longitudes and latitudes are (λ,β) = (0°,90°) (solid line), (0°,30°) (dashed line), and (45°,30°) (dotted line). Open with DEXTER\n\n### 2.3. Photocenter\n\nThe photocenter offset d is the brightness-weighted measure of the distance between an asteroid’s apparent photometric center and barycenter,", null, "(17)where I is a unit dyadic, Iee is a projection dyadic, and · denotes scalar product.\n\nThe photocenter of the LS ellipsoid is, in the ecliptic coordinate system,", null, "(18)where RE is the Euler rotation matrix and", null, "(19)For a disappearing argument in the logarithm, asymptotic analytical expressions are readily available.\n\nThe rotation matrix RE is constructed using the angles γE, βE, and αE in a standard manner,", null, "(20)where Rz and Ry denote rotations about the third and second coordinate axes, respectively. Let K be the principal-axes coordinate system of the ellipsoid and let us define the K′′ coordinate system as", null, "(21)where n and n denote the unit outward normal vectors on the surface in the directions of e and e, respectively. In detail,", null, "(22)Then, we obtain βE and γE from", null, "(23)Here, the case of βE = 0° implies a pole in the direction of the ecliptic pole and alternative expressions are available. Finally, αE follows with the help of the intermediate coordinate system K as", null, "where", null, "(24)In what follows, we utilize the norm of d(α), that is,", null, "(25)For a spherical asteroid, Eq. (25) reduces to", null, "(26)\n\n## 3. Results and discussion\n\nWe illustrate the disk-integrated brightness and photocenter of the LS ellipsoid with a number of examples (Figs. 1 and 2). We utilize two example sets of axial ratios from Torppa et al. (2008): first, b/a = 0.86 and c/a = 0.82, mimicking the C-class asteroid (19) Fortuna; and, second, b/a = 0.88 and c/a = 0.63, mimicking the C-class asteroid (1580) Betulia. The direction of the Sun is given by the ecliptic longitude and latitude (λ,β) = (0°,0°) in all examples, and the directions of the observer are (λ,β) = (0°,0°), (45°,0°), and (90°,0°). Accordingly, the solar phase angle is α = 0°, 45°, or 90°. Three different pole orientations are assumed for the asteroid with ecliptic longitudes and latitudes of (λ,β) = (0°,90°), (0°,30°), and (45°,30°). Lightcurves and photocenter variations are computed over a full rotation of the asteroid about the shortest axis, that is, the axis of maximum inertia assuming a homogeneous asteroid.\n\nThe lightcurves in Fig. 1 exhibit the typical double-maximum and double-minimum characteristics of ellipsoids in the principal-axis rotation state. In all cases, the lightcurve amplitude reaches its maximum for the pole that coincides with the ecliptic pole, that is, (λ,β) = (0°,90°). This is a natural consequence of illumination and observation in the ecliptic plane, producing a maximum aspect angle, the angle between the pole and observer directions. For α = 0°, the two lightcurves corresponding to the pole orientations with λ = 0° are seen to be in phase with each other. The remaining lightcurve with pole longitude λ = 45° stands out with a clear phase shift. For the phase angles α = 45° and 90°, the lightcurves pertaining to the different poles become differently phased. There is an exchange of order for the lightcurve amplitudes: for α = 0°, the amplitude for (λ,β) = (45°,30°) exceeds that of (0°,30°), whereas the opposite is true for α = 90°. This is in agreement with the variation of the aspect angle from one case to another. Overall, the lightcurves are more pronounced for the ellipsoid with b/a = 0.86 and c/a = 0.82.\n\nFor the pole orientations (λ,β) = (0°,30°) and (45°,30°) and the phase angle α = 45°, Fig. 1 (graphs in the middle, dotted and dashed lines) illustrates how the reciprocity relation in Eq. (2) gives rise to lightcurves that are identical except for a constant phase shift. In these specific geometries, exchanging the light source and observer directions results in mirror configurations and similar lightcurves.\n\nAs to the photocenter variations in Fig. 2, first of all, since there is no photocenter offset for the opposition geometry, the cases of α = 0° have been omitted and the variations for α = 45° and 90° have been combined into single graphs. Overall, the photocenter offset becomes more pronounced for increasing α, reaching the peak amplitude for the pole orientation (λ,β) = (0°,90°). There are, however, exceptions to that rule at certain rotational phases. The same mutual phase is seen for the photocenter variations at α = 45° for the two poles with λ = 0°, and the photocenter variations reach their maxima nearly in phase with the corresponding lightcurve minima in Fig. 1. As for the lightcurve phasing, the photocenter variation for the pole (λ,β) = (45°,30°) stands out with a clear phase shift. Overall, the range of the photocenter variation from one case to another is more pronounced for the ellipsoid with b/a = 0.88 and c/a = 0.63. In particular, this is evident for the phase angle of α = 90°.\n\nFor both example ellipsoids and α = 90°, except for a phase shift, Fig. 2 shows a peculiar similarity between the photocenter variations for the poles (λ,β) = (0°,30°) and (45°,30°). A closer inspection of the numerical values indicates, however, a modest difference in the variations. For β = 30° and λ approaching 90°, the photocenter variations enhance rapidly. Finally, for comparison, we also show the constant photocenter offsets for the LS sphere in Fig. 2. It is noteworthy that the LS sphere offsets are only exceeded by the LS ellipsoid offsets near the lightcurve minima.\n\n## 4. Conclusions\n\nWe have derived analytical expressions for the disk-integrated photometric brightness and the photocenter offset of a dark ellipsoidal asteroid with a Lommel-Seeliger surface-reflection coefficient. The expressions allow for rapid computation of lightcurves and photocenter variations in arbitrary illumination and observation geometries. Typical regular lightcurves and photocenter variations with two maxima and two minima follow for principal-axis rotation over a single rotation period, with increasing amplitude for increasing solar phase angle.\n\nThere are natural extensions to the ellipsoid shape model and how it can be utilized in studies of asteroids. Michalowski (1996) succeeded in explaining irregular lightcurve features with the ellipsoid model, assuming a rotation axis misaligned from the ellipsoid principal axes. Cellino et al. (1989) combined together octants from different ellipsoids and provided the so-called Cellinoid shape model. Whereas the present results can be readily utilized in the case of differing axis of rotation and shape, it remains to be seen if analytical work can be carried out for the Cellinoid shape model.\n\nThere are a number of topical applications for the LS ellipsoid. First, the sparse photometry of asteroids to be provided by the Gaia mission will be initially analyzed using the LS ellipsoid. Second, the LS ellipsoid allows for efficient lightcurve computation for binary asteroids outside their mutual eclipse, thus giving potential for efficient lightcurve inversion methods for binaries. Third, the LS ellipsoid enables rapid identification of binary asteroid candidates from astrometric observations via the photocenter offset. Fourth, asteroid phase-curve dependence on the illumination and observation geometries in a specific apparition can be assessed, giving estimates for intrinsic variations\n\nin the phase curves. Finally, in addition to asteroids, the LS ellipsoid has future prospects in the photometric studies of cometary nuclei, transneptunian objects, and planetary satellites.\n\n## Acknowledgments\n\nProf. emer. Kari Lumme passed away unexpectedly in Nov. 23, 2013 before the completion of the present article. A thoughtful review by Paolo Tanga helped improve the article. Karri Muinonen is grateful to Alberto Cellino, Xiaobin Wang, Johanna Torppa, Antti Penttilä, and Olli Wilkman for valuable comments. Research supported, in part, by the Academy of Finland Grant No. 1257966 entitled Electromagnetic Wave Scattering in Complex Media.\n\n## References\n\n1. Carbognani, A., Tanga, P., Cellino, A., et al. 2012, Planet. Space Sci., 73, 80 [NASA ADS] [CrossRef] [Google Scholar]\n2. Cellino, A., Zappalá, V., & Farinella, P. 1989, Icarus, 78, 298 [NASA ADS] [CrossRef] [Google Scholar]\n3. Cellino, A., Hestroffer, D., Tanga, P., Mottola, S., & Dell’Oro, A. 2009, A&A, 506, 935 [NASA ADS] [CrossRef] [EDP Sciences] [Google Scholar]\n5. Drummond, J. D., Conrad, A., Merline, W. J., et al. 2010, A&A, 523, A93 [NASA ADS] [CrossRef] [EDP Sciences] [Google Scholar]\n6. Kaasalainen, M., & Tanga, P. 2004, A&A, 416, 367 [NASA ADS] [CrossRef] [EDP Sciences] [Google Scholar]\n7. Kaasalainen, M., Torppa, J., & Muinonen, K. 2001, Icarus, 153, 37 [NASA ADS] [CrossRef] [Google Scholar]\n8. Lumme, K., & Bowell, E. 1981, AJ, 86, 1694 [NASA ADS] [CrossRef] [Google Scholar]\n9. Magnusson, P., Barucci, M. A., Drummond, J., et al. 1989, in Asteroids II, eds. R. P. Binzel, T. Gehrels, & M. S. Matthews (Tucson: The University of Arizona Press), 66 [Google Scholar]", null, "Fig. 1Lightcurves (Eq. (10)) computed for two Lommel-Seeliger ellipsoids (left and right) illuminated and observed in the ecliptic plane with a phase angle of α = 0° (bottom), 45° (middle), and 90° (top). The ellipsoid axial ratios are b/a = 0.86, c/a = 0.82 (left) and b/a = 0.88, c/a = 0.63 (right). The pole longitudes and latitudes are (λ,β) = (0°,90°) (solid line), (0°,30°) (dashed line), and (45°,30°) (dotted line). Open with DEXTER In the text", null, "Fig. 2Photocenter variations (Eq. (25)) computed for two Lommel-Seeliger ellipsoids illuminated and observed in the ecliptic plane with a phase angle of α = 45° (bottom three curves) and 90° (top three curves), with the constant photocenter offsets for the Lommel-Seeliger sphere (dash-dotted lines). The ellipsoid axial ratios are b/a = 0.86, c/a = 0.82 (left) and b/a = 0.88, c/a = 0.63 (right). The pole longitudes and latitudes are (λ,β) = (0°,90°) (solid line), (0°,30°) (dashed line), and (45°,30°) (dotted line). Open with DEXTER In the text" ]
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https://patientsaver.savingadvice.com/2011/12/30/so-whats-everyone-doing-for-new-years_89296/
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5.62.62.162\n)\n\n => Array\n(\n => 103.255.4.39\n)\n\n => Array\n(\n => 202.5.144.153\n)\n\n => Array\n(\n => 1.39.223.210\n)\n\n => Array\n(\n => 92.38.176.154\n)\n\n => Array\n(\n => 117.230.186.142\n)\n\n => Array\n(\n => 183.83.39.123\n)\n\n => Array\n(\n => 182.185.156.76\n)\n\n => Array\n(\n => 104.236.74.212\n)\n\n => Array\n(\n => 107.170.145.187\n)\n\n => Array\n(\n => 117.102.7.98\n)\n\n => Array\n(\n => 137.59.220.0\n)\n\n => Array\n(\n => 157.47.222.14\n)\n\n => Array\n(\n => 47.15.206.82\n)\n\n => Array\n(\n => 117.230.159.99\n)\n\n => Array\n(\n => 117.230.175.151\n)\n\n => Array\n(\n => 157.50.97.18\n)\n\n => Array\n(\n => 117.230.47.164\n)\n\n => Array\n(\n => 77.111.244.34\n)\n\n => Array\n(\n => 139.167.189.131\n)\n\n => Array\n(\n => 1.39.204.103\n)\n\n => Array\n(\n => 117.230.58.0\n)\n\n => Array\n(\n => 182.185.226.66\n)\n\n => Array\n(\n => 115.42.70.119\n)\n\n => Array\n(\n => 171.48.114.134\n)\n\n => Array\n(\n => 144.34.218.75\n)\n\n => Array\n(\n => 199.58.164.135\n)\n\n => Array\n(\n => 101.53.228.151\n)\n\n => Array\n(\n => 117.230.50.57\n)\n\n => Array\n(\n => 223.225.138.84\n)\n\n => Array\n(\n => 110.225.67.65\n)\n\n => Array\n(\n => 47.15.200.39\n)\n\n => Array\n(\n => 39.42.20.127\n)\n\n => Array\n(\n => 117.97.241.81\n)\n\n => Array\n(\n => 111.119.185.11\n)\n\n => Array\n(\n => 103.100.5.94\n)\n\n => Array\n(\n => 103.25.137.69\n)\n\n => Array\n(\n => 47.15.197.159\n)\n\n => Array\n(\n => 223.188.176.122\n)\n\n => Array\n(\n => 27.4.175.80\n)\n\n => Array\n(\n => 181.215.43.82\n)\n\n => Array\n(\n => 27.56.228.157\n)\n\n => Array\n(\n => 117.230.19.19\n)\n\n => Array\n(\n => 47.15.208.71\n)\n\n => Array\n(\n => 119.155.21.176\n)\n\n => Array\n(\n => 47.15.234.202\n)\n\n => Array\n(\n => 117.230.144.135\n)\n\n => Array\n(\n => 112.79.139.199\n)\n\n => Array\n(\n => 116.75.246.41\n)\n\n => Array\n(\n => 117.230.177.126\n)\n\n => Array\n(\n => 212.103.48.134\n)\n\n => Array\n(\n => 102.69.228.78\n)\n\n => Array\n(\n => 117.230.37.118\n)\n\n => Array\n(\n => 175.143.61.75\n)\n\n => Array\n(\n => 139.167.56.138\n)\n\n => Array\n(\n => 58.145.189.250\n)\n\n => Array\n(\n => 103.255.5.65\n)\n\n => Array\n(\n => 39.37.153.182\n)\n\n => Array\n(\n => 157.43.85.106\n)\n\n => Array\n(\n => 185.209.178.77\n)\n\n => Array\n(\n => 1.39.212.45\n)\n\n => Array\n(\n => 103.72.7.16\n)\n\n => Array\n(\n => 117.97.185.244\n)\n\n => Array\n(\n => 117.230.59.106\n)\n\n => Array\n(\n => 137.97.121.103\n)\n\n => Array\n(\n => 103.82.123.215\n)\n\n => Array\n(\n => 103.68.217.248\n)\n\n => Array\n(\n => 157.39.27.175\n)\n\n => Array\n(\n => 47.31.100.249\n)\n\n => Array\n(\n => 14.171.232.139\n)\n\n => Array\n(\n => 103.31.93.208\n)\n\n => Array\n(\n => 117.230.56.77\n)\n\n => Array\n(\n => 124.182.25.124\n)\n\n => Array\n(\n => 106.66.191.242\n)\n\n => Array\n(\n => 175.107.237.25\n)\n\n => Array\n(\n => 119.155.1.27\n)\n\n => Array\n(\n => 72.255.6.24\n)\n\n => Array\n(\n => 192.140.152.223\n)\n\n => Array\n(\n => 212.103.48.136\n)\n\n => Array\n(\n => 39.45.134.56\n)\n\n => Array\n(\n => 139.167.173.30\n)\n\n => Array\n(\n => 117.230.63.87\n)\n\n => Array\n(\n => 182.189.95.203\n)\n\n => Array\n(\n => 49.204.183.248\n)\n\n => Array\n(\n => 47.31.125.188\n)\n\n => Array\n(\n => 103.252.171.13\n)\n\n => Array\n(\n => 112.198.74.36\n)\n\n => Array\n(\n => 27.109.113.152\n)\n\n => Array\n(\n => 42.112.233.44\n)\n\n => Array\n(\n => 47.31.68.193\n)\n\n => Array\n(\n => 103.252.171.134\n)\n\n => Array\n(\n => 77.123.32.114\n)\n\n => Array\n(\n => 1.38.189.66\n)\n\n => Array\n(\n => 39.37.181.108\n)\n\n => Array\n(\n => 42.106.44.61\n)\n\n => Array\n(\n => 157.36.8.39\n)\n\n => Array\n(\n => 223.238.41.53\n)\n\n => Array\n(\n => 202.89.77.10\n)\n\n => Array\n(\n => 117.230.150.68\n)\n\n => Array\n(\n => 175.176.87.60\n)\n\n => Array\n(\n => 137.97.117.87\n)\n\n => Array\n(\n => 132.154.123.11\n)\n\n => Array\n(\n => 45.113.124.141\n)\n\n => Array\n(\n => 103.87.56.203\n)\n\n => Array\n(\n => 159.89.171.156\n)\n\n => Array\n(\n => 119.155.53.88\n)\n\n => Array\n(\n => 222.252.107.215\n)\n\n => Array\n(\n => 132.154.75.238\n)\n\n => Array\n(\n => 122.183.41.168\n)\n\n => Array\n(\n => 42.106.254.158\n)\n\n => Array\n(\n => 103.252.171.37\n)\n\n => Array\n(\n => 202.59.13.180\n)\n\n => Array\n(\n => 37.111.139.137\n)\n\n => Array\n(\n => 39.42.93.25\n)\n\n => Array\n(\n => 118.70.177.156\n)\n\n => Array\n(\n => 117.230.148.64\n)\n\n => Array\n(\n => 39.42.15.194\n)\n\n => Array\n(\n => 137.97.176.86\n)\n\n => Array\n(\n => 106.210.102.113\n)\n\n => Array\n(\n => 39.59.84.236\n)\n\n => Array\n(\n => 49.206.187.177\n)\n\n => Array\n(\n => 117.230.133.11\n)\n\n => Array\n(\n => 42.106.253.173\n)\n\n => Array\n(\n => 178.62.102.23\n)\n\n => Array\n(\n => 111.92.76.175\n)\n\n => Array\n(\n => 132.154.86.45\n)\n\n => Array\n(\n => 117.230.128.39\n)\n\n => Array\n(\n => 117.230.53.165\n)\n\n => Array\n(\n => 49.37.200.171\n)\n\n => Array\n(\n => 104.236.213.230\n)\n\n => Array\n(\n => 103.140.30.81\n)\n\n => Array\n(\n => 59.103.104.117\n)\n\n => Array\n(\n => 65.49.126.79\n)\n\n => Array\n(\n => 202.59.12.251\n)\n\n => Array\n(\n => 37.111.136.17\n)\n\n => Array\n(\n => 163.53.85.67\n)\n\n => Array\n(\n => 123.16.240.73\n)\n\n => Array\n(\n => 103.211.14.183\n)\n\n => Array\n(\n => 103.248.93.211\n)\n\n => Array\n(\n => 116.74.59.127\n)\n\n => Array\n(\n => 137.97.169.254\n)\n\n => Array\n(\n => 113.177.79.100\n)\n\n => Array\n(\n => 74.82.60.187\n)\n\n => Array\n(\n => 117.230.157.66\n)\n\n => Array\n(\n => 169.149.194.241\n)\n\n => Array\n(\n => 117.230.156.11\n)\n\n => Array\n(\n => 202.59.12.157\n)\n\n => Array\n(\n => 42.106.181.25\n)\n\n => Array\n(\n => 202.59.13.78\n)\n\n => Array\n(\n => 39.37.153.32\n)\n\n => Array\n(\n => 177.188.216.175\n)\n\n => Array\n(\n => 222.252.53.165\n)\n\n => Array\n(\n => 37.139.23.89\n)\n\n => Array\n(\n => 117.230.139.150\n)\n\n => Array\n(\n => 104.131.176.234\n)\n\n => Array\n(\n => 42.106.181.117\n)\n\n => Array\n(\n => 117.230.180.94\n)\n\n => Array\n(\n => 180.190.171.5\n)\n\n => Array\n(\n => 150.129.165.185\n)\n\n => Array\n(\n => 51.15.0.150\n)\n\n => Array\n(\n => 42.111.4.84\n)\n\n => Array\n(\n => 74.82.60.116\n)\n\n => Array\n(\n => 137.97.121.165\n)\n\n => Array\n(\n => 64.62.187.194\n)\n\n => Array\n(\n => 137.97.106.162\n)\n\n => Array\n(\n => 137.97.92.46\n)\n\n => Array\n(\n => 137.97.170.25\n)\n\n => Array\n(\n => 103.104.192.100\n)\n\n => Array\n(\n => 185.246.211.34\n)\n\n => Array\n(\n => 119.160.96.78\n)\n\n => Array\n(\n => 212.103.48.152\n)\n\n => Array\n(\n => 183.83.153.90\n)\n\n => Array\n(\n => 117.248.150.41\n)\n\n => Array\n(\n => 185.240.246.180\n)\n\n => Array\n(\n => 162.253.131.125\n)\n\n => Array\n(\n => 117.230.153.217\n)\n\n => Array\n(\n => 117.230.169.1\n)\n\n => Array\n(\n => 49.15.138.247\n)\n\n => Array\n(\n => 117.230.37.110\n)\n\n => Array\n(\n => 14.167.188.75\n)\n\n => Array\n(\n => 169.149.239.93\n)\n\n => Array\n(\n => 103.216.176.91\n)\n\n => Array\n(\n => 117.230.12.126\n)\n\n => Array\n(\n => 184.75.209.110\n)\n\n => Array\n(\n => 117.230.6.60\n)\n\n => Array\n(\n => 117.230.135.132\n)\n\n => Array\n(\n => 31.179.29.109\n)\n\n => Array\n(\n => 74.121.188.186\n)\n\n => Array\n(\n => 117.230.35.5\n)\n\n => Array\n(\n => 111.92.74.239\n)\n\n => Array\n(\n => 104.245.144.236\n)\n\n => Array\n(\n => 39.50.22.100\n)\n\n => Array\n(\n => 47.31.190.23\n)\n\n => Array\n(\n => 157.44.73.187\n)\n\n => Array\n(\n => 117.230.8.91\n)\n\n => Array\n(\n => 157.32.18.2\n)\n\n => Array\n(\n => 111.119.187.43\n)\n\n => Array\n(\n => 203.101.185.246\n)\n\n => Array\n(\n => 5.62.34.22\n)\n\n => Array\n(\n => 122.8.143.76\n)\n\n => Array\n(\n => 115.186.2.187\n)\n\n => Array\n(\n => 202.142.110.89\n)\n\n => Array\n(\n => 157.50.61.254\n)\n\n => Array\n(\n => 223.182.211.185\n)\n\n => Array\n(\n => 103.85.125.210\n)\n\n => Array\n(\n => 103.217.133.147\n)\n\n => Array\n(\n => 103.60.196.217\n)\n\n => Array\n(\n => 157.44.238.6\n)\n\n => Array\n(\n => 117.196.225.68\n)\n\n => Array\n(\n => 104.254.92.52\n)\n\n => Array\n(\n => 39.42.46.72\n)\n\n => Array\n(\n => 221.132.119.36\n)\n\n => Array\n(\n => 111.92.77.47\n)\n\n => Array\n(\n => 223.225.19.152\n)\n\n => Array\n(\n => 159.89.121.217\n)\n\n => Array\n(\n => 39.53.221.205\n)\n\n => Array\n(\n => 193.34.217.28\n)\n\n => Array\n(\n => 139.167.206.36\n)\n\n => Array\n(\n => 96.40.10.7\n)\n\n => Array\n(\n => 124.29.198.123\n)\n\n => Array\n(\n => 117.196.226.1\n)\n\n => Array\n(\n => 106.200.85.135\n)\n\n => Array\n(\n => 106.223.180.28\n)\n\n => Array\n(\n => 103.49.232.110\n)\n\n => Array\n(\n => 139.167.208.50\n)\n\n => Array\n(\n => 139.167.201.102\n)\n\n => Array\n(\n => 14.244.224.237\n)\n\n => Array\n(\n => 103.140.31.187\n)\n\n => Array\n(\n => 49.36.134.136\n)\n\n => Array\n(\n => 160.16.61.75\n)\n\n => Array\n(\n => 103.18.22.228\n)\n\n => Array\n(\n => 47.9.74.121\n)\n\n => Array\n(\n => 47.30.216.159\n)\n\n => Array\n(\n => 117.248.150.78\n)\n\n => Array\n(\n => 5.62.34.17\n)\n\n => Array\n(\n => 139.167.247.181\n)\n\n => Array\n(\n => 193.176.84.29\n)\n\n => Array\n(\n => 103.195.201.121\n)\n\n => Array\n(\n => 89.187.175.115\n)\n\n)\n```\nSo what's everyone doing for New Year's?: Save More, Spend Less\n << Back to all Blogs Login or Create your own free blog Layout: Blue and Brown (Default) Author's Creation\nHome > So what's everyone doing for New Year's?", null, "", null, "", null, "# So what's everyone doing for New Year's?\n\nDecember 31st, 2011 at 01:44 am\n\nJust curious what you're doing...\n\nToday was another relatively mild day here in CT, and supposed to be like that through the weekend. I still have a half tank of oil left, which should get me through January.\n\nI hauled some more cut up tree logs and brush to the driveway. I think I have close to a cord stacked now.\n\nDidn't do much else today. I have at least 3 unfinished projects around the house, off the top of my head, but no inclination to tackle any of them. A half painted spare bedroom. A half wallpapered bathroom. Ugh.\n\nSo nice to see my mortgage balance in 4 figures for the first time ever! The countdown begins!!\n\nI changed my electricity provider (not the first time) for the coming year. The state has a website where you can compare the cost of about 20 different companies. Why would anyone go with a company offering less than the lowest rate?? I just don't get it. There's no fee to switch, and no fee to cancel, which you can do at any time. It's a no-brainer.\n\nSo I switched from ConEd, who last year offered the lowest price, at 8.4 cents per kilowatt hour, to 7.98 cents were kilowatt hour with Dominion.\n\nYou might say, what a teensy difference, why bother? Well, if you consider that you use electricity every hour of the day, 24 hours a day, then it's really worth investigating. Becus it really adds up.\n\nI switched out all my bulbs to CFLs years ago and still I noticed my 2011 electrical costs were 4% cheaper than the year before. I have to think it's becus I shaved off a few cents last year switching electricity providers and that made a difference. Let's see if I can do it again in 2012.\n\n### 13 Responses to “So what's everyone doing for New Year's?”\n\n1. creditcardfree Says:\n\nWe are having mild weather in the midwest too. So nice for December!! We will stay home with the kids and play board and card games until midnight. We usually do appetizers rather than a full meal.\n\nWhat will you do?\n\n2. littlegopher Says:\n\nDuring the day, we'll take the tree down - everything else is put away already. Clean up the pine needles. Later we're doing similar as creditcardfree - spend time with our two youngest (with mom & dad struggling to stay up to midnight", null, "Happy New Year!!\n\n3. wowitsawonderfullife Says:\n\nGreat post! I laughed out loud when you said \"but no inclination to tackle any of them\". I can relate! I figure I'm doing well if I can at least make a list.\n\nYup, CFLs bulbs are the way to go. 74% savings over incandescents and fewer times to replace them. Keep the receipts and return for a new one for free if it dies before the warranty period. Just tape the receipt to the box and highlight the date you purchase and the warranty period.\n\nNew Years is spent with the immediate family at our cottage. Movies, watching the ball drop, good books, games, with the fire going. And a nice glass of dry white, natch!\n\n4. ThriftoRama Says:\n\nWe are going to a (child free) friend's party. The kids are going to grandma's for the night. In a few years, when my kids are old enough to actually stay up late every once in a while, I'd like to think we;d have a party for all of our friends and their kids, with shirley temples, confetti, and fun. But we aren't there yet!\n\n5. My English Castle Says:\n\nWe were going to stay in, but think we'll go to see \"Hugo\" tomorrow in the late afternoon --and then somewhere quiet, moderate, and child-friendly for an early dinner. We've been playing Yahtzee in the evenings--partly to help DD's math, so I predict we'll have another couple games tomorrow night. Have a Happy New Year--and great job on that 4-figure mortgage!\n\n6. FrugalTexan75 Says:\n\nNYE we will be going to Pasadena, CA to look at lights and check out the parade crowd - we might throw some marshmallows too.", null, "Then we'll probably play Kings Corner and/or watch a movie til time for the ball to drop. NYD I'll be flying home and hopefully do some grocery shopping.", null, "7. baselle Says:\n\nNice quiet night at home with DH. I'll get to meet Spondilucks in the afternoon. I know, I know, 2 north Seattle bloggers here in SA and we've never met. I picked up a lovely bottle of prosecco for midnight.\n\n8. Jerry Says:\n\nWe have no big plans to lead us out into the snow (SE Europe got some for Christmas!), we will likely just stay in and make some holiday food and celebrate at home. I'm a little under the weather, anyway, and I think I'd rather just have some insurance of being comfortable tonight. Happy New Year!\nJerry\n\n9. Jerry Says:\n\nWe have no big plans to lead us out into the snow (SE Europe got some for Christmas!), we will likely just stay in and make some holiday food and celebrate at home. I'm a little under the weather, anyway, and I think I'd rather just have some i\n\n10. Campfrugal Says:\n\nHad breakfast out with my favorite neighbor lady, going to yoga class, then cookin and ham, potatoes, brocolli and some dessert for dinner, play yahtzee with the kids, probably get in a nap and wake up just in time to watch the ball drop. Great day.\n\nBig New Year's Day dinner party tomorrow with one side of the family. Lookin forward to it.\n\n11. ceejay74 Says:\n\nGoing out to some friends' house tonight; they have older kids so AA should have fun. Probably home before midnight, mostly for the benefit of preggo AS, who gets very tired early these days.\n\nThey're cooking an array of Italian/Mediterranean dishes, so we're bringing fancy olives and artichoke dip. Should be fun!\n\n12. EarlyRetirementJoy Says:\n\nFrugalTexas75 - They seem to prefer throwing tortilla's covered in shaving cream in Pasadena on New Years over marshmellows . . . it's quite the scene if you haven't experienced it before!\n\nTonight, for the first time in years we are NOT going to a New Years Eve dance at one of our nearby dance studios. Not sure why, come to think of it, perhaps we just wanted to remember what staying in feels like! Neither DH or I enjoy champagne all that much, so we are opening a bottle of Opolo Mountain Zinfindel, one of our favorite wines from one of our favorite wineries in Paso Robles, here in California.\n\n13. Frugaltexan75 Says:\n\nOh yes, we got initiated to the tortillas last year. We go to Pasadena every year we are in southern CA - at least NYE. Been there many many times.", null, "(Note: If you were logged in, we could automatically fill in these fields for you.)\n Name: * Email: Will not be published. Subscribe: Notify me of additional comments to this entry. URL: Verification: * Please spell out the number 4.  [ Why? ]\n\nvB Code: You can use these tags: [b] [i] [u] [url] [email]" ]
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https://de.mathworks.com/matlabcentral/profile/authors/5124675
[ "Community Profile", null, "# Dimitrios\n\n### Technical Unversity of Denmark\n\nActive since 2014\n\n#### Statistics\n\nAll\n•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "•", null, "#### Content Feed\n\nView by\n\nSubmitted\n\nmpizosdim/ScientificPlotTool\nTool to export scientific oriented plots", null, "Question\n\nexporting a figure to eps format bug(?)\nI use the following code to output a figure: fig1 = figure;h=errorbar(1:5,MeanSurgeTLP,StdSurgeTLP,'o','MarkerEdgeColor','...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nIs there a way to export figure from a gui?\nIs there a way to export a figure from an existing axes in a eps format?Thanks in advance\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nconfused with ode4 results\nI am using ode4 to simulate the motion of a body.I will make it simple: dqdt = ode4(@obj.fun,obj.time,[2.5 0 0 0]') wher...\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nHow to smooth this plot?\nI am ploting a signal in frequency domain and i am trying to smooth the results in order to be clear for the viewer.The followin...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nHow to impliment this without loop?\nI need to take the rate of change of a variable and for the first value there is not a previous value to take.For the initial i ...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nFor what reason an ODE solver could run for ever?\nI am running a simulation with ODE4 and it seems that it will never end(3 hours now).I have already run it before with less time...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nHow to pass variables in ODE function?\nI have precomputed a Force in time domain and i want to use it inside an ODE function.Every t that ODE computes to pass the forc...\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nHow to change color in a 3d plot depending from the value in each position?\nI am trying to simulate the loads from air in a vertical wind turbine.I would like to visualize these results.I upload these two...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nHow to clear classes except some variables?\nI am looping through a code which generates a class with different parameters every time.In every loop i erase the previous clas...\n\nmehr als 6 Jahre ago | 2 answers | 0\n\n### 2\n\nQuestion\n\nHow to take data from plot in a pdf book?\nIs there a way to extract the values in a plot from a book?I mean there are some plots in a book and i would like to take the va...\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nhow to change mesh colorbar to appropriate colors?\nI am making a mesh which has the folowing form: Z = varargin{1};%the values that will be meshed. C = del2(Z); ...\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nHow to change the box color of the mesh?\nI have the following figure : <</matlabcentral/answers/uploaded_files/20701/export_fig_out.png>> and i want to be so...\n\nmehr als 6 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nwhat causes this display in .eps figure?\nI am plotting in Matlab the following figure in .eps format (the following figure was exported using export_fig from fileexchang...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nwhich are the default properties of plot for the MATLAB 2014b?\nIt seems that the default properties(linewidth,font size for title and label etc) for the new version of MATLAB have changed.I c...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nHow from uint8 to 0 and 1?\nI import the following image which is a [583x673x3] uint8 : <</matlabcentral/answers/uploaded_files/20641/export_fig_out....\n\nmehr als 6 Jahre ago | 3 answers | 0\n\n### 3\n\nQuestion\n\nhow to smooth data?\nFrom a simulation i got some output where there are some spikes that not correspond with the other data.Which is the best way to...\n\nmehr als 6 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\ntrouble with switch case\nI got a function which i would like to be something like this: function output = calc(input) switch input case 'Stat...\n\nfast 7 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\ncatching a value while matlab is running\nI am building a simulation with many functions using OOP(beginner). Sometimes I have some values from different variables that a...\n\nfast 7 Jahre ago | 2 answers | 0\n\n### 2\n\nQuestion\n\nextrapolation using interp2 or any other function\nI have a table of data with the following form(simplified ver.): <</matlabcentral/answers/uploaded_files/19805/%CE%A7%CF%89%C...\n\nfast 7 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nMATLAB 2014b and OOP\nI dont have yet the new version of MATLAB but i was wondering if there are any new features in OOP environment or any changes? ...\n\nfast 7 Jahre ago | 1 answer | 0\n\n### 1\n\nQuestion\n\nHow to impliment efficient the next expression?\n\nfast 7 Jahre ago | 0 answers | 0\n\n### 0\n\nQuestion\n\nIs there any more effiecient way to implement this?\nUsing MATLAB:I have a table of lets say x(size(100x1)),y(size(100x1)) and z(size(100x100)) and i use z1 = interp2(x,y,z...\n\nfast 7 Jahre ago | 2 answers | 0\n\n### 2\n\nSolved\n\nFind 100 from a Matrix and Replace With 0 with less computation time\npls use this matrix x = [208 40 167 180 112 70 192 215 90 19 231 100 9 100 97 100 ...\n\nfast 7 Jahre ago\n\nSolved\n\nSquare Diagonal\nIf n is the given number, then make a diagonal matrix of size 2*2 with the square of that number.\n\nfast 7 Jahre ago\n\nSolved\n\nLet's see how peculiar we can get\nThe task is to multiply two numbers. But do it in the most peculiar possible way.\n\nfast 7 Jahre ago\n\nSolved\n\nIs My Wife Wrong?\n\nfast 7 Jahre ago\n\nSolved\n\nDetermine the length of a string of characters\nDetermine the length of a string of characters\n\nfast 7 Jahre ago\n\nSolved\n\nReshape a Vector\nWrite a function that accept three inputs. The first one is a row vector S. The second and third arguments are m and n which de...\n\nfast 7 Jahre ago\n\nSolved\n\nMax of a Vector\nWrite a function to return the max of a vector\n\nfast 7 Jahre ago" ]
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https://unistroy.spbstu.ru/en/article/2020.91.4/
[ "# The Stress-Strain State of a Rectangular Covering Spatial Truss\n\nAuthors:\nAbstract:\n\nThe object of research is a model of a statically definable roof truss with supports on the sides of the structure. Spherical and cylindrical supports are located at two corner points of the covering, in other corners and on the sides of the structure at an equal distance from each other — stands. A multi-dome surface shape is set. For the case of loading the truss by the force in the middle of the span by the induction method according to the number of panels, the formula for the deflection is derived. Analytical dependencies of the reactions of supports on the number of panels under the action of a load uniformly distributed over the nodes of the coating surface are found. Method. The calculation of the forces in the rods and the reactions of the supports of an externally statically indeterminate truss is performed in symbolic form using the method of cutting nodes. To compose a system of equilibrium equations and obtain a solution, the operators of the Maple computer mathematics system are used. The deflection is determined by the Maxwell-Mohr's formula. Based on the data on the solution of a series of trusses with a sequentially increasing number of panels by the induction method, formulas for the dependence of the deflection on the load, the size and number of panels of the structure are derived. Operators of the genfunc software package from the Maple computer mathematics system are used to compose and solve homogeneous linear recurrent equations, which are satisfied by the sequences of the coefficients of the sought dependencies. Results. Dependences of deflection and forces on the number of panels have a form polynomial in the number of panels. It is shown that the vertical reactions of the corner supports can have negative signs, which makes it necessary to use retaining supports here. The curves illustrating the solution have a clearly pronounced jump-like shape. The quadratic asymptotics of the solution is found both in terms of the number of panels and linear in height. The dependence of the deflection on the height has a theoretically permissible minimum.\n\nThe considered scheme of a spatial statically definable roof truss allows an analytical solution to the deflection problem. The obtained dependences can be used to estimate the accuracy of numerical solutions and in problems of optimization of the structure in terms of rigidity and solutions." ]
[ null ]
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https://techhyme.com/number-systems/
[ "# [#3] – Number systems – Questions", null, "As we already know that a computer stores data internally in a format that is not easily readable by human beings. This is the reason why input and output (I/O) interfaces are required. Every computer stores numbers, letters, and other special characters in coded form. Before going into the details of these codes, it is essential to have a basic understanding of number system.\n\nNumber systems are of two types – Non-positional and Positional. In early days, human beings counted on fingers when couting beyond ten fingers, they used stones, pebbles, or sticks to indicate values. This method of counting uses an additional approach or non-positional number system. In this system, we have symbols such as I for 1, II for 2, III for 3, IIII for 4, IIIII for 5 etc. Each symbol represents the same value regardless of its position in a number, and to find the value of a number, one has to count the number of symbols presents in the number. Since it is very difficult to perform arithmetic with such a number system, positional number systems were developed.\n\nPoints To Remember:\n\n• Number systems are of two types – non-positional and positional\n• In a non-positional number system, each symbol represents the same value regardless of its position in the number and to find the value of a number, one has to count the number of symbols present in the number. It is very difficult to perform arithmetic with such a number system.\n• In a positional number system, there are only a few symbols called digits. These symbols represent different values depending on the position they occupy in a number. The value of each digit in such a number is determined by three considerations:\n– The digit itself.\n– The position of the digit in the number, and\n– The base of the number system (where base is defined as the total number of digits available in the number system).\n• In our day-to-day life, we use the decimal number system. In this system, base is equal to 10 because there are altogether ten symbols or digits (0, 1, 2, 3, 4, 5, 6, 7, 8, and 9).\n• Some positional number systems that are used in computer design and by computer professionals are binary (having base 2), octal (having base 8), and hexadecimal (having base 16).\n• Readers must know the techniques for following types of conversions to convert numbers from one base to another:\n– Converting from another base to decimal\n– Converting from decimal to another base\n– Converting from a base other than 10 to another base other than 10\n– Shortcut method for binary to octal conversion\n– Shortcut method for octal to binary to hexadecimal conversion\n– Shortcut method for octal to binary conversion\n– Shortcut method for hexadecimal to binary conversion\n\nList of Questions\n\n1. Differentiate between positional and non-positional number systems? Write examples of both types of number systems.\n2. What is base of a number system? Write examples to illustrate the role of base in positional number systems.\n3. What is the value of base for decimal, hexadecimal, binary, and octal number systems?\n4. Write an example for octal number system to show that the same digit may signify different values depending on the position it occupies in the number.\n5. What will be the total number of different symbols or digits and the maximum value of a single digit for the following number systems:\n– Number system with base 5\n– Number system with base 20\n– Number system with base 9\n– Number system with base 12\n6. What is a ‘bit’ in computer terminology? How many different patterns of bits are possible with\n(a) 6 bits\n(b) 7 bits\n(c) 8 bits\n7. Explain the meaning of the term “memory dump”.\n8. Why do we use octal and/or hexadecimal number systems as shortcut notations?\n9. Find decimal equivalent of following binary numbers:\n– 1101011 1000\n– 11010 10110001100\n– 10110011 110001\n– 11011101 1010101100\n– 1110101 111\n10. Find octal equivalent of the binary numbers of question 9.\n11. Find hexadecimal equivalent of the binary numbers of question 9.\n12. Convert the following numbers to decimal numbers:\n– 1101102\n– 2A3B16\n– 25736\n– 12349\n13. Convert the following decimal numbers to binary numbers:\n– 43510\n– 3210\n– 169410\n– 13510\n14. Convert the decimal numbers of question 13 to octal numbers.\n15. Convert the decimal numbers of question 13 to hexadecimal numbers.\n16. Carry out the following conversions:\n– 1256 =?4\n– 249 =?3\n– ABC16 =?8\n17. Convert the following numbers to their binary equivalent:\n– 2AC16\n– 26148\n– FAB16\n– 5628\n18. Find decimal equivalent of following numbers:\n– 111.01\n– 247.65\n– 1001.011\n– A2B.D4" ]
[ null, "https://techhyme.com/wp-content/uploads/2021/07/Techhyme-Computer-Fundamentals.png", null ]
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https://hssliveguru.com/plus-two-physics-chapter-wise-questions-and-answers-chapter-1/
[ "# Plus Two Physics Chapter Wise Questions and Answers Chapter 1 Electric Charges and Fields\n\nStudents can Download Chapter 1 Electric Charges and Fields Questions and Answers, Plus Two Physics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.\n\n## Kerala Plus Two Physics Chapter Wise Questions and Answers Chapter 1 Electric Charges and Fields\n\n### Plus Two Physics Electric Charges and Fields NCERT Text Book Questions and Answers\n\nQuestion 1.\nWhat is the force between two small charged spheres having charges of 2 × 10-7C and 3 × 10-7 C placed 30cm apart in air?\nGiven q1 = 2 × 10-7C, q1 = 3 × 10-7 C\nr = 30cm = 0.3m\nForce of repulsion", null, "", null, "Question 2.\nWhen a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenemenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge.\nWhen a glass rod is rubbed with silk, the charges developed on the glass rod and the piece of silk are equal and opposite. Similar is the case in other pair of bodies. So electric charge is neither be produced nor destroyed but simply transferred from one body to another, hence is consistent with the law of conservation of charge.\n\nQuestion 3.\nAn electric dipole with dipole moment 4 × 109 cm is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 104NC-1. Calculate the magnitude of the torque acting on the dipole.\nGiven\np = 4 × 10-9cm, θ = 30°, E = 5 × 104 NC-1, τ = ?\nSince τ = pEsinθ\n= 4 × 109 × 5 × 104 × sin 30°\n= 20 × 10-5 × 1/2 = 10-4Nm.", null, "Question 4.\nA Polythene piece rubbed with wool is found to have a negative charge of 3 × 107C.\n\n1. Estimate the number of electrons transferred from which to which?\n2. Is there a transfer of mass from wool to polythene?\n\n1. Charge on one electron\n∴ Number of electrons in the given charge", null, "= 1.875 × 1012 = 2 × 1012\n\n2. Since woold gets negative charge on rubbing with polythene, wool must gain electrons from polythene.\n∴ Ideally speaking there must be a transfer of mass due to transfer of electrons but since the mass of electron is very small, this transfer of mass may be negligible (=2 × 1018kg).\n\nQuestion 5.\nA uniformly charged conducting spheres of 2.4m diameter has a surface change density of 80.0m cm-2.\n\n1. Find the charge on the sphere.\n2. What is the total electric flux leaving the surface of the sphere?\n\nGiven σ = 80.0µcm-2 = 80 × 10-6cm-2\nD = 2.4m, r=1.2m\n1. Charge on the sphere,\nq = σ × 4πr2\n= 80 × 10-6 × 4 × 3.142 ×(1.2)2\n= 1.45 × 10-3C.\n\n2. Electric flux,\nΦ = $$\\frac{q}{\\varepsilon_{0}}=\\frac{1.45 \\times 10^{-3}}{8.854 \\times 10^{-12}}$$\n= 16 × 108 NC-1m2", null, "Question 6.\nAn infinite line charge produces a field of 9 × 104 NC-1 at a distance of 2cm. Calculate the linear charge density.\nGiven E = 9 × 104 NC-1, r = 2cm = 0.02m", null, "### Plus Two Physics Electric Charges and Fields One Mark Questions and Answers\n\nQuestion 1.\nA point charge Q is place at the center of a cube of side, i the electric flux emerging the cube is.", null, "(d) $$\\frac{q}{\\varepsilon_{0}}$$\n\nQuestion 2.\nA hollowing insulated conduction sphere is given a positive charge of 10p. what will be the electric field at the center of the sphere if its radius is 2 meters?\n(a) 20 μ Cm-2\n(b) 5 Cm\n(c) zero\n(d) 8 Cm\n(a) 20 μ Cm-2", null, "Question 3.\nA charge Q μ C is placed at the center of a cube, the flux coming out from each face will be.", null, "(a) $$\\frac{Q}{6 \\varepsilon_{0}} \\times 10^{-6}$$\nExplanation: For complete cube Φ = $$\\frac{Q}{\\varepsilon_{0}} \\times 10^{-6}$$\nFor each face Φ = $$\\frac{1}{6}$$ $$\\frac{Q}{\\varepsilon_{0}} \\times 10^{-6}$$\n\nQuestion 4.\nPick the odd one out of the following based on electric field intensity.\n(i) Point charge\n(ii) Uniformly charged sphere\n(iii) Uniformly charged cube\n(iv) Uniformly charged sheet\n(iv) Uniformly charged sheet (The electric field does not depend on distance)\n\nQuestion 5.\n“Electrostatic force is medium dependent that is why NaCI dissolves in water” comment on this statement.\nDielectric constant of water is 81. Hence the force between Na+ and cl reduces by 81 times.\n\nQuestion 6.\nClassify into true or false\n\n1. In a charged conductor charges reside inside and out side the conductor\n2. In a charged conductor net field is zero inside the conductor.\n\n1. False\n2. True", null, "Question 7.\nElectrostatic force is a_____force\n(i) Conservative\n(ii) non conservative\n(iii) medium independent\n(iv) dissipative Conservative\n(i) Conservative\n\n### Plus Two Physics Electric Charges and Fields Two Mark Questions and Answers\n\nQuestion 1.\nIt is safe to be inside a vehicle rather than outside, even when there is lightning and thunder. Comment on this.\nInside a spherical shell electrical field is zero. This is called electrostatic shielding. Hence it is safe to be inside a vehicle rather than outside.", null, "Question 2\nThere are two types of charges namely positive and negative.\n\n1. List any two basic properties of electric charge.\n2. Can a body have a charge of 0.8 × 1o-19 C? Which basic property of electric charge is the reason for your answer?\n\n1. Quantization of electric charge. Conservation of electric charge.\n\n2. No. According to quantisation of charge, total charge is Q = ne when ‘n’ is an intiger. Here\nn = $$\\frac{0.8 \\times 10^{-19}}{1.6 \\times 10^{-19}}$$ = 0.5 n is a fractional value.\n\n### Plus Two Physics Electric Charges and Fields Three Mark Questions and Answers\n\nQuestion 1.\nA cubical iron block is given a charge of +40m C and placed in vacuum.\n\n1. Give the direction of electric field at the centre of one face.\n2. Calculate the net flux due to the charged cube through one face.\n3. Will there be any change in the flux if it is placed underwater of dielectric constant 81. Justify.\n\n1. Normally outwards from the surface.\nTotal flux = $$\\frac{40 \\times 10^{-3}}{8.85 \\times 10^{-12}}$$ = 4.51 × 109Nm2C-1\n\n2. Through one face = $$\\frac{4.51 \\times 10^{9}}{6}$$ = 0.75 × 109Nm2C-1\n\n3. Electric flux decreases because flux depends on permittivity of medium.", null, "Question 2.\nWhen a rubber sheet is rubbed with woolen carpet, the carpet is found to acquire a positive charge of 8 × 10-7C\n1. In the above process charging is by\n\n• conduction\n• friction\n• induction\n• polarization\n\n2. Among Rubber shoe and woolen carpet which one acquire both mass and charge during rubbing? Explain.\n1. In the above process charging is by:\n\n• Friction\n\n2. Carpet is found to be positive body which means that electrons are lost from carpet to rubber shoe. Hence rubber shoe acquires charge and mass.\n\nQuestion 3.\nA glass rod rubbed with silk found to have acquired a positive charge 6.4 × 10-7C.\n1. In the above process charging is by\n\n• Induction\n• Conduction\n• Friction\n• Electromagnetic induction\n\n2. Regarding above process which statement is false\n\n• glass rod loss some mass\n• silk gain negative charge but no mass\n• Silk gain charge arid mass\n• Total charge of the silk glass system is zero\n\n3. Will the above process obey law of quantization of electric charge? Clarify your answer by finding numbers of electrons transferred to silk.\n1. In the above process charging is by:\n\n• Friction\n\n2. Regarding above process which statement is false:\n\n• Silk gains charge and mass\n\n3. yes\nNumber of electrons transferred to Silk,\nn = $$\\frac{q}{e}=\\frac{6.4 \\times 10^{-7}}{1.6 \\times 10^{-19}}$$ = 4 × 1012", null, "Question 4.\nIn a NaCI molecule there is an attractive force between Na+ ion and Cl ion\n\n1. Which law help us to find this attractive force? State the law.\n2. State the law and write it’s mathematical form\n3. Why NaCI molecule is easily soluble in water? [Hint;- Dielectric constant of water is 81]\n\n1. Coulombs law.\n\n2. The force between two changes is directly proportional to product of their charges and inversely proportional to square of the distance between them. Force on q1 due q2.\n\n3. Force between two charges depends on the medium in between them.\ni.e. F = $$\\frac{1}{4 \\pi \\varepsilon_{0} k} \\frac{q_{1} q_{2}}{r^{2}}$$\nFor water molecule K=81. Hence the force between two charge in water decreases by 81 times. As result NaCl molecule is easily soluble in water.\n\nQuestion 5.\nThere are two types of charges namely positive and negative.\n1. List any two basic properties of electric charge. (1)\n\n2. Can a body have a charge of 0.8 × 10-19 C? Which basic property of electric charge is the reason for your answer? (1)\n\n3. Name the basic property of electric charge that you can see in the equation. (1)\nRn86 → P084 + He2\n\n1. Quantization of electric charge. Conservation of electric charge.\n\n2. No. According to quantisation of charge, total charge is Q = ne when ‘n’ is an intiger. Here\nn = $$\\frac{0.8 \\times 10^{-19}}{1.6 \\times 10^{-19}}$$ = 0.5 n is a fractional value.", null, "Question 6.\nThe rectangular block shown in the figure attracts the flowing water.", null, "Identify the rectangular block as a magnet or electrically charged body. Justify your answer.\n\n• Electrically charged body.\n• Charged body attracts water flow.\n\nQuestion 7.\nFigure represent an infinite sheet of charge of surface charge density σ. You have to find electric field intensity at P due to this infinite charge.", null, "1. Can you apply Coulomb’s inverse square law to find electric field at P?\n2. Find electric field intensity at P due to this sheet\n\n1. No.\n\n2. Field due to A uniformly charged infinite plane sheet:", null, "Consider an infinite thin plane sheet of change of density σ.\nTo find electric field at a point P (at a distance ‘r’ from sheet), imagine a Gaussian surface in the form of cylinder having area of cross section ‘ds’.\nAccording to Gauss’s law we can write,", null, "But electric field passes only through end\nsurfaces ,so we get ∫ ds = 2ds", null, "E is directed away from the charged sheet, if σ is positive and directed towards the sheet if σ is negative.\n\n### Plus Two Physics Electric Charges and Fields Four Mark Questions and Answers\n\nQuestion 1.\nTwo charges +3µC and -3µC are separated by a very small distance of 5mm.\n1. What is the name of the above arrangement?\n\n2. If the above arrangement is placed in a uniform electric field of intensity 3 × 10-5 N/C with its axis perpendicular to the field direction. What is the torque acting on it?\n\n3. If the arrangement is placed in a non uniform electric field, what happens?\n\n1. Electric dipole.\n\n2. τ = P × E\n= PE (θ = 90°) = q2aE\n= 3 × 10-6 × 5 × 10-3 × 3 × 10-5 Nm(∴ 2a = 5 × 10-3)\n\n3. The dipole undergoes for both translation and rotational motion.", null, "Question 2.\nNaCI when placed in a uniform electric field 20VM-1, both Na+ and Cl ions experience a force (average distance between Na+ and Cl is 1.3A°).\n\n1. In what way the NaCI will orient in the electric field.\n2. Arrive an expression for torque experienced by the dipole.\n3. Calculate the maximum torque experience by the NaCl molecule in the electric field.\n\n1. ‘Na’ is orienting towards -ve side and cl ions towards +ve side.\n\n2.", null, "Consider an electric dipole of dipole moment P = 2aq kept in a uniform external electric field, inclined at an angle θ to the field direction.\ntorque = any one force × perpendicular distance τ = qE × 2 a sin θ\nSince P = 2aq\nτ = p E sin θ\nVectorialy", null, "3. τ = q2a.E\nτ = 1.6 × 10-19 × 1.3 × 10-10 × 20 Nm\n= 41.6 × 10-29 Nm.", null, "Question 3.\nA metal sphere of radius R carrying q (+ve) charges is shown in the figure.", null, "1. Draw the electric lines of force related to this metal sphere.\n\n2. Derive the strength of electric field at a distance ‘r’ from the centre of sphere.\n\n3. “A sphere of radius 1cm can hold a charge of 1 coulomb” Comment on the statement.\n[Hint:- The dielectric strength of air is 3 × 106 v/m]\n1.", null, "2. Field due to A uniformly charged thin spherical shell:\nConsider a uniformly changed hollow spherical conductor of radius R. Let ‘q’ be the total charge on the surface.", null, "To find the electric field at P (at a distance r from the centre), we imagine a Gaussian spherical surface having radius r.\nThen, according to Gauss’s theorem we can write,", null, "The electric field is constant, at a distance ‘r’. So we can write,", null, "Case -1: Electric field inside the shell is zero.\nCase – II: At the surface of shell r = R\n∴ E = $$\\frac{1}{4 \\pi \\varepsilon_{0}} \\frac{q}{R^{2}}$$\n\n3. The Electric field intensity due to Ic,", null, "E = 9 × 1013v/m.\nThis Electric field is higher than the dielectric strength of air (3 × 106v/m). Hence the charge will leak through air.", null, "Question 4.\nTwo metal plates A and B are connected to cell of emf 2V is shown in the figure", null, "1. Redraw the diagram and draw lines of forces to represent electric field.\n2. Calculate the value of electric field between A and B.\n3. A charged particle starting from rest moves in the opposite direction of electric field, is it an electron or proton?\n4. Calculate acceleration of above particle.\n\n1. Diagram and draw lines of forces to represent electric field:", null, "2. E = $$\\frac{v}{d}=\\frac{2}{1 \\times 10^{-3}}$$ = 2 × 103 v/m.\n\n3. Electron. Electron flows from lower potential to higher potential ie. flows from -ve terminal to +ve terminal.\n\n4. F = eE , ma = eE", null, "a = 3.5 × 1014 m/sec2.\n\nQuestion 5.\nTwo closed surface S1 and S2 enclose two charges q1 and q2 as shown in the figure.", null, "1. State the law in electrostatic that relates the electric flux passing through the surface with the charge enclosed. (1)\n2. If q1 = +6µC and q2 = -4µC find the ratio of the flux passing through surfaces S1 and S2. (2)\n3. Let the surface S2 expands to double its area while S1 remains as such. What will happen to the above ratio? (1)\n\n1. The net flux of electric field passing through a closed surface is equal to 1/ε0 times the charge enclosed by the surface.\n\n2. By Gauss’ theorem flux passing through a", null, "3. Remains the same (because electric flux is independent of the size and shape of the enclosed surface).", null, "Question 6.\nA spherical shell of radius R is uniformly charged to a surface charge density σ.\n\n1. State the theorem which can be used to find the electric field outside the shell.\n2. Using the theorem arrive at an expression for electric field at a distance r from the centre of the spherical shell.\n3. It is safe to be inside a vehicle rather than outside, even when there is lightning and thunder. Comment on this. (HSES.Q.P)\n\n1. Gauss’s theorem states that the total electric flux over a closed surface is 1/ε0 times the total charge enclosed by the surface.\n\n2. Field due to A uniformly charged thin spherical shell:\nConsider a uniformly changed hollow spherical conductor of radius R. Let ‘q’ be the total charge on the surface.", null, "To find the electric field at P (at a distance r from the centre), we imagine a Gaussian spherical surface having radius r.\nThen, according to Gauss’s theorem we can write,", null, "The electric field is constant, at a distance ‘r’. So we can write,", null, "Case -1: Electric field inside the shell is zero.\nCase – II: At the surface of shell r = R\n∴ E = $$\\frac{1}{4 \\pi \\varepsilon_{0}} \\frac{q}{R^{2}}$$.\n\n3. Inside a spherical shell electrical field is zero. This is called electrostatic shielding. Hence it is safe to be inside a vehicle rather than outside.", null, "Question 7.\nq1, q2, and q3 are three point charges located in free space\n\n1. What is the force between q1 and q2, if q3 is absent?\n2. What is the force between q1 and q2 if q3 is present?\n3. State the principle used to find total force on q1 and calculate total force F1 on q1\n4. Draw the vector diagram representing individual forces and total force on q1.\n\n1.", null, "2.", null, "3. Total force on q1 can be found using super position principle ie.", null, "", null, "Where r12 is the distance between q1 and q2 and r13 is the force between q1 and q3", null, "", null, "Question 8.\nVariation of field with distance of a charged conducting shell is given below. R is the radius of the sphere\n1. field is maximum at\n\n• centre of the sphere\n• at r<R\n• at r>R\n• at r = R (surface)\n\n2. From the graph find value of field at centre. Give on practical application of this result\n\n3. Draw the potential -distance graph in the above case", null, "1. at r = R\n\n2. E = 0\n\n• It is safe to be sit inside car during lightning\n• Sensitive electrical instruments can be pro-tected from external electric field by placing inside a metal box.\n\n3.", null, "### Plus Two Physics Electric Charges and Fields Five Mark Questions and Answers\n\nQuestion 1.\nTwo-point charges q1 and q2 are separated by a distance ‘r’ in space\n1. What happens to the force between the charges;\n\n• When the magnitude of the point charges increases\n• When the distance of separation decreases\n\n2. Three-point charges +2µC each are placed at the corners of an equilateral triangle of side 1 m. Find the magnitude of the force between charge q1 and q1 [F12] and q1 and q3 [F13].\n\n3. Draw $$\\overrightarrow{\\mathrm{F}}_{12}$$ and $$\\overrightarrow{\\mathrm{F}}_{13}$$ at A and find the total force acting on q1.\n1. The force between the charges:\n\n• Force increases\n• Force decreases\n$$F=\\frac{1}{4 \\pi \\varepsilon_{0}} \\frac{q_{1} \\times q_{2}}{r^{2}}$$\n\n2. Force between q1 and q2", null, "= 36 × 10-3 N.\n\n3.", null, "= 62.35 × 10-6 N.", null, "Question 2.\nMatch the following", null, "(a) E = constant\n(b) E ∝ 1/r\n(c) E ∝ 1/r3\n(d) E ∝ 1/r2\n(e) E = O\n\nQuestion 3.\nAn electric dipole is placed in a uniform electric field . of Intensity E as shown in the figure.", null, "1. What are the forces on +q and -q?\n2. What is the net force on the system?\n3. Copy the diagram, mark the forces and derive an expression for torque.\n4. If the dipole is placed in a non uniform electric field what nature of motion does it show?\n\n1. Force on +q, F+ = +qE (along the direction of electric field)\nForce on -q, F = -qE (Opposite to the direction of electronic field)\n\n2. Net force on the system is zero.\n\n3.", null, "Consider an electric dipole of dipole moment P = 2aq kept in a uniform external electric field, inclined at an angle θ to the field direction.\ntorque = any one force × perpendicular distance τ = qE × 2 a sin θ\nSince P = 2aq\nτ = p E sin θ\nVectorialy", null, "4. In nonuniform electric field, total force is not zero. Hence the dipole undergoes for both translational and rotational motion.", null, "Question 4.\nIn electrostatics, Electric charge is a feature of particles like protons, electrons, etc. that decides the\nforce of interaction among them.\n1. Write the name of the law that is used to measure the above force of interaction.\n\n2. Express the above law in vector form.\n\n3. Two charged spheres when placed in air attract with a force F. Keeping the distance between the charges constant, the spheres are immersed in a liquid of relative permittivity K. Then the spheres will.\n\n• attract with a force KF\n• repel with a force KF\n• attract with a force F/K\n• repel with a force F/K\n\n4. Two small aluminum spheres are separated by 80cm. How many electrons are to be transferred from one sphere to the other so that they attract with a force of 104N.\n1. Coulomb’s law in electrostatics\n\n2.", null, "3. Attract with a force F/K\n\n4. If n electrons are transferred, charge on each sphere Q = ne", null, "n = 5.27 × 1015\n\nQuestion 5.\nIntensity of electric field is a vector quantity.\n1. Define intensity of electric field at a point.\n\n2. Two small spheres A and B carrying charges 2µC and 6µC respectively are separated by a fixed distance. Intensity of electric field at the location of B due to A is E. Intensity of electric field at the location of A due B is\n\n• E\n• 3E\n• 6E\n• 12E\n\n3. Two-point charges +4nC and +5nC are placed at x = 0.2m and x = 0.3m respectively along the x-axis. Find the magnitude and direction of intensity of electric field at the origin.\n1. Intensity of electric field at point is the electrostatic force experienced by unit positive charge placed at that point.\n\n2. 3E\n\n3.", null, "Intensity of electric field at the origin due to the negative charge", null, "E(-) = 500NC-1 along -ve x axis\nIntensity of electric field at the origin due to the positive charge", null, "E(+) = 900NC-1 along -ve x axis\nNet intensity of electric field at the origin\nE = E(+) + E(-) = 500 + 900 = 1400 NC-1 along -ve x axis.", null, "Question 6.\nYou find a sealed box on your door step. You suspect that the box contain charged metal spheres packed in insulating material.\n\n1. Which law explains relation between charge of spheres and electric flux.\n2. State the law.\n3. Give a mathematical proof for this law.\n4. Using this law, can you estimate the total charge inside the box without opening the box?\n\n1. Gauss’s theorem\n\n2. Gauss’s theorem states that electric flux over a closed surface is 1/ε0 times the total charge enclosed by the surface.\nGauss’s theorem may be expressed as", null, "3. Gauss’S Law:\nGauss’s theorem states that the total electric flux over a closed surface is 1/ε0 times the total charge enclosed by the surface.\nGauss’s theorem may be expressed", null, "Proof:", null, "Consider a charge +q .which is kept inside a sphere of radius ‘r’.\nThe flux at ‘P’ can be written as,", null, "But electric field at P, E =", null, "", null, "Important points regarding Gauss’s law:\n\n• Gauss’s law is true for any closed surface.\n• Total charge enclosed by the surface must be added (algebraically). The charge may be located anywhere inside the surface.\n• The surface that we choose for the application of Gauss’s law is called the Gaussian surface.\n• Gauss’s law is used to find electric field due to system of charges having some symmetry.\n\n4.", null, "", null, "Question 7.\n\n• Write an expression to find electric flux passing through small element ds\n• Which law helps to find total flux passing through a closed surface? State the law.\n• Using this law, derive an expression for electric field due to thin uniformly charged shell.\n• How can we protect delicate instruments from external electric field?", null, "1.", null, "2. Gauss’s law:\nGuass’s law states that total flux over a closed surface is 1/s0 times net charge enclosed by the surface.\n\n3. Field due to A uniformly charged infinite plane sheet:", null, "Consider an infinite thin plane sheet of change of density σ.\nTo find electric field at a point P (at a distance ‘r’ from sheet), imagine a Gaussian surface in the form of cylinder having area of cross section ‘ds’.\nAccording to Gauss’s law we can write,", null, "But electric field passes only through end\nsurfaces ,so we get ∫ ds = 2ds", null, "E is directed away from the charged sheet, if σ is positive and directed towards the sheet if σ is negative.\n\n4. Delicate instruments can be protected from ex-ternal electric field by keeping it in a metal cavity." ]
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https://www.numerade.com/questions/find-the-limit-use-lhospitals-rule-where-appropriate-if-there-is-a-more-elementary-method-conside-39/
[ "💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!", null, "# Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why.$\\displaystyle \\lim_{x\\to -\\infty} x\\ln \\left( 1 - \\frac{1}{x} \\right)$\n\n## $-1$\n\nDerivatives\n\nDifferentiation\n\nVolume\n\n### Discussion\n\nYou must be signed in to discuss.\n##### Top Calculus 2 / BC Educators", null, "", null, "", null, "", null, "##### Michael J.\n\nIdaho State University\n\nLectures\n\nJoin Bootcamp\n\n### Video Transcript\n\nSo this problem we're gonna be using luke tells role in order to determine the limit of the function. So uh here are function is X times the natural log of one minus, so X times natural log of one minus one over X. Mhm. So this can be rewritten um as this right here divided by one over X. And the reason we do this is so that way we can substitute T to equal one over X. That way as x goes to infinity, t goes to zero. So now when we evaluate this we get 0/0. That's the indeterminant form, but we can take the derivative of it and that will end up giving us one down here. Uh This will give us a negative 1/1 -1 key. That's an ultimately going to be negative 1/1 0. That'll be negative one as our final answer.", null, "California Baptist University\n\n#### Topics\n\nDerivatives\n\nDifferentiation\n\nVolume\n\n##### Top Calculus 2 / BC Educators", null, "", null, "", null, "", null, "##### Michael J.\n\nIdaho State University\n\nLectures\n\nJoin Bootcamp" ]
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