text: I have been searched everywhere to find a way to convert float to octal or binary. I know about the
  float.hex
  float.fromhex
  12.325
  14.246
  Here's the solution, explanation below:
  def ToLessThanOne(num): # Change "num" into a decimal <1 while num > 1: num /= 10 return num def FloatToOctal(flo, places=8): # Flo is float, places is octal places main, dec = str(flo).split(".") # Split into Main (integer component) # and Dec (decimal component) main, dec = int(main), int(dec) # Turn into integers res = oct(main)[2::]+"." # Turn the integer component into an octal value # while removing the "ox" that would normally appear ([2::]) # Also, res means result # NOTE: main and dec are being recycled here for x in range(places): main, dec = str((ToLessThanOne(dec))*8).split(".") # main is integer octal # component # dec is octal point # component dec = int(dec) # make dec an integer res += main # Add the octal num to the end of the result return res # finally return the result
  So you can do
  print(FloatToOctal(12.325)) and it shall print out
  14.246314631
  Finally, if you want less octal places (decimal places but in octal) simply add the
  places argument:
  print(FloatToOctal(12.325, 3)) which returns
  14.246 as is correct according to this website: