text: I want the operator to take off fractionnary part of a real number
  ex 23,345 ------->23
  This is a discussion on take off fractionnary part within the C Programming forums, part of the General Programming Boards category; I want the operator to take off fractionnary part of a real number ex 23,345 ------->23...
  I want the operator to take off fractionnary part of a real number
  ex 23,345 ------->23
  >> operator <<
  Well, there is no operator for that (or at least not to my knowledge). You'll probably just have to write a function to do that.
  --Garfield
  1978 Silver Anniversary Corvette
  I think you meant "." instead of "," ... anyway:
  float a;
  int b;
  a = 23.456;
  b = (int) a;
  a = (float) b;
  Problem solved.
  /**
  *** EDIT:
  **/
  Actually:
  a = (int) a;
  That should work.
  /**
  *** END EDIT.
  **/
  Quzah.
  Hope is the first step on the road to disappointment.
  Oh, if you meant "." then quzah is right. I thought you wanted to round off or something.
  The reason being is because a float that is typecasted to an int can't support the fractionality of the float so it cuts it off. Just a little insight of why that happens.
  --Garfield
  1978 Silver Anniversary Corvette
  One way is to use the floor() function in math.h
  Code:#include <stdlib.h> #include <stdio.h> #include <math.h> int main(void) { double d = 23.345; d = floor(d); printf("d:%lf\n",d); return 0; }
  You seek Yoda
  Or this
  -----
  #include <math.h>
  double modf(double VAL, double *IPART);
  float modff(float VAL, float *IPART);
  Description
  ------------
  `modf' splits the double VAL apart into an integer part and a
  fractional part, returning the fractional part and storing the integer
  part in `*IPART'. No rounding whatsoever is done; the sum of the
  integer and fractional parts is guaranteed to be exactly equal to VAL.
  That is, if . REALPART = modf(VAL, &INTPART); then
  ``REALPART+INTPART'' is the same as VAL. `modff' is identical, save
  that it takes and returns `float' rather than `double' values.
  -----