text: Carlo Florendo wrote: > David Rothenberger wrote: >> On 7/18/2007 9:03 PM, Carlo Florendo wrote: >>> I've got (and attached) this simple Makefile that checks the build >>> platform of a machine. >>> >>> Here's the cut-and-pasted content of the Makefile: >>> >>> PLATFORM=$(shell uname -s | cut -f 1 -d " " | cut -f 1 -d "_"); >> >> Try removing the trailing semicolon. It is not removed by make, so >> PLATFORM ends up being "CYGWIN;". > > Bingo. That did it! > > So does that mean that make 3.80 was wrong then? Please ignore this, sorry. Both have the correct behaviour. When expanded under Linux, the make statements become ifeq ("Linux;", "CYGWIN) echo cygwin; else echo linux; endif it will "correctly" output "linux" but it got to the else conditional only because "Linux;" != "CYGWIN. The trailing semi-colon confused me. I was treating the Makefile as a bash script. Thanks, David! -- Unsubscribe info: Problem reports: Documentation: FAQ: