text: Hi there,
  I’m working on this challenge: codecademy.com/courses/learn-python-3/articles/python-code-challenges-lists
  Question 4 is the following:
  - Define the function to accept three parameters, a list of numbers, a number to look for, and a number for the number of instances
  - Count the number of occurrences of
  item(the second parameter) in
  lst(the first parameter)
  - If the number of occurrences is greater than
  n(the third parameter), return
  True. Otherwise, return
  False
  In the solution I’ve seen that I could use
  def more_than_n(lst, item, n): if lst.count(item) > n: return True else: return False
  However, I was trying to build a loop myself and it does run but doesn’t return the desired result. Where’s my mistake, how can I get to the same result as the code above?
  def more_than_n(lst, item, n): count = 0 for i in (0,len(lst)-1): if lst[i] == item: count += 1 else: count += 0 if count > n: return True else: return False
  The following should return True but returns False with my code:
  print(more_than_n([2, 4, 6, 2, 3, 2, 1, 2], 2, 3))