def braceexpand(pattern, escape=True):
    """braceexpand(pattern) -> iterator over generated strings

    Returns an iterator over the strings resulting from brace expansion
    of pattern. This function implements Brace Expansion as described in
    bash(1), with the following limitations:

    * A pattern containing unbalanced braces will raise an
      UnbalancedBracesError exception. In bash, unbalanced braces will either
      be partly expanded or ignored.

    * A mixed-case character range like '{Z..a}' or '{a..Z}' will not
      include the characters '[]^_`' between 'Z' and 'a'.

    When escape is True (the default), characters in pattern can be
    prefixed with a backslash to cause them not to be interpreted as
    special characters for brace expansion (such as '{', '}', ',').
    To pass through a a literal backslash, double it ('\\\\').

    When escape is False, backslashes in pattern have no special
    meaning and will be preserved in the output.

    Examples:

    >>> from braceexpand import braceexpand

    # Integer range
    >>> list(braceexpand('item{1..3}'))
    ['item1', 'item2', 'item3']

    # Character range
    >>> list(braceexpand('{a..c}'))
    ['a', 'b', 'c']

    # Sequence
    >>> list(braceexpand('index.html{,.backup}'))
    ['index.html', 'index.html.backup']

    # Nested patterns
    >>> list(braceexpand('python{2.{5..7},3.{2,3}}'))
    ['python2.5', 'python2.6', 'python2.7', 'python3.2', 'python3.3']

    # Prefixing an integer with zero causes all numbers to be padded to
    # the same width.
    >>> list(braceexpand('{07..10}'))
    ['07', '08', '09', '10']

    # An optional increment can be specified for ranges.
    >>> list(braceexpand('{a..g..2}'))
    ['a', 'c', 'e', 'g']

    # Ranges can go in both directions.
    >>> list(braceexpand('{4..1}'))
    ['4', '3', '2', '1']

    # Unbalanced braces raise an exception.
    >>> list(braceexpand('{1{2,3}'))
    Traceback (most recent call last):
        ...
    UnbalancedBracesError: Unbalanced braces: '{1{2,3}'

    # By default, the backslash is the escape character.
    >>> list(braceexpand(r'{1\{2,3}'))
    ['1{2', '3']

    # Setting 'escape' to False disables backslash escaping.
    >>> list(braceexpand(r'\{1,2}', escape=False))
    ['\\\\1', '\\\\2']

    """
    return (_flatten(t, escape) for t in parse_pattern(pattern, escape))
braceexpand(pattern) -> iterator over generated strings

    Returns an iterator over the strings resulting from brace expansion
    of pattern. This function implements Brace Expansion as described in
    bash(1), with the following limitations:

    * A pattern containing unbalanced braces will raise an
      UnbalancedBracesError exception. In bash, unbalanced braces will either
      be partly expanded or ignored.

    * A mixed-case character range like '{Z..a}' or '{a..Z}' will not
      include the characters '[]^_`' between 'Z' and 'a'.

    When escape is True (the default), characters in pattern can be
    prefixed with a backslash to cause them not to be interpreted as
    special characters for brace expansion (such as '{', '}', ',').
    To pass through a a literal backslash, double it ('\\\\').

    When escape is False, backslashes in pattern have no special
    meaning and will be preserved in the output.

    Examples:

    >>> from braceexpand import braceexpand

    # Integer range
    >>> list(braceexpand('item{1..3}'))
    ['item1', 'item2', 'item3']

    # Character range
    >>> list(braceexpand('{a..c}'))
    ['a', 'b', 'c']

    # Sequence
    >>> list(braceexpand('index.html{,.backup}'))
    ['index.html', 'index.html.backup']

    # Nested patterns
    >>> list(braceexpand('python{2.{5..7},3.{2,3}}'))
    ['python2.5', 'python2.6', 'python2.7', 'python3.2', 'python3.3']

    # Prefixing an integer with zero causes all numbers to be padded to
    # the same width.
    >>> list(braceexpand('{07..10}'))
    ['07', '08', '09', '10']

    # An optional increment can be specified for ranges.
    >>> list(braceexpand('{a..g..2}'))
    ['a', 'c', 'e', 'g']

    # Ranges can go in both directions.
    >>> list(braceexpand('{4..1}'))
    ['4', '3', '2', '1']

    # Unbalanced braces raise an exception.
    >>> list(braceexpand('{1{2,3}'))
    Traceback (most recent call last):
        ...
    UnbalancedBracesError: Unbalanced braces: '{1{2,3}'

    # By default, the backslash is the escape character.
    >>> list(braceexpand(r'{1\{2,3}'))
    ['1{2', '3']

    # Setting 'escape' to False disables backslash escaping.
    >>> list(braceexpand(r'\{1,2}', escape=False))
    ['\\\\1', '\\\\2']