{"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `concert_Name` FROM `concert`","question":"Show the different concert_Name in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the different `concert_Name` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT \"concert_Name\" FROM \"concert\";\n```\n\nThis query will return all unique concert names in your `concert` table.","cost":0.0005607,"response_parsed":"SELECT DISTINCT \"concert_Name\" FROM \"concert\";","time":3.9922719002}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Theme` FROM `concert`","question":"Show the different Theme in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different themes in the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Theme FROM concert;\n```\n\nThis query will return all unique values in the `Theme` column of the `concert` table.","cost":0.0004644,"response_parsed":"SELECT DISTINCT Theme FROM concert;","time":2.8984794617}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Stadium_ID` FROM `concert`","question":"Show the different Stadium_ID in the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different `Stadium_ID` values in the `concert` table, you can use the `SELECT DISTINCT` statement. Here's the SQL code:\n\n```sql\nSELECT DISTINCT Stadium_ID FROM concert;\n```","cost":0.0004815,"response_parsed":"SELECT DISTINCT Stadium_ID FROM concert;","time":2.7718403339}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Year` FROM `concert`","question":"Show the different Year in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different years in the `concert` table, you can use the `SELECT DISTINCT` statement to fetch unique values from the `Year` column.\n\n```sql\nSELECT DISTINCT Year FROM concert;\n```","cost":0.0005931,"response_parsed":"SELECT DISTINCT Year FROM concert;","time":4.1850230694}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Location` FROM `stadium`","question":"Show the different Location in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different locations in the `stadium` table, you can use the `DISTINCT` keyword to fetch unique locations.\n\n```sql\nSELECT DISTINCT Location FROM stadium;\n```","cost":0.0005283,"response_parsed":"SELECT DISTINCT Location FROM stadium;","time":3.3268442154}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `stadium`","question":"Show the different Name in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different names in the `stadium` table, you can use the `SELECT DISTINCT` statement to retrieve unique values from the `Name` column.\n\n```sql\nSELECT DISTINCT \"Name\" FROM \"stadium\";\n```","cost":0.000567,"response_parsed":"SELECT DISTINCT \"Name\" FROM \"stadium\";","time":3.9696099758}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `singer`","question":"Show the different Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different names in the \"singer\" table, you can use the `DISTINCT` keyword to fetch unique names.\n\n```sql\nSELECT DISTINCT Name FROM singer;\n```","cost":0.0005067,"response_parsed":"SELECT DISTINCT Name FROM singer;","time":3.2225604057}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Country` FROM `singer`","question":"Show the different Country in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different countries in the `singer` table, you can use the `SELECT DISTINCT` statement to fetch unique country values.\n\n```sql\nSELECT DISTINCT Country FROM singer;\n```","cost":0.000468,"response_parsed":"SELECT DISTINCT Country FROM singer;","time":2.7110192776}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Song_Name` FROM `singer`","question":"Show the different Song_Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the different `Song_Name` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Song_Name FROM singer;\n```\n\nThis query will return all unique song names present in the `singer` table.","cost":0.0005616,"response_parsed":"SELECT DISTINCT Song_Name FROM singer;","time":3.7307326794}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Song_release_year` FROM `singer`","question":"Show the different Song_release_year in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the different `Song_release_year` values from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Song_release_year FROM singer;\n```\n\nThis query will return all unique values in the `Song_release_year` column of the `singer` table.","cost":0.0005094,"response_parsed":"SELECT DISTINCT Song_release_year FROM singer;","time":3.0629169941}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Singer_ID` FROM `singer_in_concert`","question":"Show the different Singer_ID in the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show the different `Singer_ID` in the table `singer_in_concert`, you can use the `DISTINCT` keyword to fetch unique `Singer_ID` values.\n\n```sql\nSELECT DISTINCT Singer_ID FROM singer_in_concert;\n```","cost":0.0006381,"response_parsed":"SELECT DISTINCT Singer_ID FROM singer_in_concert;","time":4.669604063}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `concert_Name`, COUNT(*) FROM `concert` GROUP BY `concert_Name`","question":"For each concert_Name, count the number of rows in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `concert_Name` in the `concert` table, you can use the SQL `COUNT()` function along with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT concert_Name, COUNT(*) as number_of_concerts\nFROM concert\nGROUP BY concert_Name;\n```\n\nThis query will:\n1. Select the `concert_Name` column\n2. Count the number of rows for each `concert_Name` using `COUNT(*)`\n3. Group the results by `concert_Name` to provide the count for each unique concert name","cost":0.000648,"response_parsed":"SELECT concert_Name, COUNT(*) as number_of_concerts\nFROM concert\nGROUP BY concert_Name;","time":4.5161576271}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Theme`, COUNT(*) FROM `concert` GROUP BY `Theme`","question":"For each Theme, count the number of rows in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `concert` table for each `Theme`, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Theme, \n COUNT(*) as Number_of_Concerts\nFROM \n concert\nGROUP BY \n Theme;\n```\n\nThis query will:\n1. Select the `Theme` column\n2. Count the number of rows for each `Theme` using `COUNT(*)`\n3. Group the results by the `Theme` column\n4. Return the results with the number of concerts for each theme","cost":0.0006417,"response_parsed":"SELECT \n Theme, \n COUNT(*) as Number_of_Concerts\nFROM \n concert\nGROUP BY \n Theme;","time":4.8203470707}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Stadium_ID`, COUNT(*) FROM `concert` GROUP BY `Stadium_ID`","question":"For each Stadium_ID, count the number of rows in table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `concert` table for each `Stadium_ID`, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Stadium_ID,\n COUNT(concert_ID) AS concert_count\nFROM \n concert\nGROUP BY \n Stadium_ID;\n```\n\nThis query will:\n1. Group all rows in the `concert` table by the `Stadium_ID`.\n2. Count the number of rows (`concert_ID`) for each `Stadium_ID`.\n3. Return the `Stadium_ID` along with the corresponding count of concerts.","cost":0.0006075,"response_parsed":"SELECT \n Stadium_ID,\n COUNT(concert_ID) AS concert_count\nFROM \n concert\nGROUP BY \n Stadium_ID;","time":4.4424579144}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Year`, COUNT(*) FROM `concert` GROUP BY `Year`","question":"For each Year, count the number of rows in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `concert` table for each year, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the `Year` column.\n\n```sql\nSELECT Year, COUNT(*) AS Number_of_Concerts\nFROM concert\nGROUP BY Year;\n```","cost":0.0005571,"response_parsed":"SELECT Year, COUNT(*) AS Number_of_Concerts\nFROM concert\nGROUP BY Year;","time":3.7692387104}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Location`, COUNT(*) FROM `stadium` GROUP BY `Location`","question":"For each Location, count the number of rows in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `stadium` table for each `Location`, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Location,\n COUNT(Stadium_ID) AS Number_of_Stadiums\nFROM \n stadium\nGROUP BY \n Location;\n```\n\nThis query will:\n1. Group the rows in the `stadium` table by the `Location` column.\n2. Count the number of rows (stadiums) for each `Location` using `COUNT(Stadium_ID)`.\n3. Return the results with the `Location` and the corresponding count of stadiums.","cost":0.0006462,"response_parsed":"SELECT \n Location,\n COUNT(Stadium_ID) AS Number_of_Stadiums\nFROM \n stadium\nGROUP BY \n Location;","time":4.6743164062}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `stadium` GROUP BY `Name`","question":"For each Name, count the number of rows in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Name` in the `stadium` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, COUNT(*) as count\nFROM stadium\nGROUP BY Name;\n```\n\nThis query will:\n1. Group the rows in the `stadium` table by the `Name` column.\n2. Count the number of rows for each unique `Name`.\n3. Return a result set with two columns: `Name` and `count`, where `count` is the number of rows for each `Name`.","cost":0.0007443,"response_parsed":"SELECT Name, COUNT(*) as count\nFROM stadium\nGROUP BY Name;","time":5.7300021648}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Location`, MIN(`Capacity`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the min of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum capacity for each location in the `stadium` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, MIN(Capacity) AS min_capacity\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will return the minimum capacity for each unique location in the `stadium` table.","cost":0.000594,"response_parsed":"SELECT Location, MIN(Capacity) AS min_capacity\nFROM stadium\nGROUP BY Location;","time":4.3086555004}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Location`, MAX(`Capacity`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the max of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum capacity for each location in the `stadium` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, MAX(Capacity) AS Max_Capacity\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will return the maximum capacity for each unique location in the `stadium` table.","cost":0.0005751,"response_parsed":"SELECT Location, MAX(Capacity) AS Max_Capacity\nFROM stadium\nGROUP BY Location;","time":4.0073423386}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Location`, AVG(`Capacity`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the avg of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average capacity for each location in the `stadium` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, AVG(Capacity) AS Average_Capacity\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will:\n1. Group the rows in the `stadium` table by the `Location` column.\n2. Calculate the average `Capacity` for each group of rows with the same `Location`.\n3. Return a result set with two columns: `Location` and `Average_Capacity` (the average capacity for that location).","cost":0.0006399,"response_parsed":"SELECT Location, AVG(Capacity) AS Average_Capacity\nFROM stadium\nGROUP BY Location;","time":4.6610853672}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Location`, SUM(`Capacity`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the sum of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Capacity` for each `Location` in the `stadium` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, SUM(Capacity) AS Total_Capacity\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will:\n1. Group the rows in the `stadium` table by the `Location` column.\n2. Calculate the sum of the `Capacity` for each group (i.e., for each `Location`).\n3. Return the `Location` and the corresponding `Total_Capacity` for each group.","cost":0.0005976,"response_parsed":"SELECT Location, SUM(Capacity) AS Total_Capacity\nFROM stadium\nGROUP BY Location;","time":5.1968686581}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Location`, MIN(`Lowest`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the min of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum value of the \"Lowest\" column for each \"Location\" in the \"stadium\" table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, MIN(Lowest) as Min_Lowest\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will return the minimum value of the \"Lowest\" column for each unique \"Location\" in the \"stadium\" table.","cost":0.0006777,"response_parsed":"SELECT Location, MIN(Lowest) as Min_Lowest\nFROM stadium\nGROUP BY Location;","time":5.5037698746}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Location`, MAX(`Lowest`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the max of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum value of the \"Lowest\" column for each \"Location\" in the \"stadium\" table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, MAX(Lowest) AS Max_Lowest\nFROM stadium\nGROUP BY Location;\n```\n\nThis query will return the maximum value of the \"Lowest\" column for each unique \"Location\" in the \"stadium\" table.","cost":0.0006543,"response_parsed":"SELECT Location, MAX(Lowest) AS Max_Lowest\nFROM stadium\nGROUP BY Location;","time":4.8119843006}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Location`, AVG(`Lowest`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the avg of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average of the \"Lowest\" values for each \"Location\" in the `stadium` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Location,\n AVG(Lowest) AS Average_Lowest\nFROM \n stadium\nGROUP BY \n Location;\n```\n\nThis query will:\n1. Group the rows in the `stadium` table by the `Location` column.\n2. Calculate the average of the `Lowest` values for each group (i.e., for each location).\n3. Return a result set with two columns: `Location` and `Average_Lowest` (the average of the `Lowest` values for that location).","cost":0.0006381,"response_parsed":"SELECT \n Location,\n AVG(Lowest) AS Average_Lowest\nFROM \n stadium\nGROUP BY \n Location;","time":4.7050142288}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Location`, SUM(`Lowest`) FROM `stadium` GROUP BY `Location`","question":"For each Location, find the sum of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the sum of the \"Lowest\" values for each \"Location\" in the `stadium` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Location,\n SUM(Lowest) AS Total_Lowest\nFROM \n stadium\nGROUP BY \n Location;\n```\n\nThis query will:\n1. Select the `Location` column\n2. Calculate the sum of the `Lowest` column for each location\n3. Group the results by the `Location` column\n4. Return the results with the location and the corresponding sum of the lowest values","cost":0.0006588,"response_parsed":"SELECT \n Location,\n SUM(Lowest) AS Total_Lowest\nFROM \n stadium\nGROUP BY \n Location;","time":4.987654686}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Capacity`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the min of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum capacity for each stadium name, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Name, MIN(Capacity) AS Min_Capacity\nFROM stadium\nGROUP BY Name;\n```\n\nThis query will:\n1. Select the `Name` column and the minimum value of the `Capacity` column for each group of rows with the same `Name`.\n2. Group the rows by the `Name` column to ensure the minimum capacity is calculated for each unique stadium name.","cost":0.0005958,"response_parsed":"SELECT Name, MIN(Capacity) AS Min_Capacity\nFROM stadium\nGROUP BY Name;","time":4.4759881496}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Capacity`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the max of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum capacity for each stadium name, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Name, MAX(Capacity) AS Max_Capacity\nFROM stadium\nGROUP BY Name;\n```\n\nThis query will:\n1. Select the `Name` column and the maximum value of the `Capacity` column for each group of rows with the same `Name`.\n2. Group the rows by the `Name` column.\n3. Return a result set with two columns: `Name` and `Max_Capacity` (the maximum capacity for each name).","cost":0.0006012,"response_parsed":"SELECT Name, MAX(Capacity) AS Max_Capacity\nFROM stadium\nGROUP BY Name;","time":4.699627161}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Capacity`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the avg of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average capacity for each stadium name, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, AVG(Capacity) AS Average_Capacity\nFROM stadium\nGROUP BY Name;\n```\n\nThis query will:\n1. Select the `Name` column and calculate the average of the `Capacity` column\n2. Group the results by the `Name` column\n3. Return the average capacity for each stadium name","cost":0.0006084,"response_parsed":"SELECT Name, AVG(Capacity) AS Average_Capacity\nFROM stadium\nGROUP BY Name;","time":5.0957136154}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Capacity`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the sum of Capacity in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the sum of Capacity for each Name in the stadium table, you can use the SQL `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, SUM(Capacity) \nFROM stadium \nGROUP BY Name;\n```\n\nThis query will:\n1. Group the rows in the stadium table by the `Name` column.\n2. Calculate the sum of the `Capacity` for each group (each unique Name).\n3. Return the results with the Name and the corresponding sum of Capacity.","cost":0.0006363,"response_parsed":"SELECT Name, SUM(Capacity) \nFROM stadium \nGROUP BY Name;","time":5.1076922417}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Lowest`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the min of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum value of the \"Lowest\" column for each \"Name\" in the \"stadium\" table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MIN(Lowest) AS Min_Lowest\nFROM stadium\nGROUP BY Name;\n```\n\nThis query will:\n1. Group the rows in the \"stadium\" table by the \"Name\" column.\n2. For each group (each unique \"Name\"), it will calculate the minimum value of the \"Lowest\" column.\n3. Return a result set with two columns: \"Name\" and \"Min_Lowest\" (the minimum value of \"Lowest\" for each \"Name\").","cost":0.0006732,"response_parsed":"SELECT Name, MIN(Lowest) AS Min_Lowest\nFROM stadium\nGROUP BY Name;","time":5.6408126354}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Lowest`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the max of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum value of the \"Lowest\" column for each \"Name\" in the \"stadium\" table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n MAX(Lowest) AS Max_Lowest\nFROM \n stadium\nGROUP BY \n Name;\n```\n\nThis query will return each unique \"Name\" along with the highest \"Lowest\" value associated with that name.","cost":0.0006066,"response_parsed":"SELECT \n Name,\n MAX(Lowest) AS Max_Lowest\nFROM \n stadium\nGROUP BY \n Name;","time":4.5358495712}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Lowest`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the avg of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average of the \"Lowest\" values for each \"Name\" in the \"stadium\" table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name AS Stadium_Name,\n AVG(Lowest) AS Average_Lowest\nFROM \n stadium\nGROUP BY \n Name;\n```\n\nThis query will:\n1. Select the \"Name\" column (aliased as `Stadium_Name` for clarity)\n2. Calculate the average of the \"Lowest\" values for each group (aliased as `Average_Lowest`)\n3. Group the results by the \"Name\" column\n\nThe result will show the average of the \"Lowest\" values for each stadium name in the table.","cost":0.0007038,"response_parsed":"SELECT \n Name AS Stadium_Name,\n AVG(Lowest) AS Average_Lowest\nFROM \n stadium\nGROUP BY \n Name;","time":6.5296683311}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Lowest`) FROM `stadium` GROUP BY `Name`","question":"For each Name, find the sum of Lowest in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"For each Name, find the sum of Lowest in table stadium,\" we need to calculate the sum of the \"Lowest\" values for each unique \"Name\" in the \"stadium\" table.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT \"Name\", SUM(\"Lowest\") AS \"Sum_of_Lowest\"\nFROM stadium\nGROUP BY \"Name\";\n```\n\nThis SQL query:\n1. Selects the \"Name\" column and calculates the sum of the \"Lowest\" column for each group of rows with the same \"Name\".\n2. Uses the `GROUP BY` clause to group the rows by the \"Name\" column.\n3. Includes an alias `AS \"Sum_of_Lowest\"` to provide a meaningful name for the calculated sum column.","cost":0.0006066,"response_parsed":"SELECT \"Name\", SUM(\"Lowest\") AS \"Sum_of_Lowest\"\nFROM stadium\nGROUP BY \"Name\";","time":4.3160927296}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `singer` GROUP BY `Name`","question":"For each Name, count the number of rows in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Name` in the `singer` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name, \n COUNT(*) as row_count\nFROM \n singer\nGROUP BY \n Name;\n```\n\nThis query will return the number of rows for each unique `Name` in your `singer` table.","cost":0.0006273,"response_parsed":"SELECT \n Name, \n COUNT(*) as row_count\nFROM \n singer\nGROUP BY \n Name;","time":4.7693748474}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Country`, COUNT(*) FROM `singer` GROUP BY `Country`","question":"For each Country, count the number of rows in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `singer` table for each country, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the `Country` column.\n\n```sql\nSELECT \n Country,\n COUNT(*) AS Number_of_Singers\nFROM \n singer\nGROUP BY \n Country;\n```","cost":0.0006588,"response_parsed":"SELECT \n Country,\n COUNT(*) AS Number_of_Singers\nFROM \n singer\nGROUP BY \n Country;","time":4.9990460873}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Song_Name`, COUNT(*) FROM `singer` GROUP BY `Song_Name`","question":"For each Song_Name, count the number of rows in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Song_Name` in the `singer` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Song_Name, COUNT(*) as Song_Count\nFROM singer\nGROUP BY Song_Name;\n```\n\nThis query will:\n1. Group all rows in the `singer` table by the `Song_Name` column.\n2. Count the number of rows for each unique `Song_Name`.\n3. Return a result set with two columns: `Song_Name` and `Song_Count` (where `Song_Count` is the number of rows for each song name).","cost":0.0008127,"response_parsed":"SELECT Song_Name, COUNT(*) as Song_Count\nFROM singer\nGROUP BY Song_Name;","time":6.9847271442}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Song_release_year`, COUNT(*) FROM `singer` GROUP BY `Song_release_year`","question":"For each Song_release_year, count the number of rows in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `singer` table for each `Song_release_year`, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Song_release_year,\n COUNT(Singer_ID) AS Count_of_singers\nFROM \n singer\nGROUP BY \n Song_release_year;\n```\n\nThis query will:\n1. Select the `Song_release_year` column\n2. Count the number of rows (using `Singer_ID` as it is the primary key and should not be NULL)\n3. Group the results by `Song_release_year`\n4. Return the count of singers for each release year","cost":0.0006345,"response_parsed":"SELECT \n Song_release_year,\n COUNT(Singer_ID) AS Count_of_singers\nFROM \n singer\nGROUP BY \n Song_release_year;","time":5.6429297924}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Song_Name`, MIN(`Age`) FROM `singer` GROUP BY `Song_Name`","question":"For each Song_Name, find the min of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum age for each song name in the `singer` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Song_Name,\n MIN(Age) AS min_age\nFROM \n singer\nGROUP BY \n Song_Name;\n```\n\nThis query will return the minimum age for each unique `Song_Name` in your database.","cost":0.0006318,"response_parsed":"SELECT \n Song_Name,\n MIN(Age) AS min_age\nFROM \n singer\nGROUP BY \n Song_Name;","time":4.9607856274}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Song_Name`, MAX(`Age`) FROM `singer` GROUP BY `Song_Name`","question":"For each Song_Name, find the max of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Age` for each `Song_Name` in the `singer` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Song_Name,\n MAX(Age) AS Max_Age\nFROM \n singer\nGROUP BY \n Song_Name;\n```\n\nThis query will return the maximum age for each song name in your database.","cost":0.0006543,"response_parsed":"SELECT \n Song_Name,\n MAX(Age) AS Max_Age\nFROM \n singer\nGROUP BY \n Song_Name;","time":5.4886372089}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Song_Name`, AVG(`Age`) FROM `singer` GROUP BY `Song_Name`","question":"For each Song_Name, find the avg of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average age for each song name in the `singer` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Song_Name,\n AVG(Age) AS Average_Age\nFROM \n singer\nGROUP BY \n Song_Name;\n```\n\nThis query will:\n1. Select the `Song_Name` and the average of the `Age` column.\n2. Group the results by `Song_Name`.\n3. Return the average age for each song name.","cost":0.0007182,"response_parsed":"SELECT \n Song_Name,\n AVG(Age) AS Average_Age\nFROM \n singer\nGROUP BY \n Song_Name;","time":5.7023923397}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Song_Name`, SUM(`Age`) FROM `singer` GROUP BY `Song_Name`","question":"For each Song_Name, find the sum of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Age` for each `Song_Name` in the `singer` table, you can use the SQL `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Song_Name,\n SUM(Age) AS Total_Age\nFROM \n singer\nGROUP BY \n Song_Name;\n```\n\nThis query will:\n1. Select the `Song_Name` and the sum of `Age` for each song.\n2. Group the results by `Song_Name`.\n3. Return the total age for each song.","cost":0.0006327,"response_parsed":"SELECT \n Song_Name,\n SUM(Age) AS Total_Age\nFROM \n singer\nGROUP BY \n Song_Name;","time":4.8013341427}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Age`) FROM `singer` GROUP BY `Name`","question":"For each Name, find the min of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum age for each singer's name in the `singer` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MIN(Age) as min_age\nFROM singer\nGROUP BY Name;\n```\n\nThis query will return the minimum age for each unique singer name in the table.","cost":0.0005499,"response_parsed":"SELECT Name, MIN(Age) as min_age\nFROM singer\nGROUP BY Name;","time":3.4123904705}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Age`) FROM `singer` GROUP BY `Name`","question":"For each Name, find the max of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum age for each singer's name in the `singer` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MAX(Age) AS Max_Age\nFROM singer\nGROUP BY Name;\n```\n\nThis query will return the maximum age for each unique `Name` in the `singer` table.","cost":0.0005796,"response_parsed":"SELECT Name, MAX(Age) AS Max_Age\nFROM singer\nGROUP BY Name;","time":4.0620751381}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Age`) FROM `singer` GROUP BY `Name`","question":"For each Name, find the avg of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average age for each singer's name in the `singer` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, AVG(Age) AS Average_Age\nFROM singer\nGROUP BY Name;\n```\n\nThis query will return the average age for each unique `Name` in the `singer` table.","cost":0.0006804,"response_parsed":"SELECT Name, AVG(Age) AS Average_Age\nFROM singer\nGROUP BY Name;","time":5.1726820469}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Age`) FROM `singer` GROUP BY `Name`","question":"For each Name, find the sum of Age in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Age` for each `Name` in the `singer` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name, \n SUM(Age) AS Total_Age\nFROM \n singer\nGROUP BY \n Name\nORDER BY \n Name;\n```\n\nThis query will:\n1. Group the rows in the `singer` table by the `Name` column.\n2. Calculate the sum of the `Age` column for each group.\n3. Return the results sorted by the `Name` column.","cost":0.0006309,"response_parsed":"SELECT \n Name, \n SUM(Age) AS Total_Age\nFROM \n singer\nGROUP BY \n Name\nORDER BY \n Name;","time":4.5755982399}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Singer_ID`, COUNT(*) FROM `singer_in_concert` GROUP BY `Singer_ID`","question":"For each Singer_ID, count the number of rows in table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Singer_ID` in the `singer_in_concert` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause. Here is the SQL code:\n\n```sql\nSELECT \n Singer_ID,\n COUNT(*) as concert_count\nFROM \n singer_in_concert\nGROUP BY \n Singer_ID;\n```\n\nThis query will return a result set with two columns:\n- `Singer_ID`: The unique identifier for each singer.\n- `concert_count`: The number of rows (concerts) associated with each `Singer_ID`.","cost":0.0006408,"response_parsed":"SELECT \n Singer_ID,\n COUNT(*) as concert_count\nFROM \n singer_in_concert\nGROUP BY \n Singer_ID;","time":4.6273844242}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Stadium_ID` FROM `concert` GROUP BY `Stadium_ID` HAVING count(*) >= 1","question":"Find all the Stadium_ID that have at least 1 records in table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all `Stadium_ID`s that have at least one record in the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT s.Stadium_ID\nFROM stadium s\nINNER JOIN concert c\nON s.Stadium_ID = c.Stadium_ID;\n```\n\nThis query:\n1. Joins the `stadium` table with the `concert` table on the `Stadium_ID` field.\n2. Uses `SELECT DISTINCT` to ensure each `Stadium_ID` is only listed once, even if it appears in multiple concert records.\n3. Returns all `Stadium_ID`s that have at least one associated record in the `concert` table.","cost":0.0008406,"response_parsed":"SELECT DISTINCT s.Stadium_ID\nFROM stadium s\nINNER JOIN concert c\nON s.Stadium_ID = c.Stadium_ID;","time":7.1357579231}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Stadium_ID` FROM `concert` GROUP BY `Stadium_ID` HAVING count(*) <= 1","question":"Find all the Stadium_ID that have at most 1 records in table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all `Stadium_ID`s that have at most 1 record in the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID\nFROM concert\nGROUP BY Stadium_ID\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Groups the rows in the `concert` table by `Stadium_ID`.\n2. Counts the number of records for each `Stadium_ID`.\n3. Filters the results to include only those `Stadium_ID`s with 1 or fewer records.\n\n```sql\nSELECT Stadium_ID\nFROM concert\nGROUP BY Stadium_ID\nHAVING COUNT(*) <= 1;\n```","cost":0.0006363,"response_parsed":"SELECT Stadium_ID\nFROM concert\nGROUP BY Stadium_ID\nHAVING COUNT(*) <= 1;","time":4.6562423706}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `concert_Name` FROM `concert` GROUP BY `concert_Name` HAVING count(*) >= 1","question":"Find all the concert_Name that have at least 1 records in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the concert names that have at least 1 record in the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT concert_Name FROM concert;\n```\n\nThis query will return all unique `concert_Name` values that exist in the `concert` table.","cost":0.0006138,"response_parsed":"SELECT DISTINCT concert_Name FROM concert;","time":5.0173504353}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `concert_Name` FROM `concert` GROUP BY `concert_Name` HAVING count(*) <= 1","question":"Find all the concert_Name that have at most 1 records in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all concert names that have at most 1 record in the `concert` table, we can use the following SQL query. Since each concert is uniquely identified by `concert_ID` (the primary key), each concert name will appear only once in the table.\n\n```sql\nSELECT DISTINCT concert_Name FROM concert;\n```","cost":0.0005913,"response_parsed":"SELECT DISTINCT concert_Name FROM concert;","time":4.2493963242}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Year` FROM `concert` GROUP BY `Year` HAVING count(*) >= 3","question":"Find all the Year that have at least 3 records in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the years in the `concert` table that have at least 3 records, you can use the SQL `COUNT()` function along with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Year\nFROM concert\nGROUP BY Year\nHAVING COUNT(*) >= 3;\n```\n\nThis query will:\n1. Group the records in your `concert` table by the `Year` column.\n2. Count the number of records in each group.\n3. Return only those years that have at least 3 records.\n\nThe result will be a list of years that meet the condition of having at least 3 records in the `concert` table.","cost":0.0005805,"response_parsed":"SELECT Year\nFROM concert\nGROUP BY Year\nHAVING COUNT(*) >= 3;","time":4.2328071594}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Year` FROM `concert` GROUP BY `Year` HAVING count(*) <= 3","question":"Find all the Year that have at most 3 records in table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the years in the `concert` table that have at most 3 records, you can use the following SQL query:\n\n```sql\nSELECT Year\nFROM concert\nGROUP BY Year\nHAVING COUNT(concert_ID) <= 3;\n```\n\nThis query:\n1. Groups the rows in the `concert` table by the `Year` column.\n2. Counts the number of records (concerts) for each year using `COUNT(concert_ID)`.\n3. Filters the results to include only those years where the count of concerts is 3 or fewer, using `HAVING COUNT(concert_ID) <= 3`.\n\nThe result will be a list of years with 3 or fewer concerts.","cost":0.000675,"response_parsed":"SELECT Year\nFROM concert\nGROUP BY Year\nHAVING COUNT(concert_ID) <= 3;","time":4.8903415203}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING count(*) >= 1","question":"Find all the Location that have at least 1 records in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all unique locations that have at least one record in the `stadium` table, you can use the `DISTINCT` keyword in SQL. This will return each location only once, even if it appears multiple times in the table.\n\n```sql\nSELECT DISTINCT Location FROM stadium;\n```","cost":0.0005607,"response_parsed":"SELECT DISTINCT Location FROM stadium;","time":3.7847151756}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING count(*) <= 1","question":"Find all the Location that have at most 1 records in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the locations in the `stadium` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Location\nFROM stadium\nGROUP BY Location\nHAVING COUNT(Location) <= 1;\n```\n\nThis query will:\n1. Group the records in the `stadium` table by the `Location` field.\n2. Count the number of records for each `Location`.\n3. Return only those `Location`s that have 1 or fewer records.\n\nThe result will be a list of locations that appear at most once in the `stadium` table.","cost":0.0006075,"response_parsed":"SELECT Location\nFROM stadium\nGROUP BY Location\nHAVING COUNT(Location) <= 1;","time":4.541706562}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the names that have at least one record in the `stadium` table, we can directly query the `Name` column from the `stadium` table. Since each record in the `stadium` table represents a unique stadium, each `Name` in this table inherently has at least one record.\n\nHere is the SQL code to fetch the desired result:\n\n```sql\nSELECT DISTINCT Name FROM stadium;\n```\n\nThis query selects all unique names from the `stadium` table, ensuring each name appears only once in the result.","cost":0.0006921,"response_parsed":"SELECT DISTINCT Name FROM stadium;","time":5.289798975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the names that appear at most once in the stadium table, we can use the `COUNT` function combined with `GROUP BY` and `HAVING` clauses. Here's how to do it:\n\n```sql\nSELECT Name\nFROM stadium\nGROUP BY Name\nHAVING COUNT(Name) <= 1;\n```\n\nThis query will return the names of stadiums that appear once or not at all in the table.","cost":0.0007884,"response_parsed":"SELECT Name\nFROM stadium\nGROUP BY Name\nHAVING COUNT(Name) <= 1;","time":6.8371546268}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING AVG(`Highest`) >= 1737.56","question":"List the Location which average of Highest is at least 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the locations from the stadium table where the average of the \"Highest\" values is at least 1737.56, you can use the following SQL query:\n\n```sql\nSELECT Location \nFROM stadium \nGROUP BY Location \nHAVING AVG(Highest) >= 1737.56;\n```\n\nThis query groups the stadium entries by their \"Location\" and calculates the average of the \"Highest\" values for each location. It then filters the results to include only those locations where this average is at least 1737.56.","cost":0.0006714,"response_parsed":"SELECT Location \nFROM stadium \nGROUP BY Location \nHAVING AVG(Highest) >= 1737.56;","time":5.0930473804}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING AVG(`Highest`) <= 1737.56","question":"List the Location which average of Highest is at most 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the locations from the stadium table where the average of the \"Highest\" values is at most 1737.56, you can use the following SQL query:\n\n```sql\nSELECT Location \nFROM stadium \nGROUP BY Location \nHAVING AVG(Highest) <= 1737.56;\n```\n\nThis query groups the stadium entries by their locations and filters the results to include only those locations where the average of the \"Highest\" values is less than or equal to 1737.56.","cost":0.0008064,"response_parsed":"SELECT Location \nFROM stadium \nGROUP BY Location \nHAVING AVG(Highest) <= 1737.56;","time":6.2427110672}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING SUM(`Highest`) >= 1737.56","question":"List the Location which summation of Highest is at least 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Location which summation of Highest is at least 1737.56 in table stadium,\" we need to write an SQL query that:\n\n1. Groups the rows in the `stadium` table by the `Location` column.\n2. Calculates the sum of the `Highest` column for each group.\n3. Filters the results to include only those groups where the sum of `Highest` is at least 1737.56.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Location\nFROM stadium\nGROUP BY Location\nHAVING SUM(Highest) >= 1737.56;\n```\n\n### Explanation:\n- `SELECT Location`: This selects the `Location` column from the `stadium` table.\n- `FROM stadium`: This specifies the table from which to retrieve the data.\n- `GROUP BY Location`: This groups the rows by the `Location` column, allowing us to perform aggregate operations on each group.\n- `HAVING SUM(Highest) >= 1737.56`: This filters the groups to include only those where the sum of the `Highest` column is at least 1737.56.\n\nThis query will return the names of the locations where the total sum of the `Highest` values meets or exceeds 1737.56.","cost":0.0009396,"response_parsed":"SELECT Location\nFROM stadium\nGROUP BY Location\nHAVING SUM(Highest) >= 1737.56;","time":7.5659148693}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Location` FROM `stadium` GROUP BY `Location` HAVING SUM(`Highest`) <= 1737.56","question":"List the Location which summation of Highest is at most 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question correctly, we need to sum the \"Highest\" values for each Location and list those Locations where the sum is at most 1737.56. Here's the correct SQL code:\n\n```sql\nSELECT Location FROM stadium GROUP BY Location HAVING SUM(Highest) <= 1737.56;\n```","cost":0.0011997,"response_parsed":"SELECT Location FROM stadium GROUP BY Location HAVING SUM(Highest) <= 1737.56;","time":10.9855098724}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING AVG(`Highest`) >= 1737.56","question":"List the Name which average of Highest is at least 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Name which average of Highest is at least 1737.56 in table stadium,\" we need to fetch the names of stadiums where the average of the \"Highest\" values meets or exceeds 1737.56.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Name \nFROM stadium \nWHERE Average >= 1737.56;\n```\n\nThis query selects the `Name` from the `stadium` table where the `Average` is at least 1737.56.","cost":0.0008856,"response_parsed":"SELECT Name \nFROM stadium \nWHERE Average >= 1737.56;","time":8.3159954548}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING AVG(`Highest`) <= 1737.56","question":"List the Name which average of Highest is at most 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Name which average of Highest is at most 1737.56 in table stadium,\" we need to fetch the names of stadiums where the average of the \"Highest\" values is less than or equal to 1737.56.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Name \nFROM stadium \nWHERE Average <= 1737.56;\n```\n\nThis query selects the \"Name\" of stadiums from the \"stadium\" table where the \"Average\" value is at most 1737.56.","cost":0.0006858,"response_parsed":"SELECT Name \nFROM stadium \nWHERE Average <= 1737.56;","time":5.2244026661}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING SUM(`Highest`) >= 1737.56","question":"List the Name which summation of Highest is at least 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question of listing the names from the stadium table where the summation of the \"Highest\" values is at least 1737.56, we need to consider the structure of the database schema provided. The \"stadium\" table contains a column named \"Highest\" which stores integer values. Since the question asks for the summation of the \"Highest\" values, we will use the `SUM()` function in SQL to calculate the total of the \"Highest\" values across all entries in the \"stadium\" table. We will then filter the results to include only those entries where this summation meets or exceeds 1737.56.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Name FROM stadium WHERE Highest >= 1737.56;\n```\n\nThis SQL query will return the names of the stadiums where the \"Highest\" value is at least 1737.56.","cost":0.0015723,"response_parsed":"SELECT Name FROM stadium WHERE Highest >= 1737.56;","time":15.7700555325}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `stadium` GROUP BY `Name` HAVING SUM(`Highest`) <= 1737.56","question":"List the Name which summation of Highest is at most 1737.56 in table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the names from the stadium table where the sum of the \"Highest\" values is at most 1737.56, you can use the following SQL query:\n\n```sql\nSELECT Name FROM stadium WHERE (SELECT SUM(Highest) FROM stadium) <= 1737.56;\n```\n\nThis query first calculates the sum of the \"Highest\" column for all entries in the stadium table. If this sum is less than or equal to 1737.56, it returns the names of all stadiums. If the sum exceeds 1737.56, no results are returned.","cost":0.0015093,"response_parsed":"SELECT Name FROM stadium WHERE (SELECT SUM(Highest) FROM stadium) <= 1737.56;","time":14.1953437328}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING count(*) >= 1","question":"Find all the Song_Name that have at least 1 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all unique song names that have at least one record in the singer table, we can use the `SELECT DISTINCT` statement on the `Song_Name` column.\n\n```sql\nSELECT DISTINCT Song_Name FROM singer;\n```","cost":0.0005796,"response_parsed":"SELECT DISTINCT Song_Name FROM singer;","time":4.6875293255}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING count(*) <= 1","question":"Find all the Song_Name that have at most 1 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the `Song_Name` that have at most 1 record in the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING COUNT(Song_Name) <= 1;\n```\n\nThis query will:\n1. Group the rows in the `singer` table by the `Song_Name`.\n2. Count the number of records for each `Song_Name`.\n3. Return only those `Song_Name` that have 1 or fewer records in the table.","cost":0.0006939,"response_parsed":"SELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING COUNT(Song_Name) <= 1;","time":5.2033507824}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING count(*) >= 2","question":"Find all the Country that have at least 2 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all countries with at least two singers, we'll use the `singer` table, group by `Country`, and count the entries.\n\n```sql\nSELECT Country\nFROM singer\nGROUP BY Country\nHAVING COUNT(Singer_ID) >= 2;\n```","cost":0.0005796,"response_parsed":"SELECT Country\nFROM singer\nGROUP BY Country\nHAVING COUNT(Singer_ID) >= 2;","time":4.1042606831}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING count(*) <= 2","question":"Find all the Country that have at most 2 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all countries with at most 2 records in the `singer` table, we can use the `COUNT` function combined with `GROUP BY` and `HAVING` clauses.\n\n```sql\nSELECT DISTINCT Country\nFROM singer\nGROUP BY Country\nHAVING COUNT(Singer_ID) <= 2;\n```\n\nThis SQL query will:\n1. Group the rows in the `singer` table by the `Country` column.\n2. Count the number of singers (`Singer_ID`) for each country.\n3. Filter the results to include only those countries where the count of singers is 2 or fewer.\n4. Return the distinct country names that meet this condition.","cost":0.0005616,"response_parsed":"SELECT DISTINCT Country\nFROM singer\nGROUP BY Country\nHAVING COUNT(Singer_ID) <= 2;","time":3.7738001347}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `singer` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the Names that have at least 1 record in the `singer` table, we can use a simple `SELECT` statement to retrieve the `Name` column from the `singer` table. Since each record in the `singer` table represents a singer with a name, this query will return all the names of singers that exist in the table.\n\n```sql\nSELECT Name FROM singer;\n```","cost":0.0006021,"response_parsed":"SELECT Name FROM singer;","time":4.1659564972}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `singer` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all the names in the `singer` table that have at most one record, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM singer\nGROUP BY Name\nHAVING COUNT(*) <= 1;\n```\n\nThis query will:\n1. Group the rows in the `singer` table by the `Name` column.\n2. Count the number of records for each name using `COUNT(*)`.\n3. Filter the results to include only those names that have one or fewer records (`COUNT(*) <= 1`).\n\nThe result will be a list of names that appear at most once in the `singer` table.","cost":0.0006984,"response_parsed":"SELECT Name\nFROM singer\nGROUP BY Name\nHAVING COUNT(*) <= 1;","time":5.4559690952}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING AVG(`Age`) >= 39.5","question":"List the Country which average of Age is at least 39.5 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Country which average of Age is at least 39.5 in table singer,\" we need to write an SQL query that calculates the average age for each country and filters those countries where the average age is 39.5 or higher.\n\nHere is the SQL code:\n\n```sql\nSELECT Country, AVG(Age) AS Average_Age\nFROM singer\nGROUP BY Country\nHAVING AVG(Age) >= 39.5;\n```\n\n### Explanation:\n1. **SELECT Country, AVG(Age) AS Average_Age**: This selects the `Country` column and calculates the average age, aliasing it as `Average_Age` for clarity.\n2. **FROM singer**: Specifies the table to query, which is the `singer` table.\n3. **GROUP BY Country**: Groups the rows by the `Country` column so that we can calculate the average age for each country.\n4. **HAVING AVG(Age) >= 39.5**: Filters the results to include only those countries where the average age is at least 39.5.\n\nThis query will return the names of countries along with their average ages, but only for those countries where the average age meets or exceeds 39.5.","cost":0.0009459,"response_parsed":"SELECT Country, AVG(Age) AS Average_Age\nFROM singer\nGROUP BY Country\nHAVING AVG(Age) >= 39.5;","time":8.0973017216}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING AVG(`Age`) <= 39.5","question":"List the Country which average of Age is at most 39.5 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Country which average of Age is at most 39.5 in table singer,\" we need to calculate the average age for each country and then filter the results to include only those countries where the average age is 39.5 or less.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT \n Country,\n AVG(Age) AS Average_Age\nFROM \n singer\nGROUP BY \n Country\nHAVING \n AVG(Age) <= 39.5;\n```\n\nThis SQL query:\n1. Selects the `Country` column and calculates the average age for each country.\n2. Groups the results by the `Country` column.\n3. Filters the results to include only those countries where the average age is 39.5 or less.\n\nThe result will be a list of countries along with their average ages, but only for those countries where the average age is at most 39.5.","cost":0.0007758,"response_parsed":"SELECT \n Country,\n AVG(Age) AS Average_Age\nFROM \n singer\nGROUP BY \n Country\nHAVING \n AVG(Age) <= 39.5;","time":6.2502603531}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING SUM(`Age`) >= 74.0","question":"List the Country which summation of Age is at least 74.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Age` of singers by their `Country` and then filter the results to include only those countries where the total age is at least 74.0.\n\nHere is the SQL code:\n\n```sql\nSELECT Country, SUM(Age) AS Total_Age\nFROM singer\nGROUP BY Country\nHAVING SUM(Age) >= 74.0;\n```\n\n### Explanation:\n1. **SELECT Country, SUM(Age) AS Total_Age**: This selects the `Country` column and calculates the sum of the `Age` column, aliasing it as `Total_Age` for clarity.\n2. **FROM singer**: Specifies the table to query, which is the `singer` table.\n3. **GROUP BY Country**: Groups the rows by the `Country` column so that the `SUM` function can be applied to each group.\n4. **HAVING SUM(Age) >= 74.0**: Filters the groups to include only those where the sum of `Age` is at least 74.0.\n\nThis query will return the names of countries along with the total age of singers from each country, but only for those countries where the total age is 74.0 or higher.","cost":0.0009738,"response_parsed":"SELECT Country, SUM(Age) AS Total_Age\nFROM singer\nGROUP BY Country\nHAVING SUM(Age) >= 74.0;","time":8.1859667301}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Country` FROM `singer` GROUP BY `Country` HAVING SUM(`Age`) <= 74.0","question":"List the Country which summation of Age is at most 74.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Country which summation of Age is at most 74.0 in table singer,\" we need to write an SQL query that:\n\n1. Groups the rows in the `singer` table by the `Country` column.\n2. Calculates the sum of the `Age` column for each group.\n3. Filters the results to include only those groups where the sum of `Age` is at most 74.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Country\nFROM singer\nGROUP BY Country\nHAVING SUM(Age) <= 74;\n```\n\nThis query will return the names of the countries where the total sum of the ages of the singers from that country is 74.0 or less.","cost":0.0008163,"response_parsed":"SELECT Country\nFROM singer\nGROUP BY Country\nHAVING SUM(Age) <= 74;","time":6.2481153011}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING AVG(`Age`) >= 37.0","question":"List the Song_Name which average of Age is at least 37.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the list of `Song_Name` where the average `Age` is at least 37.0 from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING AVG(Age) >= 37.0;\n```\n\nThis query:\n1. Groups the rows in the `singer` table by the `Song_Name`.\n2. Calculates the average `Age` for each group using the `AVG()` function.\n3. Filters the results to include only those groups where the average `Age` is at least 37.0 using the `HAVING` clause.","cost":0.000783,"response_parsed":"SELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING AVG(Age) >= 37.0;","time":6.1975505352}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING AVG(`Age`) <= 37.0","question":"List the Song_Name which average of Age is at most 37.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Song_Name` from the `singer` table where the average `Age` is at most 37.0. Here's the SQL code to achieve this:\n\n```sql\nSELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING AVG(Age) <= 37.0;\n```\n\nThis query:\n1. Groups the rows in the `singer` table by `Song_Name`.\n2. Calculates the average `Age` for each group using the `AVG()` function.\n3. Filters the results to include only those groups where the average `Age` is less than or equal to 37.0.","cost":0.0007029,"response_parsed":"SELECT Song_Name\nFROM singer\nGROUP BY Song_Name\nHAVING AVG(Age) <= 37.0;","time":5.1410963535}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING SUM(`Age`) >= 37.0","question":"List the Song_Name which summation of Age is at least 37.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Song_Name which summation of Age is at least 37.0 in table singer,\" we need to:\n\n1. Select the `Song_Name` from the `singer` table.\n2. Calculate the sum of the `Age` for each `Song_Name`.\n3. Filter the results to include only those `Song_Name`s where the sum of `Age` is at least 37.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Song_Name, SUM(Age) AS total_age\nFROM singer\nGROUP BY Song_Name\nHAVING SUM(Age) >= 37.0;\n```\n\nThis query will:\n- Group the rows in the `singer` table by `Song_Name`.\n- Calculate the sum of `Age` for each group.\n- Return only those `Song_Name`s where the sum of `Age` is at least 37.0.","cost":0.0006858,"response_parsed":"SELECT Song_Name, SUM(Age) AS total_age\nFROM singer\nGROUP BY Song_Name\nHAVING SUM(Age) >= 37.0;","time":5.7708501816}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Song_Name` FROM `singer` GROUP BY `Song_Name` HAVING SUM(`Age`) <= 37.0","question":"List the Song_Name which summation of Age is at most 37.0 in table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Song_Name which summation of Age is at most 37.0 in table singer,\" we need to write an SQL query that:\n\n1. Selects the `Song_Name` from the `singer` table.\n2. Groups the results by `Song_Name`.\n3. Filters the groups where the sum of `Age` is at most 37.0.\n\nHere is the SQL code:\n\n```sql\nSELECT \"Song_Name\"\nFROM \"singer\"\nGROUP BY \"Song_Name\"\nHAVING SUM(\"Age\") <= 37.0;\n```\n\nThis query will return the names of songs where the sum of the ages of the singers associated with those songs is at most 37.0.","cost":0.0007371,"response_parsed":"SELECT \"Song_Name\"\nFROM \"singer\"\nGROUP BY \"Song_Name\"\nHAVING SUM(\"Age\") <= 37.0;","time":5.8459024429}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Singer_ID` FROM `singer_in_concert` GROUP BY `Singer_ID` HAVING count(*) >= 2","question":"Find all the Singer_ID that have at least 2 records in table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all Singer_IDs that appear at least twice in the `singer_in_concert` table, we can use the `COUNT()` function combined with `GROUP BY` and a `HAVING` clause.\n\n```sql\nSELECT Singer_ID\nFROM singer_in_concert\nGROUP BY Singer_ID\nHAVING COUNT(Singer_ID) >= 2;\n```","cost":0.000621,"response_parsed":"SELECT Singer_ID\nFROM singer_in_concert\nGROUP BY Singer_ID\nHAVING COUNT(Singer_ID) >= 2;","time":4.6937675476}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Singer_ID` FROM `singer_in_concert` GROUP BY `Singer_ID` HAVING count(*) <= 2","question":"Find all the Singer_ID that have at most 2 records in table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find all Singer_IDs that have at most 2 records in the `singer_in_concert` table, you can use the SQL `COUNT()` function combined with `GROUP BY` and `HAVING` clauses. Here's how you can do it:\n\n```sql\nSELECT Singer_ID\nFROM singer_in_concert\nGROUP BY Singer_ID\nHAVING COUNT(Singer_ID) <= 2;\n```\n\nThis query will:\n1. Group the rows in `singer_in_concert` by `Singer_ID`\n2. Count the number of records for each `Singer_ID`\n3. Return only those `Singer_ID`s that have 2 or fewer records\n\n```sql\nSELECT Singer_ID\nFROM singer_in_concert\nGROUP BY Singer_ID\nHAVING COUNT(Singer_ID) <= 2;\n```","cost":0.0006507,"response_parsed":"SELECT Singer_ID\nFROM singer_in_concert\nGROUP BY Singer_ID\nHAVING COUNT(Singer_ID) <= 2;","time":4.7074832916}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `concert` AS T1 JOIN `stadium` AS T2 ON T1.`Stadium_ID` = T2.`Stadium_ID`","question":"Join all the records from table concert with table stadium on Stadium_ID","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo join all records from the `concert` table with the `stadium` table based on the `Stadium_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nFULL OUTER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;\n```\n\nThis query will return all records from both tables where the `Stadium_ID` matches. If there are records in one table that don't have a match in the other, they will still be included in the result set.","cost":0.0007254,"response_parsed":"SELECT *\nFROM concert\nFULL OUTER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;","time":5.9137334824}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`concert_Name`, T2.`Location` FROM `concert` AS T1 JOIN `stadium` AS T2 ON T1.`Stadium_ID`=T2.`Stadium_ID`","question":"List all the concert_Name and Location from the table concert and the table stadium where Stadium_ID is the same","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `concert_Name` and `Location` from the `concert` and `stadium` tables where the `Stadium_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT c.concert_Name, s.Location\nFROM concert c\nINNER JOIN stadium s\nON c.Stadium_ID = s.Stadium_ID;\n```\n\nThis query:\n1. Selects the `concert_Name` from the `concert` table and `Location` from the `stadium` table.\n2. Uses an `INNER JOIN` to combine rows from the `concert` and `stadium` tables where the `Stadium_ID` is the same in both tables.","cost":0.0006723,"response_parsed":"SELECT c.concert_Name, s.Location\nFROM concert c\nINNER JOIN stadium s\nON c.Stadium_ID = s.Stadium_ID;","time":4.8356153965}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`concert_Name`, T2.`Name` FROM `concert` AS T1 JOIN `stadium` AS T2 ON T1.`Stadium_ID`=T2.`Stadium_ID`","question":"List all the concert_Name and Name from the table concert and the table stadium where Stadium_ID is the same","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `concert_Name` from the `concert` table and `Name` from the `stadium` table where the `Stadium_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT concert.concert_Name, stadium.Name\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;\n```\n\nThis query:\n1. Selects the `concert_Name` from the `concert` table and `Name` from the `stadium` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Stadium_ID` is the same in both tables.","cost":0.0005679,"response_parsed":"SELECT concert.concert_Name, stadium.Name\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;","time":3.8046314716}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Theme`, T2.`Location` FROM `concert` AS T1 JOIN `stadium` AS T2 ON T1.`Stadium_ID`=T2.`Stadium_ID`","question":"List all the Theme and Location from the table concert and the table stadium where Stadium_ID is the same","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Theme from the `concert` table and the Location from the `stadium` table where the `Stadium_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT concert.Theme, stadium.Location\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;\n```\n\nThis query will:\n1. Select the `Theme` column from the `concert` table.\n2. Select the `Location` column from the `stadium` table.\n3. Join the two tables based on the matching `Stadium_ID` values.\n4. Return the combined results where the `Stadium_ID` exists in both tables.","cost":0.000738,"response_parsed":"SELECT concert.Theme, stadium.Location\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;","time":5.5457582474}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Theme`, T2.`Name` FROM `concert` AS T1 JOIN `stadium` AS T2 ON T1.`Stadium_ID`=T2.`Stadium_ID`","question":"List all the Theme and Name from the table concert and the table stadium where Stadium_ID is the same","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Theme from the `concert` table and the Name from the `stadium` table where the `Stadium_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT concert.Theme, stadium.Name\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;\n```\n\nThis query will:\n1. Join the `concert` and `stadium` tables based on the `Stadium_ID` column.\n2. Select the `Theme` from the `concert` table and the `Name` from the `stadium` table.\n3. Return all matching records where the `Stadium_ID` exists in both tables.","cost":0.0006336,"response_parsed":"SELECT concert.Theme, stadium.Name\nFROM concert\nINNER JOIN stadium\nON concert.Stadium_ID = stadium.Stadium_ID;","time":4.4362902641}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `singer_in_concert` AS T1 JOIN `singer` AS T2 ON T1.`Singer_ID` = T2.`Singer_ID`","question":"Join all the records from table singer_in_concert with table singer on Singer_ID","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo join all records from the `singer_in_concert` table with the `singer` table based on the `Singer_ID`, you can use an `INNER JOIN`. Here's the SQL code:\n\n```sql\nSELECT *\nFROM singer_in_concert sic\nINNER JOIN singer s\nON sic.Singer_ID = s.Singer_ID;\n```\n\nThis SQL query will:\n1. Select all records (`*`) from both tables.\n2. Use an `INNER JOIN` to combine rows from `singer_in_concert` and `singer` where the `Singer_ID` is the same in both tables.\n3. The `ON` clause specifies the condition for joining the two tables, which is matching `Singer_ID`.\n\nThe result will be a combined table containing all columns from both `singer_in_concert` and `singer` for the rows where the `Singer_ID` exists in both tables.","cost":0.0006426,"response_parsed":"SELECT *\nFROM singer_in_concert sic\nINNER JOIN singer s\nON sic.Singer_ID = s.Singer_ID;","time":4.8393669128}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `singer_in_concert` AS T1 JOIN `concert` AS T2 ON T1.`concert_ID` = T2.`concert_ID`","question":"Join all the records from table singer_in_concert with table concert on concert_ID","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo join all records from the `singer_in_concert` table with the `concert` table based on the `concert_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nINNER JOIN concert\nON singer_in_concert.concert_ID = concert.concert_ID;\n```\n\nThis query will return all records where there is a match in both tables based on the `concert_ID`.","cost":0.0006804,"response_parsed":"SELECT *\nFROM singer_in_concert\nINNER JOIN concert\nON singer_in_concert.concert_ID = concert.concert_ID;","time":5.950756073}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Singer_ID`, T2.`Stadium_ID` FROM `singer_in_concert` AS T1 JOIN `concert` AS T2 ON T1.`concert_ID`=T2.`concert_ID`","question":"List all the Singer_ID and Stadium_ID from the table singer_in_concert and the table concert where concert_ID is the same","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Singer_ID and Stadium_ID from the tables `singer_in_concert` and `concert` where the concert_ID is the same, you can use the following SQL query:\n\n```sql\nSELECT sic.Singer_ID, c.Stadium_ID\nFROM singer_in_concert sic\nINNER JOIN concert c\nON sic.concert_ID = c.concert_ID;\n```\n\nThis query:\n1. Selects the `Singer_ID` from the `singer_in_concert` table and the `Stadium_ID` from the `concert` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `concert_ID` is the same in both tables.","cost":0.000621,"response_parsed":"SELECT sic.Singer_ID, c.Stadium_ID\nFROM singer_in_concert sic\nINNER JOIN concert c\nON sic.concert_ID = c.concert_ID;","time":4.705391407}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Singer_ID`, T2.`Year` FROM `singer_in_concert` AS T1 JOIN `concert` AS T2 ON T1.`concert_ID`=T2.`concert_ID`","question":"List all the Singer_ID and Year from the table singer_in_concert and the table concert where concert_ID is the same","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Singer_ID and Year from the tables `singer_in_concert` and `concert` where the `concert_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT sic.Singer_ID, c.Year\nFROM singer_in_concert sic\nINNER JOIN concert c\nON sic.concert_ID = c.concert_ID;\n```\n\nThis query:\n1. Selects the `Singer_ID` from the `singer_in_concert` table and the `Year` from the `concert` table.\n2. Uses an `INNER JOIN` to combine rows from `singer_in_concert` and `concert` where the `concert_ID` is the same in both tables.","cost":0.0006498,"response_parsed":"SELECT sic.Singer_ID, c.Year\nFROM singer_in_concert sic\nINNER JOIN concert c\nON sic.concert_ID = c.concert_ID;","time":4.9704282284}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Singer_ID`, T2.`Theme` FROM `singer_in_concert` AS T1 JOIN `concert` AS T2 ON T1.`concert_ID`=T2.`concert_ID`","question":"List all the Singer_ID and Theme from the table singer_in_concert and the table concert where concert_ID is the same","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Singer_ID and Theme from the tables `singer_in_concert` and `concert` where the `concert_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT singer_in_concert.Singer_ID, concert.Theme\nFROM singer_in_concert\nINNER JOIN concert\nON singer_in_concert.concert_ID = concert.concert_ID;\n```\n\nThis query will:\n1. Select the `Singer_ID` from the `singer_in_concert` table.\n2. Select the `Theme` from the `concert` table.\n3. Join the two tables based on the matching `concert_ID` using an `INNER JOIN`, which ensures only rows with matching `concert_ID` in both tables are returned.","cost":0.0007353,"response_parsed":"SELECT singer_in_concert.Singer_ID, concert.Theme\nFROM singer_in_concert\nINNER JOIN concert\nON singer_in_concert.concert_ID = concert.concert_ID;","time":5.8780565262}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `concert_Name` FROM `concert` GROUP BY `concert_Name` HAVING COUNT(DISTINCT `Year`) = (SELECT COUNT(DISTINCT `Year`) FROM `concert`)","question":"What are the concert_Name with all the Year in table concert?","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the concert names along with their respective years from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT concert_Name, Year FROM concert;\n```\n\nThis query selects the `concert_Name` and `Year` columns from the `concert` table, providing the desired information.","cost":0.0006876,"response_parsed":"SELECT concert_Name, Year FROM concert;","time":5.5303184986}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Stadium_ID` FROM `concert` GROUP BY `Stadium_ID` HAVING COUNT(DISTINCT `Year`) = (SELECT COUNT(DISTINCT `Year`) FROM `concert`)","question":"What are the Stadium_ID with all the Year in table concert?","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Stadium_ID(s) with all the Year(s) in the `concert` table, we need to ensure that each Stadium_ID appears in every Year listed in the table. Here's the SQL code to achieve this:\n\n```sql\nSELECT Stadium_ID\nFROM concert\nGROUP BY Stadium_ID\nHAVING COUNT(DISTINCT Year) = (SELECT COUNT(DISTINCT Year) FROM concert);\n```\n\nThis query:\n1. Groups the rows in the `concert` table by `Stadium_ID`\n2. Counts the number of distinct Years for each Stadium_ID\n3. Compares this count to the total number of distinct Years in the `concert` table\n4. Returns only those Stadium_ID(s) that have concerts in all the Years present in the table","cost":0.0007812,"response_parsed":"SELECT Stadium_ID\nFROM concert\nGROUP BY Stadium_ID\nHAVING COUNT(DISTINCT Year) = (SELECT COUNT(DISTINCT Year) FROM concert);","time":6.0849733353}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `concert` ORDER BY `Stadium_ID` ASC","question":"Show all data ordered by Stadium_ID in ascending order for the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `concert` table ordered by `Stadium_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nORDER BY Stadium_ID ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `concert` table.\n2. Order the results by the `Stadium_ID` column in ascending order (`ASC`).","cost":0.0005967,"response_parsed":"SELECT *\nFROM concert\nORDER BY Stadium_ID ASC;","time":4.3805184364}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `concert` ORDER BY `Stadium_ID` DESC","question":"Show all data ordered by Stadium_ID in descending order for the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `concert` table ordered by `Stadium_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nORDER BY Stadium_ID DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `concert` table.\n2. Order the results by the `Stadium_ID` column in descending order (`DESC`).","cost":0.0006102,"response_parsed":"SELECT *\nFROM concert\nORDER BY Stadium_ID DESC;","time":4.6971113682}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `concert` ORDER BY `concert_ID` ASC","question":"Show all data ordered by concert_ID in ascending order for the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `concert` table ordered by `concert_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nORDER BY concert_ID ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `concert` table.\n2. Order the results by the `concert_ID` column in ascending order (from smallest to largest).","cost":0.0006165,"response_parsed":"SELECT *\nFROM concert\nORDER BY concert_ID ASC;","time":4.7090058327}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `concert` ORDER BY `concert_ID` DESC","question":"Show all data ordered by concert_ID in descending order for the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `concert` table ordered by `concert_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nORDER BY concert_ID DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `concert` table.\n2. Order the results by the `concert_ID` column in descending order (from highest to lowest).","cost":0.0006588,"response_parsed":"SELECT *\nFROM concert\nORDER BY concert_ID DESC;","time":5.3235955238}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Year` FROM `concert` ORDER BY `Year` ASC","question":"Project the Year ordered in ascending order for the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Year` from the `concert` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Year\nFROM concert\nORDER BY Year ASC;\n```\n\nThis query will:\n1. Select the `Year` column from the `concert` table\n2. Order the results in ascending order based on the `Year` column","cost":0.0005346,"response_parsed":"SELECT Year\nFROM concert\nORDER BY Year ASC;","time":4.035640955}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Year` FROM `concert` ORDER BY `Year` DESC","question":"Project the Year ordered in descending order for the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Year` from the `concert` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Year\nFROM concert\nORDER BY Year DESC;\n```\n\nThis query will:\n1. Select the `Year` column from the `concert` table\n2. Order the results in descending order based on the `Year` values","cost":0.0005976,"response_parsed":"SELECT Year\nFROM concert\nORDER BY Year DESC;","time":4.2316758633}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Stadium_ID` FROM `concert` ORDER BY `Stadium_ID` ASC","question":"Project the Stadium_ID ordered in ascending order for the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Stadium_ID` from the `concert` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID FROM concert ORDER BY Stadium_ID ASC;\n```","cost":0.0005571,"response_parsed":"SELECT Stadium_ID FROM concert ORDER BY Stadium_ID ASC;","time":4.5409014225}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Stadium_ID` FROM `concert` ORDER BY `Stadium_ID` DESC","question":"Project the Stadium_ID ordered in descending order for the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Stadium_ID` from the `concert` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID FROM concert ORDER BY Stadium_ID DESC;\n```\n\nThis query will:\n1. Select the `Stadium_ID` column from the `concert` table.\n2. Order the results in descending order based on the `Stadium_ID` values.","cost":0.0005616,"response_parsed":"SELECT Stadium_ID FROM concert ORDER BY Stadium_ID DESC;","time":4.1050591469}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `stadium` ORDER BY `Location` ASC","question":"Show all data ordered by Location in ascending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all data ordered by Location in ascending order for the table `stadium`, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium ORDER BY Location ASC;\n```","cost":0.0005787,"response_parsed":"SELECT * FROM stadium ORDER BY Location ASC;","time":4.2328937054}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `stadium` ORDER BY `Location` DESC","question":"Show all data ordered by Location in descending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all data from the `stadium` table ordered by `Location` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium ORDER BY Location DESC;\n```","cost":0.000558,"response_parsed":"SELECT * FROM stadium ORDER BY Location DESC;","time":4.088634491}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `stadium` ORDER BY `Stadium_ID` ASC","question":"Show all data ordered by Stadium_ID in ascending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `stadium` table ordered by `Stadium_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium ORDER BY Stadium_ID ASC;\n```","cost":0.0004851,"response_parsed":"SELECT * FROM stadium ORDER BY Stadium_ID ASC;","time":2.9566845894}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `stadium` ORDER BY `Stadium_ID` DESC","question":"Show all data ordered by Stadium_ID in descending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `stadium` table ordered by `Stadium_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium ORDER BY Stadium_ID DESC;\n```","cost":0.0005346,"response_parsed":"SELECT * FROM stadium ORDER BY Stadium_ID DESC;","time":4.8217535019}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Capacity` FROM `stadium` ORDER BY `Capacity` ASC","question":"Project the Capacity ordered in ascending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Capacity` from the `stadium` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Capacity \nFROM stadium \nORDER BY Capacity ASC;\n```\n\nThis query will fetch the `Capacity` values from the `stadium` table and sort them in ascending order.","cost":0.0004761,"response_parsed":"SELECT Capacity \nFROM stadium \nORDER BY Capacity ASC;","time":3.240691185}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Capacity` FROM `stadium` ORDER BY `Capacity` DESC","question":"Project the Capacity ordered in descending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Capacity` from the `stadium` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Capacity\nFROM stadium\nORDER BY Capacity DESC;\n```\n\nThis query will:\n1. Select the `Capacity` column from the `stadium` table.\n2. Order the results in descending order based on the `Capacity` values.","cost":0.0005121,"response_parsed":"SELECT Capacity\nFROM stadium\nORDER BY Capacity DESC;","time":3.4985220432}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Highest` FROM `stadium` ORDER BY `Highest` ASC","question":"Project the Highest ordered in ascending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the \"Highest\" column from the \"stadium\" table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Highest FROM stadium ORDER BY Highest ASC;\n```","cost":0.0004851,"response_parsed":"SELECT Highest FROM stadium ORDER BY Highest ASC;","time":2.9813191891}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Highest` FROM `stadium` ORDER BY `Highest` DESC","question":"Project the Highest ordered in descending order for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the \"Highest\" column from the \"stadium\" table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Highest FROM stadium ORDER BY Highest DESC;\n```","cost":0.0005436,"response_parsed":"SELECT Highest FROM stadium ORDER BY Highest DESC;","time":3.5959413052}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer` ORDER BY `Song_release_year` ASC","question":"Show all data ordered by Song_release_year in ascending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `singer` table ordered by `Song_release_year` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nORDER BY Song_release_year ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `singer` table.\n2. Order the results by the `Song_release_year` column in ascending order (from oldest to newest).","cost":0.0006066,"response_parsed":"SELECT *\nFROM singer\nORDER BY Song_release_year ASC;","time":4.1712241173}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer` ORDER BY `Song_release_year` DESC","question":"Show all data ordered by Song_release_year in descending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `singer` table ordered by `Song_release_year` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nORDER BY Song_release_year DESC;\n```\n\nThis query will return all records from the `singer` table, sorted by the `Song_release_year` column in descending order (from the most recent to the oldest release year).","cost":0.0006345,"response_parsed":"SELECT *\nFROM singer\nORDER BY Song_release_year DESC;","time":4.3758444786}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer` ORDER BY `Name` ASC","question":"Show all data ordered by Name in ascending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `singer` table ordered by the `Name` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer ORDER BY Name ASC;\n```","cost":0.0005571,"response_parsed":"SELECT * FROM singer ORDER BY Name ASC;","time":3.8349072933}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer` ORDER BY `Name` DESC","question":"Show all data ordered by Name in descending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `singer` table ordered by the `Name` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nORDER BY Name DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `singer` table.\n2. Order the results by the `Name` column in descending order (`DESC`).","cost":0.0006057,"response_parsed":"SELECT *\nFROM singer\nORDER BY Name DESC;","time":4.459020853}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `singer` ORDER BY `Country` ASC","question":"Project the Country ordered in ascending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Country` from the `singer` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country \nFROM singer \nORDER BY Country ASC;\n```\n\nThis query will:\n1. Select the `Country` column from the `singer` table.\n2. Remove duplicates using `DISTINCT`.\n3. Order the results in ascending alphabetical order by `Country`.","cost":0.0005085,"response_parsed":"SELECT DISTINCT Country \nFROM singer \nORDER BY Country ASC;","time":3.5370857716}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `singer` ORDER BY `Country` DESC","question":"Project the Country ordered in descending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Country` from the `singer` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Country FROM singer ORDER BY Country DESC;\n```","cost":0.0004671,"response_parsed":"SELECT Country FROM singer ORDER BY Country DESC;","time":3.9877574444}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Singer_ID` FROM `singer` ORDER BY `Singer_ID` ASC","question":"Project the Singer_ID ordered in ascending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Singer_ID` from the `singer` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID\nFROM singer\nORDER BY Singer_ID ASC;\n```","cost":0.0004824,"response_parsed":"SELECT Singer_ID\nFROM singer\nORDER BY Singer_ID ASC;","time":3.6735508442}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Singer_ID` FROM `singer` ORDER BY `Singer_ID` DESC","question":"Project the Singer_ID ordered in descending order for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Singer_ID` from the `singer` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID FROM singer ORDER BY Singer_ID DESC;\n```","cost":0.0004815,"response_parsed":"SELECT Singer_ID FROM singer ORDER BY Singer_ID DESC;","time":3.5214009285}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer_in_concert` ORDER BY `concert_ID` ASC","question":"Show all data ordered by concert_ID in ascending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the table `singer_in_concert` ordered by `concert_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nORDER BY concert_ID ASC;\n```\n\nThis query will return all rows from the `singer_in_concert` table, sorted by the `concert_ID` column in ascending order.","cost":0.0005778,"response_parsed":"SELECT *\nFROM singer_in_concert\nORDER BY concert_ID ASC;","time":4.8088219166}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer_in_concert` ORDER BY `concert_ID` DESC","question":"Show all data ordered by concert_ID in descending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the table `singer_in_concert` ordered by `concert_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nORDER BY concert_ID DESC;\n```","cost":0.0005796,"response_parsed":"SELECT *\nFROM singer_in_concert\nORDER BY concert_ID DESC;","time":4.452183485}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer_in_concert` ORDER BY `Singer_ID` ASC","question":"Show all data ordered by Singer_ID in ascending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the table `singer_in_concert` ordered by `Singer_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer_in_concert ORDER BY Singer_ID ASC;\n```","cost":0.0005742,"response_parsed":"SELECT * FROM singer_in_concert ORDER BY Singer_ID ASC;","time":4.0063724518}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `singer_in_concert` ORDER BY `Singer_ID` DESC","question":"Show all data ordered by Singer_ID in descending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the table `singer_in_concert` ordered by `Singer_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nORDER BY Singer_ID DESC;\n```\n\nThis query will return all rows from the `singer_in_concert` table, sorted by the `Singer_ID` column in descending order.","cost":0.0006345,"response_parsed":"SELECT *\nFROM singer_in_concert\nORDER BY Singer_ID DESC;","time":4.3857355118}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `concert_ID` FROM `singer_in_concert` ORDER BY `concert_ID` ASC","question":"Project the concert_ID ordered in ascending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `concert_ID` from the `singer_in_concert` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT concert_ID\nFROM singer_in_concert\nORDER BY concert_ID ASC;\n```\n\nThis query will:\n1. Select the `concert_ID` column from the `singer_in_concert` table.\n2. Order the results in ascending order based on the `concert_ID`.","cost":0.0005868,"response_parsed":"SELECT concert_ID\nFROM singer_in_concert\nORDER BY concert_ID ASC;","time":3.9780197144}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `concert_ID` FROM `singer_in_concert` ORDER BY `concert_ID` DESC","question":"Project the concert_ID ordered in descending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `concert_ID` from the `singer_in_concert` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT concert_ID\nFROM singer_in_concert\nORDER BY concert_ID DESC;\n```\n\nThis query will:\n1. Select the `concert_ID` column from the `singer_in_concert` table.\n2. Order the results in descending order based on the `concert_ID`.","cost":0.0005598,"response_parsed":"SELECT concert_ID\nFROM singer_in_concert\nORDER BY concert_ID DESC;","time":3.8036363125}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Singer_ID` FROM `singer_in_concert` ORDER BY `Singer_ID` ASC","question":"Project the Singer_ID ordered in ascending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo project the `Singer_ID` from the `singer_in_concert` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID\nFROM singer_in_concert\nORDER BY Singer_ID ASC;\n```\n\nThis query will:\n1. Select the `Singer_ID` column from the `singer_in_concert` table.\n2. Order the results in ascending order based on the `Singer_ID`.","cost":0.000675,"response_parsed":"SELECT Singer_ID\nFROM singer_in_concert\nORDER BY Singer_ID ASC;","time":5.1416139603}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Singer_ID` FROM `singer_in_concert` ORDER BY `Singer_ID` DESC","question":"Project the Singer_ID ordered in descending order for the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the Singer_ID from the singer_in_concert table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID FROM singer_in_concert ORDER BY Singer_ID DESC;\n```","cost":0.0007065,"response_parsed":"SELECT Singer_ID FROM singer_in_concert ORDER BY Singer_ID DESC;","time":5.7549102306}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `concert_ID` FROM `concert`","question":"Show all concert_ID in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `concert_ID` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT concert_ID FROM concert;\n```","cost":0.0004608,"response_parsed":"SELECT concert_ID FROM concert;","time":2.713845253}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `concert_Name` FROM `concert`","question":"Show all concert_Name in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `concert_Name` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT concert_Name\nFROM concert;\n```\n\nThis query will return all entries in the `concert_Name` column of your `concert` table.","cost":0.000495,"response_parsed":"SELECT concert_Name\nFROM concert;","time":3.0445177555}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Theme` FROM `concert`","question":"Show all Theme in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all themes from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Theme FROM concert;\n```\n\nThis query will return all the unique theme values stored in the `Theme` column of your `concert` table.","cost":0.0006165,"response_parsed":"SELECT Theme FROM concert;","time":5.2104542255}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Stadium_ID` FROM `concert`","question":"Show all Stadium_ID in the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Stadium_ID` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID FROM concert;\n```\n\nThis query will return all the `Stadium_ID` values present in your `concert` table.","cost":0.000522,"response_parsed":"SELECT Stadium_ID FROM concert;","time":3.5015888214}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Year` FROM `concert`","question":"Show all Year in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the years from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Year FROM concert;\n```\n\nThis query will return all unique years present in the `Year` column of the `concert` table.","cost":0.0005004,"response_parsed":"SELECT DISTINCT Year FROM concert;","time":3.3584754467}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `concert`","question":"Show all the rows in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM concert;\n```\n\nThis query will return all rows and columns from the `concert` table.","cost":0.0004626,"response_parsed":"SELECT * FROM concert;","time":2.8621993065}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Theme` FROM `concert`","question":"Show all Theme in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all themes from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Theme FROM concert;\n```\n\nThis query will return all the unique theme values stored in the `Theme` column of your `concert` table.","cost":0.0006165,"response_parsed":"SELECT Theme FROM concert;","time":4.7352063656}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Year`, `Theme` FROM `concert`","question":"Show all Year, Theme in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the `Year` and `Theme` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Year, Theme FROM concert;\n```\n\nThis query will return all rows from the `concert` table with the `Year` and `Theme` columns.","cost":0.000558,"response_parsed":"SELECT Year, Theme FROM concert;","time":4.0875966549}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `concert_ID`, `Year`, `Theme` FROM `concert`","question":"Show all concert_ID, Year, Theme in the table concert","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `concert_ID`, `Year`, and `Theme` from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT concert_ID, Year, Theme FROM concert;\n```\n\nThis query will return all rows from the `concert` table with the specified columns.","cost":0.0005427,"response_parsed":"SELECT concert_ID, Year, Theme FROM concert;","time":4.006578207}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Theme`, `Year`, `concert_ID`, `Stadium_ID` FROM `concert`","question":"Show all Theme, Year, concert_ID, Stadium_ID in the table concert","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the details of Theme, Year, concert_ID, and Stadium_ID from the `concert` table, you can use the following SQL query:\n\n```sql\nSELECT Theme, Year, concert_ID, Stadium_ID\nFROM concert;\n```\n\nThis query will return all rows from the `concert` table with the specified columns: Theme, Year, concert_ID, and Stadium_ID.","cost":0.0005715,"response_parsed":"SELECT Theme, Year, concert_ID, Stadium_ID\nFROM concert;","time":4.1269423962}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Location` FROM `stadium`","question":"Show all Location in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all locations from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Location FROM stadium;\n```\n\nThis query will return all the entries in the `Location` column of the `stadium` table.","cost":0.0005535,"response_parsed":"SELECT Location FROM stadium;","time":4.0201485157}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Lowest` FROM `stadium`","question":"Show all Lowest in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the \"Lowest\" values from the \"stadium\" table, you can use the following SQL query:\n\n```sql\nSELECT Lowest FROM stadium;\n```\n\nThis query will return all the values in the \"Lowest\" column of the \"stadium\" table.","cost":0.000621,"response_parsed":"SELECT Lowest FROM stadium;","time":4.9404022694}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Stadium_ID` FROM `stadium`","question":"Show all Stadium_ID in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Stadium_ID` from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID FROM stadium;\n```\n\nThis query will return all the `Stadium_ID` values present in your `stadium` table.","cost":0.0005283,"response_parsed":"SELECT Stadium_ID FROM stadium;","time":3.7312438488}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Average` FROM `stadium`","question":"Show all Average in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the \"Average\" values from the \"stadium\" table, you can use the following SQL query:\n\n```sql\nSELECT Average FROM stadium;\n```","cost":0.0005769,"response_parsed":"SELECT Average FROM stadium;","time":4.1993052959}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Capacity` FROM `stadium`","question":"Show all Capacity in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the capacities from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Capacity FROM stadium;\n```","cost":0.0004968,"response_parsed":"SELECT Capacity FROM stadium;","time":3.3025515079}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `stadium`","question":"Show all the rows in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium;\n```\n\nThis query will return all columns (`Stadium_ID`, `Location`, `Name`, `Capacity`, `Highest`, `Lowest`, `Average`) for every row in the `stadium` table.","cost":0.0005202,"response_parsed":"SELECT * FROM stadium;","time":3.6937944889}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Stadium_ID` FROM `stadium`","question":"Show all Stadium_ID in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Stadium_ID` from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID FROM stadium;\n```\n\nThis query will return all the `Stadium_ID` values present in your `stadium` table.","cost":0.0005283,"response_parsed":"SELECT Stadium_ID FROM stadium;","time":3.7365064621}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Highest`, `Location` FROM `stadium`","question":"Show all Highest, Location in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the \"Highest\" and \"Location\" columns from the \"stadium\" table, you can use the following SQL query:\n\n```sql\nSELECT Highest, Location FROM stadium;\n```","cost":0.0005229,"response_parsed":"SELECT Highest, Location FROM stadium;","time":3.565461874}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Lowest`, `Stadium_ID`, `Location` FROM `stadium`","question":"Show all Lowest, Stadium_ID, Location in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Lowest`, `Stadium_ID`, and `Location` from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Lowest, Stadium_ID, Location FROM stadium;\n```\n\nThis query will return all rows in the `stadium` table with the specified columns.","cost":0.0005652,"response_parsed":"SELECT Lowest, Stadium_ID, Location FROM stadium;","time":3.9203126431}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Location`, `Capacity`, `Lowest`, `Name` FROM `stadium`","question":"Show all Location, Capacity, Lowest, Name in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the required information from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Location, Capacity, Lowest, Name FROM stadium;\n```\n\nThis query will return all rows from the `stadium` table, displaying the columns `Location`, `Capacity`, `Lowest`, and `Name`.","cost":0.0005265,"response_parsed":"SELECT Location, Capacity, Lowest, Name FROM stadium;","time":3.3714408875}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Highest`, `Stadium_ID`, `Lowest`, `Capacity`, `Location` FROM `stadium`","question":"Show all Highest, Stadium_ID, Lowest, Capacity, Location in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the required information from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Highest, Stadium_ID, Lowest, Capacity, Location FROM stadium;\n```\n\nThis query will return all the records from the `stadium` table with the specified columns: `Highest`, `Stadium_ID`, `Lowest`, `Capacity`, and `Location`.","cost":0.0005301,"response_parsed":"SELECT Highest, Stadium_ID, Lowest, Capacity, Location FROM stadium;","time":3.3350360394}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Stadium_ID`, `Average`, `Highest`, `Location`, `Name`, `Lowest` FROM `stadium`","question":"Show all Stadium_ID, Average, Highest, Location, Name, Lowest in the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the required information from the `stadium` table, you can use the following SQL query:\n\n```sql\nSELECT Stadium_ID, Average, Highest, Location, Name, Lowest\nFROM stadium;\n```\n\nThis query will return all the records from the `stadium` table with the specified columns: `Stadium_ID`, `Average`, `Highest`, `Location`, `Name`, and `Lowest`.","cost":0.0006336,"response_parsed":"SELECT Stadium_ID, Average, Highest, Location, Name, Lowest\nFROM stadium;","time":4.4511134624}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Song_release_year` FROM `singer`","question":"Show all Song_release_year in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Song_release_year` entries from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_release_year FROM singer;\n```\n\nThis query will return all the values in the `Song_release_year` column of the `singer` table.","cost":0.0005049,"response_parsed":"SELECT Song_release_year FROM singer;","time":3.7935271263}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Singer_ID` FROM `singer`","question":"Show all Singer_ID in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Singer_ID` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID FROM singer;\n```\n\nThis query will return all the unique `Singer_ID` values stored in your `singer` table.","cost":0.0007146,"response_parsed":"SELECT Singer_ID FROM singer;","time":6.4441504478}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Age` FROM `singer`","question":"Show all Age in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all the ages from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Age FROM singer;\n```\n\nThis query will return all the values in the `Age` column of the `singer` table.","cost":0.0004833,"response_parsed":"SELECT Age FROM singer;","time":3.1869678497}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Song_Name` FROM `singer`","question":"Show all Song_Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Song_Name` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_Name FROM singer;\n```\n\nThis query will return all the entries in the `Song_Name` column of the `singer` table.","cost":0.0006111,"response_parsed":"SELECT Song_Name FROM singer;","time":4.539229393}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `singer`","question":"Show all Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all names from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM singer;\n```","cost":0.0004437,"response_parsed":"SELECT Name FROM singer;","time":2.7628519535}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `singer`","question":"Show all the rows in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer;\n```\n\nThis query will return all columns (`*`) for every row in the `singer` table.","cost":0.0005112,"response_parsed":"SELECT * FROM singer;","time":3.3301830292}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Song_Name` FROM `singer`","question":"Show all Song_Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Song_Name` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_Name FROM singer;\n```\n\nThis query will return all the entries in the `Song_Name` column of the `singer` table.","cost":0.0006111,"response_parsed":"SELECT Song_Name FROM singer;","time":4.3464033604}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Age`, `Name` FROM `singer`","question":"Show all Age, Name in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Age` and `Name` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Age, Name FROM singer;\n```","cost":0.0005283,"response_parsed":"SELECT Age, Name FROM singer;","time":3.4738345146}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Song_release_year`, `Name`, `Age` FROM `singer`","question":"Show all Song_release_year, Name, Age in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Song_release_year`, `Name`, and `Age` from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Song_release_year, Name, Age FROM singer;\n```","cost":0.0006372,"response_parsed":"SELECT Song_release_year, Name, Age FROM singer;","time":4.7296934128}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Country`, `Age`, `Singer_ID`, `Song_release_year` FROM `singer`","question":"Show all Country, Age, Singer_ID, Song_release_year in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the required information from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Country, Age, Singer_ID, Song_release_year FROM singer;\n```\n\nThis query will return all rows from the `singer` table with the columns `Country`, `Age`, `Singer_ID`, and `Song_release_year`.","cost":0.000621,"response_parsed":"SELECT Country, Age, Singer_ID, Song_release_year FROM singer;","time":4.3400928974}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Age`, `Singer_ID`, `Country`, `Name`, `Song_release_year` FROM `singer`","question":"Show all Age, Singer_ID, Country, Name, Song_release_year in the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the specified columns from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT Age, Singer_ID, Country, Name, Song_release_year FROM singer;\n```\n\nThis query will return all rows from the `singer` table with the columns `Age`, `Singer_ID`, `Country`, `Name`, and `Song_release_year`.","cost":0.0006489,"response_parsed":"SELECT Age, Singer_ID, Country, Name, Song_release_year FROM singer;","time":4.3076293468}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `concert_ID` FROM `singer_in_concert`","question":"Show all concert_ID in the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `concert_ID` from the `singer_in_concert` table, you can use the following SQL query:\n\n```sql\nSELECT concert_ID FROM singer_in_concert;\n```","cost":0.0005265,"response_parsed":"SELECT concert_ID FROM singer_in_concert;","time":3.2427821159}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Singer_ID` FROM `singer_in_concert`","question":"Show all Singer_ID in the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Singer_ID`s from the `singer_in_concert` table, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID FROM singer_in_concert;\n```","cost":0.00054,"response_parsed":"SELECT Singer_ID FROM singer_in_concert;","time":3.4607021809}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `singer_in_concert`","question":"Show all the rows in the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `singer_in_concert` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer_in_concert;\n```\n\nThis query will return all rows and columns from the `singer_in_concert` table.","cost":0.0005994,"response_parsed":"SELECT * FROM singer_in_concert;","time":3.9175987244}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Singer_ID` FROM `singer_in_concert`","question":"Show all Singer_ID in the table singer_in_concert","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Singer_ID`s from the `singer_in_concert` table, you can use the following SQL query:\n\n```sql\nSELECT Singer_ID FROM singer_in_concert;\n```","cost":0.0005409,"response_parsed":"SELECT Singer_ID FROM singer_in_concert;","time":3.6136922836}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `concert_Name` == 'Week 2'","question":"Show the data of the table concert where concert_Name is equal to Week 2","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `concert_Name` is \"Week 2\", you can use the following SQL query:\n\n```sql\nSELECT * FROM concert WHERE concert_Name = 'Week 2';\n```","cost":0.0005463,"response_parsed":"SELECT * FROM concert WHERE concert_Name = 'Week 2';","time":3.815541029}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `concert_Name` != 'Home Visits'","question":"Show the data of the table concert where concert_Name is different from Home Visits","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `concert_Name` is different from \"Home Visits\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE concert_Name != 'Home Visits';\n```","cost":0.0006372,"response_parsed":"SELECT *\nFROM concert\nWHERE concert_Name != 'Home Visits';","time":4.1659984589}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `concert_Name` != 'Home Visits'","question":"Show the data of the table concert where concert_Name not equal to Home Visits","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `concert_Name` is not equal to \"Home Visits\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE concert_Name != 'Home Visits';\n```","cost":0.0006129,"response_parsed":"SELECT *\nFROM concert\nWHERE concert_Name != 'Home Visits';","time":4.1586258411}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Stadium_ID` == '10'","question":"Show the data of the table concert where Stadium_ID is equal to 10","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `Stadium_ID` is equal to 10, you can use the following SQL query:\n\n```sql\nSELECT * FROM concert WHERE Stadium_ID = '10';\n```\n\nThis query will return all rows in the `concert` table where the `Stadium_ID` matches the specified value of 10.","cost":0.0005733,"response_parsed":"SELECT * FROM concert WHERE Stadium_ID = '10';","time":3.9454424381}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Stadium_ID` != '10'","question":"Show the data of the table concert where Stadium_ID is different from 10","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `Stadium_ID` is different from 10, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE Stadium_ID != '10';\n```\n\nThis query will return all rows from the `concert` table where the `Stadium_ID` is not equal to 10.","cost":0.0006165,"response_parsed":"SELECT *\nFROM concert\nWHERE Stadium_ID != '10';","time":4.5052006245}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Stadium_ID` != '2'","question":"Show the data of the table concert where Stadium_ID not equal to 2","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where `Stadium_ID` is not equal to 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE Stadium_ID != 2;\n```","cost":0.0005175,"response_parsed":"SELECT *\nFROM concert\nWHERE Stadium_ID != 2;","time":3.0234386921}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Theme` == 'Free choice 2'","question":"Show the data of the table concert where Theme is equal to Free choice 2","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where the `Theme` is \"Free choice 2\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE Theme = 'Free choice 2';\n```","cost":0.0006246,"response_parsed":"SELECT *\nFROM concert\nWHERE Theme = 'Free choice 2';","time":4.2044775486}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Theme` != 'Wide Awake'","question":"Show the data of the table concert where Theme is different from Wide Awake","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where the `Theme` is different from \"Wide Awake\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE Theme != 'Wide Awake';\n```","cost":0.0005238,"response_parsed":"SELECT *\nFROM concert\nWHERE Theme != 'Wide Awake';","time":3.5106732845}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `concert` WHERE `Theme` != 'Free choice'","question":"Show the data of the table concert where Theme not equal to Free choice","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `concert` table where the `Theme` is not equal to \"Free choice\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM concert\nWHERE Theme != 'Free choice';\n```","cost":0.0005985,"response_parsed":"SELECT *\nFROM concert\nWHERE Theme != 'Free choice';","time":3.8996696472}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Location` == 'East Fife'","question":"Show the data of the table stadium where Location is equal to East Fife","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\n```sql\nSELECT * FROM stadium WHERE Location = 'East Fife';\n```","cost":0.0005778,"response_parsed":"SELECT * FROM stadium WHERE Location = 'East Fife';","time":3.9300289154}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Location` != 'Stirling Albion'","question":"Show the data of the table stadium where Location is different from Stirling Albion","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Location` is different from \"Stirling Albion,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM stadium\nWHERE Location != 'Stirling Albion';\n```","cost":0.0006561,"response_parsed":"SELECT *\nFROM stadium\nWHERE Location != 'Stirling Albion';","time":4.530790329}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Location` != 'Ayr United'","question":"Show the data of the table stadium where Location not equal to Ayr United","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Location` is not equal to \"Ayr United\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM stadium\nWHERE Location <> 'Ayr United';\n```","cost":0.0005796,"response_parsed":"SELECT *\nFROM stadium\nWHERE Location <> 'Ayr United';","time":4.0006666183}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Name` == 'Somerset Park'","question":"Show the data of the table stadium where Name is equal to Somerset Park","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Name` is \"Somerset Park,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium WHERE Name = 'Somerset Park';\n```","cost":0.0005409,"response_parsed":"SELECT * FROM stadium WHERE Name = 'Somerset Park';","time":3.5901477337}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Name` != 'Forthbank Stadium'","question":"Show the data of the table stadium where Name is different from Forthbank Stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Name` is different from \"Forthbank Stadium\", you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium WHERE Name <> 'Forthbank Stadium';\n```\n\nThis query will return all rows from the `stadium` table where the `Name` column does not equal \"Forthbank Stadium\".","cost":0.0006309,"response_parsed":"SELECT * FROM stadium WHERE Name <> 'Forthbank Stadium';","time":4.1531198025}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `stadium` WHERE `Name` != 'Bayview Stadium'","question":"Show the data of the table stadium where Name not equal to Bayview Stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Name` is not equal to \"Bayview Stadium\", you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium WHERE Name != 'Bayview Stadium';\n```","cost":0.0006651,"response_parsed":"SELECT * FROM stadium WHERE Name != 'Bayview Stadium';","time":5.0907144547}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `stadium` WHERE `Average` > 864","question":"Show the data of the table stadium where Average is greater than 864","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Average` is greater than 864, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM stadium\nWHERE Average > 864;\n```\n\nThis query will return all rows in the `stadium` table where the `Average` column has a value greater than 864.","cost":0.0006786,"response_parsed":"SELECT *\nFROM stadium\nWHERE Average > 864;","time":6.2991695404}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `stadium` WHERE `Average` < 1477","question":"Show the data of the table stadium where Average is less than 1477","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Average` is less than 1477, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM stadium\nWHERE Average < 1477;\n```","cost":0.0006228,"response_parsed":"SELECT *\nFROM stadium\nWHERE Average < 1477;","time":4.6928734779}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `stadium` WHERE `Lowest` < 533","question":"Show the data of the table stadium where Lowest is less than 533","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `stadium` table where the `Lowest` value is less than 533, you can use the following SQL query:\n\n```sql\nSELECT * FROM stadium WHERE Lowest < 533;\n```","cost":0.0005535,"response_parsed":"SELECT * FROM stadium WHERE Lowest < 533;","time":3.7056901455}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Country` == 'Netherlands'","question":"Show the data of the table singer where Country is equal to Netherlands","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of singers from the Netherlands, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Country = 'Netherlands';\n```","cost":0.0005499,"response_parsed":"SELECT *\nFROM singer\nWHERE Country = 'Netherlands';","time":3.4853711128}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Country` != 'France'","question":"Show the data of the table singer where Country is different from France","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of singers from countries other than France, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Country != 'France';\n```\n\nThis query will return all rows from the `singer` table where the `Country` column is not 'France'.","cost":0.0006345,"response_parsed":"SELECT *\nFROM singer\nWHERE Country != 'France';","time":4.4174308777}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Country` != 'United States'","question":"Show the data of the table singer where Country not equal to United States","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of singers from the `singer` table where the `Country` is not equal to \"United States\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Country != 'United States';\n```\n\nThis query will return all rows from the `singer` table where the `Country` column does not contain the value \"United States\".","cost":0.0005292,"response_parsed":"SELECT *\nFROM singer\nWHERE Country != 'United States';","time":3.5451693535}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Song_Name` == 'Sun'","question":"Show the data of the table singer where Song_Name is equal to Sun","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer` table where the `Song_Name` is \"Sun\", you can use the following SQL query:\n\n```sql\nSELECT * FROM singer WHERE Song_Name = 'Sun';\n```","cost":0.0005661,"response_parsed":"SELECT * FROM singer WHERE Song_Name = 'Sun';","time":3.84045434}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Song_Name` != 'Gentleman'","question":"Show the data of the table singer where Song_Name is different from Gentleman","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer` table where the `Song_Name` is different from \"Gentleman,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Song_Name != 'Gentleman';\n```","cost":0.0006732,"response_parsed":"SELECT *\nFROM singer\nWHERE Song_Name != 'Gentleman';","time":4.9112343788}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Song_Name` != 'You'","question":"Show the data of the table singer where Song_Name not equal to You","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer` table where the `Song_Name` is not equal to \"You\", you can use the following SQL query:\n\n```sql\nSELECT * FROM singer WHERE Song_Name != 'You';\n```","cost":0.0005841,"response_parsed":"SELECT * FROM singer WHERE Song_Name != 'You';","time":3.7886426449}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Name` == 'Rose White'","question":"Show the data of the table singer where Name is equal to Rose White","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of the singer with the name \"Rose White\" from the `singer` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer WHERE Name = 'Rose White';\n```","cost":0.0007146,"response_parsed":"SELECT * FROM singer WHERE Name = 'Rose White';","time":5.5820698738}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Name` != 'Rose White'","question":"Show the data of the table singer where Name is different from Rose White","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer` table where the `Name` is different from \"Rose White,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Name != 'Rose White';\n```","cost":0.0007362,"response_parsed":"SELECT *\nFROM singer\nWHERE Name != 'Rose White';","time":5.4922575951}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer` WHERE `Name` != 'Rose White'","question":"Show the data of the table singer where Name not equal to Rose White","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer` table where the `Name` is not equal to \"Rose White\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer\nWHERE Name <> 'Rose White';\n```","cost":0.0005724,"response_parsed":"SELECT *\nFROM singer\nWHERE Name <> 'Rose White';","time":3.9724049568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `singer` WHERE `Age` < 29","question":"Show the data of the table singer where Age is less than 29","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of singers where the age is less than 29, you can use the following SQL query:\n\n```sql\nSELECT * FROM singer WHERE Age < 29;\n```","cost":0.0005409,"response_parsed":"SELECT * FROM singer WHERE Age < 29;","time":3.361913681}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer_in_concert` WHERE `Singer_ID` == '5'","question":"Show the data of the table singer_in_concert where Singer_ID is equal to 5","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the table `singer_in_concert` where `Singer_ID` is equal to 5, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nWHERE Singer_ID = 5;\n```","cost":0.000549,"response_parsed":"SELECT *\nFROM singer_in_concert\nWHERE Singer_ID = 5;","time":3.4050133228}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer_in_concert` WHERE `Singer_ID` != '2'","question":"Show the data of the table singer_in_concert where Singer_ID is different from 2","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer_in_concert` table where `Singer_ID` is different from 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nWHERE Singer_ID != 2;\n```\n\nThis query will return all rows from the `singer_in_concert` table where the `Singer_ID` is not equal to 2.","cost":0.0006516,"response_parsed":"SELECT *\nFROM singer_in_concert\nWHERE Singer_ID != 2;","time":4.677970171}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `singer_in_concert` WHERE `Singer_ID` != '2'","question":"Show the data of the table singer_in_concert where Singer_ID not equal to 2","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `singer_in_concert` table where `Singer_ID` is not equal to 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM singer_in_concert\nWHERE Singer_ID <> '2';\n```\n\nThis query will return all rows from the `singer_in_concert` table where the `Singer_ID` is not equal to 2.","cost":0.0006669,"response_parsed":"SELECT *\nFROM singer_in_concert\nWHERE Singer_ID <> '2';","time":4.8110017776}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `concert_Name`) FROM `concert`","question":"How many different concert_Name are in table concert?","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `concert_Name` entries are in the `concert` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT concert_Name) AS number_of_unique_concert_names\nFROM concert;\n```\n\n### Explanation:\n- `COUNT(DISTINCT concert_Name)`: This function counts the number of unique values in the `concert_Name` column.\n- `AS number_of_unique_concert_names`: This renames the resulting column to make the output more readable.\n- `FROM concert`: This specifies the table from which to retrieve the data.\n\nWhen you execute this query, it will return the number of different concert names in your `concert` table.","cost":0.0006111,"response_parsed":"SELECT COUNT(DISTINCT concert_Name) AS number_of_unique_concert_names\nFROM concert;","time":4.3279721737}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Theme`) FROM `concert`","question":"How many different Theme are in table concert?","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different themes are in the `concert` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Theme) FROM concert;\n```","cost":0.0005346,"response_parsed":"SELECT COUNT(DISTINCT Theme) FROM concert;","time":3.4198014736}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Stadium_ID`) FROM `concert`","question":"How many different Stadium_ID are in table concert?","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Stadium_ID` values are present in the `concert` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT `Stadium_ID`) AS `Number_of_Different_Stadium_IDs`\nFROM `concert`;\n```\n\nThis query will return the number of unique `Stadium_ID` values in the `concert` table.","cost":0.0007173,"response_parsed":"SELECT COUNT(DISTINCT `Stadium_ID`) AS `Number_of_Different_Stadium_IDs`\nFROM `concert`;","time":5.3580775261}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"concert","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Year`) FROM `concert`","question":"How many different Year are in table concert?","db_schema_normalized":"`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different years are in the `concert` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Year) FROM concert;\n```","cost":0.0005688,"response_parsed":"SELECT COUNT(DISTINCT Year) FROM concert;","time":4.331196785}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Location`) FROM `stadium`","question":"How many different Location are in table stadium?","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different locations are in the `stadium` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Location) AS Number_of_Locations FROM stadium;\n```\n\nThis query will return the number of unique locations present in the `Location` column of the `stadium` table.","cost":0.0006255,"response_parsed":"SELECT COUNT(DISTINCT Location) AS Number_of_Locations FROM stadium;","time":4.4648180008}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `stadium`","question":"How many different Name are in table stadium?","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different names are in the `stadium` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM stadium;\n```","cost":0.0005976,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM stadium;","time":3.8521735668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Average`) FROM `stadium`","question":"Find the maximum Average for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum average for the table \"stadium,\" you can use the SQL `MAX()` function on the \"Average\" column.\n\n```sql\nSELECT MAX(Average) AS Maximum_Average FROM stadium;\n```\n\nThis query will return the highest value in the \"Average\" column of the \"stadium\" table.","cost":0.000684,"response_parsed":"SELECT MAX(Average) AS Maximum_Average FROM stadium;","time":10.3308260441}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Average`) FROM `stadium`","question":"Find the minimum Average for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum average for the table `stadium`, you can use the SQL `MIN()` function on the `Average` column.\n\n```sql\nSELECT MIN(Average) FROM stadium;\n```","cost":0.0004887,"response_parsed":"SELECT MIN(Average) FROM stadium;","time":3.3332824707}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Average`) FROM `stadium`","question":"Find the average Average for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average value of the \"Average\" column in the \"stadium\" table, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(\"Average\") FROM stadium;\n```\n\nThis query will calculate and return the average value of the \"Average\" column in your \"stadium\" table.","cost":0.0006273,"response_parsed":"SELECT AVG(\"Average\") FROM stadium;","time":4.4616363049}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Highest`) FROM `stadium`","question":"Find the maximum Highest for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum value in the \"Highest\" column of the \"stadium\" table, you can use the SQL `MAX()` function. Here's the SQL query:\n\n```sql\nSELECT MAX(\"Highest\") FROM stadium;\n```","cost":0.0005049,"response_parsed":"SELECT MAX(\"Highest\") FROM stadium;","time":3.0691018105}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Highest`) FROM `stadium`","question":"Find the minimum Highest for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum value in the \"Highest\" column of the \"stadium\" table, you can use the SQL `MIN()` function. Here is the SQL query:\n\n```sql\nSELECT MIN(Highest) AS min_highest FROM stadium;\n```\n\nThis query will return the smallest value in the \"Highest\" column of your \"stadium\" table.","cost":0.0006894,"response_parsed":"SELECT MIN(Highest) AS min_highest FROM stadium;","time":5.3034009933}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"stadium","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Highest`) FROM `stadium`","question":"Find the average Highest for the table stadium","db_schema_normalized":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average \"Highest\" value for the table `stadium`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(Highest) AS Average_Highest FROM stadium;\n```\n\nThis query will calculate the average of the \"Highest\" column in the `stadium` table and return it as `Average_Highest`.","cost":0.0008712,"response_parsed":"SELECT AVG(Highest) AS Average_Highest FROM stadium;","time":6.8608436584}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `singer`","question":"How many different Name are in table singer?","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different names are in the `singer` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM singer;\n```","cost":0.0005499,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM singer;","time":3.7281258106}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Country`) FROM `singer`","question":"How many different Country are in table singer?","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different countries are in the `singer` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Country) AS Number_of_Countries\nFROM singer;\n```\n\nThis query will return the number of unique countries present in the `Country` column of the `singer` table.","cost":0.0005679,"response_parsed":"SELECT COUNT(DISTINCT Country) AS Number_of_Countries\nFROM singer;","time":3.3882544041}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Song_Name`) FROM `singer`","question":"How many different Song_Name are in table singer?","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Song_Name` entries are in the `singer` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Song_Name) AS Number_of_unique_songs\nFROM singer;\n```\n\nThis query will return the number of unique song names in the `singer` table.","cost":0.0006453,"response_parsed":"SELECT COUNT(DISTINCT Song_Name) AS Number_of_unique_songs\nFROM singer;","time":4.7067737579}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Song_release_year`) FROM `singer`","question":"How many different Song_release_year are in table singer?","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Song_release_year` values are in the `singer` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Song_release_year) FROM singer;\n```","cost":0.0006039,"response_parsed":"SELECT COUNT(DISTINCT Song_release_year) FROM singer;","time":4.2444901466}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Age`) FROM `singer`","question":"Find the maximum Age for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the maximum Age for the table `singer`, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(Age) AS Maximum_Age FROM singer;\n```\n\nThis query will return the highest Age value from the `singer` table.","cost":0.0005544,"response_parsed":"SELECT MAX(Age) AS Maximum_Age FROM singer;","time":4.0989258289}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Age`) FROM `singer`","question":"Find the minimum Age for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the minimum Age for the table `singer`, you can use the SQL `MIN()` function. Here is the SQL code:\n\n```sql\nSELECT MIN(Age) FROM singer;\n```","cost":0.0005589,"response_parsed":"SELECT MIN(Age) FROM singer;","time":3.9347326756}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Age`) FROM `singer`","question":"Find the average Age for the table singer","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo find the average Age for the table `singer`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(Age) AS Average_Age FROM singer;\n```\n\nThis query will calculate and return the average age of all singers in the `singer` table.","cost":0.0005877,"response_parsed":"SELECT AVG(Age) AS Average_Age FROM singer;","time":4.2133555412}} {"db_path":"QATCH-journal\/spider_data\/test_database\/concert_singer\/concert_singer.sqlite","db_id":"concert_singer","tbl_name":"singer_in_concert","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Singer_ID`) FROM `singer_in_concert`","question":"How many different Singer_ID are in table singer_in_concert?","db_schema_normalized":"`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","db_schema":"`\"stadium\"` (\"Stadium_ID\" int, \"Location\" text, \"Name\" text, \"Capacity\" int, \"Highest\" int, \"Lowest\" int, \"Average\" int, PRIMARY KEY (\"Stadium_ID\"))\n`\"singer\"` (\"Singer_ID\" int, \"Name\" text, \"Country\" text, \"Song_Name\" text, \"Song_release_year\" text, \"Age\" int, \"Is_male\" bool, PRIMARY KEY (\"Singer_ID\"))\n`\"concert\"` (\"concert_ID\" int, \"concert_Name\" text, \"Theme\" text, \"Stadium_ID\" text, \"Year\" text, PRIMARY KEY (\"concert_ID\"), FOREIGN KEY (\"Stadium_ID\") REFERENCES \"stadium\"(\"Stadium_ID\"))\n`\"singer_in_concert\"` (\"concert_ID\" int, \"Singer_ID\" text, PRIMARY KEY (\"concert_ID\",\"Singer_ID\"), FOREIGN KEY (\"concert_ID\") REFERENCES \"concert\"(\"concert_ID\"), FOREIGN KEY (\"Singer_ID\") REFERENCES \"singer\"(\"Singer_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Singer_ID`s are in the `singer_in_concert` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Singer_ID) AS Number_of_Unique_Singer_IDs\nFROM singer_in_concert;\n```\n\nThis query will return the number of unique `Singer_ID`s in the `singer_in_concert` table.","cost":0.0006354,"response_parsed":"SELECT COUNT(DISTINCT Singer_ID) AS Number_of_Unique_Singer_IDs\nFROM singer_in_concert;","time":4.4699194431}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `PetType` FROM `Pets`","question":"Show the different PetType in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show the different `PetType` in the `Pets` table, you can use the `SELECT DISTINCT` statement to retrieve unique values from the `PetType` column.\n\n```sql\nSELECT DISTINCT PetType FROM Pets;\n```","cost":0.000522,"response_parsed":"SELECT DISTINCT PetType FROM Pets;","time":4.9346563816}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `LName` FROM `Student`","question":"Show the different LName in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show the different `LName` values in the `Student` table, you can use the `DISTINCT` keyword to retrieve unique last names.\n\n```sql\nSELECT DISTINCT LName FROM Student;\n```","cost":0.0003897,"response_parsed":"SELECT DISTINCT LName FROM Student;","time":3.37423563}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Fname` FROM `Student`","question":"Show the different Fname in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show the different `Fname` values in the `Student` table, you can use the `DISTINCT` keyword to retrieve unique first names.\n\n```sql\nSELECT DISTINCT Fname FROM Student;\n```","cost":0.0003672,"response_parsed":"SELECT DISTINCT Fname FROM Student;","time":2.8496229649}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Sex` FROM `Student`","question":"Show the different Sex in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show the different Sex values in the `Student` table, you can use the `SELECT DISTINCT` statement to retrieve unique values from the `Sex` column.\n\n```sql\nSELECT DISTINCT Sex FROM Student;\n```","cost":0.0003915,"response_parsed":"SELECT DISTINCT Sex FROM Student;","time":3.7701637745}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `city_code` FROM `Student`","question":"Show the different city_code in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show the different `city_code` values in the `Student` table, you can use the `SELECT DISTINCT` statement to retrieve unique values from the `city_code` column.\n\n```sql\nSELECT DISTINCT city_code FROM Student;\n```","cost":0.0004176,"response_parsed":"SELECT DISTINCT city_code FROM Student;","time":4.128128767}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `PetType`, COUNT(*) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, count the number of rows in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo count the number of rows in the `Pets` table for each `PetType`, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT PetType, COUNT(PetID) AS NumberOfPets\nFROM Pets\nGROUP BY PetType\nORDER BY PetType ASC;\n```\n\nThis query will:\n1. Select the `PetType` column and count the number of rows for each `PetType`.\n2. Group the results by `PetType`.\n3. Optionally, order the results alphabetically by `PetType`.\n\nThe result will show each `PetType` along with the number of pets of that type.","cost":0.0006345,"response_parsed":"SELECT PetType, COUNT(PetID) AS NumberOfPets\nFROM Pets\nGROUP BY PetType\nORDER BY PetType ASC;","time":6.0603878498}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `PetType`, MIN(`pet_age`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the min of pet_age in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum `pet_age` for each `PetType` in the `Pets` table, you can use the SQL `MIN()` function combined with a `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT PetType, MIN(pet_age) AS min_pet_age\nFROM Pets\nGROUP BY PetType;\n```\n\nThis query will return the minimum age for each type of pet in your database.","cost":0.0004806,"response_parsed":"SELECT PetType, MIN(pet_age) AS min_pet_age\nFROM Pets\nGROUP BY PetType;","time":4.1611549854}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `PetType`, MAX(`pet_age`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the max of pet_age in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum `pet_age` for each `PetType` in the `Pets` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT PetType, MAX(pet_age) AS max_age\nFROM Pets\nGROUP BY PetType;\n```\n\nThis query will return the maximum age for each type of pet in your database.","cost":0.000621,"response_parsed":"SELECT PetType, MAX(pet_age) AS max_age\nFROM Pets\nGROUP BY PetType;","time":5.8018155098}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `PetType`, AVG(`pet_age`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the avg of pet_age in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average pet age for each PetType, we'll use the AVG() function and group the results by PetType.\n\n```sql\nSELECT \n PetType,\n AVG(pet_age) AS avg_pet_age\nFROM \n Pets\nGROUP BY \n PetType;\n```","cost":0.0005976,"response_parsed":"SELECT \n PetType,\n AVG(pet_age) AS avg_pet_age\nFROM \n Pets\nGROUP BY \n PetType;","time":5.5980565548}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `PetType`, SUM(`pet_age`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the sum of pet_age in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the sum of `pet_age` for each `PetType` in the `Pets` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n PetType,\n SUM(pet_age) AS total_age\nFROM \n Pets\nGROUP BY \n PetType\nORDER BY \n PetType;\n```\n\nThis query will:\n1. Group all rows in the `Pets` table by the `PetType` column.\n2. Calculate the sum of `pet_age` for each group.\n3. Return the results sorted by `PetType` for better readability.\n\nThe result will show each `PetType` along with the total sum of ages for pets of that type.","cost":0.0005814,"response_parsed":"SELECT \n PetType,\n SUM(pet_age) AS total_age\nFROM \n Pets\nGROUP BY \n PetType\nORDER BY \n PetType;","time":5.1805765629}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `PetType`, MIN(`weight`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the min of weight in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum weight for each PetType in the Pets table, you can use the SQL `MIN()` function combined with `GROUP BY`. Here's how to do it:\n\n```sql\nSELECT PetType, MIN(weight) AS min_weight\nFROM Pets\nGROUP BY PetType;\n```\n\nThis query will return each PetType along with the minimum weight found for that type.","cost":0.0005796,"response_parsed":"SELECT PetType, MIN(weight) AS min_weight\nFROM Pets\nGROUP BY PetType;","time":5.2690677643}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `PetType`, MAX(`weight`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the max of weight in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum weight for each PetType in the Pets table, we can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how to do it:\n\n```sql\nSELECT PetType, MAX(weight) AS MaxWeight\nFROM Pets\nGROUP BY PetType;\n```\n\nThis query will return each PetType along with the maximum weight recorded for that type of pet.","cost":0.0005508,"response_parsed":"SELECT PetType, MAX(weight) AS MaxWeight\nFROM Pets\nGROUP BY PetType;","time":5.5721302032}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `PetType`, AVG(`weight`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the avg of weight in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average weight for each PetType in the Pets table, we use the AVG() function and group the results by PetType.\n\n```sql\nSELECT PetType, AVG(weight) AS avg_weight\nFROM Pets\nGROUP BY PetType;\n```","cost":0.0005013,"response_parsed":"SELECT PetType, AVG(weight) AS avg_weight\nFROM Pets\nGROUP BY PetType;","time":4.6311223507}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `PetType`, SUM(`weight`) FROM `Pets` GROUP BY `PetType`","question":"For each PetType, find the sum of weight in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the sum of weight for each PetType from the Pets table, you can use the following SQL query:\n\n```sql\nSELECT PetType, SUM(weight) AS TotalWeight\nFROM Pets\nGROUP BY PetType;\n```","cost":0.000468,"response_parsed":"SELECT PetType, SUM(weight) AS TotalWeight\nFROM Pets\nGROUP BY PetType;","time":3.9695210457}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `LName`, COUNT(*) FROM `Student` GROUP BY `LName`","question":"For each LName, count the number of rows in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo count the number of rows for each `LName` in the `Student` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT LName, COUNT(*) as NumberOfStudents\nFROM Student\nGROUP BY LName;\n```\n\nThis query will:\n1. Group all rows in the `Student` table by the `LName` column.\n2. Count the number of rows in each group using `COUNT(*)`.\n3. Return a result set with two columns: `LName` and `NumberOfStudents`, where `NumberOfStudents` is the count of rows for each `LName`.\n\nThe result will show how many students there are for each last name in the table.","cost":0.0005967,"response_parsed":"SELECT LName, COUNT(*) as NumberOfStudents\nFROM Student\nGROUP BY LName;","time":5.6528432369}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Fname`, COUNT(*) FROM `Student` GROUP BY `Fname`","question":"For each Fname, count the number of rows in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo count the number of rows in the `Student` table for each `Fname`, you can use the SQL `COUNT(*)` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Fname, COUNT(*) AS \"Count\"\nFROM Student\nGROUP BY Fname;\n```\n\nThis query will return a list of first names along with the number of rows (students) for each first name in the `Student` table.","cost":0.0007011,"response_parsed":"SELECT Fname, COUNT(*) AS \"Count\"\nFROM Student\nGROUP BY Fname;","time":6.7439446449}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Sex`, COUNT(*) FROM `Student` GROUP BY `Sex`","question":"For each Sex, count the number of rows in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo count the number of rows for each `Sex` in the `Student` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause. Here is the SQL code:\n\n```sql\nSELECT Sex, COUNT(*) AS Count\nFROM Student\nGROUP BY Sex;\n```\n\nThis query will return the number of students for each unique value in the `Sex` column.","cost":0.000513,"response_parsed":"SELECT Sex, COUNT(*) AS Count\nFROM Student\nGROUP BY Sex;","time":4.9316067696}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `city_code`, COUNT(*) FROM `Student` GROUP BY `city_code`","question":"For each city_code, count the number of rows in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo count the number of students for each city_code in the Student table, we use the `COUNT()` function combined with `GROUP BY` to group the results by city_code.\n\n```sql\nSELECT city_code, COUNT(*) as student_count\nFROM Student\nGROUP BY city_code;\n```","cost":0.0005427,"response_parsed":"SELECT city_code, COUNT(*) as student_count\nFROM Student\nGROUP BY city_code;","time":5.7969150543}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `LName`, MIN(`Advisor`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the min of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Advisor for each LName in the Student table, we can use the SQL `GROUP BY` clause along with the `MIN()` function. Here's how you can do it:\n\n```sql\nSELECT LName, MIN(Advisor) AS MinAdvisor\nFROM Student\nGROUP BY LName;\n```\n\nThis query will return each unique `LName` along with the smallest `Advisor` value associated with that `LName`.","cost":0.0006498,"response_parsed":"SELECT LName, MIN(Advisor) AS MinAdvisor\nFROM Student\nGROUP BY LName;","time":8.9996347427}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `LName`, MAX(`Advisor`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the max of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum `Advisor` for each `LName` in the `Student` table, you can use the `MAX` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT LName, MAX(Advisor) AS MaxAdvisor\nFROM Student\nGROUP BY LName;\n```","cost":0.0004635,"response_parsed":"SELECT LName, MAX(Advisor) AS MaxAdvisor\nFROM Student\nGROUP BY LName;","time":14.9934196472}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `LName`, AVG(`Advisor`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the avg of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average Advisor for each LName in the Student table, we'll use the AVG() function and GROUP BY clause.\n\n```sql\nSELECT LName, AVG(Advisor) AS Avg_Advisor\nFROM Student\nGROUP BY LName;\n```","cost":0.0005841,"response_parsed":"SELECT LName, AVG(Advisor) AS Avg_Advisor\nFROM Student\nGROUP BY LName;","time":6.6746451855}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `LName`, SUM(`Advisor`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the sum of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question of finding the sum of `Advisor` for each `LName` in the `Student` table, we can use the SQL `GROUP BY` clause along with the `SUM` function. This will group the rows by `LName` and compute the sum of `Advisor` for each group.\n\n```sql\nSELECT LName, SUM(Advisor) AS SumOfAdvisor\nFROM Student\nGROUP BY LName;\n```","cost":0.0006048,"response_parsed":"SELECT LName, SUM(Advisor) AS SumOfAdvisor\nFROM Student\nGROUP BY LName;","time":5.8196332455}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `LName`, MIN(`Major`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the min of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Major for each LName in the Student table, we can use the SQL `MIN()` function combined with `GROUP BY`.\n\n```sql\nSELECT LName, MIN(Major) AS MinMajor\nFROM Student\nGROUP BY LName;\n```","cost":0.0005049,"response_parsed":"SELECT LName, MIN(Major) AS MinMajor\nFROM Student\nGROUP BY LName;","time":4.5796644688}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `LName`, MAX(`Major`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the max of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum Major for each LName in the Student table, we use the `GROUP BY` clause to group students by their last name and then apply the `MAX` function on the Major column.\n\n```sql\nSELECT LName, MAX(Major) AS MaxMajor\nFROM Student\nGROUP BY LName;\n```","cost":0.0005373,"response_parsed":"SELECT LName, MAX(Major) AS MaxMajor\nFROM Student\nGROUP BY LName;","time":4.7344546318}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `LName`, AVG(`Major`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the avg of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average of the `Major` for each `LName` in the `Student` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT LName, AVG(Major) AS Avg_Major\nFROM Student\nGROUP BY LName;\n```\n\nThis query will:\n1. Group all rows in the `Student` table by the `LName` column.\n2. Calculate the average value of the `Major` column for each group.\n3. Return a result set with two columns: `LName` and `Avg_Major` (the average of `Major` for each `LName`).","cost":0.00054,"response_parsed":"SELECT LName, AVG(Major) AS Avg_Major\nFROM Student\nGROUP BY LName;","time":4.7390859127}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `LName`, SUM(`Major`) FROM `Student` GROUP BY `LName`","question":"For each LName, find the sum of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of the `Major` values for each unique `LName` in the `Student` table. This can be achieved using the `SUM()` function combined with the `GROUP BY` clause to group the results by `LName`.\n\n```sql\nSELECT LName, SUM(Major) FROM Student GROUP BY LName;\n```","cost":0.000603,"response_parsed":"SELECT LName, SUM(Major) FROM Student GROUP BY LName;","time":5.3619754314}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Sex`, MIN(`Advisor`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the min of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Advisor for each Sex in the Student table, we can use the SQL `MIN()` function combined with `GROUP BY`.\n\n```sql\nSELECT \n Sex,\n MIN(Advisor) AS min_Advisor\nFROM \n Student\nGROUP BY \n Sex;\n```","cost":0.0004338,"response_parsed":"SELECT \n Sex,\n MIN(Advisor) AS min_Advisor\nFROM \n Student\nGROUP BY \n Sex;","time":3.9481415749}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Sex`, MAX(`Advisor`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the max of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum Advisor for each Sex in the Student table, we can use the SQL `MAX()` function combined with a `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Sex,\n MAX(Advisor) AS Max_Advisor\nFROM \n Student\nGROUP BY \n Sex;\n```\n\nThis query will return the maximum Advisor value for each unique Sex in your Student table.","cost":0.000504,"response_parsed":"SELECT \n Sex,\n MAX(Advisor) AS Max_Advisor\nFROM \n Student\nGROUP BY \n Sex;","time":4.7669312954}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Sex`, AVG(`Advisor`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the avg of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average Advisor for each Sex in the Student table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how to do it:\n\n```sql\nSELECT Sex, AVG(Advisor) AS Average_Advisor\nFROM Student\nGROUP BY Sex;\n```\n\nThis query will:\n1. Group all students by their `Sex`\n2. Calculate the average value of the `Advisor` column for each group\n3. Return the results with the sex and the corresponding average advisor\n\nThe result will show the average advisor for each sex in the Student table.","cost":0.0004986,"response_parsed":"SELECT Sex, AVG(Advisor) AS Average_Advisor\nFROM Student\nGROUP BY Sex;","time":4.4812877178}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Sex`, SUM(`Advisor`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the sum of Advisor in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the sum of the `Advisor` column for each `Sex` in the `Student` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Sex,\n SUM(Advisor) AS total_advisor\nFROM \n Student\nGROUP BY \n Sex;\n```\n\nThis query will:\n1. Group all rows in the `Student` table by the `Sex` column.\n2. For each group (i.e., for each sex), it will calculate the sum of the `Advisor` column.\n3. Return the result with two columns: `Sex` and `total_advisor` (the sum of advisors for each sex).\n\nIf you want to filter the results to only include specific sexes, you can add a `WHERE` clause before the `GROUP BY` clause. For example:\n\n```sql\nSELECT \n Sex,\n SUM(Advisor) AS total_advisor\nFROM \n Student\nWHERE \n Sex = 'M' -- Replace 'M' with the desired sex\nGROUP BY \n Sex;\n```\n\nThis would only return the sum of advisors for male students, for instance.","cost":0.0006795,"response_parsed":"SELECT \n Sex,\n SUM(Advisor) AS total_advisor\nFROM \n Student\nWHERE \n Sex = 'M' -- Replace 'M' with the desired sex\nGROUP BY \n Sex;","time":6.3736770153}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Sex`, MIN(`Major`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the min of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Major for each Sex in the Student table, we can use the SQL `MIN()` function combined with `GROUP BY`.\n\n```sql\nSELECT Sex, MIN(Major) AS min_Major\nFROM Student\nGROUP BY Sex;\n```","cost":0.0004347,"response_parsed":"SELECT Sex, MIN(Major) AS min_Major\nFROM Student\nGROUP BY Sex;","time":3.7904405594}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Sex`, MAX(`Major`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the max of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum Major for each Sex in the Student table, we can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how the query is constructed:\n\n1. **SELECT Clause**: We select the `Sex` column and the maximum value of the `Major` column.\n2. **FROM Clause**: We specify the `Student` table as the source of data.\n3. **GROUP BY Clause**: We group the results by the `Sex` column to ensure we get one maximum value per sex.\n\nHere is the SQL code:\n\n```sql\nSELECT Sex, MAX(Major) AS Max_Major\nFROM Student\nGROUP BY Sex;\n```\n\nThis query will return each unique `Sex` value along with the highest `Major` number associated with that sex.","cost":0.0006408,"response_parsed":"SELECT Sex, MAX(Major) AS Max_Major\nFROM Student\nGROUP BY Sex;","time":7.1649737358}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Sex`, AVG(`Major`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the avg of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average `Major` for each `Sex` in the `Student` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Sex,\n AVG(Major) AS Average_Major\nFROM \n Student\nGROUP BY \n Sex;\n```\n\nThis query will:\n1. Group all students by their `Sex`.\n2. Calculate the average `Major` for each group.\n3. Return the results with the `Sex` and the corresponding average `Major`.","cost":0.0004887,"response_parsed":"SELECT \n Sex,\n AVG(Major) AS Average_Major\nFROM \n Student\nGROUP BY \n Sex;","time":5.4964365959}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Sex`, SUM(`Major`) FROM `Student` GROUP BY `Sex`","question":"For each Sex, find the sum of Major in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of the `Major` column for each unique value in the `Sex` column of the `Student` table. This can be achieved using the SQL `SUM()` function combined with the `GROUP BY` clause.\n\n```sql\nSELECT \n Sex,\n SUM(Major) AS Total_Major\nFROM \n Student\nGROUP BY \n Sex;\n```","cost":0.000441,"response_parsed":"SELECT \n Sex,\n SUM(Major) AS Total_Major\nFROM \n Student\nGROUP BY \n Sex;","time":4.5880732536}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING count(*) >= 1","question":"Find all the PetType that have at least 1 records in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all unique `PetType` values that have at least one record in the `Pets` table, you can use the `DISTINCT` keyword in SQL. This will return each unique `PetType` exactly once, ensuring that each type with at least one record is included.\n\n```sql\nSELECT DISTINCT PetType FROM Pets;\n```","cost":0.0004275,"response_parsed":"SELECT DISTINCT PetType FROM Pets;","time":4.1642405987}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING count(*) <= 1","question":"Find all the PetType that have at most 1 records in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all `PetType`s that have at most 1 record in the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Groups the rows in the `Pets` table by the `PetType` column.\n2. Counts the number of records in each group using `COUNT(*)`.\n3. Filters the results to include only those groups with a count of 1 or less using `HAVING COUNT(*) <= 1`.\n\nThe result will be a list of `PetType`s that appear at most once in the `Pets` table.","cost":0.0005922,"response_parsed":"SELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING COUNT(*) <= 1;","time":6.1179065704}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING AVG(`pet_age`) >= 2.25","question":"List the PetType which average of pet_age is at least 2.25 in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetType(s) where the average `pet_age` is at least 2.25, you can use the SQL `AVG()` function along with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING AVG(pet_age) >= 2.25;\n```\n\nThis query will:\n1. Group the rows in the `Pets` table by the `PetType` column.\n2. Calculate the average `pet_age` for each group.\n3. Return only those `PetType` values where the average `pet_age` is at least 2.25.","cost":0.0005562,"response_parsed":"SELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING AVG(pet_age) >= 2.25;","time":6.2453327179}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING AVG(`pet_age`) <= 2.25","question":"List the PetType which average of pet_age is at most 2.25 in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetType where the average of `pet_age` is at most 2.25, you can use the following SQL query:\n\n```sql\nSELECT PetType, AVG(pet_age) AS avg_pet_age\nFROM Pets\nGROUP BY PetType\nHAVING AVG(pet_age) <= 2.25;\n```\n\nThis query:\n1. Groups the rows in the `Pets` table by `PetType`.\n2. Calculates the average `pet_age` for each group.\n3. Filters the results to include only those groups where the average `pet_age` is less than or equal to 2.25.","cost":0.0005067,"response_parsed":"SELECT PetType, AVG(pet_age) AS avg_pet_age\nFROM Pets\nGROUP BY PetType\nHAVING AVG(pet_age) <= 2.25;","time":4.9079856873}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING SUM(`pet_age`) >= 3.0","question":"List the PetType which summation of pet_age is at least 3.0 in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `pet_age` for each `PetType` in the `Pets` table and then return only those `PetType`s where the sum is at least 3.0.\n\nHere is the SQL code:\n\n```sql\nSELECT PetType, SUM(pet_age) AS total_age\nFROM Pets\nGROUP BY PetType\nHAVING SUM(pet_age) >= 3.0;\n```\n\nThis query:\n1. Groups the rows in the `Pets` table by the `PetType` column.\n2. Calculates the sum of `pet_age` for each group using the `SUM()` function.\n3. Filters the results to include only those groups where the sum of `pet_age` is at least 3.0 using the `HAVING` clause.\n4. Returns the `PetType` and the corresponding sum of `pet_age` for the filtered groups.","cost":0.0006534,"response_parsed":"SELECT PetType, SUM(pet_age) AS total_age\nFROM Pets\nGROUP BY PetType\nHAVING SUM(pet_age) >= 3.0;","time":5.8484649658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `PetType` FROM `Pets` GROUP BY `PetType` HAVING SUM(`pet_age`) <= 3.0","question":"List the PetType which summation of pet_age is at most 3.0 in table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the desired result, we need to calculate the sum of `pet_age` for each `PetType` and then filter those `PetType`s where the sum is at most 3.0. Here's the SQL code to achieve this:\n\n```sql\nSELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING SUM(pet_age) <= 3.0;\n```","cost":0.000459,"response_parsed":"SELECT PetType\nFROM Pets\nGROUP BY PetType\nHAVING SUM(pet_age) <= 3.0;","time":3.6885545254}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING count(*) >= 1","question":"Find all the LName that have at least 1 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all unique last names (`LName`) that have at least one record in the `Student` table, you can use the `DISTINCT` keyword to retrieve each `LName` only once. Here's the SQL query:\n\n```sql\nSELECT DISTINCT LName FROM Student;\n```\n\nThis query will return a list of all unique last names present in the `Student` table.","cost":0.0004842,"response_parsed":"SELECT DISTINCT LName FROM Student;","time":4.5068490505}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING count(*) <= 1","question":"Find all the LName that have at most 1 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all the `LName`s in the `Student` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT LName\nFROM Student\nGROUP BY LName\nHAVING COUNT(StuID) <= 1;\n```\n\nThis query:\n1. Groups the `Student` table by the `LName` column.\n2. Counts the number of records for each `LName` using `COUNT(StuID)`.\n3. Filters the results to include only those `LName`s that have 1 or fewer records.\n\n```sql\nSELECT LName\nFROM Student\nGROUP BY LName\nHAVING COUNT(StuID) <= 1;\n```","cost":0.000504,"response_parsed":"SELECT LName\nFROM Student\nGROUP BY LName\nHAVING COUNT(StuID) <= 1;","time":4.5743994713}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Sex` FROM `Student` GROUP BY `Sex` HAVING count(*) >= 17","question":"Find all the Sex that have at least 17 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all the Sex that have at least 17 records in the `Student` table, you can use the SQL `COUNT()` function along with the `GROUP BY` and `HAVING` clauses. Here's the SQL code:\n\n```sql\nSELECT Sex, COUNT(*) as Count_Sex\nFROM Student\nGROUP BY Sex\nHAVING COUNT(*) >= 17;\n```\n\nThis query will:\n1. Group the `Student` table by the `Sex` column.\n2. Count the number of records for each `Sex`.\n3. Return only those `Sex` values that have at least 17 records.","cost":0.0006219,"response_parsed":"SELECT Sex, COUNT(*) as Count_Sex\nFROM Student\nGROUP BY Sex\nHAVING COUNT(*) >= 17;","time":5.9401855469}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Sex` FROM `Student` GROUP BY `Sex` HAVING count(*) <= 17","question":"Find all the Sex that have at most 17 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all the `Sex` values in the `Student` table that have at most 17 records, you can use the following SQL query:\n\n```sql\nSELECT Sex\nFROM Student\nGROUP BY Sex\nHAVING COUNT(*) <= 17;\n```\n\nThis query:\n1. Groups the `Student` table by the `Sex` column.\n2. Counts the number of records in each group using `COUNT(*)`.\n3. Filters the results to include only those groups with a count of 17 or fewer records using the `HAVING COUNT(*) <= 17` condition.","cost":0.000513,"response_parsed":"SELECT Sex\nFROM Student\nGROUP BY Sex\nHAVING COUNT(*) <= 17;","time":4.4073960781}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING count(*) >= 1","question":"Find all the city_code that have at least 1 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all unique `city_code` values that have at least one record in the `Student` table, you can use the `DISTINCT` keyword in SQL. This will ensure that each `city_code` appears only once in the result set, even if it appears multiple times in the table.\n\nHere is the SQL query to achieve this:\n\n```sql\nSELECT DISTINCT city_code\nFROM Student\nWHERE city_code IS NOT NULL;\n```\n\nThis query will:\n1. Select the `city_code` column from the `Student` table.\n2. Use `DISTINCT` to retrieve only unique `city_code` values.\n3. Include a `WHERE` clause to exclude any `NULL` values, ensuring that only valid `city_code` values are returned.\n\nWhen you execute this query, you will get a list of all unique `city_code` values that have at least one record in the `Student` table.","cost":0.0004797,"response_parsed":"SELECT DISTINCT city_code\nFROM Student\nWHERE city_code IS NOT NULL;","time":3.9321770668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING count(*) <= 1","question":"Find all the city_code that have at most 1 records in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find all `city_code` values in the `Student` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING COUNT(StuID) <= 1;\n```\n\nThis query:\n1. Groups the `Student` table by the `city_code` column.\n2. Counts the number of records (`StuID`) for each `city_code`.\n3. Filters the results to include only those `city_code` values with 1 or fewer records.\n\nThe result will be a list of `city_code` values that meet the criteria.","cost":0.0004905,"response_parsed":"SELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING COUNT(StuID) <= 1;","time":4.1172165871}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING AVG(`Age`) >= 19.71","question":"List the LName which average of Age is at least 19.71 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the last names (`LName`) from the `Student` table where the average age is at least 19.71, you can use the following SQL query:\n\n```sql\nSELECT LName, ROUND(AVG(Age), 2) AS Avg_Age\nFROM Student\nGROUP BY LName\nHAVING AVG(Age) >= 19.71;\n```\n\nThis query:\n1. Selects the `LName` and calculates the average age for each last name.\n2. Groups the results by `LName`.\n3. Filters the results to include only those groups where the average age is at least 19.71.\n4. Rounds the average age to two decimal places for better readability.","cost":0.0005742,"response_parsed":"SELECT LName, ROUND(AVG(Age), 2) AS Avg_Age\nFROM Student\nGROUP BY LName\nHAVING AVG(Age) >= 19.71;","time":4.9500000477}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING AVG(`Age`) <= 19.71","question":"List the LName which average of Age is at most 19.71 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the last names (`LName`) of students where the average age is at most 19.71, you can use the following SQL query:\n\n```sql\nSELECT LName\nFROM Student\nGROUP BY LName\nHAVING AVG(Age) <= 19.71;\n```\n\nThis query:\n1. Groups the students by their last name (`LName`).\n2. Calculates the average age for each group using `AVG(Age)`.\n3. Filters the results to include only those groups where the average age is less than or equal to 19.71.","cost":0.0005553,"response_parsed":"SELECT LName\nFROM Student\nGROUP BY LName\nHAVING AVG(Age) <= 19.71;","time":4.6655886173}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING SUM(`Age`) >= 21.45","question":"List the LName which summation of Age is at least 21.45 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question \"List the LName which summation of Age is at least 21.45 in table Student,\" we need to calculate the sum of the `Age` column for each `LName` and then filter the results to include only those `LName`s where the sum is at least 21.45.\n\nHere is the SQL code to accomplish this:\n\n```sql\nSELECT LName, SUM(Age) AS TotalAge\nFROM Student\nGROUP BY LName\nHAVING SUM(Age) >= 21.45;\n```\n\n### Explanation:\n1. **SELECT LName, SUM(Age) AS TotalAge**: This selects the `LName` and calculates the sum of the `Age` for each group of `LName`. The `AS TotalAge` renames the sum column to `TotalAge` for clarity.\n2. **FROM Student**: Specifies the table to query, which is the `Student` table.\n3. **GROUP BY LName**: Groups the rows by the `LName` column, allowing us to aggregate the `Age` values for each `LName`.\n4. **HAVING SUM(Age) >= 21.45**: Filters the grouped results to include only those groups where the sum of `Age` is at least 21.45.\n\nThis query will return a list of `LName`s along with their corresponding total ages, but only for those `LName`s where the total age is 21.45 or higher.","cost":0.0008109,"response_parsed":"SELECT LName, SUM(Age) AS TotalAge\nFROM Student\nGROUP BY LName\nHAVING SUM(Age) >= 21.45;","time":7.4010250568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING SUM(`Age`) <= 21.45","question":"List the LName which summation of Age is at most 21.45 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo answer the question \"List the LName which summation of Age is at most 21.45 in table Student,\" we need to calculate the sum of ages for each last name and filter those with a sum less than or equal to 21.45.\n\n```sql\nSELECT LName, SUM(Age) AS TotalAge\nFROM Student\nGROUP BY LName\nHAVING SUM(Age) <= 21.45;\n```","cost":0.0005724,"response_parsed":"SELECT LName, SUM(Age) AS TotalAge\nFROM Student\nGROUP BY LName\nHAVING SUM(Age) <= 21.45;","time":4.7348544598}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING AVG(`Age`) >= 19.51","question":"List the city_code which average of Age is at least 19.51 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the city codes where the average age of students is at least 19.51, you can use the following SQL query:\n\n```sql\nSELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING AVG(Age) >= 19.51;\n```\n\nThis query:\n1. Groups the students by their `city_code`.\n2. Calculates the average age for each group using `AVG(Age)`.\n3. Filters the results to include only those groups where the average age is at least 19.51 using `HAVING AVG(Age) >= 19.51`.","cost":0.000531,"response_parsed":"SELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING AVG(Age) >= 19.51;","time":4.2107634544}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING AVG(`Age`) <= 19.51","question":"List the city_code which average of Age is at most 19.51 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the city codes where the average age of students is at most 19.51, you can use the following SQL query:\n\n```sql\nSELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING AVG(Age) <= 19.51;\n```\n\nThis query:\n1. Groups the students by their `city_code`\n2. Calculates the average age for each group using `AVG(Age)`\n3. Filters the results to include only those groups where the average age is less than or equal to 19.51","cost":0.0005166,"response_parsed":"SELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING AVG(Age) <= 19.51;","time":4.2385032177}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING SUM(`Age`) >= 35.0","question":"List the city_code which summation of Age is at least 35.0 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the city codes where the sum of ages is at least 35.0, we can use the following SQL query:\n\n```sql\nSELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING SUM(Age) >= 35.0;\n```\n\nThis query groups the students by their `city_code` and then filters the groups where the sum of the `Age` column is at least 35.0.","cost":0.0006237,"response_parsed":"SELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING SUM(Age) >= 35.0;","time":5.2358829975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `city_code` FROM `Student` GROUP BY `city_code` HAVING SUM(`Age`) <= 35.0","question":"List the city_code which summation of Age is at most 35.0 in table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the city codes where the sum of the ages of students is at most 35.0, you can use the following SQL query:\n\n```sql\nSELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING SUM(Age) <= 35.0;\n```\n\nThis query:\n1. Groups the rows in the `Student` table by the `city_code` column.\n2. Calculates the sum of the `Age` column for each group.\n3. Filters the results to include only those groups where the sum of ages is less than or equal to 35.0.","cost":0.0005418,"response_parsed":"SELECT city_code\nFROM Student\nGROUP BY city_code\nHAVING SUM(Age) <= 35.0;","time":4.6156492233}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `Has_Pet` AS T1 JOIN `Student` AS T2 ON T1.`StuID` = T2.`StuID`","question":"Join all the records from table Has_Pet with table Student on StuID","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo join all records from the `Has_Pet` table with the `Student` table based on the `StuID` column, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nINNER JOIN Has_Pet\nON Student.StuID = Has_Pet.StuID;\n```\n\nThis SQL code performs an `INNER JOIN` between the `Student` and `Has_Pet` tables on the `StuID` column, which is common to both tables. The result will include all records where there is a match in both tables.","cost":0.0005994,"response_parsed":"SELECT *\nFROM Student\nINNER JOIN Has_Pet\nON Student.StuID = Has_Pet.StuID;","time":5.3725829124}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `Has_Pet` AS T1 JOIN `Pets` AS T2 ON T1.`PetID` = T2.`PetID`","question":"Join all the records from table Has_Pet with table Pets on PetID","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo join all records from the `Has_Pet` table with the `Pets` table based on the `PetID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Has_Pet\nINNER JOIN Pets\nON Has_Pet.PetID = Pets.PetID;\n```\n\nThis query will return all columns (`*`) from both tables where the `PetID` matches in both `Has_Pet` and `Pets` tables.","cost":0.00054,"response_parsed":"SELECT *\nFROM Has_Pet\nINNER JOIN Pets\nON Has_Pet.PetID = Pets.PetID;","time":4.4363996983}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `LName` FROM `Student` GROUP BY `LName` HAVING COUNT(DISTINCT `Sex`) = (SELECT COUNT(DISTINCT `Sex`) FROM `Student`)","question":"What are the LName with all the Sex in table Student?","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the last names (LName) along with the sex of each student from the Student table, you can use the following SQL query:\n\n```sql\nSELECT LName, Sex FROM Student;\n```\n\nThis query selects the LName and Sex columns from the Student table and returns all the rows, providing the desired information.","cost":0.0006462,"response_parsed":"SELECT LName, Sex FROM Student;","time":5.7849969864}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Has_Pet` ORDER BY `StuID` ASC","question":"Show all data ordered by StuID in ascending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Has_Pet` table ordered by `StuID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Has_Pet\nORDER BY StuID ASC;\n```","cost":0.0004995,"response_parsed":"SELECT *\nFROM Has_Pet\nORDER BY StuID ASC;","time":4.0918078423}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Has_Pet` ORDER BY `StuID` DESC","question":"Show all data ordered by StuID in descending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Has_Pet` table ordered by `StuID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Has_Pet\nORDER BY StuID DESC;\n```","cost":0.0004023,"response_parsed":"SELECT *\nFROM Has_Pet\nORDER BY StuID DESC;","time":2.9736144543}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Has_Pet` ORDER BY `PetID` ASC","question":"Show all data ordered by PetID in ascending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Has_Pet` table ordered by `PetID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Has_Pet\nORDER BY PetID ASC;\n```","cost":0.0004509,"response_parsed":"SELECT *\nFROM Has_Pet\nORDER BY PetID ASC;","time":3.4282119274}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Has_Pet` ORDER BY `PetID` DESC","question":"Show all data ordered by PetID in descending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Has_Pet` table ordered by `PetID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Has_Pet\nORDER BY PetID DESC;\n```\n\nThis query will return all rows from the `Has_Pet` table, sorted by the `PetID` column in descending order.","cost":0.0004464,"response_parsed":"SELECT *\nFROM Has_Pet\nORDER BY PetID DESC;","time":3.3548159599}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `StuID` FROM `Has_Pet` ORDER BY `StuID` ASC","question":"Project the StuID ordered in ascending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `StuID` from the `Has_Pet` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT StuID FROM Has_Pet ORDER BY StuID ASC;\n```","cost":0.0005886,"response_parsed":"SELECT StuID FROM Has_Pet ORDER BY StuID ASC;","time":4.9361329079}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `StuID` FROM `Has_Pet` ORDER BY `StuID` DESC","question":"Project the StuID ordered in descending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `StuID` from the `Has_Pet` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT StuID \nFROM Has_Pet \nORDER BY StuID DESC;\n```","cost":0.0004941,"response_parsed":"SELECT StuID \nFROM Has_Pet \nORDER BY StuID DESC;","time":3.9831113815}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `PetID` FROM `Has_Pet` ORDER BY `PetID` ASC","question":"Project the PetID ordered in ascending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetID from the Has_Pet table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT PetID FROM Has_Pet ORDER BY PetID ASC;\n```","cost":0.0004878,"response_parsed":"SELECT PetID FROM Has_Pet ORDER BY PetID ASC;","time":4.1289050579}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `PetID` FROM `Has_Pet` ORDER BY `PetID` DESC","question":"Project the PetID ordered in descending order for the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetID from the Has_Pet table in descending order, you can use the following SQL query:\n\n```sql\nSELECT PetID \nFROM Has_Pet \nORDER BY PetID DESC;\n```","cost":0.0004905,"response_parsed":"SELECT PetID \nFROM Has_Pet \nORDER BY PetID DESC;","time":3.9467041492}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Pets` ORDER BY `PetType` ASC","question":"Show all data ordered by PetType in ascending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Pets` table ordered by `PetType` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM Pets ORDER BY PetType ASC;\n```","cost":0.0004086,"response_parsed":"SELECT * FROM Pets ORDER BY PetType ASC;","time":3.2090013027}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Pets` ORDER BY `PetType` DESC","question":"Show all data ordered by PetType in descending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Pets` table ordered by `PetType` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nORDER BY PetType DESC;\n```","cost":0.0003753,"response_parsed":"SELECT *\nFROM Pets\nORDER BY PetType DESC;","time":2.6303625107}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Pets` ORDER BY `PetID` ASC","question":"Show all data ordered by PetID in ascending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Pets` table ordered by `PetID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nORDER BY PetID ASC;\n```\n\nThis query will return all records from the `Pets` table sorted by the `PetID` column in ascending order.","cost":0.0004653,"response_parsed":"SELECT *\nFROM Pets\nORDER BY PetID ASC;","time":3.7949998379}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Pets` ORDER BY `PetID` DESC","question":"Show all data ordered by PetID in descending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Pets` table ordered by `PetID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nORDER BY PetID DESC;\n```","cost":0.0003924,"response_parsed":"SELECT *\nFROM Pets\nORDER BY PetID DESC;","time":2.9004607201}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `pet_age` FROM `Pets` ORDER BY `pet_age` ASC","question":"Project the pet_age ordered in ascending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `pet_age` from the `Pets` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT pet_age\nFROM Pets\nORDER BY pet_age ASC;\n```","cost":0.0005292,"response_parsed":"SELECT pet_age\nFROM Pets\nORDER BY pet_age ASC;","time":4.5117192268}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `pet_age` FROM `Pets` ORDER BY `pet_age` DESC","question":"Project the pet_age ordered in descending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo project the `pet_age` from the `Pets` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT pet_age\nFROM Pets\nORDER BY pet_age DESC;\n```","cost":0.0004311,"response_parsed":"SELECT pet_age\nFROM Pets\nORDER BY pet_age DESC;","time":3.7418086529}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `PetID` FROM `Pets` ORDER BY `PetID` ASC","question":"Project the PetID ordered in ascending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetID from the Pets table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT PetID \nFROM Pets \nORDER BY PetID ASC;\n```","cost":0.0004302,"response_parsed":"SELECT PetID \nFROM Pets \nORDER BY PetID ASC;","time":3.4095592499}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `PetID` FROM `Pets` ORDER BY `PetID` DESC","question":"Project the PetID ordered in descending order for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the PetID from the Pets table in descending order, you can use the following SQL query:\n\n```sql\nSELECT PetID\nFROM Pets\nORDER BY PetID DESC;\n```","cost":0.0004995,"response_parsed":"SELECT PetID\nFROM Pets\nORDER BY PetID DESC;","time":4.2076821327}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Student` ORDER BY `Age` ASC","question":"Show all data ordered by Age in ascending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Student` table ordered by `Age` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nORDER BY Age ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Student` table.\n2. Order the results by the `Age` column in ascending order (from youngest to oldest).","cost":0.0004284,"response_parsed":"SELECT *\nFROM Student\nORDER BY Age ASC;","time":3.351770401}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Student` ORDER BY `Age` DESC","question":"Show all data ordered by Age in descending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Student` table ordered by `Age` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM Student ORDER BY Age DESC;\n```","cost":0.0004491,"response_parsed":"SELECT * FROM Student ORDER BY Age DESC;","time":3.6724936962}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Student` ORDER BY `city_code` ASC","question":"Show all data ordered by city_code in ascending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Student` table ordered by `city_code` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nORDER BY city_code ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Student` table\n2. Order the results by the `city_code` column in ascending order (from A to Z or lowest to highest value)","cost":0.0004716,"response_parsed":"SELECT *\nFROM Student\nORDER BY city_code ASC;","time":3.9540116787}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Student` ORDER BY `city_code` DESC","question":"Show all data ordered by city_code in descending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all data from the `Student` table ordered by `city_code` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nORDER BY city_code DESC;\n```","cost":0.0004149,"response_parsed":"SELECT *\nFROM Student\nORDER BY city_code DESC;","time":3.3868973255}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Sex` FROM `Student` ORDER BY `Sex` ASC","question":"Project the Sex ordered in ascending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo project the `Sex` column from the `Student` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Sex\nFROM Student\nORDER BY Sex ASC;\n```","cost":0.0003564,"response_parsed":"SELECT Sex\nFROM Student\nORDER BY Sex ASC;","time":2.865152359}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Sex` FROM `Student` ORDER BY `Sex` DESC","question":"Project the Sex ordered in descending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo project the `Sex` column from the `Student` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Sex\nFROM Student\nORDER BY Sex DESC;\n```\n\nThis query will:\n1. Select the `Sex` column from the `Student` table\n2. Order the results in descending order based on the `Sex` column","cost":0.0004932,"response_parsed":"SELECT Sex\nFROM Student\nORDER BY Sex DESC;","time":4.5417506695}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Major` FROM `Student` ORDER BY `Major` ASC","question":"Project the Major ordered in ascending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo project the `Major` column from the `Student` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Major\nFROM Student\nORDER BY Major ASC;\n```\n\nThis query will:\n1. Select the `Major` column from the `Student` table.\n2. Order the results in ascending order based on the `Major` values.","cost":0.0003942,"response_parsed":"SELECT Major\nFROM Student\nORDER BY Major ASC;","time":3.2070479393}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Major` FROM `Student` ORDER BY `Major` DESC","question":"Project the Major ordered in descending order for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo project the `Major` from the `Student` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Major \nFROM Student \nORDER BY Major DESC;\n```","cost":0.000468,"response_parsed":"SELECT Major \nFROM Student \nORDER BY Major DESC;","time":3.8809969425}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `StuID` FROM `Has_Pet`","question":"Show all StuID in the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `StuID` from the `Has_Pet` table, you can use the following SQL query:\n\n```sql\nSELECT StuID FROM Has_Pet;\n```","cost":0.0004707,"response_parsed":"SELECT StuID FROM Has_Pet;","time":3.7349882126}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `PetID` FROM `Has_Pet`","question":"Show all PetID in the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `PetID` from the `Has_Pet` table, you can use the following SQL query:\n\n```sql\nSELECT PetID FROM Has_Pet;\n```","cost":0.0005013,"response_parsed":"SELECT PetID FROM Has_Pet;","time":4.3649823666}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Has_Pet`","question":"Show all the rows in the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show all the rows in the `Has_Pet` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Has_Pet;\n```\n\nThis query will return all columns (`StuID` and `PetID`) for every row in the `Has_Pet` table.","cost":0.0005031,"response_parsed":"SELECT * FROM Has_Pet;","time":4.1545972824}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Has_Pet","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `StuID` FROM `Has_Pet`","question":"Show all StuID in the table Has_Pet","db_schema_normalized":"`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `StuID` from the `Has_Pet` table, you can use the following SQL query:\n\n```sql\nSELECT StuID FROM Has_Pet;\n```\n\nThis query will return all the `StuID` values present in the `Has_Pet` table.","cost":0.0005463,"response_parsed":"SELECT StuID FROM Has_Pet;","time":4.8513185978}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `PetID` FROM `Pets`","question":"Show all PetID in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `PetID` from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetID FROM Pets;\n```","cost":0.0003447,"response_parsed":"SELECT PetID FROM Pets;","time":2.690009594}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `PetType` FROM `Pets`","question":"Show all PetType in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `PetType` entries from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetType FROM Pets;\n```\n\nThis query will return all the records in the `PetType` column of your `Pets` table.","cost":0.0004374,"response_parsed":"SELECT PetType FROM Pets;","time":3.8700866699}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `pet_age` FROM `Pets`","question":"Show all pet_age in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `pet_age` from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT pet_age FROM Pets;\n```","cost":0.0003663,"response_parsed":"SELECT pet_age FROM Pets;","time":2.9978609085}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `weight` FROM `Pets`","question":"Show all weight in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all the weights from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT weight FROM Pets;\n```\n\nThis query will return all the values in the `weight` column of your `Pets` table.","cost":0.0005238,"response_parsed":"SELECT weight FROM Pets;","time":4.6985323429}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Pets`","question":"Show all the rows in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show all the rows in the `Pets` table, you can use the `SELECT` statement with the wildcard `*` to fetch all columns. Here's the SQL code:\n\n```sql\nSELECT * FROM Pets;\n```","cost":0.0004608,"response_parsed":"SELECT * FROM Pets;","time":3.8752419949}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `PetID` FROM `Pets`","question":"Show all PetID in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `PetID` from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetID FROM Pets;\n```","cost":0.0003447,"response_parsed":"SELECT PetID FROM Pets;","time":2.6612384319}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `PetType`, `PetID` FROM `Pets`","question":"Show all PetType, PetID in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `PetType` and `PetID` from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetType, PetID FROM Pets;\n```\n\nThis query will return all rows in the `Pets` table, displaying only the `PetType` and `PetID` columns.","cost":0.0004491,"response_parsed":"SELECT PetType, PetID FROM Pets;","time":3.546343565}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `PetType`, `pet_age`, `PetID` FROM `Pets`","question":"Show all PetType, pet_age, PetID in the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `PetType`, `pet_age`, and `PetID` from the `Pets` table, you can use the following SQL query:\n\n```sql\nSELECT PetID, PetType, pet_age FROM Pets;\n```","cost":0.0003834,"response_parsed":"SELECT PetID, PetType, pet_age FROM Pets;","time":2.9555163383}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Sex` FROM `Student`","question":"Show all Sex in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all unique values in the `Sex` column from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Sex FROM Student;\n```\n\nThis query will return all unique values in the `Sex` column of your `Student` table.","cost":0.0004221,"response_parsed":"SELECT DISTINCT Sex FROM Student;","time":3.498152256}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `city_code` FROM `Student`","question":"Show all city_code in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `city_code` values from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT city_code FROM Student;\n```\n\nThis query will return all the entries in the `city_code` column of your `Student` table.","cost":0.0004824,"response_parsed":"SELECT city_code FROM Student;","time":3.8982400894}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `LName` FROM `Student`","question":"Show all LName in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `LName` from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT LName FROM Student;\n```\n\nThis query will return all the last names of students stored in the `Student` table.","cost":0.0004329,"response_parsed":"SELECT LName FROM Student;","time":3.709751606}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `StuID` FROM `Student`","question":"Show all StuID in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all `StuID` from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT StuID FROM Student;\n```\n\nThis query will return a list of all `StuID` values present in the `Student` table.","cost":0.0004923,"response_parsed":"SELECT StuID FROM Student;","time":4.1437921524}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Major` FROM `Student`","question":"Show all Major in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all the majors from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT Major FROM Student;\n```\n\nThis query will return all the values in the `Major` column of the `Student` table.","cost":0.000522,"response_parsed":"SELECT Major FROM Student;","time":4.485585928}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Student`","question":"Show all the rows in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo show all the rows in the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Student;\n```\n\nThis query will return all columns (`*`) for every row in the `Student` table.","cost":0.0004554,"response_parsed":"SELECT * FROM Student;","time":4.2147853374}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Major` FROM `Student`","question":"Show all Major in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch all the majors from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT Major FROM Student;\n```\n\nThis query will return all the values in the `Major` column of the `Student` table.","cost":0.0004599,"response_parsed":"SELECT Major FROM Student;","time":4.2940387726}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `city_code`, `Age` FROM `Student`","question":"Show all city_code, Age in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `city_code` and `Age` from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT city_code, Age FROM Student;\n```","cost":0.0004392,"response_parsed":"SELECT city_code, Age FROM Student;","time":3.1809332371}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Sex`, `Major`, `Age` FROM `Student`","question":"Show all Sex, Major, Age in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the `Sex`, `Major`, and `Age` columns from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT Sex, Major, Age FROM Student;\n```","cost":0.0004059,"response_parsed":"SELECT Sex, Major, Age FROM Student;","time":2.9092955589}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `LName`, `Sex`, `city_code`, `StuID` FROM `Student`","question":"Show all LName, Sex, city_code, StuID in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the required information from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT LName, Sex, city_code, StuID FROM Student;\n```\n\nThis query will return all rows in the `Student` table with the columns `LName`, `Sex`, `city_code`, and `StuID`.","cost":0.0005742,"response_parsed":"SELECT LName, Sex, city_code, StuID FROM Student;","time":4.9701297283}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Advisor`, `LName`, `Major`, `StuID`, `Sex` FROM `Student`","question":"Show all Advisor, LName, Major, StuID, Sex in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the specified columns from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT Advisor, LName, Major, StuID, Sex FROM Student;\n```","cost":0.000468,"response_parsed":"SELECT Advisor, LName, Major, StuID, Sex FROM Student;","time":3.9831843376}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `city_code`, `LName`, `Age`, `Sex`, `Fname`, `Major` FROM `Student`","question":"Show all city_code, LName, Age, Sex, Fname, Major in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the required information from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT city_code, LName, Age, Sex, Fname, Major FROM Student;\n```\n\nThis query will return all the records from the `Student` table with the specified columns: `city_code`, `LName`, `Age`, `Sex`, `Fname`, and `Major`.","cost":0.0005544,"response_parsed":"SELECT city_code, LName, Age, Sex, Fname, Major FROM Student;","time":4.4598209858}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Major`, `city_code`, `LName`, `Sex`, `Advisor`, `Fname`, `StuID` FROM `Student`","question":"Show all Major, city_code, LName, Sex, Advisor, Fname, StuID in the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the specified columns from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT Major, city_code, LName, Sex, Advisor, Fname, StuID\nFROM Student;\n```\n\nThis query will return all the rows from the `Student` table with the columns `Major`, `city_code`, `LName`, `Sex`, `Advisor`, `Fname`, and `StuID`.","cost":0.0005355,"response_parsed":"SELECT Major, city_code, LName, Sex, Advisor, Fname, StuID\nFROM Student;","time":4.7456972599}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Pets` WHERE `PetType` == 'cat'","question":"Show the data of the table Pets where PetType is equal to cat","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where `PetType` is 'cat', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE PetType = 'cat';\n```","cost":0.0004437,"response_parsed":"SELECT *\nFROM Pets\nWHERE PetType = 'cat';","time":3.7715027332}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Pets` WHERE `PetType` != 'dog'","question":"Show the data of the table Pets where PetType is different from dog","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where the `PetType` is different from \"dog,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE PetType <> 'dog';\n```\n\nThis query will return all rows from the `Pets` table where the `PetType` is not \"dog.\"","cost":0.0004977,"response_parsed":"SELECT *\nFROM Pets\nWHERE PetType <> 'dog';","time":4.3267514706}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Pets` WHERE `PetType` != 'cat'","question":"Show the data of the table Pets where PetType not equal to cat","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where `PetType` is not equal to 'cat', you can use the following SQL query:\n\n```sql\nSELECT PetID, PetType, pet_age, weight \nFROM Pets \nWHERE PetType != 'cat';\n```","cost":0.0004392,"response_parsed":"SELECT PetID, PetType, pet_age, weight \nFROM Pets \nWHERE PetType != 'cat';","time":3.6625692844}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Pets` WHERE `pet_age` > 2","question":"Show the data of the table Pets where pet_age is greater than 2","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where `pet_age` is greater than 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE pet_age > 2;\n```","cost":0.0004239,"response_parsed":"SELECT *\nFROM Pets\nWHERE pet_age > 2;","time":3.8271951675}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Pets` WHERE `pet_age` < 2","question":"Show the data of the table Pets where pet_age is less than 2","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where `pet_age` is less than 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE pet_age < 2;\n```","cost":0.0004284,"response_parsed":"SELECT *\nFROM Pets\nWHERE pet_age < 2;","time":3.2484939098}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Pets` WHERE `weight` > 9.3","question":"Show the data of the table Pets where weight is greater than 9.3","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where the weight is greater than 9.3, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE weight > 9.3;\n```","cost":0.0004743,"response_parsed":"SELECT *\nFROM Pets\nWHERE weight > 9.3;","time":3.6369462013}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Pets` WHERE `weight` < 12.0","question":"Show the data of the table Pets where weight is less than 12.0","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Pets` table where the weight is less than 12.0, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Pets\nWHERE weight < 12.0;\n```","cost":0.0004302,"response_parsed":"SELECT *\nFROM Pets\nWHERE weight < 12.0;","time":3.7684912682}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Fname` == 'Dinesh'","question":"Show the data of the table Student where Fname is equal to Dinesh","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the first name (Fname) is \"Dinesh,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Fname = 'Dinesh';\n```","cost":0.0004635,"response_parsed":"SELECT *\nFROM Student\nWHERE Fname = 'Dinesh';","time":3.5174911022}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Fname` != 'Linda'","question":"Show the data of the table Student where Fname is different from Linda","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the first name (Fname) is different from \"Linda,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Fname <> 'Linda';\n```\n\nThis query will return all rows from the `Student` table where the `Fname` column does not contain the value \"Linda.\"","cost":0.0005436,"response_parsed":"SELECT *\nFROM Student\nWHERE Fname <> 'Linda';","time":4.5177733898}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Fname` != 'Paul'","question":"Show the data of the table Student where Fname not equal to Paul","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students whose first name is not \"Paul,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Fname != 'Paul';\n```","cost":0.0004698,"response_parsed":"SELECT *\nFROM Student\nWHERE Fname != 'Paul';","time":3.5910458565}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `LName` == 'Smith'","question":"Show the data of the table Student where LName is equal to Smith","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the last name is Smith, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE LName = 'Smith';\n```","cost":0.0004095,"response_parsed":"SELECT *\nFROM Student\nWHERE LName = 'Smith';","time":3.4575583935}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `LName` != 'Jones'","question":"Show the data of the table Student where LName is different from Jones","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students whose last name is not \"Jones\" from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE LName <> 'Jones';\n```\n\nThis query will return all rows from the `Student` table where the `LName` (last name) is different from \"Jones\".","cost":0.0005751,"response_parsed":"SELECT *\nFROM Student\nWHERE LName <> 'Jones';","time":4.7553331852}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `LName` != 'Jones'","question":"Show the data of the table Student where LName not equal to Jones","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students whose last name is not \"Jones\" from the `Student` table, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE LName <> 'Jones';\n```\n\nThis query will return all rows from the `Student` table where the `LName` (last name) is not equal to \"Jones\".","cost":0.0004707,"response_parsed":"SELECT *\nFROM Student\nWHERE LName <> 'Jones';","time":3.5486600399}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Sex` == 'M'","question":"Show the data of the table Student where Sex is equal to M","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the sex is 'M', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Sex = 'M';\n```","cost":0.0004167,"response_parsed":"SELECT *\nFROM Student\nWHERE Sex = 'M';","time":3.117513895}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Sex` != 'M'","question":"Show the data of the table Student where Sex is different from M","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the sex is different from 'M', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Sex <> 'M';\n```\n\nThis query will return all records from the `Student` table where the `Sex` column is not 'M'.","cost":0.000594,"response_parsed":"SELECT *\nFROM Student\nWHERE Sex <> 'M';","time":5.1013600826}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Student` WHERE `Sex` != 'F'","question":"Show the data of the table Student where Sex not equal to F","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the sex is not equal to 'F', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Sex != 'F';\n```","cost":0.0004617,"response_parsed":"SELECT *\nFROM Student\nWHERE Sex != 'F';","time":3.5306184292}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Student` WHERE `Age` > 26","question":"Show the data of the table Student where Age is greater than 26","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the age is greater than 26, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Age > 26;\n```","cost":0.0004626,"response_parsed":"SELECT *\nFROM Student\nWHERE Age > 26;","time":3.5464894772}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Student` WHERE `Age` < 20","question":"Show the data of the table Student where Age is less than 20","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the age is less than 20, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Age < 20;\n```","cost":0.0004662,"response_parsed":"SELECT *\nFROM Student\nWHERE Age < 20;","time":4.0519711971}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Student` WHERE `Advisor` > 8423","question":"Show the data of the table Student where Advisor is greater than 8423","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data of students where the Advisor is greater than 8423, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Advisor > 8423;\n```","cost":0.000432,"response_parsed":"SELECT *\nFROM Student\nWHERE Advisor > 8423;","time":3.3069658279}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Student` WHERE `Major` < 600","question":"Show the data of the table Student where Major is less than 600","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo fetch the data from the `Student` table where the `Major` is less than 600, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Student\nWHERE Major < 600;\n```","cost":0.0004815,"response_parsed":"SELECT *\nFROM Student\nWHERE Major < 600;","time":3.8122766018}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `PetType`) FROM `Pets`","question":"How many different PetType are in table Pets?","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo determine how many different `PetType` are in the `Pets` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT PetType) FROM Pets;\n```","cost":0.0004734,"response_parsed":"SELECT COUNT(DISTINCT PetType) FROM Pets;","time":3.7132370472}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`pet_age`) FROM `Pets`","question":"Find the maximum pet_age for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum `pet_age` for the table `Pets`, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(pet_age) AS max_age FROM Pets;\n```\n\nThis query will return the maximum value in the `pet_age` column of the `Pets` table.","cost":0.0005598,"response_parsed":"SELECT MAX(pet_age) AS max_age FROM Pets;","time":4.6363515854}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`pet_age`) FROM `Pets`","question":"Find the minimum pet_age for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum `pet_age` in the `Pets` table, you can use the SQL `MIN()` function. Here is the SQL code:\n\n```sql\nSELECT MIN(pet_age) FROM Pets;\n```","cost":0.0006057,"response_parsed":"SELECT MIN(pet_age) FROM Pets;","time":5.1855239868}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`pet_age`) FROM `Pets`","question":"Find the average pet_age for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average `pet_age` for the table `Pets`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(pet_age) AS avg_pet_age FROM Pets;\n```\n\nThis query will calculate the average value of the `pet_age` column in the `Pets` table and return it under the alias `avg_pet_age`.","cost":0.0004644,"response_parsed":"SELECT AVG(pet_age) AS avg_pet_age FROM Pets;","time":3.6551063061}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`weight`) FROM `Pets`","question":"Find the maximum weight for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum weight for the table `Pets`, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(weight) AS MaxWeight\nFROM Pets;\n```\n\nThis query will return the maximum weight value from the `weight` column in the `Pets` table.","cost":0.0004302,"response_parsed":"SELECT MAX(weight) AS MaxWeight\nFROM Pets;","time":3.2766287327}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`weight`) FROM `Pets`","question":"Find the minimum weight for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum weight for the table `Pets`, you can use the SQL `MIN()` function on the `weight` column. Here is the SQL code:\n\n```sql\nSELECT MIN(weight) AS minimum_weight\nFROM Pets;\n```\n\nThis query will return the smallest value in the `weight` column of the `Pets` table.","cost":0.000549,"response_parsed":"SELECT MIN(weight) AS minimum_weight\nFROM Pets;","time":4.6578845978}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Pets","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`weight`) FROM `Pets`","question":"Find the average weight for the table Pets","db_schema_normalized":"`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average weight for the table `Pets`, you can use the SQL `AVG()` function on the `weight` column. Here's the SQL code:\n\n```sql\nSELECT AVG(weight) AS AverageWeight\nFROM Pets;\n```\n\nThis query will calculate and return the average weight of all pets in the `Pets` table. The `AS AverageWeight` part is optional and is used to give an alias to the resulting column for better readability.","cost":0.0005085,"response_parsed":"SELECT AVG(weight) AS AverageWeight\nFROM Pets;","time":4.1114401817}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `LName`) FROM `Student`","question":"How many different LName are in table Student?","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo determine how many different last names (`LName`) are in the `Student` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in a column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT LName) FROM Student;\n```","cost":0.0005436,"response_parsed":"SELECT COUNT(DISTINCT LName) FROM Student;","time":4.4901342392}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Fname`) FROM `Student`","question":"How many different Fname are in table Student?","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo determine how many different first names (`Fname`) are in the `Student` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Fname) AS NumberOfUniqueFnames\nFROM Student;\n```\n\n### Explanation:\n- `COUNT(DISTINCT Fname)`: This function counts the number of unique values in the `Fname` column.\n- `AS NumberOfUniqueFnames`: This renames the resulting column to `NumberOfUniqueFnames` for clarity.\n- `FROM Student`: This specifies the table from which to retrieve the data.","cost":0.0005823,"response_parsed":"SELECT COUNT(DISTINCT Fname) AS NumberOfUniqueFnames\nFROM Student;","time":5.5806984901}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Sex`) FROM `Student`","question":"How many different Sex are in table Student?","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo determine how many different sexes are present in the `Student` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT Sex) FROM Student;\n```","cost":0.0003798,"response_parsed":"SELECT COUNT(DISTINCT Sex) FROM Student;","time":3.0570189953}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `city_code`) FROM `Student`","question":"How many different city_code are in table Student?","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo determine how many different `city_code` values are present in the `Student` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT city_code) AS NumberOfCityCodes FROM Student;\n```\n\nThis query will return the number of distinct `city_code` values in your `Student` table.","cost":0.000513,"response_parsed":"SELECT COUNT(DISTINCT city_code) AS NumberOfCityCodes FROM Student;","time":4.0849435329}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Major`) FROM `Student`","question":"Find the maximum Major for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum value of the `Major` column in the `Student` table, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(Major) AS MaxMajor\nFROM Student;\n```\n\nThis query will return the highest value in the `Major` column of the `Student` table.","cost":0.0004599,"response_parsed":"SELECT MAX(Major) AS MaxMajor\nFROM Student;","time":3.7609057426}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Major`) FROM `Student`","question":"Find the minimum Major for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Major value in the `Student` table, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Major) FROM Student;\n```","cost":0.0004149,"response_parsed":"SELECT MIN(Major) FROM Student;","time":3.2855470181}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Major`) FROM `Student`","question":"Find the average Major for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average value of the `Major` column in the `Student` table, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Major) FROM Student;\n```\n\nThis query will calculate and return the average value of the `Major` column for all students in the `Student` table.","cost":0.0004554,"response_parsed":"SELECT AVG(Major) FROM Student;","time":3.6524076462}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Advisor`) FROM `Student`","question":"Find the maximum Advisor for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the maximum Advisor for the table `Student`, you can use the SQL `MAX()` function on the `Advisor` column. Here is the SQL code:\n\n```sql\nSELECT MAX(Advisor) AS MaxAdvisor\nFROM Student;\n```\n\nThis query will return the highest value in the `Advisor` column of the `Student` table.","cost":0.0004491,"response_parsed":"SELECT MAX(Advisor) AS MaxAdvisor\nFROM Student;","time":3.6744918823}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Advisor`) FROM `Student`","question":"Find the minimum Advisor for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the minimum Advisor value in the Student table, we can use the SQL `MIN()` function, which retrieves the smallest value in a specified column. Here's how to do it:\n\n```sql\nSELECT MIN(Advisor) FROM Student;\n```","cost":0.0005085,"response_parsed":"SELECT MIN(Advisor) FROM Student;","time":4.087716341}} {"db_path":"QATCH-journal\/spider_data\/test_database\/pets_1\/pets_1.sqlite","db_id":"pets_1","tbl_name":"Student","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Advisor`) FROM `Student`","question":"Find the average Advisor for the table Student","db_schema_normalized":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))","db_schema":"`Student`(StuID INTEGER PRIMARY KEY, LName VARCHAR(12), Fname VARCHAR(12), Age INTEGER, Sex VARCHAR(1), Major INTEGER, Advisor INTEGER, city_code VARCHAR(3))\n`Has_Pet`(StuID INTEGER, PetID INTEGER, FOREIGN KEY(PetID) REFERENCES Pets(PetID), FOREIGN KEY(StuID) REFERENCES Student(StuID))\n`Pets`(PetID INTEGER PRIMARY KEY, PetType VARCHAR(20), pet_age INTEGER, weight REAL)","pred_dict":{"response":"\n\nTo find the average value of the `Advisor` column in the `Student` table, you can use the SQL `AVG()` function. Here's the SQL query:\n\n```sql\nSELECT AVG(Advisor) AS Average_Advisor\nFROM Student;\n```\n\nThis query will return the average value of the `Advisor` column in your `Student` table.","cost":0.0004968,"response_parsed":"SELECT AVG(Advisor) AS Average_Advisor\nFROM Student;","time":3.9358615875}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Maker` FROM `car_makers`","question":"Show the different Maker in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the different makers from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Maker FROM car_makers;\n```\n\nThis query will return a list of all unique maker names in the `car_makers` table.","cost":0.0005031,"response_parsed":"SELECT DISTINCT Maker FROM car_makers;","time":3.0187768936}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `FullName` FROM `car_makers`","question":"Show the different FullName in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the different `FullName` values from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT FullName FROM car_makers;\n```\n\nThis query will return all unique `FullName` values present in the `car_makers` table.","cost":0.0005346,"response_parsed":"SELECT DISTINCT FullName FROM car_makers;","time":3.1806635857}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Country` FROM `car_makers`","question":"Show the different Country in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the different countries from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country \nFROM car_makers;\n```\n\nThis query will return all unique country values present in the `Country` column of the `car_makers` table.","cost":0.0005445,"response_parsed":"SELECT DISTINCT Country \nFROM car_makers;","time":3.6593036652}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `CountryName` FROM `countries`","question":"Show the different CountryName in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the different `CountryName` entries from the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT CountryName FROM countries;\n```\n\nThis query will return all unique country names stored in the `CountryName` column of the `countries` table.","cost":0.0005238,"response_parsed":"SELECT DISTINCT CountryName FROM countries;","time":3.5605328083}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Continent` FROM `continents`","question":"Show the different Continent in the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show the different continents in the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Continent FROM continents;\n```\n\nThis query will return a list of all unique continent names stored in the `Continent` column of the `continents` table.","cost":0.0007677,"response_parsed":"SELECT DISTINCT Continent FROM continents;","time":6.7246289253}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Model` FROM `car_names`","question":"Show the different Model in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show the different models in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Model FROM car_names;\n```\n\nThis query will return all unique model names from the `car_names` table.","cost":0.0005562,"response_parsed":"SELECT DISTINCT Model FROM car_names;","time":3.613950491}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Make` FROM `car_names`","question":"Show the different Make in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the different \"Make\" values from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Make FROM car_names;\n```\n\nThis query will return all unique values in the \"Make\" column of the `car_names` table.","cost":0.0004491,"response_parsed":"SELECT DISTINCT Make FROM car_names;","time":2.3360245228}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Model` FROM `model_list`","question":"Show the different Model in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show the different models in the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Model FROM model_list;\n```\n\nThis query will return all unique model names from the `model_list` table.","cost":0.0005517,"response_parsed":"SELECT DISTINCT Model FROM model_list;","time":3.4742929935}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `MPG` FROM `cars_data`","question":"Show the different MPG in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show the different MPG values in the `cars_data` table, you can use the `SELECT DISTINCT` statement to retrieve unique values from the `MPG` column.\n\n```sql\nSELECT DISTINCT MPG FROM cars_data;\n```","cost":0.0005652,"response_parsed":"SELECT DISTINCT MPG FROM cars_data;","time":3.7661361694}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Horsepower` FROM `cars_data`","question":"Show the different Horsepower in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show the different Horsepower values in the `cars_data` table, you can use the `DISTINCT` keyword in SQL to fetch unique values from the `Horsepower` column.\n\n```sql\nSELECT DISTINCT Horsepower FROM cars_data;\n```","cost":0.0005229,"response_parsed":"SELECT DISTINCT Horsepower FROM cars_data;","time":3.0989437103}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Maker`, COUNT(*) FROM `car_makers` GROUP BY `Maker`","question":"For each Maker, count the number of rows in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each Maker in the `car_makers` table, you can use the SQL `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the Maker.\n\n```sql\nSELECT Maker, COUNT(*) AS NumberOfRows\nFROM car_makers\nGROUP BY Maker;\n```","cost":0.0005697,"response_parsed":"SELECT Maker, COUNT(*) AS NumberOfRows\nFROM car_makers\nGROUP BY Maker;","time":3.7933139801}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `FullName`, COUNT(*) FROM `car_makers` GROUP BY `FullName`","question":"For each FullName, count the number of rows in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each `FullName` in the `car_makers` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT FullName, COUNT(*) AS RowCount\nFROM car_makers\nGROUP BY FullName;\n```\n\nThis query will:\n1. Group all rows in the `car_makers` table by the `FullName` column.\n2. Count the number of rows for each unique `FullName`.\n3. Return a result set with two columns: `FullName` and `RowCount` (the number of rows for each `FullName`).","cost":0.0006957,"response_parsed":"SELECT FullName, COUNT(*) AS RowCount\nFROM car_makers\nGROUP BY FullName;","time":5.2843604088}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Country`, COUNT(*) FROM `car_makers` GROUP BY `Country`","question":"For each Country, count the number of rows in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows in the `car_makers` table for each country, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n `Country`,\n COUNT(*) as NumberOfMakers\nFROM \n `car_makers`\nGROUP BY \n `Country`;\n```\n\nThis query will:\n1. Select the `Country` column and count the number of rows for each country.\n2. Group the results by the `Country` column.\n3. Return a list of countries along with the number of car makers in each country.","cost":0.0007479,"response_parsed":"SELECT \n `Country`,\n COUNT(*) as NumberOfMakers\nFROM \n `car_makers`\nGROUP BY \n `Country`;","time":5.4993481636}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `CountryName`, COUNT(*) FROM `countries` GROUP BY `CountryName`","question":"For each CountryName, count the number of rows in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each `CountryName` in the `countries` table, you can use the `COUNT(*)` function combined with `GROUP BY` to group the results by `CountryName`.\n\n```sql\nSELECT CountryName, COUNT(*) AS NumberOfRows\nFROM countries\nGROUP BY CountryName;\n```","cost":0.0005283,"response_parsed":"SELECT CountryName, COUNT(*) AS NumberOfRows\nFROM countries\nGROUP BY CountryName;","time":3.0375239849}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `CountryName`, MIN(`Continent`) FROM `countries` GROUP BY `CountryName`","question":"For each CountryName, find the min of Continent in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the minimum Continent ID for each CountryName, we can use the following SQL query. This query selects each CountryName along with the minimum Continent ID from the \"countries\" table.\n\n```sql\nSELECT CountryName, MIN(Continent) AS MinContinent\nFROM countries\nGROUP BY CountryName;\n```","cost":0.0012222,"response_parsed":"SELECT CountryName, MIN(Continent) AS MinContinent\nFROM countries\nGROUP BY CountryName;","time":10.8685381413}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `CountryName`, MAX(`Continent`) FROM `countries` GROUP BY `CountryName`","question":"For each CountryName, find the max of Continent in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo retrieve the maximum `Continent` value for each `CountryName` in the `countries` table, we can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT CountryName, MAX(Continent) AS MaxContinent\nFROM countries\nGROUP BY CountryName;\n```\n\nThis query will:\n1. Group the rows in the `countries` table by the `CountryName`.\n2. For each group (each unique `CountryName`), it will find the maximum value of the `Continent` column.\n3. Return a result set with two columns: `CountryName` and `MaxContinent` (the maximum `Continent` value for that country).\n\nIf you want to get the actual continent name instead of the `Continent` ID, you would need to join the `countries` table with the `continents` table:\n\n```sql\nSELECT c.CountryName, cont.Continent\nFROM countries c\nJOIN continents cont ON c.Continent = cont.ContId\nGROUP BY c.CountryName;\n```\n\nThis query will:\n1. Join the `countries` table with the `continents` table based on the `Continent` ID.\n2. Group the rows by `CountryName`.\n3. Return a result set with the `CountryName` and the corresponding `Continent` name.","cost":0.0007173,"response_parsed":"SELECT c.CountryName, cont.Continent\nFROM countries c\nJOIN continents cont ON c.Continent = cont.ContId\nGROUP BY c.CountryName;","time":5.5996513367}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `CountryName`, AVG(`Continent`) FROM `countries` GROUP BY `CountryName`","question":"For each CountryName, find the avg of Continent in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo address the question as interpreted, here is the SQL code that calculates the average of the Continent IDs for each CountryName:\n\n```sql\nSELECT CountryName, AVG(Continent) AS AvgContinent FROM countries GROUP BY CountryName;\n```","cost":0.0010233,"response_parsed":"SELECT CountryName, AVG(Continent) AS AvgContinent FROM countries GROUP BY CountryName;","time":9.2346870899}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `CountryName`, SUM(`Continent`) FROM `countries` GROUP BY `CountryName`","question":"For each CountryName, find the sum of Continent in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question of finding the sum of the `Continent` column for each `CountryName` in the `countries` table, we can use the following SQL query. This query will group the results by `CountryName` and calculate the sum of the `Continent` values for each group.\n\n```sql\nSELECT CountryName, SUM(Continent) AS ContinentSum\nFROM countries\nGROUP BY CountryName;\n```","cost":0.0009747,"response_parsed":"SELECT CountryName, SUM(Continent) AS ContinentSum\nFROM countries\nGROUP BY CountryName;","time":7.9166281223}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Continent`, COUNT(*) FROM `continents` GROUP BY `Continent`","question":"For each Continent, count the number of rows in table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows in the `continents` table for each continent, you can use the `COUNT()` function combined with the `GROUP BY` clause to group the results by the `Continent` column.\n\n```sql\nSELECT \n Continent,\n COUNT(ContId) AS NumberOfRows\nFROM \n continents\nGROUP BY \n Continent;\n```","cost":0.0006525,"response_parsed":"SELECT \n Continent,\n COUNT(ContId) AS NumberOfRows\nFROM \n continents\nGROUP BY \n Continent;","time":4.5907611847}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Model`, COUNT(*) FROM `car_names` GROUP BY `Model`","question":"For each Model, count the number of rows in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each Model in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT \n mn.Model,\n COUNT(mn.MakeId) AS NumberOfRows\nFROM \n car_names mn\nGROUP BY \n mn.Model;\n```\n\nThis query will:\n1. Select the `Model` column from the `car_names` table.\n2. Count the number of rows for each Model using `COUNT(mn.MakeId)`.\n3. Group the results by the `Model` column to provide the count for each unique Model.\n\nThe result will show each Model along with the number of rows associated with it in the `car_names` table.","cost":0.0006471,"response_parsed":"SELECT \n mn.Model,\n COUNT(mn.MakeId) AS NumberOfRows\nFROM \n car_names mn\nGROUP BY \n mn.Model;","time":4.2575912476}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Make`, COUNT(*) FROM `car_names` GROUP BY `Make`","question":"For each Make, count the number of rows in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each `Make` in the `car_names` table, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Make, COUNT(*) AS CountOfMake\nFROM car_names\nGROUP BY Make\nORDER BY Make ASC;\n```\n\nThis query will:\n1. Select the `Make` column\n2. Count the number of rows for each `Make` using `COUNT(*)`\n3. Group the results by the `Make` column\n4. Optionally order the results by `Make` in ascending order\n\nThe result will show each unique `Make` and the number of rows associated with that `Make` in the `car_names` table.","cost":0.0007236,"response_parsed":"SELECT Make, COUNT(*) AS CountOfMake\nFROM car_names\nGROUP BY Make\nORDER BY Make ASC;","time":5.5611050129}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Model`, COUNT(*) FROM `model_list` GROUP BY `Model`","question":"For each Model, count the number of rows in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each Model in the `model_list` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Model, COUNT(*) AS NumberOfRows\nFROM model_list\nGROUP BY Model;\n```\n\nThis query will return each Model along with the number of rows (records) associated with that Model in the `model_list` table.","cost":0.0008136,"response_parsed":"SELECT Model, COUNT(*) AS NumberOfRows\nFROM model_list\nGROUP BY Model;","time":6.8167786598}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Model`, MIN(`Maker`) FROM `model_list` GROUP BY `Model`","question":"For each Model, find the min of Maker in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum value of the `Maker` column for each `Model` in the `model_list` table, you can use the following SQL query. This query will return the minimum `Maker` value for each unique `Model`.\n\n```sql\nSELECT Model, MIN(Maker) as MinMaker\nFROM model_list\nGROUP BY Model;\n```","cost":0.0010863,"response_parsed":"SELECT Model, MIN(Maker) as MinMaker\nFROM model_list\nGROUP BY Model;","time":9.7388262749}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Model`, MAX(`Maker`) FROM `model_list` GROUP BY `Model`","question":"For each Model, find the max of Maker in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum value of the `Maker` column for each `Model` in the `model_list` table, you can use the following SQL query. This query will group the results by the `Model` and compute the maximum `Maker` for each group.\n\n```sql\nSELECT Model, MAX(Maker) as MaxMaker\nFROM model_list\nGROUP BY Model;\n```","cost":0.000738,"response_parsed":"SELECT Model, MAX(Maker) as MaxMaker\nFROM model_list\nGROUP BY Model;","time":5.9094138145}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Model`, AVG(`Maker`) FROM `model_list` GROUP BY `Model`","question":"For each Model, find the avg of Maker in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average of the \"Maker\" column for each \"Model\" in the \"model_list\" table, you can use the following SQL query. This query will group the results by the \"Model\" and calculate the average value of the \"Maker\" for each group.\n\n```sql\nSELECT \n Model,\n AVG(Maker) AS Average_Maker\nFROM \n model_list\nGROUP BY \n Model;\n```","cost":0.0008118,"response_parsed":"SELECT \n Model,\n AVG(Maker) AS Average_Maker\nFROM \n model_list\nGROUP BY \n Model;","time":6.2692093849}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Model`, SUM(`Maker`) FROM `model_list` GROUP BY `Model`","question":"For each Model, find the sum of Maker in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo translate the question \"For each Model, find the sum of Maker in table model_list\" into SQL code, we need to sum the `Maker` column for each `Model` in the `model_list` table. Here's the SQL code:\n\n```sql\nSELECT Model, SUM(Maker) AS SumOfMaker\nFROM model_list\nGROUP BY Model;\n```\n\nThis SQL query will:\n1. Select the `Model` column.\n2. Calculate the sum of the `Maker` column for each `Model`.\n3. Group the results by the `Model` column.\n\nThe result will show the sum of `Maker` values for each `Model` in the `model_list` table.","cost":0.0006561,"response_parsed":"SELECT Model, SUM(Maker) AS SumOfMaker\nFROM model_list\nGROUP BY Model;","time":4.7580215931}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `MPG`, COUNT(*) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, count the number of rows in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each MPG value in the `cars_data` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT MPG, COUNT(*) AS NumberOfRows\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query will:\n1. Select the `MPG` column and count the number of rows for each unique `MPG` value.\n2. Group the results by the `MPG` values.\n3. Return a result set with two columns: `MPG` and `NumberOfRows` (the count of rows for each `MPG`).","cost":0.0007011,"response_parsed":"SELECT MPG, COUNT(*) AS NumberOfRows\nFROM cars_data\nGROUP BY MPG;","time":5.6628630161}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Horsepower`, COUNT(*) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, count the number of rows in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo count the number of rows for each `Horsepower` in the `cars_data` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Horsepower, COUNT(*) AS NumberOfRows\nFROM cars_data\nGROUP BY Horsepower\nORDER BY Horsepower;\n```\n\nThis query will:\n1. Select the `Horsepower` column and count the number of rows for each unique `Horsepower` value.\n2. Group the results by the `Horsepower` column.\n3. Optionally, order the results by the `Horsepower` values for better readability.","cost":0.0007083,"response_parsed":"SELECT Horsepower, COUNT(*) AS NumberOfRows\nFROM cars_data\nGROUP BY Horsepower\nORDER BY Horsepower;","time":5.4827537537}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `MPG`, MIN(`Cylinders`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the min of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum number of cylinders for each MPG value in the `cars_data` table, we can use the SQL `MIN()` function combined with `GROUP BY`. Here's how to do it:\n\n```sql\nSELECT MPG, MIN(Cylinders) AS MinCylinders\nFROM cars_data\nGROUP BY MPG\nORDER BY MPG;\n```\n\nThis query will:\n1. Group all rows in `cars_data` by the `MPG` values.\n2. Calculate the minimum value of `Cylinders` for each group.\n3. Return the results sorted by `MPG`.\n\n```sql\nSELECT MPG, MIN(Cylinders) AS MinCylinders\nFROM cars_data\nGROUP BY MPG\nORDER BY MPG;\n```","cost":0.0009063,"response_parsed":"SELECT MPG, MIN(Cylinders) AS MinCylinders\nFROM cars_data\nGROUP BY MPG\nORDER BY MPG;","time":7.5396461487}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `MPG`, MAX(`Cylinders`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the max of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum number of cylinders for each MPG value in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT MPG, MAX(Cylinders) AS MaxCylinders\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query groups the data by the `MPG` column and calculates the maximum value of `Cylinders` for each group.","cost":0.000657,"response_parsed":"SELECT MPG, MAX(Cylinders) AS MaxCylinders\nFROM cars_data\nGROUP BY MPG;","time":4.2326579094}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `MPG`, AVG(`Cylinders`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the avg of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average number of cylinders for each MPG in the `cars_data` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n MPG,\n AVG(Cylinders) AS \"Average_Cylinders\"\nFROM \n cars_data\nGROUP BY \n MPG;\n```\n\nThis SQL query will:\n1. Select the `MPG` column\n2. Calculate the average of the `Cylinders` column for each `MPG` value\n3. Group the results by the `MPG` values\n4. Return the results with the `MPG` and the corresponding average number of cylinders\n\nThe result will show the average number of cylinders for each distinct `MPG` value in your `cars_data` table.","cost":0.0007596,"response_parsed":"SELECT \n MPG,\n AVG(Cylinders) AS \"Average_Cylinders\"\nFROM \n cars_data\nGROUP BY \n MPG;","time":5.2650361061}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `MPG`, SUM(`Cylinders`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the sum of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo translate the question into SQL code, we need to calculate the sum of `Cylinders` for each unique `MPG` value in the `cars_data` table. Here's the SQL query:\n\n```sql\nSELECT MPG, SUM(Cylinders) AS TotalCylinders\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query:\n1. Selects the `MPG` column and calculates the sum of the `Cylinders` column for each `MPG` value.\n2. Groups the results by the `MPG` values to ensure the sum is calculated for each unique `MPG`.\n3. Uses the `AS` keyword to alias the sum of `Cylinders` as `TotalCylinders` for better readability.","cost":0.0006966,"response_parsed":"SELECT MPG, SUM(Cylinders) AS TotalCylinders\nFROM cars_data\nGROUP BY MPG;","time":4.8010363579}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `MPG`, MIN(`Weight`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the min of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum Weight for each MPG value in the cars_data table, we can use the SQL GROUP BY clause along with the MIN() function. Here's how to do it:\n\n```sql\nSELECT MPG, MIN(Weight) AS min_weight\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query will return each unique MPG value along with the minimum Weight associated with that MPG.","cost":0.0007767,"response_parsed":"SELECT MPG, MIN(Weight) AS min_weight\nFROM cars_data\nGROUP BY MPG;","time":6.6950657368}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `MPG`, MAX(`Weight`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the max of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum Weight for each MPG value in the `cars_data` table, you can use the SQL `GROUP BY` clause along with the `MAX()` function. Here's how to do it:\n\n```sql\nSELECT MPG, MAX(Weight) AS MaxWeight\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query will return each unique MPG value along with the highest Weight recorded for that MPG.","cost":0.0007731,"response_parsed":"SELECT MPG, MAX(Weight) AS MaxWeight\nFROM cars_data\nGROUP BY MPG;","time":5.9942650795}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `MPG`, AVG(`Weight`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the avg of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average `Weight` for each `MPG` in the `cars_data` table, you can use the SQL `AVG()` function combined with a `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n MPG,\n AVG(Weight) AS avg_weight\nFROM \n cars_data\nGROUP BY \n MPG\nORDER BY \n MPG;\n```\n\nThis query will:\n1. Group the rows in `cars_data` by the `MPG` values.\n2. Calculate the average `Weight` for each group.\n3. Return the results sorted by `MPG`.","cost":0.0006768,"response_parsed":"SELECT \n MPG,\n AVG(Weight) AS avg_weight\nFROM \n cars_data\nGROUP BY \n MPG\nORDER BY \n MPG;","time":5.1158432961}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `MPG`, SUM(`Weight`) FROM `cars_data` GROUP BY `MPG`","question":"For each MPG, find the sum of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the sum of `Weight` for each `MPG` in the `cars_data` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT MPG, SUM(Weight) AS TotalWeight\nFROM cars_data\nGROUP BY MPG;\n```\n\nThis query will:\n1. Select the `MPG` column.\n2. Calculate the sum of the `Weight` column for each `MPG` value.\n3. Group the results by the `MPG` values.","cost":0.0006111,"response_parsed":"SELECT MPG, SUM(Weight) AS TotalWeight\nFROM cars_data\nGROUP BY MPG;","time":4.2630221844}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Horsepower`, MIN(`Cylinders`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the min of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum number of cylinders for each horsepower in the `cars_data` table, you can use the SQL `MIN()` function combined with a `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Horsepower, MIN(Cylinders) AS MinCylinders\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will return the minimum number of cylinders for each unique horsepower value in your table.","cost":0.0007344,"response_parsed":"SELECT Horsepower, MIN(Cylinders) AS MinCylinders\nFROM cars_data\nGROUP BY Horsepower;","time":5.3463177681}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Horsepower`, MAX(`Cylinders`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the max of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum number of cylinders for each horsepower in the `cars_data` table, you can use the SQL `MAX()` function combined with `GROUP BY`. Here's how to do it:\n\n```sql\nSELECT Horsepower, MAX(Cylinders) AS MaxCylinders\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will return each unique `Horsepower` value along with the maximum `Cylinders` value associated with it.","cost":0.0007074,"response_parsed":"SELECT Horsepower, MAX(Cylinders) AS MaxCylinders\nFROM cars_data\nGROUP BY Horsepower;","time":5.2094600201}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Horsepower`, AVG(`Cylinders`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the avg of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average number of cylinders for each horsepower in the `cars_data` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Horsepower,\n AVG(Cylinders) AS Average_Cylinders\nFROM \n cars_data\nGROUP BY \n Horsepower;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculate the average value of the `Cylinders` column for each group.\n3. Return the results with the `Horsepower` value and its corresponding average number of cylinders.","cost":0.0007659,"response_parsed":"SELECT \n Horsepower,\n AVG(Cylinders) AS Average_Cylinders\nFROM \n cars_data\nGROUP BY \n Horsepower;","time":6.2085351944}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Horsepower`, SUM(`Cylinders`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the sum of Cylinders in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the sum of `Cylinders` for each `Horsepower` in the `cars_data` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Horsepower, SUM(Cylinders) AS TotalCylinders\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will:\n1. Group the rows in `cars_data` by the `Horsepower` column.\n2. Calculate the sum of the `Cylinders` for each group.\n3. Return the results with the `Horsepower` and the corresponding sum of `Cylinders`.","cost":0.0006336,"response_parsed":"SELECT Horsepower, SUM(Cylinders) AS TotalCylinders\nFROM cars_data\nGROUP BY Horsepower;","time":4.6773836613}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Horsepower`, MIN(`Weight`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the min of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum Weight for each Horsepower in the `cars_data` table, you can use the SQL `MIN()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT Horsepower, MIN(Weight) AS min_weight\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will return the minimum Weight for each distinct Horsepower value in the `cars_data` table.","cost":0.0005445,"response_parsed":"SELECT Horsepower, MIN(Weight) AS min_weight\nFROM cars_data\nGROUP BY Horsepower;","time":3.4529035091}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Horsepower`, MAX(`Weight`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the max of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum Weight for each Horsepower in the `cars_data` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Horsepower, MAX(Weight) AS MaxWeight\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will return the maximum Weight for each unique Horsepower value in the `cars_data` table.","cost":0.0006471,"response_parsed":"SELECT Horsepower, MAX(Weight) AS MaxWeight\nFROM cars_data\nGROUP BY Horsepower;","time":4.8196418285}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Horsepower`, AVG(`Weight`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the avg of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average weight for each horsepower in the `cars_data` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Horsepower, AVG(Weight) AS \"Average Weight\"\nFROM cars_data\nGROUP BY Horsepower;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculate the average value of the `Weight` column for each group of rows with the same `Horsepower`.\n3. Return the results with the `Horsepower` and the corresponding average weight.","cost":0.0008514,"response_parsed":"SELECT Horsepower, AVG(Weight) AS \"Average Weight\"\nFROM cars_data\nGROUP BY Horsepower;","time":7.6693413258}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Horsepower`, SUM(`Weight`) FROM `cars_data` GROUP BY `Horsepower`","question":"For each Horsepower, find the sum of Weight in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the sum of `Weight` for each `Horsepower` in the `cars_data` table, you can use the SQL `GROUP BY` clause to group the data by `Horsepower` and then apply the `SUM` aggregation function on the `Weight` column.\n\n```sql\nSELECT Horsepower, SUM(Weight) AS TotalWeight\nFROM cars_data\nGROUP BY Horsepower;\n```","cost":0.0006039,"response_parsed":"SELECT Horsepower, SUM(Weight) AS TotalWeight\nFROM cars_data\nGROUP BY Horsepower;","time":4.4680371284}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Maker` FROM `car_makers` GROUP BY `Maker` HAVING count(*) >= 1","question":"Find all the Maker that have at least 1 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the Makers that have at least one record in the `car_makers` table, you can use a simple `SELECT DISTINCT` statement. This will return each unique Maker name that appears in the table.\n\n```sql\nSELECT DISTINCT Maker FROM car_makers;\n```","cost":0.0005481,"response_parsed":"SELECT DISTINCT Maker FROM car_makers;","time":3.6976659298}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Maker` FROM `car_makers` GROUP BY `Maker` HAVING count(*) <= 1","question":"Find all the Maker that have at most 1 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the Makers that have at most 1 record in the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Maker\nFROM car_makers\nGROUP BY Maker\nHAVING COUNT(Maker) <= 1;\n```\n\nThis query will:\n1. Group the records in the `car_makers` table by the `Maker` field.\n2. Count the number of records for each `Maker`.\n3. Return only those Makers that have 1 or fewer records in the table.","cost":0.0007767,"response_parsed":"SELECT Maker\nFROM car_makers\nGROUP BY Maker\nHAVING COUNT(Maker) <= 1;","time":6.7550327778}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `FullName` FROM `car_makers` GROUP BY `FullName` HAVING count(*) >= 1","question":"Find all the FullName that have at least 1 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the `FullName` values that have at least one record in the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT FullName FROM car_makers;\n```\n\nThis query will return all unique `FullName` values that exist in the `car_makers` table.","cost":0.000666,"response_parsed":"SELECT DISTINCT FullName FROM car_makers;","time":5.6527838707}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `FullName` FROM `car_makers` GROUP BY `FullName` HAVING count(*) <= 1","question":"Find all the FullName that have at most 1 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the `FullName` values that have at most 1 record in the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT FullName FROM car_makers\nWHERE FullName IN (\n SELECT FullName FROM car_makers\n GROUP BY FullName\n HAVING COUNT(*) <= 1\n);\n```\n\nThis query works as follows:\n1. The subquery groups the `FullName` values and counts their occurrences.\n2. The `HAVING COUNT(*) <= 1` clause filters the groups to include only those `FullName` values that appear at most once.\n3. The outer query selects the `FullName` values from the `car_makers` table that match the filtered results from the subquery.","cost":0.0010071,"response_parsed":"SELECT FullName FROM car_makers\nWHERE FullName IN (\n SELECT FullName FROM car_makers\n GROUP BY FullName\n HAVING COUNT(*) <= 1\n);","time":9.2638459206}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `car_makers` GROUP BY `Country` HAVING count(*) >= 2","question":"Find all the Country that have at least 2 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all countries with at least two records in the `car_makers` table, we can use the following SQL query:\n\n```sql\nSELECT c.CountryName\nFROM countries c\nJOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) >= 2;\n```\n\nThis query:\n1. Joins the `countries` and `car_makers` tables based on the country relationship.\n2. Groups the results by country name.\n3. Filters the results to include only those countries with at least two car makers.\n\n```sql\nSELECT c.CountryName\nFROM countries c\nJOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) >= 2;\n```","cost":0.0006885,"response_parsed":"SELECT c.CountryName\nFROM countries c\nJOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) >= 2;","time":5.3740611076}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `car_makers` GROUP BY `Country` HAVING count(*) <= 2","question":"Find all the Country that have at most 2 records in table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all countries with at most 2 records in the `car_makers` table, we can use the following SQL query:\n\n```sql\nSELECT c.CountryName\nFROM countries c\nINNER JOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) <= 2;\n```\n\nThis query:\n1. Joins the `countries` and `car_makers` tables based on the country relationship.\n2. Groups the results by country name.\n3. Filters the groups to include only those with 2 or fewer records in `car_makers`.\n\n```sql\nSELECT c.CountryName\nFROM countries c\nINNER JOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) <= 2;\n```","cost":0.0006606,"response_parsed":"SELECT c.CountryName\nFROM countries c\nINNER JOIN car_makers cm ON c.CountryId = cm.Country\nGROUP BY c.CountryName\nHAVING COUNT(cm.Country) <= 2;","time":5.0085337162}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING count(*) >= 1","question":"Find all the CountryName that have at least 1 records in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all `CountryName` that have at least 1 record in the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT CountryName FROM countries;\n```\n\nThis query will return all unique `CountryName` values that exist in the `countries` table.","cost":0.0005535,"response_parsed":"SELECT DISTINCT CountryName FROM countries;","time":3.9434199333}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING count(*) <= 1","question":"Find all the CountryName that have at most 1 records in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all `CountryName` that have at most 1 record in the `countries` table, we can use the `COUNT` function combined with `GROUP BY` to count the occurrences of each `CountryName`. Here's how you can do it:\n\n```sql\nSELECT CountryName\nFROM countries\nGROUP BY CountryName\nHAVING COUNT(CountryName) <= 1;\n```\n\nThis query will return all `CountryName` values that appear at most once in the `countries` table.","cost":0.0007308,"response_parsed":"SELECT CountryName\nFROM countries\nGROUP BY CountryName\nHAVING COUNT(CountryName) <= 1;","time":7.0643897057}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING AVG(`Continent`) >= 2.6","question":"List the CountryName which average of Continent is at least 2.6 in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question of listing the `CountryName` where the average number of car makers per country in their respective continent is at least 2.6, we can use the following SQL query. This query calculates the average number of car makers per country within each continent and selects the countries from continents where this average meets or exceeds 2.6.\n\n```sql\nSELECT c.CountryName\nFROM countries c\nWHERE c.Continent IN (\n SELECT c2.Continent\n FROM (\n SELECT cm.Country, COUNT(*) as cnt\n FROM car_makers cm\n GROUP BY cm.Country\n ) sub\n JOIN countries c2 ON sub.Country = c2.CountryId\n GROUP BY c2.Continent\n HAVING AVG(sub.cnt) >= 2.6\n);\n```","cost":0.0018162,"response_parsed":"SELECT c.CountryName\nFROM countries c\nWHERE c.Continent IN (\n SELECT c2.Continent\n FROM (\n SELECT cm.Country, COUNT(*) as cnt\n FROM car_makers cm\n GROUP BY cm.Country\n ) sub\n JOIN countries c2 ON sub.Country = c2.CountryId\n GROUP BY c2.Continent\n HAVING AVG(sub.cnt) >= 2.6\n);","time":20.1967816353}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING AVG(`Continent`) <= 2.6","question":"List the CountryName which average of Continent is at most 2.6 in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question of listing the `CountryName` where the average number of countries per continent is at most 2.6, we need to consider the count of countries in each continent. Here's the SQL code:\n\n```sql\nSELECT CountryName FROM countries WHERE (SELECT COUNT(*) FROM countries c2 WHERE c2.Continent = countries.Continent) <= 2.6;\n```\n\nThis code selects the `CountryName` from the `countries` table where the count of countries in their respective continent is 2 or fewer.","cost":0.0017091,"response_parsed":"SELECT CountryName FROM countries WHERE (SELECT COUNT(*) FROM countries c2 WHERE c2.Continent = countries.Continent) <= 2.6;","time":17.7202005386}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING SUM(`Continent`) >= 2.6","question":"List the CountryName which summation of Continent is at least 2.6 in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to list the `CountryName` from the `countries` table where the sum of the `Continent` values is at least 2.6. \n\nHere's the SQL code to achieve this:\n\n```sql\nSELECT CountryName\nFROM countries\nWHERE Continent = (\n SELECT SUM(Continent)\n FROM countries\n GROUP BY Continent\n HAVING SUM(Continent) >= 2.6\n);\n```\n\nThis SQL query will:\n1. Calculate the sum of the `Continent` values for each group of countries.\n2. Filter the groups where the sum of `Continent` is at least 2.6.\n3. Return the `CountryName` for the countries in those groups.","cost":0.0010728,"response_parsed":"SELECT CountryName\nFROM countries\nWHERE Continent = (\n SELECT SUM(Continent)\n FROM countries\n GROUP BY Continent\n HAVING SUM(Continent) >= 2.6\n);","time":9.4394273758}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `CountryName` FROM `countries` GROUP BY `CountryName` HAVING SUM(`Continent`) <= 2.6","question":"List the CountryName which summation of Continent is at most 2.6 in table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to list the `CountryName` from the `countries` table where the sum of the `Continent` values is at most 2.6. \n\nHere's the SQL code to achieve this:\n\n```sql\nSELECT CountryName \nFROM countries \nWHERE Continent IN (\n SELECT Continent \n FROM countries \n GROUP BY Continent \n HAVING SUM(Continent) <= 2.6\n);\n```\n\nThis SQL query will:\n1. First, group the `countries` table by the `Continent` column.\n2. Then, filter the groups where the sum of the `Continent` values is at most 2.6.\n3. Finally, select the `CountryName` from the `countries` table where the `Continent` is in the filtered list.","cost":0.0010638,"response_parsed":"SELECT CountryName \nFROM countries \nWHERE Continent IN (\n SELECT Continent \n FROM countries \n GROUP BY Continent \n HAVING SUM(Continent) <= 2.6\n);","time":9.8184757233}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Continent` FROM `continents` GROUP BY `Continent` HAVING count(*) >= 1","question":"Find all the Continent that have at least 1 records in table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all continents that have at least one record in the `continents` table, you can use the following SQL query. This query will return all unique continent names from the `continents` table:\n\n```sql\nSELECT DISTINCT Continent FROM continents;\n```\n\nIf you want to ensure that the continent has at least one associated country, you can use this query:\n\n```sql\nSELECT DISTINCT c.Continent \nFROM continents c\nINNER JOIN countries co ON c.ContId = co.Continent;\n```\n\nThis query will return all continents that have at least one country associated with them.","cost":0.0009513,"response_parsed":"SELECT DISTINCT c.Continent \nFROM continents c\nINNER JOIN countries co ON c.ContId = co.Continent;","time":8.2544548512}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Continent` FROM `continents` GROUP BY `Continent` HAVING count(*) <= 1","question":"Find all the Continent that have at most 1 records in table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all continents with at most 1 record in the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT Continent, COUNT(*) as Count\nFROM continents\nGROUP BY Continent\nHAVING COUNT(*) <= 1;\n```\n\nThis query will:\n1. Group the records in the `continents` table by the `Continent` column.\n2. Count the number of records for each continent.\n3. Filter the results to include only those continents with 1 or fewer records.\n\n```sql\nSELECT Continent, COUNT(*) as Count\nFROM continents\nGROUP BY Continent\nHAVING COUNT(*) <= 1;\n```","cost":0.0006426,"response_parsed":"SELECT Continent, COUNT(*) as Count\nFROM continents\nGROUP BY Continent\nHAVING COUNT(*) <= 1;","time":4.5622234344}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Model` FROM `car_names` GROUP BY `Model` HAVING count(*) >= 12","question":"Find all the Model that have at least 12 records in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all models with at least 12 records in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT Model \nFROM car_names\nGROUP BY Model\nHAVING COUNT(Model) >= 12;\n```\n\nThis query will:\n1. Select the `Model` field from the `car_names` table\n2. Group the results by the `Model` field\n3. Filter the results to only include models that appear at least 12 times in the table\n\nThe result will be a list of models that have 12 or more records in the `car_names` table.","cost":0.000756,"response_parsed":"SELECT Model \nFROM car_names\nGROUP BY Model\nHAVING COUNT(Model) >= 12;","time":6.0057718754}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Model` FROM `car_names` GROUP BY `Model` HAVING count(*) <= 12","question":"Find all the Model that have at most 12 records in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all models with at most 12 records in the `car_names` table, we can use the following SQL query. This query groups the models and counts their occurrences, filtering those with 12 or fewer records.\n\n```sql\nSELECT Model\nFROM car_names\nGROUP BY Model\nHAVING COUNT(Model) <= 12;\n```","cost":0.0009063,"response_parsed":"SELECT Model\nFROM car_names\nGROUP BY Model\nHAVING COUNT(Model) <= 12;","time":7.4693200588}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Make` FROM `car_names` GROUP BY `Make` HAVING count(*) >= 1","question":"Find all the Make that have at least 1 records in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the `Make` that have at least 1 record in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT Make FROM car_names;\n```\n\nThis query will return all the `Make` values that exist in the `car_names` table. Since the question only asks for the `Make` values that have at least 1 record, and every record in `car_names` has a `Make`, this query will effectively return all the unique `Make` values in the table.","cost":0.0007497,"response_parsed":"SELECT Make FROM car_names;","time":5.9679427147}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Make` FROM `car_names` GROUP BY `Make` HAVING count(*) <= 1","question":"Find all the Make that have at most 1 records in table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the Makes that have at most 1 record in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT Make \nFROM car_names \nGROUP BY Make \nHAVING COUNT(Make) <= 1;\n```\n\nThis query will:\n1. Select the `Make` column from the `car_names` table.\n2. Group the results by the `Make` column.\n3. Filter the groups to include only those with 1 or fewer records.\n\nThe result will be a list of Makes that appear at most once in the `car_names` table.","cost":0.0006957,"response_parsed":"SELECT Make \nFROM car_names \nGROUP BY Make \nHAVING COUNT(Make) <= 1;","time":5.3126914501}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING count(*) >= 1","question":"Find all the Model that have at least 1 records in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all models that have at least one record in the `model_list` table, we can use a simple `SELECT` statement since each model in `model_list` inherently has at least one record.\n\n```sql\nSELECT Model FROM model_list;\n```","cost":0.0005589,"response_parsed":"SELECT Model FROM model_list;","time":3.852042675}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING count(*) <= 1","question":"Find all the Model that have at most 1 records in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all models that have at most 1 record in the `model_list` table, we can use a SQL query that selects the distinct models from the `model_list` table. Since each model in `model_list` is unique (as indicated by the `UNIQUE` constraint on the `Model` column), every model inherently has exactly one record in this table.\n\nHere is the SQL code to fetch the desired result:\n\n```sql\nSELECT Model \nFROM model_list;\n```\n\nThis query will return all the model names from the `model_list` table, each of which has exactly one record in the table.","cost":0.0006813,"response_parsed":"SELECT Model \nFROM model_list;","time":5.2381794453}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING AVG(`Maker`) >= 10.06","question":"List the Model which average of Maker is at least 10.06 in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo help you with the correct SQL query, I need a bit more clarification on your question. The current phrasing seems to suggest averaging the `Maker` column in the `model_list` table, but `Maker` is a foreign key referencing the `Id` in the `car_makers` table. Averaging a foreign key column doesn't make logical sense in this context.\n\nCould you clarify if you meant to average a different column or perhaps filter based on a specific condition related to the `Maker`? For example:\n- Do you want to average a numerical value (e.g., `Horsepower`, `Weight`, etc.) for models of makers?\n- Or are you looking to filter models based on a specific maker's average performance?\n\nPlease provide more details so I can assist you with the correct SQL query.","cost":0.0009072,"response_parsed":"\n\nTo help you with the correct SQL query, I need a bit more clarification on your question. The current phrasing seems to suggest averaging the `Maker` column in the `model_list` table, but `Maker` is a foreign key referencing the `Id` in the `car_makers` table. Averaging a foreign key column doesn't make logical sense in this context.\n\nCould you clarify if you meant to average a different column or perhaps filter based on a specific condition related to the `Maker`? For example:\n- Do you want to average a numerical value (e.g., `Horsepower`, `Weight`, etc.) for models of makers?\n- Or are you looking to filter models based on a specific maker's average performance?\n\nPlease provide more details so I can assist you with the correct SQL query.","time":7.6774187088}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING AVG(`Maker`) <= 10.06","question":"List the Model which average of Maker is at most 10.06 in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question of listing the models where the average of the Maker is at most 10.06, we need to calculate the average Maker value for each model and filter those with an average less than or equal to 10.06. Here's the SQL code:\n\n```sql\nSELECT Model \nFROM model_list \nGROUP BY Model \nHAVING AVG(Maker) <= 10.06;\n```","cost":0.0012717,"response_parsed":"SELECT Model \nFROM model_list \nGROUP BY Model \nHAVING AVG(Maker) <= 10.06;","time":11.1978273392}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING SUM(`Maker`) >= 10.06","question":"List the Model which summation of Maker is at least 10.06 in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question of listing the models where the summation of the Maker is at least 10.06, we need to consider the following:\n\n1. **Understanding the Requirement**: The goal is to sum the `Maker` values for each `Model` in the `model_list` table and filter those models where this sum is at least 10.06.\n\n2. **Database Schema Insight**: \n - The `model_list` table contains `ModelId`, `Maker`, and `Model`.\n - `Maker` is an integer that references the `Id` in the `car_makers` table.\n\n3. **SQL Query Construction**:\n - **SELECT**: Retrieve the `Model` field.\n - **FROM**: Use the `model_list` table.\n - **GROUP BY**: Group the results by the `Model` to aggregate the `Maker` values.\n - **HAVING**: Filter the grouped results where the sum of `Maker` is at least 10.06.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Model\nFROM model_list\nGROUP BY Model\nHAVING SUM(Maker) >= 10.06;\n```\n\nThis query will return the names of the models where the sum of their associated Maker IDs is at least 10.06.","cost":0.0011601,"response_parsed":"SELECT Model\nFROM model_list\nGROUP BY Model\nHAVING SUM(Maker) >= 10.06;","time":10.7312982082}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Model` FROM `model_list` GROUP BY `Model` HAVING SUM(`Maker`) <= 10.06","question":"List the Model which summation of Maker is at most 10.06 in table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question \"List the Model which summation of Maker is at most 10.06 in table model_list,\" we need to write an SQL query that sums the `Maker` column for each `Model` and filters the results to include only those with a sum of at most 10.06.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Model \nFROM model_list \nWHERE Maker IN (\n SELECT Maker \n FROM model_list \n GROUP BY Maker \n HAVING SUM(Maker) <= 10.06\n);\n```\n\n### Explanation:\n1. **Subquery**: The subquery selects the `Maker` values from the `model_list` table where the sum of the `Maker` column for each group of `Maker` is less than or equal to 10.06.\n2. **Main Query**: The main query selects the `Model` from the `model_list` table where the `Maker` is in the list of `Maker` values returned by the subquery.\n\nThis query will return all models whose corresponding `Maker` values sum up to 10.06 or less.","cost":0.0013455,"response_parsed":"SELECT Model \nFROM model_list \nWHERE Maker IN (\n SELECT Maker \n FROM model_list \n GROUP BY Maker \n HAVING SUM(Maker) <= 10.06\n);","time":12.3694860935}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING count(*) >= 3","question":"Find all the MPG that have at least 3 records in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the MPG values that appear at least 3 times in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT MPG \nFROM cars_data \nGROUP BY MPG \nHAVING COUNT(Id) >= 3;\n```\n\nThis query:\n1. Groups the rows in `cars_data` by the `MPG` column.\n2. Counts the number of records for each `MPG` value using `COUNT(Id)`.\n3. Filters the results to include only those `MPG` values that appear at least 3 times (`HAVING COUNT(Id) >= 3`).\n4. Returns the distinct `MPG` values that meet the condition.","cost":0.0006174,"response_parsed":"SELECT DISTINCT MPG \nFROM cars_data \nGROUP BY MPG \nHAVING COUNT(Id) >= 3;","time":4.5919325352}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING count(*) <= 3","question":"Find all the MPG that have at most 3 records in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the MPG values that have at most 3 records in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT MPG\nFROM cars_data\nWHERE MPG IN (\n SELECT MPG\n FROM cars_data\n GROUP BY MPG\n HAVING COUNT(*) <= 3\n);\n```\n\nThis query works as follows:\n1. The subquery groups the `cars_data` table by the `MPG` column and counts the number of records for each MPG value.\n2. The `HAVING COUNT(*) <= 3` clause filters the results to include only those MPG values that have 3 or fewer records.\n3. The outer query then selects the distinct MPG values from the filtered results.\n\nThe final result will be a list of all MPG values that appear in 3 or fewer records in the `cars_data` table.","cost":0.0007398,"response_parsed":"SELECT DISTINCT MPG\nFROM cars_data\nWHERE MPG IN (\n SELECT MPG\n FROM cars_data\n GROUP BY MPG\n HAVING COUNT(*) <= 3\n);","time":5.7946605682}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING count(*) >= 4","question":"Find all the Horsepower that have at least 4 records in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the Horsepower values that appear at least 4 times in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING COUNT(*) >= 4;\n```\n\nThis query:\n1. Groups the rows in the `cars_data` table by the `Horsepower` column.\n2. Counts the number of records in each group using `COUNT(*)`.\n3. Filters the results to include only those groups with 4 or more records using `HAVING COUNT(*) >= 4`.\n\nThe result will be a list of `Horsepower` values that appear at least 4 times in the table.","cost":0.0007947,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING COUNT(*) >= 4;","time":7.0056481361}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING count(*) <= 4","question":"Find all the Horsepower that have at most 4 records in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find all the Horsepower values that have at most 4 records in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING COUNT(Horsepower) <= 4;\n```\n\nThis query will:\n1. Group the records in the `cars_data` table by the `Horsepower` column.\n2. Count the number of records for each `Horsepower` value.\n3. Return only those `Horsepower` values that have 4 or fewer records.","cost":0.0009972,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING COUNT(Horsepower) <= 4;","time":9.4945073128}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING AVG(`Accelerate`) >= 16.12","question":"List the MPG which average of Accelerate is at least 16.12 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values from the `cars_data` table where the average acceleration is at least 16.12, you can use the following SQL query:\n\n```sql\nSELECT \"MPG\"\nFROM \"cars_data\"\nGROUP BY \"MPG\"\nHAVING AVG(\"Accelerate\") >= 16.12;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `MPG` values.\n2. Calculate the average `Accelerate` value for each group.\n3. Return only those `MPG` values where the average `Accelerate` is at least 16.12.","cost":0.0006921,"response_parsed":"SELECT \"MPG\"\nFROM \"cars_data\"\nGROUP BY \"MPG\"\nHAVING AVG(\"Accelerate\") >= 16.12;","time":4.7863936424}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING AVG(`Accelerate`) <= 16.12","question":"List the MPG which average of Accelerate is at most 16.12 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values from the `cars_data` table where the average of the `Accelerate` column is at most 16.12, you can use the following SQL query:\n\n```sql\nSELECT MPG \nFROM cars_data \nWHERE Accelerate <= 16.12;\n```\n\nThis query will return all the MPG values from the rows in your `cars_data` table where the `Accelerate` value is less than or equal to 16.12.","cost":0.0014517,"response_parsed":"SELECT MPG \nFROM cars_data \nWHERE Accelerate <= 16.12;","time":12.4979569912}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING SUM(`Accelerate`) >= 48.47","question":"List the MPG which summation of Accelerate is at least 48.47 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question \"List the MPG which summation of Accelerate is at least 48.47 in table cars_data,\" we need to write an SQL query that retrieves the MPG values from the `cars_data` table where the sum of the `Accelerate` column is at least 48.47.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT MPG \nFROM cars_data \nWHERE (SELECT SUM(Accelerate) FROM cars_data) >= 48.47;\n```\n\n### Explanation:\n1. **SELECT MPG**: This part of the query specifies that we want to retrieve the `MPG` values from the `cars_data` table.\n2. **FROM cars_data**: This specifies the table from which we want to retrieve the data.\n3. **WHERE (SELECT SUM(Accelerate) FROM cars_data) >= 48.47**: This is a subquery that calculates the sum of the `Accelerate` column in the `cars_data` table. The outer query then checks if this sum is greater than or equal to 48.47. If it is, the query will return the `MPG` values; otherwise, it will return no results.\n\nThis query will return all `MPG` values from the `cars_data` table if the total sum of the `Accelerate` column is at least 48.47.","cost":0.0010386,"response_parsed":"SELECT MPG \nFROM cars_data \nWHERE (SELECT SUM(Accelerate) FROM cars_data) >= 48.47;","time":8.1978759766}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING SUM(`Accelerate`) <= 48.47","question":"List the MPG which summation of Accelerate is at most 48.47 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values where the summation of the `Accelerate` column is at most 48.47, you can use the following SQL query:\n\n```sql\nSELECT MPG \nFROM cars_data \nGROUP BY MPG \nHAVING SUM(Accelerate) <= 48.47;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `MPG` column.\n2. Calculate the sum of the `Accelerate` column for each group.\n3. Return only those `MPG` values where the sum of `Accelerate` is less than or equal to 48.47.","cost":0.0007713,"response_parsed":"SELECT MPG \nFROM cars_data \nGROUP BY MPG \nHAVING SUM(Accelerate) <= 48.47;","time":5.5400896072}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING AVG(`Edispl`) >= 160.57","question":"List the MPG which average of Edispl is at least 160.57 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values from the `cars_data` table where the average `Edispl` is at least 160.57, you can use the following SQL query:\n\n```sql\nSELECT MPG\nFROM cars_data\nGROUP BY MPG\nHAVING AVG(Edispl) >= 160.57;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `MPG` values.\n2. Calculate the average `Edispl` for each group.\n3. Return only those `MPG` values where the average `Edispl` is at least 160.57.","cost":0.0007623,"response_parsed":"SELECT MPG\nFROM cars_data\nGROUP BY MPG\nHAVING AVG(Edispl) >= 160.57;","time":5.4588518143}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING AVG(`Edispl`) <= 160.57","question":"List the MPG which average of Edispl is at most 160.57 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values where the average of `Edispl` is at most 160.57, you can use the following SQL query:\n\n```sql\nSELECT MPG \nFROM cars_data \nWHERE (SELECT AVG(Edispl) FROM cars_data) <= 160.57;\n```\n\nThis query will:\n1. Calculate the average of the `Edispl` column in the `cars_data` table.\n2. Check if this average is less than or equal to 160.57.\n3. If the condition is met, it will return all the `MPG` values from the `cars_data` table.","cost":0.0009414,"response_parsed":"SELECT MPG \nFROM cars_data \nWHERE (SELECT AVG(Edispl) FROM cars_data) <= 160.57;","time":7.4368200302}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING SUM(`Edispl`) >= 608.31","question":"List the MPG which summation of Edispl is at least 608.31 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG values where the summation of `Edispl` is at least 608.31, you can use the following SQL query:\n\n```sql\nSELECT MPG\nFROM cars_data\nGROUP BY MPG\nHAVING SUM(Edispl) >= 608.31;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `MPG` column.\n2. Calculate the sum of the `Edispl` values for each group.\n3. Return only those `MPG` values where the sum of `Edispl` is at least 608.31.","cost":0.0010422,"response_parsed":"SELECT MPG\nFROM cars_data\nGROUP BY MPG\nHAVING SUM(Edispl) >= 608.31;","time":8.4580776691}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `MPG` FROM `cars_data` GROUP BY `MPG` HAVING SUM(`Edispl`) <= 608.31","question":"List the MPG which summation of Edispl is at most 608.31 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question \"List the MPG which summation of Edispl is at most 608.31 in table cars_data,\" we need to write an SQL query that retrieves the `MPG` values from the `cars_data` table where the sum of the `Edispl` column is less than or equal to 608.31.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT MPG \nFROM cars_data \nWHERE Edispl <= 608.31;\n```\n\nThis query will return all `MPG` values from the `cars_data` table where the corresponding `Edispl` value is at most 608.31.","cost":0.000891,"response_parsed":"SELECT MPG \nFROM cars_data \nWHERE Edispl <= 608.31;","time":7.2179636955}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING AVG(`Accelerate`) >= 15.21","question":"List the Horsepower which average of Accelerate is at least 15.21 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the horsepower values from the `cars_data` table where the average acceleration is at least 15.21, you can use the following SQL query:\n\n```sql\nSELECT Horsepower, AVG(Accelerate) AS Avg_Accelerate\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Accelerate) >= 15.21;\n```\n\nThis query:\n1. Selects the `Horsepower` column and calculates the average of the `Accelerate` column.\n2. Groups the results by the `Horsepower` values.\n3. Filters the results to include only those groups where the average `Accelerate` is at least 15.21.","cost":0.0008505,"response_parsed":"SELECT Horsepower, AVG(Accelerate) AS Avg_Accelerate\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Accelerate) >= 15.21;","time":6.3309831619}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING AVG(`Accelerate`) <= 15.21","question":"List the Horsepower which average of Accelerate is at most 15.21 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the Horsepower from the `cars_data` table where the average of `Accelerate` is at most 15.21, you can use the following SQL query:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Accelerate) <= 15.21;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculate the average value of the `Accelerate` column for each group.\n3. Return only those `Horsepower` values where the average `Accelerate` is less than or equal to 15.21.","cost":0.0009981,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Accelerate) <= 15.21;","time":8.1143462658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING SUM(`Accelerate`) >= 67.03","question":"List the Horsepower which summation of Accelerate is at least 67.03 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question \"List the Horsepower which summation of Accelerate is at least 67.03 in table cars_data,\" we need to write an SQL query that:\n\n1. Groups the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculates the sum of the `Accelerate` column for each group.\n3. Filters the groups where the sum of `Accelerate` is at least 67.03.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING SUM(Accelerate) >= 67.03;\n```\n\nThis query will return the `Horsepower` values where the sum of `Accelerate` for that `Horsepower` is at least 67.03.","cost":0.0007668,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING SUM(Accelerate) >= 67.03;","time":5.660882473}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING SUM(`Accelerate`) <= 67.03","question":"List the Horsepower which summation of Accelerate is at most 67.03 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Horsepower` values from the `cars_data` table where the sum of the `Accelerate` values is at most 67.03.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING SUM(Accelerate) <= 67.03;\n```\n\nThis query:\n1. Groups the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculates the sum of the `Accelerate` values for each group.\n3. Filters the results to include only those groups where the sum of `Accelerate` is less than or equal to 67.03.\n4. Returns the `Horsepower` values that meet this condition.","cost":0.0007668,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING SUM(Accelerate) <= 67.03;","time":5.1699669361}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING AVG(`Edispl`) >= 208.17","question":"List the Horsepower which average of Edispl is at least 208.17 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the Horsepower values from the `cars_data` table where the average `Edispl` is at least 208.17, you can use the following SQL query:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Edispl) >= 208.17;\n```\n\nThis query will:\n1. Group the rows in the `cars_data` table by the `Horsepower` column.\n2. Calculate the average `Edispl` for each group.\n3. Return only those `Horsepower` values where the average `Edispl` is at least 208.17.","cost":0.0008055,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Edispl) >= 208.17;","time":6.3691091537}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING AVG(`Edispl`) <= 208.17","question":"List the Horsepower which average of Edispl is at most 208.17 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the Horsepower from the `cars_data` table where the average of `Edispl` is at most 208.17, you can use the following SQL query:\n\n```sql\nSELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Edispl) <= 208.17;\n```\n\nThis query will:\n1. Group the rows in `cars_data` by the `Horsepower` column.\n2. Calculate the average `Edispl` for each group.\n3. Return only those `Horsepower` values where the average `Edispl` is less than or equal to 208.17.","cost":0.0007254,"response_parsed":"SELECT Horsepower\nFROM cars_data\nGROUP BY Horsepower\nHAVING AVG(Edispl) <= 208.17;","time":5.0347180367}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING SUM(`Edispl`) >= 841.28","question":"List the Horsepower which summation of Edispl is at least 841.28 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the horsepower from the `cars_data` table where the summation of `Edispl` is at least 841.28, you can use the following SQL query:\n\n```sql\nSELECT Horsepower FROM cars_data WHERE SUM(Edispl) >= 841.28;\n```\n\nThis query will return the horsepower values from the `cars_data` table where the sum of the `Edispl` values meets or exceeds 841.28.","cost":0.0008622,"response_parsed":"SELECT Horsepower FROM cars_data WHERE SUM(Edispl) >= 841.28;","time":6.6836698055}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Horsepower` FROM `cars_data` GROUP BY `Horsepower` HAVING SUM(`Edispl`) <= 841.28","question":"List the Horsepower which summation of Edispl is at most 841.28 in table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Horsepower` values from the `cars_data` table where the sum of the `Edispl` column is at most 841.28.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Horsepower FROM cars_data WHERE (SELECT SUM(Edispl) FROM cars_data) <= 841.28;\n```\n\n### Explanation:\n1. **Subquery**: `(SELECT SUM(Edispl) FROM cars_data)` calculates the total sum of the `Edispl` column in the `cars_data` table.\n2. **Condition**: `<= 841.28` checks if the calculated sum is at most 841.28.\n3. **Main Query**: If the condition is true, `SELECT Horsepower FROM cars_data` retrieves all `Horsepower` values from the table. If the condition is false, no results will be returned.","cost":0.0014589,"response_parsed":"SELECT Horsepower FROM cars_data WHERE (SELECT SUM(Edispl) FROM cars_data) <= 841.28;","time":14.5101904869}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `car_makers` AS T1 JOIN `countries` AS T2 ON T1.`Country` = T2.`CountryId`","question":"Join all the records from table car_makers with table countries on Country","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo join all records from the `car_makers` table with the `countries` table based on the `Country` field, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_makers\nINNER JOIN countries\nON car_makers.Country = countries.CountryId;\n```\n\nThis query will return all records where there is a match between the `Country` field in `car_makers` and the `CountryId` in `countries`.","cost":0.000639,"response_parsed":"SELECT *\nFROM car_makers\nINNER JOIN countries\nON car_makers.Country = countries.CountryId;","time":4.6216435432}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Maker`, T2.`CountryName` FROM `car_makers` AS T1 JOIN `countries` AS T2 ON T1.`Country`=T2.`CountryId`","question":"List all the Maker and CountryName from the table car_makers and the table countries where Country is the same","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the list of Maker and CountryName from the `car_makers` and `countries` tables where the Country is the same, you can use the following SQL query:\n\n```sql\nSELECT Maker, CountryName\nFROM car_makers\nINNER JOIN countries\nON car_makers.Country = countries.CountryId;\n```\n\nThis query joins the `car_makers` table with the `countries` table based on the matching `Country` field, ensuring that only rows where the Country is the same in both tables are returned.","cost":0.0014265,"response_parsed":"SELECT Maker, CountryName\nFROM car_makers\nINNER JOIN countries\nON car_makers.Country = countries.CountryId;","time":13.9670541286}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`FullName`, T2.`CountryName` FROM `car_makers` AS T1 JOIN `countries` AS T2 ON T1.`Country`=T2.`CountryId`","question":"List all the FullName and CountryName from the table car_makers and the table countries where Country is the same","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the required data, we need to join the `car_makers` table with the `countries` table based on the matching `Country` and `CountryId`. Here's the SQL query:\n\n```sql\nSELECT car_makers.FullName, countries.CountryName\nFROM car_makers\nINNER JOIN countries\nON countries.CountryId = car_makers.Country;\n```\n\nThis query will return the `FullName` from the `car_makers` table and the `CountryName` from the `countries` table where the `Country` in `car_makers` matches the `CountryId` in `countries`.","cost":0.0009279,"response_parsed":"SELECT car_makers.FullName, countries.CountryName\nFROM car_makers\nINNER JOIN countries\nON countries.CountryId = car_makers.Country;","time":7.7356164455}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `countries` AS T1 JOIN `continents` AS T2 ON T1.`Continent` = T2.`ContId`","question":"Join all the records from table countries with table continents on Continent","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo join all records from the `countries` table with the `continents` table based on the `Continent` field, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM countries\nLEFT JOIN continents\nON countries.Continent = continents.ContId;\n```\n\nThis query will:\n1. Select all records (`*`) from both tables.\n2. Use a `LEFT JOIN` to include all records from the `countries` table and only the matching records from the `continents` table.\n3. Join the tables based on the matching `Continent` field in `countries` and `ContId` in `continents`.","cost":0.0006597,"response_parsed":"SELECT *\nFROM countries\nLEFT JOIN continents\nON countries.Continent = continents.ContId;","time":4.8331940174}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`CountryName`, T2.`Continent` FROM `countries` AS T1 JOIN `continents` AS T2 ON T1.`Continent`=T2.`ContId`","question":"List all the CountryName and Continent from the table countries and the table continents where Continent is the same","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `CountryName` from the `countries` table and the corresponding `Continent` name from the `continents` table where the `Continent` ID in the `countries` table matches the `ContId` in the `continents` table.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT c.CountryName, co.Continent\nFROM countries c\nJOIN continents co ON c.Continent = co.ContId;\n```\n\nThis SQL query:\n1. Selects the `CountryName` from the `countries` table and the `Continent` name from the `continents` table.\n2. Joins the two tables based on the matching `Continent` ID (`Continent` in `countries` and `ContId` in `continents`).\n3. Returns a list of country names along with their corresponding continent names.","cost":0.000783,"response_parsed":"SELECT c.CountryName, co.Continent\nFROM countries c\nJOIN continents co ON c.Continent = co.ContId;","time":5.572165966}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `car_names` AS T1 JOIN `model_list` AS T2 ON T1.`Model` = T2.`Model`","question":"Join all the records from table car_names with table model_list on Model","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo join all records from the `car_names` table with the `model_list` table on the `Model` field, you can use the following SQL query:\n\n```sql\nSELECT car_names.*, model_list.*\nFROM car_names\nLEFT JOIN model_list\nON car_names.Model = model_list.Model;\n```\n\nThis query will:\n1. Select all columns (`*`) from both the `car_names` and `model_list` tables.\n2. Perform a `LEFT JOIN` on the `Model` field, which means it will return all records from `car_names` and the matching records from `model_list`. If there is no match, the result will contain `NULL` values for `model_list` columns.","cost":0.0007317,"response_parsed":"SELECT car_names.*, model_list.*\nFROM car_names\nLEFT JOIN model_list\nON car_names.Model = model_list.Model;","time":5.5954053402}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `model_list` AS T1 JOIN `car_makers` AS T2 ON T1.`Maker` = T2.`Id`","question":"Join all the records from table model_list with table car_makers on Maker","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo join all records from the `model_list` table with the `car_makers` table on the `Maker` field, you can use the following SQL query:\n\n```sql\nSELECT model_list.*, car_makers.*\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;\n```\n\nThis query will return all columns (`*`) from both the `model_list` and `car_makers` tables where the `Maker` field in `model_list` matches the `Id` field in `car_makers`.","cost":0.0005544,"response_parsed":"SELECT model_list.*, car_makers.*\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;","time":3.7683970928}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Model`, T2.`Maker` FROM `model_list` AS T1 JOIN `car_makers` AS T2 ON T1.`Maker`=T2.`Id`","question":"List all the Model and Maker from the table model_list and the table car_makers where Maker is the same","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the list of Model and Maker from the `model_list` and `car_makers` tables where the Maker is the same, you can use the following SQL query:\n\n```sql\nSELECT model_list.Model, car_makers.Maker \nFROM model_list \nINNER JOIN car_makers \nON model_list.Maker = car_makers.Id;\n```\n\nThis query:\n1. Joins the `model_list` table with the `car_makers` table based on the `Maker` field.\n2. Selects the `Model` from `model_list` and `Maker` from `car_makers`.\n3. Uses an `INNER JOIN` to ensure only records with matching Makers in both tables are returned.","cost":0.0006363,"response_parsed":"SELECT model_list.Model, car_makers.Maker \nFROM model_list \nINNER JOIN car_makers \nON model_list.Maker = car_makers.Id;","time":4.4145667553}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Model`, T2.`FullName` FROM `model_list` AS T1 JOIN `car_makers` AS T2 ON T1.`Maker`=T2.`Id`","question":"List all the Model and FullName from the table model_list and the table car_makers where Maker is the same","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the list of `Model` and `FullName` from the `model_list` and `car_makers` tables where the `Maker` is the same, you can use the following SQL query:\n\n```sql\nSELECT model_list.Model, car_makers.FullName\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;\n```\n\nThis query:\n1. Selects the `Model` column from the `model_list` table and the `FullName` column from the `car_makers` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Maker` column in `model_list` matches the `Id` column in `car_makers`.\n3. Returns only the rows where there is a match between the two tables.","cost":0.0006318,"response_parsed":"SELECT model_list.Model, car_makers.FullName\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;","time":4.1622798443}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Model`, T2.`Country` FROM `model_list` AS T1 JOIN `car_makers` AS T2 ON T1.`Maker`=T2.`Id`","question":"List all the Model and Country from the table model_list and the table car_makers where Maker is the same","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the list of Model and Country where the Maker is the same in both the `model_list` and `car_makers` tables, you can use the following SQL query:\n\n```sql\nSELECT ml.Model, cm.Country \nFROM model_list ml\nINNER JOIN car_makers cm \nON ml.Maker = cm.Id;\n```\n\nThis query:\n1. Selects the `Model` from the `model_list` table and the `Country` from the `car_makers` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Maker` in `model_list` matches the `Id` in `car_makers`.\n3. Returns only the rows where there is a match between the two tables based on the `Maker`-`Id` relationship.","cost":0.0006363,"response_parsed":"SELECT ml.Model, cm.Country \nFROM model_list ml\nINNER JOIN car_makers cm \nON ml.Maker = cm.Id;","time":4.2879652977}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `cars_data` AS T1 JOIN `car_names` AS T2 ON T1.`Id` = T2.`MakeId`","question":"Join all the records from table cars_data with table car_names on Id","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo join all records from the `cars_data` table with the `car_names` table on the `Id` field, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data AS cd\nINNER JOIN car_names AS cn\nON cd.Id = cn.MakeId;\n```\n\nThis query will return all columns (`*`) from both tables where there is a matching `Id` in `cars_data` and `MakeId` in `car_names`.","cost":0.00054,"response_parsed":"SELECT *\nFROM cars_data AS cd\nINNER JOIN car_names AS cn\nON cd.Id = cn.MakeId;","time":3.7412753105}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`MPG`, T2.`Model` FROM `cars_data` AS T1 JOIN `car_names` AS T2 ON T1.`Id`=T2.`MakeId`","question":"List all the MPG and Model from the table cars_data and the table car_names where Id is the same","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG and Model from the `cars_data` and `car_names` tables where the `Id` is the same, you can use the following SQL query:\n\n```sql\nSELECT cd.MPG, cn.Model \nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;\n```\n\nThis query:\n1. Selects the `MPG` column from the `cars_data` table and the `Model` column from the `car_names` table.\n2. Uses an `INNER JOIN` to combine rows from `cars_data` and `car_names` where the join condition `cd.Id = cn.MakeId` is met.","cost":0.0006768,"response_parsed":"SELECT cd.MPG, cn.Model \nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;","time":4.5949997902}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`MPG`, T2.`Make` FROM `cars_data` AS T1 JOIN `car_names` AS T2 ON T1.`Id`=T2.`MakeId`","question":"List all the MPG and Make from the table cars_data and the table car_names where Id is the same","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the MPG and Make from the `cars_data` and `car_names` tables where the `Id` is the same, you can use the following SQL query:\n\n```sql\nSELECT cd.MPG, cn.Make \nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;\n```\n\nThis query:\n1. Selects the `MPG` column from the `cars_data` table and the `Make` column from the `car_names` table.\n2. Uses an `INNER JOIN` to combine rows from `cars_data` and `car_names` where the join condition (`cd.Id = cn.MakeId`) is met.","cost":0.00072,"response_parsed":"SELECT cd.MPG, cn.Make \nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;","time":5.4229774475}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Horsepower`, T2.`Model` FROM `cars_data` AS T1 JOIN `car_names` AS T2 ON T1.`Id`=T2.`MakeId`","question":"List all the Horsepower and Model from the table cars_data and the table car_names where Id is the same","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Horsepower` from the `cars_data` table and the `Model` from the `car_names` table where the `Id` (in `cars_data`) matches the `MakeId` (in `car_names`).\n\nHere is the SQL code:\n\n```sql\nSELECT c_data.Horsepower, c_names.Model\nFROM cars_data c_data\nINNER JOIN car_names c_names\nON c_data.Id = c_names.MakeId;\n```\n\nThis SQL query:\n1. Selects the `Horsepower` column from the `cars_data` table\n2. Selects the `Model` column from the `car_names` table\n3. Joins the two tables on the condition that `cars_data.Id` equals `car_names.MakeId`\n4. Returns all matching records where the `Id` is the same in both tables","cost":0.0007839,"response_parsed":"SELECT c_data.Horsepower, c_names.Model\nFROM cars_data c_data\nINNER JOIN car_names c_names\nON c_data.Id = c_names.MakeId;","time":6.1485023499}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Horsepower`, T2.`Make` FROM `cars_data` AS T1 JOIN `car_names` AS T2 ON T1.`Id`=T2.`MakeId`","question":"List all the Horsepower and Make from the table cars_data and the table car_names where Id is the same","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Horsepower` from the `cars_data` table and the `Make` from the `car_names` table where the `Id` (in `cars_data`) matches the `MakeId` (in `car_names`).\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT cd.Horsepower, cn.Make\nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;\n```\n\nThis SQL query:\n1. Selects the `Horsepower` column from the `cars_data` table.\n2. Selects the `Make` column from the `car_names` table.\n3. Joins the two tables on the condition that `cars_data.Id` equals `car_names.MakeId`.\n4. Returns all matching rows where the join condition is satisfied.","cost":0.0007398,"response_parsed":"SELECT cd.Horsepower, cn.Make\nFROM cars_data cd\nINNER JOIN car_names cn\nON cd.Id = cn.MakeId;","time":5.3178086281}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_makers` ORDER BY `Maker` ASC","question":"Show all data ordered by Maker in ascending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_makers` table ordered by the `Maker` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers ORDER BY Maker ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `car_makers` table.\n2. Order the results by the `Maker` column in ascending order (`ASC`).","cost":0.000711,"response_parsed":"SELECT * FROM car_makers ORDER BY Maker ASC;","time":5.039380312}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_makers` ORDER BY `Maker` DESC","question":"Show all data ordered by Maker in descending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_makers` table ordered by the `Maker` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers ORDER BY Maker DESC;\n```","cost":0.0005157,"response_parsed":"SELECT * FROM car_makers ORDER BY Maker DESC;","time":3.2537839413}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_makers` ORDER BY `FullName` ASC","question":"Show all data ordered by FullName in ascending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_makers` table ordered by `FullName` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_makers\nORDER BY FullName ASC;\n```","cost":0.0004806,"response_parsed":"SELECT *\nFROM car_makers\nORDER BY FullName ASC;","time":2.7538533211}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_makers` ORDER BY `FullName` DESC","question":"Show all data ordered by FullName in descending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_makers` table ordered by `FullName` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers ORDER BY FullName DESC;\n```","cost":0.0004464,"response_parsed":"SELECT * FROM car_makers ORDER BY FullName DESC;","time":2.3454964161}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Maker` FROM `car_makers` ORDER BY `Maker` ASC","question":"Project the Maker ordered in ascending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Maker` from the `car_makers` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Maker\nFROM car_makers\nORDER BY Maker ASC;\n```","cost":0.0004977,"response_parsed":"SELECT Maker\nFROM car_makers\nORDER BY Maker ASC;","time":3.3702702522}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Maker` FROM `car_makers` ORDER BY `Maker` DESC","question":"Project the Maker ordered in descending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Maker` from the `car_makers` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Maker FROM car_makers ORDER BY Maker DESC;\n```","cost":0.000477,"response_parsed":"SELECT Maker FROM car_makers ORDER BY Maker DESC;","time":2.9314796925}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `car_makers` ORDER BY `Country` ASC","question":"Project the Country ordered in ascending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Country` from the `car_makers` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country \nFROM car_makers \nORDER BY Country ASC;\n```\n\nThis query selects unique country names from the `car_makers` table and sorts them in ascending alphabetical order.","cost":0.0005787,"response_parsed":"SELECT DISTINCT Country \nFROM car_makers \nORDER BY Country ASC;","time":4.1825540066}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `car_makers` ORDER BY `Country` DESC","question":"Project the Country ordered in descending order for the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Country` from the `car_makers` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Country FROM car_makers ORDER BY Country DESC;\n```","cost":0.0005931,"response_parsed":"SELECT Country FROM car_makers ORDER BY Country DESC;","time":4.3899288177}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `countries` ORDER BY `CountryName` ASC","question":"Show all data ordered by CountryName in ascending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `countries` table ordered by `CountryName` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries ORDER BY CountryName ASC;\n```","cost":0.000567,"response_parsed":"SELECT * FROM countries ORDER BY CountryName ASC;","time":3.8763587475}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `countries` ORDER BY `CountryName` DESC","question":"Show all data ordered by CountryName in descending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `countries` table ordered by `CountryName` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries ORDER BY CountryName DESC;\n```","cost":0.0005112,"response_parsed":"SELECT * FROM countries ORDER BY CountryName DESC;","time":2.9067213535}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `countries` ORDER BY `CountryId` ASC","question":"Show all data ordered by CountryId in ascending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `countries` table ordered by `CountryId` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries ORDER BY CountryId ASC;\n```","cost":0.0005517,"response_parsed":"SELECT * FROM countries ORDER BY CountryId ASC;","time":3.5421588421}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `countries` ORDER BY `CountryId` DESC","question":"Show all data ordered by CountryId in descending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `countries` table ordered by `CountryId` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries ORDER BY CountryId DESC;\n```","cost":0.0005526,"response_parsed":"SELECT * FROM countries ORDER BY CountryId DESC;","time":3.6245737076}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `CountryName` FROM `countries` ORDER BY `CountryName` ASC","question":"Project the CountryName ordered in ascending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `CountryName` from the `countries` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT CountryName FROM countries ORDER BY CountryName ASC;\n```","cost":0.0005499,"response_parsed":"SELECT CountryName FROM countries ORDER BY CountryName ASC;","time":3.5945558548}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `CountryName` FROM `countries` ORDER BY `CountryName` DESC","question":"Project the CountryName ordered in descending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `CountryName` from the `countries` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT CountryName FROM countries ORDER BY CountryName DESC;\n```","cost":0.0005904,"response_parsed":"SELECT CountryName FROM countries ORDER BY CountryName DESC;","time":4.139384985}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Continent` FROM `countries` ORDER BY `Continent` ASC","question":"Project the Continent ordered in ascending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the Continent names in ascending order from the `countries` table, we need to join the `countries` table with the `continents` table since the `countries` table contains the continent IDs, not the names. Here's the SQL query:\n\n```sql\nSELECT cnt.Continent\nFROM countries c\nINNER JOIN continents cnt\nON c.Continent = cnt.ContId\nORDER BY cnt.Continent ASC;\n```\n\nThis query:\n1. Joins the `countries` and `continents` tables on the `Continent` ID\n2. Selects the `Continent` names\n3. Orders the results alphabetically in ascending order","cost":0.0006399,"response_parsed":"SELECT cnt.Continent\nFROM countries c\nINNER JOIN continents cnt\nON c.Continent = cnt.ContId\nORDER BY cnt.Continent ASC;","time":4.5568671227}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Continent` FROM `countries` ORDER BY `Continent` DESC","question":"Project the Continent ordered in descending order for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the Continent names in descending order from the `countries` table, we need to join the `countries` table with the `continents` table since the `countries` table contains Continent IDs that reference the `continents` table.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT DISTINCT c.Continent\nFROM countries\nINNER JOIN continents c ON countries.Continent = c.ContId\nORDER BY c.Continent DESC;\n```\n\nThis SQL query:\n1. Selects the distinct `Continent` names from the `continents` table\n2. Joins the `countries` table with the `continents` table based on the matching `Continent` IDs\n3. Orders the results in descending alphabetical order by `Continent` name","cost":0.0007434,"response_parsed":"SELECT DISTINCT c.Continent\nFROM countries\nINNER JOIN continents c ON countries.Continent = c.ContId\nORDER BY c.Continent DESC;","time":5.7600464821}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `continents` ORDER BY `ContId` ASC","question":"Show all data ordered by ContId in ascending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `continents` table ordered by `ContId` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM continents ORDER BY ContId ASC;\n```","cost":0.0005652,"response_parsed":"SELECT * FROM continents ORDER BY ContId ASC;","time":3.5230743885}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `continents` ORDER BY `ContId` DESC","question":"Show all data ordered by ContId in descending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `continents` table ordered by `ContId` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM continents ORDER BY ContId DESC;\n```","cost":0.0005652,"response_parsed":"SELECT * FROM continents ORDER BY ContId DESC;","time":3.4093463421}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `continents` ORDER BY `Continent` ASC","question":"Show all data ordered by Continent in ascending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `continents` table ordered by the `Continent` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM continents ORDER BY Continent ASC;\n```","cost":0.0005868,"response_parsed":"SELECT * FROM continents ORDER BY Continent ASC;","time":4.3195576668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `continents` ORDER BY `Continent` DESC","question":"Show all data ordered by Continent in descending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `continents` table ordered by the `Continent` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM continents ORDER BY Continent DESC;\n```","cost":0.0005733,"response_parsed":"SELECT * FROM continents ORDER BY Continent DESC;","time":3.9327373505}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ContId` FROM `continents` ORDER BY `ContId` ASC","question":"Project the ContId ordered in ascending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `ContId` from the `continents` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT ContId\nFROM continents\nORDER BY ContId ASC;\n```","cost":0.0004563,"response_parsed":"SELECT ContId\nFROM continents\nORDER BY ContId ASC;","time":2.3897979259}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ContId` FROM `continents` ORDER BY `ContId` DESC","question":"Project the ContId ordered in descending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `ContId` from the `continents` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT ContId FROM continents ORDER BY ContId DESC;\n```","cost":0.0004923,"response_parsed":"SELECT ContId FROM continents ORDER BY ContId DESC;","time":2.8043272495}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Continent` FROM `continents` ORDER BY `Continent` ASC","question":"Project the Continent ordered in ascending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Continent` from the `continents` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Continent FROM continents ORDER BY Continent ASC;\n```\n\nThis query selects the `Continent` column from the `continents` table and sorts the results in ascending alphabetical order.","cost":0.0005535,"response_parsed":"SELECT Continent FROM continents ORDER BY Continent ASC;","time":3.8587033749}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Continent` FROM `continents` ORDER BY `Continent` DESC","question":"Project the Continent ordered in descending order for the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Continent` from the `continents` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT \"Continent\" FROM continents ORDER BY \"Continent\" DESC;\n```","cost":0.0004536,"response_parsed":"SELECT \"Continent\" FROM continents ORDER BY \"Continent\" DESC;","time":2.4710226059}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_names` ORDER BY `Model` ASC","question":"Show all data ordered by Model in ascending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_names` table ordered by the `Model` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names ORDER BY Model ASC;\n```","cost":0.0005598,"response_parsed":"SELECT * FROM car_names ORDER BY Model ASC;","time":3.6899704933}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_names` ORDER BY `Model` DESC","question":"Show all data ordered by Model in descending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_names` table ordered by the `Model` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_names\nORDER BY Model DESC;\n```","cost":0.0005571,"response_parsed":"SELECT *\nFROM car_names\nORDER BY Model DESC;","time":3.6049120426}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_names` ORDER BY `Make` ASC","question":"Show all data ordered by Make in ascending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_names` table ordered by the `Make` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_names\nORDER BY Make ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `car_names` table.\n2. Order the results by the `Make` column in ascending order (`ASC`).","cost":0.0005913,"response_parsed":"SELECT *\nFROM car_names\nORDER BY Make ASC;","time":3.9204089642}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `car_names` ORDER BY `Make` DESC","question":"Show all data ordered by Make in descending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `car_names` table ordered by the `Make` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_names\nORDER BY Make DESC;\n```\n\nThis query will return all rows from the `car_names` table, sorted by the `Make` column in descending alphabetical order.","cost":0.0005616,"response_parsed":"SELECT *\nFROM car_names\nORDER BY Make DESC;","time":3.7923822403}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `MakeId` FROM `car_names` ORDER BY `MakeId` ASC","question":"Project the MakeId ordered in ascending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `MakeId` from the `car_names` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT MakeId FROM car_names ORDER BY MakeId ASC;\n```","cost":0.0005904,"response_parsed":"SELECT MakeId FROM car_names ORDER BY MakeId ASC;","time":3.9456167221}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `MakeId` FROM `car_names` ORDER BY `MakeId` DESC","question":"Project the MakeId ordered in descending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `MakeId` from the `car_names` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT MakeId\nFROM car_names\nORDER BY MakeId DESC;\n```","cost":0.0004671,"response_parsed":"SELECT MakeId\nFROM car_names\nORDER BY MakeId DESC;","time":2.4986963272}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Model` FROM `car_names` ORDER BY `Model` ASC","question":"Project the Model ordered in ascending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the Model in ascending order from the car_names table, you can use the following SQL query:\n\n```sql\nSELECT Model FROM car_names ORDER BY Model ASC;\n```\n\nThis query selects the Model column from the car_names table and sorts the results in ascending order based on the Model values.","cost":0.0005877,"response_parsed":"SELECT Model FROM car_names ORDER BY Model ASC;","time":4.0557451248}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Model` FROM `car_names` ORDER BY `Model` DESC","question":"Project the Model ordered in descending order for the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Model` column from the `car_names` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Model FROM car_names ORDER BY Model DESC;\n```\n\nThis query will return the `Model` column from the `car_names` table, sorted in descending alphabetical order.","cost":0.000657,"response_parsed":"SELECT Model FROM car_names ORDER BY Model DESC;","time":4.9666771889}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `model_list` ORDER BY `Model` ASC","question":"Show all data ordered by Model in ascending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `model_list` table ordered by the `Model` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nORDER BY Model ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `model_list` table.\n2. Order the results by the `Model` column in ascending order (`ASC`).\n\nThe `ASC` keyword is optional since ascending order is the default for the `ORDER BY` clause, but it is included here for clarity.","cost":0.0005679,"response_parsed":"SELECT *\nFROM model_list\nORDER BY Model ASC;","time":3.7454636097}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `model_list` ORDER BY `Model` DESC","question":"Show all data ordered by Model in descending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `model_list` table ordered by the `Model` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nORDER BY Model DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `model_list` table.\n2. Order the results by the `Model` column in descending order (`DESC`).","cost":0.0004986,"response_parsed":"SELECT *\nFROM model_list\nORDER BY Model DESC;","time":2.9772174358}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `model_list` ORDER BY `Maker` ASC","question":"Show all data ordered by Maker in ascending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `model_list` table ordered by the `Maker` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nORDER BY Maker ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `model_list` table.\n2. Order the results by the `Maker` column in ascending order (`ASC`).","cost":0.0005553,"response_parsed":"SELECT *\nFROM model_list\nORDER BY Maker ASC;","time":3.5650279522}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `model_list` ORDER BY `Maker` DESC","question":"Show all data ordered by Maker in descending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `model_list` table ordered by the `Maker` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nORDER BY Maker DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `model_list` table.\n2. Order the results by the `Maker` column in descending order (`DESC`).","cost":0.0005634,"response_parsed":"SELECT *\nFROM model_list\nORDER BY Maker DESC;","time":3.746070385}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ModelId` FROM `model_list` ORDER BY `ModelId` ASC","question":"Project the ModelId ordered in ascending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `ModelId` from the `model_list` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT ModelId\nFROM model_list\nORDER BY ModelId ASC;\n```\n\nThis query will:\n1. Select the `ModelId` column from the `model_list` table.\n2. Order the results in ascending order based on the `ModelId`.","cost":0.0005751,"response_parsed":"SELECT ModelId\nFROM model_list\nORDER BY ModelId ASC;","time":3.9303050041}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ModelId` FROM `model_list` ORDER BY `ModelId` DESC","question":"Project the ModelId ordered in descending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `ModelId` from the `model_list` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT ModelId\nFROM model_list\nORDER BY ModelId DESC;\n```\n\nThis query will:\n1. Select the `ModelId` column from the `model_list` table.\n2. Order the results in descending order based on the `ModelId`.","cost":0.0005526,"response_parsed":"SELECT ModelId\nFROM model_list\nORDER BY ModelId DESC;","time":3.6147174835}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Model` FROM `model_list` ORDER BY `Model` ASC","question":"Project the Model ordered in ascending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Model` column from the `model_list` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Model \nFROM model_list \nORDER BY Model ASC;\n```","cost":0.0004455,"response_parsed":"SELECT Model \nFROM model_list \nORDER BY Model ASC;","time":2.2528688908}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Model` FROM `model_list` ORDER BY `Model` DESC","question":"Project the Model ordered in descending order for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Model` column from the `model_list` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Model FROM model_list ORDER BY Model DESC;\n```","cost":0.0005202,"response_parsed":"SELECT Model FROM model_list ORDER BY Model DESC;","time":3.3052284718}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `cars_data` ORDER BY `Edispl` ASC","question":"Show all data ordered by Edispl in ascending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `cars_data` table ordered by the `Edispl` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data ORDER BY Edispl ASC;\n```","cost":0.0006345,"response_parsed":"SELECT * FROM cars_data ORDER BY Edispl ASC;","time":4.1026682854}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `cars_data` ORDER BY `Edispl` DESC","question":"Show all data ordered by Edispl in descending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `cars_data` table ordered by the `Edispl` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nORDER BY Edispl DESC;\n```","cost":0.0005166,"response_parsed":"SELECT *\nFROM cars_data\nORDER BY Edispl DESC;","time":2.9137349129}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `cars_data` ORDER BY `MPG` ASC","question":"Show all data ordered by MPG in ascending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `cars_data` table ordered by MPG in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nORDER BY MPG ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `cars_data` table.\n2. Order the results by the `MPG` column in ascending order (`ASC`).","cost":0.0006003,"response_parsed":"SELECT *\nFROM cars_data\nORDER BY MPG ASC;","time":3.838180542}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `cars_data` ORDER BY `MPG` DESC","question":"Show all data ordered by MPG in descending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all data from the `cars_data` table ordered by MPG in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nORDER BY CAST(MPG AS REAL) DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `cars_data` table.\n2. Order the results by the `MPG` column in descending order. The `CAST(MPG AS REAL)` is used to ensure proper numerical sorting, as the `MPG` column is stored as a TEXT type in the schema.","cost":0.0006957,"response_parsed":"SELECT *\nFROM cars_data\nORDER BY CAST(MPG AS REAL) DESC;","time":4.8021059036}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Id` FROM `cars_data` ORDER BY `Id` ASC","question":"Project the Id ordered in ascending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Id` from the `cars_data` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Id FROM cars_data ORDER BY Id ASC;\n```","cost":0.0004698,"response_parsed":"SELECT Id FROM cars_data ORDER BY Id ASC;","time":2.7515285015}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Id` FROM `cars_data` ORDER BY `Id` DESC","question":"Project the Id ordered in descending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the `Id` from the `cars_data` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Id FROM cars_data ORDER BY Id DESC;\n```","cost":0.0005094,"response_parsed":"SELECT Id FROM cars_data ORDER BY Id DESC;","time":3.1665456295}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Accelerate` FROM `cars_data` ORDER BY `Accelerate` ASC","question":"Project the Accelerate ordered in ascending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the \"Accelerate\" column from the \"cars_data\" table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Accelerate\nFROM cars_data\nORDER BY Accelerate ASC;\n```","cost":0.0004815,"response_parsed":"SELECT Accelerate\nFROM cars_data\nORDER BY Accelerate ASC;","time":2.5205359459}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Accelerate` FROM `cars_data` ORDER BY `Accelerate` DESC","question":"Project the Accelerate ordered in descending order for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo project the \"Accelerate\" column from the \"cars_data\" table and order it in descending order, you can use the following SQL query:\n\n```sql\nSELECT Accelerate \nFROM cars_data \nORDER BY Accelerate DESC;\n```","cost":0.0004851,"response_parsed":"SELECT Accelerate \nFROM cars_data \nORDER BY Accelerate DESC;","time":2.7630517483}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Id` FROM `car_makers`","question":"Show all Id in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `Id` from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Id FROM car_makers;\n```","cost":0.0005625,"response_parsed":"SELECT Id FROM car_makers;","time":3.6830801964}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Maker` FROM `car_makers`","question":"Show all Maker in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the Maker entries from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Maker FROM car_makers;\n```","cost":0.000576,"response_parsed":"SELECT Maker FROM car_makers;","time":4.0043420792}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `FullName` FROM `car_makers`","question":"Show all FullName in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `FullName` entries from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT FullName FROM car_makers;\n```","cost":0.000558,"response_parsed":"SELECT FullName FROM car_makers;","time":3.869571209}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Country` FROM `car_makers`","question":"Show all Country in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all countries from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Country FROM car_makers;\n```\n\nThis query will return all the country names stored in the `Country` column of the `car_makers` table.","cost":0.0005202,"response_parsed":"SELECT Country FROM car_makers;","time":3.2815468311}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `car_makers`","question":"Show all the rows in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all rows from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers;\n```","cost":0.0005229,"response_parsed":"SELECT * FROM car_makers;","time":3.4381971359}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Maker` FROM `car_makers`","question":"Show all Maker in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all makers from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Maker FROM car_makers;\n```","cost":0.0004806,"response_parsed":"SELECT Maker FROM car_makers;","time":3.0299413204}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `FullName`, `Id` FROM `car_makers`","question":"Show all FullName, Id in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `FullName` and `Id` from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT Id, FullName FROM car_makers;\n```","cost":0.0005328,"response_parsed":"SELECT Id, FullName FROM car_makers;","time":3.4477934837}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `FullName`, `Country`, `Maker` FROM `car_makers`","question":"Show all FullName, Country, Maker in the table car_makers","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `FullName`, `Country`, and `Maker` from the `car_makers` table, you can use the following SQL query:\n\n```sql\nSELECT FullName, Country, Maker FROM car_makers;\n```\n\nThis query will return all rows from the `car_makers` table with the specified columns.","cost":0.0007353,"response_parsed":"SELECT FullName, Country, Maker FROM car_makers;","time":5.546769619}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `CountryId` FROM `countries`","question":"Show all CountryId in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `CountryId` from the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT CountryId FROM countries;\n```\n\nThis query will return all the `CountryId` values present in your `countries` table.","cost":0.0005319,"response_parsed":"SELECT CountryId FROM countries;","time":3.1498165131}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `CountryName` FROM `countries`","question":"Show all CountryName in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `CountryName` from the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT CountryName FROM countries;\n```","cost":0.0005022,"response_parsed":"SELECT CountryName FROM countries;","time":3.2585361004}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Continent` FROM `countries`","question":"Show all Continent in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all continents from the `countries` table, you can use the following SQL query. Note that the `countries` table does not directly store continent names but instead stores continent IDs that reference the `continents` table. Therefore, we need to join the `countries` table with the `continents` table to get the actual continent names.\n\n```sql\nSELECT DISTINCT c.Continent\nFROM countries\nJOIN continents c ON countries.Continent = c.ContId;\n```\n\nThis query will return all unique continent names associated with the countries in your database.","cost":0.0007884,"response_parsed":"SELECT DISTINCT c.Continent\nFROM countries\nJOIN continents c ON countries.Continent = c.ContId;","time":6.3378651142}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `countries`","question":"Show all the rows in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show all the rows in the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries;\n```\n\nThis query will retrieve all rows and columns from the `countries` table.","cost":0.0005031,"response_parsed":"SELECT * FROM countries;","time":3.32797122}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `CountryId` FROM `countries`","question":"Show all CountryId in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `CountryId` from the `countries` table, you can use the following SQL query:\n\n```sql\nSELECT CountryId FROM countries;\n```\n\nThis query will return all the `CountryId` values present in your `countries` table.","cost":0.0005382,"response_parsed":"SELECT CountryId FROM countries;","time":3.6060712337}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Continent`, `CountryName` FROM `countries`","question":"Show all Continent, CountryName in the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all Continent and CountryName from the `countries` table, you need to join the `countries` table with the `continents` table since the `Continent` field in the `countries` table is a foreign key referencing the `ContId` in the `continents` table.\n\nHere is the SQL code:\n\n```sql\nSELECT c.Continent, co.CountryName\nFROM countries co\nINNER JOIN continents c\nON co.Continent = c.ContId;\n```\n\nThis query will return all Continent names along with their corresponding CountryName from the `countries` table.","cost":0.0005247,"response_parsed":"SELECT c.Continent, co.CountryName\nFROM countries co\nINNER JOIN continents c\nON co.Continent = c.ContId;","time":3.5137174129}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `ContId` FROM `continents`","question":"Show all ContId in the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `ContId` from the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT ContId FROM continents;\n```","cost":0.0005454,"response_parsed":"SELECT ContId FROM continents;","time":3.542422533}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Continent` FROM `continents`","question":"Show all Continent in the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all continents from the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT Continent FROM continents;\n```\n\nThis query will return all the continent names stored in the `Continent` column of the `continents` table.","cost":0.0005778,"response_parsed":"SELECT Continent FROM continents;","time":4.0210089684}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `continents`","question":"Show all the rows in the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show all the rows in the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM continents;\n```\n\nThis query will return all columns (`ContId` and `Continent`) for every row in the `continents` table.","cost":0.0005841,"response_parsed":"SELECT * FROM continents;","time":4.2636287212}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `ContId` FROM `continents`","question":"Show all ContId in the table continents","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `ContId` from the `continents` table, you can use the following SQL query:\n\n```sql\nSELECT ContId FROM continents;\n```","cost":0.0005652,"response_parsed":"SELECT ContId FROM continents;","time":3.7856934071}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `MakeId` FROM `car_names`","question":"Show all MakeId in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `MakeId` from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT MakeId FROM car_names;\n```","cost":0.0005364,"response_parsed":"SELECT MakeId FROM car_names;","time":3.1974515915}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Model` FROM `car_names`","question":"Show all Model in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all models from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT \"Model\" FROM \"car_names\";\n```\n\nThis query will return all unique model names from the `car_names` table.","cost":0.0005058,"response_parsed":"SELECT DISTINCT \"Model\" FROM \"car_names\";","time":3.2305808067}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Make` FROM `car_names`","question":"Show all Make in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the \"Make\" entries from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT Make FROM car_names;\n```\n\nThis query will return all the distinct \"Make\" values present in the `car_names` table.","cost":0.0005346,"response_parsed":"SELECT Make FROM car_names;","time":3.381654501}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `car_names`","question":"Show all the rows in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show all the rows in the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names;\n```\n\nThis query will return all columns (`MakeId`, `Model`, and `Make`) for every row in the `car_names` table.","cost":0.0005328,"response_parsed":"SELECT * FROM car_names;","time":3.509172678}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Make` FROM `car_names`","question":"Show all Make in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the \"Make\" entries from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT Make FROM car_names;\n```","cost":0.0005184,"response_parsed":"SELECT Make FROM car_names;","time":3.3167889118}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `MakeId`, `Model` FROM `car_names`","question":"Show all MakeId, Model in the table car_names","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `MakeId` and `Model` from the `car_names` table, you can use the following SQL query:\n\n```sql\nSELECT MakeId, Model FROM car_names;\n```\n\nThis query will return all rows in the `car_names` table, displaying only the `MakeId` and `Model` columns.","cost":0.0005661,"response_parsed":"SELECT MakeId, Model FROM car_names;","time":4.6981203556}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `ModelId` FROM `model_list`","question":"Show all ModelId in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `ModelId` from the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT ModelId FROM model_list;\n```","cost":0.0004644,"response_parsed":"SELECT ModelId FROM model_list;","time":3.1296255589}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Maker` FROM `model_list`","question":"Show all Maker in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the makers from the `model_list` table, you can use the following SQL query. Note that the `Maker` in `model_list` is a foreign key that references the `Id` in the `car_makers` table, so we need to join these tables to get the actual maker names.\n\n```sql\nSELECT DISTINCT car_makers.Maker\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;\n```\n\nThis query will return all unique maker names from the `model_list` table.","cost":0.0006165,"response_parsed":"SELECT DISTINCT car_makers.Maker\nFROM model_list\nINNER JOIN car_makers\nON model_list.Maker = car_makers.Id;","time":4.6534981728}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Model` FROM `model_list`","question":"Show all Model in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all models from the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT Model FROM model_list;\n```","cost":0.0004932,"response_parsed":"SELECT Model FROM model_list;","time":3.1509876251}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `model_list`","question":"Show all the rows in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show all the rows in the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM model_list;\n```\n\nThis query will return all columns (`ModelId`, `Maker`, and `Model`) for every row in the `model_list` table.","cost":0.00045,"response_parsed":"SELECT * FROM model_list;","time":2.7406811714}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `ModelId` FROM `model_list`","question":"Show all ModelId in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `ModelId` from the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT ModelId FROM model_list;\n```","cost":0.0005283,"response_parsed":"SELECT ModelId FROM model_list;","time":3.4967205524}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Maker`, `Model` FROM `model_list`","question":"Show all Maker, Model in the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all Maker and Model from the `model_list` table, you can use the following SQL query:\n\n```sql\nSELECT Maker, Model \nFROM model_list;\n```\n\nThis query will return all rows from the `model_list` table, showing the Maker and Model columns.","cost":0.0005418,"response_parsed":"SELECT Maker, Model \nFROM model_list;","time":3.542304039}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Year` FROM `cars_data`","question":"Show all Year in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the years from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Year FROM cars_data;\n```","cost":0.0004806,"response_parsed":"SELECT Year FROM cars_data;","time":2.9550499916}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Accelerate` FROM `cars_data`","question":"Show all Accelerate in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the \"Accelerate\" values from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Accelerate AS Acceleration FROM cars_data ORDER BY Accelerate ASC;\n```\n\nThis query:\n1. Selects the `Accelerate` column from the `cars_data` table.\n2. Uses `AS Acceleration` to alias the column for better readability.\n3. Orders the results in ascending order based on the `Accelerate` values.","cost":0.0006885,"response_parsed":"SELECT Accelerate AS Acceleration FROM cars_data ORDER BY Accelerate ASC;","time":5.0613808632}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Weight` FROM `cars_data`","question":"Show all Weight in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the \"Weight\" values from the \"cars_data\" table, you can use the following SQL query:\n\n```sql\nSELECT Weight FROM cars_data;\n```","cost":0.0005517,"response_parsed":"SELECT Weight FROM cars_data;","time":3.5721783638}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Id` FROM `cars_data`","question":"Show all Id in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all `Id` from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Id FROM cars_data;\n```","cost":0.0005013,"response_parsed":"SELECT Id FROM cars_data;","time":2.8957023621}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Horsepower` FROM `cars_data`","question":"Show all Horsepower in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all the Horsepower values from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Horsepower FROM cars_data;\n```","cost":0.0005652,"response_parsed":"SELECT Horsepower FROM cars_data;","time":3.614923954}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `cars_data`","question":"Show all the rows in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo show all the rows in the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data;\n```\n\nThis query will return all columns (`*`) for every row in the `cars_data` table.","cost":0.0004869,"response_parsed":"SELECT * FROM cars_data;","time":2.7571415901}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `MPG` FROM `cars_data`","question":"Show all MPG in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch all MPG values from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT MPG FROM cars_data;\n```\n\nThis query will return all the MPG values stored in the `cars_data` table.","cost":0.0005193,"response_parsed":"SELECT MPG FROM cars_data;","time":3.0568788052}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Year`, `Id` FROM `cars_data`","question":"Show all Year, Id in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `Year` and `Id` from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Year, Id FROM cars_data;\n```","cost":0.0005913,"response_parsed":"SELECT Year, Id FROM cars_data;","time":4.1462225914}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Id`, `MPG`, `Weight` FROM `cars_data`","question":"Show all Id, MPG, Weight in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the `Id`, `MPG`, and `Weight` from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Id, MPG, Weight FROM cars_data;\n```","cost":0.0005319,"response_parsed":"SELECT Id, MPG, Weight FROM cars_data;","time":3.3745188713}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Edispl`, `Cylinders`, `Year`, `Horsepower` FROM `cars_data`","question":"Show all Edispl, Cylinders, Year, Horsepower in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the specified columns from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Edispl, Cylinders, Year, Horsepower FROM cars_data;\n```","cost":0.0005094,"response_parsed":"SELECT Edispl, Cylinders, Year, Horsepower FROM cars_data;","time":3.2204189301}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Year`, `Cylinders`, `Accelerate`, `Edispl`, `MPG` FROM `cars_data`","question":"Show all Year, Cylinders, Accelerate, Edispl, MPG in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the specified columns from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Year, Cylinders, Accelerate, Edispl, MPG\nFROM cars_data;\n```\n\nThis query will return all rows with the columns `Year`, `Cylinders`, `Accelerate`, `Edispl`, and `MPG` from the `cars_data` table.","cost":0.0006039,"response_parsed":"SELECT Year, Cylinders, Accelerate, Edispl, MPG\nFROM cars_data;","time":4.1008117199}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Weight`, `Cylinders`, `Accelerate`, `MPG`, `Horsepower`, `Id` FROM `cars_data`","question":"Show all Weight, Cylinders, Accelerate, MPG, Horsepower, Id in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the specified columns from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Weight, Cylinders, Accelerate, MPG, Horsepower, Id \nFROM cars_data;\n```\n\nThis query selects the columns `Weight`, `Cylinders`, `Accelerate`, `MPG`, `Horsepower`, and `Id` from the `cars_data` table and returns all rows.","cost":0.0006651,"response_parsed":"SELECT Weight, Cylinders, Accelerate, MPG, Horsepower, Id \nFROM cars_data;","time":4.3272001743}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Year`, `Weight`, `Cylinders`, `Accelerate`, `Horsepower`, `MPG`, `Id` FROM `cars_data`","question":"Show all Year, Weight, Cylinders, Accelerate, Horsepower, MPG, Id in the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the specified columns from the `cars_data` table, you can use the following SQL query:\n\n```sql\nSELECT Year, Weight, Cylinders, Accelerate, Horsepower, MPG, Id\nFROM cars_data;\n```","cost":0.000567,"response_parsed":"SELECT Year, Weight, Cylinders, Accelerate, Horsepower, MPG, Id\nFROM cars_data;","time":3.5536859035}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Maker` == 'bmw'","question":"Show the data of the table car_makers where Maker is equal to bmw","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Maker` is \"bmw\", you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Maker = 'bmw';\n```","cost":0.0005427,"response_parsed":"SELECT * FROM car_makers WHERE Maker = 'bmw';","time":3.4191675186}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Maker` != 'volkswagen'","question":"Show the data of the table car_makers where Maker is different from volkswagen","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Maker` is different from \"volkswagen\", you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Maker <> 'volkswagen';\n```\n\nThis query will return all rows in the `car_makers` table where the `Maker` column does not contain the value \"volkswagen\".","cost":0.0005994,"response_parsed":"SELECT * FROM car_makers WHERE Maker <> 'volkswagen';","time":3.9015967846}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Maker` != 'ford'","question":"Show the data of the table car_makers where Maker not equal to ford","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Maker` is not equal to \"ford\", you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Maker != 'ford';\n```","cost":0.0005562,"response_parsed":"SELECT * FROM car_makers WHERE Maker != 'ford';","time":4.4774606228}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `FullName` == 'BMW'","question":"Show the data of the table car_makers where FullName is equal to BMW","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where `FullName` is equal to \"BMW\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_makers\nWHERE FullName = 'BMW';\n```","cost":0.0005175,"response_parsed":"SELECT *\nFROM car_makers\nWHERE FullName = 'BMW';","time":3.2458481789}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `FullName` != 'General Motors'","question":"Show the data of the table car_makers where FullName is different from General Motors","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where `FullName` is different from \"General Motors,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM car_makers\nWHERE FullName <> 'General Motors';\n```","cost":0.0006039,"response_parsed":"SELECT *\nFROM car_makers\nWHERE FullName <> 'General Motors';","time":4.5399489403}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `FullName` != 'American Motor Company'","question":"Show the data of the table car_makers where FullName not equal to American Motor Company","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where `FullName` is not equal to \"American Motor Company,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE FullName <> 'American Motor Company';\n```","cost":0.0005823,"response_parsed":"SELECT * FROM car_makers WHERE FullName <> 'American Motor Company';","time":4.4298574924}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Country` == '1'","question":"Show the data of the table car_makers where Country is equal to 1","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Country` is equal to 1, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Country = '1';\n```\n\nThis query will return all rows in the `car_makers` table where the `Country` column matches the value '1'.","cost":0.0006075,"response_parsed":"SELECT * FROM car_makers WHERE Country = '1';","time":4.1811966896}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Country` != '2'","question":"Show the data of the table car_makers where Country is different from 2","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Country` is different from 2, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Country != '2';\n```\n\nThis query will return all rows from the `car_makers` table where the `Country` column is not equal to '2'.","cost":0.0005598,"response_parsed":"SELECT * FROM car_makers WHERE Country != '2';","time":3.4342684746}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_makers` WHERE `Country` != '1'","question":"Show the data of the table car_makers where Country not equal to 1","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_makers` table where the `Country` is not equal to 1, you can use the following SQL query:\n\n```sql\nSELECT * FROM car_makers WHERE Country != 1;\n```\n\nThis query will return all rows in the `car_makers` table where the `Country` column is not equal to 1.","cost":0.0006201,"response_parsed":"SELECT * FROM car_makers WHERE Country != 1;","time":4.1993131638}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `countries` WHERE `CountryName` == 'usa'","question":"Show the data of the table countries where CountryName is equal to usa","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `countries` table where `CountryName` is 'usa', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM countries\nWHERE CountryName = 'usa';\n```","cost":0.0005364,"response_parsed":"SELECT *\nFROM countries\nWHERE CountryName = 'usa';","time":3.1665654182}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `countries` WHERE `CountryName` != 'france'","question":"Show the data of the table countries where CountryName is different from france","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data of the table `countries` where `CountryName` is different from \"France\", you can use the following SQL query:\n\n```sql\nSELECT * FROM countries WHERE CountryName != 'France';\n```","cost":0.0005886,"response_parsed":"SELECT * FROM countries WHERE CountryName != 'France';","time":3.6860496998}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `countries` WHERE `CountryName` != 'japan'","question":"Show the data of the table countries where CountryName not equal to japan","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `countries` table where the `CountryName` is not equal to 'Japan', you can use the following SQL query:\n\n```sql\nSELECT * FROM countries WHERE CountryName != 'Japan';\n```","cost":0.0005409,"response_parsed":"SELECT * FROM countries WHERE CountryName != 'Japan';","time":3.3907847404}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `countries` WHERE `Continent` > 2","question":"Show the data of the table countries where Continent is greater than 2","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `countries` table where the `Continent` is greater than 2, you can use the following SQL query:\n\n```sql\nSELECT * FROM countries WHERE Continent > 2;\n```","cost":0.000603,"response_parsed":"SELECT * FROM countries WHERE Continent > 2;","time":3.9906086922}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `countries` WHERE `Continent` < 2","question":"Show the data of the table countries where Continent is less than 2","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `countries` table where the `Continent` is less than 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM countries\nWHERE Continent < 2;\n```","cost":0.0005319,"response_parsed":"SELECT *\nFROM countries\nWHERE Continent < 2;","time":3.3671934605}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `continents` WHERE `Continent` == 'asia'","question":"Show the data of the table continents where Continent is equal to asia","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `continents` table where the `Continent` is \"asia\", you can use the following SQL query:\n\n```sql\nSELECT * FROM continents WHERE Continent = 'asia';\n```\n\nThis query will return all rows in the `continents` table where the `Continent` column is equal to \"asia\".","cost":0.0005616,"response_parsed":"SELECT * FROM continents WHERE Continent = 'asia';","time":3.5322175026}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `continents` WHERE `Continent` != 'america'","question":"Show the data of the table continents where Continent is different from america","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `continents` table where the `Continent` is different from \"America,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM continents\nWHERE Continent != 'America';\n```","cost":0.0005787,"response_parsed":"SELECT *\nFROM continents\nWHERE Continent != 'America';","time":3.8197147846}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `continents` WHERE `Continent` != 'europe'","question":"Show the data of the table continents where Continent not equal to europe","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `continents` table where the `Continent` is not equal to \"Europe\", you can use the following SQL query:\n\n```sql\nSELECT * FROM continents WHERE Continent != 'Europe';\n```","cost":0.0006246,"response_parsed":"SELECT * FROM continents WHERE Continent != 'Europe';","time":4.4821715355}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Model` == 'plymouth'","question":"Show the data of the table car_names where Model is equal to plymouth","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Model` is \"plymouth\", you can use the following SQL query:\n\n```sql\nSELECT MakeId, Model, Make FROM car_names WHERE Model = 'plymouth';\n```\n\nThis query will return all rows in the `car_names` table where the `Model` column is exactly \"plymouth\".","cost":0.0007164,"response_parsed":"SELECT MakeId, Model, Make FROM car_names WHERE Model = 'plymouth';","time":5.4229421616}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Model` != 'plymouth'","question":"Show the data of the table car_names where Model is different from plymouth","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Model` is different from \"plymouth\", you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names WHERE Model <> 'plymouth';\n```","cost":0.0006102,"response_parsed":"SELECT * FROM car_names WHERE Model <> 'plymouth';","time":4.2680523396}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Model` != 'buick'","question":"Show the data of the table car_names where Model not equal to buick","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Model` is not equal to 'buick', you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names WHERE Model != 'buick';\n```","cost":0.0005778,"response_parsed":"SELECT * FROM car_names WHERE Model != 'buick';","time":3.6334664822}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Make` == 'amc rebel sst'","question":"Show the data of the table car_names where Make is equal to amc rebel sst","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Make` is \"amc rebel sst\", you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names WHERE Make = 'amc rebel sst';\n```","cost":0.0005796,"response_parsed":"SELECT * FROM car_names WHERE Make = 'amc rebel sst';","time":3.9415664673}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Make` != 'buick skylark 320'","question":"Show the data of the table car_names where Make is different from buick skylark 320","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Make` is different from 'buick skylark 320', you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names WHERE Make != 'buick skylark 320';\n```","cost":0.000504,"response_parsed":"SELECT * FROM car_names WHERE Make != 'buick skylark 320';","time":3.0424339771}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `car_names` WHERE `Make` != 'buick skylark 320'","question":"Show the data of the table car_names where Make not equal to buick skylark 320","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `car_names` table where the `Make` is not equal to 'buick skylark 320', you can use the following SQL query:\n\n```sql\nSELECT * FROM car_names WHERE Make != 'buick skylark 320';\n```","cost":0.0006183,"response_parsed":"SELECT * FROM car_names WHERE Make != 'buick skylark 320';","time":4.6009223461}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `model_list` WHERE `Model` == 'amc'","question":"Show the data of the table model_list where Model is equal to amc","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `model_list` table where the `Model` is equal to 'amc', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nWHERE Model = 'amc';\n```","cost":0.0005121,"response_parsed":"SELECT *\nFROM model_list\nWHERE Model = 'amc';","time":3.0938005447}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `model_list` WHERE `Model` != 'buick'","question":"Show the data of the table model_list where Model is different from buick","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `model_list` table where the `Model` is different from \"buick\", you can use the following SQL query:\n\n```sql\nSELECT * FROM model_list WHERE Model != 'buick';\n```","cost":0.0004977,"response_parsed":"SELECT * FROM model_list WHERE Model != 'buick';","time":2.9323139191}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `model_list` WHERE `Model` != 'bmw'","question":"Show the data of the table model_list where Model not equal to bmw","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `model_list` table where the `Model` is not equal to \"bmw\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nWHERE Model <> 'bmw';\n```","cost":0.0004977,"response_parsed":"SELECT *\nFROM model_list\nWHERE Model <> 'bmw';","time":2.9004852772}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `model_list` WHERE `Maker` > 4","question":"Show the data of the table model_list where Maker is greater than 4","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `model_list` table where the `Maker` is greater than 4, you can use the following SQL query:\n\n```sql\nSELECT * FROM model_list WHERE Maker > 4;\n```","cost":0.0005274,"response_parsed":"SELECT * FROM model_list WHERE Maker > 4;","time":2.9876928329}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `model_list` WHERE `Maker` < 3","question":"Show the data of the table model_list where Maker is less than 3","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `model_list` table where the `Maker` is less than 3, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM model_list\nWHERE Maker < 3;\n```","cost":0.0005292,"response_parsed":"SELECT *\nFROM model_list\nWHERE Maker < 3;","time":3.2936217785}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `MPG` == '14'","question":"Show the data of the table cars_data where MPG is equal to 14","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where `MPG` is equal to 14, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data WHERE MPG = '14';\n```\n\nThis query will return all rows in the `cars_data` table where the `MPG` column has a value of 14.","cost":0.0006462,"response_parsed":"SELECT * FROM cars_data WHERE MPG = '14';","time":4.4735708237}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `MPG` != '18'","question":"Show the data of the table cars_data where MPG is different from 18","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `MPG` is different from 18, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE MPG != '18';\n```\n\nThis query will return all rows from the `cars_data` table where the `MPG` value is not equal to 18.","cost":0.0007146,"response_parsed":"SELECT *\nFROM cars_data\nWHERE MPG != '18';","time":5.272040844}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `MPG` != '17'","question":"Show the data of the table cars_data where MPG not equal to 17","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `MPG` is not equal to 17, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data WHERE MPG != '17';\n```\n\nThis query will return all rows from the `cars_data` table where the `MPG` column does not contain the value '17'.","cost":0.0006831,"response_parsed":"SELECT * FROM cars_data WHERE MPG != '17';","time":4.9451413155}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `Horsepower` == '198'","question":"Show the data of the table cars_data where Horsepower is equal to 198","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `Horsepower` is equal to 198, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE Horsepower = 198;\n```","cost":0.0005319,"response_parsed":"SELECT *\nFROM cars_data\nWHERE Horsepower = 198;","time":3.2970421314}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `Horsepower` != '130'","question":"Show the data of the table cars_data where Horsepower is different from 130","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `Horsepower` is different from 130, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE Horsepower != '130';\n```\n\nThis query will return all rows in the `cars_data` table where the `Horsepower` value is not equal to 130.","cost":0.0006084,"response_parsed":"SELECT *\nFROM cars_data\nWHERE Horsepower != '130';","time":3.927937746}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `cars_data` WHERE `Horsepower` != '150'","question":"Show the data of the table cars_data where Horsepower not equal to 150","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `Horsepower` is not equal to 150, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE Horsepower != '150';\n```\n\nThis query will return all rows from the `cars_data` table where the `Horsepower` column is not equal to 150. Note that since `Horsepower` is of type `TEXT` in the schema, the value 150 is enclosed in quotes.","cost":0.0006822,"response_parsed":"SELECT *\nFROM cars_data\nWHERE Horsepower != '150';","time":4.6050877571}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `cars_data` WHERE `Accelerate` > 11.5","question":"Show the data of the table cars_data where Accelerate is greater than 11.5","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `Accelerate` column is greater than 11.5, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE Accelerate > 11.5;\n```\n\nThis query will return all rows in the `cars_data` table where the value in the `Accelerate` column is greater than 11.5.","cost":0.0006264,"response_parsed":"SELECT *\nFROM cars_data\nWHERE Accelerate > 11.5;","time":4.122594595}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `cars_data` WHERE `Accelerate` < 10.5","question":"Show the data of the table cars_data where Accelerate is less than 10.5","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the `Accelerate` value is less than 10.5, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data WHERE Accelerate < 10.5;\n```","cost":0.0006624,"response_parsed":"SELECT * FROM cars_data WHERE Accelerate < 10.5;","time":4.4781093597}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `cars_data` WHERE `Edispl` > 302.0","question":"Show the data of the table cars_data where Edispl is greater than 302.0","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where `Edispl` is greater than 302.0, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data WHERE Edispl > 302.0;\n```","cost":0.0005652,"response_parsed":"SELECT * FROM cars_data WHERE Edispl > 302.0;","time":3.3571989536}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `cars_data` WHERE `Edispl` < 350.0","question":"Show the data of the table cars_data where Edispl is less than 350.0","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where `Edispl` is less than 350.0, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM cars_data\nWHERE Edispl < 350.0;\n```\n\nThis query will return all rows in the `cars_data` table where the value in the `Edispl` column is less than 350.0.","cost":0.0006579,"response_parsed":"SELECT *\nFROM cars_data\nWHERE Edispl < 350.0;","time":4.5042538643}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `cars_data` WHERE `Cylinders` < 8","question":"Show the data of the table cars_data where Cylinders is less than 8","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo fetch the data from the `cars_data` table where the number of `Cylinders` is less than 8, you can use the following SQL query:\n\n```sql\nSELECT * FROM cars_data WHERE Cylinders < 8;\n```","cost":0.0006129,"response_parsed":"SELECT * FROM cars_data WHERE Cylinders < 8;","time":3.8080251217}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Maker`) FROM `car_makers`","question":"How many different Maker are in table car_makers?","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different makers are in the `car_makers` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in the `Maker` column.\n\n```sql\nSELECT COUNT(DISTINCT Maker) FROM car_makers;\n```","cost":0.0005499,"response_parsed":"SELECT COUNT(DISTINCT Maker) FROM car_makers;","time":3.3724358082}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `FullName`) FROM `car_makers`","question":"How many different FullName are in table car_makers?","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different `FullName` values exist in the `car_makers` table, you can use the `COUNT(DISTINCT)` function in SQL. Here's the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT FullName) AS NumberOfFullNames \nFROM car_makers;\n```\n\nThis query will count the number of unique `FullName` values in the `car_makers` table and return the result under the alias `NumberOfFullNames`.","cost":0.000639,"response_parsed":"SELECT COUNT(DISTINCT FullName) AS NumberOfFullNames \nFROM car_makers;","time":4.5134150982}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_makers","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Country`) FROM `car_makers`","question":"How many different Country are in table car_makers?","db_schema_normalized":"`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different countries are listed in the `car_makers` table, you can use the `COUNT(DISTINCT)` function on the `Country` column. Here's the SQL code:\n\n```sql\nSELECT COUNT(DISTINCT Country) FROM car_makers;\n```","cost":0.0005868,"response_parsed":"SELECT COUNT(DISTINCT Country) FROM car_makers;","time":4.0488262177}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `CountryName`) FROM `countries`","question":"How many different CountryName are in table countries?","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different `CountryName` entries are in the `countries` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT CountryName) FROM countries;\n```","cost":0.0005382,"response_parsed":"SELECT COUNT(DISTINCT CountryName) FROM countries;","time":3.451849699}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Continent`) FROM `countries`","question":"Find the maximum Continent for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the continent with the most countries, we'll join the `countries` and `continents` tables, count the countries per continent, and identify the continent with the highest count.\n\n```sql\nSELECT c.Continent, COUNT(co.CountryId) as CountryCount\nFROM countries co\nJOIN continents c ON co.Continent = c.ContId\nGROUP BY c.Continent\nORDER BY CountryCount DESC\nLIMIT 1;\n```","cost":0.0008658,"response_parsed":"SELECT c.Continent, COUNT(co.CountryId) as CountryCount\nFROM countries co\nJOIN continents c ON co.Continent = c.ContId\nGROUP BY c.Continent\nORDER BY CountryCount DESC\nLIMIT 1;","time":7.5093359947}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Continent`) FROM `countries`","question":"Find the minimum Continent for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum value in the `Continent` column of the `countries` table, you can use the `MIN()` function in SQL. Here's how you can do it:\n\n```sql\nSELECT MIN(Continent) FROM countries;\n```\n\nThis query will return the smallest value in the `Continent` column of your `countries` table.","cost":0.0006579,"response_parsed":"SELECT MIN(Continent) FROM countries;","time":4.873239994}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"countries","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Continent`) FROM `countries`","question":"Find the average Continent for the table countries","db_schema_normalized":"`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average value of the `Continent` column in the `countries` table, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Continent) AS AverageContinent FROM countries;\n```\n\nThis query will return the average value of the `Continent` column in the `countries` table. The `AVG()` function calculates the average of the numeric values in the specified column.","cost":0.0006381,"response_parsed":"SELECT AVG(Continent) AS AverageContinent FROM countries;","time":4.5991363525}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"continents","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Continent`) FROM `continents`","question":"How many different Continent are in table continents?","db_schema_normalized":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different continents are in the `continents` table, you can use the `COUNT(DISTINCT)` function to count the unique values in the `Continent` column.\n\n```sql\nSELECT COUNT(DISTINCT Continent) AS NumberOfContinents\nFROM continents;\n```","cost":0.0005463,"response_parsed":"SELECT COUNT(DISTINCT Continent) AS NumberOfContinents\nFROM continents;","time":3.5551714897}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Model`) FROM `car_names`","question":"How many different Model are in table car_names?","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different models are in the `car_names` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. Here's the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Model) FROM car_names;\n```","cost":0.0005517,"response_parsed":"SELECT COUNT(DISTINCT Model) FROM car_names;","time":3.4200274944}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"car_names","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Make`) FROM `car_names`","question":"How many different Make are in table car_names?","db_schema_normalized":"`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different \"Make\" entries exist in the `car_names` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Make) FROM car_names;\n```","cost":0.0006372,"response_parsed":"SELECT COUNT(DISTINCT Make) FROM car_names;","time":4.716603756}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Model`) FROM `model_list`","question":"How many different Model are in table model_list?","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different models are in the `model_list` table, you can use the `COUNT` function on the `Model` column, which is marked as `UNIQUE` in the schema. Here's the SQL query:\n\n```sql\nSELECT COUNT(Model) \nFROM model_list\nWHERE Model IS NOT NULL;\n```\n\nThis query will return the number of distinct models in your `model_list` table.","cost":0.0005778,"response_parsed":"SELECT COUNT(Model) \nFROM model_list\nWHERE Model IS NOT NULL;","time":4.0651404858}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Maker`) FROM `model_list`","question":"Find the maximum Maker for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum Maker for the table `model_list`, you can use the SQL `MAX()` function on the `Maker` column. Here's how you can do it:\n\n```sql\nSELECT MAX(Maker) FROM model_list;\n```","cost":0.0005697,"response_parsed":"SELECT MAX(Maker) FROM model_list;","time":3.9520859718}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Maker`) FROM `model_list`","question":"Find the minimum Maker for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum Maker for the table `model_list`, you can use the SQL `MIN()` function on the `Maker` column. Here's the SQL code:\n\n```sql\nSELECT MIN(Maker) FROM model_list;\n```","cost":0.0006255,"response_parsed":"SELECT MIN(Maker) FROM model_list;","time":4.3352079391}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"model_list","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Maker`) FROM `model_list`","question":"Find the average Maker for the table model_list","db_schema_normalized":"`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average Maker for the table `model_list`, we need to calculate the average value of the `Maker` column in that table. Here's the SQL query to accomplish this:\n\n```sql\nSELECT AVG(Maker) AS Average_Maker\nFROM model_list;\n```\n\nThis query will return the average value of the `Maker` column in the `model_list` table. The result will be aliased as `Average_Maker` for clarity.","cost":0.0006912,"response_parsed":"SELECT AVG(Maker) AS Average_Maker\nFROM model_list;","time":4.9408071041}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `MPG`) FROM `cars_data`","question":"How many different MPG are in table cars_data?","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different MPG values are in the `cars_data` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT MPG) FROM cars_data;\n```","cost":0.0006174,"response_parsed":"SELECT COUNT(DISTINCT MPG) FROM cars_data;","time":4.2324457169}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Horsepower`) FROM `cars_data`","question":"How many different Horsepower are in table cars_data?","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo determine how many different horsepower values exist in the `cars_data` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Horsepower) FROM cars_data;\n```\n\nThis query will return the number of unique horsepower values in your `cars_data` table.","cost":0.0006939,"response_parsed":"SELECT COUNT(DISTINCT Horsepower) FROM cars_data;","time":6.0961883068}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Accelerate`) FROM `cars_data`","question":"Find the maximum Accelerate for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum value of the `Accelerate` column in the `cars_data` table, you can use the SQL `MAX()` function. Here's the SQL query:\n\n```sql\nSELECT MAX(Accelerate) AS MaxAccelerate FROM cars_data;\n```\n\nThis query will return the maximum value of the `Accelerate` column in your `cars_data` table.","cost":0.0005301,"response_parsed":"SELECT MAX(Accelerate) AS MaxAccelerate FROM cars_data;","time":3.5332329273}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Accelerate`) FROM `cars_data`","question":"Find the minimum Accelerate for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum value of the `Accelerate` column in the `cars_data` table, you can use the SQL `MIN()` function. Here's the SQL query:\n\n```sql\nSELECT MIN(Accelerate) AS Minimum_Accelerate\nFROM cars_data;\n```\n\nThis query will return the smallest value in the `Accelerate` column of your `cars_data` table.","cost":0.0004923,"response_parsed":"SELECT MIN(Accelerate) AS Minimum_Accelerate\nFROM cars_data;","time":3.1638679504}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Accelerate`) FROM `cars_data`","question":"Find the average Accelerate for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average `Accelerate` for the table `cars_data`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Accelerate) AS Average_Accelerate\nFROM cars_data;\n```\n\nThis query will calculate the average value of the `Accelerate` column in your `cars_data` table and return it as `Average_Accelerate`.","cost":0.0005886,"response_parsed":"SELECT AVG(Accelerate) AS Average_Accelerate\nFROM cars_data;","time":3.8007164001}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Cylinders`) FROM `cars_data`","question":"Find the maximum Cylinders for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the maximum number of cylinders in the `cars_data` table, you can use the SQL `MAX()` function. Here's the SQL query:\n\n```sql\nSELECT MAX(Cylinders) AS MaxCylinders FROM cars_data;\n```\n\nThis query will return the highest value in the `Cylinders` column of the `cars_data` table.","cost":0.0005697,"response_parsed":"SELECT MAX(Cylinders) AS MaxCylinders FROM cars_data;","time":3.5835955143}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Cylinders`) FROM `cars_data`","question":"Find the minimum Cylinders for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the minimum number of cylinders in the `cars_data` table, you can use the SQL `MIN()` function. Here's the SQL query:\n\n```sql\nSELECT MIN(Cylinders) FROM cars_data;\n```\n\nThis query will return the smallest value in the `Cylinders` column of the `cars_data` table.","cost":0.0006354,"response_parsed":"SELECT MIN(Cylinders) FROM cars_data;","time":4.4109654427}} {"db_path":"QATCH-journal\/spider_data\/test_database\/car_1\/car_1.sqlite","db_id":"car_1","tbl_name":"cars_data","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Cylinders`) FROM `cars_data`","question":"Find the average Cylinders for the table cars_data","db_schema_normalized":"`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","db_schema":"`\"continents\"` (\"ContId\" INTEGER PRIMARY KEY, \"Continent\" TEXT)\n`\"countries\"` (\"CountryId\" INTEGER PRIMARY KEY, \"CountryName\" TEXT, \"Continent\" INTEGER, FOREIGN KEY (Continent) REFERENCES continents(ContId))\n`\"car_makers\"` (\"Id\" INTEGER PRIMARY KEY, \"Maker\" TEXT, \"FullName\" TEXT, \"Country\" TEXT, FOREIGN KEY (Country) REFERENCES countries(CountryId))\n`\"model_list\"` (\"ModelId\" INTEGER PRIMARY KEY, \"Maker\" INTEGER, \"Model\" TEXT UNIQUE, FOREIGN KEY (Maker) REFERENCES car_makers (Id))\n`\"car_names\"` (\"MakeId\" INTEGER PRIMARY KEY, \"Model\" TEXT, \"Make\" TEXT, FOREIGN KEY (Model) REFERENCES model_list (Model))\n`\"cars_data\"` (\"Id\" INTEGER PRIMARY KEY, \"MPG\" TEXT, \"Cylinders\" INTEGER, \"Edispl\" REAL, \"Horsepower\" TEXT, \"Weight\" INTEGER, \"Accelerate\" REAL, \"Year\" INTEGER, FOREIGN KEY (Id) REFERENCES car_names (MakeId))","pred_dict":{"response":"\n\nTo find the average number of cylinders for the table `cars_data`, you can use the SQL `AVG()` function. Here's the SQL query:\n\n```sql\nSELECT AVG(Cylinders) FROM cars_data;\n```","cost":0.0005355,"response_parsed":"SELECT AVG(Cylinders) FROM cars_data;","time":3.4111118317}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Airline` FROM `airlines`","question":"Show the different Airline in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the different airlines from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Airline FROM airlines;\n```\n\nThis query will return a list of unique airline names from the `Airline` column in the `airlines` table.","cost":0.0004068,"response_parsed":"SELECT DISTINCT Airline FROM airlines;","time":3.0235292912}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Abbreviation` FROM `airlines`","question":"Show the different Abbreviation in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the different abbreviations from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Abbreviation FROM airlines;\n```\n\nThis query will return all unique values in the `Abbreviation` column of the `airlines` table.","cost":0.0004023,"response_parsed":"SELECT DISTINCT Abbreviation FROM airlines;","time":2.9725329876}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Country` FROM `airlines`","question":"Show the different Country in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the different countries from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country FROM airlines;\n```\n\nThis query will return a list of unique country names present in the `airlines` table.","cost":0.0003969,"response_parsed":"SELECT DISTINCT Country FROM airlines;","time":3.0638179779}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `City` FROM `airports`","question":"Show the different City in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the different cities from the `airports` table, you can use the `DISTINCT` keyword to fetch unique city values. Here's the SQL code:\n\n```sql\nSELECT DISTINCT City FROM airports;\n```","cost":0.0004293,"response_parsed":"SELECT DISTINCT City FROM airports;","time":3.4847843647}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `AirportCode` FROM `airports`","question":"Show the different AirportCode in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the different `AirportCode` values from the `airports` table, you can use the `SELECT DISTINCT` statement. Here's the SQL code:\n\n```sql\nSELECT DISTINCT AirportCode FROM airports;\n```","cost":0.0003861,"response_parsed":"SELECT DISTINCT AirportCode FROM airports;","time":3.2037959099}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `AirportName` FROM `airports`","question":"Show the different AirportName in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the different `AirportName` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT AirportName FROM airports;\n```\n\nThis query will return all unique `AirportName` values present in the `airports` table.","cost":0.0003933,"response_parsed":"SELECT DISTINCT AirportName FROM airports;","time":2.9715166092}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Country` FROM `airports`","question":"Show the different Country in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the different countries from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country FROM airports;\n```\n\nThis query will return a list of unique country names present in the `airports` table.","cost":0.0004185,"response_parsed":"SELECT DISTINCT Country FROM airports;","time":3.5909314156}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `CountryAbbrev` FROM `airports`","question":"Show the different CountryAbbrev in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the different `CountryAbbrev` values from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT CountryAbbrev FROM airports;\n```\n\nThis query will return a list of all unique `CountryAbbrev` values present in the `airports` table.","cost":0.0003807,"response_parsed":"SELECT DISTINCT CountryAbbrev FROM airports;","time":3.0096895695}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `SourceAirport` FROM `flights`","question":"Show the different SourceAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the different `SourceAirport` values from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT SourceAirport FROM flights;\n```\n\nThis query will return a list of all unique `SourceAirport` values present in the `flights` table.","cost":0.0004707,"response_parsed":"SELECT DISTINCT SourceAirport FROM flights;","time":4.2365932465}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `DestAirport` FROM `flights`","question":"Show the different DestAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the different destination airports from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT DestAirport FROM flights;\n```\n\nThis query will return a list of all unique destination airports present in the `flights` table.","cost":0.0004941,"response_parsed":"SELECT DISTINCT DestAirport FROM flights;","time":4.4852368832}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Airline`, COUNT(*) FROM `airlines` GROUP BY `Airline`","question":"For each Airline, count the number of rows in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of counting the number of rows for each airline in the `airlines` table, we can use the SQL `COUNT()` function combined with `GROUP BY` to aggregate the results by each airline name. Here's how you can do it:\n\n```sql\nSELECT Airline, COUNT(uid) AS NumberOfRows\nFROM airlines\nGROUP BY Airline\nORDER BY Airline;\n```\n\n### Explanation:\n- `SELECT Airline, COUNT(uid) AS NumberOfRows`: This selects the `Airline` name and counts the number of rows (using `COUNT(uid)`) for each airline. The `AS NumberOfRows` renames the count column for clarity.\n- `FROM airlines`: Specifies the table to query.\n- `GROUP BY Airline`: Groups the results by the `Airline` name to count rows for each airline individually.\n- `ORDER BY Airline`: Optionally sorts the results alphabetically by airline name for better readability.\n\nThis query will return a list of airlines along with the number of rows each has in the `airlines` table.","cost":0.0008208,"response_parsed":"SELECT Airline, COUNT(uid) AS NumberOfRows\nFROM airlines\nGROUP BY Airline\nORDER BY Airline;","time":8.1570262909}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Abbreviation`, COUNT(*) FROM `airlines` GROUP BY `Abbreviation`","question":"For each Abbreviation, count the number of rows in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows for each Abbreviation in the airlines table, we use the COUNT() function combined with GROUP BY.\n\n```sql\nSELECT Abbreviation, COUNT(*) AS CountOfRows\nFROM airlines\nGROUP BY Abbreviation;\n```","cost":0.0005013,"response_parsed":"SELECT Abbreviation, COUNT(*) AS CountOfRows\nFROM airlines\nGROUP BY Abbreviation;","time":4.2361695766}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Country`, COUNT(*) FROM `airlines` GROUP BY `Country`","question":"For each Country, count the number of rows in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows in the `airlines` table for each country, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Country,\n COUNT(uid) AS NumberOfAirlines\nFROM \n airlines\nGROUP BY \n Country;\n```\n\nThis query will:\n1. Select the `Country` column.\n2. Count the number of rows (using `COUNT(uid)`) for each country.\n3. Group the results by the `Country` column.\n\nThe result will show the number of airlines for each country in your database.","cost":0.0005751,"response_parsed":"SELECT \n Country,\n COUNT(uid) AS NumberOfAirlines\nFROM \n airlines\nGROUP BY \n Country;","time":4.9353384972}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `City`, COUNT(*) FROM `airports` GROUP BY `City`","question":"For each City, count the number of rows in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows in the `airports` table for each city, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT City, COUNT(AirportCode) AS NumberOfAirports\nFROM airports\nGROUP BY City;\n```\n\nThis query will:\n1. Group all rows in the `airports` table by the `City` column.\n2. Count the number of rows (airports) for each city using `COUNT(AirportCode)`.\n3. Return a result set with two columns: `City` and `NumberOfAirports`.\n\nThe result will show how many airports are present in each city according to the data in your `airports` table.","cost":0.0005463,"response_parsed":"SELECT City, COUNT(AirportCode) AS NumberOfAirports\nFROM airports\nGROUP BY City;","time":5.4209148884}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `AirportCode`, COUNT(*) FROM `airports` GROUP BY `AirportCode`","question":"For each AirportCode, count the number of rows in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows for each `AirportCode` in the `airports` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n AirportCode, \n COUNT(*) as NumberOfRows\nFROM \n airports\nGROUP BY \n AirportCode;\n```\n\nThis query will return each `AirportCode` along with the number of rows associated with that `AirportCode` in the `airports` table.","cost":0.0005841,"response_parsed":"SELECT \n AirportCode, \n COUNT(*) as NumberOfRows\nFROM \n airports\nGROUP BY \n AirportCode;","time":6.2922458649}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `AirportName`, COUNT(*) FROM `airports` GROUP BY `AirportName`","question":"For each AirportName, count the number of rows in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows for each `AirportName` in the `airports` table, you can use the SQL `COUNT(*)` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n AirportName, \n COUNT(*) AS RowCount\nFROM \n airports\nGROUP BY \n AirportName;\n```\n\nThis query will:\n1. Select the `AirportName` column\n2. Count the number of rows for each `AirportName` and alias this count as `RowCount`\n3. Retrieve data from the `airports` table\n4. Group the results by `AirportName`\n\nThe result will show each `AirportName` along with the number of rows (airports) associated with that name.","cost":0.0005373,"response_parsed":"SELECT \n AirportName, \n COUNT(*) AS RowCount\nFROM \n airports\nGROUP BY \n AirportName;","time":5.2615778446}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Country`, COUNT(*) FROM `airports` GROUP BY `Country`","question":"For each Country, count the number of rows in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of airports for each country, we'll use the `airports` table, group the rows by the `Country` column, and count the number of entries in each group.\n\n```sql\nSELECT Country, COUNT(*) AS AirportCount\nFROM airports\nGROUP BY Country;\n```","cost":0.0005211,"response_parsed":"SELECT Country, COUNT(*) AS AirportCount\nFROM airports\nGROUP BY Country;","time":4.8380541801}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `CountryAbbrev`, COUNT(*) FROM `airports` GROUP BY `CountryAbbrev`","question":"For each CountryAbbrev, count the number of rows in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows in the `airports` table for each `CountryAbbrev`, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n CountryAbbrev,\n COUNT(AirportCode) AS AirportCount\nFROM \n airports\nGROUP BY \n CountryAbbrev;\n```\n\nThis query will:\n1. Select the `CountryAbbrev` column.\n2. Count the number of rows (airports) for each `CountryAbbrev` using `COUNT(AirportCode)`.\n3. Group the results by the `CountryAbbrev` column.\n\nThe result will show each country abbreviation along with the number of airports in that country.","cost":0.0006552,"response_parsed":"SELECT \n CountryAbbrev,\n COUNT(AirportCode) AS AirportCount\nFROM \n airports\nGROUP BY \n CountryAbbrev;","time":5.8703150749}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `SourceAirport`, COUNT(*) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, count the number of rows in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo count the number of rows for each `SourceAirport` in the `flights` table, you can use the `COUNT()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT \n SourceAirport, \n COUNT(*) AS NumberOfFlights\nFROM \n flights\nGROUP BY \n SourceAirport;\n```\n\nThis query will return each `SourceAirport` along with the number of flights originating from that airport.","cost":0.0004725,"response_parsed":"SELECT \n SourceAirport, \n COUNT(*) AS NumberOfFlights\nFROM \n flights\nGROUP BY \n SourceAirport;","time":4.4518229961}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `DestAirport`, COUNT(*) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, count the number of rows in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of counting the number of rows for each `DestAirport` in the `flights` table, we can use the following SQL query. This query will group the rows by `DestAirport` and count the number of flights for each destination airport.\n\n```sql\nSELECT \n DestAirport, \n COUNT(*) as FlightCount\nFROM \n flights\nGROUP BY \n DestAirport\nORDER BY \n FlightCount DESC;\n```\n\nThis SQL code:\n1. Selects the `DestAirport` column and counts the number of rows for each destination airport.\n2. Groups the results by `DestAirport`.\n3. Orders the results by the count of flights in descending order (from highest to lowest).","cost":0.0005886,"response_parsed":"SELECT \n DestAirport, \n COUNT(*) as FlightCount\nFROM \n flights\nGROUP BY \n DestAirport\nORDER BY \n FlightCount DESC;","time":5.6072964668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `SourceAirport`, MIN(`Airline`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the min of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum Airline for each SourceAirport in the flights table, we can use the SQL `MIN` function combined with `GROUP BY` to group the results by SourceAirport.\n\n```sql\nSELECT \n SourceAirport,\n MIN(Airline) AS MinAirline\nFROM \n flights\nGROUP BY \n SourceAirport;\n```","cost":0.0007263,"response_parsed":"SELECT \n SourceAirport,\n MIN(Airline) AS MinAirline\nFROM \n flights\nGROUP BY \n SourceAirport;","time":7.2205486298}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `SourceAirport`, MAX(`Airline`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the max of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum airline for each source airport, we'll use the `MAX()` function on the `Airline` column in the `flights` table, grouped by `SourceAirport`. We'll also join with the `airlines` table to get the airline names.\n\n```sql\nSELECT \n f.SourceAirport,\n a.Airline\nFROM \n flights f\nINNER JOIN \n airlines a ON f.Airline = a.uid\nWHERE \n (f.SourceAirport, f.Airline) IN (\n SELECT \n SourceAirport, \n MAX(Airline) as MaxAirline\n FROM \n flights\n GROUP BY \n SourceAirport\n );\n```","cost":0.0008073,"response_parsed":"SELECT \n f.SourceAirport,\n a.Airline\nFROM \n flights f\nINNER JOIN \n airlines a ON f.Airline = a.uid\nWHERE \n (f.SourceAirport, f.Airline) IN (\n SELECT \n SourceAirport, \n MAX(Airline) as MaxAirline\n FROM \n flights\n GROUP BY \n SourceAirport\n );","time":8.2125678062}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `SourceAirport`, AVG(`Airline`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the avg of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the average of the `Airline` values for each `SourceAirport` in the `flights` table, you can use the SQL `AVG()` function combined with a `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n SourceAirport,\n AVG(Airline) AS AverageAirline\nFROM \n flights\nGROUP BY \n SourceAirport;\n```\n\nThis query will return the average value of the `Airline` column for each unique `SourceAirport` in your database.","cost":0.0005553,"response_parsed":"SELECT \n SourceAirport,\n AVG(Airline) AS AverageAirline\nFROM \n flights\nGROUP BY \n SourceAirport;","time":4.7569944859}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `SourceAirport`, SUM(`Airline`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the sum of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of finding the sum of Airline for each SourceAirport in the flights table, we can use the following SQL query. This query groups the flights by their SourceAirport and calculates the sum of the Airline values for each group.\n\n```sql\nSELECT \n SourceAirport, \n SUM(Airline) AS SumOfAirline\nFROM \n flights\nGROUP BY \n SourceAirport;\n```","cost":0.000612,"response_parsed":"SELECT \n SourceAirport, \n SUM(Airline) AS SumOfAirline\nFROM \n flights\nGROUP BY \n SourceAirport;","time":5.3249397278}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `SourceAirport`, MIN(`FlightNo`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the min of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum FlightNo for each SourceAirport, we'll use the `MIN` function combined with `GROUP BY` on the SourceAirport column in the flights table.\n\n```sql\nSELECT SourceAirport, MIN(FlightNo) AS MinFlightNo\nFROM flights\nGROUP BY SourceAirport;\n```","cost":0.0005589,"response_parsed":"SELECT SourceAirport, MIN(FlightNo) AS MinFlightNo\nFROM flights\nGROUP BY SourceAirport;","time":5.1089940071}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `SourceAirport`, MAX(`FlightNo`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the max of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum `FlightNo` for each `SourceAirport` in the `flights` table, you can use the SQL `MAX()` function combined with `GROUP BY`. Here's how you can do it:\n\n```sql\nSELECT \n SourceAirport,\n MAX(FlightNo) AS MaxFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;\n```\n\nThis query will return each `SourceAirport` along with the highest `FlightNo` assigned to it.","cost":0.0004806,"response_parsed":"SELECT \n SourceAirport,\n MAX(FlightNo) AS MaxFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;","time":3.8830058575}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `SourceAirport`, AVG(`FlightNo`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the avg of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the average of `FlightNo` for each `SourceAirport` in the `flights` table, you can use the SQL `AVG()` function combined with `GROUP BY`. Here's how you can do it:\n\n```sql\nSELECT \n SourceAirport,\n AVG(FlightNo) AS AverageFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;\n```\n\nThis query will:\n1. Group all rows in the `flights` table by the `SourceAirport` column.\n2. Calculate the average value of `FlightNo` for each group.\n3. Return a result set with two columns: `SourceAirport` and `AverageFlightNo`.\n\nThe result will show the average `FlightNo` for each `SourceAirport`.","cost":0.0005733,"response_parsed":"SELECT \n SourceAirport,\n AVG(FlightNo) AS AverageFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;","time":4.7785553932}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `SourceAirport`, SUM(`FlightNo`) FROM `flights` GROUP BY `SourceAirport`","question":"For each SourceAirport, find the sum of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of `FlightNo` for each `SourceAirport` in the `flights` table. This can be achieved using the SQL `SUM()` function combined with the `GROUP BY` clause to group the results by `SourceAirport`.\n\n```sql\nSELECT \n SourceAirport,\n SUM(FlightNo) AS TotalFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;\n```","cost":0.000486,"response_parsed":"SELECT \n SourceAirport,\n SUM(FlightNo) AS TotalFlightNo\nFROM \n flights\nGROUP BY \n SourceAirport;","time":3.7280604839}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `DestAirport`, MIN(`Airline`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the min of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum Airline ID for each destination airport, we can use the `MIN()` function combined with `GROUP BY` on the `DestAirport` column in the `flights` table.\n\n```sql\nSELECT DestAirport, MIN(Airline) AS MinAirline\nFROM flights\nGROUP BY DestAirport;\n```","cost":0.0006093,"response_parsed":"SELECT DestAirport, MIN(Airline) AS MinAirline\nFROM flights\nGROUP BY DestAirport;","time":5.288533926}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `DestAirport`, MAX(`Airline`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the max of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum airline for each destination airport, we'll join the flights and airlines tables on the Airline field, group by DestAirport, and select the maximum Airline along with its name.\n\n```sql\nSELECT \n f.DestAirport,\n MAX(f.Airline) AS MaxAirlineUID,\n a.Airline AS AirlineName\nFROM \n flights f\nJOIN \n airlines a ON f.Airline = a.uid\nGROUP BY \n f.DestAirport;\n```","cost":0.0005571,"response_parsed":"SELECT \n f.DestAirport,\n MAX(f.Airline) AS MaxAirlineUID,\n a.Airline AS AirlineName\nFROM \n flights f\nJOIN \n airlines a ON f.Airline = a.uid\nGROUP BY \n f.DestAirport;","time":4.9861016273}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `DestAirport`, AVG(`Airline`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the avg of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine the average number of flights per airline for each destination airport, we can use a two-step approach. First, we count the number of flights each airline operates to each destination airport. Then, we calculate the average of these counts for each destination airport.\n\nHere is the SQL code to achieve this:\n\n```sql\nWITH flight_counts AS (\n SELECT DestAirport, Airline, COUNT(*) as flight_count\n FROM flights\n GROUP BY DestAirport, Airline\n)\nSELECT DestAirport, AVG(flight_count) as avg_airline\nFROM flight_counts\nGROUP BY DestAirport;\n```\n\nThis code first groups the flights by destination airport and airline, counting the flights for each combination. It then calculates the average number of flights per airline for each destination airport.","cost":0.0010494,"response_parsed":"WITH flight_counts AS (\n SELECT DestAirport, Airline, COUNT(*) as flight_count\n FROM flights\n GROUP BY DestAirport, Airline\n)\nSELECT DestAirport, AVG(flight_count) as avg_airline\nFROM flight_counts\nGROUP BY DestAirport;","time":10.1426339149}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `DestAirport`, SUM(`Airline`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the sum of Airline in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of finding the sum of Airline for each DestAirport in the flights table, we can use the following SQL query. This query groups the results by DestAirport and calculates the sum of the Airline values for each group.\n\n```sql\nSELECT DestAirport, SUM(Airline) AS SumOfAirlines\nFROM flights\nGROUP BY DestAirport;\n```","cost":0.000666,"response_parsed":"SELECT DestAirport, SUM(Airline) AS SumOfAirlines\nFROM flights\nGROUP BY DestAirport;","time":6.22072649}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `DestAirport`, MIN(`FlightNo`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the min of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum `FlightNo` for each destination airport, we can use the SQL `MIN()` function combined with `GROUP BY` to group the results by `DestAirport`.\n\n```sql\nSELECT \n DestAirport,\n MIN(FlightNo) AS MinFlightNo\nFROM \n flights\nGROUP BY \n DestAirport;\n```","cost":0.0005706,"response_parsed":"SELECT \n DestAirport,\n MIN(FlightNo) AS MinFlightNo\nFROM \n flights\nGROUP BY \n DestAirport;","time":5.0810284615}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `DestAirport`, MAX(`FlightNo`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the max of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum FlightNo for each destination airport, we'll use the `MAX()` function combined with `GROUP BY` on the DestAirport column in the flights table.\n\n```sql\nSELECT DestAirport, MAX(FlightNo) AS MaxFlightNo \nFROM flights \nGROUP BY DestAirport;\n```","cost":0.000549,"response_parsed":"SELECT DestAirport, MAX(FlightNo) AS MaxFlightNo \nFROM flights \nGROUP BY DestAirport;","time":5.3727128506}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `DestAirport`, AVG(`FlightNo`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the avg of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the average of `FlightNo` for each `DestAirport` in the `flights` table, you can use the SQL `AVG()` function combined with `GROUP BY`. Here's how to do it:\n\n```sql\nSELECT DestAirport, AVG(FlightNo) AS AverageFlightNo\nFROM flights\nGROUP BY DestAirport;\n```\n\nThis query will return each destination airport along with the average `FlightNo` for flights going to that airport.","cost":0.0005517,"response_parsed":"SELECT DestAirport, AVG(FlightNo) AS AverageFlightNo\nFROM flights\nGROUP BY DestAirport;","time":6.4162325859}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `DestAirport`, SUM(`FlightNo`) FROM `flights` GROUP BY `DestAirport`","question":"For each DestAirport, find the sum of FlightNo in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of `FlightNo` for each `DestAirport` in the `flights` table. Here's the SQL code to achieve this:\n\n```sql\nSELECT DestAirport, SUM(FlightNo) AS TotalFlightNo FROM `flights` GROUP BY DestAirport;\n```\n\nThis query:\n1. Selects the `DestAirport` column to group the results by each destination airport.\n2. Uses the `SUM()` function to calculate the total of `FlightNo` for each group.\n3. Groups the results by the `DestAirport` column to ensure the sum is calculated per destination airport.\n\nThe result will be a list of destination airports along with their corresponding total flight numbers.","cost":0.000729,"response_parsed":"SELECT DestAirport, SUM(FlightNo) AS TotalFlightNo FROM `flights` GROUP BY DestAirport;","time":9.4475162029}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Airline` FROM `airlines` GROUP BY `Airline` HAVING count(*) >= 1","question":"Find all the Airline that have at least 1 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all airlines that have at least one record in the `airlines` table, you can use the following SQL query. This query selects all unique airline names from the `airlines` table:\n\n```sql\nSELECT DISTINCT Airline FROM airlines;\n```","cost":0.0005049,"response_parsed":"SELECT DISTINCT Airline FROM airlines;","time":10.2095909119}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Airline` FROM `airlines` GROUP BY `Airline` HAVING count(*) <= 1","question":"Find all the Airline that have at most 1 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all airlines that have at most 1 record in the `airlines` table, we can use a SQL query that counts the number of records for each airline and filters those with a count of 1 or less. Here's how you can do it:\n\n```sql\nSELECT Airline\nFROM airlines\nGROUP BY Airline\nHAVING COUNT(Airline) <= 1;\n```\n\nThis query will return all airlines that appear at most once in the `airlines` table.","cost":0.0007785,"response_parsed":"SELECT Airline\nFROM airlines\nGROUP BY Airline\nHAVING COUNT(Airline) <= 1;","time":9.8999419212}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Abbreviation` FROM `airlines` GROUP BY `Abbreviation` HAVING count(*) >= 1","question":"Find all the Abbreviation that have at least 1 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all the Abbreviations that have at least one record in the `airlines` table, you can use the following SQL query. This query will return all unique abbreviations from the `airlines` table:\n\n```sql\nSELECT DISTINCT Abbreviation FROM airlines;\n```\n\nThis query works by selecting the `Abbreviation` column from the `airlines` table and using the `DISTINCT` keyword to ensure that each abbreviation is only returned once, even if it appears multiple times in the table.","cost":0.0010656,"response_parsed":"SELECT DISTINCT Abbreviation FROM airlines;","time":10.7136971951}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Abbreviation` FROM `airlines` GROUP BY `Abbreviation` HAVING count(*) <= 1","question":"Find all the Abbreviation that have at most 1 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all the Abbreviations in the `airlines` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation\nFROM airlines\nGROUP BY Abbreviation\nHAVING COUNT(Abbreviation) <= 1;\n```\n\nThis query:\n1. Groups the records in the `airlines` table by the `Abbreviation` column.\n2. Uses the `HAVING` clause to filter groups where the count of `Abbreviation` is 1 or less.\n3. Returns the `Abbreviation` values that meet this condition.","cost":0.0005058,"response_parsed":"SELECT Abbreviation\nFROM airlines\nGROUP BY Abbreviation\nHAVING COUNT(Abbreviation) <= 1;","time":3.9978148937}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `airlines` GROUP BY `Country` HAVING count(*) >= 12","question":"Find all the Country that have at least 12 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all countries with at least 12 records in the airlines table, we can use the COUNT() function along with GROUP BY and HAVING clauses.\n\n```sql\nSELECT Country\nFROM airlines\nGROUP BY Country\nHAVING COUNT(*) >= 12;\n```","cost":0.0004446,"response_parsed":"SELECT Country\nFROM airlines\nGROUP BY Country\nHAVING COUNT(*) >= 12;","time":3.7035553455}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `airlines` GROUP BY `Country` HAVING count(*) <= 12","question":"Find all the Country that have at most 12 records in table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all countries with at most 12 records in the `airlines` table, we can use the following SQL query:\n\n```sql\nSELECT Country, COUNT(uid) AS \"Count\"\nFROM airlines\nGROUP BY Country\nHAVING COUNT(uid) <= 12;\n```\n\nThis query:\n1. Selects the `Country` column and counts the number of records (`uid`) for each country.\n2. Groups the results by the `Country` column.\n3. Filters the results to include only those countries with 12 or fewer records using the `HAVING` clause.\n\n```sql\nSELECT Country, COUNT(uid) AS \"Count\"\nFROM airlines\nGROUP BY Country\nHAVING COUNT(uid) <= 12;\n```","cost":0.0005571,"response_parsed":"SELECT Country, COUNT(uid) AS \"Count\"\nFROM airlines\nGROUP BY Country\nHAVING COUNT(uid) <= 12;","time":4.6757564545}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `City` FROM `airports` GROUP BY `City` HAVING count(*) >= 1","question":"Find all the City that have at least 1 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all cities that have at least one record in the `airports` table, we can use a `SELECT DISTINCT` statement on the `City` column of the `airports` table. This will return each city only once, even if there are multiple airports in the same city.\n\n```sql\nSELECT DISTINCT City FROM airports;\n```","cost":0.0004518,"response_parsed":"SELECT DISTINCT City FROM airports;","time":3.7368209362}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `City` FROM `airports` GROUP BY `City` HAVING count(*) <= 1","question":"Find all the City that have at most 1 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all cities with at most one airport, we'll use `GROUP BY` to count airports per city and filter those with a count of 1.\n\n```sql\nSELECT City\nFROM airports\nGROUP BY City\nHAVING COUNT(AirportCode) <= 1;\n```","cost":0.0005688,"response_parsed":"SELECT City\nFROM airports\nGROUP BY City\nHAVING COUNT(AirportCode) <= 1;","time":5.0945312977}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `airports` GROUP BY `Country` HAVING count(*) >= 100","question":"Find all the Country that have at least 100 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all countries with at least 100 records in the airports table, we can use the `COUNT()` function combined with `GROUP BY` and `HAVING` clauses. Here's the SQL code:\n\n```sql\nSELECT Country, COUNT(*) as AirportCount\nFROM airports\nGROUP BY Country\nHAVING COUNT(*) >= 100;\n```\n\nThis query will return each country along with the number of airport records it has, but only for those countries that have 100 or more records.","cost":0.0005679,"response_parsed":"SELECT Country, COUNT(*) as AirportCount\nFROM airports\nGROUP BY Country\nHAVING COUNT(*) >= 100;","time":5.1173350811}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Country` FROM `airports` GROUP BY `Country` HAVING count(*) <= 100","question":"Find all the Country that have at most 100 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all countries with at most 100 records in the `airports` table, we can use the following SQL query:\n\n```sql\nSELECT Country, COUNT(AirportCode) AS AirportCount\nFROM airports\nGROUP BY Country\nHAVING COUNT(AirportCode) <= 100;\n```\n\nThis query:\n1. Selects the `Country` and counts the number of `AirportCode` entries for each country.\n2. Groups the results by `Country`.\n3. Filters the results to include only those countries where the count of airports is 100 or fewer.\n\n```sql\nSELECT Country, COUNT(AirportCode) AS AirportCount\nFROM airports\nGROUP BY Country\nHAVING COUNT(AirportCode) <= 100;\n```","cost":0.0006237,"response_parsed":"SELECT Country, COUNT(AirportCode) AS AirportCount\nFROM airports\nGROUP BY Country\nHAVING COUNT(AirportCode) <= 100;","time":6.4847018719}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `AirportName` FROM `airports` GROUP BY `AirportName` HAVING count(*) >= 1","question":"Find all the AirportName that have at least 1 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all unique AirportNames that have at least one record in the airports table, we can use the `DISTINCT` keyword to ensure each AirportName appears only once.\n\n```sql\nSELECT DISTINCT AirportName FROM airports;\n```","cost":0.0005382,"response_parsed":"SELECT DISTINCT AirportName FROM airports;","time":12.3804852962}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `AirportName` FROM `airports` GROUP BY `AirportName` HAVING count(*) <= 1","question":"Find all the AirportName that have at most 1 records in table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all `AirportName`s that have at most 1 record in the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportName, COUNT(*) as AirportCount\nFROM airports\nGROUP BY AirportName\nHAVING COUNT(*) <= 1\nORDER BY AirportName;\n```\n\nThis query:\n1. Groups the `airports` table by `AirportName`\n2. Counts the number of records for each `AirportName`\n3. Filters the results to include only those `AirportName`s with 1 or fewer records\n4. Orders the results by `AirportName` for better readability\n\nThe result will be a list of `AirportName`s that appear at most once in the `airports` table.","cost":0.0005877,"response_parsed":"SELECT AirportName, COUNT(*) as AirportCount\nFROM airports\nGROUP BY AirportName\nHAVING COUNT(*) <= 1\nORDER BY AirportName;","time":16.588919878}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING count(*) >= 12","question":"Find all the SourceAirport that have at least 12 records in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all SourceAirports with at least 12 records in the flights table, we'll use the COUNT() function and filter the results using HAVING.\n\n```sql\nSELECT SourceAirport, COUNT(*) AS FlightCount\nFROM flights\nGROUP BY SourceAirport\nHAVING COUNT(*) >= 12;\n```","cost":0.0004428,"response_parsed":"SELECT SourceAirport, COUNT(*) AS FlightCount\nFROM flights\nGROUP BY SourceAirport\nHAVING COUNT(*) >= 12;","time":3.6946470737}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING count(*) <= 12","question":"Find all the SourceAirport that have at most 12 records in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all `SourceAirport`s that have at most 12 records in the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING COUNT(*) <= 12;\n```\n\nThis query:\n1. Groups the rows in the `flights` table by the `SourceAirport` column.\n2. Counts the number of records for each `SourceAirport`.\n3. Filters the results to include only those `SourceAirport`s with 12 or fewer records.\n\n```sql\nSELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING COUNT(*) <= 12;\n```","cost":0.0005364,"response_parsed":"SELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING COUNT(*) <= 12;","time":4.5597586632}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING count(*) >= 12","question":"Find all the DestAirport that have at least 12 records in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all `DestAirport` values in the `flights` table that appear at least 12 times, you can use the following SQL query:\n\n```sql\nSELECT DestAirport, COUNT(DestAirport) AS FlightCount\nFROM flights\nGROUP BY DestAirport\nHAVING COUNT(DestAirport) >= 12;\n```\n\nThis query:\n1. Groups the `flights` table by the `DestAirport` column.\n2. Counts the number of records for each `DestAirport`.\n3. Filters the results to include only those `DestAirport` values with a count of 12 or more.\n\nThe result will show each qualifying `DestAirport` along with the total number of flights to that destination.","cost":0.0005004,"response_parsed":"SELECT DestAirport, COUNT(DestAirport) AS FlightCount\nFROM flights\nGROUP BY DestAirport\nHAVING COUNT(DestAirport) >= 12;","time":4.1302089691}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING count(*) <= 12","question":"Find all the DestAirport that have at most 12 records in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find all destination airports with at most 12 records in the `flights` table, we can use the `COUNT()` function combined with `GROUP BY` and `HAVING` clauses.\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING COUNT(DestAirport) <= 12;\n```","cost":0.0004275,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING COUNT(DestAirport) <= 12;","time":3.2817106247}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING AVG(`Airline`) >= 6.51","question":"List the SourceAirport which average of Airline is at least 6.51 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of listing the `SourceAirport` where the average number of flights per airline is at least 6.51, we can use the following SQL query. This query calculates the average number of flights per airline for each `SourceAirport` and filters those airports where this average meets or exceeds 6.51.\n\n```sql\nWITH FlightCounts AS (\n SELECT \n SourceAirport,\n Airline,\n COUNT(*) AS FlightCount\n FROM \n flights\n GROUP BY \n SourceAirport, Airline\n)\nSELECT \n SourceAirport\nFROM \n FlightCounts\nGROUP BY \n SourceAirport\nHAVING \n AVG(FlightCount) >= 6.51;\n```","cost":0.0011628,"response_parsed":"WITH FlightCounts AS (\n SELECT \n SourceAirport,\n Airline,\n COUNT(*) AS FlightCount\n FROM \n flights\n GROUP BY \n SourceAirport, Airline\n)\nSELECT \n SourceAirport\nFROM \n FlightCounts\nGROUP BY \n SourceAirport\nHAVING \n AVG(FlightCount) >= 6.51;","time":11.273471117}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING AVG(`Airline`) <= 6.51","question":"List the SourceAirport which average of Airline is at most 6.51 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question \"List the SourceAirport which average of Airline is at most 6.51 in table flights,\" we need to translate it into SQL code. However, the question seems to have a misunderstanding. The `Airline` column in the `flights` table is not a numerical value but rather a foreign key referencing the `airlines` table. Therefore, calculating an \"average of Airline\" does not make sense in this context.\n\nIf you meant to ask for something else, such as filtering based on a specific condition related to airlines, please provide additional clarification. For example, if you want to filter based on the average number of flights per airline or another numerical metric, I can help you with that.\n\nHere\u2019s how you might query for `SourceAirport` based on a specific condition if the `Airline` column were numerical:\n\n```sql\nSELECT SourceAirport \nFROM flights \nWHERE Airline <= 6.51;\n```\n\nHowever, this assumes that the `Airline` column contains numerical values, which it does not in the provided schema. If you have a different interpretation or need further assistance, please clarify your requirements.","cost":0.0008361,"response_parsed":"SELECT SourceAirport \nFROM flights \nWHERE Airline <= 6.51;","time":8.1378092766}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING SUM(`Airline`) >= 78.0","question":"List the SourceAirport which summation of Airline is at least 78.0 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of listing the `SourceAirport` where the summation of `Airline` is at least 78.0, we need to consider the following:\n\n1. The `flights` table contains the `Airline` and `SourceAirport` columns.\n2. We need to sum the `Airline` values for each `SourceAirport`.\n3. We need to filter the results to include only those `SourceAirport` values where the sum of `Airline` is at least 78.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(Airline) >= 78.0;\n```\n\nThis SQL query:\n1. Groups the rows in the `flights` table by the `SourceAirport` column.\n2. Calculates the sum of the `Airline` values for each group.\n3. Filters the results to include only those groups where the sum of `Airline` is at least 78.0.\n4. Returns the `SourceAirport` values that meet the condition.","cost":0.000927,"response_parsed":"SELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(Airline) >= 78.0;","time":9.1189928055}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING SUM(`Airline`) <= 78.0","question":"List the SourceAirport which summation of Airline is at most 78.0 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Airline` values for each `SourceAirport` in the `flights` table and return only those `SourceAirport` values where the sum is less than or equal to 78.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(Airline) <= 78.0;\n```\n\n### Explanation:\n1. **SELECT SourceAirport**: This selects the `SourceAirport` column that we want to retrieve.\n2. **FROM flights**: This specifies the table from which we want to retrieve the data.\n3. **GROUP BY SourceAirport**: This groups the rows by the `SourceAirport` values.\n4. **HAVING SUM(Airline) <= 78.0**: This filters the grouped results to include only those groups where the sum of the `Airline` values is less than or equal to 78.0.\n\nThis query will return a list of `SourceAirport` values where the sum of the `Airline` values for flights originating from that airport is at most 78.0.","cost":0.0007893,"response_parsed":"SELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(Airline) <= 78.0;","time":7.0878179073}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING AVG(`FlightNo`) >= 664.35","question":"List the SourceAirport which average of FlightNo is at least 664.35 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the average `FlightNo` for each `SourceAirport` in the `flights` table and then filter the results to include only those `SourceAirport` values where the average `FlightNo` is at least 664.35.\n\nHere is the SQL code to accomplish this:\n\n```sql\nSELECT SourceAirport, AVG(FlightNo) AS AverageFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING AVG(FlightNo) >= 664.35;\n```\n\n### Explanation:\n1. **`SELECT SourceAirport, AVG(FlightNo) AS AverageFlightNo`**:\n - This selects the `SourceAirport` and calculates the average of `FlightNo` for each `SourceAirport`. The `AVG` function is used to compute the average, and `AS AverageFlightNo` renames the calculated column for clarity.\n\n2. **`FROM flights`**:\n - This specifies the table from which to retrieve the data, which is the `flights` table.\n\n3. **`GROUP BY SourceAirport`**:\n - This groups the rows by the `SourceAirport` column, allowing us to calculate the average `FlightNo` for each `SourceAirport`.\n\n4. **`HAVING AVG(FlightNo) >= 664.35`**:\n - This filters the results to include only those groups where the average `FlightNo` is at least 664.35.\n\nThis query will return a list of `SourceAirport` values along with their corresponding average `FlightNo`, but only for those airports where the average `FlightNo` meets or exceeds 664.35.","cost":0.0007722,"response_parsed":"SELECT SourceAirport, AVG(FlightNo) AS AverageFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING AVG(FlightNo) >= 664.35;","time":6.5785076618}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING AVG(`FlightNo`) <= 664.35","question":"List the SourceAirport which average of FlightNo is at most 664.35 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the average `FlightNo` for each `SourceAirport` in the `flights` table and then filter those `SourceAirport` values where the average `FlightNo` is less than or equal to 664.35.\n\nHere is the SQL code to accomplish this:\n\n```sql\nSELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING AVG(FlightNo) <= 664.35;\n```\n\nThis query:\n1. Groups the rows in the `flights` table by the `SourceAirport` column.\n2. Calculates the average `FlightNo` for each group using the `AVG()` function.\n3. Filters the results to include only those `SourceAirport` values where the average `FlightNo` is at most 664.35.","cost":0.0005445,"response_parsed":"SELECT SourceAirport\nFROM flights\nGROUP BY SourceAirport\nHAVING AVG(FlightNo) <= 664.35;","time":4.1998710632}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING SUM(`FlightNo`) >= 7970.2","question":"List the SourceAirport which summation of FlightNo is at least 7970.2 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `FlightNo` values for each `SourceAirport` and then filter out those airports where the sum is at least 7970.2.\n\nHere is the SQL code:\n\n```sql\nSELECT SourceAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(FlightNo) >= 7970.2;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `SourceAirport` and the sum of `FlightNo` values, aliasing the sum as `TotalFlightNo` for clarity.\n2. **FROM Clause**: We specify the `flights` table as the source of data.\n3. **GROUP BY Clause**: We group the rows by the `SourceAirport` to aggregate the `FlightNo` values for each airport.\n4. **HAVING Clause**: We filter the grouped results to include only those airports where the sum of `FlightNo` is at least 7970.2.\n\nThis query will return a list of `SourceAirport` values along with their corresponding total `FlightNo` sums that meet or exceed the threshold of 7970.2.","cost":0.0007533,"response_parsed":"SELECT SourceAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(FlightNo) >= 7970.2;","time":6.8216538429}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `SourceAirport` FROM `flights` GROUP BY `SourceAirport` HAVING SUM(`FlightNo`) <= 7970.2","question":"List the SourceAirport which summation of FlightNo is at most 7970.2 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum up the `FlightNo` values for each `SourceAirport` in the `flights` table and then filter out those `SourceAirport` values where the sum is less than or equal to 7970.2.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT SourceAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(FlightNo) <= 7970.2;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `SourceAirport` column and calculate the sum of `FlightNo` values for each `SourceAirport`. The sum is aliased as `TotalFlightNo` for better readability.\n2. **FROM Clause**: We specify the `flights` table as the source of data.\n3. **GROUP BY Clause**: We group the rows by the `SourceAirport` column to aggregate the `FlightNo` values for each airport.\n4. **HAVING Clause**: We filter the grouped results to include only those `SourceAirport` values where the sum of `FlightNo` is less than or equal to 7970.2.\n\nThis query will return a list of `SourceAirport` values along with their corresponding total `FlightNo` values, but only for those airports where the total is at most 7970.2.","cost":0.0007353,"response_parsed":"SELECT SourceAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY SourceAirport\nHAVING SUM(FlightNo) <= 7970.2;","time":6.3011782169}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING AVG(`Airline`) >= 6.51","question":"List the DestAirport which average of Airline is at least 6.51 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of listing the `DestAirport` where the average of `Airline` is at least 6.51, we need to consider the following:\n\n1. The `Airline` column in the `flights` table is an integer that references the `uid` in the `airlines` table. This means it does not directly represent a numerical value that can be averaged.\n2. To find the average number of flights per airline at each destination airport, we can use the `AVG()` function on the `Airline` column.\n\nHere is the SQL code to fetch the desired result:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(Airline) >= 6.51;\n```\n\nThis query will:\n1. Group the flights by `DestAirport`.\n2. Calculate the average value of the `Airline` column for each group.\n3. Return only those `DestAirport` values where the average `Airline` value is at least 6.51.","cost":0.0009387,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(Airline) >= 6.51;","time":9.2554354668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING AVG(`Airline`) <= 6.51","question":"List the DestAirport which average of Airline is at most 6.51 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `DestAirport` from the `flights` table where the average value of the `Airline` column is at most 6.51. Here's the SQL code to achieve this:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(Airline) <= 6.51;\n```\n\n### Explanation:\n1. **SELECT DestAirport**: This selects the `DestAirport` column that we want to retrieve.\n2. **FROM flights**: This specifies the table from which to fetch the data, which is the `flights` table.\n3. **GROUP BY DestAirport**: This groups the rows by the `DestAirport` column so that we can perform an aggregation operation (in this case, `AVG`) on each group.\n4. **HAVING AVG(Airline) <= 6.51**: This filters the groups to include only those where the average value of the `Airline` column is at most 6.51.\n\nThis query will return the list of destination airports where the average airline ID is 6.51 or less.","cost":0.0008082,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(Airline) <= 6.51;","time":8.0738825798}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING SUM(`Airline`) >= 78.0","question":"List the DestAirport which summation of Airline is at least 78.0 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question of listing the `DestAirport` where the summation of `Airline` is at least 78.0, we need to use the `SUM` aggregation function on the `Airline` column in the `flights` table. We will group the results by `DestAirport` and filter the results to include only those groups where the sum of `Airline` is at least 78.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(Airline) >= 78.0;\n```\n\nThis SQL query will:\n1. Group all rows in the `flights` table by the `DestAirport` column.\n2. Calculate the sum of the `Airline` column for each group.\n3. Filter the results to include only those groups where the sum of `Airline` is at least 78.0.\n4. Return the `DestAirport` values that meet this condition.","cost":0.0008775,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(Airline) >= 78.0;","time":8.2768397331}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING SUM(`Airline`) <= 78.0","question":"List the DestAirport which summation of Airline is at most 78.0 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Airline` values for each `DestAirport` in the `flights` table and return only those `DestAirport` values where the sum is at most 78.0.\n\nHere is the SQL code:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(Airline) <= 78.0;\n```\n\n### Explanation:\n1. **SELECT DestAirport**: This selects the `DestAirport` column that we want to retrieve.\n2. **FROM flights**: This specifies the table from which we want to retrieve data.\n3. **GROUP BY DestAirport**: This groups the rows by the `DestAirport` column so that we can perform aggregation on each group.\n4. **HAVING SUM(Airline) <= 78.0**: This filters the groups to include only those where the sum of the `Airline` values is at most 78.0.\n\nThis query will return a list of `DestAirport` values where the sum of the `Airline` values for flights to that destination is at most 78.0.","cost":0.0010197,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(Airline) <= 78.0;","time":8.9594266415}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING AVG(`FlightNo`) >= 664.36","question":"List the DestAirport which average of FlightNo is at least 664.36 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the average `FlightNo` for each `DestAirport` in the `flights` table and then filter the results to include only those `DestAirport` values where the average `FlightNo` is at least 664.36.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(FlightNo) >= 664.36;\n```\n\n### Explanation:\n1. **`SELECT DestAirport`**: This selects the `DestAirport` column, which is the column we are interested in.\n2. **`FROM flights`**: This specifies the table from which to retrieve the data.\n3. **`GROUP BY DestAirport`**: This groups the rows by the `DestAirport` column, allowing us to calculate the average `FlightNo` for each destination airport.\n4. **`HAVING AVG(FlightNo) >= 664.36`**: This filters the results to include only those groups where the average `FlightNo` is at least 664.36.\n\nThis query will return a list of `DestAirport` values where the average `FlightNo` meets or exceeds 664.36.","cost":0.0007803,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(FlightNo) >= 664.36;","time":6.9612224102}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING AVG(`FlightNo`) <= 664.36","question":"List the DestAirport which average of FlightNo is at most 664.36 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that calculates the average `FlightNo` for each `DestAirport` in the `flights` table and then filters out the `DestAirport` where this average is at most 664.36.\n\nHere is the SQL code:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(FlightNo) <= 664.36;\n```\n\n### Explanation:\n1. **SELECT DestAirport**: This selects the `DestAirport` column, which contains the destination airport codes.\n2. **FROM flights**: This specifies the table from which to retrieve the data, which is the `flights` table.\n3. **GROUP BY DestAirport**: This groups the rows by the `DestAirport` column, allowing us to calculate the average `FlightNo` for each destination airport.\n4. **HAVING AVG(FlightNo) <= 664.36**: This filters the results to include only those groups where the average `FlightNo` is at most 664.36.\n\nThis query will return a list of destination airports where the average `FlightNo` is 664.36 or less.","cost":0.0007407,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING AVG(FlightNo) <= 664.36;","time":6.6611185074}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING SUM(`FlightNo`) >= 7970.2","question":"List the DestAirport which summation of FlightNo is at least 7970.2 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `FlightNo` values for each `DestAirport` and then filter the results to include only those `DestAirport` values where the sum is at least 7970.2.\n\nHere is the SQL code:\n\n```sql\nSELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(FlightNo) >= 7970.2;\n```\n\n### Explanation:\n1. **SELECT DestAirport**: This selects the `DestAirport` column that we want to retrieve.\n2. **FROM flights**: This specifies the table from which we want to retrieve the data.\n3. **GROUP BY DestAirport**: This groups the rows by the `DestAirport` column, allowing us to aggregate data for each destination airport.\n4. **HAVING SUM(FlightNo) >= 7970.2**: This filters the grouped results to include only those groups where the sum of `FlightNo` is at least 7970.2.\n\nThis query will return a list of `DestAirport` values where the sum of `FlightNo` for flights to that destination is at least 7970.2.","cost":0.000801,"response_parsed":"SELECT DestAirport\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(FlightNo) >= 7970.2;","time":7.3771979809}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `DestAirport` FROM `flights` GROUP BY `DestAirport` HAVING SUM(`FlightNo`) <= 7970.2","question":"List the DestAirport which summation of FlightNo is at most 7970.2 in table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question, we need to write a SQL query that will sum the `FlightNo` values for each `DestAirport` in the `flights` table and then filter the results to include only those `DestAirport` values where the sum is less than or equal to 7970.2.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT DestAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(FlightNo) <= 7970.2;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `DestAirport` column and calculate the sum of `FlightNo` values for each `DestAirport`. The `SUM(FlightNo)` is aliased as `TotalFlightNo` for clarity.\n2. **FROM Clause**: We specify the `flights` table as the source of data.\n3. **GROUP BY Clause**: We group the rows by the `DestAirport` column to aggregate the `FlightNo` values for each destination airport.\n4. **HAVING Clause**: We filter the grouped results to include only those groups where the sum of `FlightNo` is less than or equal to 7970.2.\n\nThis query will return a list of `DestAirport` values along with their corresponding total `FlightNo` values, but only for those airports where the total `FlightNo` is at most 7970.2.","cost":0.0008217,"response_parsed":"SELECT DestAirport, SUM(FlightNo) AS TotalFlightNo\nFROM flights\nGROUP BY DestAirport\nHAVING SUM(FlightNo) <= 7970.2;","time":7.5590946674}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Airline` FROM `airlines` GROUP BY `Airline` HAVING COUNT(DISTINCT `Country`) = (SELECT COUNT(DISTINCT `Country`) FROM `airlines`)","question":"What are the Airline with all the Country in table airlines?","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve a list of all airlines along with their corresponding countries from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Airline, Country FROM airlines;\n```\n\nThis query selects the unique combinations of `Airline` and `Country` from your `airlines` table.","cost":0.0004527,"response_parsed":"SELECT DISTINCT Airline, Country FROM airlines;","time":4.1341269016}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Abbreviation` FROM `airlines` GROUP BY `Abbreviation` HAVING COUNT(DISTINCT `Country`) = (SELECT COUNT(DISTINCT `Country`) FROM `airlines`)","question":"What are the Abbreviation with all the Country in table airlines?","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the abbreviations along with their corresponding countries from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation, Country FROM airlines;\n```\n\nThis query selects the `Abbreviation` and `Country` columns from the `airlines` table, returning all rows that contain these two pieces of information.","cost":0.0005157,"response_parsed":"SELECT Abbreviation, Country FROM airlines;","time":4.6502566338}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `City` FROM `airports` GROUP BY `City` HAVING COUNT(DISTINCT `Country`) = (SELECT COUNT(DISTINCT `Country`) FROM `airports`)","question":"What are the City with all the Country in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine which cities have airports in every country listed in the `airports` table, we can use the following SQL query. This query will:\n\n1. First, determine the total number of distinct countries in the `airports` table.\n2. Then, for each city, count how many distinct countries have airports in that city.\n3. Finally, return the cities where the count of distinct countries matches the total number of distinct countries.\n\n```sql\nSELECT City\nFROM airports\nGROUP BY City\nHAVING COUNT(DISTINCT Country) = (SELECT COUNT(DISTINCT Country) FROM airports);\n```\n\nThis query will return the names of cities that have at least one airport for every country listed in the `airports` table.","cost":0.0006858,"response_parsed":"SELECT City\nFROM airports\nGROUP BY City\nHAVING COUNT(DISTINCT Country) = (SELECT COUNT(DISTINCT Country) FROM airports);","time":5.785782814}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `City` FROM `airports` GROUP BY `City` HAVING COUNT(DISTINCT `CountryAbbrev`) = (SELECT COUNT(DISTINCT `CountryAbbrev`) FROM `airports`)","question":"What are the City with all the CountryAbbrev in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all cities along with every possible country abbreviation from the airports table, we can use a CROSS JOIN to combine each distinct city with each distinct country abbreviation.\n\n```sql\nSELECT c.City, a.CountryAbbrev\nFROM (SELECT DISTINCT City FROM airports) c\nCROSS JOIN (SELECT DISTINCT CountryAbbrev FROM airports) a;\n```","cost":0.0009999,"response_parsed":"SELECT c.City, a.CountryAbbrev\nFROM (SELECT DISTINCT City FROM airports) c\nCROSS JOIN (SELECT DISTINCT CountryAbbrev FROM airports) a;","time":9.1753537655}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `AirportCode` FROM `airports` GROUP BY `AirportCode` HAVING COUNT(DISTINCT `Country`) = (SELECT COUNT(DISTINCT `Country`) FROM `airports`)","question":"What are the AirportCode with all the Country in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the `AirportCode` along with all country-related information (`Country` and `CountryAbbrev`) from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportCode, Country, CountryAbbrev FROM airports;\n```\n\nThis query will return a list of all airport codes along with their corresponding country names and country abbreviations.","cost":0.0004473,"response_parsed":"SELECT AirportCode, Country, CountryAbbrev FROM airports;","time":3.5881071091}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `AirportName` FROM `airports` GROUP BY `AirportName` HAVING COUNT(DISTINCT `Country`) = (SELECT COUNT(DISTINCT `Country`) FROM `airports`)","question":"What are the AirportName with all the Country in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo retrieve the `AirportName` along with the corresponding `Country` for all entries in the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportName, Country FROM airports;\n```\n\nThis query will return a list of all airport names along with their respective countries from the `airports` table.","cost":0.0004536,"response_parsed":"SELECT AirportName, Country FROM airports;","time":3.5556762218}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Country` FROM `airports` GROUP BY `Country` HAVING COUNT(DISTINCT `CountryAbbrev`) = (SELECT COUNT(DISTINCT `CountryAbbrev`) FROM `airports`)","question":"What are the Country with all the CountryAbbrev in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo answer the question \"What are the Country with all the CountryAbbrev in table airports?\", we need to fetch all unique country names from the `airports` table. This can be achieved using the `SELECT DISTINCT` statement to retrieve unique values from the `Country` column in the `airports` table.\n\n```sql\nSELECT DISTINCT Country FROM airports;\n```","cost":0.0006147,"response_parsed":"SELECT DISTINCT Country FROM airports;","time":5.3069598675}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airlines` ORDER BY `Country` ASC","question":"Show all data ordered by Country in ascending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airlines` table ordered by the `Country` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines ORDER BY Country ASC;\n```","cost":0.0003645,"response_parsed":"SELECT * FROM airlines ORDER BY Country ASC;","time":2.5275466442}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airlines` ORDER BY `Country` DESC","question":"Show all data ordered by Country in descending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airlines` table ordered by the `Country` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines ORDER BY Country DESC;\n```","cost":0.000387,"response_parsed":"SELECT * FROM airlines ORDER BY Country DESC;","time":2.7466051579}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airlines` ORDER BY `Abbreviation` ASC","question":"Show all data ordered by Abbreviation in ascending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airlines` table ordered by the `Abbreviation` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines ORDER BY Abbreviation ASC;\n```","cost":0.0004995,"response_parsed":"SELECT * FROM airlines ORDER BY Abbreviation ASC;","time":4.0285844803}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airlines` ORDER BY `Abbreviation` DESC","question":"Show all data ordered by Abbreviation in descending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airlines` table ordered by the `Abbreviation` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines ORDER BY Abbreviation DESC;\n```","cost":0.0005148,"response_parsed":"SELECT * FROM airlines ORDER BY Abbreviation DESC;","time":3.905974865}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Abbreviation` FROM `airlines` ORDER BY `Abbreviation` ASC","question":"Project the Abbreviation ordered in ascending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `Abbreviation` column from the `airlines` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation \nFROM airlines \nORDER BY Abbreviation ASC;\n```","cost":0.0004401,"response_parsed":"SELECT Abbreviation \nFROM airlines \nORDER BY Abbreviation ASC;","time":3.6749763489}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Abbreviation` FROM `airlines` ORDER BY `Abbreviation` DESC","question":"Project the Abbreviation ordered in descending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the Abbreviation from the airlines table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation FROM airlines ORDER BY Abbreviation DESC;\n```","cost":0.0005283,"response_parsed":"SELECT Abbreviation FROM airlines ORDER BY Abbreviation DESC;","time":4.2993426323}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `airlines` ORDER BY `Country` ASC","question":"Project the Country ordered in ascending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `Country` from the `airlines` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country \nFROM airlines \nORDER BY Country ASC;\n```\n\nThis query will:\n1. Select the `Country` column from the `airlines` table.\n2. Use `DISTINCT` to ensure each country appears only once.\n3. Order the results in ascending alphabetical order by country name.","cost":0.0004716,"response_parsed":"SELECT DISTINCT Country \nFROM airlines \nORDER BY Country ASC;","time":3.6607730389}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `airlines` ORDER BY `Country` DESC","question":"Project the Country ordered in descending order for the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `Country` from the `airlines` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Country FROM airlines ORDER BY Country DESC;\n```","cost":0.0003915,"response_parsed":"SELECT Country FROM airlines ORDER BY Country DESC;","time":3.0499567986}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airports` ORDER BY `Country` ASC","question":"Show all data ordered by Country in ascending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airports` table ordered by the `Country` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airports ORDER BY Country ASC;\n```","cost":0.0005274,"response_parsed":"SELECT * FROM airports ORDER BY Country ASC;","time":4.510389328}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airports` ORDER BY `Country` DESC","question":"Show all data ordered by Country in descending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airports` table ordered by the `Country` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airports ORDER BY Country DESC;\n```","cost":0.0003771,"response_parsed":"SELECT * FROM airports ORDER BY Country DESC;","time":2.9163789749}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airports` ORDER BY `AirportName` ASC","question":"Show all data ordered by AirportName in ascending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airports` table ordered by `AirportName` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airports ORDER BY AirportName ASC;\n```","cost":0.0004077,"response_parsed":"SELECT * FROM airports ORDER BY AirportName ASC;","time":3.1254780293}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `airports` ORDER BY `AirportName` DESC","question":"Show all data ordered by AirportName in descending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `airports` table ordered by `AirportName` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM airports ORDER BY AirportName DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `airports` table.\n2. Order the results by the `AirportName` column in descending order (`DESC`).","cost":0.0004914,"response_parsed":"SELECT * FROM airports ORDER BY AirportName DESC;","time":3.7871742249}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `AirportName` FROM `airports` ORDER BY `AirportName` ASC","question":"Project the AirportName ordered in ascending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the AirportName from the airports table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT AirportName \nFROM airports \nORDER BY AirportName ASC;\n```","cost":0.0005139,"response_parsed":"SELECT AirportName \nFROM airports \nORDER BY AirportName ASC;","time":4.500736475}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `AirportName` FROM `airports` ORDER BY `AirportName` DESC","question":"Project the AirportName ordered in descending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `AirportName` from the `airports` table and order it in descending order, you can use the following SQL query:\n\n```sql\nSELECT AirportName\nFROM airports\nORDER BY AirportName DESC;\n```","cost":0.0005058,"response_parsed":"SELECT AirportName\nFROM airports\nORDER BY AirportName DESC;","time":4.1447789669}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `airports` ORDER BY `Country` ASC","question":"Project the Country ordered in ascending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `Country` from the `airports` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Country FROM airports ORDER BY Country ASC;\n```","cost":0.0004419,"response_parsed":"SELECT Country FROM airports ORDER BY Country ASC;","time":3.4976460934}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Country` FROM `airports` ORDER BY `Country` DESC","question":"Project the Country ordered in descending order for the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `Country` from the `airports` table and order them in descending order, you can use the following SQL query:\n\n```sql\nSELECT Country FROM airports ORDER BY Country DESC;\n```","cost":0.0004698,"response_parsed":"SELECT Country FROM airports ORDER BY Country DESC;","time":3.8640568256}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `flights` ORDER BY `SourceAirport` ASC","question":"Show all data ordered by SourceAirport in ascending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `flights` table ordered by `SourceAirport` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM flights ORDER BY SourceAirport ASC;\n```","cost":0.0004563,"response_parsed":"SELECT * FROM flights ORDER BY SourceAirport ASC;","time":3.5906946659}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `flights` ORDER BY `SourceAirport` DESC","question":"Show all data ordered by SourceAirport in descending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `flights` table ordered by `SourceAirport` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM flights ORDER BY SourceAirport DESC;\n```","cost":0.0005373,"response_parsed":"SELECT * FROM flights ORDER BY SourceAirport DESC;","time":4.6181907654}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `flights` ORDER BY `FlightNo` ASC","question":"Show all data ordered by FlightNo in ascending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `flights` table ordered by `FlightNo` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nORDER BY FlightNo ASC;\n```","cost":0.0004779,"response_parsed":"SELECT *\nFROM flights\nORDER BY FlightNo ASC;","time":3.9790768623}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `flights` ORDER BY `FlightNo` DESC","question":"Show all data ordered by FlightNo in descending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all data from the `flights` table ordered by `FlightNo` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nORDER BY FlightNo DESC;\n```","cost":0.0003483,"response_parsed":"SELECT *\nFROM flights\nORDER BY FlightNo DESC;","time":2.3372180462}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `DestAirport` FROM `flights` ORDER BY `DestAirport` ASC","question":"Project the DestAirport ordered in ascending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `DestAirport` column from the `flights` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT DestAirport\nFROM flights\nORDER BY DestAirport ASC;\n```\n\nThis query will select the `DestAirport` column from the `flights` table and return the results sorted in ascending order based on the `DestAirport` values.","cost":0.0004842,"response_parsed":"SELECT DestAirport\nFROM flights\nORDER BY DestAirport ASC;","time":4.1205825806}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `DestAirport` FROM `flights` ORDER BY `DestAirport` DESC","question":"Project the DestAirport ordered in descending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `DestAirport` column from the `flights` table and order it in descending order, you can use the following SQL query:\n\n```sql\nSELECT DestAirport FROM flights ORDER BY DestAirport DESC;\n```","cost":0.0004518,"response_parsed":"SELECT DestAirport FROM flights ORDER BY DestAirport DESC;","time":3.7481331825}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `SourceAirport` FROM `flights` ORDER BY `SourceAirport` ASC","question":"Project the SourceAirport ordered in ascending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `SourceAirport` from the `flights` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT SourceAirport\nFROM flights\nORDER BY SourceAirport ASC;\n```","cost":0.0004662,"response_parsed":"SELECT SourceAirport\nFROM flights\nORDER BY SourceAirport ASC;","time":3.7576358318}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `SourceAirport` FROM `flights` ORDER BY `SourceAirport` DESC","question":"Project the SourceAirport ordered in descending order for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo project the `SourceAirport` from the `flights` table and order it in descending order, you can use the following SQL query:\n\n```sql\nSELECT SourceAirport\nFROM flights\nORDER BY SourceAirport DESC;\n```","cost":0.0003789,"response_parsed":"SELECT SourceAirport\nFROM flights\nORDER BY SourceAirport DESC;","time":2.7430644035}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `uid` FROM `airlines`","question":"Show all uid in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `uid` values from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT uid FROM airlines;\n```","cost":0.0004473,"response_parsed":"SELECT uid FROM airlines;","time":4.0139455795}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Airline` FROM `airlines`","question":"Show all Airline in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all airlines from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines;\n```\n\nThis query will return all columns (`uid`, `Airline`, `Abbreviation`, and `Country`) for every row in the `airlines` table.","cost":0.0005958,"response_parsed":"SELECT * FROM airlines;","time":5.2941355705}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Abbreviation` FROM `airlines`","question":"Show all Abbreviation in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all abbreviations from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation FROM airlines;\n```\n\nThis query will return all the entries in the `Abbreviation` column of your `airlines` table. If you want to ensure that each abbreviation appears only once (in case of duplicates), you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Abbreviation FROM airlines;\n```","cost":0.0004329,"response_parsed":"SELECT DISTINCT Abbreviation FROM airlines;","time":3.406175375}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Country` FROM `airlines`","question":"Show all Country in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all countries from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country FROM airlines;\n```\n\nThis query will return a list of all unique countries present in the `airlines` table.","cost":0.0004518,"response_parsed":"SELECT DISTINCT Country FROM airlines;","time":3.4012992382}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `airlines`","question":"Show all the rows in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all rows from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines;\n```","cost":0.0005085,"response_parsed":"SELECT * FROM airlines;","time":4.1408824921}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `uid` FROM `airlines`","question":"Show all uid in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `uid` values from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT uid FROM airlines;\n```","cost":0.0004041,"response_parsed":"SELECT uid FROM airlines;","time":2.9235069752}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Abbreviation`, `uid` FROM `airlines`","question":"Show all Abbreviation, uid in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all abbreviations and their corresponding `uid` from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT Abbreviation, uid FROM airlines;\n```","cost":0.0004977,"response_parsed":"SELECT Abbreviation, uid FROM airlines;","time":4.2162423134}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Country`, `uid`, `Abbreviation` FROM `airlines`","question":"Show all Country, uid, Abbreviation in the table airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all the `Country`, `uid`, and `Abbreviation` from the `airlines` table, you can use the following SQL query:\n\n```sql\nSELECT Country, uid, Abbreviation FROM airlines;\n```","cost":0.000414,"response_parsed":"SELECT Country, uid, Abbreviation FROM airlines;","time":2.9912173748}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `City` FROM `airports`","question":"Show all City in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all cities from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT City FROM airports;\n```\n\nThis query will return all the city names stored in the `City` column of the `airports` table.","cost":0.0004968,"response_parsed":"SELECT City FROM airports;","time":4.2667682171}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `AirportCode` FROM `airports`","question":"Show all AirportCode in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `AirportCode` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportCode FROM airports;\n```","cost":0.0003609,"response_parsed":"SELECT AirportCode FROM airports;","time":2.4361302853}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `AirportName` FROM `airports`","question":"Show all AirportName in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `AirportName` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportName FROM airports;\n```\n\nThis query will return all the airport names stored in the `AirportName` column of the `airports` table.","cost":0.0004599,"response_parsed":"SELECT AirportName FROM airports;","time":3.5807609558}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Country` FROM `airports`","question":"Show all Country in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all countries from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Country FROM airports ORDER BY Country;\n```\n\nThis query will:\n1. Select the `Country` column from the `airports` table.\n2. Use `DISTINCT` to ensure each country appears only once.\n3. Order the results alphabetically by country name.","cost":0.0004815,"response_parsed":"SELECT DISTINCT Country FROM airports ORDER BY Country;","time":4.061422348}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `CountryAbbrev` FROM `airports`","question":"Show all CountryAbbrev in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `CountryAbbrev` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT CountryAbbrev FROM airports;\n```\n\nThis query will return all unique `CountryAbbrev` values present in the `airports` table.","cost":0.0005265,"response_parsed":"SELECT DISTINCT CountryAbbrev FROM airports;","time":4.1476471424}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `airports`","question":"Show all the rows in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo show all the rows in the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM airports;\n```\n\nThis query will return all columns (`City`, `AirportCode`, `AirportName`, `Country`, `CountryAbbrev`) for every row in the `airports` table.","cost":0.00054,"response_parsed":"SELECT * FROM airports;","time":4.5054349899}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `City` FROM `airports`","question":"Show all City in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all cities from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT City FROM airports;\n```\n\nThis query will return all the city names stored in the `City` column of the `airports` table.","cost":0.0004968,"response_parsed":"SELECT City FROM airports;","time":4.3114414215}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Country`, `CountryAbbrev` FROM `airports`","question":"Show all Country, CountryAbbrev in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `Country` and `CountryAbbrev` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT Country, CountryAbbrev FROM airports;\n```","cost":0.0004284,"response_parsed":"SELECT Country, CountryAbbrev FROM airports;","time":3.0921258926}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `AirportCode`, `City`, `AirportName` FROM `airports`","question":"Show all AirportCode, City, AirportName in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `AirportCode`, `City`, and `AirportName` from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT AirportCode, City, AirportName FROM airports;\n```","cost":0.0003771,"response_parsed":"SELECT AirportCode, City, AirportName FROM airports;","time":2.7124733925}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Country`, `CountryAbbrev`, `City`, `AirportName` FROM `airports`","question":"Show all Country, CountryAbbrev, City, AirportName in the table airports","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all the specified columns from the `airports` table, you can use the following SQL query:\n\n```sql\nSELECT Country, CountryAbbrev, City, AirportName FROM airports;\n```","cost":0.0004104,"response_parsed":"SELECT Country, CountryAbbrev, City, AirportName FROM airports;","time":3.0472722054}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Airline` FROM `flights`","question":"Show all Airline in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all airlines from the `flights` table, we need to join the `flights` table with the `airlines` table since the `Airline` column in the `flights` table is a foreign key referencing the `uid` in the `airlines` table.\n\nHere is the SQL code:\n\n```sql\nSELECT DISTINCT a.Airline\nFROM flights f\nJOIN airlines a ON f.Airline = a.uid;\n```\n\nThis query will return all unique airline names that exist in the `flights` table.","cost":0.0005193,"response_parsed":"SELECT DISTINCT a.Airline\nFROM flights f\nJOIN airlines a ON f.Airline = a.uid;","time":4.2892522812}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `FlightNo` FROM `flights`","question":"Show all FlightNo in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `FlightNo` from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT FlightNo FROM flights;\n```","cost":0.0005598,"response_parsed":"SELECT FlightNo FROM flights;","time":4.8180587292}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `SourceAirport` FROM `flights`","question":"Show all SourceAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `SourceAirport` entries from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT SourceAirport FROM flights;\n```\n\nThis query will return all unique `SourceAirport` values present in the `flights` table.","cost":0.0004356,"response_parsed":"SELECT DISTINCT SourceAirport FROM flights;","time":3.7399251461}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `DestAirport` FROM `flights`","question":"Show all DestAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `DestAirport` values from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT DestAirport FROM flights;\n```\n\nThis query will return all destination airport codes from the `flights` table. If you want to retrieve unique destination airports (i.e., without duplicates), you can modify the query to:\n\n```sql\nSELECT DISTINCT DestAirport FROM flights;\n```","cost":0.0004185,"response_parsed":"SELECT DISTINCT DestAirport FROM flights;","time":3.009916544}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `flights`","question":"Show all the rows in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo show all the rows in the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM flights;\n```\n\nThis query will return all columns (`*`) for every row in the `flights` table.","cost":0.0004617,"response_parsed":"SELECT * FROM flights;","time":3.8458821774}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `DestAirport` FROM `flights`","question":"Show all DestAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `DestAirport` values from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT DestAirport FROM flights;\n```\n\nIf you want to retrieve unique `DestAirport` values (i.e., distinct destinations), you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT DestAirport FROM flights;\n```","cost":0.0004059,"response_parsed":"SELECT DISTINCT DestAirport FROM flights;","time":2.9579293728}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `SourceAirport`, `DestAirport` FROM `flights`","question":"Show all SourceAirport, DestAirport in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch all `SourceAirport` and `DestAirport` from the `flights` table, you can use the following SQL query:\n\n```sql\nSELECT SourceAirport, DestAirport FROM flights;\n```\n\nThis query will return all rows from the `flights` table, showing the `SourceAirport` and `DestAirport` columns.","cost":0.0004356,"response_parsed":"SELECT SourceAirport, DestAirport FROM flights;","time":3.2443344593}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Airline`, `SourceAirport`, `FlightNo` FROM `flights`","question":"Show all Airline, SourceAirport, FlightNo in the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the required information, we need to join the `flights` table with the `airlines` table since the `Airline` column in `flights` is a foreign key referencing the `uid` in `airlines`. Here's the SQL query:\n\n```sql\nSELECT a.Airline, f.SourceAirport, f.FlightNo\nFROM flights f\nINNER JOIN airlines a ON f.Airline = a.uid;\n```","cost":0.0005643,"response_parsed":"SELECT a.Airline, f.SourceAirport, f.FlightNo\nFROM flights f\nINNER JOIN airlines a ON f.Airline = a.uid;","time":4.4699347019}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Airline` == 'Delta Airlines'","question":"Show the data of the table airlines where Airline is equal to Delta Airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Airline` is \"Delta Airlines,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines WHERE Airline = 'Delta Airlines';\n```","cost":0.0004887,"response_parsed":"SELECT * FROM airlines WHERE Airline = 'Delta Airlines';","time":3.9997854233}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Airline` != 'United Airlines'","question":"Show the data of the table airlines where Airline is different from United Airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Airline` is different from \"United Airlines,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM airlines\nWHERE Airline <> 'United Airlines';\n```","cost":0.0005904,"response_parsed":"SELECT *\nFROM airlines\nWHERE Airline <> 'United Airlines';","time":5.4796390533}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Airline` != 'Delta Airlines'","question":"Show the data of the table airlines where Airline not equal to Delta Airlines","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Airline` is not \"Delta Airlines,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines WHERE Airline != 'Delta Airlines';\n```","cost":0.0006957,"response_parsed":"SELECT * FROM airlines WHERE Airline != 'Delta Airlines';","time":6.0590322018}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Abbreviation` == 'USAir'","question":"Show the data of the table airlines where Abbreviation is equal to USAir","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Abbreviation` is 'USAir', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM airlines\nWHERE Abbreviation = 'USAir';\n```","cost":0.000468,"response_parsed":"SELECT *\nFROM airlines\nWHERE Abbreviation = 'USAir';","time":3.7662689686}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Abbreviation` != 'Southwest'","question":"Show the data of the table airlines where Abbreviation is different from Southwest","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Abbreviation` is different from \"Southwest,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines WHERE Abbreviation <> 'Southwest';\n```","cost":0.0005067,"response_parsed":"SELECT * FROM airlines WHERE Abbreviation <> 'Southwest';","time":3.9803218842}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Abbreviation` != 'American'","question":"Show the data of the table airlines where Abbreviation not equal to American","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Abbreviation` is not 'American', you can use the following SQL query:\n\n```sql\nSELECT * FROM airlines WHERE Abbreviation <> 'American';\n```","cost":0.0005229,"response_parsed":"SELECT * FROM airlines WHERE Abbreviation <> 'American';","time":4.7145543098}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airlines` WHERE `Country` == 'USA'","question":"Show the data of the table airlines where Country is equal to USA","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airlines` table where the `Country` is 'USA', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM airlines\nWHERE Country = 'USA';\n```","cost":0.0005508,"response_parsed":"SELECT *\nFROM airlines\nWHERE Country = 'USA';","time":4.7790250778}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `City` == 'Abingdon '","question":"Show the data of the table airports where City is equal to Abingdon ","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where the `City` is \"Abingdon\", you can use the following SQL query:\n\n```sql\nSELECT * FROM airports WHERE City = 'Abingdon';\n```","cost":0.0005598,"response_parsed":"SELECT * FROM airports WHERE City = 'Abingdon';","time":5.0725543499}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `City` != 'Ada '","question":"Show the data of the table airports where City is different from Ada ","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where the `City` is different from \"Ada,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM airports\nWHERE City != 'Ada';\n```\n\nThis query will return all rows from the `airports` table where the `City` column does not contain the value \"Ada.\"","cost":0.0005652,"response_parsed":"SELECT *\nFROM airports\nWHERE City != 'Ada';","time":5.3873119354}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `City` != 'Abingdon '","question":"Show the data of the table airports where City not equal to Abingdon ","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where the `City` is not equal to \"Abingdon\", you can use the following SQL query:\n\n```sql\nSELECT * FROM airports WHERE City != 'Abingdon';\n```","cost":0.0005724,"response_parsed":"SELECT * FROM airports WHERE City != 'Abingdon';","time":5.556189537}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `CountryAbbrev` == 'US'","question":"Show the data of the table airports where CountryAbbrev is equal to US","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where `CountryAbbrev` is equal to 'US', you can use the following SQL query:\n\n```sql\nSELECT * FROM airports WHERE CountryAbbrev = 'US';\n```","cost":0.0005373,"response_parsed":"SELECT * FROM airports WHERE CountryAbbrev = 'US';","time":4.2661628723}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `CountryAbbrev` != 'US '","question":"Show the data of the table airports where CountryAbbrev is different from US ","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where the `CountryAbbrev` is different from 'US', you can use the following SQL query:\n\n```sql\nSELECT * FROM airports WHERE CountryAbbrev != 'US';\n```","cost":0.000621,"response_parsed":"SELECT * FROM airports WHERE CountryAbbrev != 'US';","time":5.0045819283}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `CountryAbbrev` != 'US'","question":"Show the data of the table airports where CountryAbbrev not equal to US","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where `CountryAbbrev` is not equal to 'US', you can use the following SQL query:\n\n```sql\nSELECT * FROM airports WHERE CountryAbbrev <> 'US';\n```","cost":0.0005508,"response_parsed":"SELECT * FROM airports WHERE CountryAbbrev <> 'US';","time":4.6304254532}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `airports` WHERE `Country` == 'United States '","question":"Show the data of the table airports where Country is equal to United States ","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `airports` table where the `Country` is \"United States\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM airports\nWHERE Country = 'United States';\n```","cost":0.0004851,"response_parsed":"SELECT *\nFROM airports\nWHERE Country = 'United States';","time":3.9519989491}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `SourceAirport` == ' ACV'","question":"Show the data of the table flights where SourceAirport is equal to ACV","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `SourceAirport` is equal to `ACV`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE SourceAirport = 'ACV';\n```","cost":0.0004491,"response_parsed":"SELECT *\nFROM flights\nWHERE SourceAirport = 'ACV';","time":3.3143768311}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `SourceAirport` != ' ASY'","question":"Show the data of the table flights where SourceAirport is different from ASY","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where the `SourceAirport` is different from 'ASY', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE SourceAirport <> 'ASY';\n```","cost":0.0003834,"response_parsed":"SELECT *\nFROM flights\nWHERE SourceAirport <> 'ASY';","time":2.5883677006}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `SourceAirport` != ' ACV'","question":"Show the data of the table flights where SourceAirport not equal to ACV","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `SourceAirport` is not equal to `ACV`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE SourceAirport <> 'ACV';\n```","cost":0.0005643,"response_parsed":"SELECT *\nFROM flights\nWHERE SourceAirport <> 'ACV';","time":4.7580301762}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `DestAirport` == ' AHT'","question":"Show the data of the table flights where DestAirport is equal to AHT","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `DestAirport` is equal to 'AHT', you can use the following SQL query:\n\n```sql\nSELECT * FROM flights WHERE DestAirport = 'AHT';\n```","cost":0.0004716,"response_parsed":"SELECT * FROM flights WHERE DestAirport = 'AHT';","time":3.5400290489}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `DestAirport` != ' ASY'","question":"Show the data of the table flights where DestAirport is different from ASY","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `DestAirport` is different from 'ASY', you can use the following SQL query:\n\n```sql\nSELECT * FROM flights WHERE DestAirport <> 'ASY';\n```","cost":0.000549,"response_parsed":"SELECT * FROM flights WHERE DestAirport <> 'ASY';","time":4.3676280975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `flights` WHERE `DestAirport` != ' ASY'","question":"Show the data of the table flights where DestAirport not equal to ASY","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `DestAirport` is not equal to 'ASY', you can use the following SQL query:\n\n```sql\nSELECT * FROM flights WHERE DestAirport != 'ASY';\n```","cost":0.0005526,"response_parsed":"SELECT * FROM flights WHERE DestAirport != 'ASY';","time":4.5005369186}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `flights` WHERE `Airline` > 1","question":"Show the data of the table flights where Airline is greater than 1","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where the `Airline` is greater than 1, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE Airline > 1;\n```","cost":0.0004023,"response_parsed":"SELECT *\nFROM flights\nWHERE Airline > 1;","time":3.1345698833}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `flights` WHERE `FlightNo` > 54","question":"Show the data of the table flights where FlightNo is greater than 54","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `FlightNo` is greater than 54, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE FlightNo > 54;\n```","cost":0.0004815,"response_parsed":"SELECT *\nFROM flights\nWHERE FlightNo > 54;","time":3.6364233494}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `flights` WHERE `FlightNo` < 28","question":"Show the data of the table flights where FlightNo is less than 28","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo fetch the data from the `flights` table where `FlightNo` is less than 28, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM flights\nWHERE FlightNo < 28;\n```","cost":0.0004689,"response_parsed":"SELECT *\nFROM flights\nWHERE FlightNo < 28;","time":3.5397117138}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Airline`) FROM `airlines`","question":"How many different Airline are in table airlines?","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different airlines are in the `airlines` table, you can use the `COUNT(DISTINCT)` function on the `Airline` column. This will count the number of unique airline names in the table.\n\n```sql\nSELECT COUNT(DISTINCT Airline) AS NumberOfAirlines\nFROM airlines;\n```","cost":0.0004392,"response_parsed":"SELECT COUNT(DISTINCT Airline) AS NumberOfAirlines\nFROM airlines;","time":3.8170471191}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Abbreviation`) FROM `airlines`","question":"How many different Abbreviation are in table airlines?","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different abbreviations are in the `airlines` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT Abbreviation) FROM airlines;\n```","cost":0.0004896,"response_parsed":"SELECT COUNT(DISTINCT Abbreviation) FROM airlines;","time":4.4475104809}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airlines","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Country`) FROM `airlines`","question":"How many different Country are in table airlines?","db_schema_normalized":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different countries are in the `airlines` table, you can use the `COUNT(DISTINCT)` function on the `Country` column. Here is the SQL code:\n\n```sql\nSELECT COUNT(DISTINCT Country) FROM airlines;\n```","cost":0.0006057,"response_parsed":"SELECT COUNT(DISTINCT Country) FROM airlines;","time":5.8754169941}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `City`) FROM `airports`","question":"How many different City are in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine the number of different cities in the airports table, we use the COUNT(DISTINCT column_name) function to count unique entries in the City column.\n\n```sql\nSELECT COUNT(DISTINCT City) FROM airports;\n```","cost":0.0005823,"response_parsed":"SELECT COUNT(DISTINCT City) FROM airports;","time":4.9625005722}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `AirportCode`) FROM `airports`","question":"How many different AirportCode are in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different `AirportCode`s are in the `airports` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\n```sql\nSELECT COUNT(DISTINCT AirportCode) FROM airports;\n```","cost":0.0004707,"response_parsed":"SELECT COUNT(DISTINCT AirportCode) FROM airports;","time":3.9886097908}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `AirportName`) FROM `airports`","question":"How many different AirportName are in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different `AirportName` entries are in the `airports` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT AirportName) FROM airports;\n```","cost":0.0005715,"response_parsed":"SELECT COUNT(DISTINCT AirportName) FROM airports;","time":4.8336338997}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Country`) FROM `airports`","question":"How many different Country are in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine the number of different countries in the `airports` table, we use the `COUNT(DISTINCT column_name)` function on the `Country` column. This function counts each unique country only once, ignoring any NULL values.\n\n```sql\nSELECT COUNT(DISTINCT Country) FROM airports;\n```","cost":0.0006255,"response_parsed":"SELECT COUNT(DISTINCT Country) FROM airports;","time":5.4784398079}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"airports","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `CountryAbbrev`) FROM `airports`","question":"How many different CountryAbbrev are in table airports?","db_schema_normalized":"`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different `CountryAbbrev` values are present in the `airports` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT CountryAbbrev) AS Number_of_CountryAbbrev\nFROM airports;\n```\n\nThis query will return the number of unique `CountryAbbrev` values in your `airports` table.","cost":0.0004248,"response_parsed":"SELECT COUNT(DISTINCT CountryAbbrev) AS Number_of_CountryAbbrev\nFROM airports;","time":3.4036509991}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `SourceAirport`) FROM `flights`","question":"How many different SourceAirport are in table flights?","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different `SourceAirport` values are in the `flights` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT SourceAirport) FROM flights;\n```","cost":0.0004977,"response_parsed":"SELECT COUNT(DISTINCT SourceAirport) FROM flights;","time":4.1834471226}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `DestAirport`) FROM `flights`","question":"How many different DestAirport are in table flights?","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo determine how many different `DestAirport` values are in the `flights` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT DestAirport) AS NumberOfDestAirports\nFROM flights;\n```\n\nThis query will return the number of unique destination airports present in the `flights` table.","cost":0.0005112,"response_parsed":"SELECT COUNT(DISTINCT DestAirport) AS NumberOfDestAirports\nFROM flights;","time":4.9566345215}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Airline`) FROM `flights`","question":"Find the maximum Airline for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum Airline for the table `flights`, we need to determine which airline has the highest number of flights. This can be achieved by counting the number of flights each airline operates and then identifying the airline with the highest count.\n\nHere is the SQL code to accomplish this:\n\n```sql\nSELECT Airline, COUNT(FlightNo) as NumberOfFlights\nFROM flights\nGROUP BY Airline\nORDER BY NumberOfFlights DESC\nLIMIT 1;\n```\n\nThis query:\n1. Selects the `Airline` column and counts the number of `FlightNo` entries for each airline.\n2. Groups the results by the `Airline` column.\n3. Orders the results in descending order based on the count of flights.\n4. Limits the output to the top result, which corresponds to the airline with the maximum number of flights.","cost":0.0006291,"response_parsed":"SELECT Airline, COUNT(FlightNo) as NumberOfFlights\nFROM flights\nGROUP BY Airline\nORDER BY NumberOfFlights DESC\nLIMIT 1;","time":5.9912040234}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Airline`) FROM `flights`","question":"Find the minimum Airline for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum Airline for the table flights, we can use the SQL `MIN()` function on the `Airline` column in the `flights` table.\n\n```sql\nSELECT MIN(Airline) FROM flights;\n```","cost":0.0005031,"response_parsed":"SELECT MIN(Airline) FROM flights;","time":4.6472978592}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Airline`) FROM `flights`","question":"Find the average Airline for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the average number of flights per airline, we can use the following SQL query:\n\n```sql\nSELECT AVG(FlightCount) AS AverageFlightsPerAirline\nFROM (\n SELECT Airline, COUNT(*) AS FlightCount\n FROM flights\n GROUP BY Airline\n) AS FlightCounts;\n```\n\nThis query first counts the number of flights for each airline and then calculates the average of these counts.","cost":0.0005922,"response_parsed":"SELECT AVG(FlightCount) AS AverageFlightsPerAirline\nFROM (\n SELECT Airline, COUNT(*) AS FlightCount\n FROM flights\n GROUP BY Airline\n) AS FlightCounts;","time":5.4560940266}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`FlightNo`) FROM `flights`","question":"Find the maximum FlightNo for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the maximum `FlightNo` in the `flights` table, you can use the SQL `MAX()` function. Here's the SQL query:\n\n```sql\nSELECT MAX(FlightNo) FROM flights;\n```","cost":0.0004536,"response_parsed":"SELECT MAX(FlightNo) FROM flights;","time":4.0903577805}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`FlightNo`) FROM `flights`","question":"Find the minimum FlightNo for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the minimum `FlightNo` in the `flights` table, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(FlightNo) FROM flights;\n```","cost":0.0003996,"response_parsed":"SELECT MIN(FlightNo) FROM flights;","time":3.1006617546}} {"db_path":"QATCH-journal\/spider_data\/test_database\/flight_2\/flight_2.sqlite","db_id":"flight_2","tbl_name":"flights","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`FlightNo`) FROM `flights`","question":"Find the average FlightNo for the table flights","db_schema_normalized":"`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","db_schema":"`'airlines'` (uid INTEGER PRIMARY KEY, Airline TEXT, Abbreviation TEXT, Country TEXT)\n`'airports'` (City TEXT, AirportCode TEXT PRIMARY KEY, AirportName TEXT, Country TEXT, CountryAbbrev TEXT)\n`'flights'` (Airline INTEGER, FlightNo INTEGER, SourceAirport TEXT, DestAirport TEXT, PRIMARY KEY(Airline, FlightNo), FOREIGN KEY (SourceAirport) REFERENCES airports(AirportCode), FOREIGN KEY (DestAirport) REFERENCES airports(AirportCode))","pred_dict":{"response":"\n\nTo find the average `FlightNo` for the table `flights`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(FlightNo) AS AverageFlightNo FROM flights;\n```\n\nThis query will calculate the average value of the `FlightNo` column in your `flights` table and return it under the alias `AverageFlightNo`.","cost":0.0004113,"response_parsed":"SELECT AVG(FlightNo) AS AverageFlightNo FROM flights;","time":3.2008664608}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `employee`","question":"Show the different Name in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the different names from the `employee` table, you can use the `DISTINCT` keyword in SQL to retrieve unique values from the `Name` column. Here's the SQL code:\n\n```sql\nSELECT DISTINCT Name FROM employee;\n```\n\nThis query will return all unique names present in the `Name` column of the `employee` table.","cost":0.0005616,"response_parsed":"SELECT DISTINCT Name FROM employee;","time":4.1859164238}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `City` FROM `employee`","question":"Show the different City in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the different cities from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT City FROM employee;\n```\n\nThis query will return a list of unique city names present in the `City` column of the `employee` table.","cost":0.0004779,"response_parsed":"SELECT DISTINCT City FROM employee;","time":3.3969171047}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Employee_ID` FROM `evaluation`","question":"Show the different Employee_ID in the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show the different `Employee_ID`s in the `evaluation` table, you can use the `SELECT DISTINCT` statement to fetch unique `Employee_ID`s.\n\n```sql\nSELECT DISTINCT Employee_ID FROM evaluation;\n```","cost":0.0004662,"response_parsed":"SELECT DISTINCT Employee_ID FROM evaluation;","time":3.1858780384}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Year_awarded` FROM `evaluation`","question":"Show the different Year_awarded in the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the different `Year_awarded` values from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Year_awarded FROM evaluation;\n```\n\nThis query will return all unique `Year_awarded` values present in the `evaluation` table.","cost":0.0005526,"response_parsed":"SELECT DISTINCT Year_awarded FROM evaluation;","time":3.7246441841}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Start_from` FROM `hiring`","question":"Show the different Start_from in the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the different `Start_from` values from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Start_from FROM hiring;\n```\n\nThis query will return all unique values in the `Start_from` column of the `hiring` table.","cost":0.000531,"response_parsed":"SELECT DISTINCT Start_from FROM hiring;","time":3.8332138062}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `shop`","question":"Show the different Name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show the different names in the `shop` table, you can use the `DISTINCT` keyword in SQL to fetch unique names. Here's the SQL code:\n\n```sql\nSELECT DISTINCT Name FROM shop;\n```","cost":0.0004554,"response_parsed":"SELECT DISTINCT Name FROM shop;","time":2.8817827702}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Location` FROM `shop`","question":"Show the different Location in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show the different locations in the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT `Location` FROM `shop`;\n```\n\nThis query will return all unique locations present in the `shop` table.","cost":0.000504,"response_parsed":"SELECT DISTINCT `Location` FROM `shop`;","time":3.450368166}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `District` FROM `shop`","question":"Show the different District in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show the different districts in the `shop` table, you can use the `SELECT DISTINCT` statement to retrieve unique district values.\n\n```sql\nSELECT DISTINCT District FROM shop;\n```","cost":0.0004833,"response_parsed":"SELECT DISTINCT District FROM shop;","time":3.3715555668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Manager_name` FROM `shop`","question":"Show the different Manager_name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the different `Manager_name` from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Manager_name FROM shop;\n```\n\nThis query will return all unique `Manager_name` values present in the `shop` table.","cost":0.0004617,"response_parsed":"SELECT DISTINCT Manager_name FROM shop;","time":2.8644504547}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `employee` GROUP BY `Name`","question":"For each Name, count the number of rows in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows for each `Name` in the `employee` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, COUNT(*) AS Row_Count\nFROM employee\nGROUP BY Name;\n```\n\nThis query will return the number of rows for each unique `Name` in the `employee` table.","cost":0.0005949,"response_parsed":"SELECT Name, COUNT(*) AS Row_Count\nFROM employee\nGROUP BY Name;","time":4.3530218601}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `City`, COUNT(*) FROM `employee` GROUP BY `City`","question":"For each City, count the number of rows in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows in the `employee` table for each City, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT City, COUNT(*) AS Number_of_Employees\nFROM employee\nGROUP BY City;\n```\n\nThis query will:\n1. Select the `City` column\n2. Count the number of rows for each City using `COUNT(*)`\n3. Group the results by the `City` column\n4. Return the number of employees for each City","cost":0.0006948,"response_parsed":"SELECT City, COUNT(*) AS Number_of_Employees\nFROM employee\nGROUP BY City;","time":5.6732335091}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Age`) FROM `employee` GROUP BY `Name`","question":"For each Name, find the min of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum age for each name in the `employee` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MIN(Age) AS Min_Age\nFROM employee\nGROUP BY Name;\n```\n\nThis query will return the minimum age for each unique name in the `employee` table.","cost":0.0005544,"response_parsed":"SELECT Name, MIN(Age) AS Min_Age\nFROM employee\nGROUP BY Name;","time":4.328802824}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Age`) FROM `employee` GROUP BY `Name`","question":"For each Name, find the max of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum age for each name in the `employee` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MAX(Age) AS Max_Age\nFROM employee\nGROUP BY Name;\n```\n\nThis query will return the maximum age for each unique name in the `employee` table.","cost":0.00054,"response_parsed":"SELECT Name, MAX(Age) AS Max_Age\nFROM employee\nGROUP BY Name;","time":4.1888935566}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Age`) FROM `employee` GROUP BY `Name`","question":"For each Name, find the avg of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average age for each name in the `employee` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name,\n AVG(Age) AS Average_Age\nFROM \n employee\nGROUP BY \n Name;\n```\n\nThis query will return the average age for each unique name in the `employee` table.","cost":0.0005499,"response_parsed":"SELECT \n Name,\n AVG(Age) AS Average_Age\nFROM \n employee\nGROUP BY \n Name;","time":4.696403265}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Age`) FROM `employee` GROUP BY `Name`","question":"For each Name, find the sum of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the sum of `Age` for each `Name` in the `employee` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name,\n SUM(Age) AS Total_Age\nFROM \n employee\nGROUP BY \n Name;\n```\n\nThis query will:\n1. Select the `Name` column\n2. Calculate the sum of the `Age` column for each group of rows with the same `Name`\n3. Group the results by the `Name` column\n4. Return the result with the sum of ages for each name","cost":0.0005805,"response_parsed":"SELECT \n Name,\n SUM(Age) AS Total_Age\nFROM \n employee\nGROUP BY \n Name;","time":5.0480463505}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `City`, MIN(`Age`) FROM `employee` GROUP BY `City`","question":"For each City, find the min of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum age for each city in the `employee` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT City, MIN(Age) AS Min_Age\nFROM employee\nGROUP BY City;\n```\n\nThis query will return the minimum age for each city in your `employee` table.","cost":0.0005814,"response_parsed":"SELECT City, MIN(Age) AS Min_Age\nFROM employee\nGROUP BY City;","time":5.2896695137}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `City`, MAX(`Age`) FROM `employee` GROUP BY `City`","question":"For each City, find the max of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum age for each city in the `employee` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT City, MAX(Age) as Max_Age\nFROM employee\nGROUP BY City;\n```\n\nThis query will return the maximum age for each city in your database.","cost":0.0004932,"response_parsed":"SELECT City, MAX(Age) as Max_Age\nFROM employee\nGROUP BY City;","time":3.7677338123}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `City`, AVG(`Age`) FROM `employee` GROUP BY `City`","question":"For each City, find the avg of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average age of employees in each city, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how to do it:\n\n```sql\nSELECT \n City,\n AVG(Age) AS Average_Age\nFROM \n employee\nGROUP BY \n City;\n```\n\nThis query will:\n1. Select the `City` column\n2. Calculate the average age for each city using `AVG(Age)`\n3. Group the results by the `City` column\n4. Return the city name along with the average age for that city","cost":0.0004986,"response_parsed":"SELECT \n City,\n AVG(Age) AS Average_Age\nFROM \n employee\nGROUP BY \n City;","time":3.3446993828}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `City`, SUM(`Age`) FROM `employee` GROUP BY `City`","question":"For each City, find the sum of Age in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the sum of `Age` for each `City` in the `employee` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n City,\n SUM(Age) AS Total_Age\nFROM \n employee\nGROUP BY \n City;\n```\n\nThis query will:\n1. Select the `City` column\n2. Calculate the sum of the `Age` column for each city\n3. Group the results by the `City` column\n4. Alias the sum of ages as `Total_Age` for better readability","cost":0.000531,"response_parsed":"SELECT \n City,\n SUM(Age) AS Total_Age\nFROM \n employee\nGROUP BY \n City;","time":4.0589170456}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Employee_ID`, COUNT(*) FROM `evaluation` GROUP BY `Employee_ID`","question":"For each Employee_ID, count the number of rows in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows for each `Employee_ID` in the `evaluation` table, you can use the `COUNT(*)` function combined with a `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Employee_ID,\n COUNT(*) as number_of_rows\nFROM \n evaluation\nGROUP BY \n Employee_ID;\n```\n\nThis query will return the number of rows in the `evaluation` table for each `Employee_ID`.","cost":0.0006156,"response_parsed":"SELECT \n Employee_ID,\n COUNT(*) as number_of_rows\nFROM \n evaluation\nGROUP BY \n Employee_ID;","time":4.8820297718}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Year_awarded`, COUNT(*) FROM `evaluation` GROUP BY `Year_awarded`","question":"For each Year_awarded, count the number of rows in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows in the `evaluation` table for each `Year_awarded`, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by `Year_awarded`.\n\n```sql\nSELECT \n Year_awarded,\n COUNT(*) AS Number_of_rows\nFROM \n evaluation\nGROUP BY \n Year_awarded;\n```","cost":0.0005355,"response_parsed":"SELECT \n Year_awarded,\n COUNT(*) AS Number_of_rows\nFROM \n evaluation\nGROUP BY \n Year_awarded;","time":3.789031744}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Employee_ID`, MIN(`Bonus`) FROM `evaluation` GROUP BY `Employee_ID`","question":"For each Employee_ID, find the min of Bonus in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum Bonus for each Employee_ID in the `evaluation` table, you can use the SQL `MIN()` function combined with `GROUP BY`. Here's how to do it:\n\n```sql\nSELECT Employee_ID, MIN(Bonus) AS Min_Bonus\nFROM evaluation\nGROUP BY Employee_ID;\n```\n\nThis query will return each Employee_ID along with their minimum Bonus value from the `evaluation` table.","cost":0.000675,"response_parsed":"SELECT Employee_ID, MIN(Bonus) AS Min_Bonus\nFROM evaluation\nGROUP BY Employee_ID;","time":4.9069545269}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Employee_ID`, MAX(`Bonus`) FROM `evaluation` GROUP BY `Employee_ID`","question":"For each Employee_ID, find the max of Bonus in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum bonus for each employee from the `evaluation` table, you can use the SQL `MAX()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT Employee_ID, MAX(Bonus) AS max_bonus\nFROM evaluation\nGROUP BY Employee_ID;\n```\n\nThis query will return each `Employee_ID` along with their highest bonus value from the `evaluation` table.","cost":0.0006381,"response_parsed":"SELECT Employee_ID, MAX(Bonus) AS max_bonus\nFROM evaluation\nGROUP BY Employee_ID;","time":4.7839207649}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Employee_ID`, AVG(`Bonus`) FROM `evaluation` GROUP BY `Employee_ID`","question":"For each Employee_ID, find the avg of Bonus in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average bonus for each `Employee_ID` in the `evaluation` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Employee_ID,\n AVG(Bonus) AS Avg_Bonus\nFROM \n evaluation\nGROUP BY \n Employee_ID;\n```\n\nThis query will:\n1. Select the `Employee_ID` and the average of the `Bonus` column\n2. Group the results by `Employee_ID`\n3. Return the average bonus for each employee","cost":0.0005886,"response_parsed":"SELECT \n Employee_ID,\n AVG(Bonus) AS Avg_Bonus\nFROM \n evaluation\nGROUP BY \n Employee_ID;","time":3.9361672401}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Employee_ID`, SUM(`Bonus`) FROM `evaluation` GROUP BY `Employee_ID`","question":"For each Employee_ID, find the sum of Bonus in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the sum of bonuses for each employee from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT \n Employee_ID,\n SUM(Bonus) AS Total_Bonus\nFROM \n evaluation\nGROUP BY \n Employee_ID;\n```\n\nThis query will:\n1. Select the `Employee_ID` and the sum of the `Bonus` column\n2. Group the results by `Employee_ID`\n3. Return the total bonus for each employee","cost":0.000657,"response_parsed":"SELECT \n Employee_ID,\n SUM(Bonus) AS Total_Bonus\nFROM \n evaluation\nGROUP BY \n Employee_ID;","time":4.8007202148}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Year_awarded`, MIN(`Bonus`) FROM `evaluation` GROUP BY `Year_awarded`","question":"For each Year_awarded, find the min of Bonus in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum Bonus for each Year_awarded in the evaluation table, we can use the SQL `MIN` function combined with `GROUP BY`.\n\n```sql\nSELECT Year_awarded, MIN(Bonus) AS Min_Bonus\nFROM evaluation\nGROUP BY Year_awarded;\n```","cost":0.0006525,"response_parsed":"SELECT Year_awarded, MIN(Bonus) AS Min_Bonus\nFROM evaluation\nGROUP BY Year_awarded;","time":6.1955456734}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Year_awarded`, MAX(`Bonus`) FROM `evaluation` GROUP BY `Year_awarded`","question":"For each Year_awarded, find the max of Bonus in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum Bonus for each Year_awarded in the evaluation table, we can use the SQL `MAX()` function combined with `GROUP BY`.\n\n```sql\nSELECT \n Year_awarded,\n MAX(Bonus) AS max_bonus\nFROM \n evaluation\nGROUP BY \n Year_awarded;\n```","cost":0.0005481,"response_parsed":"SELECT \n Year_awarded,\n MAX(Bonus) AS max_bonus\nFROM \n evaluation\nGROUP BY \n Year_awarded;","time":4.2665653229}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Year_awarded`, AVG(`Bonus`) FROM `evaluation` GROUP BY `Year_awarded`","question":"For each Year_awarded, find the avg of Bonus in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average Bonus for each Year_awarded in the `evaluation` table, you can use the SQL `AVG()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT \n Year_awarded,\n AVG(Bonus) AS Average_Bonus\nFROM \n evaluation\nGROUP BY \n Year_awarded\nORDER BY \n Year_awarded;\n```\n\nThis query will:\n1. Group the rows in the `evaluation` table by the `Year_awarded` column.\n2. Calculate the average Bonus for each group (each Year_awarded).\n3. Return the results sorted by Year_awarded.","cost":0.0006363,"response_parsed":"SELECT \n Year_awarded,\n AVG(Bonus) AS Average_Bonus\nFROM \n evaluation\nGROUP BY \n Year_awarded\nORDER BY \n Year_awarded;","time":5.2144269943}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Year_awarded`, SUM(`Bonus`) FROM `evaluation` GROUP BY `Year_awarded`","question":"For each Year_awarded, find the sum of Bonus in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the sum of `Bonus` for each `Year_awarded` from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded, SUM(Bonus) AS Total_Bonus\nFROM evaluation\nGROUP BY Year_awarded;\n```\n\nThis query will:\n1. Select the `Year_awarded` column.\n2. Calculate the sum of the `Bonus` column for each `Year_awarded`.\n3. Group the results by `Year_awarded` to ensure the sum is calculated per year.","cost":0.0006102,"response_parsed":"SELECT Year_awarded, SUM(Bonus) AS Total_Bonus\nFROM evaluation\nGROUP BY Year_awarded;","time":4.1966226101}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Start_from`, COUNT(*) FROM `hiring` GROUP BY `Start_from`","question":"For each Start_from, count the number of rows in table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows for each `Start_from` in the `hiring` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the `Start_from` dates.\n\n```sql\nSELECT \n Start_from, \n COUNT(*) AS Number_of_rows\nFROM \n hiring\nGROUP BY \n Start_from;\n```","cost":0.000558,"response_parsed":"SELECT \n Start_from, \n COUNT(*) AS Number_of_rows\nFROM \n hiring\nGROUP BY \n Start_from;","time":4.1398396492}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `shop` GROUP BY `Name`","question":"For each Name, count the number of rows in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows for each `Name` in the `shop` table, you can use the `COUNT(*)` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, COUNT(*) AS row_count\nFROM shop\nGROUP BY Name;\n```\n\nThis query will return the number of rows for each unique `Name` in the `shop` table.","cost":0.000621,"response_parsed":"SELECT Name, COUNT(*) AS row_count\nFROM shop\nGROUP BY Name;","time":4.5242877007}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Location`, COUNT(*) FROM `shop` GROUP BY `Location`","question":"For each Location, count the number of rows in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows in the `shop` table for each `Location`, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the `Location` column.\n\n```sql\nSELECT \n Location,\n COUNT(*) as Number_of_rows\nFROM \n shop\nGROUP BY \n Location;\n```","cost":0.0005364,"response_parsed":"SELECT \n Location,\n COUNT(*) as Number_of_rows\nFROM \n shop\nGROUP BY \n Location;","time":3.8122594357}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `District`, COUNT(*) FROM `shop` GROUP BY `District`","question":"For each District, count the number of rows in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo count the number of rows in the `shop` table for each district, you can use the `COUNT(*)` function combined with the `GROUP BY` clause to group the results by the `District` column.\n\n```sql\nSELECT \n District,\n COUNT(*) as Number_of_Shops\nFROM \n shop\nGROUP BY \n District;\n```","cost":0.0005526,"response_parsed":"SELECT \n District,\n COUNT(*) as Number_of_Shops\nFROM \n shop\nGROUP BY \n District;","time":3.8579528332}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Manager_name`, COUNT(*) FROM `shop` GROUP BY `Manager_name`","question":"For each Manager_name, count the number of rows in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question \"For each Manager_name, count the number of rows in table shop,\" we can use the SQL `COUNT()` function combined with the `GROUP BY` clause. This will allow us to count the number of rows for each unique `Manager_name` in the `shop` table.\n\nHere is the SQL code:\n\n```sql\nSELECT Manager_name, COUNT(*) AS Number_of_Shops\nFROM shop\nGROUP BY Manager_name;\n```\n\n### Explanation:\n- `SELECT Manager_name`: This selects the `Manager_name` column to group the results by each manager's name.\n- `COUNT(*) AS Number_of_Shops`: This counts the total number of rows for each `Manager_name` and aliases the result as `Number_of_Shops` for clarity.\n- `FROM shop`: This specifies the table from which to retrieve the data.\n- `GROUP BY Manager_name`: This groups the rows by the `Manager_name` column, allowing us to count the number of rows for each manager.\n\nThis query will return a result set with two columns:\n1. `Manager_name`: The name of each manager.\n2. `Number_of_Shops`: The number of rows (shops) associated with each manager.\n\nYou can execute this SQL code on your database to get the desired result.","cost":0.0009864,"response_parsed":"SELECT Manager_name, COUNT(*) AS Number_of_Shops\nFROM shop\nGROUP BY Manager_name;","time":8.6221630573}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Manager_name`, MIN(`Number_products`) FROM `shop` GROUP BY `Manager_name`","question":"For each Manager_name, find the min of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum number of products for each manager in the `shop` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Manager_name, MIN(Number_products) AS min_products\nFROM shop\nGROUP BY Manager_name;\n```\n\nThis query will return the minimum number of products for each manager in your database.","cost":0.0005967,"response_parsed":"SELECT Manager_name, MIN(Number_products) AS min_products\nFROM shop\nGROUP BY Manager_name;","time":4.5175616741}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Manager_name`, MAX(`Number_products`) FROM `shop` GROUP BY `Manager_name`","question":"For each Manager_name, find the max of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum number of products for each manager in the shop table, we can use the `MAX()` function combined with `GROUP BY` to group the results by `Manager_name`.\n\n```sql\nSELECT Manager_name, MAX(Number_products) AS max_products \nFROM shop \nGROUP BY Manager_name;\n```","cost":0.0006426,"response_parsed":"SELECT Manager_name, MAX(Number_products) AS max_products \nFROM shop \nGROUP BY Manager_name;","time":5.2114729881}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Manager_name`, AVG(`Number_products`) FROM `shop` GROUP BY `Manager_name`","question":"For each Manager_name, find the avg of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average of `Number_products` for each `Manager_name` in the `shop` table, you can use the SQL `AVG()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT \n Manager_name,\n AVG(Number_products) AS average_number_of_products\nFROM \n shop\nGROUP BY \n Manager_name;\n```\n\nThis query will:\n1. Group the rows in the `shop` table by `Manager_name`\n2. Calculate the average of `Number_products` for each group\n3. Return the result with `Manager_name` and the corresponding average\n\nThe result will show the average number of products each manager is responsible for.","cost":0.0006057,"response_parsed":"SELECT \n Manager_name,\n AVG(Number_products) AS average_number_of_products\nFROM \n shop\nGROUP BY \n Manager_name;","time":4.6001937389}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Manager_name`, SUM(`Number_products`) FROM `shop` GROUP BY `Manager_name`","question":"For each Manager_name, find the sum of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the sum of `Number_products` for each `Manager_name` in the `shop` table, you can use the SQL `GROUP BY` clause along with the `SUM()` function. Here's how you can do it:\n\n```sql\nSELECT \n Manager_name,\n SUM(Number_products) AS Total_products\nFROM \n shop\nGROUP BY \n Manager_name;\n```\n\nThis query will:\n1. Select the `Manager_name` column\n2. Calculate the sum of `Number_products` for each manager\n3. Group the results by `Manager_name`\n4. Return the total number of products each manager is responsible for\n\nThe result will show each manager's name along with the total number of products they manage.","cost":0.0006894,"response_parsed":"SELECT \n Manager_name,\n SUM(Number_products) AS Total_products\nFROM \n shop\nGROUP BY \n Manager_name;","time":5.1115765572}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Location`, MIN(`Number_products`) FROM `shop` GROUP BY `Location`","question":"For each Location, find the min of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum number of products for each location in the `shop` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Location,\n MIN(Number_products) AS min_products\nFROM \n shop\nGROUP BY \n Location;\n```\n\nThis query will return the minimum number of products for each unique location in the `shop` table.","cost":0.0005967,"response_parsed":"SELECT \n Location,\n MIN(Number_products) AS min_products\nFROM \n shop\nGROUP BY \n Location;","time":4.8270425797}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Location`, MAX(`Number_products`) FROM `shop` GROUP BY `Location`","question":"For each Location, find the max of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum number of products for each location in the `shop` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Location,\n MAX(Number_products) AS max_number_products\nFROM \n shop\nGROUP BY \n Location;\n```\n\nThis query will return the maximum number of products available in each location.","cost":0.0005157,"response_parsed":"SELECT \n Location,\n MAX(Number_products) AS max_number_products\nFROM \n shop\nGROUP BY \n Location;","time":3.6887450218}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Location`, AVG(`Number_products`) FROM `shop` GROUP BY `Location`","question":"For each Location, find the avg of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average number of products for each location in the `shop` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Location, AVG(Number_products) AS average_products\nFROM shop\nGROUP BY Location;\n```\n\nThis query will:\n1. Group the rows in the `shop` table by the `Location` column.\n2. Calculate the average of `Number_products` for each group (location).\n3. Return a result set with two columns: `Location` and `average_products` (the average number of products for that location).","cost":0.0005697,"response_parsed":"SELECT Location, AVG(Number_products) AS average_products\nFROM shop\nGROUP BY Location;","time":4.3208444118}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Location`, SUM(`Number_products`) FROM `shop` GROUP BY `Location`","question":"For each Location, find the sum of Number_products in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the sum of `Number_products` for each `Location` in the `shop` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Location,\n SUM(Number_products) AS Total_products\nFROM \n shop\nGROUP BY \n Location;\n```\n\nThis query will:\n1. Group all rows in the `shop` table by the `Location` column.\n2. Calculate the sum of `Number_products` for each group (i.e., for each location).\n3. Return a result set with two columns: `Location` and `Total_products` (the sum of products for that location).","cost":0.0006165,"response_parsed":"SELECT \n Location,\n SUM(Number_products) AS Total_products\nFROM \n shop\nGROUP BY \n Location;","time":4.3482375145}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the Names that have at least 1 record in the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Name FROM employee;\n```\n\nThis query will return all unique names of employees that exist in the `employee` table.","cost":0.0004932,"response_parsed":"SELECT DISTINCT Name FROM employee;","time":3.4693574905}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the Names that have at most 1 record in the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM (\n SELECT Name, COUNT(Employee_ID) as count_records\n FROM employee\n GROUP BY Name\n) AS name_counts\nWHERE count_records <= 1;\n```\n\nThis query works as follows:\n1. It first groups the `employee` table by the `Name` column.\n2. For each group (i.e., for each Name), it counts the number of records (using `COUNT(Employee_ID)`).\n3. It then filters the results to include only those Names that have at most 1 record (`count_records <= 1`).\n\nThe final result will be a list of Names that appear at most once in the `employee` table.","cost":0.0007965,"response_parsed":"SELECT Name\nFROM (\n SELECT Name, COUNT(Employee_ID) as count_records\n FROM employee\n GROUP BY Name\n) AS name_counts\nWHERE count_records <= 1;","time":6.8784132004}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING count(*) >= 2","question":"Find all the City that have at least 2 records in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all cities with at least 2 employee records, we'll use the `employee` table, group by `City`, and filter groups with a count of 2 or more.\n\n```sql\nSELECT City, COUNT(Employee_ID) AS EmployeeCount\nFROM employee\nGROUP BY City\nHAVING COUNT(Employee_ID) >= 2;\n```","cost":0.0006102,"response_parsed":"SELECT City, COUNT(Employee_ID) AS EmployeeCount\nFROM employee\nGROUP BY City\nHAVING COUNT(Employee_ID) >= 2;","time":4.7046487331}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING count(*) <= 2","question":"Find all the City that have at most 2 records in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all cities with at most 2 employee records, we'll use the `COUNT()` function to count employees per city, group the results by city, and filter groups with 2 or fewer employees using `HAVING`.\n\n```sql\nSELECT \"City\"\nFROM \"employee\"\nGROUP BY \"City\"\nHAVING COUNT(\"Employee_ID\") <= 2;\n```","cost":0.0005517,"response_parsed":"SELECT \"City\"\nFROM \"employee\"\nGROUP BY \"City\"\nHAVING COUNT(\"Employee_ID\") <= 2;","time":4.1162383556}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING AVG(`Age`) >= 31.9","question":"List the Name which average of Age is at least 31.9 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the names of employees where the average age is at least 31.9, you can use the following SQL query:\n\n```sql\nSELECT Name FROM \"employee\" WHERE (SELECT AVG(Age) FROM \"employee\") >= 31.9;\n```\n\nThis query calculates the average age of all employees in the `employee` table and returns the names of employees if the average age is 31.9 or higher.","cost":0.0007803,"response_parsed":"SELECT Name FROM \"employee\" WHERE (SELECT AVG(Age) FROM \"employee\") >= 31.9;","time":6.2927718163}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING AVG(`Age`) <= 31.9","question":"List the Name which average of Age is at most 31.9 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the names of employees where the average age is at most 31.9, you can use the following SQL query:\n\n```sql\nSELECT Name FROM employee WHERE Age <= (SELECT AVG(Age) FROM employee);\n```\n\nThis query first calculates the average age of all employees and then selects the names of employees whose age is less than or equal to this average age.","cost":0.0007218,"response_parsed":"SELECT Name FROM employee WHERE Age <= (SELECT AVG(Age) FROM employee);","time":6.5589594841}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING SUM(`Age`) >= 31.9","question":"List the Name which summation of Age is at least 31.9 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo list the names of employees whose age is at least 31.9, we can use the following SQL query. Since the `Age` column is of type `int`, we'll round 31.9 to the nearest integer, which is 32.\n\n```sql\nSELECT Name \nFROM employee \nWHERE Age >= 32;\n```","cost":0.0007083,"response_parsed":"SELECT Name \nFROM employee \nWHERE Age >= 32;","time":5.4364323616}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `employee` GROUP BY `Name` HAVING SUM(`Age`) <= 31.9","question":"List the Name which summation of Age is at most 31.9 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the names of employees where the sum of their ages is at most 31.9, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM employee\nGROUP BY Name\nHAVING SUM(Age) <= 31.9;\n```\n\nThis query groups the employees by their names and then filters the groups where the sum of ages is less than or equal to 31.9.","cost":0.0008595,"response_parsed":"SELECT Name\nFROM employee\nGROUP BY Name\nHAVING SUM(Age) <= 31.9;","time":7.5114443302}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING AVG(`Age`) >= 32.1","question":"List the City which average of Age is at least 32.1 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the cities where the average age of employees is at least 32.1, we can use the following SQL query:\n\n```sql\nSELECT City, AVG(Age) AS Average_Age\nFROM employee\nGROUP BY City\nHAVING AVG(Age) >= 32.1;\n```\n\nThis query:\n1. Selects the `City` and calculates the average `Age` for each city.\n2. Groups the results by `City`.\n3. Filters the results to include only those cities where the average age is at least 32.1.","cost":0.0006012,"response_parsed":"SELECT City, AVG(Age) AS Average_Age\nFROM employee\nGROUP BY City\nHAVING AVG(Age) >= 32.1;","time":4.0395214558}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING AVG(`Age`) <= 32.1","question":"List the City which average of Age is at most 32.1 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the cities where the average age of employees is at most 32.1, we can use the following SQL query:\n\n```sql\nSELECT City, AVG(Age) AS \"Average_Age\"\nFROM employee\nGROUP BY City\nHAVING AVG(Age) <= 32.1;\n```\n\nThis query:\n1. Selects the `City` and calculates the average `Age` for each city.\n2. Groups the results by `City`.\n3. Filters the results to include only those cities where the average age is at most 32.1.","cost":0.0007065,"response_parsed":"SELECT City, AVG(Age) AS \"Average_Age\"\nFROM employee\nGROUP BY City\nHAVING AVG(Age) <= 32.1;","time":5.7853462696}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING SUM(`Age`) >= 63.8","question":"List the City which summation of Age is at least 63.8 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to sum the `Age` of employees grouped by their `City` and then filter the results to include only those cities where the total age is at least 63.8.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT City, SUM(Age) AS Total_Age\nFROM employee\nGROUP BY City\nHAVING SUM(Age) >= 63.8;\n```\n\nThis query:\n1. Groups employees by their `City`\n2. Calculates the sum of `Age` for each city\n3. Filters the results to include only cities where the sum of ages is at least 63.8","cost":0.0006966,"response_parsed":"SELECT City, SUM(Age) AS Total_Age\nFROM employee\nGROUP BY City\nHAVING SUM(Age) >= 63.8;","time":5.0097301006}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `City` FROM `employee` GROUP BY `City` HAVING SUM(`Age`) <= 63.8","question":"List the City which summation of Age is at most 63.8 in table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that calculates the sum of ages for each city in the `employee` table and then lists the cities where this sum is at most 63.8.\n\n```sql\nSELECT City, SUM(Age) AS total_age\nFROM employee\nGROUP BY City\nHAVING SUM(Age) <= 63.8;\n```","cost":0.0006399,"response_parsed":"SELECT City, SUM(Age) AS total_age\nFROM employee\nGROUP BY City\nHAVING SUM(Age) <= 63.8;","time":4.4940335751}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING count(*) >= 1","question":"Find all the Employee_ID that have at least 1 records in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all `Employee_ID`s that have at least one record in the `evaluation` table, you can use the `DISTINCT` keyword to retrieve unique `Employee_ID`s from the `evaluation` table.\n\n```sql\nSELECT DISTINCT Employee_ID FROM evaluation;\n```","cost":0.0005085,"response_parsed":"SELECT DISTINCT Employee_ID FROM evaluation;","time":3.3325839043}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING count(*) <= 1","question":"Find all the Employee_ID that have at most 1 records in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all `Employee_ID`s that have at most 1 record in the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Selects the `Employee_ID` from the `evaluation` table.\n2. Groups the results by `Employee_ID`.\n3. Filters the groups to include only those with 1 or fewer records using the `HAVING COUNT(*) <= 1` condition.\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING COUNT(*) <= 1;\n```","cost":0.000684,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING COUNT(*) <= 1;","time":4.93587327}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING count(*) >= 1","question":"Find all the Year_awarded that have at least 1 records in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the `Year_awarded` values that have at least one record in the `evaluation` table, you can use the `SELECT DISTINCT` statement to fetch unique `Year_awarded` values.\n\n```sql\nSELECT DISTINCT Year_awarded FROM evaluation;\n```","cost":0.0006696,"response_parsed":"SELECT DISTINCT Year_awarded FROM evaluation;","time":5.0259029865}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING count(*) <= 1","question":"Find all the Year_awarded that have at most 1 records in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all `Year_awarded` values that have at most 1 record in the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Groups the records in the `evaluation` table by the `Year_awarded` column.\n2. Uses the `HAVING` clause to filter the groups and only include those with a count of 1 or less.\n\nThe result will be a list of `Year_awarded` values that appear at most once in the table.","cost":0.0006858,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING COUNT(*) <= 1;","time":5.4132215977}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING AVG(`Bonus`) >= 3310.0","question":"List the Employee_ID which average of Bonus is at least 3310.0 in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the Employee_IDs where the average Bonus is at least 3310.0 from the evaluation table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING AVG(Bonus) >= 3310.0;\n```\n\nThis query:\n1. Selects the `Employee_ID` from the `evaluation` table.\n2. Groups the results by `Employee_ID`.\n3. Filters the groups to include only those where the average `Bonus` is at least 3310.0.","cost":0.0007974,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING AVG(Bonus) >= 3310.0;","time":6.5125069618}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING AVG(`Bonus`) <= 3310.0","question":"List the Employee_ID which average of Bonus is at most 3310.0 in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the Employee_ID(s) where the average Bonus is at most 3310.0 from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING AVG(Bonus) <= 3310.0;\n```\n\nThis query:\n1. Selects the `Employee_ID` from the `evaluation` table.\n2. Groups the results by `Employee_ID` to calculate the average Bonus for each employee.\n3. Filters the results to include only those employees where the average Bonus is less than or equal to 3310.0.","cost":0.0007884,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING AVG(Bonus) <= 3310.0;","time":6.2887451649}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING SUM(`Bonus`) >= 3900.0","question":"List the Employee_ID which summation of Bonus is at least 3900.0 in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the Employee_ID(s) where the sum of Bonus is at least 3900.0 from the evaluation table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING SUM(Bonus) >= 3900.0;\n```\n\nThis query:\n1. Selects the `Employee_ID` from the `evaluation` table.\n2. Groups the results by `Employee_ID`.\n3. Filters the results to include only those groups where the sum of `Bonus` is at least 3900.0.","cost":0.000639,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING SUM(Bonus) >= 3900.0;","time":4.7771897316}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Employee_ID` FROM `evaluation` GROUP BY `Employee_ID` HAVING SUM(`Bonus`) <= 3900.0","question":"List the Employee_ID which summation of Bonus is at most 3900.0 in table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Employee_ID` from the `evaluation` table where the sum of the `Bonus` for each employee is at most 3900.0. Here's the SQL code to achieve this:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING SUM(Bonus) <= 3900.0;\n```\n\nThis SQL query:\n1. Selects the `Employee_ID` from the `evaluation` table.\n2. Groups the results by `Employee_ID` to aggregate the bonus for each employee.\n3. Uses the `HAVING` clause to filter the results where the sum of the `Bonus` is at most 3900.0.","cost":0.0007632,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nGROUP BY Employee_ID\nHAVING SUM(Bonus) <= 3900.0;","time":6.3219940662}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING AVG(`Bonus`) >= 3210.0","question":"List the Year_awarded which average of Bonus is at least 3210.0 in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Year_awarded` from the `evaluation` table where the average `Bonus` is at least 3210.0. Here's the SQL code to achieve this:\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING AVG(Bonus) >= 3210.0;\n```\n\nThis query:\n1. Selects the `Year_awarded` column\n2. Groups the results by `Year_awarded`\n3. Filters the results to include only those groups where the average `Bonus` is at least 3210.0","cost":0.0006507,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING AVG(Bonus) >= 3210.0;","time":4.6085515022}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING AVG(`Bonus`) <= 3210.0","question":"List the Year_awarded which average of Bonus is at most 3210.0 in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Year_awarded` from the `evaluation` table where the average `Bonus` for that year is at most 3210.0.\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING AVG(Bonus) <= 3210.0;\n```","cost":0.0005589,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING AVG(Bonus) <= 3210.0;","time":4.021582365}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING SUM(`Bonus`) >= 3900.0","question":"List the Year_awarded which summation of Bonus is at least 3900.0 in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Year_awarded` from the `evaluation` table where the sum of `Bonus` for that year is at least 3900.0. Here's the SQL code to achieve this:\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING SUM(Bonus) >= 3900.0;\n```","cost":0.0006714,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nGROUP BY Year_awarded\nHAVING SUM(Bonus) >= 3900.0;","time":4.9845039845}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Year_awarded` FROM `evaluation` GROUP BY `Year_awarded` HAVING SUM(`Bonus`) <= 3900.0","question":"List the Year_awarded which summation of Bonus is at most 3900.0 in table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Year_awarded` from the `evaluation` table where the sum of `Bonus` for that year is at most 3900.0.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Year_awarded, SUM(Bonus) AS Total_Bonus\nFROM evaluation\nGROUP BY Year_awarded\nHAVING SUM(Bonus) <= 3900.0\nORDER BY Year_awarded;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `Year_awarded` and the sum of `Bonus` (aliased as `Total_Bonus`).\n2. **FROM Clause**: We specify the `evaluation` table.\n3. **GROUP BY Clause**: We group the results by `Year_awarded` to aggregate the bonuses for each year.\n4. **HAVING Clause**: We filter the results to include only those years where the sum of `Bonus` is at most 3900.0.\n5. **ORDER BY Clause**: We sort the results by `Year_awarded` for better readability.\n\nThis query will return the years and the corresponding total bonuses for those years where the total bonus is at most 3900.0.","cost":0.0008586,"response_parsed":"SELECT Year_awarded, SUM(Bonus) AS Total_Bonus\nFROM evaluation\nGROUP BY Year_awarded\nHAVING SUM(Bonus) <= 3900.0\nORDER BY Year_awarded;","time":7.2210514545}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Start_from` FROM `hiring` GROUP BY `Start_from` HAVING count(*) >= 1","question":"Find all the Start_from that have at least 1 records in table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the `Start_from` dates that have at least one record in the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Start_from FROM hiring;\n```\n\nThis query will return all unique `Start_from` dates that exist in the `hiring` table.","cost":0.0005553,"response_parsed":"SELECT DISTINCT Start_from FROM hiring;","time":4.1740972996}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Start_from` FROM `hiring` GROUP BY `Start_from` HAVING count(*) <= 1","question":"Find all the Start_from that have at most 1 records in table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the `Start_from` dates that have at most 1 record in the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Start_from\nFROM hiring\nGROUP BY Start_from\nHAVING COUNT(Start_from) <= 1;\n```\n\nThis query:\n1. Groups the records in the `hiring` table by the `Start_from` date.\n2. Counts the number of records for each `Start_from` date.\n3. Filters the results to include only those `Start_from` dates that have at most 1 record.","cost":0.000684,"response_parsed":"SELECT Start_from\nFROM hiring\nGROUP BY Start_from\nHAVING COUNT(Start_from) <= 1;","time":5.6290638447}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Location` FROM `shop` GROUP BY `Location` HAVING count(*) >= 1","question":"Find all the Location that have at least 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the unique locations that have at least one record in the `shop` table, you can use the `DISTINCT` keyword to retrieve each location only once. Here's the SQL query:\n\n```sql\nSELECT DISTINCT Location FROM shop;\n```\n\nThis query will return a list of all unique locations where there is at least one shop.","cost":0.0005112,"response_parsed":"SELECT DISTINCT Location FROM shop;","time":3.4957962036}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Location` FROM `shop` GROUP BY `Location` HAVING count(*) <= 1","question":"Find all the Location that have at most 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the Locations that have at most 1 record in the `shop` table, we can use the `COUNT` function combined with `GROUP BY` and `HAVING` clauses. Here's how to do it:\n\n```sql\nSELECT Location \nFROM shop \nGROUP BY Location \nHAVING COUNT(Location) <= 1;\n```\n\nThis query will:\n1. Group the rows in the `shop` table by the `Location` column.\n2. Count the number of records for each `Location`.\n3. Return only those `Location`s that have 1 or fewer records.","cost":0.0006768,"response_parsed":"SELECT Location \nFROM shop \nGROUP BY Location \nHAVING COUNT(Location) <= 1;","time":5.2210371494}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING count(*) >= 1","question":"Find all the Manager_name that have at least 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all the `Manager_name`s that have at least one record in the `shop` table, we can directly query the `shop` table since it contains the `Manager_name` field. We use `SELECT DISTINCT` to ensure each manager's name appears only once.\n\n```sql\nSELECT DISTINCT Manager_name FROM shop;\n```","cost":0.0005949,"response_parsed":"SELECT DISTINCT Manager_name FROM shop;","time":4.5886056423}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING count(*) <= 1","question":"Find all the Manager_name that have at most 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all `Manager_name`s that have at most 1 record in the `shop` table, we can use the `COUNT` function combined with `GROUP BY` and `HAVING` to filter the results.\n\n```sql\nSELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING COUNT(Manager_name) <= 1;\n```","cost":0.0014013,"response_parsed":"SELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING COUNT(Manager_name) <= 1;","time":14.1164586544}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `District` FROM `shop` GROUP BY `District` HAVING count(*) >= 1","question":"Find all the District that have at least 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all districts with at least one record in the `shop` table, we can use the `DISTINCT` keyword to retrieve unique district names.\n\n```sql\nSELECT DISTINCT District FROM shop;\n```","cost":0.0004527,"response_parsed":"SELECT DISTINCT District FROM shop;","time":2.9346725941}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `District` FROM `shop` GROUP BY `District` HAVING count(*) <= 1","question":"Find all the District that have at most 1 records in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find all districts with at most 1 record in the `shop` table, we can use the `COUNT()` function combined with `GROUP BY` and `HAVING` clauses.\n\n```sql\nSELECT District, COUNT(Shop_ID) AS Shop_Count\nFROM shop\nGROUP BY District\nHAVING COUNT(Shop_ID) <= 1;\n```\n\nThis query will:\n1. Group the rows in the `shop` table by the `District` column\n2. Count the number of records (shops) in each district\n3. Return only those districts where the count of shops is 1 or less\n\nThe result will include the district name and the number of shops in that district.","cost":0.0005382,"response_parsed":"SELECT District, COUNT(Shop_ID) AS Shop_Count\nFROM shop\nGROUP BY District\nHAVING COUNT(Shop_ID) <= 1;","time":3.8186216354}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `shop` GROUP BY `Name` HAVING AVG(`Number_products`) >= 6685.11","question":"List the Name which average of Number_products is at least 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the names of shops where the average number of products is at least 6685.11. This can be achieved using the SQL `AVG()` function along with the `HAVING` clause to filter the results based on the average value.\n\n```sql\nSELECT Name FROM shop GROUP BY Name HAVING AVG(Number_products) >= 6685.11\n```","cost":0.0009648,"response_parsed":"SELECT Name FROM shop GROUP BY Name HAVING AVG(Number_products) >= 6685.11","time":8.4534740448}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `shop` GROUP BY `Name` HAVING AVG(`Number_products`) <= 6685.11","question":"List the Name which average of Number_products is at most 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the names from the `shop` table where the average of `Number_products` is at most 6685.11, you can use the following SQL query:\n\n```sql\nSELECT Name FROM shop WHERE (SELECT AVG(Number_products) FROM shop) <= 6685.11;\n```\n\nThis query first calculates the average of the `Number_products` column in the `shop` table. If this average is less than or equal to 6685.11, it returns the `Name` of all shops.","cost":0.0008865,"response_parsed":"SELECT Name FROM shop WHERE (SELECT AVG(Number_products) FROM shop) <= 6685.11;","time":7.3404626846}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `shop` GROUP BY `Name` HAVING SUM(`Number_products`) >= 6685.11","question":"List the Name which summation of Number_products is at least 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Number_products` for each `Name` in the `shop` table and then filter the results to include only those names where the sum is at least 6685.11.\n\nHere is the SQL code:\n\n```sql\nSELECT Name\nFROM shop\nGROUP BY Name\nHAVING SUM(Number_products) >= 6685.11;\n```\n\nThis query:\n1. Selects the `Name` column from the `shop` table.\n2. Groups the rows by the `Name` column.\n3. Uses the `HAVING` clause to filter the results to include only those groups where the sum of `Number_products` is at least 6685.11.","cost":0.0007002,"response_parsed":"SELECT Name\nFROM shop\nGROUP BY Name\nHAVING SUM(Number_products) >= 6685.11;","time":5.2516460419}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `shop` GROUP BY `Name` HAVING SUM(`Number_products`) <= 6685.11","question":"List the Name which summation of Number_products is at most 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the names from the `shop` table where the summation of `Number_products` is at most 6685.11, you can use the following SQL query:\n\n```sql\nSELECT Name FROM shop GROUP BY Name HAVING SUM(Number_products) <= 6685.11;\n```\n\nThis query will:\n1. Group the rows in the `shop` table by the `Name` column.\n2. Calculate the sum of `Number_products` for each group.\n3. Filter the results to include only those groups where the sum of `Number_products` is less than or equal to 6685.11.","cost":0.0007731,"response_parsed":"SELECT Name FROM shop GROUP BY Name HAVING SUM(Number_products) <= 6685.11;","time":6.7009937763}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING AVG(`Number_products`) >= 6685.11","question":"List the Manager_name which average of Number_products is at least 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the list of `Manager_name` from the `shop` table where the average of `Number_products` is at least 6685.11, you can use the following SQL query:\n\n```sql\nSELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING AVG(Number_products) >= 6685.11;\n```\n\nThis query:\n1. Groups the rows in the `shop` table by `Manager_name`.\n2. Calculates the average of `Number_products` for each group.\n3. Filters the results to include only those groups where the average `Number_products` is at least 6685.11.","cost":0.0005589,"response_parsed":"SELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING AVG(Number_products) >= 6685.11;","time":4.3054728508}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING AVG(`Number_products`) <= 6685.11","question":"List the Manager_name which average of Number_products is at most 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Manager_name` from the `shop` table where the average of `Number_products` is at most 6685.11. Here's the SQL code to achieve this:\n\n```sql\nSELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING AVG(Number_products) <= 6685.11;\n```\n\n### Explanation:\n1. **SELECT Manager_name**: This selects the `Manager_name` column from the `shop` table.\n2. **FROM shop**: This specifies the table from which to retrieve the data.\n3. **GROUP BY Manager_name**: This groups the rows by the `Manager_name` column, allowing us to perform aggregate operations on each group.\n4. **HAVING AVG(Number_products) <= 6685.11**: This filters the groups to include only those where the average of `Number_products` is at most 6685.11.\n\nThis query will return the names of managers whose average number of products is 6685.11 or less.","cost":0.0007317,"response_parsed":"SELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING AVG(Number_products) <= 6685.11;","time":5.9870090485}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING SUM(`Number_products`) >= 6685.11","question":"List the Manager_name which summation of Number_products is at least 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Manager_name` from the `shop` table where the summation of `Number_products` is at least 6685.11, you can use the following SQL query:\n\n```sql\nSELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING SUM(Number_products) >= 6685.11;\n```\n\nThis query:\n1. Groups the rows in the `shop` table by `Manager_name`.\n2. Calculates the sum of `Number_products` for each group.\n3. Filters the results to include only those groups where the sum of `Number_products` is at least 6685.11.","cost":0.0005931,"response_parsed":"SELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING SUM(Number_products) >= 6685.11;","time":4.157926321}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Manager_name` FROM `shop` GROUP BY `Manager_name` HAVING SUM(`Number_products`) <= 6685.11","question":"List the Manager_name which summation of Number_products is at most 6685.11 in table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the list of `Manager_name` from the `shop` table where the summation of `Number_products` is at most 6685.11, you can use the following SQL query:\n\n```sql\nSELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING SUM(Number_products) <= 6685.11;\n```\n\nThis query:\n1. Selects the `Manager_name` from the `shop` table.\n2. Groups the results by `Manager_name`.\n3. Filters the groups to include only those where the sum of `Number_products` is less than or equal to 6685.11.","cost":0.000594,"response_parsed":"SELECT Manager_name\nFROM shop\nGROUP BY Manager_name\nHAVING SUM(Number_products) <= 6685.11;","time":4.3558118343}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `evaluation` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID` = T2.`Employee_ID`","question":"Join all the records from table evaluation with table employee on Employee_ID","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo join all records from the `evaluation` table with the `employee` table based on the `Employee_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nINNER JOIN employee\nON evaluation.Employee_ID = employee.Employee_ID;\n```\n\nThis query will return all records where there is a matching `Employee_ID` in both tables. If you want to include all records from both tables (including those without matches), you can use a `FULL OUTER JOIN` instead:\n\n```sql\nSELECT *\nFROM evaluation\nFULL OUTER JOIN employee\nON evaluation.Employee_ID = employee.Employee_ID;\n```","cost":0.0007326,"response_parsed":"SELECT *\nFROM evaluation\nFULL OUTER JOIN employee\nON evaluation.Employee_ID = employee.Employee_ID;","time":6.2388510704}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Year_awarded`, T2.`Name` FROM `evaluation` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID`=T2.`Employee_ID`","question":"List all the Year_awarded and Name from the table evaluation and the table employee where Employee_ID is the same","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Year_awarded` from the `evaluation` table and the `Name` from the `employee` table where the `Employee_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT e.Year_awarded, emp.Name\nFROM evaluation e\nINNER JOIN employee emp\nON e.Employee_ID = emp.Employee_ID;\n```\n\nThis query:\n1. Selects the `Year_awarded` column from the `evaluation` table.\n2. Selects the `Name` column from the `employee` table.\n3. Joins the two tables on the `Employee_ID` column, which is common to both tables.\n4. Returns only the rows where the `Employee_ID` exists in both tables.","cost":0.0006273,"response_parsed":"SELECT e.Year_awarded, emp.Name\nFROM evaluation e\nINNER JOIN employee emp\nON e.Employee_ID = emp.Employee_ID;","time":4.7333695889}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Year_awarded`, T2.`City` FROM `evaluation` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID`=T2.`Employee_ID`","question":"List all the Year_awarded and City from the table evaluation and the table employee where Employee_ID is the same","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Year_awarded` from the `evaluation` table and `City` from the `employee` table where the `Employee_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT e.Year_awarded, emp.City\nFROM evaluation e\nINNER JOIN employee emp\nON e.Employee_ID = emp.Employee_ID;\n```\n\nThis query will return the `Year_awarded` and `City` for employees who have matching `Employee_ID` in both the `evaluation` and `employee` tables.","cost":0.0007407,"response_parsed":"SELECT e.Year_awarded, emp.City\nFROM evaluation e\nINNER JOIN employee emp\nON e.Employee_ID = emp.Employee_ID;","time":5.8685119152}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `hiring` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID` = T2.`Employee_ID`","question":"Join all the records from table hiring with table employee on Employee_ID","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo join all records from the `hiring` table with the `employee` table based on the `Employee_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nFULL OUTER JOIN hiring\nON employee.Employee_ID = hiring.Employee_ID;\n```\n\nThis query will return all records from both tables where there is a match in the `Employee_ID`. If there is no match, the result will contain `NULL` values for the columns where no data exists.","cost":0.0006192,"response_parsed":"SELECT *\nFROM employee\nFULL OUTER JOIN hiring\nON employee.Employee_ID = hiring.Employee_ID;","time":4.9464652538}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `hiring` AS T1 JOIN `shop` AS T2 ON T1.`Shop_ID` = T2.`Shop_ID`","question":"Join all the records from table hiring with table shop on Shop_ID","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo join all records from the `hiring` table with the `shop` table based on the `Shop_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM hiring\nINNER JOIN shop\nON hiring.Shop_ID = shop.Shop_ID;\n```\n\nThis query will return all records from both tables where the `Shop_ID` matches in both tables.","cost":0.0006615,"response_parsed":"SELECT *\nFROM hiring\nINNER JOIN shop\nON hiring.Shop_ID = shop.Shop_ID;","time":5.5121433735}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Start_from`, T2.`Name` FROM `hiring` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID`=T2.`Employee_ID`","question":"List all the Start_from and Name from the table hiring and the table employee where Employee_ID is the same","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` and `Name` from the `hiring` and `employee` tables where the `Employee_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT h.Start_from, e.Name\nFROM hiring h\nINNER JOIN employee e\nON h.Employee_ID = e.Employee_ID\nORDER BY h.Start_from;\n```\n\nThis query:\n1. Selects the `Start_from` column from the `hiring` table and the `Name` column from the `employee` table.\n2. Joins the `hiring` table (`h`) with the `employee` table (`e`) using an `INNER JOIN` on the `Employee_ID` column, which is common to both tables.\n3. Orders the results by the `Start_from` date for better readability.","cost":0.0006165,"response_parsed":"SELECT h.Start_from, e.Name\nFROM hiring h\nINNER JOIN employee e\nON h.Employee_ID = e.Employee_ID\nORDER BY h.Start_from;","time":4.4284925461}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Start_from`, T2.`City` FROM `hiring` AS T1 JOIN `employee` AS T2 ON T1.`Employee_ID`=T2.`Employee_ID`","question":"List all the Start_from and City from the table hiring and the table employee where Employee_ID is the same","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` and `City` from the `hiring` and `employee` tables where the `Employee_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT h.Start_from, e.City\nFROM hiring h\nINNER JOIN employee e\nON h.Employee_ID = e.Employee_ID;\n```\n\nThis query will:\n1. Select the `Start_from` column from the `hiring` table and the `City` column from the `employee` table.\n2. Join the `hiring` table (`h`) with the `employee` table (`e`) based on the matching `Employee_ID`.\n3. Return the results where the `Employee_ID` exists in both tables.","cost":0.0006066,"response_parsed":"SELECT h.Start_from, e.City\nFROM hiring h\nINNER JOIN employee e\nON h.Employee_ID = e.Employee_ID;","time":4.3283491135}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Start_from`, T2.`District` FROM `hiring` AS T1 JOIN `shop` AS T2 ON T1.`Shop_ID`=T2.`Shop_ID`","question":"List all the Start_from and District from the table hiring and the table shop where Shop_ID is the same","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` from the `hiring` table and `District` from the `shop` table where the `Shop_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT h.Start_from, s.District\nFROM hiring h\nINNER JOIN shop s\nON h.Shop_ID = s.Shop_ID;\n```\n\nThis query will:\n1. Select the `Start_from` column from the `hiring` table.\n2. Select the `District` column from the `shop` table.\n3. Join the two tables based on the `Shop_ID` column, which is common to both tables.\n4. Return all rows where the `Shop_ID` exists in both tables.","cost":0.0006471,"response_parsed":"SELECT h.Start_from, s.District\nFROM hiring h\nINNER JOIN shop s\nON h.Shop_ID = s.Shop_ID;","time":5.074665308}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Start_from`, T2.`Location` FROM `hiring` AS T1 JOIN `shop` AS T2 ON T1.`Shop_ID`=T2.`Shop_ID`","question":"List all the Start_from and Location from the table hiring and the table shop where Shop_ID is the same","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` from the `hiring` table and `Location` from the `shop` table where the `Shop_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT h.Start_from, s.Location\nFROM hiring h\nINNER JOIN shop s\nON h.Shop_ID = s.Shop_ID;\n```\n\nThis query will:\n1. Select the `Start_from` column from the `hiring` table.\n2. Select the `Location` column from the `shop` table.\n3. Join the two tables based on the matching `Shop_ID` values.","cost":0.0005814,"response_parsed":"SELECT h.Start_from, s.Location\nFROM hiring h\nINNER JOIN shop s\nON h.Shop_ID = s.Shop_ID;","time":4.3195850849}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Start_from`, T2.`Name` FROM `hiring` AS T1 JOIN `shop` AS T2 ON T1.`Shop_ID`=T2.`Shop_ID`","question":"List all the Start_from and Name from the table hiring and the table shop where Shop_ID is the same","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` from the `hiring` table and `Name` from the `shop` table where the `Shop_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT h.Start_from, s.Name\nFROM hiring AS h\nINNER JOIN shop AS s\nON h.Shop_ID = s.Shop_ID;\n```\n\nThis query will:\n1. Select the `Start_from` column from the `hiring` table and the `Name` column from the `shop` table.\n2. Use an `INNER JOIN` to combine rows from the `hiring` and `shop` tables where the `Shop_ID` is the same in both tables.","cost":0.0006453,"response_parsed":"SELECT h.Start_from, s.Name\nFROM hiring AS h\nINNER JOIN shop AS s\nON h.Shop_ID = s.Shop_ID;","time":4.8932347298}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `employee` ORDER BY `City` ASC","question":"Show all data ordered by City in ascending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `employee` table ordered by the `City` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nORDER BY City ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `employee` table.\n2. Order the results by the `City` column in ascending alphabetical order.","cost":0.0005283,"response_parsed":"SELECT *\nFROM employee\nORDER BY City ASC;","time":3.8759024143}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `employee` ORDER BY `City` DESC","question":"Show all data ordered by City in descending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `employee` table ordered by `City` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nORDER BY City DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `employee` table\n2. Order the results by the `City` column in descending order (from Z to A)","cost":0.0005103,"response_parsed":"SELECT *\nFROM employee\nORDER BY City DESC;","time":3.8405008316}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `employee` ORDER BY `Name` ASC","question":"Show all data ordered by Name in ascending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `employee` table ordered by the `Name` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nORDER BY Name ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `employee` table\n2. Order the results by the `Name` column in ascending order (from A to Z)","cost":0.0006498,"response_parsed":"SELECT *\nFROM employee\nORDER BY Name ASC;","time":5.4061286449}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `employee` ORDER BY `Name` DESC","question":"Show all data ordered by Name in descending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `employee` table ordered by the `Name` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nORDER BY Name DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `employee` table\n2. Order the results by the `Name` column in descending alphabetical order","cost":0.0004869,"response_parsed":"SELECT *\nFROM employee\nORDER BY Name DESC;","time":3.2424869537}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Age` FROM `employee` ORDER BY `Age` ASC","question":"Project the Age ordered in ascending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Age` column from the `employee` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Age\nFROM employee\nORDER BY Age ASC;\n```\n\nThis query will:\n1. Select the `Age` column from the `employee` table\n2. Order the results in ascending order based on the `Age` values","cost":0.0004464,"response_parsed":"SELECT Age\nFROM employee\nORDER BY Age ASC;","time":3.0350680351}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Age` FROM `employee` ORDER BY `Age` DESC","question":"Project the Age ordered in descending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Age` column from the `employee` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Age\nFROM employee\nORDER BY Age DESC;\n```\n\nThis query will:\n1. Select the `Age` column from the `employee` table\n2. Order the results in descending order based on the `Age` values","cost":0.0004788,"response_parsed":"SELECT Age\nFROM employee\nORDER BY Age DESC;","time":3.62373209}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `employee` ORDER BY `Employee_ID` ASC","question":"Project the Employee_ID ordered in ascending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `employee` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID \nFROM employee \nORDER BY Employee_ID ASC;\n```\n\nThis query will:\n1. Select the `Employee_ID` column from the `employee` table.\n2. Order the results in ascending order based on `Employee_ID`.","cost":0.0004977,"response_parsed":"SELECT Employee_ID \nFROM employee \nORDER BY Employee_ID ASC;","time":3.5595724583}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `employee` ORDER BY `Employee_ID` DESC","question":"Project the Employee_ID ordered in descending order for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `employee` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID \nFROM employee \nORDER BY Employee_ID DESC;\n```\n\nThis query will:\n1. Select the `Employee_ID` column from the `employee` table.\n2. Order the results in descending order based on the `Employee_ID`.","cost":0.0005184,"response_parsed":"SELECT Employee_ID \nFROM employee \nORDER BY Employee_ID DESC;","time":3.7211413383}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `evaluation` ORDER BY `Year_awarded` ASC","question":"Show all data ordered by Year_awarded in ascending order for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `evaluation` table ordered by `Year_awarded` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM evaluation ORDER BY Year_awarded ASC;\n```","cost":0.0005274,"response_parsed":"SELECT * FROM evaluation ORDER BY Year_awarded ASC;","time":3.673085928}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `evaluation` ORDER BY `Year_awarded` DESC","question":"Show all data ordered by Year_awarded in descending order for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `evaluation` table ordered by `Year_awarded` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM evaluation ORDER BY Year_awarded DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `evaluation` table.\n2. Order the results by the `Year_awarded` column in descending order (from the most recent to the oldest year).","cost":0.000612,"response_parsed":"SELECT * FROM evaluation ORDER BY Year_awarded DESC;","time":4.471524477}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `evaluation` ORDER BY `Employee_ID` ASC","question":"Show all data ordered by Employee_ID in ascending order for the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `evaluation` table ordered by `Employee_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nORDER BY Employee_ID ASC;\n```","cost":0.0005229,"response_parsed":"SELECT *\nFROM evaluation\nORDER BY Employee_ID ASC;","time":3.5978052616}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `evaluation` ORDER BY `Employee_ID` DESC","question":"Show all data ordered by Employee_ID in descending order for the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `evaluation` table ordered by `Employee_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nORDER BY Employee_ID DESC;\n```","cost":0.0004563,"response_parsed":"SELECT *\nFROM evaluation\nORDER BY Employee_ID DESC;","time":2.9884734154}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Year_awarded` FROM `evaluation` ORDER BY `Year_awarded` ASC","question":"Project the Year_awarded ordered in ascending order for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the Year_awarded from the evaluation table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nORDER BY Year_awarded ASC;\n```","cost":0.000558,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nORDER BY Year_awarded ASC;","time":4.136244297}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Year_awarded` FROM `evaluation` ORDER BY `Year_awarded` DESC","question":"Project the Year_awarded ordered in descending order for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Year_awarded` from the `evaluation` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded\nFROM evaluation\nORDER BY Year_awarded DESC;\n```\n\nThis query will:\n1. Select the `Year_awarded` column from the `evaluation` table.\n2. Order the results in descending order based on the `Year_awarded` values.","cost":0.0006867,"response_parsed":"SELECT Year_awarded\nFROM evaluation\nORDER BY Year_awarded DESC;","time":5.8716247082}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `evaluation` ORDER BY `Employee_ID` ASC","question":"Project the Employee_ID ordered in ascending order for the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `evaluation` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nORDER BY Employee_ID ASC;\n```","cost":0.0004392,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nORDER BY Employee_ID ASC;","time":3.0014989376}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `evaluation` ORDER BY `Employee_ID` DESC","question":"Project the Employee_ID ordered in descending order for the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `evaluation` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM evaluation\nORDER BY Employee_ID DESC;\n```\n\nThis query will:\n1. Select the `Employee_ID` column from the `evaluation` table.\n2. Order the results in descending order based on the `Employee_ID`.","cost":0.0006525,"response_parsed":"SELECT Employee_ID\nFROM evaluation\nORDER BY Employee_ID DESC;","time":5.3792452812}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `hiring` ORDER BY `Employee_ID` ASC","question":"Show all data ordered by Employee_ID in ascending order for the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `hiring` table ordered by `Employee_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM hiring ORDER BY Employee_ID ASC;\n```","cost":0.0005724,"response_parsed":"SELECT * FROM hiring ORDER BY Employee_ID ASC;","time":4.6649918556}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `hiring` ORDER BY `Employee_ID` DESC","question":"Show all data ordered by Employee_ID in descending order for the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `hiring` table ordered by `Employee_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM hiring\nORDER BY Employee_ID DESC;\n```","cost":0.000558,"response_parsed":"SELECT *\nFROM hiring\nORDER BY Employee_ID DESC;","time":4.4316272736}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `hiring` ORDER BY `Start_from` ASC","question":"Show all data ordered by Start_from in ascending order for the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `hiring` table ordered by the `Start_from` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM hiring ORDER BY Start_from ASC;\n```","cost":0.0005094,"response_parsed":"SELECT * FROM hiring ORDER BY Start_from ASC;","time":3.6922662258}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `hiring` ORDER BY `Start_from` DESC","question":"Show all data ordered by Start_from in descending order for the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `hiring` table ordered by the `Start_from` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM hiring ORDER BY Start_from DESC;\n```","cost":0.0005553,"response_parsed":"SELECT * FROM hiring ORDER BY Start_from DESC;","time":4.1696629524}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Start_from` FROM `hiring` ORDER BY `Start_from` ASC","question":"Project the Start_from ordered in ascending order for the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Start_from` column from the `hiring` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Start_from\nFROM hiring\nORDER BY Start_from ASC;\n```","cost":0.0004275,"response_parsed":"SELECT Start_from\nFROM hiring\nORDER BY Start_from ASC;","time":2.6008939743}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Start_from` FROM `hiring` ORDER BY `Start_from` DESC","question":"Project the Start_from ordered in descending order for the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Start_from` column from the `hiring` table and order it in descending order, you can use the following SQL query:\n\n```sql\nSELECT Start_from\nFROM hiring\nORDER BY Start_from DESC;\n```\n\nThis query will:\n1. Select the `Start_from` column from the `hiring` table.\n2. Order the results in descending order based on the `Start_from` values.","cost":0.0005103,"response_parsed":"SELECT Start_from\nFROM hiring\nORDER BY Start_from DESC;","time":3.5356488228}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `hiring` ORDER BY `Employee_ID` ASC","question":"Project the Employee_ID ordered in ascending order for the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `hiring` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID\nFROM hiring\nORDER BY Employee_ID ASC;\n```\n\nThis query will:\n1. Select the `Employee_ID` column from the `hiring` table.\n2. Order the results in ascending order based on the `Employee_ID`.","cost":0.0005121,"response_parsed":"SELECT Employee_ID\nFROM hiring\nORDER BY Employee_ID ASC;","time":3.6839530468}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Employee_ID` FROM `hiring` ORDER BY `Employee_ID` DESC","question":"Project the Employee_ID ordered in descending order for the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Employee_ID` from the `hiring` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID \nFROM hiring \nORDER BY Employee_ID DESC;\n```\n\nThis query will:\n1. Select the `Employee_ID` column from the `hiring` table.\n2. Order the results in descending order based on the `Employee_ID`.","cost":0.0005337,"response_parsed":"SELECT Employee_ID \nFROM hiring \nORDER BY Employee_ID DESC;","time":4.1099555492}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `shop` ORDER BY `District` ASC","question":"Show all data ordered by District in ascending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `shop` table ordered by the `District` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nORDER BY District ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `shop` table.\n2. Order the results by the `District` column in ascending order (A to Z).","cost":0.0005607,"response_parsed":"SELECT *\nFROM shop\nORDER BY District ASC;","time":4.2525024414}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `shop` ORDER BY `District` DESC","question":"Show all data ordered by District in descending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `shop` table ordered by the `District` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nORDER BY District DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `shop` table\n2. Order the results by the `District` column in descending order (from Z to A)","cost":0.0005301,"response_parsed":"SELECT *\nFROM shop\nORDER BY District DESC;","time":3.8009262085}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `shop` ORDER BY `Number_products` ASC","question":"Show all data ordered by Number_products in ascending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `shop` table ordered by `Number_products` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM shop ORDER BY Number_products ASC;\n```","cost":0.000477,"response_parsed":"SELECT * FROM shop ORDER BY Number_products ASC;","time":3.1105833054}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `shop` ORDER BY `Number_products` DESC","question":"Show all data ordered by Number_products in descending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all data from the `shop` table ordered by `Number_products` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM shop ORDER BY Number_products DESC;\n```","cost":0.0004437,"response_parsed":"SELECT * FROM shop ORDER BY Number_products DESC;","time":2.9164507389}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Location` FROM `shop` ORDER BY `Location` ASC","question":"Project the Location ordered in ascending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Location` from the `shop` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Location\nFROM shop\nORDER BY Location ASC;\n```\n\nThis query will:\n1. Select the `Location` column from the `shop` table\n2. Order the results in ascending alphabetical order based on the `Location` values","cost":0.0004941,"response_parsed":"SELECT Location\nFROM shop\nORDER BY Location ASC;","time":4.4517695904}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Location` FROM `shop` ORDER BY `Location` DESC","question":"Project the Location ordered in descending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Location` from the `shop` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Location\nFROM shop\nORDER BY Location DESC;\n```\n\nThis query will:\n1. Select the `Location` column from the `shop` table\n2. Order the results in descending alphabetical order based on the `Location` values","cost":0.000486,"response_parsed":"SELECT Location\nFROM shop\nORDER BY Location DESC;","time":12.1901376247}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Shop_ID` FROM `shop` ORDER BY `Shop_ID` ASC","question":"Project the Shop_ID ordered in ascending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Shop_ID` from the `shop` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Shop_ID\nFROM shop\nORDER BY Shop_ID ASC;\n```\n\nThis query will:\n1. Select the `Shop_ID` column from the `shop` table.\n2. Order the results in ascending order based on `Shop_ID`.","cost":0.0004797,"response_parsed":"SELECT Shop_ID\nFROM shop\nORDER BY Shop_ID ASC;","time":4.5763206482}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Shop_ID` FROM `shop` ORDER BY `Shop_ID` DESC","question":"Project the Shop_ID ordered in descending order for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo project the `Shop_ID` from the `shop` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Shop_ID FROM shop ORDER BY Shop_ID DESC;\n```","cost":0.0006111,"response_parsed":"SELECT Shop_ID FROM shop ORDER BY Shop_ID DESC;","time":5.6420669556}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Employee_ID` FROM `employee`","question":"Show all Employee_ID in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Employee_ID` from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID FROM employee;\n```","cost":0.0004761,"response_parsed":"SELECT Employee_ID FROM employee;","time":3.6838972569}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `employee`","question":"Show all Name in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all names from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM employee;\n```\n\nThis query will return all the names stored in the `Name` column of your `employee` table.","cost":0.000513,"response_parsed":"SELECT Name FROM employee;","time":4.3654708862}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Age` FROM `employee`","question":"Show all Age in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all the ages from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Age FROM employee;\n```\n\nThis query will return all the values in the `Age` column of your `employee` table.","cost":0.0004608,"response_parsed":"SELECT Age FROM employee;","time":3.3773438931}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `City` FROM `employee`","question":"Show all City in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all cities from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT City FROM employee;\n```","cost":0.0004914,"response_parsed":"SELECT City FROM employee;","time":3.8009884357}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `employee`","question":"Show all the rows in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show all the rows in the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM employee;\n```\n\nThis query will return all columns (`*`) for every row in the `employee` table.","cost":0.0005418,"response_parsed":"SELECT * FROM employee;","time":4.1281051636}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `City` FROM `employee`","question":"Show all City in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all cities from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT City FROM employee;\n```","cost":0.0004743,"response_parsed":"SELECT City FROM employee;","time":4.0063021183}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Name`, `Employee_ID` FROM `employee`","question":"Show all Name, Employee_ID in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Name` and `Employee_ID` from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Name, Employee_ID FROM employee;\n```","cost":0.0004374,"response_parsed":"SELECT Name, Employee_ID FROM employee;","time":3.2938287258}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Name`, `Age`, `Employee_ID` FROM `employee`","question":"Show all Name, Age, Employee_ID in the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Name`, `Age`, and `Employee_ID` from the `employee` table, you can use the following SQL query:\n\n```sql\nSELECT Name, Age, Employee_ID FROM employee;\n```\n\nThis query will return all rows in the `employee` table with the specified columns.","cost":0.0005049,"response_parsed":"SELECT Name, Age, Employee_ID FROM employee;","time":4.0134441853}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Employee_ID` FROM `evaluation`","question":"Show all Employee_ID in the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Employee_ID`s from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID FROM evaluation;\n```\n\nThis query will return all the `Employee_ID`s present in your `evaluation` table.","cost":0.0005445,"response_parsed":"SELECT Employee_ID FROM evaluation;","time":4.0926136971}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Year_awarded` FROM `evaluation`","question":"Show all Year_awarded in the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Year_awarded` from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded FROM evaluation;\n```","cost":0.000567,"response_parsed":"SELECT Year_awarded FROM evaluation;","time":4.4278657436}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Bonus` FROM `evaluation`","question":"Show all Bonus in the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all the Bonus values from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Bonus FROM evaluation;\n```\n\nThis query will return all the Bonus values stored in the `evaluation` table.","cost":0.0005382,"response_parsed":"SELECT Bonus FROM evaluation;","time":3.8024697304}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `evaluation`","question":"Show all the rows in the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show all the rows in the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM evaluation;\n```\n\nThis query will return all columns (`Employee_ID`, `Year_awarded`, and `Bonus`) for all rows in the `evaluation` table.","cost":0.0004887,"response_parsed":"SELECT * FROM evaluation;","time":3.2667684555}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Year_awarded` FROM `evaluation`","question":"Show all Year_awarded in the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Year_awarded` values from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Year_awarded FROM evaluation;\n```","cost":0.0005292,"response_parsed":"SELECT Year_awarded FROM evaluation;","time":3.9561491013}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Bonus`, `Employee_ID` FROM `evaluation`","question":"Show all Bonus, Employee_ID in the table evaluation","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Bonus` and `Employee_ID` from the `evaluation` table, you can use the following SQL query:\n\n```sql\nSELECT Bonus, Employee_ID\nFROM evaluation;\n```\n\nThis query will return all rows from the `evaluation` table, displaying the `Bonus` and `Employee_ID` columns.","cost":0.0006093,"response_parsed":"SELECT Bonus, Employee_ID\nFROM evaluation;","time":4.5193195343}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Shop_ID` FROM `hiring`","question":"Show all Shop_ID in the table hiring","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Shop_ID`s from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Shop_ID FROM hiring;\n```\n\nThis query will return all the `Shop_ID` values present in the `hiring` table.","cost":0.000567,"response_parsed":"SELECT Shop_ID FROM hiring;","time":4.2521002293}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Employee_ID` FROM `hiring`","question":"Show all Employee_ID in the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Employee_ID`s from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID FROM hiring;\n```\n\nThis query will return all the `Employee_ID`s present in the `hiring` table.","cost":0.0005931,"response_parsed":"SELECT Employee_ID FROM hiring;","time":4.6613538265}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Start_from` FROM `hiring`","question":"Show all Start_from in the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Start_from` entries from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Start_from FROM hiring;\n```","cost":0.0006048,"response_parsed":"SELECT Start_from FROM hiring;","time":4.7067551613}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `hiring`","question":"Show all the rows in the table hiring","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all rows from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM hiring;\n```\n\nThis query will return all columns (`Shop_ID`, `Employee_ID`, `Start_from`, `Is_full_time`) for every row in the `hiring` table.","cost":0.000558,"response_parsed":"SELECT * FROM hiring;","time":4.3788077831}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Employee_ID` FROM `hiring`","question":"Show all Employee_ID in the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Employee_ID`s from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Employee_ID FROM hiring;\n```\n\nThis query will return all the `Employee_ID`s present in the `hiring` table.","cost":0.0005931,"response_parsed":"SELECT Employee_ID FROM hiring;","time":4.6761310101}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Start_from`, `Employee_ID` FROM `hiring`","question":"Show all Start_from, Employee_ID in the table hiring","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Start_from` and `Employee_ID` columns from the `hiring` table, you can use the following SQL query:\n\n```sql\nSELECT Start_from, Employee_ID FROM hiring;\n```\n\nThis query will return all rows from the `hiring` table, displaying only the `Start_from` and `Employee_ID` columns.","cost":0.0005247,"response_parsed":"SELECT Start_from, Employee_ID FROM hiring;","time":3.7493357658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `District` FROM `shop`","question":"Show all District in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all districts from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT District FROM shop;\n```","cost":0.0004545,"response_parsed":"SELECT District FROM shop;","time":3.2810077667}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Location` FROM `shop`","question":"Show all Location in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all locations from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Location FROM shop;\n```\n\nThis query will return all the entries in the `Location` column of your `shop` table.","cost":0.0005067,"response_parsed":"SELECT Location FROM shop;","time":3.6387021542}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `shop`","question":"Show all Name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all names from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM shop;\n```","cost":0.0004779,"response_parsed":"SELECT Name FROM shop;","time":3.4202506542}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Number_products` FROM `shop`","question":"Show all Number_products in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Number_products` from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Number_products FROM shop;\n```\n\nThis query will return all the values in the `Number_products` column for every row in the `shop` table.","cost":0.0005112,"response_parsed":"SELECT Number_products FROM shop;","time":3.8392887115}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Shop_ID` FROM `shop`","question":"Show all Shop_ID in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all `Shop_ID` from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Shop_ID FROM shop;\n```\n\nThis query will return all the unique `Shop_ID` values present in your `shop` table.","cost":0.0005562,"response_parsed":"SELECT Shop_ID FROM shop;","time":4.4353842735}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `shop`","question":"Show all the rows in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo show all the rows in the `shop` table, you can use the `SELECT` statement with the wildcard `*` to retrieve all columns. Here is the SQL code:\n\n```sql\nSELECT * FROM shop;\n```","cost":0.0005733,"response_parsed":"SELECT * FROM shop;","time":4.5176222324}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Location` FROM `shop`","question":"Show all Location in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch all locations from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Location FROM shop;\n```\n\nIf you want to ensure that each location appears only once (distinct values), you can use:\n\n```sql\nSELECT DISTINCT Location FROM shop;\n```","cost":0.0005103,"response_parsed":"SELECT DISTINCT Location FROM shop;","time":3.8743121624}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Name`, `Manager_name` FROM `shop`","question":"Show all Name, Manager_name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Name` and `Manager_name` from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT \"Name\", \"Manager_name\" FROM \"shop\";\n```\n\nThis query will return all rows from the `shop` table with the columns `Name` and `Manager_name`.","cost":0.0005274,"response_parsed":"SELECT \"Name\", \"Manager_name\" FROM \"shop\";","time":4.5002059937}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Number_products`, `Shop_ID`, `Manager_name` FROM `shop`","question":"Show all Number_products, Shop_ID, Manager_name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the `Number_products`, `Shop_ID`, and `Manager_name` from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Number_products, Shop_ID, Manager_name FROM shop;\n```\n\nThis query will return all rows from the `shop` table with the specified columns.","cost":0.0005283,"response_parsed":"SELECT Number_products, Shop_ID, Manager_name FROM shop;","time":4.3584625721}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Location`, `Name`, `Manager_name`, `District` FROM `shop`","question":"Show all Location, Name, Manager_name, District in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the required information from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT Location, Name, Manager_name, District FROM shop;\n```\n\nThis query will return all rows from the `shop` table with the specified columns: `Location`, `Name`, `Manager_name`, and `District`.","cost":0.0004914,"response_parsed":"SELECT Location, Name, Manager_name, District FROM shop;","time":4.0639472008}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `District`, `Number_products`, `Shop_ID`, `Location`, `Manager_name` FROM `shop`","question":"Show all District, Number_products, Shop_ID, Location, Manager_name in the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the required information from the `shop` table, you can use the following SQL query:\n\n```sql\nSELECT District, Number_products, Shop_ID, Location, Manager_name\nFROM shop;\n```\n\nThis query will return all the rows from the `shop` table with the specified columns: `District`, `Number_products`, `Shop_ID`, `Location`, and `Manager_name`.","cost":0.000585,"response_parsed":"SELECT District, Number_products, Shop_ID, Location, Manager_name\nFROM shop;","time":5.010201931}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `Name` == 'Mark Regan'","question":"Show the data of the table employee where Name is equal to Mark Regan","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees with the name \"Mark Regan,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE Name = 'Mark Regan';\n```","cost":0.0005193,"response_parsed":"SELECT *\nFROM employee\nWHERE Name = 'Mark Regan';","time":3.942040205}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `Name` != 'George Chuter'","question":"Show the data of the table employee where Name is different from George Chuter","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees whose names are different from \"George Chuter,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE Name != 'George Chuter';\n```","cost":0.0004869,"response_parsed":"SELECT *\nFROM employee\nWHERE Name != 'George Chuter';","time":3.7003245354}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `Name` != 'Lee Mears'","question":"Show the data of the table employee where Name not equal to Lee Mears","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees whose names are not \"Lee Mears,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE Name != 'Lee Mears';\n```","cost":0.0004545,"response_parsed":"SELECT *\nFROM employee\nWHERE Name != 'Lee Mears';","time":3.2134222984}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `City` == 'Bristol'","question":"Show the data of the table employee where City is equal to Bristol","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees where the City is Bristol, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE City = 'Bristol';\n```","cost":0.0005058,"response_parsed":"SELECT *\nFROM employee\nWHERE City = 'Bristol';","time":3.6072077751}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `City` != 'Bath'","question":"Show the data of the table employee where City is different from Bath","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees where the City is different from Bath, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE City <> 'Bath';\n```\n\nThis query will return all rows from the `employee` table where the `City` column is not 'Bath'.","cost":0.0005301,"response_parsed":"SELECT *\nFROM employee\nWHERE City <> 'Bath';","time":4.0289149284}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `employee` WHERE `City` != 'Bath'","question":"Show the data of the table employee where City not equal to Bath","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees where the City is not Bath, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE City <> 'Bath';\n```","cost":0.0004995,"response_parsed":"SELECT *\nFROM employee\nWHERE City <> 'Bath';","time":3.6391766071}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `employee` WHERE `Age` > 23","question":"Show the data of the table employee where Age is greater than 23","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data of employees where the age is greater than 23, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM employee\nWHERE Age > 23;\n```","cost":0.0005229,"response_parsed":"SELECT *\nFROM employee\nWHERE Age > 23;","time":3.8911018372}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Employee_ID` == '4'","question":"Show the data of the table evaluation where Employee_ID is equal to 4","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where `Employee_ID` is equal to 4, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Employee_ID = '4';\n```\n\nThis query will return all columns (`*`) from the `evaluation` table for the row(s) where the `Employee_ID` is '4'.","cost":0.0005292,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Employee_ID = '4';","time":3.9523484707}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Employee_ID` != '2'","question":"Show the data of the table evaluation where Employee_ID is different from 2","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where the `Employee_ID` is different from 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Employee_ID != '2';\n```\n\nThis query will return all rows from the `evaluation` table where the `Employee_ID` is not equal to '2'.","cost":0.0005814,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Employee_ID != '2';","time":4.1800444126}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Employee_ID` != '10'","question":"Show the data of the table evaluation where Employee_ID not equal to 10","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where `Employee_ID` is not equal to 10, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Employee_ID != '10';\n```\n\nThis query will return all rows from the `evaluation` table where the `Employee_ID` is not '10'.","cost":0.0006381,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Employee_ID != '10';","time":4.6252436638}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Year_awarded` == '2017'","question":"Show the data of the table evaluation where Year_awarded is equal to 2017","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where `Year_awarded` is equal to 2017, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Year_awarded = '2017';\n```\n\nThis query will return all rows from the `evaluation` table where the `Year_awarded` column is '2017'.","cost":0.000648,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Year_awarded = '2017';","time":4.9575254917}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Year_awarded` != '2017'","question":"Show the data of the table evaluation where Year_awarded is different from 2017","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where `Year_awarded` is different from 2017, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Year_awarded != '2017';\n```\n\nThis query will return all rows from the `evaluation` table where the `Year_awarded` column is not equal to '2017'.","cost":0.0005337,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Year_awarded != '2017';","time":3.5306451321}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `evaluation` WHERE `Year_awarded` != '2015'","question":"Show the data of the table evaluation where Year_awarded not equal to 2015","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where `Year_awarded` is not equal to 2015, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Year_awarded != '2015';\n```\n\nThis query will return all rows from the `evaluation` table where the `Year_awarded` column is not equal to '2015'.","cost":0.0005697,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Year_awarded != '2015';","time":4.0574491024}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `evaluation` WHERE `Bonus` > 3200.0","question":"Show the data of the table evaluation where Bonus is greater than 3200.0","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where the `Bonus` is greater than 3200.0, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM evaluation\nWHERE Bonus > 3200.0;\n```","cost":0.0005859,"response_parsed":"SELECT *\nFROM evaluation\nWHERE Bonus > 3200.0;","time":4.2655851841}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `evaluation` WHERE `Bonus` < 3000.0","question":"Show the data of the table evaluation where Bonus is less than 3000.0","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `evaluation` table where the `Bonus` is less than 3000.0, you can use the following SQL query:\n\n```sql\nSELECT * FROM evaluation WHERE Bonus < 3000.0;\n```","cost":0.0005877,"response_parsed":"SELECT * FROM evaluation WHERE Bonus < 3000.0;","time":4.0678458214}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `hiring` WHERE `Start_from` == '2011'","question":"Show the data of the table hiring where Start_from is equal to 2011","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `hiring` table where `Start_from` is equal to 2011, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM hiring\nWHERE Start_from = '2011';\n```","cost":0.0005139,"response_parsed":"SELECT *\nFROM hiring\nWHERE Start_from = '2011';","time":3.2539935112}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `hiring` WHERE `Start_from` != '2009'","question":"Show the data of the table hiring where Start_from is different from 2009","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `hiring` table where the `Start_from` is different from 2009, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM hiring\nWHERE Start_from != '2009';\n```\n\nThis query will return all rows in the `hiring` table where the `Start_from` value is not equal to '2009'.","cost":0.0005679,"response_parsed":"SELECT *\nFROM hiring\nWHERE Start_from != '2009';","time":3.8925485611}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `hiring` WHERE `Start_from` != '2013'","question":"Show the data of the table hiring where Start_from not equal to 2013","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `hiring` table where `Start_from` is not equal to '2013', you can use the following SQL query:\n\n```sql\nSELECT * FROM hiring WHERE Start_from != '2013';\n```","cost":0.0005553,"response_parsed":"SELECT * FROM hiring WHERE Start_from != '2013';","time":3.6659944057}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Location` == 'Turku'","question":"Show the data of the table shop where Location is equal to Turku","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Location` is \"Turku\", you can use the following SQL query:\n\n```sql\nSELECT * FROM shop WHERE Location = 'Turku';\n```","cost":0.000585,"response_parsed":"SELECT * FROM shop WHERE Location = 'Turku';","time":4.4374313354}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Location` != 'Turku'","question":"Show the data of the table shop where Location is different from Turku","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Location` is different from \"Turku\", you can use the following SQL query:\n\n```sql\nSELECT * FROM shop WHERE Location != 'Turku';\n```\n\nThis query will return all rows from the `shop` table where the `Location` column does not contain the value \"Turku\".","cost":0.000558,"response_parsed":"SELECT * FROM shop WHERE Location != 'Turku';","time":4.2637283802}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Location` != 'Espoo'","question":"Show the data of the table shop where Location not equal to Espoo","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Location` is not equal to 'Espoo', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE Location <> 'Espoo';\n```","cost":0.0006327,"response_parsed":"SELECT *\nFROM shop\nWHERE Location <> 'Espoo';","time":4.8411626816}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `District` == 'Jakobstads Centralplan'","question":"Show the data of the table shop where District is equal to Jakobstads Centralplan","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `District` is \"Jakobstads Centralplan,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE District = 'Jakobstads Centralplan';\n```","cost":0.0005976,"response_parsed":"SELECT *\nFROM shop\nWHERE District = 'Jakobstads Centralplan';","time":4.0277378559}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `District` != 'Tehtaan kentt\u00e4'","question":"Show the data of the table shop where District is different from Tehtaan kentt\u00e4","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `District` is different from \"Tehtaan kentt\u00e4\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE District != 'Tehtaan kentt\u00e4';\n```","cost":0.0006408,"response_parsed":"SELECT *\nFROM shop\nWHERE District != 'Tehtaan kentt\u00e4';","time":4.7374622822}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `District` != 'Jakobstads Centralplan'","question":"Show the data of the table shop where District not equal to Jakobstads Centralplan","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `District` is not equal to \"Jakobstads Centralplan\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE District <> 'Jakobstads Centralplan';\n```","cost":0.0005985,"response_parsed":"SELECT *\nFROM shop\nWHERE District <> 'Jakobstads Centralplan';","time":4.3731203079}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Manager_name` == 'Mika Laurikainen'","question":"Show the data of the table shop where Manager_name is equal to Mika Laurikainen","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Manager_name` is \"Mika Laurikainen\", you can use the following SQL query:\n\n```sql\nSELECT * FROM shop WHERE Manager_name = 'Mika Laurikainen';\n```","cost":0.0005184,"response_parsed":"SELECT * FROM shop WHERE Manager_name = 'Mika Laurikainen';","time":3.4929759502}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Manager_name` != 'Antti Muurinen'","question":"Show the data of the table shop where Manager_name is different from Antti Muurinen","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Manager_name` is different from \"Antti Muurinen\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE Manager_name <> 'Antti Muurinen';\n```\n\nThis query will return all rows from the `shop` table where the `Manager_name` is not \"Antti Muurinen\".","cost":0.0005328,"response_parsed":"SELECT *\nFROM shop\nWHERE Manager_name <> 'Antti Muurinen';","time":3.5459012985}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `shop` WHERE `Manager_name` != 'Olli Huttunen'","question":"Show the data of the table shop where Manager_name not equal to Olli Huttunen","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where the `Manager_name` is not equal to \"Olli Huttunen\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE Manager_name <> 'Olli Huttunen';\n```","cost":0.0005139,"response_parsed":"SELECT *\nFROM shop\nWHERE Manager_name <> 'Olli Huttunen';","time":3.3060889244}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `shop` WHERE `Number_products` > 10770","question":"Show the data of the table shop where Number_products is greater than 10770","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where `Number_products` is greater than 10770, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM shop\nWHERE Number_products > 10770;\n```","cost":0.0004878,"response_parsed":"SELECT *\nFROM shop\nWHERE Number_products > 10770;","time":3.1445186138}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `shop` WHERE `Number_products` < 5000","question":"Show the data of the table shop where Number_products is less than 5000","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo fetch the data from the `shop` table where `Number_products` is less than 5000, you can use the following SQL query:\n\n```sql\nSELECT * FROM shop WHERE Number_products < 5000;\n```","cost":0.0005553,"response_parsed":"SELECT * FROM shop WHERE Number_products < 5000;","time":3.7408246994}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `employee`","question":"How many different Name are in table employee?","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different names are in the `employee` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM employee;\n```","cost":0.0007389,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM employee;","time":6.1356453896}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `City`) FROM `employee`","question":"How many different City are in table employee?","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different cities are in the `employee` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT City) AS NumberOfCities FROM employee;\n```\n\nThis query will return the number of distinct cities present in the `City` column of the `employee` table.","cost":0.0005958,"response_parsed":"SELECT COUNT(DISTINCT City) AS NumberOfCities FROM employee;","time":4.2833201885}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Age`) FROM `employee`","question":"Find the maximum Age for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum Age in the `employee` table, you can use the SQL `MAX()` function. Here's how you can do it:\n\n```sql\nSELECT MAX(Age) FROM employee;\n```\n\nThis query will return the highest Age value from the `Age` column in your `employee` table.","cost":0.000468,"response_parsed":"SELECT MAX(Age) FROM employee;","time":3.0663969517}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Age`) FROM `employee`","question":"Find the minimum Age for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum Age for the table `employee`, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Age) FROM employee;\n```","cost":0.0004986,"response_parsed":"SELECT MIN(Age) FROM employee;","time":3.319365263}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"employee","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Age`) FROM `employee`","question":"Find the average Age for the table employee","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average age of employees in the `employee` table, you can use the SQL `AVG()` function. Here's how you can do it:\n\n```sql\nSELECT AVG(Age) FROM employee;\n```\n\nThis query will return the average age of all employees in your database.","cost":0.0004419,"response_parsed":"SELECT AVG(Age) FROM employee;","time":2.8027346134}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Employee_ID`) FROM `evaluation`","question":"How many different Employee_ID are in table evaluation?","db_schema_normalized":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different `Employee_ID`s are in the `evaluation` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Employee_ID) AS number_of_unique_employee_ids\nFROM evaluation;\n```\n\nThis query will return the number of unique `Employee_ID`s present in the `evaluation` table.","cost":0.0005778,"response_parsed":"SELECT COUNT(DISTINCT Employee_ID) AS number_of_unique_employee_ids\nFROM evaluation;","time":4.2045519352}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Year_awarded`) FROM `evaluation`","question":"How many different Year_awarded are in table evaluation?","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different `Year_awarded` values exist in the `evaluation` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Year_awarded) AS Number_of_Different_Years\nFROM evaluation;\n```\n\nThis query will return the number of unique `Year_awarded` values in your `evaluation` table.","cost":0.0005562,"response_parsed":"SELECT COUNT(DISTINCT Year_awarded) AS Number_of_Different_Years\nFROM evaluation;","time":3.9393937588}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Bonus`) FROM `evaluation`","question":"Find the maximum Bonus for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum Bonus from the `evaluation` table, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(Bonus) FROM evaluation;\n```\n\nThis query will return the highest Bonus value stored in the `Bonus` column of the `evaluation` table.","cost":0.000495,"response_parsed":"SELECT MAX(Bonus) FROM evaluation;","time":3.3827207088}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Bonus`) FROM `evaluation`","question":"Find the minimum Bonus for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum Bonus from the `evaluation` table, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Bonus) FROM evaluation;\n```\n\nThis query will return the smallest Bonus value present in the `Bonus` column of the `evaluation` table.","cost":0.0005697,"response_parsed":"SELECT MIN(Bonus) FROM evaluation;","time":3.9568927288}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"evaluation","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Bonus`) FROM `evaluation`","question":"Find the average Bonus for the table evaluation","db_schema_normalized":"`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average Bonus for the table `evaluation`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Bonus) AS Average_Bonus\nFROM evaluation;\n```\n\nThis query will calculate the average value of the `Bonus` column in your `evaluation` table and return it as `Average_Bonus`.","cost":0.0005121,"response_parsed":"SELECT AVG(Bonus) AS Average_Bonus\nFROM evaluation;","time":3.3432860374}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"hiring","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Start_from`) FROM `hiring`","question":"How many different Start_from are in table hiring?","db_schema_normalized":"`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different `Start_from` values exist in the `hiring` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Start_from) FROM hiring;\n```","cost":0.0005247,"response_parsed":"SELECT COUNT(DISTINCT Start_from) FROM hiring;","time":3.3711972237}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `shop`","question":"How many different Name are in table shop?","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different names are in the `shop` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM shop;\n```","cost":0.0005499,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM shop;","time":3.6650261879}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Location`) FROM `shop`","question":"How many different Location are in table shop?","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different locations are in the `shop` table, you can use the `COUNT(DISTINCT)` function on the `Location` column. Here's the SQL code:\n\n```sql\nSELECT COUNT(DISTINCT Location) FROM shop;\n```","cost":0.000486,"response_parsed":"SELECT COUNT(DISTINCT Location) FROM shop;","time":3.0826013088}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `District`) FROM `shop`","question":"How many different District are in table shop?","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different districts are in the `shop` table, you can use the `COUNT(DISTINCT)` function on the `District` column. Here's the SQL code:\n\n```sql\nSELECT COUNT(DISTINCT District) FROM shop;\n```","cost":0.0005337,"response_parsed":"SELECT COUNT(DISTINCT District) FROM shop;","time":3.6861124039}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Manager_name`) FROM `shop`","question":"How many different Manager_name are in table shop?","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo determine how many different `Manager_name` entries are in the `shop` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Manager_name) FROM shop;\n```","cost":0.0005058,"response_parsed":"SELECT COUNT(DISTINCT Manager_name) FROM shop;","time":3.3031797409}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Number_products`) FROM `shop`","question":"Find the maximum Number_products for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the maximum `Number_products` for the table `shop`, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(Number_products) FROM shop;\n```","cost":0.0005625,"response_parsed":"SELECT MAX(Number_products) FROM shop;","time":4.1122744083}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Number_products`) FROM `shop`","question":"Find the minimum Number_products for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the minimum `Number_products` for the table `shop`, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Number_products) AS min_products FROM shop;\n```\n\nThis query will return the smallest value in the `Number_products` column of the `shop` table.","cost":0.0005265,"response_parsed":"SELECT MIN(Number_products) AS min_products FROM shop;","time":3.7935597897}} {"db_path":"QATCH-journal\/spider_data\/test_database\/employee_hire_evaluation\/employee_hire_evaluation.sqlite","db_id":"employee_hire_evaluation","tbl_name":"shop","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Number_products`) FROM `shop`","question":"Find the average Number_products for the table shop","db_schema_normalized":"`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))","db_schema":"`\"employee\"` (\"Employee_ID\" int, \"Name\" text, \"Age\" int, \"City\" text, PRIMARY KEY (\"Employee_ID\"))\n`\"shop\"` (\"Shop_ID\" int, \"Name\" text, \"Location\" text, \"District\" text, \"Number_products\" int, \"Manager_name\" text, PRIMARY KEY (\"Shop_ID\"))\n`\"hiring\"` (\"Shop_ID\" int, \"Employee_ID\" int, \"Start_from\" text, \"Is_full_time\" bool, PRIMARY KEY (\"Employee_ID\"), FOREIGN KEY (`Shop_ID`) REFERENCES `shop`(`Shop_ID`), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))\n`\"evaluation\"` (\"Employee_ID\" text, \"Year_awarded\" text, \"Bonus\" real, PRIMARY KEY (\"Employee_ID\",\"Year_awarded\"), FOREIGN KEY (`Employee_ID`) REFERENCES `employee`(`Employee_ID`))","pred_dict":{"response":"\n\nTo find the average `Number_products` for the table `shop`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Number_products) AS Average_Number_products\nFROM shop;\n```\n\nThis query will calculate and return the average value of the `Number_products` column in the `shop` table.","cost":0.000558,"response_parsed":"SELECT AVG(Number_products) AS Average_Number_products\nFROM shop;","time":3.8149940968}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Document_Name` FROM `Documents`","question":"Show the different Document_Name in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Document_Name` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Document_Name FROM Documents;\n```\n\nThis query will return all unique values in the `Document_Name` column of the `Documents` table.","cost":0.0005274,"response_parsed":"SELECT DISTINCT Document_Name FROM Documents;","time":3.2814483643}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Document_Description` FROM `Documents`","question":"Show the different Document_Description in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Document_Description` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Document_Description FROM Documents;\n```\n\nThis query will return all unique values in the `Document_Description` column of the `Documents` table.","cost":0.0004743,"response_parsed":"SELECT DISTINCT Document_Description FROM Documents;","time":2.846909523}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Other_Details` FROM `Documents`","question":"Show the different Other_Details in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Other_Details \nFROM Documents;\n```\n\nThis query will return all unique values from the `Other_Details` column in the `Documents` table.","cost":0.0005787,"response_parsed":"SELECT DISTINCT Other_Details \nFROM Documents;","time":4.0971183777}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Template_Type_Code` FROM `Templates`","question":"Show the different Template_Type_Code in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo show the different `Template_Type_Code` values in the `Templates` table, you can use the `DISTINCT` keyword in SQL to retrieve unique values. Here's the SQL code:\n\n```sql\nSELECT DISTINCT Template_Type_Code \nFROM Templates;\n```\n\nThis query will return all unique `Template_Type_Code` values present in the `Templates` table.","cost":0.000531,"response_parsed":"SELECT DISTINCT Template_Type_Code \nFROM Templates;","time":3.6042029858}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Template_Details` FROM `Templates`","question":"Show the different Template_Details in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Template_Details` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Template_Details FROM Templates;\n```\n\nThis query will return all unique values in the `Template_Details` column of the `Templates` table.","cost":0.000504,"response_parsed":"SELECT DISTINCT Template_Details FROM Templates;","time":3.4568412304}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Template_Type_Code` FROM `Ref_Template_Types`","question":"Show the different Template_Type_Code in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Template_Type_Code` values from the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Template_Type_Code FROM Ref_Template_Types;\n```\n\nThis query will return all unique `Template_Type_Code` values present in the `Ref_Template_Types` table.","cost":0.0004392,"response_parsed":"SELECT DISTINCT Template_Type_Code FROM Ref_Template_Types;","time":2.6471898556}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Template_Type_Description` FROM `Ref_Template_Types`","question":"Show the different Template_Type_Description in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Template_Type_Description` from the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Template_Type_Description \nFROM Ref_Template_Types;\n```\n\nThis query will return all unique values of `Template_Type_Description` in your `Ref_Template_Types` table.","cost":0.00054,"response_parsed":"SELECT DISTINCT Template_Type_Description \nFROM Ref_Template_Types;","time":3.9708652496}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Paragraph_Text` FROM `Paragraphs`","question":"Show the different Paragraph_Text in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Paragraph_Text` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Paragraph_Text FROM Paragraphs;\n```\n\nThis query will return all unique values in the `Paragraph_Text` column of the `Paragraphs` table.","cost":0.000531,"response_parsed":"SELECT DISTINCT Paragraph_Text FROM Paragraphs;","time":3.7749016285}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Other_Details` FROM `Paragraphs`","question":"Show the different Other_Details in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the different `Other_Details` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Other_Details FROM Paragraphs;\n```\n\nThis query will return all unique values in the `Other_Details` column of the `Paragraphs` table.","cost":0.0004842,"response_parsed":"SELECT DISTINCT Other_Details FROM Paragraphs;","time":3.5180716515}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Document_Name`, COUNT(*) FROM `Documents` GROUP BY `Document_Name`","question":"For each Document_Name, count the number of rows in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Document_Name` in the `Documents` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Document_Name, \n COUNT(*) AS Count\nFROM \n Documents\nGROUP BY \n Document_Name;\n```\n\nThis query will return a result set with two columns:\n- `Document_Name`: The name of each document.\n- `Count`: The number of rows (documents) for each `Document_Name`.","cost":0.0007542,"response_parsed":"SELECT \n Document_Name, \n COUNT(*) AS Count\nFROM \n Documents\nGROUP BY \n Document_Name;","time":6.3069913387}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Document_Description`, COUNT(*) FROM `Documents` GROUP BY `Document_Description`","question":"For each Document_Description, count the number of rows in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to count the number of rows for each unique `Document_Description` in the `Documents` table. Here's the SQL code to achieve this:\n\n```sql\nSELECT \n Document_Description,\n COUNT(Document_ID) AS Row_Count\nFROM \n Documents\nGROUP BY \n Document_Description;\n```\n\nThis SQL query will:\n1. Select the `Document_Description` column.\n2. Count the number of rows for each `Document_Description` using `COUNT(Document_ID)`.\n3. Group the results by `Document_Description`.\n\nThe result will show each unique `Document_Description` along with the number of rows associated with it in the `Documents` table.","cost":0.0007425,"response_parsed":"SELECT \n Document_Description,\n COUNT(Document_ID) AS Row_Count\nFROM \n Documents\nGROUP BY \n Document_Description;","time":5.7116208076}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Other_Details`, COUNT(*) FROM `Documents` GROUP BY `Other_Details`","question":"For each Other_Details, count the number of rows in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows in the `Documents` table for each `Other_Details`, you can use the following SQL query:\n\n```sql\nSELECT \n Other_Details, \n COUNT(*) as Row_Count\nFROM \n Documents\nGROUP BY \n Other_Details;\n```\n\nThis query will return the number of rows for each unique value in the `Other_Details` column of the `Documents` table.","cost":0.0005859,"response_parsed":"SELECT \n Other_Details, \n COUNT(*) as Row_Count\nFROM \n Documents\nGROUP BY \n Other_Details;","time":4.0779249668}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Template_Type_Code`, COUNT(*) FROM `Templates` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, count the number of rows in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Template_Type_Code` in the `Templates` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Template_Type_Code,\n COUNT(*) AS Count\nFROM \n Templates\nGROUP BY \n Template_Type_Code\nORDER BY \n Template_Type_Code ASC;\n```\n\nThis SQL query will:\n1. Select the `Template_Type_Code` and count the number of rows for each `Template_Type_Code`.\n2. Group the results by `Template_Type_Code`.\n3. Sort the results by `Template_Type_Code` in ascending order.\n\nThe result will show each `Template_Type_Code` along with the number of rows associated with it in the `Templates` table.","cost":0.0007479,"response_parsed":"SELECT \n Template_Type_Code,\n COUNT(*) AS Count\nFROM \n Templates\nGROUP BY \n Template_Type_Code\nORDER BY \n Template_Type_Code ASC;","time":5.4854171276}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Template_Details`, COUNT(*) FROM `Templates` GROUP BY `Template_Details`","question":"For each Template_Details, count the number of rows in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Template_Details` in the `Templates` table, you can use the `COUNT()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT \n Template_Details,\n COUNT(Template_ID) AS Row_Count\nFROM \n Templates\nGROUP BY \n Template_Details;\n```\n\nThis query will return each unique `Template_Details` value along with the number of rows associated with it in the `Templates` table.","cost":0.0004977,"response_parsed":"SELECT \n Template_Details,\n COUNT(Template_ID) AS Row_Count\nFROM \n Templates\nGROUP BY \n Template_Details;","time":3.1157720089}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Template_Type_Code`, MIN(`Version_Number`) FROM `Templates` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, find the min of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the minimum `Version_Number` for each `Template_Type_Code` in the `Templates` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Template_Type_Code,\n MIN(Version_Number) AS Min_Version\nFROM \n Templates\nGROUP BY \n Template_Type_Code;\n```\n\nThis query will return the minimum `Version_Number` for each unique `Template_Type_Code` in your `Templates` table.","cost":0.0007011,"response_parsed":"SELECT \n Template_Type_Code,\n MIN(Version_Number) AS Min_Version\nFROM \n Templates\nGROUP BY \n Template_Type_Code;","time":5.3007004261}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Template_Type_Code`, MAX(`Version_Number`) FROM `Templates` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, find the max of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the maximum `Version_Number` for each `Template_Type_Code` in the `Templates` table, you can use the SQL `MAX` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Template_Type_Code,\n MAX(Version_Number) AS Max_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Type_Code\nORDER BY \n Template_Type_Code;\n```\n\nThis query will:\n1. Group all records in the `Templates` table by `Template_Type_Code`.\n2. For each group, calculate the maximum `Version_Number`.\n3. Return the results sorted by `Template_Type_Code` for better readability.\n\nThe result will show the highest version number available for each template type in your database.","cost":0.0007461,"response_parsed":"SELECT \n Template_Type_Code,\n MAX(Version_Number) AS Max_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Type_Code\nORDER BY \n Template_Type_Code;","time":5.935280323}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Template_Type_Code`, AVG(`Version_Number`) FROM `Templates` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, find the avg of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the average `Version_Number` for each `Template_Type_Code` in the `Templates` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Template_Type_Code,\n AVG(Version_Number) AS Average_Version\nFROM \n Templates\nGROUP BY \n Template_Type_Code;\n```\n\nThis query will return the average `Version_Number` for each unique `Template_Type_Code` in your `Templates` table.","cost":0.0006417,"response_parsed":"SELECT \n Template_Type_Code,\n AVG(Version_Number) AS Average_Version\nFROM \n Templates\nGROUP BY \n Template_Type_Code;","time":4.7348909378}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Template_Type_Code`, SUM(`Version_Number`) FROM `Templates` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, find the sum of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of `Version_Number` for each `Template_Type_Code` in the `Templates` table. Here's the SQL code to achieve this:\n\n```sql\nSELECT \n Template_Type_Code,\n SUM(Version_Number) AS Sum_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Type_Code;\n```\n\nThis SQL query:\n1. Selects the `Template_Type_Code` and calculates the sum of `Version_Number` for each `Template_Type_Code`.\n2. Uses the `SUM()` function to aggregate the `Version_Number` values.\n3. Groups the results by `Template_Type_Code` using the `GROUP BY` clause.","cost":0.0007929,"response_parsed":"SELECT \n Template_Type_Code,\n SUM(Version_Number) AS Sum_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Type_Code;","time":6.3660902977}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Template_Details`, MIN(`Version_Number`) FROM `Templates` GROUP BY `Template_Details`","question":"For each Template_Details, find the min of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the minimum `Version_Number` for each `Template_Details` in the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT \n Template_Details,\n MIN(Version_Number) AS Min_Version\nFROM \n Templates\nGROUP BY \n Template_Details;\n```\n\nThis query will:\n1. Select the `Template_Details` column\n2. Calculate the minimum `Version_Number` for each group of `Template_Details`\n3. Group the results by `Template_Details`\n4. Return the minimum version number for each template detail","cost":0.0005616,"response_parsed":"SELECT \n Template_Details,\n MIN(Version_Number) AS Min_Version\nFROM \n Templates\nGROUP BY \n Template_Details;","time":4.096578598}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Template_Details`, MAX(`Version_Number`) FROM `Templates` GROUP BY `Template_Details`","question":"For each Template_Details, find the max of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the maximum `Version_Number` for each `Template_Details` in the `Templates` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Template_Details,\n MAX(Version_Number) AS Max_Version\nFROM \n Templates\nGROUP BY \n Template_Details;\n```\n\nThis query will return each unique `Template_Details` along with the highest `Version_Number` associated with it.","cost":0.0006435,"response_parsed":"SELECT \n Template_Details,\n MAX(Version_Number) AS Max_Version\nFROM \n Templates\nGROUP BY \n Template_Details;","time":4.5808739662}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Template_Details`, AVG(`Version_Number`) FROM `Templates` GROUP BY `Template_Details`","question":"For each Template_Details, find the avg of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the average `Version_Number` for each `Template_Details` in the `Templates` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Template_Details AS template_details,\n AVG(Version_Number) AS avg_version\nFROM \n Templates\nGROUP BY \n Template_Details\nORDER BY \n Template_Details;\n```\n\nThis SQL query will:\n1. Select the `Template_Details` column\n2. Calculate the average of `Version_Number` for each group of `Template_Details`\n3. Group the results by `Template_Details`\n4. Sort the results alphabetically by `Template_Details`","cost":0.0006183,"response_parsed":"SELECT \n Template_Details AS template_details,\n AVG(Version_Number) AS avg_version\nFROM \n Templates\nGROUP BY \n Template_Details\nORDER BY \n Template_Details;","time":5.3201313019}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Template_Details`, SUM(`Version_Number`) FROM `Templates` GROUP BY `Template_Details`","question":"For each Template_Details, find the sum of Version_Number in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of `Version_Number` for each unique `Template_Details` in the `Templates` table. Here's the SQL query to achieve this:\n\n```sql\nSELECT \n Template_Details,\n SUM(Version_Number) AS Sum_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Details;\n```\n\nThis query will:\n1. Group all records in the `Templates` table by the `Template_Details` column.\n2. For each group (i.e., for each unique `Template_Details`), it will calculate the sum of the `Version_Number` values.\n3. Return a result set with two columns: `Template_Details` and `Sum_Version_Number` (the sum of `Version_Number` for each `Template_Details`).","cost":0.0006579,"response_parsed":"SELECT \n Template_Details,\n SUM(Version_Number) AS Sum_Version_Number\nFROM \n Templates\nGROUP BY \n Template_Details;","time":5.4139773846}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Template_Type_Code`, COUNT(*) FROM `Ref_Template_Types` GROUP BY `Template_Type_Code`","question":"For each Template_Type_Code, count the number of rows in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Template_Type_Code` in the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT \n Template_Type_Code,\n COUNT(*) as Row_Count\nFROM \n Ref_Template_Types\nGROUP BY \n Template_Type_Code;\n```\n\nThis query will return the number of rows for each unique `Template_Type_Code` in the `Ref_Template_Types` table.","cost":0.0007065,"response_parsed":"SELECT \n Template_Type_Code,\n COUNT(*) as Row_Count\nFROM \n Ref_Template_Types\nGROUP BY \n Template_Type_Code;","time":5.2724189758}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Template_Type_Description`, COUNT(*) FROM `Ref_Template_Types` GROUP BY `Template_Type_Description`","question":"For each Template_Type_Description, count the number of rows in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Template_Type_Description` in the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT \n Template_Type_Description,\n COUNT(*) AS Count_per_Template_Type\nFROM \n Ref_Template_Types\nGROUP BY \n Template_Type_Description;\n```\n\nThis query will return the number of rows for each unique `Template_Type_Description` in the `Ref_Template_Types` table.","cost":0.0007866,"response_parsed":"SELECT \n Template_Type_Description,\n COUNT(*) AS Count_per_Template_Type\nFROM \n Ref_Template_Types\nGROUP BY \n Template_Type_Description;","time":6.4436047077}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Paragraph_Text`, COUNT(*) FROM `Paragraphs` GROUP BY `Paragraph_Text`","question":"For each Paragraph_Text, count the number of rows in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Paragraph_Text` in the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT \n Paragraph_Text,\n COUNT(Paragraph_ID) AS Row_Count\nFROM \n Paragraphs\nGROUP BY \n Paragraph_Text;\n```\n\nThis query will return the number of rows for each unique `Paragraph_Text` in the `Paragraphs` table.","cost":0.0005895,"response_parsed":"SELECT \n Paragraph_Text,\n COUNT(Paragraph_ID) AS Row_Count\nFROM \n Paragraphs\nGROUP BY \n Paragraph_Text;","time":3.923178196}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Other_Details`, COUNT(*) FROM `Paragraphs` GROUP BY `Other_Details`","question":"For each Other_Details, count the number of rows in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo count the number of rows for each `Other_Details` in the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Other_Details, COUNT(*) AS Row_Count\nFROM Paragraphs\nGROUP BY Other_Details;\n```\n\nThis query will:\n1. Select the `Other_Details` column\n2. Count the number of rows for each unique `Other_Details` value using `COUNT(*)`\n3. Group the results by the `Other_Details` column\n4. Return the results with the count of rows for each `Other_Details` value","cost":0.0007254,"response_parsed":"SELECT Other_Details, COUNT(*) AS Row_Count\nFROM Paragraphs\nGROUP BY Other_Details;","time":5.3242621422}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Document_Name` FROM `Documents` GROUP BY `Document_Name` HAVING count(*) >= 1","question":"Find all the Document_Name that have at least 1 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Document_Name` entries in the `Documents` table that have at least one record, you can use the following SQL query. This query selects distinct `Document_Name` values from the `Documents` table where `Document_Name` is not null.\n\n```sql\nSELECT DISTINCT Document_Name \nFROM Documents \nWHERE Document_Name IS NOT NULL;\n```","cost":0.0005022,"response_parsed":"SELECT DISTINCT Document_Name \nFROM Documents \nWHERE Document_Name IS NOT NULL;","time":3.2809531689}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Document_Name` FROM `Documents` GROUP BY `Document_Name` HAVING count(*) <= 1","question":"Find all the Document_Name that have at most 1 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Document_Name`s that have at most 1 record in the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Name\nFROM Documents\nGROUP BY Document_Name\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Groups the records in the `Documents` table by `Document_Name`\n2. Filters the groups to include only those with 1 or fewer records\n3. Returns the `Document_Name`s that meet this condition","cost":0.0005688,"response_parsed":"SELECT Document_Name\nFROM Documents\nGROUP BY Document_Name\nHAVING COUNT(*) <= 1;","time":4.2204208374}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Document_Description` FROM `Documents` GROUP BY `Document_Description` HAVING count(*) >= 1","question":"Find all the Document_Description that have at least 1 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all unique `Document_Description`s that exist in the `Documents` table, you can use the `DISTINCT` keyword in SQL. This will return each unique `Document_Description` only once, even if it appears multiple times in the table.\n\n```sql\nSELECT DISTINCT Document_Description \nFROM Documents \nWHERE Document_Description IS NOT NULL;\n```\n\nThis query will:\n1. Select the `Document_Description` column from the `Documents` table\n2. Use `DISTINCT` to ensure each description appears only once\n3. Filter out any `NULL` values with the `WHERE` clause\n\nThe result will be a list of all unique, non-null `Document_Description`s that exist in your database.","cost":0.0007704,"response_parsed":"SELECT DISTINCT Document_Description \nFROM Documents \nWHERE Document_Description IS NOT NULL;","time":5.9610333443}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Document_Description` FROM `Documents` GROUP BY `Document_Description` HAVING count(*) <= 1","question":"Find all the Document_Description that have at most 1 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Document_Description`s that have at most 1 record in the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Description\nFROM Documents\nGROUP BY Document_Description\nHAVING COUNT(Document_ID) <= 1;\n```\n\nThis query:\n1. Groups the records in the `Documents` table by `Document_Description`\n2. Counts the number of records (`Document_ID`) for each `Document_Description`\n3. Filters the results to include only those `Document_Description`s that have 1 or fewer records\n\n```sql\nSELECT Document_Description\nFROM Documents\nGROUP BY Document_Description\nHAVING COUNT(Document_ID) <= 1;\n```","cost":0.0006624,"response_parsed":"SELECT Document_Description\nFROM Documents\nGROUP BY Document_Description\nHAVING COUNT(Document_ID) <= 1;","time":4.9340803623}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Other_Details` FROM `Documents` GROUP BY `Other_Details` HAVING count(*) >= 15","question":"Find all the Other_Details that have at least 15 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Other_Details` in the `Documents` table that appear in at least 15 records, you can use the following SQL query:\n\n```sql\nSELECT Other_Details\nFROM Documents\nGROUP BY Other_Details\nHAVING COUNT(Other_Details) >= 15;\n```\n\nThis query:\n1. Groups the records in the `Documents` table by the `Other_Details` column.\n2. Counts the number of records for each `Other_Details` value.\n3. Filters the results to include only those `Other_Details` values that appear in 15 or more records.","cost":0.0006498,"response_parsed":"SELECT Other_Details\nFROM Documents\nGROUP BY Other_Details\nHAVING COUNT(Other_Details) >= 15;","time":4.7453255653}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Other_Details` FROM `Documents` GROUP BY `Other_Details` HAVING count(*) <= 15","question":"Find all the Other_Details that have at most 15 records in table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Other_Details` in the `Documents` table that have at most 15 records, you can use the following SQL query:\n\n```sql\nSELECT Other_Details\nFROM Documents\nGROUP BY Other_Details\nHAVING COUNT(*) <= 15;\n```\n\nThis query:\n1. Selects the `Other_Details` column from the `Documents` table.\n2. Groups the rows by the `Other_Details` values.\n3. Filters the groups to include only those with 15 or fewer records using the `HAVING COUNT(*) <= 15` condition.","cost":0.000594,"response_parsed":"SELECT Other_Details\nFROM Documents\nGROUP BY Other_Details\nHAVING COUNT(*) <= 15;","time":4.0345582962}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING count(*) >= 4","question":"Find all the Template_Type_Code that have at least 4 records in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Type_Code` values that have at least 4 records in the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code, COUNT(*) AS Count\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING COUNT(*) >= 4;\n```\n\nThis query:\n1. Selects the `Template_Type_Code` and counts the number of records for each code.\n2. Groups the results by `Template_Type_Code`.\n3. Filters the results to include only those groups with 4 or more records.","cost":0.0005913,"response_parsed":"SELECT Template_Type_Code, COUNT(*) AS Count\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING COUNT(*) >= 4;","time":4.0056622028}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING count(*) <= 4","question":"Find all the Template_Type_Code that have at most 4 records in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Type_Code` values that have at most 4 records in the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING COUNT(Template_ID) <= 4;\n```\n\nThis query:\n1. Groups the records in the `Templates` table by `Template_Type_Code`.\n2. Counts the number of records for each `Template_Type_Code` using `COUNT(Template_ID)`.\n3. Filters the results to include only those `Template_Type_Code` values that have 4 or fewer records.\n\nThe result will be a list of `Template_Type_Code` values that meet the condition of having at most 4 records in the `Templates` table.","cost":0.0006966,"response_parsed":"SELECT Template_Type_Code\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING COUNT(Template_ID) <= 4;","time":5.1038100719}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING count(*) >= 20","question":"Find all the Template_Details that have at least 20 records in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Details` in the `Templates` table that have at least 20 records, you can use the following SQL query:\n\n```sql\nSELECT Template_Details\nFROM Templates\nGROUP BY Template_Details\nHAVING COUNT(Template_ID) >= 20;\n```\n\nThis query:\n1. Selects the `Template_Details` column\n2. Groups the rows by `Template_Details`\n3. Filters the groups to include only those with at least 20 records using `HAVING COUNT(Template_ID) >= 20`\n\n```sql\nSELECT Template_Details\nFROM Templates\nGROUP BY Template_Details\nHAVING COUNT(Template_ID) >= 20;\n```","cost":0.0006399,"response_parsed":"SELECT Template_Details\nFROM Templates\nGROUP BY Template_Details\nHAVING COUNT(Template_ID) >= 20;","time":4.8391497135}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING count(*) <= 20","question":"Find all the Template_Details that have at most 20 records in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Details` in the `Templates` table that have at most 20 records, you can use the following SQL query:\n\n```sql\nSELECT \n Template_Details,\n COUNT(*) as Record_Count\nFROM \n Templates\nGROUP BY \n Template_Details\nHAVING \n COUNT(*) <= 20;\n```\n\nThis query will:\n1. Group the rows in the `Templates` table by the `Template_Details` column.\n2. Count the number of records for each `Template_Details`.\n3. Return only those `Template_Details` that have 20 or fewer records.","cost":0.0005751,"response_parsed":"SELECT \n Template_Details,\n COUNT(*) as Record_Count\nFROM \n Templates\nGROUP BY \n Template_Details\nHAVING \n COUNT(*) <= 20;","time":3.9674804211}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING AVG(`Version_Number`) >= 5.5","question":"List the Template_Type_Code which average of Version_Number is at least 5.5 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Template_Type_Code` from the `Templates` table where the average of `Version_Number` is at least 5.5. Here's the SQL code to achieve this:\n\n```sql\nSELECT Template_Type_Code, AVG(Version_Number) AS Average_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING AVG(Version_Number) >= 5.5;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `Template_Type_Code` and calculate the average of `Version_Number` using the `AVG()` function. The `AS` keyword is used to alias the average column as `Average_Version` for better readability.\n2. **FROM Clause**: We specify the `Templates` table as the source of data.\n3. **GROUP BY Clause**: We group the results by `Template_Type_Code` to calculate the average `Version_Number` for each type.\n4. **HAVING Clause**: We filter the results to include only those groups where the average `Version_Number` is at least 5.5.\n\nThis query will return the `Template_Type_Code` and the corresponding average `Version_Number` for the types that meet the condition.","cost":0.0008334,"response_parsed":"SELECT Template_Type_Code, AVG(Version_Number) AS Average_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING AVG(Version_Number) >= 5.5;","time":6.2666404247}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING AVG(`Version_Number`) <= 5.5","question":"List the Template_Type_Code which average of Version_Number is at most 5.5 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Type_Code` where the average of `Version_Number` is at most 5.5, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code, AVG(Version_Number) AS Average_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING AVG(Version_Number) <= 5.5;\n```\n\nThis query:\n1. Selects the `Template_Type_Code` and calculates the average of `Version_Number` for each type.\n2. Groups the results by `Template_Type_Code`.\n3. Filters the results to include only those groups where the average `Version_Number` is at most 5.5.","cost":0.0006138,"response_parsed":"SELECT Template_Type_Code, AVG(Version_Number) AS Average_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING AVG(Version_Number) <= 5.5;","time":4.2424123287}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING SUM(`Version_Number`) >= 20.6","question":"List the Template_Type_Code which summation of Version_Number is at least 20.6 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Template_Type_Code` from the `Templates` table where the sum of `Version_Number` is at least 20.6. Here's the SQL code to achieve this:\n\n```sql\nSELECT Template_Type_Code\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING SUM(Version_Number) >= 20.6;\n```\n\n### Explanation:\n1. **SELECT Template_Type_Code**: This selects the `Template_Type_Code` column that we want to retrieve.\n2. **FROM Templates**: This specifies the table from which to fetch the data.\n3. **GROUP BY Template_Type_Code**: This groups the rows by the `Template_Type_Code` so that we can perform aggregation on each group.\n4. **HAVING SUM(Version_Number) >= 20.6**: This filters the groups to include only those where the sum of `Version_Number` is at least 20.6.\n\nThis query will return the `Template_Type_Code` values where the sum of `Version_Number` meets or exceeds 20.6.","cost":0.0007857,"response_parsed":"SELECT Template_Type_Code\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING SUM(Version_Number) >= 20.6;","time":6.5081026554}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING SUM(`Version_Number`) <= 20.6","question":"List the Template_Type_Code which summation of Version_Number is at most 20.6 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `Template_Type_Code` from the `Templates` table where the sum of `Version_Number` for each `Template_Type_Code` is at most 20.6.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT Template_Type_Code, SUM(Version_Number) AS Total_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING SUM(Version_Number) <= 20.6;\n```\n\nThis query:\n1. Groups the rows in the `Templates` table by `Template_Type_Code`.\n2. Calculates the sum of `Version_Number` for each group.\n3. Filters the results to include only those groups where the sum of `Version_Number` is at most 20.6.","cost":0.0008055,"response_parsed":"SELECT Template_Type_Code, SUM(Version_Number) AS Total_Version\nFROM Templates\nGROUP BY Template_Type_Code\nHAVING SUM(Version_Number) <= 20.6;","time":6.1616740227}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING AVG(`Version_Number`) >= 5.15","question":"List the Template_Details which average of Version_Number is at least 5.15 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Details` from the `Templates` table where the average of `Version_Number` is at least 5.15, you can use the following SQL query:\n\n```sql\nSELECT Template_Details\nFROM Templates\nGROUP BY Template_Details\nHAVING AVG(Version_Number) >= 5.15;\n```\n\nThis query:\n1. Groups the rows in the `Templates` table by the `Template_Details` column.\n2. Filters the groups to include only those where the average `Version_Number` is at least 5.15.\n3. Returns the `Template_Details` for the filtered groups.","cost":0.0006417,"response_parsed":"SELECT Template_Details\nFROM Templates\nGROUP BY Template_Details\nHAVING AVG(Version_Number) >= 5.15;","time":4.8302152157}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING AVG(`Version_Number`) <= 5.15","question":"List the Template_Details which average of Version_Number is at most 5.15 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Details` from the `Templates` table where the average of `Version_Number` is at most 5.15, you can use the following SQL query:\n\n```sql\nSELECT Template_Details \nFROM Templates \nGROUP BY Template_Details \nHAVING AVG(Version_Number) <= 5.15;\n```\n\nThis query:\n1. Groups the rows in the `Templates` table by the `Template_Details` column.\n2. Calculates the average `Version_Number` for each group using the `AVG()` function.\n3. Filters the results to include only those groups where the average `Version_Number` is less than or equal to 5.15.","cost":0.0007344,"response_parsed":"SELECT Template_Details \nFROM Templates \nGROUP BY Template_Details \nHAVING AVG(Version_Number) <= 5.15;","time":5.704436779}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING SUM(`Version_Number`) >= 103.0","question":"List the Template_Details which summation of Version_Number is at least 103.0 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Details` from the `Templates` table where the summation of `Version_Number` is at least 103.0, you can use the following SQL query:\n\n```sql\nSELECT Template_Details\nFROM Templates\nWHERE Version_Number >= 103.0;\n```\n\nThis query will return all `Template_Details` where the `Version_Number` is 103.0 or higher.","cost":0.0007965,"response_parsed":"SELECT Template_Details\nFROM Templates\nWHERE Version_Number >= 103.0;","time":6.6442072392}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Template_Details` FROM `Templates` GROUP BY `Template_Details` HAVING SUM(`Version_Number`) <= 103.0","question":"List the Template_Details which summation of Version_Number is at most 103.0 in table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Details` from the `Templates` table where the summation of `Version_Number` is at most 103.0, you can use the following SQL query:\n\n```sql\nSELECT Template_Details \nFROM Templates \nWHERE (SELECT SUM(Version_Number) FROM Templates) <= 103;\n```\n\nThis query will:\n1. Calculate the sum of all `Version_Number` values in the `Templates` table using a subquery.\n2. Check if this sum is less than or equal to 103.\n3. If the condition is met, it will return the `Template_Details` from the `Templates` table.","cost":0.0010764,"response_parsed":"SELECT Template_Details \nFROM Templates \nWHERE (SELECT SUM(Version_Number) FROM Templates) <= 103;","time":9.4985792637}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Code` FROM `Ref_Template_Types` GROUP BY `Template_Type_Code` HAVING count(*) >= 1","question":"Find all the Template_Type_Code that have at least 1 records in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo answer the question of finding all `Template_Type_Code` that have at least 1 record in the `Ref_Template_Types` table, we can use a simple `SELECT` statement since every record in `Ref_Template_Types` inherently has at least one record.\n\n```sql\nSELECT Template_Type_Code FROM Ref_Template_Types;\n```\n\nIf the intention is to find `Template_Type_Code` values that are actually used in the `Templates` table, you can use the following query:\n\n```sql\nSELECT DISTINCT Template_Type_Code \nFROM Templates \nWHERE Template_Type_Code IN (SELECT Template_Type_Code FROM Ref_Template_Types);\n```\n\nThis will return all `Template_Type_Code` values that exist in both `Ref_Template_Types` and `Templates`.","cost":0.0008217,"response_parsed":"SELECT DISTINCT Template_Type_Code \nFROM Templates \nWHERE Template_Type_Code IN (SELECT Template_Type_Code FROM Ref_Template_Types);","time":6.7829430103}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Code` FROM `Ref_Template_Types` GROUP BY `Template_Type_Code` HAVING count(*) <= 1","question":"Find all the Template_Type_Code that have at most 1 records in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Type_Code` values in the `Ref_Template_Types` table that have at most 1 record in the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT r.Template_Type_Code\nFROM Ref_Template_Types r\nLEFT JOIN Templates t\n ON r.Template_Type_Code = t.Template_Type_Code\nGROUP BY r.Template_Type_Code\nHAVING COUNT(t.Template_ID) <= 1;\n```\n\nThis query:\n1. Joins `Ref_Template_Types` with `Templates` on `Template_Type_Code`.\n2. Groups the results by `Template_Type_Code`.\n3. Filters the groups to include only those with 1 or fewer records in `Templates`.\n\nThe result will be a list of `Template_Type_Code` values that meet the criteria.","cost":0.0007488,"response_parsed":"SELECT r.Template_Type_Code\nFROM Ref_Template_Types r\nLEFT JOIN Templates t\n ON r.Template_Type_Code = t.Template_Type_Code\nGROUP BY r.Template_Type_Code\nHAVING COUNT(t.Template_ID) <= 1;","time":6.1436629295}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types` GROUP BY `Template_Type_Description` HAVING count(*) >= 1","question":"Find all the Template_Type_Description that have at least 1 records in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Type_Description` that have at least 1 record in the `Ref_Template_Types` table, you can use the following SQL query. This query will return all descriptions of template types that exist in the `Ref_Template_Types` table and have corresponding records in the `Templates` table.\n\n```sql\nSELECT DISTINCT r.Template_Type_Description\nFROM Ref_Template_Types r\nINNER JOIN Templates t\nON r.Template_Type_Code = t.Template_Type_Code;\n```\n\nThis query:\n1. Selects the `Template_Type_Description` from the `Ref_Template_Types` table.\n2. Uses an `INNER JOIN` to ensure that only template types with matching records in the `Templates` table are included.\n3. Uses `DISTINCT` to avoid duplicate descriptions in the result set.","cost":0.0007272,"response_parsed":"SELECT DISTINCT r.Template_Type_Description\nFROM Ref_Template_Types r\nINNER JOIN Templates t\nON r.Template_Type_Code = t.Template_Type_Code;","time":5.8447141647}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types` GROUP BY `Template_Type_Description` HAVING count(*) <= 1","question":"Find all the Template_Type_Description that have at most 1 records in table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Template_Type_Description` that have at most 1 record in the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT \n rtt.Template_Type_Description\nFROM \n Ref_Template_Types rtt\nLEFT JOIN \n Templates t ON rtt.Template_Type_Code = t.Template_Type_Code\nGROUP BY \n rtt.Template_Type_Description\nHAVING \n COUNT(t.Template_ID) <= 1;\n```\n\nThis query:\n1. Joins `Ref_Template_Types` with `Templates` on `Template_Type_Code`\n2. Groups the results by `Template_Type_Description`\n3. Filters the groups to include only those with at most 1 record in `Templates`\n\n```sql\nSELECT \n rtt.Template_Type_Description\nFROM \n Ref_Template_Types rtt\nLEFT JOIN \n Templates t ON rtt.Template_Type_Code = t.Template_Type_Code\nGROUP BY \n rtt.Template_Type_Description\nHAVING \n COUNT(t.Template_ID) <= 1;\n```","cost":0.0006759,"response_parsed":"SELECT \n rtt.Template_Type_Description\nFROM \n Ref_Template_Types rtt\nLEFT JOIN \n Templates t ON rtt.Template_Type_Code = t.Template_Type_Code\nGROUP BY \n rtt.Template_Type_Description\nHAVING \n COUNT(t.Template_ID) <= 1;","time":5.2401628494}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Paragraph_Text` FROM `Paragraphs` GROUP BY `Paragraph_Text` HAVING count(*) >= 1","question":"Find all the Paragraph_Text that have at least 1 records in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all the `Paragraph_Text` that have at least 1 record in the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text\nFROM Paragraphs\nWHERE Paragraph_Text IS NOT NULL;\n```\n\nThis query will return all non-null `Paragraph_Text` values from the `Paragraphs` table. If you want to ensure that each `Paragraph_Text` appears only once in the result (i.e., distinct values), you can modify the query as follows:\n\n```sql\nSELECT DISTINCT Paragraph_Text\nFROM Paragraphs\nWHERE Paragraph_Text IS NOT NULL;\n```","cost":0.0007047,"response_parsed":"SELECT DISTINCT Paragraph_Text\nFROM Paragraphs\nWHERE Paragraph_Text IS NOT NULL;","time":5.5300774574}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Paragraph_Text` FROM `Paragraphs` GROUP BY `Paragraph_Text` HAVING count(*) <= 1","question":"Find all the Paragraph_Text that have at most 1 records in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Paragraph_Text` that appear at most once in the `Paragraphs` table, you can use the following SQL query. This query groups the paragraphs by their text and filters those groups that have one or fewer records.\n\n```sql\nSELECT Paragraph_Text\nFROM Paragraphs\nGROUP BY Paragraph_Text\nHAVING COUNT(Paragraph_Text) <= 1;\n```","cost":0.0006327,"response_parsed":"SELECT Paragraph_Text\nFROM Paragraphs\nGROUP BY Paragraph_Text\nHAVING COUNT(Paragraph_Text) <= 1;","time":4.4081788063}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Other_Details` FROM `Paragraphs` GROUP BY `Other_Details` HAVING count(*) >= 15","question":"Find all the Other_Details that have at least 15 records in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all `Other_Details` in the `Paragraphs` table that have at least 15 records, you can use the following SQL query:\n\n```sql\nSELECT Other_Details, COUNT(*) AS Record_Count\nFROM Paragraphs\nGROUP BY Other_Details\nHAVING COUNT(*) >= 15;\n```\n\nThis query:\n1. Selects the `Other_Details` column and counts the number of records for each `Other_Details` value.\n2. Groups the results by the `Other_Details` values.\n3. Filters the results to include only those `Other_Details` values that have 15 or more records.","cost":0.0005697,"response_parsed":"SELECT Other_Details, COUNT(*) AS Record_Count\nFROM Paragraphs\nGROUP BY Other_Details\nHAVING COUNT(*) >= 15;","time":3.6747922897}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Other_Details` FROM `Paragraphs` GROUP BY `Other_Details` HAVING count(*) <= 15","question":"Find all the Other_Details that have at most 15 records in table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find all the `Other_Details` in the `Paragraphs` table that have at most 15 records, you can use the following SQL query:\n\n```sql\nSELECT Other_Details\nFROM Paragraphs\nGROUP BY Other_Details\nHAVING COUNT(*) <= 15;\n```\n\nThis query:\n1. Groups the rows in the `Paragraphs` table by the `Other_Details` column.\n2. Counts the number of records in each group using `COUNT(*)`.\n3. Filters the groups to include only those with a count of 15 or fewer records using the `HAVING` clause.\n\nThe result will be a list of `Other_Details` values that appear in 15 or fewer records in the `Paragraphs` table.","cost":0.0008091,"response_parsed":"SELECT Other_Details\nFROM Paragraphs\nGROUP BY Other_Details\nHAVING COUNT(*) <= 15;","time":6.7858877182}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID` = T2.`Template_ID`","question":"Join all the records from table Documents with table Templates on Template_ID","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo join all records from the `Documents` table with the `Templates` table based on the `Template_ID`, you can use the following SQL query:\n\n```sql\nSELECT D.*, T.*\nFROM Documents AS D\nINNER JOIN Templates AS T\nON D.Template_ID = T.Template_ID;\n```\n\nThis query will return all columns from both the `Documents` and `Templates` tables where there is a matching `Template_ID` in both tables.","cost":0.0004986,"response_parsed":"SELECT D.*, T.*\nFROM Documents AS D\nINNER JOIN Templates AS T\nON D.Template_ID = T.Template_ID;","time":3.6536111832}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Document_Name`, T2.`Template_Type_Code` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Document_Name and Template_Type_Code from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the required information, we need to join the `Documents` and `Templates` tables based on the `Template_ID` column, as it is the common key between them. Here is the SQL query:\n\n```sql\nSELECT \n D.Document_Name,\n T.Template_Type_Code\nFROM \n Documents D\nINNER JOIN \n Templates T\nON \n D.Template_ID = T.Template_ID;\n```\n\nThis query will return all `Document_Name` and `Template_Type_Code` where the `Template_ID` exists in both tables.","cost":0.0007542,"response_parsed":"SELECT \n D.Document_Name,\n T.Template_Type_Code\nFROM \n Documents D\nINNER JOIN \n Templates T\nON \n D.Template_ID = T.Template_ID;","time":6.0433218479}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Document_Name`, T2.`Template_Details` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Document_Name and Template_Details from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Document_Name` from the `Documents` table and `Template_Details` from the `Templates` table where the `Template_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT D.Document_Name, T.Template_Details\nFROM Documents D\nINNER JOIN Templates T\nON D.Template_ID = T.Template_ID;\n```\n\nThis query:\n1. Selects the `Document_Name` from the `Documents` table and `Template_Details` from the `Templates` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Template_ID` is the same in both tables.","cost":0.0006615,"response_parsed":"SELECT D.Document_Name, T.Template_Details\nFROM Documents D\nINNER JOIN Templates T\nON D.Template_ID = T.Template_ID;","time":5.079356432}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Document_Description`, T2.`Template_Type_Code` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Document_Description and Template_Type_Code from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the required information, we need to join the `Documents` table and the `Templates` table based on the `Template_ID` column, as the question specifies that `Template_ID` should be the same in both tables.\n\nHere is the SQL query:\n\n```sql\nSELECT \n D.Document_Description,\n T.Template_Type_Code\nFROM \n Documents D\nINNER JOIN \n Templates T ON D.Template_ID = T.Template_ID;\n```\n\nThis query will:\n1. Select the `Document_Description` from the `Documents` table.\n2. Select the `Template_Type_Code` from the `Templates` table.\n3. Join the two tables on the `Template_ID` column, ensuring that only rows with matching `Template_ID` values in both tables are included in the result.","cost":0.0006642,"response_parsed":"SELECT \n D.Document_Description,\n T.Template_Type_Code\nFROM \n Documents D\nINNER JOIN \n Templates T ON D.Template_ID = T.Template_ID;","time":5.0588920116}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Document_Description`, T2.`Template_Details` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Document_Description and Template_Details from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the required information, we need to join the `Documents` and `Templates` tables based on the `Template_ID` column, as it is the common key between them. Here is the SQL query:\n\n```sql\nSELECT \n D.Document_Description, \n T.Template_Details\nFROM \n Documents D\nINNER JOIN \n Templates T ON D.Template_ID = T.Template_ID;\n```\n\nThis query will return all the `Document_Description` from the `Documents` table and `Template_Details` from the `Templates` table where the `Template_ID` matches in both tables.","cost":0.000648,"response_parsed":"SELECT \n D.Document_Description, \n T.Template_Details\nFROM \n Documents D\nINNER JOIN \n Templates T ON D.Template_ID = T.Template_ID;","time":6.6325426102}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Other_Details`, T2.`Template_Type_Code` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Other_Details and Template_Type_Code from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details` from the `Documents` table and the `Template_Type_Code` from the `Templates` table where the `Template_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT D.Other_Details, T.Template_Type_Code\nFROM Documents D\nINNER JOIN Templates T\nON D.Template_ID = T.Template_ID;\n```\n\nThis query will:\n1. Select the `Other_Details` column from the `Documents` table.\n2. Select the `Template_Type_Code` column from the `Templates` table.\n3. Join the two tables based on the matching `Template_ID` values.\n4. Return only the rows where the `Template_ID` exists in both tables.","cost":0.0006696,"response_parsed":"SELECT D.Other_Details, T.Template_Type_Code\nFROM Documents D\nINNER JOIN Templates T\nON D.Template_ID = T.Template_ID;","time":4.839728117}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Other_Details`, T2.`Template_Details` FROM `Documents` AS T1 JOIN `Templates` AS T2 ON T1.`Template_ID`=T2.`Template_ID`","question":"List all the Other_Details and Template_Details from the table Documents and the table Templates where Template_ID is the same","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details` from the `Documents` table and `Template_Details` from the `Templates` table where the `Template_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT D.Other_Details, T.Template_Details\nFROM Templates T\nINNER JOIN Documents D\nON T.Template_ID = D.Template_ID;\n```\n\nThis query:\n1. Selects the `Other_Details` column from the `Documents` table and the `Template_Details` column from the `Templates` table.\n2. Uses an `INNER JOIN` to combine rows from the `Templates` and `Documents` tables where the `Template_ID` is the same in both tables.","cost":0.0005652,"response_parsed":"SELECT D.Other_Details, T.Template_Details\nFROM Templates T\nINNER JOIN Documents D\nON T.Template_ID = D.Template_ID;","time":3.749651432}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `Templates` AS T1 JOIN `Ref_Template_Types` AS T2 ON T1.`Template_Type_Code` = T2.`Template_Type_Code`","question":"Join all the records from table Templates with table Ref_Template_Types on Template_Type_Code","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo join all records from the `Templates` table with the `Ref_Template_Types` table on the `Template_Type_Code` column, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nINNER JOIN Ref_Template_Types\nON Templates.Template_Type_Code = Ref_Template_Types.Template_Type_Code;\n```\n\nThis query will return all columns (`*`) from both tables where there is a matching `Template_Type_Code` in both tables.","cost":0.0004851,"response_parsed":"SELECT *\nFROM Templates\nINNER JOIN Ref_Template_Types\nON Templates.Template_Type_Code = Ref_Template_Types.Template_Type_Code;","time":3.3357765675}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Template_Details`, T2.`Template_Type_Description` FROM `Templates` AS T1 JOIN `Ref_Template_Types` AS T2 ON T1.`Template_Type_Code`=T2.`Template_Type_Code`","question":"List all the Template_Details and Template_Type_Description from the table Templates and the table Ref_Template_Types where Template_Type_Code is the same","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the required data, you can use the following SQL query that joins the `Templates` table with the `Ref_Template_Types` table based on the `Template_Type_Code`:\n\n```sql\nSELECT \n T.Template_Details,\n R.Template_Type_Description\nFROM \n Templates T\nINNER JOIN \n Ref_Template_Types R\nON \n T.Template_Type_Code = R.Template_Type_Code;\n```\n\nThis query will return all rows where the `Template_Type_Code` exists in both tables, along with the corresponding `Template_Details` and `Template_Type_Description`.","cost":0.00063,"response_parsed":"SELECT \n T.Template_Details,\n R.Template_Type_Description\nFROM \n Templates T\nINNER JOIN \n Ref_Template_Types R\nON \n T.Template_Type_Code = R.Template_Type_Code;","time":4.7609426975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID` = T2.`Document_ID`","question":"Join all the records from table Paragraphs with table Documents on Document_ID","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo join all records from the `Paragraphs` table with the `Documents` table on `Document_ID`, you can use the following SQL query:\n\n```sql\nSELECT Paragraphs.*, Documents.*\nFROM Paragraphs\nINNER JOIN Documents\nON Paragraphs.Document_ID = Documents.Document_ID;\n```\n\nThis query will return all columns (`*`) from both the `Paragraphs` and `Documents` tables where the `Document_ID` matches in both tables.","cost":0.0005967,"response_parsed":"SELECT Paragraphs.*, Documents.*\nFROM Paragraphs\nINNER JOIN Documents\nON Paragraphs.Document_ID = Documents.Document_ID;","time":4.887355566}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Paragraph_Text`, T2.`Document_Name` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Paragraph_Text and Document_Name from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Paragraph_Text` and `Document_Name` from the `Paragraphs` and `Documents` tables where the `Document_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT P.Paragraph_Text, D.Document_Name\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;\n```\n\nThis query:\n1. Selects the `Paragraph_Text` from the `Paragraphs` table and `Document_Name` from the `Documents` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Document_ID` is the same.\n3. The `ON` clause specifies the condition for joining the tables based on the `Document_ID`.","cost":0.0007371,"response_parsed":"SELECT P.Paragraph_Text, D.Document_Name\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;","time":5.7956445217}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Paragraph_Text`, T2.`Document_Description` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Paragraph_Text and Document_Description from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Paragraph_Text` from the `Paragraphs` table and `Document_Description` from the `Documents` table where the `Document_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT P.Paragraph_Text, D.Document_Description\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;\n```\n\nThis query:\n1. Selects the `Paragraph_Text` from the `Paragraphs` table and `Document_Description` from the `Documents` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Document_ID` is the same in both tables.","cost":0.0006237,"response_parsed":"SELECT P.Paragraph_Text, D.Document_Description\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;","time":4.9006044865}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Paragraph_Text`, T2.`Other_Details` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Paragraph_Text and Other_Details from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Paragraph_Text` and `Other_Details` from both the `Paragraphs` and `Documents` tables where the `Document_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT \n P.Paragraph_Text, \n P.Other_Details AS Paragraph_Other_Details,\n D.Other_Details AS Document_Other_Details\nFROM \n Paragraphs P\nINNER JOIN \n Documents D ON P.Document_ID = D.Document_ID;\n```\n\nThis query:\n1. Selects `Paragraph_Text` from the `Paragraphs` table.\n2. Selects `Other_Details` from both the `Paragraphs` and `Documents` tables, using aliases to distinguish between them (`Paragraph_Other_Details` and `Document_Other_Details`).\n3. Uses an `INNER JOIN` to combine rows from `Paragraphs` and `Documents` where the `Document_ID` is the same in both tables.","cost":0.0007461,"response_parsed":"SELECT \n P.Paragraph_Text, \n P.Other_Details AS Paragraph_Other_Details,\n D.Other_Details AS Document_Other_Details\nFROM \n Paragraphs P\nINNER JOIN \n Documents D ON P.Document_ID = D.Document_ID;","time":6.2790024281}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Other_Details`, T2.`Document_Name` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Other_Details and Document_Name from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details` from the `Paragraphs` table and `Document_Name` from the `Documents` table where the `Document_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT P.Other_Details, D.Document_Name\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;\n```\n\nThis query:\n1. Selects the `Other_Details` column from the `Paragraphs` table and the `Document_Name` column from the `Documents` table.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Document_ID` is the same in both tables.","cost":0.0007488,"response_parsed":"SELECT P.Other_Details, D.Document_Name\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;","time":6.544413805}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Other_Details`, T2.`Document_Description` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Other_Details and Document_Description from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details` from the `Paragraphs` table and `Document_Description` from the `Documents` table where the `Document_ID` is the same in both tables, you can use the following SQL query:\n\n```sql\nSELECT P.Other_Details, D.Document_Description\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;\n```\n\nThis query:\n1. Selects the `Other_Details` column from the `Paragraphs` table.\n2. Selects the `Document_Description` column from the `Documents` table.\n3. Uses an `INNER JOIN` to combine rows from both tables where the `Document_ID` is the same in both tables.","cost":0.0006165,"response_parsed":"SELECT P.Other_Details, D.Document_Description\nFROM Paragraphs P\nINNER JOIN Documents D\nON P.Document_ID = D.Document_ID;","time":4.8708732128}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`Other_Details`, T2.`Other_Details` FROM `Paragraphs` AS T1 JOIN `Documents` AS T2 ON T1.`Document_ID`=T2.`Document_ID`","question":"List all the Other_Details and Other_Details from the table Paragraphs and the table Documents where Document_ID is the same","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details` from both the `Paragraphs` and `Documents` tables where the `Document_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT \n D.Other_Details AS Document_Other_Details,\n P.Other_Details AS Paragraph_Other_Details\nFROM \n Documents D\nINNER JOIN \n Paragraphs P ON D.Document_ID = P.Document_ID;\n```\n\nThis query:\n1. Selects the `Other_Details` from both the `Documents` and `Paragraphs` tables.\n2. Uses an `INNER JOIN` to combine rows from both tables where the `Document_ID` is the same.\n3. Aliases the `Other_Details` columns to avoid ambiguity (`Document_Other_Details` for the `Documents` table and `Paragraph_Other_Details` for the `Paragraphs` table).","cost":0.0007101,"response_parsed":"SELECT \n D.Other_Details AS Document_Other_Details,\n P.Other_Details AS Paragraph_Other_Details\nFROM \n Documents D\nINNER JOIN \n Paragraphs P ON D.Document_ID = P.Document_ID;","time":5.6919939518}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Document_Name` FROM `Documents` GROUP BY `Document_Name` HAVING COUNT(DISTINCT `Other_Details`) = (SELECT COUNT(DISTINCT `Other_Details`) FROM `Documents`)","question":"What are the Document_Name with all the Other_Details in table Documents?","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Document_Name` along with `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Name, Other_Details FROM Documents;\n```\n\nThis query will return all rows from the `Documents` table, displaying the `Document_Name` and `Other_Details` columns.","cost":0.0006021,"response_parsed":"SELECT Document_Name, Other_Details FROM Documents;","time":4.2719032764}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Document_Description` FROM `Documents` GROUP BY `Document_Description` HAVING COUNT(DISTINCT `Other_Details`) = (SELECT COUNT(DISTINCT `Other_Details`) FROM `Documents`)","question":"What are the Document_Description with all the Other_Details in table Documents?","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Document_Description` along with `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Description, Other_Details \nFROM Documents;\n```\n\nThis query will return all rows from the `Documents` table, displaying the `Document_Description` and `Other_Details` columns.","cost":0.0005598,"response_parsed":"SELECT Document_Description, Other_Details \nFROM Documents;","time":4.5729963779}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Template_Type_Code` FROM `Templates` GROUP BY `Template_Type_Code` HAVING COUNT(DISTINCT `Template_Details`) = (SELECT COUNT(DISTINCT `Template_Details`) FROM `Templates`)","question":"What are the Template_Type_Code with all the Template_Details in table Templates?","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Type_Code` along with all the `Template_Details` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code, Template_Details \nFROM Templates;\n```\n\nThis query will return all rows from your `Templates` table, showing the `Template_Type_Code` and the corresponding `Template_Details` for each entry.","cost":0.0006129,"response_parsed":"SELECT Template_Type_Code, Template_Details \nFROM Templates;","time":4.7138702869}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"many-to-many-generator","sql_tag":"many-to-many","query":"SELECT `Paragraph_Text` FROM `Paragraphs` GROUP BY `Paragraph_Text` HAVING COUNT(DISTINCT `Other_Details`) = (SELECT COUNT(DISTINCT `Other_Details`) FROM `Paragraphs`)","question":"What are the Paragraph_Text with all the Other_Details in table Paragraphs?","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo retrieve the `Paragraph_Text` along with `Other_Details` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text, Other_Details FROM Paragraphs;\n```\n\nThis query will return all rows from your `Paragraphs` table, displaying the `Paragraph_Text` and `Other_Details` columns.","cost":0.0004896,"response_parsed":"SELECT Paragraph_Text, Other_Details FROM Paragraphs;","time":4.1603951454}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Documents` ORDER BY `Template_ID` ASC","question":"Show all data ordered by Template_ID in ascending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Documents` table ordered by `Template_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nORDER BY Template_ID ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Documents` table\n2. Order the results by the `Template_ID` column in ascending order (from smallest to largest value)","cost":0.0004878,"response_parsed":"SELECT *\nFROM Documents\nORDER BY Template_ID ASC;","time":3.3455393314}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Documents` ORDER BY `Template_ID` DESC","question":"Show all data ordered by Template_ID in descending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Documents` table ordered by `Template_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nORDER BY Template_ID DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Documents` table\n2. Order the results by the `Template_ID` column in descending order (highest values first)","cost":0.0006237,"response_parsed":"SELECT *\nFROM Documents\nORDER BY Template_ID DESC;","time":5.1371865273}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Documents` ORDER BY `Document_Description` ASC","question":"Show all data ordered by Document_Description in ascending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Documents` table ordered by `Document_Description` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nORDER BY Document_Description ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Documents` table.\n2. Order the results by the `Document_Description` column in ascending order (from A to Z).","cost":0.0005526,"response_parsed":"SELECT *\nFROM Documents\nORDER BY Document_Description ASC;","time":4.2160496712}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Documents` ORDER BY `Document_Description` DESC","question":"Show all data ordered by Document_Description in descending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Documents` table ordered by `Document_Description` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nORDER BY Document_Description DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Documents` table.\n2. Order the results by the `Document_Description` column in descending order (from Z to A).","cost":0.0005139,"response_parsed":"SELECT *\nFROM Documents\nORDER BY Document_Description DESC;","time":3.0884327888}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Document_Description` FROM `Documents` ORDER BY `Document_Description` ASC","question":"Project the Document_Description ordered in ascending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Document_Description` from the `Documents` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Document_Description \nFROM Documents \nORDER BY Document_Description ASC;\n```\n\nThis query will:\n1. Select the `Document_Description` column from the `Documents` table.\n2. Order the results in ascending order based on the `Document_Description`.","cost":0.0005409,"response_parsed":"SELECT Document_Description \nFROM Documents \nORDER BY Document_Description ASC;","time":3.8148548603}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Document_Description` FROM `Documents` ORDER BY `Document_Description` DESC","question":"Project the Document_Description ordered in descending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Document_Description` from the `Documents` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Document_Description \nFROM Documents \nORDER BY Document_Description DESC;\n```","cost":0.0004968,"response_parsed":"SELECT Document_Description \nFROM Documents \nORDER BY Document_Description DESC;","time":3.3988406658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_ID` FROM `Documents` ORDER BY `Template_ID` ASC","question":"Project the Template_ID ordered in ascending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Template_ID` from the `Documents` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Template_ID\nFROM Documents\nORDER BY Template_ID ASC;\n```\n\nThis query will:\n1. Select the `Template_ID` column from the `Documents` table.\n2. Order the results in ascending order based on `Template_ID`.\n\nIf you want to avoid duplicate `Template_ID` values in the result, you can add the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Template_ID\nFROM Documents\nORDER BY Template_ID ASC;\n```","cost":0.0005733,"response_parsed":"SELECT DISTINCT Template_ID\nFROM Documents\nORDER BY Template_ID ASC;","time":4.2379367352}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_ID` FROM `Documents` ORDER BY `Template_ID` DESC","question":"Project the Template_ID ordered in descending order for the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Template_ID` from the `Documents` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Template_ID\nFROM Documents\nORDER BY Template_ID DESC;\n```","cost":0.0004437,"response_parsed":"SELECT Template_ID\nFROM Documents\nORDER BY Template_ID DESC;","time":2.6011710167}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Templates` ORDER BY `Version_Number` ASC","question":"Show all data ordered by Version_Number in ascending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Templates` table ordered by `Version_Number` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nORDER BY Version_Number ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Templates` table.\n2. Order the results by the `Version_Number` column in ascending order (from the smallest to the largest version number).","cost":0.0005004,"response_parsed":"SELECT *\nFROM Templates\nORDER BY Version_Number ASC;","time":3.3614287376}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Templates` ORDER BY `Version_Number` DESC","question":"Show all data ordered by Version_Number in descending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Templates` table ordered by `Version_Number` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nORDER BY Version_Number DESC;\n```\n\nThis query will return all records from the `Templates` table, sorted by the `Version_Number` column in descending order (from highest to lowest).","cost":0.0004806,"response_parsed":"SELECT *\nFROM Templates\nORDER BY Version_Number DESC;","time":2.8761284351}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Templates` ORDER BY `Template_Type_Code` ASC","question":"Show all data ordered by Template_Type_Code in ascending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Templates` table ordered by `Template_Type_Code` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nORDER BY Template_Type_Code ASC;\n```","cost":0.0005391,"response_parsed":"SELECT *\nFROM Templates\nORDER BY Template_Type_Code ASC;","time":3.7216460705}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Templates` ORDER BY `Template_Type_Code` DESC","question":"Show all data ordered by Template_Type_Code in descending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Templates` table ordered by `Template_Type_Code` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM Templates ORDER BY Template_Type_Code DESC;\n```","cost":0.0005634,"response_parsed":"SELECT * FROM Templates ORDER BY Template_Type_Code DESC;","time":3.948854208}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Code` FROM `Templates` ORDER BY `Template_Type_Code` ASC","question":"Project the Template_Type_Code ordered in ascending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Type_Code` from the `Templates` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code \nFROM Templates \nORDER BY Template_Type_Code ASC;\n```","cost":0.00054,"response_parsed":"SELECT Template_Type_Code \nFROM Templates \nORDER BY Template_Type_Code ASC;","time":3.7156176567}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Code` FROM `Templates` ORDER BY `Template_Type_Code` DESC","question":"Project the Template_Type_Code ordered in descending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Type_Code` from the `Templates` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code \nFROM Templates \nORDER BY Template_Type_Code DESC;\n```","cost":0.0005229,"response_parsed":"SELECT Template_Type_Code \nFROM Templates \nORDER BY Template_Type_Code DESC;","time":3.7560663223}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Version_Number` FROM `Templates` ORDER BY `Version_Number` ASC","question":"Project the Version_Number ordered in ascending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Version_Number` from the `Templates` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Version_Number \nFROM Templates \nORDER BY Version_Number ASC;\n```","cost":0.0004995,"response_parsed":"SELECT Version_Number \nFROM Templates \nORDER BY Version_Number ASC;","time":3.4012813568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Version_Number` FROM `Templates` ORDER BY `Version_Number` DESC","question":"Project the Version_Number ordered in descending order for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Version_Number` from the `Templates` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Version_Number \nFROM Templates \nORDER BY Version_Number DESC;\n```\n\nThis query will return the `Version_Number` values from your `Templates` table, sorted from the highest to the lowest version number.","cost":0.0005355,"response_parsed":"SELECT Version_Number \nFROM Templates \nORDER BY Version_Number DESC;","time":3.7266213894}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Ref_Template_Types` ORDER BY `Template_Type_Code` ASC","question":"Show all data ordered by Template_Type_Code in ascending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Ref_Template_Types` table ordered by `Template_Type_Code` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Code ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Ref_Template_Types` table.\n2. Order the results by the `Template_Type_Code` column in ascending order.","cost":0.0005652,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Code ASC;","time":4.0481610298}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Ref_Template_Types` ORDER BY `Template_Type_Code` DESC","question":"Show all data ordered by Template_Type_Code in descending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Ref_Template_Types` table ordered by `Template_Type_Code` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Code DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Ref_Template_Types` table.\n2. Order the results by the `Template_Type_Code` column in descending order (`DESC`).","cost":0.0005256,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Code DESC;","time":3.1509103775}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Ref_Template_Types` ORDER BY `Template_Type_Description` ASC","question":"Show all data ordered by Template_Type_Description in ascending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Ref_Template_Types` table ordered by `Template_Type_Description` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Description ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Ref_Template_Types` table.\n2. Order the results by the `Template_Type_Description` column in ascending order (`ASC`).","cost":0.000558,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Description ASC;","time":4.2254285812}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Ref_Template_Types` ORDER BY `Template_Type_Description` DESC","question":"Show all data ordered by Template_Type_Description in descending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Ref_Template_Types` table ordered by `Template_Type_Description` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Description DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Ref_Template_Types` table.\n2. Order the results by the `Template_Type_Description` column in descending order (from Z to A).","cost":0.0005445,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nORDER BY Template_Type_Description DESC;","time":3.5576319695}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Code` FROM `Ref_Template_Types` ORDER BY `Template_Type_Code` ASC","question":"Project the Template_Type_Code ordered in ascending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_Type_Code` from the `Ref_Template_Types` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code \nFROM Ref_Template_Types \nORDER BY Template_Type_Code ASC;\n```","cost":0.0005202,"response_parsed":"SELECT Template_Type_Code \nFROM Ref_Template_Types \nORDER BY Template_Type_Code ASC;","time":3.7964158058}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Code` FROM `Ref_Template_Types` ORDER BY `Template_Type_Code` DESC","question":"Project the Template_Type_Code ordered in descending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Template_Type_Code` from the `Ref_Template_Types` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code \nFROM Ref_Template_Types \nORDER BY Template_Type_Code DESC;\n```","cost":0.0004248,"response_parsed":"SELECT Template_Type_Code \nFROM Ref_Template_Types \nORDER BY Template_Type_Code DESC;","time":2.4289414883}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types` ORDER BY `Template_Type_Description` ASC","question":"Project the Template_Type_Description ordered in ascending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Template_Type_Description` from the `Ref_Template_Types` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Description\nFROM Ref_Template_Types\nORDER BY Template_Type_Description ASC;\n```\n\nThis query will:\n1. Select the `Template_Type_Description` column from the `Ref_Template_Types` table.\n2. Order the results in ascending alphabetical order based on the `Template_Type_Description`.\n\nThe result will be a list of unique template type descriptions sorted from A to Z.","cost":0.0005274,"response_parsed":"SELECT Template_Type_Description\nFROM Ref_Template_Types\nORDER BY Template_Type_Description ASC;","time":3.8706946373}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types` ORDER BY `Template_Type_Description` DESC","question":"Project the Template_Type_Description ordered in descending order for the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Template_Type_Description` from the `Ref_Template_Types` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT `Template_Type_Description`\nFROM `Ref_Template_Types`\nORDER BY `Template_Type_Description` DESC;\n```\n\nThis query will:\n1. Select the `Template_Type_Description` column from the `Ref_Template_Types` table.\n2. Order the results in descending order based on the `Template_Type_Description` values.","cost":0.0005283,"response_parsed":"SELECT `Template_Type_Description`\nFROM `Ref_Template_Types`\nORDER BY `Template_Type_Description` DESC;","time":3.4298508167}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Paragraphs` ORDER BY `Paragraph_Text` ASC","question":"Show all data ordered by Paragraph_Text in ascending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Paragraphs` table ordered by `Paragraph_Text` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nORDER BY Paragraph_Text ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Paragraphs` table.\n2. Order the results by the `Paragraph_Text` column in ascending order.","cost":0.0004995,"response_parsed":"SELECT *\nFROM Paragraphs\nORDER BY Paragraph_Text ASC;","time":3.2111382484}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Paragraphs` ORDER BY `Paragraph_Text` DESC","question":"Show all data ordered by Paragraph_Text in descending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Paragraphs` table ordered by `Paragraph_Text` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nORDER BY Paragraph_Text DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `Paragraphs` table.\n2. Order the results by the `Paragraph_Text` column in descending order (`DESC`).","cost":0.0005409,"response_parsed":"SELECT *\nFROM Paragraphs\nORDER BY Paragraph_Text DESC;","time":3.5898663998}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Paragraphs` ORDER BY `Other_Details` ASC","question":"Show all data ordered by Other_Details in ascending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Paragraphs` table ordered by the `Other_Details` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nORDER BY Other_Details ASC;\n```","cost":0.0004554,"response_parsed":"SELECT *\nFROM Paragraphs\nORDER BY Other_Details ASC;","time":2.8387150764}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `Paragraphs` ORDER BY `Other_Details` DESC","question":"Show all data ordered by Other_Details in descending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all data from the `Paragraphs` table ordered by the `Other_Details` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nORDER BY Other_Details DESC;\n```","cost":0.000594,"response_parsed":"SELECT *\nFROM Paragraphs\nORDER BY Other_Details DESC;","time":4.4521658421}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Paragraph_Text` FROM `Paragraphs` ORDER BY `Paragraph_Text` ASC","question":"Project the Paragraph_Text ordered in ascending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Paragraph_Text` from the `Paragraphs` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text\nFROM Paragraphs\nORDER BY Paragraph_Text ASC;\n```\n\nThis query selects the `Paragraph_Text` column from the `Paragraphs` table and sorts the results in ascending order based on the `Paragraph_Text`.","cost":0.0005796,"response_parsed":"SELECT Paragraph_Text\nFROM Paragraphs\nORDER BY Paragraph_Text ASC;","time":3.9924244881}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Paragraph_Text` FROM `Paragraphs` ORDER BY `Paragraph_Text` DESC","question":"Project the Paragraph_Text ordered in descending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Paragraph_Text` from the `Paragraphs` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text FROM Paragraphs ORDER BY Paragraph_Text DESC;\n```","cost":0.0004419,"response_parsed":"SELECT Paragraph_Text FROM Paragraphs ORDER BY Paragraph_Text DESC;","time":2.7519629002}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Other_Details` FROM `Paragraphs` ORDER BY `Other_Details` ASC","question":"Project the Other_Details ordered in ascending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Other_Details` from the `Paragraphs` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Other_Details\nFROM Paragraphs\nORDER BY Other_Details ASC;\n```","cost":0.0005049,"response_parsed":"SELECT Other_Details\nFROM Paragraphs\nORDER BY Other_Details ASC;","time":3.1445057392}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Other_Details` FROM `Paragraphs` ORDER BY `Other_Details` DESC","question":"Project the Other_Details ordered in descending order for the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo project the `Other_Details` column from the `Paragraphs` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Other_Details\nFROM Paragraphs\nORDER BY Other_Details DESC;\n```\n\nThis query will:\n1. Select the `Other_Details` column from the `Paragraphs` table.\n2. Order the results in descending order based on the values in the `Other_Details` column.","cost":0.0005229,"response_parsed":"SELECT Other_Details\nFROM Paragraphs\nORDER BY Other_Details DESC;","time":3.1494407654}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Document_ID` FROM `Documents`","question":"Show all Document_ID in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Document_ID`s from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_ID FROM Documents;\n```\n\nThis query will return a list of all `Document_ID`s present in your `Documents` table.","cost":0.0005589,"response_parsed":"SELECT Document_ID FROM Documents;","time":4.1582686901}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_ID` FROM `Documents`","question":"Show all Template_ID in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_ID`s from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Template_ID FROM Documents;\n```\n\nThis query will return all the `Template_ID` values present in your `Documents` table.","cost":0.0005571,"response_parsed":"SELECT Template_ID FROM Documents;","time":3.8909623623}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Document_Name` FROM `Documents`","question":"Show all Document_Name in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Document_Name` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Name \nFROM Documents\nWHERE Document_Name IS NOT NULL;\n```\n\nThis query will return all non-null `Document_Name` entries from the `Documents` table.","cost":0.0004725,"response_parsed":"SELECT Document_Name \nFROM Documents\nWHERE Document_Name IS NOT NULL;","time":2.9968473911}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Document_Description` FROM `Documents`","question":"Show all Document_Description in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Document_Description` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Description FROM Documents;\n```\n\nThis query will return all the entries in the `Document_Description` column of your `Documents` table.","cost":0.0005184,"response_parsed":"SELECT Document_Description FROM Documents;","time":3.8801095486}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Other_Details` FROM `Documents`","question":"Show all Other_Details in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Other_Details FROM Documents;\n```\n\nThis query will return all the values in the `Other_Details` column of the `Documents` table.","cost":0.0005058,"response_parsed":"SELECT Other_Details FROM Documents;","time":3.5418674946}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Documents`","question":"Show all the rows in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all rows from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Documents;\n```\n\nThis query will return all columns for every row in your `Documents` table.","cost":0.0004797,"response_parsed":"SELECT * FROM Documents;","time":3.0738322735}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Other_Details` FROM `Documents`","question":"Show all Other_Details in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Other_Details FROM Documents;\n```\n\nThis query will return all the values in the `Other_Details` column of the `Documents` table.","cost":0.0005886,"response_parsed":"SELECT Other_Details FROM Documents;","time":4.6389920712}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Document_Description`, `Other_Details` FROM `Documents`","question":"Show all Document_Description, Other_Details in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Document_Description` and `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_Description, Other_Details FROM Documents;\n```\n\nThis query will return all rows from the `Documents` table, displaying only the `Document_Description` and `Other_Details` columns.","cost":0.0005526,"response_parsed":"SELECT Document_Description, Other_Details FROM Documents;","time":3.6952548027}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Document_ID`, `Document_Name`, `Other_Details` FROM `Documents`","question":"Show all Document_ID, Document_Name, Other_Details in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Document_ID`, `Document_Name`, and `Other_Details` from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Document_ID, Document_Name, Other_Details FROM Documents;\n```\n\nThis query will return all rows from the `Documents` table with the specified columns.","cost":0.0005634,"response_parsed":"SELECT Document_ID, Document_Name, Other_Details FROM Documents;","time":3.6347851753}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Template_ID`, `Document_Name`, `Document_Description`, `Document_ID` FROM `Documents`","question":"Show all Template_ID, Document_Name, Document_Description, Document_ID in the table Documents","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the required information from the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT Template_ID, Document_Name, Document_Description, Document_ID\nFROM Documents;\n```\n\nThis query will return all the rows from your `Documents` table with the specified columns: `Template_ID`, `Document_Name`, `Document_Description`, and `Document_ID`.","cost":0.0004815,"response_parsed":"SELECT Template_ID, Document_Name, Document_Description, Document_ID\nFROM Documents;","time":2.8217306137}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_ID` FROM `Templates`","question":"Show all Template_ID in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_ID` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_ID FROM Templates;\n```\n\nThis query will return all the unique `Template_ID` values present in your `Templates` table.","cost":0.0004806,"response_parsed":"SELECT Template_ID FROM Templates;","time":3.2583346367}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Version_Number` FROM `Templates`","question":"Show all Version_Number in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Version_Number` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Version_Number FROM Templates;\n```\n\nThis query will return all the `Version_Number` values present in your `Templates` table.","cost":0.000504,"response_parsed":"SELECT Version_Number FROM Templates;","time":3.3957443237}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_Type_Code` FROM `Templates`","question":"Show all Template_Type_Code in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Type_Code` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Template_Type_Code FROM Templates;\n```\n\nThis query will return all unique `Template_Type_Code` values present in the `Templates` table.","cost":0.0004995,"response_parsed":"SELECT DISTINCT Template_Type_Code FROM Templates;","time":3.415555954}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_Details` FROM `Templates`","question":"Show all Template_Details in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Details` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Details FROM Templates;\n```","cost":0.0004698,"response_parsed":"SELECT Template_Details FROM Templates;","time":3.0803263187}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Templates`","question":"Show all the rows in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo show all the rows in the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Templates;\n```\n\nThis query will retrieve all rows and all columns from the `Templates` table.","cost":0.0004977,"response_parsed":"SELECT * FROM Templates;","time":3.7708108425}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Template_Type_Code` FROM `Templates`","question":"Show all Template_Type_Code in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Type_Code` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Template_Type_Code FROM Templates;\n```\n\nThis query will return all unique `Template_Type_Code` values present in the `Templates` table.","cost":0.0004995,"response_parsed":"SELECT DISTINCT Template_Type_Code FROM Templates;","time":3.5789477825}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Version_Number`, `Template_ID` FROM `Templates`","question":"Show all Version_Number, Template_ID in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Version_Number` and `Template_ID` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Version_Number, Template_ID FROM Templates;\n```","cost":0.0004365,"response_parsed":"SELECT Version_Number, Template_ID FROM Templates;","time":3.0474250317}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Template_ID`, `Template_Type_Code`, `Template_Details` FROM `Templates`","question":"Show all Template_ID, Template_Type_Code, Template_Details in the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Template_ID`, `Template_Type_Code`, and `Template_Details` from the `Templates` table, you can use the following SQL query:\n\n```sql\nSELECT Template_ID, Template_Type_Code, Template_Details\nFROM Templates;\n```\n\nThis query will return all rows from the `Templates` table with the specified columns.","cost":0.0005283,"response_parsed":"SELECT Template_ID, Template_Type_Code, Template_Details\nFROM Templates;","time":3.7678923607}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_Type_Code` FROM `Ref_Template_Types`","question":"Show all Template_Type_Code in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Type_Code` from the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Code FROM Ref_Template_Types;\n```\n\nThis query will return all the unique `Template_Type_Code` values stored in the `Ref_Template_Types` table.","cost":0.000495,"response_parsed":"SELECT Template_Type_Code FROM Ref_Template_Types;","time":3.5248606205}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types`","question":"Show all Template_Type_Description in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Type_Description` from the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Description FROM Ref_Template_Types;\n```","cost":0.0004716,"response_parsed":"SELECT Template_Type_Description FROM Ref_Template_Types;","time":3.0576424599}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Ref_Template_Types`","question":"Show all the rows in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo show all the rows in the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Ref_Template_Types;\n```\n\nThis query will return all columns (`Template_Type_Code` and `Template_Type_Description`) for every row in the `Ref_Template_Types` table.","cost":0.0005121,"response_parsed":"SELECT * FROM Ref_Template_Types;","time":3.2342984676}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Template_Type_Description` FROM `Ref_Template_Types`","question":"Show all Template_Type_Description in the table Ref_Template_Types","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Template_Type_Description` from the `Ref_Template_Types` table, you can use the following SQL query:\n\n```sql\nSELECT Template_Type_Description FROM Ref_Template_Types;\n```","cost":0.0004716,"response_parsed":"SELECT Template_Type_Description FROM Ref_Template_Types;","time":3.0645952225}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Paragraph_ID` FROM `Paragraphs`","question":"Show all Paragraph_ID in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Paragraph_ID` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_ID FROM Paragraphs;\n```\n\nThis query will return all the `Paragraph_ID` values present in your `Paragraphs` table.","cost":0.0005832,"response_parsed":"SELECT Paragraph_ID FROM Paragraphs;","time":3.9862885475}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Document_ID` FROM `Paragraphs`","question":"Show all Document_ID in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Document_ID`s from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Document_ID FROM Paragraphs;\n```\n\nThis query will return all the `Document_ID`s present in your `Paragraphs` table.","cost":0.0005256,"response_parsed":"SELECT Document_ID FROM Paragraphs;","time":3.6705424786}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Paragraph_Text` FROM `Paragraphs`","question":"Show all Paragraph_Text in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Paragraph_Text` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text FROM Paragraphs;\n```\n\nThis query will return all the records in the `Paragraph_Text` column of your `Paragraphs` table.","cost":0.000513,"response_parsed":"SELECT Paragraph_Text FROM Paragraphs;","time":3.2661762238}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Other_Details` FROM `Paragraphs`","question":"Show all Other_Details in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Other_Details` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Other_Details FROM Paragraphs;\n```","cost":0.0004779,"response_parsed":"SELECT Other_Details FROM Paragraphs;","time":3.0865607262}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `Paragraphs`","question":"Show all the rows in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all rows from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM Paragraphs;\n```\n\nThis query will return all columns (`*`) for every row in the `Paragraphs` table.","cost":0.000504,"response_parsed":"SELECT * FROM Paragraphs;","time":3.4114561081}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Paragraph_Text` FROM `Paragraphs`","question":"Show all Paragraph_Text in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Paragraph_Text` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_Text FROM Paragraphs;\n```\n\nThis query will return all the records in the `Paragraph_Text` column of your `Paragraphs` table.","cost":0.000513,"response_parsed":"SELECT Paragraph_Text FROM Paragraphs;","time":3.2929496765}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Paragraph_ID`, `Document_ID` FROM `Paragraphs`","question":"Show all Paragraph_ID, Document_ID in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch all `Paragraph_ID` and `Document_ID` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Paragraph_ID, Document_ID FROM Paragraphs;\n```\n\nThis query will return all rows from the `Paragraphs` table, displaying only the `Paragraph_ID` and `Document_ID` columns.","cost":0.0005364,"response_parsed":"SELECT Paragraph_ID, Document_ID FROM Paragraphs;","time":3.9335668087}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Other_Details`, `Paragraph_Text`, `Document_ID` FROM `Paragraphs`","question":"Show all Other_Details, Paragraph_Text, Document_ID in the table Paragraphs","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the `Other_Details`, `Paragraph_Text`, and `Document_ID` from the `Paragraphs` table, you can use the following SQL query:\n\n```sql\nSELECT Other_Details, Paragraph_Text, Document_ID\nFROM Paragraphs;\n```\n\nThis query will return all rows from the `Paragraphs` table with the specified columns.","cost":0.0004986,"response_parsed":"SELECT Other_Details, Paragraph_Text, Document_ID\nFROM Paragraphs;","time":3.2598176003}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Name` == 'Introduction of OS'","question":"Show the data of the table Documents where Document_Name is equal to Introduction of OS","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Name` is equal to \"Introduction of OS,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Name = 'Introduction of OS';\n```","cost":0.0005166,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Name = 'Introduction of OS';","time":3.698987484}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Name` != 'Welcome to NY'","question":"Show the data of the table Documents where Document_Name is different from Welcome to NY","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Name` is different from \"Welcome to NY,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Name != 'Welcome to NY';\n```\n\nThis query will return all rows from the `Documents` table where the `Document_Name` column does not contain the value \"Welcome to NY.\"","cost":0.0005301,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Name != 'Welcome to NY';","time":3.9816167355}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Name` != 'Understanding DB'","question":"Show the data of the table Documents where Document_Name not equal to Understanding DB","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Name` is not equal to \"Understanding DB,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Name != 'Understanding DB';\n```","cost":0.0005616,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Name != 'Understanding DB';","time":4.3807837963}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Description` == 'w'","question":"Show the data of the table Documents where Document_Description is equal to w","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Description` is equal to 'w', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Description = 'w';\n```","cost":0.0004554,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Description = 'w';","time":2.7559523582}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Description` != 'n'","question":"Show the data of the table Documents where Document_Description is different from n","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Description` is different from 'n', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Description != 'n';\n```\n\nThis query will return all rows from the `Documents` table where the `Document_Description` column does not contain the value 'n'.","cost":0.0006282,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Description != 'n';","time":4.8446428776}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Documents` WHERE `Document_Description` != 'h'","question":"Show the data of the table Documents where Document_Description not equal to h","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Documents` table where `Document_Description` is not equal to 'h', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Documents\nWHERE Document_Description != 'h';\n```","cost":0.0005868,"response_parsed":"SELECT *\nFROM Documents\nWHERE Document_Description != 'h';","time":4.091057539}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Templates` WHERE `Template_Type_Code` == 'BK'","question":"Show the data of the table Templates where Template_Type_Code is equal to BK","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where `Template_Type_Code` is equal to 'BK', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nWHERE Template_Type_Code = 'BK';\n```","cost":0.0004923,"response_parsed":"SELECT *\nFROM Templates\nWHERE Template_Type_Code = 'BK';","time":2.8913080692}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Templates` WHERE `Template_Type_Code` != 'PPT'","question":"Show the data of the table Templates where Template_Type_Code is different from PPT","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where `Template_Type_Code` is different from 'PPT', you can use the following SQL query:\n\n```sql\nSELECT * FROM Templates WHERE Template_Type_Code != 'PPT';\n```","cost":0.0007065,"response_parsed":"SELECT * FROM Templates WHERE Template_Type_Code != 'PPT';","time":5.6073806286}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Templates` WHERE `Template_Type_Code` != 'PP'","question":"Show the data of the table Templates where Template_Type_Code not equal to PP","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where `Template_Type_Code` is not equal to 'PP', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nWHERE Template_Type_Code <> 'PP';\n```\n\nThis query will return all rows from the `Templates` table where the `Template_Type_Code` is not 'PP'.","cost":0.0006831,"response_parsed":"SELECT *\nFROM Templates\nWHERE Template_Type_Code <> 'PP';","time":5.2368817329}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Templates` WHERE `Template_Details` == ''","question":"Show the data of the table Templates where Template_Details is equal to ","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where `Template_Details` is equal to a specific value, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nWHERE Template_Details = 'specific value';\n```\n\nReplace `'specific value'` with the actual value you want to filter by.","cost":0.0005265,"response_parsed":"SELECT *\nFROM Templates\nWHERE Template_Details = 'specific value';","time":3.6459515095}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Templates` WHERE `Version_Number` > 2","question":"Show the data of the table Templates where Version_Number is greater than 2","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where the `Version_Number` is greater than 2, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nWHERE Version_Number > 2;\n```","cost":0.0004599,"response_parsed":"SELECT *\nFROM Templates\nWHERE Version_Number > 2;","time":2.6394786835}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `Templates` WHERE `Version_Number` < 4","question":"Show the data of the table Templates where Version_Number is less than 4","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Templates` table where the `Version_Number` is less than 4, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Templates\nWHERE Version_Number < 4;\n```\n\nThis query will return all rows in the `Templates` table where the `Version_Number` is less than 4.","cost":0.0005904,"response_parsed":"SELECT *\nFROM Templates\nWHERE Version_Number < 4;","time":4.4039371014}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Code` == 'BK'","question":"Show the data of the table Ref_Template_Types where Template_Type_Code is equal to BK","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Code` is equal to 'BK', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code = 'BK';\n```","cost":0.0005787,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code = 'BK';","time":3.9770209789}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Code` != 'PPT'","question":"Show the data of the table Ref_Template_Types where Template_Type_Code is different from PPT","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Code` is different from 'PPT', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code != 'PPT';\n```","cost":0.0005625,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code != 'PPT';","time":3.7227890491}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Code` != 'PPT'","question":"Show the data of the table Ref_Template_Types where Template_Type_Code not equal to PPT","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Code` is not equal to 'PPT', you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code != 'PPT';\n```","cost":0.0005832,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Code != 'PPT';","time":4.6376760006}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Description` == 'Advertisement'","question":"Show the data of the table Ref_Template_Types where Template_Type_Description is equal to Advertisement","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Description` is equal to \"Advertisement,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Description = 'Advertisement';\n```","cost":0.0005499,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Description = 'Advertisement';","time":3.9507000446}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Description` != 'Presentation'","question":"Show the data of the table Ref_Template_Types where Template_Type_Description is different from Presentation","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Description` is different from \"Presentation,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM Ref_Template_Types WHERE Template_Type_Description != 'Presentation';\n```","cost":0.0005922,"response_parsed":"SELECT * FROM Ref_Template_Types WHERE Template_Type_Description != 'Presentation';","time":4.1569130421}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Ref_Template_Types` WHERE `Template_Type_Description` != 'Advertisement'","question":"Show the data of the table Ref_Template_Types where Template_Type_Description not equal to Advertisement","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Ref_Template_Types` table where `Template_Type_Description` is not equal to \"Advertisement\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Description <> 'Advertisement';\n```\n\nThis query will return all rows from the `Ref_Template_Types` table where the `Template_Type_Description` column does not contain the value \"Advertisement\".","cost":0.000639,"response_parsed":"SELECT *\nFROM Ref_Template_Types\nWHERE Template_Type_Description <> 'Advertisement';","time":4.7917811871}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Paragraphs` WHERE `Paragraph_Text` == 'Jersey'","question":"Show the data of the table Paragraphs where Paragraph_Text is equal to Jersey","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Paragraphs` table where `Paragraph_Text` is equal to \"Jersey,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nWHERE Paragraph_Text = 'Jersey';\n```","cost":0.0005958,"response_parsed":"SELECT *\nFROM Paragraphs\nWHERE Paragraph_Text = 'Jersey';","time":4.3296968937}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Paragraphs` WHERE `Paragraph_Text` != 'Korea'","question":"Show the data of the table Paragraphs where Paragraph_Text is different from Korea","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Paragraphs` table where `Paragraph_Text` is different from \"Korea,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nWHERE Paragraph_Text != 'Korea';\n```","cost":0.0005544,"response_parsed":"SELECT *\nFROM Paragraphs\nWHERE Paragraph_Text != 'Korea';","time":3.8259577751}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `Paragraphs` WHERE `Paragraph_Text` != 'Palestinian Territory'","question":"Show the data of the table Paragraphs where Paragraph_Text not equal to Palestinian Territory","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo fetch the data from the `Paragraphs` table where `Paragraph_Text` is not equal to \"Palestinian Territory,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM Paragraphs\nWHERE Paragraph_Text != 'Palestinian Territory';\n```","cost":0.0005418,"response_parsed":"SELECT *\nFROM Paragraphs\nWHERE Paragraph_Text != 'Palestinian Territory';","time":3.5797288418}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Document_Name`) FROM `Documents`","question":"How many different Document_Name are in table Documents?","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Document_Name` entries exist in the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT COUNT(DISTINCT Document_Name) FROM Documents;\n```\n\nThis query will return the number of unique `Document_Name` values in your `Documents` table.","cost":0.0006021,"response_parsed":"SELECT COUNT(DISTINCT Document_Name) FROM Documents;","time":4.4594688416}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Document_Description`) FROM `Documents`","question":"How many different Document_Description are in table Documents?","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Document_Description` entries exist in the `Documents` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Document_Description) AS Number_of_Different_Descriptions\nFROM Documents;\n```\n\nThis query will return the number of unique `Document_Description` values in your `Documents` table.","cost":0.0005211,"response_parsed":"SELECT COUNT(DISTINCT Document_Description) AS Number_of_Different_Descriptions\nFROM Documents;","time":3.8164310455}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Documents","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Other_Details`) FROM `Documents`","question":"How many different Other_Details are in table Documents?","db_schema_normalized":"`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Other_Details` are in the `Documents` table, you can use the following SQL query:\n\n```sql\nSELECT COUNT(DISTINCT Other_Details) \nFROM Documents;\n```\n\nThis query will return the number of unique values in the `Other_Details` column of the `Documents` table.","cost":0.0005634,"response_parsed":"SELECT COUNT(DISTINCT Other_Details) \nFROM Documents;","time":4.3562757969}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Template_Type_Code`) FROM `Templates`","question":"How many different Template_Type_Code are in table Templates?","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Template_Type_Code` values exist in the `Templates` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL query to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Template_Type_Code) AS Number_of_Template_Types\nFROM Templates;\n```\n\nThis query will return the number of unique `Template_Type_Code` values present in your `Templates` table.","cost":0.0005472,"response_parsed":"SELECT COUNT(DISTINCT Template_Type_Code) AS Number_of_Template_Types\nFROM Templates;","time":3.9382348061}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Template_Details`) FROM `Templates`","question":"How many different Template_Details are in table Templates?","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Template_Details` are in the `Templates` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT Template_Details) AS NumberOfTemplateDetails \nFROM Templates;\n```\n\nThis query will return the number of unique `Template_Details` values in your `Templates` table.","cost":0.0005427,"response_parsed":"SELECT COUNT(DISTINCT Template_Details) AS NumberOfTemplateDetails \nFROM Templates;","time":3.8342158794}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Version_Number`) FROM `Templates`","question":"Find the maximum Version_Number for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the maximum `Version_Number` for the table `Templates`, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(Version_Number) FROM Templates;\n```","cost":0.0004698,"response_parsed":"SELECT MAX(Version_Number) FROM Templates;","time":3.0961213112}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Version_Number`) FROM `Templates`","question":"Find the minimum Version_Number for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the minimum `Version_Number` in the `Templates` table, you can use the SQL `MIN()` function. Here's how you can do it:\n\n```sql\nSELECT MIN(Version_Number) AS Minimum_Version\nFROM Templates;\n```\n\nThis query will return the smallest `Version_Number` value from your `Templates` table.","cost":0.000459,"response_parsed":"SELECT MIN(Version_Number) AS Minimum_Version\nFROM Templates;","time":2.7050454617}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Templates","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Version_Number`) FROM `Templates`","question":"Find the average Version_Number for the table Templates","db_schema_normalized":"`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo find the average `Version_Number` for the table `Templates`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(Version_Number) AS Average_Version_Number\nFROM Templates;\n```\n\nThis query will calculate and return the average value of the `Version_Number` column in your `Templates` table.","cost":0.0005256,"response_parsed":"SELECT AVG(Version_Number) AS Average_Version_Number\nFROM Templates;","time":3.4132275581}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Template_Type_Code`) FROM `Ref_Template_Types`","question":"How many different Template_Type_Code are in table Ref_Template_Types?","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Template_Type_Code` values exist in the `Ref_Template_Types` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Template_Type_Code) AS Number_of_Template_Types\nFROM Ref_Template_Types;\n```\n\nThis query will return the number of unique `Template_Type_Code` values in the `Ref_Template_Types` table.","cost":0.0005571,"response_parsed":"SELECT COUNT(DISTINCT Template_Type_Code) AS Number_of_Template_Types\nFROM Ref_Template_Types;","time":3.6400177479}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Ref_Template_Types","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Template_Type_Description`) FROM `Ref_Template_Types`","question":"How many different Template_Type_Description are in table Ref_Template_Types?","db_schema_normalized":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Template_Type_Description` entries exist in the `Ref_Template_Types` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Template_Type_Description) AS NumberOfDescriptions \nFROM Ref_Template_Types;\n```\n\nThis query will return the number of unique `Template_Type_Description` values in your `Ref_Template_Types` table.","cost":0.0006246,"response_parsed":"SELECT COUNT(DISTINCT Template_Type_Description) AS NumberOfDescriptions \nFROM Ref_Template_Types;","time":4.5929703712}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Paragraph_Text`) FROM `Paragraphs`","question":"How many different Paragraph_Text are in table Paragraphs?","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Paragraph_Text` entries are in the `Paragraphs` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT Paragraph_Text) AS NumberOfUniqueParagraphs \nFROM Paragraphs;\n```\n\nThis query will return the number of unique `Paragraph_Text` values in your `Paragraphs` table.","cost":0.0006093,"response_parsed":"SELECT COUNT(DISTINCT Paragraph_Text) AS NumberOfUniqueParagraphs \nFROM Paragraphs;","time":4.4768891335}} {"db_path":"QATCH-journal\/spider_data\/test_database\/cre_Doc_Template_Mgt\/cre_Doc_Template_Mgt.sqlite","db_id":"cre_Doc_Template_Mgt","tbl_name":"Paragraphs","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Other_Details`) FROM `Paragraphs`","question":"How many different Other_Details are in table Paragraphs?","db_schema_normalized":"`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","db_schema":"`Ref_Template_Types`(Template_Type_Code CHAR(15) NOT NULL, Template_Type_Description VARCHAR(255) NOT NULL, PRIMARY KEY (Template_Type_Code))\n`Templates`(Template_ID INTEGER NOT NULL, Version_Number INTEGER NOT NULL, Template_Type_Code CHAR(15) NOT NULL, Date_Effective_From DATETIME, Date_Effective_To DATETIME, Template_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Template_ID), FOREIGN KEY (Template_Type_Code) REFERENCES Ref_Template_Types (Template_Type_Code))\n`Documents`(Document_ID INTEGER NOT NULL, Template_ID INTEGER, Document_Name VARCHAR(255), Document_Description VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Document_ID), FOREIGN KEY (Template_ID) REFERENCES Templates (Template_ID))\n`Paragraphs`(Paragraph_ID INTEGER NOT NULL, Document_ID INTEGER NOT NULL, Paragraph_Text VARCHAR(255), Other_Details VARCHAR(255), PRIMARY KEY (Paragraph_ID), FOREIGN KEY (Document_ID) REFERENCES Documents (Document_ID))","pred_dict":{"response":"\n\nTo determine how many different `Other_Details` are in the `Paragraphs` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\n```sql\nSELECT COUNT(DISTINCT Other_Details) AS Number_of_Different_Other_Details\nFROM Paragraphs;\n```","cost":0.0005085,"response_parsed":"SELECT COUNT(DISTINCT Other_Details) AS Number_of_Different_Other_Details\nFROM Paragraphs;","time":3.5330197811}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Staring_Date` FROM `course`","question":"Show the different Staring_Date in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the different `Staring_Date` values from the `course` table, you can use the `DISTINCT` keyword in SQL to retrieve unique values. Here's the SQL code:\n\n```sql\nSELECT DISTINCT Staring_Date FROM course;\n```","cost":0.0004239,"response_parsed":"SELECT DISTINCT Staring_Date FROM course;","time":3.5003447533}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Course` FROM `course`","question":"Show the different Course in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show the different courses in the `course` table, you can use the `SELECT DISTINCT` statement to fetch unique course names.\n\n```sql\nSELECT DISTINCT \"Course\" FROM course;\n```","cost":0.0004311,"response_parsed":"SELECT DISTINCT \"Course\" FROM course;","time":3.3495633602}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `teacher`","question":"Show the different Name in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show the different names in the `teacher` table, you can use the `SELECT DISTINCT` statement to fetch unique names.\n\n```sql\nSELECT DISTINCT Name FROM teacher;\n```","cost":0.0003609,"response_parsed":"SELECT DISTINCT Name FROM teacher;","time":2.6315255165}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Age` FROM `teacher`","question":"Show the different Age in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show the different ages in the `teacher` table, you can use the `SELECT DISTINCT` statement to fetch unique `Age` values.\n\n```sql\nSELECT DISTINCT Age FROM teacher;\n```","cost":0.0003771,"response_parsed":"SELECT DISTINCT Age FROM teacher;","time":2.6646883488}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Hometown` FROM `teacher`","question":"Show the different Hometown in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show the different hometowns in the `teacher` table, you can use the `SELECT DISTINCT` statement to fetch unique values from the `Hometown` column.\n\n```sql\nSELECT DISTINCT Hometown FROM teacher;\n```","cost":0.0004149,"response_parsed":"SELECT DISTINCT Hometown FROM teacher;","time":3.0595276356}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Staring_Date`, COUNT(*) FROM `course` GROUP BY `Staring_Date`","question":"For each Staring_Date, count the number of rows in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Starting_Date` in the `course` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Starting_Date, \n COUNT(*) as Number_of_Courses\nFROM \n course\nGROUP BY \n Starting_Date;\n```\n\nThis query will:\n1. Select the `Starting_Date` column\n2. Count the number of rows for each `Starting_Date` using `COUNT(*)`\n3. Group the results by the `Starting_Date` column\n4. Return the result with the number of courses for each starting date","cost":0.0006102,"response_parsed":"SELECT \n Starting_Date, \n COUNT(*) as Number_of_Courses\nFROM \n course\nGROUP BY \n Starting_Date;","time":5.0230753422}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Course`, COUNT(*) FROM `course` GROUP BY `Course`","question":"For each Course, count the number of rows in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `course` table for each course, you can use the `COUNT(*)` function along with the `GROUP BY` clause to group the results by the `Course` column.\n\n```sql\nSELECT \n Course,\n COUNT(*) as Number_of_Rows\nFROM \n course\nGROUP BY \n Course;\n```\n\nThis SQL query will:\n1. Select the `Course` column and count the number of rows for each course.\n2. Group the results by the `Course` column.\n3. Return the course name along with the count of rows for each course.","cost":0.0006273,"response_parsed":"SELECT \n Course,\n COUNT(*) as Number_of_Rows\nFROM \n course\nGROUP BY \n Course;","time":5.5406565666}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `teacher` GROUP BY `Name`","question":"For each Name, count the number of rows in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each Name in the teacher table, we use the COUNT() function combined with GROUP BY to group the results by the Name column.\n\n```sql\nSELECT Name, COUNT(*) FROM teacher GROUP BY Name;\n```","cost":0.0006093,"response_parsed":"SELECT Name, COUNT(*) FROM teacher GROUP BY Name;","time":5.4869596958}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Age`, COUNT(*) FROM `teacher` GROUP BY `Age`","question":"For each Age, count the number of rows in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Age` in the `teacher` table, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Age, COUNT(*) AS NumberOfTeachers\nFROM teacher\nGROUP BY Age;\n```\n\nThis query will:\n1. Group all rows in the `teacher` table by the `Age` column.\n2. Count the number of rows for each unique `Age` value.\n3. Return a result set with two columns: `Age` and `NumberOfTeachers` (the count of rows for each age).","cost":0.0006417,"response_parsed":"SELECT Age, COUNT(*) AS NumberOfTeachers\nFROM teacher\nGROUP BY Age;","time":5.3942456245}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Hometown`, COUNT(*) FROM `teacher` GROUP BY `Hometown`","question":"For each Hometown, count the number of rows in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `teacher` table for each `Hometown`, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Hometown, COUNT(*) as Number_of_Teachers\nFROM teacher\nGROUP BY Hometown\nORDER BY Hometown;\n```\n\nThis SQL query will:\n1. Select the `Hometown` column and count the number of rows for each `Hometown`.\n2. Group the results by the `Hometown` column.\n3. Optionally, order the results alphabetically by `Hometown` for better readability.\n\nThe result will show each `Hometown` along with the number of teachers from that hometown.","cost":0.0005022,"response_parsed":"SELECT Hometown, COUNT(*) as Number_of_Teachers\nFROM teacher\nGROUP BY Hometown\nORDER BY Hometown;","time":3.8695788383}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Staring_Date` FROM `course` GROUP BY `Staring_Date` HAVING count(*) >= 1","question":"Find all the Staring_Date that have at least 1 records in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the `Staring_Date` values that have at least one record in the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Staring_Date FROM course;\n```\n\nThis query will return all the `Staring_Date` values present in the `course` table. If you want to ensure that each `Staring_Date` appears only once in the result (i.e., to get unique `Staring_Date` values), you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Staring_Date FROM course;\n```","cost":0.0006723,"response_parsed":"SELECT DISTINCT Staring_Date FROM course;","time":5.8684453964}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Staring_Date` FROM `course` GROUP BY `Staring_Date` HAVING count(*) <= 1","question":"Find all the Staring_Date that have at most 1 records in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the `Staring_Date` values that have at most 1 record in the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Starting_Date\nFROM course\nWHERE Starting_Date IN (\n SELECT Starting_Date\n FROM course\n GROUP BY Starting_Date\n HAVING COUNT(Starting_Date) <= 1\n);\n```\n\nThis query works as follows:\n1. The subquery groups the `course` table by `Starting_Date` and filters those dates that appear at most once.\n2. The outer query selects all `Starting_Date` values from the `course` table that match the filtered dates from the subquery.","cost":0.0005904,"response_parsed":"SELECT Starting_Date\nFROM course\nWHERE Starting_Date IN (\n SELECT Starting_Date\n FROM course\n GROUP BY Starting_Date\n HAVING COUNT(Starting_Date) <= 1\n);","time":5.1216542721}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Course` FROM `course` GROUP BY `Course` HAVING count(*) >= 1","question":"Find all the Course that have at least 1 records in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all courses that have at least one record in the `course` table, you can use a simple `SELECT` statement since every record in the `course` table inherently has at least one record. However, if you want to ensure that each course has at least one related record in the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT c.Course_ID, c.Course\nFROM course c\nINNER JOIN course_arrange ca\nON c.Course_ID = ca.Course_ID;\n```\n\nThis query will return all courses that have at least one record in the `course_arrange` table.","cost":0.0006867,"response_parsed":"SELECT c.Course_ID, c.Course\nFROM course c\nINNER JOIN course_arrange ca\nON c.Course_ID = ca.Course_ID;","time":6.4495239258}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Course` FROM `course` GROUP BY `Course` HAVING count(*) <= 1","question":"Find all the Course that have at most 1 records in table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all courses that have at most 1 record in the `course` table, we can use the following SQL query. This query will count the number of records for each course and return those courses with a count of 1 or less.\n\n```sql\nSELECT Course_ID, Course\nFROM course\nWHERE Course_ID IN (\n SELECT Course_ID\n FROM course_arrange\n GROUP BY Course_ID\n HAVING COUNT(*) <= 1\n);\n```\n\nThis query:\n1. Uses a subquery to select `Course_ID`s from the `course_arrange` table where the count of records for each `Course_ID` is 1 or less.\n2. Joins this result with the `course` table to get the corresponding course details.\n3. Returns the `Course_ID` and `Course` name for courses that meet the condition.","cost":0.0007938,"response_parsed":"SELECT Course_ID, Course\nFROM course\nWHERE Course_ID IN (\n SELECT Course_ID\n FROM course_arrange\n GROUP BY Course_ID\n HAVING COUNT(*) <= 1\n);","time":7.0613150597}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `teacher` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the names of teachers who have at least one record in the `teacher` table, you can use the following SQL query. This query will return all the names from the `teacher` table:\n\n```sql\nSELECT Name FROM teacher;\n```\n\nIf you want to ensure that the teacher has at least one record in both the `teacher` table and the `course_arrange` table (i.e., the teacher is assigned to at least one course), you can use the following SQL query:\n\n```sql\nSELECT DISTINCT t.Name \nFROM teacher t\nINNER JOIN course_arrange ca \nON t.Teacher_ID = ca.Teacher_ID;\n```\n\nThis query will return the names of teachers who have at least one course assigned to them.","cost":0.0007335,"response_parsed":"SELECT DISTINCT t.Name \nFROM teacher t\nINNER JOIN course_arrange ca \nON t.Teacher_ID = ca.Teacher_ID;","time":6.499576807}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `teacher` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all teacher names that have at most 1 record in the `teacher` table, we can use a query that counts the number of records for each teacher and filters those with a count of 1 or less.\n\n```sql\nSELECT Name\nFROM teacher\nWHERE Teacher_ID IN (\n SELECT Teacher_ID\n FROM course_arrange\n GROUP BY Teacher_ID\n HAVING COUNT(*) <= 1\n)\nGROUP BY Name\nHAVING COUNT(*) <= 1;\n```\n\nHowever, since each teacher should have only one record in the `teacher` table (as `Teacher_ID` is the primary key), this query will return all teacher names. If you meant to find teachers with at most one course arrangement, you can use:\n\n```sql\nSELECT t.Name\nFROM teacher t\nLEFT JOIN course_arrange ca ON t.Teacher_ID = ca.Teacher_ID\nGROUP BY t.Name\nHAVING COUNT(ca.Course_ID) <= 1;\n```\n\nThis will return all teachers who have 0 or 1 course arrangements.","cost":0.0005967,"response_parsed":"SELECT t.Name\nFROM teacher t\nLEFT JOIN course_arrange ca ON t.Teacher_ID = ca.Teacher_ID\nGROUP BY t.Name\nHAVING COUNT(ca.Course_ID) <= 1;","time":6.1259756088}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Age` FROM `teacher` GROUP BY `Age` HAVING count(*) >= 1","question":"Find all the Age that have at least 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all unique ages that have at least one record in the `teacher` table, you can use the `SELECT DISTINCT` statement. This will retrieve each unique `Age` value from the `teacher` table.\n\n```sql\nSELECT DISTINCT Age FROM teacher;\n```","cost":0.0004464,"response_parsed":"SELECT DISTINCT Age FROM teacher;","time":3.6587467194}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Age` FROM `teacher` GROUP BY `Age` HAVING count(*) <= 1","question":"Find all the Age that have at most 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the Ages in the `teacher` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Age, COUNT(*) \nFROM teacher \nGROUP BY Age \nHAVING COUNT(*) <= 1;\n```\n\nThis query will return the `Age` values along with the count of records for each `Age` that has at most 1 record in the table.","cost":0.0005481,"response_parsed":"SELECT Age, COUNT(*) \nFROM teacher \nGROUP BY Age \nHAVING COUNT(*) <= 1;","time":4.4390108585}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Hometown` FROM `teacher` GROUP BY `Hometown` HAVING count(*) >= 1","question":"Find all the Hometown that have at least 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the Hometowns that have at least one record in the `teacher` table, you can use the `SELECT DISTINCT` statement to retrieve unique Hometown values.\n\n```sql\nSELECT DISTINCT Hometown FROM teacher;\n```","cost":0.000423,"response_parsed":"SELECT DISTINCT Hometown FROM teacher;","time":3.0874745846}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Hometown` FROM `teacher` GROUP BY `Hometown` HAVING count(*) <= 1","question":"Find all the Hometown that have at most 1 records in table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find all the Hometowns that have at most 1 record in the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Hometown\nFROM teacher\nGROUP BY Hometown\nHAVING COUNT(Teacher_ID) <= 1;\n```\n\nThis query will:\n1. Group the teachers by their `Hometown`.\n2. Count the number of teachers for each `Hometown`.\n3. Return only those `Hometown`s that have 1 or fewer teachers.\n\n```sql\nSELECT Hometown\nFROM teacher\nGROUP BY Hometown\nHAVING COUNT(Teacher_ID) <= 1;\n```","cost":0.0006534,"response_parsed":"SELECT Hometown\nFROM teacher\nGROUP BY Hometown\nHAVING COUNT(Teacher_ID) <= 1;","time":6.2381742001}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `course_arrange` AS T1 JOIN `course` AS T2 ON T1.`Course_ID` = T2.`Course_ID`","question":"Join all the records from table course_arrange with table course on Course_ID","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo join all records from the `course_arrange` table with the `course` table based on the `Course_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM course_arrange\nINNER JOIN course\nON course_arrange.Course_ID = course.Course_ID;\n```\n\nThis SQL code performs an inner join between the `course_arrange` and `course` tables based on the `Course_ID` field. The result will include all columns from both tables where there is a matching `Course_ID` in both tables.","cost":0.0005742,"response_parsed":"SELECT *\nFROM course_arrange\nINNER JOIN course\nON course_arrange.Course_ID = course.Course_ID;","time":4.9986877441}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `course_arrange` AS T1 JOIN `teacher` AS T2 ON T1.`Teacher_ID` = T2.`Teacher_ID`","question":"Join all the records from table course_arrange with table teacher on Teacher_ID","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo join all records from the `course_arrange` table with the `teacher` table based on the `Teacher_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM course_arrange\nINNER JOIN teacher\nON course_arrange.Teacher_ID = teacher.Teacher_ID;\n```\n\nThis query will return all records where there is a matching `Teacher_ID` in both tables. If you want to include all records from `course_arrange` even if there is no match in `teacher`, you can use a `LEFT JOIN` instead:\n\n```sql\nSELECT *\nFROM course_arrange\nLEFT JOIN teacher\nON course_arrange.Teacher_ID = teacher.Teacher_ID;\n```","cost":0.0005679,"response_parsed":"SELECT *\nFROM course_arrange\nLEFT JOIN teacher\nON course_arrange.Teacher_ID = teacher.Teacher_ID;","time":4.5713245869}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course` ORDER BY `Staring_Date` ASC","question":"Show all data ordered by Staring_Date in ascending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course` table ordered by `Staring_Date` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM \"course\" ORDER BY \"Staring_Date\" ASC;\n```","cost":0.0004914,"response_parsed":"SELECT * FROM \"course\" ORDER BY \"Staring_Date\" ASC;","time":4.0570352077}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course` ORDER BY `Staring_Date` DESC","question":"Show all data ordered by Staring_Date in descending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course` table ordered by `Staring_Date` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course ORDER BY Staring_Date DESC;\n```","cost":0.0005049,"response_parsed":"SELECT * FROM course ORDER BY Staring_Date DESC;","time":4.2051460743}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course` ORDER BY `Course_ID` ASC","question":"Show all data ordered by Course_ID in ascending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course` table ordered by `Course_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course ORDER BY Course_ID ASC;\n```","cost":0.0004104,"response_parsed":"SELECT * FROM course ORDER BY Course_ID ASC;","time":3.0221903324}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course` ORDER BY `Course_ID` DESC","question":"Show all data ordered by Course_ID in descending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course` table ordered by `Course_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course ORDER BY Course_ID DESC;\n```","cost":0.0004545,"response_parsed":"SELECT * FROM course ORDER BY Course_ID DESC;","time":4.0346486568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Course_ID` FROM `course` ORDER BY `Course_ID` ASC","question":"Project the Course_ID ordered in ascending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Course_ID` from the `course` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Course_ID \nFROM course \nORDER BY Course_ID ASC;\n```","cost":0.0003555,"response_parsed":"SELECT Course_ID \nFROM course \nORDER BY Course_ID ASC;","time":2.8988165855}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Course_ID` FROM `course` ORDER BY `Course_ID` DESC","question":"Project the Course_ID ordered in descending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Course_ID` from the `course` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course ORDER BY Course_ID DESC;\n```","cost":0.0005787,"response_parsed":"SELECT Course_ID FROM course ORDER BY Course_ID DESC;","time":5.7479059696}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Staring_Date` FROM `course` ORDER BY `Staring_Date` ASC","question":"Project the Staring_Date ordered in ascending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Staring_Date` from the `course` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Staring_Date\nFROM course\nORDER BY Staring_Date ASC;\n```\n\nThis query will:\n1. Select the `Staring_Date` column from the `course` table.\n2. Order the results in ascending order based on the `Staring_Date` values.","cost":0.0005328,"response_parsed":"SELECT Staring_Date\nFROM course\nORDER BY Staring_Date ASC;","time":4.9674248695}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Staring_Date` FROM `course` ORDER BY `Staring_Date` DESC","question":"Project the Staring_Date ordered in descending order for the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Staring_Date` from the `course` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Staring_Date\nFROM course\nORDER BY Staring_Date DESC;\n```\n\nThis query will:\n1. Select the `Staring_Date` column from the `course` table.\n2. Order the results in descending order based on the `Staring_Date`.","cost":0.0004617,"response_parsed":"SELECT Staring_Date\nFROM course\nORDER BY Staring_Date DESC;","time":3.3967008591}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course_arrange` ORDER BY `Grade` ASC","question":"Show all data ordered by Grade in ascending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course_arrange` table ordered by the `Grade` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course_arrange ORDER BY Grade ASC;\n```","cost":0.000693,"response_parsed":"SELECT * FROM course_arrange ORDER BY Grade ASC;","time":6.495421648}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course_arrange` ORDER BY `Grade` DESC","question":"Show all data ordered by Grade in descending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course_arrange` table ordered by `Grade` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM course_arrange\nORDER BY Grade DESC;\n```\n\nThis query will return all records from the `course_arrange` table, sorted by the `Grade` column in descending order (from highest to lowest).","cost":0.0004455,"response_parsed":"SELECT *\nFROM course_arrange\nORDER BY Grade DESC;","time":3.979521513}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course_arrange` ORDER BY `Teacher_ID` ASC","question":"Show all data ordered by Teacher_ID in ascending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course_arrange` table ordered by `Teacher_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course_arrange ORDER BY Teacher_ID ASC;\n```","cost":0.0004428,"response_parsed":"SELECT * FROM course_arrange ORDER BY Teacher_ID ASC;","time":3.6342804432}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `course_arrange` ORDER BY `Teacher_ID` DESC","question":"Show all data ordered by Teacher_ID in descending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `course_arrange` table ordered by `Teacher_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM course_arrange ORDER BY Teacher_ID DESC;\n```","cost":0.0004653,"response_parsed":"SELECT * FROM course_arrange ORDER BY Teacher_ID DESC;","time":3.8637182713}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Course_ID` FROM `course_arrange` ORDER BY `Course_ID` ASC","question":"Project the Course_ID ordered in ascending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Course_ID` from the `course_arrange` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course_arrange ORDER BY Course_ID ASC;\n```","cost":0.0004428,"response_parsed":"SELECT Course_ID FROM course_arrange ORDER BY Course_ID ASC;","time":3.8977310658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Course_ID` FROM `course_arrange` ORDER BY `Course_ID` DESC","question":"Project the Course_ID ordered in descending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Course_ID` from the `course_arrange` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course_arrange ORDER BY Course_ID DESC;\n```","cost":0.0004122,"response_parsed":"SELECT Course_ID FROM course_arrange ORDER BY Course_ID DESC;","time":3.1213777065}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Grade` FROM `course_arrange` ORDER BY `Grade` ASC","question":"Project the Grade ordered in ascending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the Grade from the `course_arrange` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Grade\nFROM course_arrange\nORDER BY Grade ASC;\n```","cost":0.0003798,"response_parsed":"SELECT Grade\nFROM course_arrange\nORDER BY Grade ASC;","time":2.6521441936}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Grade` FROM `course_arrange` ORDER BY `Grade` DESC","question":"Project the Grade ordered in descending order for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the Grade from the `course_arrange` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Grade FROM course_arrange ORDER BY Grade DESC;\n```","cost":0.0004248,"response_parsed":"SELECT Grade FROM course_arrange ORDER BY Grade DESC;","time":3.2668361664}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `teacher` ORDER BY `Teacher_ID` ASC","question":"Show all data ordered by Teacher_ID in ascending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `teacher` table ordered by `Teacher_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nORDER BY Teacher_ID ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `teacher` table.\n2. Order the results by the `Teacher_ID` column in ascending order (`ASC`).","cost":0.0005211,"response_parsed":"SELECT *\nFROM teacher\nORDER BY Teacher_ID ASC;","time":4.1996819973}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `teacher` ORDER BY `Teacher_ID` DESC","question":"Show all data ordered by Teacher_ID in descending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `teacher` table ordered by `Teacher_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nORDER BY Teacher_ID DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `teacher` table.\n2. Order the results by the `Teacher_ID` column in descending order (from highest to lowest).","cost":0.000459,"response_parsed":"SELECT *\nFROM teacher\nORDER BY Teacher_ID DESC;","time":3.5077130795}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `teacher` ORDER BY `Name` ASC","question":"Show all data ordered by Name in ascending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `teacher` table ordered by the `Name` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nORDER BY Name ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `teacher` table\n2. Order the results by the `Name` column in ascending order (from A to Z)","cost":0.0004194,"response_parsed":"SELECT *\nFROM teacher\nORDER BY Name ASC;","time":3.0266385078}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `teacher` ORDER BY `Name` DESC","question":"Show all data ordered by Name in descending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `teacher` table ordered by the `Name` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nORDER BY Name DESC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `teacher` table\n2. Order the results by the `Name` column in descending alphabetical order","cost":0.0004671,"response_parsed":"SELECT *\nFROM teacher\nORDER BY Name DESC;","time":3.6836669445}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Name` FROM `teacher` ORDER BY `Name` ASC","question":"Project the Name ordered in ascending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Name` column from the `teacher` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Name FROM teacher ORDER BY Name ASC;\n```","cost":0.0003753,"response_parsed":"SELECT Name FROM teacher ORDER BY Name ASC;","time":2.5989775658}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Name` FROM `teacher` ORDER BY `Name` DESC","question":"Project the Name ordered in descending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Name` column from the `teacher` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT \"Name\" \nFROM teacher \nORDER BY \"Name\" DESC;\n```\n\nThis query will:\n1. Select the `Name` column from the `teacher` table\n2. Order the results in descending alphabetical order based on the `Name` column","cost":0.00045,"response_parsed":"SELECT \"Name\" \nFROM teacher \nORDER BY \"Name\" DESC;","time":3.2628040314}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Hometown` FROM `teacher` ORDER BY `Hometown` ASC","question":"Project the Hometown ordered in ascending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Hometown` from the `teacher` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Hometown\nFROM teacher\nORDER BY Hometown ASC;\n```","cost":0.0003834,"response_parsed":"SELECT Hometown\nFROM teacher\nORDER BY Hometown ASC;","time":2.7807192802}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Hometown` FROM `teacher` ORDER BY `Hometown` DESC","question":"Project the Hometown ordered in descending order for the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo project the `Hometown` column from the `teacher` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT DISTINCT Hometown\nFROM teacher\nORDER BY Hometown DESC;\n```\n\nThis query will:\n1. Select the `Hometown` column from the `teacher` table.\n2. Remove any duplicate `Hometown` entries using `DISTINCT`.\n3. Order the results in descending alphabetical order.","cost":0.0004338,"response_parsed":"SELECT DISTINCT Hometown\nFROM teacher\nORDER BY Hometown DESC;","time":3.234395504}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Course_ID` FROM `course`","question":"Show all Course_ID in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Course_ID` from the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course;\n```","cost":0.000432,"response_parsed":"SELECT Course_ID FROM course;","time":3.5704240799}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Staring_Date` FROM `course`","question":"Show all Staring_Date in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Staring_Date` from the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Staring_Date FROM course;\n```","cost":0.0004005,"response_parsed":"SELECT Staring_Date FROM course;","time":2.9253282547}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Course` FROM `course`","question":"Show all Course in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show all courses in the `course` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM course;\n```\n\nThis query will return all rows and columns from the `course` table.","cost":0.0005598,"response_parsed":"SELECT * FROM course;","time":4.6419489384}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `course`","question":"Show all the rows in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `course` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM course;\n```","cost":0.0004572,"response_parsed":"SELECT * FROM course;","time":3.9908120632}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Course_ID` FROM `course`","question":"Show all Course_ID in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Course_ID` from the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course;\n```","cost":0.0003609,"response_parsed":"SELECT Course_ID FROM course;","time":2.5011997223}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Course`, `Staring_Date` FROM `course`","question":"Show all Course, Staring_Date in the table course","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all courses and their starting dates from the `course` table, you can use the following SQL query:\n\n```sql\nSELECT Course, Staring_Date FROM course;\n```\n\nThis query will return all rows from the `course` table, displaying the `Course` and `Staring_Date` columns.","cost":0.0005229,"response_parsed":"SELECT Course, Staring_Date FROM course;","time":4.2384500504}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Course_ID` FROM `course_arrange`","question":"Show all Course_ID in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Course_ID` from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT Course_ID FROM course_arrange;\n```","cost":0.0006147,"response_parsed":"SELECT Course_ID FROM course_arrange;","time":5.2840168476}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Teacher_ID` FROM `course_arrange`","question":"Show all Teacher_ID in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Teacher_ID`s from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT Teacher_ID FROM course_arrange;\n```","cost":0.0004248,"response_parsed":"SELECT Teacher_ID FROM course_arrange;","time":3.9158058167}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Grade` FROM `course_arrange`","question":"Show all Grade in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the grades from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT Grade FROM course_arrange;\n```\n\nThis query will return all the values in the `Grade` column of the `course_arrange` table.","cost":0.0004257,"response_parsed":"SELECT Grade FROM course_arrange;","time":3.1022918224}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `course_arrange`","question":"Show all the rows in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all rows from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM course_arrange;\n```\n\nThis query will return all rows and columns from the `course_arrange` table.","cost":0.0004374,"response_parsed":"SELECT * FROM course_arrange;","time":3.4774303436}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Grade` FROM `course_arrange`","question":"Show all Grade in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the grades from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT Grade FROM course_arrange;\n```\n\nThis query will return all the values in the `Grade` column of the `course_arrange` table.","cost":0.0004257,"response_parsed":"SELECT Grade FROM course_arrange;","time":3.2013764381}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Grade`, `Course_ID` FROM `course_arrange`","question":"Show all Grade, Course_ID in the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Grade` and `Course_ID` from the `course_arrange` table, you can use the following SQL query:\n\n```sql\nSELECT Grade, Course_ID FROM course_arrange;\n```","cost":0.0004815,"response_parsed":"SELECT Grade, Course_ID FROM course_arrange;","time":3.8149588108}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Teacher_ID` FROM `teacher`","question":"Show all Teacher_ID in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all `Teacher_ID` from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Teacher_ID FROM teacher;\n```\n\nThis query will return all the `Teacher_ID` values present in your `teacher` table.","cost":0.0004122,"response_parsed":"SELECT Teacher_ID FROM teacher;","time":3.1000118256}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `teacher`","question":"Show all Name in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the names from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM teacher;\n```\n\nThis query will return all the names stored in the `Name` column of the `teacher` table.","cost":0.0004275,"response_parsed":"SELECT Name FROM teacher;","time":3.2119426727}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Age` FROM `teacher`","question":"Show all Age in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the ages of teachers from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Age FROM teacher;\n```\n\nThis query will return all the values in the `Age` column of the `teacher` table.","cost":0.0004176,"response_parsed":"SELECT Age FROM teacher;","time":3.4416525364}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Hometown` FROM `teacher`","question":"Show all Hometown in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the \"Hometown\" entries from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Hometown FROM teacher;\n```\n\nThis query will return all the hometowns of the teachers listed in your database.","cost":0.0004014,"response_parsed":"SELECT Hometown FROM teacher;","time":3.1075308323}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `teacher`","question":"Show all the rows in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `teacher` table, you can use the `SELECT` statement with the asterisk `*` wildcard to select all columns. Here is the SQL code:\n\n```sql\nSELECT * FROM teacher;\n```","cost":0.0004401,"response_parsed":"SELECT * FROM teacher;","time":3.6251995564}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Hometown` FROM `teacher`","question":"Show all Hometown in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch all the \"Hometown\" entries from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Hometown FROM teacher;\n```\n\nThis query will return all the hometowns of the teachers listed in the `teacher` table. If you want to avoid duplicate hometown entries, you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Hometown FROM teacher;\n```","cost":0.0005022,"response_parsed":"SELECT DISTINCT Hometown FROM teacher;","time":4.6561479568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Hometown`, `Age` FROM `teacher`","question":"Show all Hometown, Age in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Hometown` and `Age` of all teachers from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Hometown, Age FROM teacher;\n```","cost":0.0004266,"response_parsed":"SELECT Hometown, Age FROM teacher;","time":3.8084938526}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Teacher_ID`, `Hometown`, `Name` FROM `teacher`","question":"Show all Teacher_ID, Hometown, Name in the table teacher","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the `Teacher_ID`, `Hometown`, and `Name` from the `teacher` table, you can use the following SQL query:\n\n```sql\nSELECT Teacher_ID, Hometown, Name FROM teacher;\n```","cost":0.0004797,"response_parsed":"SELECT Teacher_ID, Hometown, Name FROM teacher;","time":3.3362512589}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Staring_Date` == '10 May'","question":"Show the data of the table course where Staring_Date is equal to 10 May","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where `Staring_Date` is equal to '10 May', you can use the following SQL query:\n\n```sql\nSELECT * FROM course WHERE Staring_Date = '10 May';\n```","cost":0.0006417,"response_parsed":"SELECT * FROM course WHERE Staring_Date = '10 May';","time":5.3175141811}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Staring_Date` != '5 May'","question":"Show the data of the table course where Staring_Date is different from 5 May","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where the `Staring_Date` is different from '5 May', you can use the following SQL query:\n\n```sql\nSELECT * FROM course WHERE Staring_Date != '5 May';\n```\n\nThis query will return all rows in the `course` table where the `Staring_Date` is not '5 May'.","cost":0.000495,"response_parsed":"SELECT * FROM course WHERE Staring_Date != '5 May';","time":3.7491214275}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Staring_Date` != '5 May'","question":"Show the data of the table course where Staring_Date not equal to 5 May","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where `Staring_Date` is not equal to '5 May', you can use the following SQL query:\n\n```sql\nSELECT * FROM course WHERE Staring_Date != '5 May';\n```","cost":0.0005094,"response_parsed":"SELECT * FROM course WHERE Staring_Date != '5 May';","time":4.2285106182}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Course` == 'Science'","question":"Show the data of the table course where Course is equal to Science","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where the `Course` is equal to \"Science\", you can use the following SQL query:\n\n```sql\nSELECT * FROM course WHERE Course = 'Science';\n```","cost":0.0004464,"response_parsed":"SELECT * FROM course WHERE Course = 'Science';","time":3.6249601841}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Course` != 'Science'","question":"Show the data of the table course where Course is different from Science","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where the `Course` is different from \"Science\", you can use the following SQL query:\n\n```sql\nSELECT * FROM course WHERE Course != 'Science';\n```","cost":0.000414,"response_parsed":"SELECT * FROM course WHERE Course != 'Science';","time":2.9978532791}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `course` WHERE `Course` != 'Science'","question":"Show the data of the table course where Course not equal to Science","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course` table where the `Course` is not equal to \"Science\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM course\nWHERE Course != 'Science';\n```","cost":0.0005202,"response_parsed":"SELECT *\nFROM course\nWHERE Course != 'Science';","time":4.620390892}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `course_arrange` WHERE `Grade` > 3","question":"Show the data of the table course_arrange where Grade is greater than 3","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `course_arrange` table where the `Grade` is greater than 3, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM course_arrange\nWHERE Grade > 3;\n```","cost":0.0003816,"response_parsed":"SELECT *\nFROM course_arrange\nWHERE Grade > 3;","time":2.3982377052}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Name` == 'Gustaaf Deloor'","question":"Show the data of the table teacher where Name is equal to Gustaaf Deloor","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of the teacher with the name \"Gustaaf Deloor,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM teacher WHERE Name = 'Gustaaf Deloor';\n```","cost":0.0006138,"response_parsed":"SELECT * FROM teacher WHERE Name = 'Gustaaf Deloor';","time":5.7392134666}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Name` != 'John Deloor'","question":"Show the data of the table teacher where Name is different from John Deloor","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers whose names are different from \"John Deloor,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nWHERE Name <> 'John Deloor';\n```","cost":0.0004608,"response_parsed":"SELECT *\nFROM teacher\nWHERE Name <> 'John Deloor';","time":3.4904706478}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Name` != 'John Deloor'","question":"Show the data of the table teacher where Name not equal to John Deloor","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers whose names are not \"John Deloor\", you can use the following SQL query:\n\n```sql\nSELECT * FROM teacher WHERE Name != 'John Deloor';\n```","cost":0.0005598,"response_parsed":"SELECT * FROM teacher WHERE Name != 'John Deloor';","time":5.1011533737}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Age` == '26'","question":"Show the data of the table teacher where Age is equal to 26","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers who are 26 years old, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nWHERE Age = '26';\n```\n\nThis query will return all rows from the `teacher` table where the `Age` column is equal to '26'.","cost":0.0004761,"response_parsed":"SELECT *\nFROM teacher\nWHERE Age = '26';","time":3.6783928871}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Age` != '32'","question":"Show the data of the table teacher where Age is different from 32","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers where the `Age` is different from 32, you can use the following SQL query:\n\n```sql\nSELECT * FROM teacher WHERE Age != '32';\n```\n\nThis query will return all rows from the `teacher` table where the `Age` column does not contain the value '32'.","cost":0.0005193,"response_parsed":"SELECT * FROM teacher WHERE Age != '32';","time":4.6533093452}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Age` != '29'","question":"Show the data of the table teacher where Age not equal to 29","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `teacher` table where the `Age` is not equal to 29, you can use the following SQL query:\n\n```sql\nSELECT * FROM teacher WHERE Age != '29';\n```\n\nThis query will return all rows from the `teacher` table where the `Age` column does not contain the value '29'.","cost":0.0005112,"response_parsed":"SELECT * FROM teacher WHERE Age != '29';","time":4.1603426933}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Hometown` == 'Blackrod Urban District'","question":"Show the data of the table teacher where Hometown is equal to Blackrod Urban District","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers where the Hometown is \"Blackrod Urban District,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nWHERE Hometown = 'Blackrod Urban District';\n```","cost":0.0004509,"response_parsed":"SELECT *\nFROM teacher\nWHERE Hometown = 'Blackrod Urban District';","time":3.824691534}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Hometown` != 'Blackrod Urban District'","question":"Show the data of the table teacher where Hometown is different from Blackrod Urban District","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data of teachers whose hometown is different from \"Blackrod Urban District,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nWHERE Hometown <> 'Blackrod Urban District';\n```","cost":0.0004518,"response_parsed":"SELECT *\nFROM teacher\nWHERE Hometown <> 'Blackrod Urban District';","time":4.0177805424}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `teacher` WHERE `Hometown` != 'Horwich Urban District'","question":"Show the data of the table teacher where Hometown not equal to Horwich Urban District","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `teacher` table where the `Hometown` is not equal to \"Horwich Urban District\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM teacher\nWHERE Hometown != 'Horwich Urban District';\n```","cost":0.0004887,"response_parsed":"SELECT *\nFROM teacher\nWHERE Hometown != 'Horwich Urban District';","time":4.5860230923}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Staring_Date`) FROM `course`","question":"How many different Staring_Date are in table course?","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Staring_Date` values are present in the `course` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Staring_Date) FROM course;\n```","cost":0.0005094,"response_parsed":"SELECT COUNT(DISTINCT Staring_Date) FROM course;","time":4.6693971157}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Course`) FROM `course`","question":"How many different Course are in table course?","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo determine how many different courses are in the `course` table, you can use the `COUNT(DISTINCT)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Course) FROM course;\n```\n\nThis query will return the number of unique course names in your `course` table.","cost":0.0005121,"response_parsed":"SELECT COUNT(DISTINCT Course) FROM course;","time":4.0506417751}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Grade`) FROM `course_arrange`","question":"Find the maximum Grade for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find the maximum Grade in the `course_arrange` table, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(Grade) FROM course_arrange;\n```\n\nThis query will return the highest Grade value from the `course_arrange` table.","cost":0.0004257,"response_parsed":"SELECT MAX(Grade) FROM course_arrange;","time":3.7429535389}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Grade`) FROM `course_arrange`","question":"Find the minimum Grade for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find the minimum Grade from the `course_arrange` table, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Grade) AS Minimum_Grade\nFROM course_arrange;\n```\n\nThis query will return the smallest Grade value in the `Grade` column of the `course_arrange` table.","cost":0.0004725,"response_parsed":"SELECT MIN(Grade) AS Minimum_Grade\nFROM course_arrange;","time":3.8055882454}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"course_arrange","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Grade`) FROM `course_arrange`","question":"Find the average Grade for the table course_arrange","db_schema_normalized":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo find the average Grade for the table `course_arrange`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(Grade) AS Average_Grade FROM course_arrange;\n```\n\nThis query will calculate the average value of the `Grade` column in the `course_arrange` table and return it as `Average_Grade`.","cost":0.0005337,"response_parsed":"SELECT AVG(Grade) AS Average_Grade FROM course_arrange;","time":4.3844704628}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `teacher`","question":"How many different Name are in table teacher?","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo determine how many different names are in the `teacher` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column. Here's the SQL code:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM teacher;\n```","cost":0.0004986,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM teacher;","time":3.9534769058}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Age`) FROM `teacher`","question":"How many different Age are in table teacher?","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo determine how many different ages are in the `teacher` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Age) FROM teacher;\n```","cost":0.0005571,"response_parsed":"SELECT COUNT(DISTINCT Age) FROM teacher;","time":4.380089283}} {"db_path":"QATCH-journal\/spider_data\/test_database\/course_teach\/course_teach.sqlite","db_id":"course_teach","tbl_name":"teacher","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Hometown`) FROM `teacher`","question":"How many different Hometown are in table teacher?","db_schema_normalized":"`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))","db_schema":"`\"course\"` (\"Course_ID\" int, \"Staring_Date\" text, \"Course\" text, PRIMARY KEY (\"Course_ID\"))\n`\"teacher\"` (\"Teacher_ID\" int, \"Name\" text, \"Age\" text, \"Hometown\" text, PRIMARY KEY (\"Teacher_ID\"))\n`\"course_arrange\"` (\"Course_ID\" int, \"Teacher_ID\" int, \"Grade\" int, PRIMARY KEY (\"Course_ID\",\"Teacher_ID\",\"Grade\"), FOREIGN KEY (\"Course_ID\") REFERENCES `course`(\"Course_ID\"), FOREIGN KEY (\"Teacher_ID\") REFERENCES `teacher`(\"Teacher_ID\"))","pred_dict":{"response":"\n\nTo determine how many different hometowns are in the `teacher` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Hometown) AS Number_of_Different_Hometowns\nFROM teacher;\n```\n\nThis query will return the number of unique hometowns present in the `Hometown` column of the `teacher` table.","cost":0.0004824,"response_parsed":"SELECT COUNT(DISTINCT Hometown) AS Number_of_Different_Hometowns\nFROM teacher;","time":3.7539219856}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `museum`","question":"Show the different Name in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo show the different names in the `museum` table, you can use the `SELECT DISTINCT` statement to retrieve unique names.\n\n```sql\nSELECT DISTINCT Name FROM museum;\n```","cost":0.0004554,"response_parsed":"SELECT DISTINCT Name FROM museum;","time":3.5907685757}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Open_Year` FROM `museum`","question":"Show the different Open_Year in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the different `Open_Year` values from the `museum` table, you can use the `DISTINCT` keyword to retrieve unique values. Here is the SQL code:\n\n```sql\nSELECT DISTINCT Open_Year FROM museum;\n```","cost":0.0005472,"response_parsed":"SELECT DISTINCT Open_Year FROM museum;","time":4.3026380539}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `visitor_ID` FROM `visit`","question":"Show the different visitor_ID in the table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo retrieve the different `visitor_ID`s from the `visit` table, you can use the `SELECT DISTINCT` statement. Here's the SQL code:\n\n```sql\nSELECT DISTINCT visitor_ID FROM visit;\n```\n\nThis query will return a list of unique `visitor_ID`s present in the `visit` table.","cost":0.00045,"response_parsed":"SELECT DISTINCT visitor_ID FROM visit;","time":3.4201385975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"DISTINCT","sql_tag":"DISTINCT-SINGLE","query":"SELECT DISTINCT `Name` FROM `visitor`","question":"Show the different Name in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo show the different names in the `visitor` table, you can use the `SELECT DISTINCT` statement to retrieve unique names.\n\n```sql\nSELECT DISTINCT Name FROM visitor;\n```","cost":0.0003681,"response_parsed":"SELECT DISTINCT Name FROM visitor;","time":2.6050057411}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `museum` GROUP BY `Name`","question":"For each Name, count the number of rows in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `Name` in the `museum` table, we can use the `COUNT()` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT Name, COUNT(Museum_ID) \nFROM museum \nGROUP BY Name;\n```\n\nThis query will return each unique `Name` from the `museum` table along with the number of rows (museums) associated with that name.","cost":0.0005841,"response_parsed":"SELECT Name, COUNT(Museum_ID) \nFROM museum \nGROUP BY Name;","time":5.1671869755}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Open_Year`, COUNT(*) FROM `museum` GROUP BY `Open_Year`","question":"For each Open_Year, count the number of rows in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo count the number of rows in the `museum` table for each `Open_Year`, you can use the `COUNT()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Open_Year,\n COUNT(Museum_ID) AS Number_of_Museums\nFROM \n museum\nGROUP BY \n Open_Year;\n```\n\nThis query will:\n1. Select the `Open_Year` column.\n2. Count the number of rows (museums) for each `Open_Year` using `COUNT(Museum_ID)`.\n3. Group the results by the `Open_Year` column.\n\nThe result will show the number of museums opened in each year.","cost":0.0006372,"response_parsed":"SELECT \n Open_Year,\n COUNT(Museum_ID) AS Number_of_Museums\nFROM \n museum\nGROUP BY \n Open_Year;","time":5.5036523342}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Num_of_Staff`) FROM `museum` GROUP BY `Name`","question":"For each Name, find the min of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum number of staff for each museum name, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, MIN(Num_of_Staff) AS min_staff\nFROM museum\nGROUP BY Name;\n```\n\nThis query will:\n1. Group the rows in the `museum` table by the `Name` column.\n2. For each group (i.e., for each museum name), it will calculate the minimum value of `Num_of_Staff`.\n3. Return a result set with two columns: `Name` (the museum name) and `min_staff` (the minimum number of staff for that museum name).","cost":0.0006372,"response_parsed":"SELECT Name, MIN(Num_of_Staff) AS min_staff\nFROM museum\nGROUP BY Name;","time":5.8311281204}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Num_of_Staff`) FROM `museum` GROUP BY `Name`","question":"For each Name, find the max of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum number of staff for each museum name, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n MAX(Num_of_Staff) AS Max_Num_of_Staff\nFROM \n museum\nGROUP BY \n Name\nORDER BY \n Max_Num_of_Staff DESC;\n```\n\nThis query will:\n1. Group the rows in your `museum` table by the `Name` column.\n2. Calculate the maximum `Num_of_Staff` for each group (i.e., for each museum name).\n3. Return a result set with two columns: `Name` and `Max_Num_of_Staff`.\n4. Optionally, sort the results in descending order based on `Max_Num_of_Staff`.\n\nYou can remove the `ORDER BY` clause if you don't need the results sorted.","cost":0.000648,"response_parsed":"SELECT \n Name,\n MAX(Num_of_Staff) AS Max_Num_of_Staff\nFROM \n museum\nGROUP BY \n Name\nORDER BY \n Max_Num_of_Staff DESC;","time":6.0488674641}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Num_of_Staff`) FROM `museum` GROUP BY `Name`","question":"For each Name, find the avg of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average number of staff for each museum name, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, AVG(Num_of_Staff) AS Average_Staff\nFROM museum\nGROUP BY Name;\n```\n\nThis query will:\n1. Select the `Name` of the museum.\n2. Calculate the average of `Num_of_Staff` for each museum name.\n3. Group the results by the museum `Name`.\n\nThe result will show the average number of staff for each museum name in your database.","cost":0.0006372,"response_parsed":"SELECT Name, AVG(Num_of_Staff) AS Average_Staff\nFROM museum\nGROUP BY Name;","time":5.375688076}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Num_of_Staff`) FROM `museum` GROUP BY `Name`","question":"For each Name, find the sum of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Num_of_Staff` for each `Name` in the `museum` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Name,\n SUM(Num_of_Staff) AS Total_Staff\nFROM \n museum\nGROUP BY \n Name;\n```\n\nThis query will:\n1. Select the `Name` column.\n2. Calculate the sum of `Num_of_Staff` for each `Name` using `SUM(Num_of_Staff)`.\n3. Group the results by the `Name` column to ensure the sum is calculated for each unique `Name`.\n\nThe result will show each `Name` along with the total number of staff associated with it.","cost":0.0005517,"response_parsed":"SELECT \n Name,\n SUM(Num_of_Staff) AS Total_Staff\nFROM \n museum\nGROUP BY \n Name;","time":4.8080620766}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Open_Year`, MIN(`Num_of_Staff`) FROM `museum` GROUP BY `Open_Year`","question":"For each Open_Year, find the min of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum number of staff for each Open Year in the `museum` table, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT \n Open_Year,\n MIN(Num_of_Staff) AS min_staff\nFROM \n museum\nGROUP BY \n Open_Year;\n```\n\nThis query will return the minimum number of staff for each Open Year in your database.","cost":0.0005436,"response_parsed":"SELECT \n Open_Year,\n MIN(Num_of_Staff) AS min_staff\nFROM \n museum\nGROUP BY \n Open_Year;","time":4.1223037243}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Open_Year`, MAX(`Num_of_Staff`) FROM `museum` GROUP BY `Open_Year`","question":"For each Open_Year, find the max of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum number of staff for each Open Year in the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT \n Open_Year,\n MAX(Num_of_Staff) AS Max_Staff\nFROM \n museum\nGROUP BY \n Open_Year;\n```\n\nThis query will return the maximum number of staff for each Open Year in your database.","cost":0.0005247,"response_parsed":"SELECT \n Open_Year,\n MAX(Num_of_Staff) AS Max_Staff\nFROM \n museum\nGROUP BY \n Open_Year;","time":3.9492900372}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Open_Year`, AVG(`Num_of_Staff`) FROM `museum` GROUP BY `Open_Year`","question":"For each Open_Year, find the avg of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo translate the question into SQL code, we need to calculate the average number of staff for each `Open_Year` in the `museum` table. Here is the SQL code:\n\n```sql\nSELECT Open_Year, AVG(Num_of_Staff) AS Average_Num_of_Staff\nFROM museum\nGROUP BY Open_Year;\n```\n\nThis SQL query will:\n1. Select the `Open_Year` column.\n2. Calculate the average of the `Num_of_Staff` column for each `Open_Year` using the `AVG()` function.\n3. Group the results by the `Open_Year` column using the `GROUP BY` clause.","cost":0.0006732,"response_parsed":"SELECT Open_Year, AVG(Num_of_Staff) AS Average_Num_of_Staff\nFROM museum\nGROUP BY Open_Year;","time":6.2992081642}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Open_Year`, SUM(`Num_of_Staff`) FROM `museum` GROUP BY `Open_Year`","question":"For each Open_Year, find the sum of Num_of_Staff in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the sum of `Num_of_Staff` for each `Open_Year` from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT \n Open_Year AS \"Open Year\",\n SUM(Num_of_Staff) AS \"Total Staff\"\nFROM \n museum\nGROUP BY \n Open_Year\nORDER BY \n Open_Year ASC;\n```\n\nThis query:\n1. Selects the `Open_Year` and calculates the sum of `Num_of_Staff` for each year.\n2. Groups the results by `Open_Year`.\n3. Orders the results by `Open_Year` in ascending order for better readability.","cost":0.0005643,"response_parsed":"SELECT \n Open_Year AS \"Open Year\",\n SUM(Num_of_Staff) AS \"Total Staff\"\nFROM \n museum\nGROUP BY \n Open_Year\nORDER BY \n Open_Year ASC;","time":4.4125928879}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `visitor_ID`, COUNT(*) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, count the number of rows in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each `visitor_ID` in the `visit` table, we can use the `COUNT(*)` function combined with the `GROUP BY` clause. This will group the rows by `visitor_ID` and count the occurrences for each group.\n\n```sql\nSELECT visitor_ID, COUNT(*) AS count_of_visits FROM visit GROUP BY visitor_ID;\n```","cost":0.0007308,"response_parsed":"SELECT visitor_ID, COUNT(*) AS count_of_visits FROM visit GROUP BY visitor_ID;","time":6.3655674458}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `visitor_ID`, MIN(`Num_of_Ticket`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the min of Num_of_Ticket in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum number of tickets purchased by each visitor, you can use the SQL `MIN()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n visitor_ID,\n MIN(Num_of_Ticket) AS min_num_of_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;\n```\n\nThis query will return the minimum number of tickets purchased by each visitor.","cost":0.0005481,"response_parsed":"SELECT \n visitor_ID,\n MIN(Num_of_Ticket) AS min_num_of_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;","time":4.138969183}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `visitor_ID`, MAX(`Num_of_Ticket`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the max of Num_of_Ticket in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum number of tickets purchased by each visitor, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n visitor_ID,\n MAX(Num_of_Ticket) AS max_num_of_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;\n```\n\nThis query will return the maximum number of tickets purchased by each visitor, grouped by their `visitor_ID`.","cost":0.000603,"response_parsed":"SELECT \n visitor_ID,\n MAX(Num_of_Ticket) AS max_num_of_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;","time":4.7825512886}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `visitor_ID`, AVG(`Num_of_Ticket`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the avg of Num_of_Ticket in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average number of tickets for each visitor, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n visitor_ID,\n AVG(Num_of_Ticket) AS avg_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;\n```\n\nThis query will:\n1. Select the `visitor_ID` and the average of `Num_of_Ticket` for each visitor.\n2. Group the results by `visitor_ID`.\n3. Return a table with two columns: `visitor_ID` and `avg_tickets` (the average number of tickets for each visitor).","cost":0.00072,"response_parsed":"SELECT \n visitor_ID,\n AVG(Num_of_Ticket) AS avg_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;","time":6.2394678593}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `visitor_ID`, SUM(`Num_of_Ticket`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the sum of Num_of_Ticket in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to calculate the sum of `Num_of_Ticket` for each `visitor_ID` in the `visit` table. Here's the SQL code to achieve this:\n\n```sql\nSELECT \n visitor_ID,\n SUM(Num_of_Ticket) AS total_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;\n```\n\nThis query will return the total number of tickets purchased by each visitor.","cost":0.0006075,"response_parsed":"SELECT \n visitor_ID,\n SUM(Num_of_Ticket) AS total_tickets\nFROM \n visit\nGROUP BY \n visitor_ID;","time":5.1472682953}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `visitor_ID`, MIN(`Total_spent`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the min of Total_spent in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum Total_spent for each visitor_ID in the visit table, we can use the SQL `MIN()` function combined with `GROUP BY` to group the results by visitor_ID.\n\n```sql\nSELECT visitor_ID, MIN(Total_spent) AS min_Total_spent\nFROM visit\nGROUP BY visitor_ID;\n```","cost":0.0005787,"response_parsed":"SELECT visitor_ID, MIN(Total_spent) AS min_Total_spent\nFROM visit\nGROUP BY visitor_ID;","time":4.7140350342}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `visitor_ID`, MAX(`Total_spent`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the max of Total_spent in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Total_spent` for each `visitor_ID` in the `visit` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n visitor_ID,\n MAX(Total_spent) AS max_total_spent\nFROM \n visit\nGROUP BY \n visitor_ID;\n```\n\nThis query will return the maximum amount spent (`max_total_spent`) for each unique `visitor_ID` in the `visit` table.","cost":0.0008037,"response_parsed":"SELECT \n visitor_ID,\n MAX(Total_spent) AS max_total_spent\nFROM \n visit\nGROUP BY \n visitor_ID;","time":7.3880953789}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `visitor_ID`, AVG(`Total_spent`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the avg of Total_spent in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average Total_spent for each visitor_ID, we use the AVG() function and group the results by visitor_ID.\n\n```sql\nSELECT visitor_ID, AVG(Total_spent) FROM visit GROUP BY visitor_ID;\n```","cost":0.0006138,"response_parsed":"SELECT visitor_ID, AVG(Total_spent) FROM visit GROUP BY visitor_ID;","time":4.9942805767}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `visitor_ID`, SUM(`Total_spent`) FROM `visit` GROUP BY `visitor_ID`","question":"For each visitor_ID, find the sum of Total_spent in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the sum of `Total_spent` for each `visitor_ID` from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID, SUM(Total_spent) AS total_spent_per_visitor\nFROM visit\nGROUP BY visitor_ID;\n```","cost":0.0005454,"response_parsed":"SELECT visitor_ID, SUM(Total_spent) AS total_spent_per_visitor\nFROM visit\nGROUP BY visitor_ID;","time":4.5768339634}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-COUNT","query":"SELECT `Name`, COUNT(*) FROM `visitor` GROUP BY `Name`","question":"For each Name, count the number of rows in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo count the number of rows for each Name in the `visitor` table, you can use the SQL `COUNT()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Name, COUNT(*) \nFROM visitor \nGROUP BY Name;\n```\n\nThis query will return each unique `Name` from the `visitor` table along with the number of rows (records) associated with that name.","cost":0.0005121,"response_parsed":"SELECT Name, COUNT(*) \nFROM visitor \nGROUP BY Name;","time":4.1538176537}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Level_of_membership`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the min of Level_of_membership in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum `Level_of_membership` for each `Name` in the `visitor` table, you can use the SQL `MIN` function combined with `GROUP BY`. Here's how you can do it:\n\n```sql\nSELECT Name, MIN(Level_of_membership) AS min_level\nFROM visitor\nGROUP BY Name;\n```\n\nThis query will return the minimum `Level_of_membership` for each unique `Name` in your `visitor` table.","cost":0.0005697,"response_parsed":"SELECT Name, MIN(Level_of_membership) AS min_level\nFROM visitor\nGROUP BY Name;","time":4.6956012249}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Level_of_membership`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the max of Level_of_membership in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Level_of_membership` for each `Name` in the `visitor` table, you can use the SQL `MAX` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n MAX(Level_of_membership) AS max_level\nFROM \n visitor\nGROUP BY \n Name;\n```\n\nThis query will return the maximum `Level_of_membership` for each unique `Name` in your `visitor` table.","cost":0.0005292,"response_parsed":"SELECT \n Name,\n MAX(Level_of_membership) AS max_level\nFROM \n visitor\nGROUP BY \n Name;","time":4.3084082603}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Level_of_membership`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the avg of Level_of_membership in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average `Level_of_membership` for each `Name` in the `visitor` table, you can use the SQL `AVG()` function combined with `GROUP BY`. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n AVG(Level_of_membership) AS average_level\nFROM \n visitor\nGROUP BY \n Name;\n```\n\nThis query will return the average `Level_of_membership` for each unique `Name` in your `visitor` table.","cost":0.0005103,"response_parsed":"SELECT \n Name,\n AVG(Level_of_membership) AS average_level\nFROM \n visitor\nGROUP BY \n Name;","time":3.9025273323}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Level_of_membership`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the sum of Level_of_membership in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Level_of_membership` for each `Name` in the `visitor` table, you can use the SQL `SUM()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n SUM(Level_of_membership) AS total_level\nFROM \n visitor\nGROUP BY \n Name;\n```\n\nThis query will:\n1. Select the `Name` column and calculate the sum of `Level_of_membership` for each name.\n2. Group the results by the `Name` column to ensure the sum is calculated for each unique name.\n3. The result will show each name along with their total `Level_of_membership`.\n\nYou can execute this SQL code on your database to get the desired result.","cost":0.0005814,"response_parsed":"SELECT \n Name,\n SUM(Level_of_membership) AS total_level\nFROM \n visitor\nGROUP BY \n Name;","time":5.1810467243}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MIN","query":"SELECT `Name`, MIN(`Age`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the min of Age in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum Age for each Name in the `visitor` table, we can use the `MIN` function combined with `GROUP BY`. Here's the SQL code:\n\n```sql\nSELECT Name, MIN(Age) AS min_age\nFROM visitor\nGROUP BY Name;\n```","cost":0.0005004,"response_parsed":"SELECT Name, MIN(Age) AS min_age\nFROM visitor\nGROUP BY Name;","time":3.8807916641}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-MAX","query":"SELECT `Name`, MAX(`Age`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the max of Age in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum age for each name in the `visitor` table, you can use the SQL `MAX()` function combined with the `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT \n Name,\n MAX(Age) AS Max_Age\nFROM \n visitor\nGROUP BY \n Name;\n```\n\nThis query will return each unique `Name` along with their maximum `Age` from the `visitor` table.","cost":0.0004986,"response_parsed":"SELECT \n Name,\n MAX(Age) AS Max_Age\nFROM \n visitor\nGROUP BY \n Name;","time":3.6580579281}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-AVG","query":"SELECT `Name`, AVG(`Age`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the avg of Age in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average age for each name in the `visitor` table, you can use the SQL `AVG()` function combined with the `GROUP BY` clause. Here's the SQL code:\n\n```sql\nSELECT Name, AVG(Age) AS avg_age\nFROM visitor\nGROUP BY Name;\n```\n\nThis query will:\n1. Group all rows in the `visitor` table by the `Name` column.\n2. Calculate the average age for each group (each unique name).\n3. Return a result set with two columns: `Name` and `avg_age` (the average age for that name).","cost":0.0005733,"response_parsed":"SELECT Name, AVG(Age) AS avg_age\nFROM visitor\nGROUP BY Name;","time":4.5819544792}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"GROUPBY","sql_tag":"GROUPBY-AGG-SUM","query":"SELECT `Name`, SUM(`Age`) FROM `visitor` GROUP BY `Name`","question":"For each Name, find the sum of Age in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the sum of `Age` for each `Name` in the `visitor` table, you can use the SQL `GROUP BY` clause. Here's how you can do it:\n\n```sql\nSELECT Name, SUM(Age) AS Total_Age\nFROM visitor\nGROUP BY Name;\n```\n\nThis query will:\n1. Select the `Name` column\n2. Calculate the sum of the `Age` column for each group of rows with the same `Name`\n3. Group the results by the `Name` column\n4. Return the results with the sum of ages for each name\n\nThe result will show each unique `Name` along with the total sum of their ages.","cost":0.0006237,"response_parsed":"SELECT Name, SUM(Age) AS Total_Age\nFROM visitor\nGROUP BY Name;","time":5.3427624702}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all the names that have at least one record in the `museum` table, we can use a simple `SELECT` statement with the `DISTINCT` keyword to ensure each name appears only once.\n\n```sql\nSELECT DISTINCT Name FROM museum;\n```","cost":0.0005193,"response_parsed":"SELECT DISTINCT Name FROM museum;","time":4.1682610512}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all the names in the `museum` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM museum\nGROUP BY Name\nHAVING COUNT(*) <= 1;\n```\n\nThis query will:\n1. Group the records in the `museum` table by the `Name` column.\n2. Count the number of records for each `Name`.\n3. Return only those `Name`s that have 1 or fewer records.","cost":0.0005013,"response_parsed":"SELECT Name\nFROM museum\nGROUP BY Name\nHAVING COUNT(*) <= 1;","time":4.3740162849}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING count(*) >= 1","question":"Find all the Open_Year that have at least 1 records in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all the `Open_Year` values that have at least one record in the `museum` table, you can use the `SELECT DISTINCT` statement to fetch unique `Open_Year` values.\n\n```sql\nSELECT DISTINCT Open_Year FROM museum;\n```","cost":0.0004932,"response_parsed":"SELECT DISTINCT Open_Year FROM museum;","time":3.9488248825}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING count(*) <= 1","question":"Find all the Open_Year that have at most 1 records in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all `Open_Year` values in the `museum` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING COUNT(*) <= 1;\n```\n\nThis query:\n1. Groups the records in the `museum` table by the `Open_Year` column.\n2. Counts the number of records in each group using `COUNT(*)`.\n3. Filters the groups to include only those with a count of 1 or less using `HAVING COUNT(*) <= 1`.\n\nThe result will be a list of `Open_Year` values that appear at most once in the `museum` table.","cost":0.0005607,"response_parsed":"SELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING COUNT(*) <= 1;","time":4.5767345428}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING AVG(`Num_of_Staff`) >= 22.62","question":"List the Name which average of Num_of_Staff is at least 22.62 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Name which average of Num_of_Staff is at least 22.62 in table museum,\" we can use the following SQL query:\n\n```sql\nSELECT Name \nFROM museum \nWHERE Num_of_Staff >= 22.62;\n```\n\nThis query selects the `Name` of museums from the `museum` table where the `Num_of_Staff` is at least 22.62.","cost":0.0006525,"response_parsed":"SELECT Name \nFROM museum \nWHERE Num_of_Staff >= 22.62;","time":5.3545117378}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING AVG(`Num_of_Staff`) <= 22.62","question":"List the Name which average of Num_of_Staff is at most 22.62 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the names of museums where the average number of staff is at most 22.62. Here's the SQL code to achieve this:\n\n```sql\nSELECT Name \nFROM \"museum\" \nWHERE AVG(Num_of_Staff) <= 22.62;\n```\n\nThis query selects the `Name` of museums from the `museum` table where the average of `Num_of_Staff` is less than or equal to 22.62.","cost":0.0006831,"response_parsed":"SELECT Name \nFROM \"museum\" \nWHERE AVG(Num_of_Staff) <= 22.62;","time":5.6713869572}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING SUM(`Num_of_Staff`) >= 22.62","question":"List the Name which summation of Num_of_Staff is at least 22.62 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the names of museums where the sum of `Num_of_Staff` is at least 22.62, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM museum\nWHERE Num_of_Staff >= 22.62;\n```\n\nThis query will return the names of museums where the number of staff meets or exceeds the specified threshold.","cost":0.0008802,"response_parsed":"SELECT Name\nFROM museum\nWHERE Num_of_Staff >= 22.62;","time":8.0957217216}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `museum` GROUP BY `Name` HAVING SUM(`Num_of_Staff`) <= 22.62","question":"List the Name which summation of Num_of_Staff is at most 22.62 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question \"List the Name which summation of Num_of_Staff is at most 22.62 in table museum,\" we need to write an SQL query that:\n\n1. Selects the `Name` from the `museum` table.\n2. Filters the results to include only those rows where the `Num_of_Staff` is at most 22.62.\n\nHere is the SQL code:\n\n```sql\nSELECT Name\nFROM museum\nWHERE Num_of_Staff <= 22.62;\n```\n\nThis query will return the names of museums where the number of staff is 22.62 or fewer.","cost":0.000612,"response_parsed":"SELECT Name\nFROM museum\nWHERE Num_of_Staff <= 22.62;","time":5.1665785313}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING AVG(`Num_of_Staff`) >= 24.75","question":"List the Open_Year which average of Num_of_Staff is at least 24.75 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `Open_Year` where the average of `Num_of_Staff` is at least 24.75, you can use the following SQL query:\n\n```sql\nSELECT Open_Year, AVG(Num_of_Staff) AS Avg_Staff\nFROM museum\nGROUP BY Open_Year\nHAVING AVG(Num_of_Staff) >= 24.75;\n```\n\nThis query:\n1. Groups the data by `Open_Year`.\n2. Calculates the average of `Num_of_Staff` for each group.\n3. Filters the results to include only those groups where the average is at least 24.75.","cost":0.0005796,"response_parsed":"SELECT Open_Year, AVG(Num_of_Staff) AS Avg_Staff\nFROM museum\nGROUP BY Open_Year\nHAVING AVG(Num_of_Staff) >= 24.75;","time":4.5060036182}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING AVG(`Num_of_Staff`) <= 24.75","question":"List the Open_Year which average of Num_of_Staff is at most 24.75 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that calculates the average of `Num_of_Staff` for each `Open_Year` in the `museum` table and then filters the results to include only those `Open_Year` values where the average is less than or equal to 24.75.\n\nHere is the SQL code:\n\n```sql\nSELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING AVG(Num_of_Staff) <= 24.75;\n```\n\n### Explanation:\n1. **`SELECT Open_Year`**: This selects the `Open_Year` column that we want to display in the final result.\n2. **`FROM museum`**: This specifies the table from which to retrieve the data, which is the `museum` table.\n3. **`GROUP BY Open_Year`**: This groups the rows in the table by the `Open_Year` column, allowing us to calculate the average `Num_of_Staff` for each year.\n4. **`HAVING AVG(Num_of_Staff) <= 24.75`**: This filters the grouped results to include only those `Open_Year` values where the average `Num_of_Staff` is less than or equal to 24.75.\n\nThis query will return a list of `Open_Year` values where the average number of staff is at most 24.75.","cost":0.0007587,"response_parsed":"SELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING AVG(Num_of_Staff) <= 24.75;","time":6.6278071404}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING SUM(`Num_of_Staff`) >= 30.17","question":"List the Open_Year which summation of Num_of_Staff is at least 30.17 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Num_of_Staff` for each `Open_Year` in the `museum` table and return the `Open_Year` where the summation is at least 30.17.\n\nHere is the SQL code:\n\n```sql\nSELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING SUM(Num_of_Staff) >= 30.17;\n```\n\n### Explanation:\n1. **SELECT Open_Year**: This selects the `Open_Year` column that we want to retrieve.\n2. **FROM museum**: This specifies the table from which to retrieve the data.\n3. **GROUP BY Open_Year**: This groups the rows by the `Open_Year` column, allowing us to aggregate data for each year.\n4. **HAVING SUM(Num_of_Staff) >= 30.17**: This filters the grouped results to only include those years where the sum of `Num_of_Staff` is at least 30.17.\n\nThis query will return the `Open_Year` values where the total number of staff is 30.17 or more.","cost":0.0008037,"response_parsed":"SELECT Open_Year\nFROM museum\nGROUP BY Open_Year\nHAVING SUM(Num_of_Staff) >= 30.17;","time":7.046582222}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Open_Year` FROM `museum` GROUP BY `Open_Year` HAVING SUM(`Num_of_Staff`) <= 30.17","question":"List the Open_Year which summation of Num_of_Staff is at most 30.17 in table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that will sum the `Num_of_Staff` for each `Open_Year` in the `museum` table and then filter the results to include only those `Open_Year` values where the total `Num_of_Staff` is at most 30.17.\n\nHere is the SQL code to achieve this:\n\n```sql\nSELECT \n Open_Year,\n SUM(Num_of_Staff) AS Total_Staff\nFROM \n museum\nGROUP BY \n Open_Year\nHAVING \n SUM(Num_of_Staff) <= 30.17;\n```\n\n### Explanation:\n1. **SELECT Clause**: We select the `Open_Year` column and calculate the sum of `Num_of_Staff` for each `Open_Year`, aliasing the sum as `Total_Staff` for clarity.\n2. **FROM Clause**: We specify the `museum` table as the source of data.\n3. **GROUP BY Clause**: We group the results by the `Open_Year` column to aggregate the `Num_of_Staff` values by year.\n4. **HAVING Clause**: We filter the grouped results to include only those `Open_Year` values where the sum of `Num_of_Staff` is less than or equal to 30.17.\n\nThis query will return the `Open_Year` and the corresponding total staff count for the years where the total staff is at most 30.17.","cost":0.0006804,"response_parsed":"SELECT \n Open_Year,\n SUM(Num_of_Staff) AS Total_Staff\nFROM \n museum\nGROUP BY \n Open_Year\nHAVING \n SUM(Num_of_Staff) <= 30.17;","time":5.2359848022}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING count(*) >= 2","question":"Find all the visitor_ID that have at least 2 records in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all `visitor_ID`s that have at least 2 records in the `visit` table, you can use the `COUNT` function combined with `GROUP BY` and `HAVING` clauses. Here's the SQL code:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING COUNT(visitor_ID) >= 2;\n```\n\nThis query:\n1. Selects the `visitor_ID` from the `visit` table\n2. Groups the results by `visitor_ID`\n3. Filters the groups to include only those with at least 2 records using `HAVING COUNT(visitor_ID) >= 2`","cost":0.0005418,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING COUNT(visitor_ID) >= 2;","time":4.3699040413}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING count(*) <= 2","question":"Find all the visitor_ID that have at most 2 records in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all `visitor_ID`s that have at most 2 records in the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING COUNT(visitor_ID) <= 2;\n```\n\nThis query:\n1. Selects the `visitor_ID` from the `visit` table.\n2. Groups the results by `visitor_ID`.\n3. Filters the groups to include only those with 2 or fewer records using the `HAVING COUNT(visitor_ID) <= 2` condition.","cost":0.0005823,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING COUNT(visitor_ID) <= 2;","time":4.6755862236}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING AVG(`Num_of_Ticket`) >= 10.5","question":"List the visitor_ID which average of Num_of_Ticket is at least 10.5 in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the visitor_IDs where the average of Num_of_Ticket is at least 10.5, you can use the SQL `AVG()` function along with the `GROUP BY` and `HAVING` clauses. Here's the SQL code:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING AVG(Num_of_Ticket) >= 10.5;\n```\n\nThis query will:\n1. Group the rows in the `visit` table by `visitor_ID`.\n2. Calculate the average of `Num_of_Ticket` for each group.\n3. Return only those `visitor_ID`s where the average `Num_of_Ticket` is at least 10.5.","cost":0.0007326,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING AVG(Num_of_Ticket) >= 10.5;","time":6.5258629322}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING AVG(`Num_of_Ticket`) <= 10.5","question":"List the visitor_ID which average of Num_of_Ticket is at most 10.5 in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to fetch the `visitor_ID` from the `visit` table where the average of `Num_of_Ticket` is at most 10.5. Here's the SQL code to achieve this:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING AVG(Num_of_Ticket) <= 10.5;\n```\n\n### Explanation:\n1. **SELECT visitor_ID**: We are selecting the `visitor_ID` from the `visit` table.\n2. **FROM visit**: We are querying the `visit` table.\n3. **GROUP BY visitor_ID**: We group the records by `visitor_ID` to calculate the average `Num_of_Ticket` for each visitor.\n4. **HAVING AVG(Num_of_Ticket) <= 10.5**: We filter the groups to include only those where the average `Num_of_Ticket` is at most 10.5.\n\nThis query will return the `visitor_ID` values that meet the specified condition.","cost":0.0007767,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING AVG(Num_of_Ticket) <= 10.5;","time":6.5783288479}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING SUM(`Num_of_Ticket`) >= 21.0","question":"List the visitor_ID which summation of Num_of_Ticket is at least 21.0 in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo answer the question, we need to write an SQL query that retrieves the `visitor_ID` from the `visit` table where the sum of `Num_of_Ticket` is at least 21.0.\n\nHere is the SQL code:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING SUM(Num_of_Ticket) >= 21.0;\n```\n\nThis query:\n1. Selects the `visitor_ID` from the `visit` table.\n2. Groups the results by `visitor_ID` to aggregate the data for each visitor.\n3. Uses the `HAVING` clause to filter the results and only include visitors where the sum of `Num_of_Ticket` is at least 21.0.","cost":0.0007146,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING SUM(Num_of_Ticket) >= 21.0;","time":6.0165481567}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `visitor_ID` FROM `visit` GROUP BY `visitor_ID` HAVING SUM(`Num_of_Ticket`) <= 21.0","question":"List the visitor_ID which summation of Num_of_Ticket is at most 21.0 in table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID` where the sum of `Num_of_Ticket` is at most 21.0, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING SUM(Num_of_Ticket) <= 21.0;\n```\n\nThis query:\n1. Selects the `visitor_ID` from the `visit` table.\n2. Groups the results by `visitor_ID`.\n3. Filters the groups where the sum of `Num_of_Ticket` is less than or equal to 21.0.","cost":0.0005742,"response_parsed":"SELECT visitor_ID\nFROM visit\nGROUP BY visitor_ID\nHAVING SUM(Num_of_Ticket) <= 21.0;","time":4.5874328613}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING count(*) >= 1","question":"Find all the Name that have at least 1 records in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all Museum Names that have at least one visitor, we'll join the `museum` and `visit` tables on `Museum_ID` and select the distinct Names.\n\n```sql\nSELECT DISTINCT m.Name \nFROM museum m\nJOIN visit v ON m.Museum_ID = v.Museum_ID;\n```","cost":0.000576,"response_parsed":"SELECT DISTINCT m.Name \nFROM museum m\nJOIN visit v ON m.Museum_ID = v.Museum_ID;","time":4.9434056282}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-COUNT","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING count(*) <= 1","question":"Find all the Name that have at most 1 records in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find all the Names in the `visitor` table that have at most 1 record, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM visitor\nGROUP BY Name\nHAVING COUNT(*) <= 1;\n```\n\nThis query will:\n1. Group the records in the `visitor` table by the `Name` column.\n2. Count the number of records for each `Name`.\n3. Return only those `Name`s that have 1 or fewer records.\n\n```sql\nSELECT Name\nFROM visitor\nGROUP BY Name\nHAVING COUNT(*) <= 1;\n```","cost":0.0005139,"response_parsed":"SELECT Name\nFROM visitor\nGROUP BY Name\nHAVING COUNT(*) <= 1;","time":3.7421705723}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING AVG(`Level_of_membership`) >= 3.83","question":"List the Name which average of Level_of_membership is at least 3.83 in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the names of visitors where the average `Level_of_membership` is at least 3.83, we can use the following SQL query:\n\n```sql\nSELECT Name \nFROM visitor \nWHERE Level_of_membership >= 3.83;\n```\n\nThis query selects the `Name` from the `visitor` table where the `Level_of_membership` is at least 3.83.","cost":0.0013203,"response_parsed":"SELECT Name \nFROM visitor \nWHERE Level_of_membership >= 3.83;","time":12.8692703247}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-AGG-AVG","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING AVG(`Level_of_membership`) <= 3.83","question":"List the Name which average of Level_of_membership is at most 3.83 in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the names of visitors whose average `Level_of_membership` is at most 3.83, you can use the following SQL query:\n\n```sql\nSELECT Name\nFROM visitor\nGROUP BY Name\nHAVING AVG(Level_of_membership) <= 3.83;\n```\n\nThis query:\n1. Groups the `visitor` table by the `Name` column.\n2. Calculates the average `Level_of_membership` for each group.\n3. Filters the results to include only those groups where the average `Level_of_membership` is less than or equal to 3.83.","cost":0.0005931,"response_parsed":"SELECT Name\nFROM visitor\nGROUP BY Name\nHAVING AVG(Level_of_membership) <= 3.83;","time":5.6797516346}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING SUM(`Level_of_membership`) >= 3.83","question":"List the Name which summation of Level_of_membership is at least 3.83 in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the names of visitors whose total `Level_of_membership` is at least 3.83, you can use the following SQL query:\n\n```sql\nSELECT Name FROM visitor WHERE Level_of_membership >= 3.83;\n```\n\nThis query will return the names of all visitors whose `Level_of_membership` is 3.83 or higher.","cost":0.0012483,"response_parsed":"SELECT Name FROM visitor WHERE Level_of_membership >= 3.83;","time":12.6240367889}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"HAVING","sql_tag":"HAVING-AGG-SUM","query":"SELECT `Name` FROM `visitor` GROUP BY `Name` HAVING SUM(`Level_of_membership`) <= 3.83","question":"List the Name which summation of Level_of_membership is at most 3.83 in table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the names of visitors where the sum of their `Level_of_membership` is at most 3.83, you can use the following SQL query:\n\n```sql\nSELECT Name FROM visitor WHERE Level_of_membership <= 3.83;\n```\n\nThis query will return the names of visitors whose `Level_of_membership` value is less than or equal to 3.83.","cost":0.0010116,"response_parsed":"SELECT Name FROM visitor WHERE Level_of_membership <= 3.83;","time":9.3425240517}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `visit` AS T1 JOIN `museum` AS T2 ON T1.`Museum_ID` = T2.`Museum_ID`","question":"Join all the records from table visit with table museum on Museum_ID","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo join all records from the `visit` table with the `museum` table based on the `Museum_ID`, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nINNER JOIN museum\nON visit.Museum_ID = museum.Museum_ID;\n```\n\nThis query will return all columns (`*`) from both the `visit` and `museum` tables where the `Museum_ID` matches in both tables.","cost":0.0005697,"response_parsed":"SELECT *\nFROM visit\nINNER JOIN museum\nON visit.Museum_ID = museum.Museum_ID;","time":5.03226614}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-ALL","query":"SELECT * FROM `visit` AS T1 JOIN `visitor` AS T2 ON T1.`visitor_ID` = T2.`ID`","question":"Join all the records from table visit with table visitor on visitor_ID","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo join all records from the `visit` table with the `visitor` table on the `visitor_ID` field, you can use the following SQL query:\n\n```sql\nSELECT v.*, i.*\nFROM visit i\nINNER JOIN visitor v\nON i.visitor_ID = v.ID;\n```\n\nThis SQL code performs an inner join between the `visit` and `visitor` tables based on the `visitor_ID` field, which is common to both tables. The result will include all columns from both tables where there is a match.","cost":0.0005778,"response_parsed":"SELECT v.*, i.*\nFROM visit i\nINNER JOIN visitor v\nON i.visitor_ID = v.ID;","time":4.9702386856}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`visitor_ID`, T2.`Name` FROM `visit` AS T1 JOIN `museum` AS T2 ON T1.`Museum_ID`=T2.`Museum_ID`","question":"List all the visitor_ID and Name from the table visit and the table museum where Museum_ID is the same","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID` and `Name` from the `visit` and `museum` tables where the `Museum_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT v.visitor_ID, vis.Name\nFROM visit v\nJOIN museum m ON v.Museum_ID = m.Museum_ID;\n```\n\nThis query will join the `visit` table with the `museum` table based on the `Museum_ID` and return the `visitor_ID` and `Name` from the `visit` table.","cost":0.0006804,"response_parsed":"SELECT v.visitor_ID, vis.Name\nFROM visit v\nJOIN museum m ON v.Museum_ID = m.Museum_ID;","time":6.1449697018}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"INNER-JOIN","sql_tag":"JOIN-PROJECT-CAT","query":"SELECT T1.`visitor_ID`, T2.`Open_Year` FROM `visit` AS T1 JOIN `museum` AS T2 ON T1.`Museum_ID`=T2.`Museum_ID`","question":"List all the visitor_ID and Open_Year from the table visit and the table museum where Museum_ID is the same","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID` and `Open_Year` from the `visit` and `museum` tables where the `Museum_ID` is the same, you can use the following SQL query:\n\n```sql\nSELECT v.visitor_ID, m.Open_Year\nFROM visit v\nINNER JOIN museum m\nON v.Museum_ID = m.Museum_ID;\n```\n\nThis query:\n1. Selects the `visitor_ID` from the `visit` table and `Open_Year` from the `museum` table.\n2. Uses an `INNER JOIN` to combine rows from the `visit` and `museum` tables where the `Museum_ID` is the same in both tables.","cost":0.0007848,"response_parsed":"SELECT v.visitor_ID, m.Open_Year\nFROM visit v\nINNER JOIN museum m\nON v.Museum_ID = m.Museum_ID;","time":6.4637691975}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `museum` ORDER BY `Open_Year` ASC","question":"Show all data ordered by Open_Year in ascending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `museum` table ordered by the `Open_Year` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM \"museum\" ORDER BY Open_Year ASC;\n```","cost":0.0005094,"response_parsed":"SELECT * FROM \"museum\" ORDER BY Open_Year ASC;","time":4.2474591732}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `museum` ORDER BY `Open_Year` DESC","question":"Show all data ordered by Open_Year in descending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `museum` table ordered by `Open_Year` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum ORDER BY Open_Year DESC;\n```","cost":0.0005391,"response_parsed":"SELECT * FROM museum ORDER BY Open_Year DESC;","time":4.2066197395}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `museum` ORDER BY `Name` ASC","question":"Show all data ordered by Name in ascending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `museum` table ordered by the `Name` column in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum ORDER BY Name ASC;\n```","cost":0.0004257,"response_parsed":"SELECT * FROM museum ORDER BY Name ASC;","time":2.8224589825}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `museum` ORDER BY `Name` DESC","question":"Show all data ordered by Name in descending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `museum` table ordered by the `Name` column in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM \"museum\" ORDER BY Name DESC;\n```","cost":0.0004374,"response_parsed":"SELECT * FROM \"museum\" ORDER BY Name DESC;","time":3.2717797756}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Museum_ID` FROM `museum` ORDER BY `Museum_ID` ASC","question":"Project the Museum_ID ordered in ascending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Museum_ID` from the `museum` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID\nFROM museum\nORDER BY Museum_ID ASC;\n```\n\nThis query selects the `Museum_ID` column from the `museum` table and sorts the results in ascending order based on `Museum_ID`.","cost":0.000441,"response_parsed":"SELECT Museum_ID\nFROM museum\nORDER BY Museum_ID ASC;","time":3.089168787}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Museum_ID` FROM `museum` ORDER BY `Museum_ID` DESC","question":"Project the Museum_ID ordered in descending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Museum_ID` from the `museum` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID FROM museum ORDER BY Museum_ID DESC;\n```","cost":0.0004077,"response_parsed":"SELECT Museum_ID FROM museum ORDER BY Museum_ID DESC;","time":2.9332232475}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Open_Year` FROM `museum` ORDER BY `Open_Year` ASC","question":"Project the Open_Year ordered in ascending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Open_Year` from the `museum` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Open_Year\nFROM museum\nORDER BY Open_Year ASC;\n```","cost":0.0004617,"response_parsed":"SELECT Open_Year\nFROM museum\nORDER BY Open_Year ASC;","time":3.1159613132}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Open_Year` FROM `museum` ORDER BY `Open_Year` DESC","question":"Project the Open_Year ordered in descending order for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Open_Year` from the `museum` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Open_Year\nFROM museum\nORDER BY Open_Year DESC;\n```","cost":0.0004959,"response_parsed":"SELECT Open_Year\nFROM museum\nORDER BY Open_Year DESC;","time":4.0060207844}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visit` ORDER BY `Museum_ID` ASC","question":"Show all data ordered by Museum_ID in ascending order for the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visit` table ordered by `Museum_ID` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nORDER BY Museum_ID ASC;\n```\n\nThis query will:\n1. Select all columns (`*`) from the `visit` table.\n2. Order the results by the `Museum_ID` column in ascending order.","cost":0.0004563,"response_parsed":"SELECT *\nFROM visit\nORDER BY Museum_ID ASC;","time":3.4892961979}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visit` ORDER BY `Museum_ID` DESC","question":"Show all data ordered by Museum_ID in descending order for the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visit` table ordered by `Museum_ID` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM visit ORDER BY Museum_ID DESC;\n```","cost":0.0004239,"response_parsed":"SELECT * FROM visit ORDER BY Museum_ID DESC;","time":2.940397501}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visit` ORDER BY `Num_of_Ticket` ASC","question":"Show all data ordered by Num_of_Ticket in ascending order for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visit` table ordered by `Num_of_Ticket` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM visit ORDER BY Num_of_Ticket ASC;\n```","cost":0.0006039,"response_parsed":"SELECT * FROM visit ORDER BY Num_of_Ticket ASC;","time":5.0770409107}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visit` ORDER BY `Num_of_Ticket` DESC","question":"Show all data ordered by Num_of_Ticket in descending order for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visit` table ordered by `Num_of_Ticket` in descending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM `visit` ORDER BY Num_of_Ticket DESC;\n```","cost":0.0006165,"response_parsed":"SELECT * FROM `visit` ORDER BY Num_of_Ticket DESC;","time":5.2006742954}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Museum_ID` FROM `visit` ORDER BY `Museum_ID` ASC","question":"Project the Museum_ID ordered in ascending order for the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Museum_ID` from the `visit` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID\nFROM visit\nORDER BY Museum_ID ASC;\n```\n\nThis query will return a list of `Museum_ID` values sorted in ascending order.","cost":0.0004797,"response_parsed":"SELECT Museum_ID\nFROM visit\nORDER BY Museum_ID ASC;","time":3.78226614}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Museum_ID` FROM `visit` ORDER BY `Museum_ID` DESC","question":"Project the Museum_ID ordered in descending order for the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Museum_ID` from the `visit` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID\nFROM visit\nORDER BY Museum_ID DESC;\n```\n\nThis query selects the `Museum_ID` column from the `visit` table and sorts the results in descending order based on the `Museum_ID`.","cost":0.0004545,"response_parsed":"SELECT Museum_ID\nFROM visit\nORDER BY Museum_ID DESC;","time":3.3442983627}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `visitor_ID` FROM `visit` ORDER BY `visitor_ID` ASC","question":"Project the visitor_ID ordered in ascending order for the table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID` from the `visit` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID FROM visit ORDER BY visitor_ID ASC;\n```","cost":0.0006066,"response_parsed":"SELECT visitor_ID FROM visit ORDER BY visitor_ID ASC;","time":5.2548949718}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `visitor_ID` FROM `visit` ORDER BY `visitor_ID` DESC","question":"Project the visitor_ID ordered in descending order for the table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID` from the `visit` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID FROM visit ORDER BY visitor_ID DESC;\n```","cost":0.0005508,"response_parsed":"SELECT visitor_ID FROM visit ORDER BY visitor_ID DESC;","time":4.4251723289}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visitor` ORDER BY `Level_of_membership` ASC","question":"Show all data ordered by Level_of_membership in ascending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visitor` table ordered by `Level_of_membership` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT * FROM visitor ORDER BY Level_of_membership ASC;\n```","cost":0.0004779,"response_parsed":"SELECT * FROM visitor ORDER BY Level_of_membership ASC;","time":3.7130556107}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visitor` ORDER BY `Level_of_membership` DESC","question":"Show all data ordered by Level_of_membership in descending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visitor` table ordered by `Level_of_membership` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nORDER BY Level_of_membership DESC;\n```","cost":0.0004662,"response_parsed":"SELECT *\nFROM visitor\nORDER BY Level_of_membership DESC;","time":3.4616580009}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visitor` ORDER BY `Age` ASC","question":"Show all data ordered by Age in ascending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visitor` table ordered by `Age` in ascending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nORDER BY Age ASC;\n```\n\nThis query will return all columns (`*`) for every record in the `visitor` table, sorted by the `Age` column in ascending order (from youngest to oldest).","cost":0.0005121,"response_parsed":"SELECT *\nFROM visitor\nORDER BY Age ASC;","time":3.7555177212}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-SINGLE","query":"SELECT * FROM `visitor` ORDER BY `Age` DESC","question":"Show all data ordered by Age in descending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all data from the `visitor` table ordered by `Age` in descending order, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nORDER BY Age DESC;\n```\n\nThis query will return all columns (`*`) for every record in the `visitor` table, sorted by the `Age` column in descending order (from oldest to youngest).","cost":0.0004734,"response_parsed":"SELECT *\nFROM visitor\nORDER BY Age DESC;","time":3.7731926441}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ID` FROM `visitor` ORDER BY `ID` ASC","question":"Project the ID ordered in ascending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `ID` from the `visitor` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT ID FROM visitor ORDER BY ID ASC;\n```","cost":0.000441,"response_parsed":"SELECT ID FROM visitor ORDER BY ID ASC;","time":3.250074625}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `ID` FROM `visitor` ORDER BY `ID` DESC","question":"Project the ID ordered in descending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `ID` from the `visitor` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT ID FROM visitor ORDER BY ID DESC;\n```","cost":0.0003825,"response_parsed":"SELECT ID FROM visitor ORDER BY ID DESC;","time":2.4396517277}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Name` FROM `visitor` ORDER BY `Name` ASC","question":"Project the Name ordered in ascending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Name` from the `visitor` table in ascending order, you can use the following SQL query:\n\n```sql\nSELECT Name FROM visitor ORDER BY Name ASC;\n```","cost":0.000396,"response_parsed":"SELECT Name FROM visitor ORDER BY Name ASC;","time":2.5856468678}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"ORDERBY","sql_tag":"ORDERBY-PROJECT","query":"SELECT `Name` FROM `visitor` ORDER BY `Name` DESC","question":"Project the Name ordered in descending order for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo project the `Name` from the `visitor` table in descending order, you can use the following SQL query:\n\n```sql\nSELECT Name FROM visitor ORDER BY Name DESC;\n```","cost":0.0005085,"response_parsed":"SELECT Name FROM visitor ORDER BY Name DESC;","time":3.8855266571}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Museum_ID` FROM `museum`","question":"Show all Museum_ID in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Museum_ID` from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID FROM museum;\n```\n\nThis query will return all the unique `Museum_ID` values present in your `museum` table.","cost":0.0005652,"response_parsed":"SELECT Museum_ID FROM museum;","time":4.8559277058}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `museum`","question":"Show all Name in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all the names from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM museum;\n```\n\nThis query will return all the entries in the `Name` column of the `museum` table. If you want to avoid duplicate names (if any), you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Name FROM museum;\n```","cost":0.0005067,"response_parsed":"SELECT DISTINCT Name FROM museum;","time":3.9506011009}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Num_of_Staff` FROM `museum`","question":"Show all Num_of_Staff in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Num_of_Staff` from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Num_of_Staff FROM museum;\n```","cost":0.0004365,"response_parsed":"SELECT Num_of_Staff FROM museum;","time":2.9740777016}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Open_Year` FROM `museum`","question":"Show all Open_Year in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Open_Year` values from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Open_Year FROM museum;\n```","cost":0.0004698,"response_parsed":"SELECT Open_Year FROM museum;","time":3.5351734161}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `museum`","question":"Show all the rows in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all rows from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum;\n```\n\nThis query will return all rows and columns from the `museum` table.","cost":0.0005229,"response_parsed":"SELECT * FROM museum;","time":4.2492291927}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Name` FROM `museum`","question":"Show all Name in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all the names from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM museum;\n```\n\nThis query will return all the entries in the `Name` column of the `museum` table. If you want to avoid duplicates and only see unique names, you can use the `DISTINCT` keyword:\n\n```sql\nSELECT DISTINCT Name FROM museum;\n```","cost":0.0005499,"response_parsed":"SELECT DISTINCT Name FROM museum;","time":4.5963804722}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Museum_ID`, `Name` FROM `museum`","question":"Show all Museum_ID, Name in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Museum_ID` and `Name` from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID, Name FROM museum;\n```\n\nThis query will return a result set containing all the `Museum_ID` and `Name` values from your `museum` table.","cost":0.0006687,"response_parsed":"SELECT Museum_ID, Name FROM museum;","time":5.8842859268}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Open_Year`, `Name`, `Num_of_Staff` FROM `museum`","question":"Show all Open_Year, Name, Num_of_Staff in the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `Open_Year`, `Name`, and `Num_of_Staff` from the `museum` table, you can use the following SQL query:\n\n```sql\nSELECT Open_Year, Name, Num_of_Staff FROM museum;\n```","cost":0.0004932,"response_parsed":"SELECT Open_Year, Name, Num_of_Staff FROM museum;","time":3.4875798225}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Museum_ID` FROM `visit`","question":"Show all Museum_ID in the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Museum_ID` values from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT \"Museum_ID\" FROM \"visit\";\n```\n\nThis query will return all the `Museum_ID` values present in the `visit` table.","cost":0.0004617,"response_parsed":"SELECT \"Museum_ID\" FROM \"visit\";","time":4.2993552685}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `visitor_ID` FROM `visit`","question":"Show all visitor_ID in the table visit","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `visitor_ID` from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID FROM visit;\n```\n\nThis query will return all the `visitor_ID` entries present in your `visit` table.","cost":0.0004293,"response_parsed":"SELECT visitor_ID FROM visit;","time":2.9065818787}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Num_of_Ticket` FROM `visit`","question":"Show all Num_of_Ticket in the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Num_of_Ticket` values from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT Num_of_Ticket FROM visit;\n```","cost":0.0004311,"response_parsed":"SELECT Num_of_Ticket FROM visit;","time":2.9268078804}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Total_spent` FROM `visit`","question":"Show all Total_spent in the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Total_spent` values from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT Total_spent FROM visit;\n```","cost":0.0003906,"response_parsed":"SELECT Total_spent FROM visit;","time":2.3313455582}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `visit`","question":"Show all the rows in the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `visit` table, you can use the `SELECT` statement with the wildcard `*` to retrieve all columns. Here's the SQL code:\n\n```sql\nSELECT * FROM visit;\n```","cost":0.0004311,"response_parsed":"SELECT * FROM visit;","time":3.293027401}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Total_spent` FROM `visit`","question":"Show all Total_spent in the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Total_spent` values from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT Total_spent FROM visit;\n```","cost":0.0003906,"response_parsed":"SELECT Total_spent FROM visit;","time":2.6112775803}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Museum_ID`, `Total_spent` FROM `visit`","question":"Show all Museum_ID, Total_spent in the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Museum_ID` and `Total_spent` from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT Museum_ID, Total_spent FROM visit;\n```\n\nThis query will return all rows from the `visit` table with the columns `Museum_ID` and `Total_spent`.","cost":0.0004419,"response_parsed":"SELECT Museum_ID, Total_spent FROM visit;","time":3.2552416325}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `visitor_ID`, `Museum_ID`, `Total_spent` FROM `visit`","question":"Show all visitor_ID, Museum_ID, Total_spent in the table visit","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `visitor_ID`, `Museum_ID`, and `Total_spent` from the `visit` table, you can use the following SQL query:\n\n```sql\nSELECT visitor_ID, Museum_ID, Total_spent FROM visit;\n```","cost":0.0004851,"response_parsed":"SELECT visitor_ID, Museum_ID, Total_spent FROM visit;","time":3.7353014946}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `ID` FROM `visitor`","question":"Show all ID in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all IDs from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT ID FROM visitor;\n```\n\nThis query will return all the `ID` values stored in your `visitor` table.","cost":0.0004086,"response_parsed":"SELECT ID FROM visitor;","time":2.778380394}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Name` FROM `visitor`","question":"Show all Name in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all names from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Name FROM \"visitor\";\n```","cost":0.0004752,"response_parsed":"SELECT Name FROM \"visitor\";","time":3.6664750576}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Level_of_membership` FROM `visitor`","question":"Show all Level_of_membership in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Level_of_membership` entries from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Level_of_membership FROM visitor;\n```","cost":0.0003843,"response_parsed":"SELECT Level_of_membership FROM visitor;","time":2.8540418148}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-SINGLE-COL","query":"SELECT `Age` FROM `visitor`","question":"Show all Age in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all the ages from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Age FROM visitor;\n```\n\nThis query will return all the values in the `Age` column of your `visitor` table.","cost":0.0004041,"response_parsed":"SELECT Age FROM visitor;","time":2.8903121948}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-ALL","query":"SELECT * FROM `visitor`","question":"Show all the rows in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo show all the rows in the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT * FROM visitor;\n```\n\nThis query will return all columns (`ID`, `Name`, `Level_of_membership`, and `Age`) for every row in the `visitor` table.","cost":0.0004914,"response_parsed":"SELECT * FROM visitor;","time":3.5623250008}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Level_of_membership` FROM `visitor`","question":"Show all Level_of_membership in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all `Level_of_membership` entries from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Level_of_membership FROM visitor;\n```","cost":0.0003843,"response_parsed":"SELECT Level_of_membership FROM visitor;","time":2.4546339512}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Level_of_membership`, `Name` FROM `visitor`","question":"Show all Level_of_membership, Name in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the `Level_of_membership` and `Name` from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Level_of_membership, Name FROM visitor;\n```\n\nThis query will return all rows in the `visitor` table, displaying only the `Level_of_membership` and `Name` columns.","cost":0.0005472,"response_parsed":"SELECT Level_of_membership, Name FROM visitor;","time":4.4617466927}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"PROJECT","sql_tag":"SELECT-RANDOM-COL","query":"SELECT `Age`, `ID`, `Name` FROM `visitor`","question":"Show all Age, ID, Name in the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch all the `Age`, `ID`, and `Name` from the `visitor` table, you can use the following SQL query:\n\n```sql\nSELECT Age, ID, Name FROM visitor;\n```\n\nThis query will return all rows in the `visitor` table with the specified columns.","cost":0.0004131,"response_parsed":"SELECT Age, ID, Name FROM visitor;","time":2.9077749252}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Name` == 'Plaza Museum'","question":"Show the data of the table museum where Name is equal to Plaza Museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where the `Name` is \"Plaza Museum,\" you can use the following SQL query:\n\n```sql\nSELECT * FROM museum WHERE Name = 'Plaza Museum';\n```","cost":0.0005292,"response_parsed":"SELECT * FROM museum WHERE Name = 'Plaza Museum';","time":3.8911907673}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Name` != 'Willow Grande Museum'","question":"Show the data of the table museum where Name is different from Willow Grande Museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data of the table `museum` where the `Name` is different from \"Willow Grande Museum\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM museum\nWHERE Name != 'Willow Grande Museum';\n```","cost":0.0004554,"response_parsed":"SELECT *\nFROM museum\nWHERE Name != 'Willow Grande Museum';","time":3.3980154991}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Name` != 'Willow Grande Museum'","question":"Show the data of the table museum where Name not equal to Willow Grande Museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where the `Name` is not equal to \"Willow Grande Museum\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM museum\nWHERE Name <> 'Willow Grande Museum';\n```\n\nThis query will return all rows from the `museum` table except the one where the `Name` is \"Willow Grande Museum\".","cost":0.0006516,"response_parsed":"SELECT *\nFROM museum\nWHERE Name <> 'Willow Grande Museum';","time":5.4404435158}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Open_Year` == '2012'","question":"Show the data of the table museum where Open_Year is equal to 2012","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where the `Open_Year` is equal to 2012, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum WHERE Open_Year = '2012';\n```","cost":0.0004941,"response_parsed":"SELECT * FROM museum WHERE Open_Year = '2012';","time":3.5245962143}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Open_Year` != '2008'","question":"Show the data of the table museum where Open_Year is different from 2008","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where the `Open_Year` is different from 2008, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum WHERE Open_Year != '2008';\n```","cost":0.0004221,"response_parsed":"SELECT * FROM museum WHERE Open_Year != '2008';","time":2.680590868}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `museum` WHERE `Open_Year` != '2010'","question":"Show the data of the table museum where Open_Year not equal to 2010","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where the `Open_Year` is not equal to 2010, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum WHERE Open_Year != '2010';\n```","cost":0.0004815,"response_parsed":"SELECT * FROM museum WHERE Open_Year != '2010';","time":3.5543367863}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `museum` WHERE `Num_of_Staff` > 18","question":"Show the data of the table museum where Num_of_Staff is greater than 18","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where `Num_of_Staff` is greater than 18, you can use the following SQL query:\n\n```sql\nSELECT * FROM museum WHERE Num_of_Staff > 18;\n```","cost":0.0004959,"response_parsed":"SELECT * FROM museum WHERE Num_of_Staff > 18;","time":3.6172587872}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `museum` WHERE `Num_of_Staff` < 18","question":"Show the data of the table museum where Num_of_Staff is less than 18","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `museum` table where `Num_of_Staff` is less than 18, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM museum\nWHERE Num_of_Staff < 18;\n```","cost":0.0005049,"response_parsed":"SELECT *\nFROM museum\nWHERE Num_of_Staff < 18;","time":3.9320032597}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visit` WHERE `visitor_ID` == '5'","question":"Show the data of the table visit where visitor_ID is equal to 5","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `visitor_ID` is equal to 5, you can use the following SQL query:\n\n```sql\nSELECT * FROM visit WHERE visitor_ID = 5;\n```","cost":0.0004266,"response_parsed":"SELECT * FROM visit WHERE visitor_ID = 5;","time":2.8514604568}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visit` WHERE `visitor_ID` != '5'","question":"Show the data of the table visit where visitor_ID is different from 5","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `visitor_ID` is different from 5, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nWHERE visitor_ID != 5;\n```","cost":0.0004572,"response_parsed":"SELECT *\nFROM visit\nWHERE visitor_ID != 5;","time":3.2507138252}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visit` WHERE `visitor_ID` != '6'","question":"Show the data of the table visit where visitor_ID not equal to 6","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `visitor_ID` is not equal to 6, you can use the following SQL query:\n\n```sql\nSELECT * FROM visit WHERE visitor_ID != 6;\n```\n\nThis query will return all rows from the `visit` table where the `visitor_ID` is not equal to 6.","cost":0.0005166,"response_parsed":"SELECT * FROM visit WHERE visitor_ID != 6;","time":3.936747551}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `visit` WHERE `Num_of_Ticket` > 10","question":"Show the data of the table visit where Num_of_Ticket is greater than 10","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `Num_of_Ticket` is greater than 10, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nWHERE Num_of_Ticket > 10;\n```","cost":0.0004599,"response_parsed":"SELECT *\nFROM visit\nWHERE Num_of_Ticket > 10;","time":3.5866985321}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `visit` WHERE `Num_of_Ticket` < 20","question":"Show the data of the table visit where Num_of_Ticket is less than 20","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `Num_of_Ticket` is less than 20, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nWHERE Num_of_Ticket < 20;\n```","cost":0.0004752,"response_parsed":"SELECT *\nFROM visit\nWHERE Num_of_Ticket < 20;","time":3.5190424919}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `visit` WHERE `Total_spent` < 320.14","question":"Show the data of the table visit where Total_spent is less than 320.14","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visit` table where `Total_spent` is less than 320.14, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visit\nWHERE Total_spent < 320.14;\n```","cost":0.000441,"response_parsed":"SELECT *\nFROM visit\nWHERE Total_spent < 320.14;","time":3.1408417225}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visitor` WHERE `Name` == 'Fernando Gago'","question":"Show the data of the table visitor where Name is equal to Fernando Gago","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visitor` table where the `Name` is \"Fernando Gago,\" you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nWHERE Name = 'Fernando Gago';\n```","cost":0.0004869,"response_parsed":"SELECT *\nFROM visitor\nWHERE Name = 'Fernando Gago';","time":3.5656700134}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visitor` WHERE `Name` != 'Arjen Robben'","question":"Show the data of the table visitor where Name is different from Arjen Robben","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visitor` table where the `Name` is different from \"Arjen Robben\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nWHERE Name != 'Arjen Robben';\n```\n\nThis query will return all rows from the `visitor` table where the `Name` column does not contain the value \"Arjen Robben\".","cost":0.0005985,"response_parsed":"SELECT *\nFROM visitor\nWHERE Name != 'Arjen Robben';","time":5.0061118603}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SELECT","sql_tag":"WHERE-CAT","query":"SELECT * FROM `visitor` WHERE `Name` != 'Arjen Robben'","question":"Show the data of the table visitor where Name not equal to Arjen Robben","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visitor` table where the `Name` is not equal to \"Arjen Robben\", you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nWHERE Name != 'Arjen Robben';\n```","cost":0.0005202,"response_parsed":"SELECT *\nFROM visitor\nWHERE Name != 'Arjen Robben';","time":3.8932116032}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `visitor` WHERE `Age` > 28","question":"Show the data of the table visitor where Age is greater than 28","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visitor` table where the `Age` is greater than 28, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nWHERE Age > 28;\n```","cost":0.0004257,"response_parsed":"SELECT *\nFROM visitor\nWHERE Age > 28;","time":3.2037687302}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SELECT","sql_tag":"WHERE-NUM","query":"SELECT * FROM `visitor` WHERE `Age` < 28","question":"Show the data of the table visitor where Age is less than 28","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo fetch the data from the `visitor` table where the `Age` is less than 28, you can use the following SQL query:\n\n```sql\nSELECT *\nFROM visitor\nWHERE Age < 28;\n```","cost":0.0005094,"response_parsed":"SELECT *\nFROM visitor\nWHERE Age < 28;","time":3.8358550072}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `museum`","question":"How many different Name are in table museum?","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo determine how many different names are in the `museum` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM museum;\n```","cost":0.0005445,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM museum;","time":4.5975143909}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Open_Year`) FROM `museum`","question":"How many different Open_Year are in table museum?","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo determine how many different `Open_Year` values are in the `museum` table, you can use the `COUNT(DISTINCT column_name)` function in SQL. This function counts the number of unique values in the specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT Open_Year) AS Number_of_Open_Years\nFROM museum;\n```\n\nThis query will return the number of unique `Open_Year` values in the `museum` table.","cost":0.0006111,"response_parsed":"SELECT COUNT(DISTINCT Open_Year) AS Number_of_Open_Years\nFROM museum;","time":5.1829969883}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Num_of_Staff`) FROM `museum`","question":"Find the maximum Num_of_Staff for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Num_of_Staff` for the table `museum`, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(Num_of_Staff) AS Max_Staff\nFROM museum;\n```\n\nThis query will return the highest value in the `Num_of_Staff` column of the `museum` table.","cost":0.0004698,"response_parsed":"SELECT MAX(Num_of_Staff) AS Max_Staff\nFROM museum;","time":3.8338398933}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Num_of_Staff`) FROM `museum`","question":"Find the minimum Num_of_Staff for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum `Num_of_Staff` for the table `museum`, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Num_of_Staff) AS Minimum_Staff\nFROM museum;\n```\n\nThis query will return the smallest value in the `Num_of_Staff` column of the `museum` table.","cost":0.0004464,"response_parsed":"SELECT MIN(Num_of_Staff) AS Minimum_Staff\nFROM museum;","time":3.3665347099}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"museum","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Num_of_Staff`) FROM `museum`","question":"Find the average Num_of_Staff for the table museum","db_schema_normalized":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average `Num_of_Staff` for the table `museum`, you can use the SQL `AVG()` function. Here is the SQL code:\n\n```sql\nSELECT AVG(Num_of_Staff) AS Average_Num_of_Staff\nFROM museum;\n```\n\nThis query will calculate the average number of staff across all records in the `museum` table and return it as `Average_Num_of_Staff`.","cost":0.000585,"response_parsed":"SELECT AVG(Num_of_Staff) AS Average_Num_of_Staff\nFROM museum;","time":4.625980854}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `visitor_ID`) FROM `visit`","question":"How many different visitor_ID are in table visit?","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo determine how many different `visitor_ID`s are in the `visit` table, you can use the `COUNT(DISTINCT column_name)` function in SQL, which counts the number of unique values in a specified column.\n\nHere is the SQL code to fetch the answer:\n\n```sql\nSELECT COUNT(DISTINCT visitor_ID) FROM visit;\n```\n\nThis query will return the number of unique `visitor_ID`s present in the `visit` table.","cost":0.0005436,"response_parsed":"SELECT COUNT(DISTINCT visitor_ID) FROM visit;","time":4.1489052773}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Num_of_Ticket`) FROM `visit`","question":"Find the maximum Num_of_Ticket for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Num_of_Ticket` for the table `visit`, you can use the `MAX()` function in SQL. Here's the SQL code:\n\n```sql\nSELECT MAX(Num_of_Ticket) AS Maximum_Num_of_Ticket\nFROM visit;\n```\n\nThis query will return the highest value in the `Num_of_Ticket` column of the `visit` table.","cost":0.0005481,"response_parsed":"SELECT MAX(Num_of_Ticket) AS Maximum_Num_of_Ticket\nFROM visit;","time":4.6431701183}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Num_of_Ticket`) FROM `visit`","question":"Find the minimum Num_of_Ticket for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum `Num_of_Ticket` for the `visit` table, you can use the `MIN()` function in SQL. Here's the SQL code:\n\n```sql\nSELECT MIN(Num_of_Ticket) AS Minimum_Num_of_Ticket\nFROM visit;\n```\n\nThis query will return the smallest value in the `Num_of_Ticket` column of the `visit` table.","cost":0.0004914,"response_parsed":"SELECT MIN(Num_of_Ticket) AS Minimum_Num_of_Ticket\nFROM visit;","time":3.8309352398}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Num_of_Ticket`) FROM `visit`","question":"Find the average Num_of_Ticket for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average number of tickets for the table `visit`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Num_of_Ticket) AS average_num_of_tickets\nFROM visit;\n```\n\nThis query will calculate the average value of the `Num_of_Ticket` column in the `visit` table and return it as `average_num_of_tickets`.","cost":0.000486,"response_parsed":"SELECT AVG(Num_of_Ticket) AS average_num_of_tickets\nFROM visit;","time":3.4420144558}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Total_spent`) FROM `visit`","question":"Find the maximum Total_spent for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Total_spent` for the table `visit`, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(Total_spent) FROM visit;\n```","cost":0.0004329,"response_parsed":"SELECT MAX(Total_spent) FROM visit;","time":2.9894113541}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Total_spent`) FROM `visit`","question":"Find the minimum Total_spent for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum `Total_spent` for the table `visit`, you can use the SQL `MIN()` function. Here is the SQL code:\n\n```sql\nSELECT MIN(Total_spent) FROM visit;\n```","cost":0.0004383,"response_parsed":"SELECT MIN(Total_spent) FROM visit;","time":3.1366500854}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visit","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Total_spent`) FROM `visit`","question":"Find the average Total_spent for the table visit","db_schema_normalized":"`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average `Total_spent` for the `visit` table, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Total_spent) AS average_total_spent\nFROM visit;\n```\n\nThis query will calculate the average value of the `Total_spent` column in the `visit` table and return it as `average_total_spent`.","cost":0.0005274,"response_parsed":"SELECT AVG(Total_spent) AS average_total_spent\nFROM visit;","time":4.4883596897}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-COUNT-DISTINCT","query":"SELECT COUNT(DISTINCT `Name`) FROM `visitor`","question":"How many different Name are in table visitor?","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo determine how many different names are in the `visitor` table, you can use the `COUNT(DISTINCT)` function in SQL, which counts the number of unique values in a column.\n\n```sql\nSELECT COUNT(DISTINCT Name) FROM visitor;\n```","cost":0.0005382,"response_parsed":"SELECT COUNT(DISTINCT Name) FROM visitor;","time":4.1377856731}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Level_of_membership`) FROM `visitor`","question":"Find the maximum Level_of_membership for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum `Level_of_membership` for the `visitor` table, you can use the SQL `MAX()` function. Here is the SQL code:\n\n```sql\nSELECT MAX(Level_of_membership) FROM visitor;\n```","cost":0.0004473,"response_parsed":"SELECT MAX(Level_of_membership) FROM visitor;","time":3.4583516121}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Level_of_membership`) FROM `visitor`","question":"Find the minimum Level_of_membership for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum `Level_of_membership` for the `visitor` table, you can use the SQL `MIN()` function. Here's the SQL code:\n\n```sql\nSELECT MIN(Level_of_membership) FROM visitor;\n```","cost":0.0004554,"response_parsed":"SELECT MIN(Level_of_membership) FROM visitor;","time":3.2639706135}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Level_of_membership`) FROM `visitor`","question":"Find the average Level_of_membership for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average `Level_of_membership` for the table `visitor`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Level_of_membership) AS average_level FROM visitor;\n```\n\nThis query will calculate the average value of the `Level_of_membership` column in your `visitor` table and return it as `average_level`.","cost":0.0004599,"response_parsed":"SELECT AVG(Level_of_membership) AS average_level FROM visitor;","time":3.5368156433}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MAX","query":"SELECT MAX(`Age`) FROM `visitor`","question":"Find the maximum Age for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the maximum Age for the table `visitor`, you can use the SQL `MAX()` function. Here's the SQL code:\n\n```sql\nSELECT MAX(Age) AS max_age FROM visitor;\n```\n\nThis query will return the maximum age value from the `Age` column in your `visitor` table.","cost":0.0004725,"response_parsed":"SELECT MAX(Age) AS max_age FROM visitor;","time":3.5945193768}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-MIN","query":"SELECT MIN(`Age`) FROM `visitor`","question":"Find the minimum Age for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the minimum Age from the `visitor` table, you can use the SQL `MIN()` function. Here's the SQL query:\n\n```sql\nSELECT MIN(Age) FROM visitor;\n```","cost":0.0003915,"response_parsed":"SELECT MIN(Age) FROM visitor;","time":2.5615022182}} {"db_path":"QATCH-journal\/spider_data\/test_database\/museum_visit\/museum_visit.sqlite","db_id":"museum_visit","tbl_name":"visitor","test_category":"SIMPLE-AGG","sql_tag":"SIMPLE-AGG-AVG","query":"SELECT AVG(`Age`) FROM `visitor`","question":"Find the average Age for the table visitor","db_schema_normalized":"`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","db_schema":"`\"museum\"` (\"Museum_ID\" int, \"Name\" text, \"Num_of_Staff\" int, \"Open_Year\" text, PRIMARY KEY (\"Museum_ID\"))\n`\"visitor\"` (\"ID\" int, \"Name\" text, \"Level_of_membership\" int, \"Age\" int, PRIMARY KEY (\"ID\"))\n`\"visit\"` (\"Museum_ID\" int, \"visitor_ID\" text, \"Num_of_Ticket\" int, \"Total_spent\" real, PRIMARY KEY (\"Museum_ID\",\"visitor_ID\"), FOREIGN KEY (\"Museum_ID\") REFERENCES `museum`(\"Museum_ID\"), FOREIGN KEY (\"visitor_ID\") REFERENCES `visitor`(\"ID\"))","pred_dict":{"response":"\n\nTo find the average age for the table `visitor`, you can use the SQL `AVG()` function. Here's the SQL code:\n\n```sql\nSELECT AVG(Age) FROM visitor;\n```","cost":0.0004176,"response_parsed":"SELECT AVG(Age) FROM visitor;","time":2.8813819885}}