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import { isTag, hasChildren } from "domhandler"; | |
/** | |
* Search a node and its children for nodes passing a test function. If `node` is not an array, it will be wrapped in one. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param node Node to search. Will be included in the result set if it matches. | |
* @param recurse Also consider child nodes. | |
* @param limit Maximum number of nodes to return. | |
* @returns All nodes passing `test`. | |
*/ | |
export function filter(test, node, recurse = true, limit = Infinity) { | |
return find(test, Array.isArray(node) ? node : [node], recurse, limit); | |
} | |
/** | |
* Search an array of nodes and their children for nodes passing a test function. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param nodes Array of nodes to search. | |
* @param recurse Also consider child nodes. | |
* @param limit Maximum number of nodes to return. | |
* @returns All nodes passing `test`. | |
*/ | |
export function find(test, nodes, recurse, limit) { | |
const result = []; | |
/** Stack of the arrays we are looking at. */ | |
const nodeStack = [nodes]; | |
/** Stack of the indices within the arrays. */ | |
const indexStack = [0]; | |
for (;;) { | |
// First, check if the current array has any more elements to look at. | |
if (indexStack[0] >= nodeStack[0].length) { | |
// If we have no more arrays to look at, we are done. | |
if (indexStack.length === 1) { | |
return result; | |
} | |
// Otherwise, remove the current array from the stack. | |
nodeStack.shift(); | |
indexStack.shift(); | |
// Loop back to the start to continue with the next array. | |
continue; | |
} | |
const elem = nodeStack[0][indexStack[0]++]; | |
if (test(elem)) { | |
result.push(elem); | |
if (--limit <= 0) | |
return result; | |
} | |
if (recurse && hasChildren(elem) && elem.children.length > 0) { | |
/* | |
* Add the children to the stack. We are depth-first, so this is | |
* the next array we look at. | |
*/ | |
indexStack.unshift(0); | |
nodeStack.unshift(elem.children); | |
} | |
} | |
} | |
/** | |
* Finds the first element inside of an array that matches a test function. This is an alias for `Array.prototype.find`. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param nodes Array of nodes to search. | |
* @returns The first node in the array that passes `test`. | |
* @deprecated Use `Array.prototype.find` directly. | |
*/ | |
export function findOneChild(test, nodes) { | |
return nodes.find(test); | |
} | |
/** | |
* Finds one element in a tree that passes a test. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param nodes Node or array of nodes to search. | |
* @param recurse Also consider child nodes. | |
* @returns The first node that passes `test`. | |
*/ | |
export function findOne(test, nodes, recurse = true) { | |
let elem = null; | |
for (let i = 0; i < nodes.length && !elem; i++) { | |
const node = nodes[i]; | |
if (!isTag(node)) { | |
continue; | |
} | |
else if (test(node)) { | |
elem = node; | |
} | |
else if (recurse && node.children.length > 0) { | |
elem = findOne(test, node.children, true); | |
} | |
} | |
return elem; | |
} | |
/** | |
* Checks if a tree of nodes contains at least one node passing a test. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param nodes Array of nodes to search. | |
* @returns Whether a tree of nodes contains at least one node passing the test. | |
*/ | |
export function existsOne(test, nodes) { | |
return nodes.some((checked) => isTag(checked) && | |
(test(checked) || existsOne(test, checked.children))); | |
} | |
/** | |
* Search an array of nodes and their children for elements passing a test function. | |
* | |
* Same as `find`, but limited to elements and with less options, leading to reduced complexity. | |
* | |
* @category Querying | |
* @param test Function to test nodes on. | |
* @param nodes Array of nodes to search. | |
* @returns All nodes passing `test`. | |
*/ | |
export function findAll(test, nodes) { | |
const result = []; | |
const nodeStack = [nodes]; | |
const indexStack = [0]; | |
for (;;) { | |
if (indexStack[0] >= nodeStack[0].length) { | |
if (nodeStack.length === 1) { | |
return result; | |
} | |
// Otherwise, remove the current array from the stack. | |
nodeStack.shift(); | |
indexStack.shift(); | |
// Loop back to the start to continue with the next array. | |
continue; | |
} | |
const elem = nodeStack[0][indexStack[0]++]; | |
if (!isTag(elem)) | |
continue; | |
if (test(elem)) | |
result.push(elem); | |
if (elem.children.length > 0) { | |
indexStack.unshift(0); | |
nodeStack.unshift(elem.children); | |
} | |
} | |
} | |
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