Problem:
Compute the (pseudo)inverse of
$\left(
\begin{array}{ccc}
 2 & \frac{11}{3} & -\frac{11}{3} \\
 \frac{4}{3} & -\frac{8}{3} & \frac{14}{3} \\
 -\frac{10}{3} & 3 & \frac{10}{3} \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccc}
 \frac{309}{1366} & \frac{627}{2732} & -\frac{99}{1366} \\
 \frac{135}{683} & \frac{75}{1366} & \frac{96}{683} \\
 \frac{33}{683} & \frac{123}{683} & \frac{69}{683} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/pseudoinverse/30974.txt'}