Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccc}
 10 & -8 & 0 & -1 & -3 \\
 -4 & 9 & 0 & -9 & -2 \\
 4 & -5 & 5 & 4 & -6 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccc}
 1 & 0 & 0 & -\frac{81}{58} & -\frac{43}{58} \\
 0 & 1 & 0 & -\frac{47}{29} & -\frac{16}{29} \\
 0 & 0 & 1 & \frac{43}{145} & -\frac{168}{145} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/22323.txt'}