Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccc}
 -2 & 7 & -1 & 0 & -2 \\
 1 & 5 & -9 & -7 & 5 \\
 7 & 7 & 4 & 8 & -7 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccc}
 1 & 0 & 0 & \frac{219}{607} & -\frac{65}{607} \\
 0 & 1 & 0 & \frac{145}{607} & -\frac{262}{607} \\
 0 & 0 & 1 & \frac{577}{607} & -\frac{490}{607} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/26830.txt'}