Problem:
Find the third order series of the inverse of the following function around 3:
$16 x^8$
Answer:
$-\frac{35 (x-4096)^3}{35184372088832}+\frac{7 (x-4096)^2}{1073741824}+\frac{4096-x}{16384}-2$
{'source': 'AMPS', 'file': 'amps/mathematica/calculus/series_inverse/18817.txt'}