Problem:
Consider the arithmetic sequence defined by $a_1=\frac{46}{41}$, and $a_n=a_{n-1}+\frac{11}{\sqrt{2}}$ for $n > 1$. Compute the nth partial sum, $S_n=\sum_{k=1}^n a_k$, where $n=26$.
Answer:
$13 \left(\frac{92}{41}+\frac{275}{\sqrt{2}}\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/algebra/arithmetic_series/18045.txt'}