Problem:
A triangle has sides $\frac{23}{2}, \frac{17}{2}, 16$. Determine points to define lines for the triangle's altitude, cevian, median, and symmedian lines.
Answer:
Cevian: $\left(
\begin{array}{cc}
 16 & 0 \\
 \frac{49}{16} & \frac{3 \sqrt{247}}{16} \\
\end{array}
\right)$ 
Median: $\left(
\begin{array}{cc}
 16 & 0 \\
 \frac{49}{16} & \frac{3 \sqrt{247}}{16} \\
\end{array}
\right)$ 
Altitude: $\left(
\begin{array}{cc}
 16 & 0 \\
 \frac{2401}{289} & \frac{147 \sqrt{247}}{289} \\
\end{array}
\right)$ 
Symmedian: $\left(
\begin{array}{cc}
 16 & 0 \\
 \frac{6272}{1553} & \frac{384 \sqrt{247}}{1553} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/geometry/triangles/35093.txt'}