Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccc}
 -7 & -1 & 2 & -6 & -10 \\
 -8 & 0 & 10 & -1 & 0 \\
 -7 & -10 & 10 & -10 & 5 \\
 -4 & -2 & -3 & -9 & -3 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccc}
 1 & 0 & 0 & 0 & \frac{5915}{891} \\
 0 & 1 & 0 & 0 & \frac{4403}{891} \\
 0 & 0 & 1 & 0 & \frac{4259}{891} \\
 0 & 0 & 0 & 1 & -\frac{430}{81} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/36795.txt'}