Problem:
Find the plane defined by the following points:
${\left\{-\frac{4}{3},-\frac{7}{3},-\frac{14}{3}\right\}, \left\{-\frac{1}{3},-\frac{1}{3},-1\right\}, \left\{-\frac{13}{3},\frac{7}{3},\frac{11}{3}\right\}}$.
Answer:
$6 x+261 y-144 z-55=0$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/convert_points_to_plane/26226.txt'}