Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{cccccc}
 1 & 10 & -3 & -8 & -1 & -2 \\
 -5 & 8 & -6 & 10 & -4 & 3 \\
 -4 & -5 & -1 & -4 & -2 & 3 \\
 2 & -7 & 2 & 5 & -5 & -7 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{cccccc}
 1 & 0 & 0 & 0 & -\frac{1302}{659} & -\frac{1969}{659} \\
 0 & 1 & 0 & 0 & \frac{813}{659} & \frac{736}{659} \\
 0 & 0 & 1 & 0 & \frac{2565}{659} & \frac{2271}{659} \\
 0 & 0 & 0 & 1 & -\frac{26}{659} & -\frac{13}{659} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/34703.txt'}