Problem:
Compute the (pseudo)inverse of
$\left(
\begin{array}{ccc}
 \frac{1}{5} & -\frac{12}{5} & \frac{24}{5} \\
 -\frac{17}{5} & -\frac{14}{5} & \frac{13}{5} \\
 -\frac{1}{5} & -\frac{17}{5} & \frac{16}{5} \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccc}
 -\frac{5}{1163} & -\frac{360}{1163} & \frac{300}{1163} \\
 \frac{1295}{3489} & \frac{200}{3489} & -\frac{2105}{3489} \\
 \frac{1375}{3489} & \frac{145}{3489} & -\frac{1090}{3489} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/pseudoinverse/37131.txt'}