Problem:
Subtract the second matrix from the first:
$\left(
\begin{array}{c}
 \frac{40}{7} \\
 -\frac{67}{7} \\
\end{array}
\right)$
$\left(
\begin{array}{c}
 \frac{38}{7} \\
 \frac{32}{7} \\
\end{array}
\right)$
Answer:
\begin{array}{l}
 
\begin{array}{l}
 \text{Simplify the following}: \\
 \left(
\begin{array}{c}
 \frac{40}{7} \\
 -\frac{67}{7} \\
\end{array}
\right)-\left(
\begin{array}{c}
 \frac{38}{7} \\
 \frac{32}{7} \\
\end{array}
\right) \\
\end{array}
 \\
\hline
 
\begin{array}{l}
 -1\left(
\begin{array}{c}
 \frac{38}{7} \\
 \frac{32}{7} \\
\end{array}
\right)=\left(
\begin{array}{c}
 -\frac{38}{7} \\
 -\frac{32}{7} \\
\end{array}
\right): \\
 \left(
\begin{array}{c}
 \frac{40}{7} \\
 -\frac{67}{7} \\
\end{array}
\right)+\fbox{$\left(
\begin{array}{c}
 -\frac{38}{7} \\
 -\frac{32}{7} \\
\end{array}
\right)$} \\
\end{array}
 \\
 
\begin{array}{l}
 \left(
\begin{array}{c}
 \frac{40}{7} \\
 -\frac{67}{7} \\
\end{array}
\right)+\left(
\begin{array}{c}
 -\frac{38}{7} \\
 -\frac{32}{7} \\
\end{array}
\right)=\left(
\begin{array}{c}
 \frac{40}{7}-\frac{38}{7} \\
 -\frac{67}{7}-\frac{32}{7} \\
\end{array}
\right): \\
 \left(
\begin{array}{c}
 \frac{40}{7}-\frac{38}{7} \\
 -\frac{67}{7}-\frac{32}{7} \\
\end{array}
\right) \\
\end{array}
 \\
 
\begin{array}{l}
 \frac{40}{7}-\frac{38}{7} \text{= }\frac{40-38}{7}: \\
 \left(
\begin{array}{c}
 \fbox{$\frac{40-38}{7}$} \\
 -\frac{67}{7}-\frac{32}{7} \\
\end{array}
\right) \\
\end{array}
 \\
 
\begin{array}{l}
 
\begin{array}{c}
 
\begin{array}{ccc}
\hline
 \text{} & 3 & 10 \\
\hline
 \text{} & 4 & 0 \\
 - & 3 & 8 \\
 \text{} & 0 & 2 \\
\end{array}
 \\
\end{array}
: \\
 \left(
\begin{array}{c}
 \frac{\fbox{$2$}}{7} \\
 -\frac{67}{7}-\frac{32}{7} \\
\end{array}
\right) \\
\end{array}
 \\
 
\begin{array}{l}
 -\frac{67}{7}-\frac{32}{7} \text{= }\frac{-67-32}{7}: \\
 \left(
\begin{array}{c}
 \frac{2}{7} \\
 \fbox{$\frac{-67-32}{7}$} \\
\end{array}
\right) \\
\end{array}
 \\
 
\begin{array}{l}
 -67-32=-(67+32): \\
 \left(
\begin{array}{c}
 \frac{2}{7} \\
 \frac{\fbox{$-(67+32)$}}{7} \\
\end{array}
\right) \\
\end{array}
 \\
 
\begin{array}{l}
 
\begin{array}{c}
 
\begin{array}{ccc}
\hline
 \text{} & 6 & 7 \\
\hline
 + & 3 & 2 \\
 \text{} & 9 & 9 \\
\end{array}
 \\
\end{array}
: \\
 \fbox{$
\begin{array}{ll}
 \text{Answer:} &  \\
 \text{} & \left(
\begin{array}{c}
 \frac{2}{7} \\
 \frac{-\fbox{$99$}}{7} \\
\end{array}
\right) \\
\end{array}
$} \\
\end{array}
 \\
\end{array}
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/subtract_w_steps/91.txt'}