Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccccc}
 6 & 8 & -7 & 8 & -5 & -5 & -6 \\
 -8 & 8 & 5 & -1 & 1 & -1 & 0 \\
 -4 & -7 & 2 & -4 & 0 & -5 & 1 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccccc}
 1 & 0 & 0 & \frac{1}{38} & \frac{37}{57} & \frac{128}{57} & \frac{35}{57} \\
 0 & 1 & 0 & \frac{20}{57} & -\frac{2}{171} & \frac{47}{171} & -\frac{25}{171} \\
 0 & 0 & 1 & -\frac{41}{57} & \frac{215}{171} & \frac{505}{171} & \frac{208}{171} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/35335.txt'}