Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{cccccc}
 10 & -2 & 6 & -8 & -2 & 2 \\
 -4 & -2 & -7 & 1 & 2 & 3 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{cccccc}
 1 & 0 & \frac{13}{14} & -\frac{9}{14} & -\frac{2}{7} & -\frac{1}{14} \\
 0 & 1 & \frac{23}{14} & \frac{11}{14} & -\frac{3}{7} & -\frac{19}{14} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/45606.txt'}