Problem:
Find the distance from the point ${\frac{49}{10}, \frac{14}{5}}$ to the line $-\frac{41 x}{10}+\frac{37 y}{10}+\frac{24}{5}=0$.
Answer:
$\frac{493}{50 \sqrt{122}}$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/point_to_plane_distance/16780.txt'}