programing 1 integers, a and b (obtained by the user) and will perform the division a/b, store the result in another integer c and show the result of the division using cout. In a similar way, extend the program to add, subtract, multiply, do modulo and power using integers a and b. Modify your program so that when it starts, it asks the user which type of calculation it should do, then asks for the 2 integers, then runs the user selected calculation and outputs the result in a user friendly formatted manner. Solution #1 #include  #include using namespace std; int main() { int a[10],i,b=0,N=10; //declaration cout<<"Enter the array:\n"; //enter 10 number for(i=0;i>a[i]; //arrays of 10 integers if (a[i]>=10) //check whether the integers are greater or equal to 10 b++; //in crement } cout<<"The number of integers greater or equal to 10 is: "< using namespace std; #define X 10 //--------------------------------------------------------------------------- void outputFunc(int array[]); int testFunc(int array[]); void inputFunc(int array[]); int main(int argc, char* argv[]) { int array[X]; inputFunc(array); outputFunc(array); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int array[]) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array[" << count << "]: "; while(! << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array[" << count << "]: "; } fflush(stdin); } } int testFunc(int array[]) { int count = 0; for(int i = 0; i < X; ++i) if(array[i] >= 10) ++count; return count; } void outputFunc(int array[]) { cout << "\n\tYou entered " << testFunc(array) << " integers greater than or equal to" << " 10.\n" << endl; } Solution #3 //by blazzer12 //input 10 integers and print number of integers grater than or equal to 10 #include  using namespace std; int main() { const int limit = 10; int list[10], count=0; cout<<"Enter 10 integers :"<>list[i]; (list[i]<10) ? : count++; //observe closely and if needed, recall the syntax of ? : operator } cout<<"Number of interger(s) greater than 10 = "< using namespace std; int main () { int i; //"for" loop counter //EXERCISE 1 int cinArray1; //integer value of array indexes int overTen = 0; //integer value of the amount of numbers in the array that are greater than ten, starts of at 0 as we do not know yet int array1[10]; //array of 10 integers cout << "Enter 10 numbers for array1. "; for (i = 0; i < 10; i++) { //for loop to gather data cout << "Enter number " << (i + 1) << ": "; cin >> cinArray1; array1[i] = cinArray1; } for (int j = 0; j < 10; j++) { if (array1[j] > 10) { overTen++;} } cout << "There are " << overTen << " numbers in array1 that are greater than ten. "; cin.get(); cin.get(); Solution #5: #include  using namespace std; int main() { int arr[10], n,greaterIntergers = 0; for (n = 0; n < 10; n++) { cout << "Input an Integer "; cin >> arr[n]; if (arr[n] >= 10) { greaterIntergers++; } } cout << greaterIntergers << " integers are greater than or equals to 10" << endl; return 0; } Solution #6: /* Note by editor GReaperEx: This program uses pre-standard/really old code, therefore its use is discouraged. Please try using newer/standard code instead. */ #include  #include  void main() { int no[10],i,c=0; for(i=0;i<10;i++) { cin>>no[i]; if(no[i]>=10) c++; } cout<<"Number Greater or Equal to 10 are"< using namespace std; void searching(int[]); void printarray(int[]); void main() { int array[10]; cout << "Enter 10 integers: "; for (int x = 0; x < 10; x += 1) { cout << "Enter the " << x + 1 << "'st element: "; cin >> array[x]; } searching(array); printarray(array); } void searching(int a[]) { int total = 0; for (int i = 0; i < 10; i += 1) { if (a[i] <= 10) { total = total + 1; } } cout << "there is a total of " << total << " less or equal to 10!" << endl; } void printarray(int a[]) { cout << "the number entered are: "; for (int j = 0; j < 10; j += 1) { cout <<"\t"< using namespace std; const int N = 10; int main () { int t[N], i=0, V; for (i = 0; i < N; i++) { cout << "Type an integer: "; cin >> t[i]; } cout << "Type the value of V: "; cin >> V; for (i = 0; i < N; i++) { if (t[i] == V) { cout << "V is in the array" << endl; return 0; } } cout << "V is not in the array" << endl; return 0; } Solution #2 #include  using namespace std; int main(void) { int V,input[10]; bool equalsV(false); cout << "Type the value of V: "; cin >> V; for(int currentBlock(0); currentBlock < 10; currentBlock++) { cout << "Enter input[" << currentBlock << "]: "; cin >> input[currentBlock]; if (input[currentBlock] == V) equalsV = true; } cout << "V is "; if (!equalsV) cout << "not "; cout << "in the array" << endl; system("PAUSE"); return 0; } Solution #3 //------------------------- By Brandon Cox ---------------------------------- #include  using namespace std; #define X 10 //--------------------------------------------------------------------------- void outputFunc(int array[], int V); bool testFunc(int array[], int V); void inputFunc(int array[], int& V); int main(int argc, char* argv[]) { int V, array[X]; inputFunc(array, V); outputFunc(array, V); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int array[], int& V) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array[" << count << "]: "; while(! << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array[" << count << "]: "; } fflush(stdin); } cout << "\nNow, enter the integer, \"V\": "; while(! (cin >> V) ) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "Enter the integer, \"V\": "; } fflush(stdin); } bool testFunc(int array[], int V) { int isIn = 0; for(int count = 0; count < X; ++count) if(array[count] == V) isIn = 1; if(isIn == 1) return true; else return false; } void outputFunc(int array[], int V) { cout << "\nV is "; if(! (testFunc(array, V) ) ) cout << "not "; cout << "in the array.\n" << endl; } Solution #4 // by blazzer12 // input 10 integers into an array. Find if an integer(that is input by user) is in the array. #include #include using namespace std; int main() { int arrNum[10], V, count=0; bool found=false; while(count<10) { cout<<"Enter Number "<>arrNum[count++]; // post increment count by one } cout<<"Enter a Number (V) : "; cin>>V; for(int i=0; i<10; i++) if(arrNum[i]==V) { found = true; break; // gets out of loop after V is found; no need to run the remaining iterations :) } if(found) cout<<"V is in the array"; else cout<<"V is not in the array"; } Solution #5 //By iCheats--------------------------------------------------------------//> #include  using namespace std; //variables int basArray[10]; int askNum; int V; bool youWin = false; int main() { while(1) { for (int f = 0; f < 10; f++) { cout << "Type a number: "; cin >> basArray[askNum]; } cout << "Enter number to guess!! "; cin >> V; for (int n = 0; n < 10; n++) if (basArray[n] == V) { youWin = true; break; // found match, don't check any more } if (youWin) { cout << "V is in the array"; break; // exit program } else { cout << "V is not in the array"; } } return 0; } Solution #6 #include  using namespace std; int main() { int arr[10], intergerV, n; bool inArray; cout << "Type an Integer: (it will be labeled Integer V): "; cin >> intergerV; for (int n = 0; n < 10; n++) { cout << "Type an integer: "; cin >> arr[n]; if (intergerV == arr[n]) { inArray = true; } } if (inArray) cout << "Integer V is in the Array"; else cout << "Integer V is not in the Array"; return 0; } by MAK JUNIOR #include  #include  using namespace std; int main() { int v = 0, ar[10]; bool flag = false; printf("Enter a value for the variable V\n"); cin >> v; cout << "enter values for the array"<< endl; for (int i = 0; i < 10; ++i) { cin >> ar[i]; if (ar[i] == v) flag = true; break; } flag  ? cout << "match" : cout << "mismatch"; cout << endl; } solution #7 include include define MAX 50 using namespace std; void NumbersToEnter(); void LoopNumbers(); void NumberSearch(); int numbersToEnter, number[MAX], numberSearch, lookNumber, i; int main(){ NumbersToEnter(); LoopNumbers(); NumberSearch(); for(i = 1; i <= numbersToEnter; i ++){ if(numberSearch == number[i]){ system("cls"); cout << "The number you searched is: " << numberSearch << endl; cout << "The number is in the array\n"; system("pause"); return 0; } } system("cls"); cout << "The number you searched is: " << numberSearch << endl; cout << "Number not found\n"; system("pause"); return 0; } void NumbersToEnter(){ cout << "Enter numbers to enter: "; cin >> numbersToEnter; } void LoopNumbers(){ system("cls"); for(int i = 1; i <= numbersToEnter; i ++){ cout << "Enter number [" << i << "]: "; cin >> number[i]; } } void NumberSearch(){ system("cls"); cout << "search number: "; cin >> numberSearch; }  Write a program that asks the user to type 10 integers of an array and an integer value V. The program must search if the value V exists in the array and must remove the first occurrence of V, shifting each following element left and adding a zero at the end of the array. The program must then write the final array. Solution Solution #1 #include  using namespace std; const int N=10; int main() { int t[N],i,j,V; bool found; for(i=0;i> t[i]; } cout << "Type the value of V: "; cin >> V; for (i=0;i using namespace std; #define X 10 //--------------------------------------------------------------------------- void outputFunc(int array[], int V); int searchFunc(int array[], int V); void inputFunc(int array[], int& V); int main(int argc, char* argv[]) { int V, array[X]; inputFunc(array, V); outputFunc(array, V); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int array[], int& V) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array[" << count << "]: "; while(! << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array[" << count << "]: "; } fflush(stdin); } cout << "\nNow, enter the integer, \"V\": "; while(! (cin >> V) ) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "Enter the integer, \"V\": "; } fflush(stdin); } int searchFunc(int array[], int V) { int index_V; for(int count = 0; count < X; ++count) if(array[count] == V) { index_V = count; break; } return index_V; } void outputFunc(int array[], int V) { int count, newArray[X]; for(count = 0; count < X - 1; ++count) newArray[count] = array[count]; for(count = searchFunc(array, V); count < X - 1; ++count) newArray[count] = array[count + 1]; if(count < X) newArray[X - 1] = 0; else { newArray[X - 1] = array[X - 1]; cout << "\nThe number, " << V << ", is not contained within the array.\n" << endl; } cout << "\nThe final array is:\n" << endl; for(count = 0; count < X; ++count) cout << "array[" << count << "]: " << newArray[count] << endl; cout << endl; } Solution #3 // by blazzer12 #include  #include  #define SIZE 4 using namespace std; void getVal(int *x) { for(int i=0; i>choice; if(choice == 'Y' || choice == 'y') tryAgain = true; else exit(0); } else tryAgain= false; }while(tryAgain); // delete the element V deleteElement(array,location); cout< using namespace std; const int SZ = 10; int main() { int arr[SZ]; int V; cout << "Please enter 10 integers: " << endl; for (int i = 0; i < SZ; i++) { cin >> arr[i]; } cout << "Enter V: "; cin >> V; for (int i = 0; i < SZ; i++) { if (V == arr[i]) { for (int j = i; j < SZ-1; j++) arr[j] = arr[j+1]; arr[SZ-1] = 0; } } for (auto i : arr) cout << i << endl; return 0; } Write a program that asks the user to type 10 integers of an array and an integer value V and an index value i between 0 and 9. The program must put the value V at the place i in the array, shifting each element right and dropping off the last element. The program must then write the final array. Solution Solution #1 #include  #include  void word_shift(int[], int, int); int main() { int insert; int index1; int num_in[10]; cout << "Enter the value to insert:"; cin >> insert; cout << "Enter index to place the value:"; cin >> index1; cout << "Enter the 10 integer values:"; for(int index=0; index<=9; index++) { cin >> num_in[index]; } word_shift( num_in, insert, index1 ); getch(); return 0 ; } void word_shift(int array[10], int ins, int index) { int temp; //array[index]=ins; for(int index1=0; index1<=9; index1++) if (index1==index) array[index1]=ins; cout << endl; for(index1=0; index1<=9;index1++) cout << array[index1] << endl; for(index1=0; index1<=9; index1++) { if(array[index1]==ins && index1<9) { temp = array[index1]; array[index1]=array[index1+1]; array[index1+1]=temp; } } cout << endl; for(index1=0; index1<=9;index1++) cout << array[index1] << endl; } Solution #2 //------------------------- By Brandon Cox ---------------------------------- #include  using namespace std; #define X 10 //--------------------------------------------------------------------------- void outputFunc(int array[], int V, int i); int* insertFunc(int array[], int V, int i); void inputFunc(int array[], int& V, int& i); int main(int argc, char* argv[]) { int V, i, array[X]; inputFunc(array, V, i); outputFunc(array, V, i); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int array[], int& V, int& i) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array[" << count << "]: "; while(! << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array[" << count << "]: "; } fflush(stdin); } cout << "\nNext, enter a new integer element, \"V\": "; while(! (cin >> V) ) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "Enter a new integer element, \"V\": "; } fflush(stdin); cout << "\nNow, enter the index, i(0 - " << X - 1 << "), in which to place" << " the new element, \n"; cout << "\t" << V << ", into the array: "; while(! (cin >> i) || i < 0 || i > X - 1) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "\nNow, enter the index, i(0 - " << X - 1 << "), in which to place" << " the new element, \n"; cout << "\t" << V << ", into the array: "; } fflush(stdin); } int* insertFunc(int array[], int V, int i) { int count, newArray[X], * newArrayPtr = newArray; for(count = 0; count < i; ++count) newArrayPtr[count] = array[count]; newArrayPtr[count] = V; for(count = i + 1; count < X; ++count) newArrayPtr[count] = array[count - 1]; return newArrayPtr; } void outputFunc(int array[], int V, int i) { cout << "\nThe new array is:\n" << endl; for(int count = 0; count < X; ++count) cout << "array[" << count << "]: " << insertFunc(array, V, i)[count] << endl; cout << endl; } Solution #3 // By J0nDaFr3aK #include  using namespace std; #define LENGTH 10 int main() { int array[LENGTH], v, i(-1), j, temp1, temp2; for (j = 0; j < LENGTH; j++) { cout << "enter number: "; cin >> array[j]; } cout << "\nenter value of V: "; cin >> v; do { cout << "\nenter value of i (0 to " << LENGTH - 1 << "): "; cin >> i; } while (i < 0 || i > LENGTH - 1); // saves value to copy in next one before replacing it with V temp1 = array[i]; array[i] = v; for (j = i + 1; j < LENGTH - 1; j++) { temp2 = array[j]; array[j] = temp1; temp1 = temp2; } array[j] = temp2; // j == LENGTH - 1 (9) // prints new values for (j = 0; j < LENGTH; j++) { cout << array[j] << " "; } return 0; } Solution #4 // By Tinnin // Inserting element into array #include  using namespace std; int main() { int array[10], V, i; cout << "Enter ten integers into the array: \n"; for(int j=0;j<10;j++) { cin >> array[j]; } for(int j=0;j<10;j++) { cout << array[j] << " | "; } cout << "\nEnter an integer V to insert into the array: "; cin >> V; cout << "Choose the index i between 0 and 9 at which to enter V: "; cin >> i; while(i<0||i>9) { cout << "Choose the index i between 0 and 9 at which to enter V: "; cin >> i; } for(int j=0;j<10;j++) { if(j==(i+1)) { for(int k=9;k>i;k--) { array[k]=array[k-1]; } break; } } array[i]=V; for(int j=0;j<10;j++) { cout << array[j] << " | "; } return 0; } Solution #5 //by David J #include  using namespace std; const int SZ = 10; int main() { int arr[SZ]; int V, i; cout << "Please enter 10 integers: " << endl; for (int x = 0; x < SZ; x++) { cin >> arr[x]; } cout << "Enter value to insert in array: "; cin >> V; cout << "Enter Index (0-9) to place the value: "; cin >> i; while (i < 0 || i > 9) { cout << "Index must be within range 0-9: "; cin >> i; } int z = SZ-1; while (z != i) { arr[z] = arr[z-1]; z--; } arr[i] = V; for (auto y : arr) cout << y << endl; return 0; } Solution #6 #include  //by YC CHAN using namespace std; int main() { int array[10], V, index=10; for (int i = 0; i < 10; i++) { cout << "please enter a number into array[" << i << "]: "; cin >> array[i]; } cout << "please enter the value V: "; cin >> V; if (index< 0 || index> 9) { cout << "please enter the index value(0 - 9): "; cin >> index; array[index] = V; for (int i = 0; i < 10; i++) { cout << "array[" << i << "] is: " << array[i] << endl; } } Solution #7 #include  // by Mane Burlic using namespace std; int main() { int unos,i,j,n,mesto; cout<<"Enter replacing number "<>unos; cout<<"Enter number of elements in array "<>n; cout<<"Enter place of replacement in an array "<>mesto; int niz[n]; cout<<"Enter the members in an array "<>niz[i]; for(j=0;j using namespace std; const int N=10; int main() { int a[N],i; bool found=false; bool up=false,down=false; cout << "Please enter an integer: "; cin >> a[0]; for(i=1;i> a[i]; if(a[i-1]>a[i]) down=true; if(a[i-1] using namespace std; #define X 10 //--------------------------------------------------------------------------- void outputFunc(bool increasing, bool decreasing); void inputFunc(int array[], bool& increasing, bool& decreasing); int main(int argc, char* argv[]) { int array[X]; bool increasing, decreasing; inputFunc(array, increasing, decreasing);; outputFunc(increasing, decreasing); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int array[], bool& increasing, bool& decreasing) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array[" << count << "]: "; while(! << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array[" << count << "]: "; } if(array[count] < array[count - 1] && count != 0) decreasing = true; else if(array[count] > array[count - 1] && count != 0) increasing = true; fflush(stdin); } } void outputFunc(bool increasing, bool decreasing) { cout << "The array is " << (increasing ? (decreasing ? "growing and decreasing.\n" : "increasing.\n") : (decreasing ? "decreasing.\n" : "constant.\n") ) << endl; } Solution #3 // by blazzer12 #include  #define SIZE 10 using namespace std; int main() { int numbers[SIZE]; bool increase=false, decrease=false; cout<<"Welcome, enter integers to know the nature of sequence. "< using namespace std; const int N=10; int main() { int a[N],i; bool found=false; bool up=false,down=false; cout << "Please enter an integer: "; cin >> a[0]; for(i=1;i> a[i]; if(a[i-1]>a[i]) down=true; if(a[i-1] using namespace std; int main() { int const SIZE = 10; int arr[SIZE]; bool order = true; cout << "Please enter 10 integers: "; for(int i=0; i < SIZE; i++) { cin >> arr[i]; } cout << "\nThe table is: "; if(arr[0] < arr[SIZE-1]) // it's possibly growing { // we'll go over the loop to search for contradiction // if it does exist order will change for(int i=0; i arr[i+1]) { cout << "growing and decreasing.\n"; order = false; break; } } // if order still = true, means we did not found contradiction // so, its growing if(order == true) { cout << "growing.\n"; } } else if(arr[0] > arr[SIZE-1]) // it's possibly decreasing { for(int i=0; i using namespace std; bool increase(int a[]) { for (int i = 0; i < 9; i++) { if (a[i + 1] > a[i]) { return true; } } return false; } bool decrease(int a[]) { for (int j = 0; j < 9; j++) { if (a[j + 1] < a[j]) { return true; } } return false; } int main() { int array[10]; for (int i = 0; i < 10; i++) { cout << "please enter a number into array[" << i << "]: "; cin >> array[i]; } if (increase(array) && !decrease(array)) { cout << "the array is growing. "< using namespace std; const int N=10; int main() { int a[N],b[N],c[2*N],i; cout << "Enter table a:" << endl; for (i=0;i> a[i]; } cout << "Enter table b:" << endl; for (i=0;i> b[i]; } for (i=0;i using namespace std; #define X 10 #define Y 10 //--------------------------------------------------------------------------- void outputFunc(int a[], int b[]); int* concatenate(int a[], int b[]); void inputFunc(int a[], int b[]); int main(int argc, char* argv[]) { int a[X], b[Y]; inputFunc(a, b); outputFunc(a, b); system("pause"); return 0; } //--------------------------------------------------------------------------- void inputFunc(int a[], int b[]) { cout << "Please enter " << X << " integer elements of an array.\n" << endl; for(int count = 0; count < X; ++count) { cout << "array a[" << count << "]: "; while(! (cin >> a[count]) ) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array a[" << count << "]: "; } fflush(stdin); } cout << "\nPlease enter " << Y << " integer elements of another array.\n" << endl; for(int count = 0; count < Y; ++count) { cout << "array b[" << count << "]: "; while(! (cin >> b[count]) ) { cout << "\n\tSorry, invalid input... was expecting an integer." << " Please try again:\n" << endl; cin.clear(); cin.ignore(10000, '\n'); cout << "array b[" << count << "]: "; } fflush(stdin); } } int* concatenate(int a[], int b[]) { int count, c[X + Y], * cPtr = c; for(count = 0; count < X; ++count) cPtr[count] = a[count]; for(count = X; count < X + Y; ++count) cPtr[count] = b[count - X]; return cPtr; } void outputFunc(int a[], int b[]) { cout << "\n\tThe final array, \"c\", is:\n" << endl; for(int count = 0; count < X + Y; ++count) cout << "c[" << count << "]: " << concatenate(a, b)[count] << endl; cout << endl; } // interesting note... I thought of using the old *strcat from C, but since I // am trying to hone my function and pointer handling skills, I had more fun // doing it this way :) Solution #3 // by blazzer12 #include  #define SIZE 10 #define dSIZE SIZE*2 //tempArray is global variable, so its values are not overwritten; to see, try declaring it as local variable int tempArray[dSIZE]; using namespace std; void getVal(int *x) { for(int i=0; i using namespace std; #define LENGTH 10 int main() { int a[LENGTH], b[LENGTH], c[LENGTH*2], i; cout << "type numbers into first array:\n"; for (i = 0; i < LENGTH; i++) { cout << i << " = "; cin >> a[i]; } cout << "type numbers into second array:\n"; for (i = 0; i < LENGTH; i++) { cout << i << " = "; cin >> b[i]; } for (i = 0; i < LENGTH * 2; i++) { if (i < LENGTH) c[i] = a[i]; else c[i] = b[i - LENGTH]; } for (i = 0; i < LENGTH * 2; i++) cout << c[i] << " "; return 0; } Solution #5 #include //by YC CHAN using namespace std; int main() { int array[10],array1[10],array2[20]; for (int i = 0; i < 10; i++) { cout << "please enter a number into array[" << i << "]: "; cin >> array[i]; } for (int j = 0; j < 10; j++) { cout << "please enter a number into array1[" << j << "]: "; cin >> array1[j]; } for (int k = 0; k < 10; k++) { array2[k] = array[k]; array2[k + 10] = array1[k]; } for (int k = 0; k < 20; k++) { cout << "array2[" << k << "] is: " << array2[k] << endl; } return 0; } Edit
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