Problem:
Find the distance from the point ${-\frac{10}{3}, \frac{8}{3}, -4}$ to the plane $\frac{7 x}{3}-\frac{13 y}{3}-\frac{10 z}{3}+4=0$.
Answer:
$\sqrt{\frac{6}{53}}$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/point_to_plane_distance/32507.txt'}