Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccccc}
 -6 & 8 & -10 & -4 & -8 & 6 & -10 \\
 9 & 7 & 7 & 4 & 10 & -6 & -8 \\
 5 & -5 & -6 & 8 & 10 & -1 & 1 \\
 -5 & 0 & 9 & -6 & -3 & 2 & 9 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccccc}
 1 & 0 & 0 & 0 & -\frac{455}{232} & -\frac{355}{232} & -\frac{129}{58} \\
 0 & 1 & 0 & 0 & \frac{515}{696} & \frac{77}{232} & -\frac{31}{58} \\
 0 & 0 & 1 & 0 & \frac{373}{348} & \frac{15}{116} & \frac{32}{29} \\
 0 & 0 & 0 & 1 & \frac{5209}{1392} & \frac{527}{464} & \frac{233}{116} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/40519.txt'}