Problem:
Solve for $y=f(x)$ given the following parametric equations:
$y(t)=4 \left(32 t^2-240 t+453\right)^2, x(t)=16 t^2-120 t+225$
Answer:
$y=16 x^2+48 x+36$
{'source': 'AMPS', 'file': 'amps/mathematica/algebra/parametric_equations/9055.txt'}