Problem:
Convert the following matrix to reduced row echelon form:
$\left(
\begin{array}{ccccc}
 5 & 3 & -7 & 7 & -9 \\
 -3 & -8 & -3 & -2 & -8 \\
 4 & 4 & 6 & 5 & -3 \\
\end{array}
\right)$.
Answer:
$\left(
\begin{array}{ccccc}
 1 & 0 & 0 & \frac{485}{302} & -\frac{887}{302} \\
 0 & 1 & 0 & -\frac{53}{151} & \frac{313}{151} \\
 0 & 0 & 1 & -\frac{1}{302} & \frac{23}{302} \\
\end{array}
\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/linear_algebra/row_reduce/46428.txt'}