Problem:
Consider the arithmetic sequence defined by $a_1=-\frac{2}{41}$, and $a_n=a_{n-1}+4 \sqrt{3}$ for $n > 1$. Compute the nth partial sum, $S_n=\sum_{k=1}^n a_k$, where $n=29$.
Answer:
$\frac{29}{2} \left(112 \sqrt{3}-\frac{4}{41}\right)$
{'source': 'AMPS', 'file': 'amps/mathematica/algebra/arithmetic_series/39658.txt'}