Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 20. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium?
A. P(butane) = 0.77 atm and P(isobutane) = 19.2 atm
B. P(butane) = 0.80 atm and P(isobutane) = 20. atm
C. P(butane) = 19.2 atm and P(isobutane) = 0.77 atm
D. P(butane) = 20 atm and P(isobutane) = 0.80 atm
Answer:A
Kp equals 25 at 500°C. If the initial pressures of butane and isobutane are 20. atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium?
A. P(butane) = 0.77 atm and P(isobutane) = 19.2 atm B. P(butane) = 0.80 atm and P(isobutane) = 20. atm C. P(butane) = 19.2 atm and P(isobutane) = 0.77 atm D. P(butane) = 20 atm and P(isobutane) = 0.80 atm