The sum of the cube of first n positive integer is :
A. \(\frac {n(n + 1)}{2}\)
B. \(\frac {n(n + 1)(2n + 1)}{6}\)
C. \(\frac {n(n + 1)(n + 2)}{6}\)
D. {\(\frac {n(n + 1)}{2}\)}2
Answer:D
The sum of the cube of first n positive integer is :
A. \(\frac {n(n + 1)}{2}\) B. \(\frac {n(n + 1)(2n + 1)}{6}\) C. \(\frac {n(n + 1)(n + 2)}{6}\) D. {\(\frac {n(n + 1)}{2}\)}2