CREATE TABLE table_name_97 (area_km_2 INT, census_ranking VARCHAR)

What is the area of the community with a census ranking of 636 of 5,008?
SELECT AVG(area_km_2) FROM table_name_97 WHERE census_ranking = "636 of 5,008"
SELECT AVG("area_km_2") FROM "table_name_97" WHERE "636 of 5,008" = "census_ranking"