CREATE TABLE table_name_77 (surface VARCHAR2, score_in_the_final VARCHAR2)

Which surface has a score in the final of 4 6, 3 6?
SELECT surface FROM table_name_77 WHERE score_in_the_final = "4–6, 3–6"
SELECT "surface" FROM "table_name_77" WHERE "4–6, 3–6" = "score_in_the_final"