CREATE TABLE table_65704 ("Score" CLOB, "2007" CLOB, "2008" CLOB, "2009" CLOB, "2010" CLOB, "2011" CLOB, "2012" CLOB)

What score has 15.0% as the 2012?
SELECT "Score" FROM table_65704 WHERE "2012" = '15.0%'
SELECT "Score" FROM "table_65704" WHERE "2012" = '15.0%'