CREATE TABLE table_name_38 (club VARCHAR2, tries_against VARCHAR2, try_bonus VARCHAR2)

Which club has a try bonus of 9 and 43 tries against?
SELECT club FROM table_name_38 WHERE tries_against = "43" AND try_bonus = "9"
SELECT "club" FROM "table_name_38" WHERE "43" = "tries_against" AND "9" = "try_bonus"