CREATE TABLE table_12836 ("2013" CLOB, "2012" CLOB, "2011" CLOB, "2010" CLOB, "2009" CLOB, "2008" CLOB, "2007" CLOB)

What 2009 has 39th as the 2011?
SELECT "2009" FROM table_12836 WHERE "2011" = '39th'
SELECT "2009" FROM "table_12836" WHERE "2011" = '39th'