CREATE TABLE table_28819393_1 (year VARCHAR2, average__percentage_of_vote_per_candidate VARCHAR2)

In what year was 1.35% the average vote per candidate?
SELECT year FROM table_28819393_1 WHERE average__percentage_of_vote_per_candidate = "1.35"
SELECT "year" FROM "table_28819393_1" WHERE "1.35" = "average__percentage_of_vote_per_candidate"