CREATE TABLE table_name_19 (year NUMBER, issue_price__proof_ VARCHAR2, artist VARCHAR2)

What's the average Year with an Issue Price (Proof) of $49.95, and Artist of W.H.J. Blakemore?
SELECT AVG(year) FROM table_name_19 WHERE issue_price__proof_ = "$49.95" AND artist = "w.h.j. blakemore"
SELECT AVG("year") FROM "table_name_19" WHERE "$49.95" = "issue_price__proof_" AND "artist" = "w.h.j. blakemore"