CREATE TABLE table_name_47 (number_of_examinees VARCHAR2, number_of_passed_students VARCHAR2, year VARCHAR2, pass_percentage VARCHAR2)

What number of examines after 2005 has a pass percentage of 78.35% with less than 297 students?
SELECT COUNT(number_of_examinees) FROM table_name_47 WHERE year > 2005 AND pass_percentage = "78.35%" AND number_of_passed_students < 297
SELECT COUNT("number_of_examinees") FROM "table_name_47" WHERE "78.35%" = "pass_percentage" AND "number_of_passed_students" < 297 AND "year" > 2005