CREATE TABLE table_65708 ("Score" CLOB, "2007" CLOB, "2008" CLOB, "2009" CLOB, "2010" CLOB, "2011" CLOB, "2012" CLOB)

What 2011 has 12.7% as the 2010?
SELECT "2011" FROM table_65708 WHERE "2010" = '12.7%'
SELECT "2011" FROM "table_65708" WHERE "2010" = '12.7%'