CREATE TABLE table_261642_3 (c__nf_km_ VARCHAR2, l__mh_km_ VARCHAR2)

what is the c (nf/km) when the l (mh/km) is 0.6099?
SELECT c__nf_km_ FROM table_261642_3 WHERE l__mh_km_ = "0.6099"
SELECT "c__nf_km_" FROM "table_261642_3" WHERE "0.6099" = "l__mh_km_"