CREATE TABLE table_10798421_1 (village__german_ VARCHAR2, percent_of_slovenes_1951 VARCHAR2)

Provide me with the name of the village (German) where there is 96.9% Slovenes in 1951.
SELECT village__german_ FROM table_10798421_1 WHERE percent_of_slovenes_1951 = "96.9%"
SELECT "village__german_" FROM "table_10798421_1" WHERE "96.9%" = "percent_of_slovenes_1951"