CREATE TABLE table_15909409_2 (country VARCHAR2, agricultural_use__m_3__p_yr__in__percentage_ VARCHAR2)

What was the country in which the agricultural use (m 3 /p/yr)(in %) was 794(86%)?
SELECT country FROM table_15909409_2 WHERE agricultural_use__m_3__p_yr__in__percentage_ = "794(86%)"
SELECT "country" FROM "table_15909409_2" WHERE "794(86%)" = "agricultural_use__m_3__p_yr__in__percentage_"