CREATE TABLE table_name_78 (year VARCHAR2, day_of_week VARCHAR2, rank VARCHAR2)

What is the year of the movie with an opening day on Friday with a rank 10?
SELECT COUNT(year) FROM table_name_78 WHERE day_of_week = "friday" AND rank = 10
SELECT COUNT("year") FROM "table_name_78" WHERE "day_of_week" = "friday" AND "rank" = 10