CREATE TABLE table_204_15 (id NUMBER, "year" NUMBER, "date" CLOB, "venue" CLOB, "city" CLOB, "country" CLOB, "notes" CLOB)

is canada at least on the chart 3 times ?
SELECT (SELECT COUNT(*) FROM table_204_15 WHERE "country" = 'canada') > 3
WITH "_u_0" AS (SELECT COUNT(*), 'canada' AS "_u_1" FROM "table_204_15" GROUP BY 'canada') SELECT COALESCE("_u_0"."", *) > 3 LEFT JOIN "_u_0" "_u_0" ON "_u_0"."_u_1" = "country"