CREATE TABLE table_12545 ("Tournament" CLOB, "1973" CLOB, "1974" CLOB, "1975" CLOB, "1976" CLOB, "1977" CLOB, "1978" CLOB, "1979" CLOB, "1983" CLOB, "1984" CLOB, "1985" CLOB, "1986" CLOB)

What 1973 has a 1978 of 75%?
SELECT "1973" FROM table_12545 WHERE "1978" = '75%'
SELECT "1973" FROM "table_12545" WHERE "1978" = '75%'