CREATE TABLE table_name_16 (surface VARCHAR2, score VARCHAR2)

Which Surface has a score of 7-5, 5-7, 6-3?
SELECT surface FROM table_name_16 WHERE score = "7-5, 5-7, 6-3"
SELECT "surface" FROM "table_name_16" WHERE "7-5, 5-7, 6-3" = "score"