CREATE TABLE table_name_98 (_percentage__1960_ VARCHAR2, _percentage__2040_ VARCHAR2)

What is the % (1960) of the county with a % (2040) of 3.4?
SELECT COUNT(_percentage__1960_) FROM table_name_98 WHERE _percentage__2040_ = 3.4
SELECT COUNT("_percentage__1960_") FROM "table_name_98" WHERE "_percentage__2040_" = 3.4