CREATE TABLE table_64270 ("Period" CLOB, "Internet Explorer" CLOB, "Chrome" CLOB, "Firefox" CLOB, "Safari" CLOB, "Opera" CLOB, "Other Mozilla" CLOB)

What internet explorer has 7.89% as the safari, and 8.22% as the chrome?
SELECT "Internet Explorer" FROM table_64270 WHERE "Safari" = '7.89%' AND "Chrome" = '8.22%'
SELECT "Internet Explorer" FROM "table_64270" WHERE "Chrome" = '8.22%' AND "Safari" = '7.89%'