CREATE TABLE table_20803241_1 (type_of_fare VARCHAR2, cash_fare VARCHAR2, day_pass VARCHAR2)

When n/a is the cash fate and n/a is the 31-day pass how many types of fare are there?
SELECT COUNT(type_of_fare) FROM table_20803241_1 WHERE 31 - day_pass = "N/A" AND cash_fare = "N/A"
SELECT COUNT("type_of_fare") FROM "table_20803241_1" WHERE "N/A" = "cash_fare" AND "N/A" = 31 - "day_pass"