CREATE TABLE table_46449 ("Tournament" CLOB, "1984" CLOB, "1985" CLOB, "1986" CLOB, "1987" CLOB, "1988" CLOB, "1989" CLOB, "1990" CLOB, "1991" CLOB, "1992" CLOB, "1993" CLOB, "1994" CLOB, "1995" CLOB, "1996" CLOB, "1997" CLOB, "1998" CLOB, "1999" CLOB, "2000" CLOB)

What is the 1995 value with A in 1986 and 2r in 1992?
SELECT "1995" FROM table_46449 WHERE "1986" = 'a' AND "1992" = '2r'
SELECT "1995" FROM "table_46449" WHERE "1986" = 'a' AND "1992" = '2r'