CREATE TABLE table_name_30 (tries_against VARCHAR2, try_diff VARCHAR2, points_for VARCHAR2)

How many Tries against has a Try diff of 17 and Points for smaller than 80?
SELECT COUNT(tries_against) FROM table_name_30 WHERE try_diff = "–17" AND points_for < 80
SELECT COUNT("tries_against") FROM "table_name_30" WHERE "points_for" < 80 AND "try_diff" = "–17"