CREATE TABLE table_name_88 (mac_os_x VARCHAR2, android VARCHAR2, linux VARCHAR2, amigaos VARCHAR2)

Which Mac OS X has a Linux of no, and an AmigaOS of no, and an Android of unknown?
SELECT mac_os_x FROM table_name_88 WHERE linux = "no" AND amigaos = "no" AND android = "unknown"
SELECT "mac_os_x" FROM "table_name_88" WHERE "amigaos" = "no" AND "android" = "unknown" AND "linux" = "no"