CREATE TABLE table_name_19 (interview VARCHAR2, country VARCHAR2, swimsuit VARCHAR2)

What is the interview number in Louisiana, and the swimsuit number is more than 9.1?
SELECT COUNT(interview) FROM table_name_19 WHERE country = "louisiana" AND swimsuit > 9.1
SELECT COUNT("interview") FROM "table_name_19" WHERE "country" = "louisiana" AND "swimsuit" > 9.1