CREATE TABLE table_51881 ("D 41" CLOB, "D 42" CLOB, "D 43" CLOB, "D 44" CLOB, "D 45" CLOB, "D 46" CLOB, "R 54" CLOB, "R 53" CLOB, "R 52" CLOB, "R 51" CLOB)

Name the D 42 which has a D 44 of d 44
SELECT "D 42" FROM table_51881 WHERE "D 44" = 'd 44'
SELECT "D 42" FROM "table_51881" WHERE "D 44" = 'd 44'