CREATE TABLE table_51878 ("D 41" CLOB, "D 42" CLOB, "D 43" CLOB, "D 44" CLOB, "D 45" CLOB, "D 46" CLOB, "R 54" CLOB, "R 53" CLOB, "R 52" CLOB, "R 51" CLOB)

Name the R 52 which has a D 44 of d 44
SELECT "R 52" FROM table_51878 WHERE "D 44" = 'd 44'
SELECT "R 52" FROM "table_51878" WHERE "D 44" = 'd 44'