CREATE TABLE table_17004367_3 (nightly_rank VARCHAR2, episode_number_production_number VARCHAR2)

what is the nightly rank where the episode number production number is 06 1-06?
SELECT COUNT(nightly_rank) FROM table_17004367_3 WHERE episode_number_production_number = "06 1-06"
SELECT COUNT("nightly_rank") FROM "table_17004367_3" WHERE "06 1-06" = "episode_number_production_number"