CREATE TABLE table_name_26 (free_or_pay VARCHAR2, years VARCHAR2, provider VARCHAR2)

What kind of Free or pay has Years of 2006 and a Provider of bt tv (formerly bt vision)?
SELECT free_or_pay FROM table_name_26 WHERE years = "2006–" AND provider = "bt tv (formerly bt vision)"
SELECT "free_or_pay" FROM "table_name_26" WHERE "2006–" = "years" AND "bt tv (formerly bt vision)" = "provider"