CREATE TABLE table_52017 ("D 40 \\u221a" CLOB, "D 41 \\u221a" CLOB, "D 42 \\u221a" CLOB, "D 43 \\u221a" CLOB, "D 44 \\u221a" CLOB, "D 45 O" CLOB, "D 46 O" CLOB, "R 53 +" CLOB, "R 52 +" CLOB, "R 51 +" CLOB)

Name the D 45 O that has D 46 O of d 26
SELECT "D 45 O" FROM table_52017 WHERE "D 46 O" = 'd 26'
SELECT "D 45 O" FROM "table_52017" WHERE "D 46 O" = 'd 26'