caption: Kinematics of a Particle moving in a Straight Line
exif: {"Image DocumentName": "Kinematics of a Particle moving in a Straight Line", "Image ImageDescription": "A particle is moving in a straight horizontal line with constant deceleration 4ms-2. At time t = 0 the particle passes through a point O with speed 13ms-1, travelling to a point A where OA = 20m. Find: The times when the particle passes through A \u2013 2.5 and 4 seconds. The total time the particle is beyond A \u2013 1.5 seconds. The time taken for the particle to return to O. You can also use 3 more formulae linking different combination of \u2018SUVAT\u2019, for a particle moving in a straight line with constant acceleration. \ud835\udc60= \ud835\udc62+\ud835\udc63 2 \ud835\udc61. Draw a diagram. \ud835\udc63=\ud835\udc62+\ud835\udc4e\ud835\udc61. 13ms-1. Write out \u2018suvat\u2019 with the information given. \ud835\udc60=\ud835\udc62\ud835\udc61+ 1 2 \ud835\udc4e \ud835\udc61 2. \ud835\udc63 2 = \ud835\udc62 2 +2\ud835\udc4e\ud835\udc60. O. A. \ud835\udc60=20. \ud835\udc60=0. \ud835\udc62=13. \ud835\udc63= \ud835\udc4e=\u22124. \ud835\udc61= The particle returns to O when s = 0. \ud835\udc60=\ud835\udc63\ud835\udc61\u2212 1 2 \ud835\udc4e \ud835\udc61 2. \ud835\udc60=\ud835\udc62\ud835\udc61+ 1 2 \ud835\udc4e \ud835\udc61 2. Replace s, u and a. 0=(13)\ud835\udc61+(\u22122) \ud835\udc61 2. Simplify. 0=13\ud835\udc61\u22122 \ud835\udc61 2. Rearrange. The particle is at O when t = 0 seconds (to begin with) and is at O again when t = 6.5 seconds. 2 \ud835\udc61 2 \u221213\ud835\udc61=0. Factorise. \ud835\udc61(2\ud835\udc61\u221213)=0. \ud835\udc61=0 \ud835\udc5c\ud835\udc5f B.", "Image XResolution": "300", "Image YResolution": "300", "Image ResolutionUnit": "Pixels/Inch", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}