and { only { filter_eq { all_rows ; no party preference ; 22.6 % } } ; eq { hop { filter_eq { all_rows ; no party preference ; 22.6 % } ; city } ; lemon grove } } = true
select the rows whose no party preference record fuzzily matches to 22.6  . there is only one such row in the table . the city record of this unqiue row is lemon grove .