and { only { filter_eq { all_rows ; cons ; 18 % } } ; eq { hop { filter_eq { all_rows ; cons ; 18 % } ; date ( s ) conducted } ; 27 october 2010 } } = true
select the rows whose cons record fuzzily matches to 18  . there is only one such row in the table . the date  s  conducted record of this unqiue row is 27 october 2010 .