greater { hop { filter_eq { all_rows ; english name ; hexi district } ; density } ; hop { filter_eq { all_rows ; english name ; fenghuang } ; density } } = true
select the rows whose english name record fuzzily matches to hexi district . take the density record of this row . select the rows whose english name record fuzzily matches to fenghuang . take the density record of this row . the first record is greater than the second record .