eq { diff { hop { filter_eq { all_rows ; year ; 1997 } ; td 's } ; hop { filter_eq { all_rows ; year ; 1996 } ; td 's } } ; 2 } = true
select the rows whose year record fuzzily matches to 1997 . take the td s record of this row . select the rows whose year record fuzzily matches to 1996 . take the td s record of this row . the first record is 2 larger than the second record .