Title: 62 FDV - Heis (TKS).pdf.pdf
fT1/T2 < eT1/T2 =1,74µFrcar = Fxcar ·α fCar Frame=e1,86µFrcwt = Fxcount ·Number Pulleys (without deflection pul)udsipcar2T3) Car retained (Counterweight stalled condition)Pulley diameter (without deflection pul)mm240T1 = (P + Mcrcar + Mtrav) · G / r + (Frcar / r)Reduced mass pulley car sidemmmpcar64,00T2 = Msrcwt · G µ =Counterweight frame0,20αfT1/T2 =T1/T2 > e42,30udsCantidad polea reenvío1ipcwtµFrcar = Fxcar ·α fDiámetro polea reenvío4,42mm265=eReduced mass pulley cwt sideArticle 5.5.2.1 (EN 81.20)mpcwt54,00kgNRatio between diámeter of pulley and diameter of cables must be >= 40DmRelMRelM ==> = 40DcDd> = 40RelDRelD ==DcFO.210.02.01C/ Coeters 27, 46980 Paterna, VALENCIA (Spain)Page 10 / 1043100 / 174TRACEABILITYFO.220.08/ZGA_SUBPORTADA_0144