'Replace lintcode with leetcode if prefer leetcode.'

def _lint2leet(self):

    if self._url.startswith('https://leetcode.com/problems/'):
        return
    url = 'https://leetcode.com/problems/{}/'.format(self._p_url_path)
    response = requests.head(url)
    if (response.status_code == 200):
        self._site = 'leetcode'
        self._url = url
        self._raw_p_html = PyQuery(url=self._url)
