description: Polycarp doesn't like integers that are divisible by 3 or end with the digit 3 in their decimal representation. Integers that meet both conditions are disliked by Polycarp, too.
  
  Polycarp starts to write out the positive (greater than 0) integers which he likes: 1, 2, 4, 5, 7, 8, 10, 11, 14, 16, .... Output the k-th element of this sequence (the elements are numbered from 1).
  
  Input
  
  The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
  
  Each test case consists of one line containing one integer k (1 ≤ k ≤ 1000).
  
  Output
  
  For each test case, output in a separate line one integer x — the k-th element of the sequence that was written out by Polycarp.
  
  Example
  
  Input
  
  
  10
  1
  2
  3
  4
  5
  6
  7
  8
  9
  1000
  
  
  Output
  
  
  1
  2
  4
  5
  7
  8
  10
  11
  14
  1666
solution: import java.util.*;
  public class Solution{
      public static void main(String[] args) {
          Scanner sc = new Scanner(System.in);
          int t = sc.nextInt();
          for(int i=0; i<t; i++){
              int n = sc.nextInt();
              solve(n);
          }
      }
      public static void solve(int n){
          int count = 1;
          int num = 1;
          if(count==n){
              System.out.println(num);
              return;
          }
          int c = 0;
          while(c==0){
              if(num%3==0 || num%10==3 || (num%3==0 && num%10==3)){
                  // System.out.println("1: "+num);
                  num++;
                  // System.out.println("1: "+num+" "+count);
              }
              else{
                  count++;
                  num++;
              }
              if(count==n){
                  if(num%3!=0 && num%10!=3){
                      // System.out.println("2: "+num+" "+count);
                      System.out.println(num);
                      c=1;
                      return;
                  }
              }
             
          }
          // System.out.println(num);
      }
  }