description: When you play the game of thrones, you win, or you die. There is no middle ground.
  
  Cersei Lannister, A Game of Thrones by George R. R. Martin
  
  There are n nobles, numbered from 1 to n. Noble i has a power of i. There are also m "friendships". A friendship between nobles a and b is always mutual.
  
  A noble is defined to be vulnerable if both of the following conditions are satisfied: 
  
    * the noble has at least one friend, and 
    * all of that noble's friends have a higher power. 
  
  
  
  You will have to process the following three types of queries. 
  
    1. Add a friendship between nobles u and v. 
    2. Remove a friendship between nobles u and v. 
    3. Calculate the answer to the following process. 
  
  
  
  The process: all vulnerable nobles are simultaneously killed, and all their friendships end. Then, it is possible that new nobles become vulnerable. The process repeats itself until no nobles are vulnerable. It can be proven that the process will end in finite time. After the process is complete, you need to calculate the number of remaining nobles.
  
  Note that the results of the process are not carried over between queries, that is, every process starts with all nobles being alive!
  
  Input
  
  The first line contains the integers n and m (1 ≤ n ≤ 2⋅ 10^5, 0 ≤ m ≤ 2⋅ 10^5) — the number of nobles and number of original friendships respectively.
  
  The next m lines each contain the integers u and v (1 ≤ u,v ≤ n, u ≠ v), describing a friendship. No friendship is listed twice.
  
  The next line contains the integer q (1 ≤ q ≤ 2⋅ {10}^{5}) — the number of queries. 
  
  The next q lines contain the queries themselves, each query has one of the following three formats. 
  
    * 1 u v (1 ≤ u,v ≤ n, u ≠ v) — add a friendship between u and v. It is guaranteed that u and v are not friends at this moment. 
    * 2 u v (1 ≤ u,v ≤ n, u ≠ v) — remove a friendship between u and v. It is guaranteed that u and v are friends at this moment. 
    * 3 — print the answer to the process described in the statement. 
  
  Output
  
  For each type 3 query print one integer to a new line. It is guaranteed that there will be at least one type 3 query.
  
  Examples
  
  Input
  
  
  4 3
  2 1
  1 3
  3 4
  4
  3
  1 2 3
  2 3 1
  3
  
  
  Output
  
  
  2
  1
  
  
  Input
  
  
  4 3
  2 3
  3 4
  4 1
  1
  3
  
  
  Output
  
  
  1
  
  Note
  
  Consider the first example. In the first type 3 query, we have the diagram below.
  
  In the first round of the process, noble 1 is weaker than all of his friends (2 and 3), and is thus killed. No other noble is vulnerable in round 1. In round 2, noble 3 is weaker than his only friend, noble 4, and is therefore killed. At this point, the process ends, and the answer is 2.
  
  <image>
  
  In the second type 3 query, the only surviving noble is 4.
  
  The second example consists of only one type 3 query. In the first round, two nobles are killed, and in the second round, one noble is killed. The final answer is 1, since only one noble survives.
  
  <image>
solution: import java.util.*;
  import java.lang.*;
  import java.io.*;
  
  
  public class cf {
      static PrintWriter out;
      static int MOD = 1000000007;
      static FastReader scan;
  
      /*-------- I/O using short named function ---------*/
      public static String ns() {
          return scan.next();
      }
  
      public static int ni() {
          return scan.nextInt();
      }
  
      public static long nl() {
          return scan.nextLong();
      }
  
      public static double nd() {
          return scan.nextDouble();
      }
  
      public static String nln() {
          return scan.nextLine();
      }
  
      public static void p(Object o) {
          out.print(o);
      }
  
      public static void ps(Object o) {
          out.print(o + " ");
      }
  
      public static void pn(Object o) {
          out.println(o);
      }
  
      /*-------- for output of an array ---------------------*/
      static void iPA(int arr[]) {
          StringBuilder output = new StringBuilder();
          for (int i = 0; i < arr.length; i++) output.append(arr[i] + " ");
          out.println(output);
      }
  
      static void lPA(long arr[]) {
          StringBuilder output = new StringBuilder();
          for (int i = 0; i < arr.length; i++) output.append(arr[i] + " ");
          out.println(output);
      }
  
      static void sPA(String arr[]) {
          StringBuilder output = new StringBuilder();
          for (int i = 0; i < arr.length; i++) output.append(arr[i] + " ");
          out.println(output);
      }
  
      static void dPA(double arr[]) {
          StringBuilder output = new StringBuilder();
          for (int i = 0; i < arr.length; i++) output.append(arr[i] + " ");
          out.println(output);
      }
  
      /*-------------- for input in an array ---------------------*/
      static void iIA(int arr[]) {
          for (int i = 0; i < arr.length; i++) arr[i] = ni();
      }
  
      static void lIA(long arr[]) {
          for (int i = 0; i < arr.length; i++) arr[i] = nl();
      }
  
      static void sIA(String arr[]) {
          for (int i = 0; i < arr.length; i++) arr[i] = ns();
      }
  
      static void dIA(double arr[]) {
          for (int i = 0; i < arr.length; i++) arr[i] = nd();
      }
  
      /*------------ for taking input faster ----------------*/
      static class FastReader {
          BufferedReader br;
          StringTokenizer st;
  
          public FastReader() {
              br = new BufferedReader(new InputStreamReader(System.in));
          }
  
          String next() {
              while (st == null || !st.hasMoreElements()) {
                  try {
                      st = new StringTokenizer(br.readLine());
                  } catch (IOException e) {
                      e.printStackTrace();
                  }
              }
              return st.nextToken();
          }
  
          int nextInt() {
              return Integer.parseInt(next());
          }
  
          long nextLong() {
              return Long.parseLong(next());
          }
  
          double nextDouble() {
              return Double.parseDouble(next());
          }
  
          String nextLine() {
              String str = "";
              try {
                  str = br.readLine();
              } catch (IOException e) {
                  e.printStackTrace();
              }
              return str;
          }
      }
  
      public static ArrayList<Integer> sieveOfEratosthenes(int n) {
          // Create a boolean array
          // "prime[0..n]" and
          // initialize all entries
          // it as true. A value in
          // prime[i] will finally be
          // false if i is Not a
          // prime, else true.
          boolean prime[] = new boolean[n + 1];
          for (int i = 0; i <= n; i++)
              prime[i] = true;
  
          for (int p = 2; p * p <= n; p++) {
              // If prime[p] is not changed, then it is a
              // prime
              if (prime[p] == true) {
                  // Update all multiples of p
                  for (int i = p * p; i <= n; i += p)
                      prime[i] = false;
              }
          }
          ArrayList<Integer> arr = new ArrayList<>();
          // Print all prime numbers
          for (int i = 2; i <= n; i++) {
              if (prime[i] == true)
                  arr.add(i);
          }
          return arr;
      }
  
      // Method to check if x is power of 2
      static boolean isPowerOfTwo(int x) {
          return x != 0 && ((x & (x - 1)) == 0);
      }
  
      //Method to return lcm of two numbers
      static int gcd(int a, int b) {
          return a == 0 ? b : gcd(b % a, a);
      }
  
      //Method to count digit of a number
      static int countDigit(long n) {
          String sex = Long.toString(n);
          return sex.length();
      }
  
      static void reverse(int a[]) {
          int i, k, t;
          int n = a.length;
          for (i = 0; i < n / 2; i++) {
              t = a[i];
              a[i] = a[n - i - 1];
              a[n - i - 1] = t;
          }
      }
  
      static final Random random = new Random();
  
      //Method for sorting
      static void ruffleSort(int[] arr) {
          int n = arr.length;
          for (int i = 0; i < n; i++) {
              int j = random.nextInt(n);
              int temp = arr[j];
              arr[j] = arr[i];
              arr[i] = temp;
          }
          Arrays.sort(arr);
      }
  
      static void sortadv(long[] a) {
          ArrayList<Long> l = new ArrayList<>();
          for (long value : a) {
              l.add(value);
          }
          Collections.sort(l);
          for (int i = 0; i < l.size(); i++)
              a[i] = l.get(i);
      }
  
      //Method for checking if a number is prime or not
      static boolean isPrime(int n) {
          if (n <= 1) return false;
          if (n <= 3) return true;
          if (n % 2 == 0 || n % 3 == 0) return false;
          for (int i = 5; i * i <= n; i = i + 6)
              if (n % i == 0 || n % (i + 2) == 0)
                  return false;
          return true;
      }
  
      public static void main(String[] args) throws java.lang.Exception {
          OutputStream outputStream = System.out;
          out = new PrintWriter(outputStream);
          scan = new FastReader();
          //for fast output sometimes
          StringBuilder sb = new StringBuilder();
          int t = 1;
          while (t-- != 0) {
              int n=ni();
              int m=ni();HashMap<Integer,Integer> hm=new HashMap<>();
              while(m--!=0){
                  int u=ni();
                  int v=ni();
                  int min=Math.min(u,v);
                  hm.put(min,hm.getOrDefault(min,0)+1);
              }
              int q=ni();
              while(q--!=0){
                  int a=ni();
                  if(a==3){
                      pn(n-hm.size());//pn(hs);
                      continue;
                  }
                  else{
                      int b=ni();
                      int c=ni();
                      int min=Math.min(b,c);
                      if(a==1){
                          hm.put(min,hm.getOrDefault(min,0)+1);
                      }
                      else{
                          if(hm.get(min)==1){
                              hm.remove(min);
                          }
                          else
                              hm.put(min,hm.getOrDefault(min,0)-1);
                      }
  
                      //pn(hs.size());
                  }
              }
          }
  
          out.flush();
          out.close();
      }
  }
  