description: This is the easy version of the problem. The difference between the versions is that the easy version does not require you to output the numbers of the rods to be removed. You can make hacks only if all versions of the problem are solved.
  
  Stitch likes experimenting with different machines with his friend Sparky. Today they built another machine.
  
  The main element of this machine are n rods arranged along one straight line and numbered from 1 to n inclusive. Each of these rods must carry an electric charge quantitatively equal to either 1 or -1 (otherwise the machine will not work). Another condition for this machine to work is that the sign-variable sum of the charge on all rods must be zero.
  
  More formally, the rods can be represented as an array of n numbers characterizing the charge: either 1 or -1. Then the condition must hold: a_1 - a_2 + a_3 - a_4 + … = 0, or ∑_{i=1}^n (-1)^{i-1} ⋅ a_i = 0.
  
  Sparky charged all n rods with an electric current, but unfortunately it happened that the rods were not charged correctly (the sign-variable sum of the charge is not zero). The friends decided to leave only some of the rods in the machine. Sparky has q questions. In the ith question Sparky asks: if the machine consisted only of rods with numbers l_i to r_i inclusive, what minimal number of rods could be removed from the machine so that the sign-variable sum of charges on the remaining ones would be zero? Perhaps the friends got something wrong, and the sign-variable sum is already zero. In that case, you don't have to remove the rods at all.
  
  If the number of rods is zero, we will assume that the sign-variable sum of charges is zero, that is, we can always remove all rods.
  
  Help your friends and answer all of Sparky's questions!
  
  Input
  
  Each test contains multiple test cases.
  
  The first line contains one positive integer t (1 ≤ t ≤ 10^3), denoting the number of test cases. Description of the test cases follows.
  
  The first line of each test case contains two positive integers n and q (1 ≤ n, q ≤ 3 ⋅ 10^5) — the number of rods and the number of questions.
  
  The second line of each test case contains a non-empty string s of length n, where the charge of the i-th rod is 1 if s_i is the "+" symbol, or -1 if s_i is the "-" symbol.
  
  Each next line from the next q lines contains two positive integers l_i ans r_i (1 ≤ l_i ≤ r_i ≤ n) — numbers, describing Sparky's questions.
  
  It is guaranteed that the sum of n over all test cases does not exceed 3 ⋅ 10^5, and the sum of q over all test cases does not exceed 3 ⋅ 10^5.
  
  Output
  
  For each test case, print a single integer — the minimal number of rods that can be removed.
  
  Example
  
  Input
  
  
  3
  14 1
  +--++---++-++-
  1 14
  14 3
  +--++---+++---
  1 14
  6 12
  3 10
  4 10
  +-+-
  1 1
  1 2
  1 3
  1 4
  2 2
  2 3
  2 4
  3 3
  3 4
  4 4
  
  
  Output
  
  
  2
  2
  1
  0
  1
  2
  1
  2
  1
  2
  1
  1
  2
  1
  
  Note
  
  In the first test case for the first query you can remove the rods numbered 5 and 8, then the following set of rods will remain: +--+--++-++-. It is easy to see that here the sign-variable sum is zero.
  
  In the second test case:
  
    * For the first query, we can remove the rods numbered 1 and 11, then the following set of rods will remain: --++---++---. It is easy to see that here the sign-variable sum is zero. 
    * For the second query we can remove the rod numbered 9, then the following set of rods will remain: ---++-. It is easy to see that here the variable sum is zero. 
    * For the third query we can not remove the rods at all. 
solution: 
  def divisors(M):
      d=[]
      i=1
      while M>=i**2:
          if M%i==0:
              d.append(i)
              if i**2!=M:
                  d.append(M//i)
          i=i+1
      return d
  
  def popcount(x):
      x = x - ((x >> 1) & 0x55555555)
      x = (x & 0x33333333) + ((x >> 2) & 0x33333333)
      x = (x + (x >> 4)) & 0x0f0f0f0f
      x = x + (x >> 8)
      x = x + (x >> 16)
      return x & 0x0000007f
  
  def eratosthenes(n):
      res=[0 for i in range(n+1)]
      prime=set([])
      for i in range(2,n+1):
          if not res[i]:
              prime.add(i)
              for j in range(1,n//i+1):
                  res[i*j]=1
      return prime
  
  def factorization(n):
      res=[]
      for p in prime:
          if n%p==0:
              while n%p==0:
                  n//=p
              res.append(p)
      if n!=1:
          res.append(n)
      return res
  
  def euler_phi(n):
      res = n
      for x in range(2,n+1):
          if x ** 2 > n:
              break
          if n%x==0:
              res = res//x * (x-1)
              while n%x==0:
                  n //= x
      if n!=1:
          res = res//n * (n-1)
      return res
  
  def ind(b,n):
      res=0
      while n%b==0:
          res+=1
          n//=b
      return res
  
  def isPrimeMR(n):
      d = n - 1
      d = d // (d & -d)
      L = [2, 3, 5, 7, 11, 13, 17]
      for a in L:
          t = d
          y = pow(a, t, n)
          if y == 1: continue
          while y != n - 1:
              y = (y * y) % n
              if y == 1 or t == n - 1: return 0
              t <<= 1
      return 1
  def findFactorRho(n):
      from math import gcd
      m = 1 << n.bit_length() // 8
      for c in range(1, 99):
          f = lambda x: (x * x + c) % n
          y, r, q, g = 2, 1, 1, 1
          while g == 1:
              x = y
              for i in range(r):
                  y = f(y)
              k = 0
              while k < r and g == 1:
                  ys = y
                  for i in range(min(m, r - k)):
                      y = f(y)
                      q = q * abs(x - y) % n
                  g = gcd(q, n)
                  k += m
              r <<= 1
          if g == n:
              g = 1
              while g == 1:
                  ys = f(ys)
                  g = gcd(abs(x - ys), n)
          if g < n:
              if isPrimeMR(g): return g
              elif isPrimeMR(n // g): return n // g
              return findFactorRho(g)
  def primeFactor(n):
      i = 2
      ret = {}
      rhoFlg = 0
      while i*i <= n:
          k = 0
          while n % i == 0:
              n //= i
              k += 1
          if k: ret[i] = k
          i += 1 + i % 2
          if i == 101 and n >= 2 ** 20:
              while n > 1:
                  if isPrimeMR(n):
                      ret[n], n = 1, 1
                  else:
                      rhoFlg = 1
                      j = findFactorRho(n)
                      k = 0
                      while n % j == 0:
                          n //= j
                          k += 1
                      ret[j] = k
  
      if n > 1: ret[n] = 1
      if rhoFlg: ret = {x: ret[x] for x in sorted(ret)}
      return ret
  
  def divisors(n):
      res = [1]
      prime = primeFactor(n)
      for p in prime:
          newres = []
          for d in res:
              for j in range(prime[p]+1):
                  newres.append(d*p**j)
          res = newres
      res.sort()
      return res
  
  def xorfactorial(num):
      if num==0:
          return 0
      elif num==1:
          return 1
      elif num==2:
          return 3
      elif num==3:
          return 0
      else:
          x=baseorder(num)
          return (2**x)*((num-2**x+1)%2)+function(num-2**x)
  
  def xorconv(n,X,Y):
      if n==0:
          res=[(X[0]*Y[0])%mod]
          return res
      x=[X[i]+X[i+2**(n-1)] for i in range(2**(n-1))]
      y=[Y[i]+Y[i+2**(n-1)] for i in range(2**(n-1))]
      z=[X[i]-X[i+2**(n-1)] for i in range(2**(n-1))]
      w=[Y[i]-Y[i+2**(n-1)] for i in range(2**(n-1))]
      res1=xorconv(n-1,x,y)
      res2=xorconv(n-1,z,w)
      former=[(res1[i]+res2[i])*inv for i in range(2**(n-1))]
      latter=[(res1[i]-res2[i])*inv for i in range(2**(n-1))]
      former=list(map(lambda x:x%mod,former))
      latter=list(map(lambda x:x%mod,latter))
      return former+latter
  
  def merge_sort(A,B):
      pos_A,pos_B = 0,0
      n,m = len(A),len(B)
      res = []
      while pos_A < n and pos_B < m:
          a,b = A[pos_A],B[pos_B]
          if a < b:
              res.append(a)
              pos_A += 1
          else:
              res.append(b)
              pos_B += 1
      res += A[pos_A:]
      res += B[pos_B:]
      return res
  
  class UnionFindVerSize():
      def __init__(self, N):
          self._parent = [n for n in range(0, N)]
          self._size = [1] * N
          self.group = N
  
      def find_root(self, x):
          if self._parent[x] == x: return x
          self._parent[x] = self.find_root(self._parent[x])
          stack = [x]
          while self._parent[stack[-1]]!=stack[-1]:
              stack.append(self._parent[stack[-1]])
          for v in stack:
              self._parent[v] = stack[-1]
          return self._parent[x]
  
      def unite(self, x, y):
          gx = self.find_root(x)
          gy = self.find_root(y)
          if gx == gy: return
  
          self.group -= 1
  
          if self._size[gx] < self._size[gy]:
              self._parent[gx] = gy
              self._size[gy] += self._size[gx]
          else:
              self._parent[gy] = gx
              self._size[gx] += self._size[gy]
  
      def get_size(self, x):
          return self._size[self.find_root(x)]
  
      def is_same_group(self, x, y):
          return self.find_root(x) == self.find_root(y)
  
  class WeightedUnionFind():
      def __init__(self,N):
          self.parent = [i for i in range(N)]
          self.size = [1 for i in range(N)]
          self.val = [0 for i in range(N)]
          self.flag = True
          self.edge = [[] for i in range(N)]
  
      def dfs(self,v,pv):
          stack = [(v,pv)]
          new_parent = self.parent[pv]
          while stack:
              v,pv = stack.pop()
              self.parent[v] = new_parent
              for nv,w in self.edge[v]:
                  if nv!=pv:
                      self.val[nv] = self.val[v] + w
                      stack.append((nv,v))
  
      def unite(self,x,y,w):
          if not self.flag:
              return
          if self.parent[x]==self.parent[y]:
              self.flag = (self.val[x] - self.val[y] == w)
              return
  
          if self.size[self.parent[x]]>self.size[self.parent[y]]:
              self.edge[x].append((y,-w))
              self.edge[y].append((x,w))
              self.size[x] += self.size[y]
              self.val[y] = self.val[x] - w
              self.dfs(y,x)
          else:
              self.edge[x].append((y,-w))
              self.edge[y].append((x,w))
              self.size[y] += self.size[x]
              self.val[x] = self.val[y] + w
              self.dfs(x,y)
  
  class Dijkstra():
      class Edge():
          def __init__(self, _to, _cost):
              self.to = _to
              self.cost = _cost
  
      def __init__(self, V):
          self.G = [[] for i in range(V)]
          self._E = 0
          self._V = V
  
      @property
      def E(self):
          return self._E
  
      @property
      def V(self):
          return self._V
  
      def add_edge(self, _from, _to, _cost):
          self.G[_from].append(self.Edge(_to, _cost))
          self._E += 1
  
      def shortest_path(self, s):
          import heapq
          que = []
          d = [10**15] * self.V
          d[s] = 0
          heapq.heappush(que, (0, s))
  
          while len(que) != 0:
              cost, v = heapq.heappop(que)
              if d[v] < cost: continue
  
              for i in range(len(self.G[v])):
                  e = self.G[v][i]
                  if d[e.to] > d[v] + e.cost:
                      d[e.to] = d[v] + e.cost
                      heapq.heappush(que, (d[e.to], e.to))
          return d
  
  #Z[i]:length of the longest list starting from S[i] which is also a prefix of S
  #O(|S|)
  def Z_algorithm(s):
      N = len(s)
      Z_alg = [0]*N
  
      Z_alg[0] = N
      i = 1
      j = 0
      while i < N:
          while i+j < N and s[j] == s[i+j]:
              j += 1
          Z_alg[i] = j
          if j == 0:
              i += 1
              continue
          k = 1
          while i+k < N and k + Z_alg[k]<j:
              Z_alg[i+k] = Z_alg[k]
              k += 1
          i += k
          j -= k
      return Z_alg
  
  class BIT():
      def __init__(self,n,mod=0):
          self.BIT = [0]*(n+1)
          self.num = n
          self.mod = mod
  
      def query(self,idx):
          res_sum = 0
          mod = self.mod
          while idx > 0:
              res_sum += self.BIT[idx]
              if mod:
                  res_sum %= mod
              idx -= idx&(-idx)
          return res_sum
  
      #Ai += x O(logN)
      def update(self,idx,x):
          mod = self.mod
          while idx <= self.num:
              self.BIT[idx] += x
              if mod:
                  self.BIT[idx] %= mod
              idx += idx&(-idx)
          return
  
  class dancinglink():
      def __init__(self,n,debug=False):
          self.n = n
          self.debug = debug
          self._left = [i-1 for i in range(n)]
          self._right = [i+1 for i in range(n)]
          self.exist = [True for i in range(n)]
  
      def pop(self,k):
          if self.debug:
              assert self.exist[k]
          L = self._left[k]
          R = self._right[k]
          if L!=-1:
              if R!=self.n:
                  self._right[L],self._left[R] = R,L
              else:
                  self._right[L] = self.n
          elif R!=self.n:
              self._left[R] = -1
          self.exist[k] = False
  
      def left(self,idx,k=1):
          if self.debug:
              assert self.exist[idx]
          res = idx
          while k:
              res = self._left[res]
              if res==-1:
                  break
              k -= 1
          return res
  
      def right(self,idx,k=1):
          if self.debug:
              assert self.exist[idx]
          res = idx
          while k:
              res = self._right[res]
              if res==self.n:
                  break
              k -= 1
          return res
  
  class SparseTable():
      def __init__(self,A,merge_func,ide_ele):
          N=len(A)
          n=N.bit_length()
          self.table=[[ide_ele for i in range(n)] for i in range(N)]
          self.merge_func=merge_func
  
          for i in range(N):
              self.table[i][0]=A[i]
  
          for j in range(1,n):
              for i in range(0,N-2**j+1):
                  f=self.table[i][j-1]
                  s=self.table[i+2**(j-1)][j-1]
                  self.table[i][j]=self.merge_func(f,s)
  
      def query(self,s,t):
          b=t-s+1
          m=b.bit_length()-1
          return self.merge_func(self.table[s][m],self.table[t-2**m+1][m])
  
  class BinaryTrie:
      class node:
          def __init__(self,val):
              self.left = None
              self.right = None
              self.max = val
  
      def __init__(self):
          self.root = self.node(-10**15)
  
      def append(self,key,val):
          pos = self.root
          for i in range(29,-1,-1):
              pos.max = max(pos.max,val)
              if key>>i & 1:
                  if pos.right is None:
                      pos.right = self.node(val)
                      pos = pos.right
                  else:
                      pos = pos.right
              else:
                  if pos.left is None:
                      pos.left = self.node(val)
                      pos = pos.left
                  else:
                      pos = pos.left
          pos.max = max(pos.max,val)
  
      def search(self,M,xor):
          res = -10**15
          pos = self.root
          for i in range(29,-1,-1):
              if pos is None:
                  break
  
              if M>>i & 1:
                  if xor>>i & 1:
                      if pos.right:
                          res = max(res,pos.right.max)
                      pos = pos.left
                  else:
                      if pos.left:
                          res = max(res,pos.left.max)
                      pos = pos.right
              else:
                  if xor>>i & 1:
                      pos = pos.right
                  else:
                      pos = pos.left
  
          if pos:
              res = max(res,pos.max)
          return res
  
  def solveequation(edge,ans,n,m):
      #edge=[[to,dire,id]...]
      x=[0]*m
      used=[False]*n
      for v in range(n):
          if used[v]:
              continue
          y = dfs(v)
          if y!=0:
              return False
      return x
  
      def dfs(v):
          used[v]=True
          r=ans[v]
          for to,dire,id in edge[v]:
              if used[to]:
                  continue
              y=dfs(to)
              if dire==-1:
                  x[id]=y
              else:
                  x[id]=-y
              r+=y
          return r
  
  class SegmentTree:
      def __init__(self, init_val, segfunc, ide_ele):
          n = len(init_val)
          self.segfunc = segfunc
          self.ide_ele = ide_ele
          self.num = 1 << (n - 1).bit_length()
          self.tree = [ide_ele] * 2 * self.num
          self.size = n
          for i in range(n):
              self.tree[self.num + i] = init_val[i]
          for i in range(self.num - 1, 0, -1):
              self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])
  
      def update(self, k, x):
          k += self.num
          self.tree[k] = x
          while k > 1:
              self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
              k >>= 1
  
      def query(self, l, r):
          if r==self.size:
              r = self.num
  
          res = self.ide_ele
  
          l += self.num
          r += self.num
          while l < r:
              if l & 1:
                  res = self.segfunc(res, self.tree[l])
                  l += 1
              if r & 1:
                  res = self.segfunc(res, self.tree[r - 1])
              l >>= 1
              r >>= 1
          return res
  
      def bisect_l(self,l,r,x):
          l += self.num
          r += self.num
          Lmin = -1
          Rmin = -1
          while l<r:
              if l & 1:
                  if self.tree[l] <= x and Lmin==-1:
                      Lmin = l
                  l += 1
              if r & 1:
                  if self.tree[r-1] <=x:
                      Rmin = r-1
              l >>= 1
              r >>= 1
  
          if Lmin != -1:
              pos = Lmin
              while pos<self.num:
                  if self.tree[2 * pos] <=x:
                      pos = 2 * pos
                  else:
                      pos = 2 * pos +1
              return pos-self.num
          elif Rmin != -1:
              pos = Rmin
              while pos<self.num:
                  if self.tree[2 * pos] <=x:
                      pos = 2 * pos
                  else:
                      pos = 2 * pos +1
              return pos-self.num
          else:
              return -1
  
  import sys,random,bisect
  from collections import deque,defaultdict
  from heapq import heapify,heappop,heappush
  from itertools import permutations
  from math import gcd,log
  
  input = lambda :sys.stdin.readline().rstrip()
  mi = lambda :map(int,input().split())
  li = lambda :list(mi())
  
  c = {"+":1,"-":-1}
  
  for _ in range(int(input())):
      n,q = mi()
      S = input()
      A = [0]
      for i in range(n):
          if i&1:
              A.append(-c[S[i]])
          else:
              A.append(c[S[i]])
      for i in range(1,n+1):
          A[i] += A[i-1]
      
      for i in range(q):
          l,r = mi()
          if (r-l+1)&1:
              print(1)
          else:
              tmp = A[r] - A[l-1]
              if tmp==0:
                  print(0)
              else:
                  print(2)
  