description: You are given a string s, consisting of n letters, each letter is either 'a' or 'b'. The letters in the string are numbered from 1 to n.
  
  s[l; r] is a continuous substring of letters from index l to r of the string inclusive. 
  
  A string is called balanced if the number of letters 'a' in it is equal to the number of letters 'b'. For example, strings "baba" and "aabbab" are balanced and strings "aaab" and "b" are not.
  
  Find any non-empty balanced substring s[l; r] of string s. Print its l and r (1 ≤ l ≤ r ≤ n). If there is no such substring, then print -1 -1.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of testcases.
  
  Then the descriptions of t testcases follow.
  
  The first line of the testcase contains a single integer n (1 ≤ n ≤ 50) — the length of the string.
  
  The second line of the testcase contains a string s, consisting of n letters, each letter is either 'a' or 'b'.
  
  Output
  
  For each testcase print two integers. If there exists a non-empty balanced substring s[l; r], then print l r (1 ≤ l ≤ r ≤ n). Otherwise, print -1 -1.
  
  Example
  
  Input
  
  
  4
  1
  a
  6
  abbaba
  6
  abbaba
  9
  babbabbaa
  
  
  Output
  
  
  -1 -1
  1 6
  3 6
  2 5
  
  Note
  
  In the first testcase there are no non-empty balanced subtrings.
  
  In the second and third testcases there are multiple balanced substrings, including the entire string "abbaba" and substring "baba".
solution: import java.io.BufferedReader;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.util.ArrayList;
  import java.util.List;
  import java.util.Objects;
  import java.util.StringTokenizer;
  
  import static java.lang.Math.log;
  import static java.lang.Math.min;
  
  public class Codeforces742 {
  
      //------------------------------------------CONSTANTS---------------------------------------------------------------
      public static final int MOD = (int) (1e9 + 7);
  
      //---------------------------------------------I/0------------------------------------------------------------------
  
      static class FastReader {
          BufferedReader br;
          StringTokenizer st;
  
          public FastReader()
          {
              br = new BufferedReader(
                      new InputStreamReader(System.in));
          }
  
          String next()
          {
              while (st == null || !st.hasMoreElements()) {
                  try {
                      st = new StringTokenizer(br.readLine());
                  }
                  catch (IOException e) {
                      e.printStackTrace();
                  }
              }
              return st.nextToken();
          }
  
          int nextInt() { return Integer.parseInt(next()); }
  
          long nextLong() { return Long.parseLong(next()); }
  
          double nextDouble()
          {
              return Double.parseDouble(next());
          }
  
          String nextLine()
          {
              String str = "";
              try {
                  str = br.readLine();
              }
              catch (IOException e) {
                  e.printStackTrace();
              }
              return str;
          }
      }
  
      public static void print(String s) {
          System.out.println(s);
      }
  
      public static void main(String[] args) {
          FastReader sc = new FastReader();
  
          int t = 1;
          t = sc.nextInt();
  
          for(int i = 0; i<t; i++) {
              System.out.println(solve(sc));
          }
      }
  
      //------------------------------------------------SOLVE-------------------------------------------------------------
  
      public static String solve(FastReader sc) {
          int n = sc.nextInt();
          char[] s = sc.next().toCharArray();
  
          int[] psa = new int[n+1];
          int[] psb = new int[n+1];
  
          if (s[0] == 'a') {
              psa[1] = 1;
          } else {
              psb[1] = 1;
          }
  
          for (int i = 1; i<n; i++) {
              if (s[i] == 'a') {
                  psb[i+1] = psb[i];
                  psa[i+1] = psa[i] + 1;
              } else {
                  psa[i+1] = psa[i];
                  psb[i+1] = psb[i] + 1;
              }
          }
  
          for (int l = 1; l<=n; l++) {
              for (int r = l+1; r<=n; r++) {
                  if (psa[r] - psa[l-1] == psb[r] - psb[l-1]) {
                      return l + " " + r;
                  }
              }
          }
  
          return -1 + " " + -1;
      }
  
      //-----------------------------------------------FUNCTIONS----------------------------------------------------------
  
      public static void printArray(int[] a) {
          for(int i = 0; i<a.length; i++) {
              System.out.print(a[i] + " ");
          }
      }
  
      // first element that is not less than target
      public static int lowerBound(int[] arr, int begin, int end, int target) {
          while(begin < end) {
              int mid = begin + (end - begin) / 2;
              // When the element is less than the mid target
              if(arr[mid] < target)
                  // begin to mid + 1, arr [begin] value is less than or equal target
                  begin = mid + 1;
                  // When the mid target element when greater than or equal
              else if(arr[mid] >= target)
                  end = mid;
          }
          return begin;
      }
  
      // first element that is greater than target
      public static int upperBound(int[] arr, int begin, int end, int target) {
          while(begin < end) {
              int mid = begin + (end - begin) / 2;
              if(arr[mid] <= target)
                  begin = mid + 1;
              else if(arr[mid] < target)
                  end = mid;
          }
          return begin;
      }
  
      // generate permutations (call search and access through permutations)
      public static class Permutations {
          List<List<Integer>> permutations = new ArrayList<>();
          List<Integer> permutation = new ArrayList<>();
          boolean[] taken;
          int[] a;
  
          public Permutations(int[] a) {
              this.a = a;
              taken = new boolean[a.length];
          }
  
          void search() {
              if (permutation.size()==a.length) {
                  permutations.add(new ArrayList<>(permutation));
              } else {
                  for (int i = 0; i<a.length; i++) {
                      if (taken[i]) {
                          continue;
                      }
                      taken[i] = true;
                      permutation.add(a[i]);
                      search();
                      taken[i] = false;
                      permutation.remove(permutation.size()-1);
                  }
              }
          }
      }
  
      // generate subsets (call search and access subsets)
      public static class Subsets {
          List<List<Integer>> subsets = new ArrayList<>();
          List<Integer> subset = new ArrayList<>();
  
          void search(int[] a, int x) {
              if (x == a.length) {
                  subsets.add(new ArrayList<>(subset));
              } else {
                  subset.add(a[x]);
                  search(a, x+1);
                  subset.remove(subset.size() - 1);
                  search(a, x+1);
              }
          }
      }
  
      public static int gcd(int a, int b) {
          while (b != 0) {
              int t = b;
              b = a % b;
              a = t;
          }
          return a;
      }
  
      public static int lcm(int a, int b) {
          return (a*b)/gcd(a, b);
      }
  
      public static int[] prefixSum(int[] a) {
          int n = a.length;
          int[] ps = new int[n];
          ps[0] = a[0];
  
          for (int i = 1; i<n; i++) {
              ps[i] = ps[i-1] + a[i];
          }
  
          return ps;
      }
  
      public static int[][] prefixSum2D(int[][] a) {
          int n = a.length;
          int m = a[0].length;
          int[][] ps = new int[n][m];
          ps[0][0] = a[0][0];
  
          for (int j = 1; j<m; j++) {
              ps[0][j] = ps[0][j-1] + a[0][j];
          }
          for (int i = 1; i<n; i++) {
              ps[i][0] = ps[i-1][0] + a[i][0];
          }
  
          for (int i = 1; i<n; i++) {
              for (int j = 1; j<m; j++) {
                  ps[i][j] = ps[i-1][j] + ps[i][j-1] - ps[i-1][j-1] + a[i][j];
              }
          }
  
          return ps;
      }
  
      public static double log2(double a) {
          return log(a)/log(2);
      }
  
      //----------------------------------------DATA-STRUCTURES-----------------------------------------------------------
  
      // Range queries (i.e. RMQ) in O(1), others with functions in O(log n)
      public static class SparseTable {
          int[][] st;
          int n;
          int k;
  
          public SparseTable(int[] a) {
              n = a.length;
              k = (int) log2(n);
              st = new int[n][k+1];
  
              for (int i = 0; i<n; i++) {
                  st[i][0] = a[i];
              }
  
              // 1<<j == 2^j
              for (int j = 1; j<=k; j++) {
                  for (int i = 0; i + (1 << j) <= n; i++) {
                      st[i][j] = min(st[i][j-1], st[i + (1 << (j - 1))][j - 1]);
                  }
              }
          }
  
          //not always available O(log n) -- change the constructor to use it
          public long sumQuery(int l, int r) {
              long sum = 0;
              for (int j = k; j>=0; j--) {
                  if ((1 << j) <= r - l + 1) {
                      sum += st[l][j];
                      l += 1 << j;
                  }
              }
  
              return sum;
          }
  
          //always available O(1) -- change this and the constructor for rangeMaxQuery
          public int rangeMinQuery(int l, int r) {
              int j = (int) log2(r - l + 1);
              int min = min(st[l][j], st[r - (1 << j) + 1][j]);
              return min;
          }
  
      }
  
      //Range Sum Dynamic Queries O(log n)
      public static class BinaryIndexedTree {
  
          int[] bit;
  
          public BinaryIndexedTree(int[] a) {
              int n = a.length;
              bit = new int[n+1];
              // Store the actual values in BITree[]
              // using update()
              for(int i = 0; i < n; i++)
                  updateBit(i, a[i]);
          }
  
          // O(log n) update delta at index in the array (do it on the array and then call this function)
          public void updateBit(int index, int delta) {
              index += 1;
  
              while (index <= bit.length) {
                  bit[index] += delta;
  
                  index += index & (-index);
              }
          }
  
          // Computes sum a[0...index] in O(log n)
          public int getSum(int index) {
              int sum = 0;
  
              index += 1;
  
              while (index > 0) {
                  sum += bit[index];
  
                  index -= index & (-index);
              }
  
              return sum;
          }
      }
  
      public static class UnionFind {
  
          int[] link;
          int[] size;
  
          UnionFind(int n) {
              link = new int[n];
              size = new int[n];
              for (int i = 0; i<n; i++) {
                  link[i] = i;
                  size[i] = 1;
              }
          }
  
          int find(int x) {
              while (x != link[x]) x = link[x];
              return x;
          }
  
          boolean same(int a, int b) {
              return find(a) == find(b);
          }
  
          void unite(int a, int b) {
              a = find(a);
              b = find(b);
  
              if (size[a] < size[b]) {
                  int temp = a;
                  a = b;
                  b = temp;
              }
  
              size[a] += size[b];
              link[b] = a;
          }
      }
  
      public static class SegmentTree {
  
          int st[];
  
          public SegmentTree(int arr[]) {
              int n = arr.length;
  
              int x = (int) (Math.ceil(log2(n)));
  
              int maxSize = 2 * (int) Math.pow(2, x) - 1;
  
              st = new int[maxSize];
  
              build(arr, 0, n-1, 0);
          }
  
          int build(int arr[], int ss, int se, int si) {
              if (ss == se) {
                  st[si] = arr[ss];
                  return arr[ss];
              }
  
              int mid = ss + (se - ss) / 2; //ss+se/2
  
              st[si] = build(arr, ss, mid, si * 2 + 1) +
                      build(arr, mid + 1, se, si * 2 + 2);
              return st[si];
          }
  
          private int getSumUtil(int ss, int se, int l, int r, int si) {
              if (l <= ss && r >= se) {
                  return st[si];
              }
  
              if (se < l || ss > r) {
                  return 0;
              }
  
              int mid = ss + (se - ss) / 2;
              return getSumUtil(ss, mid, l, r, 2 * si + 1) +
                      getSumUtil(mid + 1, se, l, r, 2 * si + 2);
          }
  
          void updateValueUtil(int ss, int se, int i, int diff, int si) {
              if (i < ss || i > se) {
                  return;
              }
  
              st[si] = st[si] + diff;
              if (se != ss) {
                  int mid = ss + (se - ss) / 2;
                  updateValueUtil(ss, mid, i, diff, 2 * si + 1);
                  updateValueUtil(mid + 1, se, i, diff, 2 * si + 2);
              }
          }
  
          int getSum(int n, int l, int r) {
              if (l < 0 || r > n - 1 || l > r) {
                  return -1;
              }
  
              return getSumUtil(0, n-1, l, r, 0);
          }
  
          // don't do it directly on the array but use this function that will
          // do everything for you
          void updateValue(int arr[], int n, int i, int newValue) {
              if (i < 0 || i > n - 1) {
                  return;
              }
  
              int diff = newValue - arr[i];
  
              arr[i] = newValue;
  
              updateValueUtil(0, n - 1, i, diff, 0);
          }
      }
  
      // Similar to Pair in c++, non-null objects as parameters
      public static class Pair<T extends Comparable<T>, Q extends Comparable<Q>> implements Comparable<Pair<T, Q>>{
          T a;
          Q b;
  
          public Pair(T a, Q b) {
              this.a = a;
              this.b = b;
          }
  
          @Override
          public boolean equals(Object o) {
              if (this == o) return true;
              if (o == null || getClass() != o.getClass()) return false;
              Pair<?, ?> pair = (Pair<?, ?>) o;
              return a.equals(pair.a) && b.equals(pair.b);
          }
  
          @Override
          public int hashCode() {
              return Objects.hash(a, b);
          }
  
  
          @Override
          public int compareTo(Pair<T, Q> tqPair) {
              int compareA = this.a.compareTo(tqPair.a);
  
              if (compareA == 0) {
                  return this.b.compareTo(tqPair.b);
              } else {
                  return compareA;
              }
          }
      }
  
  
  }