description: You are given two strings s and t, both consisting of lowercase English letters. You are going to type the string s character by character, from the first character to the last one.
  
  When typing a character, instead of pressing the button corresponding to it, you can press the "Backspace" button. It deletes the last character you have typed among those that aren't deleted yet (or does nothing if there are no characters in the current string). For example, if s is "abcbd" and you press Backspace instead of typing the first and the fourth characters, you will get the string "bd" (the first press of Backspace deletes no character, and the second press deletes the character 'c'). Another example, if s is "abcaa" and you press Backspace instead of the last two letters, then the resulting text is "a".
  
  Your task is to determine whether you can obtain the string t, if you type the string s and press "Backspace" instead of typing several (maybe zero) characters of s.
  
  Input
  
  The first line contains a single integer q (1 ≤ q ≤ 10^5) — the number of test cases.
  
  The first line of each test case contains the string s (1 ≤ |s| ≤ 10^5). Each character of s is a lowercase English letter.
  
  The second line of each test case contains the string t (1 ≤ |t| ≤ 10^5). Each character of t is a lowercase English letter.
  
  It is guaranteed that the total number of characters in the strings over all test cases does not exceed 2 ⋅ 10^5.
  
  Output
  
  For each test case, print "YES" if you can obtain the string t by typing the string s and replacing some characters with presses of "Backspace" button, or "NO" if you cannot.
  
  You may print each letter in any case (YES, yes, Yes will all be recognized as positive answer, NO, no and nO will all be recognized as negative answer).
  
  Example
  
  Input
  
  
  4
  ababa
  ba
  ababa
  bb
  aaa
  aaaa
  aababa
  ababa
  
  
  Output
  
  
  YES
  NO
  NO
  YES
  
  Note
  
  Consider the example test from the statement.
  
  In order to obtain "ba" from "ababa", you may press Backspace instead of typing the first and the fourth characters.
  
  There's no way to obtain "bb" while typing "ababa".
  
  There's no way to obtain "aaaa" while typing "aaa".
  
  In order to obtain "ababa" while typing "aababa", you have to press Backspace instead of typing the first character, then type all the remaining characters.
solution: /*
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   * To change this template file, choose Tools | Templates
   * and open the template in the editor.
   */
  
  import java.io.BufferedReader;
  import java.io.DataInputStream;
  import java.io.FileInputStream;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.io.PrintWriter;
  import java.util.Arrays;
  import java.util.StringTokenizer;
  
  /**
   *
   * @author is2ac
   */
  public class D_CF {
  
      public static void main(String[] args) throws IOException {
          FastScanner58 fs = new FastScanner58();
          //Reader fs = new Reader();
          PrintWriter pw = new PrintWriter(System.out);
          int t = fs.ni();
          //int t = 1;
          for (int tc = 0; tc < t; tc++) {
              String a = fs.next();
              String b = fs.next();
              int p = -1;
              int ind = 0;
              for (int i = 0; i < a.length() && ind<b.length(); i++) {
                  if (a.charAt(i)==b.charAt(ind)) {
                      if ((p==-1&&i%2==0) || (p!=-1&&(i-p)%2==1)) {
                          p = i;
                          ind++;
                      }
                  }
              }
              if (ind==b.length() && (a.length()-p-1)%2==0) {
                  pw.println("YES");
                  continue;
              }
              p = -1;
              ind = 0;
              for (int i = 0; i < a.length() && ind<b.length(); i++) {
                  if (a.charAt(i)==b.charAt(ind)) {
                      if ((p==-1&&i%2==1) || (p!=-1&&(i-p)%2==1)) {
                          p = i;
                          ind++;
                      }
                  }
              }
              if (ind==b.length() && (a.length()-p-1)%2==0) {
                  pw.println("YES");
                  continue;
              }
              pw.println("NO");
          }
          pw.close();
      }
      public static boolean isPrime(int n) {
          if (n == 1) {
              return false;
          }
          for (int i = 2; i <= (int) Math.sqrt(n); i++) {
              if (n % i == 0) {
                  return false;
              }
          }
          return true;
      }
  
      public static int primes(int a) {
          int b = a;
          int ct = 0;
          for (int i = 2; i <= (int) Math.sqrt(b); i++) {
              if (a % i != 0) {
                  continue;
              }
              if (!isPrime(i)) {
                  continue;
              }
              int j = a / i;
              while (a % i == 0) {
                  a /= i;
                  ct++;
              }
              if (!isPrime(j)) {
                  continue;
              }
              if (j == 1) {
                  continue;
              }
              while (a % j == 0) {
                  a /= j;
                  ct++;
              }
          }
          return ct;
      }
  
      public static int dis(int a, int b, int n) {
          //for a to get to b
          if (a < b) {
              return b - a;
          }
          b += n;
          return b - a;
      }
  
      public static long gcd(long n1, long n2) {
          if (n2 == 0) {
              return n1;
          }
          return gcd(n2, n1 % n2);
      }
  }
  
  class GFG {
  
      // A utility function to get the
      // middle index of given range.
      static int getMid(int s, int e) {
          return s + (e - s) / 2;
      }
  
      /*
      * A recursive function to get the sum
      of values in given range of the array.
      * The following are parameters
        for this function.
      *
      * st -> Pointer to segment tree
      * node -> Index of current node in
      *         the segment tree.
      * ss & se -> Starting and ending indexes
      *         of the segment represented
      *         by current node, i.e., st[node]
      * l & r -> Starting and ending indexes
      *         of range query
       */
      static long MinUtil(long[] st, int ss,
              int se, int l,
              int r, int node) {
  
          // If segment of this node is completely
          // part of given range, then return
          // the max of segment
          if (l <= ss && r >= se) {
              return st[node];
          }
  
          // If segment of this node does not
          // belong to given range
          if (se < l || ss > r) {
              return (long) (1e11);
          }
  
          // If segment of this node is partially
          // the part of given range
          int mid = getMid(ss, se);
  
          return Math.min(
                  MinUtil(st, ss, mid, l, r,
                          2 * node + 1),
                  MinUtil(st, mid + 1, se, l, r,
                          2 * node + 2));
      }
  
      /*
      * A recursive function to update the
      nodes which have the given index in their
      * range. The following are parameters
      st, ss and se are same as defined above
      * index -> index of the element to be updated.
       */
      static void updateValue(long arr[], long[] st, int ss,
              int se, int index,
              long value,
              int node) {
          if (index < ss || index > se) {
              //System.out.println("Invalid Input");
              return;
          }
  
          if (ss == se) {
  
              // update value in array and in
              // segment tree
              arr[index] = value;
              st[node] = value;
          } else {
              int mid = getMid(ss, se);
  
              if (index >= ss && index <= mid) {
                  updateValue(arr, st, ss, mid,
                          index, value,
                          2 * node + 1);
              } else {
                  updateValue(arr, st, mid + 1, se, index,
                          value, 2 * node + 2);
              }
  
              st[node] = Math.min(st[2 * node + 1],
                      st[2 * node + 2]);
          }
          return;
      }
  
      // Return max of elements in range from
      // index l (query start) to r (query end).
      static long getMin(long[] st, int n, int l, int r) {
  
          // Check for erroneous input values
          if (l < 0 || r > n - 1 || l > r) {
              //System.out.printf("Invalid Input\n");
              return (long) (1e11);
          }
  
          return MinUtil(st, 0, n - 1, l, r, 0);
      }
  
      // A recursive function that constructs Segment
      // Tree for array[ss..se]. si is index of
      // current node in segment tree st
      static long constructSTUtil(long arr[],
              int ss, int se,
              long[] st, int si) {
  
          // If there is one element in array, store
          // it in current node of segment tree and return
          if (ss == se) {
              st[si] = arr[ss];
              return arr[ss];
          }
  
          // If there are more than one elements, then
          // recur for left and right subtrees and
          // store the max of values in this node
          int mid = getMid(ss, se);
  
          st[si] = Math.min(
                  constructSTUtil(arr, ss, mid,
                          st, si * 2 + 1),
                  constructSTUtil(arr, mid + 1,
                          se, st,
                          si * 2 + 2));
  
          return st[si];
      }
  
      /*
      * Function to construct segment tree from
      given array. This function allocates
      * memory for segment tree.
       */
      static long[] constructST(long arr[], int n) {
  
          // Height of segment tree
          int x = (int) Math.ceil(Math.log(n) / Math.log(2));
  
          // Maximum size of segment tree
          int max_size = 2 * (int) Math.pow(2, x) - 1;
  
          // Allocate memory
          long[] st = new long[max_size];
  
          // Fill the allocated memory st
          constructSTUtil(arr, 0, n - 1, st, 0);
  
          // Return the constructed segment tree
          return st;
      }
  }
  
  class BIT16 {
  
      long[] bit;
  
      public BIT16(int size) {
          bit = new long[size];
      }
  
      public void update(int ind, long delta) {
          while (ind < bit.length) {
              bit[ind] += delta;
              ind = ind + (ind & (-1 * ind));
          }
      }
  
      public long sum(int ind) {
          long s = 0;
          while (ind > 0) {
              s += bit[ind];
              ind = ind - (ind & (-1 * ind));
          }
          return s;
      }
  
      public long query(int l, int r) {
          return sum(r) - sum(l);
      }
  }
  
  class UnionFind18 {
  
      int[] id;
  
      public UnionFind18(int size) {
          id = new int[size];
          for (int i = 0; i < size; i++) {
              id[i] = i;
          }
      }
  
      public int find(int p) {
          int root = p;
          while (root != id[root]) {
              root = id[root];
          }
          while (p != root) {
              int next = id[p];
              id[p] = root;
              p = next;
          }
          return root;
      }
  
      public void union(int p, int q) {
          int a = find(p), b = find(q);
          if (a == b) {
              return;
          }
          id[b] = a;
      }
  }
  
  class Reader {
  
      final private int BUFFER_SIZE = 1 << 16;
      private DataInputStream din;
      private byte[] buffer;
      private int bufferPointer, bytesRead;
  
      public Reader() {
          din = new DataInputStream(System.in);
          buffer = new byte[BUFFER_SIZE];
          bufferPointer = bytesRead = 0;
      }
  
      public Reader(String file_name) throws IOException {
          din = new DataInputStream(new FileInputStream(file_name));
          buffer = new byte[BUFFER_SIZE];
          bufferPointer = bytesRead = 0;
      }
  
      public String readLine() throws IOException {
          byte[] buf = new byte[64];
          int cnt = 0, c;
          while ((c = read()) != -1) {
              if (c == '\n') {
                  break;
              }
              buf[cnt++] = (byte) c;
          }
          return new String(buf, 0, cnt);
      }
  
      public int ni() throws IOException {
          int ret = 0;
          byte c = read();
          while (c <= ' ') {
              c = read();
          }
          boolean neg = (c == '-');
          if (neg) {
              c = read();
          }
          do {
              ret = ret * 10 + c - '0';
          } while ((c = read()) >= '0' && c <= '9');
          if (neg) {
              return -ret;
          }
          return ret;
      }
  
      public long nextLong() throws IOException {
          long ret = 0;
          byte c = read();
          while (c <= ' ') {
              c = read();
          }
          boolean neg = (c == '-');
          if (neg) {
              c = read();
          }
          do {
              ret = ret * 10 + c - '0';
          } while ((c = read()) >= '0' && c <= '9');
          if (neg) {
              return -ret;
          }
          return ret;
      }
  
      public double nextDouble() throws IOException {
          double ret = 0, div = 1;
          byte c = read();
          while (c <= ' ') {
              c = read();
          }
          boolean neg = (c == '-');
          if (neg) {
              c = read();
          }
          do {
              ret = ret * 10 + c - '0';
          } while ((c = read()) >= '0' && c <= '9');
          if (c == '.') {
              while ((c = read()) >= '0' && c <= '9') {
                  ret += (c - '0') / (div *= 10);
              }
          }
          if (neg) {
              return -ret;
          }
          return ret;
      }
  
      private void fillBuffer() throws IOException {
          bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
          if (bytesRead == -1) {
              buffer[0] = -1;
          }
      }
  
      private byte read() throws IOException {
          if (bufferPointer == bytesRead) {
              fillBuffer();
          }
          return buffer[bufferPointer++];
      }
  
      public void close() throws IOException {
          if (din == null) {
              return;
          }
          din.close();
      }
  }
  
  class FastScanner58 {
  
      BufferedReader br;
      StringTokenizer st;
  
      public FastScanner58() {
          br = new BufferedReader(new InputStreamReader(System.in), 32768);
          st = null;
      }
  
      String next() {
          while (st == null || !st.hasMoreElements()) {
              try {
                  st = new StringTokenizer(br.readLine());
              } catch (IOException e) {
                  e.printStackTrace();
              }
          }
          return st.nextToken();
      }
  
      int ni() {
          return Integer.parseInt(next());
      }
  
      int[] intArray(int N) {
          int[] ret = new int[N];
          for (int i = 0; i < N; i++) {
              ret[i] = ni();
          }
          return ret;
      }
  
      long nl() {
          return Long.parseLong(next());
      }
  
      long[] longArray(int N) {
          long[] ret = new long[N];
          for (int i = 0; i < N; i++) {
              ret[i] = nl();
          }
          return ret;
      }
  
      double nd() {
          return Double.parseDouble(next());
      }
  
      String nextLine() {
          String str = "";
          try {
              str = br.readLine();
          } catch (IOException e) {
              e.printStackTrace();
          }
          return str;
      }
  }
  