description: A string s of length n, consisting of lowercase letters of the English alphabet, is given.
  
  You must choose some number k between 0 and n. Then, you select k characters of s and permute them however you want. In this process, the positions of the other n-k characters remain unchanged. You have to perform this operation exactly once.
  
  For example, if s="andrea", you can choose the k=4 characters "a_d_ea" and permute them into "d_e_aa" so that after the operation the string becomes "dneraa".
  
  Determine the minimum k so that it is possible to sort s alphabetically (that is, after the operation its characters appear in alphabetical order).
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.
  
  The first line of each test case contains one integer n (1 ≤ n ≤ 40) — the length of the string.
  
  The second line of each test case contains the string s. It is guaranteed that s contains only lowercase letters of the English alphabet.
  
  Output
  
  For each test case, output the minimum k that allows you to obtain a string sorted alphabetically, through the operation described above.
  
  Example
  
  Input
  
  
  4
  3
  lol
  10
  codeforces
  5
  aaaaa
  4
  dcba
  
  
  Output
  
  
  2
  6
  0
  4
  
  Note
  
  In the first test case, we can choose the k=2 characters "_ol" and rearrange them as "_lo" (so the resulting string is "llo"). It is not possible to sort the string choosing strictly less than 2 characters.
  
  In the second test case, one possible way to sort s is to consider the k=6 characters "_o__force_" and rearrange them as "_c__efoor_" (so the resulting string is "ccdeefoors"). One can show that it is not possible to sort the string choosing strictly less than 6 characters.
  
  In the third test case, string s is already sorted (so we can choose k=0 characters).
  
  In the fourth test case, we can choose all k=4 characters "dcba" and reverse the whole string (so the resulting string is "abcd").
solution: import java.io.*;
  import java.util.*;
  
  public class Solution1 {
  
      public static void main(String[] args) throws Exception {
          int t = io.nextInt();
          for (int i = 0; i < t; i++) {
              solve();
          }
          io.close();
      }
  
      private static void solve() throws Exception {
          io.nextInt();
          String s = io.next();
          char[] c1 = s.toCharArray();
          char[] c2 = s.toCharArray();
          Arrays.sort(c2);
          int d = 0;
          for (int i = 0; i < c1.length; i++) {
              if (c1[i] != c2[i]) {
                  d++;
              }
          }
          io.println(d);
      }
  
      static void sort(int[] a) {
          ArrayList<Integer> l = new ArrayList<>(a.length);
          for (int i : a) l.add(i);
          Collections.sort(l);
          for (int i = 0; i < a.length; i++) a[i] = l.get(i);
      }
  
      //-----------PrintWriter for faster output---------------------------------
      public static FastIO io = new FastIO();
  
      //-----------MyScanner class for faster input----------
      static class FastIO extends PrintWriter {
          private InputStream stream;
          private byte[] buf = new byte[1 << 16];
          private int curChar, numChars;
  
          // standard input
          public FastIO() {
              this(System.in, System.out);
          }
  
          public FastIO(InputStream i, OutputStream o) {
              super(o);
              stream = i;
          }
  
          // file input
          public FastIO(String i, String o) throws IOException {
              super(new FileWriter(o));
              stream = new FileInputStream(i);
          }
  
          // throws InputMismatchException() if previously detected end of file
          private int nextByte() {
              if (numChars == -1) throw new InputMismatchException();
              if (curChar >= numChars) {
                  curChar = 0;
                  try {
                      numChars = stream.read(buf);
                  } catch (IOException e) {
                      throw new InputMismatchException();
                  }
                  if (numChars == -1) return -1; // end of file
              }
              return buf[curChar++];
          }
  
          // to read in entire lines, replace c <= ' '
          // with a function that checks whether c is a line break
          public String next() {
              int c;
              do {
                  c = nextByte();
              } while (c <= ' ');
              StringBuilder res = new StringBuilder();
              do {
                  res.appendCodePoint(c);
                  c = nextByte();
              } while (c > ' ');
              return res.toString();
          }
  
          public String nextLine() {
              int c;
              do {
                  c = nextByte();
              } while (c < '\n');
              StringBuilder res = new StringBuilder();
              do {
                  res.appendCodePoint(c);
                  c = nextByte();
              } while (c > '\n');
              return res.toString();
          }
  
          public int nextInt() { // nextLong() would be implemented similarly
              int c;
              do {
                  c = nextByte();
              } while (c <= ' ');
              int sgn = 1;
              if (c == '-') {
                  sgn = -1;
                  c = nextByte();
              }
              int res = 0;
              do {
                  if (c < '0' || c > '9')
                      throw new InputMismatchException();
                  res = 10 * res + c - '0';
                  c = nextByte();
              } while (c > ' ');
              return res * sgn;
          }
  
          public double nextDouble() {
              return Double.parseDouble(next());
          }
      }
  //--------------------------------------------------------
  }