description: Ivan is playing yet another roguelike computer game. He controls a single hero in the game. The hero has n equipment slots. There is a list of c_i items for the i-th slot, the j-th of them increases the hero strength by a_{i,j}. The items for each slot are pairwise distinct and are listed in the increasing order of their strength increase. So, a_{i,1} < a_{i,2} < ... < a_{i,c_i}.
  
  For each slot Ivan chooses exactly one item. Let the chosen item for the i-th slot be the b_i-th item in the corresponding list. The sequence of choices [b_1, b_2, ..., b_n] is called a build.
  
  The strength of a build is the sum of the strength increases of the items in it. Some builds are banned from the game. There is a list of m pairwise distinct banned builds. It's guaranteed that there's at least one build that's not banned.
  
  What is the build with the maximum strength that is not banned from the game? If there are multiple builds with maximum strength, print any of them.
  
  Input
  
  The first line contains a single integer n (1 ≤ n ≤ 10) — the number of equipment slots.
  
  The i-th of the next n lines contains the description of the items for the i-th slot. First, one integer c_i (1 ≤ c_i ≤ 2 ⋅ 10^5) — the number of items for the i-th slot. Then c_i integers a_{i,1}, a_{i,2}, ..., a_{i,c_i} (1 ≤ a_{i,1} < a_{i,2} < ... < a_{i,c_i} ≤ 10^8).
  
  The sum of c_i doesn't exceed 2 ⋅ 10^5.
  
  The next line contains a single integer m (0 ≤ m ≤ 10^5) — the number of banned builds.
  
  Each of the next m lines contains a description of a banned build — a sequence of n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ c_i).
  
  The builds are pairwise distinct, and there's at least one build that's not banned.
  
  Output
  
  Print the build with the maximum strength that is not banned from the game. If there are multiple builds with maximum strength, print any of them.
  
  Examples
  
  Input
  
  
  3
  3 1 2 3
  2 1 5
  3 2 4 6
  2
  3 2 3
  3 2 2
  
  
  Output
  
  
  2 2 3 
  
  
  Input
  
  
  3
  3 1 2 3
  2 1 5
  3 2 4 6
  2
  3 2 3
  2 2 3
  
  
  Output
  
  
  1 2 3
  
  
  Input
  
  
  3
  3 1 2 3
  2 1 5
  3 2 4 6
  2
  3 2 3
  2 2 3
  
  
  Output
  
  
  3 2 2
  
  
  Input
  
  
  4
  1 10
  1 4
  1 7
  1 3
  0
  
  
  Output
  
  
  1 1 1 1 
solution: import sys
  import math
  import heapq
  import bisect
  from collections import Counter, deque
  from collections import defaultdict
  from io import BytesIO, IOBase
  from itertools import permutations
  import string
  
  
  class FastIO(IOBase):
      newlines = 0
  
      def __init__(self, file):
          import os
          self.os = os
          self._fd = file.fileno()
          self.buffer = BytesIO()
          self.writable = "x" in file.mode or "r" not in file.mode
          self.write = self.buffer.write if self.writable else None
          self.BUFSIZE = 8192
  
      def read(self):
          while True:
              b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
              if not b:
                  break
              ptr = self.buffer.tell()
              self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
          self.newlines = 0
          return self.buffer.read()
  
      def readline(self):
          while self.newlines == 0:
              b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
              self.newlines = b.count(b"\n") + (not b)
              ptr = self.buffer.tell()
              self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
          self.newlines -= 1
          return self.buffer.readline()
  
      def flush(self):
          if self.writable:
              self.os.write(self._fd, self.buffer.getvalue())
              self.buffer.truncate(0), self.buffer.seek(0)
  
  
  class IOWrapper(IOBase):
      def __init__(self, file):
          self.buffer = FastIO(file)
          self.flush = self.buffer.flush
          self.writable = self.buffer.writable
          self.write = lambda s: self.buffer.write(s.encode("ascii"))
          self.read = lambda: self.buffer.read().decode("ascii")
          self.readline = lambda: self.buffer.readline().decode("ascii")
  
  
  sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
  input = lambda: sys.stdin.readline().rstrip("\r\n")
  
  
  def get_int():
      return int(input())
  
  
  def get_ints():
      return list(map(int, input().split(' ')))
  
  
  def get_int_grid(n):
      return [get_ints() for _ in range(n)]
  
  
  def get_str():
      return input().strip()
  
  
  def get_strs():
      return get_str().split(' ')
  
  
  def flat_list(arr):
      return [item for subarr in arr for item in subarr]
  
  
  def yes_no(b):
      if b:
          return "YES"
      else:
          return "NO"
  
  
  def binary_search(good, left, right, delta=1, right_true=False):
      """
      Performs binary search
      ----------
      Parameters
      ----------
      :param good: Function used to perform the binary search
      :param left: Starting value of left limit
      :param right: Starting value of the right limit
      :param delta: Margin of error, defaults value of 1 for integer binary search
      :param right_true: Boolean, for whether the right limit is the true invariant
      :return: Returns the most extremal value interval [left, right] which is good function evaluates to True,
              alternatively returns False if no such value found
      """
  
      limits = [left, right]
      while limits[1] - limits[0] > delta:
          if delta == 1:
              mid = sum(limits) // 2
          else:
              mid = sum(limits) / 2
          if good(mid):
              limits[int(right_true)] = mid
          else:
              limits[int(~right_true)] = mid
      if good(limits[int(right_true)]):
          return limits[int(right_true)]
      else:
          return False
  
  
  def prefix_sums(a):
      p = [0]
      for x in a:
          p.append(p[-1] + x)
      return p
  
  
  def solve_a():
      n = get_int()
      for i in range(1, n + 1):
          r = []
          for j in range(i):
              r.append('(')
          for j in range(i):
              r.append(')')
          for j in range(n - i):
              r.append('()')
          print(''.join(r))
      return
  
  
  def solve_b():
      a, b, c, m = get_ints()
      n = a + b + c
  
      if m > a + b + c - 3:
          return "NO"
  
      if max(a, b, c) > n - n // 2:
          if m < 2 * max(a, b, c) - n - 1:
              return "NO"
  
      return "YES"
  
  
  def solve_c():
      n = get_int()
      a = get_ints()
      m = get_int()
      a.sort()
      S = sum(a)
  
      for d in range(m):
          x, y = get_ints()
  
          best = float('inf')
  
          j = bisect.bisect_right(a, x)
  
          for i in range(max(0, j - 1), min(n, j + 2)):
              h = a[i]
              curr = max(0, x - h) + max(0, y - (S - h))
              best = min(curr, best)
          print(best)
      return
  
  
  def solve_d():
      n = get_int()
      a = []
      c = []
      for _ in range(n):
          ci, *aij = get_ints()
          c.append(ci)
          a.append(aij)
  
      m = get_int()
      b = [get_ints() for _ in range(m)]
  
      set_b = set([tuple(x) for x in b])
  
      def sum_tup(x):
          S = 0
          for i, j in enumerate(x):
              S += a[i][j - 1]
          return S
  
      ans = -1
      res = None
      tup = tuple(c)
      if tuple(c) not in set_b:
          return tup
  
      for z in b:
          for i in range(n):
              if z[i] == 1:
                  continue
              zc = z[:]
              zc[i] -= 1
              tup = tuple(zc)
              S = sum_tup(tup)
              if tup not in set_b and S > ans:
                  ans = S
                  res = tup
  
      return res
  
  
  
  
  print(*solve_d())
  
  