description: Alice gave Bob two integers a and b (a > 0 and b ≥ 0). Being a curious boy, Bob wrote down an array of non-negative integers with \operatorname{MEX} value of all elements equal to a and \operatorname{XOR} value of all elements equal to b.
  
  What is the shortest possible length of the array Bob wrote?
  
  Recall that the \operatorname{MEX} (Minimum EXcluded) of an array is the minimum non-negative integer that does not belong to the array and the \operatorname{XOR} of an array is the [bitwise XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of all the elements of the array.
  
  Input
  
  The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 5 ⋅ 10^4) — the number of test cases. The description of the test cases follows.
  
  The only line of each test case contains two integers a and b (1 ≤ a ≤ 3 ⋅ 10^5; 0 ≤ b ≤ 3 ⋅ 10^5) — the \operatorname{MEX} and \operatorname{XOR} of the array, respectively.
  
  Output
  
  For each test case, output one (positive) integer — the length of the shortest array with \operatorname{MEX} a and \operatorname{XOR} b. We can show that such an array always exists.
  
  Example
  
  Input
  
  
  5
  1 1
  2 1
  2 0
  1 10000
  2 10000
  
  
  Output
  
  
  3
  2
  3
  2
  3
  
  Note
  
  In the first test case, one of the shortest arrays with \operatorname{MEX} 1 and \operatorname{XOR} 1 is [0, 2020, 2021].
  
  In the second test case, one of the shortest arrays with \operatorname{MEX} 2 and \operatorname{XOR} 1 is [0, 1].
  
  It can be shown that these arrays are the shortest arrays possible.
solution: /*
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   */
  import static java.lang.Math.*;
  import java.util.*;
  import java.io.*;
  import java.math.*;
  
  public class x1567B
  {
      static final int MAX = 300005;
      public static void main(String hi[]) throws Exception
      {
          int[] xors = new int[MAX];
          for(int i=1; i < MAX; i++)
              xors[i] = xors[i-1]^i;
          BufferedReader infile = new BufferedReader(new InputStreamReader(System.in));
          StringTokenizer st = new StringTokenizer(infile.readLine());
          int T = Integer.parseInt(st.nextToken());
          StringBuilder sb = new StringBuilder();
          while(T-->0)
          {
              st = new StringTokenizer(infile.readLine());
              int A = Integer.parseInt(st.nextToken());
              int B = Integer.parseInt(st.nextToken());
              int res = A;
              int xor = 0;
              if(A > 0)
                  xor = xors[A-1];
              if(xor != B)
              {
                  res++;
                  if((xor^B) == A)
                      res++;
              }
              if(A == 0)
                  res = B == 0 ? 2 : 1;
              sb.append(res+"\n");
          }
          System.out.print(sb);
      }
      public static int[] readArr(int N, BufferedReader infile, StringTokenizer st) throws Exception
      {
          int[] arr = new int[N];
          st = new StringTokenizer(infile.readLine());
          for(int i=0; i < N; i++)
              arr[i] = Integer.parseInt(st.nextToken());
          return arr;
      }
  }