description: This problem is an extension of the problem "Wonderful Coloring - 1". It has quite many differences, so you should read this statement completely.
  
  Recently, Paul and Mary have found a new favorite sequence of integers a_1, a_2, ..., a_n. They want to paint it using pieces of chalk of k colors. The coloring of a sequence is called wonderful if the following conditions are met:
  
    1. each element of the sequence is either painted in one of k colors or isn't painted; 
    2. each two elements which are painted in the same color are different (i. e. there's no two equal values painted in the same color); 
    3. let's calculate for each of k colors the number of elements painted in the color — all calculated numbers must be equal; 
    4. the total number of painted elements of the sequence is the maximum among all colorings of the sequence which meet the first three conditions. 
  
  
  
  E. g. consider a sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. One of the wonderful colorings of the sequence is shown in the figure.
  
  <image> The example of a wonderful coloring of the sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. Note that one of the elements isn't painted.
  
  Help Paul and Mary to find a wonderful coloring of a given sequence a.
  
  Input
  
  The first line contains one integer t (1 ≤ t ≤ 10000) — the number of test cases. Then t test cases follow.
  
  Each test case consists of two lines. The first one contains two integers n and k (1 ≤ n ≤ 2⋅10^5, 1 ≤ k ≤ n) — the length of a given sequence and the number of colors, respectively. The second one contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n).
  
  It is guaranteed that the sum of n over all test cases doesn't exceed 2 ⋅ 10^5.
  
  Output
  
  Output t lines, each of them must contain a description of a wonderful coloring for the corresponding test case.
  
  Each wonderful coloring must be printed as a sequence of n integers c_1, c_2, ..., c_n (0 ≤ c_i ≤ k) separated by spaces where
  
    * c_i=0, if i-th element isn't painted; 
    * c_i>0, if i-th element is painted in the c_i-th color. 
  
  
  
  Remember that you need to maximize the total count of painted elements for the wonderful coloring. If there are multiple solutions, print any one.
  
  Example
  
  Input
  
  
  6
  10 3
  3 1 1 1 1 10 3 10 10 2
  4 4
  1 1 1 1
  1 1
  1
  13 1
  3 1 4 1 5 9 2 6 5 3 5 8 9
  13 2
  3 1 4 1 5 9 2 6 5 3 5 8 9
  13 3
  3 1 4 1 5 9 2 6 5 3 5 8 9
  
  
  Output
  
  
  1 1 0 2 3 2 2 1 3 3
  4 2 1 3
  1
  0 0 1 1 0 1 1 1 0 1 1 1 0
  2 1 2 2 1 1 1 1 2 1 0 2 2
  1 1 3 2 1 3 3 1 2 2 3 2 0
  
  Note
  
  In the first test case, the answer is shown in the figure in the statement. The red color has number 1, the blue color — 2, the green — 3.
solution: //package codeforce.div3.r734;
  
  import java.io.BufferedReader;
  import java.io.File;
  import java.io.FileNotFoundException;
  import java.io.FileReader;
  import java.io.IOException;
  import java.io.InputStream;
  import java.io.InputStreamReader;
  import java.io.PrintWriter;
  import java.util.Collection;
  import java.util.Collections;
  import java.util.Scanner;
  import java.util.StringTokenizer;
  import java.util.stream.Collectors;
  import java.util.stream.IntStream;
  import java.util.ArrayList;
  import java.util.List;
  import java.util.HashMap;
  import java.util.Map;
  import java.util.Set;
  import java.util.HashSet;
  
  import static java.lang.System.in;
  import static java.lang.System.out;
  import static java.util.stream.Collectors.joining;
  
  
  /**
   * @author pribic (Priyank Doshi)
   * @see <a href="https://m1.codeforces.com/contest/1551/problem/B2" target="_top">https://m1.codeforces.com/contest/1551/problem/B2</a>
   * @since 23/07/21 8:26 PM
   */
  public class B2 {
    static FastScanner sc = new FastScanner(System.in);
  
    public static void main(String[] args) {
      try (PrintWriter out = new PrintWriter(System.out)) {
        int T = sc.nextInt();
        for (int tt = 1; tt <= T; tt++) {
          int n = sc.nextInt();
          int k = sc.nextInt();
          int[] arr = new int[n];
          Map<Integer, List<Integer>> map = new HashMap<>();
          for (int i = 0; i < n; i++) {
            arr[i] = sc.nextInt();
            map.putIfAbsent(arr[i], new ArrayList<>());
            if (map.get(arr[i]).size() < k)
              map.get(arr[i]).add(i);
          }
          List<Integer> indexes = map.values().stream().flatMap(Collection::stream).collect(Collectors.toList());
          while (indexes.size() % k != 0) indexes.remove(indexes.size() - 1);
          indexes.sort((i, j) -> arr[i] - arr[j]);
          int[] ans = new int[n];
          int curcolor = 0;
          int maxLimit = (indexes.size() / k) * k;
          for (int i = 0; i < maxLimit; i++) {
            ans[indexes.get(i)] = curcolor % k + 1;
            curcolor++;
          }
  
          StringBuilder str = new StringBuilder();
          for (int num : ans) str.append(num).append(" ");
          System.out.println(str);
        }
      }
    }
  
    static class FastScanner {
      BufferedReader br;
      StringTokenizer st;
  
      public FastScanner(File f) {
        try {
          br = new BufferedReader(new FileReader(f));
        } catch (FileNotFoundException e) {
          e.printStackTrace();
        }
      }
  
      public FastScanner(InputStream f) {
        br = new BufferedReader(new InputStreamReader(f), 32768);
      }
  
      String next() {
        while (st == null || !st.hasMoreTokens()) {
          String s = null;
          try {
            s = br.readLine();
          } catch (IOException e) {
            e.printStackTrace();
          }
          if (s == null)
            return null;
          st = new StringTokenizer(s);
        }
        return st.nextToken();
      }
  
      boolean hasMoreTokens() {
        while (st == null || !st.hasMoreTokens()) {
          String s = null;
          try {
            s = br.readLine();
          } catch (IOException e) {
            e.printStackTrace();
          }
          if (s == null)
            return false;
          st = new StringTokenizer(s);
        }
        return true;
      }
  
      int nextInt() {
        return Integer.parseInt(next());
      }
  
      long nextLong() {
        return Long.parseLong(next());
      }
  
      double nextDouble() {
        return Double.parseDouble(next());
      }
    }
  }