description: A binary string is a string that consists of characters 0 and 1.
  
  Let \operatorname{MEX} of a binary string be the smallest digit among 0, 1, or 2 that does not occur in the string. For example, \operatorname{MEX} of 001011 is 2, because 0 and 1 occur in the string at least once, \operatorname{MEX} of 1111 is 0, because 0 and 2 do not occur in the string and 0 < 2.
  
  A binary string s is given. You should cut it into any number of substrings such that each character is in exactly one substring. It is possible to cut the string into a single substring — the whole string.
  
  A string a is a substring of a string b if a can be obtained from b by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.
  
  What is the minimal sum of \operatorname{MEX} of all substrings pieces can be?
  
  Input
  
  The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.
  
  Each test case contains a single binary string s (1 ≤ |s| ≤ 10^5).
  
  It's guaranteed that the sum of lengths of s over all test cases does not exceed 10^5.
  
  Output
  
  For each test case print a single integer — the minimal sum of \operatorname{MEX} of all substrings that it is possible to get by cutting s optimally.
  
  Example
  
  Input
  
  
  6
  01
  1111
  01100
  101
  0000
  01010
  
  
  Output
  
  
  1
  0
  2
  1
  1
  2
  
  Note
  
  In the first test case the minimal sum is \operatorname{MEX}(0) + \operatorname{MEX}(1) = 1 + 0 = 1.
  
  In the second test case the minimal sum is \operatorname{MEX}(1111) = 0.
  
  In the third test case the minimal sum is \operatorname{MEX}(01100) = 2.
solution: import java.io.BufferedReader; 
  import java.io.IOException; 
  import java.io.InputStreamReader; 
  import java.util.StringTokenizer; 
  import java.io.FileInputStream;
  import java.io.FileOutputStream;
  import java.io.PrintStream;
  import java.util.Arrays;
  import java.util.HashSet;
  public class Sol2 
  { 
  	public static  FastReader fs;
  	public static void main(String[] args) 
  	{ 
  		try {
  			System.setIn(new FileInputStream("input.txt"));
  			System.setOut(new PrintStream(new FileOutputStream("output.txt")));
  		} catch (Exception e) {}
  		fs = new FastReader();
  		int test = fs.nextInt();
  		while(test-- > 0){
  			solve();
  		}
  	}
  
  	static class FastReader 
  	{ 
  		BufferedReader br; 
  		StringTokenizer st; 
  
  		public FastReader() 
  		{ 
  			br = new BufferedReader(new
  					InputStreamReader(System.in)); 
  		} 
  
  		String next() 
  		{ 
  			while (st == null || !st.hasMoreElements()) 
  			{ 
  				try
  				{ 
  					st = new StringTokenizer(br.readLine()); 
  				} 
  				catch (IOException e) 
  				{ 
  					e.printStackTrace(); 
  				} 
  			} 
  			return st.nextToken(); 
  		} 
  
  		int nextInt() 
  		{ 
  			return Integer.parseInt(next()); 
  		} 
  
  		long nextLong() 
  		{ 
  			return Long.parseLong(next()); 
  		} 
  
  		double nextDouble() 
  		{ 
  			return Double.parseDouble(next()); 
  		} 
  
  		String nextLine() 
  		{ 
  			String str = ""; 
  			try
  			{ 
  				str = br.readLine(); 
  			} 
  			catch (IOException e) 
  			{ 
  				e.printStackTrace(); 
  			} 
  			return str; 
  		} 
  	} 
  	// use fs as scanner
  	// ctrl + shift + b to compile and run 
  	public static void solve(){
  		// start code here
  		
  		String str = fs.nextLine();
  		int zero = 0, one = 0;
  		int sum = 0;
  		int len = str.length();
  		for(int i=0; i<len; i++){
  			char cur = str.charAt(i);
  			char pre = i == 0 ? '5' : str.charAt(i-1);
  			if(cur == '0'){
  				if(cur == pre){
  					continue;
  				}
  				zero++;
  			}
  			else{
  				one++;
  			}
  		}
  
  		if( zero > 0 && one > 0 ){
  			if(zero < 2){
  				System.out.println(zero);
  			}
  			else{
  				System.out.println("2");
  			}
  		}
  		else if(one == 0){
  			System.out.println("1");
  		}
  		else if(zero == 0){
  			System.out.println("0");
  		}
  	}
  }