description: Consider a sequence of integers a_1, a_2, …, a_n. In one move, you can select any element of the sequence and delete it. After an element is deleted, all elements to the right are shifted to the left by 1 position, so there are no empty spaces in the sequence. So after you make a move, the sequence's length decreases by 1. The indices of the elements after the move are recalculated.
  
  E. g. let the sequence be a=[3, 2, 2, 1, 5]. Let's select the element a_3=2 in a move. Then after the move the sequence will be equal to a=[3, 2, 1, 5], so the 3-rd element of the new sequence will be a_3=1 and the 4-th element will be a_4=5.
  
  You are given a sequence a_1, a_2, …, a_n and a number k. You need to find the minimum number of moves you have to make so that in the resulting sequence there will be at least k elements that are equal to their indices, i. e. the resulting sequence b_1, b_2, …, b_m will contain at least k indices i such that b_i = i.
  
  Input
  
  The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
  
  Each test case consists of two consecutive lines. The first line contains two integers n and k (1 ≤ k ≤ n ≤ 2000). The second line contains a sequence of integers a_1, a_2, …, a_n (1 ≤ a_i ≤ n). The numbers in the sequence are not necessarily different.
  
  It is guaranteed that the sum of n over all test cases doesn't exceed 2000.
  
  Output
  
  For each test case output in a single line:
  
    * -1 if there's no desired move sequence; 
    * otherwise, the integer x (0 ≤ x ≤ n) — the minimum number of the moves to be made so that the resulting sequence will contain at least k elements that are equal to their indices. 
  
  Example
  
  Input
  
  
  4
  7 6
  1 1 2 3 4 5 6
  5 2
  5 1 3 2 3
  5 2
  5 5 5 5 4
  8 4
  1 2 3 3 2 2 5 5
  
  
  Output
  
  
  1
  2
  -1
  2
  
  Note
  
  In the first test case the sequence doesn't satisfy the desired condition, but it can be provided by deleting the first element, hence the sequence will be [1, 2, 3, 4, 5, 6] and 6 elements will be equal to their indices.
  
  In the second test case there are two ways to get the desired result in 2 moves: the first one is to delete the 1-st and the 3-rd elements so that the sequence will be [1, 2, 3] and have 3 elements equal to their indices; the second way is to delete the 2-nd and the 3-rd elements to get the sequence [5, 2, 3] with 2 desired elements.
solution: import java.util.*;
  import java.io.*;
  import static java.lang.Math.*;
  
  public class ACMIND
  {
      static FastReader scan;
      static PrintWriter pw;
      static long MOD = 1_000_000_007;
      static long INF = 2_000_000_000_000_000_000L;
      static long inf = 2_000_000_000;
      public static void main(String[] args) {
          new Thread(null,null,"_",1<<27)
          {
              public void run()
              {
                  try
                  {
                      solve();
                  }
                  catch(Exception e)
                  {
                      e.printStackTrace();
                      System.exit(1);
                  }
              }
          }.start();
      }
  
  
      static int n,k,arr[],dp[][];
      static void solve() throws IOException {
          scan = new FastReader();
          pw = new PrintWriter(System.out, true);
          StringBuilder sb = new StringBuilder();
  
          int t = ni();
          while (t-->0) {
              n = ni();
              k = ni();
              arr = new int[n];
              for(int i=0;i<n;i++) {
                  arr[i] = ni();
              }
              dp = new int[n][n+1];
              for(int i=0;i<n;i++) {
                  Arrays.fill(dp[i], -1);
              }
              int ans = -1;
              for(int i=0;i<n;i++) {
                  if(f(n-1, i) >= k) {
                      ans = i;
                      break;
                  }
              }
  
              pl(ans);
          }
  
          pw.flush();
          pw.close();
      }
  
      static int f(int idx, int deleted) {
          if(deleted<0) {
              return -2000;
          }
          if(idx==-1) {
              return 0;
          }
          if(dp[idx][deleted] != -1) {
              return dp[idx][deleted];
          }
          return dp[idx][deleted] = max(f(idx-1, deleted-1),
                  f(idx-1, deleted) + (arr[idx] == (idx-deleted+1) ? 1 : 0));
      }
  
      static void assert_in_range(String varName, int n, int l, int r) {
          if (n >=l && n<=r) return;
          System.out.println(varName + " is not in range. Actual: "+n+" l : "+l+" r: "+r);
          System.exit(1);
      }
      static void assert_in_range(String varName, long n, long l, long r) {
          if (n>=l && n<=r) return;
          System.out.println(varName + " is not in range. Actual: "+n+" l : "+l+" r: "+r);
          System.exit(1);
      }
  
      static int ni() throws IOException
      {
          return scan.nextInt();
      }
      static long nl() throws IOException
      {
          return scan.nextLong();
      }
      static double nd() throws IOException
      {
          return scan.nextDouble();
      }
      static void pl()
      {
          pw.println();
      }
      static void p(Object o)
      {
          pw.print(o+" ");
      }
      static void pl(Object o)
      {
          pw.println(o);
      }
      static void psb(StringBuilder sb)
      {
          pw.print(sb);
      }
      static void pa(String arrayName, Set<Object> set)
      {
          pl(arrayName+" : ");
          for(Object o : set)
              p(o);
          pl();
      }
      static void pa(String arrayName, Object arr[])
      {
          pl(arrayName+" : ");
          for(Object o : arr)
              p(o);
          pl();
      }
      static void pa(String arrayName, int arr[])
      {
          pl(arrayName+" : ");
          for(int o : arr)
              p(o);
          pl();
      }
      static void pa(String arrayName, long arr[])
      {
          pl(arrayName+" : ");
          for(long o : arr)
              p(o);
          pl();
      }
      static void pa(String arrayName, double arr[])
      {
          pl(arrayName+" : ");
          for(double o : arr)
              p(o);
          pl();
      }
      static void pa(String arrayName, char arr[])
      {
          pl(arrayName+" : ");
          for(char o : arr)
              p(o);
          pl();
      }
      static void pa(String listName, List list)
      {
          pl(listName+" : ");
          for(Object o : list)
              p(o);
          pl();
      }
      static void pa(String arrayName, Object[][] arr) {
          pl(arrayName+" : ");
          for(int i=0;i<arr.length;++i) {
              for(Object o : arr[i])
                  p(o);
              pl();
          }
      }
      static void pa(String arrayName, int[][] arr) {
          pl(arrayName+" : ");
          for(int i=0;i<arr.length;++i) {
              for(int o : arr[i])
                  p(o);
              pl();
          }
      }
      static void pa(String arrayName, long[][] arr) {
          pl(arrayName+" : ");
          for(int i=0;i<arr.length;++i) {
              for(long o : arr[i])
                  p(o);
              pl();
          }
      }
      static void pa(String arrayName, char[][] arr) {
          pl(arrayName+" : ");
          for(int i=0;i<arr.length;++i) {
              for(char o : arr[i])
                  p(o);
              pl();
          }
      }
      static void pa(String arrayName, double[][] arr) {
          pl(arrayName+" : ");
          for(int i=0;i<arr.length;++i) {
              for(double o : arr[i])
                  p(o);
              pl();
          }
      }
      static class FastReader {
          final private int BUFFER_SIZE = 1 << 16;
          private DataInputStream din;
          private byte[] buffer;
          private int bufferPointer, bytesRead;
  
          public FastReader() {
              din = new DataInputStream(System.in);
              buffer = new byte[BUFFER_SIZE];
              bufferPointer = bytesRead = 0;
          }
  
          public FastReader(String file_name) throws IOException {
              din = new DataInputStream(new FileInputStream(file_name));
              buffer = new byte[BUFFER_SIZE];
              bufferPointer = bytesRead = 0;
          }
  
          public String readLine() throws IOException {
              byte[] buf = new byte[1000000];
              int cnt = 0, c;
              while ((c = read()) != -1) {
                  if (c == '\n') break;
                  buf[cnt++] = (byte) c;
              }
              return new String(buf, 0, cnt);
          }
  
          public int nextInt() throws IOException {
              int ret = 0;
              byte c = read();
              while (c <= ' ') c = read();
              boolean neg = (c == '-');
              if (neg) c = read();
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
              if (neg) return -ret;
              return ret;
          }
  
          public long nextLong() throws IOException {
              long ret = 0;
              byte c = read();
              while (c <= ' ') c = read();
              boolean neg = (c == '-');
              if (neg) c = read();
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
              if (neg) return -ret;
              return ret;
          }
  
          public double nextDouble() throws IOException {
              double ret = 0, div = 1;
              byte c = read();
              while (c <= ' ') c = read();
              boolean neg = (c == '-');
              if (neg) c = read();
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
              if (c == '.') while ((c = read()) >= '0' && c <= '9') ret += (c - '0') / (div *= 10);
              if (neg) return -ret;
              return ret;
          }
  
          private void fillBuffer() throws IOException {
              bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
              if (bytesRead == -1) buffer[0] = -1;
          }
  
          private byte read() throws IOException {
              if (bufferPointer == bytesRead) fillBuffer();
              return buffer[bufferPointer++];
          }
  
          public void close() throws IOException {
              if (din == null) return;
              din.close();
          }
      }
  }