description: The Olympic Games have just started and Federico is eager to watch the marathon race.
  
  There will be n athletes, numbered from 1 to n, competing in the marathon, and all of them have taken part in 5 important marathons, numbered from 1 to 5, in the past. For each 1≤ i≤ n and 1≤ j≤ 5, Federico remembers that athlete i ranked r_{i,j}-th in marathon j (e.g., r_{2,4}=3 means that athlete 2 was third in marathon 4).
  
  Federico considers athlete x superior to athlete y if athlete x ranked better than athlete y in at least 3 past marathons, i.e., r_{x,j}<r_{y,j} for at least 3 distinct values of j.
  
  Federico believes that an athlete is likely to get the gold medal at the Olympics if he is superior to all other athletes.
  
  Find any athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes), or determine that there is no such athlete.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.
  
  The first line of each test case contains a single integer n (1≤ n≤ 50 000) — the number of athletes.
  
  Then n lines follow, each describing the ranking positions of one athlete.
  
  The i-th of these lines contains the 5 integers r_{i,1},\,r_{i,2},\,r_{i,3},\,r_{i,4},  r_{i,5} (1≤ r_{i,j}≤ 50 000) — the ranking positions of athlete i in the past 5 marathons. It is guaranteed that, in each of the 5 past marathons, the n athletes have distinct ranking positions, i.e., for each 1≤ j≤ 5, the n values r_{1,j},  r_{2, j},  ...,  r_{n, j} are distinct.
  
  It is guaranteed that the sum of n over all test cases does not exceed 50 000.
  
  Output
  
  For each test case, print a single integer — the number of an athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes). If there are no such athletes, print -1. If there is more than such one athlete, print any of them.
  
  Example
  
  Input
  
  
  4
  1
  50000 1 50000 50000 50000
  3
  10 10 20 30 30
  20 20 30 10 10
  30 30 10 20 20
  3
  1 1 1 1 1
  2 2 2 2 2
  3 3 3 3 3
  6
  9 5 3 7 1
  7 4 1 6 8
  5 6 7 3 2
  6 7 8 8 6
  4 2 2 4 5
  8 3 6 9 4
  
  
  Output
  
  
  1
  -1
  1
  5
  
  Note
  
  Explanation of the first test case: There is only one athlete, therefore he is superior to everyone else (since there is no one else), and thus he is likely to get the gold medal.
  
  Explanation of the second test case: There are n=3 athletes. 
  
    * Athlete 1 is superior to athlete 2. Indeed athlete 1 ranks better than athlete 2 in the marathons 1, 2 and 3. 
    * Athlete 2 is superior to athlete 3. Indeed athlete 2 ranks better than athlete 3 in the marathons 1, 2, 4 and 5. 
    * Athlete 3 is superior to athlete 1. Indeed athlete 3 ranks better than athlete 1 in the marathons 3, 4 and 5. 
  
  
  
  Explanation of the third test case: There are n=3 athletes. 
  
    * Athlete 1 is superior to athletes 2 and 3. Since he is superior to all other athletes, he is likely to get the gold medal. 
    * Athlete 2 is superior to athlete 3. 
    * Athlete 3 is not superior to any other athlete. 
  
  
  
  Explanation of the fourth test case: There are n=6 athletes. 
  
    * Athlete 1 is superior to athletes 3, 4, 6. 
    * Athlete 2 is superior to athletes 1, 4, 6. 
    * Athlete 3 is superior to athletes 2, 4, 6. 
    * Athlete 4 is not superior to any other athlete. 
    * Athlete 5 is superior to athletes 1, 2, 3, 4, 6. Since he is superior to all other athletes, he is likely to get the gold medal. 
    * Athlete 6 is only superior to athlete 4. 
solution: import sys
  input = lambda:sys.stdin.readline()
  
  int_arr = lambda: list(map(int,input().split()))
  str_arr = lambda: list(map(str,input().split()))
  get_str = lambda: map(str,input().split())
  get_int = lambda: map(int,input().split())
  get_flo = lambda: map(float,input().split())
  
  mod = 1000000007
  
  def solve(n,mat):
      i = 0
      for j in range(1,n):
          c = 0
          for k in range(5):
              if mat[j][k] < mat[i][k]:
                  c += 1
  
          if c >= 3:
              i = j
  
  
      for j in range(n):
          if i != j:
              c = 0
              for k in range(5):
                  if mat[j][k] < mat[i][k]:
                      c += 1
              if c >= 3:
                  print(-1)
                  return
  
      print(i+1)
  
  
  
  
  for _ in range(int(input())):
      n = int(input())
      mat = []
      for i in range(n):
          mat.append(int_arr())
      solve(n,mat)