description: Frodo was caught by Saruman. He tore a pouch from Frodo's neck, shook out its contents —there was a pile of different rings: gold and silver...
  
  "How am I to tell which is the One?!" the mage howled.
  
  "Throw them one by one into the Cracks of Doom and watch when Mordor falls!" 
  
  Somewhere in a parallel Middle-earth, when Saruman caught Frodo, he only found n rings. And the i-th ring was either gold or silver. For convenience Saruman wrote down a binary string s of n characters, where the i-th character was 0 if the i-th ring was gold, and 1 if it was silver.
  
  Saruman has a magic function f, which takes a binary string and returns a number obtained by converting the string into a binary number and then converting the binary number into a decimal number. For example, f(001010) = 10, f(111) = 7, f(11011101) = 221.
  
  Saruman, however, thinks that the order of the rings plays some important role. He wants to find 2 pairs of integers (l_1, r_1), (l_2, r_2), such that:
  
    * 1 ≤ l_1 ≤ n, 1 ≤ r_1 ≤ n, r_1-l_1+1≥ ⌊ n/2 ⌋ 
    * 1 ≤ l_2 ≤ n, 1 ≤ r_2 ≤ n, r_2-l_2+1≥ ⌊ n/2 ⌋ 
    * Pairs (l_1, r_1) and (l_2, r_2) are distinct. That is, at least one of l_1 ≠ l_2 and r_1 ≠ r_2 must hold.
    * Let t be the substring s[l_1:r_1] of s, and w be the substring s[l_2:r_2] of s. Then there exists non-negative integer k, such that f(t) = f(w) ⋅ k.
  
  
  
  Here substring s[l:r] denotes s_ls_{l+1}… s_{r-1}s_r, and ⌊ x ⌋ denotes rounding the number down to the nearest integer.
  
  Help Saruman solve this problem! It is guaranteed that under the constraints of the problem at least one solution exists.
  
  Input
  
  Each test contains multiple test cases.
  
  The first line contains one positive integer t (1 ≤ t ≤ 10^3), denoting the number of test cases. Description of the test cases follows.
  
  The first line of each test case contains one positive integer n (2 ≤ n ≤ 2 ⋅ 10^4) — length of the string.
  
  The second line of each test case contains a non-empty binary string of length n.
  
  It is guaranteed that the sum of n over all test cases does not exceed 10^5.
  
  Output
  
  For every test case print four integers l_1, r_1, l_2, r_2, which denote the beginning of the first substring, the end of the first substring, the beginning of the second substring, and the end of the second substring, respectively.
  
  If there are multiple solutions, print any.
  
  Example
  
  Input
  
  
  7
  6
  101111
  9
  111000111
  8
  10000000
  5
  11011
  6
  001111
  3
  101
  30
  100000000000000100000000000000
  
  
  Output
  
  
  3 6 1 3
  1 9 4 9
  5 8 1 4
  1 5 3 5
  1 6 2 4
  1 2 2 3
  1 15 16 30
  
  Note
  
  In the first testcase f(t) = f(1111) = 15, f(w) = f(101) = 5.
  
  In the second testcase f(t) = f(111000111) = 455, f(w) = f(000111) = 7.
  
  In the third testcase f(t) = f(0000) = 0, f(w) = f(1000) = 8.
  
  In the fourth testcase f(t) = f(11011) = 27, f(w) = f(011) = 3.
  
  In the fifth testcase f(t) = f(001111) = 15, f(w) = f(011) = 3.
solution: import java.util.*;
  import java.lang.*;
  import java.io.*;
  
  public class Main
  {
      static long mod = (int)1e9+7;
  	public static void main (String[] args) throws java.lang.Exception
  	{
  		FastReader sc =new FastReader();
  		
  	    int t=sc.nextInt();
  	    
  	   // int t=1;
  	    
  	    while(t-->0)
  	    {
  	        int n=sc.nextInt();
  	        char arr[] = sc.next().toCharArray();
  	        int left = -1 , right = -1;
  	        
  	        for(int i=0;i<n/2;i++)
  	        {
  	            if(arr[i]=='0')
  	            {
  	                left = i+1;
  	                break;
  	            }
  	        }
  	        if(left!=-1)
  	        {
  	            System.out.println((left+1)+" "+n+" "+left+" "+n+" ");
  	        }
  	        else
  	        {
  	            for(int i=n-1;i>=n/2;i--)
  	            {
  	                if(arr[i]=='0')
  	                {
  	                    right = i+1;
  	                    break;
  	                }
  	            }
  	            if(right!=-1)
  	            {
  	                System.out.println(1+" "+right+" "+1+" "+(right - 1));
  	            }
  	            else
  	            {
  	                System.out.println(1+" "+(n-1)+" "+2+" "+n);
  	            }
  	        }
  	    }
  	}
  	
  	
  	
  	static class FastReader {
          BufferedReader br;
          StringTokenizer st;
   
          public FastReader()
          {
              br = new BufferedReader(
                  new InputStreamReader(System.in));
          }
   
          String next()
          {
              while (st == null || !st.hasMoreElements()) {
                  try {
                      st = new StringTokenizer(br.readLine());
                  }
                  catch (IOException e) {
                      e.printStackTrace();
                  }
              }
              return st.nextToken();
          }
   
          int nextInt() { return Integer.parseInt(next()); }
   
          long nextLong() { return Long.parseLong(next()); }
   
          double nextDouble()
          {
              return Double.parseDouble(next());
          }
          
          float nextFloat()
          {
              return Float.parseFloat(next());
          }
   
          String nextLine()
          {
              String str = "";
              try {
                  str = br.readLine();
              }
              catch (IOException e) {
                  e.printStackTrace();
              }
              return str;
          }
          
          int[] readArray(int n) {
  			int[] a=new int[n];
  			for (int i=0; i<n; i++) a[i]=nextInt();
  			return a;
  		}
  		
  		long[] readArrayLong(int n) {
  			long[] a=new long[n];
  			for (int i=0; i<n; i++) a[i]=nextLong();
  			return a;
  		}
  		
      }
      
      public static int[] radixSort2(int[] a)
  	{
  		int n = a.length;
  		int[] c0 = new int[0x101];
  		int[] c1 = new int[0x101];
  		int[] c2 = new int[0x101];
  		int[] c3 = new int[0x101];
  		for(int v : a) {
  			c0[(v&0xff)+1]++;
  			c1[(v>>>8&0xff)+1]++;
  			c2[(v>>>16&0xff)+1]++;
  			c3[(v>>>24^0x80)+1]++;
  		}
  		for(int i = 0;i < 0xff;i++) {
  			c0[i+1] += c0[i];
  			c1[i+1] += c1[i];
  			c2[i+1] += c2[i];
  			c3[i+1] += c3[i];
  		}
  		int[] t = new int[n];
  		for(int v : a)t[c0[v&0xff]++] = v;
  		for(int v : t)a[c1[v>>>8&0xff]++] = v;
  		for(int v : a)t[c2[v>>>16&0xff]++] = v;
  		for(int v : t)a[c3[v>>>24^0x80]++] = v;
  		return a;
  	}
  	
  	
      
      public static HashMap<Integer, Integer> sortByValue(HashMap<Integer, Integer> hm)
      {
          // Create a list from elements of HashMap
          List<Map.Entry<Integer, Integer> > list =
                 new LinkedList<Map.Entry<Integer, Integer> >(hm.entrySet());
   
          // Sort the list
          Collections.sort(list, new Comparator<Map.Entry<Integer, Integer> >() {
              public int compare(Map.Entry<Integer, Integer> o1,
                                 Map.Entry<Integer, Integer> o2)
              {
                  return (o1.getValue()).compareTo(o2.getValue());
              }
          });
           
          // put data from sorted list to hashmap
          HashMap<Integer, Integer> temp = new LinkedHashMap<Integer, Integer>();
          for (Map.Entry<Integer, Integer> aa : list) {
              temp.put(aa.getKey(), aa.getValue());
          }
          return temp;
      }
      
      static void leftRotate(int arr[], int d, int n)
      {
          for (int i = 0; i < d; i++)
              leftRotatebyOne(arr, n);
      }
   
      static void leftRotatebyOne(int arr[], int n)
      {
          int i, temp;
          temp = arr[0];
          for (i = 0; i < n - 1; i++)
              arr[i] = arr[i + 1];
          arr[n-1] = temp;
          
      }
      
      static boolean isPalindrome(String str)
      {
   
          // Pointers pointing to the beginning
          // and the end of the string
          int i = 0, j = str.length() - 1;
   
          // While there are characters to compare
          while (i < j) {
   
              // If there is a mismatch
              if (str.charAt(i) != str.charAt(j))
                  return false;
   
              // Increment first pointer and
              // decrement the other
              i++;
              j--;
          }
   
          // Given string is a palindrome
          return true;
      }
      
      static boolean palindrome_array(char arr[], int n)
      {
          // Initialise flag to zero.
          int flag = 0;
   
          // Loop till array size n/2.
          for (int i = 0; i <= n / 2 && n != 0; i++) {
   
              // Check if first and last element are different
              // Then set flag to 1.
              if (arr[i] != arr[n - i - 1]) {
                  flag = 1;
                  break;
              }
          }
   
          // If flag is set then print Not Palindrome
          // else print Palindrome.
          if (flag == 1)
              return false;
          else
              return true;
      }
      
  	static boolean allElementsEqual(int[] arr,int n)
  	{
  	    int z=0;
  	        for(int i=0;i<n-1;i++)
  		    {
  		        if(arr[i]==arr[i+1])
  		        {
  		            z++;
  		        }
  		    }
  		    if(z==n-1)
  		    {
  		        return true;
  		    }
  		    else
  		    {
  		        return false;
  		    }
  		    
  	}
  	
  	static boolean allElementsDistinct(int[] arr,int n)
  	{
  	    int z=0;
  	        for(int i=0;i<n-1;i++)
  		    {
  		        if(arr[i]!=arr[i+1])
  		        {
  		            z++;
  		        }
  		    }
  		    if(z==n-1)
  		    {
  		        return true;
  		    }
  		    else
  		    {
  		        return false;
  		    }
  		    
  		    
  	}
  	
  	public static void reverse(int[] array)
      {
    
          // Length of the array
          int n = array.length;
    
          // Swaping the first half elements with last half
          // elements
          for (int i = 0; i < n / 2; i++) {
    
              // Storing the first half elements temporarily
              int temp = array[i];
    
              // Assigning the first half to the last half
              array[i] = array[n - i - 1];
    
              // Assigning the last half to the first half
              array[n - i - 1] = temp;
          }
      }
      
      public static void reverse_Long(long[] array)
      {
    
          // Length of the array
          int n = array.length;
    
          // Swaping the first half elements with last half
          // elements
          for (int i = 0; i < n / 2; i++) {
    
              // Storing the first half elements temporarily
              long temp = array[i];
    
              // Assigning the first half to the last half
              array[i] = array[n - i - 1];
    
              // Assigning the last half to the first half
              array[n - i - 1] = temp;
          }
      }
  	
  	static boolean isSorted(int[] a)
      {
          for (int i = 0; i < a.length - 1; i++)
          {
              if (a[i] > a[i + 1]) {
                  return false;
              }
          }
   
          return true;
      }
      
      
      
      static boolean isReverseSorted(int[] a)
      {
          for (int i = 0; i < a.length - 1; i++)
          {
              if (a[i] < a[i + 1]) {
                  return false;
              }
          }
   
          return true;
      }
      
      static int[] rearrangeEvenAndOdd(int arr[], int n)
      {
          ArrayList<Integer> list = new ArrayList<>();
  		    
  		    for(int i=0;i<n;i++)
  		    {
  		        if(arr[i]%2==0)
  		        {
  		            list.add(arr[i]);
  		        }
  		    }
  		    
  		    for(int i=0;i<n;i++)
  		    {
  		        if(arr[i]%2!=0)
  		        {
  		            list.add(arr[i]);
  		        }
  		    }
  		    int len = list.size();
  		    int[] array = list.stream().mapToInt(i->i).toArray();
  		    return array;
      }
      
      static long[] rearrangeEvenAndOddLong(long arr[], int n)
      {
          ArrayList<Long> list = new ArrayList<>();
  		    
  		    for(int i=0;i<n;i++)
  		    {
  		        if(arr[i]%2==0)
  		        {
  		            list.add(arr[i]);
  		        }
  		    }
  		    
  		    for(int i=0;i<n;i++)
  		    {
  		        if(arr[i]%2!=0)
  		        {
  		            list.add(arr[i]);
  		        }
  		    }
  		    int len = list.size();
  		    long[] array = list.stream().mapToLong(i->i).toArray();
  		    return array;
      }
  	
  	
      
      static boolean isPrime(long n)
      {
   
          // Check if number is less than
          // equal to 1
          if (n <= 1)
              return false;
   
          // Check if number is 2
          else if (n == 2)
              return true;
   
          // Check if n is a multiple of 2
          else if (n % 2 == 0)
              return false;
   
          // If not, then just check the odds
          for (long i = 3; i <= Math.sqrt(n); i += 2)
          {
              if (n % i == 0)
                  return false;
          }
          return true;
      }
      
      static int getSum(int n)
      {    
          int sum = 0;
            
          while (n != 0)
          {
              sum = sum + n % 10;
              n = n/10;
          }
        
      return sum;
      }
      
      static int gcd(int a, int b)
      {
        if (b == 0)
          return a;
        return gcd(b, a % b);
      }
       
      static long gcdLong(long a, long b)
      {
          if (b == 0)
          return a;
        return gcdLong(b, a % b);
      }
      
      static void swap(int i, int j)
      {
          int temp = i;
          i = j;
          j = temp;
      }
  	
  	static int countDigit(long n)
      {
          return (int)Math.floor(Math.log10(n) + 1);
      }
  	
  }