description: You are given four integer values a, b, c and m.
  
  Check if there exists a string that contains: 
  
    * a letters 'A'; 
    * b letters 'B'; 
    * c letters 'C'; 
    * no other letters; 
    * exactly m pairs of adjacent equal letters (exactly m such positions i that the i-th letter is equal to the (i+1)-th one). 
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of testcases.
  
  Each of the next t lines contains the description of the testcase — four integers a, b, c and m (1 ≤ a, b, c ≤ 10^8; 0 ≤ m ≤ 10^8).
  
  Output
  
  For each testcase print "YES" if there exists a string that satisfies all the requirements. Print "NO" if there are no such strings.
  
  You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).
  
  Example
  
  Input
  
  
  3
  2 2 1 0
  1 1 1 1
  1 2 3 2
  
  
  Output
  
  
  YES
  NO
  YES
  
  Note
  
  In the first testcase strings "ABCAB" or "BCABA" satisfy the requirements. There exist other possible strings.
  
  In the second testcase there's no way to put adjacent equal letters if there's no letter that appears at least twice.
  
  In the third testcase string "CABBCC" satisfies the requirements. There exist other possible strings.
solution: /**
   * 09/20/21 morning
   * https://codeforces.com/contest/1574/problem/B
   */
  // package codeforce.ecf.r114;
  
  import java.util.*;
  import java.io.*;
  
  public class B {
  
      static PrintWriter pw;
  
      void solve(int a, int b, int c, int m) {
          int max = (a - 1) + (b - 1) + (c - 1);
          if (max < m) {
              pr("NO");
          } else if (max == m) {
              pr("YES");
          } else { // min pair is has to minus large first (greedy), wrong
              int[] t = {a, b, c};
              Arrays.sort(t);
  //            t[2] -= t[1] - t[0];
  //            int minPair = t[2] - 1;
              int minPair = Math.max(0, t[2] - 1 - t[0] - t[1]);
              pr(minPair <= m ? "YES" : "NO");
          }
      }
  
      private void run() {
          // read_write_file(); // comment this before submission
          FastScanner fs = new FastScanner();
          int t = fs.nextInt();
          while (t-- > 0) {
              int a = fs.nextInt();
              int b = fs.nextInt();
              int c = fs.nextInt();
              int m = fs.nextInt();
              solve(a, b, c, m);
          }
      }
  
      private final String INPUT = "input.txt";
      private final String OUTPUT = "output.txt";
  
      void read_write_file() {
          FileInputStream instream = null;
          PrintStream outstream = null;
          try {
              instream = new FileInputStream(INPUT);
              outstream = new PrintStream(new FileOutputStream(OUTPUT));
              System.setIn(instream);
              System.setOut(outstream);
          } catch (Exception e) {
          }
      }
  
      public static void main(String[] args) {
          pw = new PrintWriter(System.out);
          new B().run();
          pw.close();
      }
  
      void pr(int num) {
          pw.println(num);
      }
  
      void pr(long num) {
          pw.println(num);
      }
  
      void pr(double num) {
          pw.println(num);
      }
  
      void pr(String s) {
          pw.println(s);
      }
  
      void pr(char c) {
          pw.println(c);
      }
  
      class FastScanner {
          BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
          StringTokenizer st = new StringTokenizer("");
  
          String next() {
              while (!st.hasMoreTokens())
                  try {
                      st = new StringTokenizer(br.readLine());
                  } catch (IOException e) {
                      e.printStackTrace();
                  }
              return st.nextToken();
          }
  
          int nextInt() {
              return Integer.parseInt(next());
          }
  
          int[] readArray(int n) {
              int[] a = new int[n];
              for (int i = 0; i < n; i++)
                  a[i] = nextInt();
              return a;
          }
  
          Integer[] readIntegerArray(int n) {
              Integer[] a = new Integer[n];
              for (int i = 0; i < n; i++)
                  a[i] = nextInt();
              return a;
          }
  
          long nextLong() {
              return Long.parseLong(next());
          }
  
          double nextDouble() {
              return Double.parseDouble(next());
          }
      }
  
      void tr(Object... o) {
          pw.println(Arrays.deepToString(o));
      }
  }