description: You are given a sequence of n integers a_1,   a_2,   ...,   a_n.
  
  Does there exist a sequence of n integers b_1,   b_2,   ...,   b_n such that the following property holds?
  
    * For each 1 ≤ i ≤ n, there exist two (not necessarily distinct) indices j and k (1 ≤ j,   k ≤ n) such that a_i = b_j - b_k. 
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 20) — the number of test cases. Then t test cases follow.
  
  The first line of each test case contains one integer n (1 ≤ n ≤ 10).
  
  The second line of each test case contains the n integers a_1,   ...,   a_n (-10^5 ≤ a_i ≤ 10^5).
  
  Output
  
  For each test case, output a line containing YES if a sequence b_1,   ...,   b_n satisfying the required property exists, and NO otherwise.
  
  Example
  
  Input
  
  
  5
  5
  4 -7 -1 5 10
  1
  0
  3
  1 10 100
  4
  -3 2 10 2
  9
  25 -171 250 174 152 242 100 -205 -258
  
  
  Output
  
  
  YES
  YES
  NO
  YES
  YES
  
  Note
  
  In the first test case, the sequence b = [-9,   2,   1,   3,   -2] satisfies the property. Indeed, the following holds: 
  
    * a_1 = 4 = 2 - (-2) = b_2 - b_5; 
    * a_2 = -7 = -9 - (-2) = b_1 - b_5; 
    * a_3 = -1 = 1 - 2 = b_3 - b_2; 
    * a_4 = 5 = 3 - (-2) = b_4 - b_5; 
    * a_5 = 10 = 1 - (-9) = b_3 - b_1. 
  
  
  
  In the second test case, it is sufficient to choose b = [0], since a_1 = 0 = 0 - 0 = b_1 - b_1.
  
  In the third test case, it is possible to show that no sequence b of length 3 satisfies the property.
solution: import java.io.OutputStream;
  import java.io.IOException;
  import java.io.InputStream;
  import java.io.PrintWriter;
  import java.util.HashSet;
  import java.util.StringTokenizer;
  import java.util.Set;
  import java.io.IOException;
  import java.io.BufferedReader;
  import java.io.InputStreamReader;
  import java.io.InputStream;
  
  /**
   * Built using CHelper plug-in
   * Actual solution is at the top
   *
   * @author lucasr
   */
  public class Main {
  	public static void main(String[] args) {
  		InputStream inputStream = System.in;
  		OutputStream outputStream = System.out;
  		MyScanner in = new MyScanner(inputStream);
  		PrintWriter out = new PrintWriter(outputStream);
  		DArrayDifferentiation solver = new DArrayDifferentiation();
  		int testCount = Integer.parseInt(in.next());
  		for (int i = 1; i <= testCount; i++)
  			solver.solve(i, in, out);
  		out.close();
  	}
  
  	static class DArrayDifferentiation {
  		public static MyScanner sc;
  		public static PrintWriter out;
  
  		public void solve(int testNumber, MyScanner sc, PrintWriter out) {
  			DArrayDifferentiation.sc = sc;
  			DArrayDifferentiation.out = out;
  			int n = sc.nextInt();
  			int[] vals = new int[n];
  			for (int i = 0; i < n; i++) {
  				vals[i] = Math.abs(sc.nextInt());
  			}
  			Set<Integer> got = new HashSet<>();
  			boolean ok = false;
  			for (int mask = 0; mask < 1 << n && !ok; mask++) {
  				int sum = 0;
  				for (int i = 0; i < n; i++) {
  					if ((mask & 1 << i) != 0) sum += vals[i];
  				}
  				if (got.contains(sum)) {
  					ok = true;
  					break;
  				}
  				got.add(sum);
  			}
  			out.println(ok ? "YES" : "NO");
  		}
  
  	}
  
  	static class MyScanner {
  		private BufferedReader br;
  		private StringTokenizer tokenizer;
  
  		public MyScanner(InputStream is) {
  			br = new BufferedReader(new InputStreamReader(is));
  		}
  
  		public String next() {
  			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
  				try {
  					tokenizer = new StringTokenizer(br.readLine());
  				} catch (IOException e) {
  					throw new RuntimeException(e);
  				}
  			}
  			return tokenizer.nextToken();
  		}
  
  		public int nextInt() {
  			return Integer.parseInt(next());
  		}
  
  	}
  }
  
  