description: You are given four integer values a, b, c and m.
  
  Check if there exists a string that contains: 
  
    * a letters 'A'; 
    * b letters 'B'; 
    * c letters 'C'; 
    * no other letters; 
    * exactly m pairs of adjacent equal letters (exactly m such positions i that the i-th letter is equal to the (i+1)-th one). 
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of testcases.
  
  Each of the next t lines contains the description of the testcase — four integers a, b, c and m (1 ≤ a, b, c ≤ 10^8; 0 ≤ m ≤ 10^8).
  
  Output
  
  For each testcase print "YES" if there exists a string that satisfies all the requirements. Print "NO" if there are no such strings.
  
  You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).
  
  Example
  
  Input
  
  
  3
  2 2 1 0
  1 1 1 1
  1 2 3 2
  
  
  Output
  
  
  YES
  NO
  YES
  
  Note
  
  In the first testcase strings "ABCAB" or "BCABA" satisfy the requirements. There exist other possible strings.
  
  In the second testcase there's no way to put adjacent equal letters if there's no letter that appears at least twice.
  
  In the third testcase string "CABBCC" satisfies the requirements. There exist other possible strings.
solution: #include <bits/stdc++.h>
  using namespace std;
  const long long M = 1e9 + 7;
  void flashSpeed() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
  }
  const long long N = 2e5 + 5;
  long long fact[N];
  double Round(double var) {
    float value = (long long)(var * 100 + .5);
    return (float)value / 100;
  }
  long long ceils(long long x, long long y) { return x / y + ((x % y) != 0); }
  long long Gcd(long long a, long long b) {
    if (b > a) {
      return Gcd(b, a);
    }
    if (b == 0)
      return a;
    else
      return Gcd(b, a % b);
  }
  long long lcm(long long a, long long b) { return a / Gcd(a, b) * b; }
  bool isPal(string s) {
    for (long long i = 0; i < (long long)s.size() / 2; i++) {
      if (s[i] != s[(long long)s.size() - 1 - i]) return false;
    }
    return true;
  }
  long long Sumdigits(long long a) {
    long long total = 0;
    while (a) {
      total += a % 10;
      a /= 10;
    }
    return total;
  }
  bool isPerfectSquare(long long n) {
    for (long long i = 1; i * i <= n; i++) {
      if ((n % i == 0) && (n / i == i)) {
        return true;
      }
    }
    return false;
  }
  bool isPowerOfTwo(long long n) { return (ceil(log2(n)) == floor(log2(n))); }
  void lexosmaintest(string s, string c) {
    string t1 = s;
    sort(t1.begin(), t1.end());
    long long index = -1;
    for (long long i = 0; i < s.length(); i++) {
      if (s[i] != t1[i]) {
        index = i;
        break;
      }
    }
    long long j;
    for (long long i = 0; i < s.length(); i++) {
      if (s[i] == t1[index]) j = i;
    }
    swap(s[index], s[j]);
  }
  const long long NN = 1e4 + 5;
  long long primes[NN];
  vector<long long> pr;
  void sieve() {
    for (long long i = 2; i < NN; i++) {
      if (primes[i] == 0) {
        pr.push_back(i);
        for (long long j = i * i; j < NN; j += i) {
          primes[j] = 1;
        }
      }
      primes[i] ^= 1;
    }
  }
  const long long mod2 = 998244353;
  long long powerr(long long x, long long y, long long p = mod2) {
    long long res = 1;
    x = x % p;
    if (x == 0) return 0;
    while (y > 0) {
      if (y & 1) res = (res * x) % p;
      y = y >> 1;
      x = (x * x) % p;
    }
    return res;
  }
  long long iAmUseless(long long n) {}
  const double PI = acos(-1);
  long long lefty[N];
  long long righty[N];
  void chaloTryKrteHai() {
    long long a, b, c;
    cin >> a >> b >> c;
    long long m;
    cin >> m;
    long long second = a + b + c;
    if (m > second - 3LL) {
      cout << "NO" << endl;
    } else {
      long long maxi = max({a, b, c});
      second -= maxi;
      if (maxi - 1 > second) {
        if (m < (maxi - second) - 1) {
          cout << "NO" << endl;
        } else {
          cout << "YES" << endl;
        }
      } else {
        cout << "YES" << endl;
      }
    }
  }
  int32_t main() {
    flashSpeed();
    sieve();
    long long t = 1;
    cin >> t;
    while (t--) {
      chaloTryKrteHai();
    }
    return 0;
  }
  