description: On a circle lie 2n distinct points, with the following property: however you choose 3 chords that connect 3 disjoint pairs of points, no point strictly inside the circle belongs to all 3 chords. The points are numbered 1,   2,   ...,   2n in clockwise order.
  
  Initially, k chords connect k pairs of points, in such a way that all the 2k endpoints of these chords are distinct.
  
  You want to draw n - k additional chords that connect the remaining 2(n - k) points (each point must be an endpoint of exactly one chord).
  
  In the end, let x be the total number of intersections among all n chords. Compute the maximum value that x can attain if you choose the n - k chords optimally.
  
  Note that the exact position of the 2n points is not relevant, as long as the property stated in the first paragraph holds.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.
  
  The first line of each test case contains two integers n and k (1 ≤ n ≤ 100, 0 ≤ k ≤ n) — half the number of points and the number of chords initially drawn.
  
  Then k lines follow. The i-th of them contains two integers x_i and y_i (1 ≤ x_i,   y_i ≤ 2n, x_i ≠ y_i) — the endpoints of the i-th chord. It is guaranteed that the 2k numbers x_1,   y_1,   x_2,   y_2,   ...,   x_k,   y_k are all distinct.
  
  Output
  
  For each test case, output the maximum number of intersections that can be obtained by drawing n - k additional chords.
  
  Example
  
  Input
  
  
  4
  4 2
  8 2
  1 5
  1 1
  2 1
  2 0
  10 6
  14 6
  2 20
  9 10
  13 18
  15 12
  11 7
  
  
  Output
  
  
  4
  0
  1
  14
  
  Note
  
  In the first test case, there are three ways to draw the 2 additional chords, shown below (black chords are the ones initially drawn, while red chords are the new ones):
  
  <image>
  
  We see that the third way gives the maximum number of intersections, namely 4.
  
  In the second test case, there are no more chords to draw. Of course, with only one chord present there are no intersections.
  
  In the third test case, we can make at most one intersection by drawing chords 1-3 and 2-4, as shown below:
  
  <image>
solution: public class Main {
  
  	public static void main(String[] args) {
  		new Main();
  	}
  
  	public Main() {
  		FastScanner fs = new FastScanner();
  		java.io.PrintWriter out = new java.io.PrintWriter(System.out);
  		solve(fs, out);
  		out.flush();
  	}
  
  	public void solve(FastScanner fs, java.io.PrintWriter out) {
  		int t = fs.nextInt();
  		test: while(t --> 0) {
  			int n = fs.nextInt(), k = fs.nextInt();
  			int[] pair = new int[2 * n];
  			java.util.Arrays.fill(pair, -1);
  			for (int i = 0;i < k;++ i) {
  				int x = fs.nextInt() - 1, y = fs.nextInt() - 1;
  				pair[x] = y;
  				pair[y] = x;
  			}
  			int[] stock = new int[n - k];
  			for (int i = 0, j = 0;i < 2 * n;++ i) {
  				if (pair[i] != -1) continue;
  				if (j < n - k) {
  					stock[j] = i;
  				} else {
  					pair[i] = stock[j % (n - k)];
  					pair[stock[j % (n - k)]] = i;
  				}
  				++ j;
  			}
  			int ans = 0;
  			for (int i = 0;i < 2 * n;++ i) {
  				if (pair[i] < i) continue;
  				for (int j = i + 1;j < 2 * n;++ j) {
  					if (pair[j] < j) continue;
  					if (j < pair[i] && pair[j] > pair[i]) ++ ans;
  				}
  			}
  			out.println(ans);
  		}
  	}
  
  	final int MOD = 998_244_353;
  	int plus(int n, int m) {
  		int sum = n + m;
  		if (sum >= MOD) sum -= MOD;
  		return sum;
  	}
  	int minus(int n, int m) {
  		int sum = n - m;
  		if (sum < 0) sum += MOD;
  		return sum;
  	}
  	int times(int n, int m) {
  		return (int)((long)n * m % MOD);
  	}
  	int divide(int n, int m) {
  		return times(n, IntMath.pow(m, MOD - 2, MOD));
  	}
  	int[] fact, invf;
  	void calc(int len) {
  		len += 2;
  		fact = new int[len];
  		invf = new int[len];
  		fact[0] = fact[1] = invf[0] = invf[1] = 1;
  		for (int i = 2;i < fact.length;++ i) fact[i] = times(fact[i - 1], i);
  		invf[len - 1] = divide(1, fact[len - 1]);
  		for (int i = len - 1;i > 1;-- i) invf[i - 1] = times(i, invf[i]);
  	}
  	int comb(int n, int m) {
  		if (n < m) return 0;
  		return times(fact[n], times(invf[n - m], invf[m]));
  	}
  }
  
  class FastScanner {
  
  	private final java.io.InputStream in = System.in;
  	private final byte[] buffer = new byte[8192];
  	private int ptr = 0;
  	private int buflen = 0;
  
  	private boolean hasNextByte() {
  		if (ptr < buflen) return true;
  		ptr = 0;
  		try {
  			buflen = in.read(buffer);
  		} catch (java.io.IOException e) {
  			e.printStackTrace();
  		}
  		return buflen > 0;
  	}
  
  	private byte readByte() {
  		return hasNextByte() ? buffer[ptr++ ] : -1;
  	}
  
  	private static boolean isPrintableChar(byte c) {
  		return 32 < c || c < 0;
  	}
  
  	private static boolean isNumber(int c) {
  		return '0' <= c && c <= '9';
  	}
  
  	public boolean hasNext() {
  		while (hasNextByte() && !isPrintableChar(buffer[ptr]))
  			ptr++ ;
  		return hasNextByte();
  	}
  
  	public String next() {
  		if (!hasNext()) throw new java.util.NoSuchElementException();
  		StringBuilder sb = new StringBuilder();
  		byte b;
  		while (isPrintableChar(b = readByte()))
  			sb.appendCodePoint(b);
  		return sb.toString();
  	}
  
  	public final char nextChar() {
  		if (!hasNext()) throw new java.util.NoSuchElementException();
  		return (char)readByte();
  	}
  
  	public final long nextLong() {
  		if (!hasNext()) throw new java.util.NoSuchElementException();
  		long n = 0;
  		try {
  			byte b = readByte();
  			if (b == '-') {
  				while (isNumber(b = readByte()))
  					n = n * 10 + '0' - b;
  				return n;
  			} else if (!isNumber(b)) throw new NumberFormatException();
  			do
  				n = n * 10 + b - '0';
  			while (isNumber(b = readByte()));
  		} catch (java.util.NoSuchElementException e) {}
  		return n;
  	}
  
  	public final int nextInt() {
  		if (!hasNext()) throw new java.util.NoSuchElementException();
  		int n = 0;
  		try {
  			byte b = readByte();
  			if (b == '-') {
  				while (isNumber(b = readByte()))
  					n = n * 10 + '0' - b;
  				return n;
  			} else if (!isNumber(b)) throw new NumberFormatException();
  			do
  				n = n * 10 + b - '0';
  			while (isNumber(b = readByte()));
  		} catch (java.util.NoSuchElementException e) {}
  		return n;
  	}
  
  	public double nextDouble() {
  		return Double.parseDouble(next());
  	}
  }
  
  class Arrays {
  
  	public static void sort(final int[] array) {
  		sort(array, 0, array.length);
  	}
  
  	public static void sort(final int[] array, int fromIndex, int toIndex) {
  		if (toIndex - fromIndex  <= 512) {
  			java.util.Arrays.sort(array, fromIndex, toIndex);
  			return;
  		}
  		sort(array, fromIndex, toIndex, 0, new int[array.length]);
  	}
  
  	private static final void sort(int[] a, final int from, final int to, final int l, final int[] bucket) {
  		if (to - from  <= 512) {
  			java.util.Arrays.sort(a, from, to);
  			return;
  		}
  		final int BUCKET_SIZE = 256;
  		final int INT_RECURSION = 4;
  		final int MASK = 0xff;
  		final int shift = l << 3;
  		final int[] cnt = new int[BUCKET_SIZE + 1];
  		final int[] put = new int[BUCKET_SIZE];
  		for (int i = from; i < to; i++) ++ cnt[(a[i] >>> shift & MASK) + 1];
  		for (int i = 0; i < BUCKET_SIZE; i++) cnt[i + 1] += cnt[i];
  		for (int i = from; i < to; i++) {
  			int bi = a[i] >>> shift & MASK;
  			bucket[cnt[bi] + put[bi]++] = a[i];
  		}
  		for (int i = BUCKET_SIZE - 1, idx = from; i >= 0; i--) {
  			int begin = cnt[i];
  			int len = cnt[i + 1] - begin;
  			System.arraycopy(bucket, begin, a, idx, len);
  			idx += len;
  	    }
  		final int nxtL = l + 1;
  		if (nxtL < INT_RECURSION) {
  			sort(a, from, to, nxtL, bucket);
  			if (l == 0) {
  				int lft, rgt;
  				lft = from - 1; rgt = to;
  				while (rgt - lft > 1) {
  					int mid = lft + rgt >> 1;
  					if (a[mid] < 0) lft = mid;
  					else rgt = mid;
  				}
  				reverse(a, from, rgt);
  				reverse(a, rgt, to);
  	        }
  	    }
  	}
  
  	public static void sort(final long[] array) {
  		sort(array, 0, array.length);
  	}
  
  	public static void sort(final long[] array, int fromIndex, int toIndex) {
  		if (toIndex - fromIndex  <= 512) {
  			java.util.Arrays.sort(array, fromIndex, toIndex);
  			return;
  		}
  		sort(array, fromIndex, toIndex, 0, new long[array.length]);
  	}
  
  	private static final void sort(long[] a, final int from, final int to, final int l, final long[] bucket) {
  		final int BUCKET_SIZE = 256;
  		final int LONG_RECURSION = 8;
  		final int MASK = 0xff;
  		final int shift = l << 3;
  		final int[] cnt = new int[BUCKET_SIZE + 1];
  		final int[] put = new int[BUCKET_SIZE];
  		for (int i = from; i < to; i++) ++ cnt[(int) ((a[i] >>> shift & MASK) + 1)];
  		for (int i = 0; i < BUCKET_SIZE; i++) cnt[i + 1] += cnt[i];
  		for (int i = from; i < to; i++) {
  			int bi = (int) (a[i] >>> shift & MASK);
  			bucket[cnt[bi] + put[bi]++] = a[i];
  		}
  		for (int i = BUCKET_SIZE - 1, idx = from; i >= 0; i--) {
  			int begin = cnt[i];
  			int len = cnt[i + 1] - begin;
  			System.arraycopy(bucket, begin, a, idx, len);
  			idx += len;
  	    }
  		final int nxtL = l + 1;
  		if (nxtL < LONG_RECURSION) {
  			sort(a, from, to, nxtL, bucket);
  			if (l == 0) {
  				int lft, rgt;
  				lft = from - 1; rgt = to;
  				while (rgt - lft > 1) {
  					int mid = lft + rgt >> 1;
  					if (a[mid] < 0) lft = mid;
  					else rgt = mid;
  				}
  				reverse(a, from, rgt);
  				reverse(a, rgt, to);
  	        }
  	    }
  	}
  
  	public static void reverse(int[] array) {
  		reverse(array, 0, array.length);
  	}
  
  	public static void reverse(int[] array, int fromIndex, int toIndex) {
  		for (-- toIndex;fromIndex < toIndex;++ fromIndex, -- toIndex) {
  			int swap = array[fromIndex];
  			array[fromIndex] = array[toIndex];
  			array[toIndex] = swap;
  		}
  	}
  
  	public static void reverse(long[] array) {
  		reverse(array, 0, array.length);
  	}
  
  	public static void reverse(long[] array, int fromIndex, int toIndex) {
  		for (-- toIndex;fromIndex < toIndex;++ fromIndex, -- toIndex) {
  			long swap = array[fromIndex];
  			array[fromIndex] = array[toIndex];
  			array[toIndex] = swap;
  		}
  	}
  
  	public static void shuffle(int[] array) {
  		java.util.Random rnd = new java.util.Random();
  		for (int i = 0;i < array.length;++ i) {
  			int j = rnd.nextInt(array.length - i) + i;
  			int swap = array[i];
  			array[i] = array[j];
  			array[j] = swap;
  		}
  	}
  
  	public static void shuffle(long[] array) {
  		java.util.Random rnd = new java.util.Random();
  		for (int i = 0;i < array.length;++ i) {
  			int j = rnd.nextInt(array.length - i) + i;
  			long swap = array[i];
  			array[i] = array[j];
  			array[j] = swap;
  		}
  	}
  }
  
  class IntMath {
  
  	public static int gcd(int a, int b) {
  		while (a != 0)
  			if ((b %= a) != 0) a %= b;
  			else return a;
  		return b;
  	}
  
  	public static int gcd(int... array) {
  		int ret = array[0];
  		for (int i = 1; i < array.length; ++i)
  			ret = gcd(ret, array[i]);
  		return ret;
  	}
  
  	public static long gcd(long a, long b) {
  		while (a != 0)
  			if ((b %= a) != 0) a %= b;
  			else return a;
  		return b;
  	}
  
  	public static long gcd(long... array) {
  		long ret = array[0];
  		for (int i = 1; i < array.length; ++i)
  			ret = gcd(ret, array[i]);
  		return ret;
  	}
  
  	public static long lcm(long a, long b) {
  		return a / gcd(a, b) * b;
  	}
  
  	public static int pow(int a, int b) {
  		int ans = 1;
  		for (int mul = a; b > 0; b >>= 1, mul *= mul)
  			if ((b & 1) != 0) ans *= mul;
  		return ans;
  	}
  
  	public static long pow(long a, long b) {
  		long ans = 1;
  		for (long mul = a; b > 0; b >>= 1, mul *= mul)
  			if ((b & 1) != 0) ans *= mul;
  		return ans;
  	}
  
  	public static int pow(int a, long b, int mod) {
  		if (b < 0) b = b % (mod - 1) + mod - 1;
  		long ans = 1;
  		for (long mul = a; b > 0; b >>= 1, mul = mul * mul % mod)
  			if ((b & 1) != 0) ans = ans * mul % mod;
  		return (int)ans;
  	}
  
  	public static int pow(long a, long b, int mod) {
  		return pow((int)(a % mod), b, mod);
  	}
  
  	public static int floorsqrt(long n) {
  		return (int)Math.sqrt(n + 0.1);
  	}
  
  	public static int ceilsqrt(long n) {
  		return n <= 1 ? (int)n : (int)Math.sqrt(n - 0.1) + 1;
  	}
  }
  