description: The numbers 1,   2,   ...,   n ⋅ k are colored with n colors. These colors are indexed by 1,   2,   ...,   n. For each 1 ≤ i ≤ n, there are exactly k numbers colored with color i.
  
  Let [a,   b] denote the interval of integers between a and b inclusive, that is, the set \\{a,   a + 1,   ...,   b\}. You must choose n intervals [a_1,   b_1],   [a_2,   b_2],   ..., [a_n,   b_n] such that: 
  
    * for each 1 ≤ i ≤ n, it holds 1 ≤ a_i < b_i ≤ n ⋅ k; 
    * for each 1 ≤ i ≤ n, the numbers a_i and b_i are colored with color i; 
    * each number 1 ≤ x ≤ n ⋅ k belongs to at most \left⌈ (n)/(k - 1) \right⌉ intervals. 
  
  
  
  One can show that such a family of intervals always exists under the given constraints.
  
  Input
  
  The first line contains two integers n and k (1 ≤ n ≤ 100, 2 ≤ k ≤ 100) — the number of colors and the number of occurrences of each color.
  
  The second line contains n ⋅ k integers c_1,   c_2,   ...,   c_{nk} (1 ≤ c_j ≤ n), where c_j is the color of number j. It is guaranteed that, for each 1 ≤ i ≤ n, it holds c_j = i for exactly k distinct indices j.
  
  Output
  
  Output n lines. The i-th line should contain the two integers a_i and b_i.
  
  If there are multiple valid choices of the intervals, output any.
  
  Examples
  
  Input
  
  
  4 3
  2 4 3 1 1 4 2 3 2 1 3 4
  
  
  Output
  
  
  4 5
  1 7
  8 11
  6 12
  
  Input
  
  
  1 2
  1 1
  
  
  Output
  
  
  1 2
  
  
  Input
  
  
  3 3
  3 1 2 3 2 1 2 1 3
  
  
  Output
  
  
  6 8
  3 7
  1 4
  
  Input
  
  
  2 3
  2 1 1 1 2 2
  
  
  Output
  
  
  2 3
  5 6
  
  Note
  
  In the first sample, each number can be contained in at most \left⌈ (4)/(3 - 1) \right⌉ = 2 intervals. The output is described by the following picture:
  
  <image>
  
  In the second sample, the only interval to be chosen is forced to be [1,   2], and each number is indeed contained in at most \left⌈ (1)/(2 - 1) \right⌉ = 1 interval.
  
  In the third sample, each number can be contained in at most \left⌈ (3)/(3 - 1) \right⌉ = 2 intervals. The output is described by the following picture:
  
  <image>
solution: import java.io.*;
  import java.util.*;
   
  public class Main extends PrintWriter {
      
      void solve() {
          int n = sc.nextInt();
          int k = sc.nextInt();
          int nk = n*k;
          int[] c = new int[nk];
          for(int i = 0; i < nk; i++) {
              c[i] = sc.nextInt()-1;
          }
          int[] last = new int[n];
          Arrays.fill(last, -1);
          int bound = (n + k-2) / (k-1);
          int[] cnt = new int[nk];
          boolean[] done = new boolean[n];
          int[] a = new int[n];
          int[] b = new int[n];
          for(int i = 0; i < nk; i++) {
              if(done[c[i]]) continue;
              if(last[c[i]] != -1) {
                  boolean bad = false;
                  for(int j = last[c[i]]; j <= i; j++) {
                      if(cnt[j] >= bound) {
                          bad = true;
                          break;
                      }
                  }
                  if(!bad) {
                      for(int j = last[c[i]]; j <= i; j++) {
                          cnt[j]++;
                      }
                      a[c[i]] = last[c[i]]+1;
                      b[c[i]] = i+1;
                      done[c[i]] = true;
                  }                
              } 
              last[c[i]] = i;
          }
          for(int i = 0; i < n; i++) {
              println(a[i] + " " + b[i]);
          }
      }
      
      
  //  Main() throws FileNotFoundException { super(new File("output.txt")); }
  //  InputReader sc = new InputReader(new FileInputStream("1_08"));
    Main() { super(System.out); }
    InputReader sc = new InputReader(System.in);
    static class InputReader {
        InputReader(InputStream in) { this.in = in; } InputStream in;
        
        private byte[] buf = new byte[16384];
        private int    curChar;
        private int    numChars;
        
   
        public int read() {
            if (numChars == -1)
                throw new InputMismatchException();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = in.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }
   
        private String nextLine() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isEndOfLine(c));
            return res.toString();
        }
   
        public String nextString() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }
   
        public long nextLong() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
   
        public int nextInt() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
   
        private boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
   
        private boolean isEndOfLine(int c) {
            return c == '\n' || c == '\r' || c == -1;
        }
    }
   
      public static void main(String[] $) {
          new Thread(null, new Runnable() {
              public void run() {
                  long start = System.nanoTime();
                  try {Main solution = new Main(); solution.solve(); solution.flush();} 
                  catch (Exception e) {e.printStackTrace(); System.exit(1);}
                  System.err.println((System.nanoTime()-start)/1E9);
              }
          }, "1", 1 << 27).start();
   
      }
  }