Since it only requires that the final position of beads be remembered, it takes less memory and less computation time.
sˈɪns ɪɾ ˈoʊnli ɹᵻkwˈaɪɚz ðætðə fˈaɪnəl pəzˈɪʃən ʌv bˈiːdz biː ɹᵻmˈɛmbɚd, ɪt tˈeɪks lˈɛs mˈɛmɚɹi ænd lˈɛs kˌɑːmpjuːtˈeɪʃən tˈaɪm.