def parse(date_str, inclusive=False, default_hour=None, default_minute=None):
    """Parses a string containing a fuzzy date and returns a datetime.datetime object"""
    if not date_str:
        return None
    elif isinstance(date_str, datetime):
        return date_str

    default_date = DEFAULT_FUTURE if inclusive else DEFAULT_PAST
    date = None
    year_present = False
    while not date:
        try:
            date = dateparse(date_str, default=default_date)
            if date.year == FAKE_YEAR:
                date = datetime(datetime.now().year, date.timetuple()[1:6])
            else:
                year_present = True
            flag = 1 if date.hour == date.minute == 0 else 2
            date = date.timetuple()
        except Exception as e:
            if e.args[0] == 'day is out of range for month':
                y, m, d, H, M, S = default_date.timetuple()[:6]
                default_date = datetime(y, m, d - 1, H, M, S)
            else:
                date, flag = CALENDAR.parse(date_str)

    if not flag:  # Oops, unparsable.
        try:  # Try and parse this as a single year
            year = int(date_str)
            return datetime(year, 1, 1)
        except __HOLE__:
            return None
        except TypeError:
            return None

    if flag is 1:  # Date found, but no time. Use the default time.
        date = datetime(*date[:3],
                        hour=23 if inclusive else default_hour or 0,
                        minute=59 if inclusive else default_minute or 0,
                        second=59 if inclusive else 0)
    else:
        date = datetime(*date[:6])

    # Ugly heuristic: if the date is more than 4 weeks in the future, we got the year wrong.
    # Rather then this, we would like to see parsedatetime patched so we can tell it to prefer
    # past dates
    dt = datetime.now() - date
    if dt.days < -28 and not year_present:
        date = date.replace(date.year - 1)
    return date
dataset/ETHPy150Open maebert/jrnl/jrnl/time.py/parse