def urlunparse(data):
scheme, netloc, url, params, query, fragment = data<EOL>if params:<EOL><INDENT>url = "<STR_LIT>" % (url, params)<EOL><DEDENT>return urlunsplit((scheme, netloc, url, query, fragment))<EOL>
Put a parsed URL back together again.  This may result in a
    slightly different, but equivalent URL, if the URL that was parsed
    originally had redundant delimiters, e.g. a ? with an empty query
    (the draft states that these are equivalent).