def _restore_path(table):
name = None<EOL>splited = table.split('<STR_LIT>')<EOL>path = splited[<NUM_LIT:0>]<EOL>if len(splited) == <NUM_LIT:2>:<EOL><INDENT>name = splited[<NUM_LIT:1>]<EOL><DEDENT>path = path.replace('<STR_LIT>', os.path.sep)<EOL>path += '<STR_LIT>'<EOL>return path, name<EOL>
Restore resource's path and name from storage's table.

    Args:
        table (str): table name

    Returns:
        (str, str): resource path and name