JQuery reverse each() with find()
<p>I know this kind of question has been asked before, but the general solution of </p>

<pre><code>$($("input").get().reverse()).each(function() { /* ... */ });
</code></pre>

<p>is not working for me. I have an xml document that contains a list of concerts that I'd like to display on a webpage. So, in JQuery:</p>

<pre><code>$.ajax({
    type: "GET",
    url: "concerts.xml",
    dataType: "xml",
    cache: false,
    success: function(xml) {
        $(xml).find('concert').each(function() {
            /*do stuff*/
        });
    }
});
</code></pre>

<p>However, I'd like to display the concerts in reverse order. So, I tried the following, but it did not work:</p>

<pre><code>$.ajax({
    type: "GET",
    url: "concerts.xml",
    dataType: "xml",
    cache: false,
    success: function(xml) {
        $($(xml).find('concert').reverse()).each(function() {
            /*do stuff*/
        });
    }
});
</code></pre>

<p>Any assistance would be much appreciated. Thanks.</p>
