Math.pow JS vs. PHP
<p>I need help to "translate" this snippet to PHP from JS.</p>

<p>The original JS code is this:</p>

<pre><code>result  = A * ( B / 1200 ) /
          ( 1 - 1 / Math.pow( 1 + ( B / 1200 ), C * 12 ) ) * D;   
</code></pre>

<p>I need this code in PHP. I try with this, but it gives me a different result:</p>

<pre><code>$result = $A * ( $B / 1200) /
          ( 1 - 1 / pow( 1 + ( $B / 1200 ), $C * 12 ) ) * $D;
</code></pre>
