Passing two values for ajaxForm(), using jQuery and PHP
<p>I want to pass both the values using ajaxForm, displaying both the values separately in test.php</p>

<pre><code>-------test.php-----------------------------------------

&lt;script language="javascript" type="text/javascript"&gt;

$('#test_form').ajaxForm({
    target:'#result',

    success:function() {
        $('#result').show();
    }
});


&lt;/script&gt;



&lt;form id="test_form" method="" action="test1.php"&gt;
&lt;input type="submit" id="sub" value="sub_value"&gt;
&lt;/form&gt;

&lt;div id="result"&gt;&lt;/div&gt;

-------test1.php---------------------------------------


&lt;?
$t="test value";
$u="test value 1";

?&gt;
</code></pre>

<p>Thanks
Jean</p>
