don't work 'fadeOut' If there is 'replaceWith'.?
<p>When i use of <code>fadeOut</code> and <code>replaceWith</code> together, does not work fadeOut. but if i use only of <code>fadeOut</code> it worked. i want use of each tow they together. how is it in my code?</p>

<pre><code>$.ajax({
        type: "POST",
        url: url,
        data: dataString,
        cache: false,
        success: function(html){
            var $html = $(html);
////////////////////////////////// here ////////////////////////////////
                    $('.ser_form #paginate input:checkbox:checked').parent().parent().fadeOut("slow");

                    $('#num_count').replaceWith($html.find('#num_count'));
                    $('tr#paginate').replaceWith($html.find('tr#paginate'));
                    $('.pagination').replaceWith($html.find('.pagination'));
////////////////////////////////// here ////////////////////////////////

        },
</code></pre>

<p><strong>EXAMPLE:</strong> <a href="http://www.binboy.gigfa.com/admin/accommodation/show" rel="nofollow">Yourself see</a><p>
In example above please check row and click on DELETE to see it.</p>
