prompt: You will be provided with a partial code base and an issue statement explaining a problem to resolve.
  <issue>
  Review links to OWASP wiki
  ### Describe the bug
  
  We have references to other OWASP projects in our files:
  
  ```
  rules/REQUEST-933-APPLICATION-ATTACK-PHP.conf
  28:# https://www.owasp.org/index.php/PHP_Top_5#P1:_Remote_Code_Executionh
  366:# https://www.owasp.org/index.php/PHP_Object_Injection
  
  rules/REQUEST-921-PROTOCOL-ATTACK.conf
  194:# Reference: https://www.owasp.org/index.php/Testing_for_HTTP_Splitting/Smuggling_(OTG-INPVAL-016)
  
  rules/REQUEST-920-PROTOCOL-ENFORCEMENT.conf
  97:# https://www.owasp.org/index.php/ModSecurity_CRS_RuleID-96000
  
  CHANGES.md
  977:  https://www.owasp.org/index.php/AppSensor_DetectionPoints
  
  rules/REQUEST-932-APPLICATION-ATTACK-RCE.conf
  690:# https://www.owasp.org/index.php/Unrestricted_File_Upload
  
  rules/scanners-user-agents.data
  58:# https://www.owasp.org/index.php/Category:OWASP_DirBuster_Project
  ```
  We need to double check they are still valid and update if not.
  
  </issue>
  <code>
  [start of util/regexp-tricks/negative-lookahead.py]
  1 import argparse
  2 
  3 # WARNING: This script is EXPERIMENTAL. Use with caution.
  4 #
  5 # Known issues:
  6 #   * At the moment, it will probably not work with more than two strings.
  7 #
  8 # Known limitations:
  9 #   * Any substrings of a target string will also NOT be matched. This is probably due to a limitation in this technique,
  10 #   make sure that subtrings of the negative lookahead are not harmful in any way.
  11 
  12 parser = argparse.ArgumentParser(description="This script takes a list of strings and converts them into \
  13     a regex that acts like a negative lookahead")
  14 parser.add_argument("strings", type=str, nargs='+',
  15     help="the strings to convert into a negative lookahead")
  16 parser.add_argument("--prefix", type=str, default="",
  17     help="sets a prefix for the resulting regex")
  18 parser.add_argument("--suffix", type=str, default="",
  19     help="sets a suffix for the resulting regex")
  20 
  21 args = parser.parse_args()
  22 
  23 # Return the longest prefix of all list elements. Shamelessly copied from:
  24 # https://stackoverflow.com/questions/6718196/determine-prefix-from-a-set-of-similar-strings
  25 def commonprefix(m):
  26     "Given a list of pathnames, returns the longest common leading component"
  27     if not m: return ''
  28     s1 = min(m)
  29     s2 = max(m)
  30     for i, c in enumerate(s1):
  31         if c != s2[i]:
  32             return s1[:i]
  33     return s1
  34 
  35 # flatten returns a string with concatenated dictionary keys
  36 def flatten(dict):
  37     s = ""
  38 
  39     for key in dict.keys():
  40         s += key
  41 
  42     return s
  43 
  44 # set returns a character set containing the unique characters across all strings for the given index
  45 def set(strings, index, flags):
  46     dict = {}
  47 
  48     for s in strings:
  49         # Continue so we don't panic
  50         if index > len(s) -1:
  51             continue
  52         
  53         dict[s[index]] = ''
  54     
  55     return "[" + flags + flatten(dict) + "]"
  56 
  57 # prepare converts a string for negative lookaheads emulation
  58 def prepare(s, offset):
  59     r = ""
  60 
  61     if len(s) == 0:
  62         return r
  63 
  64     for i in range(offset, len(s)):
  65         for j in range(0, i + 1):
  66             if j == i:
  67                 r += "[^" + s[j] + "]"
  68             else:
  69                 r += s[j]
  70 
  71         if i != len(s) - 1:
  72             r += "|"
  73 
  74     return r
  75 
  76 # run runs the 
  77 def run():
  78     strings = args.strings
  79 
  80     r = ""
  81     r += set(strings, 0, "^")
  82 
  83     c = ""
  84     d = {}
  85 
  86     # Only find common string if we have more than one
  87     if len(strings) > 1:
  88         c = commonprefix(strings)
  89         
  90         # Collect all characters after the common substring from every string
  91         for s in strings:
  92             if len(s) > len(c) and s.startswith(c):
  93                 d[s[len(c)]] = ''
  94 
  95     # Add the common string to the regex to prevent accidental matching
  96     if len(c) > 0:
  97         if len(c) > 1:
  98             r += "|" +  "(?:" + prepare(c, 1) + ")"
  99 
  100         r +=  "|" + "(?:" + c + "[^" + flatten(d) + "]" + ")"
  101 
  102     for s in strings:
  103         g = ""
  104 
  105         # When the common string is > 0, offset with len(c) + 1 because we handled this earlier
  106         if len(c) > 0:
  107             g = prepare(s, len(c) + 1)
  108         else:
  109             g = prepare(s, 1)
  110         
  111         # Add OR boolean if necessary
  112         if len(g) > 0:
  113             r += "|"
  114 
  115         r += g
  116 
  117     print(args.prefix + "(?:" + r + ")" + args.suffix)
  118 
  119 # Only run if script is called directly
  120 if __name__ == "__main__":
  121     run()
  122
  [end of util/regexp-tricks/negative-lookahead.py]
  </code>
  
  I need you to solve this issue by generating a single patch file that I can apply directly to this repository using git apply. Please respond with a single patch file in the following format.
  <patch>
  diff --git a/file.py b/file.py
  --- a/file.py
  +++ b/file.py
  @@ -1,27 +1,35 @@
   def euclidean(a, b):
  -    while b:
  -        a, b = b, a % b
  -    return a
  +    if b == 0:
  +        return a
  +    return euclidean(b, a % b)
   
   
   def bresenham(x0, y0, x1, y1):
       points = []
       dx = abs(x1 - x0)
       dy = abs(y1 - y0)
  -    sx = 1 if x0 < x1 else -1
  -    sy = 1 if y0 < y1 else -1
  -    err = dx - dy
  +    x, y = x0, y0
  +    sx = -1 if x0 > x1 else 1
  +    sy = -1 if y0 > y1 else 1
   
  -    while True:
  -        points.append((x0, y0))
  -        if x0 == x1 and y0 == y1:
  -            break
  -        e2 = 2 * err
  -        if e2 > -dy:
  -            err -= dy
  -            x0 += sx
  -        if e2 < dx:
  -            err += dx
  -            y0 += sy
  +    if dx > dy:
  +        err = dx / 2.0
  +        while x != x1:
  +            points.append((x, y))
  +            err -= dy
  +            if err < 0:
  +                y += sy
  +                err += dx
  +            x += sx
  +    else:
  +        err = dy / 2.0
  +        while y != y1:
  +            points.append((x, y))
  +            err -= dx
  +            if err < 0:
  +                x += sx
  +                err += dy
  +            y += sy
  +
  +    points.append((x, y))
       return points
  
  </patch>
golden_diff: diff --git a/util/regexp-tricks/negative-lookahead.py b/util/regexp-tricks/negative-lookahead.py
  --- a/util/regexp-tricks/negative-lookahead.py
  +++ b/util/regexp-tricks/negative-lookahead.py
  @@ -21,7 +21,7 @@
   args = parser.parse_args()
   
   # Return the longest prefix of all list elements. Shamelessly copied from:
  -# https://stackoverflow.com/questions/6718196/determine-prefix-from-a-set-of-similar-strings
  +# https://stackoverflow.com/questions/6718196/determine-the-common-prefix-of-multiple-strings
   def commonprefix(m):
       "Given a list of pathnames, returns the longest common leading component"
       if not m: return ''
  
verification_info: {"golden_diff": "diff --git a/util/regexp-tricks/negative-lookahead.py b/util/regexp-tricks/negative-lookahead.py\n--- a/util/regexp-tricks/negative-lookahead.py\n+++ b/util/regexp-tricks/negative-lookahead.py\n@@ -21,7 +21,7 @@\n args = parser.parse_args()\n \n # Return the longest prefix of all list elements. Shamelessly copied from:\n-# https://stackoverflow.com/questions/6718196/determine-prefix-from-a-set-of-similar-strings\n+# https://stackoverflow.com/questions/6718196/determine-the-common-prefix-of-multiple-strings\n def commonprefix(m):\n     \"Given a list of pathnames, returns the longest common leading component\"\n     if not m: return ''\n", "issue": "Review links to OWASP wiki\n### Describe the bug\r\n\r\nWe have references to other OWASP projects in our files:\r\n\r\n```\r\nrules/REQUEST-933-APPLICATION-ATTACK-PHP.conf\r\n28:# https://www.owasp.org/index.php/PHP_Top_5#P1:_Remote_Code_Executionh\r\n366:# https://www.owasp.org/index.php/PHP_Object_Injection\r\n\r\nrules/REQUEST-921-PROTOCOL-ATTACK.conf\r\n194:# Reference: https://www.owasp.org/index.php/Testing_for_HTTP_Splitting/Smuggling_(OTG-INPVAL-016)\r\n\r\nrules/REQUEST-920-PROTOCOL-ENFORCEMENT.conf\r\n97:# https://www.owasp.org/index.php/ModSecurity_CRS_RuleID-96000\r\n\r\nCHANGES.md\r\n977:  https://www.owasp.org/index.php/AppSensor_DetectionPoints\r\n\r\nrules/REQUEST-932-APPLICATION-ATTACK-RCE.conf\r\n690:# https://www.owasp.org/index.php/Unrestricted_File_Upload\r\n\r\nrules/scanners-user-agents.data\r\n58:# https://www.owasp.org/index.php/Category:OWASP_DirBuster_Project\r\n```\r\nWe need to double check they are still valid and update if not.\n", "before_files": [{"content": "import argparse\n\n# WARNING: This script is EXPERIMENTAL. Use with caution.\n#\n# Known issues:\n#   * At the moment, it will probably not work with more than two strings.\n#\n# Known limitations:\n#   * Any substrings of a target string will also NOT be matched. This is probably due to a limitation in this technique,\n#   make sure that subtrings of the negative lookahead are not harmful in any way.\n\nparser = argparse.ArgumentParser(description=\"This script takes a list of strings and converts them into \\\n    a regex that acts like a negative lookahead\")\nparser.add_argument(\"strings\", type=str, nargs='+',\n    help=\"the strings to convert into a negative lookahead\")\nparser.add_argument(\"--prefix\", type=str, default=\"\",\n    help=\"sets a prefix for the resulting regex\")\nparser.add_argument(\"--suffix\", type=str, default=\"\",\n    help=\"sets a suffix for the resulting regex\")\n\nargs = parser.parse_args()\n\n# Return the longest prefix of all list elements. Shamelessly copied from:\n# https://stackoverflow.com/questions/6718196/determine-prefix-from-a-set-of-similar-strings\ndef commonprefix(m):\n    \"Given a list of pathnames, returns the longest common leading component\"\n    if not m: return ''\n    s1 = min(m)\n    s2 = max(m)\n    for i, c in enumerate(s1):\n        if c != s2[i]:\n            return s1[:i]\n    return s1\n\n# flatten returns a string with concatenated dictionary keys\ndef flatten(dict):\n    s = \"\"\n\n    for key in dict.keys():\n        s += key\n\n    return s\n\n# set returns a character set containing the unique characters across all strings for the given index\ndef set(strings, index, flags):\n    dict = {}\n\n    for s in strings:\n        # Continue so we don't panic\n        if index > len(s) -1:\n            continue\n        \n        dict[s[index]] = ''\n    \n    return \"[\" + flags + flatten(dict) + \"]\"\n\n# prepare converts a string for negative lookaheads emulation\ndef prepare(s, offset):\n    r = \"\"\n\n    if len(s) == 0:\n        return r\n\n    for i in range(offset, len(s)):\n        for j in range(0, i + 1):\n            if j == i:\n                r += \"[^\" + s[j] + \"]\"\n            else:\n                r += s[j]\n\n        if i != len(s) - 1:\n            r += \"|\"\n\n    return r\n\n# run runs the \ndef run():\n    strings = args.strings\n\n    r = \"\"\n    r += set(strings, 0, \"^\")\n\n    c = \"\"\n    d = {}\n\n    # Only find common string if we have more than one\n    if len(strings) > 1:\n        c = commonprefix(strings)\n        \n        # Collect all characters after the common substring from every string\n        for s in strings:\n            if len(s) > len(c) and s.startswith(c):\n                d[s[len(c)]] = ''\n\n    # Add the common string to the regex to prevent accidental matching\n    if len(c) > 0:\n        if len(c) > 1:\n            r += \"|\" +  \"(?:\" + prepare(c, 1) + \")\"\n\n        r +=  \"|\" + \"(?:\" + c + \"[^\" + flatten(d) + \"]\" + \")\"\n\n    for s in strings:\n        g = \"\"\n\n        # When the common string is > 0, offset with len(c) + 1 because we handled this earlier\n        if len(c) > 0:\n            g = prepare(s, len(c) + 1)\n        else:\n            g = prepare(s, 1)\n        \n        # Add OR boolean if necessary\n        if len(g) > 0:\n            r += \"|\"\n\n        r += g\n\n    print(args.prefix + \"(?:\" + r + \")\" + args.suffix)\n\n# Only run if script is called directly\nif __name__ == \"__main__\":\n    run()\n", "path": "util/regexp-tricks/negative-lookahead.py"}]}