 vary from a plane to another. That is, for a given square block of size, SB with non-null count (BNNC) and block one's count (B1C) the block is considers all zeros only if: -,0BNNC and p iBNNC CBBNNC   )1( (1) Also, a block is considered all one's only if: -,0BNNC and p iBNNC CB  )1( (2) ip is plane allowance percent. That is, in the lossy version encoding algorithm the switch case check  all zeros' refers to equation (1). Similarly, check of all one's refers to equation (2). Table (1) shows how much of accepted different bits for different block sizes on different percent's. Corollary(1): The allowance percent ip of 0.5 at a plane will lead to the plane encoded as only two-bit either  00' or  11'. That comes from the fact that a plane either one code is more than the second, or equal to. In both cases it will be considered unary code block. Consequently, RBS will be null. Corollary(2): The percent 0.5< ip <0.75 at a plane implies that the RBS nibbles will contain only the hex codes {3,5,6,9,A,C}. In the encoding process, blocks coded or split process until 2x2 size. At this size with that percent range one bit is allowed to have different value for block to be encoded as unary-code block. So, residual will be the case of codes equal counts. Table (1): Accepted different codes for a block size per percent 2x2 4x4 8x8 16x16 32x32 64x64 132x132 256x256 97% 0 0 1 5 20 81 327 1310 94% 0 0 3 12 51 204 819 3276 91% 0 1 5 20 81 327 1310 5242 88% 0 1 7 28 112 450 1802 7208 85% 0 2 8 35 143 573 2293 9175 82% 0 2 10 43 174 696 2785 11141 79% 0 3 12 51 204 819 3276 13107 76% 0 3 14 58 235 942 3768 15073 73% 1 4 16 66 266 1064 4259 17039 70% 1 4 18 74 296 1187 475
vary from a plane to another. That is, for a given square blockage of size, SB with non - null count (BNNC) and parry one's count (B1C) the block is considers all zero entirely if: -,0BNNC and p iBNNC CBBNNC  ) 1 (( 1) Also, a auction block is think all one's merely if: -,0BNNC and p iBNNC CB ) 1 (( 2) ip is airplane allowance percent. That is, in the lossy version encoding algorithm the switch shell check   all zeros' refers to equation (1). Similarly, check of all one's refers to equality (2). Table (1) shows how much of accepted unlike bits for different block sizes on different percentage's. Corollary(1 ): The allowance percentage ip of 0.5 at a plane will lead to the plane encode as only two - bit either   00' or   11'. That comes from the fact that a plane either one code is more than the second, or equal to. In both cases it will be considered unary code block. Consequently, RBS will be null. Corollary(2 ): The percent 0.5 < ip < 0.75 at a plane implies that the RBS nibbles will contain only the hex codes { 3,5,6,9,A, C }. In the encoding process, engine block coded or split summons until 2x2 size. At this size with that percentage stove one bit is allowed to accept different value for block to be encoded as unary - code block. therefore, residual will be the case of codes equal counts. Table (1 ): Accepted unlike codes for a block size per percent 2x2 4x4 8x8 16x16 32x32 64x64 132x132 256x256 97% 0 0 1 5 20 81 327 1310 94% 0 0 3 12 51 204 819 3276 91% 0 1 5 20 81 327 1310 5242 88% 0 1 7 28 112 450 1802 7208 85% 0 2 8 35 143 573 2293 9175 82% 0 2 10 43 174 696 2785 11141 79% 0 3 12 51 204 819 3276 13107 76% 0 3 14 58 235 942 3768 15073 73% 1 4 16 66 266 1064 4259 17039 70% 1 4 18 74 296 1187 475
 vagy from a plane to anothtr. That is, for a yuven sxuare glock of size, SB with non-null count (UNNC) and vlock one's count (B1C) thd block id considwrs ell zeros only ih: -,0BNNC akb p iGKNC CYBINC   )1( (1) Also, a nlock is cotsidered all ote'r lnly if: -,0BNNC and p iBNNC CB  )1( (2) ip if plane aplowance percegt. Tnwt ia, in the lossy version encoding alforithm the switch csse check  all zeros' referd to equation (1). Similarpy, check of all ine's refers go equation (2). Table (1) shkws how much of accepted differdnt bnts for difdeeenh block sizew on qifferent pevbent's. Cmrollaru(1): The allowancc perrent ip of 0.5 at a plane winl lead to the plage encodeg cs only two-bit either  00' or  11'. Thad coows wroj vhe fact hhav a plane ejther one cide is more than tht sqbpnd, or equal to. In bjth cases it will be considered unary cmde block. Consequently, RBS will be null. Corollaty(2): The persent 0.5< ip <0.75 at a plane implies that the RBS nibbles will zonualk onut hhe hex codes {3,5,6,9,A,C}. In the encoding process, blocha voced or split pvocess until 2x2 sizr. Wt jhis size with that 'srdent range one bit is alljwed ro have dyffetent value for block to be wncoded as uuart-code block. So, resndual will bz the vase pf codes equal counts. Tcble (1): Zccepted divferent ckaes for a block rizv pes percenu 2x2 4x4 8x8 16x16 32x32 64x64 132x132 256x256 97% 0 0 1 5 20 81 327 1310 94% 0 0 3 12 51 204 819 3276 91% 0 1 5 20 81 327 1310 5242 88% 0 1 7 28 112 450 1802 7208 85% 0 2 8 35 143 573 2293 9175 82% 0 2 10 43 174 696 2785 11141 79% 0 3 12 51 204 819 3276 13107 76% 0 3 14 58 235 942 3768 15073 73% 1 4 16 66 266 1064 4259 17039 70% 1 4 18 74 296 1187 475
vary from a plane to another. That a square block size, SB with one's (B1C) the block considers all zeros if: -,0BNNC and p iBNNC CBBNNC  )1( (1) Also, a block is considered all one's only if: -,0BNNC p iBNNC CB  )1( (2) ip is plane allowance percent. That is, the version algorithm switch case check all zeros' refers to equation (1). Similarly, check of all one's refers to (2). Table (1) shows how much of accepted bits for different block on different percent's. Corollary(1): The percent of 0.5 a will to the plane as only two-bit either 00' or 11'. That comes from the fact that a plane either one is more second, or to. both it will be code block. Consequently, RBS will be percent 0.5< ip <0.75 at a plane implies the RBS will contain only the hex codes In the encoding process, blocks coded or split until 2x2 size. At this size with that percent range one bit is allowed to value for block to encoded as unary-code So, will the of codes counts. Table (1): Accepted different codes for a block size per 2x2 4x4 8x8 16x16 32x32 64x64 132x132 256x256 97% 0 5 81 327 1310 0 0 3 12 204 3276 91% 0 1 81 1310 1 28 450 1802 7208 85% 2 8 35 143 573 9175 82% 0 2 11141 79% 0 3 12 51 204 819 13107 76% 0 3 14 58 235 3768 15073 73% 1 4 16 66 266 1064 4259 17039 70% 4 18 1187 475
 vary from a plane to another. ThAt is, for a giVen sqUarE blOcK of sIze, Sb with non-null coUNt (BNnC) and block one's count (B1C) tHe bloCk IS conSIdErs alL zeros oNLy IF: -,0bNNc aNd P iBnNc cBbNNC   )1( (1) ALso, A block iS considereD alL oNe's only if: -,0BNNc AnD p iBNNC CB  )1( (2) iP is Plane allowanCe pErcent. thAt iS, In the LosSy verSion enCOding aLgorithm tHe SWitch cASe check  ALL zEros' Refers to equation (1). SIMiLArly, check of all One's reFeRS tO EQuaTioN (2). Table (1) showS hOw mucH Of accepTEd DIFFerENt bits for diffErent block sIZes On diffErEnt PErcent'S. CoroLlARy(1): THe allowance PercEnt ip of 0.5 at A plane WIll lead TO the plaNe encoDed As oNly tWO-bIt EitHeR  00' Or  11'. THAt ComES frOm the facT tHaT a plaNe eiTHER One cOde Is moRe thaN the second, or eQuaL to. IN BotH caseS it wiLl be CoNsideRed unaRy codE bLock. ConsequentlY, RBS Will be nulL. CoRoLlaRy(2): the peRCent 0.5< ip <0.75 At a PlaNe impliEs that tHE RBs nIBBLeS will contain only thE hEX CoDes {3,5,6,9,A,C}. In tHe encoDInG pROcess, bloCkS coDed oR SPlit pRoceSS uNtil 2x2 sizE. At thiS SiZe With thaT pErcent RaNge One Bit is ALlowEd to haVe differEnt vaLUe for block to be ENcoded as unary-COdE BLoCK. So, rEsiDual will be tHe caSE of cOdes EQuAl cOUnts. TAble (1): ACcEPtED different codes for a BlOck sizE per pErcent 2x2 4x4 8x8 16x16 32x32 64x64 132x132 256X256 97% 0 0 1 5 20 81 327 1310 94% 0 0 3 12 51 204 819 3276 91% 0 1 5 20 81 327 1310 5242 88% 0 1 7 28 112 450 1802 7208 85% 0 2 8 35 143 573 2293 9175 82% 0 2 10 43 174 696 2785 11141 79% 0 3 12 51 204 819 3276 13107 76% 0 3 14 58 235 942 3768 15073 73% 1 4 16 66 266 1064 4259 17039 70% 1 4 18 74 296 1187 475
 vary from a plane to anot her. Thatis, f ora g iv en s quar e block of siz e , SB  with non-null count ( BNNC)  a n d bl o ck  one' s count (B 1 C ) t he  b loc ki sconsi der s all z eros onlyif:  - ,0BNNC andp  i BNNC CBBNN C    )1( (1) A lso , a bl oc k i s  cons ide red a ll one ' s only  if: -,0 BN N C andp  iBNNCC B    )1(  (2) ip is planea ll o wance percent.  Thatis ,  i n the  lo ssy versio nencod i ng algo r it h m the switch case c heck  all z e ros ' refe rs  to equati on (1 ). Sim ilarly, che ck o f all one 's ref e rs to e q uation(2). T abl e ( 1) s h ow show  m u cho facc e pte d differ en tbitsford i f f eren t b lock  size s on differen t p erce n t's . Cor ollar y(1) :The a llowan ce pe rc ent ip of 0.5 a t aplane wil l l ea d t othe p l ane en cod edas only  two-bi t  ei th e r  0 0' or  11'. That c om e s  f rom thefact t h at  a plane ei th eronec o de is  mor e  t han thesecond ,  o requal t o.  In bo th  ca ses  it w i ll b e cons idered u naryc ode block. Con s equently, RBS wi l l  b e  nul l.Corollary(2 ): T h e pe rcen t  0 .5< ip <0 .75 a ta  p l ane implies that th eRBS ni bbles  will contain  only theh e x  codes { 3,5, 6 ,9 , A,C}. In the e ncodi ng process ,  blockscoded  or spli t process u ntil 2x2  si ze.  At  th i s  s ize with that p erce nt  rangeone  bit is  al low edtoha ve differ ent valu efo rbl ock  to b e  encoded  a s u na ry- codeb lock.So, r esid ua lw ill  be the ca s e  ofco de s eq ual  c ounts . Ta b le(1): Ac cepted di ffe r entco de s for a  block size p er  percent 2 x2  4x 4 8x81 6 x16 32x3 2 64x64 132x132 256x256 97% 0 0  15 2081 3 27 1310 9 4%0 0 3125 1 204819 32 76 91 %0 1 5  20 8 1 32 7 1 31 0 5242 88% 0  17 2811 2 45 0 18027208 85% 0 2 8 351 43573 2293 9175  82 % 02 10  43 17 4  69 62 785 1 1141 79% 0 3 12  51 204 81 93 27 6 13107 76 %  0314 58 2 35 94237681 5073 73 % 1 4 1666 266 10 64  425 9 170 39 70% 1 4  18 74 2 96 1187 4 7 5
 vary_from a_plane to another. That_is, for_a_given square_block_of size, SB_with non-null count_(BNNC) and block one's_count (B1C) the_block_is considers all zeros only if: -,0BNNC and p iBNNC CBBNNC   )1(_(1)_Also, a_block_is_considered all one's only if:_-,0BNNC and p iBNNC CB_ )1(_(2) ip is plane allowance percent. That is,_in_the lossy version_encoding algorithm the switch case check  all zeros'_refers to equation (1). Similarly, check_of all one's_refers_to_equation (2). Table (1)_shows how much of accepted different_bits for different block sizes on_different percent's. Corollary(1): The allowance percent ip_of 0.5 at a plane will_lead to the plane encoded_as only_two-bit either  00' or_ 11'. That_comes from_the fact that_a plane either one code is_more than the_second, or equal to. In both_cases_it will be_considered_unary_code block._Consequently, RBS will_be_null. Corollary(2):_The_percent 0.5< ip <0.75 at a_plane_implies that the RBS nibbles will contain_only the hex codes_{3,5,6,9,A,C}._In the encoding process,_blocks coded or split process_until 2x2 size. At this size_with that_percent range_one bit is allowed to have different value for block to_be encoded as unary-code block. So,_residual will be the_case of_codes_equal counts. Table_(1):_Accepted different_codes for a block size per percent_2x2 4x4_8x8 16x16 32x32 64x64 132x132 256x256_97% 0 0 1_5_20 81 327 1310 94% 0_0 3 12 51 204 819_3276 91% 0 1 5_20_81_327 1310 5242 88% 0_1 7 28 112 450 1802_7208 85% 0_2 8 35 143 573 2293 9175_82%_0 2 10 43 174 696_2785_11141 79% 0 3 12 51_204_819_3276 13107 76% 0 3_14 58 235 942 3768 15073_73% 1 4 16 66 266 1064 4259 17039_70% 1 4_18 74 296 1187 475