Please reason step by step, and put your final answer within \boxed{}.
Given a triangle \(ABC\) and a point \(P\) inside it, construct a parallelogram within the triangle such that its diagonals intersect at point \(P\). (We consider only that parallelogram inscribed whose all 4 vertices lie on the perimeter of the triangle, thus none of its vertices is on the extension of any side of the triangle.)
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