_:n6667aea63ca94128b3af697fb00e08b9xb2
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"&quot;Concept:\n\nLoad life equation:\n\nFaL = Constant\n\nwhere a = 3 For ball bearing and a = 103 For roller bearing.\n\nFor 90% reliability, L = 106 cycles.\n\nLoad life in cycles is represented as \n\nL = 60 × LH × N, where L = Life in cycles, LH = Life in hour, N = RPM.\n\nCalculation:\n\nGiven:\n\nApplication factor (k) = 1.7, N = 1600 rpm, LH = 18000 hours, Fr = 6.5 kN\n\nNow, we know that\n\nFaL = Constant\n\ni.e. ({left( {frac{F}{k}} right)^{frac{{10}}{3}}} times {L_{90}} = {left( {{F_r}} right)^{frac{{10}}{3}}} times Lr;)\n\n({left( {frac{{bf{F}}}{{1.7}}} right)^{frac{{10}}{3}}} times {10^6} = {left( {6.5} right)^{frac{{10}}{3}}} times 60 times 18000 times 1600)\n\n∴ F = 103.4 kN&quot;"
<https://testbook.com/question-answer/a-radial-load-of-6-5-kn-is-applied-on-a-cylindrica--5f46722c4f90bb269fa27fe6>