title: How to order by a column greater than 0 then by date
body: <p>Lets say I have a table called Car and with the columns Age and CreationDate. </p>
  
  <p>I now want to order so that all cars that have an age greater than 0 are sorted first and then sorted by creationDate in descending order. So it doesn't matter if the cars age is 4,6,7 for example just that it is greater than 0. This would mean that basically all rows are sorted by CreationDate, except that all the cars with an age greater than 0 are sorted first. </p>
  
  <p>For example the below won't work because the cars would first be sorted by the age and ignore what the actual CreationDate is. (I don't want to reverse it and have CreationDate first either because then the cars with age > 0 wouldn't be listed first).</p>
  
  <pre><code>SELECT * FROM Car ORDER BY Age, CreationDate DESC
  </code></pre>
  
  <p>Any help or input is highly appreciated, thanks!</p>