title: Expand a NominalDiffTime by a factor
body: <p>Using the <code>time</code> library in Haskell, I have computed <code>delta :: NominalDiffTime</code> previously in my program, and I have a <code>successFactor :: Double</code>, <code>successFactor = 2.8</code>. I would want to (naively) compute
  a new <code>deltaExpanded :: NominalDiffTime</code>:</p>
  <pre><code>deltaExpanded = delta * successFactor
  </code></pre>
  <p>However, I get the error:</p>
  <pre><code>Couldn't match expected type ‘time1.9.3:Data.Time.Clock.Internal.NominalDiffTime.NominalDiffTime’ with actual type ‘Double’
  </code></pre>
  <p>Not being very good at Haskell coding yet, I would like to know what the simplest perform the computation would be.</p>