title: Java: Read array of integers from file
body: <p>Say i have a file called <code>"input.txt"</code> that has a bunch of positive integers in it:<br/></p>
  
  <pre><code>6
  5
  6
  8
  6
  2
  4
  </code></pre>
  
  <p>and so on....(one integer per line)</p>
  
  <p>I want to read this file and make it into an array. The first integer (in this case 6) tells the number of indexes or elements in the array, so 6 spots. The other numbers fill in the array starting at 0. So at index 0, the number is 5, at index 1 the number is 6, and so on. </p>
  
  <p>Can someone please show me how to read this file and make it into an array called A and return the integers in each index as n?</p>
  
  <p>this is what i have so far:</p>
  
  <pre><code>import java.io.*;
  public class inputFile {
      public static jobScheduleRecursive(int[] A, int i)
      {
          try
      {
          FileReader filereader = new FileReader("input.txt");
          BufferedReader bufferedreader = new BufferedReader(filereader);
          String line = bufferedreader.readLine();
          //While we have read in a valid line
          while (line != null) {
              //Try to parse integer from the String line
              try {
                  System.out.println(Integer.parseInt(line));
              } catch (NumberFormatException nfe) {
                  System.err.println("Failed to parse integer from line:" + line);
                  System.err.println(nfe.getMessage());
                  System.exit(1);
              }
              line = bufferedreader.readLine();
          }
      }
      catch(FileNotFoundException filenotfoundexception)
      {
          System.out.println("File not found.");
      }
      catch(IOException ioexception)
      {
          System.out.println("File input error occured!");
          ioexception.printStackTrace();
      }
      return A;
  }
  </code></pre>
  
  <p>I think i'm doing something completely wrong. please help.</p>