title: Unable to open file for playback: Invalid argument [status=120022]
body: <p>I am using pjsua python wrapper to make a sip call and play wav file.  Below is the code which tries to play the file:</p>
  
  <pre><code># Notification when call's media state has changed.
      def on_media_state(self):
          global lib
          if self.call.info().media_state == pj.MediaState.ACTIVE:
              # Connect the call to sound device
              call_slot = self.call.info().conf_slot
              lib.conf_connect(call_slot, 0)
              lib.conf_connect(0, call_slot)
              print "Media is now active"
  
              # stream wav file
          # calculate wav time
          wfile = wave.open("test.wav")
          time = (1.0 * wfile.getnframes ()) / wfile.getframerate ()
          print str(time) + "ms"
          wfile.close()
  
          # stream wav file
          player_id = pj.Lib.instance().create_player("test.wav", loop=False)
          print "Wav player id is: ", player_id
          lib.conf_connect(lib.player_get_slot(player_id), call.info().conf_slot)
  
          sleep(time)
          lib.conf_disconnect(lib.player_get_slot(player_id), call.info().conf_slot)
          lib.player_destroy(player_id)
  
          else:
              print "Media is inactive"
  </code></pre>
  
  <p>What I see in the log is below:</p>
  
  <pre><code>Media is now active
  23.3436281179ms
  08:08:55.455    pjsua_aud.c  .....Creating file player: voice_tag_for_wolfgang.wav..
  08:08:55.456    pjsua_aud.c  ......Unable to open file for playback: Invalid argument [status=120022]
  </code></pre>
  
  <p>Does anyone has any clue why it is not able to open the file?</p>