title: TypeScript: How to use `resolveJsonModule` flag without emitting `.json` files?
body: <p>I need to have following structure (previously I have had it, before updating of <code>tsconfig</code>):</p>
  
  <ul>
  <li>app (folder which includes only ts files)
  
  <ul>
  <li>...</li>
  <li>*.ts</li>
  </ul></li>
  <li>dist (output for js files as compiled ones)
  
  <ul>
  <li>...</li>
  <li>*.js</li>
  </ul></li>
  <li>data (folder for any data which is not a code)
  
  <ul>
  <li>data1.csv</li>
  <li>data2.json</li>
  <li>...</li>
  </ul></li>
  </ul>
  
  <p>Updated <code>tsconfig.json</code>:</p>
  
  <pre><code>{
    "include": [
      "app"
    ],
    "compilerOptions": {
      ...
      "outDir": "dist",
      "resolveJsonModule": true,
    }
  }
  </code></pre>
  
  <p><strong>Before:</strong> When I didn't use <code>resolveJsonModule</code> flag , all data (all <code>ts</code> files) has been compiled and moved into <code>dist</code></p>
  
  <p><strong>Now:</strong> When I'm adding <code>resolveJsonModule</code> flag, <code>dist</code> contains <code>app</code> folder where are located compiled JS files + contains <code>data</code> folder (containing json files)</p>
  
  <p><strong>Question:</strong>
  <em>How can I stay with previous logic, when json files were not being moved into output?</em></p>