title: Initializing array on the fly in constructor (Java)
body: <pre><code> public class A{
        public A(int[] a){}
   }
  
   public class B extends A{
        public B(double[] b){
             super({b.length});  //ERROR
        }
   }
  </code></pre>
  
  <p>I want to be able to compile the code above.  To clarify, I have class A and B that extends it.  Class A does not have an empty parameter constructor.  If I don't put a call to super in Class B's constructor on the first line, it will try to call super(), which doesn't exist.  But, I want to call super(int[] a) instead.  I want to do this by taking the length of a given double array and sending it as an array with length 1.  It does not let me do this because apparently you can't declare an array like that, and if I were to declare it on a separate line it would call super() first and that won't work.  </p>
  
  <p>Is there any way to declare an int[] on the fly like that?  Or are the only solution here to either make a constructor for A with no parameters or make my own function that returns an int[]?  </p>
  
  <p>(Don't ask why I want to send it as an array like that.)</p>