title: Scrapy crawl extracted links
body: <p>I need to crawl a website, and crawl every url from that site on a specific xpath
  for example.:
  I need to crawl "<a href="http://someurl.com/world/" rel="nofollow">http://someurl.com/world/</a>" which has 10 links in the container (xpath("//div[@class='pane-content']")) and i need to crawl all those 10 links and extract images from them, but the links in "<a href="http://someurl.com/world/" rel="nofollow">http://someurl.com/world/</a>" look like
  "<a href="http://someurl.com/node/xxxx" rel="nofollow">http://someurl.com/node/xxxx</a>"</p>
  
  <p>what i have till now:</p>
  
  <pre><code>import scrapy
  from scrapy.contrib.spiders import Rule, CrawlSpider
  from scrapy.contrib.linkextractors import LinkExtractor
  from imgur.items import ImgurItem
  
  class ImgurSpider(CrawlSpider):
      name = 'imgur'
      allowed_domains = ['someurl.com/']
      start_urls = ['http://someurl.com/news']
      rules = [Rule(LinkExtractor(allow=('/node/.*')), callback='parse_imgur', follow=True)]
  
      def parse_imgur(self, response):
          image = ImgurItem()
          image['title'] = response.xpath(\
              "//h1[@class='pane-content']/a/text()").extract()
          rel = response.xpath("//img/@src").extract()
          image['image_urls'] = response.xpath("//img/@src").extract()
          return image
  </code></pre>