title: Python Counter() function to count words in documents with more then one occurrence
body: <p>I am working on an NLP (Natural Language Processing) project where I used the Python Counter() function from collections library. I am getting the results in the following form:</p>
  
  <p><strong>OUTPUT</strong>:</p>
  
  <pre><code>Counter({'due': 23, 'support': 20, 'ATM': 16, 'come': 12, 'case': 11, 'Sallu': 10, 'tough,': 9, 'team': 8, 'evident': , 'likely': 6, 'rupee': 4, 'depreciated': 2, 'senior': 1, 'neutral': 1, 'told': 1, 'tour\n\nRussia’s': 1, 'Vladimir': 1, 'indeed,': 1, 'welcome,”': 1, 'player': 1, 'added': 1, 'Games,': 1, 'Russia': 1, 'arrest': 1, 'system.\nBut': 1, 'rate': 1, 'Tuesday': 1, 'February,': 1, 'idea': 1, 'ban': 1, 'data': 1, 'consecutive': 1, 'interbank': 1, 'man,': 1, 'involved': 1, 'aggressive': 1, 'took': 1, 'sure': 1, 'market': 1, 'custody': 1, 'gang.\nWithholding': 1, 'cricketer': 1})
  </code></pre>
  
  <p>The problem is, I want to extract the words having count more than 1. In other words, I am trying to get only those words whose count is greater than 1 or 2.</p>
  
  <p>I want to use the output to make a vocabulary list after reducing the words with low frequency.</p>
  
  <p><strong>PS</strong>: I have more than 100 documents to test my data with almost 2000 distinct words.</p>
  
  <p><strong>PPS</strong>: I have tried everything to get the results but unable to do so. I only need a logic and will be able to implement. </p>