title: Properly echo a bunch of CSS options using PHP?
body: <p>Consider a following function with <b>one option</b> echoed out:</p>
  
  <pre><code>function dynamic_options() {
  $getheadercolor = get_header_textcolor();
  $options_social = get_option('sandbox_theme_social_options');   
  $wrapper_background_color = get_option('wrapper_background_color');
  
  if($getheadercolor !='blank'){
  echo '&lt;style type="text/css"&gt;';
  }
  
    if($getheadercolor !='blank') {
       echo "\n"."#header a{   
       color:#$getheadercolor;
       }";     
    }//End If $getheadercolor
  
     if($getheadercolor !='blank'){
          echo "\n".'&lt;/style&gt;';
     }
  
  }// End Dynamic options
  </code></pre>
  
  <p>It outputs something like this into my header (<i>it works flawlessly and does exactly as I want</i>)</p>
  
  <pre><code>&lt;style type="text/css"&gt;
  
  #header a{
  
   color:#30409b;
  }
  &lt;/style&gt;
  </code></pre>
  
  <p>Now here is the problem: This function will not have only one option but a <b>bunch of options</b> (20-30 options). So to illustrate my point let's say that for now my function will have <b>five</b> options. So it will look like this:</p>
  
  <pre><code>function dynamic_options() {
  $getheadercolor = get_header_textcolor();
  $options_social = get_option('sandbox_theme_social_options');   
  $wrapper_background_color = get_option('wrapper_background_color');
  
  //My main "problem" is an IF Statement below because it will look like a mess
  //With 20 options or more and with all those OR inside it... 
  if($getheadercolor !='blank' || $sitecolor !='' || $textcolor !='' 
  || $backgroundcolor !='' || $menucolor !=''){
  echo '&lt;style type="text/css"&gt;';
  }
  
    if($getheadercolor !='blank') {
       echo "\n"."#header a{   
       color:#$getheadercolor;
       }";     
    }//End If $getheadercolor
  
       if($sitecolor !='blank') {
       echo "\n"."#wrapper{    
       background-color:#$sitecolor;
       }";     
    }//End If $sitecolor
  
       if($textcolor !='blank') {
       echo "\n".".entry p{    
       color:#$textcolor;
       }";     
    }//End If $textcolor
  
       if($backgroundcolor !='blank') {
       echo "\n"."body{    
       background-color:#$backgroundcolor;
       }";     
    }//End If $backgroundcolor
  
       if($menucolor !='blank') {
       echo "\n".".nav{    
       background-color:#$menucolor;
       }";     
    }//End If $menucolor
  
     //So to even close my style tag i need a bunch of those statments
     if($getheadercolor !='blank' || $sitecolor !='' || $textcolor !='' 
         || $backgroundcolor !='' || $menucolor !=''){
          echo "\n".'&lt;/style&gt;';
     }
  </code></pre>
  
  <p>So my function above <i>will work</i> but this part <br/><code>if($getheadercolor !='blank' || $sitecolor !='' || $textcolor !='' 
             || $backgroundcolor !='' || $menucolor !='')</code> just seem wrong to me. <br/>Because this IF statement will have more than <b>20</b> options I am afraid that my code will be Slow and Inefficient.<br/>My PHP Force is not strong... so my only (not ideal) solution is to simply omit those two IF statement like so:  </p>
  
  <pre><code>     function dynamic_options() {
       $getheadercolor = get_header_textcolor();
       $options_social = get_option('sandbox_theme_social_options');  
       $wrapper_background_color = get_option('wrapper_background_color');
       echo '&lt;style type="text/css"&gt;';    
  
   if($getheadercolor !='blank') {
       echo "\n"."#header a{   
       color:#$getheadercolor;
       }";     
    }//End If $getheadercolor
  
       if($sitecolor !='blank') {
       echo "\n"."#wrapper{    
       background-color:#$sitecolor;
       }";     
    }//End If $sitecolor
  
       if($textcolor !='blank') {
       echo "\n".".entry p{    
       color:#$textcolor;
       }";     
    }//End If $textcolor
  
       if($backgroundcolor !='blank') {
       echo "\n"."body{    
       background-color:#$backgroundcolor;
       }";     
    }//End If $backgroundcolor
  
       if($menucolor !='blank') {
       echo "\n".".nav{    
       background-color:#$menucolor;
       }";     
    }//End If $menucolor
  
       echo "\n".'&lt;/style&gt;';  
  }// End Dynamic options
  </code></pre>
  
  <p>Now my code <b>without</b> those IF statements <i>will work too</i> but now problem is, if there are no options my function will still echo an <b>empty</b> CSS style tag inside my header:<code>&lt;style type="text/css"&gt;&lt;/style&gt;</code> and that is something I don't want.
  <br/><br/>Can somebody give me an example or advice for making this function work better?
  <br/><br/>P.S. I am considering myself as PHP <i>noob</i> so if someone can give me a nice and clear advice or example it would be much appreciated! Thank You!!!      </p>