title: Image Orientation Of JPEG Uploaded Using ASIHTTPRequest iPhone
body: <p>I have written an app which takes a photo and uploads it to a remote database using a PHP file on that database. The problem is that when the photo is read from a website or just loaded from the link, the image is presented in landscape.
  There is a part of the app which displays this image, the orientation is correct when loaded in the app so I presume it is getting the exif data in order to do this?
  My question basically is how do I rotate either the UIImage object before its uploaded or how do I change the PHP data so it will place it in the database in the correct orientation?</p>
  
  <p>Code from app:</p>
  
  <pre><code>// Display the activity indicator 
  [myActivityIndicator startAnimating];
  //Set up variables and copy image into NSData compressed
  srandom(time(NULL));
  NSURL *url = [NSURL URLWithString:@"http://www.mydomain/test-upload.php"];
  ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];  
  NSData *compressedImageData = UIImageJPEGRepresentation(theImageView.image, 0.5f);
  
  //set the filename to a random number
  
  int randomNumber = (random() % 250000);
  NSString* fileName = [NSString stringWithFormat:@"%d.jpg", randomNumber];
  
  // Set the filename and upload
  
  [request setFile:compressedImageData withFileName:fileName andContentType:@"image/jpeg" forKey:@"photo"];
  [request setDelegate:self];
  [self Update:fileName];
  
  //Create a location manager and start it uploading (delegate : Location update)
  [request startAsynchronous];
  </code></pre>
  
  <p>The code sample wouldnt work for the PHP:</p>
  
  <pre><code>$uploaddir = 'images/';
  $file = basename($_FILES['photo']['name']);
  $uploadfile = $uploaddir . $file;
  
  if (move_uploaded_file($_FILES['photo']['tmp_name'], $uploadfile)) {
          echo "http://www.mysite.com/{$file}";
  }
  else {
  $isfile = $_FILES['photo'];
  
  if(file_exists($file)) {
  echo 'file exists';
  } else {
  echo 'File not found!';
  }
  
  echo "fail";
  echo "Name is" . $file; 
  </code></pre>