title: How can I access a row by its index using pandas itertuples() methode?
body: <p>this is my code where I need to access a certain tuple from the DataFrame df. Can you please help me with this matter as I can't find any answer regarding this issue.</p>
  <pre><code>import pandas as pd
  import openpyxl
      df_sheet_index = pd.read_excel(&quot;path/to/excel/file.xlsx&quot;)
      df = df_sheet_index.itertuples()
      for tuple in df:
          print(tuple)
  </code></pre>
  <p>This is the output</p>
  <pre><code>Pandas(Index=0, _1=nan, _2=nan, _3=nan, _4=nan, _5=nan, _6=nan, _7=nan, _8=nan, _9=nan, _10=nan, _11=nan, _12=nan, _13=nan, _14=nan, _15=nan, _16=nan, _17=nan, _18=nan, _19=nan, _20=nan, _21=nan, _22=nan)
  Pandas(Index=1, _1=nan, _2=nan, _3=nan, _4=nan, _5=nan, _6=nan, _7=nan, _8=nan, _9=nan, _10=nan, _11=nan, _12=nan, _13=nan, _14=nan, _15=nan, _16=nan, _17=nan, _18=nan, _19=nan, _20=nan, _21=nan, _22=nan)
  Pandas(Index=2, _1=nan, _2=nan, _3=nan, _4=nan, _5=nan, _6=nan, _7=nan, _8=nan, _9=nan, _10=nan, _11=nan, _12=nan, _13=nan, _14=nan, _15=nan, _16=nan, _17=nan, _18=nan, _19=nan, _20=nan, _21=nan, _22=nan)
  ...
  </code></pre>