title: Creating a thumbnail from an uploaded image
body: <p>I'm wanting to create a thumbnail from a user uploaded image so the image doesn't look squashed. But also would like a copy of the original image.. So I would like the original image to send the original image to my server and also create a thumb version and send it to my server so I can call each of them for each user that uploads their own image.</p>
  
  <p>My user table has 2 tables </p>
  
  <pre><code>`user_pic` longblob NOT NULL,
  `user_pic_small` longblob NOT NULL,
  </code></pre>
  
  <p>I'm not crash hot with the image side of coding but this is what I have so far. </p>
  
  <p>Imageupload.php</p>
  
  <pre><code>&gt; &lt;form id="myForm" action="include/media.profileimage.upload.php"
  &gt; method="POST" enctype="multipart/form-data" target="ifr1"&gt;
  &gt;                   &lt;input type = "file" name = "image_data" class = "input_text" style="width:800px;" &gt;    
  &gt;                   &lt;input type = "submit" name = "submit"   class = "btn_login" value = "Upload"&gt;
  &gt;         &lt;/form&gt;
  </code></pre>
  
  <p>media.profileimage.upload.php</p>
  
  <pre><code>if(isset($_FILES['image_data'])){
         if(is_uploaded_file($_FILES['image_data']['tmp_name'])) {
  
              // prepare the image for insertion
                  $imgData =addslashes (file_get_contents($_FILES['image_data']['tmp_name']));
  
              // get the image info..
                $size = getimagesize($_FILES['image_data']['tmp_name']);
  
  
              // our sql query
              $creator_id     =   $_SESSION['id'];
              $sql = "UPDATE users SET user_pic='".$imgData."' WHERE id=$creator_id";
              $sql2 = "INSERT INTO userphotos(photo_ownerid,photo_ispublic, photo_name, photo_caption, photo_imagedata) VALUES ($creator_id,1,'Profile Picture','Profile Picture','$imgData')";
  
              // insert the image
              if(!mysql_query($sql)) {
                  echo "Fail. It broke.";
              }else{
              $c=mysql_query($sql2);
  
                  echo "&lt;script&gt; parent.alert('Image Uploaded','',1000);&lt;/script&gt;";
              }
          }
      }
  </code></pre>
  
  <p>Would appreciate any help or guidence. Thankyou </p>