title: Count the number of letters in a small matrix that appear in a Big matrix
body: <p>C - Void method count how many letters from the small matrix that also appear in the Big matrix <strong>WITHOUT using string.h</strong> </p>
  
  <p>The <code>Count()</code> Function needs to count the letters in the small matrix that appear in the large matrix by using POINTERS.</p>
  
  <p>The result should be presented in a new Result matrix.  The Result Matrix will have the same dimensions as the Small Matrix, but each cell will be an integer count representing the number of times that the letter from the Small Matrix appears in the Large Matrix.</p>
  
  <p>I tried used pointer to a specific char in the small matrix.</p>
  
  <pre><code>void Count(char mat[ROWS][COLS], char smallMat[SIZE][SIZE]) {
      int i, j;
      int count = 0;
      for (i = 0; i &lt; SIZE; i++) {
          for (j = 0; j &lt; SIZE; j++) {
              const char stringptr = smallMat[i][j];
              if (stringptr == mat[i][j])
                  count++;
          }
  
      }
      return count;
  }
  </code></pre>
  
  <p>The count should return main.
  This example of the 2 matrices and the new matrix should be</p>
  
  <p><strong>Big Matrix</strong></p>
  
  <pre>
  P A D A Q E Q B G H R O P H C W S P B Q
  M B R P R N V S C H M U J P W C V M F D
  V W R K E V I Y K K Q Y N H N G V L B Z
  </pre>
  
  <p><strong>Small Matrix</strong></p>
  
  <pre>
  U N T E
  C P G X
  D L A B
  </pre>
  
  <p><strong>Result Matrix</strong></p>
  
  <pre>
  1 3 0 2
  3 4 2 0 
  2 1 2 4
  </pre>