title: make a java code that prints the roots of a quadratic equation
body: <p>I have posted this question before. But have made a huge edit to it. And would like to ask for help in correcting my steps since my java code is not compiling. </p>
  
  <p>write a method printRoots that given 3 terms as input, representing a,b, and c in that order prints their roots. </p>
  
  <p>We have the following given information </p>
  
  <p><em><strong></em>**If b²-4ac is a positive number, your program should print “The two roots are X and Y” where X is the larger root and Y is the smaller root</strong> </p>
  
  <p><strong>If b²-4ac <em>equals 0</em>, the program should print. “The equation has one X” where X is the only root</strong> </p>
  
  <p><strong>If b²-4ac is a negative number, the program should print.” The equation has two roots(-X1 + Y1i) and (-X2 and Y2i)<em>*</em>*</strong> </p>
  
  <p>The term can be determined based on: </p>
  
  <p>If b^2 - 4ac is a negative number, then the quadratic equation becomes: (-b+/- √C)/2a -This means the equation can be simplified to become (-b+/- √Ci)/2a where the square root is not a positive number 
  Calculate the coefficient and <strong>print that(i.e X1 is -b/2a and Y1 is sqrt(-C)/2i)</strong></p>
  
  <p>Note: Not allowed to use Scanners for this question </p>
  
  <p><strong>Is it possible for someone to review my program and tell me where I have gone wrong and do i just remove my scanners to make it a program without scanners? How do i enter a,b,c then??</strong></p>
  
  <p>Give note: you should NOT use Scanner inside this method. To test your method you can use SCanner in the main method OR you can hard code values into your code from the main method and then call the method printRoots with those inputs or ouputs. </p>
  
  <hr>
  
  <pre><code>import java.util.Scanner;//delete this part after 
  public class findingRoots {
    public static void main(String[] args)
      {
    }
      public static double printRoots (){ //should it be double here or int? 
        //read in the coefficients a,b,and c 
      Scanner reader = new Scanner(System.in);
      System.out.println("Enter the value of a");
      int a=reader.nextInt();
      System.out.println("Enter the value of b");
      int b=reader.nextInt();
      System.out.println("Enter the value of c");
      int c=reader.nextInt();        
      //now compte the discrimintat d 
       double discriminant = (Math.pow(b, 2.0)) - (4 * a * c);
       d=Math.sqrt(discriminant);
       double X,Y; //root 1 &amp; root 2, respectively
       // is the step double X,Y necessary? 
       double d = (b*b)-(4.0*a*c);
  
         if (discriminant &gt; 0.0){ 
         X = (-b + d)/(2.0 * a ); //X= root 1, which is larger 
         **//do i put int or double in front of X?** 
         Y = (-b - d)/(2.0 *a); //Y= root 2, which is the smaller root 
             String root1 = Double.toString(X)
         String root2 = Double.toString(Y)
     System.out.println("The two roots are X and Y:" + root1 + "and" + root2);
   }
   else{
     if (discriminant==0.0) 
       X = (-b + 0.0)/(2.0 * a);//repeated root
       String root2 = Double.toString(X)
       System.out.println("The equation has one root X:"  + root1);//where X is the only root 
   }
   if(discriminant &lt; 0.0){
      X1 = -b/(2*a);
      Y1 = (Math.sqrt(-C))/(2*a);
      X2 = -b/(2*a);
      Y2 = (-(Math.sqrt(-C)))/(2*a);
      String root1 = Double.toString(X1)
      String root2 = Double.toString(Y1)
      String root3 = Double.toString(X2)
      String root4 = Double.toString(Y2)
      System.out.println("The equation has two roots:" + (root1 + (root2)"i") "and" + (root3 + (root4)"i");
     // where i represents the square root of negative 1 
   }
  }
  }
  </code></pre>