title: windbg disassemble function command (uf) need some formatting
body: <p>I did a uf command in windbg after attaching notepad.exe
  Command was uf notepad!WinMain i got the following output</p>
  
  <pre><code>0:000&gt; uf notepad!WinMain
  notepad!WinMain:
  0021138d mov     edi,edi
  0021138f push    ebp
  00211390 mov     ebp,esp
  00211392 sub     esp,1Ch
  00211395 push    esi
  00211396 push    edi
  00211397 push    6
  002113c8 test    eax,eax
  002113ca jl      notepad!WinMain+0x118 (00211c93)
  
  notepad!WinMain+0x43:
  002113d0 push    ebx
  002113d1 push    dword ptr [ebp+14h]
  002113d4 push    edi
  002113d5 call    notepad!SkipProgramName (00213170)
  002113e5 je      notepad!WinMain+0x10e (00211ca9)
  
  notepad!WinMain+0x5e:
  002113eb push    esi
  002113ec push    esi
  002113ed call    dword ptr [notepad!_imp__GetCurrentProcessId (00211084)]
  </code></pre>
  
  <p>and so on.. If you notice after every jump instruction it creates a new block like </p>
  
  <pre><code>002113ca jl      notepad!WinMain+0x118 (00211c93)
  
  notepad!WinMain+0x43:
  </code></pre>
  
  <p>and at </p>
  
  <pre><code>002113e5 je      notepad!WinMain+0x10e (00211ca9)
  
  notepad!WinMain+0x5e:
  </code></pre>
  
  <p>So what i wanted to know a setting in WinDbg where i can omit the creation of the new block on every jump for a function disassembly. Why can't i get the output the way i get it with U command?</p>
  
  <p>So i am looking for an option like this</p>
  
  <pre><code>002113c8 test    eax,eax002113ca 
  jl      notepad!WinMain+0x118 (00211c93)
  **blank line omitted**
  **notepad!WinMain+0x43:** omitted**
  002113d0 push    ebx002113d1 push    dword ptr [ebp+14h]
  </code></pre>
  
  <p>Any help?</p>