title: Making a craps game in python using a counter, but it won't count past 1
body: <p>I edited this down. What testCraps(number) does is that it calls a function called quietCraps() that returns a 1 for a win and a 0 for a loss. testCraps(number) is supposed to run quietCraps() a number of times equal to (number), adding 1 to winCoutner if a 1 is returned and adding 1 to lossCounter if a 0 is returned. </p>
  
  <pre><code>def testCraps(number):
      winCounter = 0
      lossCounter = 0
      for test in range(number): 
          testGame = quietCraps(value1 = 1)
          if str(test) == "1":
              winCounter = winCounter + 1
          elif str(test) == "0":
              lossCounter = lossCounter + 1
      print("The amount of wins is " + str(winCounter))
      print("The amount of losses is " + str(lossCounter))
  </code></pre>
  
  <p>Just to clarify, a win will return a 1 and a loss will return a 0. I konw that the counter in testCraps(number) is counting, but it will only go up to 1 for both counters. For example:</p>
  
  <pre><code>testCraps(5)
  0
  1
  1 
  1
  1
  The amount of wins is 1
  The amount of losses is 1
  </code></pre>
  
  <p>I'm sure the answer is pretty simple, but I'm at a loss. Can anyone help me? If I did anything wrong with my post, I'm sorry. This is my first time asking a question here. </p>