title: Using YQL how can I select an item from a feed that contains a colon in its name?
body: <p>I'm using YQL to parse some web feeds, this one in particular.</p>
  
  <p><a href="http://query.yahooapis.com/v1/public/yql?q=SELECT%20*%20FROM%20rss%20WHERE%20url%3D&#39;http%3A%2F%2Fwww.arena.net%2Fblog%2Ffeed&#39;&amp;diagnostics=true&amp;env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys" rel="nofollow noreferrer">SELECT * FROM rss WHERE url='http://www.arena.net/blog/feed'</a></p>
  
  <p>This query returns a bunch of fields, one of which looks like</p>
  
  <pre><code>content:encoded
  </code></pre>
  
  <p>How can I select that field to filter? I want to do something like this,</p>
  
  <pre><code>SELECT title, link, pubDate, content:encoded FROM rss WHERE url='http://www.arena.net/blog/feed'
  </code></pre>
  
  <p>but that is invalid. I've tried escaping with a slash without any luck.</p>