title: Boolean Algebra Simplification of (x'y'+z)'+z+xy+wz
body: <p>How would you simplify the following? I'm having a bit of trouble with the first part with negation. How would DeMorgan’s Theorem be applied here?</p>
  
  <blockquote>
    <p>(x'y'+z)'+z+xy+wz</p>
  </blockquote>
  
  <p>Please provide answer in detail.</p>
  
  <p><strong>Update:</strong></p>
  
  <p>The complete question that I got was to prove that </p>
  
  <blockquote>
    <p>(x'y'+z)'+z+xy+wz </p>
  </blockquote>
  
  <p>equals </p>
  
  <blockquote>
    <p>x+y+z</p>
  </blockquote>