title: Print the index of the sorted list in unstable sorting technique
body: <p>I tried the following code:</p>
  <pre><code>import numpy
  s = [6,6,6,6,6]
  print(numpy.argsort(s))
  </code></pre>
  <p>Output:</p>
  <pre><code>[0 1 2 3 4]
  </code></pre>
  <p>Expected Output:
  [4 3 2 1 0]</p>
  <p>Another example sample code:</p>
  <pre><code>s = [5, 5, 2, 2, 3]
  li = []
  
  for i in range(len(s)):
      li.append([s[i], i])
  li.sort()
  sort_index = []
  
  for x in li:
      sort_index.append(x[1])
  
  print(sort_index)
  </code></pre>
  <p>Output:</p>
  <pre><code>[2, 3, 4, 0, 1]
  </code></pre>
  <p>Expected Output:</p>
  <pre><code>[3 2 4 1 0]
  </code></pre>
  <p>Could this unstable sort index return is possible in python?</p>