title: web2py: sqlform dropdown without submit and form actions
body: <p>This is a bit outside of my understanding of web2py and SQLFORMS. I have 5 separate named dropdown SQLFORMS that are accessing the same db table information. I want the user to just pick an option on the dropdown and that would be it, no submit button. When they pick an option I want another dropdown SQLFORMS to be generated to the page. </p>
  
  <p>Here is the code:</p>
  
  <pre><code>def deck():
  
  form1 = SQLFORM.factory(Field('cards', requires=IS_IN_DB(db, 'tbl_card.id', '%(name)s', orderby=db.tbl_card.id)))
  form1.process(formname='form1')
  
  form2 = SQLFORM.factory(Field('cards', requires=IS_IN_DB(db, 'tbl_card.id', '%(name)s', orderby=db.tbl_card.id)))
  form2.process(formname='form1')
  
  form3 = SQLFORM.factory(Field('cards', requires=IS_IN_DB(db, 'tbl_card.id', '%(name)s', orderby=db.tbl_card.id)))
  form3.process(formname='form1')
  
  form4 = SQLFORM.factory(Field('cards', requires=IS_IN_DB(db, 'tbl_card.id', '%(name)s', orderby=db.tbl_card.id)))
  form4.process(formname='form1')    
  
  form5 = SQLFORM.factory(Field('cards', requires=IS_IN_DB(db, 'tbl_card.id', '%(name)s', orderby=db.tbl_card.id)))
  form5.process(formname='form1')
  
  #form = SQLFORM.factory(Field('evo', requires=IS_IN_DB(db, 'tbl_evo.id', '%(evo_type)s', orderby=db.tbl_evo.id)))
  #form2.process(formname='form2')
  
  return dict(form1=form1,form2=form2,form3=form3,form4=form4,form5=form5)
  </code></pre>
  
  <p>How do I remove the submit button?</p>
  
  <p>How do I create an action or generate a dropdown SQLFORM based on the option that was picked?</p>
  
  <p>Thank you so much</p>