title: How to unzip a zip file using scala?
body: <p>Basically I need to unzip a .zip file which contains a folder called modeled which in turn contains a number of excel files. </p>
  
  <p>I have had some luck in finding code that was already written (ZipArchive) which is meant to unzip the zip file, but I cannot figure out why it throws an error message when I use it. The code for ZipArchive and the error message are listed below:</p>
  
  <pre><code>import java.io.{OutputStream, InputStream, File, FileOutputStream}
  import java.util.zip.{ZipEntry, ZipFile}
  import scala.collection.JavaConversions._
  
  object ZipArchive {
  
    val BUFSIZE = 4096
    val buffer = new Array[Byte](BUFSIZE)
  
    def unZip(source: String, targetFolder: String) = {
      val zipFile = new ZipFile(source)
  
      unzipAllFile(zipFile.entries.toList, getZipEntryInputStream(zipFile)_, new File(targetFolder))
    }
  
    def getZipEntryInputStream(zipFile: ZipFile)(entry: ZipEntry) = zipFile.getInputStream(entry)
  
    def unzipAllFile(entryList: List[ZipEntry], inputGetter: (ZipEntry) =&gt; InputStream, targetFolder: File): Boolean = {
  
      entryList match {
        case entry :: entries =&gt;
  
          if (entry.isDirectory)
            new File(targetFolder, entry.getName).mkdirs
          else
            saveFile(inputGetter(entry), new FileOutputStream(new File(targetFolder, entry.getName)))
  
          unzipAllFile(entries, inputGetter, targetFolder)
        case _ =&gt;
          true
      }
    }
  
    def saveFile(fis: InputStream, fos: OutputStream) = {
      writeToFile(bufferReader(fis)_, fos)
      fis.close
      fos.close
    }
  
    def bufferReader(fis: InputStream)(buffer: Array[Byte]) = (fis.read(buffer), buffer)
  
    def writeToFile(reader: (Array[Byte]) =&gt; Tuple2[Int, Array[Byte]], fos: OutputStream): Boolean = {
      val (length, data) = reader(buffer)
      if (length &gt;= 0) {
        fos.write(data, 0, length)
        writeToFile(reader, fos)
      } else
        true
    }
  }
  </code></pre>
  
  <p>Error Message:</p>
  
  <pre><code>java.io.FileNotFoundException: src/test/resources/oepTemp/modeled/EQ_US_2_NULL_('CA')_ALL_ELT_IL_EQ_US.xlsx (No such file or directory), took 6.406 sec
  [error]     at java.io.FileOutputStream.open(Native Method)
  [error]     at java.io.FileOutputStream.&lt;init&gt;(FileOutputStream.java:221)
  [error]     at java.io.FileOutputStream.&lt;init&gt;(FileOutputStream.java:171)
  [error]     at com.contract.testing.ZipArchive$.unzipAllFile(ZipArchive.scala:28)
  [error]     at com.contract.testing.ZipArchive$.unZip(ZipArchive.scala:15)
  [error]     at com.contract.testing.OepStepDefinitions$$anonfun$1.apply$mcZ$sp(OepStepDefinitions.scala:175)
  [error]     at com.contract.testing.OepStepDefinitions$$anonfun$1.apply(OepStepDefinitions.scala:150)
  [error]     at com.contract.testing.OepStepDefinitions$$anonfun$1.apply(OepStepDefinitions.scala:150)
  [error]     at cucumber.api.scala.ScalaDsl$StepBody$$anonfun$apply$1.applyOrElse(ScalaDsl.scala:61)
  [error]     at cucumber.api.scala.ScalaDsl$StepBody$$anonfun$apply$1.applyOrElse(ScalaDsl.scala:61)
  [error]     at scala.runtime.AbstractPartialFunction.apply(AbstractPartialFunction.scala:36)
  [error]     at cucumber.runtime.scala.ScalaStepDefinition.execute(ScalaStepDefinition.scala:71)
  [error]     at cucumber.runtime.StepDefinitionMatch.runStep(StepDefinitionMatch.java:37)
  [error]     at cucumber.runtime.Runtime.runStep(Runtime.java:298)
  [error]     at cucumber.runtime.model.StepContainer.runStep(StepContainer.java:44)
  [error]     at cucumber.runtime.model.StepContainer.runSteps(StepContainer.java:39)
  [error]     at cucumber.runtime.model.CucumberScenario.run(CucumberScenario.java:48)
  [error]     at cucumber.runtime.junit.ExecutionUnitRunner.run(ExecutionUnitRunner.java:91)
  [error]     at cucumber.runtime.junit.FeatureRunner.runChild(FeatureRunner.java:63)
  [error]     at cucumber.runtime.junit.FeatureRunner.runChild(FeatureRunner.java:18)
  [error]     ...
  </code></pre>
  
  <p>So based on the error message it looks like it's trying to find the exported excel file? This part completely throws me off. Any help would be greatly appreciated.
  I've added below how I'm calling the method, perhaps I'm doing something silly. Also I'm up for using a different way to extract my zip file if you can recommend one.</p>
  
  <pre><code>val tempDirectoryDir = "src/test/resources/oepTemp/"
  ZipArchive.unZip(tempDirectoryDir + "Sub Region Input - Output.zip", tempDirectoryDir)
  </code></pre>