title: IV of first 16 bytes gets remove from decrypted string? C#/Python3
body: <p>I was wondering why the first 16 bytes of all my strings being encrypted, then when being decrypted are missing and how to fix this if it is possible. I am encrypting like so in c#</p>
  <pre class="lang-cs prettyprint-override"><code>        public static string EncryptString(string b_key, string plainText)  
          {  
              byte[] iv = new byte[16];  
              byte[] array;  
    
              using (Aes aes = Aes.Create())  
              {  
                  aes.Key = Convert.FromBase64String(b_key);  
                  aes.IV = iv;  
    
                  ICryptoTransform encryptor = aes.CreateEncryptor(aes.Key, aes.IV);  
    
                  using (MemoryStream memoryStream = new MemoryStream())  
                  {  
                      using (CryptoStream cryptoStream = new CryptoStream((Stream)memoryStream, encryptor, CryptoStreamMode.Write))  
                      {  
                          using (StreamWriter streamWriter = new StreamWriter((Stream)cryptoStream))  
                          {  
                              streamWriter.Write(plainText);
                          }  
    
                          array = memoryStream.ToArray();  
                      }  
                  }  
              }  
    
              return Convert.ToBase64String(array);  
          }  
  </code></pre>
  <p>and decrypting in python3 like so</p>
  <pre class="lang-py prettyprint-override"><code>            enc = base64.b64decode(self.text)
              iv = enc[:16]
              cipher = AES.new(self.key, AES.MODE_CBC, iv)
              plain_text = cipher.decrypt(enc[16:])
              plain_text = self.dePKCS7_padding(plain_text)
              return plain_text
  </code></pre>
  <p>Is readding the first 16 bytes possible? or must be used for encryption. I also want it to crypto safe but the first 16 bytes are kind of important is this possible? anyway to get around this in either c# or python3?</p>