title: Regex - get group 1 as "full match"/group 0
body: <p>Given the following examples, I want to get the email address</p>
  
  <pre><code>Eg. 1: some standard text.   Bugs Bunny bugs@gmail.com 0411111111 more standard text 
  Eg. 2: some standard text.   Bugs The Bunny bugs@gmail.com 0411111111 more standard text
  Eg. 3: some standard text.   Bugs-Bunny bugs.bunny@gmail.com 0411111111 more standard text
  Eg. 4: some standard text.   Bugs bugs.bunny@gmail.com +6141 111 111 more standard text
  Eg. 5: some standard text.   Bugs o'Bunny bugs@gmail.com 0411111111 more standard text 
  </code></pre>
  
  <p>This will do it: <code>(?&lt;=some standard text.   )(?:.*?)([^\s]+@[^\s]+)</code> <a href="https://regex101.com/r/A29hjE/9" rel="nofollow noreferrer">https://regex101.com/r/A29hjE/9</a></p>
  
  <p>But the email address is in group 1. I need it to be group 0 or the full match because this regex will be created dynamically by some code in which all other regex's produce their findings as the full match.</p>
  
  <p>I don't know enough about groups, but I know I need the first email address after the <code>some standard text.</code> bit and, like I said, it need's to be the full match.</p>