title: Creating lots of dictionaries from a list of names
body: <p>I am making a times table/ division game where I have created dictionaries for each times table and division (up to 12) made up of the question as the key and answer as the value. That is 24 dictionaries! There is surely a better way of doing this than what I have done, perhaps creating a for loop.</p>
  
  <p>I have managed to make each times table/ division dictionary using the following loop code (24 times; 12 for the multiple tables and 12 for the division equivalents) I have included an example of a multiple dictionary as well as a division one.</p>
  
  <pre><code>eleven_division = {}
  for i in range (0,13):
      division_factor = 11 
      answer = i * division_factor
      eleven_division ['{} / {} ='.format(answer,division_factor)] = i
  
  six_times = {}
  for i in range (0,13):
      multiple = 6
      answer = i * multiple
      six_times ['{} x {} ='.format(i,multiple)] = answer
  </code></pre>
  
  <p>I would like to create all the dictionaries using nested for loops, but have each dictionary named in the following way: two_times, three_times, four_times. However, I can figure out a way to do this. </p>
  
  <p>I know I can do this to print out all the division tables.</p>
  
  <pre><code>for x in range (1,13):
      division_factor = x
      for i in range (0,13):
          answer = i * division_factor
          print ('%s / %s = %s' %(answer, x, i))
  </code></pre>
  
  <p>I now need to create a new dictionary every time is goes through the loop so I thought the following might do it, but no! </p>
  
  <pre><code>    dicts =['one division', 'two division','three division','four division', 'five division', 'six division', 'seven division', 'eight division', 'nine division', 'ten division', 'eleven division', 'twelve division']
  for f in dicts:
      f = {} 
      for x in range (1,13):
          division_factor = x
          for i in range (0,13):
              answer = i * division_factor
              f ['{} x {} ='.format(answer,x)] = i
  
  print (one division) #THIS IS THE BIT I WANT WORKING!
  </code></pre>
  
  <p>I hope I have made my issue clear enough for you.</p>
  
  <p>TIA!</p>