title: Find .nextsibling with Beautifulsoup4
body: <p>I am trying to get (some) contents of a table from an URL.
  So far I have managed to get two desired contents of the page, but there is a third one (third column) that I would like to get only its text. The problem is, the underlying link exists elsewhere on the page (with different text) and if I want to load the table into an SQL database, the contents of the third colum won't match the first two columns.</p>
  
  <pre><code>import urllib2
  from bs4 import BeautifulSoup4
  startURL = "http://some.url/website.html"
  page = urllib2.urlopen(startURL).read()
  soup = BeautifulSoup(page, "html.parser")
  for links in soup.findAll("a"):
      if "href" in links.attrs:
          www = links.attrs.values()
          if not "https://" in www[0]:  # to exclude all non-relative links, e.g. external links
              if "view/" in www[0]: # To get only my desired links of column 1
                  link_of_column1 = www[0]   # this is now my wanted link
  </code></pre>
  
  <p>Okay, so with this code I can get the second column. Where and how would I have to apply the .nextsibling() function, to get the next link in the next (3rd) column?</p>
  
  <p>Edit:
  As I have been asked: The URL is <a href="https://myip.ms/browse/web_hosting/World_Web_Hosting_Global_Statistics.html" rel="nofollow noreferrer">https://myip.ms/browse/web_hosting/World_Web_Hosting_Global_Statistics.html</a> and I want to get the contents from Column 2 and 3, which is "Hosting Company" (link-text and link) and "Country" (only the text).</p>
  
  <p>Edit2:
  Another thing I forgot...how can I extract the information that its <code>137,157 records</code>? </p>