title: Compiling a kernel - no bzImage/vmlinuz produced
body: <p>I'm trying to compile a kernel (altered version of 2.6.32.9, found here <a href="https://github.com/rabeeh/linux-2.6.32.9" rel="nofollow">https://github.com/rabeeh/linux-2.6.32.9</a>). I am doing the compilation on a emulated ARM system (qemu) (yes, I should probably cross-compile, but that's a different topic) running Ubuntu Core (https://wiki.ubuntu.com/Core) and the kernel (vmlinuz) from Ubuntu 11.04 (downloaded from <a href="http://ports.ubuntu.com/ubuntu-ports/dists/natty/main/installer-armel/current/images/versatile/netboot/vmlinuz" rel="nofollow">http://ports.ubuntu.com/ubuntu-ports/dists/natty/main/installer-armel/current/images/versatile/netboot/vmlinuz</a>).</p>
  
  <p>After running <code>make bzImage</code>, I look in the <code>arch/arm/boot</code> folder, and find only a file called zImage. I tried using this zImage instead of the vmlinuz I downloaded from ubuntu.com in qemu, but that doesn't work, just shows a black screen. I guess zImage is not the same as bzImage, which is what I think vmlinuz (judging from different articles on the internet) is.</p>
  
  <p>So, a few questions:</p>
  
  <ol>
  <li>Why doesn't <code>make bzImage</code> produce a bzImage/vmlinuz?</li>
  <li>Can I convert a vmlinux to a vmlinuz using for example mkimage (there are lots of guides on the opposite...)?</li>
  </ol>
  
  <p>Thanks</p>