title: React Native - How to Application X open Application Y if Application Y has been installed
body: <p>I want My Application (say Application X) want to open Application Y, if Application Y installed. And work in Android and iOS (open App Store / Play store if Application Y not installed)</p>
  
  <p>What i have done :</p>
  
  <pre><code>Linking.openURL(applicationStoreURL);
  </code></pre>
  
  <blockquote>
    <p>The code above success open Play Store/App Store of Application Y, but
    actually the application Y has been installed so i want to direct open
    to Application Y from Application X.</p>
  </blockquote>