title: [Duntemann's Book 3rd Edition]. How could 16-bit 8086 address 16 times as much memory as 8080?
body: <p>Duntemann says <strong>8086 could address 16 times as much memory as 8080</strong> and has gone on to elaborate upon this as <strong>16 * 64K = 1MB</strong>. So I am assuming 16 bits at a time (16-bit processor) * 64K because 16 address lines (2^16). But, by that logic for calculation shouldn't 8080 (8-bit processor) also having 16 address lines have been able to address 8 * 64K = 0.5MB?</p>
  
  <p><strong>shouldn't the 8086 then be able to address twice as much as 8080?</strong></p>
  
  <p><img src="https://i.stack.imgur.com/hBOnn.png" alt="kindly note highlighted sentence"></p>