title: How to name the list of the group_split output in dplyr
body: <p>I have the following process which uses <a href="https://dplyr.tidyverse.org/reference/group_split.html" rel="noreferrer">group_split of dplyr</a>:</p>
  
  <pre><code>library(tidyverse)
  set.seed(1)
  iris %&gt;% sample_n(size = 5) %&gt;% 
      group_by(Species) %&gt;% 
      group_split()
  </code></pre>
  
  <p>The result is: </p>
  
  <pre><code>[[1]]
  # A tibble: 2 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;  
  1          5           3.5          1.6         0.6 setosa 
  2          5.1         3.8          1.5         0.3 setosa 
  
  [[2]]
  # A tibble: 2 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species   
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;     
  1          5.9         3            4.2         1.5 versicolor
  2          6.2         2.2          4.5         1.5 versicolor
  
  [[3]]
  # A tibble: 1 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species  
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;    
  1          6.2         3.4          5.4         2.3 virginica
  </code></pre>
  
  <p>What I want to achieve is to name this list by grouped name (i.e. Species).
  Yielding this (done by hand):</p>
  
  <pre><code>$setosa
  # A tibble: 2 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;  
  1          5           3.5          1.6         0.6 setosa 
  2          5.1         3.8          1.5         0.3 setosa 
  
  $versicolor
  # A tibble: 2 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species   
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;     
  1          5.9         3            4.2         1.5 versicolor
  2          6.2         2.2          4.5         1.5 versicolor
  
  $virginica
  # A tibble: 1 x 5
    Sepal.Length Sepal.Width Petal.Length Petal.Width Species  
           &lt;dbl&gt;       &lt;dbl&gt;        &lt;dbl&gt;       &lt;dbl&gt; &lt;fct&gt;    
  1          6.2         3.4          5.4         2.3 virginica
  </code></pre>
  
  <p>How can I achieve that?</p>
  
  <p><strong>Update</strong></p>
  
  <p>I tried this new data, where the naming now is called <code>Cluster</code> :</p>
  
  <pre><code>df &lt;- structure(list(Cluster = c("Cluster9", "Cluster11", "Cluster1", 
  "Cluster9", "Cluster6", "Cluster12", "Cluster9", "Cluster11", 
  "Cluster8", "Cluster8"), gene_name = c("Tbc1d8", "Vimp", "Grhpr", 
  "H1f0", "Zfp398", "Pikfyve", "Ankrd13a", "Fgfr1op2", "Golga7", 
  "Lars2"), p_value = c(3.46629097620496e-47, 3.16837338947245e-62, 
  1.55108439059684e-06, 9.46078511685542e-131, 0.000354049720507017, 
  0.0146807415917158, 1.42799750295289e-38, 2.0697825959399e-08, 
  4.13777221466668e-06, 3.92889640704683e-184), morans_test_statistic = c(14.3797687352223, 
  16.6057085487911, 4.66393667525872, 24.301453902967, 3.38642377758137, 
  2.17859882998961, 12.9350063459509, 5.48479186018979, 4.4579286289179, 
  28.9144540271157), morans_I = c(0.0814728893885783, 0.0947505609609695, 
  0.0260671534007409, 0.138921824574569, 0.018764800166045, 0.0119813199210325, 
  0.0736554862590782, 0.0309849638728409, 0.0250591347318986, 0.165310420808725
  ), q_value = c(1.57917584337356e-46, 1.62106594498462e-61, 3.43312171446844e-06, 
  6.99503520654745e-130, 0.000683559649593623, 0.0245476826213791, 
  5.96116678335584e-38, 4.97603701391971e-08, 8.9649490080526e-06, 
  3.48152096326702e-183)), row.names = c(NA, -10L), class = c("tbl_df", 
  "tbl", "data.frame"))
  </code></pre>
  
  <p>With Ronak Shah's approach I get inconsistent result:</p>
  
  <pre><code>df %&gt;% group_split(Cluster) %&gt;% setNames(unique(df$Cluster))
  $Cluster9
  # A tibble: 1 x 6
    Cluster  gene_name    p_value morans_test_statistic morans_I    q_value
    &lt;chr&gt;    &lt;chr&gt;          &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;      &lt;dbl&gt;
  1 Cluster1 Grhpr     0.00000155                  4.66   0.0261 0.00000343
  
  $Cluster11
  # A tibble: 2 x 6
    Cluster   gene_name  p_value morans_test_statistic morans_I  q_value
    &lt;chr&gt;     &lt;chr&gt;        &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;    &lt;dbl&gt;
  1 Cluster11 Vimp      3.17e-62                 16.6    0.0948 1.62e-61
  2 Cluster11 Fgfr1op2  2.07e- 8                  5.48   0.0310 4.98e- 8
  
  $Cluster1
  # A tibble: 1 x 6
    Cluster   gene_name p_value morans_test_statistic morans_I q_value
    &lt;chr&gt;     &lt;chr&gt;       &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;   &lt;dbl&gt;
  1 Cluster12 Pikfyve    0.0147                  2.18   0.0120  0.0245
  
  $Cluster6
  # A tibble: 1 x 6
    Cluster  gene_name  p_value morans_test_statistic morans_I  q_value
    &lt;chr&gt;    &lt;chr&gt;        &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;    &lt;dbl&gt;
  1 Cluster6 Zfp398    0.000354                  3.39   0.0188 0.000684
  
  $Cluster12
  # A tibble: 2 x 6
    Cluster  gene_name   p_value morans_test_statistic morans_I   q_value
    &lt;chr&gt;    &lt;chr&gt;         &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;     &lt;dbl&gt;
  1 Cluster8 Golga7    4.14e-  6                  4.46   0.0251 8.96e-  6
  2 Cluster8 Lars2     3.93e-184                 28.9    0.165  3.48e-183
  
  $Cluster8
  # A tibble: 3 x 6
    Cluster  gene_name   p_value morans_test_statistic morans_I   q_value
    &lt;chr&gt;    &lt;chr&gt;         &lt;dbl&gt;                 &lt;dbl&gt;    &lt;dbl&gt;     &lt;dbl&gt;
  1 Cluster9 Tbc1d8    3.47e- 47                  14.4   0.0815 1.58e- 46
  2 Cluster9 H1f0      9.46e-131                  24.3   0.139  7.00e-130
  3 Cluster9 Ankrd13a  1.43e- 38                  12.9   0.0737 5.96e- 38
  </code></pre>
  
  <p>Note that <code>$Cluster9</code> has <code>Cluster1</code> in it.</p>
  
  <p>Please advice how to go about this?</p>