title: How to display full docblocks for inherited methods in PhpDocumentor?
body: <p>I currently have code where there is an abstract parent class that defines some concrete methods, and the children classes extend this parent class, and will use the concrete methods.  For example:</p>
  
  <pre><code>&lt;?php
  
  abstract class abstract_class {
      /**
      *   I document foo.
      */
      public function foo() {
          echo "I am the foo function!";
      }
  }
  
  class child_class {
      /**
      *   I document bar.
      */
      public function bar() {
          echo "I am the bar function!";
      }
  }
  
  ?&gt;
  </code></pre>
  
  <p>In my documentation for child_class, I see my bar() function well documented, both in the Method summary and verbose description of the method...but my foo() function, which was inherited, is only stated to be inherited and I need to follow a link to see its full documentation, and even just see that it is callable by this function.  An example of what I see is shown in the image <a href="https://imgur.com/K6maD" rel="nofollow noreferrer">here</a>. (I can't put the image here because I am a new user...)</p>
  
  <p>According to the <a href="http://manual.phpdoc.org/HTMLSmartyConverter/HandS/phpDocumentor/tutorial_elements.pkg.html" rel="nofollow noreferrer">PhpDocumentors documentation</a> I should be able to see the Docblock somehow, but I don't know how to do so:</p>
  
  <blockquote>
    <p>New in version 1.2.0, DocBlock's are inherited by child classes, variables, and methods.</p>
  </blockquote>
  
  <p>I looked all over for a switch or something to run when calling phpdoc from a command-line but haven't found anything.</p>
  
  <p>How can I display the information I want, in the way that I want?</p>