title: Open link from cell in firefox
body: <p>I am trying to make vba open in Firefox a link that i have in a cell, the link is updating based on specific rows. This is what i have but i want to replace youtube with the link i have in a cell. Thank you in advance.</p>
  <pre><code>Sub mfOpen()
  
  Shell &quot;C:\Program Files\Mozilla Firefox\firefox.exe&quot; &amp; &quot; http://www.youtube.com&quot;
  
  End Sub
  </code></pre>