title: Playing Vimeo video using HCVimeoVideoExtractor, can't get video URL with specific quality
body: <p>I'm using this lib <a href="https://github.com/superm0/HCVimeoVideoExtractor" rel="nofollow noreferrer">https://github.com/superm0/HCVimeoVideoExtractor</a> to play vimeo url. It works fine but changing the quality doesn't return videoURL for some videos. I'm talking about this line </p>
  
  <pre><code>if let videoURL = vid.videoURL[.Quality1080p] 
  </code></pre>
  
  <p>I'm not able to understand why it doesn't return videoURL for a video when I pass Quality1080p?
  How to fix it? Is there something wrong with my videos? Do I need to convert all of videos to same quality and then upload on Vimeo?</p>
  
  <p>Following is my code:</p>
  
  <pre><code>import UIKit
  import HCVimeoVideoExtractor
  import AVKit
  
  class ViewController: UIViewController {
  
      override func viewDidLoad() {
          super.viewDidLoad()
  
      }
  
      @IBAction func playClicked(_ sender: UIButton) {
  
          guard let url = URL(string: "https://vimeo.com/1234567") else {
              print("Error url nill")
              return
          }
  
          HCVimeoVideoExtractor.fetchVideoURLFrom(url: url, completion: { ( video:HCVimeoVideo?, error:Error?) -&gt; Void in
              if let err = error {
                 print("Error = \(err.localizedDescription)")
                 return
              }
  
              guard let vid = video else {
                  print("Invalid video object")
                  return
              }
  
              print("Title = \(vid.title), url = \(vid.videoURL), thumbnail = \(vid.thumbnailURL)")
  
              if let videoURL = vid.videoURL[.Quality1080p] {
  
                  let player = AVPlayer(url: videoURL)
  
                  DispatchQueue.main.async {
                      let playerController = AVPlayerViewController()
                      playerController.player = player
                      self.present(playerController, animated: true) {
                          player.play()
                      }
                  }
              } else {
                  print("Error: videoURL not found")
              }
          })
      }
  }
  </code></pre>