title: Default node type for Node<T>
body: <p>I am starting to investigate the use of Neo4j using the neo4client API.
  I have created a basic database, and can query it using the web client. I am now trying to build a sample C# interface. I am having some problems with index lookups. My database consists of nodes with two properties: conceptID and fullySpecifiedName. Auto-indexing is enabled, and both node properties are listed in the node_keys_indexable property of neo4j.properties.</p>
  
  <p>I keep getting IntelliSense errors in my C# when using the Node class. It appears to be defined as <code>Node&lt;T&gt;</code>, but I don't know what to supply as the value of the type. Consider this example from this forum...</p>
  
  <pre><code>var result = _graphClient
  .Cypher
  .Start(new
  {
      n = Node.ByIndexLookup("index_name", "key_name", "Key_value")
  })
  .Return((n) =&gt; new
  {
      N = n.Node&lt;Item&gt;()
  })
  .Results
  .Single();
  
  var n = result.N;
  </code></pre>
  
  <p>Where does the "Item" in <code>Node&lt;Item&gt;</code> come from?
  I have deduced that the index name I should use is <code>node_auto_index</code>, but I can't figure out a default node type.</p>