title: How to change the directory to program files using Powershell?
body: <p>I would like to open a C:\Program Files\R\R-3.2.0\bin\Rscript.exe. For that I am trying to change the directory. I figured that the error is in opening Program files. Following is the code </p>
  
  <pre><code>cd Program Files\R\R-3.2.0\bin
  
  Error: A positional parameter cannot be found that accepts argument Files
  </code></pre>