title: the number of ways of selecting numbers, that multiplied together, result in the given number
body: <p>I have a programming problem which looks like this.
  Returns the number of ways of selecting numbers in the first
  argument that multiplied together, result in the second
  argument.</p>
  <p>Recall that the product of an empty sequence of numbers equals 1.</p>
  <p>You can assume that the function is called with a list of
  integers as first argument, and an integer as second argument.
  ​
  ​Code structure with test case look like this.</p>
  <pre><code>def f(numbers, desired_product):
      '''
      &gt;&gt;&gt; f([2], 3)
      0
      &gt;&gt;&gt; f([2, 3, 5], 11)
      0
      &gt;&gt;&gt; f([1], 1)
      2
      &gt;&gt;&gt; f([1, 1, 1], 1)
      8
      &gt;&gt;&gt; f([2, 3], 2)
      1
      &gt;&gt;&gt; f([1, 2, 3], 2)
      2
      &gt;&gt;&gt; f([1, 2, 3], 6)
      2
      &gt;&gt;&gt; f([3, 8, 7, 3, 7, 3, 7, 8, 5], 3 * 3 * 7)
      9
      &gt;&gt;&gt; f([2, 5, 7, 11] * 4, 2 * 5 * 7)
      64
      &gt;&gt;&gt; f([1, 2, 5, 7, 11] * 4, 2 * 5 * 7)
      1024
      &gt;&gt;&gt; f(list(range(1, 10)), 40)
      4
      '''
      return -1
      # REPLACE THE RETURN STATEMENT ABOBVE WITH YOUR CODE
  ​
  ​
  if __name__ == '__main__':
      import doctest
      doctest.testmod()
  </code></pre>
  <p>I understand the problem but didn't understand the</p>
  <pre><code>&gt;&gt;&gt; f([1], 1)
      
  
  2
  </code></pre>
  <p>test case. Can anyone help me understand the test case and provide me the solution?</p>