title: Is there any way to not load an element with knockout conditionals?
body: <p>I have a list of items that can be one of two types - depending on the type, I need to use a different styling/layout.  What I'm doing right now is iterating over all items and displaying both "templates" for each one, but displaying only one template per item depending on how the type() evaluates.  This seems inelegant because I really only need one template per item - half of the markup on the page will never be visible.  </p>
  
  <p>Is there any way I can only load the markup I need for these items, without breaking them into two different arrays?  </p>