title: bash: how to execute function instead of command with same name
body: <p>I'm about to learn bash scripting and wrote a little script like this for testing purposes:</p>
  
  <pre><code>#!/bin/bash
  function time {
      echo $(date)
  }
  
  time
  </code></pre>
  
  <p>However the function doesn't get executed, instead the command <code>time</code> is running.</p>
  
  <p>So what do I have to do to execute the function instead?</p>
  
  <p>I'm running bash 4.2.45</p>