title: awk for multiple patterns
body: <p>My file looks like:</p>
  <pre><code>L   0   256 *   *   *   *   *
  H   0   307 100.0   +   0   0
  S   30  351 *   *   *   *   *
  D   8   27  *   *   *   *   99.3    
  C   11  1   *   *   *   *   *   
  </code></pre>
  <p>for my script I would like to start by awk print $0  for certain lines using $1</p>
  <p>Such as</p>
  <pre><code>awk '{if ($1!=&quot;C&quot;) {print $0}  else if ($1!=&quot;D&quot;) {print $0}}'
  </code></pre>
  <p>But, there has to be a way to combine &quot;C&quot; and &quot;D&quot; into one IF statement... right?</p>
  <p>For example if I want to search for == L,H,S   ie... NOT C or D how would I right this?</p>