title: Python3: search csv file for string and return row and column
body: <p>I have a large csv file, and I am trying to search it for a string. and return the row and column.
  The code that I have so far will always return 'nope' for anything that I enter.</p>
  
  <p>The code that I have so far:</p>
  
  <pre><code>def search_cell(string):
      with open('aanmaningen.chr', 'r') as f:
          reader = csv.reader(f)
          for row in reader:
              if string in row:
                  print(row[0])
                  return row[0]
              else:
                  print('nope')
                  return 'nope'
  </code></pre>
  
  <p>For example:</p>
  
  <p>When the csv file contains the string 'vve' in row 20, column 9, I want to be able to enter the string 'vve' and get the row and column number back.</p>
  
  <p>Note: because the way the program i'm using exports data, it saves as a character  seperated file (.chr), using the seperator and delimiter ';' essentially a .csv file with a non-standard seperator and delimiter</p>