title: Turn a large list into a rowwise dataframe
body: <p>I convert a large list to a dataframe using the structure command (I read the related posts in SO):</p>
  
  <pre><code>l &lt;- list()
  l[[1]]&lt;-c("2048","0","25","0","453826","65101","1503497087","1503497031","4_1R")     
  
  l[[2]]&lt;-c("406","0","26","0","453826","65101","1503497087","1503497055","4_1R")      
  
  l[[3]]&lt;-c("407","0","27","0","453826","65101","1503497087","1503497083","4_1R")     
  
  
  n &lt;- length(l[[1]])
  DF &lt;- structure(l, row.names = c(NA, -n), class = "data.frame")
  print(DF)
  </code></pre>
  
  <p>But the rows are arranged like columns. I could use transpose the dataframe:</p>
  
  <pre><code>library(data.table)
  DF &lt;- transpose(DF)
  </code></pre>
  
  <p>Which is fine, </p>
  
  <p>however is there any option in "structure" to indicate I want a row-binding &amp; row-ordered dataframe?</p>