title: Skype4COM: to identify the incoming call event and assosciate it with one of the active skype clients on my machine
body: <p><strong>My Project:</strong>
  I need to build up a Skype Listener server for one of my project. It will:
   1. Host 8 different dummy Skype accounts.
   2. All accounts will already have associated:
    (a) Already Recorded audio files 
    (b) Pre-recorded video files .
  3. A Skype call to any of these Skype accounts will automatically initiate the pre-recorded audio or the video depending upon the call type.</p>
  
  <p><strong>My Reasearch:</strong>
   I have researched in Skype Developer forum but I could not find any URI or API to accept the incoming programatically. However I am able to catch the Incoming call event and respond to that using Skype4COM.</p>
  
  <p><a href="http://devforum.skype.com/t5/Desktop-API/Event-for-incoming-call/td-p/9174" rel="nofollow">http://devforum.skype.com/t5/Desktop-API/Event-for-incoming-call/td-p/9174</a></p>
  
  <p>Now As I have to implement the same in 8 differenet skype account running on same machine using secondary method provided by SKype. But while using the same, I am unable to identify that when an incoming call event occurs, which is the account which is receiving the call. So whicheve be the account it opens the same pre-recorded video and not the one assosciated with the skype account.
  Hope I am clear in explaining it.</p>
  
  <p><strong>My Problem</strong>:
  1.I am looking for a method (using SkypeKIT or Skype4COM) to identify the incoming call event and assosciate it with one of the active skype clients on my machine.
  2. To play the pre-recorded video and audio, I am currently changing the viedo source of the skype client on my machine. Now Since all the Skype accounts are running on the same client so I am unable to attach different video sources to different accounts. Is there a way to run multiple skype instance on same machine?
  Any suggestion/immediate help on how to accomplish these using SkypeKIT and SKype4COM or any other way will be highly appreciated.</p>
  
  <p>P.S: I have re-posted this question with adding my research work.</p>
  
  <p>Regards
  Raj</p>