title: Escape backquote in a double-quoted string in shell
body: <p>For the command: /usr/bin/sh -c "ls 1`" (a backquote after 1).</p>
  
  <p>How to make it run successfully? Adding a backslash before "`" does not work. 
  ` is a special char as we know, and I tried surrounding it with single quote too (/usr/bin/sh -c "ls 1'`'"), but that doesn't work either.</p>
  
  <p>The error always are: </p>
  
  <pre><code>% /usr/bin/sh -c "ls 1\`"
  Unmatched `
  </code></pre>