title: Oracle SQL : search column that starts with digits
body: <p>I'd like to find all the rows which column value begins with a digit.</p>
  
  <p>Its works well with this request :</p>
  
  <pre><code>    WHERE trim(u_ods_val3.ods_itn_PHRSBMO.NO_ART_TECH_OI)    IS NOT NULL
    AND (SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)='0'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='1'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='2 '
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='3'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='4'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='5'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='6'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='7'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='8'
    OR SUBSTR(u_ods_val3.ODS_ITN_PHRSBMO.NO_ART_TECH_OI,0,1)  ='9')
  </code></pre>
  
  <p>But it is too long.</p>
  
  <p>Thank you for your help.</p>