title: Python & requests | ImportError: No module named util
body: <p>I just installed the package requests on a new computer. I'm getting this error when I try to import that module. Any ideas what's causing the issue w/ the util module?</p>
  
  <pre><code>Python 2.7.6 (v2.7.6:3a1db0d2747e, Nov 10 2013, 00:42:54) 
  
  [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
  
  Type "help", "copyright", "credits" or "license" for more information.
  
  &gt;&gt;&gt; import requests
  
  Traceback (most recent call last):
  
  File "&lt;stdin&gt;", line 1, in &lt;module&gt;
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/__init__.py", line 58, in &lt;module&gt;
    from . import utils
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/utils.py", line 25, in &lt;module&gt;
    from .compat import parse_http_list as _parse_list_header
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/compat.py", line 7, in &lt;module&gt;
    from .packages import chardet
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/packages/__init__.py", line 3, in &lt;module&gt;
    from . import urllib3
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/packages/urllib3/__init__.py", line 16, in &lt;module&gt;
    from .connectionpool import (
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/packages/urllib3/connectionpool.py", line 36, in &lt;module&gt;
    from .connection import (
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/requests-2.3.0-py2.7.egg/requests/packages/urllib3/connection.py", line 43, in &lt;module&gt;
    from .util import (
  ImportError: No module named util
  </code></pre>