title: React Native Expo - Open my app from android browser when clicking a link
body: <p>I want to implement a link on my website <strong>that opens my Android App when clicked in the browser from the phone</strong>.</p>
  
  <p>I can send them to Google Play from the app with </p>
  
  <pre><code>Linking.openURL("market://details?id=com.myapp.android")
  </code></pre>
  
  <p>and from my website I can send them to the same page with a link as
  <a href="https://play.google.com/store/apps/details?id=com.myapp.android" rel="nofollow noreferrer">https://play.google.com/store/apps/details?id=com.myapp.android</a></p>
  
  <p>But <strong>I want it to open the app itself if is already installed</strong>. Is this possible? If so, how?</p>
  
  <p><strong>EDIT</strong></p>
  
  <p><a href="https://docs.expo.io/versions/latest/guides/linking.html" rel="nofollow noreferrer">Expo Linking</a> says all I have to do is add</p>
  
  <pre><code>{
    "expo": {
      "scheme": "myapp"
    }
  }
  </code></pre>
  
  <p>to my <code>app.json</code> and then enter the scheme value in my browser</p>
  
  <p>However, I tried this and then entered </p>
  
  <blockquote>
    <p>myapp://</p>
  </blockquote>
  
  <p>in my browser, but it just sent me to a google seach with this as keywords.</p>