title: Pass PHP variables to a Bash script and then launch it
body: <p>So, basically, what I want to do is execute this Bash script :</p>
  
  <pre><code>#!/bin/bash
  
  path="./"
  filename="Ellly.blend"
  file=${path}${filename}
  description="Test of the api with a simple model"
  token_api="ff00ff"
  title="Uber Glasses"
  tags="test collada glasses"
  private=1
  password="Tr0b4dor&amp;3"
  
  curl -k -X POST -F "fileModel=@${file}" -F "filenameModel=${filename}" -F "title=${title}" -F "description=${description}" -F "tags=${tags}" -F "private=${private}" -F "password=${password}" -F "token=${token_api}" https://api.sketchfab.com/v1/models
  </code></pre>
  
  <p>Inside a PHP function. Problem is, I don't really see how I can pass to it some variables and then wait for it to end before resuming the PHP function.</p>
  
  <p>Any help ?</p>