title: Exception message (Python 2.6)
body: <p>In Python, if I open a binary file that doesn't exist, the program exits with an error and prints:</p>
  
  <pre><code>Traceback (most recent call last):
    File "C:\Python_tests\Exception_Handling\src\exception_handling.py", 
    line 4, in &lt;module&gt;
    pkl_file = open('monitor.dat', 'rb')
    IOError: [Errno 2] No such file or directory: 'monitor.dat'
  </code></pre>
  
  <p>I can handle this with 'try-except', like:</p>
  
  <pre><code>try:
      pkl_file = open('monitor.dat', 'rb')
      monitoring_pickle = pickle.load(pkl_file)
      pkl_file.close()
  except Exception:
      print 'No such file or directory'
  </code></pre>
  
  <p>How could I, in caught Exception, print the following line?</p>
  
  <pre><code>File "C:\Python_tests\Exception_Handling\src\exception_handling.py", 
  line 11, in &lt;module&gt;
  pkl_file = open('monitor.dat', 'rb')
  </code></pre>
  
  <p>So the program would not exit.</p>