title: celery consume send_task response
body: <p>In django application I need to call an external rabbitmq, running on a windows server and using some application there, where the django app runs on a linux server.</p>
  
  <p>I'm currently able to add a task to the queue by using the celery <code>send_task</code>:</p>
  
  <pre><code>app.send_task('tasks', kwargs=self.get_input(), queue=Queue('queue_async', durable=False))
  </code></pre>
  
  <p>My settings looks like:</p>
  
  <pre><code>CELERY_BROKER_URL = CELERY_CONFIG['broker_url']
  BROKER_TRANSPORT_OPTIONS = {"max_retries": 3, "interval_start": 0, "interval_step": 0.2, "interval_max": 0.5}
  
  CELERY_ACCEPT_CONTENT = ['application/json']
  CELERY_TASK_SERIALIZER = 'json'
  CELERY_RESULT_SERIALIZER = 'json'
  CELERY_TASK_DEFAULT_QUEUE = 'celery'
  CELERY_TASK_RESULT_EXPIRES = 3600
  CELERY_RESULT_BACKEND = 'rpc://'
  CELERY_CREATE_MISSING_QUEUES = True
  </code></pre>
  
  <p>What I'm not sure about is how I can get and parse the response, since the send_task only returns a key?</p>