title: Bash: How to pass input file content as command argument
body: <p>I have a command <code>command</code> that takes an input file as argument. Is there a way to call <code>command</code> without actually creating a file?</p>
  
  <p>I would like to achieve the following behavior</p>
  
  <pre><code>$ echo "content" &gt; tempfile
  $ command tempfile
  $ rm tempfile
  </code></pre>
  
  <p>if possible:</p>
  
  <ul>
  <li>as a one-liner, </li>
  <li>without creating a file, </li>
  <li>using either a bash (or sh) feature or a "well-known" command (as standard as <code>xargs</code>)</li>
  </ul>
  
  <p>It feels like there must be an easy way to do it but I can't find it.</p>