title: Call Django command with phrase as argument
body: <p>I'm trying to run the command </p>
  
  <p><code>zappa manage staging 'run_sql --sql \"show databases\"'</code></p>
  
  <p>But I get the following error:</p>
  
  <pre><code>zappa manage staging 'run_sql --sql "show databases"'
  [START] RequestId: dd895134-dc62-41c3-987b-3ea550af1129 Version: $LATEST
  [DEBUG] 2019-03-02T10:51:18.213Z dd895134-dc62-41c3-987b-3ea550af1129 Zappa Event: {'manage': 'run_sql --sql show databases'}
  Error: unrecognized arguments: databases: CommandError
  Traceback (most recent call last):
    File "/var/task/handler.py", line 580, in lambda_handler
      return LambdaHandler.lambda_handler(event, context)
    File "/var/task/handler.py", line 248, in lambda_handler
      return handler.handler(event, context)
    File "/var/task/handler.py", line 413, in handler
      management.call_command(*event['manage'].split(' '))
    File "/var/task/django/core/management/__init__.py", line 127, in call_command
      defaults = parser.parse_args(args=parse_args)
    File "/var/task/django/core/management/base.py", line 55, in parse_args
      return super().parse_args(args, namespace)
    File "/var/lang/lib/python3.6/argparse.py", line 1737, in parse_args
      self.error(msg % ' '.join(argv))
    File "/var/task/django/core/management/base.py", line 61, in error
      raise CommandError("Error: %s" % message)
  django.core.management.base.CommandError: Error: unrecognized arguments: databases
  </code></pre>
  
  <p>I tried various things like </p>
  
  <pre><code>zappa manage staging 'run_sql --sql \"show databases\"'
  zappa manage staging 'run_sql --sql \\\"show databases\\\"'
  zappa manage staging 'run_sql --sql \"show\ databases\"'
  zappa manage staging 'run_sql --sql \\\"show\\\ databases\\\"'
  </code></pre>
  
  <p>But all fail for the same reason:</p>
  
  <blockquote>
    <p>django.core.management.base.CommandError: Error: unrecognized arguments: databases\\”</p>
  </blockquote>
  
  <p>It looks like Django command parser believes the phrase are several options or something, but I can't figure out the way to treat it as a single argument.</p>
  
  <p>Based on the following Django Command:</p>
  
  <pre><code>import MySQLdb as db
  from django.conf import settings
  from django.core.management.base import BaseCommand
  
  
  class Command(BaseCommand):
    help = "Runs a raw SQL query"
  
    def add_arguments(self, parser):
      parser.add_argument(
        '--user',
        dest='user',
        help='Username to be used to create database',
      )
      parser.add_argument(
        '--password',
        dest='password',
        help='Password for the mysql user.',
      )
      parser.add_argument(
        '--db-name',
        dest='db_name',
        help='Name of the database if it is different from the one defined in settings',
      )
      parser.add_argument(
        '--sql',
        dest='sql',
        help='SQL query to run',
        default='show databases'
      )
  
    def handle(self, *args, **options):
      self.stdout.write(self.style.SUCCESS('Running raw SQL query'))
  
      sql = options.get('sql')
      dbname = options.get('db_name') or settings.DATABASES['default']['NAME']
      user = options.get('user') or settings.DATABASES['default']['USER']
      password = options.get('password') or settings.DATABASES['default']['PASSWORD']
      host = settings.DATABASES['default']['HOST']
  
      self.stdout.write(self.style.SUCCESS(
        'Running SQL query\n'
        '"{sql}"\n'
        'with \n'
        'dbname="{dbname}"\n'
        'user="{user}"\n'
        'password="{password}"\n'
        'host="{host}"\n'
        ''.format(
          sql=sql,
          dbname=dbname,
          user=user,
          password=password,
          host=host,
        )
      ))
  
      con = db.connect(user=user, host=host, password=password)
      cur = con.cursor()
      cur.execute(f'{sql}'.format(sql=sql))
  
      output = cur.fetchall()
      self.stdout.write(self.style.SUCCESS(
        "\nSQL query output:\n"
        "{output}".format(output=output))
      )
      self.stdout.write(self.style.SUCCESS('\n'))
  
      cur.close()
      con.close()
  
      self.stdout.write(self.style.SUCCESS('All Done'))
  </code></pre>