title: Parsing dates with different formats
body: <p>I have a csv file with a column containing dates, but the dates are in two different formats: "m/d/y H:M" and "y m d H:M:S". I want to make a new column with these dates all in one format (I don't care which one). I tried the parse_date_time function but it would only work for one of the formats, not both. How can I go about doing this?</p>
  
  <p>Here is the code I was trying to use:</p>
  
  <pre><code>newdata &lt;- mutate(data,
                          newcolumn = parse_date_time(x = data$date_column,
                                                          orders = c("m/d/y H:M", "y m d H:M:S"),
                                                          locale = "eng") )
  </code></pre>
  
  <p>Here are some example dates from the column:</p>
  
  <pre><code>x &lt;- c("6/21/2006 0:00",
         "1889-06-13 00:00:00",
         "6/28/2012 0:00",
         "5/19/2015 0:00",
         "6/6/2016 0:00",
         "1884-05-24 00:00:00",
         "7/28/2013 0:00")
  </code></pre>