title: Python 3.2.2 open('C:\file.txt') doesn't work
body: <p><br>
  Admittedly, I am a novice; however, (I think) I did what the tutorial said (for the version I installed) and I can't get Python to read a file. Others have had problems with long file names or paths, but I kept mine short and sweet... so I thought. <br>
  The file itself contains one word on a single line. <br>
  The print('string') works, len('string') works...<br></p>
  
  <p>Here's what I got, in IDLE and CMD, even before using the import statements included below:</p>
  
  <blockquote>
    <p>Python 3.2.2 (default, Sep  4 2011, 09:07:29) [MSC v.1500 64 bit (AMD64)] on win32</p>
    
    <p>Type "copyright", "credits" or "license()" for more information.</p>
    
    <blockquote>
      <blockquote>
        <p>import os, csv, urllib</p>
        
        <p>f0txt = ()</p>
        
        <p>f0txt = open("C:\try\in0.txt")</p>
      </blockquote>
    </blockquote>
    
    <p>Traceback (most recent call last):</p>
    
    <p>File "<code>&lt;pyshell#4</code>>", line 1, in </p>
    
    <p>f0txt = open("C:\try\in0.txt")</p>
    
    <p>IOError: [Errno 22] Invalid argument: 'C:\try\in0.txt'</p>
  </blockquote>