title: Julia select element from tuple for each row in array
body: <p>I know there has to be a clever way to do this in Julia but I'm stumped. I have a 1d array of tuples and I want to extract the third element from each row of the array. Here is an example of what I'm working with:</p>
  
  <pre><code>julia&gt; experArr 20-element Array{(Any,Any,Any),1}:
   (4000,0.97613,1.6e6) 
   (2000,0.97613,800000.0)
   (8000,0.97613,3.2e6) 
   (1000,0.97613,400000.0)
   ...
  </code></pre>
  
  <p>My first thought was to do something like this:</p>
  
  <pre><code>julia&gt; experArr[:][3]
  </code></pre>
  
  <p>but that returns the following:</p>
  
  <pre><code>julia&gt; experArr[:][3] 
  (8000,0.97613,3.2e6)
  </code></pre>
  
  <p>What I want it to return is this:</p>
  
  <pre><code>20-element Array{Any,1}:
  1.6e6
  800000.0
  3.2e6
  400000.0
  ...
  </code></pre>
  
  <p>I have tried several other permutations of indexing but I keep only returning a single element. I feel that there is a right way to do this and I'm just missing</p>