title: jqGrid: how to hide a specific search field in the search toolbar
body: <p>I am using jqGrid with a search toolbar. Now for several columns I do not need the search field, because I do not want to make them searchable (i.e. a column of checkboxes). For these columns I want to hide the search field in the search toolbar. 
  I have read in the jqGrid <a href="http://www.trirand.com/jqgridwiki/doku.php?id=wiki:colmodel_options" rel="noreferrer">documentation</a> that the <code>viewable</code> option can be set to <code>false</code>. 
  Here is the part where I set the <code>viewable</code> option:</p>
  
  <pre><code>colModel :[ 
            {name:'checkbox', index:'checkbox', width:'3%', viewable:false},
  </code></pre>
  
  <p>Here is how I create the search toolbar:</p>
  
  <pre><code>jQuery(function(){
      jQuery("#listTable").jqGrid('filterToolbar',{stringResult: true, searchOnEnter: false});
  });
  </code></pre>
  
  <p>According to the <a href="http://www.trirand.com/jqgridwiki/doku.php?id=wiki:colmodel_options" rel="noreferrer">documentation</a>, the <code>viewable</code> option is valid only if the <code>viewGridRow</code> method is activated.</p>
  
  <p>But when I use (activate) the <code>viewGridRow</code> method, that creates another dialog. In that dialog the column whose <code>viewable</code> is set to false does not appear. But I want to hide the search field in the search toolbar not in a new dialog. How can I do that?</p>
  
  <p>I have also tried to get the corresponding <code>div</code> (the one that surrounds my search field) and set its <code>style.display</code> to <code>none</code>. But that does not help.</p>
  
  <p>Is there a way I could hide this search field in the search toolbar?</p>