title: Python loops with break and continue
body: <p>Given a set of N real numbers numbers = [10.10, 6.4, 7.3, 2.2, 1.1, 0, 5.5, -2.3].
  If every second element from the beginning of the set forms a descending sequence, then output 0; otherwise, print the number of the first number that violates the pattern.</p>
  <pre><code>numbers = [10.10, 6.4, 7.3, 2.2, 1.1, 0, 5.5, -2.3]
  i = 1
  while i &lt; len(numbers) - 1:
      if all(numbers[i+1] &lt;= numbers[i] for i in range(0, len(numbers), 2)):
          print(0)
          break
      i += 2
  else:
      print(1)
  </code></pre>
  <p>But it's incorrect, input is still 0 if I change for example 7.2 to 2.2 and I don't what to write in else
  Can you help me?</p>