title: How to get file name of the linux awk and find results
body: <p>i have this linux command using pipes which find files in directyrids and grep and awk on the results the 
   command working just fine , what im missing is  the bility to get the file name of the results so i could know what is the source file of the result .</p>
  
  <pre><code> $ find . -name "*.log" | xargs grep -i TypeOf | grep -v 'Error=APP1' | awk '{split($0,a,"Name="); print a[2]}' | sort -h
  </code></pre>
  
  <p>how do i add to this command something to pring the file names</p>