title: How can I make a inf-Matrix in Julia?
body: <p>I want to set up the lowest boundary of my Problem as a -inf also without a limit and here comes the codes</p>
  <pre><code>@time begin
  using COSMO, SparseArrays, LinearAlgebra
  using NPZ
  
  Matrix10 = npzread(&quot;C:/Users/skqkr/Desktop/Semesterarbeit/Chiwan_Q1.npz&quot;)
  q = Matrix10[&quot;p&quot;];
  P = sparse(Matrix10[&quot;Q&quot;]);
  A = sparse(Matrix10[&quot;G&quot;]);
  h = Matrix10[&quot;h&quot;];
  l = Matrix10[&quot;l&quot;];
  
  # First, we decide to solve the problem with two one-sided constraints using `COSMO.Nonnegatives` as the convex set:
  Aa = [-A; A]
  ba = [h; -l]
  constraint1 = COSMO.Constraint(Aa, ba, COSMO.Nonnegatives);
  
  # Next, we define the settings object, the model and then assemble everything:
  settings = COSMO.Settings(verbose=true);
  model = COSMO.Model();
  assemble!(model, P, q, constraint1, settings = settings);
  res = COSMO.optimize!(model);
  
  
  # Alternatively, we can also use two-sided constraints with `COSMO.Box`:
  constraint1 = COSMO.Constraint(A, zeros(3), COSMO.Box(-l, h));
  
  model = COSMO.Model();
  assemble!(model, P, q, constraint1, settings = settings);
  res_box = COSMO.optimize!(model);
  
  
  
  end
  </code></pre>
  <p>so I want</p>
  <pre><code>l = Matrix10[&quot;l&quot;];
  </code></pre>
  <p>here ll as a Matrix without a limit so, the constraints of the qp would be this form.
  A*X&lt;h</p>
  <p>How should I do in order to make the limits minus infinits.</p>
  <p>thank you!!</p>