title: Specify filename in python script to open Excel workbook
body: <p>this is a really dumb question, but Im trying to learn python and I got stuck on example with reading Excel files using xlrd. 
  I found this script online but I cant figure out where am I supposed to fill my filename to get it open. </p>
  
  <p><pre>from <strong>future</strong> import print_function
  from os.path import join, dirname, abspath, isfile
  from collections import Counter
  import xlrd
  from xlrd.sheet import ctype_text   </p>
  
  <p>def get_excel_sheet_object(fname, idx=0):
      if not isfile(fname):
          print ('File doesn't exist: ', fname)
              # Open the workbook and 1st sheet
      xl_workbook = xlrd.open_workbook(fname)
      xl_sheet = xl_workbook.sheet_by_index(0)
      print (40 * '-' + 'nRetrieved worksheet: %s' % xl_sheet.name)</p>
  
  <code>return xl_sheetsdf
  </code></pre>