title: Print all even numbers in a list until a given number
body: <p>I am just beginning to dabble in Python, and have started to go through the chapters on learnpython.org. In the 'Loops' chapter, I have solved the challenge with the following code. However I am not sure it is the most efficient. It certainly doesn't seem to be as I have to define the "number to not go beyond" twice. In this (I'm guessing) easy problem, DRY should be possible to adhere to, right?</p>
  
  <p>The <a href="http://www.learnpython.org/page/Loops" rel="nofollow">exercise</a> is </p>
  
  <blockquote>
    <p>Loop through and print out all even numbers from the numbers list in
    the same order they are received. Don't print any numbers that come
    after 237 in the sequence.</p>
  </blockquote>
  
  <p>My code:</p>
  
  <pre><code>numbers = [ 951, 402, 984, 651, 360, 69, 408, 319, 601, 485, 980, 507, 725, 547, 544, 615, 83, 165, 141, 501, 263, 617, 865, 575, 219, 390, 984, 592, 236, 105, 942, 941, 386, 462, 47, 418, 907, 344, 236, 375, 823, 566, 597, 978, 328, 615, 953, 345, 399, 162, 758, 219, 918, 237, 412, 566, 826, 248, 866, 950, 626, 949, 687, 217, 815, 67, 104, 58, 512, 24, 892, 894, 767, 553, 81, 379, 843, 831, 445, 742, 717, 958, 609, 842, 451, 688, 753, 854, 685, 93, 857, 440, 380, 126, 721, 328, 753, 470, 743, 527 ]
  
  # My Solution
  for x in numbers:
    if x != 237:
      if x % 2 == 0:
        print x
    if x == 237:
      break
  </code></pre>