title: Python error when using urllib.open
body: <p>When I run this:</p>
  
  <pre><code>import urllib
  
  feed = urllib.urlopen("http://www.yahoo.com")
  
  print feed
  </code></pre>
  
  <p>I get this output in the interactive window (PythonWin):</p>
  
  <pre><code>&lt;addinfourl at 48213968 whose fp = &lt;socket._fileobject object at 0x02E14070&gt;&gt;
  </code></pre>
  
  <p>I'm expecting to get the source of the above URL.  I know this has worked on other computers (like the ones at school) but this is on my laptop and I'm not sure what the problem is here.  Also, I don't understand this error at all.  What does it mean?  Addinfourl?  fp?  Please help.</p>