title: Visual Studio Code not activating the selected python interpreter for jupyter notebook
body: <p>My conda environments all show up in the select interpreter path. When I select the conda environment (<code>Python 3.7.7 64-bit ('adv_ml':conda)</code>) I want and navigate to an existing jupyter notebook in vscode. I noticed that a different conda env (conda env B) is active despite both the kernel and python interpreter saying <code>Python 3.7.7 64-bit ('adv_ml':conda)</code> is selected.</p>
  <p>Additionally, the .vscode settings.json in my project has the correct conda env</p>
  <pre><code>{
      &quot;python.pythonPath&quot;: &quot;/Users/me/anaconda3/envs/adv_ml/bin/python&quot;,
      &quot;jupyter.jupyterServerType&quot;: &quot;local&quot;
  }
  </code></pre>
  <p>Now here is the kicker... if I create a new jupyter notebook, when I check what conda env it is using it is using the correct conda environment <code>Python 3.7.7 64-bit ('adv_ml':conda)</code>.</p>
  <p>Is there a setting I am missing that is causing existing jupyter notebooks in my vscode to be tied to this other environment? Additionally, I didn't create these other notebooks so it's not like they have this incorrect environment to begin with. I should be able to edit existing notebooks with the selected environment.</p>