title: Actor model with Akka.NET: how to prevent sending messages to dead actors
body: <p>I am using Akka.NET to implement an actor system in which some actors are created on demand and are deleted after a configurable idle period (I use Akka's "ReceiveTimeout" mechanism for this). Each of these actors is identified by a key, and there should not exist two actors with the same key.</p>
  
  <p>These actors are currently created and deleted by a common supervisor. The supervisor can be asked to return a reference to the actor matching a given key, either by returning an existing one or creating a new one, if an actor with this key doesn't exist yet. When an actor receives the "ReceiveTimeout" message, it notifies the supervisor who in turn kills it with a "PoisonPill". </p>
  
  <p>I have an issue when sending a message to one of these actors right after it has been deleted. I noticed that sending a message to a dead actor doesn't generate an exception. Worse, when sending an "Ask" message, the sender remains blocked, waiting indefinitely (or until a timeout) for a response that he will never receive.</p>
  
  <p>I first thought about Akka's "Deatchwatch" mechanism to monitor an actor's lifecycle. But, if I'm not mistaken, the "Terminated" message sent by the dying actor will be received by the monitoring actor asynchronously just like any other message, so the problem may still occur in between the target actor's death and the reception of its "Terminated" message.</p>
  
  <p>To solve this problem, I made it so that anyone asking the supervisor for a reference to such an actor has to send a "close session" message to the supervisor to release the actor when he doesn't need it anymore (this is done transparently by a disposable "ActorSession" object). As long as there are any open sessions on an actor, the supervisor will not delete it.</p>
  
  <p>I suppose that this situation is quite common and am therefore wondering if there isn't a simpler pattern to follow to address this kind of problem. Any suggestion would be appreciated.</p>