title: Splitting a line in bash based on delimiter with Sed / Regex
body: <p>Regex rookie and hoping to change that. I have the following seemingly very simple problem that I cannot figure the correct regex implementation to parse properly. Basically I have a file that has lines that looks like this: </p>
  
  <pre><code>time:3:35PM
  </code></pre>
  
  <p>I am just trying to cut out all characters up to and including ONLY FIRST ':' delimiter and keep the rest intact with sed so that I can process on many files with same format. What I am trying to get is this:</p>
  
  <pre><code>3:35PM
  </code></pre>
  
  <p>The below is the closest I got but is just using the last occurrence of the delimiter instead of the first.:</p>
  
  <pre><code>sed 's/.*://'
  </code></pre>
  
  <p>I have also tried with python but have challenges with applying a python function to iterate through all lines in many files as opposed to just one file. </p>
  
  <p>Any help would be greatly appreciated. </p>