title: jQuery serialize the form twice (caching serialize ?)
body: <p>In this URL <a href="http://www.juju.runover.com.br/meus-dados" rel="nofollow">http://www.juju.runover.com.br/meus-dados</a>, I have a form loaded dinamicaly in the "Bancos" section.
  I put an alert to show me the data sent and when I change the "Selecionar banco" option and try to submit, the serialization is duplicated!</p>
  
  <p>Here is my first submit:</p>
  
  <pre><code>pessoa=0&amp;cpf_cnpj=40367993805&amp;conta=0082734&amp;conta_digito=7&amp;agencia=0395&amp;agencia_digito=6&amp;tipo=0&amp;id=1&amp;acao=alterar
  </code></pre>
  
  <p>Now, after I've changed the "Selecionar banco" option to "outro..." and again to "itau", this is the result:</p>
  
  <pre><code>pessoa=0&amp;cpf_cnpj=40367993805&amp;conta=0082734&amp;conta_digito=7&amp;agencia=0395&amp;agencia_digito=6&amp;tipo=0&amp;id=1&amp;acao=alterar&amp;pessoa=0&amp;cpf_cnpj=40367993805&amp;conta=0082734&amp;conta_digito=7&amp;agencia=0395&amp;agencia_digito=6&amp;tipo=0&amp;id=1&amp;acao=alterar
  </code></pre>
  
  <p>Because of that I can't update the record, because de new data is sent before the old data (the second submit generated)...</p>
  
  <p>I've searched a lot, tried serializeArray, and nothing</p>
  
  <p>The Serialization Code:</p>
  
  <pre><code>jQuery('#banco').live('submit', function () {
      var dados = jQuery('#banco').serialize();
      alert(dados);
  
      /*
      jQuery.post(
          'app/painel/form/form_banco.php',
          dados,
          function (data) {
              alert(data);
              atualizaLista();
          }
      );
      */
      return false;
  });
  </code></pre>