title: jQuery .each() multiplying "i"?
body: <p>I'm trying to make a kind of newswire for a school project but I'm having a few problems with jQuery's <code>.each()</code> function. I'm trying to find a way to skip every 2nd array element in a loop.</p>
  
  <p>Basically I have data from a NY Times API and got both title and abstract and push these into an array that I then loop and animate every once and awhile.</p>
  
  <p>My problem is, I can't seem to find a way to get Title + Abstract <code>(Index[0]+[1])</code> without the loop just moving to <code>index[1]</code> again. Now I knows in Javascript you can simply use a <code>for (i=0; i &lt; array.length; i+2)</code> and thus skip every 2nd array element, but I haven't had any luck incorporating that. Any suggestions? :)</p>
  
  <pre><code>$(document).ready(function() {
  var newsWire = [];
      function loadNewswire() {
          return $.getJSON('http://api.nytimes.com/svc/news/v3/content/all/all.json',
          {'api-key': 'XXXXXXXXXXXXXXXXXXX'},
          function(data) {
              console.log(data)
              var newsWireTemp = [];
              for (var i = 0; i &lt; data.results.length; i++) {
                  var breakingNews = data.results[i];
                  var breakingTitle = breakingNews.title.toUpperCase();
                  var breakingAbstract = breakingNews.abstract;
                  newsWireTemp.push(breakingTitle);
                  newsWireTemp.push(breakingAbstract);
              }
              newsWire = newsWireTemp;
          });
      }
      loadNewswire().done(function () {
          var items = newsWire;
          $text = $('#newswiretxt span'),
          delay = 10; //seconds
          function loop (delay) {
              $.each(items, function (i, elm){
                  $text.delay(delay*1E3).fadeOut();
                  $text.queue(function(){
                      $text.html(items[i]+ ": " +items[i+1]);
                      $text.dequeue();
                  });
                  $text.fadeIn();
                  $text.queue(function(){
                      if (i == items.length -1) {
                          loop(delay);   
                      }
                  $text.dequeue();
                  });
              });
          }
          console.log(items.length);
          loop(delay);
          });
  });
  </code></pre>