title: Bash script: always show menu after loop execution
body: <p>I'm using a bash script menu like this:</p>
  
  <pre><code>#!/bin/bash
  PS3='Please enter your choice: '
  options=("Option 1" "Option 2" "Option3" "Quit")
  select opt in "${options[@]}"
  do
      case $opt in
          "Option 1")
              echo "you chose choice 1"
              ;;
          "Option 2")
              echo "you chose choice 2"
              ;;
          "Option 3")
              echo "you chose choice 3"
              ;;
          "Quit")
              break
              ;;
          *) echo invalid option;;
      esac
  done
  </code></pre>
  
  <p>After each menu selection I just get prompted with</p>
  
  <pre><code>Please enter your choice:
  </code></pre>
  
  <p>How do I always show the menu after each option has finished execution? I've done some looking around and I think I can do some kind of while loop, but I haven't been able to get anything working.</p>