title: Simplifying Boolean Expression (A'BC) + (A'B'C) + (A'BC) + (AB'C)
body: <p>please help me with simplifying this one. I am a bit new to these..</p>
  
  <pre><code>(A'BC') + (A'B'C) + (A'BC) + (AB'C)
  </code></pre>
  
  <p>the book i use shows and answer, which is,</p>
  
  <pre><code>Answer = A'B + B'C
  </code></pre>
  
  <p>I tried simplifying, but I get stucked with two eXors,<br/> my simplification so far goes like this...</p>
  
  <pre><code>(A'BC') + (A'B'C) + (A'BC) + (AB'C)
  A (BC' + B'C) + C (A'B + AB')
  </code></pre>
  
  <p>This doesn't seem to be a write way, Please someone help me simplify this,<br/> and please show step by step, as I am sort of new..
  <br/> Also I don't get how to simplify eXor further..</p>