title: How to display a sfWidgetFormSelectRadio item without showing the label
body: <p>I am using Symfony 1.3.6 on Ubuntu 10.0.4.</p>
  
  <p>I am using the sfWidgetFormSelectRadio to allow a user to select a picture from a list, in a form.</p>
  
  <p>In the action, the pictures are set up like this:</p>
  
  <pre><code>    $this-&gt;form-&gt;setWidget('chosenpic', new sfWidgetFormSelectRadio(array(
                              'choices' =&gt; $this-&gt;pictures,
                              'default' =&gt; $this-&gt;pictures[count($this-&gt;pictures)-1] ))
                              );
  </code></pre>
  
  <p>In the template, the widget is displayed like this:</p>
  
  <pre><code>&lt;?php echo $form['chosenpic']-&gt;render(array('id'=&gt;'check'.($i+1), 'value'=&gt; ($i+1), 'width' =&gt; "80", 'height' =&gt; "80")); ?&gt;
  </code></pre>
  
  <p>This generates the following output:</p>
  
  <pre><code>&lt;ul class="radio_list"&gt;&lt;li&gt;&lt;input type="radio" width="80" height="80" id="check1" value="1" name="flowers[chosenpic]"&gt;&amp;nbsp;&lt;label for="flowers_chosenpic_0"&gt;http://example.com/media/images/48408000/jpg/_48408794_009829449-1.jpg&lt;/label&gt;&lt;/li&gt;&lt;/ul&gt;
  </code></pre>
  
  <p>I do no want the the label for appearing, as it messes up the form. Short of manually generating the HTML myself (using the form and widget names, is there a way that I can prevent the widget from displaying a 'label for' ?</p>