title: how to access custom row(s) data via Alloy?
body: <p>ive tried many/multiple ways to get this to work but just cant as yet, so would appreciate anyone's assistance.</p>
  
  <p>i have a view as follows :</p>
  
  <p>"LBProw.xml"</p>
  
  <pre><code>    &lt;Alloy&gt;
          &lt;TableViewRow id="LBProw" &gt;
             &lt;ScrollableView id="sView" &gt;
                  &lt;View id="view1"  &gt;
                          &lt;!-- text labels on the row --&gt;
                          &lt;Label id="LBPheading" &gt;  &lt;/Label&gt;
                          &lt;Label id="myLabel1" &gt;      &lt;/Label&gt;
                          &lt;Label id="myLabel2" &gt;      &lt;/Label&gt;
                  &lt;/View&gt;                     
             &lt;/ScrollableView&gt;
          &lt;/TableViewRow&gt;
      &lt;/Alloy&gt;
  </code></pre>
  
  <ul>
  <li>adding rows to the table is working 100% fine.</li>
  </ul>
  
  <p>what i cant work out, is how can I loop through the previously created tableview rows, access the rows (custom) fields values, and then do something with those values. I need to access these rows (and their custom row fields values) from a different JS file.</p>
  
  <p>eg. somelogic.JS &lt;--- loop thru the table view rows, retrieve the rows custom field values and then use those values (note that $.myTable is directly accessible from this JS file)</p>
  
  <p>as an example, i tried using the following but could not work out how to get the individual rows custom fields values (the label values for "LBPheading", "myLabel1", "myLabel2")</p>
  
  <pre><code>    // loop thru the rows    
      for (i = 0; i &lt; $.myTable.data[0].rows.length; i++) {`
           Ti.API.info('row #' + i);
           ?? $.myTable.data[0].rows[i].????   &lt;== how can i get the rows (custom) field values ?
      }
  </code></pre>
  
  <p>I think, it has to do with the embedded ScrollableView and View in the row ? but I cant figure out how to reference the Label(s) within that structure.</p>
  
  <p>Really appreciate any assistance/advice.</p>