title: Compare two numbers in shell script
body: <p>Write a Bash shell script “order.sh” that takes two integer arguments “a” and “b”, and prints out the appropriate relationship “a &lt; b”, “a == b” or “a > b” (with “a” and “b” replaced by their values). </p>
  
  <p>code: </p>
  
  <pre><code>#!/bin/bash
  echo -n "enter the first number:"; read x
  echo -n " enter the second number:"; read y
  
  if ["$x " -lt "$y"]
  then
  echo "$x &lt; $y"
  else
  echo"$y &lt; $x"
  
  if [ "$x" -eq "$y"]
  then
  echo " $x == $y "
  
  fi 
  </code></pre>
  
  <p>i am not being able to compile his code as it is failing and says "/bin/sh: make command not found"
  can someone tell me what this means? i am new to shell scripting and i have no idea what is the problem...</p>