title: How can I bypass 403 error in python using requests?
body: <p>I know that some of you already wrote about this problem, but after all atempts nothing works for me. So when I try to scrape web page (<a href="https://www.askgamblers.com/" rel="nofollow noreferrer">https://www.askgamblers.com/</a>) I get 403 error. I already tried:</p>
  <ul>
  <li>Changing to difrend request modes (GET, POST, HEAD)</li>
  <li>Different User-Agent (I copy the same User-Agent that i found in dev console in Chrome)</li>
  <li>Putting more params in header (i copy whole header that i found in dev console)</li>
  <li>Using session</li>
  </ul>
  <p>And still nothing works for me. What could try next. Did i miss something? What would you do in this case? You can also check my code with only user agent in header.</p>
  <pre class="lang-py prettyprint-override"><code>url = &quot;https://www.askgamblers.com/&quot;
  page = requests.get(url, headers={'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/96.0.4664.45 Safari/537.36'})
  print(page.status_code)
  </code></pre>
  <p>I am using the latest version of requests libary (2.26.0)</p>
  <p>This is my first post, so be gentle on me :)</p>
  <p>EDIT:</p>
  <p>My problem was solved with this help: <a href="https://stackoverflow.com/a/61379638/17637402">https://stackoverflow.com/a/61379638/17637402</a></p>