title: How can go into this <a> link using selenium driver? (google-chrome version 102.0.5005)
body: <p><a href="https://en.dict.naver.com/#/search?range=all&amp;query=practice" rel="nofollow noreferrer">https://en.dict.naver.com/#/search?range=all&amp;query=practice</a></p>
  <p><a href="https://i.stack.imgur.com/TCJ9O.png" rel="nofollow noreferrer">image of the link i want to click</a></p>
  <p><a href="https://i.stack.imgur.com/Wejvf.png" rel="nofollow noreferrer">image of the html of the part</a></p>
  <p>i want to click that word. That word is link so if i click that on the website then i will go to new page.</p>
  <p>I tried to click that using it's xpath, like,</p>
  <pre><code>word_link=driver.find_element_by_xpath('//*[@id=&quot;searchPage_entry&quot;]/div/div[1]/div[1]/a')
  word_link.click()
  </code></pre>
  <p>but when i debugged, there's an error message;
  <a href="https://i.stack.imgur.com/jnZUh.png" rel="nofollow noreferrer">error message</a></p>
  <p>why the problem occurs?
  And, how can i go into the link using selenium?</p>