title: bash sort characters before numbers
body: <p>How to call sort to ensure that the following list is the result of any its randomizations? In particular, standard sort sorts [0-9] before [A-Za-z] but I need [A-Za-z] before [0-9]. I read the manpage but nothing seems to fit. I read that the locale influences the sorting of individual characters but which locale is the right one?</p>
  
  <pre><code>    01_abc
      02_abc
      02_01_abc
      02_02_abc
      02_02_01_abc
      02_02_02_abc
      02_02_03_abc
      02_03_abc
      03_abc
      04_abc
  </code></pre>