title: finding how many consecutive numbers in an array [java]
body: <p>For example, array is like this  {1,1,2,1,1,1 } and they key int is 1, the Largest number of consecutive times 1 is going to be 3.  When i run my code and type the same numbers, I'm getting 4 consecutive numbers of 1. Can someone give me advice? is there a built-in method that will help me solve this?</p>
  
  <pre><code> Scanner kbd = new Scanner (System.in);
              int count = 1;
              int largest = 0;
  
              System.out.println("Enter number");
              int numbers = kbd.nextInt();
              int[] numb = new int[numbers];
              System.out.println("Now enter "+numbers+" integers:");
              for(int i =0; i&lt;numb.length;i++){
                  numb[i] = kbd.nextInt();
              }
              System.out.println("Now enter the key integer: ");
              int key = kbd.nextInt();
  
              for (int i = 0; i&lt;numb.length-1; i++) {
              if (numb[i] == key) {
                  if (numb[i] == numb[i + 1]) {
                       count++;
                      }
              else {
                      largest = Math.max(largest, count);
                      count = 1;
  
                    }
             }
      }
  
              System.out.println("Largest number of consecutive times "+key+" was entered: "+largest);
  </code></pre>