title: scrapy list of links from parse result
body: <p>Here's my current code: </p>
  
  <pre><code>#scrap all the cafe links from example.com
  
      import scrapy, re
      from scrapy.linkextractors import LinkExtractor
      from scrapy.contrib.spiders import CrawlSpider, Rule
      from scrapy import Selector
  
      class DengaSpider(scrapy.Spider):
          name = 'cafes'
          allowed_domains = ['example.com']
          start_urls = [
              'http://example.com/archives/8136.html',
          ]
  
          cafeOnlyLink = []
  
          def parse(self, response):
              cafelink = response.xpath('//li/a[contains(@href, "archives")]/@href').extract()
              twoHourRegex = re.compile(r'^http://example\.com/archives/\d+.html$')
              cafeOnlyLink = [ s for s in cafelink if twoHourRegex.match(s) ]
  </code></pre>
  
  <p>So how should I continue to parse content from each url containing in the [cafeOnlyLink] list? and I want to save all the result from each page in a csv file. </p>