title: (Errno 22) invalid argument when trying to run a python program from a bat file
body: <p>I'm following this exactly but it is not working <a href="https://youtu.be/qHcHUHF_Qfo?t=438" rel="nofollow">https://youtu.be/qHcHUHF_Qfo?t=438</a> </p>
  
  <p>I type the location in the run window:</p>
  
  <pre><code>C:\Users\Zachary lastName\mypythonscripts\hello.py
  </code></pre>
  
  <p>I get error message: </p>
  
  <blockquote>
    <p>can't open file 'c:\users"Zachary': [Errno 22] invalid argument</p>
  </blockquote>
  
  <p>The bat file is:</p>
  
  <pre><code>@py C:\Users\Zachary lastName\mypythonscripts\hello.py %*
  
  @pause
  </code></pre>
  
  <p>I've searched everywhere and can't find an answer, I also edited the path environment variable so I can just type the name of the program in the run window but again I get the error. Any help is appreciated!</p>