title: Get all Trello cards in a specific list from all boards in an organization sorted by member
body: <p>I am quite new to the Trello API and I am looking for a good solution for an issue I am having.</p>
  
  <p><strong>Issue</strong></p>
  
  <p>We have an organization with quite some boards. </p>
  
  <ul>
  <li>All boards are organization visible</li>
  <li>Some boards also include members who are not member of the organization.</li>
  <li>Lists inside a board have specific names, like "To Do", "In Progress" etc.</li>
  </ul>
  
  <p>We have a status screen where we would like to display all cards from a specific list inside the organization. These cards should be sorted by member, even for the members not in our organization.</p>
  
  <p>A lot of this information is dynamic, like members, cards and boards.</p>
  
  <p><strong>What I am doing now</strong></p>
  
  <p>At the moment I have only found a solution where we make a lot of requests to the API, which of course has a <a href="http://help.trello.com/article/838-api-rate-limits" rel="nofollow">limit</a>.</p>
  
  <ol>
  <li>At first we are going through all boards inside the organization to get the board id's.</li>
  <li>Then we are looping through these id's to get all members inside all boards. This is needed because some board-members are not member of the organization. Duplicates are removed.</li>
  <li>When this is done, we found 2 different ways to get the cards. (1) Go through <code>members/[idMember or username]/cards</code>. here we can't get the list name. (2) Go through <code>boards/[board_id]/lists</code>, here we can't get the member name.</li>
  </ol>
  
  <p>Because we can't get all information in a single or just a few requests this process is very slow and even unstable because of the limit in the API. </p>
  
  <p>Is there anyone with a good/better solution? In a perfect world I'd like to have a single request like this:</p>
  
  <p><code>GET /1/organizations/[idOrg or name]/boards</code> where we can send in arguments to get all cards, all members and all lists. </p>