title: Passing different column id in jqgrid showLink formatter
body: <p>I had a bean object with me in the colmodel of jqgrid. the object hold two attributes name and id. I used a showLink formatter to form the hyperlink in one of the column. Now i have names the colum with object.name and on click i want to send the id in URL. Any inputs on how to work on this. 
  Any inputs could help me</p>
  
  <p>code :</p>
  
  <pre><code>colModel :[ 
        {name:'xxx', label:'xxx', width:200,align:'left'},
        {name:'yyy', label:'yyy', width:110,align:'left'}, 
        {
            name:'zzz',
            label:'zzz',
            width:100,
            sorttype:'int',
            formatter:'currency',
            formatoptions:{decimalSeparator:".", thousandsSeparator: ",", decimalPlaces: 0, prefix: "$ "},
            align:'center'
        }, 
        {name:'aaa', label:'aaa', width:80,align:'left'}, 
        {name:'bbb', label:'bbb', width:100,align:'left'}, 
        {
            name:'strategies.name',
            label:'strategies',
            width:160,
            align:'left',
            formatter:'showlink',
            formatoptions:{baseLinkUrl:'MyLink.html',addParam: '',showAction:'',idName:'id'}
        }]
  jQuery("#gridtableid").jqGrid('filterToolbar',{defaultSearch : "cn",stringResult: true,searchOnEnter : false});
  </code></pre>
  
  <p>Thanks in advance....</p>