title: Using Swagger with Flask alone
body: <p>I have discovered Swagger to generate the doc for a Restful Api I've developing, but the issue is that I'm using Flask alone not flask-restful and when I try to use the flask-restful-swagger wrapper it's not working, for example something like this :</p>
  
  <pre><code>from sqlalchemy.orm import create_session
  from flask import Flask, request, jsonify
  from Model import *
  from flask_restful import Api
  from flask_restful_swagger import swagger  
  
  app = Flask(__name__)
  api = swagger.docs(Api(app), apiVersion='0.1', api_spec_url="/api/spec")
  session = create_session(bind=engine)
  
  
  @app.route('/employees/', methods=['GET'])
  @swagger.operation(
     parameters=[
        {
           "name": "body",
           "description": "Get the employees in the shop.",
           "required": True,
           "allowMultiple": False,
           "dataType": NsEmployee.__name__,
           "paramType": "body"
        }
      ],
  
     responseMessages=[
        {
            "code": 201,
            "message": "Created. The URL of the created blueprint should appear in the Location header"
        },
        {
            "code": 405,
            "message": "Invalid input"
        }
  ])
  
  def employees():
     if request.method == 'GET':
       # do something...        
  
     return jsonify(json_results)
  
  
  if __name__ == '__main__':
     app.run(debug=True)
  </code></pre>
  
  <p>But when I try to get <code>/api/spec/</code> I obtain <strong>Not Found</strong>. My question is there is any way to avoid the use of flask-restful-swagger and integrate Swagger only with Flask.</p>
  
  <p>Any help is appreciated.</p>