title: How to assign (use) input name to Uppy uploader when we have multiple uppy uploader
body: <p>I am trying to use <code>Uppy</code> to upload some images in my <code>Laravel</code> application. I need multiple uppy elements in one page that each one upload one specific image. For example Uppy1 for upload Nationality Card image and Uppy2 for upload Drive Licence image. I use below code for upload images.</p>
  
  <pre><code>&lt;script&gt;
          const Dashboard = Uppy.Dashboard;
          const XHRUpload = Uppy.XHRUpload;
  
          var cls = '.kt_uppy';
          var options = {
              proudlyDisplayPoweredByUppy: false,
              target: id,
              inline: true,
              resultName: 'uppyResult',
              replaceTargetContent: true,
              showProgressDetails: true,
              note: null,
              height: 170,
              metaFields: [
                  { id: 'name', name: 'Name', placeholder: 'file name' },
                  { id: 'caption', name: 'Caption', placeholder: 'describe what the image is about' }
              ],
              browserBackButtonClose: true,
          }
  
          var uppyDashboard = Uppy.Core({
              autoProceed: true,
              restrictions: {
                  maxFileSize: 1000000, // 1mb
                  maxNumberOfFiles: 1,
                  minNumberOfFiles: 1
              }
          });
  
          uppyDashboard.use(Dashboard, options);
          uppyDashboard.use(XHRUpload, {
              endpoint: '{{ route('upload') }}',
          })
  </code></pre>
  
  <p><strong>Problems:</strong></p>
  
  <p>1 - Can we use and init multiple uppy elements just with write one code? (above code)
  because number of persons that I need to get informations are Flexible. For ex: one family have 1 child and other family have 3 children and number of Nationality Card to upload is flexible</p>
  
  <p>2 - How to assign different name attribute to each uppy element? like: <code>&lt;input type="file" name"name1"&gt;</code> and <code>&lt;input type="file" name"name2"&gt;</code></p>