title: How to return multiple files in HttpResponse Django
body: <p>I have been wracking my brains in this problem. Is there a way in django to serve multiple files from a single HttpResponse?</p>
  
  <p>I have a scenario where i am looping through a list of json and want to return all those as file form my admin view.</p>
  
  <pre><code>class CompanyAdmin(admin.ModelAdmin):
      form = CompanyAdminForm
      actions = ['export_company_setup']
  
      def export_company_setup(self, request, queryset):
          update_count = 0
          error_count = 0
          company_json_list = []
          response_file_list = []
          for pb in queryset.all():
              try:
                  # get_company_json_data takes id and returns json for the company.
                  company_json_list.append(get_company_json_data(pb.pk))
                  update_count += 1
              except:
                  error_count += 1
  
          # TODO: Get multiple json files from here.
          for company in company_json_list:
              response = HttpResponse(json.dumps(company), content_type="application/json")
              response['Content-Disposition'] = 'attachment; filename=%s.json' % company['name']
              return response
          #self.message_user(request,("%s company setup extracted and %s company setup extraction failed" % (update_count, error_count)))
          #return response
  </code></pre>
  
  <p>Now this will only let me return/download one json file as return would break the loop. Is there a simpler way to just append all this in a single response object and return that outside loop and download all json in the list in multiple files?</p>
  
  <p>I looked through a way to wrap all these files into a zip file, but i failed to do so as all the examples that i could find had files with path and name which i don't really have in this case. </p>
  
  <p>UPDATE:</p>
  
  <p>I tried to integrate zartch's solution to get a zip file using following:</p>
  
  <pre><code>    import StringIO, zipfile
      outfile = StringIO.StringIO()
      with zipfile.ZipFile(outfile, 'w') as zf:
          for company in company_json_list:
              zf.writestr("{}.json".format(company['name']), json.dumps(company))
          response = HttpResponse(outfile.getvalue(), content_type="application/octet-stream")
          response['Content-Disposition'] = 'attachment; filename=%s.zip' % 'company_list'
          return response
  </code></pre>
  
  <p>Since i never had the files to begin with, i thought about just using json dump that i had and adding individual filename. This just creates an empty zipfile. Which i think is expected as i am sure <code>zf.writestr("{}.json".format(company['name']), json.dumps(company))</code> is not the way to do it. I would appreciate if anyone can help me with this.</p>