title: Convert RGBA values to hex color code
body: <p>I have some sliders in my application that allows the user to change ARGB colors, however I need to convert these values to a hex value like 0xff000000, which is solid black.</p>
  
  <p>This is what I have so far:</p>
  
  <pre><code>protected int toHex(Color col) {
      String as = pad(Integer.toHexString(col.getAlpha()));
      String rs = pad(Integer.toHexString(col.getRed()));
      String gs = pad(Integer.toHexString(col.getGreen()));
      String bs = pad(Integer.toHexString(col.getBlue()));
      String hex = "0x" + as + rs + gs + bs;
      return Integer.parseInt(hex, 16);
  }
  
  private static final String pad(String s) {
      return (s.length() == 1) ? "0" + s : s;
  }
  </code></pre>
  
  <p>However upon getting the Integer value like below, I get a NumberFormatException for input string: "0xccffffff":</p>
  
  <pre><code>int color = toHex(new Color(153f, 153f, 153f, 0.80f));
  </code></pre>
  
  <p>Any ideas on how to get this to an Integer? Thanks.</p>