title: Confusion with "smallest width 600 dp" selector
body: <p>In my application I am supporting phone/tablet form factors and to have individual layouts I use selector "layout" (for phones), "layout-sw600dp" (for tablets).</p>
  
  <p>Following are the details:</p>
  
  <p><a href="http://android-developers.blogspot.in/2011/07/new-tools-for-managing-screen-sizes.html">http://android-developers.blogspot.in/2011/07/new-tools-for-managing-screen-sizes.html</a></p>
  
  <pre><code>Typical numbers for screen width dp are:
  320: a phone screen (240x320 ldpi, 320x480 mdpi, 480x800 hdpi, etc).
  480: a tweener tablet like the Streak (480x800 mdpi).
  600: a 7” tablet (600x1024).
  720: a 10” tablet (720x1280, 800x1280, etc).
  </code></pre>
  
  <p>I am having a Nexus 4 mobile, following are its attirbutes</p>
  
  <pre><code>Size:       4.7 inches
  Resolution: 768 x 1280 pixels
  DPI:        318
  dp:         386 
  Here is the dp calculation
  dp = (px * 160)/dpi
  dp = (768 * 160)/318
  </code></pre>
  
  <p>When I use 768 px in dp calculation formula the dp value comes as 386, but when I pass 1280 px the dp value comes as 644. </p>
  
  <p>With the following understanding I thought for Nexus 4 landscape it would read the layout from sw600dp, but that's not the case.</p>
  
  <p><strong>As the resolution is width X Height, it will be reversed when the device is rotated.</strong></p>
  
  <p>I thought this is the improvisation made with sw selectors compare to pre-3.2 large, xlarge sectors.</p>