title: Regex for Last Two Quotes per Line
body: <p>I'm using the following as part of SQL query and it got me hooked in trying to figure this out:</p>
  
  <pre><code>"ZENDCUST" as "End Customer ID",
  "ZCENCSLS___T" as "End Customer Desc",
  "ZCENCSLS__0CUST_GROUP" as "Cust Grp-EC-MD ID",
  "ZCENCSLS__0CUST_GROUP___T" as "Cust Grp-EC-MD Desc",
  "ZENDCUST__0CITY" as "End Customer City",
  </code></pre>
  
  <p>Is there a RegEx that can get the third &amp; fourth double quote marks?
  i.e. line 1 becomes 
  <code>"ZENDCUST" as 'End Customer ID',</code></p>
  
  <p>This would be repeated across more than the 5 example rows. </p>
  
  <p>I was able to use <code>\"(?!\sas)</code> but this wasn't able to omit the first quote. </p>
  
  <p><a href="https://regexr.com/40jhr" rel="nofollow noreferrer">https://regexr.com/40jhr</a></p>