George needs to pay for dental work. He needs 2 implants. Each implant has a base price of $2000. For one of the implants, he wants a crown made of porcelain. That feature costs an extra $500. He’s already put down a deposit of $600. He makes $15 per hour at work. How many hours does he need to work before he has enough to pay for the dental work?
The total base cost of the implants is 2 * $2000 = $<<2*2000=4000>>4000.
Adding the porcelain crown increases the total to $4000 + $500 = $<<4000+500=4500>>4500.
Subtracting the deposit, George needs to pay a total of $4500 - $600 = $<<4500-600=3900>>3900.
This means George would need to work a total of $3900 / $15 per hour = <<3900/15=260>>260 hours.
#### 260