Palindrome Number
<p>Given an integer <code>x</code>, return <code>true</code><em> if </em><code>x</code><em> is a </em><span data-keyword="palindrome-integer"><em><strong>palindrome</strong></em></span><em>, and </em><code>false</code><em> otherwise</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> x = 121
<strong>Output:</strong> true
<strong>Explanation:</strong> 121 reads as 121 from left to right and from right to left.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> x = -121
<strong>Output:</strong> false
<strong>Explanation:</strong> From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> x = 10
<strong>Output:</strong> false
<strong>Explanation:</strong> Reads 01 from right to left. Therefore it is not a palindrome.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-2<sup>31</sup>&nbsp;&lt;= x &lt;= 2<sup>31</sup>&nbsp;- 1</code></li>
</ul>

<p>&nbsp;</p>
<strong>Follow up:</strong> Could you solve it without converting the integer to a string?
Math
class Solution:
    def isPalindrome(self, x: int) -> bool:
        if x < 0 or (x and x % 10 == 0):
            return False
        y = 0
        while y < x:
            y = y * 10 + x % 10
            x //= 10
        return x in (y, y // 10)
