Minimum White Tiles After Covering With Carpets
<p>You are given a <strong>0-indexed binary</strong> string <code>floor</code>, which represents the colors of tiles on a floor:</p>

<ul>
	<li><code>floor[i] = &#39;0&#39;</code> denotes that the <code>i<sup>th</sup></code> tile of the floor is colored <strong>black</strong>.</li>
	<li>On the other hand, <code>floor[i] = &#39;1&#39;</code> denotes that the <code>i<sup>th</sup></code> tile of the floor is colored <strong>white</strong>.</li>
</ul>

<p>You are also given <code>numCarpets</code> and <code>carpetLen</code>. You have <code>numCarpets</code> <strong>black</strong> carpets, each of length <code>carpetLen</code> tiles. Cover the tiles with the given carpets such that the number of <strong>white</strong> tiles still visible is <strong>minimum</strong>. Carpets may overlap one another.</p>

<p>Return <em>the <strong>minimum</strong> number of white tiles still visible.</em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2200-2299/2209.Minimum%20White%20Tiles%20After%20Covering%20With%20Carpets/images/ex1-1.png" style="width: 400px; height: 73px;" />
<pre>
<strong>Input:</strong> floor = &quot;10110101&quot;, numCarpets = 2, carpetLen = 2
<strong>Output:</strong> 2
<strong>Explanation:</strong> 
The figure above shows one way of covering the tiles with the carpets such that only 2 white tiles are visible.
No other way of covering the tiles with the carpets can leave less than 2 white tiles visible.
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2200-2299/2209.Minimum%20White%20Tiles%20After%20Covering%20With%20Carpets/images/ex2.png" style="width: 353px; height: 123px;" />
<pre>
<strong>Input:</strong> floor = &quot;11111&quot;, numCarpets = 2, carpetLen = 3
<strong>Output:</strong> 0
<strong>Explanation:</strong> 
The figure above shows one way of covering the tiles with the carpets such that no white tiles are visible.
Note that the carpets are able to overlap one another.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= carpetLen &lt;= floor.length &lt;= 1000</code></li>
	<li><code>floor[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>
	<li><code>1 &lt;= numCarpets &lt;= 1000</code></li>
</ul>
String; Dynamic Programming; Prefix Sum
class Solution:
    def minimumWhiteTiles(self, floor: str, numCarpets: int, carpetLen: int) -> int:
        @cache
        def dfs(i: int, j: int) -> int:
            if i >= n:
                return 0
            if floor[i] == "0":
                return dfs(i + 1, j)
            if j == 0:
                return s[-1] - s[i]
            return min(1 + dfs(i + 1, j), dfs(i + carpetLen, j - 1))

        n = len(floor)
        s = [0] * (n + 1)
        for i, c in enumerate(floor):
            s[i + 1] = s[i] + int(c == "1")
        ans = dfs(0, numCarpets)
        dfs.cache_clear()
        return ans
