Can Make Arithmetic Progression From Sequence
<p>A sequence of numbers is called an <strong>arithmetic progression</strong> if the difference between any two consecutive elements is the same.</p>

<p>Given an array of numbers <code>arr</code>, return <code>true</code> <em>if the array can be rearranged to form an <strong>arithmetic progression</strong>. Otherwise, return</em> <code>false</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr = [3,5,1]
<strong>Output:</strong> true
<strong>Explanation: </strong>We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive elements.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr = [1,2,4]
<strong>Output:</strong> false
<strong>Explanation: </strong>There is no way to reorder the elements to obtain an arithmetic progression.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= arr.length &lt;= 1000</code></li>
	<li><code>-10<sup>6</sup> &lt;= arr[i] &lt;= 10<sup>6</sup></code></li>
</ul>
Array; Sorting
function canMakeArithmeticProgression(arr: number[]): boolean {
    arr.sort((a, b) => a - b);
    const n = arr.length;
    for (let i = 2; i < n; i++) {
        if (arr[i - 2] - arr[i - 1] !== arr[i - 1] - arr[i]) {
            return false;
        }
    }
    return true;
}
