Multiply Strings
<p>Given two non-negative integers <code>num1</code> and <code>num2</code> represented as strings, return the product of <code>num1</code> and <code>num2</code>, also represented as a string.</p>

<p><strong>Note:</strong>&nbsp;You must not use any built-in BigInteger library or convert the inputs to integer directly.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> num1 = "2", num2 = "3"
<strong>Output:</strong> "6"
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> num1 = "123", num2 = "456"
<strong>Output:</strong> "56088"
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= num1.length, num2.length &lt;= 200</code></li>
	<li><code>num1</code> and <code>num2</code> consist of digits only.</li>
	<li>Both <code>num1</code> and <code>num2</code>&nbsp;do not contain any leading zero, except the number <code>0</code> itself.</li>
</ul>
Math; String; Simulation
class Solution {
    public String multiply(String num1, String num2) {
        if ("0".equals(num1) || "0".equals(num2)) {
            return "0";
        }
        int m = num1.length(), n = num2.length();
        int[] arr = new int[m + n];
        for (int i = m - 1; i >= 0; --i) {
            int a = num1.charAt(i) - '0';
            for (int j = n - 1; j >= 0; --j) {
                int b = num2.charAt(j) - '0';
                arr[i + j + 1] += a * b;
            }
        }
        for (int i = arr.length - 1; i > 0; --i) {
            arr[i - 1] += arr[i] / 10;
            arr[i] %= 10;
        }
        int i = arr[0] == 0 ? 1 : 0;
        StringBuilder ans = new StringBuilder();
        for (; i < arr.length; ++i) {
            ans.append(arr[i]);
        }
        return ans.toString();
    }
}