Convert an Array Into a 2D Array With Conditions
<p>You are given an integer array <code>nums</code>. You need to create a 2D array from <code>nums</code> satisfying the following conditions:</p>

<ul>
	<li>The 2D array should contain <strong>only</strong> the elements of the array <code>nums</code>.</li>
	<li>Each row in the 2D array contains <strong>distinct</strong> integers.</li>
	<li>The number of rows in the 2D array should be <strong>minimal</strong>.</li>
</ul>

<p>Return <em>the resulting array</em>. If there are multiple answers, return any of them.</p>

<p><strong>Note</strong> that the 2D array can have a different number of elements on each row.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,3,4,1,2,3,1]
<strong>Output:</strong> [[1,3,4,2],[1,3],[1]]
<strong>Explanation:</strong> We can create a 2D array that contains the following rows:
- 1,3,4,2
- 1,3
- 1
All elements of nums were used, and each row of the 2D array contains distinct integers, so it is a valid answer.
It can be shown that we cannot have less than 3 rows in a valid array.</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> [[4,3,2,1]]
<strong>Explanation:</strong> All elements of the array are distinct, so we can keep all of them in the first row of the 2D array.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 200</code></li>
	<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>
</ul>
Array; Hash Table
class Solution:
    def findMatrix(self, nums: List[int]) -> List[List[int]]:
        cnt = Counter(nums)
        ans = []
        for x, v in cnt.items():
            for i in range(v):
                if len(ans) <= i:
                    ans.append([])
                ans[i].append(x)
        return ans
