Largest Substring Between Two Equal Characters
<p>Given a string <code>s</code>, return <em>the length of the longest substring between two equal characters, excluding the two characters.</em> If there is no such substring return <code>-1</code>.</p>

<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;aa&quot;
<strong>Output:</strong> 0
<strong>Explanation:</strong> The optimal substring here is an empty substring between the two <code>&#39;a&#39;s</code>.</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abca&quot;
<strong>Output:</strong> 2
<strong>Explanation:</strong> The optimal substring here is &quot;bc&quot;.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;cbzxy&quot;
<strong>Output:</strong> -1
<strong>Explanation:</strong> There are no characters that appear twice in s.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 300</code></li>
	<li><code>s</code> contains only lowercase English letters.</li>
</ul>
Hash Table; String
class Solution:
    def maxLengthBetweenEqualCharacters(self, s: str) -> int:
        d = {}
        ans = -1
        for i, c in enumerate(s):
            if c in d:
                ans = max(ans, i - d[c] - 1)
            else:
                d[c] = i
        return ans
