Validate Binary Search Tree
<p>Given the <code>root</code> of a binary tree, <em>determine if it is a valid binary search tree (BST)</em>.</p>

<p>A <strong>valid BST</strong> is defined as follows:</p>

<ul>
	<li>The left <span data-keyword="subtree">subtree</span> of a node contains only nodes with keys&nbsp;<strong>strictly less than</strong> the node&#39;s key.</li>
	<li>The right subtree of a node contains only nodes with keys <strong>strictly greater than</strong> the node&#39;s key.</li>
	<li>Both the left and right subtrees must also be binary search trees.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0098.Validate%20Binary%20Search%20Tree/images/tree1.jpg" style="width: 302px; height: 182px;" />
<pre>
<strong>Input:</strong> root = [2,1,3]
<strong>Output:</strong> true
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0098.Validate%20Binary%20Search%20Tree/images/tree2.jpg" style="width: 422px; height: 292px;" />
<pre>
<strong>Input:</strong> root = [5,1,4,null,null,3,6]
<strong>Output:</strong> false
<strong>Explanation:</strong> The root node&#39;s value is 5 but its right child&#39;s value is 4.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>
	<li><code>-2<sup>31</sup> &lt;= Node.val &lt;= 2<sup>31</sup> - 1</code></li>
</ul>
Tree; Depth-First Search; Binary Search Tree; Binary Tree
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    private TreeNode prev;

    public boolean isValidBST(TreeNode root) {
        return dfs(root);
    }

    private boolean dfs(TreeNode root) {
        if (root == null) {
            return true;
        }
        if (!dfs(root.left)) {
            return false;
        }
        if (prev != null && prev.val >= root.val) {
            return false;
        }
        prev = root;
        return dfs(root.right);
    }
}