Binary Tree Coloring Game
<p>Two players play a turn based game on a binary tree. We are given the <code>root</code> of this binary tree, and the number of nodes <code>n</code> in the tree. <code>n</code> is odd, and each node has a distinct value from <code>1</code> to <code>n</code>.</p>

<p>Initially, the first player names a value <code>x</code> with <code>1 &lt;= x &lt;= n</code>, and the second player names a value <code>y</code> with <code>1 &lt;= y &lt;= n</code> and <code>y != x</code>. The first player colors the node with value <code>x</code> red, and the second player colors the node with value <code>y</code> blue.</p>

<p>Then, the players take turns starting with the first player. In each turn, that player chooses a node of their color (red if player 1, blue if player 2) and colors an <strong>uncolored</strong> neighbor of the chosen node (either the left child, right child, or parent of the chosen node.)</p>

<p>If (and only if) a player cannot choose such a node in this way, they must pass their turn. If both players pass their turn, the game ends, and the winner is the player that colored more nodes.</p>

<p>You are the second player. If it is possible to choose such a <code>y</code> to ensure you win the game, return <code>true</code>. If it is not possible, return <code>false</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1100-1199/1145.Binary%20Tree%20Coloring%20Game/images/1480-binary-tree-coloring-game.png" style="width: 500px; height: 310px;" />
<pre>
<strong>Input:</strong> root = [1,2,3,4,5,6,7,8,9,10,11], n = 11, x = 3
<strong>Output:</strong> true
<strong>Explanation: </strong>The second player can choose the node with value 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> root = [1,2,3], n = 3, x = 1
<strong>Output:</strong> false
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in the tree is <code>n</code>.</li>
	<li><code>1 &lt;= x &lt;= n &lt;= 100</code></li>
	<li><code>n</code> is odd.</li>
	<li>1 &lt;= Node.val &lt;= n</li>
	<li>All the values of the tree are <strong>unique</strong>.</li>
</ul>
Tree; Depth-First Search; Binary Tree
/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func btreeGameWinningMove(root *TreeNode, n int, x int) bool {
	var dfs func(*TreeNode) *TreeNode
	dfs = func(root *TreeNode) *TreeNode {
		if root == nil || root.Val == x {
			return root
		}
		node := dfs(root.Left)
		if node != nil {
			return node
		}
		return dfs(root.Right)
	}

	var count func(*TreeNode) int
	count = func(root *TreeNode) int {
		if root == nil {
			return 0
		}
		return 1 + count(root.Left) + count(root.Right)
	}

	node := dfs(root)
	l, r := count(node.Left), count(node.Right)
	return max(max(l, r), n-l-r-1) > n/2
}