Find and Replace Pattern
<p>Given a list of strings <code>words</code> and a string <code>pattern</code>, return <em>a list of</em> <code>words[i]</code> <em>that match</em> <code>pattern</code>. You may return the answer in <strong>any order</strong>.</p>

<p>A word matches the pattern if there exists a permutation of letters <code>p</code> so that after replacing every letter <code>x</code> in the pattern with <code>p(x)</code>, we get the desired word.</p>

<p>Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;abc&quot;,&quot;deq&quot;,&quot;mee&quot;,&quot;aqq&quot;,&quot;dkd&quot;,&quot;ccc&quot;], pattern = &quot;abb&quot;
<strong>Output:</strong> [&quot;mee&quot;,&quot;aqq&quot;]
<strong>Explanation:</strong> &quot;mee&quot; matches the pattern because there is a permutation {a -&gt; m, b -&gt; e, ...}. 
&quot;ccc&quot; does not match the pattern because {a -&gt; c, b -&gt; c, ...} is not a permutation, since a and b map to the same letter.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;], pattern = &quot;a&quot;
<strong>Output:</strong> [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= pattern.length &lt;= 20</code></li>
	<li><code>1 &lt;= words.length &lt;= 50</code></li>
	<li><code>words[i].length == pattern.length</code></li>
	<li><code>pattern</code> and <code>words[i]</code> are lowercase English letters.</li>
</ul>
Array; Hash Table; String
use std::collections::HashMap;
impl Solution {
    pub fn find_and_replace_pattern(words: Vec<String>, pattern: String) -> Vec<String> {
        let pattern = pattern.as_bytes();
        let n = pattern.len();
        words
            .into_iter()
            .filter(|word| {
                let word = word.as_bytes();
                let mut map1 = HashMap::new();
                let mut map2 = HashMap::new();
                for i in 0..n {
                    if map1.get(&word[i]).unwrap_or(&n) != map2.get(&pattern[i]).unwrap_or(&n) {
                        return false;
                    }
                    map1.insert(word[i], i);
                    map2.insert(pattern[i], i);
                }
                true
            })
            .collect()
    }
}
