Rearrange Array Elements by Sign
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of <strong>even</strong> length consisting of an <strong>equal</strong> number of positive and negative integers.</p>

<p>You should return the array of nums such that the the array follows the given conditions:</p>

<ol>
	<li>Every <strong>consecutive pair</strong> of integers have <strong>opposite signs</strong>.</li>
	<li>For all integers with the same sign, the <strong>order</strong> in which they were present in <code>nums</code> is <strong>preserved</strong>.</li>
	<li>The rearranged array begins with a positive integer.</li>
</ol>

<p>Return <em>the modified array after rearranging the elements to satisfy the aforementioned conditions</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,1,-2,-5,2,-4]
<strong>Output:</strong> [3,-2,1,-5,2,-4]
<strong>Explanation:</strong>
The positive integers in nums are [3,1,2]. The negative integers are [-2,-5,-4].
The only possible way to rearrange them such that they satisfy all conditions is [3,-2,1,-5,2,-4].
Other ways such as [1,-2,2,-5,3,-4], [3,1,2,-2,-5,-4], [-2,3,-5,1,-4,2] are incorrect because they do not satisfy one or more conditions.  
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [-1,1]
<strong>Output:</strong> [1,-1]
<strong>Explanation:</strong>
1 is the only positive integer and -1 the only negative integer in nums.
So nums is rearranged to [1,-1].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= nums.length &lt;= 2 * 10<sup>5</sup></code></li>
	<li><code>nums.length</code> is <strong>even</strong></li>
	<li><code>1 &lt;= |nums[i]| &lt;= 10<sup>5</sup></code></li>
	<li><code>nums</code> consists of <strong>equal</strong> number of positive and negative integers.</li>
</ul>

<p>&nbsp;</p>
It is not required to do the modifications in-place.
Array; Two Pointers; Simulation
class Solution:
    def rearrangeArray(self, nums: List[int]) -> List[int]:
        ans = [0] * len(nums)
        i, j = 0, 1
        for x in nums:
            if x > 0:
                ans[i] = x
                i += 2
            else:
                ans[j] = x
                j += 2
        return ans
