Shortest Subarray With OR at Least K I
<p>You are given an array <code>nums</code> of <strong>non-negative</strong> integers and an integer <code>k</code>.</p>

<p>An array is called <strong>special</strong> if the bitwise <code>OR</code> of all of its elements is <strong>at least</strong> <code>k</code>.</p>

<p>Return <em>the length of the <strong>shortest</strong> <strong>special</strong> <strong>non-empty</strong> <span data-keyword="subarray-nonempty">subarray</span> of</em> <code>nums</code>, <em>or return</em> <code>-1</code> <em>if no special subarray exists</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3], k = 2</span></p>

<p><strong>Output:</strong> <span class="example-io">1</span></p>

<p><strong>Explanation:</strong></p>

<p>The subarray <code>[3]</code> has <code>OR</code> value of <code>3</code>. Hence, we return <code>1</code>.</p>

<p>Note that <code>[2]</code> is also a special subarray.</p>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [2,1,8], k = 10</span></p>

<p><strong>Output:</strong> <span class="example-io">3</span></p>

<p><strong>Explanation:</strong></p>

<p>The subarray <code>[2,1,8]</code> has <code>OR</code> value of <code>11</code>. Hence, we return <code>3</code>.</p>
</div>

<p><strong class="example">Example 3:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2], k = 0</span></p>

<p><strong>Output:</strong> <span class="example-io">1</span></p>

<p><strong>Explanation:</strong></p>

<p>The subarray <code>[1]</code> has <code>OR</code> value of <code>1</code>. Hence, we return <code>1</code>.</p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 50</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 50</code></li>
	<li><code>0 &lt;= k &lt; 64</code></li>
</ul>
Bit Manipulation; Array; Sliding Window
class Solution:
    def minimumSubarrayLength(self, nums: List[int], k: int) -> int:
        n = len(nums)
        cnt = [0] * 32
        ans = n + 1
        s = i = 0
        for j, x in enumerate(nums):
            s |= x
            for h in range(32):
                if x >> h & 1:
                    cnt[h] += 1
            while s >= k and i <= j:
                ans = min(ans, j - i + 1)
                y = nums[i]
                for h in range(32):
                    if y >> h & 1:
                        cnt[h] -= 1
                        if cnt[h] == 0:
                            s ^= 1 << h
                i += 1
        return -1 if ans > n else ans
