Latest Time by Replacing Hidden Digits
<p>You are given a string <code>time</code> in the form of <code> hh:mm</code>, where some of the digits in the string are hidden (represented by <code>?</code>).</p>

<p>The valid times are those inclusively between <code>00:00</code> and <code>23:59</code>.</p>

<p>Return <em>the latest valid time you can get from</em> <code>time</code><em> by replacing the hidden</em> <em>digits</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> time = &quot;2?:?0&quot;
<strong>Output:</strong> &quot;23:50&quot;
<strong>Explanation:</strong> The latest hour beginning with the digit &#39;2&#39; is 23 and the latest minute ending with the digit &#39;0&#39; is 50.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> time = &quot;0?:3?&quot;
<strong>Output:</strong> &quot;09:39&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> time = &quot;1?:22&quot;
<strong>Output:</strong> &quot;19:22&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>time</code> is in the format <code>hh:mm</code>.</li>
	<li>It is guaranteed that you can produce a valid time from the given string.</li>
</ul>
Greedy; String
func maximumTime(time string) string {
	t := []byte(time)
	if t[0] == '?' {
		if t[1] >= '4' && t[1] <= '9' {
			t[0] = '1'
		} else {
			t[0] = '2'
		}
	}
	if t[1] == '?' {
		if t[0] == '2' {
			t[1] = '3'
		} else {
			t[1] = '9'
		}
	}
	if t[3] == '?' {
		t[3] = '5'
	}
	if t[4] == '?' {
		t[4] = '9'
	}
	return string(t)
}