Binary Tree Coloring Game
<p>Two players play a turn based game on a binary tree. We are given the <code>root</code> of this binary tree, and the number of nodes <code>n</code> in the tree. <code>n</code> is odd, and each node has a distinct value from <code>1</code> to <code>n</code>.</p>

<p>Initially, the first player names a value <code>x</code> with <code>1 &lt;= x &lt;= n</code>, and the second player names a value <code>y</code> with <code>1 &lt;= y &lt;= n</code> and <code>y != x</code>. The first player colors the node with value <code>x</code> red, and the second player colors the node with value <code>y</code> blue.</p>

<p>Then, the players take turns starting with the first player. In each turn, that player chooses a node of their color (red if player 1, blue if player 2) and colors an <strong>uncolored</strong> neighbor of the chosen node (either the left child, right child, or parent of the chosen node.)</p>

<p>If (and only if) a player cannot choose such a node in this way, they must pass their turn. If both players pass their turn, the game ends, and the winner is the player that colored more nodes.</p>

<p>You are the second player. If it is possible to choose such a <code>y</code> to ensure you win the game, return <code>true</code>. If it is not possible, return <code>false</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1100-1199/1145.Binary%20Tree%20Coloring%20Game/images/1480-binary-tree-coloring-game.png" style="width: 500px; height: 310px;" />
<pre>
<strong>Input:</strong> root = [1,2,3,4,5,6,7,8,9,10,11], n = 11, x = 3
<strong>Output:</strong> true
<strong>Explanation: </strong>The second player can choose the node with value 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> root = [1,2,3], n = 3, x = 1
<strong>Output:</strong> false
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in the tree is <code>n</code>.</li>
	<li><code>1 &lt;= x &lt;= n &lt;= 100</code></li>
	<li><code>n</code> is odd.</li>
	<li>1 &lt;= Node.val &lt;= n</li>
	<li>All the values of the tree are <strong>unique</strong>.</li>
</ul>
Tree; Depth-First Search; Binary Tree
/**
 * Definition for a binary tree node.
 * class TreeNode {
 *     val: number
 *     left: TreeNode | null
 *     right: TreeNode | null
 *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
 *         this.val = (val===undefined ? 0 : val)
 *         this.left = (left===undefined ? null : left)
 *         this.right = (right===undefined ? null : right)
 *     }
 * }
 */

function btreeGameWinningMove(root: TreeNode | null, n: number, x: number): boolean {
    const dfs = (root: TreeNode | null): TreeNode | null => {
        if (!root || root.val === x) {
            return root;
        }
        return dfs(root.left) || dfs(root.right);
    };

    const count = (root: TreeNode | null): number => {
        if (!root) {
            return 0;
        }
        return 1 + count(root.left) + count(root.right);
    };

    const node = dfs(root);
    const l = count(node.left);
    const r = count(node.right);
    return Math.max(l, r, n - l - r - 1) > n / 2;
}
