Last Moment Before All Ants Fall Out of a Plank
<p>We have a wooden plank of the length <code>n</code> <strong>units</strong>. Some ants are walking on the plank, each ant moves with a speed of <strong>1 unit per second</strong>. Some of the ants move to the <strong>left</strong>, the other move to the <strong>right</strong>.</p>

<p>When two ants moving in two <strong>different</strong> directions meet at some point, they change their directions and continue moving again. Assume changing directions does not take any additional time.</p>

<p>When an ant reaches <strong>one end</strong> of the plank at a time <code>t</code>, it falls out of the plank immediately.</p>

<p>Given an integer <code>n</code> and two integer arrays <code>left</code> and <code>right</code>, the positions of the ants moving to the left and the right, return <em>the moment when the last ant(s) fall out of the plank</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1500-1599/1503.Last%20Moment%20Before%20All%20Ants%20Fall%20Out%20of%20a%20Plank/images/ants.jpg" style="width: 450px; height: 610px;" />
<pre>
<strong>Input:</strong> n = 4, left = [4,3], right = [0,1]
<strong>Output:</strong> 4
<strong>Explanation:</strong> In the image above:
-The ant at index 0 is named A and going to the right.
-The ant at index 1 is named B and going to the right.
-The ant at index 3 is named C and going to the left.
-The ant at index 4 is named D and going to the left.
The last moment when an ant was on the plank is t = 4 seconds. After that, it falls immediately out of the plank. (i.e., We can say that at t = 4.0000000001, there are no ants on the plank).
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1500-1599/1503.Last%20Moment%20Before%20All%20Ants%20Fall%20Out%20of%20a%20Plank/images/ants2.jpg" style="width: 639px; height: 101px;" />
<pre>
<strong>Input:</strong> n = 7, left = [], right = [0,1,2,3,4,5,6,7]
<strong>Output:</strong> 7
<strong>Explanation:</strong> All ants are going to the right, the ant at index 0 needs 7 seconds to fall.
</pre>

<p><strong class="example">Example 3:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1500-1599/1503.Last%20Moment%20Before%20All%20Ants%20Fall%20Out%20of%20a%20Plank/images/ants3.jpg" style="width: 639px; height: 100px;" />
<pre>
<strong>Input:</strong> n = 7, left = [0,1,2,3,4,5,6,7], right = []
<strong>Output:</strong> 7
<strong>Explanation:</strong> All ants are going to the left, the ant at index 7 needs 7 seconds to fall.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= left.length &lt;= n + 1</code></li>
	<li><code>0 &lt;= left[i] &lt;= n</code></li>
	<li><code>0 &lt;= right.length &lt;= n + 1</code></li>
	<li><code>0 &lt;= right[i] &lt;= n</code></li>
	<li><code>1 &lt;= left.length + right.length &lt;= n + 1</code></li>
	<li>All values of <code>left</code> and <code>right</code> are unique, and each value can appear <strong>only in one</strong> of the two arrays.</li>
</ul>
Brainteaser; Array; Simulation
func getLastMoment(n int, left []int, right []int) (ans int) {
	for _, x := range left {
		ans = max(ans, x)
	}
	for _, x := range right {
		ans = max(ans, n-x)
	}
	return
}