Rectangle Area
<p>Given the coordinates of two <strong>rectilinear</strong> rectangles in a 2D plane, return <em>the total area covered by the two rectangles</em>.</p>

<p>The first rectangle is defined by its <strong>bottom-left</strong> corner <code>(ax1, ay1)</code> and its <strong>top-right</strong> corner <code>(ax2, ay2)</code>.</p>

<p>The second rectangle is defined by its <strong>bottom-left</strong> corner <code>(bx1, by1)</code> and its <strong>top-right</strong> corner <code>(bx2, by2)</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="Rectangle Area" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0200-0299/0223.Rectangle%20Area/images/rectangle-plane.png" style="width: 700px; height: 365px;" />
<pre>
<strong>Input:</strong> ax1 = -3, ay1 = 0, ax2 = 3, ay2 = 4, bx1 = 0, by1 = -1, bx2 = 9, by2 = 2
<strong>Output:</strong> 45
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> ax1 = -2, ay1 = -2, ax2 = 2, ay2 = 2, bx1 = -2, by1 = -2, bx2 = 2, by2 = 2
<strong>Output:</strong> 16
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-10<sup>4</sup> &lt;= ax1 &lt;= ax2 &lt;= 10<sup>4</sup></code></li>
	<li><code>-10<sup>4</sup> &lt;= ay1 &lt;= ay2 &lt;= 10<sup>4</sup></code></li>
	<li><code>-10<sup>4</sup> &lt;= bx1 &lt;= bx2 &lt;= 10<sup>4</sup></code></li>
	<li><code>-10<sup>4</sup> &lt;= by1 &lt;= by2 &lt;= 10<sup>4</sup></code></li>
</ul>
Geometry; Math
class Solution {
public:
    int computeArea(int ax1, int ay1, int ax2, int ay2, int bx1, int by1, int bx2, int by2) {
        int a = (ax2 - ax1) * (ay2 - ay1);
        int b = (bx2 - bx1) * (by2 - by1);
        int width = min(ax2, bx2) - max(ax1, bx1);
        int height = min(ay2, by2) - max(ay1, by1);
        return a + b - max(height, 0) * max(width, 0);
    }
};