Container With Most Water
<p>You are given an integer array <code>height</code> of length <code>n</code>. There are <code>n</code> vertical lines drawn such that the two endpoints of the <code>i<sup>th</sup></code> line are <code>(i, 0)</code> and <code>(i, height[i])</code>.</p>

<p>Find two lines that together with the x-axis form a container, such that the container contains the most water.</p>

<p>Return <em>the maximum amount of water a container can store</em>.</p>

<p><strong>Notice</strong> that you may not slant the container.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0011.Container%20With%20Most%20Water/images/question_11.jpg" style="width: 600px; height: 287px;" />
<pre>
<strong>Input:</strong> height = [1,8,6,2,5,4,8,3,7]
<strong>Output:</strong> 49
<strong>Explanation:</strong> The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> height = [1,1]
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == height.length</code></li>
	<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>
	<li><code>0 &lt;= height[i] &lt;= 10<sup>4</sup></code></li>
</ul>
Greedy; Array; Two Pointers
class Solution {
    /**
     * @param Integer[] $height
     * @return Integer
     */
    function maxArea($height) {
        $l = 0;
        $r = count($height) - 1;
        $ans = 0;
        while ($l < $r) {
            $t = min($height[$l], $height[$r]) * ($r - $l);
            $ans = max($ans, $t);
            if ($height[$l] < $height[$r]) {
                ++$l;
            } else {
                --$r;
            }
        }
        return $ans;
    }
}
