Binary Prefix Divisible By 5
<p>You are given a binary array <code>nums</code> (<strong>0-indexed</strong>).</p>

<p>We define <code>x<sub>i</sub></code> as the number whose binary representation is the subarray <code>nums[0..i]</code> (from most-significant-bit to least-significant-bit).</p>

<ul>
	<li>For example, if <code>nums = [1,0,1]</code>, then <code>x<sub>0</sub> = 1</code>, <code>x<sub>1</sub> = 2</code>, and <code>x<sub>2</sub> = 5</code>.</li>
</ul>

<p>Return <em>an array of booleans </em><code>answer</code><em> where </em><code>answer[i]</code><em> is </em><code>true</code><em> if </em><code>x<sub>i</sub></code><em> is divisible by </em><code>5</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [0,1,1]
<strong>Output:</strong> [true,false,false]
<strong>Explanation:</strong> The input numbers in binary are 0, 01, 011; which are 0, 1, and 3 in base-10.
Only the first number is divisible by 5, so answer[0] is true.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,1,1]
<strong>Output:</strong> [false,false,false]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>
Bit Manipulation; Array
class Solution:
    def prefixesDivBy5(self, nums: List[int]) -> List[bool]:
        ans = []
        x = 0
        for v in nums:
            x = (x << 1 | v) % 5
            ans.append(x == 0)
        return ans
