Find Minimum Time to Finish All Jobs
<p>You are given an integer array <code>jobs</code>, where <code>jobs[i]</code> is the amount of time it takes to complete the <code>i<sup>th</sup></code> job.</p>

<p>There are <code>k</code> workers that you can assign jobs to. Each job should be assigned to <strong>exactly</strong> one worker. The <strong>working time</strong> of a worker is the sum of the time it takes to complete all jobs assigned to them. Your goal is to devise an optimal assignment such that the <strong>maximum working time</strong> of any worker is <strong>minimized</strong>.</p>

<p><em>Return the <strong>minimum</strong> possible <strong>maximum working time</strong> of any assignment. </em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> jobs = [3,2,3], k = 3
<strong>Output:</strong> 3
<strong>Explanation:</strong> By assigning each person one job, the maximum time is 3.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> jobs = [1,2,4,7,8], k = 2
<strong>Output:</strong> 11
<strong>Explanation:</strong> Assign the jobs the following way:
Worker 1: 1, 2, 8 (working time = 1 + 2 + 8 = 11)
Worker 2: 4, 7 (working time = 4 + 7 = 11)
The maximum working time is 11.</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= k &lt;= jobs.length &lt;= 12</code></li>
	<li><code>1 &lt;= jobs[i] &lt;= 10<sup>7</sup></code></li>
</ul>
Bit Manipulation; Array; Dynamic Programming; Backtracking; Bitmask
func minimumTimeRequired(jobs []int, k int) int {
	cnt := make([]int, k)
	ans := 0x3f3f3f3f
	sort.Slice(jobs, func(i, j int) bool {
		return jobs[i] > jobs[j]
	})
	var dfs func(int)
	dfs = func(i int) {
		if i == len(jobs) {
			mx := slices.Max(cnt)
			ans = min(ans, mx)
			return
		}
		for j := 0; j < k; j++ {
			if cnt[j]+jobs[i] >= ans {
				continue
			}
			cnt[j] += jobs[i]
			dfs(i + 1)
			cnt[j] -= jobs[i]
			if cnt[j] == 0 {
				break
			}
		}
	}
	dfs(0)
	return ans
}