Maximum Product of Three Numbers
<p>Given an integer array <code>nums</code>, <em>find three numbers whose product is maximum and return the maximum product</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> nums = [1,2,3]
<strong>Output:</strong> 6
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> 24
</pre><p><strong class="example">Example 3:</strong></p>
<pre><strong>Input:</strong> nums = [-1,-2,-3]
<strong>Output:</strong> -6
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>3 &lt;= nums.length &lt;=&nbsp;10<sup>4</sup></code></li>
	<li><code>-1000 &lt;= nums[i] &lt;= 1000</code></li>
</ul>
Array; Math; Sorting
class Solution:
    def maximumProduct(self, nums: List[int]) -> int:
        nums.sort()
        a = nums[-1] * nums[-2] * nums[-3]
        b = nums[-1] * nums[0] * nums[1]
        return max(a, b)
