Find Target Indices After Sorting Array
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and a target element <code>target</code>.</p>

<p>A <strong>target index</strong> is an index <code>i</code> such that <code>nums[i] == target</code>.</p>

<p>Return <em>a list of the target indices of</em> <code>nums</code> after<em> sorting </em><code>nums</code><em> in <strong>non-decreasing</strong> order</em>. If there are no target indices, return <em>an <strong>empty</strong> list</em>. The returned list must be sorted in <strong>increasing</strong> order.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,5,2,3], target = 2
<strong>Output:</strong> [1,2]
<strong>Explanation:</strong> After sorting, nums is [1,<u><strong>2</strong></u>,<u><strong>2</strong></u>,3,5].
The indices where nums[i] == 2 are 1 and 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,5,2,3], target = 3
<strong>Output:</strong> [3]
<strong>Explanation:</strong> After sorting, nums is [1,2,2,<u><strong>3</strong></u>,5].
The index where nums[i] == 3 is 3.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,5,2,3], target = 5
<strong>Output:</strong> [4]
<strong>Explanation:</strong> After sorting, nums is [1,2,2,3,<u><strong>5</strong></u>].
The index where nums[i] == 5 is 4.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 100</code></li>
	<li><code>1 &lt;= nums[i], target &lt;= 100</code></li>
</ul>
Array; Binary Search; Sorting
class Solution {
    public List<Integer> targetIndices(int[] nums, int target) {
        Arrays.sort(nums);
        List<Integer> ans = new ArrayList<>();
        for (int i = 0; i < nums.length; ++i) {
            if (nums[i] == target) {
                ans.add(i);
            }
        }
        return ans;
    }
}