Reducing Dishes
<p>A chef has collected data on the <code>satisfaction</code> level of his <code>n</code> dishes. Chef can cook any dish in 1 unit of time.</p>

<p><strong>Like-time coefficient</strong> of a dish is defined as the time taken to cook that dish including previous dishes multiplied by its satisfaction level i.e. <code>time[i] * satisfaction[i]</code>.</p>

<p>Return the maximum sum of <strong>like-time coefficient </strong>that the chef can obtain after preparing some amount of dishes.</p>

<p>Dishes can be prepared in <strong>any </strong>order and the chef can discard some dishes to get this maximum value.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> satisfaction = [-1,-8,0,5,-9]
<strong>Output:</strong> 14
<strong>Explanation:</strong> After Removing the second and last dish, the maximum total <strong>like-time coefficient</strong> will be equal to (-1*1 + 0*2 + 5*3 = 14).
Each dish is prepared in one unit of time.</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> satisfaction = [4,3,2]
<strong>Output:</strong> 20
<strong>Explanation:</strong> Dishes can be prepared in any order, (2*1 + 3*2 + 4*3 = 20)
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> satisfaction = [-1,-4,-5]
<strong>Output:</strong> 0
<strong>Explanation:</strong> People do not like the dishes. No dish is prepared.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == satisfaction.length</code></li>
	<li><code>1 &lt;= n &lt;= 500</code></li>
	<li><code>-1000 &lt;= satisfaction[i] &lt;= 1000</code></li>
</ul>
Greedy; Array; Dynamic Programming; Sorting
func maxSatisfaction(satisfaction []int) (ans int) {
	sort.Slice(satisfaction, func(i, j int) bool { return satisfaction[i] > satisfaction[j] })
	s := 0
	for _, x := range satisfaction {
		s += x
		if s <= 0 {
			break
		}
		ans += s
	}
	return
}