Arithmetic Slices
<p>An integer array is called arithmetic if it consists of <strong>at least three elements</strong> and if the difference between any two consecutive elements is the same.</p>

<ul>
	<li>For example, <code>[1,3,5,7,9]</code>, <code>[7,7,7,7]</code>, and <code>[3,-1,-5,-9]</code> are arithmetic sequences.</li>
</ul>

<p>Given an integer array <code>nums</code>, return <em>the number of arithmetic <strong>subarrays</strong> of</em> <code>nums</code>.</p>

<p>A <strong>subarray</strong> is a contiguous subsequence of the array.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> 3
<strong>Explanation:</strong> We have 3 arithmetic slices in nums: [1, 2, 3], [2, 3, 4] and [1,2,3,4] itself.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1]
<strong>Output:</strong> 0
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 5000</code></li>
	<li><code>-1000 &lt;= nums[i] &lt;= 1000</code></li>
</ul>
Array; Dynamic Programming; Sliding Window
class Solution:
    def numberOfArithmeticSlices(self, nums: List[int]) -> int:
        ans = cnt = 0
        d = 3000
        for a, b in pairwise(nums):
            if b - a == d:
                cnt += 1
            else:
                d = b - a
                cnt = 0
            ans += cnt
        return ans
