Minimum Moves to Equal Array Elements
<p>Given an integer array <code>nums</code> of size <code>n</code>, return <em>the minimum number of moves required to make all array elements equal</em>.</p>

<p>In one move, you can increment <code>n - 1</code> elements of the array by <code>1</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3]
<strong>Output:</strong> 3
<strong>Explanation:</strong> Only three moves are needed (remember each move increments two elements):
[1,2,3]  =&gt;  [2,3,3]  =&gt;  [3,4,3]  =&gt;  [4,4,4]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,1,1]
<strong>Output:</strong> 0
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == nums.length</code></li>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
	<li>The answer is guaranteed to fit in a <strong>32-bit</strong> integer.</li>
</ul>
Array; Math
class Solution:
    def minMoves(self, nums: List[int]) -> int:
        return sum(nums) - min(nums) * len(nums)
