Leftmost Column with at Least a One
<p>A <strong>row-sorted binary matrix</strong> means that all elements are <code>0</code> or <code>1</code> and each row of the matrix is sorted in non-decreasing order.</p>

<p>Given a <strong>row-sorted binary matrix</strong> <code>binaryMatrix</code>, return <em>the index (0-indexed) of the <strong>leftmost column</strong> with a 1 in it</em>. If such an index does not exist, return <code>-1</code>.</p>

<p><strong>You can&#39;t access the Binary Matrix directly.</strong> You may only access the matrix using a <code>BinaryMatrix</code> interface:</p>

<ul>
	<li><code>BinaryMatrix.get(row, col)</code> returns the element of the matrix at index <code>(row, col)</code> (0-indexed).</li>
	<li><code>BinaryMatrix.dimensions()</code> returns the dimensions of the matrix as a list of 2 elements <code>[rows, cols]</code>, which means the matrix is <code>rows x cols</code>.</li>
</ul>

<p>Submissions making more than <code>1000</code> calls to <code>BinaryMatrix.get</code> will be judged <em>Wrong Answer</em>. Also, any solutions that attempt to circumvent the judge will result in disqualification.</p>

<p>For custom testing purposes, the input will be the entire binary matrix <code>mat</code>. You will not have access to the binary matrix directly.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1400-1499/1428.Leftmost%20Column%20with%20at%20Least%20a%20One/images/untitled-diagram-5.jpg" style="width: 81px; height: 81px;" />
<pre>
<strong>Input:</strong> mat = [[0,0],[1,1]]
<strong>Output:</strong> 0
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1400-1499/1428.Leftmost%20Column%20with%20at%20Least%20a%20One/images/untitled-diagram-4.jpg" style="width: 81px; height: 81px;" />
<pre>
<strong>Input:</strong> mat = [[0,0],[0,1]]
<strong>Output:</strong> 1
</pre>

<p><strong class="example">Example 3:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1400-1499/1428.Leftmost%20Column%20with%20at%20Least%20a%20One/images/untitled-diagram-3.jpg" style="width: 81px; height: 81px;" />
<pre>
<strong>Input:</strong> mat = [[0,0],[0,0]]
<strong>Output:</strong> -1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>rows == mat.length</code></li>
	<li><code>cols == mat[i].length</code></li>
	<li><code>1 &lt;= rows, cols &lt;= 100</code></li>
	<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
	<li><code>mat[i]</code> is sorted in non-decreasing order.</li>
</ul>
Array; Binary Search; Interactive; Matrix
/**
 * // This is the BinaryMatrix's API interface.
 * // You should not implement it, or speculate about its implementation
 * class BinaryMatrix {
 *      get(row: number, col: number): number {}
 *
 *      dimensions(): number[] {}
 * }
 */

function leftMostColumnWithOne(binaryMatrix: BinaryMatrix) {
    const [m, n] = binaryMatrix.dimensions();
    let ans = n;
    for (let i = 0; i < m; ++i) {
        let [l, r] = [0, n];
        while (l < r) {
            const mid = (l + r) >> 1;
            if (binaryMatrix.get(i, mid) === 1) {
                r = mid;
            } else {
                l = mid + 1;
            }
        }
        ans = Math.min(ans, l);
    }
    return ans >= n ? -1 : ans;
}
