Maximum Average Subarray I
<p>You are given an integer array <code>nums</code> consisting of <code>n</code> elements, and an integer <code>k</code>.</p>

<p>Find a contiguous subarray whose <strong>length is equal to</strong> <code>k</code> that has the maximum average value and return <em>this value</em>. Any answer with a calculation error less than <code>10<sup>-5</sup></code> will be accepted.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,12,-5,-6,50,3], k = 4
<strong>Output:</strong> 12.75000
<strong>Explanation:</strong> Maximum average is (12 - 5 - 6 + 50) / 4 = 51 / 4 = 12.75
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [5], k = 1
<strong>Output:</strong> 5.00000
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == nums.length</code></li>
	<li><code>1 &lt;= k &lt;= n &lt;= 10<sup>5</sup></code></li>
	<li><code>-10<sup>4</sup> &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
</ul>
Array; Sliding Window
impl Solution {
    pub fn find_max_average(nums: Vec<i32>, k: i32) -> f64 {
        let k = k as usize;
        let n = nums.len();
        let mut s = nums.iter().take(k).sum::<i32>();
        let mut ans = s;
        for i in k..n {
            s += nums[i] - nums[i - k];
            ans = ans.max(s);
        }
        f64::from(ans) / f64::from(k as i32)
    }
}
