Find First Palindromic String in the Array
<p>Given an array of strings <code>words</code>, return <em>the first <strong>palindromic</strong> string in the array</em>. If there is no such string, return <em>an <strong>empty string</strong> </em><code>&quot;&quot;</code>.</p>

<p>A string is <strong>palindromic</strong> if it reads the same forward and backward.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;abc&quot;,&quot;car&quot;,&quot;ada&quot;,&quot;racecar&quot;,&quot;cool&quot;]
<strong>Output:</strong> &quot;ada&quot;
<strong>Explanation:</strong> The first string that is palindromic is &quot;ada&quot;.
Note that &quot;racecar&quot; is also palindromic, but it is not the first.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;notapalindrome&quot;,&quot;racecar&quot;]
<strong>Output:</strong> &quot;racecar&quot;
<strong>Explanation:</strong> The first and only string that is palindromic is &quot;racecar&quot;.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;def&quot;,&quot;ghi&quot;]
<strong>Output:</strong> &quot;&quot;
<strong>Explanation:</strong> There are no palindromic strings, so the empty string is returned.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= words.length &lt;= 100</code></li>
	<li><code>1 &lt;= words[i].length &lt;= 100</code></li>
	<li><code>words[i]</code> consists only of lowercase English letters.</li>
</ul>
Array; Two Pointers; String
class Solution {
    public String firstPalindrome(String[] words) {
        for (var w : words) {
            boolean ok = true;
            for (int i = 0, j = w.length() - 1; i < j && ok; ++i, --j) {
                if (w.charAt(i) != w.charAt(j)) {
                    ok = false;
                }
            }
            if (ok) {
                return w;
            }
        }
        return "";
    }
}