Restore IP Addresses
<p>A <strong>valid IP address</strong> consists of exactly four integers separated by single dots. Each integer is between <code>0</code> and <code>255</code> (<strong>inclusive</strong>) and cannot have leading zeros.</p>

<ul>
	<li>For example, <code>&quot;0.1.2.201&quot;</code> and <code>&quot;192.168.1.1&quot;</code> are <strong>valid</strong> IP addresses, but <code>&quot;0.011.255.245&quot;</code>, <code>&quot;192.168.1.312&quot;</code> and <code>&quot;192.168@1.1&quot;</code> are <strong>invalid</strong> IP addresses.</li>
</ul>

<p>Given a string <code>s</code> containing only digits, return <em>all possible valid IP addresses that can be formed by inserting dots into </em><code>s</code>. You are <strong>not</strong> allowed to reorder or remove any digits in <code>s</code>. You may return the valid IP addresses in <strong>any</strong> order.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;25525511135&quot;
<strong>Output:</strong> [&quot;255.255.11.135&quot;,&quot;255.255.111.35&quot;]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;0000&quot;
<strong>Output:</strong> [&quot;0.0.0.0&quot;]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;101023&quot;
<strong>Output:</strong> [&quot;1.0.10.23&quot;,&quot;1.0.102.3&quot;,&quot;10.1.0.23&quot;,&quot;10.10.2.3&quot;,&quot;101.0.2.3&quot;]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 20</code></li>
	<li><code>s</code> consists of digits only.</li>
</ul>
String; Backtracking
public class Solution {
    private IList<string> ans = new List<string>();
    private IList<string> t = new List<string>();
    private int n;
    private string s;

    public IList<string> RestoreIpAddresses(string s) {
        n = s.Length;
        this.s = s;
        dfs(0);
        return ans;
    }

    private void dfs(int i) {
        if (i >= n && t.Count == 4) {
            ans.Add(string.Join(".", t));
            return;
        }
        if (i >= n || t.Count == 4) {
            return;
        }
        int x = 0;
        for (int j = i; j < i + 3 && j < n; ++j) {
            x = x * 10 + (s[j] - '0');
            if (x > 255 || (j > i && s[i] == '0')) {
                break;
            }
            t.Add(x.ToString());
            dfs(j + 1);
            t.RemoveAt(t.Count - 1);
        }
    }
}
