lets factor a x/2 out now the first term is 2x cube since we factored a 1/2 out we need to multiply by 2 the second term is plus 7x square the third term is 4x since we factored a 1/2 out we need to multiply by 2 and lastly fourth term is minus 4 since we factored a 1/2 out we need to multiply by 2 now if we re-write g(x) observe what we have as its factors now both p(x) and g(x) has x/2 as a common factor... now isn't that part of its GCD/GCF? now all that we need to find is if there are any more common factor(s) in p(x) and g(x)..........confused? yeah me too!! we shall use the Euclidean Algorithm to find the other common factor of p(x) and g(x) the DlVIDEND is the other factor of g(x) the DlVISOR is the other factor of p(x) so now we DlVIDE both the polynomials...ok observe the steps during this division process we can factor out any integer that's common and ignore it...they are just not part of Euclidean Division here in this case it is integer 3 that we shall ignore ... ok 