#include <bits/stdc++.h>
using namespace std;
void do1(int n) {
  int i, t = 0;
  printf("1 * 2 = 2\n");
  printf("2 * 3 = 6\n");
  printf("6 * 4 = 24\n");
  for (i = 1; i < (n / 4); i++) {
    int a = 4 * i + 1, b = 4 * i + 2, c = 4 * i + 3, d = 4 * i + 4;
    printf("%d + %d = %d\n", a, d, a + d);
    printf("%d + %d = %d\n", b, c, b + c);
    printf("%d - %d = 0\n", a + d, b + c);
    printf("24 + 0 = 24\n");
  }
}
void do2(int n) {
  int i, t = 1;
  printf("5 + 3 = 8\n");
  printf("8 - 2 = 6\n");
  printf("6 * 4 = 24\n");
  printf("1 * 24 = 24\n");
  for (i = 1; i < (n / 4); i++) {
    int a = 4 * i + 1, b = 4 * i + 2, c = 4 * i + 3, d = 4 * i + 4;
    a += t;
    b += t;
    c += t;
    d += t;
    printf("%d + %d = %d\n", a, d, a + d);
    printf("%d + %d = %d\n", b, c, b + c);
    printf("%d - %d = 0\n", a + d, b + c);
    printf("24 + 0 = 24\n");
  }
}
void do3(int n) {
  int i, t = 2;
  printf("6 + 5 = 11\n");
  printf("11 - 2 = 9\n");
  printf("9 - 3 = 6\n");
  printf("6 * 4 = 24\n");
  printf("1 * 24 = 24\n");
  for (i = 1; i < (n / 4); i++) {
    int a = 4 * i + 1, b = 4 * i + 2, c = 4 * i + 3, d = 4 * i + 4;
    a += t;
    b += t;
    c += t;
    d += t;
    printf("%d + %d = %d\n", a, d, a + d);
    printf("%d + %d = %d\n", b, c, b + c);
    printf("%d - %d = 0\n", a + d, b + c);
    printf("24 + 0 = 24\n");
  }
}
void do4(int n) {
  int i, t = 3;
  printf("7 - 6 = 1\n");
  printf("1 + 5 = 6\n");
  printf("6 + 3 = 9\n");
  printf("9 - 2 = 7\n");
  printf("7 - 1 = 6\n");
  printf("6 * 4 = 24\n");
  for (i = 1; i < (n / 4); i++) {
    int a = 4 * i + 1, b = 4 * i + 2, c = 4 * i + 3, d = 4 * i + 4;
    a += t;
    b += t;
    c += t;
    d += t;
    printf("%d + %d = %d\n", a, d, a + d);
    printf("%d + %d = %d\n", b, c, b + c);
    printf("%d - %d = 0\n", a + d, b + c);
    printf("24 + 0 = 24\n");
  }
}
int main() {
  int n;
  scanf("%d", &n);
  if (n < 4)
    printf("NO\n");
  else {
    printf("YES\n");
    if (n % 4 == 0)
      do1(n);
    else if (n % 4 == 1)
      do2(n);
    else if (n % 4 == 2)
      do3(n);
    else if (n % 4 == 3)
      do4(n);
  }
  return 0;
}
