#include <bits/stdc++.h>
using namespace std;
const long long INF = 1e9 + 10, MAX = 2e5 + 1e4, MOD = 1e9 + 7, MAXL = 25;
void OUT(long double o, int x) {
  cout << fixed << setprecision(x) << o;
  return;
}
pair<pair<long long, long long>, pair<long long, long long> > a[MAX];
pair<long long, long long> b[MAX];
double seg[4 * MAX];
int bsl(int s, int e, int k) {
  if (s == e) return s;
  int m = (s + e) / 2;
  if (b[m].first < k) return bsl(m + 1, e, k);
  return bsl(s, m, k);
}
int bsr(int s, int e, int k) {
  if (s == e) return s;
  int m = ((s + e) / 2) + 1;
  if (b[m].first > k) return bsr(s, m - 1, k);
  return bsr(m, e, k);
}
void upd(int id, int b, int e, int l, int r, double x) {
  if (e <= l || r <= b) return;
  if (l <= b && e <= r) {
    seg[id] *= x;
    return;
  }
  int m = (b + e) / 2;
  upd(id * 2, b, m, l, r, x);
  upd(id * 2 + 1, m, e, l, r, x);
  return;
}
double geta(int id, int b, int e, int x) {
  if (e - b == 1) return seg[id];
  int m = (b + e) / 2;
  if (x < m) return seg[id] * geta(id * 2, b, m, x);
  return seg[id] * geta(id * 2 + 1, m, e, x);
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  long long n, m;
  cin >> n >> m;
  for (int i = 0; i < n; i++)
    cin >> a[i].first.first >> a[i].first.second >> a[i].second.first >>
        a[i].second.second;
  for (int i = 0; i < m; i++) cin >> b[i].first >> b[i].second;
  sort(a, a + n);
  sort(b, b + m);
  for (int i = 0; i <= 4 * m; i++) seg[i] = 1.0;
  for (int i = 0; i < n; i++) {
    long long l = bsl(0, m - 1, a[i].first.first - a[i].first.second),
              r = bsr(0, m - 1, a[i].first.first + a[i].first.second);
    long long ri = bsl(0, m - 1, a[i].first.first + 1),
              li = bsr(0, m - 1, a[i].first.first - 1);
    if (b[l].first < a[i].first.first &&
        b[l].first >= a[i].first.first - a[i].first.second)
      upd(1, 0, m, l, li + 1, ((100 - a[i].second.first) * 1.0) / 100.0);
    if (a[i].first.first < b[r].first &&
        b[r].first <= a[i].first.first + a[i].first.second)
      upd(1, 0, m, ri, r + 1, ((100 - a[i].second.second) * 1.0) / 100.0);
  }
  long double x = 0.0;
  for (int i = 0; i < m; i++) x += geta(1, 0, m, i) * b[i].second;
  cout << fixed << setprecision(6) << x;
  return 0;
}
