#include <bits/stdc++.h>
using namespace std;
int n, k, q, t, x, y, s;
int last[100005], mx[100005], reg[100005], arr[100005];
long long bas[405][405], son[405][405], ok[405];
vector<pair<double, int> > V[405];
long long calc(int x, int b, int s, int t) {
  int i;
  long long sum = 0;
  if (ok[x] == -1) {
    if (s - b + 1 == k) {
      for (i = b; i <= s; i++) {
        sum +=
            min((long long)mx[i], reg[i] * (long long)(t - arr[i]) + last[i]);
        arr[i] = t;
        last[i] = 0;
      }
      ok[x] = t;
      return sum;
    }
    for (i = b; i <= s; i++) {
      sum += min((long long)(t - arr[i]) * reg[i] + last[i], (long long)mx[i]);
      last[i] = 0;
      arr[i] = t;
    }
    return sum;
  }
  if (s - b + 1 == k) {
    int p =
        upper_bound(V[x].begin(), V[x].end(), make_pair((double)t - ok[x], 0)) -
        V[x].begin();
    sum = (!!p) * bas[x][p - 1] + ((p < V[x].size()) * son[x][p] * (t - ok[x]));
    ok[x] = t;
    return sum;
  }
  for (i = (x - 1) * k + 1; i <= x * k; i++) {
    if (i < b or i > s) {
      arr[i] = ok[x];
    } else {
      sum += min((long long)(t - ok[x]) * reg[i] + last[i], (long long)mx[i]);
      last[i] = 0;
      arr[i] = t;
    }
  }
  ok[x] = -1;
  return sum;
}
int main() {
  cin >> n;
  k = sqrt(n);
  int i, j;
  for (i = 1; i <= n; i++) scanf("%d %d %d", last + i, mx + i, reg + i);
  for (i = 1; i <= n; i += k) {
    int s = i / k + 1;
    for (j = i; j < i + k; j++)
      if (!reg[j])
        V[s].push_back(make_pair(10000000.0, j));
      else
        V[s].push_back(make_pair((double)mx[j] / reg[j], j));
    sort(V[s].begin(), V[s].end());
    for (j = 0; j < k; j++) bas[s][j] = mx[V[s][j].second] + bas[s][j - 1];
    for (j = k - 1; j >= 0; j--)
      son[s][j] = son[s][j + 1] + reg[V[s][j].second];
  }
  memset(ok, -1, sizeof ok);
  cin >> q;
  for (i = 1; i <= q; i++) {
    scanf("%d %d %d", &t, &x, &y);
    long long ans = 0;
    for (j = 1; j <= y; j += k)
      if (x < j + k) ans += calc(j / k + 1, max(j, x), min(j + k - 1, y), t);
    printf("%lld\n", ans);
  }
  return 0;
}
