#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  long long m;
  cin >> m;
  long long int cost[125], cost2[125], cost3[125], a[100001], b[100001];
  int n = cbrt(m);
  if (n * n * n != m) {
    n++;
  }
  cost[0] = cost2[0] = 0;
  for (int i = 1; i < 125; i++) {
    int j = i;
    while (j >= 64) {
      cost[i]++;
      j -= 64;
    }
    while (j >= 27) {
      cost[i]++;
      j -= 27;
    }
    while (j >= 8) {
      cost[i]++;
      j -= 8;
    }
    while (j >= 1) {
      cost[i]++;
      j -= 1;
    }
    a[5] = max(a[5], cost[i]);
    if (cost[i] >= cost2[i - 1]) {
      cost3[i] = i;
    } else {
      cost3[i] = cost3[i - 1];
    }
    cost2[i] = max(cost[i], cost2[i - 1]);
  }
  if (m < 125) {
    cout << cost2[m] << ' ' << cost3[m] << endl;
    return 0;
  }
  a[5] = cost2[124], b[5] = cost3[124];
  for (long long int i = 6; i <= 100000; i++) {
    a[i] = a[i - 1];
    b[i] = b[i - 1];
    long long int taken = 0, left = i * i * i - 1;
    long long c = 0;
    long long int l = 5, r = i, mid;
    while (true) {
      r--;
      l = 5;
      if (r < l || l * l * l > left) {
        break;
      }
      while (l != r) {
        mid = (l + r + 1) / 2;
        if (mid * mid * mid <= left) {
          l = mid;
        } else {
          r = mid - 1;
        }
      }
      left -= l * l * l;
      if (taken + a[l] > a[i] || taken + a[l] == a[i] && b[l] + c > b[i]) {
        a[i] = taken + a[l];
        b[i] = b[l] + c;
      }
      c += l * l * l;
      taken++;
    }
    if (taken + cost2[left] > a[i] ||
        taken + cost2[left] == a[i] && cost3[left] + c > b[i]) {
      a[i] = taken + cost2[left];
      b[i] = cost3[left] + c;
    }
  }
  long long aa = 0, bb = 0, taken = 0, c = 0;
  for (long long i = 100000; i >= 5; i--) {
    if (i * i * i <= m) {
      m -= i * i * i;
      if (a[i] + taken > aa || a[i] + taken == aa && b[i] + c > bb) {
        aa = a[i] + taken;
        bb = b[i] + c;
      }
      c += i * i * i;
      taken++;
    }
  }
  if (taken + cost2[m] > aa || taken + cost2[m] == aa && cost3[m] + c > bb) {
    aa = taken + cost2[m];
    bb = cost3[m] + c;
  }
  cout << aa << ' ' << bb << endl;
}
