#include<iostream> 
#include<algorithm>
#include<climits>

using namespace std;

#define N 5
#define REP(i, n) for ( int i = 0; i < (int)n; i++ )
#define LIMIT 20

// S[ÌÇ±É éÌ©
static const int T[12][2] = {
	{-1, -1},
	{1, 1},
	{1, 2},
	{1, 3},
	{2, 0},
	{2, 1},
	{2, 2},
	{2, 3},
	{2, 4},
	{3, 1},
	{3, 2},
	{3, 3}
};

// S[Ìzu
static const int g[N][N] = {
	{-1, -1,  0, -1, -1},
	{-1,  1,  2,  3, -1},
	{ 4,  5,  6,  7,  8},
	{-1,  9, 10, 11, -1},
	{-1, -1,  0, -1, -1}
};

class Puzzle
{
public:
	int C[N][N], mdist; //manhatta distance
	Puzzle(){}
	
	bool swapAdj( int si, int sj, int ti, int tj )
	{
		if ( ti < 0 || tj < 0 || ti >= N || tj >= N )
			return false;
		if ( C[ti][tj] <= 0 )
			return false;

		swap( C[ti][tj], C[si][sj] );

		int tti = T[C[si][sj]][0];
		int ttj = T[C[si][sj]][1];
		mdist -= max(tti, ti)-min(tti, ti) + max(ttj, tj)-min(ttj, tj);
		mdist += max(tti, si)-min(tti, si) + max(ttj, sj)-min(ttj, sj);
		return true;
	}
	
	bool isGoal()
	{
		REP(i, N) REP(j, N)
			if ( g[i][j] != C[i][j] )
				return false;
		return true;
	}
	
	// get initial manhattan distance
	int getMD()
	{
		int sum = 0;
		int ti, tj;
		REP(i, 5) REP(j, 5)
		{
			if ( C[i][j] <= 0 )
				continue;
			ti = T[C[i][j]][0];
			tj = T[C[i][j]][1];
			sum += (max(ti, i)-min(ti, i) + max(tj, j) - min(tj, j));
		}
		return sum;
	}
};
 
int limit;
 
bool dfs( int depth, Puzzle P )
{
	if ( P.isGoal() )
		return true;
	if ( depth + P.getMD() > limit )
		return false;
	
	static const int di[4] = {0, -1, 0, 1};
	static const int dj[4] = {1, 0, -1, 0};
	
	REP(i, N) REP(j, N)
	{
		if ( P.C[i][j] != 0 )
			continue;

		REP(r, 4)
		{
			Puzzle v = P;
			if ( !v.swapAdj(i, j, i+di[r], j+dj[r]) )
				continue;
			if ( dfs( depth + 1, v ) )
				return true;
		}
	}
	
	return false;
}

int idp(Puzzle source)
{
	for ( limit = 0; limit <= LIMIT; limit++ )
	{
		source.mdist = source.getMD();
		if ( dfs(0, source) )
			return limit;
	}
	return INT_MAX;
}

int main()
{
	Puzzle P;
	int top;
	
	while(1)
	{
		cin >> top;
		if ( top == -1 ) break;
		REP(j, N) P.C[0][j] = -1;
		P.C[0][2] = top;
		for(int i = 1; i < N; i++) REP(j, N)
		{
			if ( (i == 1 || i == 3) && (j == 0 || j == 4 ) )
				P.C[i][j] = -1;
			else if ( i == 4 && j != 2 )
				P.C[i][j] = -1;
			else
				cin >> P.C[i][j];
		}
	
		int cost = idp(P);
		
		if ( cost == INT_MAX )
			cout << "NA" << endl;
		else
			cout << cost << endl;	
	}
	
	return 0;
}