#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <cmath>
#include <stack>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <list>
#include <iostream>
#include <sstream>
#include <climits>
#include <cfloat>
#include <complex>

using namespace std;

typedef long long ll;

ll encode(int* state)
{
	ll res = 0;
	for (int i = 0; i < 13; ++i)
		res = res << 4 | state[i];
	return res;
}
void decode(int* d, ll e)
{
	for (int i = 12; i >= 0; --i, e >>= 4)
		d[i] = e & 15;
}

map<ll, int> minSteps;
int dir[] = { -1, 1, -2, 2, -4, 4 };
map<int, bool> ok[3];

const int InitialDepth = 14;
map<ll, int> problemSteps;

int start_from_initial(ll current, ll next)
{
	bool newState = minSteps.count(next) == 0;
	if (newState)
		minSteps[next] = minSteps[current] + 1;

	return newState && minSteps[next] < InitialDepth ? 0 : -1;
}
int start_from_problem(ll current, ll next)
{
	bool newState = problemSteps.count(next) == 0;
	if (newState)
		problemSteps[next] = problemSteps[current] + 1;

	if (minSteps.count(next))
		return problemSteps[next] + minSteps[next];

	return newState && problemSteps[next] < 20 - InitialDepth ? 0 : -1;
}
int bfs(ll initial, int (*f)(ll, ll))
{
	queue<ll> q;
	q.push(initial);

	while (!q.empty())
	{
		ll e = q.front();
		q.pop();
		int d[13];
		decode(d, e);

		int zero_pos[2];
		for (int i = 0, j = 0; j < 2; ++i)
			if (!d[i])
				zero_pos[j++] = i;

		for (int i = 0; i < 2; ++i)
		{
			for (int j = 0; j < 6; ++j)
			{
				int a = zero_pos[i];
				int b = a + dir[j];
				if (a > b)
					swap(a, b);
				if (a < 0 || b > 12 || !d[a] && !d[b] || !ok[j/2][a])
					continue;

				int copy[13];
				memcpy(copy, d, sizeof(copy));
				swap(copy[a], copy[b]);
				ll next = encode(copy);

				int r = f(e, next);
				if (r == 0)
					q.push(next);
				else if (r > 0)
					return r;
			}
		}
	}

	return -1;
}

int main()
{
	int o[][9] = {
		{ 1, 2, 4, 5, 6, 7, 9, 10, -1 },
		{ 0, 10, -1 },
		{ 1, 2, 3, 5, 6, 7, -1 }
	};
	for (int i = 0; i < 3; ++i)
		for (int j = 0; o[i][j] != -1; ++j)
			ok[i][o[i][j]] = true;

	int initial[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 0 };
	ll t = encode(initial);
	minSteps[t] = 0;

	bfs(t, start_from_initial);

	while (true)
	{
		int d[13];
		for (int i = 0; i < 13; ++i)
			scanf("%d", d + i);
		if (d[0] == -1)
			break;

		int ans = -1;
		ll s = encode(d);
		if (minSteps.count(s))
			ans = minSteps[s];
		else
		{
			problemSteps.clear();
			ans = bfs(s, start_from_problem);
		}

		if (ans != -1)
			printf("%d\n", ans);
		else
			puts("NA");
	}

	return 0;
}