#include <bits/stdc++.h>
using namespace std;
const int MAX = 150000;
long long mod = 2000000011;
void pls() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
}
long long mul_mod(long long a, long long b, long long m) {
  long long x = 0, y = a;
  while (b > 0) {
    if (b & 1) {
      x = (x + y) % m;
    }
    y = (y + y) % m;
    b >>= 1;
  }
  return x;
}
inline int madd(int x, int y) { return (x % mod + y % mod) % mod; }
inline int msub(int x, int y) { return (mod + x % mod - y % mod) % mod; }
long long gcd(long long a, long long b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
long long powmod(long long a, long long mod, long long p) {
  if (p == 0) return 1LL % mod;
  long long res;
  long long x = powmod(a, mod, p / 2);
  res = x;
  if (p & 1) x = mul_mod(x, a, mod);
  return mul_mod(x, res, mod);
}
long long exp(long long a, long long p) {
  if (p == 0) return 1;
  long long res;
  long long x = exp(a, p / 2);
  res = x;
  if (p & 1) x = (x * a);
  return (x * res);
}
long long sqt(long long x) {
  long long l = 1LL;
  long long r = x;
  long long res;
  while (l <= r) {
    long long mid = l + (r - l) / 2;
    if (mid * mid <= x) {
      res = mid;
      l = mid + 1;
    } else
      r = mid - 1;
  }
  return res;
}
vector<int> soe(long long upto) {
  vector<bool> prime(upto + 1, 0);
  prime[1] = 1;
  prime[0] = 1;
  for (int i = 2; i <= sqt(upto); i++) {
    if (!prime[i]) {
      for (int j = 2 * i; j <= upto; j += i) prime[j] = 1;
    }
  }
  vector<int> res;
  res.push_back(2);
  for (int i = 3; i < prime.size(); i += 2) {
    if (!prime[i]) res.push_back(i);
  }
  return res;
}
int di[8] = {-1, -1, -1, 1, 1, 1, 0, 0};
int dj[8] = {-1, 0, 1, -1, 0, 1, -1, 1};
int ii[4] = {0, 0, -1, 1};
int jj[4] = {-1, 1, 0, 0};
void solve() {
  long long n;
  cin >> n;
  long long a[n];
  long long num = 0, den = n;
  for (int i = 0; i < n; i++) {
    cin >> a[i];
    num += a[i];
  }
  sort(a, a + n);
  long long s = a[0];
  long long sum2 = 0;
  for (int i = 1; i < n; i++) {
    sum2 += (a[i] * i - s), s += a[i];
  }
  num += 2LL * sum2;
  long long gc = gcd(num, den);
  cout << num / gc << " " << den / gc << endl;
}
int main() {
  pls();
  solve();
  return 0;
}
