#include <bits/stdc++.h>
using namespace std;
const int N = 1e4 + 10, M = 1e6 + 50000, inf = 1e9 + 10, mod = 1000000007;
int a[N] = {2, 3, 5};
int main() {
  int x, y, i, z, t;
  scanf("%d", &x);
  if (x == 2)
    printf("-1");
  else {
    printf("6\n10\n15\n");
    for (int i = 0, t = 2; i < x - 3; i++, t++) printf("%d\n", 6 * t);
  }
  return 0;
}
