#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int n, k, i, a[200005], temp, sum = 0;
  cin >> n >> k;
  for (i = 0; i < k; i++) cin >> a[i];
  temp = 1;
  for (i = k - 1; i >= 0; i--) {
    sum += a[i] * temp;
    temp *= n;
  }
  if (sum % 2 == 0)
    cout << "even" << endl;
  else
    cout << "odd" << endl;
  return 0;
}
