#include <bits/stdc++.h>
int A, B, M = 6, N;
int main() {
  scanf("%d%d%d", &N, &A, &B);
  int nda = N / A;
  for (int i = 1; (i <= 2) && (B * i <= N); ++i)
    M = std::min((i ^ 3) + (4 - ((N - B * i) / A) * (i ^ 3) + nda - 1) / nda,
                 M);
  printf("%d\n", M);
  return 0;
}
