#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1e9 + 7;
int main() {
  int n, k;
  cin >> n >> k;
  cout << k * (6 * (n - 1) + 5) << endl;
  for (int i = 1; i <= n; i++) {
    printf("%d %d %d %d\n", k * (6 * (i - 1) + 1), k * (6 * (i - 1) + 2),
           k * (6 * (i - 1) + 3), k * (6 * (i - 1) + 5));
  }
  return 0;
}
